output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
const long long N = 205, inf = 1e18;
string second, t;
long long dp[N][N][N];
char par[N][N][N];
long long first(long long i, long long j, long long x) {
if (x < 0 or x > 204) return inf;
if (i == 0 and j == 0) return x;
if (dp[i][j][x] != -1) return dp[i][j][x];
lo... | ### Prompt
Construct a CPP code solution to the problem outlined:
You are given two bracket sequences (not necessarily regular) s and t consisting only of characters '(' and ')'. You want to construct the shortest regular bracket sequence that contains both given bracket sequences as subsequences (not necessarily con... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base ::sync_with_stdio(0);
int q;
cin >> q;
for (int i = 1; i <= q; ++i) {
int n;
cin >> n;
int a = 0, b = 0;
for (int j = 1; j <= n; ++j) {
int x;
cin >> x;
if (x % 2) {
a++;
} else {
b++;
... | ### Prompt
In cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
long long int gcd(long long int a, long long int b) {
if (b == 0) {
return a;
}
return (b % a, a);
}
void primesieve(long long int N, long long int s[]) {
vector<bool> prime(N + 1, false);
for (long long int i = 2; i <= N; i += 2) s[i] = 2;
for (long long in... | ### Prompt
Develop a solution in CPP to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main(int argc, char const *argv[]) {
int t;
cin >> t;
bool even;
bool odd;
for (int i = 1; i <= t; i++) {
int size;
even = false;
odd = false;
cin >> size;
int arr[size];
for (int j = 0; j < size; j++) cin >> arr[j];
for (int j = 0;... | ### Prompt
Please formulate a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, num;
scanf("%d", &t);
for (int i = 1; i <= t; i++) {
scanf("%d", &n);
int E = 0, O = 0;
for (int j = 1; j <= n; j++) {
scanf("%d", &num);
if (num % 2 == 0)
E = 1;
else
O = 1;
}
if ((E && O) |... | ### Prompt
Generate a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
long long t, n, odd, even, x;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
cin >> t;
while (t--) {
cin >> n;
odd = 0;
even = 0;
for (long long i = 0; i < n; i++) {
cin >> x;
if (x % 2 == 1)
odd++;
els... | ### Prompt
Develop a solution in Cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, k, o;
cin >> t;
for (int j = 0; j < t; j++) {
cin >> n;
o = 0;
for (int i = 0; i < n; i++) {
cin >> k;
if (k % 2 == 1) o++;
}
if ((o != n && o != 0) || o % 2 == 1)
cout << "YES\n";
else
cout << "NO... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, j;
cin >> t;
for (j = 0; j < t; j++) {
int n, i, s = 0, a[3000];
cin >> n;
for (i = 0; i < n; i++) {
cin >> a[i];
s = s + a[i];
}
if (s % 2 != 0) {
cout << "YES" << endl;
} else {
int k = 0, l = 0, v,... | ### Prompt
Construct a CPP code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, i, n, j, b, c, s;
cin >> t;
for (i = 0; i < t; i++) {
b = 0;
c = 0;
s = 0;
cin >> n;
int a[n];
for (j = 0; j < n; j++) {
cin >> a[j];
}
for (j = 0; j < n; j++) {
if (a[j] % 2 == 0)
b++;
else... | ### Prompt
Your task is to create a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
long long t, n;
cin >> t;
while (t--) {
cin >> n;
vector<long long> v(n, 0);
for (int i = 0; i < n; i++) {
cin >> v[i];
}
long long odd = 0;
for (int i = 0; i <... | ### Prompt
Generate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
void fast();
long long int ar[200005];
long long int n, a, b, c, d, m, k, q, mod;
vector<long long int> v;
int32_t main() {
fast();
long long int t = 1;
cin >> t;
while (t--) {
cin >> n;
for (long long int i = 0; i < n; i++) cin >> ar[i];
;
long long... | ### Prompt
Generate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
int a[501102];
int ans, cnt, sum, d;
void solve() {
ans = 0;
cnt = 0;
sum = 0;
d = 0;
int n;
cin >> n;
for (int i = 1; n >= i; i++) {
cin >> a[i];
if (a[i] % 2 == 1) {
ans++;
if (a[i] * n % 2 == 1) d = 1;
} else
cnt++;
sum += ... | ### Prompt
Your task is to create a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int check() {
int n, sum = 0, c = 0, flag = 0;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
sum = sum + a[i];
if (a[i] % 2 != 0) c++;
}
if (sum % 2 != 0)
flag = 1;
else if (n % 2 == 0) {
if (c == 0 || c == n)
flag = ... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
vector<int> a;
vector<string> f;
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
int s = 0;
for (int j = 0; j < n; j++) {
int temp;
cin >> temp;
a.push_back(temp);
s += temp;
}
if (s % 2 == 0) {
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
int t;
cin >> t;
for (int i = 0; i < t; i++) {
cin >> n;
vector<int> v(n);
for (int i = 0; i < n; i++) cin >> v[i];
if (n % 2 == 0) {
int k = 0;
int p = 0;
for (int i = 0; i < n; i++) {
if (v[i] % 2 == 0)... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
bool is_even = false, is_odd = false;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
if (x % 2)
is_odd = true;
else
is_even = true;
}
if (is_od... | ### Prompt
Please formulate a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int odd = 0, even = 0;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
odd += (x & 1 ? 1 : 0);
even += (!(x & 1) ? 1 : 0);
}
if (n & 1) {
if (odd > 0) {
... | ### Prompt
In Cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
vector<int> a(n);
for (int i = 0; i < n; i++) {
cin >> a[i];
}
map<int, int> m;
for (int i = 0; i < n; i++) {
if (a[i] & 1) {
m[1]++;
} else {
m[... | ### Prompt
Please create a solution in Cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
void err() { std::cout << '\n'; }
template <typename T, typename... Args>
void err(T a, Args... args) {
std::cout << a << ' ';
err(args...);
}
void pt() { std::cout << '\n'; }
template <typename T, typename... Args>
void pt(T a, Args... args) {
std::cout << a << ' ';
pt(args...);
}
usin... | ### Prompt
Please formulate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
void solve();
signed main() {
srand(time(0));
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
cout.setf(ios::fixed);
cout.precision(9);
solve();
return 0;
}
const long long INF = 1e18;
void query() {
long long n;
cin >> n;
long long cnt = 0;
f... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
int n;
while (t--) {
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int odd = 0, even = 0;
for (int i = 0; i < n;... | ### Prompt
Your task is to create a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
const long long maxn = 2e5 + 100;
long long n, m, t;
long long ans;
int main() {
while (cin >> t) {
while (t--) {
cin >> n;
long long odd = 0, even = 0;
long long sum = 0;
for (long long i = 0; i < n; i++) {
... | ### Prompt
Construct a cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
int main() {
int testCaseCount, caseInpCount;
scanf("%d", &testCaseCount);
for (int testCaseNum = 0; testCaseNum < testCaseCount; testCaseNum++) {
scanf("%d", &caseInpCount);
int oddCount = 0;
int evenCount = 0;
for (int caseNum = 0; caseNum < caseInpCount; caseNum++) {
... | ### Prompt
Develop a solution in cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
bool isSort(long long *a, long long n) {
for (int i = 0; i < n - 1; i++) {
if (a[i] > a[i + 1]) return false;
}
return true;
}
int main() {
int t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long o = 0, e = 0;
long long a[n];
for ... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
long long binpow(long long a, long long b) {
if (b == 0) {
return 1;
}
long long result = binpow(a, b / 2);
if (b % 2) {
return a * result * result;
} else {
return result * result;
}
}
long long digit_sum(long long n) {
if (n <= 9) {
return n;... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
long long int mod = 1e9 + 7;
long long int fast_pow(long long int a, long long int p) {
long long int res = 1;
while (p) {
if (p % 2 == 0) {
a = a * 1ll * a % mod;
p /= 2;
} else {
res = res * 1ll * a % mod;
p--;
}
}
return res;
}... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int t, n;
cin >> t;
while (t--) {
cin >> n;
int cnt = 0, x;
for (int i = 0; i < n; i++) {
cin >> x;
if (x & 1) cnt++;
}
if (cnt == n) {
if (cnt & 1)
cout << "YES" <... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t-- > 0) {
int n;
cin >> n;
int arr[n];
int odd = 0;
int even = 0;
for (int i = 0; i < n; i++) {
cin >> arr[i];
if (arr[i] % 2 == 0) {
even++;
} else {
odd++;
}
}
... | ### Prompt
Please formulate a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
long long t, n, a, nech = 0;
cin >> t;
for (long long q = 0; q < t; q++) {
cin >> n;
for (long long i = 0; i < n; i++) {
cin >> a;
if (a & 1) nech++;
}
if (nech == 0 ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
int num, oddcount = 0, evencount = 0;
for (int i = 0; i < n; i++) {
cin >> num;
num % 2 ? oddcount++ : evencount++;
}
if (n == evencount)
cout << "NO\n";
else if (n == oddcount && n % 2 == 0)
cout << "NO\n";
el... | ### Prompt
Generate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(0);
cin.tie(0);
int t;
cin >> t;
while (t--) {
int a, demc = 0, deml = 0;
cin >> a;
int b[a + 2];
for (int i = 1; i <= a; ++i) {
cin >> b[i];
if (b[i] % 2 == 0)
++demc;
else
+... | ### Prompt
Please provide a cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio();
cin.tie(0);
int t;
cin >> t;
for (int titr = 0; titr < t; titr++) {
int n;
int a[2001];
cin >> n;
for (int i = 0; i < n; i++) cin >> a[i];
if (n % 2 == 0) {
bool o = 0;
bool e = 0;
for... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
using namespace chrono;
template <class T>
void Swap(T &a, T &b) {
a ^= b;
b ^= a;
a ^= b;
}
template <class type>
void show(type name) {
for (auto &nm : name) cerr << nm << ' ';
cerr << '\n';
}
using lng = long long;
using ivec = vector<int>;
int main() {
int n... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
ifstream f("submatrix.in");
ofstream g("submatrix.out");
int t, i, j, n, nr, x;
int main() {
cin >> t;
for (i = 1; i <= t; i++) {
cin >> n;
nr = 0;
for (j = 1; j <= n; j++) {
cin >> x;
if (x % 2 == 0) nr++;
}
if (nr == n)
cout << "N... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int gcd(int a, int b) {
if (b == 0) {
return a;
} else {
return gcd(b, a % b);
}
}
void sol() {
int n;
cin >> n;
vector<int> arr(n);
for (int i = 0; i < n; i++) {
cin >> arr[i];
}
int odd = 0, even = 0;
for (int i = 0; i < n; i++) {
if (a... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
long long fpow(long long x, long long y, long long p = 1000000007) {
x = x % p;
long long sum = 1;
while (y) {
if (y & 1) sum = sum * x;
sum %= p;
y = y >> 1;
x = x * x;
x %= p;
}
return sum;
}
long long modmul(long long x, long long y) { retur... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int sum = 0;
int even = 0;
int odd = 0;
int arr[2001];
for (int i = 0; i < n; i++) {
cin >> arr[i];
sum += (arr[i]);
if (arr[i] % 2 == 0) {
even++;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, i, r, j, n;
cin >> t;
for (i = 0; i < t; i++) {
cin >> n;
int a[n];
r = 0;
for (j = 0; j < n; j++) {
cin >> a[j];
if (a[j] % 2 == 1) {
r = r + 1;
}
}
if (r == 0) {
cout << "NO\n";
} else i... | ### Prompt
Your task is to create a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t, n, i, j;
cin >> t;
for (i = 0; i < t; i++) {
long long int e = 0, o = 0;
cin >> n;
for (j = 0; j < n; j++) {
long long int p;
cin >> p;
if (p % 2 == 0)
e++;
else
o++;
}
if (o % 2... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, c, d;
cin >> t;
for (int i = 0; i < t; i++) {
c = 0;
cin >> n;
int a[n];
for (int j = 0; j < n; j++) {
cin >> a[j];
c += a[j];
}
if (c % 2 != 0)
cout << "YES" << endl;
else {
c = 0;
d = 0... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int tc;
cin >> tc;
while (tc--) {
int n;
cin >> n;
int arr[n];
int odd = 0;
int even = 0;
int total = 0;
bool fl = false;
for (int i = 0; i < n; i++) {
cin >> arr[i];
if (arr[i] & 1) {
odd += 1;
}
... | ### Prompt
Develop a solution in cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
const double eps = 1e-9;
const int inf = 1e9;
int a[N];
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int pos = -1;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] & 1) {
if (pos == -1) pos... | ### Prompt
Please provide a cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long ar[n];
long long sum = 0;
long long e = 0;
long long o = 0;
for (long long i = 0; i < n; i++) {
cin >> ar[i];
if (ar[i] % 2 != 0)
o++;
... | ### Prompt
Create a solution in CPP for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int t;
cin >> t;
int n;
int sum;
int odd;
int even;
while (t--) {
cin >> n;
sum = 0;
odd = 0;
even = 0;
int arr[n];
for (int j = 0; j < n; j++) {
cin >> arr[j];
if (arr[j] % 2 != 0 || arr[j] == 1) {
od... | ### Prompt
Construct a CPP code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
ifstream fin("input.txt");
ofstream fout("output.txt");
int main() {
int calls;
cin >> calls;
int N;
int a;
bool even, odd;
for (int call = 0; call < calls; call++) {
cin >> N;
even = false;
odd = false;
for (int i = 0; i < N; i++) {
cin >>... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
const int maxx = 1e5 + 7;
const int maxn = 1e9 + 1;
using namespace std;
int t;
int n;
int a[maxx];
int main() {
scanf("%d", &t);
while (t--) {
scanf("%d", &n);
int flag1 = 0, flag2 = 0;
for (int i = 0; i < n; i++) {
scanf("%d", &a[i]);
if (a[i] % 2 == 0)
fla... | ### Prompt
Please provide a cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int n;
cin >> n;
int ar[n];
int sum = 0;
int numOdd = 0;
int even = 0;
for (int i = 0; i < n; i++) {
cin >> ar[i];
sum += ar[i];
if (ar[i] % 2 != 0)
numOdd++;
else
even++;
}
if (sum % 2 != 0 || (numOdd - 1 % 2 != ... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int t, n, temp;
bool hasOdd, hasEven;
int main() {
cin >> t;
for (int i = 0; i < t; i++) {
hasEven = false;
hasOdd = false;
cin >> n;
for (int j = 0; j < n; j++) {
cin >> temp;
if (temp & 1) {
hasOdd = true;
} else {
has... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int read() {
int sum = 0, f = 1;
char s = getchar();
while (s < '0' or s > '9') {
if (s == '-') f = -1;
s = getchar();
}
while (s >= '0' and s <= '9') {
sum = sum * 10 + s - '0';
s = getchar();
}
return sum * f;
}
int n, t, a, b, sum, c;
int ma... | ### Prompt
Your task is to create a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n, sum = 0, odd = 0, even = 0;
cin >> n;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
if (arr[i] % 2 != 0 || arr[i] == 1) {
odd++;
} else {
even++;
}
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
inline int read() {
int s = 0, w = 1;
char ch = getchar();
while (ch < '0' || ch > '9') {
if (ch == '-') w = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') s = s * 10 + ch - '0', ch = getchar();
return s * w;
}
int a[2010];
int main() {
int T = r... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int tc;
cin >> tc;
while (tc--) {
int n;
cin >> n;
int x[n], sum = 0;
for (int i = 0; i < n; i++) {
cin >> x[i];
sum += x[i];
}
bool b = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j++) {
i... | ### Prompt
Construct a CPP code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
vector<long long> a;
int sum = 0;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
a.push_back(x);
s... | ### Prompt
Create a solution in cpp for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
int main() {
std::ios::sync_with_stdio(false);
int times;
cin >> times;
while (times) {
int n;
cin >> n;
int count = 0;
bool o = false;
for (int i = 0; i < n; i++) {
int a;
cin >> a;
if (a % 2 == 0)
o = true;
else
... | ### Prompt
Please formulate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n], sum = 0;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 != 0) sum++;
}
if ((sum == n && sum % 2 == 0) || sum == 0)
cout << "NO" << endl;
else
... | ### Prompt
Generate a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int odd = 0, even = 0;
for (int i = 0; i < n; i++) {
int tmp;
cin >> tmp;
int test = tmp & 1;
if (tmp & 1)
odd++;
else
even++;
}
if ((odd... | ### Prompt
Your task is to create a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
signed int main() {
long long int n, a, q;
cin >> q;
vector<int> v;
for (long long int i = 0; i < q; i++) {
cin >> n;
int sum = 0, odd = 0, even = 0;
for (long long int j = 0; j < n; j++) {
cin >> a;
if (a % 2 == 0) even++;
if (a % 2 ==... | ### Prompt
Develop a solution in Cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n], sum = 0;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 != 0) sum++;
}
if ((n % 2 != 0 && sum != 0) || (n % 2 == 0 && sum != 0 && sum != n))
cout ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
inline long long read() {
long long num = 0, w = 0;
char ch = 0;
while (!isdigit(ch)) {
w |= ch == '-';
ch = getchar();
}
while (isdigit(ch)) {
num = (num << 3) + (num << 1) + (ch ^ 48);
ch = getchar();
}
return w ? -num : num;
}
inline void wr... | ### Prompt
Please provide a cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int t, n, a;
int main() {
ios::sync_with_stdio(0);
cin.tie(NULL);
cout.tie(NULL);
;
cin >> t;
while (t--) {
cin >> n;
bool e = 0, o = 0;
int sum = 0;
for (int i = 0; i < n; ++i) {
cin >> a;
sum += a;
if (a % 2 == 0)
e = ... | ### Prompt
Create a solution in cpp for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
long long exp(long long a, long long n) {
if (n == 0) return 1;
long long residue = 1, result = a;
while (n > 1LL) {
if (n % 2LL == 1LL) residue = residue * residue % 1000000007LL;
result = result * result % 1000000007LL;
n = n >> 1;
}
return residue *... | ### Prompt
Develop a solution in CPP to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
long long t, n, a[2010], kt, vt;
int main() {
cin >> t;
while (t--) {
cin >> n;
kt = 0;
vt = 0;
for (int i = 1; i <= n; i++) {
cin >> a[i];
if (a[i] % 2)
kt++;
else
vt++;
}
if (kt == 0)
cout << "NO"
... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
long long a[n + 4];
long long i, sum = 0;
long long o = 0, e = 0;
for (i = 0; i < n; i++) {
cin >> a[i];
sum += a[i];
if (a[i] & 1) {
o = 1;
... | ### Prompt
Please formulate a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
const double pie = 2 * acos(0.0);
const long long mxl = 1000000007;
template <class T>
inline void sarray(T* st, T* nd) {
while (st < nd) cin >> *st++;
}
template <class T>
inline void parray(T* st, T* nd) {
while (st < nd) cout << *st++ << endl;
}
int main() {
int t;... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
int Case, n, a[2001];
int main(void) {
register int i, sum = 0;
scanf("%d", &Case);
while (Case--) {
scanf("%d", &n);
sum = 0;
for (i = 1; i <= n; ++i) scanf("%d", a + i), sum += a[i] & 1;
if (sum & 1 || (sum && sum ^ n))
puts("YES");
else
puts("NO");
}
... | ### Prompt
Your task is to create a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int a[2005];
int main() {
int T;
scanf("%d", &T);
int n;
while (T--) {
int tag1 = 0, tag2 = 0;
scanf("%d", &n);
int sum = 0, cnt = 0;
for (int i = 1; i <= n; i++) {
scanf("%d", &a[i]);
sum += a[i];
if (a[i] % 2 == 1) cnt++;
}
... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, i;
cin >> t;
for (i = 0; i < t; i++) {
cin >> n;
int sum = 0, sumEven = 0, sumOdd = 0;
int array[n];
for (int i = 1; i <= n; i++) {
scanf("%d", &array[i]);
sum += array[i];
if (array[i] % 2 == 0) {
sumEv... | ### Prompt
Develop a solution in cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int t;
int main() {
cin >> t;
while (t--) {
int n, nrp = 0, nri = 0;
cin >> n;
while (n--) {
int x;
cin >> x;
if (x % 2)
nri++;
else
nrp++;
}
if (nrp == 0)
if (nri % 2)
cout << "YES\n";
else... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
long long int a[1000005];
bool isOdd(long long int arr[], long long int n) {
long long int l, r, flag = 0, flag1 = 0, sum = 0;
for (int i = 0; i < n; i++) {
sum += arr[i];
if (arr[i] % 2 == 0 && flag == 0) {
flag = 1;
l = arr[i];
}
if (arr[i]... | ### Prompt
Please formulate a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
cin >> n;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
int cnt = 0;
int arr[x];
for (int j = 0; j < x; j++) {
cin >> arr[j];
if (arr[j] % 2 == 1) {
cnt++;
}
}
if (cnt == x && x % 2 == 0) {
... | ### Prompt
Please provide a cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int k = 0; k < t; k++) {
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
}
int e = 0;
int o = 0;
for (int i = 0; i < n; i++) {
if (a[i] % 2 == 0) {
e++;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, i;
cin >> t;
for (i = 0; i < t; i++) {
cin >> n;
int sum = 0, sumEven = 0, sumOdd = 0;
int array[n];
for (int i = 1; i <= n; i++) {
scanf("%d", &array[i]);
sum += array[i];
if (array[i] % 2 == 0) {
sumEv... | ### Prompt
Please formulate a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
int main() {
int t;
scanf("%d", &t);
int i;
for (i = 0; i < t; i++) {
int n;
scanf("%d", &n);
int count = 0;
int counter = 0;
int j;
for (j = 0; j < n; j++) {
int temp;
scanf("%d", &temp);
if (temp % 2) {
count++;
} else {
... | ### Prompt
Construct a CPP code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
int T, N;
template <typename elemType>
inline void Read(elemType &T) {
elemType X = 0, w = 0;
char ch = 0;
while (!isdigit(ch)) {
w |= ch == '-';
ch = getchar();
}
while (isdigit(ch)) X = (X << 3) + (X << 1) + (ch ^ 48), ch = getchar();
T = (w ? -X : X);... | ### Prompt
Your task is to create a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
long long n, x = 0, y = 0, i, j, k;
cin >> n;
vector<long long> a(n);
for (i = 0; i < n; i++) cin >> a[i];
for (i = 0; i < n; i++) {
if (a[i] % 2 == 0)
x++;
else
y++;
}
... | ### Prompt
Please create a solution in Cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[2000];
int i;
long long sum = 0;
int o = 0;
int e = 0;
for (i = 0; i < n; i++) {
cin >> a[i];
sum += a[i];
if (a[i] % 2 == 0) e = 1;
if (a[i] % 2... | ### Prompt
Construct a Cpp code solution to the problem outlined:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1e9 + 7;
const double pi = 3.14159265358979323846;
const long long mxN = 2e5 + 1;
void _print(long long t) { cerr << t; }
void _print(string t) { cerr << t; }
void _print(char t) { cerr << t; }
void _print(double t) { cerr << t; }
template <class T, cl... | ### Prompt
Develop a solution in cpp to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
const int mod = 1000000007;
const double dancila = 3.14159265359;
const double eps = 1e-9;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
int t;
cin >> t;
for (; t; --t) {
int n;
cin >> n;
bool imp = 0;
boo... | ### Prompt
Create a solution in cpp for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
int even = 0, odd = 0;
while (t > 0) {
t--;
int n;
cin >> n;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 == 0) even = 1;
if (a[i] % 2 != 0) odd = 1;
}
if (n % 2 == 0) {... | ### Prompt
In Cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int A[2] = {0, 0};
int x;
for (int i = 0; i < n; i++) {
cin >> x;
A[x % 2] += 1;
}
if (A[1] == 0 || A[1] == n && n % 2 == 0)
cout << "NO\n";
else
cout ... | ### Prompt
Please formulate a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base ::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int odd = 0, ev = 0;
for (int i = 0, num; i < n; i++) {
cin >> num;
if (num % 2 == 0) {
ev++;
... | ### Prompt
Create a solution in cpp for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
int main() {
bool odd, even;
int sum;
int in;
int n;
int T;
cin >> T;
while (T--) {
cin >> n;
odd = 0;
even = 0;
sum = 0;
for (int i = 0; i < n; i++) {
cin >> in;
sum += in % 2;
if (in % 2 == 1) {
odd = 1;
} ... | ### Prompt
In cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
start:
while (t--) {
int n;
cin >> n;
int sum = 0;
int a[n];
for (int i = 0; i < n; i++) {
cin >> a[i];
sum += a[i];
}
int count = 0;
for (int i = 0; i < n; i++) {
for (int j = 0; j < n; j... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int long long n;
cin >> n;
int a[n];
int even = 0, odd = 0;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 == 0)
even++;
else
odd++;
}
if (odd % 2 != 0)
... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
void solve() {
int num;
cin >> num;
int arr[num + 1];
int count = 0;
int odd = 0;
for (int i = 0; i < num; i++) {
cin >> arr[i];
count += arr[i];
if (arr[i] % 2 != 0) odd++;
}
if (count % 2 != 0)
cout << "Yes" << endl;
else if (odd == num &... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
const int MAXN = 2e6 + 1;
const int INF = 2e9 + 1;
const int MOD = (1e9 + 7);
void bye(string s = "") {
cout << s << '\n';
exit(0);
}
signed main() {
ios::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
int t = 1;
cin >> t;
while (t--) {
int n;
... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
int dx4[] = {0, 0, -1, 1};
int dy4[] = {-1, 1, 0, 0};
bool valid(int r, int c, int x, int y) {
if (x >= 1 && x <= r && y >= 1 && y <= c) return 1;
return 0;
}
using namespace std;
int main() {
int t;
cin >> t;
for (int cs = 1; cs <= t; cs++) {
int n;
cin >> n;
int a[n + 2]... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
template <typename Arg1>
void ZZ(const char* name, Arg1&& arg1) {
cerr << name << " = " << arg1 << "\n";
}
template <typename Arg1, typename... Args>
void ZZ(const char* names, Arg1&& arg1, Args&&... args) {
const char* comma = strchr(names + 1, ',');
cerr.write(names... | ### Prompt
Please provide a CPP coded solution to the problem described below:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
for (int z = 0; z < t; z++) {
int n;
cin >> n;
int odd = 0, even = 0;
int arr[n];
for (int i = 0; i < n; i++) {
cin >> arr[i];
if (arr[i] % 2 == 0) {
even++;
} else {
odd++;
}
... | ### Prompt
Please create a solution in Cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
#pragma optimize("Ofast")
using namespace std;
using ll = long long;
const int N = 2e5 + 5;
int main() {
ios_base::sync_with_stdio(0);
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int o = 0, e = 0;
for (int i = 0; i < n; ++i) {
int x;
cin >> x;
if (x... | ### Prompt
Generate a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a, sum = 0;
int count_even = 0, count_odd = 0;
for (int i = 0; i < n; i++) {
cin >> a;
if (a % 2 == 0)
count_even++;
else
count_odd++;
sum += a... | ### Prompt
Please create a solution in cpp to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n];
int c = 0;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 == 1) c++;
}
if (c == 0)
cout << "NO\n";
else if (c > 0) {
if (c == n && n... | ### Prompt
Your task is to create a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in d... |
#include <bits/stdc++.h>
int main() {
int i, j, t, n, a[20000], counto, counte;
scanf("%d", &t);
for (i = 1; i <= t; i++) {
counto = 0, counte = 0;
scanf("%d", &n);
for (j = 0; j < n; j++) {
scanf("%d", &a[j]);
if (a[j] % 2 == 0)
counte++;
else
counto++;
}
if ... | ### Prompt
In CPP, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
const int inf = int(1e9) + 15;
long long time() {
return chrono::system_clock().now().time_since_epoch().count();
}
mt19937 rnd(time());
const double PI = acos(-1);
const double PPI = 2 * PI;
const int base = (1000 * 1000 * 1000);
void solve() {
int n;
cin >> n;
int... | ### Prompt
Generate a Cpp solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different opera... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n;
int v, cnt;
scanf("%d", &t);
while (t--) {
cnt = 0;
scanf("%d", &n);
for (int i = 0; i < n; ++i) {
scanf("%d", &v);
if (v % 2 == 1) {
cnt++;
}
}
if (cnt > 0 && (cnt < n || n % 2 == 1)) {
prin... | ### Prompt
Create a solution in Cpp for the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different ope... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int tests;
cin >> tests;
string ans[tests];
for (int i = 0; i < tests; i++) {
int n;
int sum = 0;
cin >> n;
int arr[n];
int odd = 0;
for (int j = 0; j < n; j++) {
cin >> arr[j];
if (arr[j] & 1) odd++;
sum += arr... | ### Prompt
Please create a solution in CPP to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, t, a, sum;
cin >> t;
while (t--) {
cin >> n;
sum = 0;
bool flag = 0;
for (int i = 0; i < n; i++) {
scanf("%d", &a);
sum += a % 2;
}
if (sum > 0 && sum < n || sum % 2 == 1)
cout << "YES" << endl;
else
... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
bool e = false, o = false;
for (int i = 0; i < n; i++) {
int temp;
cin >> temp;
if (temp % 2 == 0)
e = true;
else
o = true;
}
if (e && !o)
... | ### Prompt
Please create a solution in CPP to the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in differe... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(0);
cin.tie(0), cout.tie(0);
long long t;
cin >> t;
while (t--) {
long long n;
cin >> n;
vector<long long> a(n);
long long sum = 0;
for (auto &i : a) {
cin >> i;
sum += i;
}
if (sum ... | ### Prompt
In cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t;
cin >> t;
while (t--) {
int n;
cin >> n;
int a[n], sum = 0;
for (int i = 0; i < n; i++) {
cin >> a[i];
if (a[i] % 2 != 0) sum++;
}
if (sum != 0 && (n % 2 != 0 || (n % 2 == 0 && sum != n)))
cout << "YES" << ... | ### Prompt
In Cpp, your task is to solve the following problem:
You are given an array a consisting of n integers.
In one move, you can choose two indices 1 ≤ i, j ≤ n such that i ≠ j and set a_i := a_j. You can perform such moves any number of times (possibly, zero). You can choose different indices in different op... |
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