prompt
string
response
string
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.io.*; public class Main { static final int M = 1000000007; static FastReader in = new FastReader(); // static PrintWriter out = new PrintWriter(System.out); // static Scanner in = new Scanner(System.in); // File file = new File("input.txt"); // Scanner in = new Scanner(file); // Prin...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from collections import deque import sys def input(): return sys.stdin.readline().rstrip() for _ in range(int(input())): h, c, t = list(map(int, input().split())) if (2 * t == c + h): print(2) continue base = abs(h - c) // abs(2*t - c - h) ans = 0 d = 2e18 for i in range(bas...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from math import floor, ceil from fractions import Fraction as F T = int(input()) for _ in range(T): H, C, O = map(int, input().split()) if H == C or O >= H: print(1) elif O <= (H+C)/2: print(2) else: x = F((O-C),(H-C)) N = F((x-1),(1-2*x)) low = floor(N) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; const long long N = 1e6 + 5; const long long INF = 1e17 + 7; const long long mod = 1e9 + 7; int main() { long long t; cin >> t; while (t--) { double h, c, t; cin >> h >> c >> t; double k = (h + c) / 2; if (t <= k) { cout << 2 << "\n"; } else ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; double h, c, t; inline double avg(long long m) { return (m * h + (m - 1) * c) / (2 * m - 1); } int32_t main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long tc; cin >> tc; while (tc--) { cin >> h >> c >> t; if (t == h) { cout << "1\n...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; bool comp(const pair<int, int> &a, const pair<int, int> &b) { if (a.first == b.first) return a.second < b.second; return a.first < b.first; } bool comps(const pair<int, int> &a, const pair<int, int> &b) { if (a.second == b.second) return a.first < b.first; return a....
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Main { public static void main(String[] args) throws Exception { Scanner sc = new Scanner(System.in); PrintWriter out = new PrintWriter(System.out) ; int T = sc.nextInt() ; while (T-->0) { long h = sc.nex...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import os import sys if os.path.exists('/mnt/c/Users/Square/square/codeforces'): _f = iter(open('C.txt').readlines()) def input(): return next(_f) # input = lambda: sys.stdin.readline().strip() else: input = lambda: sys.stdin.readline().strip() fprint = lambda *args: print(*args, flush=True) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from fractions import Fraction as frac import sys, os input = sys.stdin.buffer.read().split(b'\n')[::-1].pop from heapq import heappush, heappop def i(): return input() def ii(): return int(input()) def iis(): return map(int, input().split()) def liis(): return list(map(int, input().split())) def pint(x): os.wri...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
for _ in range(int(input())): h, c, t = map(int, input().split()) n = 0 ct = 0 if h == t: print(1) elif t <= (h+c)//2: print(2) else: t -= (h+c)/2 t1 = ((h-c)/2)/t x1 = int(((t1-1)//2)*2+1) x2 = int(((t1+1)//2)*2+1) if (h-c)/(x1*2)-t <= t - (h-c)/(x2*2): ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
# Template 1.0 from decimal import * import sys, re, math from collections import deque, defaultdict, Counter, OrderedDict from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, gcd, floor from heapq import heappush, heappop, heapify, nlargest, nsmallest def STR(): return list(input()) def INT(): return ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.BufferedReader; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.FileOutputStream; import java.io.InputStreamReader; import java.io.PrintWriter; import java.math.BigInteger; import java.util.ArrayList; import java.util.Arrays; import java.util.BitS...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin, exit import fractions input = stdin.readline def i(): return input() def ii(): return int(input()) def iis(): return map(int, input().split()) def liis(): return list(map(int, input().split())) def print_array(a): print(" ".join(map(str, a))) def eq(x): return F((h*x + c*(x-1)),(x+x-1)) def ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
for _ in range(int(input())): h,c,t = map(int,input().split()) if(h==t):print(1) else: if(((h+c)/2) >= t):print(2) else: dif=(t-((h+c)/2));j=int(abs((c-h)//(2*dif))) if(j%2==0):j+=1 print(j-2) if(dif-(h-c)/(2*j)>=abs(dif-(h-c)/(2*(j-2)))) else print(j) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys from fractions import Fraction as f t = int(input()) for _ in range(t): h, c, t = [int(x) for x in input().split()] if h == t: print(1) continue x = (h + c) / 2 if x == t: print(2) continue y = (t - h) / ((h + c) - 2 * t) if y < 0: print(2) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.Scanner; public class MixingWater { public static void main(String args[]) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); for(int i=0; i<n; i++) { int hot=sc.nextInt(); int cold=sc.nextInt(); int goal=sc.nextInt(); if(goal<=(hot+cold)/2) { System.out.println(...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import math t = int(input()) for i in range(0, t): h, c, d = map(int, input().split(' ')) if d <= (h + c) / 2: print(2) else: ex = (h-d) // (2*d-h-c) if abs((ex * (h+c) + h) - d * (2*ex+1)) * (2*ex+3) <= abs((ex+1) * (h+c) + h - d * (2*ex+3)) * (2*ex+1): print(2*ex+1) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.net.ConnectException; import java.rmi.dgc.Lease; import java.util.ArrayDeque; import java.util.ArrayList; import java.util.Arrays; import java.util.Collections; import java.util.Deque; import java.util.HashMap; import java.u...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.io.*; public class C { public static void main(String[] args) throws IOException{ BufferedReader f = new BufferedReader(new InputStreamReader(System.in)); PrintWriter out = new PrintWriter(new OutputStreamWriter(System.out)); int t = Integer.parseInt(f.readLi...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; void solve() { int h, c, t; cin >> h >> c >> t; if ((h + c) / 2 >= t) { cout << 2 << '\n'; return; } int a = h - t; int b = 2 * t - h - c; int k = 2 * (a / b) + 1; long long val1 = abs(k / 2 * 1ll * c + (k + 1) / 2 * 1ll * h - t * 1ll * k); long lo...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; const long long Mod = 1e9 + 7; const int N = 1000; int main() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int numCases = 1; cin >> numCases; for (int caseNo = 1; caseNo <= numCases; caseNo++) { long long h, c, t; cin >> h >> c >> t; ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
# cook your dish here import math def bs(H, C, res): lo = 0 hi = 10**12 ans = 0 while(lo<=hi): mid = (lo + hi)//2 if (H*(mid+1) + ((mid)*C)) >= res*((2*mid) + 1): lo = mid + 1 ans = mid else: hi = mid - 1 return ans def main(): for q...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import bisect import heapq import math import collections import sys import copy from functools import reduce import decimal from io import BytesIO, IOBase import os import itertools sys.setrecursionlimit(10 ** 9) decimal.getcontext().rounding = decimal.ROUND_HALF_UP graphDict = collections.defaultdict queue = colle...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.util.StringTokenizer; import java.io.IOException; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.InputStream; /** * Built using CHelper plug-in * Actual soluti...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; using ll = long long; double h, c, t; double f(ll i) { return (ll((i + 1) / 2) * h + ll(i / 2) * c) / (double)i; } void solve() { cin >> h >> c >> t; if (t >= h) { cout << 1 << endl; return; } if (t <= (h + c) / 2) { cout << 2 << endl; return; } ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
for case in range(int(input())): a = input().split(' ') h = int(a[0]) c = int(a[1]) t = int(a[2]) avg = (h + c) / 2 if t < avg : ans = 2 elif t == avg: ans = 2 elif t == h: ans = 1 elif h > t > avg: diff = t - avg v = (h-avg) // diff if...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys import decimal as dc dc.getcontext().prec = 18 readline = sys.stdin.readline readlines = sys.stdin.readlines ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) prn = lambda x: print(*x, sep='\n') d...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; void solve() { double a, b, c; cin >> a >> b >> c; double x = (a + b) - c - c; double y = -c + b; x = abs(x); y = abs(y); double hihi = abs(c - ((a + b) / 2.0)); double haha = abs(c - (max(ceil(y / x), 1.0) * a + (max(ceil(y / x), 1.0) - 1) * b) / ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from fractions import Fraction T = int(input()) def TMP(h, c, nbH): return c + Fraction(nbH, 2*nbH-1) * (h-c) for _ in range(T): h, c, t = [int(_) for _ in input().split()] if t <= (h+c)//2: print(2) continue L, R = 1, 10**9 a = 0 while L <= R: m = (L+R)//2 t...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; const int inf = 0x7FFFFFFF; const long long mod = (0 ? 1000000007 : 998244353); const double eps = 1e-7; const long long llinf = 4223372036854775807; inline void out(long long a) { if (a) cout << "Yes" << endl; else cout << "No" << endl; } void work() { double...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; void solve() { float h, c, t; cin >> h >> c >> t; if (t >= h) { cout << "1\n"; return; } else if (2 * t <= (h + c)) { cout << "2\n"; return; } else { int val = (h - t) / (2 * t - h - c); float t1 = ((val + 1) * h + val * c) / (2 * val + 1);...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { Scanner sc=new Scanner(System.in); // BufferedReader br=new BufferedReader(new InputStreamReader(System.in)); int T=1; T=sc.nextInt(); // int t=Inte...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.OutputStream; import java.io.IOException; import java.io.InputStream; import java.io.PrintWriter; import java.io.IOException; import java.io.InputStreamReader; import java.util.StringTokenizer; import java.math.BigInteger; import java.io.BufferedReader; import java.io.InputStream; /** * Built using CHe...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
t = int(input()) for i in range(t): h,c,t = map(int,input().split()) x = t - (h+c)/2 if x <= 0: print(2) else: n = (h-c)//(2*t - h - c) if n%2 == 0: if abs(x - (h-c)/(2*(n+1))) > abs(x - (h-c)/(2*(n+3))): print(n+3) else: pr...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { ios_base::sync_with_stdio(false); cin.tie(0); cout.tie(0); long long tst, h, c, t; cin >> tst; while (tst--) { cin >> h >> c >> t; if (t <= (h + c) / 2) cout << 2 << '\n'; else { long long t1 = (long long)ceil((h - t) / ((2 *...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { int t; cin >> t; while (t--) { int h, c, t; cin >> h >> c >> t; long long res1 = 0, res2 = 0; if (h + c - 2 * t >= 0) cout << 2 << endl; else { int a = h - t; int b = 2 * t - c - h; int k = 2 * (a / b) + 1; ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.lang.*; import java.io.*; import java.awt.Point; // U KNOW THAT IF THIS DAY WILL BE URS THEN NO ONE CAN DEFEAT U HERE................ // ASCII = 48 + i ;// 2^28 = 268,435,456 > 2* 10^8 // log 10 base 2 = 3.3219 // odd:: (x^2+1)/2 , (x^2-1)/2 ; x>=3// even:: (x^2/4)+1 ,(x^2/4)-1 x >=...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.lang.*; import java.io.*; public class Main { public static void main (String[] args) throws java.lang.Exception { Scanner sc = new Scanner(System.in); int test = sc.nextInt(); while(test-->0) { long h = sc.nextLong(); long c = sc.nextLong(); long t = sc...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from decimal import * T = int(input()) def ctemp(x): return (h*(x+1)+c*x)/(2*x+1) def ctemp2(x): return (h*(x+1)+c*x)/(2*x+1) for _ in range(T): h,c,t = map(int,input().split()) now = abs((h+c)/2-t) if (h+c)/2 >= t: print(2) else: l = 0 r = h while r > l + 1: ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin, gettrace from fractions import Fraction if not gettrace(): def input(): return next(stdin)[:-1] # def input(): # return stdin.buffer.readline() def main(): def solve(): h,c,t = map(int, input().split()) if t <= (h+c)/2: print(2) retu...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(0); cin.tie(0); int t; cin >> t; while (t--) { double h, c, x; cin >> h >> c >> x; double lw = (h + c) / 2.0; if (x <= lw) { cout << 2 << '\n'; continue; } int l = -1, r = h; int mn = 0; ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.BufferedReader; import java.io.File; import java.io.FileNotFoundException; import java.io.FileReader; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter; import java.util.Arrays; public class C { // change to name String nameIn = getClass().getSimpleName() + ".i...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys input = sys.stdin.buffer.readline def print(val): sys.stdout.write(str(val) + '\n') for _ in range(int(input())): h, c, t = map(int, input().split()) if h <= t: print(1) elif (h + c) // 2 >= t: print(2) else: n_c = (h - t) // (2 * t - h - c) n_h = n_c ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys if sys.subversion[0] == "PyPy": import io, atexit sys.stdout = io.BytesIO() atexit.register(lambda: sys.__stdout__.write(sys.stdout.getvalue())) sys.stdin = io.BytesIO(sys.stdin.read()) input = lambda: sys.stdin.readline().rstrip() RS = raw_input RI = lambda x=int: map(x,RS().split...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#!/usr/bin/env python from __future__ import division, print_function import os import sys from io import BytesIO, IOBase from fractions import Fraction if sys.version_info[0] < 3: from __builtin__ import xrange as range from future_builtins import ascii, filter, hex, map, oct, zip def oddVal(i, h, c): ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import bisect import decimal import os from collections import Counter import bisect from collections import defaultdict import math import random import heapq from math import sqrt import sys from functools import reduce, cmp_to_key from collections import deque import threading from itertools import combinations fro...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
# | # _` | __ \ _` | __| _ \ __ \ _` | _` | # ( | | | ( | ( ( | | | ( | ( | # \__,_| _| _| \__,_| \___| \___/ _| _| \__,_| \__,_| import sys import math import operator as op from functools import reduce from sys import maxsize ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Codeforces { public static void main(String args[])throws Exception { BufferedReader bu=new BufferedReader(new InputStreamReader(System.in)); StringBuilder sb=new StringBuilder(); int t=Integer.parseInt(bu.readLine()); while(t--...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.io.InputStream; import java.io.InputStreamReader; import java.io.PrintWriter; import java.math.BigInteger; import java.util.ArrayList; import java.util.Arrays; import java.util.HashMap; import java.util.HashSet; import...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.io.*; public class poker{ public static void main(String []args) throws Exception{ BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); int trials = Integer.parseInt(br.readLine()); for(int trial = 0; trial < trials; trial++){ ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
try: for _ in range(int(input())): h,c,t=map(int,input().split()) if h<=t: print(1) elif h+c>=2*t: print(2) else: x=int((c-t)/(h+c-2*t)) m=abs((x*(h+c-2*t)+t-c)/(2*x-1)) n=abs(((x+1)*(h+c-2*t)+t-c)/(2*(x+1)-1)) i...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int q; cin >> q; while (q--) { double t, h, c; cin >> h >> c >> t; if (h == t) { cout << 1 << '\n'; } else if (h + c == 2 * t) { cout << 2 << '\n'; } else { ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.Scanner; public class MixingWater { public static void main(String args[]) { Scanner sc=new Scanner(System.in); int n=sc.nextInt(); for(int i=0; i<n; i++) { int hot=sc.nextInt(); int cold=sc.nextInt(); int goal=sc.nextInt(); if(goal<=(hot+cold)/2) { System.out.println(...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
def read_int(): return int(input()) def read_ints(): return map(int, input().split(' ')) tt = read_int() for case_num in range(tt): h, c, t = read_ints() if 2 * t <= h + c: print(2) continue l = 1 r = int(1e7) def calc(x): return x * h + (x - 1) * c while l <= r: ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
//package cc; import java.util.*; public class Test { static int caly(int h,int c,int t) { int ret; ret=(h-t)/(2*t-h-c); return ret; } public static void main(String [] arsg) { Scanner s=new Scanner(System.in); int t=s.nextInt(); //Random r=new Random(); while(t-->0) { int h=s.nextInt(); int c=s.nextInt(); int te...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; void __print(int x) { cerr << x; } void __print(long x) { cerr << x; } void __print(long long int x) { cerr << x; } void __print(unsigned x) { cerr << x; } void __print(unsigned long x) { cerr << x; } void __print(unsigned long long x) { cerr << x; } void __print(float x) {...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; long long int power(long long int x, long long int n, long long int m) { long long int res = 1; while (n > 0) { if (n & 1) res = (res * x) % m; x = (x * x) % m; n = n >> 1; } return res; } long long int maxSubsetSum(vector<long long int> v) { long long...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys from collections import defaultdict from copy import copy from fractions import Fraction as FR R = lambda t = int: t(input()) RL = lambda t = int: [t(x) for x in input().split()] RLL = lambda n, t = int: [RL(t) for _ in range(n)] def solve(): h, c, t = RL() P = [(FR(abs(h - t)), 1), (abs(FR((h + ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from decimal import * cases = int(input()) def get_delta(h, t, x): return h * (1 + x) / (1 + 2*x) - t for _ in range(cases): h, c, t = [int(x) for x in input().split()] if t <= (h + c) / 2: print(2) continue # h = Decimal(h - c) # t = Decimal(t - c) h = h - c t = t - c x = 0 delta = get_delta(h, t, x) w...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys input = sys.stdin.readline """ infinite water: h = hot water c = cold water (c < h) """ from decimal import Decimal from math import floor, ceil def calc_temp(cups, h, c): # cups = total cups if cups <= 0: return 0 if cups % 2 == 0: return ((h * (cups/2) + c * (cups/2))) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from collections import Counter import math import sys from bisect import bisect,bisect_left,bisect_right def input(): return sys.stdin.readline().strip() def INT(): return int(input()) def MAP(): return map(int, input().split()) def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)] def mod()...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.lang.*; import java.io.*; public class Main { static class FastReader { BufferedReader br; StringTokenizer st; public FastReader() { br = new BufferedReader(new InputStreamReader(System.in)); } ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin, stdout # 30, 10, 20 # (30x + 10y) / (x + y) = 20 # x = y || x = y+1 # 40x / 2x = 20 # (30x + 10x - 10) / (2x - 1) = 20 # (10x + 30x - 30) / (2x - 1) = 20 # (40x - 10) / (2x - 1) # 40x/(2x-1) - 10/(2x-1) # 40x/(2x-1) - 30/(2x-1) # (30x + 10(x - 1)) / (2x - 1) def mixing_water(h, c, t): r...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Solution { public static void main(String args[]) throws IOException { InOut inout = new InOut(); Resolver resolver = new Resolver(inout); resolver.solve(); inout.flush(); } private static class Resolver { final l...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { long long tt; cin >> tt; label: while (tt--) { long long h, c, t; cin >> h >> c >> t; if (h == t) { cout << 1 << "\n"; goto label; } long long x; long double answer; long long ans; if (double(h - t) <= abs((h + ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.InputStream; import java.io.PrintStream; import java.math.BigDecimal; import java.math.MathContext; import java.util.Scanner; public class Problem1359C { private static long solveSingle(int h, int c, int t) { if (t <= (h + c) / 2) return 2; long hotN = (t - c) / (2 * t ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
def solve(): h, c, t = [int(x) for x in input().split()] if h == c: print(1) elif t >= h: print(1) elif 2 * t <= h + c: print(2) else: ans = (h - c) // (2 * t - h - c) if ans % 2 == 0: ans += 1 variants = [] variants.append(ans) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Test { public static void main(String[] args) { FastScanner in = new FastScanner(); // Scanner in = new Scanner(System.in); PrintWriter out = new PrintWriter(System.out); int T = in.nextInt(); int h, c, t, x, y, minx; ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Main { private static final boolean N_CASE = true; private void solve() { int h = sc.nextInt(); int c = sc.nextInt(); int t = sc.nextInt(); long left = 0, right = Integer.MAX_VALUE; while (left <= right) { ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
t = int(input()) for _ in range(t): h, c, g = [int(x) for x in input().split()] av = (h + c)/2 if g == h: print(1) elif g <= av + 0.001: print(2) else: # after 2n+1 pours (n = 0, 1, ...) we have a temp of ((n+1)*h + n*c)/(2*n+1) = g, # so we have n*(h+c) + h = g*(2*n...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
for i in range(int(input())): h, c, t= map(int, input().split()) result = float('inf') avg = (h+c)/2 D = {} if(t==h): result = 1 elif(t in (c,avg)): result = 2 else: D[abs(t-c)] = 2 D[abs(t-h)] = 1 if(t-avg > 0): X = (h-avg)/(t-avg) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; const long long N = 200005; bool col2(pair<long long, long long> p1, pair<long long, long long> p2) { if (p1.second == p2.second) return p1.first > p2.first; return p1.second > p2.second; } struct comp { bool operator()(long long const &x, long long const &y) { return...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import math from decimal import * T= int(input()) def f(j): a=Decimal((h+c)*(j//2) + h*(j%2))/Decimal(j) return abs(a-t) for i in range(T): h,c,t= map(int,input().split()) if h==t: print(1) elif (h+c)//2 == t: print(2) else: k=(h-t)//(2*t-h-c) z=(c-t)//(h+c-2*t) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
T = int(input()) for _ in range(T): h, c, t = map(int, input().split()) if h + c >= t * 2: print(2) else: l, r = 0, 10 ** 9 while r - l > 1: m = (l + r) // 2 if h * (m + 1) + c * m >= t * (2 * m + 1): l = m else: r =...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.BufferedReader; import java.io.InputStreamReader; public class Sola3 { public int minCups(int h, int c, int t){ // 12/4 if(((h+c)%2) == 0 && (h+c)/2 == t)return 2; if(h == t)return 1; int x = c - t; int y = h+c - 2*t; if(x < 0 && y <0){ x = x * -1; y = y*-1; } if(x == 0|| (x < 0...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys input = sys.stdin.buffer.readline def print(val): sys.stdout.write(str(val) + '\n') def val(x,h,c): return (h-c)/(2*(x*2 -1)) def prog(): for _ in range(int(input())): L = 1 R = 10**6 h,c,t = map(int,input().split()) if t <= (h+c)/2: print(2) el...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.nio.file.Path; import java.util.*; public class Solution { static class Pair{ String s; int pos; Pair(String s, int pos){ this.s = s; this.pos = pos; } ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; import java.io.*; public class _1359_C { public static void main(String[] args) throws IOException { BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); PrintWriter out = new PrintWriter(System.out); int t = Integer.parseInt(in.readLine()); for(int i = 0; i < t; i++)...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import fractions def calc_temp(h, c, curr): numerator = h * curr[0] + c * curr[1] denominator = curr[0] + curr[1] return fractions.Fraction(numerator, denominator) def solve(h, c, t): if h == t or t >= (c + 5 / 6 * (h - c)): return 1 if t <= (h + c) / 2: return 2 start = 1 ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
T = int(input()) for _ in range(T): h,c,t = map(int,input().split()) if h+c >= 2*t: print(2) else: x = (h-t)//(2*t-c-h) y = x+1 if abs(h*(x+1)+c*x-t*(2*x+1))*(2*y+1) <= abs(h*(y+1)+c*y-t*(2*y+1))*(2*x+1): print(2*x+1) else: print(2*y+1) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; const long long int INF = (long long int)1e18; const long long int MOD = (long long int)1e9 + 7; const long long int maxn = (long long int)2e5 + 10, L = 23; int main() { ios::sync_with_stdio(0); cin.tie(0); cout.tie(0); long long int T; cin >> T; while (T--) { ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#-------------------- fast io -------------------- import os import sys from io import BytesIO, IOBase BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys __author__ = 'ratmir' from collections import deque from math import asin, pi, tan alphabet = "abcdefghijklmnopqrstuvwxyz" def solve(n, a, graph): return 1 def execute(): [t] = [int(x) for x in sys.stdin.readline().split()] results = [] for ti in range(0, t): [h, c, t] = [int(x...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; public class Contest1 { static int[][][]memo; static int[]a; static int dp(int state,int mx,int idx){ if (idx==a.length) return state==0?0:-(mx-30); if (memo[state][mx][idx]!=-1) return memo[state][mx][idx]; int ans=0;...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.io.*; import java.util.*; import java.math.*; import java.awt.Point; public class Main { //static final long MOD = 998244353L; //static final long INF = 1000000000000000007L; static String letters = "abcdefghijklmnopqrstuvwxyz"; static final long MOD = 1000000007L; static final int INF = 1000000007; ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> using namespace std; int main() { int q; cin >> q; while (q--) { double h, c, t; cin >> h >> c >> t; long long ans = 0; long long l = 0; long long r = 1000000; long long diff = 10000000000; double cnt = 100000000.100; while (l <= r) { long long mid = ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin input = stdin.readline for _ in range(int(input())): h, c, t = map(int, input().split()) if t >= h: print(1) continue if 2 * t <= h + c: print(2) continue l, r = 1, 1000000000 while l < r: m = (l + r) >> 1 if m * h + (m - 1) * c > (2 * m - 1) * t: l = m + 1 else: r = m k ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from fractions import Fraction as frac t = int(input()) for _ in range(t): hotTemp, coldTemp, barrelTemp = map(int, input().rstrip().split()) if barrelTemp == hotTemp: print(1) elif (hotTemp+coldTemp) >= barrelTemp*2: print(2) else: cups1 = (barrelTemp - coldTemp) // ((2 * barrel...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
#include <bits/stdc++.h> long long int mod = 1e9 + 7; using namespace std; const long long int INF = 1e18; const long long int MAX = 2e5 + 10; long long int power(long long int a, long long int b) { if (b == 0) return 1; long long int num = 1; long long int m = mod + 2; while (b != 1) { if (b % 2 == 0) { ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
// Working program using Reader Class import java.io.DataInputStream; import java.io.FileInputStream; import java.io.IOException; import java.io.InputStreamReader; import java.util.Scanner; import java.util.*; public class Main { static class Reader { final private int BUFFER_SIZE = 1 << 16; private ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import io, os input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline for _ in range(int(input())): h, c, t = map(int, input().split()) if h <= t: print(1) elif (h + c) // 2 >= t: print(2) else: n_c = (h - t) // (2 * t - h - c) n_h = n_c + 1 if abs((n_c * c +...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import math def f(k,h,c,t): return ((2*k)+3)*abs(k*(h+c)+h-(2*t*k)-t)<=((2*k)+1)*abs((k+1)*(h+c)+h-(2*t*k)-(3*t)) t=int(input()) for _ in range(t): ar=input().split() h=int(ar[0]) c=int(ar[1]) t=int(ar[2]) if t==h: print(1) else: if 2*t<=h+c: print(2) else...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys import heapq def gcd(a, b): if a < b: a, b = b, a if b == 0: return a return gcd(b, a % b) def main(): a = int(input()) for _ in range(a): h, c, t = map(int, sys.stdin.readline().split()) if t >= h: print(1) continue if t <...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys, fractions range = xrange inp = [int(x) for x in sys.stdin.read().split()] ii = 0 def rint(): global ii i = ii ii += 1 return inp[i] def rints(n): global ii i = ii ii += n return inp[i:ii] def rintss(n, k): global ii i = ii ii += n * k return [inp[i + j: ii...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import java.util.*; public class Main { public static void main(String[] args) { Scanner sc = new Scanner(System.in); StringBuilder ans = new StringBuilder(); int tt = sc.nextInt(); while (tt-- > 0) { int h = sc.nextInt(); int c = sc.nextInt(); ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import math from decimal import Decimal n = int(input()) for i in range(n): h,c,t = map(int,input().split()) if t<=(h+c)/2: print(2) continue avg = (h-t)/(2*t-h-c) a = max(0,math.floor(avg)+1) b = max(0,math.floor(avg)) t1 = Decimal((a+1)*h+a*c)/(2*a+1) t2 = Decimal((b+1)*h+b...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
for _ in range(int(input())): h,c,t = map(int,input().split()) if(h==t): print(1) else: if(((h+c)/2) >= t): print(2) else: dif=(t-((h+c)/2));j=int(abs((c-h)//(2*dif))) if(j%2==0): j+=1 if(dif-(h-c)/(2*j)>=abs(dif-(h-c)/(...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
import sys input = sys.stdin.buffer.readline import math T = int(input()) for _ in range(T): h, c, t = map(int, input().split()) if t <= (h+c)/2: print(2) else: if (h-t)%(2*t-h-c)==0: x = (h-t)//(2*t-h-c) print(2*x+1) else: x = (h-t)/(2*t-h-c) ...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin ############################################################### def iinput(): return int(stdin.readline()) def sinput(): return input() def minput(): return map(int, stdin.readline().split()) def linput(): return list(map(int, stdin.readline().split())) ############################################...
Problem: There are two infinite sources of water: * hot water of temperature h; * cold water of temperature c (c < h). You perform the following procedure of alternating moves: 1. take one cup of the hot water and pour it into an infinitely deep barrel; 2. take one cup of the cold water and pour it into...
from sys import stdin, stdout from decimal import * cin = stdin.readline cout = stdout.write getcontext().prec = 50 for _ in range(int(cin())): h, c, t = map(int, cin().split()) if (h+c)/2 >= t: cout('2\n') continue i = (c-t) // (h+c-t-t) if abs(t - Decimal(h*i + c*(i-1))/Decimal(i+i-1)) <= abs(t - Decimal(h...