blob_id string | repo_name string | path string | length_bytes int64 | score float64 | int_score int64 | text string | is_english bool |
|---|---|---|---|---|---|---|---|
498b2f1bf20f12d2da8c02558edd87297f5c6fed | khanhdodang/automation-training-python | /python_basics/tutorial/31_string_formatting.py | 2,023 | 4.65625 | 5 | '''
Python String Formatting
To make sure a string will display as expected, we can format the result with the format() method.
String format()
The format() method allows you to format selected parts of a string.
Sometimes there are parts of a text that you do not control, maybe they come from a database, or user input?
To control such values, add placeholders (curly brackets {}) in the text, and run the values through the format() method:
Example
Add a placeholder where you want to display the price:
'''
price = 49
txt = "The price is {} dollars"
print(txt.format(price))
'''
You can add parameters inside the curly brackets to specify how to convert the value:
Example
Format the price to be displayed as a number with two decimals:
'''
txt = "The price is {:.2f} dollars"
'''
Check out all formatting types in our String format() Reference.
Multiple Values
If you want to use more values, just add more values to the format() method:
print(txt.format(price, itemno, count))
And add more placeholders:
Example
'''
quantity = 3
itemno = 567
price = 49
myorder = "I want {} pieces of item number {} for {:.2f} dollars."
print(myorder.format(quantity, itemno, price))
'''
Index Numbers
You can use index numbers (a number inside the curly brackets {0}) to be sure the values are placed in the correct placeholders:
Example
'''
quantity = 3
itemno = 567
price = 49
myorder = "I want {0} pieces of item number {1} for {2:.2f} dollars."
print(myorder.format(quantity, itemno, price))
'''
Also, if you want to refer to the same value more than once, use the index number:
Example
'''
age = 36
name = "John"
txt = "His name is {1}. {1} is {0} years old."
print(txt.format(age, name))
'''
Named Indexes
You can also use named indexes by entering a name inside the curly brackets {carname}, but then you must use names when you pass the parameter values txt.format(carname = "Ford"):
Example
'''
myorder = "I have a {carname}, it is a {model}."
print(myorder.format(carname="Ford", model="Mustang"))
| true |
9c7bde7f37c9e75e5a39314ec3fd7587984a83bf | khanhdodang/automation-training-python | /python_basics/tutorial/30_user_input.py | 656 | 4.28125 | 4 | '''
Python User Input
User Input
Python allows for user input.
That means we are able to ask the user for input.
The method is a bit different in Python 3.6 than Python 2.7.
Python 3.6 uses the input() method.
Python 2.7 uses the raw_input() method.
The following example asks for the username, and when you entered the username, it gets printed on the screen:
Python 3.6
'''
username = input("Enter username:")
print("Username is: " + username)
# Python 2.7
username = raw_input("Enter username:")
print("Username is: " + username)
# Python stops executing when it comes to the input() function, and continues when the user has given some input.
| true |
fc1c238515effb961f4efae4eee9d9ec71997aa0 | green-fox-academy/RudolfDaniel | /[week-02]/[day-01]/Exercise-34.py | 262 | 4.1875 | 4 | lenght_of_list = int(input("Type in a number "))
list_of_nr = []
while len(list_of_nr) < lenght_of_list:
list_of_nr.append(int(input("Type in a number: ")))
print("Sum: " + str((sum(list_of_nr))))
print("Average: " + str((sum(list_of_nr))/lenght_of_list)) | false |
54436c30c613ca141c8a12af9e8f64c8efab1c93 | dominichul/HackerRank | /python/warm_up/repeated_string/repeated_string.py | 1,570 | 4.1875 | 4 | #!/bin/python
"""
HackerRank Challenge: Warm-up Challenges -> Repeated String
Args:
@:param s (str): String given by user
@:param n (int): Integer given by user
Problem:
- Assume string entered by user is infinitely repeating.
- How many times is ACTIVATE_CHARACTER found in the repeating string up to index of n-1?
Solution:
1. Identify the ACTIVATE_CHARACTER count for string 's'.
2. Determine how many times the entire string 's' can fit into the repeating string up to n-1.
3. Multiply result from step 1 by result from step 2 to get a base count
4. Determine # of remaining characters up to index n-1 in repeating string
5. Identify the ACTIVATE_CHARACTER count for substring of 's' from [0:x-1], where x is the result of step 4
6. Return the sum of steps 3 and 5
"""
ACTIVATE_CHARACTER = 'a'
def repeatedString(s, n):
"""
:param s: str -> Repeating string
:param n: int -> Number of characters to include in repeating string
:return: # of occurences of ACTIVATE_CHARACTER in repeating string of s (str) up to index n-1 (int)
f(s,n) = (# of occurences of 'a' in s) * (number of times entire 's' string fits in n) + (# of occurences of 'a' in 's' up to index of (remainder character count from n - 1))
"""
return s.count(ACTIVATE_CHARACTER) * (n / len(s)) + s[:(n % len(s))].count(ACTIVATE_CHARACTER)
if __name__ == '__main__':
print("Enter String:")
s = raw_input()
print("Enter Integer:")
n = int(raw_input())
result = repeatedString(s, n)
print(result)
| true |
2dfce74b1c570a8505902256578c802266fea491 | akshay2242/Python_All_Basic_Programs | /Operators/3.py | 230 | 4.15625 | 4 | # Program to find two numbers Equal or Not
a = int(input("Enter first number: "))
b = int(input("Enter second number: "))
if a==b:
print("The value of a and b are equal")
else:
print("The value of a and b are not equal") | true |
a855f6afe88dfdbe7e619d01e4bcd649b0de8d63 | akshay2242/Python_All_Basic_Programs | /Loops/3.py | 245 | 4.28125 | 4 | # Program to equal operator and not equal operator
a = int(input("Enter the value of a: "))
b = int(input("Enter the value of b: "))
if a==b:
print("The value of a and b are equal")
if a!=b:
print("The value of a and b are not equal") | true |
f1c5713bd893ccd51ddd7d420e30cedde4bba0a7 | KaterynaKandziuba/ITStep-hws | /HW_9/Kandziuba_hw9_task6-7.py | 1,242 | 4.125 | 4 | #Задание 6
#Напишите функцию, которая считает количество
#цифр в числе. Число передаётся в качестве параметра. Из
#функции нужно вернуть полученное количество цифр.
#Например, если передали 3456, количество цифр будет 4.
a = int(input("Enter your number: "))
def digits(n):
counter = 0;
i = 1
while n > 0:
n = n//(10**i)
counter +=1
print("Your number has", counter, "digits.")
digits(a)
#Задание 7
#Напишите функцию, которая проверяет является ли
#число палиндромом. Число передаётся в качестве параметра. Если число палиндром,
# нужно вернуть из функции true, иначе false.
number = int(input('Enter a number to check if it is a palindrome:'))
def palindrome(n):
n = str(n)
n_rev = n[::-1]
if n == n_rev:
return True
else:
return False
if palindrome(number):
print("Yeap!")
else:
print('Oh, no!')
| false |
a7f34b32ef678b193d30f0044cac7f5c286c76f7 | KaterynaKandziuba/ITStep-hws | /HW_15/Kandziuba_hw15.py | 885 | 4.125 | 4 | #Створити множини: A, B, C з довільними елементами.
from random import randint
A = set([randint(1, 100) for i in range(10)])
B = set([randint(1, 100) for i in range(10)])
C = set([randint(1, 100) for i in range(10)])
print(f"There are sets A: {A}, \nB: {B} \nand C: {C}")
#1. Знаходимо різні елементи для A, B
def different(A: set, B:set):
return A^B
D = different(A, B)
print("Different elements of A and B:", D)
#2. Знаходимо однакові елементи для A, C
def similar(A: set, B: set):
return A&C
S = similar(A, C)
print ("Similar elements of A and C:", S)
#3. Знаходимо об'єднання всіх трьох множин
def united(A: set, B: set, C: set):
return A|B|C
U = united(A, B, C)
print ("United elements of A, B, and C:", U)
| false |
1d206fae96c945bdb83ba2731365680949715e34 | schartun/pythoncrashcourse | /chapter_03/3-1. Names.py | 259 | 4.34375 | 4 | #Store the names of a few of your friends in a list called names. Print
#each person’s name by accessing each element in the list, one at a time.
names = ["arvin", "mario", "paulo", "adrian"]
print(names[0])
print(names[1])
print(names[2])
print(names[3])
| true |
c03217169380baaef5b4a39ae2799886cb975289 | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 8/p14p3.py | 575 | 4.15625 | 4 | """
Set count to 0
Prompt for non-negative, set as limit
if limit is negative
print warning
exit
for loop between 2 and limit
if limit divides by counter evenly then
print not prime
break
else then
print prime
"""
count=0
limit=int(input('Enter an an integer >=0: '))
if limit<=0:
print(limit,'is not a prime number. The prime number sequence begins at 1.')
exit()
for i in range(2,limit):
if limit%i==0:
print(limit,'is not a prime number.')
break
else:
print(limit,'is a prime number.') | true |
2139d880cca5d28ec1c45d4e01ce2f0c024da030 | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 4/p6p3.py | 359 | 4.46875 | 4 | '''
Prompt user to enter a name as a string.
If the name is Mickey Mouse or Spongebob Squarepants, then print I am not sure that is your name.
Else print you have a nice name.
Print finished.
'''
name=str(input('Enter name:'))
if name=='Mickey Mouse' or name=='Spongebob Squarepants':
print('I am not sure that is your name.')
else:
print('You have a nice name.')
print('finished!') | true |
b69f3a95cb2be123852a55b5993fb756e65ff7ab | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 7/p13p6.py | 713 | 4.3125 | 4 | """
define factorial function of variable x
if x is 0 then
return 1
else then
print x
return x multiplied by factorial function of x-1
prompt for non-negative integer
if input isn't negative
print factorial function of input
else then
print warning
"""
def fact(x):
"""Function that returns the factorial of its argument
Assumes that its argument is a non-negative integer
Uses a recursive definition
"""
if x==0:
return 1
else:
print(x)
return x*fact(x-1)
number=int(input('Enter an integer (must be >=0): '))
if number>=0:
print(fact(number))
else:
print('Integer must be >=0.') | true |
e5d4c440ccafc0654bfaa60a4c65ffdf1251be88 | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 2/p4p1.py | 438 | 4.15625 | 4 | #Ask the user to enter the Euro amount
euro_amount=float(input('Enter Euro amount:'))
print('Amount in Euro:',euro_amount)
#Converting Euro to US Dollars
euro_dollar_conversion=1.117547
#Converting Euro as long as the amount entered is at least zero
if euro_amount>=0:
print('Amount in US Dollars:',euro_amount*euro_dollar_conversion)
else:
print('Amount must be >= 0')
print('Please try again.')
print('Finished!') | true |
302a4a8e23443aa8d2221b8409b999e67b8e6647 | AdamMcCarthyCompSci/Programming-1-Practicals | /Midterm/q2v2.py | 678 | 4.3125 | 4 | monthname=['September','October','November','December','January','February','March','April','May','June','July','August']
monthnumber=[30,61,91,122,153,181,212,242,273,303,334,365]
monthvalue=0
dateinput=int(input('Enter an integer: '))
if dateinput<=0:
print('Integer must be greater than 0.')
elif dateinput<=30:
date=dateinput
else:
while monthvalue<12:
if (dateinput-monthnumber[monthvalue])<=0:
date=dateinput-monthnumber[monthvalue-1]
break
else:
monthvalue+=1
if monthvalue<=3:
year=2020
else:
year=2021
print('Day',dateinput,'is the',date,'of',monthname[monthvalue]+',',year) | true |
4f93b998772d503ea5936a3f12ac78bd724bd74e | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 5/p8p2.py | 848 | 4.15625 | 4 | '''
Prompt input
Test if input<=0
print warning if true
else
create variables for two multiplier numbers
set a while loop where the loop can't exceed the inputted number
Create nested while loop, where second variable can't exceed inputted number (other axis in table)
multiply two variables and add space at end
add 1 to second variable
print empty line
reset two variables
'''
numberinput=int(input('Enter a positive integer: '))
if numberinput<=0:
print('Integer must be greater than 0.')
else:
multiplylimit=1
multiplier=1
while multiplylimit<=numberinput:
while multiplier<=numberinput:
print(multiplier*multiplylimit,end=' ')
multiplier+=1
print()
multiplier=1
multiplylimit+=1
print('Finished!') | true |
2e91b7c4d5bc7acf8119e8903b5e494370fd95d8 | AdamMcCarthyCompSci/Programming-1-Practicals | /Practical 5/p9p1.py | 560 | 4.25 | 4 | '''
Prompt for positive integer
If input isn't positive
print warning
else
set counter variable
set sum variable
create while loop where counter must not be greater than input
add counter to sum
add 1 to counter
print sum
'''
integerinput=int(input('Enter a positive integer: '))
if integerinput<=0:
print('Integer must be greater than 0.')
else:
counter=0
integersum=0
while counter<=integerinput:
integersum+=counter
counter+=1
print(integersum)
print('Finished!') | true |
57e95c26b15b4b2093eb13591f4b2318b57d57a8 | AdamMcCarthyCompSci/Programming-1-Practicals | /Midterm/q1.py | 944 | 4.1875 | 4 | '''
Ask for integer.
If integer less than 0, print statement.
Else: while loop using inputted integer to capture modulus of 3,5,7,11.
Count up by 1 if true.
Add 1 to while loop.
'''
integerinput=int(input('Enter an integer:'))
print('You entered: ',integerinput)
if integerinput<0:
print('Number entered should be >=0')
else:
count=1
divisible3=0
divisible5=0
divisible7=0
divisible11=0
while count<=integerinput:
if count%3==0:
divisible3+=1
if count%5==0:
divisible5+=1
if count%7==0:
divisible7+=1
if count%11==0:
divisible11+=1
count+=1
print('Number of numbers divisible by 3: ',divisible3)
print('Number of numbers divisible by 5: ',divisible5)
print('Number of numbers divisible by 7: ',divisible7)
print('Number of numbers divisible by 11: ',divisible11)
print('Finished!') | true |
c829fb744e544e7fecc846902830ece85836970f | jacobollinger/CS-112L | /Lab5/Lab5 Solution.py | 1,035 | 4.34375 | 4 | # Lab5: Design software to calculate continued fractions for a real number and for a rational number.
# By Jacob Bollinger
def findContinuedFraction(a, b) :
continuedFraction = ''
searching = True
while (searching) :
integer = a // b
a = a - integer * b
a,b = b,a
continuedFraction = continuedFraction + ' ' + str(integer)
searching = (b != 0)
return continuedFraction
def findRealContinuedFraction(r, steps):
continuedFraction = ''
for i in range(steps) :
integer = int(r)
r = r - integer
r = 1 / r
continuedFraction = continuedFraction + ' ' + str(integer)
i = i - 1
return continuedFraction
# Inputs
# Numerator
N1 = 13
# Denomenator
N2 = 7
# Real Number
R = 2 ** (1/3)
# How many times findRealContinuedFraction runs
STEPS = 10
# Outputs
# Continued fraction of N1 / N2
print ('Continued Fraction:', findContinuedFraction(N1, N2))
# Real Continued Fraction
print ('Real Continued Fraction:', findRealContinuedFraction(R, STEPS)) | true |
e1e7b170c4d6de94a102fae266176b6c1c9016d5 | ArunkumarSennimalai/-Python-Assignment2 | /Assingment2/35.py | 1,937 | 4.25 | 4 | def printTupleElements(tuple1):
for element in tuple1:
print element,
print "\v"
def concatenateTuples(tuple1,tuple2):
tuple1 += tuple2
return tuple1
def findingGreaterTuple(tup1,tup2,tup3):
greatertuple=tup2
if cmp(tup1,tup2)==1:
greatertuple=tup1
if cmp(tup3,greatertuple)==1:
greatertuple=tup3
print "Greater tuple is", greatertuple
def delTuple(tup1,tup2):
try:
#deleting entire tuple is possible
del(tup2)
#trying to delete tuple element will throw error
del(tup1[0])
except TypeError:
print "Tuple doesn't support deletion"
def convertToList(tup1):
return list(tup1)
print list1
list1.append(123)
print list
def appendValueToList(list1,value):
list1.append(value)
if __name__ == "__main__":
try:
#printing elements in tuple
tuple1 = ("Sunday","Monday","Tuesday","Wednesday","Thursday","Friday","Saturday")
printTupleElements(tuple1)
tuple2 = ("January","February","March","April","May","June","July","August","September","October","November","December")
printTupleElements(tuple2)
#concatenating tuples
tuple1 = concatenateTuples(tuple1,tuple2)
printTupleElements(tuple1)
#finding greater tuple
tup1 = (34,23,45,12,25,67,89,33,77)
tup2 = (5,53,65,45,36,67,76,99,10)
tup3 = (66,55,1,23,9,98,76,45,34,33)
findingGreaterTuple(tup1,tup2,tup3)
#tying to delete tuple element and entire tuple
delTuple(tup1,tup2)
#typecating to list
list1 = convertToList(tup1)
#inserting value into list
appendValueToList(list1,123)
print list1
except Exception as e:
print(e)
| false |
c37d21f2729953d3d553935f57b409171148a7d7 | mykisscool/doing-math-with-python | /Chapter 1/2_enhanced_multiplication_table_generator.py | 891 | 4.21875 | 4 | """
Enhanced Multiplication Table Generator
"""
def multi_table(a, b):
for i in range(1, b + 1):
print('{0} x {1} = {2}'.format(a, i, a * i))
if __name__ == '__main__':
# 5: Give Exit Power to the User
while True:
'''
The classical Python mentality, though, is that it's easier to ask forgiveness than permission.
In other words, don't check whether x is an integer; assume that it is and catch the exception
results if it isn't.
'''
try:
a = int(input('Please enter the number to be multiplied: '))
b = int(input('Please enter the number of multiples of the first number: '))
multi_table(a, b)
except ValueError:
exit('An invalid integer was inputted.')
answer = input('Do you want to exit? (y) for yes ')
if answer == 'y':
break
| true |
0fb33d1900e0bf5e5bd20a9accf5fe18c9167897 | Akshaytomar893/Strings | /Isomorphic String.py | 810 | 4.15625 | 4 | #Given two strings s and t, determine if they are isomorphic.
#Two strings s and t are isomorphic if the characters in s can be replaced to get t.
#All occurrences of a character must be replaced with another character while preserving the order of characters.
#No two characters may map to the same character, but a character may map to itself.
#leetcode : https://leetcode.com/problems/isomorphic-strings/
#python code :
def isIsomorphic(self, s: str, t: str) -> bool:
dic={}
lis=[]
l=len(s)
for i in range(l):
c1=s[i]
c2=t[i]
if c1 not in dic and c2 not in lis:
dic[c1]=c2
lis.append(c2)
elif c1 in dic and dic[c1] !=c2:
return False
elif c1 not in dic and c2 in lis:
return False
return True
| true |
96faa26b410a378ae2da6f9b241900c23fde0651 | kumargagank/pytthon | /def add(x,y).py | 609 | 4.125 | 4 | def add(x,y)
return x+y
def substract(x,y)
return x-y
def multiply(x,y)
return x*y
def divide(x,y)
return x/y
print("select operation")
print("1.add")
print("2.subtract")
print("3.multiply")
print("4.divide")
choice=input("enter choice(1/2/3/4):")
num1=int(input("enter the first number:"))
num2=int(input("enter the second number:"))
if choice =='1':
print(num1,"+",num2,"=",add(num1,num2))
elif choice =='2':
print(num1,"-",num2,"=",subtract(num1,num2))
elif choice =='3'
print(num2,"*",num2,"=",multiply(num1,num2))
elif choice =='4':
print(num2,"/",num2,"=",divide(num1,num2))
else:print("invalid inputS") | false |
6653cff9a769a3a03c027ca3eefd44af94c760ff | JorgeSchelotto/Practica-4---Seminario-Python | /Ejercicio2.py | 2,500 | 4.1875 | 4 | """ Dado el archivo utilizado con datos de jugadores del Ejercicio 3 de la Práctica 3, implemente
una función que reciba el nombre del archivo como parámetro y maneje con excepciones el
caso que el archivo no exista, informando dicha situación."""
import json
jugadores = {}
clave = {}
def modifica_datos():
# leo jugador a buscar
print()
nom = input('ingrese el jugador a buscar: ')
# cargo el diccionario almacenado en el txt. E el bloque try busco si el
# jugador existe para actualizar sus datos. Sino existe, lo agrego mediante
# el bloque except. En finally imprimo el diccionario completo.
with open('json.txt', 'r+') as f:
d = json.load(f)
try:
print('Los datos del jugador ',nom,' son: ',d[nom])
print('Actualice los datos del jugador: ', nom)
nivel = input('Ingrese el nuevo nivel: ')
puntaje = int(input('Ingrese el nuevo puntaje: '))
horasJuego = input('Ingrese las nuevas horas de juego: ')
clave['nivel'] = nivel
clave['puntaje'] = puntaje
clave['horas'] = horasJuego
d[nom] = clave.copy()
except (KeyError):
print()
print('El jugador no existe. Cargue los datos de: ', nom, ', nuevo jugador.')
nivel = input('Ingrese el nuevo nivel: ')
puntaje = int(input('Ingrese el nuevo puntaje: '))
horasJuego = input('Ingrese las nuevas horas de juego: ')
clave['nivel'] = nivel
clave['puntaje'] = puntaje
clave['horas'] = horasJuego
d[nom] = clave.copy()
# imprimo versión final del diccionario
finally:
print()
print('Último registro de jugadores: ')
print(d)
# carga inicial de jugadores y sus datos
nombre = input('Ingrese Nombre del jugador. Ingrese "fin" para cortar la carga: ')
while(nombre != 'fin'):
nivel = input('Ingrese Nivel del jugador: ')
puntaje = input('Ingrese puntaje del jugador: ')
horasJuego = input('Ingrese horas de juego del jugador: ')
clave['nivel'] = nivel
clave['puntaje'] = puntaje
clave['horas'] = horasJuego
jugadores[nombre] = clave.copy()
nombre = input('Ingrese Nombre del jugador: ')
# guardo el diccionario de jugadores en archivo de texto plano
file = open('json.txt', 'w')
json.dump(jugadores,file)
file.close()
print()
print('diccionario inicial: ')
print(jugadores)
modifica_datos()
| false |
d933a3d320c54d9b4e108a2edb68cccfa1d26587 | AbdallahElGhamry/Python-Programming-Exercises | /Decision Structures/6. Software Sales.py | 796 | 4.1875 | 4 | '''
A software company sells a package that retails for $99. Quantity
discounts are given according to the following table:
Quantity Discount
10–19 10%
20–49 20%
50–99 30%
100 or more 40%
Write a program that asks the user to enter the number of
packages purchased. The program should then display the
amount of the discount (if any) and the total amount of the
purchase after the discount.
'''
qnt = int(input('Enter the quantity: '))
disc = 0.0
if qnt >= 100:
disc = 40/100
elif qnt >= 50 and qnt <= 99:
disc = 30/100
elif qnt >= 20 and qnt <= 49:
disc = 20/100
elif qnt >= 10 and qnt <= 19:
disc = 10/100
print('Discount Percentage:', disc)
print('Discount Value:', disc * qnt)
print('Total Amount:', qnt + disc * qnt )
| true |
c88f233573a6b85252068141cc7f96c732c5b2f3 | AbdallahElGhamry/Python-Programming-Exercises | /Decision Structures/4. Roulette Wheel Colors.py | 1,536 | 4.5625 | 5 | '''
On a roulette wheel, the pockets are numbered from 0 to 36. The
colors of the pockets are as follows:
Pocket 0 is green.
For pockets 1 through 10, the odd-numbered pockets are red
and the even-numbered pockets are black.
For pockets 11 through 18, the odd-numbered pockets are
black and the even-numbered pockets are red.
For pockets 19 through 28, the odd-numbered pockets are red
and the even-numbered pockets are black.
For pockets 29 through 36, the odd-numbered pockets are
black and the even-numbered pockets are red.
Write a program that asks the user to enter a pocket number and
displays whether the pocket is green, red, or black. The program
should display an error message if the user enters a number that
is outside the range of 0 through 36.
'''
num = int(input('Enter an integer in range of 0 through 36: '))
if num == 0:
print('Pocket', num, 'is green')
elif num >= 1 and num <= 10:
if num % 2 == 0:
print('Pocket', num, 'is black')
else:
print('Pocket', num, 'is red')
elif num >= 11 and num <= 18:
if num % 2 == 0:
print('Pocket', num, 'is red')
else:
print('Pocket', num, 'is black')
elif num >= 19 and num <= 28:
if num % 2 == 0:
print('Pocket', num, 'is black')
else:
print('Pocket', num, 'is red')
elif num >= 29 and num <= 36:
if num % 2 == 0:
print('Pocket', num, 'is red')
else:
print('Pocket', num, 'is black')
else:
print('Invalid input.')
| true |
707869713e87750ec6c1356f4defc3e68f9ea242 | karadisairam/Loops | /45.py | 259 | 4.21875 | 4 | for x in range(5):
print(x)
#To display numbers 0 to 10:
for x in range(11):
print(x)
#Odd numbers in 0 to 20 :
for x in range(21):
if x%2!=0:
print(x)
#Even numbers :
for i in range(10):
if i%2==0:
print(i) | false |
58ab85b8a7b00945bb1dbf69893d5c3f53480895 | rollinscms430/Project-2-Search-nkirpalani | /anagrams.py | 1,016 | 4.15625 | 4 | #NSK, 2017
from collections import defaultdict
'''
Loading tuple dictopnary with words from file using rstrip() which returns a copy of the string in which all chars have been stripped from the end of the string.
'''
def load_words(filename='words.txt'):
with open(filename) as f:
tuples = []
for word in f:
tuples.append(word.strip())
return tuples
'''
Generating anagrams from the list of words in the dictionary
by sorting the word alphabetically and then checking it against other words in the dictionary to see if they match up
'''
def get_anagrams(source):
dd = defaultdict(list)
for word in source:
key = "".join(sorted(word))
dd[key].append(word)
return dd
'''
Prints the anagrams pairings.
'''
def print_anagrams(word_source):
dd = get_anagrams(word_source)
for key, anagrams in dd.iteritems():
if len(anagrams) > 1:
print(anagrams)
word_source = load_words()
print_anagrams(word_source)
| true |
b2e9047f39d4589640e8d24b04da11b70ce19a3b | harshalb7/Python-Programming | /mathOperation.py | 581 | 4.125 | 4 | def addtion(num1, num2):
return num1 + num2
def subtraction(num1, num2):
return num1 - num2
def multiplication(num1, num2):
return num1 * num2
def division(num1, num2):
if num2 != 0:
return num1/num2
else:
print("Divide by Zero Error")
#print("Enter Numbers: ")
num1 = float(input(" Number 1: "))
num2 = float(input(" Number 2: "))
print(" Addition is : ",addtion(num1, num2))
print(" Subtraction is : ",subtraction(num1, num2))
print(" Multiplication is: ",multiplication(num1, num2))
print(" Division is : ",division(num1, num2)) | false |
fdd3f44f9134cb6d4883028607a621aab324544e | tarunteja04/cs5590-python-deep-learning | /python/ICP 1/Source/Digits and Number counting.py | 531 | 4.15625 | 4 | data=input("enter a string") # Taking a string from user
letters=numbers=0 # Initially taking letters and numbers as zero
for i in data:
if i.isdigit(): # checking whether it is a digit or not
numbers =numbers+1 # storing that digit in the numeric
elif i.isalpha(): # checking whether it is a alphabet or not
letters =letters+1 # storing that word in the letters
print(numbers) # printing numbers
print(letters) # printing letters
| true |
a8a95401de57afff950c9daa0d3ebc00a6f71d97 | uchenna-j-edeh/advanced_data_structures | /trees.py | 2,155 | 4.15625 | 4 |
from unittest import TestCase
class Node:
def __init__(self, data):
self.data = data
self.left = None
self.right = None
def insertLeft(self, nodeData):
"""
If node has no left child, add a node to the tree
When node has a left child however, insert a node and push the existing child downone level in the tree
Mirror the same thing in right
"""
if self.left == None:
self.left = Node(nodeData)
else:
t = Node(nodeData)
t.left = self.left
self.left = t
def insertRight(self, nodeData):
if self.right == None:
self.right = Node(nodeData)
else:
t = Node(nodeData)
t.right = self.right
self.right = t
def getRight(self):
return self.right
def getLeft(self):
return self.left
def setRootValue(self, data):
self.data = data
def getRootValue(self):
return self.data
def BuildSpecialTree():
nodeA = Node('a')
nodeA.insertRight('c')
nodeA.insertLeft('b')
nodeA.getRight().insertRight('f')
nodeA.getRight().insertLeft('e')
# nodeA.left = Node('d')
nodeA.getLeft().insertRight('d')
return nodeA
if __name__ == '__main__':
# node = Node('a')
# print(node.getRootValue())
# print(node.getLeft())
# node.insertLeft('b')
# print(node.getLeft())
# print(node.getLeft().getRootValue())
# node.insertRight('c')
# print(node.getRight())
# print(node.getRight().getRootValue())
# node.getRight().setRootValue('Hello Uchenna')
# print(node.getRight().getRootValue())
# root = BuildSpecialTree()
ttree = BuildSpecialTree()
# ttree.getRightChild().getRootVal()
if ttree.getLeft().getRight().getRootValue() == 'd':
print("Success! d is Right child of b")
if ttree.getRight().getLeft().getRootValue() =='e':
print("Success! e is left child of c")
print(ttree.getRight().getRootValue())
if ttree.getRight().getRootValue() == 'c':
print("Success! c is Right child of a")
| true |
8d4e15b9469bf3995f028159220c368a65f05477 | jwcheong0420/TIL | /language/python/opentutorials-lecture/string.py | 873 | 4.46875 | 4 | print("=== String ===")
print('Hello')
print("Hello")
#print('Hello") #SyntaxError: EOL while scanning string literal
#print('Hello 'world'') #SyntaxError: invalid syntax
print("Hello 'world'")
print('Hello "world"')
print("=== String control ===")
print('Hello ' + 'world')
print('Hello '*3)
#print('Hello ' - 'world') #TypeError: unsupported operand type(s) for -: 'str' and 'str'
print('Hello'[0])
print('Hello'[1])
print('Hello'[2])
print('Hello'[3])
print('Hello'[4])
print("=== String control2 ===")
print('hello world'.capitalize())
print('hello world'.upper())
print('hello world'.__len__())
print(len('hello world'))
print('hello world'.replace('world', 'programming'))
print("=== Escape character ===")
print("hello\tworld\n!\\\a")
print('hello\tworld\n!\\\a')
print("=== Number and String ===")
print("10+5 :", 10 + 5)
print("\"10\"+\"5\" : " + "10" + "5")
| false |
975086efaaa919404fa684488fbcd4c65c503c45 | ujjwaltambe03/PythonDemo | /Radio_button.py | 823 | 4.125 | 4 | # A radio button is a widget that allows the user to choose only one of a predefined options.
# syntax : Rbttn = Radiobutton(master, option..........)
from tkinter import *
def Retreive_data():
var2.set(var1.get())
root = Tk()
root.geometry("480x340")
frame = Frame(root)
frame.pack()
var1 = IntVar()
var2 = StringVar()
# creating option 1 and 2
Rad_Button_1 = Radiobutton(frame, text = "Option_1", variable = var1,value = 1)
Rad_Button_1.pack()
Rad_Button_2 = Radiobutton(frame, text = "Option_2", variable = var1,value = 2)
Rad_Button_2.pack()
# label to print which option choosed
label = Label(frame, textvariable= var2, width = 10, bg = 'grey')
label.pack()
# submit button to submit selected option
Sub_button = Button (frame, text = "Submit", command = Retreive_data)
Sub_button.pack()
root.mainloop() | true |
d5b43f00da6e3b1ca7b5c0a4154a2f3685abe828 | mihirakaranam/Coursera_IIPP | /week4/week4a/week4a_practice_exercise_2.py | 496 | 4.1875 | 4 | # List reference problem
###################################################
# Student should enter code below
a = [5, 3, 1, -1, -3, 5]
b = a
b[0] = 0
print a
print b
###################################################
# Explanation
# The assignment b = a created a second reference to a.
# Setting b[0] = 0 also mutated the list that both
# a and b reference. As a result, a[0] == 0.
# See the Programming Tips videos for a more detail
# explanation and examples
| true |
0de5779a615203dd0710fe663c287e105de7a76b | AviaTorX/Digit-Recognition | /src/NeuralNetworkCreation.py | 807 | 4.25 | 4 | import numpy as num
class NetworkLayers(object):
#It will create Neural Network Architecture and Assign Weights and Biases to
#np.random.randn function to generate
#Gaussian distributions with mean and standard deviation in given range
#if we want to create neural network with 3 layers we create NetworkLayers
#object like net = NetworkLayers([2, 3, 1]) means
#first layer contain 2 input neuron hidden layer contain 3 neurons
#nuber of hidden layer = 1 and one output layer contain 1 neuron
def __init__(self, configuration):
self.number_of_layers = len(configuration);
self.configuration = configuration;
self.weights = [np.random.randn(y, 1) for y in configuration[1:]]
self.biases = [np.random.randn(y, x) for x, y in zip([:-1], [1:])]
| true |
3f9ad579246727df4a26bebe3c1081c0a4cbefd8 | valken24/IA-Studies | /MODEL_CLASS/Python Basic/strings.py | 861 | 4.21875 | 4 | myStr = "Hello World"
print("My name is " + myStr)
print(f"My name is {myStr}")
print("My name is {0}".format(myStr))
# myStr_2 = "Hello_World"
#Opciones para myStr
#print(dir(myStr))
# print(myStr.upper())
# print(myStr.lower())
# print(myStr.swapcase())
# print(myStr.capitalize())
# print(myStr.replace('Hello', 'bye'))
# print(myStr.replace('Hello', 'bye').upper()) #Metodos Encadenados
# a = myStr.count('l')
# print(a)
# b = myStr.startswith('Hola')
# print(b)
# b = myStr.endswith('World')
# print(b)
# c = myStr.split()
# print(c)
# d = myStr_2.split('_')
# print(d)
# e = myStr_2.split('o')
# print(e)
# f = myStr.find('o')
# print(f)
# g = len(myStr)
# print(g)
# h = myStr.index('e')
# print(h)
# i = myStr.isnumeric()
# j = myStr.isalpha()
# print(i,j)
# k = myStr[4]
# print(k)
# l = myStr[-1]
# print(l)
# m = myStr[-5]
# print(m) | false |
b5875b14cd960422cdf1ad58d2c16016e902c173 | FatemehRezapoor/PythonExercise | /Ex2.py | 783 | 4.4375 | 4 | # June 10, 2018
# Ask the user for a number. Depending on whether the number is even or odd, print out an appropriate message to the
# user. Hint: how does an even / odd number react differently when divided by 2?
# Extras:
#If the number is a multiple of 4, print out a different message.
# Date: July 13, 2020
num = input('Type your number:')
if int(num)%2 is 0:
print(' Number {} is even'.format(num))
if int(num)%4==0:
print('Number {} is a multiple of 4'.format(num))
else:
print('Number {} is odd'.format(num))
# Date: June 10, 2020
number=int(input('Please inter your number:\t'))
if number%2==0:
print('Your number is even')
if number%4==0:
print('This number is 4 multiple')
else:
print('Your number is odd')
| true |
3dc19f7d472668e0a72e135ba7fce1c56afcae44 | FatemehRezapoor/PythonExercise | /PythonExercise/Ex15.py | 523 | 4.375 | 4 | # June 12, 2018
# For example, say I type the string: My name is Michele
# Then I would see the string: Michele is name My shown back to me.
sen='My name is sara'
sent=sen.split(' ')
# METHOD 1
senr=list(reversed(sent))
for x in senr:
print(x,end=' ') # Avoids the print command from printing in a new line
# METHOD 2
a=' '.join(reversed(sent))
print(a)
# JOIN IN PYTHON
# Joins a sequence of elements
s = "-";
seq = ("a", "b", "c"); # This is sequence of strings.
print (s.join( seq ))
| true |
25bc058398981b237796deed186a2a18f3892d0b | Tansir93/PythonStudy | /PythonStudy/FirstPython/使用list和tuple.py | 1,298 | 4.40625 | 4 | print("/n/n")
print("~~~~~~~~~~~~~~~~~list~~~~~~~~~~~~~~~~~~")
classmates = ['Michael', 'Bob', 'Tracy']#list是一种有序的集合
print(classmates)
print(len(classmates))#获取list元素个数
print(classmates[0])
print(classmates[-1])#取最后一个元素
classmates.append('Adam')#追加元素到末尾
print(classmates)
classmates.insert(1,"jack")#插入指定位置
print(classmates)
classmates.pop(1)#删除指定位置元素
print(classmates)
classmates[1]='sarah'#赋值
print(classmates)
classmates=[123,'apple',True]#允许不同数据类型
print(classmates)
classmates=[123,'apple',[123,'pop'],True]#list元素也可以是另一个list
print(classmates)
print(classmates[2][1])#获取嵌套list中元素
print("/n/n")
print("~~~~~~~~~~~~~~~~~tuple~~~~~~~~~~~~~~~~~~")
classmates = ('Michael', 'Bob', 'Tracy')#classmates这个tuple不能变了，它也没有append()，insert()这样的方法。其他获取元素的方法和list是一样的，tuple使用(),list使用[]。
t=(1,2)
print(t)#(1,2)
t=()#定义空tuple
print(t)#()
t=(1)#括号()既可以表示tuple，又可以表示数学公式中的小括号
print(t)#1
t=(1,)#只有1个元素的tuple定义时必须加一个逗号,，来消除歧义
print(t)#(1,)
t = ('a', 'b', ['A', 'B'])
t[2][0] = 'X'
t[2][1] = 'Y'
print(t) | false |
feeeb57bf97b74bfbd42d3f0a507cc38f50f4e4f | ogaroh/lpthw | /ex3.py | 971 | 4.34375 | 4 | # PS:
# we are using the American standard in the order of execution of the arithmetic operations
# (PEMDAS - Parentheses, Exponents, Multiplication, Division, Addition, Subtraction)
print("I will now count my chickens: ")
# addition and division
print("Hens: ",25 + 30 / 6)
# subtraction, multiplication & modulus*
print("Roosters :", float(100 - 25 * 3 % 4))
# addition, subtraction, multiplication, division, modulus
print("Now I will count my eggs: ")
print(float(3 + 2 + 1 - 5 + 4 % 2 - 1 / 4 + 6))
# less than operation (comparator)
print("Is it true that 3 + 2 < 5 - 7?")
print(float(3 + 2) < float(5 - 7))
print("What is 3 + 2? ", float(3 + 2))
print("What is 5 - 7? ", float(5 - 7))
print("Oh that is why it's false.")
print("How about some more? ")
# greater than
print("Is it greater? ", 5 > -2)
# greater than or equal to comparator
print("Is it greater or equal? ", 5 >= -2)
# less than or equal to comparator
print("Is it less or equal? ", 5 <=-2) | true |
99e206828b296637d6454faaa00dad6a7933ad92 | ogaroh/lpthw | /ex15.py | 542 | 4.28125 | 4 | from sys import argv
# uses argv to get file names --> method 1
script_name, filename = argv
# creates the file object so that you can read or write to it
txt = open(filename)
print(f"here is your {filename} file.")
# shows the contents of the file specified
print(txt.read())
# requires user to manually enter the file name --> method 2
filename_again = input("Enter your file name: \n\t>>> ")
# open the file specified
txtfile_again = open(filename_again)
# prints out the contents of the file specified
print(txtfile_again.read()) | true |
79f5012df575349d232f21155c78cb473bbf5d61 | yulyzulu/holbertonschool-higher_level_programming | /0x07-python-test_driven_development/2-matrix_divided.py | 1,137 | 4.21875 | 4 | #!/usr/bin/python3
"""
Module to execute the function to divides elements of a matrix.
"""
def matrix_divided(matrix, div):
"""
Function that divides all elements of a matrix.
"""
if type(matrix) != list:
raise TypeError("matrix must be a matrix (list of lists)\
of integers/floats")
if div == 0:
raise ZeroDivisionError("division by zero")
if type(div) != int and type(div) != float:
raise TypeError("div must be a number")
if len(matrix) < 1:
raise TypeError("matrix must be a matrix (list of lists)\
of integers/floats")
for i in matrix:
if type(i) != list:
raise TypeError("matrix must be a matrix (list of lists)\
of integers/floats")
length = len(matrix[0])
if length != len(i):
raise TypeError("Each row of the matrix must have the same size")
for j in i:
if type(j) != int and type(j) != float:
raise TypeError("matrix must be a matrix (list of lists)\
of integers/floats")
return (list(map(lambda i: list(map(
lambda j: round(j / div, 2), i)), matrix)))
| true |
10b3e3ca4d8d51ef4bd07d04fbf90c5b0c11b571 | chethan-kt/Python-Exercises | /q46.py | 377 | 4.21875 | 4 | """
Question:
Define a class named Circle which can be constructed by a radius. The Circle class has a method which can compute the area.
Hints:
Use def methodName(self) to define a method.
"""
class Circle:
def __init__(self, rad):
self.radius = rad
def area(self):
print "Area of a circle is ", 3.14*(self.radius**2)
c1 = Circle(2)
c1.area()
| true |
2a3ed43cf2817ef3b0b8bf0246306834e17f745d | lucasrodrix/aula_python | /aula6.py | 1,369 | 4.375 | 4 | # #Aula 6 - Fundamentos em Python
# conjunto = {1,2,3,4}
# conjunto.add(5)
# conjunto.discard(3)
# print(conjunto)
conjunto1 = {1,2,3,4,5}
conjunto2 = {5,6,7,8,9}
conjuntoUniao = conjunto1.union(conjunto2)
print("União entre Conjunto 1 e 2: {}".format(conjuntoUniao))
conjuntoInter = conjunto1.intersection(conjunto2)
print("Intersecção entre o Conjunto 1 e 2: {}".format(conjuntoInter))
conjuntoDifer1 = conjunto1.difference(conjunto2)
conjuntoDifer2 = conjunto2.difference(conjunto1)
print("Diferença entre Conjunto 1 e 2: {}".format(conjuntoDifer1))
print("Diferença entre Conjunto 2 e 1: {}".format(conjuntoDifer2))
conjuntoDifeSimetr1 = conjunto1.symmetric_difference(conjunto2)
conjuntoDifeSimetr2 = conjunto2.symmetric_difference(conjunto1)
print("Diferença Simétrica entre Conjunto 1 e 2: {}".format(conjuntoDifeSimetr1))
print("Diferença Simétrica entre Conjunto 2 e 1: {}".format(conjuntoDifeSimetr2))
conjuntoA = {1,2,3}
conjuntoB = {1,2,3,4,5,6}
conjuntoSubset = conjuntoA.issubset(conjuntoB)
print("A é subconjunto de B: {}".format(conjuntoSubset))
conjuntoSuperset = conjuntoB.issuperset(conjuntoA)
print("B é um superconjunto de A: {}".format(conjuntoSuperset))
lista = ['cachorro', 'gato', 'gato', 'elefante']
print(lista)
conjuntoAnimais = set(lista)
print(conjuntoAnimais)
listaAnimais = list(conjuntoAnimais)
print(listaAnimais) | false |
e9625d7ba880a8c1adfacbb2902436faa8f3f091 | regithiel/python-homework | /homework_1.py | 1,128 | 4.4375 | 4 | # Catarina Soeiro
# January 26 2016
# homework_1.py
##### Template for Homework 1, exercises 1.2-1.5 ######
# Do your work for Exercise 1.2 here
print " | | "
print "-----"
print " | | "
print "-----"
print " | | "
print "********** Exercise 1.3 **********"
a = " | | "
b = "-----"
print a
print b
print a
print b
print a
print "********** Exercise 1.4 **********"
print "********* Part II *************"
a = (3*5)/(2+3)
print "a is " + str(a)
b = ((7+9)**0.5)*2
print "b is " + str(b)
c = (4-7)**3
print "c is " + str(c)
d = (-19+100)**0.25
print "d is " + str(d)
e = 6 % 4
print "e is " + str(e)
print "********* Part III *************"
#assign equations to variable names
e1 = (3+4)*5+(-10/2)
e2 = (3+4*5)+(-10/2)
#print result
print e1
print e2
print "********** Exercise 1.5 **********"
#collect name info from user
name1 = raw_input('Enter your first name: ')
name2 = raw_input('Enter your last name: ')
#collect birth date from user
print 'Enter your date of birth:'
mo = raw_input('Month? ')
day = raw_input('Day? ')
year = raw_input('Year? ')
#print result
print name1, name2, 'was born on', mo, day+',', year+'.'
| false |
fdf8fda907a1354ef5ba43ae5e0030186c0164c5 | kawalot/checkio | /Digits-Multiplication.py | 545 | 4.3125 | 4 | #You are given a positive integer. Your function should calculate the product of the digits excluding any zeroes.
#For example: The number given is 123405. The result will be 1*2*3*4*5=120 (don't forget to exclude zeroes).
#Input: A positive integer.
#Output: The product of the digits as an integer.
def checkio(number):
eval = 1
for digit in str(number):
if int(digit) == 0:
continue
else:
eval = eval * int(digit)
return eval
print(checkio(123405))
print(checkio(999))
print(checkio(1000))
print(checkio(1111)) | true |
2043bdaa42162dc495174f8034c3ca1c19bd8796 | kawalot/checkio | /The-Most-Numbers.py | 987 | 4.46875 | 4 | #Determine the difference between the smallest and the biggest numbers.
#You are given an array of numbers (floats).
#You should find the difference between the maximum and minimum element.
#Your function should be able to handle an undefined amount of arguments.
#For an empty argument list, the function should return 0.
#Floating-point numbers are represented in computer hardware as base 2 (binary) fractions.
#So we should check the result with ±0.001 precision.
#Think about how to work with an arbitrary number of arguments.
#Input: An arbitrary number of arguments as numbers (int, float).
#Output: The difference between maximum and minimum as a number (int, float).
def checkio(*args):
if len(args) < 1:
return 0
else:
min = args[0]
max = args[0]
for i in args:
if min > i:
min = i
if max < i:
max = i
print("min =", min, "max =", max )
return max - min
print(checkio(10.2, -2.2, 0, 1.1, 0.5))
| true |
52acb5bf56135c2731caa0d0b007c8528a01d2ef | SentientSam/Dice_Roll | /Dice_Roll.py | 2,722 | 4.375 | 4 | # Name : Dice_Roll.py
# Author : Samuel Lamb
# Purpose : Software to emulate rolling a dice, allowing for any size dice to be selected
import random
while(True):
validEntry = False # Variable to check for a valid (or supported) dice
Result = 0
Sides = int(input("Please enter number of sides (Enter 0 to leave): ")) # User enters an integer value for number os sides of dice
if (Sides == 10): # For use with DnD, if they are rolling a d10 then it is a percentage roll consisting of two dice
validEntry = True
randRoll = random.randint(0,9)
percentRoll = random.randrange(00,90,10)
print("You rolled:",percentRoll,"and:",randRoll)
if (randRoll == 0 and percentRoll == 0):
Result = 100
else:
Result = randRoll + percentRoll
if (Sides == 0): # If 0 is entered, exit program and flag validEntry so that the score is not posted
validEntry = True
print("Thank you! Good luck")
break
if (Sides == 8):
Quantity = int(input("How many do you want to roll?: "))
validEntry = True
while(Quantity != 0):
randRoll = random.randint(1,8)
Quantity = Quantity - 1
print("You rolled:",randRoll)
Result += randRoll
if (Sides == 6):
Quantity = int(input("How many do you want to roll?: "))
validEntry = True
while(Quantity != 0):
randRoll = random.randint(1,6)
Quantity = Quantity - 1
print("You rolled:",randRoll)
Result += randRoll
if (Sides == 4):
Quantity = int(input("How many do you want to roll?: "))
validEntry = True
while(Quantity != 0):
randRoll = random.randint(1,4)
Quantity = Quantity - 1
print("You rolled:",randRoll)
Result += randRoll
if (Sides == 20):
Quantity = int(input("How many do you want to roll?: "))
validEntry = True
while(Quantity != 0):
randRoll = random.randint(1,20)
Quantity = Quantity - 1
print("You rolled:",randRoll)
Result += randRoll
if (Sides == 12):
Quantity = int(input("How many do you want to roll?: "))
validEntry = True
while(Quantity != 0):
randRoll = random.randint(1,12)
Quantity = Quantity - 1
print("You rolled:",randRoll)
Result += randRoll
if(validEntry == False): # If not valid entry, repeat loop but inform user that the type of dice they entered is not supported
print("That type of dice is not supported or does not exist, please try again!")
if(Sides == 10): # If a d10, the result will be a percentile
print("Your score is: ",Result,"%")
else:
if(validEntry == True):
print("Your score is: ",Result)
| true |
59a5d9c2c5942457919e92613191e758a82829d7 | lijiyan77/API_pytest_new | /pyTest/aaatest/test_0330.py | 1,903 | 4.21875 | 4 | # -*- coding: UTF-8 -*-
# @File : test_0330.py
# author by : Li Jiyan
# date : 2020/3/30
# name=''
# while not name.strip():
# name = input('Please enter your name: ')
# print('hello, %s' % name)
# numbers=[0,1,2,3,4,5,6,7,8,9]
# for number in range(0,10):
# print(number)
# d={'x':1,'y':2,'z':3}
# for key,value in d.items():
# print(key,"corresponds to",value)
# names=['anne','beth','george','damon']
# ages=[12,45,32,102]
# for i in range(len(names)):
# print(names[i],'is',ages[i],'years old.')
# a=zip(names,ages)
# print(list(a))
# for name,age in list(zip(names,ages)):
# print(name,'is',age,'years old.')
# from math import sqrt
# for n in range(99,0,-1):
# root = sqrt(n)
# if root == int(root):
# print(n)
# break
# word = 'dummy'
# while word:
# word = input('please enter a word: ')
# print('The word was ' + word)
# while True:
# word = input('Please enter a word: ')
# if not word:break
# print("The word was " + word)
# from math import sqrt
# for n in range(99,81,-1):
# root = sqrt(n)
# if root == int(root):
# print(n)
# break
# else:
# print("Didn't find it")
# def hello(name):
# return ('hello, '+name+'!')
#
# print(hello('jojo'))
# def fibs(num):
# result = [0,1]
# for i in range(num-2):
# result.append(result[-2]+result[-1])
# return result
#
# print(fibs(10))
# def print_params_3(**params):
# print(params)
#
# print_params_3(x=1,y=2,z=3)
# def print_params_4(x,y,z=3,*pospar,**keypar):
# print(x,y,z)
# print(pospar)
# print(keypar)
#
# print_params_4(1,2,3,5,6,7,foo=1,bar=2)
def store(data,*full_names):
for full_name in full_names:
names = full_name.split()
if len(names) == 2:names.insert(1,'')
labels = 'first','middle','last'
for label,name in list(zip(labels,names)):
pass | false |
880889547dde4dbef94e8f232b96df99bb26d088 | RicardoCuevasR/Codeacademy | /Python/Shorts/likes.py | 713 | 4.15625 | 4 | def likes(names):
#your code here
if len(names) == 0:
print("no one likes this")
elif len(names) ==1:
print(names[0]+' likes this')
elif len(names) == 2:
print(names[0]+' and ' + names[1]+' like this')
elif len(names) == 3:
print(names[0]+', ' + names[1]+' and '+ names[2]+' like this')
else:
print(names[0]+', ' + names[1]+' and '+str(len(names)-2)+' others like this')
likes([]), 'no one likes this'
likes(['Peter']), 'Peter likes this'
likes(['Jacob', 'Alex']), 'Jacob and Alex like this'
likes(['Max', 'John', 'Mark']), 'Max, John and Mark like this'
likes(['Alex', 'Jacob', 'Mark', 'Max']), 'Alex, Jacob and 2 others like this' | true |
7b555da54d5dfef0f46b1357b2ed2a4ad17ccb4b | igoraugustocostaesouza/SEII-IgorAugustoCostaeSouza | /Semana02/prog02.py | 1,730 | 4.46875 | 4 | #Autor: Igor Augusto
#Data: 16/03/2021
# Arithmetic Operators:
# Addition: 3 + 2
# Subtraction: 3 - 2
# Multiplication: 3 * 2
# Division: 3 / 2
# Floor Division: 3 // 2
# Exponent: 3 ** 2
# Modulus: 3 % 2
# Comparisons:
# Equal: 3 == 2
# Not Equal: 3 != 2
# Greater Than: 3 > 2
# Less Than: 3 < 2
# Greater or Equal: 3 >= 2
# Less or Equal: 3 <= 2
#Aritmética de divisão
print(3/2)
#Aritmética de pegar o resto inteiro da divisão
print(3//2)
#Utilização de parenteses para ordenar a as operações aritméticas
#Resultado será 7
print(3*2+1)
#Resultado será 9
print((2+1)*3)
#Incrementar uma variável
num = 1
num +=1
print (num) #resultado será 2
#Função abs = valor absoluto de um número
print(abs(-3)) #resultado será 3
#Função round = arredonda o número || pode-se informar a quantidade de casas para arredondamento
print(round(3.75)) #resultado será 4
print(round(3.75,1)) #resultado será 3.8
#--------- Operadores Lógicos ------------
num_1 = 3
num_2 = 2
#Vai verificar se num1 é igual ao num2, caso verdade True, caso falso False
print(num_1 == num_2) #resultado será False
#Vai verificar se num1 é diferente do num2, caso verdade True, caso falso False
print(num_1 != num_2) #resultado será True
#Vai verificar se num1 é maior do num2, caso verdade True, caso falso False
print(num_1 > num_2) #resultado será True
#Vai verificar se num1 é menor do num2, caso verdade True, caso falso False
print(num_1 < num_2) #resultado será False
#Converter strings de textos em números
#String no formato de texto
num_3 = '100'
num_4 = '200'
#Convertendo a string em inteiro
num_3 = int(num_3)
num_4 = int(num_4)
print(num_3 + num_4)
| false |
74c0161c03a4b03745500f1a5f48bb4d44bde202 | biswanathdehury01/OpenCV-All-Fundamentals | /03_Draw Shapes with Mouse Click Event using OpenCV_1_2.py | 2,192 | 4.34375 | 4 | ######################### Chap 3 - Draw Shapes with Mouse Click Event using OpenCV
# In[ ]:
# ### Drawing Blue Circles on Black Screen by Left Button Click on Mouse
# In[1]:
#Import Necessary Libraries
import cv2
import numpy as np
# Create a circle shape function to draw a circle on left button click event
def circle_shape(event,x,y,flagval,par):
if event == cv2.EVENT_LBUTTONDOWN:
cv2.circle(image_window,(x,y),50,(255,0,0),-1)
# (x,y) are treated as center of circle, with radius 50, with BGR, and -1 => a solid filled structure
# Naming the window so we can reference it
cv2.namedWindow(winname='Image_Window')
# Connecting the mouse button to the callback function
cv2.setMouseCallback('Image_Window',circle_shape)
# Creating a black image
image_window = np.zeros((1024,1024,3), np.uint8)
while True: #Keep the black image window open until we break with Esc key on keyboard
# Showing the image window
cv2.imshow('Image_Window',image_window)
if cv2.waitKey(20) & 0xFF == 27:
break
cv2.destroyAllWindows()
# ### Drawing Blue Circles on Black Screen by Left Button Click & Red Color Circle on Right Button Click on Mouse
# In[2]:
#Import Necessary Libraries
import cv2
import numpy as np
# Create a circle shape function to draw a blue circle on left button click & red circle on right button click event
def circle_shape(event,x,y,flagval,par):
if event == cv2.EVENT_LBUTTONDOWN: # left click event
cv2.circle(image_window,(x,y),50,(255,0,0),-1)
elif event == cv2.EVENT_RBUTTONDOWN: # Right Click Event
cv2.circle(image_window,(x,y),50,(0,0,255),-1)
# Naming the window for reference
cv2.namedWindow(winname='Image_Window')
# Connecting the mouse button to the callback function
cv2.setMouseCallback('Image_Window',circle_shape)
# Creating a black image
image_window = np.zeros((1024,1204,3), np.uint8)
while True: #Keep the black image window open until we break with Esc key on keyboard
# Showing the image window
cv2.imshow('Image_Window',image_window)
# Coming out of window by pressing Escape key
if cv2.waitKey(20) & 0xFF == 27:
break
cv2.destroyAllWindows() | true |
3162f2fd4cdc036ff2c5d738e84c02b0a103c0f3 | vinit911/python-practice-set | /list_1.py | 208 | 4.25 | 4 | '''
Python program to interchange first and last elements in a list
'''
l1 = [1,2,3,4,5,6]
print("List before modification:\t",l1)
l1[0],l1[-1] = l1[-1],l1[0]
print("List after modification: \t",l1) | false |
65ec5511e1077bc2ea20132d4fc884152b2d5694 | BauerJustin/Elements-of-Programming-Interviews-in-Python | /Ch.9 Binary Trees/9.15 Exterior/exterior.py | 1,153 | 4.125 | 4 | #code
def exterior(tree):
def leaf(node):
return not node.left and not node.right
def left(subtree, boundary):
if not subtree:
return []
output = [subtree] if boundary or leaf(subtree) else []
output += left(subtree.left, boundary)
output += left(subtree.right, boundary and not subtree.left)
return output
def right(subtree, boundary):
if not subtree:
return []
output = right(subtree.left, boundary and not subtree.right)
output += right(subtree.right, boundary)
output += [subtree] if boundary or leaf(subtree) else []
return output
return ([tree] + left(tree.left, True) + right(tree.right, True)) if tree else []
# Binary tree base code
class BinaryTreeNode:
def __init__(self,data=None,left=None,right=None,parent=None):
self.data = data
self.left = left
self.right = right
def print_list(A):
for i in A:
print(i.data)
tree = BinaryTreeNode(6, BinaryTreeNode(3, BinaryTreeNode(1, BinaryTreeNode(0), BinaryTreeNode(2)), BinaryTreeNode(5)))
# Test
print_list(exterior(tree)) | true |
ee5d83a77a0532313d10cbcee893239f05fd15b1 | FriendlyUser/code-algorithm-questions | /python/sample_amazon/eduactive-crack-amazon/number_missing_in_array.py | 495 | 4.1875 | 4 | """
1. Find the missing number in the array
You are given an array of positive numbers from 1 to n, such that all numbers from 1 to n are present except one number x. You have to find x. The input array is not sorted.
3 7 1 2 8 4 5
n = 8, missing number = 6
"""
def find_missing(input):
n = len(input) + 1
n_sum = sum(input)
expected_sum = n * (n + 1) / 2
missing_int = expected_sum - n_sum
return missing_int
input_list = [3, 7, 1, 2, 8, 4, 5]
find_missing(input_list)
| true |
1ffcdeb6e51ba01fc4b94da6e3b6e327ce8de210 | shereen141/learnpython | /pythonbasics/filewrite.py | 583 | 4.34375 | 4 | writeMe = "Some sample text"
'''
to open a file in python we use the open function which accepts the filename
and the mode in which the file is to be opened.If the file exists then the
existing file is openened otherwise a new file is created in the mode passed.
The mode can be either write(w) or append(a). where write overwrites the file contents
and append, appends to the existing content.
'''
fileToWrite = open("examplefilewrite.txt","a")
fileToWrite.write(writeMe)
#This is an important step which signifies that the operation with the file is
#complete.
fileToWrite.close()
| true |
b726cb1c56550af0e1c07dcb6382dd4da09bec07 | jeffrisandy/number_guessing_game | /guessing_game.py | 2,962 | 4.28125 | 4 | """
Python Web Development Techdegree
Project 1 - Number Guessing Game
--------------------------------
"""
import random
import os
def start_game():
"""Psuedo-code Hints
When the program starts, we want to:
------------------------------------
1. Display an intro/welcome message to the player.
2. Store a random number as the answer/solution.
3. Continuously prompt the player for a guess.
a. If the guess greater than the solution, display to the player "It's lower".
b. If the guess is less than the solution, display to the player "It's higher".
4. Once the guess is correct, stop looping, inform the user they "Got it"
and show how many attempts it took them to get the correct number.
5. Let the player know the game is ending, or something that indicates the game is over.
( You can add more features/enhancements if you'd like to. )
"""
# welcome message
welcome()
# initiate highscore value
high_score = 0
# set initial trial to zero
trial = 0
# actual random number
num = random.randint(1, 10)
while True:
trial += 1
guess = get_input()
if guess < num:
print("It is higher!")
elif guess > num:
print("It is lower!")
else:
# inform the user once the guess correct
print(f"\nYou got it. It took you {trial} tries.\n")
if high_score == 0:
# set high_score equal to trial when first attempt
high_score = trial
# the high score is the least number of trials
elif (trial < high_score):
high_score = trial
# take input whether player want to continue or not
game = input("Do you want to continue? [y/n] : ")
if game.lower() == 'y':
# reset trial
trial = 0
# re-generate actual random number
num = random.randint(1, 10)
welcome()
print(f"\nThe HIGHSCORE is {high_score}\n")
else:
print("\nThank you for playing, Good Bye!")
print(f"\nThe HIGHSCORE is {high_score}\n")
break
def get_input():
# ensure input is an int number and within range 1-10
while True:
guess = input("Pick a number between 1 and 10 : ")
try :
guess = int(guess)
if (guess < 1) or (guess > 10):
raise ValueError("Try again, your number is outside the guessing range")
except ValueError as err:
print(err)
else:
return guess
def clear_screen():
os.system('cls' if os.name == 'nt' else 'clear')
def welcome():
clear_screen()
print("-" * 38)
print(" Welcome to the Number Guessing Game!")
print("-" *38)
if __name__ == '__main__':
# Kick off the program by calling the start_game function.
start_game()
| true |
19fb4f046f9cf172b14966d89fa72c725fd32a3a | chuzhinoves/DevOps_Python_HW3 | /6.py | 998 | 4.46875 | 4 | """
Реализовать функцию int_func(), принимающую слово из
маленьких латинских букв и возвращающую его же, но с прописной первой буквой.
Например, print(int_func(‘text’)) -> Text.
Продолжить работу над заданием
В программу должна попадать строка из слов, разделенных пробелом.
Каждое слово состоит из латинских букв в нижнем регистре.
Сделать вывод исходной строки, но каждое слово должно начинаться с заглавной буквы.
Необходимо использовать написанную ранее функцию int_func().
"""
def int_func(word):
return word[0].upper() + word[1:]
sentence = input("enter any words: ").split()
print(" ".join([int_func(word) for word in sentence]))
| false |
203c7ee24ed65452344662a98a33aaa255b8b139 | sichkar-valentyn/Processing_json_files_in_Python | /json_format.py | 1,640 | 4.125 | 4 | # File: json_format.py
# Description: Examples on how to process json files in Python
# Environment: PyCharm and Anaconda environment
#
# MIT License
# Copyright (c) 2018 Valentyn N Sichkar
# github.com/sichkar-valentyn
#
# Reference to:
# [1] Valentyn N Sichkar. Examples on how to process json files in Python with help of json library // GitHub platform [Electronic resource]. URL: https://github.com/sichkar-valentyn/Processing_json_files_in_Python (date of access: XX.XX.XXXX)
# Working with files in json formats
import json
# Creating dictionaries with information about the students
student1 = {
'first_name': 'Greg',
'last_name': 'Dean',
'scores': [70, 80, 90],
'description': 'Good job, Greg',
'certificate': True
}
student2 = {
'first_name': 'Wirt',
'last_name': 'Wood',
'scores': [80, 80.2, 80],
'description': 'Nicely Done',
'certificate': True
}
# Creating a list with elements of dictionaries
data = [student1, student2]
# Showing the results with the help of library json
print(json.dumps(data, indent=4, sort_keys=True))
# Writing the data inside the file
with open('students.json', 'w') as f:
json.dump(data, f, indent=4, sort_keys=True)
# Loading data from json into the Python object as list with dictionaries
data_json = json.dumps(data, indent=4, sort_keys=True)
data_again = json.loads(data_json)
# Calculating the sum of all scores for the first student
print(sum(data_again[0]["scores"]))
# Loading data from json file
with open("students.json", "r") as f:
data_again = json.load(f)
# Calculating the sum of all scores for the second student
print(sum(data_again[1]["scores"]))
| true |
77908738d410ed8129e08f8e8f9c0daf425c3fb0 | johnytheunbravo/python | /challenge.py | 463 | 4.125 | 4 | # uppercase and reverse = banana and should get back ANANAB print the result
def uppercase_and_reverse(word):
result = word[::-1]
return result
print(uppercase_and_reverse("do not go gentle into that good thing").upper())
print(uppercase_and_reverse("lol i forgot what mattan asked me to type.").upper())
print(uppercase_and_reverse("banana").upper())
# if you want to form a function
def uper_rev(x):
return x.upper()[::-1]
print(uper_rev("banana")) | true |
3a1b3832537abc58d395b143a5efb5549730cbf1 | eliffyildirim1/Wtech-Homeworks | /Homework-2/02_05_Errors_Exceptions_Handling.py | 1,155 | 4.34375 | 4 | #!/usr/bin/env python
# coding: utf-8
# # Assignments for "Errors and Exception Handling"
# 1. Let us define a division operation inside a function (using `def`) but to get an error, define the denominator as 0. So, type properly except statement.
# In[1]:
def division(number1, number2):
try:
result = number1 // number2
print("Result :", result)
except Exception as e:
print ("'{}' hatası oluştu ! ".format(e))
number1 = int(input("Enter the number to divide:"))
number2 = int(input("Enter the divisor:"))
division(number1,number2)
# 2. It is possible to get multiple errors after the execution of one try block. So, please define an error-exception issue with `NameError`
# In[2]:
try:
print(x)
except Exception as e:
print ("'{}' hatası oluştu ! ".format(e))
# 3. Please define a function and with this function, generate a `ValueError` exception simply by entering a string instead of numerical value.
# In[4]:
def num():
try:
x=int(input("Bir sayı girin : "))
print(x)
except ValueError:
print (ValueError)
num()
# In[ ]:
# In[ ]:
| true |
3814a8939c8f1598fb9069ceb0b0aa3fff6869b7 | kacpergrzenda/graph-theory-project | /PythonLabs/rectangle.py | 711 | 4.21875 | 4 | class Rectangle:
# Constructor.
def __init__(self, height, width):
self.height = height
self.width = width
# Calculate the area.
def area(self):
# Area is width times height.
return self.height * self.width
# Calculate the perimeter.
def perimeter(self):
# Perimeter is height times two plus width times two.
return (2 * self.height) + (2 * self.width)
# Create Instances.
r1 = Rectangle(10, 35)
r2 = Rectangle(2, 5)
print(f"The area of r1 = {r1.height} x {r1.width} = { r1.area() }")
print("The area of the second rectangle is", r2.area())
print("The perimeter of the other rectangle is", r2.perimeter())
| true |
f05a587b591f6af6d3f676dbaf918c4f1a2b6a13 | lianlian-YE/Mypycharm | /Python_file/write_blog/访问限制.py | 902 | 4.125 | 4 | class fruit(object): #定义一个类
atest='this is a test'
def __init__(self,name): #定义属性name
self.__name=name
@property
def name(self):
return self.__name
@name.setter
def name(self,name):
if isinstance(name,str):
self.__name=name
else:
raise ValueError('name must be str')
f1=fruit('apple') #实例化一个对象，name=apple
f2=fruit(123) #实例化一个对象，name=123,原则上，我们希望name是一个字符串类型，可是，无法进行参数验证
# print(f1.name) #apple
# print(f2.name) #123
print(f1.name)
f1.name='banana' #可以直接对属性进行修改
print(f1.name) #banana
print(f1.atest) #banana
| false |
f9e12f4dac413abd7442c2ec6690d4b8a551eefb | rpoliselit/python-for-dummies | /exercises/030.py | 492 | 4.3125 | 4 | """
Make a program that reads a integer number,
and returns its parity.
------------------------
Terminal customization (best choices):
\33[style;text;backm
style: 0,1,4,7.
text color: 30~37
background color: 40~47
"""
number = int(input('{}Enter a integer number: {}'.format('\33[1;37m','\33[m')))
print('\33[1;35m-=-\33[m'*10)
if (number % 2) == 0:
print('{} is {}even!{}'.format(number,'\33[1;30;41m','\33[m'))
else:
print('{} is {}odd!{}'.format(number,'\33[1;30;41m','\33[m'))
| true |
6fe882f36016d1dc46e77ef84fdb18fa4240b231 | rpoliselit/python-for-dummies | /exercises/017.py | 1,034 | 4.25 | 4 | """
Make a program that reads the adjacent and opposite catheta of
a rectangle triangle, and returns the hypotenuse length.
"""
import math
print('-'*20)
ac = float(input('Adjacent cathetus length: '))
oc = float(input('opposite cathetus length: '))
print('-'*20)
#calculating by math.hypot
h1 = math.hypot(ac, oc)
print('The hypotenuse length is {:.2f} by math.hypot.'.format(h1))
print('-'*20)
#calculating by Pythagoras' theorem
h2 = math.sqrt(ac ** 2 + oc ** 2)
print('The hypotenuse length is {:.2f} by Pythagorean theorem.'.format(h2))
print('-'*20)
#calculating by using the amgle
angle = math.atan(oc / ac)
h3 = ac / math.cos(angle)
h4 = oc / math.sin(angle)
angle_degrees = math.degrees(angle)
print('The angle between adjacent and opposite catheta is {:.1f}º.'.format(angle_degrees))
print('The hypotenuse length is {:.2f} by cos {:.1f}º = {:.2f}.'.format(h3, angle_degrees, math.cos(angle)))
print('The hypotenuse length is {:.2f} by sin {:.1f}º = {:.2f}.'.format(h4, angle_degrees, math.sin(angle)))
print('-'*20)
| false |
318fd6e1c833584aca292e523a30a3028bcb96ad | rpoliselit/python-for-dummies | /exercises/057.py | 532 | 4.1875 | 4 | """
Make a game that cpu choose a number,
and player must guess. The game runs
until player hit the guess.
"""
from random import randint
cpu = randint(0,10)
guess = player = 0
print('Guess a number between 0 and 10')
while player != cpu:
player = int(input())
guess += 1
if player > cpu:
print('Try a lesser one!')
elif player < cpu:
print('Try a greather one!')
print('You got it right with ', end = '')
if guess == 1:
print('the FIRST guess!')
else:
print('{} hunches!'.format(guess))
| true |
306cbf064c6d98330fc23646323d2287484bec96 | rpoliselit/python-for-dummies | /exercises/081.py | 679 | 4.3125 | 4 | """
Make a program that reads several values
and registers in a list.
Make other list with even numbers and
another one with odd numbers.
Show all lists.
"""
numbers, even, odd = [], [], []
while True:
num = input('Enter any number ['' stops]: ').strip().lower()
if num.isalnum() == False:
break
elif num.isnumeric() == False:
print('Try again. This is not a number.')
elif int(num) not in numbers:
numbers.append(int(num))
for n in numbers:
if n % 2 == 0:
even.append(n)
else:
odd.append(n)
print(f'All numbers: {sorted(numbers)}')
print(f'Even numbers: {sorted(even)}')
print(f'Odd numbers: {sorted(odd)}')
| true |
688eefa12611f6d19472efda8904f77311dbd17c | rpoliselit/python-for-dummies | /exercises/071.py | 558 | 4.40625 | 4 | """
Make a program that has a tuple
fully populated by a count, from
0 to 20. Your program should read
a number from the keyboard, and
display it written.
"""
tuple = ('zero', 'one', 'two', 'three', 'four', 'five', \
'six', 'seven', 'eight', 'nine', 'ten', 'eleven', \
'twelve', 'thirteen', 'fourteen', 'fifteen', \
'sixteen', 'seventeen', 'eighteen', 'nineteen', \
'twenty')
num = -1
while num not in range(0,21):
num = int(input('Enter a number between 0 and 20: '))
print(f'The chosen number is {tuple[num]}.')
| true |
5444981935267fb575c5962b0a460c4cbc1a7c47 | rpoliselit/python-for-dummies | /exercises/101.py | 829 | 4.5 | 4 | """
Make a program that has a factorial
function, which one gets to parameters:
1 - integer number
2 - logical value (optional) that indicates
whether the calculation process is shown or
not.
"""
def factorial(number, show=False):
"""
-> Calculate the factorial of a integer number.
:parameter number: Number to be calculate.
:parameter show: (optional) Show the calculation process.
:return: Factorial of number.
"""
num = count = 1
print('-'*40)
while count <= number:
num *= count
if show == True:
print(f'{count}', end = '')
if count < number:
print(end = ' x ')
elif count == number:
print(end = ' = ')
count += 1
return num
#Main program
#help(factorial)
print(factorial(5, show = True))
| true |
5c99608d5acae4298597d87a462602e20113ae94 | rpoliselit/python-for-dummies | /underscore/us001.py | 223 | 4.40625 | 4 | """
2 - The underscore is used to ignore a given value.
You can just assign the values to underscore.
"""
x, _ , z = (1,2,3)
print(x, z)
a, *_ , b = (1,2,3,4,5)
print(a,b)
for _ in range(10):
print('hello world')
| true |
1f6f0c463871286e1537f6725b94c07d0db09b23 | rpoliselit/python-for-dummies | /exercises/007.py | 342 | 4.21875 | 4 | """
Make a code that reads the score of a student, and calculate this mean.
"""
tests = []
number = int(input('What is the number of tests? '))
sum = 0
for i in range(number):
tests.append(float(input('Score of test {}: '.format(i+1))))
sum = sum + tests[i]
mean = sum / len(tests)
print('The mean score is: {:.2f}'.format(mean))
| true |
9c5fb759051dfcdc71638d79f49b907f282c3ff9 | rpoliselit/python-for-dummies | /exercises/062.py | 419 | 4.1875 | 4 | """
Make a program that show the n first
elements of Fibonacci.
0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144
"""
print('{:=^40}'.format(' FIBONACCI '))
num = int(input('\nHow many Fibonacci elements do you want? '))
n = count = 0
while count != num:
print('{}'.format(n), end = ' ')
count += 1
if n == 0:
n += 1
prev = 0
else:
n = n + prev
prev = n - prev
print('\n')
| false |
8c225192a42331d6b3b69792a9ee227435bdaa58 | nkanungo/session12_epfi | /calculator/cos_module.py | 439 | 4.34375 | 4 | """
Created on Tue Oct 27 16:30:27 2020
@author: Nihar Kanungo
"""
import math
__all__ = ['cos']
def cos(x):
'''
Calculates the cos of the given value
FInd out the derivative of the cos of the given value
'''
print(f'the value of cos of given input is: {math.cos(x)}')
return math.cos(x)
def der_cos(x):
print(f'the value of the derivative of cos for given input is : {-(math.sin(x))}')
return -(math.sin(x))
| true |
a7dfdb9022f668e3d07e6c9047fb2a6978ec14e6 | rohittwr55/LetsUpgradeAssignment | /Day 2 Assignment.py | 2,265 | 4.25 | 4 | # -*- coding: utf-8 -*-
"""
Created on Thu Sep 3 09:36:56 2020
@author: nitish
"""
#--------------------------------------
#List And their default functions
lis=[1,2,"Rohit"]
print("Lists",lis)
lis.append("Tiwari") #Adding new element
print(lis)
print(lis.count("Rohit")) #counting particular number
lis.reverse() #Reverse a string
print(lis)
lis.insert(1,"Mukesh") #to insert eelemet at particular index
print(lis)
lis2=lis.copy() #Copy list to another list
print(lis2)
lis2.extend(["Suresh"]) #To use of extend method
print(lis2)
lis2.remove("Tiwari") #To remove Particular element
print(lis2)
lis2.clear() #To use clear method
print(lis2)
lis2=[1,2,3,4]
lis2.remove(2) #To use remove method
print(lis2)
lis2.pop(2) # To use remove method
print(lis2)
#---------------------------------------
#Dictionary
dic={"Name":"Rohit","Age":24,"Degree":"MCA"} #Dictionary
print("Dictionaru 1",dic)
dic2=dic.copy() # Copy method
print("Dictionaru 2",dic2)
dic2["Height"]= 5.5 #Add new Item
print(dic2)
dic2["Name"]="Rohit Tiwari" # Updating perticular item
print(dic2)
del dic2["Height"] #Deletig particular item
print(dic2)
del dic2 #Deleting A dictionary
#-----------------------------------------
#Sets
#Defining Sets
st={"Rohit","Letsupgrade","Rohit","Letsupgrade",1,2,3}
print("Sets" ,st)
st.add("Hello") #Add element
print(st)
st2=st.copy() #copy Method
print("Sets 2",st2)
st2.update(["Tiwari","Python"]) #Update Method
print("Set2", st2)
st2.remove("Tiwari") #Remove a particular item
print("Set2",st2)
st3=st.union(st2) #USe of Union method
print("Set 3", st3)
st4=st.intersection(st2) #Intersection
print(st4)
#------------------------------------------
#Tupple
tup=("Rohit","Tiwari",410)
print("Tupple",tup)
x=tup.count(410) #Count
print(x)
#-------------------------------------------------
#String and Default method
name="Rohit tiwari is my name"
n=name.capitalize() #conver First leter to capital letter
print(n)
n=name.count("m")# To count number of word alphabet
print(n) #To find the word at perticular index
n=name.index("tiwari")
print(n)
n=name.lower() #To conver the letter to lower case
print(n)
n=name.upper() #To conver the letter to Upper case
print(n)
| true |
2d43a286af1687d2a612d120f4918e4b8ec8be11 | kwiseth/CIS-024 | /2_assign/math_basics_better.py | 978 | 4.34375 | 4 | #!/usr/bin/python3.6/math_basics_better.py
"""Exercise P2.5. Script that prompts user for two integers and then exercises
Python's math library to perform basic summary calculations, printing the results.
Script uses format operator.
"""
print("\nEnter two different integers as prompted below to see the sum,\ndifference, \
product, average, distance between the two numbers, and\nmaximum and minimum \
values.\n")
print("=" * 60)
first_num = int(input("Enter the first integer: "))
second_num = int(input("Enter the second integer: "))
print("-" * 60, "\n")
print("Sum: %10d" % (first_num + second_num))
print("Difference: %10d" % (first_num - second_num))
print("Product: %10d" % (first_num * second_num))
print("Average: %13.2f" % ((first_num + second_num)/2))
print("Distance: %10d" % (abs(first_num - second_num)))
print("Maximum: %10d" % (max(first_num, second_num)))
print("Minimum: %10d" % (min(first_num, second_num)))
print("-" * 60, "\n")
| true |
59030f740f8b1dac5375715c79012791a910a3cc | kwiseth/CIS-024 | /3_assign/letter_grades.py | 950 | 4.34375 | 4 | #!/usr/bin/python3.6/letter_grades.py
"""Exercise P3.12. User enters a letter grade at prompt and the script converts
to numeric value. Only VALID_INPUT entries are evaluated. The check for
letter_grade[0] != 'F' is not needed if F- and F+ are removed from VALID_INPUT.
"""
VALID_INPUT = {'A', 'A+', 'A-', 'B', 'B+', 'B-', 'C', 'C+', 'C-', 'D', 'D+',\
'D-', 'F', 'F-', 'F+'}
GRADE_POINTS = {'A' : 4.0, 'B' : 3.0, 'C' : 2.0, 'D' : 1.0, 'F' : 0}
letter_grade = input("Enter a letter grade: ").upper()
if not letter_grade in VALID_INPUT:
exit("Please enter a valid letter grade, A thru F only (A, A+, A-, B, B+, ... F): ")
else:
grade_pts = GRADE_POINTS[letter_grade[0]]
if letter_grade.endswith("-") and letter_grade[0] != 'F':
grade_pts = grade_pts - 0.3
if letter_grade.endswith("+") and letter_grade[0] != 'A' and letter_grade[0] != 'F':
grade_pts = grade_pts + 0.3
print("The numeric value is", grade_pts)
| true |
b04c318093fdbd1a9a046abb2a335f6e183d1593 | kwiseth/CIS-024 | /3_assign/tax_calculator.py | 1,584 | 4.28125 | 4 | #!/usr/bin/python3.6/tax_calculator.py
"""Exercise P3.25. Computes income tax due based on schedule in book. Tax rates
take into account Married or Single filing status. Rates also vary based on
three different income levels.
"""
# Initialize constant variables for the tax rates and rate limits.
RATE1 = 0.10
RATE2 = 0.15
RATE3 = 0.25
# These constants should be the threshold values between tax rates
RATE1_S_CAP = 8000.0
RATE2_S_CAP = 32000.0
RATE1_M_CAP = 16000.0
RATE2_M_CAP = 64000.0
BASE_TAX_RATE2_S = 800.0
BASE_TAX_RATE3_S = 4400.0
BASE_TAX_RATE2_M = 1600.0
BASE_TAX_RATE3_M = 8800.0
# Obtain income amount and filing status
income = float(input("Please enter your income: "))
filing_status = input("Please enter 's' for single or 'm' for married: ").lower()
total_tax = 0
# Calculate taxes due on the income amount based on filing status
if filing_status == "s" :
if income < RATE1_S_CAP :
total_tax = RATE1 * income
elif income > RATE2_S_CAP :
total_tax = BASE_TAX_RATE3_S + (income - RATE2_S_CAP) * RATE3
else :
total_tax = BASE_TAX_RATE2_S + (income - RATE1_S_CAP) * RATE2
elif filing_status == "m":
if income < RATE1_M_CAP :
total_tax = RATE1 * income
elif income > RATE2_M_CAP :
total_tax = BASE_TAX_RATE3_M + (income -RATE2_M_CAP) * RATE3
else :
total_tax = BASE_TAX_RATE2_M + (income - RATE1_M_CAP) * RATE2
elif filing_status != "m" or filing_status != "s":
exit("Please enter 'm' for married or 's' for single.")
# Print the results.
print("The tax due is ${:,.2f}".format(total_tax))
| true |
d54aba7f63e6ad92dc356165fcbaac321c64979a | kwiseth/CIS-024 | /2_assign/math_basics.py | 973 | 4.25 | 4 | #!/usr/bin/python3.6/math_basics.py
"""Exercise P2.4. Script that prompts user for two integers and then exercises Python's math
library to perform basic summary calculations, printing the results.
"""
print("=" * 80)
print("Enter two different integers when prompted below to see the sum, difference,\n\
product, average, distance between the two numbers, and maximum and\nminimum values.")
print("=" * 80)
first_num = int(input("Enter the first integer: "))
second_num = int(input("Enter the second integer: "))
print("Sum is ", first_num + second_num)
print("Difference between first number and second is ", first_num - second_num)
print("Product is ", first_num * second_num)
print("Average of the two numbers is ", (first_num + second_num)/2)
print("Distance between the two integer numbers is ", abs(first_num - second_num))
print("Number with the maximum value is ", max(first_num, second_num))
print("Number with minimum value is ", min(first_num, second_num))
| true |
94139007515084b9c89628f6da96ae392c6dc29a | jurelou/pypis | /pypis/services/html.py | 1,427 | 4.15625 | 4 | import html
from typing import Dict
def build_html_text(title: str = "", body: str = "") -> str:
"""Build a basic html page.
Args:
title (str): Title used in the HTML <head><title> tag
body (str): Content of the <body> HTML tag
Returns:
HTML string.
"""
indented_body = "\n ".join(body.split("\n"))
text_html = """\
<!DOCTYPE html>
<html>
<head>
<title>{title}</title>
</head>
<body>
{body}
</body>
</html>
""".format(
title=title, body=indented_body
)
return text_html
def dicts_to_anchors(d: Dict[str, Dict]) -> str:
"""Convert a dictionary to an HTML list of anchors.
Example:
The following dict:
{
"foo" : {
"href": "http://foo.org"
},
"bar": {
"href": "http://bar.org",
"color": "blue"
}
}
Will be converted to:
<a href="http://foo.org"> foo </a><br/>
<a href="http://bar.org" color="blue"> bar </a><br/>
"""
response = ""
for package_name, attributes in d.items():
for a, b in attributes.items():
print("MMMMMMMMMMMM", a, b)
string_attributes = " ".join(
[f'{a}="{html.escape(b)}"' for a, b in attributes.items()]
)
response = response + f"<a {string_attributes}>{package_name}</a><br/>\n"
return response
| true |
452e2508c61c4020d3eac97cf57ef1f5255baa0a | fernandoDB2016/FirstGitRepo | /Suspicious-test2.py | 2,198 | 4.1875 | 4 | # Simple examples defining functions
def firstFunction():
print('Functions are very cool!!')
firstFunction()
def convert_bitcoint_to_usd(btc):
amount = btc * 435
print(btc, ' is equivalent to: ', amount)
convert_bitcoint_to_usd(3.45)
convert_bitcoint_to_usd(4)
# Returning values from a function
# The function below returns the age of a girl (max of 7 years older) that can boy date
def calculate_dating_age(my_age):
girls_age = my_age//2 + 7;
return girls_age
my_age = 25
date_age = calculate_dating_age(my_age)
print('If you age is', my_age, 'you can date with girls', date_age, 'or older')
# Rather than doing for just a given age, we can do a table for different ages
print()
for i in range(15,60):
current_age = calculate_dating_age(i)
print('for boy age', i, 'can date girls',current_age,'or older')
# Default values for arguments
print()
def get_gender(sex='unknown'):
if sex == 'M':
sex = 'Male'
elif sex == 'F':
sex = 'Female'
print(sex)
get_gender()
get_gender('M')
get_gender('F')
# Variables Scope
aux = 77
def func1():
print(aux)
def func2():
aux = 88
print(aux)
func1()
func2()
# Keyword Arguments
def complex_function(name = 'Yo', surname = 'Soy', action = 'Sospechoso'):
print(name, surname, action)
complex_function()
complex_function(action = 'Super hero', name = 'Yo no a')
print('-------------------')
numbers = [6, 7, 8, 9, 10]
total = 0
for j in numbers:
print('number to add is', j)
total = total + j
print('total is', total)
'''
list_of_lists = [ [1, 2, 3], [4, 5, 6], [7, 8, 9]]
for list in list_of_lists:
print(list)
for x in list:
print(x)
'''
print()
# Function that receives any amount of arguments.
def any_arguments(*args):
total_sum = 0
total_sum1 = 0
print('argument value = ', args)
for i in args:
print('value i =', i)
total_sum = total_sum + i
total_sum1 += i
print('Total Sum =', total_sum)
print('Total Sum2 =', total_sum1)
print('One argument')
any_arguments(4)
print()
print('Two arguments')
any_arguments(3, 4)
print()
print('More arguments')
any_arguments(8, 20, 44, 50)
| true |
b8e7fc418a1ca093c0c937046a31e231b2719180 | Azer7/PY1 | /chap3.py | 1,459 | 4.53125 | 5 |
#Working with lists
#Just a list with element selection.
colors=["red", "blue", "green", "orange"]
print(colors)
print(colors[3].upper())
print(colors[-1].upper())
#New list with using format or f.
cars=["bmw", "mercedes", "audi", "toyota"]
print("My favourite car is {0} Land Cruiser \n".format(cars[3].title()))
print(f"My favourite car is {cars[0].upper()} M5")
#2 ways of adding new element to the list.
cars.append("suzuki")
print("\n",cars)
cars.insert(1, "jeep")
print("\n",cars)
#Deleting element from the list by element number or elemen value.
poped_car=cars.pop(2)
print("\n", cars)
print("===", poped_car, "===")
cars.remove("suzuki")
print("\n" , cars)
# Soring methods for lists
print("\n" , sorted(cars))
cars.reverse()
print("\n" ,cars)
cars.reverse()
print("\n" ,cars)
cars.sort()
print("\n" , cars)
cars.sort(reverse=True)
print("\n" , cars)
#Element q-ty in lists
print("\n" ,len(cars))
print(cars[-4])
#Homework
visit_places=["japan","korea","canada","new zeeland","italy"]
print(visit_places)
print(sorted(visit_places))
print(visit_places) #Sorted above didn't change the list itself
print(sorted(visit_places, reverse=True))
print(visit_places) #Sorted reverse above didn't change the list itself
visit_places.reverse()
print(visit_places)
visit_places.reverse()
print(visit_places)#Second reverse returned to the first stage
visit_places.sort()
print(visit_places)
visit_places.sort(reverse=True)
print(visit_places) | true |
e542e56ece9454291ea2396f8161e3fe1b16e64f | atnguyen1/AdventOfCode2017 | /src/4b.py | 2,135 | 4.5 | 4 | #!/usr/bin/env python
"""
A new system policy has been put in place that requires all accounts to use a passphrase instead of simply a password. A passphrase consists of a series of words (lowercase letters) separated by spaces.
To ensure security, a valid passphrase must contain no duplicate words.
For example:
aa bb cc dd ee is valid.
aa bb cc dd aa is not valid - the word aa appears more than once.
aa bb cc dd aaa is valid - aa and aaa count as different words.
The system's full passphrase list is available as your puzzle input. How many passphrases are valid?
For added security, yet another system policy has been put in place. Now, a valid passphrase must contain no two words that are anagrams of each other - that is, a passphrase is invalid if any word's letters can be rearranged to form any other word in the passphrase.
For example:
abcde fghij is a valid passphrase.
abcde xyz ecdab is not valid - the letters from the third word can be rearranged to form the first word.
a ab abc abd abf abj is a valid passphrase, because all letters need to be used when forming another word.
iiii oiii ooii oooi oooo is valid.
oiii ioii iioi iiio is not valid - any of these words can be rearranged to form any other word.
Under this new system policy, how many passphrases are valid?
"""
import argparse
import sys
PASS = 'data/4.txt'
def main(args):
"""Main."""
pass_data = dict()
valid = 0
with open(PASS, 'r') as fh:
for line in fh:
data = dict()
repeat = False
line = line.rstrip().split(' ')
for entry in line:
entry2 = sorted(list(entry))
entry2 = ' '.join(entry2)
if entry2 in data:
repeat = True
break
else:
data[entry2] = 1
if not repeat:
valid += 1
print valid
if __name__ == '__main__':
desc = 'Advent of Code 2'
parser = argparse.ArgumentParser(description=desc)
# parser.add_argument('dir1', type=str, help='Dir 1')
args = parser.parse_args()
main(args)
| true |
ce25838044eb5e061bee745c7c279e256cd5d5af | JuanchoVoltio/python-2021-II | /Taller05/Triangulos_Diana.py | 918 | 4.4375 | 4 | """ Ejercicio 1:
Dado los 3 ángulos de un triángulo definir que tipo de triángulo es.
"""
print("#################### TIPOS DE TRIÁNGULOS ##################")
angulo1 = int(input("Digite el primer ángulo: "))
angulo2 = int(input("Digite el segundo ángulo: "))
angulo3 = int(input("Digite el tercer ángulo: "))
if angulo1 > 0 and angulo2 > 0 and angulo3 > 0:
suma = angulo1 + angulo2 + angulo3
if suma == 180 and angulo1 == 90 or angulo2 == 90 or angulo3 == 90:
print("Es un triángulo rectángulo")
elif suma == 180 and angulo1 < 90 and angulo2 < 90 and angulo3 < 90:
print("Es un triángulo acutángulo")
elif suma == 180 and angulo1 > 90 or angulo2 > 90 or angulo3 > 90:
print("Es un triángulo escaleno")
else:
print("Los ángulos no corresponden a un triángulo (La suma de estos debe ser mayor que 180)")
else:
print("Los valores no aplican")
| false |
7cea4e88bd8635f59ba127bbf6851d8f4adc26cc | Uswa-Habeeb/PythonLearning | /Assignment#10.py | 1,487 | 4.46875 | 4 | # PROBLEM 1
# Create a program that will take all the necessary information from the user like
# (First Name, Last Name, Age, Gender, Religion, Nationality, Polling Station City, User's residential city etc.).
# Base on that information show that whether the user is allowed to cast the vote or not keeeping the following parameters in mind for decision making:
# User must be 18 or over.
# SOLUTION:
# User's Information:
FirstName = (input("Enter your First Name : "))
LastName = (input("Enter your Last Name : "))
Age = int(input("Enter your Age : " ))
Gender = (input("Enter your Gender : "))
Religion = (input("Enter your Religion : "))
Nationality = (input("Enter your Nationality : "))
Polling_Station_City = (input("Enter your Polling Station City : "))
Residential_City = (input("Enter your User's Residential City : "))
# Age = 17
if Age >= 18:
print(f"{FirstName} {LastName}, Age {Age}, Gender {Gender}, Religion {Religion}, Nationality {Nationality}, Polling Station City {Polling_Station_City}, Residential City {Residential_City} is ALLOWED TO CAST THE VOTE.")
else:
print(f"{FirstName}, {LastName}, Age {Age}, Gender {Gender}, Religion {Religion}, Nationality {Nationality}, Polling Station City {Polling_Station_City}, Residential City {Residential_City} is NOT ALLOWED TO CAST THE VOTE.")
# Uswa, Habeeb, Age 17, Gender Female, Religion Islam, Nationality Pakistani, Polling Station City Sahiwal, Residential City Sahiwal is NOT ALLOWED TO CAST THE VOTE.
| true |
3df59ff4121decc45813fd98c0462b4f31ec1d6d | HoldenGs/holbertonschool-higher_level_programming | /0x06-python-test_driven_development/0-add_integer.py | 536 | 4.28125 | 4 | #!/usr/bin/python3
"""
0-add_integer
1 Function:
add_integer
"""
def add_integer(a, b):
"""
add_integer: adds two integers
a: first integer
b: second integer
converts floats to ints; raises exceptions for non-number input
"""
try:
if isinstance(a, (int, float)) is False:
raise TypeError("a must be an integer")
if isinstance(b, (int, float)) is False:
raise TypeError("b must be an integer")
c = int(a) + int(b)
return c
except:
raise
| true |
acd415474a377d0f46e7d00214e3a21c49dcfdea | Ty-Allen/Allen_T_DataViz | /data/america_medals_by_year.py | 818 | 4.125 | 4 | import matplotlib.pyplot as plt
#draw a simple line chart showing population growth over the last 115 years
years = [1924, 1928, 1932, 1936, 1948, 1952, 1956, 1960, 1964, 1968, 1972, 1976, 1980, 1984, 1988, 1992, 1994, 1998, 2002, 2006, 2010, 2014]
medals = [13, 14, 45, 16, 16, 30, 26, 27, 8, 7, 25, 11, 30, 9, 7, 14, 21, 34, 84, 53, 98, 65]
#plot our chart with the data above, and also format the line color and width
plt.plot(years, medals, color=(10/255, 10/255, 255/255), linewidth=3.0)
#label on the left hand side
plt.ylabel("Medals Won")
#label on the bottom of the chart
plt.xlabel("Year")
#add a title to chart
plt.title("United States of America's Medal Count by Year", pad="15")
#run the show method (this lives inside the pyplot package)
#this will generate a graphic in a new window
plt.show()
| true |
52765eb47d6434526b4b923705a2b13d9fa22042 | RichardAfolabi/Scientific-Python | /dow_database.py | 2,804 | 4.15625 | 4 | """
Dow Database
-------------
This exercise covers with interacting with SQL databases from Python using the DB-API 2.0 interface. It will require for you to write a few basic SQL instructions. Take the time to refresh on them if you haven't written SQL commands in a while. Feel free to refer to http://www.sqlcourse.com/ or search for other resources.
The database table in the file 'dow2008.csv' has records holding the daily performance of the Dow Jones Industrial Average from the beginning of 2008. The table has the following columns (separated by a comma).
DATE OPEN HIGH LOW CLOSE VOLUME ADJ_CLOSE
2008-01-02 13261.82 13338.23 12969.42 13043.96 3452650000 13043.96
2008-01-03 13044.12 13197.43 12968.44 13056.72 3429500000 13056.72
2008-01-04 13046.56 13049.65 12740.51 12800.18 4166000000 12800.18
2008-01-07 12801.15 12984.95 12640.44 12827.49 4221260000 12827.49
2008-01-08 12820.9 12998.11 12511.03 12589.07 4705390000 12589.07
2008-01-09 12590.21 12814.97 12431.53 12735.31 5351030000 12735.31
... ... ... ... ... ... ...
1. Create a new sqlite database. Create a table that has the same structure
(use real for all the columns except the date column).
"""
import sqlite3 as db
conn = db.connect('dowbase.db')
cursor = conn.cursor()
cursor.execute(""" CREATE TABLE IF NOT EXISTS dowtable (Data text, Open float, High float, Low float, Close float, Volume float, Adj_Close float) """)
conn.commit()
#%%
""" 2. Insert all the records from dow.csv into the database. """
try:
with open("dow2008.csv") as fp:
fp.readline()
for row in fp:
value = row.strip().split(',')
cursor.execute("INSERT INTO dowtable VALUES (?, ?, ?, ?, ?, ?, ?)", value)
conn.commit()
except:
conn.rollback()
raise
else:
conn.commit()
#%%
"""
3. Select (and print out) the records from the database that have a volume greater than 5.5 billion. How many are there?
"""
point = 5500000000
cursor.execute(""" SELECT * FROM dowtable WHERE volume > ? """,(point,))
countx = 0
for row in cursor:
countx += 1
print(row)
cursor.execute("SELECT COUNT(*) FROM dowtable WHERE volume > 5500000000")
print "Number of entries:"
for row in cursor:
print row
print("\n -- %s rows --" %countx)
#%%
"""
Bonus
~~~~~
1. Select the records which have a spread between high and low that is greater than 4% and sort them in order of that spread.
"""
lpt = 0.04
cursor.execute(""" SELECT * FROM dowtable WHERE (High - Low)/Low > ? ORDER BY (High - Low)/Low """,(lpt,))
countx = 0
for row in cursor:
countx += 1
print(row)
print("\n -- %s entries have spread above 4 percent --" %countx)
#%%
cursor.close()
conn.close()
| true |
e393b61785254a6185d3bfe1e9c3f92ea9f5bd87 | shivaniraut5555/sorting-algorithms | /shell_python.py | 1,084 | 4.21875 | 4 | '''
Shell sort
By breaking the original list into a number of smaller sublists,each sublist is sorted using the insertion sort
It will move the items nearer to its original index
step1:Take the list of numbers
step2:Find out the gap(turnacted division 2)/incrementor
step3:Create the sublist based on gap and sort them using insertion sort algorithm
step4:reduce gap and repeat step3
step5:stop when gap is 0
'''
def shell_asc(li):
gap=len(li)//2#turncated gap
while(gap>0):
for i in range(gap,len(li)):
curr_ele=li[i]
pos=i
while(pos>=gap and curr_ele<li[pos-gap]):#comparison with index gap, for descending order " curr_ele>li[pos-gap]):"
li[pos]=li[pos-gap]
pos=pos-gap
li[pos]=curr_ele
print(f'In the gap {gap} list is:{li}')
gap=gap//2#reducing gap
return li
n=int(input("Enter the number of elements:"))#input of elements of list
li=[int(input("Enter elements:")) for x in range(n)]
print("Unsorted list:",li)
print('List in ascending order is:',shell_asc(li))
| true |
1b6854b1073fc7009538f9d4ba04155be29fbb58 | EdssonOziel/Programacion2doSemestre | /Funciones.py | 1,836 | 4.46875 | 4 | #Demostracion de los diferentes tipos de funciones
#Argumentos utilizados
# No recibe argumentos
# Recibe argumentos
# Tiene argumentos opcionales
#Retorno de valores
# No retorna valores
# Retorna valores
#Se pueden dar combinaciones de ambos aspectos
#Para declarar funciones se utiliza def
#def nombredefuncion():
#Codigo
#El codigo de la funcion es obligatorio. Si no hay codigo por el momento, usar pass
#Si una variable se declara fuera de procedimiento se dice que es global
variableglobal="soy global"
#Dentro de las funciones, si se quiere usar la variable global, debe anteponerse la palabra reservada global
def pendiente():
pass
def norecibeargumentos():
#Si se comenta la siguiente linea, usar la variable equivalente a declarar una version local de la variable; si no se comenta, usar la variable implica usar la global variableglobal
variableglobal=4
print("No recibe argumentos")
print(variableglobal)
#Los argumentos son dentro del parentesis en forma de lista separada por comas.
def recibeargumentos(fname, lname):
print(fname + " " + lname)
print(variableglobal)
#Un argumento es opcional cuando le asignas un valor al momento de su declaracion.
#Los argumentos opcionales siempre van al final de la lista de argumentos.
def argumentosopcionales(city, country = "Mexico"):
print("I am from " + city + ", " + country)
#Si se especifica return, la funcion retorna valores
#Cuidar que el flujo del programa siempre los retorne
#Se debe utilizar como expresion, atendiendo el retorno correspondiente
def elevoalcuadrado(x):
return x * x
def main():
#norecibeargumentos()
#recibeargumentos ("Felipe", "Ramirez")
#argumentosopcionales("Monterrey")
#argumentosopcionales("New York", "USA")
print(elevoalcuadrado(4))
#Creditos: FelipeRamirezPhD | false |
e0b3b47054e242abaabb1208e16734f2c6e7b592 | ea3/lists-Python | /lists.py | 836 | 4.15625 | 4 | # Indexing , slicing and concatenation of lists.
my_list = [1,2,3]
my_list = ['STRING', 100, 23.2]
print(len(my_list)) # prints the length of the list.
mylist = ['one','two','three']
print(mylist[0]) # prints elemtent at position 0.
print(mylist[1:]) # prints elements 1 and two from the list.
another_list = ['four', 'five']
newlist = mylist + another_list
print(newlist)
newlist[0] = 'ONE IN ALL CAPS'
print(newlist)
newlist.append('six')
print(newlist)
newlist.append('seven')
newlist.append(8)
newlist.append("NINE")
print(newlist)
newlist.pop()
print(newlist)
popped_item = newlist.pop()
print(popped_item)
print(newlist)
new_list = ['s','k','j','b','a','f','g']
num_list = [4,8,0,3,6,2,1]
new_list.sort()
print(new_list)
num_list.sort()
print(num_list)
num_list.reverse()
print(num_list)
new_list.reverse()
print(new_list)
| true |
bcf2cad6e00d7254fd6b60499e0daa2a124aa278 | JoyJoel/HelloWorld | /chapter22/person.py | 1,204 | 4.21875 | 4 | """人 类型
"""
#
# class Person: #先不设定对象类的定义
# pass
#
# from chapter22 import person
# from chapter22.person import Person
#
# p1 = Person()
# p1.name = 'Tom'
# p1.age = 20
#
# p2 = Person()
# p2.name = 'Jerry'
# p2.age = 23
#
# p1.say = lambda word:print('说', word)
# p1.say('优品课堂')
#
# print('-------------------------------------------')
# #构造函数就是初始化实例成员的功能函数!
# class Person: #事先设定对象类的定义
# def __init__(self): #self指的是三个步骤里实际实例的对象
# self.name = ''
# self.age = 0
# self.gender = ''
# 构造函数-例:
class Person:
def __init__(self, name='', age=0, gender='Male'):
#此处可写为 def __init__(self, name, age, gender),但因无默认值,各项均需传值,否则报错
self.name = name
self.age = age
self.gender = gender
# p = Person('Tom', 20, 'Male')
# p = Person(name='Tom', age=20, gender='Male')
def say(self, word):
print('{}说:{}'.format(self.name,word))
p = Person('Tom', 20)
p2 = Person('Jerry', 22)
print(p.name)
print(p2.name)
p.say('今天天气真好!')
p2.say('我想学Python!')
| false |
e8c2e10306f54d38bc472fb5cf46ae1bf0b06d26 | vietthanh179980123/VoVietThanh_58474_CA20B1 | /page_70_exercise_02.py | 216 | 4.15625 | 4 | """
Author: Võ Viết Thanh
Date: 15/09/2021
Program: Write a loop that prints your name 100 times. Each output should begin on a
new line.
Solution:
....
"""
for count in range(100):
print("Vo Viet Thanh")
| true |
e99e3ca19c906f4f8984edf2a72323e89c46f5bd | saikatsahoo160523/python | /FileHandling/Ass8a.py | 246 | 4.1875 | 4 | def longest_word(file3):
with open(file3, 'r') as infile:
words = infile.read().split()
maxlen = len(max(words, key=len))
return [word for word in words if len(word) == maxlen]
print(longest_word('file3.txt'))
| true |
a369cfc16af14d945ab3370f9b635f43c9a5c397 | saikatsahoo160523/python | /FileHandling/Ass10.py | 364 | 4.21875 | 4 | # 10. Write a Python program to get the file size of a plain file.
def file_size(python):
import os
statinfo = os.stat(python)
return statinfo.st_size
print("File size in bytes of the File3 is : ", file_size("file3.txt"))
'''OUTPUT :
[root@python FileHandling]# python Ass10.py
('File size in bytes of the File3 is : ', 41)'''
| true |
f2e2a6f793497629e3bb1bafc0274b7ce9840148 | saikatsahoo160523/python | /FileHandling/Ass8.py | 378 | 4.40625 | 4 | # 8. Write a python program to find the longest words.
def longest_word(file3):
with open(file3, 'r') as infile:
words = infile.read().split()
maxlen = len(max(words, key=len))
return [word for word in words if len(word) == maxlen]
print(longest_word('file3.txt'))
''' OUTPUT :
[root@python FileHandling]# python Ass8.py
['Raspberry']
'''
| true |
48592530c9935c09d8ebe002b2b552224ae55914 | Mazhar004/algo-in-python | /data_structure/linked_list/UniLinkedList.py | 1,731 | 4.125 | 4 | class Node():
def __init__(self, val=None):
'''
Node for Unidirectional Linked List
val = Value of the node
next_address = Address of next node linked with current node
'''
self.val = val
self.next_address = None
class UniLinkedList():
def __init__(self):
'''
Unidirectional Linked List
head = Linked list starting node
'''
self.head = None
def append(self, val):
'''
Append value in Linked List
val = Value append in Linked list at last position
'''
new_node = Node(val)
temp = self.head
if temp:
while temp.next_address:
temp = temp.next_address
temp.next_address = new_node
else:
self.head = new_node
def delete(self, val):
'''
Delete value from Linked List
val = Find matching value in Linked list to delete
'''
prev, current = None, self.head
while current:
if current.val == val:
break
prev, current = current, current.next_address
if current:
if current == self.head:
self.head = self.head.next_address
else:
prev.next_address = current.next_address
del current
print('Value deleted\n')
else:
print("Value not found in the list!")
self.traverse()
def traverse(self):
'''
Print all value of the Linked List
'''
temp = self.head
while temp:
print(temp.val, end=" ")
temp = temp.next_address
print("\n")
| true |
be7604df227006c9de4075194f0cbda22a23fc61 | clairejaja/project-euler | /src/main/python/problem2/even_fibonacci_numbers.py | 871 | 4.125 | 4 | # Claire Jaja
# 11/1/2014
#
# Project Euler
# Problem 2
# Even Fibonacci numbers
#
# Each new term in the Fibonacci sequence is generated by adding
# the previous two terms.
# By starting with 1 and 2, the first 10 terms will be:
# 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ...
# By considering the terms in the Fibonacci sequence
# whose values do not exceed four million,
# find the sum of the even-valued terms.
def main():
max_value = 4000000
# set up first three terms
previous_previous_term = 1
previous_term = 1
current_term = 2
my_sum = 0
while current_term < max_value:
if current_term % 2 == 0:
my_sum += current_term
previous_previous_term = previous_term
previous_term = current_term
current_term = previous_term + previous_previous_term
print(my_sum)
if __name__ == "__main__":
main()
| true |
3184028f7e719da8eac53ff60066beb2aaa497f8 | jrhodesy4/DojoAssignments | /Python/multiples.py | 577 | 4.21875 | 4 | #Part 1 this for loop runs through 1 to 1000 and prints all the numbers
for count in range(1, 1001):
print count
#Part 2 his for loop runs through 5 to 1000000 and prints all multiples of 5
for count in range(5, 1000001):
if count % 5 == 0:
print count
#Sum list- this program takes the sum of all the numbers in the list
a =[1, 2, 5, 10, 255, 3]
b = sum(a)
print b
#AvgList -this program first finds the sum of the list, then divides it by the number of values in the list, thus finding the average
a = [1, 2, 5, 10, 255, 3]
b = sum(a)
c = b/len(a)
print c
| true |
3ae8582cc2be6eac26d12ed12c76667e482b597e | MartiniBnu/DataScienceLearning | /python/map.py | 290 | 4.15625 | 4 | def double(x):
return x*2
value = 2
print(double(value))
#### If we pass a list, python will just duplicate the list
list = [1,2,3,4,5]
print(double(list))
### We can map the list to double all the list members
mapped_list = map(double, list)
for v in mapped_list:
print(v) | true |
b99a9e50590a845c6880260fc58ce856fcf04c9d | Abhishesh123/Python-list-coding-question-answer-interview | /list13.py | 778 | 4.28125 | 4 | # # Python | Convert a nested list into a flat list
# Input : l = [1, 2, [3, 4, [5, 6] ], 7, 8, [9, [10] ] ]
# Output : l = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
# Input : l = [[[‘item1’, ‘item2’]], [[‘item3’, ‘item4’]]]
# Output : l = [‘item1’, ‘item2’, ‘itm3, ‘item4”]
# Python code to flat a nested list with
# multiple levels of nesting allowed.
# input list
l = [1, 2, [3, 4, [5, 6]], 7, 8, [9, [10]]]
# output list
output = []
# function used for removing nested
# lists in python.
def reemovNestings(l):
for i in l:
if type(i) == list:
reemovNestings(i)
else:
output.append(i)
# Driver code
print ('The original list: ', l)
reemovNestings(l)
print ('The list after removing nesting: ', output)
| false |
6c9d08f1c9ac10a6258c195dc3fcc9bcaf00d284 | Chronocast/pythonRefresher | /newTest.py | 875 | 4.4375 | 4 | # The pound sign is used as a comment character in Python. Programmers
# use comments to annotate code. Python ignores everything after the
# comment character on a line.
# Notice how the 'print' command has been inserting a new line at the
# end of our strings.
print("The last three mayors of Philadelphia were:")
# We can insert newlines ourselves, using "\n".
print("Michael Nutter\nJohn Street\nEd Rendell\nObama Biden")
# "" Is the empty string. Since the print command will insert a
# newline at the end, this will print a newline by itself:
print("")
# Here's a new kind of printing: you can use triple quotes to create
# multiline strings.
print("""Jim Kenney was elected Mayor
of Philadelphia on November 3, 2015, beating
Republican challenger Melissa Murray Bailey.""")
print("")
# When you use triple quotes, whitespace is preserved.
print("""Jim Kenney received
84% of the
popular vote""") | true |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.