Reasoning Datasets
Collection
5 items • Updated
Datasets:
facts stringlengths 20 1.2k | rules stringlengths 72 3.47k | preferences stringlengths 0 418 | example stringlengths 308 4.53k | proof stringlengths 97 3.19k | goal stringlengths 15 39 | theory stringlengths 93 2.51k | label stringclasses 3
values | category stringclasses 15
values | id stringlengths 30 46 |
|---|---|---|---|---|---|---|---|---|---|
The donkey has some spinach. The sheep prepares armor for the donkey. The squid does not wink at the donkey. | Rule1: Regarding the donkey, if it has a leafy green vegetable, then we can conclude that it does not knock down the fortress of the sea bass. Rule2: If the squid does not wink at the donkey but the sheep prepares armor for the donkey, then the donkey knocks down the fortress that belongs to the sea bass unavoidably. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The donkey has some spinach. The sheep prepares armor for the donkey. The squid does not wink at the donkey. And the rules of the game are as follows. Rule1: Regarding the donkey, if it has a leafy green vegetable, then we can conclude ... | We know the squid does not wink at the donkey and the sheep prepares armor for the donkey, and according to Rule2 "if the squid does not wink at the donkey but the sheep prepares armor for the donkey, then the donkey knocks down the fortress of the sea bass", and Rule2 has a higher preference than the conflicting rules... | (donkey, knock, sea bass) | Facts:
(donkey, has, some spinach)
(sheep, prepare, donkey)
~(squid, wink, donkey)
Rules:
Rule1: (donkey, has, a leafy green vegetable) => ~(donkey, knock, sea bass)
Rule2: ~(squid, wink, donkey)^(sheep, prepare, donkey) => (donkey, knock, sea bass)
Preferences:
Rule2 > Rule1 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-0 |
The cat steals five points from the ferret. The tilapia raises a peace flag for the cat. The cat does not burn the warehouse of the raven. | Rule1: If the tilapia raises a flag of peace for the cat, then the cat is not going to learn elementary resource management from the lion. | A few players are playing a boardgame. The current state of the game is as follows. The cat steals five points from the ferret. The tilapia raises a peace flag for the cat. The cat does not burn the warehouse of the raven. And the rules of the game are as follows. Rule1: If the tilapia raises a flag of peace for the ca... | We know the tilapia raises a peace flag for the cat, and according to Rule1 "if the tilapia raises a peace flag for the cat, then the cat does not learn the basics of resource management from the lion", so we can conclude "the cat does not learn the basics of resource management from the lion". So the statement "the ca... | (cat, learn, lion) | Facts:
(cat, steal, ferret)
(tilapia, raise, cat)
~(cat, burn, raven)
Rules:
Rule1: (tilapia, raise, cat) => ~(cat, learn, lion)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-1 | |
The carp learns the basics of resource management from the puffin. The doctorfish does not show all her cards to the donkey. | Rule1: If at least one animal learns elementary resource management from the puffin, then the donkey eats the food of the turtle. Rule2: For the donkey, if the belief is that the doctorfish is not going to show her cards (all of them) to the donkey but the oscar burns the warehouse that is in possession of the donkey, ... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The carp learns the basics of resource management from the puffin. The doctorfish does not show all her cards to the donkey. And the rules of the game are as follows. Rule1: If at least one animal learns elementary resource management f... | We know the carp learns the basics of resource management from the puffin, and according to Rule1 "if at least one animal learns the basics of resource management from the puffin, then the donkey eats the food of the turtle", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the osc... | (donkey, eat, turtle) | Facts:
(carp, learn, puffin)
~(doctorfish, show, donkey)
Rules:
Rule1: exists X (X, learn, puffin) => (donkey, eat, turtle)
Rule2: ~(doctorfish, show, donkey)^(oscar, burn, donkey) => ~(donkey, eat, turtle)
Preferences:
Rule2 > Rule1 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-2 |
The cricket learns the basics of resource management from the dog but does not proceed to the spot right after the kudu. | Rule1: The cricket unquestionably removes one of the pieces of the halibut, in the case where the bat becomes an actual enemy of the cricket. Rule2: If you see that something learns elementary resource management from the dog but does not proceed to the spot that is right after the spot of the kudu, what can you certai... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The cricket learns the basics of resource management from the dog but does not proceed to the spot right after the kudu. And the rules of the game are as follows. Rule1: The cricket unquestionably removes one of the pieces of the halibu... | We know the cricket learns the basics of resource management from the dog and the cricket does not proceed to the spot right after the kudu, and according to Rule2 "if something learns the basics of resource management from the dog but does not proceed to the spot right after the kudu, then it does not remove from the ... | (cricket, remove, halibut) | Facts:
(cricket, learn, dog)
~(cricket, proceed, kudu)
Rules:
Rule1: (bat, become, cricket) => (cricket, remove, halibut)
Rule2: (X, learn, dog)^~(X, proceed, kudu) => ~(X, remove, halibut)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-3 |
The sun bear is named Lily. The canary does not respect the eel. The doctorfish does not hold the same number of points as the eel. | Rule1: If the eel has a name whose first letter is the same as the first letter of the sun bear's name, then the eel does not prepare armor for the dog. Rule2: For the eel, if the belief is that the canary does not respect the eel and the doctorfish does not hold the same number of points as the eel, then you can add "... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The sun bear is named Lily. The canary does not respect the eel. The doctorfish does not hold the same number of points as the eel. And the rules of the game are as follows. Rule1: If the eel has a name whose first letter is the same as... | We know the canary does not respect the eel and the doctorfish does not hold the same number of points as the eel, and according to Rule2 "if the canary does not respect the eel and the doctorfish does not hold the same number of points as the eel, then the eel, inevitably, prepares armor for the dog", and for the conf... | (eel, prepare, dog) | Facts:
(sun bear, is named, Lily)
~(canary, respect, eel)
~(doctorfish, hold, eel)
Rules:
Rule1: (eel, has a name whose first letter is the same as the first letter of the, sun bear's name) => ~(eel, prepare, dog)
Rule2: ~(canary, respect, eel)^~(doctorfish, hold, eel) => (eel, prepare, dog)
Preferences:
Rule1 > ... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-4 |
The raven has a low-income job, and is named Beauty. The starfish is named Bella. | Rule1: If the raven has a card whose color appears in the flag of Italy, then the raven rolls the dice for the polar bear. Rule2: If the raven has a name whose first letter is the same as the first letter of the starfish's name, then the raven does not roll the dice for the polar bear. Rule3: Regarding the raven, if it... | Rule1 is preferred over Rule2. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The raven has a low-income job, and is named Beauty. The starfish is named Bella. And the rules of the game are as follows. Rule1: If the raven has a card whose color appears in the flag of Italy, then the raven rolls the dice for the p... | We know the raven is named Beauty and the starfish is named Bella, both names start with "B", and according to Rule2 "if the raven has a name whose first letter is the same as the first letter of the starfish's name, then the raven does not roll the dice for the polar bear", and for the conflicting and higher priority ... | (raven, roll, polar bear) | Facts:
(raven, has, a low-income job)
(raven, is named, Beauty)
(starfish, is named, Bella)
Rules:
Rule1: (raven, has, a card whose color appears in the flag of Italy) => (raven, roll, polar bear)
Rule2: (raven, has a name whose first letter is the same as the first letter of the, starfish's name) => ~(raven, roll... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-5 |
The goldfish is named Tango, and needs support from the puffin. The goldfish parked her bike in front of the store. The mosquito is named Tessa. | Rule1: If something needs support from the puffin, then it becomes an enemy of the zander, too. | A few players are playing a boardgame. The current state of the game is as follows. The goldfish is named Tango, and needs support from the puffin. The goldfish parked her bike in front of the store. The mosquito is named Tessa. And the rules of the game are as follows. Rule1: If something needs support from the puffin... | We know the goldfish needs support from the puffin, and according to Rule1 "if something needs support from the puffin, then it becomes an enemy of the zander", so we can conclude "the goldfish becomes an enemy of the zander". So the statement "the goldfish becomes an enemy of the zander" is proved and the answer is "y... | (goldfish, become, zander) | Facts:
(goldfish, is named, Tango)
(goldfish, need, puffin)
(goldfish, parked, her bike in front of the store)
(mosquito, is named, Tessa)
Rules:
Rule1: (X, need, puffin) => (X, become, zander)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-6 | |
The puffin has a card that is blue in color, and is named Meadow. The snail is named Lily. | Rule1: Regarding the puffin, if it has more than eight friends, then we can conclude that it prepares armor for the whale. Rule2: Regarding the puffin, if it has a name whose first letter is the same as the first letter of the snail's name, then we can conclude that it does not prepare armor for the whale. Rule3: If th... | Rule1 is preferred over Rule2. Rule1 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The puffin has a card that is blue in color, and is named Meadow. The snail is named Lily. And the rules of the game are as follows. Rule1: Regarding the puffin, if it has more than eight friends, then we can conclude that it prepares a... | We know the puffin has a card that is blue in color, blue is a primary color, and according to Rule3 "if the puffin has a card with a primary color, then the puffin does not prepare armor for the whale", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the puffin has more than eigh... | (puffin, prepare, whale) | Facts:
(puffin, has, a card that is blue in color)
(puffin, is named, Meadow)
(snail, is named, Lily)
Rules:
Rule1: (puffin, has, more than eight friends) => (puffin, prepare, whale)
Rule2: (puffin, has a name whose first letter is the same as the first letter of the, snail's name) => ~(puffin, prepare, whale)
Ru... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-7 |
The cockroach eats the food of the donkey, and has 18 friends. The cockroach offers a job to the rabbit. | Rule1: Regarding the cockroach, if it has fewer than 10 friends, then we can conclude that it does not need support from the baboon. Rule2: Be careful when something eats the food that belongs to the donkey and also offers a job position to the rabbit because in this case it will surely need support from the baboon (th... | Rule1 is preferred over Rule2. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The cockroach eats the food of the donkey, and has 18 friends. The cockroach offers a job to the rabbit. And the rules of the game are as follows. Rule1: Regarding the cockroach, if it has fewer than 10 friends, then we can conclude tha... | We know the cockroach eats the food of the donkey and the cockroach offers a job to the rabbit, and according to Rule2 "if something eats the food of the donkey and offers a job to the rabbit, then it needs support from the baboon", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "... | (cockroach, need, baboon) | Facts:
(cockroach, eat, donkey)
(cockroach, has, 18 friends)
(cockroach, offer, rabbit)
Rules:
Rule1: (cockroach, has, fewer than 10 friends) => ~(cockroach, need, baboon)
Rule2: (X, eat, donkey)^(X, offer, rabbit) => (X, need, baboon)
Rule3: (cockroach, has, a card whose color is one of the rainbow colors) => ~(... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-8 |
The mosquito struggles to find food. | Rule1: If at least one animal burns the warehouse of the catfish, then the mosquito eats the food that belongs to the zander. Rule2: If the mosquito has difficulty to find food, then the mosquito does not eat the food of the zander. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The mosquito struggles to find food. And the rules of the game are as follows. Rule1: If at least one animal burns the warehouse of the catfish, then the mosquito eats the food that belongs to the zander. Rule2: If the mosquito has diff... | We know the mosquito struggles to find food, and according to Rule2 "if the mosquito has difficulty to find food, then the mosquito does not eat the food of the zander", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "at least one animal burns the warehouse of the catfish", so we ... | (mosquito, eat, zander) | Facts:
(mosquito, struggles, to find food)
Rules:
Rule1: exists X (X, burn, catfish) => (mosquito, eat, zander)
Rule2: (mosquito, has, difficulty to find food) => ~(mosquito, eat, zander)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-9 |
The lion attacks the green fields whose owner is the viperfish but does not show all her cards to the squirrel. | Rule1: Be careful when something winks at the octopus and also attacks the green fields of the viperfish because in this case it will surely not roll the dice for the cow (this may or may not be problematic). Rule2: If you are positive that one of the animals does not show her cards (all of them) to the squirrel, you c... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The lion attacks the green fields whose owner is the viperfish but does not show all her cards to the squirrel. And the rules of the game are as follows. Rule1: Be careful when something winks at the octopus and also attacks the green f... | We know the lion does not show all her cards to the squirrel, and according to Rule2 "if something does not show all her cards to the squirrel, then it rolls the dice for the cow", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the lion winks at the octopus", so we can conclude "... | (lion, roll, cow) | Facts:
(lion, attack, viperfish)
~(lion, show, squirrel)
Rules:
Rule1: (X, wink, octopus)^(X, attack, viperfish) => ~(X, roll, cow)
Rule2: ~(X, show, squirrel) => (X, roll, cow)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-10 |
The crocodile removes from the board one of the pieces of the cockroach. The meerkat becomes an enemy of the cockroach. | Rule1: If the crocodile removes from the board one of the pieces of the cockroach and the meerkat becomes an enemy of the cockroach, then the cockroach will not need the support of the buffalo. Rule2: If at least one animal owes money to the snail, then the cockroach needs support from the buffalo. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The crocodile removes from the board one of the pieces of the cockroach. The meerkat becomes an enemy of the cockroach. And the rules of the game are as follows. Rule1: If the crocodile removes from the board one of the pieces of the co... | We know the crocodile removes from the board one of the pieces of the cockroach and the meerkat becomes an enemy of the cockroach, and according to Rule1 "if the crocodile removes from the board one of the pieces of the cockroach and the meerkat becomes an enemy of the cockroach, then the cockroach does not need suppor... | (cockroach, need, buffalo) | Facts:
(crocodile, remove, cockroach)
(meerkat, become, cockroach)
Rules:
Rule1: (crocodile, remove, cockroach)^(meerkat, become, cockroach) => ~(cockroach, need, buffalo)
Rule2: exists X (X, owe, snail) => (cockroach, need, buffalo)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-11 |
The baboon has a hot chocolate. The polar bear is named Milo. The panda bear does not respect the baboon. The pig does not learn the basics of resource management from the baboon. | Rule1: For the baboon, if the belief is that the panda bear does not respect the baboon and the pig does not learn the basics of resource management from the baboon, then you can add "the baboon offers a job to the puffin" to your conclusions. Rule2: Regarding the baboon, if it has something to carry apples and oranges... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The baboon has a hot chocolate. The polar bear is named Milo. The panda bear does not respect the baboon. The pig does not learn the basics of resource management from the baboon. And the rules of the game are as follows. Rule1: For the... | We know the panda bear does not respect the baboon and the pig does not learn the basics of resource management from the baboon, and according to Rule1 "if the panda bear does not respect the baboon and the pig does not learn the basics of resource management from the baboon, then the baboon, inevitably, offers a job t... | (baboon, offer, puffin) | Facts:
(baboon, has, a hot chocolate)
(polar bear, is named, Milo)
~(panda bear, respect, baboon)
~(pig, learn, baboon)
Rules:
Rule1: ~(panda bear, respect, baboon)^~(pig, learn, baboon) => (baboon, offer, puffin)
Rule2: (baboon, has, something to carry apples and oranges) => ~(baboon, offer, puffin)
Rule3: (bab... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-12 |
The grizzly bear sings a victory song for the lion. The koala raises a peace flag for the lion. The lion owes money to the donkey. | Rule1: For the lion, if the belief is that the koala raises a peace flag for the lion and the grizzly bear sings a song of victory for the lion, then you can add that "the lion is not going to learn the basics of resource management from the carp" to your conclusions. Rule2: If you see that something does not steal fiv... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The grizzly bear sings a victory song for the lion. The koala raises a peace flag for the lion. The lion owes money to the donkey. And the rules of the game are as follows. Rule1: For the lion, if the belief is that the koala raises a p... | We know the koala raises a peace flag for the lion and the grizzly bear sings a victory song for the lion, and according to Rule1 "if the koala raises a peace flag for the lion and the grizzly bear sings a victory song for the lion, then the lion does not learn the basics of resource management from the carp", and for ... | (lion, learn, carp) | Facts:
(grizzly bear, sing, lion)
(koala, raise, lion)
(lion, owe, donkey)
Rules:
Rule1: (koala, raise, lion)^(grizzly bear, sing, lion) => ~(lion, learn, carp)
Rule2: ~(X, steal, black bear)^(X, owe, donkey) => (X, learn, carp)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-13 |
The hare is named Lily. The hippopotamus learns the basics of resource management from the hare. The parrot is named Pashmak. | Rule1: Regarding the hare, if it has a card whose color is one of the rainbow colors, then we can conclude that it does not wink at the turtle. Rule2: If the hippopotamus learns the basics of resource management from the hare, then the hare winks at the turtle. Rule3: If the hare has a name whose first letter is the sa... | Rule1 is preferred over Rule2. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The hare is named Lily. The hippopotamus learns the basics of resource management from the hare. The parrot is named Pashmak. And the rules of the game are as follows. Rule1: Regarding the hare, if it has a card whose color is one of th... | We know the hippopotamus learns the basics of resource management from the hare, and according to Rule2 "if the hippopotamus learns the basics of resource management from the hare, then the hare winks at the turtle", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the hare has a c... | (hare, wink, turtle) | Facts:
(hare, is named, Lily)
(hippopotamus, learn, hare)
(parrot, is named, Pashmak)
Rules:
Rule1: (hare, has, a card whose color is one of the rainbow colors) => ~(hare, wink, turtle)
Rule2: (hippopotamus, learn, hare) => (hare, wink, turtle)
Rule3: (hare, has a name whose first letter is the same as the first ... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-14 |
The carp has some kale. | Rule1: Regarding the carp, if it has a leafy green vegetable, then we can conclude that it does not remove from the board one of the pieces of the puffin. Rule2: If the carp works fewer hours than before, then the carp removes one of the pieces of the puffin. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The carp has some kale. And the rules of the game are as follows. Rule1: Regarding the carp, if it has a leafy green vegetable, then we can conclude that it does not remove from the board one of the pieces of the puffin. Rule2: If the c... | We know the carp has some kale, kale is a leafy green vegetable, and according to Rule1 "if the carp has a leafy green vegetable, then the carp does not remove from the board one of the pieces of the puffin", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the carp works fewer hou... | (carp, remove, puffin) | Facts:
(carp, has, some kale)
Rules:
Rule1: (carp, has, a leafy green vegetable) => ~(carp, remove, puffin)
Rule2: (carp, works, fewer hours than before) => (carp, remove, puffin)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-15 |
The kiwi knocks down the fortress of the aardvark, and published a high-quality paper. | Rule1: If you are positive that you saw one of the animals knocks down the fortress that belongs to the aardvark, you can be certain that it will also eat the food that belongs to the blobfish. | A few players are playing a boardgame. The current state of the game is as follows. The kiwi knocks down the fortress of the aardvark, and published a high-quality paper. And the rules of the game are as follows. Rule1: If you are positive that you saw one of the animals knocks down the fortress that belongs to the aar... | We know the kiwi knocks down the fortress of the aardvark, and according to Rule1 "if something knocks down the fortress of the aardvark, then it eats the food of the blobfish", so we can conclude "the kiwi eats the food of the blobfish". So the statement "the kiwi eats the food of the blobfish" is proved and the answe... | (kiwi, eat, blobfish) | Facts:
(kiwi, knock, aardvark)
(kiwi, published, a high-quality paper)
Rules:
Rule1: (X, knock, aardvark) => (X, eat, blobfish)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-16 | |
The blobfish owes money to the crocodile. The sun bear has a card that is black in color. The sun bear has a love seat sofa. | Rule1: The sun bear does not roll the dice for the caterpillar whenever at least one animal owes money to the crocodile. | A few players are playing a boardgame. The current state of the game is as follows. The blobfish owes money to the crocodile. The sun bear has a card that is black in color. The sun bear has a love seat sofa. And the rules of the game are as follows. Rule1: The sun bear does not roll the dice for the caterpillar whenev... | We know the blobfish owes money to the crocodile, and according to Rule1 "if at least one animal owes money to the crocodile, then the sun bear does not roll the dice for the caterpillar", so we can conclude "the sun bear does not roll the dice for the caterpillar". So the statement "the sun bear rolls the dice for the... | (sun bear, roll, caterpillar) | Facts:
(blobfish, owe, crocodile)
(sun bear, has, a card that is black in color)
(sun bear, has, a love seat sofa)
Rules:
Rule1: exists X (X, owe, crocodile) => ~(sun bear, roll, caterpillar)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-17 | |
The leopard got a well-paid job, and is named Tango. The tilapia is named Tessa. | Rule1: If the leopard has a high salary, then the leopard rolls the dice for the halibut. Rule2: Regarding the leopard, if it has a name whose first letter is the same as the first letter of the tilapia's name, then we can conclude that it does not roll the dice for the halibut. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The leopard got a well-paid job, and is named Tango. The tilapia is named Tessa. And the rules of the game are as follows. Rule1: If the leopard has a high salary, then the leopard rolls the dice for the halibut. Rule2: Regarding the le... | We know the leopard got a well-paid job, and according to Rule1 "if the leopard has a high salary, then the leopard rolls the dice for the halibut", and Rule1 has a higher preference than the conflicting rules (Rule2), so we can conclude "the leopard rolls the dice for the halibut". So the statement "the leopard rolls ... | (leopard, roll, halibut) | Facts:
(leopard, got, a well-paid job)
(leopard, is named, Tango)
(tilapia, is named, Tessa)
Rules:
Rule1: (leopard, has, a high salary) => (leopard, roll, halibut)
Rule2: (leopard, has a name whose first letter is the same as the first letter of the, tilapia's name) => ~(leopard, roll, halibut)
Preferences:
Rule... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-18 |
The carp winks at the jellyfish. The jellyfish has a card that is white in color. | Rule1: If the jellyfish has a card whose color appears in the flag of Italy, then the jellyfish does not prepare armor for the hippopotamus. | A few players are playing a boardgame. The current state of the game is as follows. The carp winks at the jellyfish. The jellyfish has a card that is white in color. And the rules of the game are as follows. Rule1: If the jellyfish has a card whose color appears in the flag of Italy, then the jellyfish does not prepare... | We know the jellyfish has a card that is white in color, white appears in the flag of Italy, and according to Rule1 "if the jellyfish has a card whose color appears in the flag of Italy, then the jellyfish does not prepare armor for the hippopotamus", so we can conclude "the jellyfish does not prepare armor for the hip... | (jellyfish, prepare, hippopotamus) | Facts:
(carp, wink, jellyfish)
(jellyfish, has, a card that is white in color)
Rules:
Rule1: (jellyfish, has, a card whose color appears in the flag of Italy) => ~(jellyfish, prepare, hippopotamus)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-19 | |
The hummingbird is named Lola. The hummingbird raises a peace flag for the amberjack. | Rule1: Regarding the hummingbird, if it has a name whose first letter is the same as the first letter of the polar bear's name, then we can conclude that it does not prepare armor for the elephant. Rule2: If something raises a flag of peace for the amberjack, then it prepares armor for the elephant, too. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The hummingbird is named Lola. The hummingbird raises a peace flag for the amberjack. And the rules of the game are as follows. Rule1: Regarding the hummingbird, if it has a name whose first letter is the same as the first letter of the... | We know the hummingbird raises a peace flag for the amberjack, and according to Rule2 "if something raises a peace flag for the amberjack, then it prepares armor for the elephant", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the hummingbird has a name whose first letter is the... | (hummingbird, prepare, elephant) | Facts:
(hummingbird, is named, Lola)
(hummingbird, raise, amberjack)
Rules:
Rule1: (hummingbird, has a name whose first letter is the same as the first letter of the, polar bear's name) => ~(hummingbird, prepare, elephant)
Rule2: (X, raise, amberjack) => (X, prepare, elephant)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-20 |
The bat is named Tarzan. The leopard gives a magnifier to the wolverine. The leopard is named Tessa. The leopard prepares armor for the crocodile. | Rule1: Regarding the leopard, if it has a name whose first letter is the same as the first letter of the bat's name, then we can conclude that it does not owe money to the tiger. | A few players are playing a boardgame. The current state of the game is as follows. The bat is named Tarzan. The leopard gives a magnifier to the wolverine. The leopard is named Tessa. The leopard prepares armor for the crocodile. And the rules of the game are as follows. Rule1: Regarding the leopard, if it has a name ... | We know the leopard is named Tessa and the bat is named Tarzan, both names start with "T", and according to Rule1 "if the leopard has a name whose first letter is the same as the first letter of the bat's name, then the leopard does not owe money to the tiger", so we can conclude "the leopard does not owe money to the ... | (leopard, owe, tiger) | Facts:
(bat, is named, Tarzan)
(leopard, give, wolverine)
(leopard, is named, Tessa)
(leopard, prepare, crocodile)
Rules:
Rule1: (leopard, has a name whose first letter is the same as the first letter of the, bat's name) => ~(leopard, owe, tiger)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-21 | |
The squirrel assassinated the mayor, and has seventeen friends. The swordfish does not know the defensive plans of the squirrel. | Rule1: Regarding the squirrel, if it voted for the mayor, then we can conclude that it raises a flag of peace for the moose. Rule2: Regarding the squirrel, if it has more than eight friends, then we can conclude that it raises a peace flag for the moose. Rule3: For the squirrel, if the belief is that the swordfish is n... | Rule3 is preferred over Rule1. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The squirrel assassinated the mayor, and has seventeen friends. The swordfish does not know the defensive plans of the squirrel. And the rules of the game are as follows. Rule1: Regarding the squirrel, if it voted for the mayor, then we... | We know the squirrel has seventeen friends, 17 is more than 8, and according to Rule2 "if the squirrel has more than eight friends, then the squirrel raises a peace flag for the moose", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "the gecko needs support from the squirrel", so ... | (squirrel, raise, moose) | Facts:
(squirrel, assassinated, the mayor)
(squirrel, has, seventeen friends)
~(swordfish, know, squirrel)
Rules:
Rule1: (squirrel, voted, for the mayor) => (squirrel, raise, moose)
Rule2: (squirrel, has, more than eight friends) => (squirrel, raise, moose)
Rule3: ~(swordfish, know, squirrel)^(gecko, need, squirr... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-22 |
The raven has a card that is blue in color, and is holding her keys. The doctorfish does not wink at the raven. The parrot does not wink at the raven. | Rule1: For the raven, if the belief is that the doctorfish does not wink at the raven and the parrot does not wink at the raven, then you can add "the raven does not eat the food of the panda bear" to your conclusions. | A few players are playing a boardgame. The current state of the game is as follows. The raven has a card that is blue in color, and is holding her keys. The doctorfish does not wink at the raven. The parrot does not wink at the raven. And the rules of the game are as follows. Rule1: For the raven, if the belief is that... | We know the doctorfish does not wink at the raven and the parrot does not wink at the raven, and according to Rule1 "if the doctorfish does not wink at the raven and the parrot does not winks at the raven, then the raven does not eat the food of the panda bear", so we can conclude "the raven does not eat the food of th... | (raven, eat, panda bear) | Facts:
(raven, has, a card that is blue in color)
(raven, is, holding her keys)
~(doctorfish, wink, raven)
~(parrot, wink, raven)
Rules:
Rule1: ~(doctorfish, wink, raven)^~(parrot, wink, raven) => ~(raven, eat, panda bear)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-23 | |
The crocodile has a basket. | Rule1: If the koala proceeds to the spot that is right after the spot of the crocodile, then the crocodile is not going to owe $$$ to the snail. Rule2: Regarding the crocodile, if it has something to carry apples and oranges, then we can conclude that it owes $$$ to the snail. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The crocodile has a basket. And the rules of the game are as follows. Rule1: If the koala proceeds to the spot that is right after the spot of the crocodile, then the crocodile is not going to owe $$$ to the snail. Rule2: Regarding the ... | We know the crocodile has a basket, one can carry apples and oranges in a basket, and according to Rule2 "if the crocodile has something to carry apples and oranges, then the crocodile owes money to the snail", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the koala proceeds to ... | (crocodile, owe, snail) | Facts:
(crocodile, has, a basket)
Rules:
Rule1: (koala, proceed, crocodile) => ~(crocodile, owe, snail)
Rule2: (crocodile, has, something to carry apples and oranges) => (crocodile, owe, snail)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-24 |
The aardvark has a bench. The aardvark has a card that is black in color. | Rule1: If the aardvark has something to sit on, then the aardvark does not respect the viperfish. Rule2: If the aardvark has more than 2 friends, then the aardvark respects the viperfish. Rule3: Regarding the aardvark, if it has a card whose color is one of the rainbow colors, then we can conclude that it respects the ... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The aardvark has a bench. The aardvark has a card that is black in color. And the rules of the game are as follows. Rule1: If the aardvark has something to sit on, then the aardvark does not respect the viperfish. Rule2: If the aardvark... | We know the aardvark has a bench, one can sit on a bench, and according to Rule1 "if the aardvark has something to sit on, then the aardvark does not respect the viperfish", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the aardvark has more than 2 friends" and for Rule3 we cann... | (aardvark, respect, viperfish) | Facts:
(aardvark, has, a bench)
(aardvark, has, a card that is black in color)
Rules:
Rule1: (aardvark, has, something to sit on) => ~(aardvark, respect, viperfish)
Rule2: (aardvark, has, more than 2 friends) => (aardvark, respect, viperfish)
Rule3: (aardvark, has, a card whose color is one of the rainbow colors) ... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-25 |
The parrot respects the panther. The squid does not know the defensive plans of the panther. | Rule1: If the parrot respects the panther and the squid does not know the defense plan of the panther, then, inevitably, the panther knows the defensive plans of the amberjack. Rule2: If at least one animal knows the defense plan of the buffalo, then the panther does not know the defense plan of the amberjack. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The parrot respects the panther. The squid does not know the defensive plans of the panther. And the rules of the game are as follows. Rule1: If the parrot respects the panther and the squid does not know the defense plan of the panther... | We know the parrot respects the panther and the squid does not know the defensive plans of the panther, and according to Rule1 "if the parrot respects the panther but the squid does not know the defensive plans of the panther, then the panther knows the defensive plans of the amberjack", and for the conflicting and hig... | (panther, know, amberjack) | Facts:
(parrot, respect, panther)
~(squid, know, panther)
Rules:
Rule1: (parrot, respect, panther)^~(squid, know, panther) => (panther, know, amberjack)
Rule2: exists X (X, know, buffalo) => ~(panther, know, amberjack)
Preferences:
Rule2 > Rule1 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-26 |
The leopard has some arugula. The leopard is named Blossom. The tilapia is named Bella. | Rule1: If the leopard has a name whose first letter is the same as the first letter of the tilapia's name, then the leopard does not attack the green fields whose owner is the gecko. Rule2: If the leopard has something to carry apples and oranges, then the leopard does not attack the green fields whose owner is the gec... | Rule3 is preferred over Rule1. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The leopard has some arugula. The leopard is named Blossom. The tilapia is named Bella. And the rules of the game are as follows. Rule1: If the leopard has a name whose first letter is the same as the first letter of the tilapia's name,... | We know the leopard is named Blossom and the tilapia is named Bella, both names start with "B", and according to Rule1 "if the leopard has a name whose first letter is the same as the first letter of the tilapia's name, then the leopard does not attack the green fields whose owner is the gecko", and for the conflicting... | (leopard, attack, gecko) | Facts:
(leopard, has, some arugula)
(leopard, is named, Blossom)
(tilapia, is named, Bella)
Rules:
Rule1: (leopard, has a name whose first letter is the same as the first letter of the, tilapia's name) => ~(leopard, attack, gecko)
Rule2: (leopard, has, something to carry apples and oranges) => ~(leopard, attack, g... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-27 |
The cockroach is named Paco. The puffin has a card that is violet in color, and is named Teddy. The puffin has thirteen friends, and purchased a luxury aircraft. | Rule1: Regarding the puffin, if it has fewer than 8 friends, then we can conclude that it knows the defense plan of the whale. Rule2: Regarding the puffin, if it has a card whose color is one of the rainbow colors, then we can conclude that it knows the defense plan of the whale. | A few players are playing a boardgame. The current state of the game is as follows. The cockroach is named Paco. The puffin has a card that is violet in color, and is named Teddy. The puffin has thirteen friends, and purchased a luxury aircraft. And the rules of the game are as follows. Rule1: Regarding the puffin, if ... | We know the puffin has a card that is violet in color, violet is one of the rainbow colors, and according to Rule2 "if the puffin has a card whose color is one of the rainbow colors, then the puffin knows the defensive plans of the whale", so we can conclude "the puffin knows the defensive plans of the whale". So the s... | (puffin, know, whale) | Facts:
(cockroach, is named, Paco)
(puffin, has, a card that is violet in color)
(puffin, has, thirteen friends)
(puffin, is named, Teddy)
(puffin, purchased, a luxury aircraft)
Rules:
Rule1: (puffin, has, fewer than 8 friends) => (puffin, know, whale)
Rule2: (puffin, has, a card whose color is one of the rainbo... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-28 | |
The grasshopper attacks the green fields whose owner is the swordfish. The starfish has 1 friend that is playful and three friends that are not. The starfish has a card that is green in color. | Rule1: If at least one animal attacks the green fields of the swordfish, then the starfish does not become an enemy of the panda bear. Rule2: Regarding the starfish, if it has a card with a primary color, then we can conclude that it becomes an actual enemy of the panda bear. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The grasshopper attacks the green fields whose owner is the swordfish. The starfish has 1 friend that is playful and three friends that are not. The starfish has a card that is green in color. And the rules of the game are as follows. R... | We know the grasshopper attacks the green fields whose owner is the swordfish, and according to Rule1 "if at least one animal attacks the green fields whose owner is the swordfish, then the starfish does not become an enemy of the panda bear", and Rule1 has a higher preference than the conflicting rules (Rule2), so we ... | (starfish, become, panda bear) | Facts:
(grasshopper, attack, swordfish)
(starfish, has, 1 friend that is playful and three friends that are not)
(starfish, has, a card that is green in color)
Rules:
Rule1: exists X (X, attack, swordfish) => ~(starfish, become, panda bear)
Rule2: (starfish, has, a card with a primary color) => (starfish, become, ... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-29 |
The lion eats the food of the rabbit. The panther is named Tarzan. The starfish offers a job to the rabbit. | Rule1: For the rabbit, if the belief is that the lion eats the food that belongs to the rabbit and the starfish offers a job to the rabbit, then you can add "the rabbit rolls the dice for the phoenix" to your conclusions. Rule2: Regarding the rabbit, if it has a name whose first letter is the same as the first letter o... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The lion eats the food of the rabbit. The panther is named Tarzan. The starfish offers a job to the rabbit. And the rules of the game are as follows. Rule1: For the rabbit, if the belief is that the lion eats the food that belongs to th... | We know the lion eats the food of the rabbit and the starfish offers a job to the rabbit, and according to Rule1 "if the lion eats the food of the rabbit and the starfish offers a job to the rabbit, then the rabbit rolls the dice for the phoenix", and for the conflicting and higher priority rule Rule2 we cannot prove t... | (rabbit, roll, phoenix) | Facts:
(lion, eat, rabbit)
(panther, is named, Tarzan)
(starfish, offer, rabbit)
Rules:
Rule1: (lion, eat, rabbit)^(starfish, offer, rabbit) => (rabbit, roll, phoenix)
Rule2: (rabbit, has a name whose first letter is the same as the first letter of the, panther's name) => ~(rabbit, roll, phoenix)
Preferences:
Rul... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-30 |
The pig struggles to find food. The swordfish attacks the green fields whose owner is the pig. | Rule1: If the swordfish attacks the green fields of the pig, then the pig is not going to remove one of the pieces of the leopard. | A few players are playing a boardgame. The current state of the game is as follows. The pig struggles to find food. The swordfish attacks the green fields whose owner is the pig. And the rules of the game are as follows. Rule1: If the swordfish attacks the green fields of the pig, then the pig is not going to remove on... | We know the swordfish attacks the green fields whose owner is the pig, and according to Rule1 "if the swordfish attacks the green fields whose owner is the pig, then the pig does not remove from the board one of the pieces of the leopard", so we can conclude "the pig does not remove from the board one of the pieces of ... | (pig, remove, leopard) | Facts:
(pig, struggles, to find food)
(swordfish, attack, pig)
Rules:
Rule1: (swordfish, attack, pig) => ~(pig, remove, leopard)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-31 | |
The panda bear sings a victory song for the cheetah. The cheetah does not give a magnifier to the lobster. | Rule1: If you see that something offers a job position to the squirrel but does not give a magnifier to the lobster, what can you certainly conclude? You can conclude that it does not offer a job position to the kangaroo. Rule2: The cheetah unquestionably offers a job to the kangaroo, in the case where the panda bear s... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The panda bear sings a victory song for the cheetah. The cheetah does not give a magnifier to the lobster. And the rules of the game are as follows. Rule1: If you see that something offers a job position to the squirrel but does not giv... | We know the panda bear sings a victory song for the cheetah, and according to Rule2 "if the panda bear sings a victory song for the cheetah, then the cheetah offers a job to the kangaroo", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the cheetah offers a job to the squirrel", s... | (cheetah, offer, kangaroo) | Facts:
(panda bear, sing, cheetah)
~(cheetah, give, lobster)
Rules:
Rule1: (X, offer, squirrel)^~(X, give, lobster) => ~(X, offer, kangaroo)
Rule2: (panda bear, sing, cheetah) => (cheetah, offer, kangaroo)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-32 |
The catfish is named Pablo. The grasshopper does not show all her cards to the catfish. | Rule1: If you are positive that one of the animals does not show all her cards to the catfish, you can be certain that it will not remove from the board one of the pieces of the wolverine. Rule2: If the grasshopper has a name whose first letter is the same as the first letter of the catfish's name, then the grasshopper... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The catfish is named Pablo. The grasshopper does not show all her cards to the catfish. And the rules of the game are as follows. Rule1: If you are positive that one of the animals does not show all her cards to the catfish, you can be ... | We know the grasshopper does not show all her cards to the catfish, and according to Rule1 "if something does not show all her cards to the catfish, then it doesn't remove from the board one of the pieces of the wolverine", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the grass... | (grasshopper, remove, wolverine) | Facts:
(catfish, is named, Pablo)
~(grasshopper, show, catfish)
Rules:
Rule1: ~(X, show, catfish) => ~(X, remove, wolverine)
Rule2: (grasshopper, has a name whose first letter is the same as the first letter of the, catfish's name) => (grasshopper, remove, wolverine)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-33 |
The crocodile has 14 friends, has a card that is orange in color, and hates Chris Ronaldo. The crocodile has a club chair. | Rule1: Regarding the crocodile, if it has a card whose color starts with the letter "o", then we can conclude that it respects the tilapia. Rule2: If the crocodile has something to drink, then the crocodile respects the tilapia. | A few players are playing a boardgame. The current state of the game is as follows. The crocodile has 14 friends, has a card that is orange in color, and hates Chris Ronaldo. The crocodile has a club chair. And the rules of the game are as follows. Rule1: Regarding the crocodile, if it has a card whose color starts wit... | We know the crocodile has a card that is orange in color, orange starts with "o", and according to Rule1 "if the crocodile has a card whose color starts with the letter "o", then the crocodile respects the tilapia", so we can conclude "the crocodile respects the tilapia". So the statement "the crocodile respects the ti... | (crocodile, respect, tilapia) | Facts:
(crocodile, has, 14 friends)
(crocodile, has, a card that is orange in color)
(crocodile, has, a club chair)
(crocodile, hates, Chris Ronaldo)
Rules:
Rule1: (crocodile, has, a card whose color starts with the letter "o") => (crocodile, respect, tilapia)
Rule2: (crocodile, has, something to drink) => (croco... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-34 | |
The rabbit is named Mojo. The jellyfish does not owe money to the wolverine. | Rule1: If something does not owe money to the wolverine, then it does not burn the warehouse of the panda bear. Rule2: If the jellyfish has a name whose first letter is the same as the first letter of the rabbit's name, then the jellyfish burns the warehouse of the panda bear. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The rabbit is named Mojo. The jellyfish does not owe money to the wolverine. And the rules of the game are as follows. Rule1: If something does not owe money to the wolverine, then it does not burn the warehouse of the panda bear. Rule2... | We know the jellyfish does not owe money to the wolverine, and according to Rule1 "if something does not owe money to the wolverine, then it doesn't burn the warehouse of the panda bear", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the jellyfish has a name whose first letter i... | (jellyfish, burn, panda bear) | Facts:
(rabbit, is named, Mojo)
~(jellyfish, owe, wolverine)
Rules:
Rule1: ~(X, owe, wolverine) => ~(X, burn, panda bear)
Rule2: (jellyfish, has a name whose first letter is the same as the first letter of the, rabbit's name) => (jellyfish, burn, panda bear)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-35 |
The polar bear has a basket, and has fourteen friends. The polar bear has a card that is orange in color. | Rule1: If the polar bear has a card whose color starts with the letter "r", then the polar bear does not need the support of the amberjack. Rule2: If the polar bear has something to carry apples and oranges, then the polar bear needs the support of the amberjack. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The polar bear has a basket, and has fourteen friends. The polar bear has a card that is orange in color. And the rules of the game are as follows. Rule1: If the polar bear has a card whose color starts with the letter "r", then the pol... | We know the polar bear has a basket, one can carry apples and oranges in a basket, and according to Rule2 "if the polar bear has something to carry apples and oranges, then the polar bear needs support from the amberjack", and Rule2 has a higher preference than the conflicting rules (Rule1), so we can conclude "the pol... | (polar bear, need, amberjack) | Facts:
(polar bear, has, a basket)
(polar bear, has, a card that is orange in color)
(polar bear, has, fourteen friends)
Rules:
Rule1: (polar bear, has, a card whose color starts with the letter "r") => ~(polar bear, need, amberjack)
Rule2: (polar bear, has, something to carry apples and oranges) => (polar bear, n... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-36 |
The raven has fourteen friends, is named Buddy, and does not need support from the jellyfish. The sun bear is named Tango. | Rule1: If you are positive that one of the animals does not need support from the jellyfish, you can be certain that it will not owe $$$ to the hippopotamus. | A few players are playing a boardgame. The current state of the game is as follows. The raven has fourteen friends, is named Buddy, and does not need support from the jellyfish. The sun bear is named Tango. And the rules of the game are as follows. Rule1: If you are positive that one of the animals does not need suppor... | We know the raven does not need support from the jellyfish, and according to Rule1 "if something does not need support from the jellyfish, then it doesn't owe money to the hippopotamus", so we can conclude "the raven does not owe money to the hippopotamus". So the statement "the raven owes money to the hippopotamus" is... | (raven, owe, hippopotamus) | Facts:
(raven, has, fourteen friends)
(raven, is named, Buddy)
(sun bear, is named, Tango)
~(raven, need, jellyfish)
Rules:
Rule1: ~(X, need, jellyfish) => ~(X, owe, hippopotamus)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-37 | |
The cow has 1 friend. | Rule1: If the cow has fewer than eight friends, then the cow knows the defensive plans of the phoenix. Rule2: If at least one animal removes one of the pieces of the ferret, then the cow does not know the defense plan of the phoenix. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The cow has 1 friend. And the rules of the game are as follows. Rule1: If the cow has fewer than eight friends, then the cow knows the defensive plans of the phoenix. Rule2: If at least one animal removes one of the pieces of the ferret... | We know the cow has 1 friend, 1 is fewer than 8, and according to Rule1 "if the cow has fewer than eight friends, then the cow knows the defensive plans of the phoenix", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "at least one animal removes from the board one of the pieces of... | (cow, know, phoenix) | Facts:
(cow, has, 1 friend)
Rules:
Rule1: (cow, has, fewer than eight friends) => (cow, know, phoenix)
Rule2: exists X (X, remove, ferret) => ~(cow, know, phoenix)
Preferences:
Rule2 > Rule1 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-38 |
The cockroach is named Tessa. The sun bear has a cappuccino, and is named Teddy. | Rule1: If the sun bear has a sharp object, then the sun bear does not need support from the cheetah. Rule2: Regarding the sun bear, if it has a leafy green vegetable, then we can conclude that it needs the support of the cheetah. Rule3: Regarding the sun bear, if it has a name whose first letter is the same as the firs... | Rule2 is preferred over Rule1. Rule2 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The cockroach is named Tessa. The sun bear has a cappuccino, and is named Teddy. And the rules of the game are as follows. Rule1: If the sun bear has a sharp object, then the sun bear does not need support from the cheetah. Rule2: Regar... | We know the sun bear is named Teddy and the cockroach is named Tessa, both names start with "T", and according to Rule3 "if the sun bear has a name whose first letter is the same as the first letter of the cockroach's name, then the sun bear does not need support from the cheetah", and for the conflicting and higher pr... | (sun bear, need, cheetah) | Facts:
(cockroach, is named, Tessa)
(sun bear, has, a cappuccino)
(sun bear, is named, Teddy)
Rules:
Rule1: (sun bear, has, a sharp object) => ~(sun bear, need, cheetah)
Rule2: (sun bear, has, a leafy green vegetable) => (sun bear, need, cheetah)
Rule3: (sun bear, has a name whose first letter is the same as the ... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-39 |
The cheetah has four friends that are kind and four friends that are not. The kudu respects the cheetah. The starfish knocks down the fortress of the cheetah. | Rule1: If the cheetah has fewer than sixteen friends, then the cheetah sings a victory song for the squid. | A few players are playing a boardgame. The current state of the game is as follows. The cheetah has four friends that are kind and four friends that are not. The kudu respects the cheetah. The starfish knocks down the fortress of the cheetah. And the rules of the game are as follows. Rule1: If the cheetah has fewer tha... | We know the cheetah has four friends that are kind and four friends that are not, so the cheetah has 8 friends in total which is fewer than 16, and according to Rule1 "if the cheetah has fewer than sixteen friends, then the cheetah sings a victory song for the squid", so we can conclude "the cheetah sings a victory son... | (cheetah, sing, squid) | Facts:
(cheetah, has, four friends that are kind and four friends that are not)
(kudu, respect, cheetah)
(starfish, knock, cheetah)
Rules:
Rule1: (cheetah, has, fewer than sixteen friends) => (cheetah, sing, squid)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-40 | |
The turtle gives a magnifier to the wolverine, and proceeds to the spot right after the cricket. The turtle has a card that is white in color, and invented a time machine. | Rule1: Regarding the turtle, if it has a card with a primary color, then we can conclude that it learns elementary resource management from the lion. Rule2: Be careful when something proceeds to the spot that is right after the spot of the cricket and also gives a magnifier to the wolverine because in this case it will... | Rule2 is preferred over Rule1. Rule2 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The turtle gives a magnifier to the wolverine, and proceeds to the spot right after the cricket. The turtle has a card that is white in color, and invented a time machine. And the rules of the game are as follows. Rule1: Regarding the t... | We know the turtle proceeds to the spot right after the cricket and the turtle gives a magnifier to the wolverine, and according to Rule2 "if something proceeds to the spot right after the cricket and gives a magnifier to the wolverine, then it does not learn the basics of resource management from the lion", and Rule2 ... | (turtle, learn, lion) | Facts:
(turtle, give, wolverine)
(turtle, has, a card that is white in color)
(turtle, invented, a time machine)
(turtle, proceed, cricket)
Rules:
Rule1: (turtle, has, a card with a primary color) => (turtle, learn, lion)
Rule2: (X, proceed, cricket)^(X, give, wolverine) => ~(X, learn, lion)
Rule3: (turtle, crea... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-41 |
The lion is named Cinnamon. The viperfish is named Tarzan, and knows the defensive plans of the cow. | Rule1: If something knows the defense plan of the cow, then it winks at the mosquito, too. Rule2: Regarding the viperfish, if it has a name whose first letter is the same as the first letter of the lion's name, then we can conclude that it does not wink at the mosquito. Rule3: Regarding the viperfish, if it has more th... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The lion is named Cinnamon. The viperfish is named Tarzan, and knows the defensive plans of the cow. And the rules of the game are as follows. Rule1: If something knows the defense plan of the cow, then it winks at the mosquito, too. Ru... | We know the viperfish knows the defensive plans of the cow, and according to Rule1 "if something knows the defensive plans of the cow, then it winks at the mosquito", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "the viperfish has more than three friends" and for Rule2 we cannot... | (viperfish, wink, mosquito) | Facts:
(lion, is named, Cinnamon)
(viperfish, is named, Tarzan)
(viperfish, know, cow)
Rules:
Rule1: (X, know, cow) => (X, wink, mosquito)
Rule2: (viperfish, has a name whose first letter is the same as the first letter of the, lion's name) => ~(viperfish, wink, mosquito)
Rule3: (viperfish, has, more than three f... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-42 |
The cheetah removes from the board one of the pieces of the panda bear. | Rule1: The panda bear does not prepare armor for the hare, in the case where the cheetah removes one of the pieces of the panda bear. Rule2: The panda bear prepares armor for the hare whenever at least one animal sings a victory song for the eagle. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The cheetah removes from the board one of the pieces of the panda bear. And the rules of the game are as follows. Rule1: The panda bear does not prepare armor for the hare, in the case where the cheetah removes one of the pieces of the ... | We know the cheetah removes from the board one of the pieces of the panda bear, and according to Rule1 "if the cheetah removes from the board one of the pieces of the panda bear, then the panda bear does not prepare armor for the hare", and for the conflicting and higher priority rule Rule2 we cannot prove the antecede... | (panda bear, prepare, hare) | Facts:
(cheetah, remove, panda bear)
Rules:
Rule1: (cheetah, remove, panda bear) => ~(panda bear, prepare, hare)
Rule2: exists X (X, sing, eagle) => (panda bear, prepare, hare)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-43 |
The blobfish is named Meadow. The puffin is named Casper. The puffin supports Chris Ronaldo. The doctorfish does not roll the dice for the puffin. | Rule1: For the puffin, if the belief is that the doctorfish is not going to roll the dice for the puffin but the cockroach holds the same number of points as the puffin, then you can add that "the puffin is not going to show her cards (all of them) to the tiger" to your conclusions. Rule2: Regarding the puffin, if it i... | Rule1 is preferred over Rule2. Rule1 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The blobfish is named Meadow. The puffin is named Casper. The puffin supports Chris Ronaldo. The doctorfish does not roll the dice for the puffin. And the rules of the game are as follows. Rule1: For the puffin, if the belief is that th... | We know the puffin supports Chris Ronaldo, and according to Rule2 "if the puffin is a fan of Chris Ronaldo, then the puffin shows all her cards to the tiger", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the cockroach holds the same number of points as the puffin", so we can co... | (puffin, show, tiger) | Facts:
(blobfish, is named, Meadow)
(puffin, is named, Casper)
(puffin, supports, Chris Ronaldo)
~(doctorfish, roll, puffin)
Rules:
Rule1: ~(doctorfish, roll, puffin)^(cockroach, hold, puffin) => ~(puffin, show, tiger)
Rule2: (puffin, is, a fan of Chris Ronaldo) => (puffin, show, tiger)
Rule3: (puffin, has a nam... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-44 |
The crocodile gives a magnifier to the cow. The hippopotamus is named Lily. The sun bear does not learn the basics of resource management from the cow. | Rule1: Regarding the cow, if it has a name whose first letter is the same as the first letter of the hippopotamus's name, then we can conclude that it rolls the dice for the canary. Rule2: If the crocodile gives a magnifier to the cow and the sun bear does not learn elementary resource management from the cow, then the... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The crocodile gives a magnifier to the cow. The hippopotamus is named Lily. The sun bear does not learn the basics of resource management from the cow. And the rules of the game are as follows. Rule1: Regarding the cow, if it has a name... | We know the crocodile gives a magnifier to the cow and the sun bear does not learn the basics of resource management from the cow, and according to Rule2 "if the crocodile gives a magnifier to the cow but the sun bear does not learns the basics of resource management from the cow, then the cow does not roll the dice fo... | (cow, roll, canary) | Facts:
(crocodile, give, cow)
(hippopotamus, is named, Lily)
~(sun bear, learn, cow)
Rules:
Rule1: (cow, has a name whose first letter is the same as the first letter of the, hippopotamus's name) => (cow, roll, canary)
Rule2: (crocodile, give, cow)^~(sun bear, learn, cow) => ~(cow, roll, canary)
Preferences:
Rule... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-45 |
The buffalo has a card that is white in color, and is named Teddy. The viperfish is named Luna, and does not hold the same number of points as the buffalo. | Rule1: Regarding the buffalo, if it has a name whose first letter is the same as the first letter of the viperfish's name, then we can conclude that it knocks down the fortress that belongs to the phoenix. Rule2: If the buffalo has a card whose color appears in the flag of Japan, then the buffalo knocks down the fortre... | A few players are playing a boardgame. The current state of the game is as follows. The buffalo has a card that is white in color, and is named Teddy. The viperfish is named Luna, and does not hold the same number of points as the buffalo. And the rules of the game are as follows. Rule1: Regarding the buffalo, if it ha... | We know the buffalo has a card that is white in color, white appears in the flag of Japan, and according to Rule2 "if the buffalo has a card whose color appears in the flag of Japan, then the buffalo knocks down the fortress of the phoenix", so we can conclude "the buffalo knocks down the fortress of the phoenix". So t... | (buffalo, knock, phoenix) | Facts:
(buffalo, has, a card that is white in color)
(buffalo, is named, Teddy)
(viperfish, is named, Luna)
~(viperfish, hold, buffalo)
Rules:
Rule1: (buffalo, has a name whose first letter is the same as the first letter of the, viperfish's name) => (buffalo, knock, phoenix)
Rule2: (buffalo, has, a card whose co... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-46 | |
The cat has 3 friends that are adventurous and five friends that are not, and has a card that is indigo in color. | Rule1: If the cat has a card whose color starts with the letter "i", then the cat does not show all her cards to the spider. | A few players are playing a boardgame. The current state of the game is as follows. The cat has 3 friends that are adventurous and five friends that are not, and has a card that is indigo in color. And the rules of the game are as follows. Rule1: If the cat has a card whose color starts with the letter "i", then the ca... | We know the cat has a card that is indigo in color, indigo starts with "i", and according to Rule1 "if the cat has a card whose color starts with the letter "i", then the cat does not show all her cards to the spider", so we can conclude "the cat does not show all her cards to the spider". So the statement "the cat sho... | (cat, show, spider) | Facts:
(cat, has, 3 friends that are adventurous and five friends that are not)
(cat, has, a card that is indigo in color)
Rules:
Rule1: (cat, has, a card whose color starts with the letter "i") => ~(cat, show, spider)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-47 | |
The sea bass has a card that is red in color. The sea bass has fourteen friends. | Rule1: Regarding the sea bass, if it has more than 6 friends, then we can conclude that it respects the octopus. | A few players are playing a boardgame. The current state of the game is as follows. The sea bass has a card that is red in color. The sea bass has fourteen friends. And the rules of the game are as follows. Rule1: Regarding the sea bass, if it has more than 6 friends, then we can conclude that it respects the octopus. ... | We know the sea bass has fourteen friends, 14 is more than 6, and according to Rule1 "if the sea bass has more than 6 friends, then the sea bass respects the octopus", so we can conclude "the sea bass respects the octopus". So the statement "the sea bass respects the octopus" is proved and the answer is "yes". | (sea bass, respect, octopus) | Facts:
(sea bass, has, a card that is red in color)
(sea bass, has, fourteen friends)
Rules:
Rule1: (sea bass, has, more than 6 friends) => (sea bass, respect, octopus)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-48 | |
The elephant raises a peace flag for the phoenix. The mosquito sings a victory song for the cockroach. | Rule1: If at least one animal raises a peace flag for the phoenix, then the cockroach does not know the defensive plans of the rabbit. Rule2: If the mosquito sings a victory song for the cockroach and the polar bear proceeds to the spot that is right after the spot of the cockroach, then the cockroach knows the defensi... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The elephant raises a peace flag for the phoenix. The mosquito sings a victory song for the cockroach. And the rules of the game are as follows. Rule1: If at least one animal raises a peace flag for the phoenix, then the cockroach does ... | We know the elephant raises a peace flag for the phoenix, and according to Rule1 "if at least one animal raises a peace flag for the phoenix, then the cockroach does not know the defensive plans of the rabbit", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the polar bear proceed... | (cockroach, know, rabbit) | Facts:
(elephant, raise, phoenix)
(mosquito, sing, cockroach)
Rules:
Rule1: exists X (X, raise, phoenix) => ~(cockroach, know, rabbit)
Rule2: (mosquito, sing, cockroach)^(polar bear, proceed, cockroach) => (cockroach, know, rabbit)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-49 |
The whale has a hot chocolate. The whale supports Chris Ronaldo. | Rule1: Regarding the whale, if it has a leafy green vegetable, then we can conclude that it shows all her cards to the kiwi. Rule2: Regarding the whale, if it is a fan of Chris Ronaldo, then we can conclude that it shows all her cards to the kiwi. Rule3: The whale does not show all her cards to the kiwi, in the case wh... | Rule3 is preferred over Rule1. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The whale has a hot chocolate. The whale supports Chris Ronaldo. And the rules of the game are as follows. Rule1: Regarding the whale, if it has a leafy green vegetable, then we can conclude that it shows all her cards to the kiwi. Rule... | We know the whale supports Chris Ronaldo, and according to Rule2 "if the whale is a fan of Chris Ronaldo, then the whale shows all her cards to the kiwi", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "the hummingbird removes from the board one of the pieces of the whale", so we ... | (whale, show, kiwi) | Facts:
(whale, has, a hot chocolate)
(whale, supports, Chris Ronaldo)
Rules:
Rule1: (whale, has, a leafy green vegetable) => (whale, show, kiwi)
Rule2: (whale, is, a fan of Chris Ronaldo) => (whale, show, kiwi)
Rule3: (hummingbird, remove, whale) => ~(whale, show, kiwi)
Preferences:
Rule3 > Rule1
Rule3 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-50 |
The lion gives a magnifier to the moose. The moose is named Max. The starfish is named Peddi. The raven does not show all her cards to the moose. | Rule1: If the raven does not show all her cards to the moose however the lion gives a magnifying glass to the moose, then the moose will not owe $$$ to the rabbit. Rule2: Regarding the moose, if it has a name whose first letter is the same as the first letter of the starfish's name, then we can conclude that it owes $$... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The lion gives a magnifier to the moose. The moose is named Max. The starfish is named Peddi. The raven does not show all her cards to the moose. And the rules of the game are as follows. Rule1: If the raven does not show all her cards ... | We know the raven does not show all her cards to the moose and the lion gives a magnifier to the moose, and according to Rule1 "if the raven does not show all her cards to the moose but the lion gives a magnifier to the moose, then the moose does not owe money to the rabbit", and for the conflicting and higher priority... | (moose, owe, rabbit) | Facts:
(lion, give, moose)
(moose, is named, Max)
(starfish, is named, Peddi)
~(raven, show, moose)
Rules:
Rule1: ~(raven, show, moose)^(lion, give, moose) => ~(moose, owe, rabbit)
Rule2: (moose, has a name whose first letter is the same as the first letter of the, starfish's name) => (moose, owe, rabbit)
Rule3:... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-51 |
The kangaroo knows the defensive plans of the tiger. The tiger has a cello. The swordfish does not become an enemy of the tiger. | Rule1: For the tiger, if the belief is that the swordfish does not become an enemy of the tiger but the kangaroo knows the defense plan of the tiger, then you can add "the tiger knows the defensive plans of the cockroach" to your conclusions. Rule2: Regarding the tiger, if it has a card whose color appears in the flag ... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The kangaroo knows the defensive plans of the tiger. The tiger has a cello. The swordfish does not become an enemy of the tiger. And the rules of the game are as follows. Rule1: For the tiger, if the belief is that the swordfish does no... | We know the swordfish does not become an enemy of the tiger and the kangaroo knows the defensive plans of the tiger, and according to Rule1 "if the swordfish does not become an enemy of the tiger but the kangaroo knows the defensive plans of the tiger, then the tiger knows the defensive plans of the cockroach", and for... | (tiger, know, cockroach) | Facts:
(kangaroo, know, tiger)
(tiger, has, a cello)
~(swordfish, become, tiger)
Rules:
Rule1: ~(swordfish, become, tiger)^(kangaroo, know, tiger) => (tiger, know, cockroach)
Rule2: (tiger, has, a card whose color appears in the flag of France) => ~(tiger, know, cockroach)
Rule3: (tiger, has, a leafy green vegeta... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-52 |
The dog has 16 friends. The dog invented a time machine. The swordfish raises a peace flag for the zander. | Rule1: If at least one animal raises a flag of peace for the zander, then the dog does not roll the dice for the cricket. | A few players are playing a boardgame. The current state of the game is as follows. The dog has 16 friends. The dog invented a time machine. The swordfish raises a peace flag for the zander. And the rules of the game are as follows. Rule1: If at least one animal raises a flag of peace for the zander, then the dog does ... | We know the swordfish raises a peace flag for the zander, and according to Rule1 "if at least one animal raises a peace flag for the zander, then the dog does not roll the dice for the cricket", so we can conclude "the dog does not roll the dice for the cricket". So the statement "the dog rolls the dice for the cricket... | (dog, roll, cricket) | Facts:
(dog, has, 16 friends)
(dog, invented, a time machine)
(swordfish, raise, zander)
Rules:
Rule1: exists X (X, raise, zander) => ~(dog, roll, cricket)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-53 | |
The carp has two friends that are playful and 1 friend that is not, and is named Tessa. The carp published a high-quality paper. The eel is named Casper. | Rule1: If the carp has a name whose first letter is the same as the first letter of the eel's name, then the carp does not offer a job position to the koala. Rule2: Regarding the carp, if it has a card whose color appears in the flag of Japan, then we can conclude that it does not offer a job to the koala. Rule3: If th... | Rule1 is preferred over Rule3. Rule1 is preferred over Rule4. Rule2 is preferred over Rule3. Rule2 is preferred over Rule4. | A few players are playing a boardgame. The current state of the game is as follows. The carp has two friends that are playful and 1 friend that is not, and is named Tessa. The carp published a high-quality paper. The eel is named Casper. And the rules of the game are as follows. Rule1: If the carp has a name whose firs... | We know the carp published a high-quality paper, and according to Rule4 "if the carp has a high-quality paper, then the carp offers a job to the koala", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the carp has a card whose color appears in the flag of Japan" and for Rule1 we c... | (carp, offer, koala) | Facts:
(carp, has, two friends that are playful and 1 friend that is not)
(carp, is named, Tessa)
(carp, published, a high-quality paper)
(eel, is named, Casper)
Rules:
Rule1: (carp, has a name whose first letter is the same as the first letter of the, eel's name) => ~(carp, offer, koala)
Rule2: (carp, has, a car... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-54 |
The starfish eats the food of the elephant. | Rule1: Regarding the elephant, if it has a card whose color is one of the rainbow colors, then we can conclude that it shows her cards (all of them) to the dog. Rule2: The elephant does not show her cards (all of them) to the dog, in the case where the starfish eats the food of the elephant. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The starfish eats the food of the elephant. And the rules of the game are as follows. Rule1: Regarding the elephant, if it has a card whose color is one of the rainbow colors, then we can conclude that it shows her cards (all of them) t... | We know the starfish eats the food of the elephant, and according to Rule2 "if the starfish eats the food of the elephant, then the elephant does not show all her cards to the dog", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the elephant has a card whose color is one of the r... | (elephant, show, dog) | Facts:
(starfish, eat, elephant)
Rules:
Rule1: (elephant, has, a card whose color is one of the rainbow colors) => (elephant, show, dog)
Rule2: (starfish, eat, elephant) => ~(elephant, show, dog)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-55 |
The aardvark burns the warehouse of the doctorfish. The doctorfish has a cappuccino, and has a card that is white in color. | Rule1: If the aardvark burns the warehouse of the doctorfish, then the doctorfish is not going to raise a flag of peace for the penguin. Rule2: Regarding the doctorfish, if it has a card whose color appears in the flag of Netherlands, then we can conclude that it raises a peace flag for the penguin. Rule3: If the docto... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The aardvark burns the warehouse of the doctorfish. The doctorfish has a cappuccino, and has a card that is white in color. And the rules of the game are as follows. Rule1: If the aardvark burns the warehouse of the doctorfish, then the... | We know the doctorfish has a card that is white in color, white appears in the flag of Netherlands, and according to Rule2 "if the doctorfish has a card whose color appears in the flag of Netherlands, then the doctorfish raises a peace flag for the penguin", and Rule2 has a higher preference than the conflicting rules ... | (doctorfish, raise, penguin) | Facts:
(aardvark, burn, doctorfish)
(doctorfish, has, a cappuccino)
(doctorfish, has, a card that is white in color)
Rules:
Rule1: (aardvark, burn, doctorfish) => ~(doctorfish, raise, penguin)
Rule2: (doctorfish, has, a card whose color appears in the flag of Netherlands) => (doctorfish, raise, penguin)
Rule3: (d... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-56 |
The turtle has a basket. The turtle has a card that is green in color. | Rule1: If the turtle has something to sit on, then the turtle raises a peace flag for the kudu. Rule2: If the turtle has something to sit on, then the turtle raises a peace flag for the kudu. Rule3: If the turtle has a card whose color starts with the letter "g", then the turtle does not raise a flag of peace for the k... | Rule1 is preferred over Rule3. Rule2 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The turtle has a basket. The turtle has a card that is green in color. And the rules of the game are as follows. Rule1: If the turtle has something to sit on, then the turtle raises a peace flag for the kudu. Rule2: If the turtle has so... | We know the turtle has a card that is green in color, green starts with "g", and according to Rule3 "if the turtle has a card whose color starts with the letter "g", then the turtle does not raise a peace flag for the kudu", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the turt... | (turtle, raise, kudu) | Facts:
(turtle, has, a basket)
(turtle, has, a card that is green in color)
Rules:
Rule1: (turtle, has, something to sit on) => (turtle, raise, kudu)
Rule2: (turtle, has, something to sit on) => (turtle, raise, kudu)
Rule3: (turtle, has, a card whose color starts with the letter "g") => ~(turtle, raise, kudu)
Pref... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-57 |
The eel does not attack the green fields whose owner is the hippopotamus. | Rule1: Regarding the eel, if it does not have her keys, then we can conclude that it does not become an actual enemy of the doctorfish. Rule2: If something does not attack the green fields of the hippopotamus, then it becomes an enemy of the doctorfish. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The eel does not attack the green fields whose owner is the hippopotamus. And the rules of the game are as follows. Rule1: Regarding the eel, if it does not have her keys, then we can conclude that it does not become an actual enemy of ... | We know the eel does not attack the green fields whose owner is the hippopotamus, and according to Rule2 "if something does not attack the green fields whose owner is the hippopotamus, then it becomes an enemy of the doctorfish", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the... | (eel, become, doctorfish) | Facts:
~(eel, attack, hippopotamus)
Rules:
Rule1: (eel, does not have, her keys) => ~(eel, become, doctorfish)
Rule2: ~(X, attack, hippopotamus) => (X, become, doctorfish)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-58 |
The sheep has a card that is violet in color. The sheep has seventeen friends. | Rule1: If the sheep has a card whose color is one of the rainbow colors, then the sheep does not need support from the puffin. Rule2: Regarding the sheep, if it has a high-quality paper, then we can conclude that it needs support from the puffin. Rule3: Regarding the sheep, if it has fewer than eight friends, then we c... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The sheep has a card that is violet in color. The sheep has seventeen friends. And the rules of the game are as follows. Rule1: If the sheep has a card whose color is one of the rainbow colors, then the sheep does not need support from ... | We know the sheep has a card that is violet in color, violet is one of the rainbow colors, and according to Rule1 "if the sheep has a card whose color is one of the rainbow colors, then the sheep does not need support from the puffin", and for the conflicting and higher priority rule Rule2 we cannot prove the anteceden... | (sheep, need, puffin) | Facts:
(sheep, has, a card that is violet in color)
(sheep, has, seventeen friends)
Rules:
Rule1: (sheep, has, a card whose color is one of the rainbow colors) => ~(sheep, need, puffin)
Rule2: (sheep, has, a high-quality paper) => (sheep, need, puffin)
Rule3: (sheep, has, fewer than eight friends) => (sheep, need,... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-59 |
The catfish becomes an enemy of the turtle. The lobster has twelve friends, and is named Chickpea. The squirrel is named Casper. | Rule1: Regarding the lobster, if it has a name whose first letter is the same as the first letter of the squirrel's name, then we can conclude that it offers a job position to the dog. Rule2: If the lobster has fewer than six friends, then the lobster offers a job to the dog. | A few players are playing a boardgame. The current state of the game is as follows. The catfish becomes an enemy of the turtle. The lobster has twelve friends, and is named Chickpea. The squirrel is named Casper. And the rules of the game are as follows. Rule1: Regarding the lobster, if it has a name whose first letter... | We know the lobster is named Chickpea and the squirrel is named Casper, both names start with "C", and according to Rule1 "if the lobster has a name whose first letter is the same as the first letter of the squirrel's name, then the lobster offers a job to the dog", so we can conclude "the lobster offers a job to the d... | (lobster, offer, dog) | Facts:
(catfish, become, turtle)
(lobster, has, twelve friends)
(lobster, is named, Chickpea)
(squirrel, is named, Casper)
Rules:
Rule1: (lobster, has a name whose first letter is the same as the first letter of the, squirrel's name) => (lobster, offer, dog)
Rule2: (lobster, has, fewer than six friends) => (lobst... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-60 | |
The sea bass has six friends. The squid knows the defensive plans of the tiger. | Rule1: The sea bass does not respect the eagle whenever at least one animal knows the defensive plans of the tiger. | A few players are playing a boardgame. The current state of the game is as follows. The sea bass has six friends. The squid knows the defensive plans of the tiger. And the rules of the game are as follows. Rule1: The sea bass does not respect the eagle whenever at least one animal knows the defensive plans of the tiger... | We know the squid knows the defensive plans of the tiger, and according to Rule1 "if at least one animal knows the defensive plans of the tiger, then the sea bass does not respect the eagle", so we can conclude "the sea bass does not respect the eagle". So the statement "the sea bass respects the eagle" is disproved an... | (sea bass, respect, eagle) | Facts:
(sea bass, has, six friends)
(squid, know, tiger)
Rules:
Rule1: exists X (X, know, tiger) => ~(sea bass, respect, eagle)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-61 | |
The halibut invented a time machine. The halibut needs support from the baboon. | Rule1: If you are positive that you saw one of the animals needs the support of the baboon, you can be certain that it will also proceed to the spot right after the raven. Rule2: Regarding the halibut, if it purchased a time machine, then we can conclude that it does not proceed to the spot right after the raven. Rule3... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The halibut invented a time machine. The halibut needs support from the baboon. And the rules of the game are as follows. Rule1: If you are positive that you saw one of the animals needs the support of the baboon, you can be certain tha... | We know the halibut needs support from the baboon, and according to Rule1 "if something needs support from the baboon, then it proceeds to the spot right after the raven", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "the halibut has more than two friends" and for Rule2 we canno... | (halibut, proceed, raven) | Facts:
(halibut, invented, a time machine)
(halibut, need, baboon)
Rules:
Rule1: (X, need, baboon) => (X, proceed, raven)
Rule2: (halibut, purchased, a time machine) => ~(halibut, proceed, raven)
Rule3: (halibut, has, more than two friends) => ~(halibut, proceed, raven)
Preferences:
Rule2 > Rule1
Rule3 > Rule1 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-62 |
The hummingbird is named Lola, and published a high-quality paper. The rabbit is named Buddy. | Rule1: If the hummingbird has a high-quality paper, then the hummingbird does not remove one of the pieces of the ferret. Rule2: If the hummingbird has a name whose first letter is the same as the first letter of the rabbit's name, then the hummingbird does not remove from the board one of the pieces of the ferret. Rul... | Rule3 is preferred over Rule1. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The hummingbird is named Lola, and published a high-quality paper. The rabbit is named Buddy. And the rules of the game are as follows. Rule1: If the hummingbird has a high-quality paper, then the hummingbird does not remove one of the ... | We know the hummingbird published a high-quality paper, and according to Rule1 "if the hummingbird has a high-quality paper, then the hummingbird does not remove from the board one of the pieces of the ferret", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "at least one animal ne... | (hummingbird, remove, ferret) | Facts:
(hummingbird, is named, Lola)
(hummingbird, published, a high-quality paper)
(rabbit, is named, Buddy)
Rules:
Rule1: (hummingbird, has, a high-quality paper) => ~(hummingbird, remove, ferret)
Rule2: (hummingbird, has a name whose first letter is the same as the first letter of the, rabbit's name) => ~(hummi... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-63 |
The cricket has 2 friends that are adventurous and 3 friends that are not, has a card that is blue in color, and hates Chris Ronaldo. The cricket is named Teddy. The wolverine is named Tango. | Rule1: If the cricket has a name whose first letter is the same as the first letter of the wolverine's name, then the cricket knocks down the fortress of the hare. Rule2: If the cricket is a fan of Chris Ronaldo, then the cricket knocks down the fortress that belongs to the hare. Rule3: Regarding the cricket, if it has... | Rule1 is preferred over Rule3. Rule2 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The cricket has 2 friends that are adventurous and 3 friends that are not, has a card that is blue in color, and hates Chris Ronaldo. The cricket is named Teddy. The wolverine is named Tango. And the rules of the game are as follows. Ru... | We know the cricket is named Teddy and the wolverine is named Tango, both names start with "T", and according to Rule1 "if the cricket has a name whose first letter is the same as the first letter of the wolverine's name, then the cricket knocks down the fortress of the hare", and Rule1 has a higher preference than the... | (cricket, knock, hare) | Facts:
(cricket, has, 2 friends that are adventurous and 3 friends that are not)
(cricket, has, a card that is blue in color)
(cricket, hates, Chris Ronaldo)
(cricket, is named, Teddy)
(wolverine, is named, Tango)
Rules:
Rule1: (cricket, has a name whose first letter is the same as the first letter of the, wolver... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-64 |
The catfish rolls the dice for the hare. | Rule1: If something becomes an actual enemy of the raven, then it removes one of the pieces of the tilapia, too. Rule2: If something rolls the dice for the hare, then it does not remove one of the pieces of the tilapia. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The catfish rolls the dice for the hare. And the rules of the game are as follows. Rule1: If something becomes an actual enemy of the raven, then it removes one of the pieces of the tilapia, too. Rule2: If something rolls the dice for t... | We know the catfish rolls the dice for the hare, and according to Rule2 "if something rolls the dice for the hare, then it does not remove from the board one of the pieces of the tilapia", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the catfish becomes an enemy of the raven", ... | (catfish, remove, tilapia) | Facts:
(catfish, roll, hare)
Rules:
Rule1: (X, become, raven) => (X, remove, tilapia)
Rule2: (X, roll, hare) => ~(X, remove, tilapia)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-65 |
The kiwi respects the salmon. The salmon assassinated the mayor. The turtle does not steal five points from the salmon. | Rule1: If the salmon has fewer than 9 friends, then the salmon does not prepare armor for the carp. Rule2: For the salmon, if the belief is that the turtle does not steal five of the points of the salmon but the kiwi respects the salmon, then you can add "the salmon prepares armor for the carp" to your conclusions. Rul... | Rule1 is preferred over Rule2. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The kiwi respects the salmon. The salmon assassinated the mayor. The turtle does not steal five points from the salmon. And the rules of the game are as follows. Rule1: If the salmon has fewer than 9 friends, then the salmon does not pr... | We know the turtle does not steal five points from the salmon and the kiwi respects the salmon, and according to Rule2 "if the turtle does not steal five points from the salmon but the kiwi respects the salmon, then the salmon prepares armor for the carp", and for the conflicting and higher priority rule Rule1 we canno... | (salmon, prepare, carp) | Facts:
(kiwi, respect, salmon)
(salmon, assassinated, the mayor)
~(turtle, steal, salmon)
Rules:
Rule1: (salmon, has, fewer than 9 friends) => ~(salmon, prepare, carp)
Rule2: ~(turtle, steal, salmon)^(kiwi, respect, salmon) => (salmon, prepare, carp)
Rule3: (salmon, voted, for the mayor) => ~(salmon, prepare, car... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-66 |
The hummingbird has a cell phone, and has a computer. | Rule1: If the hummingbird has a device to connect to the internet, then the hummingbird does not steal five points from the octopus. Rule2: Regarding the hummingbird, if it has something to carry apples and oranges, then we can conclude that it steals five of the points of the octopus. Rule3: If the hummingbird has a m... | Rule2 is preferred over Rule1. Rule3 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The hummingbird has a cell phone, and has a computer. And the rules of the game are as follows. Rule1: If the hummingbird has a device to connect to the internet, then the hummingbird does not steal five points from the octopus. Rule2: ... | We know the hummingbird has a computer, computer can be used to connect to the internet, and according to Rule1 "if the hummingbird has a device to connect to the internet, then the hummingbird does not steal five points from the octopus", and for the conflicting and higher priority rule Rule2 we cannot prove the antec... | (hummingbird, steal, octopus) | Facts:
(hummingbird, has, a cell phone)
(hummingbird, has, a computer)
Rules:
Rule1: (hummingbird, has, a device to connect to the internet) => ~(hummingbird, steal, octopus)
Rule2: (hummingbird, has, something to carry apples and oranges) => (hummingbird, steal, octopus)
Rule3: (hummingbird, has, a musical instru... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-67 |
The squid is named Teddy. The kiwi does not wink at the zander. The oscar does not remove from the board one of the pieces of the zander. | Rule1: If the zander has a name whose first letter is the same as the first letter of the squid's name, then the zander does not proceed to the spot that is right after the spot of the dog. Rule2: For the zander, if the belief is that the oscar does not remove from the board one of the pieces of the zander and the kiwi... | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The squid is named Teddy. The kiwi does not wink at the zander. The oscar does not remove from the board one of the pieces of the zander. And the rules of the game are as follows. Rule1: If the zander has a name whose first letter is th... | We know the oscar does not remove from the board one of the pieces of the zander and the kiwi does not wink at the zander, and according to Rule2 "if the oscar does not remove from the board one of the pieces of the zander and the kiwi does not wink at the zander, then the zander, inevitably, proceeds to the spot right... | (zander, proceed, dog) | Facts:
(squid, is named, Teddy)
~(kiwi, wink, zander)
~(oscar, remove, zander)
Rules:
Rule1: (zander, has a name whose first letter is the same as the first letter of the, squid's name) => ~(zander, proceed, dog)
Rule2: ~(oscar, remove, zander)^~(kiwi, wink, zander) => (zander, proceed, dog)
Preferences:
Rule1 > ... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-68 |
The goldfish is named Cinnamon. The parrot is named Paco, and does not wink at the canary. The parrot reduced her work hours recently, and does not need support from the gecko. | Rule1: Be careful when something does not need the support of the gecko and also does not wink at the canary because in this case it will surely not sing a victory song for the caterpillar (this may or may not be problematic). | A few players are playing a boardgame. The current state of the game is as follows. The goldfish is named Cinnamon. The parrot is named Paco, and does not wink at the canary. The parrot reduced her work hours recently, and does not need support from the gecko. And the rules of the game are as follows. Rule1: Be careful... | We know the parrot does not need support from the gecko and the parrot does not wink at the canary, and according to Rule1 "if something does not need support from the gecko and does not wink at the canary, then it does not sing a victory song for the caterpillar", so we can conclude "the parrot does not sing a victory... | (parrot, sing, caterpillar) | Facts:
(goldfish, is named, Cinnamon)
(parrot, is named, Paco)
(parrot, reduced, her work hours recently)
~(parrot, need, gecko)
~(parrot, wink, canary)
Rules:
Rule1: ~(X, need, gecko)^~(X, wink, canary) => ~(X, sing, caterpillar)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-69 | |
The elephant is named Peddi. The squirrel is named Tango, and knows the defensive plans of the hippopotamus. The squirrel purchased a luxury aircraft. | Rule1: If the squirrel has a name whose first letter is the same as the first letter of the elephant's name, then the squirrel owes money to the moose. Rule2: Be careful when something knows the defense plan of the hippopotamus and also owes $$$ to the ferret because in this case it will surely not owe money to the moo... | Rule2 is preferred over Rule1. Rule2 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The elephant is named Peddi. The squirrel is named Tango, and knows the defensive plans of the hippopotamus. The squirrel purchased a luxury aircraft. And the rules of the game are as follows. Rule1: If the squirrel has a name whose fir... | We know the squirrel purchased a luxury aircraft, and according to Rule3 "if the squirrel owns a luxury aircraft, then the squirrel owes money to the moose", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the squirrel owes money to the ferret", so we can conclude "the squirrel ow... | (squirrel, owe, moose) | Facts:
(elephant, is named, Peddi)
(squirrel, is named, Tango)
(squirrel, know, hippopotamus)
(squirrel, purchased, a luxury aircraft)
Rules:
Rule1: (squirrel, has a name whose first letter is the same as the first letter of the, elephant's name) => (squirrel, owe, moose)
Rule2: (X, know, hippopotamus)^(X, owe, f... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-70 |
The donkey holds the same number of points as the puffin. The spider knows the defensive plans of the puffin. | Rule1: If the donkey holds an equal number of points as the puffin and the spider knows the defensive plans of the puffin, then the puffin will not eat the food that belongs to the koala. Rule2: If you are positive that you saw one of the animals prepares armor for the cow, you can be certain that it will also eat the ... | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The donkey holds the same number of points as the puffin. The spider knows the defensive plans of the puffin. And the rules of the game are as follows. Rule1: If the donkey holds an equal number of points as the puffin and the spider kn... | We know the donkey holds the same number of points as the puffin and the spider knows the defensive plans of the puffin, and according to Rule1 "if the donkey holds the same number of points as the puffin and the spider knows the defensive plans of the puffin, then the puffin does not eat the food of the koala", and fo... | (puffin, eat, koala) | Facts:
(donkey, hold, puffin)
(spider, know, puffin)
Rules:
Rule1: (donkey, hold, puffin)^(spider, know, puffin) => ~(puffin, eat, koala)
Rule2: (X, prepare, cow) => (X, eat, koala)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-71 |
The kangaroo winks at the puffin. | Rule1: The tiger does not show all her cards to the hare, in the case where the gecko knows the defense plan of the tiger. Rule2: If at least one animal winks at the puffin, then the tiger shows all her cards to the hare. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The kangaroo winks at the puffin. And the rules of the game are as follows. Rule1: The tiger does not show all her cards to the hare, in the case where the gecko knows the defense plan of the tiger. Rule2: If at least one animal winks a... | We know the kangaroo winks at the puffin, and according to Rule2 "if at least one animal winks at the puffin, then the tiger shows all her cards to the hare", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the gecko knows the defensive plans of the tiger", so we can conclude "the... | (tiger, show, hare) | Facts:
(kangaroo, wink, puffin)
Rules:
Rule1: (gecko, know, tiger) => ~(tiger, show, hare)
Rule2: exists X (X, wink, puffin) => (tiger, show, hare)
Preferences:
Rule1 > Rule2 | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-72 |
The pig is named Max. The starfish becomes an enemy of the raven. | Rule1: If the parrot has a name whose first letter is the same as the first letter of the pig's name, then the parrot shows all her cards to the baboon. Rule2: If at least one animal becomes an actual enemy of the raven, then the parrot does not show all her cards to the baboon. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The pig is named Max. The starfish becomes an enemy of the raven. And the rules of the game are as follows. Rule1: If the parrot has a name whose first letter is the same as the first letter of the pig's name, then the parrot shows all ... | We know the starfish becomes an enemy of the raven, and according to Rule2 "if at least one animal becomes an enemy of the raven, then the parrot does not show all her cards to the baboon", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the parrot has a name whose first letter is... | (parrot, show, baboon) | Facts:
(pig, is named, Max)
(starfish, become, raven)
Rules:
Rule1: (parrot, has a name whose first letter is the same as the first letter of the, pig's name) => (parrot, show, baboon)
Rule2: exists X (X, become, raven) => ~(parrot, show, baboon)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-73 |
The canary is named Teddy. The octopus invented a time machine. The octopus is named Tarzan. The squirrel removes from the board one of the pieces of the octopus. | Rule1: Regarding the octopus, if it has a name whose first letter is the same as the first letter of the canary's name, then we can conclude that it burns the warehouse of the crocodile. Rule2: If the octopus purchased a time machine, then the octopus burns the warehouse that is in possession of the crocodile. Rule3: F... | Rule3 is preferred over Rule1. Rule3 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The canary is named Teddy. The octopus invented a time machine. The octopus is named Tarzan. The squirrel removes from the board one of the pieces of the octopus. And the rules of the game are as follows. Rule1: Regarding the octopus, i... | We know the octopus is named Tarzan and the canary is named Teddy, both names start with "T", and according to Rule1 "if the octopus has a name whose first letter is the same as the first letter of the canary's name, then the octopus burns the warehouse of the crocodile", and for the conflicting and higher priority rul... | (octopus, burn, crocodile) | Facts:
(canary, is named, Teddy)
(octopus, invented, a time machine)
(octopus, is named, Tarzan)
(squirrel, remove, octopus)
Rules:
Rule1: (octopus, has a name whose first letter is the same as the first letter of the, canary's name) => (octopus, burn, crocodile)
Rule2: (octopus, purchased, a time machine) => (oc... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-74 |
The catfish has a club chair. | Rule1: If the catfish has fewer than 6 friends, then the catfish needs support from the eagle. Rule2: Regarding the catfish, if it has something to sit on, then we can conclude that it does not need the support of the eagle. | Rule1 is preferred over Rule2. | A few players are playing a boardgame. The current state of the game is as follows. The catfish has a club chair. And the rules of the game are as follows. Rule1: If the catfish has fewer than 6 friends, then the catfish needs support from the eagle. Rule2: Regarding the catfish, if it has something to sit on, then we ... | We know the catfish has a club chair, one can sit on a club chair, and according to Rule2 "if the catfish has something to sit on, then the catfish does not need support from the eagle", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the catfish has fewer than 6 friends", so we c... | (catfish, need, eagle) | Facts:
(catfish, has, a club chair)
Rules:
Rule1: (catfish, has, fewer than 6 friends) => (catfish, need, eagle)
Rule2: (catfish, has, something to sit on) => ~(catfish, need, eagle)
Preferences:
Rule1 > Rule2 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-75 |
The hare published a high-quality paper. The cockroach does not learn the basics of resource management from the hare. | Rule1: Regarding the hare, if it has a high-quality paper, then we can conclude that it knocks down the fortress of the jellyfish. | A few players are playing a boardgame. The current state of the game is as follows. The hare published a high-quality paper. The cockroach does not learn the basics of resource management from the hare. And the rules of the game are as follows. Rule1: Regarding the hare, if it has a high-quality paper, then we can conc... | We know the hare published a high-quality paper, and according to Rule1 "if the hare has a high-quality paper, then the hare knocks down the fortress of the jellyfish", so we can conclude "the hare knocks down the fortress of the jellyfish". So the statement "the hare knocks down the fortress of the jellyfish" is prove... | (hare, knock, jellyfish) | Facts:
(hare, published, a high-quality paper)
~(cockroach, learn, hare)
Rules:
Rule1: (hare, has, a high-quality paper) => (hare, knock, jellyfish)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-76 | |
The gecko has a basket. | Rule1: If the gecko has something to carry apples and oranges, then the gecko does not burn the warehouse that is in possession of the sheep. Rule2: Regarding the gecko, if it created a time machine, then we can conclude that it burns the warehouse of the sheep. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The gecko has a basket. And the rules of the game are as follows. Rule1: If the gecko has something to carry apples and oranges, then the gecko does not burn the warehouse that is in possession of the sheep. Rule2: Regarding the gecko, ... | We know the gecko has a basket, one can carry apples and oranges in a basket, and according to Rule1 "if the gecko has something to carry apples and oranges, then the gecko does not burn the warehouse of the sheep", and for the conflicting and higher priority rule Rule2 we cannot prove the antecedent "the gecko created... | (gecko, burn, sheep) | Facts:
(gecko, has, a basket)
Rules:
Rule1: (gecko, has, something to carry apples and oranges) => ~(gecko, burn, sheep)
Rule2: (gecko, created, a time machine) => (gecko, burn, sheep)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-77 |
The cow has a card that is black in color, has four friends, and is named Luna. The cow purchased a luxury aircraft. | Rule1: Regarding the cow, if it has more than thirteen friends, then we can conclude that it does not need support from the elephant. Rule2: Regarding the cow, if it owns a luxury aircraft, then we can conclude that it needs support from the elephant. Rule3: If the cow has a name whose first letter is the same as the f... | Rule1 is preferred over Rule2. Rule1 is preferred over Rule4. Rule3 is preferred over Rule2. Rule3 is preferred over Rule4. | A few players are playing a boardgame. The current state of the game is as follows. The cow has a card that is black in color, has four friends, and is named Luna. The cow purchased a luxury aircraft. And the rules of the game are as follows. Rule1: Regarding the cow, if it has more than thirteen friends, then we can c... | We know the cow purchased a luxury aircraft, and according to Rule2 "if the cow owns a luxury aircraft, then the cow needs support from the elephant", and for the conflicting and higher priority rule Rule3 we cannot prove the antecedent "the cow has a name whose first letter is the same as the first letter of the ferre... | (cow, need, elephant) | Facts:
(cow, has, a card that is black in color)
(cow, has, four friends)
(cow, is named, Luna)
(cow, purchased, a luxury aircraft)
Rules:
Rule1: (cow, has, more than thirteen friends) => ~(cow, need, elephant)
Rule2: (cow, owns, a luxury aircraft) => (cow, need, elephant)
Rule3: (cow, has a name whose first let... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-78 |
The canary is named Cinnamon. The cockroach holds the same number of points as the halibut. The halibut is named Chickpea. | Rule1: If the halibut has a name whose first letter is the same as the first letter of the canary's name, then the halibut does not remove one of the pieces of the rabbit. | A few players are playing a boardgame. The current state of the game is as follows. The canary is named Cinnamon. The cockroach holds the same number of points as the halibut. The halibut is named Chickpea. And the rules of the game are as follows. Rule1: If the halibut has a name whose first letter is the same as the ... | We know the halibut is named Chickpea and the canary is named Cinnamon, both names start with "C", and according to Rule1 "if the halibut has a name whose first letter is the same as the first letter of the canary's name, then the halibut does not remove from the board one of the pieces of the rabbit", so we can conclu... | (halibut, remove, rabbit) | Facts:
(canary, is named, Cinnamon)
(cockroach, hold, halibut)
(halibut, is named, Chickpea)
Rules:
Rule1: (halibut, has a name whose first letter is the same as the first letter of the, canary's name) => ~(halibut, remove, rabbit)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-79 | |
The lobster has 18 friends, and has a card that is green in color. The starfish attacks the green fields whose owner is the lobster. The crocodile does not prepare armor for the lobster. | Rule1: If the lobster has fewer than ten friends, then the lobster knocks down the fortress of the hummingbird. Rule2: If the lobster has a card with a primary color, then the lobster knocks down the fortress of the hummingbird. | A few players are playing a boardgame. The current state of the game is as follows. The lobster has 18 friends, and has a card that is green in color. The starfish attacks the green fields whose owner is the lobster. The crocodile does not prepare armor for the lobster. And the rules of the game are as follows. Rule1: ... | We know the lobster has a card that is green in color, green is a primary color, and according to Rule2 "if the lobster has a card with a primary color, then the lobster knocks down the fortress of the hummingbird", so we can conclude "the lobster knocks down the fortress of the hummingbird". So the statement "the lobs... | (lobster, knock, hummingbird) | Facts:
(lobster, has, 18 friends)
(lobster, has, a card that is green in color)
(starfish, attack, lobster)
~(crocodile, prepare, lobster)
Rules:
Rule1: (lobster, has, fewer than ten friends) => (lobster, knock, hummingbird)
Rule2: (lobster, has, a card with a primary color) => (lobster, knock, hummingbird)
Prefe... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-80 | |
The goldfish has 5 friends that are wise and 1 friend that is not, and has a cell phone. The goldfish offers a job to the panther. | Rule1: If the goldfish has fewer than nine friends, then the goldfish does not burn the warehouse that is in possession of the octopus. Rule2: Regarding the goldfish, if it has something to drink, then we can conclude that it does not burn the warehouse that is in possession of the octopus. | A few players are playing a boardgame. The current state of the game is as follows. The goldfish has 5 friends that are wise and 1 friend that is not, and has a cell phone. The goldfish offers a job to the panther. And the rules of the game are as follows. Rule1: If the goldfish has fewer than nine friends, then the go... | We know the goldfish has 5 friends that are wise and 1 friend that is not, so the goldfish has 6 friends in total which is fewer than 9, and according to Rule1 "if the goldfish has fewer than nine friends, then the goldfish does not burn the warehouse of the octopus", so we can conclude "the goldfish does not burn the ... | (goldfish, burn, octopus) | Facts:
(goldfish, has, 5 friends that are wise and 1 friend that is not)
(goldfish, has, a cell phone)
(goldfish, offer, panther)
Rules:
Rule1: (goldfish, has, fewer than nine friends) => ~(goldfish, burn, octopus)
Rule2: (goldfish, has, something to drink) => ~(goldfish, burn, octopus)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-81 | |
The sea bass invented a time machine, does not burn the warehouse of the kangaroo, and does not hold the same number of points as the canary. | Rule1: Regarding the sea bass, if it created a time machine, then we can conclude that it attacks the green fields whose owner is the black bear. | A few players are playing a boardgame. The current state of the game is as follows. The sea bass invented a time machine, does not burn the warehouse of the kangaroo, and does not hold the same number of points as the canary. And the rules of the game are as follows. Rule1: Regarding the sea bass, if it created a time ... | We know the sea bass invented a time machine, and according to Rule1 "if the sea bass created a time machine, then the sea bass attacks the green fields whose owner is the black bear", so we can conclude "the sea bass attacks the green fields whose owner is the black bear". So the statement "the sea bass attacks the gr... | (sea bass, attack, black bear) | Facts:
(sea bass, invented, a time machine)
~(sea bass, burn, kangaroo)
~(sea bass, hold, canary)
Rules:
Rule1: (sea bass, created, a time machine) => (sea bass, attack, black bear)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-82 | |
The donkey has five friends that are mean and two friends that are not, and has some kale. The turtle proceeds to the spot right after the koala. | Rule1: If at least one animal proceeds to the spot that is right after the spot of the koala, then the donkey does not proceed to the spot right after the starfish. | A few players are playing a boardgame. The current state of the game is as follows. The donkey has five friends that are mean and two friends that are not, and has some kale. The turtle proceeds to the spot right after the koala. And the rules of the game are as follows. Rule1: If at least one animal proceeds to the sp... | We know the turtle proceeds to the spot right after the koala, and according to Rule1 "if at least one animal proceeds to the spot right after the koala, then the donkey does not proceed to the spot right after the starfish", so we can conclude "the donkey does not proceed to the spot right after the starfish". So the ... | (donkey, proceed, starfish) | Facts:
(donkey, has, five friends that are mean and two friends that are not)
(donkey, has, some kale)
(turtle, proceed, koala)
Rules:
Rule1: exists X (X, proceed, koala) => ~(donkey, proceed, starfish)
Preferences:
| disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-83 | |
The cockroach has a love seat sofa. The cockroach learns the basics of resource management from the lobster, and offers a job to the eel. | Rule1: If the cockroach has something to sit on, then the cockroach owes money to the gecko. | A few players are playing a boardgame. The current state of the game is as follows. The cockroach has a love seat sofa. The cockroach learns the basics of resource management from the lobster, and offers a job to the eel. And the rules of the game are as follows. Rule1: If the cockroach has something to sit on, then th... | We know the cockroach has a love seat sofa, one can sit on a love seat sofa, and according to Rule1 "if the cockroach has something to sit on, then the cockroach owes money to the gecko", so we can conclude "the cockroach owes money to the gecko". So the statement "the cockroach owes money to the gecko" is proved and t... | (cockroach, owe, gecko) | Facts:
(cockroach, has, a love seat sofa)
(cockroach, learn, lobster)
(cockroach, offer, eel)
Rules:
Rule1: (cockroach, has, something to sit on) => (cockroach, owe, gecko)
Preferences:
| proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-84 | |
The kiwi winks at the viperfish. The viperfish has a knife. | Rule1: If the kiwi winks at the viperfish, then the viperfish becomes an actual enemy of the cockroach. Rule2: Regarding the viperfish, if it has a sharp object, then we can conclude that it does not become an enemy of the cockroach. | Rule2 is preferred over Rule1. | A few players are playing a boardgame. The current state of the game is as follows. The kiwi winks at the viperfish. The viperfish has a knife. And the rules of the game are as follows. Rule1: If the kiwi winks at the viperfish, then the viperfish becomes an actual enemy of the cockroach. Rule2: Regarding the viperfish... | We know the viperfish has a knife, knife is a sharp object, and according to Rule2 "if the viperfish has a sharp object, then the viperfish does not become an enemy of the cockroach", and Rule2 has a higher preference than the conflicting rules (Rule1), so we can conclude "the viperfish does not become an enemy of the ... | (viperfish, become, cockroach) | Facts:
(kiwi, wink, viperfish)
(viperfish, has, a knife)
Rules:
Rule1: (kiwi, wink, viperfish) => (viperfish, become, cockroach)
Rule2: (viperfish, has, a sharp object) => ~(viperfish, become, cockroach)
Preferences:
Rule2 > Rule1 | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-85 |
The black bear is named Pablo, and lost her keys. The wolverine is named Tessa. | Rule1: If you are positive that you saw one of the animals eats the food of the hippopotamus, you can be certain that it will not raise a peace flag for the tilapia. Rule2: Regarding the black bear, if it does not have her keys, then we can conclude that it raises a flag of peace for the tilapia. Rule3: If the black be... | Rule1 is preferred over Rule2. Rule1 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The black bear is named Pablo, and lost her keys. The wolverine is named Tessa. And the rules of the game are as follows. Rule1: If you are positive that you saw one of the animals eats the food of the hippopotamus, you can be certain t... | We know the black bear lost her keys, and according to Rule2 "if the black bear does not have her keys, then the black bear raises a peace flag for the tilapia", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the black bear eats the food of the hippopotamus", so we can conclude "... | (black bear, raise, tilapia) | Facts:
(black bear, is named, Pablo)
(black bear, lost, her keys)
(wolverine, is named, Tessa)
Rules:
Rule1: (X, eat, hippopotamus) => ~(X, raise, tilapia)
Rule2: (black bear, does not have, her keys) => (black bear, raise, tilapia)
Rule3: (black bear, has a name whose first letter is the same as the first letter... | proved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-86 |
The buffalo is named Milo. The turtle has a blade, and is named Pashmak. | Rule1: If something becomes an actual enemy of the puffin, then it prepares armor for the eagle, too. Rule2: If the turtle has a sharp object, then the turtle does not prepare armor for the eagle. Rule3: If the turtle has a name whose first letter is the same as the first letter of the buffalo's name, then the turtle d... | Rule1 is preferred over Rule2. Rule1 is preferred over Rule3. | A few players are playing a boardgame. The current state of the game is as follows. The buffalo is named Milo. The turtle has a blade, and is named Pashmak. And the rules of the game are as follows. Rule1: If something becomes an actual enemy of the puffin, then it prepares armor for the eagle, too. Rule2: If the turtl... | We know the turtle has a blade, blade is a sharp object, and according to Rule2 "if the turtle has a sharp object, then the turtle does not prepare armor for the eagle", and for the conflicting and higher priority rule Rule1 we cannot prove the antecedent "the turtle becomes an enemy of the puffin", so we can conclude ... | (turtle, prepare, eagle) | Facts:
(buffalo, is named, Milo)
(turtle, has, a blade)
(turtle, is named, Pashmak)
Rules:
Rule1: (X, become, puffin) => (X, prepare, eagle)
Rule2: (turtle, has, a sharp object) => ~(turtle, prepare, eagle)
Rule3: (turtle, has a name whose first letter is the same as the first letter of the, buffalo's name) => ~(... | disproved | BoardgameQA-Binary-depth1 | BoardgameQA-Binary-depth1-train-87 |
End of preview. Expand in Data Studio
BoardgameQA-Hard
This dataset contains a curated train/test split of BoardgameQA, used in our paper Enhancing Language Model Reasoning with Structured Multi-Level Modeling (ICLR 2026). Each example asks whether a target fact can be proved, disproved, or is undetermined given a set of facts, defeasible rules, and rule preferences.
Files
train.jsonl— 37,000 examplestest.jsonl— 500 examples
test.jsonl is a fixed "hard" evaluation set drawn in equal parts (100 examples each) from the test splits of five BoardgameQA subsets that stress different failure modes:
| Category | # examples |
|---|---|
| BoardgameQA-DifficultConflict-depth2 | 100 |
| BoardgameQA-HighConflict-depth2 | 100 |
| BoardgameQA-KnowledgeHeavy-depth2 | 100 |
| BoardgameQA-Main-depth3 | 100 |
| BoardgameQA-ManyDistractors-depth2 | 100 |
train.jsonl combines the train, valid, and test splits of all 15 BoardgameQA subsets (Binary-depth1/2/3, DifficultConflict-depth2, EasyConflict-depth2, HighConflict-depth2, KnowledgeHeavy-depth2, KnowledgeLight-depth2, LowConflict-depth2, Main-depth1/2/3, ManyDistractors-depth2, SomeDistractors-depth2, ZeroConflict-depth2), excluding the 500 examples held out for test.jsonl to avoid train/test leakage.
Label distribution:
| Split | proved | disproved | unknown |
|---|---|---|---|
| train | 13,600 | 13,581 | 9,819 |
| test | 170 | 165 | 165 |
Schema
Each line is a JSON object with the following fields:
| Field | Description |
|---|---|
facts |
The ground facts of the game state, in natural language. |
rules |
The natural-language rules that can be applied to derive new facts. |
preferences |
Priority ordering between rules that may conflict. |
example |
The full natural-language problem statement (facts + rules + preferences + question), as presented to a model. |
proof |
A natural-language proof/derivation trace for the answer. |
goal |
The target fact being queried, in (subject, predicate, object) form. |
theory |
A symbolic (Prolog-style) rendering of facts, rules, and preferences. |
label |
The answer: proved, disproved, or unknown. |
category |
Which BoardgameQA subset the example was drawn from, e.g. BoardgameQA-Main-depth3. |
id |
A unique identifier {category}-{original_split}-{original_index}, e.g. BoardgameQA-Main-depth3-train-0. |
Usage
Each file is plain JSONL — one JSON object per line, no header.
import json
with open("train.jsonl") as f:
examples = [json.loads(line) for line in f]
print(len(examples)) # 37000
print(examples[0]["id"]) # e.g. "BoardgameQA-Binary-depth1-train-0"
print(examples[0]["example"]) # natural-language problem statement
print(examples[0]["label"]) # "proved" | "disproved" | "unknown"
Or with the Hugging Face datasets library:
from datasets import load_dataset
ds = load_dataset(
"json",
data_files={"train": "train.jsonl", "test": "test.jsonl"},
)
To evaluate a model, prompt it with the example field and score its predicted answer against label. Use category to break down results by BoardgameQA subset (e.g. to report performance separately on Main-depth3 vs. ManyDistractors-depth2).
Citation
@inproceedings{xiong2026enhancing,
title={Enhancing language model reasoning with structured multi-level modeling},
author={Xiong, Siheng and Payani, Ali and Fekri, Faramarz},
booktitle={The Fourteenth International Conference on Learning Representations},
year={2026}
}
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