output stringlengths 52 181k | instruction stringlengths 296 182k |
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#include <bits/stdc++.h>
using namespace std;
void debug_out() { cerr << endl; }
template <class T>
ostream& prnt(ostream& out, T v) {
out << v.size() << '\n';
for (auto e : v) out << e << ' ';
return out;
}
template <class T>
ostream& operator<<(ostream& out, vector<T> v) {
return prnt(out, v);
}
template <cla... | ### Prompt
Develop a solution in cpp to the problem described below:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
int n, k, a[maxn];
vector<int> g[maxn];
int par[maxn], h[maxn];
void dfs(int cur) {
for (auto nxt : g[cur]) {
h[nxt] = h[cur] + 1;
dfs(nxt);
}
}
int p[maxn];
multiset<int> res[maxn];
multiset<int> ans;
int pa(int x) { return x == p[x] ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int a[1000005], p[1000005];
basic_string<int> e[1000005], st;
int l[1000005], r[1000005], dub[1000005], lrt;
void dfs(int x) {
l[x] = ++lrt;
for (int y : e[x]) {
dub[y] = dub[x] + 1;
dfs(y);
}
r[x] = lrt;
}
const int MAXN = 1 << 20;
int b[2 * MAXN]... | ### Prompt
Please create a solution in Cpp to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
struct Tree {
int l, r, mx, laz;
} t[maxn << 2];
struct Node {
int v, next;
} e[maxn << 1];
int head[maxn], dfn[maxn], siz[maxn], tot, num;
int sta[maxn], top;
long long a[maxn];
void Add(int x, int y) {
e[++tot].v = y;
e[tot].next = head[... | ### Prompt
Please provide a CPP coded solution to the problem described below:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000005;
const int unit = 450;
int n, m, a[maxn], b[maxn], l[maxn], r[maxn];
long long t[maxn << 2], lz[maxn << 2], tim;
vector<int> v[maxn];
void dfs(int x) {
l[x] = ++tim;
for (auto u : v[x]) dfs(u);
r[x] = tim;
}
void update(int L, int R, int d, in... | ### Prompt
Develop a solution in cpp to the problem described below:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
template <typename A, typename B>
ostream &operator<<(ostream &cout, pair<A, B> const &p) {
return cout << "(" << p.first << ", " << p.second << ")";
}
template <typename A>
ostream &operator<<(ostream &cout, vector<A> const &v) {
cout << "[";
for (int i = 0; i < v.si... | ### Prompt
Construct a cpp code solution to the problem outlined:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].... |
#include <bits/stdc++.h>
using namespace std;
mt19937 rng(static_cast<unsigned int>(
chrono::steady_clock::now().time_since_epoch().count()));
template <typename num_t>
inline void add_mod(num_t& a, const int& b, const int& m) {
a = (a + b);
if (a >= m) a -= m;
}
template <typename num_t>
inline bool update_max... | ### Prompt
Please create a solution in CPP to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 5, mod = 1e9 + 7;
int t, tree[4 * N], tmin[N], tmout[N], timer, lazy[4 * N], r[N], n, k, a[N];
vector<int> V[N];
void update(int u, int start, int end, int l, int r, int val) {
if (lazy[u]) {
tree[u] += lazy[u];
if (l != r) {
lazy[2 * u] ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int arr[1000008];
int l[1000008];
int mx[1000008 << 2], lazy[1000008 << 2];
void pushup(int rt) { mx[rt] = max(mx[rt << 1], mx[rt << 1 | 1]); }
void build(int rt, int l, int r) {
if (l > r) return;
if (l == r) {
mx[l] = arr[l];
return;
}
int mid = ... | ### Prompt
Please formulate a Cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1000010;
struct SegementTree {
int mx, lz;
};
SegementTree tr[maxn * 4];
int L[maxn], a[maxn];
void pushup(int x) { tr[x].mx = max(tr[(x << 1)].mx, tr[((x << 1) | 1)].mx); }
void maintain(int x, int val) {
tr[x].mx += val;
tr[x].lz += val;
}
void push... | ### Prompt
Create a solution in cpp for the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].
Y... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
void out(T x) {
cout << x << endl;
exit(0);
}
const int inf = 2e9;
const int maxn = 1e6 + 5;
struct MaxLazySegmentTree {
vector<int> t, o;
void init(int n) {
n += 10;
t.resize(4 * n);
o.resize(4 * n);
}
void push(int v) {
t[... | ### Prompt
Generate a cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].
You... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
vector<int> a, bit;
bool par[1000005];
vector<int> in, out;
int cnt(0);
struct it {
int COUNT, LAZY;
it *l, *r;
void Update(int l, int r, int L, int R, int a);
};
it *add() {
it *t = new it;
t->COUNT = 0;
t->LAZY = 0;
t->l = t->r = NULL;
return t;
... | ### Prompt
Your task is to create a CPP solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] ... |
#include <bits/stdc++.h>
using namespace std;
const int MX = 1e6;
int st[MX * 4], la[MX * 4], tin[MX], tout[MX], t, n;
vector<int> chd[MX];
void dfs(int u) {
tin[u] = ++t;
for (auto c : chd[u]) {
dfs(c);
}
tout[u] = t;
}
void push(int v) {
st[v * 2] += la[v];
la[v * 2] += la[v];
st[v * 2 + 1] += la[v]... | ### Prompt
Please create a solution in cpp to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 1e6 + 10;
int seg[4 * maxn], lazy[4 * maxn];
void propagate(int, int, int);
int get(int id, int L, int R, int l, int r) {
if (L == l and R == r) return seg[id];
propagate(id, L, R);
int mid = (L + R) >> 1, ret = 0;
if (l < mid) ret = max(ret, get(2 ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
const int MAX_N = 1000025;
int in[MAX_N], out[MAX_N], arr[MAX_N], dep, s[MAX_N << 2], col[MAX_N << 2],
ans[MAX_N];
stack<int> st;
vector<int> vt[MAX_N];
void dfs(int rt, int fa) {
in[rt] = ++dep;
for (int i = 0; i < vt[rt].size(); i++) {
int to = vt[rt][i];
... | ### Prompt
Construct a CPP code solution to the problem outlined:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].... |
#include <bits/stdc++.h>
using namespace std;
int i, j, l, cnt = 0;
int ar[1000050], tin[1000050], tout[1000050], ans[1000050], ta = 0;
int co[1000050] = {0};
vector<int> g[1000050];
void dfs(int x) {
tin[x] = ++ta;
for (auto it : g[x]) dfs(it);
tout[x] = ta;
}
struct Segment {
int l, r;
int im, _im;
} seg[10... | ### Prompt
Construct a CPP code solution to the problem outlined:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].... |
#include <bits/stdc++.h>
using namespace std;
int n, m, tot, num[1000010], L[1000010];
struct node {
int l, r, mx, sum;
} t[1000010 << 1];
void build(int d, int l, int r) {
if (l == r) return;
int mid = l + r >> 1;
t[d].l = ++tot, build(tot, l, mid), t[d].r = ++tot, build(tot, mid + 1, r);
}
void add(int d, int... | ### Prompt
Develop a solution in CPP to the problem described below:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
int st[1000007];
int top;
int s[1000007], t[1000007];
int mx[4000007];
int sum[4000007];
int head[1000007], to[2000007], nex[2000007];
int n, k;
int a[10000077];
int dfn;
int tot;
void pushup(int rt) { mx[rt] = max(mx[rt << 1], mx[rt << 1 | 1]); }
void pushdown(int rt) {
... | ### Prompt
Please create a solution in CPP to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1000005;
int n, k, ara[N], to[N];
vector<int> g[N];
int tree[4 * N], lazy[4 * N];
void upd(int node, int val) {
lazy[node] += val;
tree[node] += val;
}
void push(int node) {
if (lazy[node] != 0) {
upd(2 * node, lazy[node]);
upd(2 * node + 1, lazy... | ### Prompt
Your task is to create a Cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] ... |
#include <bits/stdc++.h>
int N, K, a[1000002], q[1000002], next[1000002];
int RMQ[20][1000001], *dep = RMQ[0], LOG[1000001];
struct heap {
std::priority_queue<int> add, rmv;
void push(int x) { add.push(x); }
void del(int x) { rmv.push(x); }
int top() {
while (!rmv.empty() && add.top() == rmv.top()) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
struct edge {
int to, next;
} e[1000010];
struct Seg {
int c, add;
} tr[4000010];
int n, K, a[1000010], head[1000010], siz[1000010], dfn[1000010], cnt, tot, top,
S[1000010];
inline void add(int u, int v) {
cnt++;
e[cnt].to = v;
e[cnt].next = head[u];
head[u]... | ### Prompt
Generate a Cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_i].
You... |
#include <bits/stdc++.h>
using namespace std;
const long double eps = 1e-13;
const long double PI = acos(-1);
const int INF = (int)1e9 + 7;
const long long INFF = (long long)1e18;
const int mod = (int)1e9 + 7;
const int MXN = (int)1e6 + 7;
int a[MXN], siz[MXN], gp[MXN], pos[MXN];
vector<int> mem[MXN];
int fd(int v) { r... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e6 + 3;
const int MAXM = 2048 * 1024 + 3;
int t[MAXN];
int nas[MAXN];
int tree[MAXM];
int lazy[MAXM];
pair<int, int> zak[MAXN];
vector<int> vec[MAXN];
int ile = 0;
void DFS(int x) {
zak[x].first = ile + 1;
for (auto it : vec[x]) DFS(it);
if (vec[x].e... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + ... |
#include <bits/stdc++.h>
using namespace std;
struct xy {
int x, y;
};
int a[1212121], par[1212121], depth[1212121];
vector<int> C[1212121];
void dfs(int w, int dep) {
depth[w] = dep;
for (int nxt : C[w]) dfs(nxt, dep + 1);
}
int Hn = 0, myH[1212121], sz[1212121], root[1212121], ppar[1212121];
int find(int x) {
... | ### Prompt
Your task is to create a Cpp solution to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e6 + 10;
int arr[N];
int par[N];
vector<int> adj[N];
int start[N], ending[N];
int ctr = 0;
int tree[4 * N] = {0};
int lazy[4 * N] = {0};
int ans[N];
inline int maxi(int a, int b) { return a > b ? a : b; }
void dfs(int node) {
start[node] = ctr++;
for (int... | ### Prompt
Please create a solution in Cpp to the following problem:
For some array c, let's denote a greedy subsequence as a sequence of indices p_1, p_2, ..., p_l such that 1 ≤ p_1 < p_2 < ... < p_l ≤ |c|, and for each i ∈ [1, l - 1], p_{i + 1} is the minimum number such that p_{i + 1} > p_i and c[p_{i + 1}] > c[p_... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, a = 1, b;
string s, t;
cin >> n >> s;
if (s[0] == '?') s[0] = '(';
if (s[n - 1] == '?') s[n - 1] = ')';
if (n % 2 != 0 || s[0] != '(' || s[n - 1] != ')') {
cout << ":(";
return 0;
}
for (int i = 1; i < n; i++) {
if (s[i] == '(... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
int i;
if (n % 2 == 1) {
cout << ":(" << endl;
return 0;
}
int a = 0, b = 0, c = 0;
int curr = 0;
for (i = 0; i < n; i++)
if (s[i] == '(')
curr++;
else if (s[i] == ')')
curr--;... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
long long sigma(long long n) { return (n * (n + 1) / 2); }
long long MOD(long long x) {
if (x >= 0) return x;
return (-x);
}
bool great(long long a, long long b) { return a > b; }
bool p_sm(pair<long long, long long> a, pair<long long, long long> b) {
if (a.first == b... | ### Prompt
Please create a solution in CPP to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC optimize("-ffloat-store")
#pragma GCC optimize("-fno-defer-pop")
long long int power(long long int a, long long int b, long long int m) {
if (b == 0) return 1;
if (b == 1) return a % m;
lon... | ### Prompt
In Cpp, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
int n, num, top;
string a;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> a;
for (int i = 0; i < n; i++)
if (a[i] == ')') num++;
for (int i = n - 1; i >= 0; i--) {
if (a[i] == '?') {
if (num < n / 2)
a[i] = ... | ### Prompt
In CPP, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, n, p, q, x, flag;
string s;
cin >> n >> s;
if (n & 1) {
cout << ":(" << endl;
return 0;
}
x = n / 2;
p = 0;
for (i = 0; i < n; i += 1)
if (s[i] == '(') p += 1;
p = x - p;
i = 0;
while (p > 0 && i < n) {
if (s[i] == '... | ### Prompt
Please create a solution in CPP to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 6;
int n, c1, c2, v[N], mn = 1e9;
string s;
int main() {
ios::sync_with_stdio(0);
cin >> n;
cin >> s;
if (s[0] == '?') s[0] = '(';
if (s[n - 1] == '?') s[n - 1] = ')';
if (s[0] != '(' || s[n - 1] != ')') {
puts(":(");
return 0;
}
... | ### Prompt
Generate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
inline void Boost() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
}
void NO() {
cout << ":(" << endl;
exit(0);
}
int main() {
Boost();
int n;
cin >> n;
string s;
cin >> s;
if (n % 2 == 1) {
NO();
}
int op = 0;
for (auto x : s)... | ### Prompt
Your task is to create a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only chara... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long int n, i, x, f = 1, y, req;
string s;
cin >> n;
cin >> s;
if ((s[0] == ')') || (n % 2)) {
cout << ":(";
exit(0);
}
y = count(s.begin(), s.end(), '(');
req = n / 2;
if (y > ... | ### Prompt
Create a solution in cpp for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
void dbg_out() { cerr << "\b\b]\n"; }
template <typename Head, typename... Tail>
void dbg_out(Head H, Tail... T) {
cerr << H << ", ";
dbg_out(T...);
}
int main() {
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int n;
cin >> n;
string s;
cin >> s;
if ... | ### Prompt
Generate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
long long n;
cin >> n;
string s;
cin >> s;
if (n & 1) {
cout << ":(" << '\n';
return 0;
}
long long o = n / 2, c = n / 2;
for (char ch : s) {
if (ch == '(')
o--;
else if (ch... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
int n;
string s;
cin >> n >> s;
map<char, int> count;
for (char c : s) count[c]++;
string ans;
int lefts = (count['?'] - count['('] + count[')']) / 2;
for (char c : s) {
if (c == '?') {
ans += l... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
bool is_balanced_and_not_prefix_balanced(string x) {
stack<char> s;
for (int i = 0; i < x.size(); i++) {
if (x[i] == '(') {
s.push(x[i]);
} else if (x[i] == ')' && !s.empty()) {
s.pop();
if (i != x.size() - 1 && s.empty()) return false;
} e... | ### Prompt
Generate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
string s, ans;
long long n, d;
int32_t main() {
ios_base::sync_with_stdio(false), cin.tie(0), cout.tie(0);
cin >> n >> s;
if (n % 2) return cout << ":(", 0;
long long a = n / 2;
for (long long i = 0; i < n; i++) a -= (s[i] == '(');
for (long long i = 0; i < n; i... | ### Prompt
Your task is to create a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only chara... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 1e5 + 5;
int main() {
int n;
scanf("%d", &n);
string s;
cin >> s;
if (n % 2 == 1) {
cout << ":(";
return 0;
}
int no_open = 0;
int no_clos = 0;
for (int i = 0; i < n; i++) {
if (s[i] == '(')
no_open++;
else if (s[i] =... | ### Prompt
Your task is to create a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only chara... |
#include <bits/stdc++.h>
const int N = 3e5 + 5;
int n, cnt1, cnt2, cnt;
char s[N];
int sum[N], a[N];
int char_to_int(char ch) {
if (ch == '(') return -1;
if (ch == ')') return 1;
return 0;
}
char int_to_char(int x) {
if (x == -1) return '(';
if (x == 1) return ')';
return '?';
}
int main() {
scanf("%d%s",... | ### Prompt
Create a solution in cpp for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
const long long N = (long long)(1e6 + 7);
const long long INF = (long long)(1e18 + 7);
const long long MOD = (long long)(1e9 + 7);
signed main() {
ios::sync_with_stdio(false);
cin.tie(nullptr);
long long n;
cin >> n;
string str;
cin >> str;
long long op[n + 1]... | ### Prompt
Construct a cpp code solution to the problem outlined:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "("... |
#include <bits/stdc++.h>
using namespace std;
int32_t main() {
long long n;
string s;
cin >> n >> s;
long long cnt = 0;
for (long long i = 0; i < n; i++) {
if (s[i] == '(') cnt++;
}
for (long long i = 0; i < n; i++) {
if (s[i] == '?') {
if (cnt < n / 2) {
s[i] = '(';
cnt++;
... | ### Prompt
Generate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 5;
int read() {
int x = 0, f = 1;
char ch;
while (!isdigit(ch = getchar())) (ch == '-') && (f = -f);
for (x = ch ^ 48; isdigit(ch = getchar());
x = (x << 3) + (x << 1) + (ch ^ 48))
;
return x * f;
}
template <class T>
T Max(T a, T b)... | ### Prompt
Create a solution in cpp for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
int fmin(int a, int b) {
if (a < b) {
return a;
}
return b;
}
int main() {
int s1, s2 = 0, i, j, o = 0, c = 0, q = 0, temp = 0, flag = 0;
cin >> s1;
int B[s1 + 1];
char ch[s1 + 1], ch2[s1 + 1];
cin >> ch;
B[0] = 0;
for (i = 0; i < s1; i++) {
if (... | ### Prompt
Please formulate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int N;
string S;
int main() {
cin >> N;
cin >> S;
if (N % 2 == 1) {
cout << ":(\n";
return 0;
}
int cnt = 0;
for (auto it : S)
if (it == '(') cnt++;
int L = N / 2 - cnt;
for (int i = 0; i < N; i++)
if (S[i] == '?') {
if (L != 0)
... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
const int inf = 1 << 30;
const long long linf = 1LL << 62;
const int MAX = 510000;
long long dy[8] = {0, 1, 0, -1, 1, -1, 1, -1};
long long dx[8] = {1, 0, -1, 0, 1, -1, -1, 1};
const double pi = acos(-1);
const double eps = 1e-7;
template <typename T1, typename T2>
inline b... | ### Prompt
Generate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 300001;
int len, prefix[3];
string word;
string QQ = {":(\n"};
int main() {
cin >> len >> word;
if (len & 1)
cout << QQ << '\n';
else {
int ff = 0;
for (int i = 0; i < len; ++i) {
ff += (word[i] == '(');
}
for (int i = 0; i <... | ### Prompt
Please create a solution in Cpp to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const int hashP = 239017;
const int N = 1e5 + 10;
const int MOD = 1e9 + 7;
const int MOD2 = 998244353;
int a[1111][1111];
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
string s;
cin >> s;
int kol = 0;
for (auto now : ... | ### Prompt
In Cpp, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
long long int n, cnto = 0, cntc = 0, fino = 0, finc = 0;
string s;
cin >> n;
cin >> s;
stack<char> st;
if (s.size() % 2 != 0) {
cout << ":(" << endl;
return 0;
}
for ... | ### Prompt
Please create a solution in CPP to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
if (n % 2) {
cout << ":(" << endl;
return 0;
}
int n1 = 0, n2 = 0, n3 = 0;
for (int i = 0; i < n; i++) {
if (s[i] == '?') {
n3++;
} else if (s[i] == '(') {
n1++;
} else {
... | ### Prompt
Please create a solution in cpp to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD1 = 1e9 + 7;
const int MOD2 = 998244353;
const long long INF = 2 * 1e18;
const long double PI = 3.14159265358979323846;
int main() {
long long n, cnt = 0, t = 0;
bool x = 0;
string s;
cin >> n >> s;
if (n % 2) {
cout << ":(";
return 0;
}
f... | ### Prompt
Develop a solution in Cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e5;
long long mod = 1e9 + 7;
long long binpow(long long a, long long n) {
long long res = 1;
while (n) {
if (n & 1) res = (res * a) % mod;
n >>= 1;
a = (a * a) % mod;
}
return res;
}
int main() {
ios_base ::sync_with_stdio(false);
c... | ### Prompt
Please create a solution in cpp to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
char s[300005];
int n;
int l = 0, r = 0;
int addl = 0;
int lmax = 0;
int main() {
ios::sync_with_stdio(false);
scanf("%d", &n);
scanf("%s", s + 1);
if (n & 1) {
cout << ":(" << endl;
return 0;
}
lmax = n / 2;
for (int i = 1; i <= n; ++i)
if (s[i] =... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
const int N = 300000 + 77;
int n, P[N];
char S[N];
int main() {
scanf("%d %s", &n, S + 1);
for (int i = n; i > 0; --i) P[i] = ((S[i] != '(') + P[i + 1] - (S[i] == '('));
int t = 0;
for (int i = 1; i <= n; ++i) {
if (S[i] == '?') {
S[i] = ')';
if (P[i... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 200 * 1000 + 9;
const long long inf = 1e18;
const long long mod = 1e9 + 7;
vector<long long> hello(100005, -1);
void HakunaMatata() {
long long n;
cin >> n;
string s;
cin >> s;
if (n % 2) {
cout << ":(" << '\n';
return;
}
string ans... | ### Prompt
Create a solution in CPP for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &vec) {
os << "[";
for (const auto &v : vec) {
os << v << ",";
}
os << "]";
return os;
}
template <typename T, typename U>
ostream &operator<<(ostream &os, const pair<T, U> &p) {
os << "(... | ### Prompt
Create a solution in CPP for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
int n;
string s;
int main() {
cin >> n >> s;
if (n & 1) {
cout << ":(";
return 0;
}
if (s[0] == ')') {
cout << ":(";
return 0;
}
if (s[n - 1] == '(') {
cout << ":(";
return 0;
}
s[0] = '(';
s[n - 1] = ')';
int tmp = 0;
int open ... | ### Prompt
Please formulate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
template <typename T>
ostream &operator<<(ostream &os, const vector<T> &v);
template <typename T>
ostream &operator<<(ostream &os, const set<T> &v);
template <typename T>
ostream &operator<<(ostream &os, const multiset<T> &v);
template <typename T, typename S>
ostream &oper... | ### Prompt
Your task is to create a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only chara... |
#include <bits/stdc++.h>
using namespace std;
char s[300000 + 5];
int main() {
int n;
scanf("%d", &n);
scanf("%s", s);
if (n % 2) {
printf(":(\n");
return 0;
}
int ans = n / 2;
for (int i = 0; i < n; i++)
if (s[i] == '(') ans--;
for (int i = 0; i < n; i++) {
if (s[i] == '?') {
if (... | ### Prompt
Generate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
const double esp = 1e-6;
const double pi = acos(-1.0);
const int INF = 0x3f3f3f3f;
const int inf = 1e9;
using namespace std;
char s[300005];
int n;
void unhy() {
cout << ":(" << endl;
return;
}
int main() {
cin >> n;
int lf = 0, rt = 0;
int qu = 0;
if (n & 1) {
unhy();
retur... | ### Prompt
Construct a CPP code solution to the problem outlined:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "("... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 1e9 + 10;
const int SZ = 1e6 + 10;
const int mod = 1e9 + 7;
const double PI = acos(-1);
const double eps = 1e-7;
long long read() {
long long n = 0;
char a = getchar();
bool flag = 0;
while (a > '9' || a < '0') {
if (a == '-') flag = 1;
a = g... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
bool check(string s) {
stack<char> st;
for (int index = 0; index < s.size(); index++) {
if (index != 0 && st.empty()) return false;
if (s[index] == '(') {
st.push('(');
} else {
if (st.empty()) {
return false;
} else {
st.po... | ### Prompt
Please formulate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long int n;
cin >> n;
if (n % 2 == 1) {
cout << ":(";
return 0;
}
string a;
cin >> a;
if (a[0] == ')' || a[n - 1] == '(' || a[1] == ')' || a[n - 2] == '(') {
cout << ":(... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
bool sortbysec(pair<int64_t, int64_t> a, pair<int64_t, int64_t> b) {
return (a.second < b.second);
}
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
;
int64_t n, a = 0, b = 0;
string s;
cin >> n >> s;
if (n % 2) return cout << "... | ### Prompt
Your task is to create a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only chara... |
#include <bits/stdc++.h>
using namespace std;
bool valid(string s) {
stack<char> st;
bool valid = true;
for (int i = 0; i < s.length() && valid; i++) {
if (i > 0 && st.empty()) valid = false;
if (s[i] == '(')
st.push('(');
else if (st.empty())
valid = false;
else
st.pop();
}
... | ### Prompt
In Cpp, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
const int N = 3e5 + 5;
char s[N];
int main(void) {
int n;
while (cin >> n) {
int cntl = 0;
int cntr = 0;
int cntq = 0;
getchar();
n = abs(n);
scanf("%s", s);
if (s[0] == ')' || s[n - 1] == '(') {
puts(":(");
continue;
}
if... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
const int N = 100010;
string s;
int n;
bool check() {
int dif = 0;
for (int i = 1; i < s.length() - 1; i++) {
if (s[i] == '(')
dif++;
else if (s[i] == ')')
dif--;
if (dif < 0) return 0;
}
if (dif == 0) return 1;
return 0;
}
int main() {
i... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
int b[300005] = {0};
stack<char> ch;
int main() {
int n;
cin >> n;
char a[300005], ans[300005];
cin >> a;
int l = 0, r = 0;
for (int i = 0; i <= n - 1; i++)
if (a[i] == '(')
l++;
else if (a[i] == ')')
r++;
l = n / 2 - l;
r = n / 2 - r;
... | ### Prompt
Develop a solution in CPP to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
;
int main() {
long long n;
cin >> n;
string s;
cin >> s;
long long open = 0, close = 0;
for (long long i = 0; i < n; i++)
if (s[i] == '(') open++;
for (long long i = 0; i < n; i++) {
if (s[i] == '?') {
if (open < (n / 2)) {
s[i] = '(';
... | ### Prompt
Develop a solution in cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int n, m, k;
string s;
long long ans;
bool flag;
void solve() {
int n;
cin >> n;
string s;
cin >> s;
int r = 0;
for (auto i = 0; i < n; i++) {
if (s[i] == '(') r++;
}
int h = n / 2;
if (r > h || n % 2 != 0) {
cout << ":(";
return;
}
for (au... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
int n, ans, ans2, z, x;
string s;
int main() {
ios::sync_with_stdio(0), cin.tie(NULL), cout.tie(NULL);
cin >> n >> s;
if (n % 2) {
cout << ":(\n";
return 0;
} else {
for (int i = 1; i < n - 1; i++) {
if (s[i] == '(')
ans++;
else if (s... | ### Prompt
Develop a solution in Cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
int i, j, n;
cin >> n;
cin >> s;
j = 0;
for (i = 0; i < n; i++)
if (s[i] == '(') j++;
if (n % 2 == 1) {
cout << ":(";
return 0;
}
j = n / 2 - j;
int k = 0;
for (i = 0; i < n; i++) {
if (s[i] == '?') {
if (j)... | ### Prompt
Develop a solution in cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int n;
string str;
int main(int argc, char const *argv[]) {
cin >> n;
getline(cin, str);
getline(cin, str);
if (str.size() % 2 == 1) {
cout << ":(" << endl;
return 0;
}
int remOpen = n / 2;
int remClose = n / 2;
vector<int> sign;
for (auto it = str... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 3e5 + 10;
const long long inf = 1e9;
int SUM;
int n;
char s[N];
int main() {
scanf("%d", &n);
scanf("%s", s);
bool f = 1;
int cnt = 0;
int l = 0;
for (int i = 0; i < n; ++i) {
if (s[i] == '?') continue;
cnt++;
if (s[i] == '(') l++... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
int n, q, sum;
string s;
void solve() {
cin >> n >> s;
for (auto i : s) {
if (i == '?')
q++;
else
sum += (i == '(') - (i == ')');
}
if ((q - sum) % 2 or q - sum < 0) {
cout << ":(";
return;
}
int o = (q - sum) / 2;
int c = q - o;
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
char s[300010];
int main() {
int n;
scanf("%d%s", &n, s);
int c = 0, cq = 0;
for (int i = 0; i < n; i++)
if (s[i] == '(')
c++;
else if (s[i] == ')')
c--;
else
cq++;
if (c > 0) {
for (int i = n - 1; i >= 0 && c; i--)
if (s[i]... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
const long double PI = 4 * atan((long double)1);
long long int get_hash(string s) {
long long int N = 1000001;
long long int base[N], A = 11, MD = 1110111110111;
base[0] = 1;
for (long long int i = (1); i < (N); ++i) base[i] = (base[i - 1] *... | ### Prompt
Please formulate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
void by() {
cout << ":(";
exit(0);
}
int main() {
int i, j, k, n, m, h;
string s;
cin >> n;
cin >> s;
if (n & 1) by();
int op = (n / 2);
int cl = (n / 2);
int su = 0;
for (i = 0; i < n; i++)
if (s[i] == '(')
op--;
else if (s[i] == ')')
... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
bool check(string &s) {
int ans = 0;
int n = s.size();
for (int i = 1; i < n - 1; i++) {
if (s[i] == ')') {
ans--;
} else {
ans++;
}
if (ans < 0) {
break;
}
}
return ans == 0;
}
int main() {
ios_base::sync_with_stdio(false);... | ### Prompt
Construct a cpp code solution to the problem outlined:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "("... |
#include <bits/stdc++.h>
using namespace std;
string s;
int l, r, n;
bool check() {
int zhan = 0;
for (int i = 1; i <= n - 2; i++) {
if (s[i] == '(')
zhan++;
else {
zhan--;
if (zhan < 0) return 0;
}
}
if (zhan == 0) return 1;
return 0;
}
int main() {
cin >> n;
cin >> s;
if ... | ### Prompt
Develop a solution in cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const long double EPS = 1e-8;
const long long INF = 1e18 + 7;
inline long long read() {
long long X = 0, w = 0;
char ch = 0;
while (!isdigit(ch)) {
w |= ch == '-';
ch = getchar();
}
while (isdigit(ch)) {
X = (X << 3) + (X << 1) + (ch ^ 48);
ch = ge... | ### Prompt
Develop a solution in Cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
string s;
cin >> s;
int a = 0, b = 0;
for (int i = 0; i < n; i++) {
if (s[i] == '(') {
a += 1;
} else if (s[i] == ')') {
b += 1;
}
}
a = n / 2 ... | ### Prompt
Create a solution in CPP for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
void pr() {
cout << ":(";
exit(0);
}
int main() {
string s;
long long int i, j, k, l, p;
cin >> p >> s;
if (p % 2) {
cout << ":("
<< "\n";
} else if ((s[0] == '(' && s[p - 1] == '?') ||
(s[0] == '?' && s[p - 1] == '?') ||
... | ### Prompt
Develop a solution in Cpp to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string a;
cin >> a;
if (n == 0 || n == 1 || n % 2 != 0) cout << "";
int l = 0, r = 0;
for (int i = 0; i < n; i++) {
if (a[i] == '(') l++;
if (a[i] == ')') r++;
if (l > n / 2 || r > n / 2) {
cout << ":(" << endl;
... | ### Prompt
Create a solution in CPP for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
const int INF = 0x3f3f3f3f;
const int N = 500005;
char s[N], p[N];
int read() {
int x = 0, v = 1;
char ch = getchar();
for (; ch < '0' || ch > '9'; v = (ch == '-') ? (-1) : v, ch = getchar())
;
for (; ch <= '9' && ch >= '0'; x = x * 10 + ch - '0', ch = getchar())
;
return x * ... | ### Prompt
Generate a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
string s;
int main() {
int n;
cin >> n >> s;
if (n % 2) {
cout << ":(\n";
return 0;
}
int l = 0, r = 0;
for (int i = 0; i < (n); ++i) {
if (s[i] == '(') l++;
if (s[i] == ')') r++;
}
if (l > n / 2 || r > n / 2) {
cout << ":(\n";
return... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
string s;
cin >> s;
if (n & 1) {
cout << ":(" << endl;
return 0;
}
int cnt1, cnt2;
cnt1 = cnt2 = 0;
for (int i = 0; i < s.size(); i++) {
if (s[i] == '(')
cnt1++;
else if (s[i] == ')')
cnt2++;
}
... | ### Prompt
Generate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
int n;
char s[300005];
int cnt;
inline int read() {
int x = 0, f = 1;
char ch = getchar();
while (ch > '9' || ch < '0') {
if (ch == '-') f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') {
x = x * 10 + ch - '0';
ch = getchar();
}
return ... | ### Prompt
Create a solution in Cpp for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
#include <bits/stdc++.h>
using namespace std;
char z[300005], ans[300005];
int st[300005], last, Min = 1e9, first, cnt[300005], chk;
int main() {
int i, j, n;
scanf("%d %s", &n, z);
if (n % 2 != 0) {
printf(":(");
return 0;
}
if (n == 2) {
if (z[0] == '?') z[0] = '(';
if (z[1] == '?') z[1] = '... | ### Prompt
Please formulate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
long long n, otvoreni = 0, otvorio = 0;
string s;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n;
cin >> s;
if (n & 1) {
cout << ":(";
return 0;
}
long long novi = n / 2;
for (int i = 0; i < n; i++) {
if (s[i] == '(') n... | ### Prompt
Develop a solution in CPP to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
string s;
cin >> n;
cin >> s;
int cont1 = 0;
int cont2 = 0;
if ((s[0] == ')') || (s[n - 1] == '(') || (n % 2 == 1)) {
cout << ":(" << endl;
return 0;
}
string s1(s, 1, n - 2);
int n1 = s1.size();
int cont3 = 0;
int cont4 =... | ### Prompt
In CPP, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int len;
cin >> len;
if (len % 2) {
printf(":(");
return 0;
}
char s[len + 5];
scanf("%s", s);
stack<char> st;
if (s[0] == '?' || s[0] == '(')
s[0] = '(';
else {
printf(":(");
return 0;
}
if (s[len - 1] == '?' || s[len ... | ### Prompt
Please create a solution in cpp to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
bool check(const string &s) {
int bal = 0;
for (int i = 0; i < s.size(); i++) {
if (s[i] == '(') {
bal++;
} else {
bal--;
}
if (bal < 0) return false;
}
return bal == 0;
}
int main() {
int n;
cin >> n;
string s;
cin >> s;
n = s.... | ### Prompt
In cpp, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
int n;
string s;
int main() {
cin >> n >> s;
if (s.size() % 2 != 0) return printf(":("), 0;
int t = s.size() / 2;
int n1 = 0, n2 = 0;
for (auto c : s) {
if (c == '(') n1++;
if (c == ')') n2++;
}
n1 = t - n1;
n2 = t - n2;
if (n1 < 0 or n2 < 0) retur... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only c... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 3e5 + 100;
char str[maxn];
int main() {
int len;
scanf("%d", &len);
scanf("%s", str + 1);
len = strlen(str + 1);
int cnt1 = 0, cnt2 = 0;
for (int i = 1; i <= len; i++) {
if (str[i] == '(')
cnt1++;
else if (str[i] == ')')
cnt2... | ### Prompt
Please formulate a CPP solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters ... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 3e5 + 5;
int n, f[N];
string s, res;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cin >> n >> s;
s = ' ' + s;
long long cnt = 0;
queue<int> q;
for (int i = 1; i <= n; i++) {
if (s[i] == '(')
cnt++;
els... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "("... |
#include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) {
if (a % b == 0)
return b;
else
return gcd(b, a % b);
}
int sum(long long a) {
int sum = 0;
while (a > 0) {
sum = sum + (a % 10);
a = a / 10;
}
return sum;
}
int count_digit(long long n) {
int count = 0;... | ### Prompt
In CPP, your task is to solve the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" a... |
#include <bits/stdc++.h>
using namespace std;
char ss[333333];
string s;
int n, tt, sum(0), dem[255];
bool flag(true);
int main() {
cin >> n;
cin >> ss;
if (n % 2 == 1) flag = false;
for (int i = 0; i < n; i++) {
ss[i] == '(' ? ++dem[40] : ss[i] == ')' ? ++dem[41] : 0;
}
if (dem[40] > n / 2 || dem[41] >... | ### Prompt
Generate a Cpp solution to the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" and ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n;
cin >> n;
string a;
cin >> a;
if (n & 1) {
cout << ":(";
return 0;
}
int cnt1 = 1;
int cnt2 = 1;
if (a[0] == ')') {
cout << ":(";
return 0;
}
a[0] = '(';
... | ### Prompt
Create a solution in cpp for the following problem:
Serval soon said goodbye to Japari kindergarten, and began his life in Japari Primary School.
In his favorite math class, the teacher taught him the following interesting definitions.
A parenthesis sequence is a string, containing only characters "(" an... |
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