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Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const long long mx = 2e5 + 10; set<pair<long long, long long> > ad[mx]; vector<long long> ver; long long ans[mx], l[mx], r[mx]; void dfst(long long v) { while ((long long)ad[v].size()) { long long u = ad[v].begin()->first, yal = ad[v].begin()->second; ad[v].erase(...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 10; inline long long rd() { long long x = 0, w = 1; char ch = 0; while (ch < '0' || ch > '9') { if (ch == '-') w = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') { x = (x << 3) + (x << 1) + (ch ^ 48); ch = getchar(); } ...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int maxn = 200005; inline int gi() { char c = getchar(); while (c < '0' || c > '9') c = getchar(); int sum = 0; while ('0' <= c && c <= '9') sum = sum * 10 + c - 48, c = getchar(); return sum; } int n, l[maxn], r[maxn], ans[maxn], *q[maxn], num, cnt; struct ...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int _ = 1e5 + 5; inline int read() { char ch = '!'; int z = 1, num = 0; while (ch != '-' && (ch < '0' || ch > '9')) ch = getchar(); if (ch == '-') z = -1, ch = getchar(); while (ch <= '9' && ch >= '0') num = (num << 3) + (num << 1) + ch - '0', ch = getch...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int maxn = 3e5 + 10; int n; int l[maxn]; int r[maxn]; int clr[maxn]; bool mark[maxn]; vector<int> cmp; map<int, int> compress; stack<pair<int, int>> adj[maxn]; void in(); void solve(); void dfs(int u); void out(); int main() { ios::sync_with_stdio(false); cout.tie...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; inline int read() { int ans = 0, fh = 1; char ch = getchar(); while (ch < '0' || ch > '9') { if (ch == '-') fh = -1; ch = getchar(); } while (ch >= '0' && ch <= '9') ans = ans * 10 + ch - '0', ch = getchar(); return ans * fh; } const int maxn = 4e5; int ...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int MAXN = 3e5 + 10; int n, l[MAXN], r[MAXN], sec[MAXN], sz; int ptr[MAXN]; vector<int> adj[MAXN]; short used[MAXN], cur = 1; void dfs(int v, int p = -1) { for (; ptr[v] < adj[v].size();) { int e = adj[v][ptr[v]++]; if (!used[e]) { used[e] = 1; d...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int N = 222222; int n, p[N], c[N], a, b, i; pair<int, int> s[N]; int dp(int x, int t) { if (c[x]) return c[x]; c[x] = t; dp(p[x << 1] >> 1, p[x << 1] & 1 ^ t ^ 1); dp(p[x << 1 | 1] >> 1, p[x << 1 | 1] & 1 ^ t); return t; } int main() { scanf("%d", &n); f...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
import java.io.*; import java.util.*; /** * Created by Katushka on 14.02.2021. */ public class Main { static void sortArray(long[] a, boolean rev) { Random random = new Random(); for (int i = 0; i < a.length; i++) { int randomPos = random.nextInt(a.length); long t = a[i...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int MAXN = 2e5 + 10; int n, fir[MAXN], nxt[MAXN << 1], to[MAXN << 1], ans[MAXN << 1], vis[MAXN << 1], tot = 1, d[MAXN << 1]; int d1[MAXN << 1], d2[MAXN << 1]; int l[MAXN], r[MAXN], t[MAXN << 1], cnt; void add(int u, int v) { to[++tot] = v; nxt[tot] = fir[u]; ...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> const int maxn = 1e6 + 9; int Read() { int x(0), f(1); char c = getchar(); while (c < '0' || c > '9') { if (c == '-') f = -1; c = getchar(); } while (c >= '0' && c <= '9') { x = (x << 3ll) + (x << 1ll) + c - '0'; c = getchar(); } return x * f; } struct node { int...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int maxN = 101000 * 2; const int maxM = maxN * 4; int n, m; int num, Num[maxN], L[maxN], R[maxN], Dg[maxN]; int edgecnt = -1, Hd[maxN], Nt[maxM], V[maxM], vis[maxM]; void Add_Edge(int u, int v); void dfs(int u); int main() { memset(Hd, -1, sizeof(Hd)); scanf("%d",...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; const int N = 100030; pair<int, int> l[N], r[N], tot[N * 2]; int n, cnt; vector<int> mp[N << 1]; int vis[N << 1]; int read() { char c = getchar(); int k = 0; for (; c < 48 || c > 57; c = getchar()) ; for (; c > 47 && c < 58; c = getchar()) k = (k << 3) + (k << 1...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> const int N = 400050; int l[N], r[N], num[N], nk; int n, tot; int id(int v) { int L = 1, R = nk, mid; while (L <= R) { mid = (L + R) / 2; if (num[mid] == v) return mid; if (num[mid] < v) L = mid + 1; else R = mid - 1; } } int first[2 * N], to[4 * N], next[4 * N...
Problem: Iahub isn't well prepared on geometry problems, but he heard that this year there will be a lot of geometry problems on the IOI selection camp. Scared, Iahub locked himself in the basement and started thinking of new problems of this kind. One of them is the following. Iahub wants to draw n distinct segments ...
#include <bits/stdc++.h> using namespace std; struct sweep { pair<int, int> P; int idx; }; int N, L; sweep B[2 * 100005]; vector<int> G[2 * 100005]; int color[2 * 100005]; bool qx(sweep a, sweep b) { return a.P < b.P; } void doIt(int node) { for (auto it : G[node]) if (!color[it]) color[it] = -1 * color[node]...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long q, t, n, k, d1, d2, x, y; cin >> t; while (t--) { cin >> n >> k >> d1 >> d2; q = k; k = n - k; if (k - (d1 + d2) >= 0) { x = (d1 + d2 + q) / 3; y = (q - d1 - d2) / 3; if ((k - (d1 + d2)) % 3 == 0 && (d1 + d2 + q...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long n, k, d1, d2, ave, x; int main() { int T; cin >> T; while (T--) { cin >> n >> k >> d1 >> d2; if (n % 3) { puts("no"); continue; } ave = n / 3; bool flag = false; if ((k - d1 - 2 * d2) % 3 == 0 && (k - d1 - 2 * d2) >= 0) { ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.Scanner; public class Main { public static void main(String args[]) { Scanner s=new Scanner(System.in); int t=s.nextInt(); for(int i=0;i<t;i++) { long n=s.nextLong(); long k=s.nextLong(); long d1=s.nextLong(); long ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.InputStream; import java.io.InputStreamReader; import java.io.BufferedReader; import java.io.OutputStream; import java.io.PrintWriter; import java.io.IOException; import java.util.StringTokenizer; /** * Built using CHelper plug-in * Actual solution is at the top * @author Rubanenko */ public class M...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.InputStream; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.io.PrintStream; import java.io.PrintWriter; import java.io.StreamTokenizer; public class Solution { public static void main(String[] args) throws Exception { solve(Sy...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
from sys import * t=int(stdin.readline()) for i in range(t): n,k,d1,d2=(int(z) for z in stdin.readline().split()) vars=((2*d1+d2,2*d2+d1),(2*max(d1,d2)-min(d1,d2),d1+d2)) y=False for i in vars: if i[0]<=k and i[0]%3==k%3 and n-k-i[1]>=0 and (n-i[1]-k)%3==0: print("yes") ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.Scanner; public class Sample { public static void main(String[] args) { long i,j,n,k,d1,d2,t; long n1, n2, n3; Scanner sc = new Scanner(System.in); t = sc.nextInt(); while (t-- != 0) { n = sc.nextLong(); k = sc.nextLong(); ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> int inf = 1e9 + 7; using namespace std; long long n, k, d1, d2; long long a[4]; int judge() { long long r = n - k, sum = 0; sort(a, a + 3); if (a[0] < 0) { long long ad = -a[0]; for (int i = 0; i < (3); i++) a[i] += ad; } for (int i = 0; i < (3); i++) sum += a[i]; if (sum > ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.File; import java.io.FileReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.StringTokenizer; import static java.lang.Math.*; import static java.util.Arrays.*; public class Main { public static void main(Stri...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.IOException; import java.io.OutputStreamWriter; import java.io.BufferedWriter; import java.io.OutputStream; import java.io.PrintWriter; import java.io.Writer; import java.io.InputStream; /** * Built using CHelper plug-in * Actual solution is at the top * @author Mahmoud Aladdin <aladdin3> */ public ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
t = int(input()) for l in range(t): n, k, d1, d2 = map(int, input().split()) if n % 3 != 0: print("no") continue n = n // 3 ok = False for i in [-1, 1]: for j in [-1, 1]: tmp = k; tmp -= d1 * i tmp -= d1 * i tmp -= d2 * j ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.*; import java.io.*; public class C { static void solve() { int T = in.nextInt(); outer : for (int i = 0; i < T; i++) { long n, k, d1, d2; n = in.nextLong(); k = in.nextLong(); d1 = in.nextLong(); d2 = in.nextLong(); ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
def get(k, d1, d2): x = (k + (2 * d1) + d2) if x < 0 or x % 3 != 0: return -1, -1, -1 x /= 3 y = (k + d1 + d2) - (2 * x) if y < 0: return -1, -1, -1 z = (x - d1 - d2) if z < 0: return -1, -1, -1 return x, y, z def solve(n, k, d1, d2): signs = [ (1, 1...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.Arrays; import java.util.Collection; import java.util.Locale; import java.util.PriorityQueue; import java.util.StringTokenizer; public class Main { public static void main(String[]...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int check(long long int n, long long int k, long long int d1, long long int d2) { long long int A[4] = {1, -1, -1, 1}, B[4] = {1, -1, 1, -1}, x, a, b, c, D1, D2; x = n / 3; if (n % 3 != 0) return 0; for (int i = (0); i < (4); ++i) { D1 ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> int t; long long n, k, x, y, z; int chk(long long d1, long long d2) { y = (k + d2 - d1); if (y % 3 != 0) { return 0; } y /= 3; x = y + d1; z = y - d2; if (x < 0 || y < 0 || z < 0) { return 0; } if (x > n || y > n || z > n) { return 0; } return 1; } int main() {...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.IOException; import java.io.OutputStreamWriter; import java.io.BufferedWriter; import java.util.InputMismatchException; import java.io.OutputStream; import java.io.PrintWriter; import java.util.NoSuchElementException; import java.io.Writer; import java.math.BigInteger; import java.io.InputStream; /** *...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; bool solve(int64_t n, int64_t k, int64_t d1, int64_t d2) { if (n % 3 != 0) return false; for (int i = -1; i <= 1; i++) { for (int j = -1; j <= 1; j++) { if (i == 0 || j == 0) continue; int64_t D1 = d1 * i; int64_t D2 = d2 * j; int64_t x2 = (k...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.util.*; public final class predict_outcome { static BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); static FastScanner sc=new FastScanner(br); static PrintWriter out=new PrintWriter(System.out); static boolean check(long curr1,long curr2,long curr3,long ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.Scanner; public class PredictOutcomeOfTheGame { static boolean solve(long n, long k, long d1, long d2) { if (n % 3 == 0) { long d3 = 0; long min = Math.min(Math.min(d1, d2), 0); if (min < 0) { d1 += -min; d2 += -min; d3 += -min; } long end = d1 + d2 + d3; if (k - end ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { int t; scanf("%d", &t); while (t--) { long long n, k, d1, d2; scanf("%lld%lld%lld%lld", &n, &k, &d1, &d2); if (n % 3 != 0) { cout << "no\n"; continue; } long long gamesRem = n - k; bool poss = false; for (int sign1 ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long num; long long n, k, d1, d2; bool solve() { if (n % 3) return false; long long aim = n / 3; bool res = false; if ((k + d1 + d2) % 3 == 0) { long long x2 = (k + d1 + d2) / 3; long long x1 = x2 - d1; long long x3 = x2 - d2; if (x1 <= aim && x...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long G(long long a, long long b) { if (b == 0) return a; return G(b, a % b); } int main() { int t; cin >> t; while (t--) { long long n, k, d1, d2, a, b, c, t, kk; cin >> n >> k >> d1 >> d2; kk = k - d1 - d1 - d2; if (kk >= 0 && kk % 3 == 0) { ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
t=int(input()) while(t>0): n,k,d1,d2=map(int,raw_input().split()) w1=k+2*d1+d2 f=0 p=0 if(n%3!=0): print "no" t-=1 continue if(w1%3==0 and w1>=0): w1=w1/3 w2=w1-d1 w3=w2-d2 diff=n-k ch=max(w1,w2,w3) diff-=ch-w1 diff-=ch-w2 diff-=ch-w3 # p=w1-w2 # diff-=p # p=w1-w3 # diff-=p # if(diff>=0...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.Arrays; public class PredictOutcomeOfTheGame { static long[] arr = new long[3]; public static void main(String[] args) throws IOException { BufferedReader bf = new BufferedReader(new InputStre...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.IOException; import java.util.StringTokenizer; public class PredictOutcomeOfTheGame { public static void main(String[] args) { MyScanner sc = new MyScanner(); int T = sc.nextInt(); StringBuilde...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long d1, d2; bool res(long long n, long long k, long long a, long long b, long long c) { long long maxi = max(max(a, b), c), still = (n - k) + (a + b + c); if (((a + b + c) > k) || (a < 0) || (b < 0) || (c < 0) || (n % 3 != 0) || ((k - a - b - c) % 3 != 0)) {...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long n, k, d1, d2; bool f(long long a, long long b) { long long c = k - a - b * 2; if (c < 0 || c % 3) return 0; return n / 3 >= a + b + c / 3; } int main() { int t; cin >> t; for (int i = 1; i <= t; i++) { cin >> n >> k >> d1 >> d2; if (n % 3) { ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import sys stdin = sys.stdin t = int(stdin.readline()) for icase in range(t): n, k, d1, d2 = map(int, stdin.readline().split()) found = False for dir1, dir2 in [[1, 1], [-1, -1], [-1, 1], [1, -1]]: delta1 = d1*dir1 delta2 = d2*dir2 scores = [0, delta1, delta1+delta2] offs...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
for i in range(int(input())): n, u, a, b = map(int, input().split()) if n % 3: print('no') else: if a > b: a, b = b, a p, q = a + b, 2 * b - a s, r, v = p + a, p + b, n - u t = [(p, q), (q, p), (s, r), (r, s)] print('no' if all(x > u or (x - u) % 3 or y > v or...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long t, n, k, d1, d2; bool solve(long long t1, long long t2, long long t3) { long long sum = t1 + t2 + t3; if (k < sum || (k - sum) % 3) return false; long long t = n - k - (3 * max(max(t1, t2), t3) - sum); if (t < 0 || t % 3) return false; return true; } int...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; inline void Boost() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); } long long n, k, d1, d2, T; bool solve(long long &n, long long &k, long long &d1, long long &d2) { if (n % 3 != 0) return 0; short sign, sign2; long long x1, x2, x3, dd1, dd2, v[3...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import sys from functools import lru_cache, cmp_to_key from heapq import merge, heapify, heappop, heappush from math import * from collections import defaultdict as dd, deque, Counter as C from itertools import combinations as comb, permutations as perm from bisect import bisect_left as bl, bisect_right as br, bisect f...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long t, n, k, d1, d2, a, b, c; bool make(long long n, long long k, long long d1, long long d2) { long long a, b, c; a = (k + d1 + d1 + d2) / 3; b = a - d1; c = a - d1 - d2; if (a >= b && b >= c && a >= 0 && b >= 0 && c >= 0 && a <= n / 3 && a + b + c ==...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long int t, n, k, d1, d2; cin >> t; while (t--) { cin >> n >> k >> d1 >> d2; if (n % 3 != 0) { cout << "no\n"; continue; } long long int x, y, z; y = k + d1 - d2; if (y % 3 == 0 && y >= 0 && y - d1 >= 0) { y ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; const int N = 1e5 + 10; long long n, k, d1, d2; int solve(long long d1, long long d2) { long long x, y, z; y = (k - d1 + d2) / 3; if ((k - d1 + d2) % 3 != 0) return 0; x = y + d1; z = y - d2; if (x >= 0 && x <= n / 3 && y >= 0 && y <= n / 3 && z >= 0 && z <= n /...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
from sys import * t=int(stdin.readline()) mm=0 for i in range(t): n,k,d1,d2=(int(z) for z in stdin.readline().split()) mm=2*max(d1,d2)-min(d1,d2) if (k-2*d1-d2>=0 and (k-2*d1-d2)%3==0 and n-2*d2-d1-k>=0 and (n-2*d2-d1-k)%3==0) or (k-2*d2-d1>=0 and (k-2*d2-d1)%3==0 and n-2*d1-d2-k>=0 and (n-2*d1-d2-k)%3==0)...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int calc(long long n, long long k, long long a1, long long a2, long long a3) { long long sum; if (a2 < a3) { swap(a2, a3); } if (a1 < a2) { swap(a1, a2); } if (a2 < a3) { swap(a2, a3); } if (a1 < 0 || a2 < 0 || a3 < 0) { return 0; } sum =...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long int t; scanf("%lld", &t); while (t--) { long long int n, k, d1, d2, x, y, z; scanf("%lld", &n); scanf("%lld", &k); scanf("%lld", &d1); scanf("%lld", &d2); x = (k + 2 * d1 + d2) / 3; y = x - d1; z = y - d2; if ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.math.*; import java.util.*; public class Main{ FastScanner in; PrintWriter out; public void solve() { int t = in.nextInt(); while (t --> 0) { long n = in.nextLong(); long k = in.nextLong(); long d1 = in.nextLong(); ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
def f1(d1, d2, n, k): a1 = 2 * d1 + d2 + k a2 = -d1 + d2 + k a3 = -d1 - (2 * d2) + k if (a1 < 0 or a2 < 0 or a3 < 0 or a1 % 3 or a2 % 3 or a2 % 3): return False else: a1 //= 3 a2 //= 3 a3 //= 3 a1, a2, a3 = tuple(sorted([a1, a2, a3])[::-1]) if (a2 - a...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; public class CR258_predict_outcome_of_the_game { public static void main(String... args) throws IOException { MyScanner sc = new MyScanner(); int t = sc.nextInt(); ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long T, n, k, d1, d2, x, y, z; scanf("%lld", &T); while (T--) { scanf("%lld%lld%lld%lld", &n, &k, &d1, &d2); int flag = 0; if ((k - d1 - d2) % 3 == 0 && k - d1 - d2 >= 0) { y = (k - d1 - d2) / 3; x = y + d1; z = y + d2; ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
for i in range(int(input())): n, k, d1, d2 = map(int, input().split()) flag = True if flag: c = (k - d1 - 2*d2)//3 b = c + d2 a = b + d1 if a >= 0 and b >= 0 and c >= 0 and k == a + b + c: v = [a, b, c] v.sort(reverse=True) if n-k >= v[0...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedReader; import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStreamReader; import java.io.OutputStreamWriter; import java.io.PrintWriter; import java.util.Arrays; import java.util.StringTokenizer; public class C { static StringTokenizer st; static BufferedRead...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int t; long long n, k, d1, d2; long long A, W; long long add1, add2, add3; bool moze; bool try1() { A = k - d1 - d2 - d2; if (A % 3 != 0 || A < 0) return false; A /= 3; if (A + d1 + d2 > W) return false; if (A + d2 > W) return false; if (A > W) return false; a...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long a[10], b[10]; int main() { long long t, n, k, d1, d2; scanf("%I64d", &t); for (int i = 1; i <= t; i++) { scanf("%I64d%I64d%I64d%I64d", &n, &k, &d1, &d2); if (d1 > d2) { swap(d1, d2); } a[1] = d1 * 2 + d2; a[2] = d1 + d2 * 2; a[3...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
from sys import stdin rints = lambda: [int(x) for x in stdin.readline().split()] out = [] for _ in range(int(input())): n, k, d1, d2 = rints() cases, ans = [[d1, 0, d2], [0, d1, d1 + d2], [d2 + d1, d2, 0]], 'no' if d1 >= d2: cases.append([0, d1, d1 - d2]) if d2 >= d1: cases.append([d2 ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> bool solve(long long k, long long y, long long z, long long &x1, long long &x2, long long &x3) { if ((k - y - 2 * z) % 3 != 0) return (false); x3 = (k - y - 2 * z) / 3; x2 = x3 + z; x1 = x2 + y; return (x1 >= 0 && x2 >= 0 && x3 >= 0); } bool canwin(long long n, long long x1...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; const int INF = (1 << 30) - 1; const int mod = 1000000007; const int maxn = 1000005; int flag; long long n, k, d1, d2; void f(long long a, long long b, long long c) { if (n % 3 || a % 3 || b % 3 || c % 3) { flag = 0; return; } long long ans = n / 3; a = a / ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.util.*; import java.math.*; //import java.util.logging.Level; //import java.util.logging.Logger; public class Main { BufferedReader read; BufferedWriter write; public static void main(String args[]) throws Exception { new Main().init("1"); } void ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; bool checking(long long x, long long y, long long z, long long n, long long k) { if (x < 0 || y < 0 || z < 0) return false; if ((x + y + z + n - k) % 3) return false; else { long long q = (x + y + z + n - k) / 3; if (q >= x && q >= y && q >= z) retur...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.*; import java.io.*; public class Task3 { private FastScanner in; private PrintWriter out; public Task3(InputStream in, OutputStream out) { this.in = new FastScanner(in); this.out = new PrintWriter(out); } public boolean canBe(long n, long k, long d1,...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; bool check(long long n, long long k, long long d1, long long d2) { long long b = k; long long a = b - d1; long long c = b + d2; long long sum = a + b + c; if (sum % 3 != k % 3) { return false; } a -= (sum - k) / 3; b -= (sum - k) / 3; c -= (sum - k) / ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
t = int(input()) for _ in range(t): n, k, d1, d2 = map(int, input().split()) if n % 3 != 0: print("no") continue n = n // 3 ok = False for i in [-1, 1]: for j in [-1, 1]: tmp = k; tmp -= d1 * i tmp -= d1 * i tmp -= d2 * j ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import static java.util.Arrays.deepToString; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.ArrayList; import java.util.Arrays; import java.util.HashMap; import java.util.List; import java.util.Map; import java.util.Scanner; im...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.InputMismatchException; import java.math.BigInteger; import java.io.*; /** * Generated by Contest helper plug-in * Actual solution is at the bottom */ public class Main { public static void main(String[] args) { InputReader in = new StreamInputReader(System.in); PrintWriter out = new PrintWri...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.*; public class GameOutcome { private static class Case { long n, k, d1, d2; public Case(long n, long k, long d1, long d2) { this.n = n; this.k = k; this.d1 = d1; this.d2 = d2; } } public static void main(String[] args) { Scanner s = new Scanner(System.in); int t = s.nextI...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long n, k, d1, d2; long long valid(long long w1, long long w2, long long w3) { if (w1 < 0 || w2 < 0 || w3 < 0) { return 0; } if (w1 + w2 + w3 != k) { return 0; } if (n % 3 != 0) { return 0; } long long d = n / 3; if (w1 > d || w2 > d || w3 >...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; void FastIO() { ios_base::sync_with_stdio(0); cin.tie(NULL); cout.tie(NULL); } int64_t modpow(int64_t a, int64_t p, int64_t mod) { int64_t ret = 1; while (p) { if (p & 1) ret = (ret * a) % mod; a = (a * a) % mod; p /= 2; } return ret; } int64_t pow...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedWriter; import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.io.OutputStreamWriter; import java.io.PrintWriter; import java.io.Writer; import java.util.InputMismatchException; /** * * @author jigsaw */ public class Main { /** * @param arg...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.math.*; import java.util.*; public class A { final static int MOD = 1000000007; public static void main(String[] args) throws Exception { FastReader in = new FastReader(System.in); int t = in.nextInt(); while (t-- > 0) { long n = in.nextLong(); long k = in.nextLong(); long d1 ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.InputMismatchException; import java.io.IOException; import java.io.InputStream; /** * Built using CHelper plug-in * Actual solution is at the top * * @author cunbidun */ public class M...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
rIn = lambda: raw_input().strip() def verdict(k, d1, d2, n): a = k+2*d1+d2 if a % 3: return False a /= 3 b = a-d1 c = b-d2 if a < 0 or b < 0 or c < 0: return False avg = n/3 return True if a <= avg and b <= avg and c <= avg else False T = int(rIn()) for t in xrange(T): n, k, d1, d2 = map(int, rIn()...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import itertools import sys ''' w1 - w2 = d1 w2 - w3 = d2 w1 + w2 + w3 = k w1 = w2 + d1 w3 = w2 - d2 w2 + d1 + w2 + w2 - d2 = k w2 = (k - d1 + d2) / 3 w1 = w2 + d1 w3 = w2 - d2 ''' for _ in range(int(input())): n, k, d1, d2 = map(int, str.split(sys.stdin.readline())) for s1, s2 in itertools.product((1, -1)...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; struct comp { bool operator()(const pair<int, int> &a, const pair<int, int> &b) { return a.second > b.second; } }; struct myclass { bool operator()(const pair<int, int> &a, const pair<int, int> &b) { return a.first > b.first; } } myobject; inline void in(int...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.util.*; public class A implements Runnable { private static final boolean ONLINE_JUDGE = System.getProperty("ONLINE_JUDGE") != null; private BufferedReader in; private PrintWriter out; private StringTokenizer tok = new StringTokenizer(""); private void init() throws...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.BufferedInputStream; import java.io.IOException; import java.io.PrintWriter; import java.util.ArrayDeque; import java.util.ArrayList; import java.util.Arrays; import java.util.Comparator; import java.util.Deque; import java.util.HashSet; import java.util.InputMismatchException; import java.util.Set; pub...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long n, k, d1, d2; int t; scanf("%d", &t); while (t--) { cin >> n >> k >> d1 >> d2; long long left = n - k; long long d = d1 + 2 * d2; long long twins = d1 + d1 + d2; if (d <= left && twins <= k && (k - twins) % 3 == 0) { ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { long long T, n, k, a, b; cin >> T; while (T--) { cin >> n >> k >> a >> b; n -= k; bool flag = 0; if (a < b) swap(a, b); if ((2 * a + b) <= n && (n - 2 * a - b) % 3 == 0 && (2 * b + a) <= k && (k - 2 * b - a) % 3 == 0) fla...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; const double pi = acos(-1.0); const double eps = 1e-11; const int INFINITE = 0x3f3f3f3f; template <class T> inline void checkmin(T &a, T b) { if (b < a) a = b; } template <class T> inline void checkmax(T &a, T b) { if (b > a) a = b; } template <class T> inline T sqr(T x...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
def checksituation(x1, x2, n, k, d1, d2): q = (k + x1*d1 + x2*d2) if q % 3 != 0: return False t2 = q / 3 t1 = t2 - x1*d1 t3 = t2 - x2*d2 if t1 >= 0 and t2 >= 0 and t3 >= 0 and t1 <= k and t2 <= k and t3 <= k and (t1 + t2 + t3 == k): needed = n / 3 if t1 <= needed and t2 <...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
t = int(raw_input()) def check(a, b, c, n, k): # print a, b, c val = min(a, b, c) if val < 0: a += -val b += -val c += -val # print a, b, c s = a + b + c if k < s: return False if (k-s) % 3 != 0: return False games = n - k if (games+s) % 3 == 0:...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; bool cond(long long num, long long lim) { if (num <= lim && num >= 0 && num % 3 == 0) return true; return false; } int main() { int t; scanf("%d", &t); while (t--) { long long n, x, y, z, a, b, c; bool ans = false; cin >> n >> x >> y >> z; if (n % ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
from sys import stdin rints = lambda: [int(x) for x in stdin.readline().split()] out, n = [], int(input()) inputs = [rints() for _ in range(n)] for n, k, d1, d2 in inputs: cases, ans = [[d1, 0, d2], [0, d1, d1 + d2], [d2 + d1, d2, 0]], 'no' if d1 >= d2: cases.append([0, d1, d1 - d2]) if d2 >= d1:...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int check(long long n, long long k, long long d1, long long d2) { return (k - d1 - d2 - d2) >= 0 && (k - d1 - d2 - d2) % 3 == 0 && (n - k - d1 - d1 - d2) >= 0 && (n - k - d1 - d1 - d2) % 3 == 0; } int main() { int ca; long long n, k, d1, d2; while (~scanf("...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
from sys import stdin def getint(): return int(stdin.readline()) def getints(): return tuple([int(z) for z in stdin.readline().split()]) def f((n,k,d1,d2)): p = [[0,z,z+t] for z in [d1,-d1] for t in [d2,-d2]] p = [[i-min(v) for i in v] for v in p] p = [v for v in p if sum(v) <= k and ((k % 3) == ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; const int LIM = 100005; int main(int argc, char* argv[]) { long long T, n, k, d1, d2, t1, t2, t3; long long m; int r; bool flag; cin >> T; while (T-- > 0LL) { cin >> n >> k >> d1 >> d2; if (n % 3 != 0) { printf("no\n"); continue; } m ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; int main() { int t; scanf("%d", &t); for (int i = 0; i < t; i++) { long long n, k, d1, d2; long long x1, x2, x3, av; bool tag = false; cin >> n >> k >> d1 >> d2; if (n % 3) { printf("no\n"); continue; } av = n / 3; if ((2 * ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> #pragma comment(linker, "/STACK:100000000000000") using namespace std; const long long int INF = 2e9 + 1; int main() { int T; cin >> T; for (int(Q) = 0; (Q) < (T); (Q)++) { long long int n, k, d1, d2; cin >> n >> k >> d1 >> d2; bool can = false; for (int(i) = 0; (i) < (2);...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.io.*; import java.math.*; import java.util.*; public class Main { static long mod=((long)1e9)+7;//toString public static int gcd(int a,int b){if(b==0)return a;else return gcd(b,a%b);} public static long pow_mod(long x,long y){long res=1;x=x%mod;while(y > 0){if((y & 1)==1)res=(res * x)%mod;y=y>>1...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long n, k, d1, d2; bool isok(long long d1, long long d2) { long long x, y, z; if (k - 2 * d2 - d1 < 0) return false; if ((k - 2 * d2 - d1) % 3) return false; z = (k - 2 * d2 - d1) / 3; y = d2 + z; x = d1 + y; if (x < 0 || y < 0) return false; long long ...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; bool check(long long n, long long k, long long d1, long long d2) { if (n % 3) return 0; long long win = n / 3; for (long long sgn1 = -1; sgn1 <= 1; sgn1++) { for (long long sgn2 = -1; sgn2 <= 1; sgn2++) { if (sgn1 == 0 || sgn2 == 0) continue; long long...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
import java.util.Scanner; public class T451C { private boolean getres(long n, long k, long d1, long d2) { if (n % 3 != 0) return false; long div = n / 3; long x1, x2, x3; if ((2 * d1 + k + d2) % 3 != 0) return false; x1 = (2 * d1 + k + d2) / 3; x2 = x1 - d1; x3 = x2 - d2; if (x1 < 0...
Problem: There are n games in a football tournament. Three teams are participating in it. Currently k games had already been played. You are an avid football fan, but recently you missed the whole k games. Fortunately, you remember a guess of your friend for these k games. Your friend did not tell exact number of win...
#include <bits/stdc++.h> using namespace std; long long n, k, d1, d2; bool Possibility(long long n, long long k, long long d1, long long d2) { if (n % 3) return false; if (d1 + d2 > k) return false; if (n - k - 3 * max(d1, d2) + d1 + d2 < 0) return false; if ((n - k - 3 * max(d1, d2) + d1 + d2) % 3 > 0) return ...