output stringlengths 52 181k | instruction stringlengths 296 182k |
|---|---|
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k, i, j, tot = 0;
scanf("%d%d", &n, &k);
if (n * (n - 1) / 2 > k) {
for (i = 1; i <= n && tot < n; i++) {
for (j = i + 1; j <= n && tot < n; j++, tot++) {
printf("%d %d\n", i, j);
}
}
} else
puts("no solution");
... | ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d", &n);
scanf("%d", &k);
int tComplexity = n * (n - 1) / 2;
if (tComplexity > k) {
for (int i = 0; i < n; i++) {
printf("%d %d\n", 0, i);
}
} else
printf("%s\n", "no solution");
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
long long t;
t = 1;
while (t--) {
long long n, k, i;
cin >> n >> k;
if (k >= (n * (n - 1)) / 2)
cout << "no solution";
else {
long long a[n], b[n];
for (i = 0; i < n; i... | ### Prompt
Your challenge is to write a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d%d", &n, &k);
if (n * (n - 1) / 2 > k) {
for (int i = 0; i < n; i++) printf("0 %d\n", i);
} else
printf("no solution");
return 0;
}
| ### Prompt
Your challenge is to write a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
long long n, k;
int main() {
cin >> n >> k;
if (((n - 1) * n) / 2 <= k) {
cout << "no solution" << endl;
return 0;
}
for (int i = 0; i < n; i++) cout << 0 << " " << i << endl;
return 0;
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
int main() {
int n, k;
while (scanf("%d%d", &n, &k) != EOF) {
if (k >= n * (n - 1) / 2) {
printf("no solution\n");
} else {
for (int i = 0; i < n; i++) {
printf("0 %d\n", i);
}
}
}
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k) {
cout << "no solution" << endl;
} else {
for (int i = 0; i < n; i++) {
cout << "0 " << i << endl;
}
}
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k)
cout << "no solution";
else
for (int i = 1; i <= n; i++) cout << "0 " << i << '\n';
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d %d", &n, &k);
if (n * 1LL * (n - 1) / 2 <= k)
printf("no solution\n");
else {
for (int i = 0; i < n; i++) printf("%d %d\n", 0, i);
}
return 0;
}
| ### Prompt
Create a solution in cpp for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k, i;
cin >> n >> k;
if (k >= n * (n - 1) / 2) {
cout << "no solution" << endl;
return 0;
}
for (i = 1; i <= n; i++) cout << "0 " << i << endl;
return 0;
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
inline long long mod(long long n, long long m = (long long)(1e9 + 7)) {
return (n % m + m) % m;
}
inline long long gcd(long long a, long long b) {
return (b == 0LL) ? a : gcd(b, a % b);
}
inline long long modPow(long long a, long long b,
long lon... | ### Prompt
Construct a cpp code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
long long int modpow(long long int a, long long int n, long long int temp) {
long long int res = 1;
while (n > 0) {
res = (res * res) % temp;
if (n & 1) res = (res * a) % temp;
n /= 2;
}
return res;
}
long long int gcd(long long int a, long long int b) {... | ### Prompt
Please formulate a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
int main() {
int n, k, i;
scanf("%d %d", &n, &k);
if (k >= n * (n - 1) / 2) {
puts("no solution");
} else {
for (i = 0; i < n; i++) printf("0 %d\n", i);
}
return 0;
}
| ### Prompt
Construct a cpp code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) / 2 > k) {
for (int i = 0; i < n; i++) {
printf("%d %d\n", 0, i);
}
} else {
cout << "no solution";
}
}
| ### Prompt
Generate a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the foll... |
#include <bits/stdc++.h>
using namespace std;
const int INFint = 2147483647;
const long long INF = 9223372036854775807ll;
const long long MOD = 1000000007ll;
int main() {
ios_base::sync_with_stdio(0);
long long n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k) {
cout << "no solution" << endl;
return 0;
}... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long int t, i, j, n, k, mx;
mx = 1000000000LL;
cin >> n >> k;
t = (n * (n - 1)) / 2;
if (t <= k) {
cout << "no solution";
} else {
for (i = 0; i < n - 1; i++) {
cout << "0 " << i << "\n";
}
cout << mx << " " << mx;
}
r... | ### Prompt
Please create a solution in CPP to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long n, k;
cin >> n >> k;
if (k >= n * (n - 1) / 2) {
cout << "no solution";
return 0;
}
for (long i = 0; i < n; i++) cout << "0 " << i << endl;
return 0;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
int main() {
int n, k;
scanf("%d%d", &n, &k);
if (k >= n * (n - 1) / 2) {
printf("no solution\n");
return 0;
}
for (int i = 0; i < n; ++i) printf("0 %d\n", i);
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k) {
cout << "no solution";
} else {
for (int i = 0; i < n; i++) cout << "0 " << i << "\n";
}
return 0;
}
| ### Prompt
Please formulate a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int n, k, p1, p2;
int main() {
cin >> n >> k;
int tot = 0;
for (int i = 1; i <= n; ++i)
for (int j = i + 1; j <= n; ++j) ++tot;
if (tot > k) {
for (int i = 0; i < n; ++i) {
cout << 0 << ' ' << i << endl;
}
} else
cout << "no solution" << endl... | ### Prompt
In cpp, your task is to solve the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the f... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (k >= (n * (n - 1)) / 2) {
cout << "no solution";
return 0;
}
for (int i = 0; i < n; i++) {
cout << 0 << ' ' << i << endl;
}
return 0;
}
| ### Prompt
Create a solution in Cpp for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
using namespace std;
char a[1000];
void solve() {
int n, k;
while (scanf("%d%d", &n, &k) != EOF) {
if (((1 + n - 1) * (n - 1) / 2) <= k) {
printf("no solution\n");
continue;
} else {
int temp = 0;
for (int i = 1; i <= n; i++) {
printf("0 %d\n", i);
... | ### Prompt
Construct a CPP code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
string c;
int main() {
int i, j, k, n, m, l;
scanf("%d%d", &n, &k);
if (n * (n - 1) / 2 <= k) {
puts("no solution");
return 0;
}
for (i = 1; i <= n; i++) printf("%d %d\n", 0, i);
return 0;
}
| ### Prompt
Generate a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the foll... |
#include <bits/stdc++.h>
using namespace std;
struct node {
int x;
int y;
};
node point[2000 + 10];
int n;
int sum;
void solve() {
for (int i = 2; i <= n; ++i) {
point[i].y = point[i - 1].y + 1;
}
for (int i = 1; i <= n; ++i)
for (int j = i + 1; j <= n; ++j) ++sum;
}
int main() {
int k;
int tem;
... | ### Prompt
Please formulate a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const long long N = 1e6 + 7;
long long n, k;
int32_t main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
long long mx = n * (n - 1) / 2;
if (k >= mx) return cout << "no solution", 0;
long long y = 0;
for (long long i = 1; i < n; i++, y += ... | ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
inline long long inp() {
long long n = 0, s = 1;
char p = getchar();
if (p == '-') s = -1;
while ((p < '0' || p > '9') && p != EOF && p != '-') p = getchar();
if (p == '-') s = -1, p = getchar();
while (p >= '0' && p <= '9') {
n = (n << 3) + (n << 1) + (p - ... | ### Prompt
Generate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the foll... |
#include <bits/stdc++.h>
int main() {
int n, k;
scanf("%d%d", &n, &k);
if ((n * (n - 1) / 2) <= k) {
printf("no solution\n");
} else {
int i;
for (i = 0; i < n; i++) {
printf("0 %d\n", i);
}
}
}
| ### Prompt
Please provide a CPP coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
inline T Max(T a, T b) {
if (a > b)
return a;
else
return b;
}
template <class T>
inline T Min(T a, T b) {
if (a < b)
return a;
else
return b;
}
template <class T>
inline T gcd(T a, T b) {
if (a < 0) return gcd(-a, b);
if (b < ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
int x[2010], y[2010];
using namespace std;
int main() {
int n, k;
cin >> n >> k;
for (int i = 0; i < n; ++i) x[i] = 0, y[i] = i;
int c = 0, tot = 0;
int d = (1 << 29);
for (int i = 0; i < n; ++i) {
for (int j = i + 1; j < n; ++j) {
tot++;
int t = (x[j] - x[i]) * (x[j... | ### Prompt
Create a solution in Cpp for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
int main() {
int cn = 0, i, n, k, p;
scanf("%d%d", &n, &k);
if (k >= (n * (n - 1)) / 2) {
printf("no solution\n");
return (0);
}
p = n;
while (p--) {
printf("0 %d\n", cn);
cn++;
}
return (0);
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int n, k;
int main() {
cin >> n >> k;
int temp = n * (n - 1) / 2;
if (temp <= k) {
cout << "no solution\n";
return 0;
}
for (int i = 0; i < n; i++) {
cout << 0 << " " << i << endl;
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the f... |
#include <bits/stdc++.h>
using namespace std;
const int MAX = 2001;
int N, K;
int main() {
scanf("%d%d", &N, &K);
if (K >= N * (N - 1) / 2) {
puts("no solution");
} else {
for (int i = 0; i < N; i++) {
printf("0 %d\n", i);
}
}
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
#pragma warning(disable : 4996)
struct point {
int x, y;
};
int n, k;
int dx[2010], dy[2010];
int tot;
int sqr(int x) { return x * x; };
int imin(int a, int b) {
if (a < b) return a;
return b;
};
void algo() {
int d = 2100000000;
for (int i = 0; i < n; i++)
fo... | ### Prompt
Construct a CPP code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, i, k;
int tot;
cin >> n >> k;
tot = (n * (n - 1)) / 2;
if (tot <= k) {
cout << "no solution\n";
return 0;
}
for (i = 0; i < n; i++) {
cout << i << " " << i * 100000 << "\n";
}
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
long long n, k;
cin >> n >> k;
long long tot;
tot = (n * (n - 1)) / 2;
if (tot <= k) {
cout << "no solution";
return 0;
}
for (int i = 0; i < n; i++) cout << 0 << " " << i << endl;
return 0;
}
| ### Prompt
Your task is to create a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int l = n * (n - 1);
l /= 2;
if (k >= l) {
cout << "no solution\n";
return 0;
}
pair<int, int> p;
vector<pair<int, int> > v;
int a = 0, b = 0;
for (int i = 0; i < n; i++) {
p = make_pair(b, a);
v.push... | ### Prompt
Create a solution in CPP for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
#pragma comment(linker, "/STACK:256777216")
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (2 * k >= n * (n - 1)) {
puts("no solution");
return 0;
}
for (int i = 1; i <= n; i++) {
cout << 0 << " " << i << endl;
}
return 0;
}
| ### Prompt
Please create a solution in Cpp to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int cnt = (n * (n - 1)) / 2;
if (cnt <= k)
cout << "no solution";
else {
for (int i = 1; i <= n; i++) {
cout << 0 << ' ' << i << '\n';
}
}
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int t, n, k, ax, bx, tot;
cin >> n >> k;
tot = (n * (n + 1)) / 2 - n;
if (tot <= k)
cout << "no solution" << endl;
else {
for (int i = 1; i <= n; i++) {
cout << 0 << " " << i << endl;
}
}
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
unsigned long long mod = 1000000007;
int main() {
int nop, k;
cin >> nop >> k;
int max_possi = nop * (nop - 1);
max_possi /= 2;
if (k >= max_possi)
cout << "no solution"
<< "\n";
else {
int x = 0, y = 0;
while (nop--) cout << x << " " << y++... | ### Prompt
Develop a solution in Cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
long long distance(long long x1, long long y1, long long x2, long long y2) {
return sqrt(pow(x2 - x1, 2) + pow(y2 - y1, 2));
}
int main() {
long long n, k, d, x, y, tot = 0;
cin >> n >> k;
for (int i = 1; i <= n; i++) {
for (int j = i + 1; j <= n; j++) {
t... | ### Prompt
Construct a CPP code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) <= 2 * k)
cout << "no solution" << endl;
else
for (int y = 0; y < n; y++) {
cout << 0 << " " << y << endl;
}
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
long n, k;
int main() {
ios_base::sync_with_stdio(0);
cin >> n >> k;
if (n * (n - 1) / 2 <= k)
cout << "no solution" << endl;
else
for (int i = 0; i < n; i++) cout << 0 << " " << i << endl;
cin.get();
cin.get();
return 0;
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int x = n - 1, tot = 0;
tot = (x * (x + 1)) / 2;
if (tot <= k) return cout << "no solution" << endl, 0;
for (int i = 0; i < n; i++) cout << 1 << " " << i << endl;
return 0;
}
| ### Prompt
Create a solution in CPP for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, tot;
scanf("%d%d", &n, &tot);
if (n * (n - 1) / 2 <= tot) {
printf("no solution");
return 0;
}
for (int i = 0; i < n; i++) printf("%d %d\n", 0, i);
return 0;
}
| ### Prompt
Please provide a Cpp coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
int tot = (n) * (n - 1);
tot /= 2;
if (tot <= k)
cout << "no solution" << endl;
else {
for (int i = 0; i < n; ++i) cout << 1 << " " << i + 1 << endl;
}
}
| ### Prompt
Please create a solution in cpp to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
double distance(pair<int, int> a, pair<int, int> b) {
return pow(a.first - b.first, 2.0) + pow(a.second - b.second, 2.0);
}
int gettot(vector<pair<int, int> > v) {
sort(v.begin(), v.end());
double d = 1e100;
int tot = 0;
for (int i = 0; i < v.size(); i++) {
fo... | ### Prompt
Your task is to create a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if ((n * (n - 1)) / 2 <= k) {
cout << "no solution\n";
} else {
for (int i = 0; i < n; i++) {
cout << "0 " << i << endl;
}
}
return 0;
}
| ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, n;
long long k;
while (~scanf("%d%I64d", &n, &k)) {
long long t = (long long)n * (n - 1) / 2;
if (k >= t) {
printf("no solution\n");
continue;
}
int y = 1;
for (i = 0; i < n; i++) printf("%d %d\n", 0, y), y++;
}... | ### Prompt
Generate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the foll... |
#include <bits/stdc++.h>
using namespace std;
const int N = 105;
const int M = 505;
const int MOD = int(1e9) + 7;
const int INF = 0x3f3f3f3f;
const double EPS = 1e-9;
const double PI = acos(-1.0);
const int dx[] = {-1, 1, 0, 0};
const int dy[] = {0, 0, -1, 1};
template <class T>
inline T Min(T a, T b) {
return a < b ... | ### Prompt
Please create a solution in cpp to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k)
cout << "no solution";
else
for (int i = 0; i < n; ++i) cout << "0 " << i << endl;
return 0;
}
| ### Prompt
Please formulate a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
int main() {
int n, k, i;
scanf("%d %d", &n, &k);
if (k < n * (n - 1) / 2) {
for (i = 0; i < n; i++) printf("%d %d\n", 0, 3 * i);
} else
puts("no solution");
return 0;
}
| ### Prompt
Your task is to create a Cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n;
long long k;
cin >> n >> k;
int ans = (n * (n - 1)) / 2;
if (k >= ans) {
cout << "no solution" << endl;
return 0;
} else {
for (int i = 0; i < n; i++) {
cout << 0 << ' ' << i << endl;
}
}
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int k, n;
int main() {
int i, j;
scanf("%d%d", &n, &k);
if (k >= (n * (n - 1) / 2))
puts("no solution");
else {
for (i = 1; i <= n; ++i) printf("0 %d\n", i);
}
return 0;
}
| ### Prompt
Construct a Cpp code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
string mirror = "AHIMOTUVWXY";
string letter = "ABCDEFGHIJKLMNOPQRSTUVWXYZ";
const int mxn = 1e6 + 5;
const int mod = 1e9 + 7;
int main() {
long long n, m, i, j, k, x, y, t;
cin >> n >> k;
x = n * (n - 1) / 2;
if (x <= k) {
cout << "no solution" << endl;
} els... | ### Prompt
Please create a solution in CPP to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const int maxn = 100500;
const int infi = (1 << 30);
const long long infl = (1LL << 62);
const double eps = 1e-9;
const long long mod = 1000000007LL;
const double pi = acos(-1.0);
int n, k;
int main() {
cin >> n >> k;
if (n * (n - 1) <= k * 2) {
cout << "no solution... | ### Prompt
Please formulate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d %d", &n, &k);
if ((n * (n - 1) / 2 <= k))
printf("no solution\n");
else {
for (int i = 0; i < n; i++) printf("0 %d\n", i);
}
return 0;
}
| ### Prompt
Please formulate a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const int INF = 0x3fffffff;
const int PRIME = 999983;
const int MOD = 1000000007;
const int MULTI = 1000000007;
const long double EPS = 1e-10;
inline bool isodd(int x) { return x & 1; }
inline bool isodd(long long x) { return x & 1; }
int main(void) {
int n, k;
scanf("%... | ### Prompt
Please create a solution in cpp to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (n * (n - 1) / 2 <= k) {
return cout << "no solution", 0;
}
for (int i = 0; i < 1; i++) {
for (int j = 0; j < n; j++) {
cout << i << " " << j << endl;
}
}
return 0;
}
| ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const long long mod = 1000000007;
const double PI = 3.141592653589793238463;
const int N = 2e5 + 100;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
;
int x, k;
cin >> x >> k;
if (x * (x - 1) / 2 <= k) {
cout << "no solution\... | ### Prompt
Create a solution in CPP for the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the fo... |
#include <bits/stdc++.h>
using namespace std;
long long n, k;
int main() {
long long cnt;
while (cin >> n >> k) {
cnt = n * (n - 1) / 2;
if (cnt > k) {
for (int i = 0; i < n; i++) cout << 0 << " " << i << endl;
} else
cout << "no solution" << endl;
}
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
int i, j, k, m, n;
int main() {
while (scanf("%d %d", &n, &k) == 2) {
if (k >= n * (n - 1) / 2) {
printf("no solution\n");
continue;
}
for (i = 1; i <= n; i++) printf("0 %d\n", i);
}
return 0;
}
| ### Prompt
In cpp, your task is to solve the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the f... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
scanf("%d%d", &n, &k);
if (((n - 1) * n) / 2 <= k) {
printf("no solution\n");
} else {
int ypos = 0;
for (int i = 0; i < n; ++i) {
printf("%d %d\n", i, ypos);
ypos += (n + 1);
}
}
return 0;
}
| ### Prompt
Develop a solution in Cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const int dr[] = {-1, 0, 1, 0};
const int dc[] = {0, 1, 0, -1};
string FILE_NAME = "testcase.C";
string NAME;
string itos(int n) {
stringstream ss;
ss << n;
return ss.str();
}
int main() {
int n, k;
cin >> n >> k;
if (k >= n * (n - 1) / 2) {
cout << "no solu... | ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(0);
cout.tie(0);
int n, k;
cin >> n >> k;
if (k >= n * (n - 1) / 2)
cout << "no solution" << endl;
else
for (int i = 1; i <= n; i++) cout << 0 << " " << i << endl;
return 0;
}
| ### Prompt
Construct a CPP code solution to the problem outlined:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(false);
cin.tie(0);
int n, k;
cin >> n >> k;
if (k >= n * (n - 1) / 2) {
cout << "no solution";
return 0;
}
for (int i = 1; i <= n; i++) {
cout << 0 << ' ' << i << "\n";
}
return 0;
}
| ### Prompt
Your challenge is to write a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int i, j, k, n, m;
while (cin >> n >> k) {
if (n * (n - 1) / 2 <= k) {
puts("no solution");
} else {
for (i = 0; i < n; i++) printf("0 %d\n", i);
}
}
return 0;
}
| ### Prompt
Please formulate a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
struct A {
int x;
int y;
} p[2000];
double d;
double min(double a, double b) {
if (a > b)
return b;
else
return a;
}
double distance(int ax, int ay, int bx, int by) {
return sqrt((ax - bx) * (ax - bx) + (ay - by) * (ay - by));
}
int main() {
int i, j, n, k, tot;
scanf("%d ... | ### Prompt
In Cpp, your task is to solve the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the f... |
#include <bits/stdc++.h>
using namespace std;
int main() {
int n, k;
cin >> n >> k;
if (k >= (n * n - n) / 2)
puts("no solution");
else {
for (int i = 0; i < n; i++) cout << 0 << " " << i << endl;
}
return 0;
}
| ### Prompt
Your task is to create a cpp solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The probl... |
#include <bits/stdc++.h>
using namespace std;
using pii = pair<long long, long long>;
const long long INF = 1e18;
void dprint(string s) { cout << "\n"; }
void dprint() { cout << "\n"; }
template <class T, class... U>
void dprint(string s, T t, U... u) {
long long w = s.find(',');
cout << "[" << s.substr(0, w) << ":... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The p... |
#include <bits/stdc++.h>
using namespace std;
void OMG() { cout << "OMG>.< I don't know!\n"; }
void W1() { cout << "Freda's\n"; }
void W2() { cout << "Rainbow's\n"; }
bool ff1(string S) {
string A = "";
for (int i = 0; i < 5; i++) A += S[i];
return (A == "miao.");
}
bool ff2(string S) {
string A = "";
for (in... | ### Prompt
Please create a solution in CPP to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
const int maxN = 2005;
long long n, k, x[maxN] = {-3000}, y[maxN] = {-3000}, ans;
int main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cin >> n >> k;
for (int i = 1; i < n; i++) {
ans += i;
x[i] = x[i - 1];
y[i] = y[i - 1] - 1;
}
if (ans <= ... | ### Prompt
Develop a solution in cpp to the problem described below:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is ... |
#include <bits/stdc++.h>
using namespace std;
static const int INF = 500000000;
template <class T>
void debug(T a, T b) {
for (; a != b; ++a) cerr << *a << ' ';
cerr << endl;
}
int n, k;
int main() {
cin >> n >> k;
int maxi = n * (n - 1) / 2;
if (k >= maxi) {
puts("no solution");
return 0;
}
for (... | ### Prompt
Generate a CPP solution to the following problem:
Currently Tiny is learning Computational Geometry. When trying to solve a problem called "The Closest Pair Of Points In The Plane", he found that a code which gave a wrong time complexity got Accepted instead of Time Limit Exceeded.
The problem is the foll... |
#include <bits/stdc++.h>
using namespace std;
char s[1001];
int co[200];
int len;
struct p {
char c;
int num;
int ap;
bool operator<(const p& other) const {
int t1, t2;
t1 = num / ap;
if (double(num) / ap > t1) {
t1++;
}
t2 = other.num / other.ap;
if (double(other.num) / other.ap >... | ### Prompt
Please provide a cpp coded solution to the problem described below:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
string s;
int tedad[300];
bool possible(int t, int n) {
int len = 0;
for (int i = 'a'; i <= 'z'; i++) {
len += tedad[i] / t;
if (tedad[i] % t != 0) len++;
}
return len <= n;
}
int bs(int first, int second, int n) {
if (first == second) return first;
int ... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string a;
int n;
int freq[26] = {0};
cin >> a >> n;
for (int i = 0; i < a.length(); i++) freq[a[i] - 'a']++;
int lo = 1, hi = 1001;
int ans = -1;
while (lo <= hi) {
int mid = (lo + hi) / 2;
int need = 0;
for (int i = 0; i < 26; i++) ... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
#pragma comment(linker, "/STACK:64000000")
int j, n, l, i, h, q1, q2, x, y, m, k, t, ans, p1, p2, ans1, ans2, a[1000500],
q, d[1000500], p;
string s, z;
set<char> ss;
void init() {
cin >> s;
n = s.size();
cin >> k;
}
void solve() {
for (j = 1; j <= n; j++) {
... | ### Prompt
Please provide a CPP coded solution to the problem described below:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
string s;
int n;
int cnt[256];
bool check(int x) {
if (x == 0) return false;
int sum = 0;
for (char c = 'a'; c <= 'z'; ++c) {
int d = cnt[c] / x + !!(cnt[c] % x);
sum += d;
}
return sum <= n;
}
string get(int x) {
string t = "";
for (char c = 'a'; c <=... | ### Prompt
Generate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
int n;
string s;
cin >> s >> n;
set<char> se(s.begin(), s.end());
if ((int)se.size() > n) {
cout << "-1"
<< "\n";
} else {
string str;
map<char, int> x, y;
for (int i =... | ### Prompt
Your challenge is to write a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
set<char> st;
int a[26] = {0};
int main() {
int n;
string s;
cin >> s >> n;
for (auto c : s) {
st.insert(c);
a[c - 97]++;
}
if ((int)st.size() > n) {
printf("-1\n");
return 0;
}
for (int i = 1; i <= 1000; ++i) {
int co = 0;
for (int j... | ### Prompt
In cpp, your task is to solve the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl want... |
#include <bits/stdc++.h>
using namespace std;
template <class T>
void PV(T a, T b) {
while (a != b) cout << *a++ << " ";
cout << endl;
}
template <class T>
inline bool chmin(T &a, T b) {
return a > b ? a = b, 1 : 0;
}
template <class T>
inline bool chmax(T &a, T b) {
return a < b ? a = b, 1 : 0;
}
const int inf... | ### Prompt
Generate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
string s;
int n;
int cnt[256];
bool check(int x) {
int sum = 0;
for (char c = 'a'; c <= 'z'; ++c) {
int d = cnt[c] / x + !!(cnt[c] % x);
sum += d;
}
return sum <= n;
}
string get(int x) {
string t = "";
for (char c = 'a'; c <= 'z'; ++c) {
int d = cnt... | ### Prompt
Construct a cpp code solution to the problem outlined:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wa... |
#include <bits/stdc++.h>
using namespace std;
string S;
int N, L;
map<char, int> ch;
void read();
void solve();
bool test(int);
void howdy(int);
int main() {
read();
solve();
return 0;
}
void read() { cin >> S >> N, L = int(S.length()); }
void solve() {
for (int i = 0; i < L; ++i) ++ch[S[i]];
if (int(ch.size(... | ### Prompt
Please create a solution in Cpp to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
#include <bits/stdc++.h>
using namespace std;
int n;
string str;
map<char, int> mp;
set<char> st;
bool ok(int k) {
int rem = n - int((st).size());
for (auto it = st.begin(); it != st.end(); it++) {
char c = *it;
int r = mp[c] - k;
if (r <= 0) continue;
int need = (r + k - 1) / k;
if (need > rem)... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wa... |
#include <bits/stdc++.h>
using namespace std;
int Up(int a, int b) { return (a + b - 1) / b; }
class Type {
public:
char ch;
int number;
int k;
int value;
Type() {}
Type(char _ch, int _number) : ch(_ch), number(_number), k(0) {}
friend bool operator<(const Type& a, const Type& b) {
return a.number < ... | ### Prompt
Your challenge is to write a Cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
string s;
int c[26];
bool check(int m, string t) {}
bool solve() {
int l = 1, r = 10000;
while (l <= r) {
}
}
bool compare(pair<char, int> a, pair<char, int> b) {
return a.second > b.second;
}
int main() {
cin >> s;
int n;
cin >> n;
unordered_set<char> st;
... | ### Prompt
Please formulate a Cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
#include <bits/stdc++.h>
using namespace std;
string s;
int n;
int cnt[256];
bool check(int x) {
if (x == 0) return false;
int sum = 0;
for (char c = 'a'; c <= 'z'; ++c) {
int d = cnt[c] / x + !!(cnt[c] % x);
sum += d;
}
return sum <= n;
}
string get(int x) {
string t = "";
for (char c = 'a'; c <=... | ### Prompt
Generate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
int am[27];
int dp[27][1010];
int path[27][1010];
int call(int p, int n) {
if (p == 26) return (n == 0 ? 0 : (1 << 29));
int &ret = dp[p][n];
if (ret != -1) return ret;
int &ppp = path[p][n];
ret = (1 << 29);
if (!am[p]) {
ret = call(p + 1, n);
ppp = 0;
... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wa... |
#include <bits/stdc++.h>
using namespace std;
int a[27], c[27], d[27];
int main() {
int count, i, n, max, co, t, index, k;
char str[1010], ch, b[1010];
ch = getchar();
while (ch != '\n') {
a[ch - 'a' + 1]++;
ch = getchar();
}
count = 0;
for (i = 1; i <= 26; i++)
if (a[i] != 0) count++;
scanf... | ### Prompt
Please create a solution in cpp to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
#include <bits/stdc++.h>
using namespace std;
template <class F, class T>
T convert(F a, int p = -1) {
stringstream ss;
if (p >= 0) ss << fixed << setprecision(p);
ss << a;
T r;
ss >> r;
return r;
}
template <class T>
void db(T a, int p = -1) {
if (p >= 0) cout << fixed << setprecision(p);
cout << a << ... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
int ceil_div(int a, int b) { return (a + b - 1) / b; }
int main() {
cin.tie(0);
cout.tie(0);
ios_base::sync_with_stdio(0);
string s;
cin >> s;
int n;
cin >> n;
set<char> st(s.begin(), s.end());
if (n < st.size()) {
cout << -1 << endl;
return 0;
}... | ### Prompt
Generate a Cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
struct lett {
char let;
int nb;
int at;
};
int main() {
int values[26], offset = static_cast<int>('a'), total;
lett letts[26];
string str;
cin >> str;
for (int i = 0; i < 26; i++) {
values[i] = 0;
}
for (int i = 0; i < str.length(); i++) {
values... | ### Prompt
Create a solution in CPP for the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants... |
#include <bits/stdc++.h>
using namespace std;
const double eps = 1e-8;
int dblcmp(double d) {
if (fabs(d) < eps) return 0;
return d > eps ? 1 : -1;
}
const double PI = 3.1415926535897932384626433832795;
const double pi = acos(-1.0);
int dx[4] = {-1, 0, 1, 0};
int dy[4] = {0, -1, 0, 1};
long long pov(long long a, lo... | ### Prompt
Construct a CPP code solution to the problem outlined:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wa... |
#include <bits/stdc++.h>
using namespace std;
const int mod = 1e9 + 9;
long long gcd(long long a, long long b) {
if (b == 0) return b;
return gcd(b, a % b) + a / b;
}
int main() {
ios::sync_with_stdio(0);
cin.tie(0);
string s;
cin >> s;
int n;
cin >> n;
vector<pair<int, int>> a(26);
for (int i = 0; ... | ### Prompt
Please create a solution in Cpp to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
#include <bits/stdc++.h>
using namespace std;
int i, j, n, m, k, v[30];
string s;
int main() {
cin >> s >> n;
for (i = 0; i < s.size(); i++) v[s[i] - 'a']++;
for (k = 1; k <= s.size(); k++) {
m = 0;
for (i = 0; i < 26; i++) m += ceil(v[i] / (double)k);
if (m <= n) {
cout << k << "\n";
for ... | ### Prompt
Please formulate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
#include <bits/stdc++.h>
using namespace std;
namespace p335ABanana {
void solve(int test_num) {
int cnt[26] = {0};
string str;
int n;
cin >> str >> n;
for (int i = 0; i < (int)str.size(); i++) cnt[str[i] - 'a']++;
for (int res = 1; res <= 1000; res++) {
int need = 0;
for (int c = 0; c < 26; c++) ne... | ### Prompt
Please provide a Cpp coded solution to the problem described below:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length ... |
#include <bits/stdc++.h>
using namespace std;
int v[10001];
int main() {
string s;
int n, i, j, k, m, o, p;
cin >> s >> n;
o = s.length();
for (i = 0; i < o; i++) {
v[s[i] - 'a']++;
}
for (i = 1; i <= 1000; i++) {
string ans = "";
for (j = 0; j < 26; j++) {
if (v[j]) {
int y = (v... | ### Prompt
Generate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
string s;
int coos;
map<char, int> cnt;
string getcoos(int nos) {
string p = "";
for (auto y : cnt) {
int t = (y.second + nos - 1) / nos;
for (int j = 0; j < t; j++) p += (char)(y.first);
}
return p;
}
int main() {
cin >> s;
cin >> coos;
int n = s.size... | ### Prompt
Generate a cpp solution to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wants t... |
#include <bits/stdc++.h>
using namespace std;
int main() {
string s;
cin >> s;
long long int n;
cin >> n;
long long int size = s.length();
vector<long long int> freq(26, 0);
for (long long int i = 0; i < size; i++) {
freq[s[i] - 'a']++;
}
long long int diff = 0;
for (long long int i = 0; i < 26;... | ### Prompt
Construct a Cpp code solution to the problem outlined:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl wa... |
#include <bits/stdc++.h>
using namespace std;
signed main() {
ios_base::sync_with_stdio(false);
cin.tie(NULL);
cout.tie(NULL);
;
string s, t;
long long n, i;
cin >> s;
cin >> n;
set<pair<double, char>> m;
map<char, long long> freq, c;
for (i = 0; i < s.length(); ++i) {
freq[s[i]]++;
}
for ... | ### Prompt
Please create a solution in CPP to the following problem:
Piegirl is buying stickers for a project. Stickers come on sheets, and each sheet of stickers contains exactly n stickers. Each sticker has exactly one character printed on it, so a sheet of stickers can be described by a string of length n. Piegirl... |
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