task_id stringlengths 11 13 | prompt stringlengths 115 1.36k | canonical_solution stringlengths 16 864 | test stringlengths 117 1.8k | entry_point stringlengths 1 30 | generated_code sequencelengths 1 1 | gt_rewards sequencelengths 1 1 |
|---|---|---|---|---|---|---|
HumanEval/0 | from typing import List
def has_close_elements(numbers: List[float], threshold: float) -> bool:
""" Check if in given list of numbers, are any two numbers closer to each other than
given threshold.
>>> has_close_elements([1.0, 2.0, 3.0], 0.5)
False
>>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3)
True
"""
| for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
distance = abs(elem - elem2)
if distance < threshold:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True
assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True
assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False
| has_close_elements | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef has_close_elements(numbers: List[float], threshold: float) -> bool:\n \"\"\" Check if in given list of numbers, are any two numbers closer to each other than\n given threshold.\n \"\"\"\n numbers.sort()\n for i... | [
1
] |
HumanEval/1 | from typing import List
def separate_paren_groups(paren_string: str) -> List[str]:
""" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to
separate those group into separate strings and return the list of those.
Separate groups are balanced (each open brace is properly closed) and not nested within each other
Ignore any spaces in the input string.
>>> separate_paren_groups('( ) (( )) (( )( ))')
['()', '(())', '(()())']
"""
| result = []
current_string = []
current_depth = 0
for c in paren_string:
if c == '(':
current_depth += 1
current_string.append(c)
elif c == ')':
current_depth -= 1
current_string.append(c)
if current_depth == 0:
result.append(''.join(current_string))
current_string.clear()
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [
'(()())', '((()))', '()', '((())()())'
]
assert candidate('() (()) ((())) (((())))') == [
'()', '(())', '((()))', '(((())))'
]
assert candidate('(()(())((())))') == [
'(()(())((())))'
]
assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']
| separate_paren_groups | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef separate_paren_groups(paren_string: str) -> List[str]:\n \"\"\" Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n separate those group into separate strings and retur... | [
0
] |
HumanEval/2 |
def truncate_number(number: float) -> float:
""" Given a positive floating point number, it can be decomposed into
and integer part (largest integer smaller than given number) and decimals
(leftover part always smaller than 1).
Return the decimal part of the number.
>>> truncate_number(3.5)
0.5
"""
| return number % 1.0
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3.5) == 0.5
assert abs(candidate(1.33) - 0.33) < 1e-6
assert abs(candidate(123.456) - 0.456) < 1e-6
| truncate_number | [
"Here is the Python code to solve the problem:\n\n```python\ndef truncate_number(number: float) -> float:\n \"\"\" Given a positive floating point number, it can be decomposed into\n and integer part (largest integer smaller than given number) and decimals\n (leftover part always smaller than 1).\n\n Re... | [
1
] |
HumanEval/3 | from typing import List
def below_zero(operations: List[int]) -> bool:
""" You're given a list of deposit and withdrawal operations on a bank account that starts with
zero balance. Your task is to detect if at any point the balance of account fallls below zero, and
at that point function should return True. Otherwise it should return False.
>>> below_zero([1, 2, 3])
False
>>> below_zero([1, 2, -4, 5])
True
"""
| balance = 0
for op in operations:
balance += op
if balance < 0:
return True
return False
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == False
assert candidate([1, 2, -3, 1, 2, -3]) == False
assert candidate([1, 2, -4, 5, 6]) == True
assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False
assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True
assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True
| below_zero | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List\n\n\ndef below_zero(operations: List[int]) -> bool:\n balance = 0\n for operation in operations:\n balance += operation\n if balance < 0:\n return True\n return False\n```\n\nThis function iterates... | [
1
] |
HumanEval/4 | from typing import List
def mean_absolute_deviation(numbers: List[float]) -> float:
""" For a given list of input numbers, calculate Mean Absolute Deviation
around the mean of this dataset.
Mean Absolute Deviation is the average absolute difference between each
element and a centerpoint (mean in this case):
MAD = average | x - x_mean |
>>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0])
1.0
"""
| mean = sum(numbers) / len(numbers)
return sum(abs(x - mean) for x in numbers) / len(numbers)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6
assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
| mean_absolute_deviation | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List\n\n\ndef mean_absolute_deviation(numbers: List[float]) -> float:\n \"\"\" For a given list of input numbers, calculate Mean Absolute Deviation\n around the mean of this dataset.\n Mean Absolute Deviation is the average abs... | [
1
] |
HumanEval/5 | from typing import List
def intersperse(numbers: List[int], delimeter: int) -> List[int]:
""" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'
>>> intersperse([], 4)
[]
>>> intersperse([1, 2, 3], 4)
[1, 4, 2, 4, 3]
"""
| if not numbers:
return []
result = []
for n in numbers[:-1]:
result.append(n)
result.append(delimeter)
result.append(numbers[-1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 7) == []
assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2]
assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
| intersperse | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef intersperse(numbers: List[int], delimeter: int) -> List[int]:\n \"\"\" Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n \"\"\"\n if not numbers:\n return []\n res... | [
1
] |
HumanEval/6 | from typing import List
def parse_nested_parens(paren_string: str) -> List[int]:
""" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.
For each of the group, output the deepest level of nesting of parentheses.
E.g. (()()) has maximum two levels of nesting while ((())) has three.
>>> parse_nested_parens('(()()) ((())) () ((())()())')
[2, 3, 1, 3]
"""
| def parse_paren_group(s):
depth = 0
max_depth = 0
for c in s:
if c == '(':
depth += 1
max_depth = max(depth, max_depth)
else:
depth -= 1
return max_depth
return [parse_paren_group(x) for x in paren_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3]
assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4]
assert candidate('(()(())((())))') == [4]
| parse_nested_parens | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef parse_nested_parens(paren_string: str) -> List[int]:\n \"\"\" Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n For each of the group, output the deepest level ... | [
1
] |
HumanEval/7 | from typing import List
def filter_by_substring(strings: List[str], substring: str) -> List[str]:
""" Filter an input list of strings only for ones that contain given substring
>>> filter_by_substring([], 'a')
[]
>>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a')
['abc', 'bacd', 'array']
"""
| return [x for x in strings if substring in x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx']
assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']
| filter_by_substring | [
"Here is the solution to the problem:\n\n```python\nfrom typing import List\n\n\ndef filter_by_substring(strings: List[str], substring: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that contain given substring\n \"\"\"\n return [s for s in strings if substring in s]\n```\n\nThi... | [
1
] |
HumanEval/8 | from typing import List, Tuple
def sum_product(numbers: List[int]) -> Tuple[int, int]:
""" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.
Empty sum should be equal to 0 and empty product should be equal to 1.
>>> sum_product([])
(0, 1)
>>> sum_product([1, 2, 3, 4])
(10, 24)
"""
| sum_value = 0
prod_value = 1
for n in numbers:
sum_value += n
prod_value *= n
return sum_value, prod_value
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == (0, 1)
assert candidate([1, 1, 1]) == (3, 1)
assert candidate([100, 0]) == (100, 0)
assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7)
assert candidate([10]) == (10, 10)
| sum_product | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List, Tuple\n\n\ndef sum_product(numbers: List[int]) -> Tuple[int, int]:\n \"\"\" For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list.\n Empty sum should be equal to 0 and e... | [
1
] |
HumanEval/9 | from typing import List, Tuple
def rolling_max(numbers: List[int]) -> List[int]:
""" From a given list of integers, generate a list of rolling maximum element found until given moment
in the sequence.
>>> rolling_max([1, 2, 3, 2, 3, 4, 2])
[1, 2, 3, 3, 3, 4, 4]
"""
| running_max = None
result = []
for n in numbers:
if running_max is None:
running_max = n
else:
running_max = max(running_max, n)
result.append(running_max)
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4]
assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
| rolling_max | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List, Tuple\n\n\ndef rolling_max(numbers: List[int]) -> List[int]:\n \"\"\" From a given list of integers, generate a list of rolling maximum element found until given moment\n in the sequence.\n \"\"\"\n if not numbers:\n ... | [
1
] |
HumanEval/10 |
def is_palindrome(string: str) -> bool:
""" Test if given string is a palindrome """
return string == string[::-1]
def make_palindrome(string: str) -> str:
""" Find the shortest palindrome that begins with a supplied string.
Algorithm idea is simple:
- Find the longest postfix of supplied string that is a palindrome.
- Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.
>>> make_palindrome('')
''
>>> make_palindrome('cat')
'catac'
>>> make_palindrome('cata')
'catac'
"""
| if not string:
return ''
beginning_of_suffix = 0
while not is_palindrome(string[beginning_of_suffix:]):
beginning_of_suffix += 1
return string + string[:beginning_of_suffix][::-1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('x') == 'x'
assert candidate('xyz') == 'xyzyx'
assert candidate('xyx') == 'xyx'
assert candidate('jerry') == 'jerryrrej'
| make_palindrome | [
"Here is the solution to the problem:\n\n```python\ndef is_palindrome(string: str) -> bool:\n \"\"\" Test if given string is a palindrome \"\"\"\n return string == string[::-1]\n\n\ndef make_palindrome(string: str) -> str:\n \"\"\" Find the shortest palindrome that begins with a supplied string.\n Algor... | [
1
] |
HumanEval/11 | from typing import List
def string_xor(a: str, b: str) -> str:
""" Input are two strings a and b consisting only of 1s and 0s.
Perform binary XOR on these inputs and return result also as a string.
>>> string_xor('010', '110')
'100'
"""
| def xor(i, j):
if i == j:
return '0'
else:
return '1'
return ''.join(xor(x, y) for x, y in zip(a, b))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('111000', '101010') == '010010'
assert candidate('1', '1') == '0'
assert candidate('0101', '0000') == '0101'
| string_xor | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List\n\n\ndef string_xor(a: str, b: str) -> str:\n \"\"\" Input are two strings a and b consisting only of 1s and 0s.\n Perform binary XOR on these inputs and return result also as a string.\n \"\"\"\n return ''.join(str(int... | [
1
] |
HumanEval/12 | from typing import List, Optional
def longest(strings: List[str]) -> Optional[str]:
""" Out of list of strings, return the longest one. Return the first one in case of multiple
strings of the same length. Return None in case the input list is empty.
>>> longest([])
>>> longest(['a', 'b', 'c'])
'a'
>>> longest(['a', 'bb', 'ccc'])
'ccc'
"""
| if not strings:
return None
maxlen = max(len(x) for x in strings)
for s in strings:
if len(s) == maxlen:
return s
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == None
assert candidate(['x', 'y', 'z']) == 'x'
assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
| longest | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List, Optional\n\n\ndef longest(strings: List[str]) -> Optional[str]:\n \"\"\" Out of list of strings, return the longest one. Return the first one in case of multiple\n strings of the same length. Return None in case the input li... | [
1
] |
HumanEval/13 |
def greatest_common_divisor(a: int, b: int) -> int:
""" Return a greatest common divisor of two integers a and b
>>> greatest_common_divisor(3, 5)
1
>>> greatest_common_divisor(25, 15)
5
"""
| while b:
a, b = b, a % b
return a
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3, 7) == 1
assert candidate(10, 15) == 5
assert candidate(49, 14) == 7
assert candidate(144, 60) == 12
| greatest_common_divisor | [
"Here is a Python function that calculates the greatest common divisor (GCD) of two integers using the Euclidean algorithm:\n\n```python\ndef greatest_common_divisor(a: int, b: int) -> int:\n \"\"\" Return a greatest common divisor of two integers a and b\n \"\"\"\n while b:\n a, b = b, a % b\n r... | [
1
] |
HumanEval/14 | from typing import List
def all_prefixes(string: str) -> List[str]:
""" Return list of all prefixes from shortest to longest of the input string
>>> all_prefixes('abc')
['a', 'ab', 'abc']
"""
| result = []
for i in range(len(string)):
result.append(string[:i+1])
return result
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh']
assert candidate('WWW') == ['W', 'WW', 'WWW']
| all_prefixes | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List\n\n\ndef all_prefixes(string: str) -> List[str]:\n \"\"\" Return list of all prefixes from shortest to longest of the input string\n \"\"\"\n return [string[:i] for i in range(1, len(string) + 1)]\n```\n\nThis function use... | [
1
] |
HumanEval/15 |
def string_sequence(n: int) -> str:
""" Return a string containing space-delimited numbers starting from 0 upto n inclusive.
>>> string_sequence(0)
'0'
>>> string_sequence(5)
'0 1 2 3 4 5'
"""
| return ' '.join([str(x) for x in range(n + 1)])
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(0) == '0'
assert candidate(3) == '0 1 2 3'
assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
| string_sequence | [
"Here is the Python code to solve the problem:\n\n```python\ndef string_sequence(n: int) -> str:\n \"\"\" Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n \"\"\"\n return ' '.join(str(i) for i in range(n+1))\n```\n\nThis function uses a generator expression to create a... | [
1
] |
HumanEval/16 |
def count_distinct_characters(string: str) -> int:
""" Given a string, find out how many distinct characters (regardless of case) does it consist of
>>> count_distinct_characters('xyzXYZ')
3
>>> count_distinct_characters('Jerry')
4
"""
| return len(set(string.lower()))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('abcde') == 5
assert candidate('abcde' + 'cade' + 'CADE') == 5
assert candidate('aaaaAAAAaaaa') == 1
assert candidate('Jerry jERRY JeRRRY') == 5
| count_distinct_characters | [
"Here is a Python solution for the problem:\n\n```python\ndef count_distinct_characters(string: str) -> int:\n \"\"\" Given a string, find out how many distinct characters (regardless of case) does it consist of\n \"\"\"\n return len(set(string.lower()))\n```\n\nThis function works by converting the string... | [
1
] |
HumanEval/17 | from typing import List
def parse_music(music_string: str) -> List[int]:
""" Input to this function is a string representing musical notes in a special ASCII format.
Your task is to parse this string and return list of integers corresponding to how many beats does each
not last.
Here is a legend:
'o' - whole note, lasts four beats
'o|' - half note, lasts two beats
'.|' - quater note, lasts one beat
>>> parse_music('o o| .| o| o| .| .| .| .| o o')
[4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4]
"""
| note_map = {'o': 4, 'o|': 2, '.|': 1}
return [note_map[x] for x in music_string.split(' ') if x]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == []
assert candidate('o o o o') == [4, 4, 4, 4]
assert candidate('.| .| .| .|') == [1, 1, 1, 1]
assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4]
assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]
| parse_music | [
"Here is the Python code to solve the problem:\n\n```python\nfrom typing import List\n\n\ndef parse_music(music_string: str) -> List[int]:\n \"\"\" Input to this function is a string representing musical notes in a special ASCII format.\n Your task is to parse this string and return list of integers correspon... | [
1
] |
HumanEval/18 |
def how_many_times(string: str, substring: str) -> int:
""" Find how many times a given substring can be found in the original string. Count overlaping cases.
>>> how_many_times('', 'a')
0
>>> how_many_times('aaa', 'a')
3
>>> how_many_times('aaaa', 'aa')
3
"""
| times = 0
for i in range(len(string) - len(substring) + 1):
if string[i:i+len(substring)] == substring:
times += 1
return times
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('', 'x') == 0
assert candidate('xyxyxyx', 'x') == 4
assert candidate('cacacacac', 'cac') == 4
assert candidate('john doe', 'john') == 1
| how_many_times | [
"Here is a Python solution for the problem:\n\n```python\ndef how_many_times(string: str, substring: str) -> int:\n count = 0\n start = 0\n while True:\n start = string.find(substring, start)\n if start == -1: return count\n count += 1\n start += 1\n```\n\nThis function uses the... | [
1
] |
HumanEval/19 | from typing import List
def sort_numbers(numbers: str) -> str:
""" Input is a space-delimited string of numberals from 'zero' to 'nine'.
Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.
Return the string with numbers sorted from smallest to largest
>>> sort_numbers('three one five')
'one three five'
"""
| value_map = {
'zero': 0,
'one': 1,
'two': 2,
'three': 3,
'four': 4,
'five': 5,
'six': 6,
'seven': 7,
'eight': 8,
'nine': 9
}
return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('three') == 'three'
assert candidate('three five nine') == 'three five nine'
assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine'
assert candidate('six five four three two one zero') == 'zero one two three four five six'
| sort_numbers | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef sort_numbers(numbers: str) -> str:\n \"\"\" Input is a space-delimited string of numberals from 'zero' to 'nine'.\n Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n ... | [
1
] |
HumanEval/20 | from typing import List, Tuple
def find_closest_elements(numbers: List[float]) -> Tuple[float, float]:
""" From a supplied list of numbers (of length at least two) select and return two that are the closest to each
other and return them in order (smaller number, larger number).
>>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2])
(2.0, 2.2)
>>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0])
(2.0, 2.0)
"""
| closest_pair = None
distance = None
for idx, elem in enumerate(numbers):
for idx2, elem2 in enumerate(numbers):
if idx != idx2:
if distance is None:
distance = abs(elem - elem2)
closest_pair = tuple(sorted([elem, elem2]))
else:
new_distance = abs(elem - elem2)
if new_distance < distance:
distance = new_distance
closest_pair = tuple(sorted([elem, elem2]))
return closest_pair
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0)
assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2)
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0)
assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)
| find_closest_elements | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List, Tuple\n\n\ndef find_closest_elements(numbers: List[float]) -> Tuple[float, float]:\n \"\"\" From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n other and return them in ... | [
1
] |
HumanEval/21 | from typing import List
def rescale_to_unit(numbers: List[float]) -> List[float]:
""" Given list of numbers (of at least two elements), apply a linear transform to that list,
such that the smallest number will become 0 and the largest will become 1
>>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0])
[0.0, 0.25, 0.5, 0.75, 1.0]
"""
| min_number = min(numbers)
max_number = max(numbers)
return [(x - min_number) / (max_number - min_number) for x in numbers]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([2.0, 49.9]) == [0.0, 1.0]
assert candidate([100.0, 49.9]) == [1.0, 0.0]
assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0]
assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]
assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]
| rescale_to_unit | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef rescale_to_unit(numbers: List[float]) -> List[float]:\n \"\"\" Given list of numbers (of at least two elements), apply a linear transform to that list,\n such that the smallest number will become 0 and the largest will ... | [
1
] |
HumanEval/22 | from typing import List, Any
def filter_integers(values: List[Any]) -> List[int]:
""" Filter given list of any python values only for integers
>>> filter_integers(['a', 3.14, 5])
[5]
>>> filter_integers([1, 2, 3, 'abc', {}, []])
[1, 2, 3]
"""
| return [x for x in values if isinstance(x, int)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9]
assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
| filter_integers | [
"Here is the solution to the problem:\n\n```python\nfrom typing import List, Any\n\n\ndef filter_integers(values: List[Any]) -> List[int]:\n \"\"\" Filter given list of any python values only for integers\n \"\"\"\n return [value for value in values if isinstance(value, int)]\n```\n\nThis function uses lis... | [
1
] |
HumanEval/23 |
def strlen(string: str) -> int:
""" Return length of given string
>>> strlen('')
0
>>> strlen('abc')
3
"""
| return len(string)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == 0
assert candidate('x') == 1
assert candidate('asdasnakj') == 9
| strlen | [
"Here is the solution to the problem:\n\n```python\ndef strlen(string: str) -> int:\n \"\"\" Return length of given string\n \"\"\"\n return len(string)\n```\n\nThis function uses the built-in `len()` function in Python to return the length of the given string."
] | [
1
] |
HumanEval/24 |
def largest_divisor(n: int) -> int:
""" For a given number n, find the largest number that divides n evenly, smaller than n
>>> largest_divisor(15)
5
"""
| for i in reversed(range(n)):
if n % i == 0:
return i
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(3) == 1
assert candidate(7) == 1
assert candidate(10) == 5
assert candidate(100) == 50
assert candidate(49) == 7
| largest_divisor | [
"Here is a Python solution for the problem:\n\n```python\ndef largest_divisor(n: int) -> int:\n \"\"\" For a given number n, find the largest number that divides n evenly, smaller than n\n \"\"\"\n for i in range(n-1, 0, -1):\n if n % i == 0:\n return i\n return 1\n```\n\nThis function... | [
1
] |
HumanEval/25 | from typing import List
def factorize(n: int) -> List[int]:
""" Return list of prime factors of given integer in the order from smallest to largest.
Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.
Input number should be equal to the product of all factors
>>> factorize(8)
[2, 2, 2]
>>> factorize(25)
[5, 5]
>>> factorize(70)
[2, 5, 7]
"""
| import math
fact = []
i = 2
while i <= int(math.sqrt(n) + 1):
if n % i == 0:
fact.append(i)
n //= i
else:
i += 1
if n > 1:
fact.append(n)
return fact
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate(2) == [2]
assert candidate(4) == [2, 2]
assert candidate(8) == [2, 2, 2]
assert candidate(3 * 19) == [3, 19]
assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19]
assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19]
assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19]
assert candidate(3 * 2 * 3) == [2, 3, 3]
| factorize | [
"Here is a Python solution for the problem:\n\n```python\nfrom typing import List\n\n\ndef factorize(n: int) -> List[int]:\n \"\"\" Return list of prime factors of given integer in the order from smallest to largest.\n Each of the factors should be listed number of times corresponding to how many times it app... | [
1
] |
HumanEval/26 | from typing import List
def remove_duplicates(numbers: List[int]) -> List[int]:
""" From a list of integers, remove all elements that occur more than once.
Keep order of elements left the same as in the input.
>>> remove_duplicates([1, 2, 3, 2, 4])
[1, 3, 4]
"""
| import collections
c = collections.Counter(numbers)
return [n for n in numbers if c[n] <= 1]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == []
assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4]
assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
| remove_duplicates | [
"Here is a Python solution using a dictionary to keep track of the count of each number. Then, we iterate over the original list and add the numbers to the result list only if they occur once.\n\n```python\nfrom typing import List\n\n\ndef remove_duplicates(numbers: List[int]) -> List[int]:\n count = {}\n for... | [
1
] |
HumanEval/27 |
def flip_case(string: str) -> str:
""" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.
>>> flip_case('Hello')
'hELLO'
"""
| return string.swapcase()
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate('') == ''
assert candidate('Hello!') == 'hELLO!'
assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
| flip_case | [
"Here is the Python code to solve the problem:\n\n```python\ndef flip_case(string: str) -> str:\n \"\"\" For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n \"\"\"\n return string.swapcase()\n```\n\nThe `swapcase()` function in Python is used to swap the case of all cha... | [
1
] |
HumanEval/28 | from typing import List
def concatenate(strings: List[str]) -> str:
""" Concatenate list of strings into a single string
>>> concatenate([])
''
>>> concatenate(['a', 'b', 'c'])
'abc'
"""
| return ''.join(strings)
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([]) == ''
assert candidate(['x', 'y', 'z']) == 'xyz'
assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
| concatenate | [
"Here is the solution to the problem:\n\n```python\nfrom typing import List\n\n\ndef concatenate(strings: List[str]) -> str:\n \"\"\" Concatenate list of strings into a single string\n \"\"\"\n return ''.join(strings)\n```\n\nIn this solution, we use the built-in Python function `join()`, which is a string... | [
1
] |
HumanEval/29 | from typing import List
def filter_by_prefix(strings: List[str], prefix: str) -> List[str]:
""" Filter an input list of strings only for ones that start with a given prefix.
>>> filter_by_prefix([], 'a')
[]
>>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a')
['abc', 'array']
"""
| return [x for x in strings if x.startswith(prefix)]
|
METADATA = {
'author': 'jt',
'dataset': 'test'
}
def check(candidate):
assert candidate([], 'john') == []
assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
| filter_by_prefix | [
"Here is the solution to the problem:\n\n```python\nfrom typing import List\n\n\ndef filter_by_prefix(strings: List[str], prefix: str) -> List[str]:\n \"\"\" Filter an input list of strings only for ones that start with a given prefix.\n \"\"\"\n return [s for s in strings if s.startswith(prefix)]\n```\n\n... | [
1
] |
HumanEval/30 |
def get_positive(l: list):
"""Return only positive numbers in the list.
>>> get_positive([-1, 2, -4, 5, 6])
[2, 5, 6]
>>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
[5, 3, 2, 3, 9, 123, 1]
"""
| return [e for e in l if e > 0]
|
METADATA = {}
def check(candidate):
assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6]
assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1]
assert candidate([-1, -2]) == []
assert candidate([]) == []
| get_positive | [
"Here is a simple Python function that solves the problem:\n\n```python\ndef get_positive(l: list):\n \"\"\"Return only positive numbers in the list.\n \"\"\"\n return [i for i in l if i > 0]\n```\n\nThis function uses list comprehension to iterate over the list and return a new list that only contains pos... | [
1
] |
HumanEval/31 |
def is_prime(n):
"""Return true if a given number is prime, and false otherwise.
>>> is_prime(6)
False
>>> is_prime(101)
True
>>> is_prime(11)
True
>>> is_prime(13441)
True
>>> is_prime(61)
True
>>> is_prime(4)
False
>>> is_prime(1)
False
"""
| if n < 2:
return False
for k in range(2, n - 1):
if n % k == 0:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate(6) == False
assert candidate(101) == True
assert candidate(11) == True
assert candidate(13441) == True
assert candidate(61) == True
assert candidate(4) == False
assert candidate(1) == False
assert candidate(5) == True
assert candidate(11) == True
assert candidate(17) == True
assert candidate(5 * 17) == False
assert candidate(11 * 7) == False
assert candidate(13441 * 19) == False
| is_prime | [
"Here is a simple Python function that checks if a number is prime:\n\n```python\ndef is_prime(n):\n \"\"\"Return true if a given number is prime, and false otherwise.\"\"\"\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n ... | [
1
] |
HumanEval/32 | import math
def poly(xs: list, x: float):
"""
Evaluates polynomial with coefficients xs at point x.
return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n
"""
return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)])
def find_zero(xs: list):
""" xs are coefficients of a polynomial.
find_zero find x such that poly(x) = 0.
find_zero returns only only zero point, even if there are many.
Moreover, find_zero only takes list xs having even number of coefficients
and largest non zero coefficient as it guarantees
a solution.
>>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x
-0.5
>>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3
1.0
"""
| begin, end = -1., 1.
while poly(xs, begin) * poly(xs, end) > 0:
begin *= 2.0
end *= 2.0
while end - begin > 1e-10:
center = (begin + end) / 2.0
if poly(xs, center) * poly(xs, begin) > 0:
begin = center
else:
end = center
return begin
|
METADATA = {}
def check(candidate):
import math
import random
rng = random.Random(42)
import copy
for _ in range(100):
ncoeff = 2 * rng.randint(1, 4)
coeffs = []
for _ in range(ncoeff):
coeff = rng.randint(-10, 10)
if coeff == 0:
coeff = 1
coeffs.append(coeff)
solution = candidate(copy.deepcopy(coeffs))
assert math.fabs(poly(coeffs, solution)) < 1e-4
| find_zero | [
"To solve the problem of finding a zero of a polynomial given its coefficients, we can use numerical methods. One common method for finding roots of polynomials is the Newton-Raphson method. This method requires the polynomial and its derivative. Here's how you can implement it in Python:\n\n1. Define the polynomia... | [
0
] |
HumanEval/33 |
def sort_third(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal
to the values of the corresponding indicies of l, but sorted.
>>> sort_third([1, 2, 3])
[1, 2, 3]
>>> sort_third([5, 6, 3, 4, 8, 9, 2])
[2, 6, 3, 4, 8, 9, 5]
"""
| l = list(l)
l[::3] = sorted(l[::3])
return l
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3]))
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]))
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10]))
assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5])
assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5])
assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5])
assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])
| sort_third | [
"Here is a Python solution for the problem:\n\n```python\ndef sort_third(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n to the val... | [
1
] |
HumanEval/34 |
def unique(l: list):
"""Return sorted unique elements in a list
>>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123])
[0, 2, 3, 5, 9, 123]
"""
| return sorted(list(set(l)))
|
METADATA = {}
def check(candidate):
assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
| unique | [
"Here is a Python solution for the problem:\n\n```python\ndef unique(l: list):\n \"\"\"Return sorted unique elements in a list\n \"\"\"\n return sorted(set(l))\n```\n\nThis function works by first converting the list to a set, which automatically removes any duplicate elements. Then it converts the set bac... | [
1
] |
HumanEval/35 |
def max_element(l: list):
"""Return maximum element in the list.
>>> max_element([1, 2, 3])
3
>>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])
123
"""
| m = l[0]
for e in l:
if e > m:
m = e
return m
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 3]) == 3
assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
| max_element | [
"Here is a simple Python function that solves the problem:\n\n```python\ndef max_element(l: list):\n \"\"\"Return maximum element in the list.\n \"\"\"\n return max(l)\n```\n\nThis function uses Python's built-in `max()` function to find and return the maximum element in the list. If the list is empty, it ... | [
1
] |
HumanEval/36 |
def fizz_buzz(n: int):
"""Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.
>>> fizz_buzz(50)
0
>>> fizz_buzz(78)
2
>>> fizz_buzz(79)
3
"""
| ns = []
for i in range(n):
if i % 11 == 0 or i % 13 == 0:
ns.append(i)
s = ''.join(list(map(str, ns)))
ans = 0
for c in s:
ans += (c == '7')
return ans
|
METADATA = {}
def check(candidate):
assert candidate(50) == 0
assert candidate(78) == 2
assert candidate(79) == 3
assert candidate(100) == 3
assert candidate(200) == 6
assert candidate(4000) == 192
assert candidate(10000) == 639
assert candidate(100000) == 8026
| fizz_buzz | [
"Here is a Python solution for the problem:\n\n```python\ndef fizz_buzz(n: int) -> int:\n count = 0\n for i in range(n):\n if i % 11 == 0 or i % 13 == 0:\n count += str(i).count('7')\n return count\n```\n\nThis function works by iterating over all numbers less than `n`. For each number, i... | [
1
] |
HumanEval/37 |
def sort_even(l: list):
"""This function takes a list l and returns a list l' such that
l' is identical to l in the odd indicies, while its values at the even indicies are equal
to the values of the even indicies of l, but sorted.
>>> sort_even([1, 2, 3])
[1, 2, 3]
>>> sort_even([5, 6, 3, 4])
[3, 6, 5, 4]
"""
| evens = l[::2]
odds = l[1::2]
evens.sort()
ans = []
for e, o in zip(evens, odds):
ans.extend([e, o])
if len(evens) > len(odds):
ans.append(evens[-1])
return ans
|
METADATA = {}
def check(candidate):
assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3])
assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123])
assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])
| sort_even | [
"Here is a Python solution for the problem:\n\n```python\ndef sort_even(l: list):\n \"\"\"This function takes a list l and returns a list l' such that\n l' is identical to l in the odd indicies, while its values at the even indicies are equal\n to the values of the even indicies of l, but sorted.\n \"\"... | [
1
] |
HumanEval/38 |
def encode_cyclic(s: str):
"""
returns encoded string by cycling groups of three characters.
"""
# split string to groups. Each of length 3.
groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)]
# cycle elements in each group. Unless group has fewer elements than 3.
groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups]
return "".join(groups)
def decode_cyclic(s: str):
"""
takes as input string encoded with encode_cyclic function. Returns decoded string.
"""
| return encode_cyclic(encode_cyclic(s))
|
METADATA = {}
def check(candidate):
from random import randint, choice
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_cyclic(str)
assert candidate(encoded_str) == str
| decode_cyclic | [
"Here is the solution for the problem:\n\n```python\ndef decode_cyclic(s: str):\n \"\"\"\n takes as input string encoded with encode_cyclic function. Returns decoded string.\n \"\"\"\n # split string to groups. Each of length 3.\n groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) +... | [
0
] |
HumanEval/39 |
def prime_fib(n: int):
"""
prime_fib returns n-th number that is a Fibonacci number and it's also prime.
>>> prime_fib(1)
2
>>> prime_fib(2)
3
>>> prime_fib(3)
5
>>> prime_fib(4)
13
>>> prime_fib(5)
89
"""
| import math
def is_prime(p):
if p < 2:
return False
for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)):
if p % k == 0:
return False
return True
f = [0, 1]
while True:
f.append(f[-1] + f[-2])
if is_prime(f[-1]):
n -= 1
if n == 0:
return f[-1]
|
METADATA = {}
def check(candidate):
assert candidate(1) == 2
assert candidate(2) == 3
assert candidate(3) == 5
assert candidate(4) == 13
assert candidate(5) == 89
assert candidate(6) == 233
assert candidate(7) == 1597
assert candidate(8) == 28657
assert candidate(9) == 514229
assert candidate(10) == 433494437
| prime_fib | [
"Here is a Python solution for the problem:\n\n```python\ndef prime_fib(n: int):\n def is_prime(num):\n if num < 2:\n return False\n for i in range(2, int(num**0.5) + 1):\n if num % i == 0:\n return False\n return True\n\n def fib_generator():\n ... | [
1
] |
HumanEval/40 |
def triples_sum_to_zero(l: list):
"""
triples_sum_to_zero takes a list of integers as an input.
it returns True if there are three distinct elements in the list that
sum to zero, and False otherwise.
>>> triples_sum_to_zero([1, 3, 5, 0])
False
>>> triples_sum_to_zero([1, 3, -2, 1])
True
>>> triples_sum_to_zero([1, 2, 3, 7])
False
>>> triples_sum_to_zero([2, 4, -5, 3, 9, 7])
True
>>> triples_sum_to_zero([1])
False
"""
| for i in range(len(l)):
for j in range(i + 1, len(l)):
for k in range(j + 1, len(l)):
if l[i] + l[j] + l[k] == 0:
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 3, 5, 0]) == False
assert candidate([1, 3, 5, -1]) == False
assert candidate([1, 3, -2, 1]) == True
assert candidate([1, 2, 3, 7]) == False
assert candidate([1, 2, 5, 7]) == False
assert candidate([2, 4, -5, 3, 9, 7]) == True
assert candidate([1]) == False
assert candidate([1, 3, 5, -100]) == False
assert candidate([100, 3, 5, -100]) == False
| triples_sum_to_zero | [
"Here is a Python solution using a set to store the complements of the sums of pairs of numbers. This solution has a time complexity of O(n^2), which is efficient for this problem.\n\n```python\ndef triples_sum_to_zero(l: list):\n n = len(l)\n for i in range(n):\n s = set()\n for j in range(i + ... | [
1
] |
HumanEval/41 |
def car_race_collision(n: int):
"""
Imagine a road that's a perfectly straight infinitely long line.
n cars are driving left to right; simultaneously, a different set of n cars
are driving right to left. The two sets of cars start out being very far from
each other. All cars move in the same speed. Two cars are said to collide
when a car that's moving left to right hits a car that's moving right to left.
However, the cars are infinitely sturdy and strong; as a result, they continue moving
in their trajectory as if they did not collide.
This function outputs the number of such collisions.
"""
| return n**2
|
METADATA = {}
def check(candidate):
assert candidate(2) == 4
assert candidate(3) == 9
assert candidate(4) == 16
assert candidate(8) == 64
assert candidate(10) == 100
| car_race_collision | [
"The problem is quite straightforward. Since all cars are moving at the same speed and the road is infinitely long, each car moving left to right will collide with each car moving right to left exactly once. Therefore, the total number of collisions will be the product of the number of cars moving in each direction... | [
1
] |
HumanEval/42 |
def incr_list(l: list):
"""Return list with elements incremented by 1.
>>> incr_list([1, 2, 3])
[2, 3, 4]
>>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123])
[6, 4, 6, 3, 4, 4, 10, 1, 124]
"""
| return [(e + 1) for e in l]
|
METADATA = {}
def check(candidate):
assert candidate([]) == []
assert candidate([3, 2, 1]) == [4, 3, 2]
assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
| incr_list | [
"Here is a simple Python function that solves the problem:\n\n```python\ndef incr_list(l: list):\n \"\"\"Return list with elements incremented by 1.\n \"\"\"\n return [i + 1 for i in l]\n```\n\nThis function uses a list comprehension to create a new list where each element is the corresponding element in t... | [
1
] |
HumanEval/43 |
def pairs_sum_to_zero(l):
"""
pairs_sum_to_zero takes a list of integers as an input.
it returns True if there are two distinct elements in the list that
sum to zero, and False otherwise.
>>> pairs_sum_to_zero([1, 3, 5, 0])
False
>>> pairs_sum_to_zero([1, 3, -2, 1])
False
>>> pairs_sum_to_zero([1, 2, 3, 7])
False
>>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7])
True
>>> pairs_sum_to_zero([1])
False
"""
| for i, l1 in enumerate(l):
for j in range(i + 1, len(l)):
if l1 + l[j] == 0:
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 3, 5, 0]) == False
assert candidate([1, 3, -2, 1]) == False
assert candidate([1, 2, 3, 7]) == False
assert candidate([2, 4, -5, 3, 5, 7]) == True
assert candidate([1]) == False
assert candidate([-3, 9, -1, 3, 2, 30]) == True
assert candidate([-3, 9, -1, 3, 2, 31]) == True
assert candidate([-3, 9, -1, 4, 2, 30]) == False
assert candidate([-3, 9, -1, 4, 2, 31]) == False
| pairs_sum_to_zero | [
"Here is a Python solution for the problem:\n\n```python\ndef pairs_sum_to_zero(l):\n \"\"\"\n pairs_sum_to_zero takes a list of integers as an input.\n it returns True if there are two distinct elements in the list that\n sum to zero, and False otherwise.\n \"\"\"\n seen = set()\n for num in l... | [
1
] |
HumanEval/44 |
def change_base(x: int, base: int):
"""Change numerical base of input number x to base.
return string representation after the conversion.
base numbers are less than 10.
>>> change_base(8, 3)
'22'
>>> change_base(8, 2)
'1000'
>>> change_base(7, 2)
'111'
"""
| ret = ""
while x > 0:
ret = str(x % base) + ret
x //= base
return ret
|
METADATA = {}
def check(candidate):
assert candidate(8, 3) == "22"
assert candidate(9, 3) == "100"
assert candidate(234, 2) == "11101010"
assert candidate(16, 2) == "10000"
assert candidate(8, 2) == "1000"
assert candidate(7, 2) == "111"
for x in range(2, 8):
assert candidate(x, x + 1) == str(x)
| change_base | [
"Here is a Python function that solves the problem:\n\n```python\ndef change_base(x: int, base: int):\n \"\"\"Change numerical base of input number x to base.\n return string representation after the conversion.\n base numbers are less than 10.\n \"\"\"\n if base < 2 or base > 9:\n raise Value... | [
0
] |
HumanEval/45 |
def triangle_area(a, h):
"""Given length of a side and high return area for a triangle.
>>> triangle_area(5, 3)
7.5
"""
| return a * h / 2.0
|
METADATA = {}
def check(candidate):
assert candidate(5, 3) == 7.5
assert candidate(2, 2) == 2.0
assert candidate(10, 8) == 40.0
| triangle_area | [
"Here is the Python code to solve the problem:\n\n```python\ndef triangle_area(a, h):\n \"\"\"Given length of a side and high return area for a triangle.\n \"\"\"\n return 0.5 * a * h\n```\n\nThis function takes two arguments, `a` (the length of a side of the triangle) and `h` (the height of the triangle),... | [
1
] |
HumanEval/46 |
def fib4(n: int):
"""The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fib4(0) -> 0
fib4(1) -> 0
fib4(2) -> 2
fib4(3) -> 0
fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).
Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion.
>>> fib4(5)
4
>>> fib4(6)
8
>>> fib4(7)
14
"""
| results = [0, 0, 2, 0]
if n < 4:
return results[n]
for _ in range(4, n + 1):
results.append(results[-1] + results[-2] + results[-3] + results[-4])
results.pop(0)
return results[-1]
|
METADATA = {}
def check(candidate):
assert candidate(5) == 4
assert candidate(8) == 28
assert candidate(10) == 104
assert candidate(12) == 386
| fib4 | [
"Sure, I can help you with that. The Fib4 sequence is a sequence similar to the Fibonacci sequence, but it is defined as follows:\n\n- Fib4(0) = 0\n- Fib4(1) = 1\n- Fib4(2) = 1\n- Fib4(3) = 2\n- Fib4(n) = Fib4(n-1) + Fib4(n-2) + Fib4(n-3) + Fib4(n-4) for n > 3\n\nHere is the Python function to compute the nth Fib4 ... | [
0
] |
HumanEval/47 |
def median(l: list):
"""Return median of elements in the list l.
>>> median([3, 1, 2, 4, 5])
3
>>> median([-10, 4, 6, 1000, 10, 20])
15.0
"""
| l = sorted(l)
if len(l) % 2 == 1:
return l[len(l) // 2]
else:
return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == 3
assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0
assert candidate([5]) == 5
assert candidate([6, 5]) == 5.5
assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7
| median | [
"Here is a Python function that calculates the median of a list:\n\n```python\ndef median(l: list):\n \"\"\"Return median of elements in the list l.\n \"\"\"\n l.sort()\n n = len(l)\n if n % 2 == 0:\n return (l[n//2 - 1] + l[n//2]) / 2\n else:\n return l[n//2]\n```\n\nThis function f... | [
1
] |
HumanEval/48 |
def is_palindrome(text: str):
"""
Checks if given string is a palindrome
>>> is_palindrome('')
True
>>> is_palindrome('aba')
True
>>> is_palindrome('aaaaa')
True
>>> is_palindrome('zbcd')
False
"""
| for i in range(len(text)):
if text[i] != text[len(text) - 1 - i]:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate('') == True
assert candidate('aba') == True
assert candidate('aaaaa') == True
assert candidate('zbcd') == False
assert candidate('xywyx') == True
assert candidate('xywyz') == False
assert candidate('xywzx') == False
| is_palindrome | [
"Here is a Python function that checks if a given string is a palindrome:\n\n```python\ndef is_palindrome(text: str) -> bool:\n \"\"\"\n Checks if given string is a palindrome\n \"\"\"\n return text == text[::-1]\n```\n\nThis function works by comparing the original string with its reverse. If they are ... | [
1
] |
HumanEval/49 |
def modp(n: int, p: int):
"""Return 2^n modulo p (be aware of numerics).
>>> modp(3, 5)
3
>>> modp(1101, 101)
2
>>> modp(0, 101)
1
>>> modp(3, 11)
8
>>> modp(100, 101)
1
"""
| ret = 1
for i in range(n):
ret = (2 * ret) % p
return ret
|
METADATA = {}
def check(candidate):
assert candidate(3, 5) == 3
assert candidate(1101, 101) == 2
assert candidate(0, 101) == 1
assert candidate(3, 11) == 8
assert candidate(100, 101) == 1
assert candidate(30, 5) == 4
assert candidate(31, 5) == 3
| modp | [
"Here is a Python solution for the problem:\n\n```python\ndef modp(n: int, p: int) -> int:\n \"\"\"Return 2^n modulo p (be aware of numerics).\n \"\"\"\n return pow(2, n, p)\n```\n\nThis function uses Python's built-in pow function, which can take three arguments: the base, the exponent, and the modulus. I... | [
1
] |
HumanEval/50 |
def encode_shift(s: str):
"""
returns encoded string by shifting every character by 5 in the alphabet.
"""
return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s])
def decode_shift(s: str):
"""
takes as input string encoded with encode_shift function. Returns decoded string.
"""
| return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
|
METADATA = {}
def check(candidate):
from random import randint, choice
import copy
import string
letters = string.ascii_lowercase
for _ in range(100):
str = ''.join(choice(letters) for i in range(randint(10, 20)))
encoded_str = encode_shift(str)
assert candidate(copy.deepcopy(encoded_str)) == str
| decode_shift | [
"Here is the solution for the problem:\n\n```python\ndef encode_shift(s: str):\n \"\"\"\n returns encoded string by shifting every character by 5 in the alphabet.\n \"\"\"\n return \"\".join([chr(((ord(ch) + 5 - ord(\"a\")) % 26) + ord(\"a\")) for ch in s])\n\n\ndef decode_shift(s: str):\n \"\"\"\n ... | [
0
] |
HumanEval/51 |
def remove_vowels(text):
"""
remove_vowels is a function that takes string and returns string without vowels.
>>> remove_vowels('')
''
>>> remove_vowels("abcdef\nghijklm")
'bcdf\nghjklm'
>>> remove_vowels('abcdef')
'bcdf'
>>> remove_vowels('aaaaa')
''
>>> remove_vowels('aaBAA')
'B'
>>> remove_vowels('zbcd')
'zbcd'
"""
| return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
|
METADATA = {}
def check(candidate):
assert candidate('') == ''
assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm'
assert candidate('fedcba') == 'fdcb'
assert candidate('eeeee') == ''
assert candidate('acBAA') == 'cB'
assert candidate('EcBOO') == 'cB'
assert candidate('ybcd') == 'ybcd'
| remove_vowels | [
"Here is a Python solution for the problem:\n\n```python\ndef remove_vowels(text):\n \"\"\"\n remove_vowels is a function that takes string and returns string without vowels.\n \"\"\"\n vowels = 'aeiouAEIOU'\n return ''.join([char for char in text if char not in vowels])\n```\n\nThis function works b... | [
1
] |
HumanEval/52 |
def below_threshold(l: list, t: int):
"""Return True if all numbers in the list l are below threshold t.
>>> below_threshold([1, 2, 4, 10], 100)
True
>>> below_threshold([1, 20, 4, 10], 5)
False
"""
| for e in l:
if e >= t:
return False
return True
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 4, 10], 100)
assert not candidate([1, 20, 4, 10], 5)
assert candidate([1, 20, 4, 10], 21)
assert candidate([1, 20, 4, 10], 22)
assert candidate([1, 8, 4, 10], 11)
assert not candidate([1, 8, 4, 10], 10)
| below_threshold | [
"Here is a simple Python function that solves the problem:\n\n```python\ndef below_threshold(l: list, t: int) -> bool:\n \"\"\"Return True if all numbers in the list l are below threshold t.\"\"\"\n for num in l:\n if num >= t:\n return False\n return True\n```\n\nThis function iterates o... | [
1
] |
HumanEval/53 |
def add(x: int, y: int):
"""Add two numbers x and y
>>> add(2, 3)
5
>>> add(5, 7)
12
"""
| return x + y
|
METADATA = {}
def check(candidate):
import random
assert candidate(0, 1) == 1
assert candidate(1, 0) == 1
assert candidate(2, 3) == 5
assert candidate(5, 7) == 12
assert candidate(7, 5) == 12
for i in range(100):
x, y = random.randint(0, 1000), random.randint(0, 1000)
assert candidate(x, y) == x + y
| add | [
"Here is the solution to the problem:\n\n```python\ndef add(x: int, y: int) -> int:\n \"\"\"Add two numbers x and y\n \"\"\"\n return x + y\n```\n\nThis function takes two integers as input and returns their sum."
] | [
0
] |
HumanEval/54 |
def same_chars(s0: str, s1: str):
"""
Check if two words have the same characters.
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')
True
>>> same_chars('abcd', 'dddddddabc')
True
>>> same_chars('dddddddabc', 'abcd')
True
>>> same_chars('eabcd', 'dddddddabc')
False
>>> same_chars('abcd', 'dddddddabce')
False
>>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')
False
"""
| return set(s0) == set(s1)
|
METADATA = {}
def check(candidate):
assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True
assert candidate('abcd', 'dddddddabc') == True
assert candidate('dddddddabc', 'abcd') == True
assert candidate('eabcd', 'dddddddabc') == False
assert candidate('abcd', 'dddddddabcf') == False
assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False
assert candidate('aabb', 'aaccc') == False
| same_chars | [
"Here is a Python solution for the problem:\n\n```python\ndef same_chars(s0: str, s1: str) -> bool:\n \"\"\"\n Check if two words have the same characters.\n \"\"\"\n return set(s0) == set(s1)\n```\n\nThis function works by converting each string into a set of characters, which automatically removes any... | [
1
] |
HumanEval/55 |
def fib(n: int):
"""Return n-th Fibonacci number.
>>> fib(10)
55
>>> fib(1)
1
>>> fib(8)
21
"""
| if n == 0:
return 0
if n == 1:
return 1
return fib(n - 1) + fib(n - 2)
|
METADATA = {}
def check(candidate):
assert candidate(10) == 55
assert candidate(1) == 1
assert candidate(8) == 21
assert candidate(11) == 89
assert candidate(12) == 144
| fib | [
"Here is a simple Python function that calculates the n-th Fibonacci number using recursion:\n\n```python\ndef fib(n: int):\n \"\"\"Return n-th Fibonacci number.\n \"\"\"\n if n <= 0:\n return \"Input should be a positive integer\"\n elif n == 1:\n return 0\n elif n == 2:\n retur... | [
0
] |
HumanEval/56 |
def correct_bracketing(brackets: str):
""" brackets is a string of "<" and ">".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("<")
False
>>> correct_bracketing("<>")
True
>>> correct_bracketing("<<><>>")
True
>>> correct_bracketing("><<>")
False
"""
| depth = 0
for b in brackets:
if b == "<":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("<>")
assert candidate("<<><>>")
assert candidate("<><><<><>><>")
assert candidate("<><><<<><><>><>><<><><<>>>")
assert not candidate("<<<><>>>>")
assert not candidate("><<>")
assert not candidate("<")
assert not candidate("<<<<")
assert not candidate(">")
assert not candidate("<<>")
assert not candidate("<><><<><>><>><<>")
assert not candidate("<><><<><>><>>><>")
| correct_bracketing | [
"Here is a Python solution for the problem:\n\n```python\ndef correct_bracketing(brackets: str) -> bool:\n stack = []\n for bracket in brackets:\n if bracket == '<':\n stack.append(bracket)\n elif bracket == '>':\n if not stack:\n return False\n st... | [
1
] |
HumanEval/57 |
def monotonic(l: list):
"""Return True is list elements are monotonically increasing or decreasing.
>>> monotonic([1, 2, 4, 20])
True
>>> monotonic([1, 20, 4, 10])
False
>>> monotonic([4, 1, 0, -10])
True
"""
| if l == sorted(l) or l == sorted(l, reverse=True):
return True
return False
|
METADATA = {}
def check(candidate):
assert candidate([1, 2, 4, 10]) == True
assert candidate([1, 2, 4, 20]) == True
assert candidate([1, 20, 4, 10]) == False
assert candidate([4, 1, 0, -10]) == True
assert candidate([4, 1, 1, 0]) == True
assert candidate([1, 2, 3, 2, 5, 60]) == False
assert candidate([1, 2, 3, 4, 5, 60]) == True
assert candidate([9, 9, 9, 9]) == True
| monotonic | [
"Here is a Python solution for the problem:\n\n```python\ndef monotonic(l: list):\n \"\"\"Return True is list elements are monotonically increasing or decreasing.\n \"\"\"\n return (all(l[i] <= l[i + 1] for i in range(len(l) - 1)) or\n all(l[i] >= l[i + 1] for i in range(len(l) - 1)))\n```\n\nTh... | [
1
] |
HumanEval/58 |
def common(l1: list, l2: list):
"""Return sorted unique common elements for two lists.
>>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121])
[1, 5, 653]
>>> common([5, 3, 2, 8], [3, 2])
[2, 3]
"""
| ret = set()
for e1 in l1:
for e2 in l2:
if e1 == e2:
ret.add(e1)
return sorted(list(ret))
|
METADATA = {}
def check(candidate):
assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653]
assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3]
assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4]
assert candidate([4, 3, 2, 8], []) == []
| common | [
"Here is a Python solution for the problem:\n\n```python\ndef common(l1: list, l2: list):\n \"\"\"Return sorted unique common elements for two lists.\n \"\"\"\n return sorted(list(set(l1) & set(l2)))\n```\n\nThis function works by first converting both lists to sets, which automatically removes any duplica... | [
1
] |
HumanEval/59 |
def largest_prime_factor(n: int):
"""Return the largest prime factor of n. Assume n > 1 and is not a prime.
>>> largest_prime_factor(13195)
29
>>> largest_prime_factor(2048)
2
"""
| def is_prime(k):
if k < 2:
return False
for i in range(2, k - 1):
if k % i == 0:
return False
return True
largest = 1
for j in range(2, n + 1):
if n % j == 0 and is_prime(j):
largest = max(largest, j)
return largest
|
METADATA = {}
def check(candidate):
assert candidate(15) == 5
assert candidate(27) == 3
assert candidate(63) == 7
assert candidate(330) == 11
assert candidate(13195) == 29
| largest_prime_factor | [
"Here is a Python solution for the problem:\n\n```python\ndef largest_prime_factor(n: int):\n \"\"\"Return the largest prime factor of n. Assume n > 1 and is not a prime.\n \"\"\"\n i = 2\n while i * i <= n:\n if n % i:\n i += 1\n else:\n n //= i\n return n\n```\n\... | [
1
] |
HumanEval/60 |
def sum_to_n(n: int):
"""sum_to_n is a function that sums numbers from 1 to n.
>>> sum_to_n(30)
465
>>> sum_to_n(100)
5050
>>> sum_to_n(5)
15
>>> sum_to_n(10)
55
>>> sum_to_n(1)
1
"""
| return sum(range(n + 1))
|
METADATA = {}
def check(candidate):
assert candidate(1) == 1
assert candidate(6) == 21
assert candidate(11) == 66
assert candidate(30) == 465
assert candidate(100) == 5050
| sum_to_n | [
"Here is a simple Python function that solves the problem:\n\n```python\ndef sum_to_n(n: int) -> int:\n \"\"\"sum_to_n is a function that sums numbers from 1 to n.\n \"\"\"\n return sum(range(1, n+1))\n```\n\nThis function uses Python's built-in `sum` function and `range` function to generate a sequence of... | [
1
] |
HumanEval/61 |
def correct_bracketing(brackets: str):
""" brackets is a string of "(" and ")".
return True if every opening bracket has a corresponding closing bracket.
>>> correct_bracketing("(")
False
>>> correct_bracketing("()")
True
>>> correct_bracketing("(()())")
True
>>> correct_bracketing(")(()")
False
"""
| depth = 0
for b in brackets:
if b == "(":
depth += 1
else:
depth -= 1
if depth < 0:
return False
return depth == 0
|
METADATA = {}
def check(candidate):
assert candidate("()")
assert candidate("(()())")
assert candidate("()()(()())()")
assert candidate("()()((()()())())(()()(()))")
assert not candidate("((()())))")
assert not candidate(")(()")
assert not candidate("(")
assert not candidate("((((")
assert not candidate(")")
assert not candidate("(()")
assert not candidate("()()(()())())(()")
assert not candidate("()()(()())()))()")
| correct_bracketing | [
"Here is a Python solution for the problem:\n\n```python\ndef correct_bracketing(brackets: str) -> bool:\n stack = []\n for bracket in brackets:\n if bracket == '(':\n stack.append(bracket)\n elif bracket == ')':\n if not stack:\n return False\n st... | [
1
] |
HumanEval/62 |
def derivative(xs: list):
""" xs represent coefficients of a polynomial.
xs[0] + xs[1] * x + xs[2] * x^2 + ....
Return derivative of this polynomial in the same form.
>>> derivative([3, 1, 2, 4, 5])
[1, 4, 12, 20]
>>> derivative([1, 2, 3])
[2, 6]
"""
| return [(i * x) for i, x in enumerate(xs)][1:]
|
METADATA = {}
def check(candidate):
assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20]
assert candidate([1, 2, 3]) == [2, 6]
assert candidate([3, 2, 1]) == [2, 2]
assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16]
assert candidate([1]) == []
| derivative | [
"Here is a Python function that calculates the derivative of a polynomial represented by a list of coefficients:\n\n```python\ndef derivative(xs: list):\n \"\"\" xs represent coefficients of a polynomial.\n xs[0] + xs[1] * x + xs[2] * x^2 + ....\n Return derivative of this polynomial in the same form.\n ... | [
1
] |
HumanEval/63 |
def fibfib(n: int):
"""The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:
fibfib(0) == 0
fibfib(1) == 0
fibfib(2) == 1
fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).
Please write a function to efficiently compute the n-th element of the fibfib number sequence.
>>> fibfib(1)
0
>>> fibfib(5)
4
>>> fibfib(8)
24
"""
| if n == 0:
return 0
if n == 1:
return 0
if n == 2:
return 1
return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
|
METADATA = {}
def check(candidate):
assert candidate(2) == 1
assert candidate(1) == 0
assert candidate(5) == 4
assert candidate(8) == 24
assert candidate(10) == 81
assert candidate(12) == 274
assert candidate(14) == 927
| fibfib | [
"Here is a Python solution for the FibFib sequence:\n\n```python\ndef fibfib(n: int):\n \"\"\"The FibFib number sequence is a sequence similar to the Fibonacci sequence that's defined as follows:\n fibfib(0) = 0\n fibfib(1) = 1\n fibfib(n) = fibfib(n-1) + fibfib(n-2) for n > 1\n \"\"\"\n if n == 0... | [
0
] |
HumanEval/64 |
FIX = """
Add more test cases.
"""
def vowels_count(s):
"""Write a function vowels_count which takes a string representing
a word as input and returns the number of vowels in the string.
Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a
vowel, but only when it is at the end of the given word.
Example:
>>> vowels_count("abcde")
2
>>> vowels_count("ACEDY")
3
"""
| vowels = "aeiouAEIOU"
n_vowels = sum(c in vowels for c in s)
if s[-1] == 'y' or s[-1] == 'Y':
n_vowels += 1
return n_vowels
| def check(candidate):
# Check some simple cases
assert candidate("abcde") == 2, "Test 1"
assert candidate("Alone") == 3, "Test 2"
assert candidate("key") == 2, "Test 3"
assert candidate("bye") == 1, "Test 4"
assert candidate("keY") == 2, "Test 5"
assert candidate("bYe") == 1, "Test 6"
assert candidate("ACEDY") == 3, "Test 7"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
| vowels_count | [
"Here is the solution to the problem:\n\n```python\ndef vowels_count(s):\n \"\"\"Write a function vowels_count which takes a string representing\n a word as input and returns the number of vowels in the string.\n Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n vowel, but only when... | [
1
] |
HumanEval/65 |
def circular_shift(x, shift):
"""Circular shift the digits of the integer x, shift the digits right by shift
and return the result as a string.
If shift > number of digits, return digits reversed.
>>> circular_shift(12, 1)
"21"
>>> circular_shift(12, 2)
"12"
"""
| s = str(x)
if shift > len(s):
return s[::-1]
else:
return s[len(s) - shift:] + s[:len(s) - shift]
| def check(candidate):
# Check some simple cases
assert candidate(100, 2) == "001"
assert candidate(12, 2) == "12"
assert candidate(97, 8) == "79"
assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(11, 101) == "11", "This prints if this assert fails 2 (also good for debugging!)"
| circular_shift | [
"Here is a Python solution for the problem:\n\n```python\ndef circular_shift(x, shift):\n \"\"\"Circular shift the digits of the integer x, shift the digits right by shift\n and return the result as a string.\n If shift > number of digits, return digits reversed.\n \"\"\"\n x = str(x)\n if shift >... | [
1
] |
HumanEval/66 |
def digitSum(s):
"""Task
Write a function that takes a string as input and returns the sum of the upper characters only'
ASCII codes.
Examples:
digitSum("") => 0
digitSum("abAB") => 131
digitSum("abcCd") => 67
digitSum("helloE") => 69
digitSum("woArBld") => 131
digitSum("aAaaaXa") => 153
"""
| if s == "": return 0
return sum(ord(char) if char.isupper() else 0 for char in s)
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate("") == 0, "Error"
assert candidate("abAB") == 131, "Error"
assert candidate("abcCd") == 67, "Error"
assert candidate("helloE") == 69, "Error"
assert candidate("woArBld") == 131, "Error"
assert candidate("aAaaaXa") == 153, "Error"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate(" How are yOu?") == 151, "Error"
assert candidate("You arE Very Smart") == 327, "Error"
| digitSum | [
"Here is a Python solution for the problem:\n\n```python\ndef digitSum(s):\n return sum(ord(c) for c in s if c.isupper())\n```\n\nThis function works by iterating over each character in the input string. If the character is an uppercase letter (as determined by the `isupper()` method), it is converted to its ASC... | [
1
] |
HumanEval/67 |
def fruit_distribution(s,n):
"""
In this task, you will be given a string that represents a number of apples and oranges
that are distributed in a basket of fruit this basket contains
apples, oranges, and mango fruits. Given the string that represents the total number of
the oranges and apples and an integer that represent the total number of the fruits
in the basket return the number of the mango fruits in the basket.
for examble:
fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8
fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2
fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95
fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19
"""
| lis = list()
for i in s.split(' '):
if i.isdigit():
lis.append(int(i))
return n - sum(lis)
| def check(candidate):
# Check some simple cases
assert candidate("5 apples and 6 oranges",19) == 8
assert candidate("5 apples and 6 oranges",21) == 10
assert candidate("0 apples and 1 oranges",3) == 2
assert candidate("1 apples and 0 oranges",3) == 2
assert candidate("2 apples and 3 oranges",100) == 95
assert candidate("2 apples and 3 oranges",5) == 0
assert candidate("1 apples and 100 oranges",120) == 19
| fruit_distribution | [
"Here is a Python solution for the problem:\n\n```python\ndef fruit_distribution(s,n):\n # Split the string into a list of numbers\n numbers = list(map(int, s.split()))\n # The sum of the numbers in the list is the total number of apples and oranges\n total_apples_oranges = sum(numbers)\n # The numbe... | [
0
] |
HumanEval/68 |
def pluck(arr):
"""
"Given an array representing a branch of a tree that has non-negative integer nodes
your task is to pluck one of the nodes and return it.
The plucked node should be the node with the smallest even value.
If multiple nodes with the same smallest even value are found return the node that has smallest index.
The plucked node should be returned in a list, [ smalest_value, its index ],
If there are no even values or the given array is empty, return [].
Example 1:
Input: [4,2,3]
Output: [2, 1]
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 2:
Input: [1,2,3]
Output: [2, 1]
Explanation: 2 has the smallest even value, and 2 has the smallest index.
Example 3:
Input: []
Output: []
Example 4:
Input: [5, 0, 3, 0, 4, 2]
Output: [0, 1]
Explanation: 0 is the smallest value, but there are two zeros,
so we will choose the first zero, which has the smallest index.
Constraints:
* 1 <= nodes.length <= 10000
* 0 <= node.value
"""
| if(len(arr) == 0): return []
evens = list(filter(lambda x: x%2 == 0, arr))
if(evens == []): return []
return [min(evens), arr.index(min(evens))]
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([4,2,3]) == [2, 1], "Error"
assert candidate([1,2,3]) == [2, 1], "Error"
assert candidate([]) == [], "Error"
assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], "Error"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], "Error"
assert candidate([5, 4, 8, 4 ,8]) == [4, 1], "Error"
assert candidate([7, 6, 7, 1]) == [6, 1], "Error"
assert candidate([7, 9, 7, 1]) == [], "Error"
| pluck | [
"Here is a Python solution for the problem:\n\n```python\ndef pluck(arr):\n smallest_even = float('inf')\n smallest_index = -1\n\n for i, num in enumerate(arr):\n if num % 2 == 0 and num < smallest_even:\n smallest_even = num\n smallest_index = i\n\n if smallest_index == -1:... | [
1
] |
HumanEval/69 |
def search(lst):
'''
You are given a non-empty list of positive integers. Return the greatest integer that is greater than
zero, and has a frequency greater than or equal to the value of the integer itself.
The frequency of an integer is the number of times it appears in the list.
If no such a value exist, return -1.
Examples:
search([4, 1, 2, 2, 3, 1]) == 2
search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3
search([5, 5, 4, 4, 4]) == -1
'''
| frq = [0] * (max(lst) + 1)
for i in lst:
frq[i] += 1;
ans = -1
for i in range(1, len(frq)):
if frq[i] >= i:
ans = i
return ans
| def check(candidate):
# manually generated tests
assert candidate([5, 5, 5, 5, 1]) == 1
assert candidate([4, 1, 4, 1, 4, 4]) == 4
assert candidate([3, 3]) == -1
assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8
assert candidate([2, 3, 3, 2, 2]) == 2
# automatically generated tests
assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1
assert candidate([3, 2, 8, 2]) == 2
assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1
assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1
assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1
assert candidate([1, 9, 10, 1, 3]) == 1
assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5
assert candidate([1]) == 1
assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4
assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2
assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1
assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4
assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4
assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2
assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1
assert candidate([10]) == -1
assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2
assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1
assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1
assert candidate([3, 10, 10, 9, 2]) == -1
| search | [
"Here is a Python solution for the problem:\n\n```python\ndef search(lst):\n from collections import Counter\n count = Counter(lst)\n for i in range(len(lst), 0, -1):\n if count[i] >= i:\n return i\n return -1\n```\n\nThis function first counts the frequency of each number in the list ... | [
1
] |
HumanEval/70 |
def strange_sort_list(lst):
'''
Given list of integers, return list in strange order.
Strange sorting, is when you start with the minimum value,
then maximum of the remaining integers, then minimum and so on.
Examples:
strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3]
strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5]
strange_sort_list([]) == []
'''
| res, switch = [], True
while lst:
res.append(min(lst) if switch else max(lst))
lst.remove(res[-1])
switch = not switch
return res
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3]
assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7]
assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3]
assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7]
assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5]
assert candidate([]) == []
assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5]
assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2]
assert candidate([111111]) == [111111]
# Check some edge cases that are easy to work out by hand.
assert True
| strange_sort_list | [
"Here is a Python solution for the problem:\n\n```python\ndef strange_sort_list(lst):\n lst.sort()\n result = []\n while lst:\n result.append(lst.pop(0))\n if lst:\n result.append(lst.pop())\n return result\n```\n\nThis function first sorts the list in ascending order. Then it p... | [
1
] |
HumanEval/71 |
def triangle_area(a, b, c):
'''
Given the lengths of the three sides of a triangle. Return the area of
the triangle rounded to 2 decimal points if the three sides form a valid triangle.
Otherwise return -1
Three sides make a valid triangle when the sum of any two sides is greater
than the third side.
Example:
triangle_area(3, 4, 5) == 6.00
triangle_area(1, 2, 10) == -1
'''
| if a + b <= c or a + c <= b or b + c <= a:
return -1
s = (a + b + c)/2
area = (s * (s - a) * (s - b) * (s - c)) ** 0.5
area = round(area, 2)
return area
| def check(candidate):
# Check some simple cases
assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1, 2, 10) == -1
assert candidate(4, 8, 5) == 8.18
assert candidate(2, 2, 2) == 1.73
assert candidate(1, 2, 3) == -1
assert candidate(10, 5, 7) == 16.25
assert candidate(2, 6, 3) == -1
# Check some edge cases that are easy to work out by hand.
assert candidate(1, 1, 1) == 0.43, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate(2, 2, 10) == -1
| triangle_area | [
"Here is the Python code to solve the problem:\n\n```python\nimport math\n\ndef triangle_area(a, b, c):\n if a + b > c and a + c > b and b + c > a:\n s = (a + b + c) / 2\n area = math.sqrt(s * (s - a) * (s - b) * (s - c))\n return round(area, 2)\n else:\n return -1\n```\n\nThis fun... | [
1
] |
HumanEval/72 |
def will_it_fly(q,w):
'''
Write a function that returns True if the object q will fly, and False otherwise.
The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.
Example:
will_it_fly([1, 2], 5) ➞ False
# 1+2 is less than the maximum possible weight, but it's unbalanced.
will_it_fly([3, 2, 3], 1) ➞ False
# it's balanced, but 3+2+3 is more than the maximum possible weight.
will_it_fly([3, 2, 3], 9) ➞ True
# 3+2+3 is less than the maximum possible weight, and it's balanced.
will_it_fly([3], 5) ➞ True
# 3 is less than the maximum possible weight, and it's balanced.
'''
| if sum(q) > w:
return False
i, j = 0, len(q)-1
while i<j:
if q[i] != q[j]:
return False
i+=1
j-=1
return True
| def check(candidate):
# Check some simple cases
assert candidate([3, 2, 3], 9) is True
assert candidate([1, 2], 5) is False
assert candidate([3], 5) is True
assert candidate([3, 2, 3], 1) is False
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3], 6) is False
assert candidate([5], 5) is True
| will_it_fly | [
"Here is a Python solution for the problem:\n\n```python\ndef will_it_fly(q,w):\n # Check if the list is a palindrome\n if q != q[::-1]:\n return False\n # Check if the sum of the elements is less than or equal to the maximum possible weight\n if sum(q) > w:\n return False\n return True... | [
1
] |
HumanEval/73 |
def smallest_change(arr):
"""
Given an array arr of integers, find the minimum number of elements that
need to be changed to make the array palindromic. A palindromic array is an array that
is read the same backwards and forwards. In one change, you can change one element to any other element.
For example:
smallest_change([1,2,3,5,4,7,9,6]) == 4
smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1
smallest_change([1, 2, 3, 2, 1]) == 0
"""
| ans = 0
for i in range(len(arr) // 2):
if arr[i] != arr[len(arr) - i - 1]:
ans += 1
return ans
| def check(candidate):
# Check some simple cases
assert candidate([1,2,3,5,4,7,9,6]) == 4
assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1
assert candidate([1, 4, 2]) == 1
assert candidate([1, 4, 4, 2]) == 1
# Check some edge cases that are easy to work out by hand.
assert candidate([1, 2, 3, 2, 1]) == 0
assert candidate([3, 1, 1, 3]) == 0
assert candidate([1]) == 0
assert candidate([0, 1]) == 1
| smallest_change | [
"Here is a Python solution for the problem:\n\n```python\ndef smallest_change(arr):\n \"\"\"\n Given an array arr of integers, find the minimum number of elements that\n need to be changed to make the array palindromic. A palindromic array is an array that\n is read the same backwards and forwards. In o... | [
1
] |
HumanEval/74 |
def total_match(lst1, lst2):
'''
Write a function that accepts two lists of strings and returns the list that has
total number of chars in the all strings of the list less than the other list.
if the two lists have the same number of chars, return the first list.
Examples
total_match([], []) ➞ []
total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi']
total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin']
total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi']
total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4']
'''
| l1 = 0
for st in lst1:
l1 += len(st)
l2 = 0
for st in lst2:
l2 += len(st)
if l1 <= l2:
return lst1
else:
return lst2
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([], []) == []
assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi']
assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin']
assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4']
assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi']
assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi']
assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin']
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate([], ['this']) == []
assert candidate(['this'], []) == []
| total_match | [
"Here is the Python code to solve the problem:\n\n```python\ndef total_match(lst1, lst2):\n total_chars_lst1 = sum(len(s) for s in lst1)\n total_chars_lst2 = sum(len(s) for s in lst2)\n \n if total_chars_lst1 < total_chars_lst2:\n return lst1\n elif total_chars_lst1 > total_chars_lst2:\n ... | [
1
] |
HumanEval/75 |
def is_multiply_prime(a):
"""Write a function that returns true if the given number is the multiplication of 3 prime numbers
and false otherwise.
Knowing that (a) is less then 100.
Example:
is_multiply_prime(30) == True
30 = 2 * 3 * 5
"""
| def is_prime(n):
for j in range(2,n):
if n%j == 0:
return False
return True
for i in range(2,101):
if not is_prime(i): continue
for j in range(2,101):
if not is_prime(j): continue
for k in range(2,101):
if not is_prime(k): continue
if i*j*k == a: return True
return False
| def check(candidate):
assert candidate(5) == False
assert candidate(30) == True
assert candidate(8) == True
assert candidate(10) == False
assert candidate(125) == True
assert candidate(3 * 5 * 7) == True
assert candidate(3 * 6 * 7) == False
assert candidate(9 * 9 * 9) == False
assert candidate(11 * 9 * 9) == False
assert candidate(11 * 13 * 7) == True
| is_multiply_prime | [
"Here is a Python solution for the problem:\n\n```python\ndef is_multiply_prime(a):\n def is_prime(n):\n if n <= 1:\n return False\n elif n <= 3:\n return True\n elif n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n ... | [
1
] |
HumanEval/76 |
def is_simple_power(x, n):
"""Your task is to write a function that returns true if a number x is a simple
power of n and false in other cases.
x is a simple power of n if n**int=x
For example:
is_simple_power(1, 4) => true
is_simple_power(2, 2) => true
is_simple_power(8, 2) => true
is_simple_power(3, 2) => false
is_simple_power(3, 1) => false
is_simple_power(5, 3) => false
"""
| if (n == 1):
return (x == 1)
power = 1
while (power < x):
power = power * n
return (power == x)
| def check(candidate):
# Check some simple cases
assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"
| is_simple_power | [
"Here is a Python solution for the problem:\n\n```python\ndef is_simple_power(x, n):\n \"\"\"Your task is to write a function that returns true if a number x is a simple\n power of n and false in other cases.\n x is a simple power of n if n**int=x\n \"\"\"\n if n == 1:\n return x == 1\n pow... | [
1
] |
HumanEval/77 |
def iscube(a):
'''
Write a function that takes an integer a and returns True
if this ingeger is a cube of some integer number.
Note: you may assume the input is always valid.
Examples:
iscube(1) ==> True
iscube(2) ==> False
iscube(-1) ==> True
iscube(64) ==> True
iscube(0) ==> True
iscube(180) ==> False
'''
| a = abs(a)
return int(round(a ** (1. / 3))) ** 3 == a
| def check(candidate):
# Check some simple cases
assert candidate(1) == True, "First test error: " + str(candidate(1))
assert candidate(2) == False, "Second test error: " + str(candidate(2))
assert candidate(-1) == True, "Third test error: " + str(candidate(-1))
assert candidate(64) == True, "Fourth test error: " + str(candidate(64))
assert candidate(180) == False, "Fifth test error: " + str(candidate(180))
assert candidate(1000) == True, "Sixth test error: " + str(candidate(1000))
# Check some edge cases that are easy to work out by hand.
assert candidate(0) == True, "1st edge test error: " + str(candidate(0))
assert candidate(1729) == False, "2nd edge test error: " + str(candidate(1728))
| iscube | [
"Here is a Python function that solves the problem:\n\n```python\ndef iscube(a):\n '''\n Write a function that takes an integer a and returns True \n if this integer is a cube of some integer number.\n Note: you may assume the input is always valid.\n '''\n if a < 0:\n a = -a\n cube_root... | [
1
] |
HumanEval/78 |
def hex_key(num):
"""You have been tasked to write a function that receives
a hexadecimal number as a string and counts the number of hexadecimal
digits that are primes (prime number, or a prime, is a natural number
greater than 1 that is not a product of two smaller natural numbers).
Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.
Prime numbers are 2, 3, 5, 7, 11, 13, 17,...
So you have to determine a number of the following digits: 2, 3, 5, 7,
B (=decimal 11), D (=decimal 13).
Note: you may assume the input is always correct or empty string,
and symbols A,B,C,D,E,F are always uppercase.
Examples:
For num = "AB" the output should be 1.
For num = "1077E" the output should be 2.
For num = "ABED1A33" the output should be 4.
For num = "123456789ABCDEF0" the output should be 6.
For num = "2020" the output should be 2.
"""
| primes = ('2', '3', '5', '7', 'B', 'D')
total = 0
for i in range(0, len(num)):
if num[i] in primes:
total += 1
return total
| def check(candidate):
# Check some simple cases
assert candidate("AB") == 1, "First test error: " + str(candidate("AB"))
assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E"))
assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33"))
assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020"))
assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0"))
assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00"))
# Check some edge cases that are easy to work out by hand.
assert candidate([]) == 0
| hex_key | [
"Here is the Python code to solve the problem:\n\n```python\ndef hex_key(num):\n # Define the prime hexadecimal digits\n prime_hex_digits = {'2', '3', '5', '7', 'B', 'D'}\n \n # Count the number of prime hexadecimal digits in the input string\n count = sum(1 for digit in num if digit in prime_hex_dig... | [
1
] |
HumanEval/79 |
def decimal_to_binary(decimal):
"""You will be given a number in decimal form and your task is to convert it to
binary format. The function should return a string, with each character representing a binary
number. Each character in the string will be '0' or '1'.
There will be an extra couple of characters 'db' at the beginning and at the end of the string.
The extra characters are there to help with the format.
Examples:
decimal_to_binary(15) # returns "db1111db"
decimal_to_binary(32) # returns "db100000db"
"""
| return "db" + bin(decimal)[2:] + "db"
| def check(candidate):
# Check some simple cases
assert candidate(0) == "db0db"
assert candidate(32) == "db100000db"
assert candidate(103) == "db1100111db"
assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
| decimal_to_binary | [
"Here is the Python code to solve the problem:\n\n```python\ndef decimal_to_binary(decimal):\n binary = bin(decimal).replace(\"0b\", \"\")\n return \"db\" + binary + \"db\"\n```\n\nThis function uses Python's built-in `bin()` function to convert the decimal number to binary. The `bin()` function returns a str... | [
1
] |
HumanEval/80 |
def is_happy(s):
"""You are given a string s.
Your task is to check if the string is happy or not.
A string is happy if its length is at least 3 and every 3 consecutive letters are distinct
For example:
is_happy(a) => False
is_happy(aa) => False
is_happy(abcd) => True
is_happy(aabb) => False
is_happy(adb) => True
is_happy(xyy) => False
"""
| if len(s) < 3:
return False
for i in range(len(s) - 2):
if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]:
return False
return True
| def check(candidate):
# Check some simple cases
assert candidate("a") == False , "a"
assert candidate("aa") == False , "aa"
assert candidate("abcd") == True , "abcd"
assert candidate("aabb") == False , "aabb"
assert candidate("adb") == True , "adb"
assert candidate("xyy") == False , "xyy"
assert candidate("iopaxpoi") == True , "iopaxpoi"
assert candidate("iopaxioi") == False , "iopaxioi"
| is_happy | [
"Here is a Python solution for the problem:\n\n```python\ndef is_happy(s):\n if len(s) < 3:\n return False\n for i in range(len(s) - 2):\n if s[i] == s[i+1] or s[i] == s[i+2] or s[i+1] == s[i+2]:\n return False\n return True\n```\n\nThis function first checks if the length of the s... | [
1
] |
HumanEval/81 |
def numerical_letter_grade(grades):
"""It is the last week of the semester and the teacher has to give the grades
to students. The teacher has been making her own algorithm for grading.
The only problem is, she has lost the code she used for grading.
She has given you a list of GPAs for some students and you have to write
a function that can output a list of letter grades using the following table:
GPA | Letter grade
4.0 A+
> 3.7 A
> 3.3 A-
> 3.0 B+
> 2.7 B
> 2.3 B-
> 2.0 C+
> 1.7 C
> 1.3 C-
> 1.0 D+
> 0.7 D
> 0.0 D-
0.0 E
Example:
grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-']
"""
|
letter_grade = []
for gpa in grades:
if gpa == 4.0:
letter_grade.append("A+")
elif gpa > 3.7:
letter_grade.append("A")
elif gpa > 3.3:
letter_grade.append("A-")
elif gpa > 3.0:
letter_grade.append("B+")
elif gpa > 2.7:
letter_grade.append("B")
elif gpa > 2.3:
letter_grade.append("B-")
elif gpa > 2.0:
letter_grade.append("C+")
elif gpa > 1.7:
letter_grade.append("C")
elif gpa > 1.3:
letter_grade.append("C-")
elif gpa > 1.0:
letter_grade.append("D+")
elif gpa > 0.7:
letter_grade.append("D")
elif gpa > 0.0:
letter_grade.append("D-")
else:
letter_grade.append("E")
return letter_grade
| def check(candidate):
# Check some simple cases
assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-']
assert candidate([1.2]) == ['D+']
assert candidate([0.5]) == ['D-']
assert candidate([0.0]) == ['E']
assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+']
assert candidate([0, 0.7]) == ['E', 'D-']
# Check some edge cases that are easy to work out by hand.
assert True
| numerical_letter_grade | [
"Here is the Python code to solve the problem:\n\n```python\ndef numerical_letter_grade(grades):\n letter_grades = []\n for gpa in grades:\n if gpa == 4.0:\n letter_grades.append('A+')\n elif gpa > 3.7:\n letter_grades.append('A')\n elif gpa > 3.3:\n lette... | [
0
] |
HumanEval/82 |
def prime_length(string):
"""Write a function that takes a string and returns True if the string
length is a prime number or False otherwise
Examples
prime_length('Hello') == True
prime_length('abcdcba') == True
prime_length('kittens') == True
prime_length('orange') == False
"""
| l = len(string)
if l == 0 or l == 1:
return False
for i in range(2, l):
if l % i == 0:
return False
return True
| def check(candidate):
# Check some simple cases
assert candidate('Hello') == True
assert candidate('abcdcba') == True
assert candidate('kittens') == True
assert candidate('orange') == False
assert candidate('wow') == True
assert candidate('world') == True
assert candidate('MadaM') == True
assert candidate('Wow') == True
assert candidate('') == False
assert candidate('HI') == True
assert candidate('go') == True
assert candidate('gogo') == False
assert candidate('aaaaaaaaaaaaaaa') == False
# Check some edge cases that are easy to work out by hand.
assert candidate('Madam') == True
assert candidate('M') == False
assert candidate('0') == False
| prime_length | [
"Here is a Python solution for the problem:\n\n```python\ndef prime_length(string):\n \"\"\"Write a function that takes a string and returns True if the string\n length is a prime number or False otherwise\n \"\"\"\n length = len(string)\n if length < 2:\n return False\n for i in range(2, i... | [
1
] |
HumanEval/83 |
def starts_one_ends(n):
"""
Given a positive integer n, return the count of the numbers of n-digit
positive integers that start or end with 1.
"""
| if n == 1: return 1
return 18 * (10 ** (n - 2))
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1) == 1
assert candidate(2) == 18
assert candidate(3) == 180
assert candidate(4) == 1800
assert candidate(5) == 18000
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
| starts_one_ends | [
"Here is a Python solution for the problem:\n\n```python\ndef starts_one_ends(n):\n if n == 1:\n return 1\n else:\n return 18 * (10 ** (n - 2))\n```\n\nThis function works by considering the number of n-digit numbers that start or end with 1. If n is 1, there is only one such number, which is 1 ... | [
1
] |
HumanEval/84 |
def solve(N):
"""Given a positive integer N, return the total sum of its digits in binary.
Example
For N = 1000, the sum of digits will be 1 the output should be "1".
For N = 150, the sum of digits will be 6 the output should be "110".
For N = 147, the sum of digits will be 12 the output should be "1100".
Variables:
@N integer
Constraints: 0 ≤ N ≤ 10000.
Output:
a string of binary number
"""
| return bin(sum(int(i) for i in str(N)))[2:]
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(1000) == "1", "Error"
assert candidate(150) == "110", "Error"
assert candidate(147) == "1100", "Error"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate(333) == "1001", "Error"
assert candidate(963) == "10010", "Error"
| solve | [
"Here is the Python code to solve the problem:\n\n```python\ndef solve(N):\n \"\"\"Given a positive integer N, return the total sum of its digits in binary.\n \n Example\n For N = 1000, the sum of digits will be 1 the output should be \"1\".\n For N = 150, the sum of digits will be 6 the outp... | [
1
] |
HumanEval/85 |
def add(lst):
"""Given a non-empty list of integers lst. add the even elements that are at odd indices..
Examples:
add([4, 2, 6, 7]) ==> 2
"""
| return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
| def check(candidate):
# Check some simple cases
assert candidate([4, 88]) == 88
assert candidate([4, 5, 6, 7, 2, 122]) == 122
assert candidate([4, 0, 6, 7]) == 0
assert candidate([4, 4, 6, 8]) == 12
# Check some edge cases that are easy to work out by hand.
| add | [
"Here is a Python solution for the problem:\n\n```python\ndef add(lst):\n \"\"\"Given a non-empty list of integers lst. add the even elements that are at odd indices..\n \"\"\"\n return sum(x for i, x in enumerate(lst) if i % 2 != 0 and x % 2 == 0)\n```\n\nThis function uses a generator expression to itera... | [
1
] |
HumanEval/86 |
def anti_shuffle(s):
"""
Write a function that takes a string and returns an ordered version of it.
Ordered version of string, is a string where all words (separated by space)
are replaced by a new word where all the characters arranged in
ascending order based on ascii value.
Note: You should keep the order of words and blank spaces in the sentence.
For example:
anti_shuffle('Hi') returns 'Hi'
anti_shuffle('hello') returns 'ehllo'
anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor'
"""
| return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
| def check(candidate):
# Check some simple cases
assert candidate('Hi') == 'Hi'
assert candidate('hello') == 'ehllo'
assert candidate('number') == 'bemnru'
assert candidate('abcd') == 'abcd'
assert candidate('Hello World!!!') == 'Hello !!!Wdlor'
assert candidate('') == ''
assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy'
# Check some edge cases that are easy to work out by hand.
assert True
| anti_shuffle | [
"Here is a Python solution for the problem:\n\n```python\ndef anti_shuffle(s):\n words = s.split(' ')\n ordered_words = [''.join(sorted(word)) for word in words]\n return ' '.join(ordered_words)\n```\n\nThis function works by splitting the input string into a list of words, sorting the characters in each w... | [
1
] |
HumanEval/87 |
def get_row(lst, x):
"""
You are given a 2 dimensional data, as a nested lists,
which is similar to matrix, however, unlike matrices,
each row may contain a different number of columns.
Given lst, and integer x, find integers x in the list,
and return list of tuples, [(x1, y1), (x2, y2) ...] such that
each tuple is a coordinate - (row, columns), starting with 0.
Sort coordinates initially by rows in ascending order.
Also, sort coordinates of the row by columns in descending order.
Examples:
get_row([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
get_row([], 1) == []
get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)]
"""
| coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x]
return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
| def check(candidate):
# Check some simple cases
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)]
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,2,3,4,5,6]
], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)]
assert candidate([
[1,2,3,4,5,6],
[1,2,3,4,5,6],
[1,1,3,4,5,6],
[1,2,1,4,5,6],
[1,2,3,1,5,6],
[1,2,3,4,1,6],
[1,2,3,4,5,1]
], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)]
assert candidate([], 1) == []
assert candidate([[1]], 2) == []
assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)]
# Check some edge cases that are easy to work out by hand.
assert True
| get_row | [
"Here is a Python solution for the problem:\n\n```python\ndef get_row(lst, x):\n result = []\n for i, row in enumerate(lst):\n for j, val in enumerate(row):\n if val == x:\n result.append((i, j))\n result.sort(key=lambda x: (x[0], -x[1]))\n return result\n```\n\nThis fun... | [
0
] |
HumanEval/88 |
def sort_array(array):
"""
Given an array of non-negative integers, return a copy of the given array after sorting,
you will sort the given array in ascending order if the sum( first index value, last index value) is odd,
or sort it in descending order if the sum( first index value, last index value) is even.
Note:
* don't change the given array.
Examples:
* sort_array([]) => []
* sort_array([5]) => [5]
* sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5]
* sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0]
"""
| return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
| def check(candidate):
# Check some simple cases
assert True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate([]) == [], "Error"
assert candidate([5]) == [5], "Error"
assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], "Error"
assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], "Error"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
assert candidate([2, 1]) == [1, 2], "Error"
assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], "Error"
assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], "Error"
| sort_array | [
"Here is a Python solution for the problem:\n\n```python\ndef sort_array(array):\n \"\"\"\n Given an array of non-negative integers, return a copy of the given array after sorting,\n you will sort the given array in ascending order if the sum( first index value, last index value) is odd,\n or sort it in... | [
0
] |
HumanEval/89 |
def encrypt(s):
"""Create a function encrypt that takes a string as an argument and
returns a string encrypted with the alphabet being rotated.
The alphabet should be rotated in a manner such that the letters
shift down by two multiplied to two places.
For example:
encrypt('hi') returns 'lm'
encrypt('asdfghjkl') returns 'ewhjklnop'
encrypt('gf') returns 'kj'
encrypt('et') returns 'ix'
"""
| d = 'abcdefghijklmnopqrstuvwxyz'
out = ''
for c in s:
if c in d:
out += d[(d.index(c)+2*2) % 26]
else:
out += c
return out
| def check(candidate):
# Check some simple cases
assert candidate('hi') == 'lm', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('asdfghjkl') == 'ewhjklnop', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('gf') == 'kj', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('et') == 'ix', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('faewfawefaewg')=='jeiajeaijeiak', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('hellomyfriend')=='lippsqcjvmirh', "This prints if this assert fails 2 (good for debugging!)"
assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', "This prints if this assert fails 3 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate('a')=='e', "This prints if this assert fails 2 (also good for debugging!)"
| encrypt | [
"Here is a Python solution for the problem:\n\n```python\ndef encrypt(s):\n result = \"\"\n for char in s:\n if char.isalpha():\n ascii_offset = 65 if char.isupper() else 97\n result += chr((ord(char) - ascii_offset + 2*2) % 26 + ascii_offset)\n else:\n result +=... | [
1
] |
HumanEval/90 |
def next_smallest(lst):
"""
You are given a list of integers.
Write a function next_smallest() that returns the 2nd smallest element of the list.
Return None if there is no such element.
next_smallest([1, 2, 3, 4, 5]) == 2
next_smallest([5, 1, 4, 3, 2]) == 2
next_smallest([]) == None
next_smallest([1, 1]) == None
"""
| lst = sorted(set(lst))
return None if len(lst) < 2 else lst[1]
| def check(candidate):
# Check some simple cases
assert candidate([1, 2, 3, 4, 5]) == 2
assert candidate([5, 1, 4, 3, 2]) == 2
assert candidate([]) == None
assert candidate([1, 1]) == None
assert candidate([1,1,1,1,0]) == 1
assert candidate([1, 0**0]) == None
assert candidate([-35, 34, 12, -45]) == -35
# Check some edge cases that are easy to work out by hand.
assert True
| next_smallest | [
"Here is a Python function that solves the problem:\n\n```python\ndef next_smallest(lst):\n \"\"\"\n You are given a list of integers.\n \"\"\"\n if len(lst) < 2:\n return None\n else:\n lst.sort()\n return lst[1]\n```\n\nThis function first checks if the list has less than 2 ele... | [
0
] |
HumanEval/91 |
def is_bored(S):
"""
You'll be given a string of words, and your task is to count the number
of boredoms. A boredom is a sentence that starts with the word "I".
Sentences are delimited by '.', '?' or '!'.
For example:
>>> is_bored("Hello world")
0
>>> is_bored("The sky is blue. The sun is shining. I love this weather")
1
"""
| import re
sentences = re.split(r'[.?!]\s*', S)
return sum(sentence[0:2] == 'I ' for sentence in sentences)
| def check(candidate):
# Check some simple cases
assert candidate("Hello world") == 0, "Test 1"
assert candidate("Is the sky blue?") == 0, "Test 2"
assert candidate("I love It !") == 1, "Test 3"
assert candidate("bIt") == 0, "Test 4"
assert candidate("I feel good today. I will be productive. will kill It") == 2, "Test 5"
assert candidate("You and I are going for a walk") == 0, "Test 6"
# Check some edge cases that are easy to work out by hand.
assert True, "This prints if this assert fails 2 (also good for debugging!)"
| is_bored | [
"Here is a Python solution for the problem:\n\n```python\ndef is_bored(S):\n sentences = S.split('.')\n sentences = [sentence.strip() for sentence in sentences if sentence.strip()]\n count = 0\n for sentence in sentences:\n if sentence.startswith('I '):\n count += 1\n return count\n... | [
1
] |
HumanEval/92 |
def any_int(x, y, z):
'''
Create a function that takes 3 numbers.
Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.
Returns false in any other cases.
Examples
any_int(5, 2, 7) ➞ True
any_int(3, 2, 2) ➞ False
any_int(3, -2, 1) ➞ True
any_int(3.6, -2.2, 2) ➞ False
'''
|
if isinstance(x,int) and isinstance(y,int) and isinstance(z,int):
if (x+y==z) or (x+z==y) or (y+z==x):
return True
return False
return False
| def check(candidate):
# Check some simple cases
assert candidate(2, 3, 1)==True, "This prints if this assert fails 1 (good for debugging!)"
assert candidate(2.5, 2, 3)==False, "This prints if this assert fails 2 (good for debugging!)"
assert candidate(1.5, 5, 3.5)==False, "This prints if this assert fails 3 (good for debugging!)"
assert candidate(2, 6, 2)==False, "This prints if this assert fails 4 (good for debugging!)"
assert candidate(4, 2, 2)==True, "This prints if this assert fails 5 (good for debugging!)"
assert candidate(2.2, 2.2, 2.2)==False, "This prints if this assert fails 6 (good for debugging!)"
assert candidate(-4, 6, 2)==True, "This prints if this assert fails 7 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate(2,1,1)==True, "This prints if this assert fails 8 (also good for debugging!)"
assert candidate(3,4,7)==True, "This prints if this assert fails 9 (also good for debugging!)"
assert candidate(3.0,4,7)==False, "This prints if this assert fails 10 (also good for debugging!)"
| any_int | [
"Here is the Python code to solve the problem:\n\n```python\ndef any_int(x, y, z):\n if all(isinstance(i, int) for i in [x, y, z]):\n return x + y == z or x + z == y or y + z == x\n else:\n return False\n```\n\nThis function first checks if all the inputs are integers using the `all()` function ... | [
1
] |
HumanEval/93 |
def encode(message):
"""
Write a function that takes a message, and encodes in such a
way that it swaps case of all letters, replaces all vowels in
the message with the letter that appears 2 places ahead of that
vowel in the english alphabet.
Assume only letters.
Examples:
>>> encode('test')
'TGST'
>>> encode('This is a message')
'tHKS KS C MGSSCGG'
"""
| vowels = "aeiouAEIOU"
vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels])
message = message.swapcase()
return ''.join([vowels_replace[i] if i in vowels else i for i in message])
| def check(candidate):
# Check some simple cases
assert candidate('TEST') == 'tgst', "This prints if this assert fails 1 (good for debugging!)"
assert candidate('Mudasir') == 'mWDCSKR', "This prints if this assert fails 2 (good for debugging!)"
assert candidate('YES') == 'ygs', "This prints if this assert fails 3 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate('This is a message') == 'tHKS KS C MGSSCGG', "This prints if this assert fails 2 (also good for debugging!)"
assert candidate("I DoNt KnOw WhAt tO WrItE") == 'k dQnT kNqW wHcT Tq wRkTg', "This prints if this assert fails 2 (also good for debugging!)"
| encode | [
"Here is a Python solution for the problem:\n\n```python\ndef encode(message):\n vowels = 'aeiou'\n encoded_message = ''\n for char in message:\n if char.isalpha():\n if char.islower():\n char = char.upper()\n else:\n char = char.lower()\n ... | [
0
] |
HumanEval/94 |
def skjkasdkd(lst):
"""You are given a list of integers.
You need to find the largest prime value and return the sum of its digits.
Examples:
For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10
For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25
For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13
For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11
For lst = [0,81,12,3,1,21] the output should be 3
For lst = [0,8,1,2,1,7] the output should be 7
"""
| def isPrime(n):
for i in range(2,int(n**0.5)+1):
if n%i==0:
return False
return True
maxx = 0
i = 0
while i < len(lst):
if(lst[i] > maxx and isPrime(lst[i])):
maxx = lst[i]
i+=1
result = sum(int(digit) for digit in str(maxx))
return result
| def check(candidate):
# Check some simple cases
assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, "This prints if this assert fails 1 (good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, "This prints if this assert fails 2 (also good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, "This prints if this assert fails 3 (also good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, "This prints if this assert fails 4 (also good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([0,81,12,3,1,21]) == 3, "This prints if this assert fails 5 (also good for debugging!)"
# Check some edge cases that are easy to work out by hand.
assert candidate([0,8,1,2,1,7]) == 7, "This prints if this assert fails 6 (also good for debugging!)"
assert candidate([8191]) == 19, "This prints if this assert fails 7 (also good for debugging!)"
assert candidate([8191, 123456, 127, 7]) == 19, "This prints if this assert fails 8 (also good for debugging!)"
assert candidate([127, 97, 8192]) == 10, "This prints if this assert fails 9 (also good for debugging!)"
| skjkasdkd | [
"Here is a Python solution for the problem:\n\n```python\ndef skjkasdkd(lst):\n def is_prime(n):\n if n <= 1:\n return False\n if n <= 3:\n return True\n if n % 2 == 0 or n % 3 == 0:\n return False\n i = 5\n while i * i <= n:\n if n %... | [
1
] |
HumanEval/95 |
def check_dict_case(dict):
"""
Given a dictionary, return True if all keys are strings in lower
case or all keys are strings in upper case, else return False.
The function should return False is the given dictionary is empty.
Examples:
check_dict_case({"a":"apple", "b":"banana"}) should return True.
check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False.
check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False.
check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False.
check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True.
"""
| if len(dict.keys()) == 0:
return False
else:
state = "start"
for key in dict.keys():
if isinstance(key, str) == False:
state = "mixed"
break
if state == "start":
if key.isupper():
state = "upper"
elif key.islower():
state = "lower"
else:
break
elif (state == "upper" and not key.isupper()) or (state == "lower" and not key.islower()):
state = "mixed"
break
else:
break
return state == "upper" or state == "lower"
| def check(candidate):
# Check some simple cases
assert candidate({"p":"pineapple", "b":"banana"}) == True, "First test error: " + str(candidate({"p":"pineapple", "b":"banana"}))
assert candidate({"p":"pineapple", "A":"banana", "B":"banana"}) == False, "Second test error: " + str(candidate({"p":"pineapple", "A":"banana", "B":"banana"}))
assert candidate({"p":"pineapple", 5:"banana", "a":"apple"}) == False, "Third test error: " + str(candidate({"p":"pineapple", 5:"banana", "a":"apple"}))
assert candidate({"Name":"John", "Age":"36", "City":"Houston"}) == False, "Fourth test error: " + str(candidate({"Name":"John", "Age":"36", "City":"Houston"}))
assert candidate({"STATE":"NC", "ZIP":"12345" }) == True, "Fifth test error: " + str(candidate({"STATE":"NC", "ZIP":"12345" }))
assert candidate({"fruit":"Orange", "taste":"Sweet" }) == True, "Fourth test error: " + str(candidate({"fruit":"Orange", "taste":"Sweet" }))
# Check some edge cases that are easy to work out by hand.
assert candidate({}) == False, "1st edge test error: " + str(candidate({}))
| check_dict_case | [
"Here is a Python solution for the problem:\n\n```python\ndef check_dict_case(dict):\n if not dict:\n return False\n\n all_lower = all(key.islower() for key in dict if isinstance(key, str))\n all_upper = all(key.isupper() for key in dict if isinstance(key, str))\n\n return all_lower or all_upper\... | [
0
] |
HumanEval/96 |
def count_up_to(n):
"""Implement a function that takes an non-negative integer and returns an array of the first n
integers that are prime numbers and less than n.
for example:
count_up_to(5) => [2,3]
count_up_to(11) => [2,3,5,7]
count_up_to(0) => []
count_up_to(20) => [2,3,5,7,11,13,17,19]
count_up_to(1) => []
count_up_to(18) => [2,3,5,7,11,13,17]
"""
| primes = []
for i in range(2, n):
is_prime = True
for j in range(2, i):
if i % j == 0:
is_prime = False
break
if is_prime:
primes.append(i)
return primes
| def check(candidate):
assert candidate(5) == [2,3]
assert candidate(6) == [2,3,5]
assert candidate(7) == [2,3,5]
assert candidate(10) == [2,3,5,7]
assert candidate(0) == []
assert candidate(22) == [2,3,5,7,11,13,17,19]
assert candidate(1) == []
assert candidate(18) == [2,3,5,7,11,13,17]
assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43]
assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
| count_up_to | [
"Here is a Python solution for the problem:\n\n```python\ndef count_up_to(n):\n def is_prime(num):\n if num <= 1:\n return False\n elif num <= 3:\n return True\n elif num % 2 == 0 or num % 3 == 0:\n return False\n i = 5\n while i * i <= num:\n ... | [
1
] |
HumanEval/97 |
def multiply(a, b):
"""Complete the function that takes two integers and returns
the product of their unit digits.
Assume the input is always valid.
Examples:
multiply(148, 412) should return 16.
multiply(19, 28) should return 72.
multiply(2020, 1851) should return 0.
multiply(14,-15) should return 20.
"""
| return abs(a % 10) * abs(b % 10)
| def check(candidate):
# Check some simple cases
assert candidate(148, 412) == 16, "First test error: " + str(candidate(148, 412))
assert candidate(19, 28) == 72, "Second test error: " + str(candidate(19, 28))
assert candidate(2020, 1851) == 0, "Third test error: " + str(candidate(2020, 1851))
assert candidate(14,-15) == 20, "Fourth test error: " + str(candidate(14,-15))
assert candidate(76, 67) == 42, "Fifth test error: " + str(candidate(76, 67))
assert candidate(17, 27) == 49, "Sixth test error: " + str(candidate(17, 27))
# Check some edge cases that are easy to work out by hand.
assert candidate(0, 1) == 0, "1st edge test error: " + str(candidate(0, 1))
assert candidate(0, 0) == 0, "2nd edge test error: " + str(candidate(0, 0))
| multiply | [
"Here is the Python code to solve the problem:\n\n```python\ndef multiply(a, b):\n \"\"\"Complete the function that takes two integers and returns \n the product of their unit digits.\n Assume the input is always valid.\n \"\"\"\n return (a % 10) * (b % 10)\n```\n\nThis function works by using the mo... | [
1
] |
HumanEval/98 |
def count_upper(s):
"""
Given a string s, count the number of uppercase vowels in even indices.
For example:
count_upper('aBCdEf') returns 1
count_upper('abcdefg') returns 0
count_upper('dBBE') returns 0
"""
| count = 0
for i in range(0,len(s),2):
if s[i] in "AEIOU":
count += 1
return count
| def check(candidate):
# Check some simple cases
assert candidate('aBCdEf') == 1
assert candidate('abcdefg') == 0
assert candidate('dBBE') == 0
assert candidate('B') == 0
assert candidate('U') == 1
assert candidate('') == 0
assert candidate('EEEE') == 2
# Check some edge cases that are easy to work out by hand.
assert True
| count_upper | [
"Here is a Python solution for the problem:\n\n```python\ndef count_upper(s):\n \"\"\"\n Given a string s, count the number of uppercase vowels in even indices.\n \"\"\"\n count = 0\n vowels = 'AEIOU'\n for i in range(0, len(s), 2):\n if s[i] in vowels:\n count += 1\n return c... | [
1
] |
HumanEval/99 |
def closest_integer(value):
'''
Create a function that takes a value (string) representing a number
and returns the closest integer to it. If the number is equidistant
from two integers, round it away from zero.
Examples
>>> closest_integer("10")
10
>>> closest_integer("15.3")
15
Note:
Rounding away from zero means that if the given number is equidistant
from two integers, the one you should return is the one that is the
farthest from zero. For example closest_integer("14.5") should
return 15 and closest_integer("-14.5") should return -15.
'''
| from math import floor, ceil
if value.count('.') == 1:
# remove trailing zeros
while (value[-1] == '0'):
value = value[:-1]
num = float(value)
if value[-2:] == '.5':
if num > 0:
res = ceil(num)
else:
res = floor(num)
elif len(value) > 0:
res = int(round(num))
else:
res = 0
return res
| def check(candidate):
# Check some simple cases
assert candidate("10") == 10, "Test 1"
assert candidate("14.5") == 15, "Test 2"
assert candidate("-15.5") == -16, "Test 3"
assert candidate("15.3") == 15, "Test 3"
# Check some edge cases that are easy to work out by hand.
assert candidate("0") == 0, "Test 0"
| closest_integer | [
"Here is a Python solution for the problem:\n\n```python\ndef closest_integer(value):\n '''\n Create a function that takes a value (string) representing a number\n and returns the closest integer to it. If the number is equidistant\n from two integers, round it away from zero.\n '''\n num = float(... | [
1
] |
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