Search is not available for this dataset
name stringlengths 2 112 | description stringlengths 29 13k | source int64 1 7 | difficulty int64 0 25 | solution stringlengths 7 983k | language stringclasses 4
values |
|---|---|---|---|---|---|
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
bool debug = 0;
int n, m, k;
int dx[4] = {0, 1, 0, -1}, dy[4] = {1, 0, -1, 0};
string direc = "RDLU";
long long ln, lk, lm;
void etp(bool f = 0) {
puts(f ? "YES" : "NO");
exit(0);
}
void addmod(int &x, int y, int mod = 1000000007) {
assert(y >= 0);
x += y;
if (x >... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 100005;
template <typename T>
inline void read(T &AKNOI) {
T x = 0, flag = 1;
char ch = getchar();
while (!isdigit(ch)) {
if (ch == '-') flag = -1;
ch = getchar();
}
while (isdigit(ch)) {
x = x * 10 + ch - '0';
ch = getchar();
}
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
map<long long, long long> mp;
long long a[55], b[55], m[55];
bool prime[40005];
long long gcd(long long a, long long b) {
if (b == 0) return a;
return gcd(b, a % b);
}
long long extgcd(long long a, long long b, long long &x, long long &y) {
if (b == 0) {
x = 1, y ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
char getc() {
char c = getchar();
while ((c < 'A' || c > 'Z') && (c < 'a' || c > 'z') && (c < '0' || c > '9'))
c = getchar();
return c;
}
long long gcd(long long n, long long m) { return m == 0 ? n : gcd(m, n % m); }
long long read() {
long long x = 0, f = 1;
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 100;
vector<int> v;
vector<int> vp;
int a[N][20], f[N], invf[N];
int n, p, l, r;
bool vis[N];
int qpow(int x, int b) {
long long sum = 1;
long long now = x;
while (b) {
if (b & 1) sum = sum * now % p;
now = now * now % p;
b >>= 1;
}
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <typename T>
inline void cmax(T &x, T y) {
y > x ? x = y : 0;
}
template <typename T>
inline void cmin(T &x, T y) {
y < x ? x = y : 0;
}
int mod, ss;
inline int add(long long a, long long b) {
a += b;
return a >= mod ? a - mod : a;
}
inline int pop(long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
const int N = 100050;
using namespace std;
inline int gi() {
char ch = getchar();
int x = 0, q = 0;
while (ch < '0' || ch > '9') ch == '-' ? q = 1 : 0, ch = getchar();
while (ch >= '0' && ch <= '9') x = x * 10 + ch - '0', ch = getchar();
return q ? (-x) : x;
}
int fap(int a, int b, in... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <typename T, typename U>
inline void smin(T &a, U b) {
if (a > b) a = b;
}
template <typename T, typename U>
inline void smax(T &a, U b) {
if (a < b) a = b;
}
template <class T>
inline void gn(T &first) {
char c, sg = 0;
while (c = getchar(), (c > '9' || c ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long double pi = acosl(-1);
const int maxn = 100010;
const long long mod = 1e9 + 7;
const int inf = 1e9;
const long double eps = 1e-10;
int n, l, r;
long long p, fac[maxn], inv[maxn];
vector<pair<int, int> > vec;
long long phi;
long long pwr(long long x, long long P) ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma comment(linker, "/STACK:512000000")
using namespace std;
void solve(bool);
void precalc();
clock_t start;
int main() {
start = clock();
int t = 1;
cout.sync_with_stdio(0);
cin.tie(0);
precalc();
cout.precision(10);
cout << fixed;
int testNum = 1;
while (t--) {
solv... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int P = 10, N = 1e5 + 10;
int inverse(int a, int m) {
if (a <= 1) return a;
int ans = (1 - (long long int)inverse(m % a, a) * m) / a;
if (ans < 0) ans += m;
return ans;
}
int fact[N], ifact[N], pot[N][P];
vector<int> primes(int n) {
vector<int> ans;
for (i... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | import java.io.OutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.HashMap;
import java.util.Random;
import java.util.Map;
import java.io.OutputStreamWriter;
import java.io.OutputStream;
import java.util.Iterator;
import java.util.Set;
import java.io.IOException;
import java.io.Unchec... | JAVA |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100007], fac[100007], p[100007], t[100007][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
inline long long read() {
long long x = 0, f = 1;
char ch = getchar();
while (ch > '9' || ch < '0') {
if (ch == '-') f = -1;
ch = getchar();
}
while (ch >= '0' && ch <= '9') {
x = x * 10 + ch - '0';
ch = getchar();
}
return x * f;
}
const long ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
int n;
long long P;
int l, r;
long long fpow(long long a, long long b) {
long long ans = 1, t = a;
while (b) {
if (b & 1) ans = ans * t % P;
t = t * t % P;
b >>= 1;
}
return ans;
}
void exgcd(long long a, long long b, long long& x, long long& y) {
if (... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100003;
int n, L, R, phi;
long long mod;
long long fac[N], inv[N];
int d[N][33];
int tot, p[N];
long long fpow(long long x, int y) {
long long res = 1;
while (y) {
if (y & 1) res = res * x % mod;
x = x * x % mod;
y >>= 1;
}
return res;
}
vo... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100000 + 10;
int n, p, l, r;
long long fc[N], ifc[N];
void exgcd(long long a, long long b, long long &d, long long &x, long long &y) {
if (!b) return x = 1, y = 0, d = a, void();
exgcd(b, a % b, d, y, x);
y -= a / b * x;
}
long long inv(long long a, long... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100005;
long long p, n, l, r;
long long pr[N], inv[N], f[N], c[N][40], phi;
int cnt = 0;
long long powe(long long a, long long b) {
long long base = 1;
while (b) {
if (b & 1) base = (base * a) % p;
a = (a * a) % p;
b >>= 1;
}
return base;
}... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
inline void read(long long &x) {
static char c;
for (c = getchar(); !('0' <= c && c <= '9'); c = getchar())
;
for (x = 0; ('0' <= c && c <= '9'); c = getchar()) x = x * 10 + c - 48;
}
using namespace std;
void write(long long x) {
if (x < 10) {
putchar('0' + x);
return;
}
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long shin[25];
long long seto(void);
void ayano(long long x, char spliter = '\n');
int p, phip, phipm;
int prims[10], primdeg[10], primcnt = 0;
int kasumi(int a, int b);
int comb(int a, int b);
struct Num {
int x, xinv, degs[10];
Num(void) : x(1), xinv(1) {
for... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MM = 1e9 + 7;
const double eps = 1e-8;
const int MAXN = 1e5 + 10;
int n, m;
void prework() {}
void read() {}
long long A[MAXN][11], B[MAXN][11], C[MAXN][11];
long long P;
vector<pair<int, int> > pm;
long long pw(long long p, long long q, long long MM) {
long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | import java.io.*;
import java.util.*;
public class D896 {
long mod;
long[][] factorial(int n, Long[] prime) {
int k = prime.length;
long[][] f = new long[n+1][k+1];
f[0][0] = 1L;
for(int i = 1; i <= n; i++) {
long cur = i;
for(int j = 0; j <= k; j++) f[i][j] = f[i-1][j];
for(int j = 0; j < k; j+... | JAVA |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <typename S, typename T>
ostream& operator<<(ostream& out, pair<S, T> const& p) {
out << '(' << p.first << ", " << p.second << ')';
return out;
}
template <typename T>
ostream& operator<<(ostream& out, vector<T> const& v) {
int l = v.size();
for (int i = 0;... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
template <typename T>
inline void read(T &x) {
x = 0;
char c = getchar();
bool flag = false;
while (!isdigit(c)) {
if (c == '-') flag = true;
c = getchar();
}
while (isdigit(c)) x = x * 10 + (c ^ 48), c = getchar();
if (flag) x = -x;
}
using namespace std;
int n, mod, l, r... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | import java.util.*;
/**
* Created by mcl on 2017/12/2.
*/
public class Main {
public static void main(String[] args) {
new Main().cal();
}
int n;
int p;
int left;
int right;
long[][] fact = null;
List<Integer[]> list = new ArrayList<>();
void cal() {
Scanner in = new Scanner(System.in);... | JAVA |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long factorial_invertible[100001];
int factor[100001], p;
const int MAX_BAD = 17;
int idx_bad[100001];
int pow_bad[MAX_BAD][100001];
int factorial_bad[100001][MAX_BAD];
vector<int> bad_factors;
struct t {
long long a, b;
int g;
t(long long a, long long b, int g) ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long n, m, mod, l, r, ans, fac[100005], inv[100005], a[100005][20],
p[100005];
long long kp(long long a, long long b, long long p) {
if (!b) return 1;
long long c = kp(a, b >> 1, p);
c = c * c % p;
if (b & 1) c = c * a % p;
return c;
}
long long c(long lo... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
inline int read() {
int w = 0, x = 0;
char c = getchar();
while (!isdigit(c)) w |= c == '-', c = getchar();
while (isdigit(c)) x = x * 10 + (c ^ 48), c = getchar();
return w ? -x : x;
}
namespace star {
const int maxn = 1e5 + 10;
int p, n, l, r, tot;
int pn[40], i... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
int n, l, r, p, prime[20], cnt;
long long power(long long x, long long y) {
long long ans = 1;
for (; y; y >>= 1, x = (long long)x * x % p)
if (y & 1) ans = (long long)ans * x % p;
return ans;
}
void exgcd(long long a, long long b, long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100010], fac[100010], p[100010], t[100010][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <class T>
ostream& operator<<(ostream& stream, const vector<T> v) {
stream << "[ ";
for (int i = 0; i < (int)v.size(); i++) stream << v[i] << " ";
stream << "]";
return stream;
}
long long fpow(long long x, long long p, long long m) {
long long r = 1;
f... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | import java.util.*;
/**
* Created by mcl on 2017/12/2.
*/
public class Main {
public static void main(String[] args) {
new Main().cal();
}
int n;
int p;
int left;
int right;
long[] fact = null;
int[] primes = null;
void init() {
primes = split(p);
fact = new long[n + 1];
fact[0] ... | JAVA |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int sz = 1e5 + 10;
int mod, m, ef = 1;
int f[sz][12], f2[sz], st[sz][12];
int po(int x, int y) {
int re = 1 % mod;
while (y) {
if (y & 1) re = (1ll * re * x) % mod;
x = (1ll * x * x) % mod;
y >>= 1;
}
return re;
}
int fc(int n, int k) {
int re = ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
int n, p, l, r, phi, cp[20], num[N][20], tot, ans, f[N], ny[N];
inline int read() {
int x, f = 1;
char ch;
while (!(isdigit(ch = getchar()))) ch == '-' ? f = -1 : f;
x = ch ^ 48;
while ((isdigit(ch = getchar()))) x = (x << 1) + (x << 3) + (c... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long gcd(long long a, long long b) { return b == 0 ? a : gcd(b, a % b); }
const int MAXN = 100000;
int n, MOD, l, r;
int egcd(int x, int y, int &a, int &b) {
if (y == 0) {
a = 1, b = 0;
return x;
}
int g = egcd(y, x % y, b, a);
b -= a * (x / y);
retur... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int c = 200002, k = 30;
long long n, mod, mod2, l, r;
long long cnt, pr[k], t[k], fakt[c][k], sum = 0;
int phi(int n) {
int result = n;
for (int i = 2; i * i <= n; i++) {
if (n % i == 0) {
pr[++cnt] = i;
while (n % i == 0) n /= i;
result -= r... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100010], fac[100010], p[100010], t[100010][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MOD = 1e9 + 7;
map<int, int> M;
vector<pair<int, int> > V;
long long F1[12][100010], F2[12][100010];
int p;
int pw(int x, int y, int M) {
int res = 1;
while (y) {
if (y & 1) res = (long long)res * x % M;
x = (long long)x * x % M;
y >>= 1;
}
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100010], fac[100010], p[100010], t[100010][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
using VS = vector<string>;
using LL = long long;
using VI = vector<int>;
using VVI = vector<VI>;
using PII = pair<int, int>;
using PLL = pair<LL, LL>;
using VL = vector<LL>;
using VVL = vector<VL>;
const int INF = 1e9;
const LL LINF = 1e16;
const LL MOD = 1000000007;
const ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
inline int rd() {
char ch = getchar();
int i = 0, f = 1;
while (!isdigit(ch)) {
if (ch == '-') f = -1;
ch = getchar();
}
while (isdigit(ch)) {
i = (i << 1) + (i << 3) + ch - '0';
ch = getchar();
}
return i * f;
}
const int Maxn = 1e5 + 50;
vect... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <class T>
void splitstr(const string &s, vector<T> &out) {
istringstream in(s);
out.clear();
copy(istream_iterator<T>(in), istream_iterator<T>(), back_inserter(out));
}
static void redirect(int argc, const char **argv) {
ios::sync_with_stdio(false);
cin.t... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
void Gcd(long long x, long long y, long long mod, long long& kx,
long long& ky) {
if (y == 0) return void(kx = ky = 1);
long long del = x / y;
Gcd(y, x - del * y, mod, ky, kx);
(ky -= del * kx) %= mod;
}
long long Oem(long long x, long long mod) {
long lo... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int Imx = 2147483647;
const long long Lbig = 2e18;
int mod;
struct fastio {
char s[100000];
int it, len;
fastio() { it = len = 0; }
inline char get() {
if (it < len) return s[it++];
it = 0;
len = fread(s, 1, 100000, stdin);
if (len == 0)
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100005;
long long p, n, l, r;
long long pr[N], inv[N], f[N], c[N][40], phi;
int cnt = 0;
long long powe(long long a, long long b) {
long long base = 1;
while (b) {
if (b & 1) base = (base * a) % p;
a = (a * a) % p;
b >>= 1;
}
return base;
}... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long int inf = 1000000000;
const long long int mod = 1000000000 + 7;
inline void IO() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
inline int dcmp(long double x) { return x < -1e-12 ? -1 : (x > 1e-12); }
template <class T>
inline int CHECK(T M... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100003;
int n, L, R, phi;
long long mod;
long long fac[N], inv[N];
int d[N][33];
int tot, p[N];
long long fpow(long long x, int y) {
long long res = 1;
while (y) {
if (y & 1) res = res * x % mod;
x = x * x % mod;
y >>= 1;
}
return res;
}
vo... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
using ll = long long;
template <class t, class u>
void chmax(t& first, u second) {
if (first < second) first = second;
}
template <class t, class u>
void chmin(t& first, u second) {
if (second < first) first = second;
}
template <class t>
using vc = vector<t>;
template ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long inf = 1e9;
const long long Inf = 1e18;
const long long N = 1e5 + 10;
long long mod;
long long gi() {
long long x = 0, o = 1;
char ch = getchar();
while ((ch < '0' || ch > '9') && ch != '-') ch = getchar();
if (ch == '-') o = -1, ch = getchar();
whi... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <typename T>
inline bool upmin(T &x, T y) {
return y < x ? x = y, 1 : 0;
}
template <typename T>
inline bool upmax(T &x, T y) {
return x < y ? x = y, 1 : 0;
}
const long double eps = 1e-11;
const long double pi = acos(-1);
const long long oo = 1 << 30;
const lo... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int maxN = 2e5 + 10, lim = 2e5;
int n, P, l, r, phi;
int fac[maxN + 1], inv[maxN + 1];
int cnt, p[maxN + 1], c[maxN + 1][22];
inline long long ADD(long long x, long long y) {
return x + y >= P ? x + y - P : x + y;
}
inline long long SUB(long long x, long long y) {
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const unsigned MAXN = 1e5 + 5;
unsigned n, p, l, r, phi, t, ans;
unsigned pp[MAXN], fac[MAXN], ifac[MAXN], a[15][MAXN];
inline unsigned read() {
unsigned x = 0;
char ch = getchar();
while (!isdigit(ch)) ch = getchar();
while (isdigit(ch)) {
x = x * 10 + ch - '0'... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 5;
long long d[11], iv[N], ad[11][N], f[N];
int t, p;
long long qp(long long a, int b) {
long long r = 1;
for (; b; b >>= 1, a = a * a % p)
if (b & 1) r = r * a % p;
return r;
}
long long c(int n, int m) {
if (m < 0) return 0;
long long r =... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 100005;
int n, p, l, r;
int fac[MAXN];
int inv[MAXN];
int cnt[MAXN];
int power(int a, int b) {
int res = 1;
while (b) {
if (b & 1) res *= a;
a *= a;
b >>= 1;
}
return res;
}
void exgcd(int a, int b, int &x, int &y) {
if (!b) {
x = ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("O2,unroll-loops")
using namespace std;
const int inf = 1000000010;
const long long INF = 10000000000000010LL;
const int MAXN = 300010, LOG = 20;
long long n, mod, k, u, v, l, r, t, p, ans;
long long A[MAXN], F[MAXN], I[MAXN], phi;
vector<int> prime;
long long powmod(long l... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 100010;
const int INF = 1000000007;
const double PI = acos(-1.0);
long long f[MAXN], g[MAXN];
long long extended_euclidean(long long a, long long b, long long &x,
long long &y) {
if (b == 0) {
x = 1;
y = 0;
return ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | import java.io.*;
import java.util.*;
public class MainD {
static StdIn in = new StdIn();
static PrintWriter out = new PrintWriter(System.out);
static long p;
static List<Long> pFs = new ArrayList<Long>();
static long[] fact1;
static int[][] fact2;
public static void main(String[] args) {
int n=in.nextInt()... | JAVA |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MN = 100010;
vector<int> pr, pchk;
void Sieve() {
pchk = vector<int>(MN, 0);
for (int i = 2; i < MN; i++) {
if (!pchk[i]) {
pr.push_back(i);
}
for (int j = 0; j < pr.size() && i * pr[j] < MN; j++) {
pchk[i * pr[j]] = 1;
if (i % pr... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
vector<pair<pair<int, int>, vector<int>>> lst;
vector<int> fact;
pair<int, vector<int>> tmp, _tmp;
void init(int p) {
fact.clear();
int i;
for (i = 2; i * i <= p; i++) {
if (p % i == 0) {
fact.push_back(i);
while (p % i == 0) p /= i;
} else
;... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <class T>
void _R(T &x) {
cin >> x;
}
void _R(int &x) { scanf("%d", &x); }
void _R(int64_t &x) { scanf("%lld", &x); }
void _R(double &x) { scanf("%lf", &x); }
void _R(char &x) { scanf(" %c", &x); }
void _R(char *x) { scanf("%s", x); }
void R() {}
template <class ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int inf = 1.01e9;
const double eps = 1e-9;
int P;
const int N = 1e5 + 10;
int p[111], pp = 0;
struct num {
vector<int> a;
int r;
num(int x) {
a = vector<int>(pp);
for (int i = 0; (i) < (pp); ++i) {
while (x % p[i] == 0) {
a[i]++;
x ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
int n, l, r;
long long p;
long long mod, bs, expo;
pair<long long, long long> gcd(long long a, long long b) {
if (a == 0) {
return make_pair(0, 1);
}
pair<long long, long long> prev = gcd(b % a, a);
return make_pair(prev.second - (b / a) * prev.first, prev.first... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long n, p, l1, r1, ans, cnt, q[105], r[105], Q, R, P, pw[55];
void exgcd(long long a, long long b, long long &x, long long &y) {
if (b == 0) {
x = 1;
y = 0;
return;
}
exgcd(b, a % b, x, y);
int t = x;
x = y;
y = t - y * (a / b);
return;
}
stru... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long N = 1e5 + 10;
long long c[N][50], pri[N], phi, fac[N], inv[N], skc, len, n;
void upd(long long &x, long long y) { x = (x + y) % skc; }
long long qpow(long long A, long long B) {
long long C = 1;
for (; B; B >>= 1, A = A * A % skc)
if (B & 1) C = A * ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long size = 1e5 + 5;
long long n, p, l, r;
long long tot;
long long prime[45];
long long fac[size], inv[size];
long long tim[size][45];
long long quick_pow(long long a, long long b) {
long long ans = 1;
while (b) {
if (b & 1) ans = ans * a % p;
a = a ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("-O3")
using namespace std;
void _main();
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
_main();
}
const int inf = INT_MAX / 2;
const long long infl = 1LL << 60;
template <class T>
bool chmax(T &a, const T &b) {
if (a < b) {
a = b;
return 1;
}
re... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long n, p, phi, l, r, ans, g[100005][10], fac[100005], inv[100005], pr[30];
long long pw(long long a, long long b) {
long long s = 1;
for (; b; b /= 2, a = a * a % p)
if (b & 1) s = s * a % p;
return s;
}
long long C(long long a, long long b) {
if (a < b) r... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long expo(long long base, long long exponent, long long mod) {
long long ans = 1;
while (exponent != 0) {
if (exponent & 1) ans = (1LL * ans * base) % mod;
base = (1LL * base * base) % mod;
exponent >>= 1;
}
return ans % mod;
}
const long long N = 1... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long n, p, l, r;
long long p0[25], pu[25], re[25];
long long mul[25][200005];
long long g[200005][25];
int cnt = 0;
void make_init() {
long long tempp = p;
for (long long i = 2; i * i <= p; i++) {
if (p % i == 0) {
cnt++, p0[cnt] = i, pu[cnt] = 1;
w... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <typename T>
inline bool cmin(T& a, const T& b) {
return a > b ? a = b, 1 : 0;
}
template <typename T>
inline bool cmax(T& a, const T& b) {
return a < b ? a = b, 1 : 0;
}
int inp() {
int x = 0, f = 1;
char ch;
for (ch = getchar(); !isdigit(ch); ch = getch... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
inline void read(int &x) {
int v = 0, f = 1;
char c = getchar();
while (!isdigit(c) && c != '-') c = getchar();
if (c == '-')
f = -1;
else
v = v * 10 + c - '0';
while (isdigit(c = getchar())) v = v * 10 + c - '0';
x = v * f;
}
inline void read(long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
int IN() {
int c, f, x;
while (!isdigit(c = getchar()) && c != '-')
;
c == '-' ? (f = 1, x = 0) : (f = 0, x = c - '0');
while (isdigit(c = getchar())) x = (x << 1) + (x << 3) + c - '0';
return !f ? x : -x;
}
const int N = 100000 + 19;
int A[N], B[N], C[N];
int... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
const int N = 100010;
using namespace std;
long long inv[N], fac[N], p[N], t[N][20];
int n, l, r, mod, tot, Phi;
inline int mult(int a, int b, int md) {
long long t = 1ll * a * b;
if (t >= md) t %= md;
return t;
}
inline int power(int a, int b, int md) {
int ret = 1;
while (b) {
i... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long size = 1e5 + 5;
long long n, p, l, r;
long long tot;
long long prime[45];
long long fac[size], inv[size];
long long tim[size][45];
long long quick_pow(long long a, long long b) {
long long ans = 1;
while (b) {
if (b & 1) ans = ans * a % p;
a = a ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
class Integer {
public:
static void SetModulo(int mod) {
mod_ = mod;
phi_ = mod;
divisors_.clear();
for (int i = 2; i * i <= mod; i += 1) {
if (mod % i == 0) {
divisors_.push_back(i);
phi_ /= i;
phi_ *= i - 1;
while (... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long N = 100001;
long long n, p, phi, l, r;
long long ans;
long long g[N][30], f[N], F[N], pr[30], t[30];
long long mi(long long a, long long b) {
long long s = 1;
for (; b; b >>= 1, a = (long long)a * a % p)
if (b & 1) s = (long long)s * a % p;
return ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
int n, l, r;
long long p, phi, fac[100005], inv[100005];
int a[11], cnt[100005][11], t[100005], tot = 0;
inline long long qpow(long long a, long long b, long long mod... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 1e5 + 10;
int n, p, l, r, pri[30], cnt;
long long d[N][30], fac[N], inv[N];
long long POW(long long x, long long k) {
long long a = 1;
while (k) {
if (k & 1) a = a * x % p;
x = x * x % p;
k >>= 1;
}
return a;
}
void init() {
int s = p, re... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int P = 10, N = 1e5 + 10;
int inverse(int a, int m) {
if (a <= 1) return a;
int ans = (1 - (long long int)inverse(m % a, a) * m) / a;
if (ans < 0) ans += m;
return ans;
}
int fact[N], ifact[N], pot[N][P];
int sz, p[P];
void primes(int n) {
for (int d = 2; d ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("-O3")
using namespace std;
void _main();
int main() {
cin.tie(0);
ios::sync_with_stdio(false);
_main();
}
const int inf = INT_MAX / 2;
const long long infl = 1LL << 60;
template <class T>
bool chmax(T &a, const T &b) {
if (a < b) {
a = b;
return 1;
}
re... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int P = 10, N = 1e5 + 10;
int inverse(int a, int m) {
if (a <= 1) return a;
int ans = (1 - (long long int)inverse(m % a, a) * m) / a;
if (ans < 0) ans += m;
return ans;
}
int fact[N], ifact[N], pot[N][P];
vector<int> primes(int n) {
vector<int> ans;
for (i... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
long long MOD = 1000000007;
long double EPS = 1e-9;
long long binpow(long long b, long long p, long long mod) {
long long ans =... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const long long int inf = 1000000000;
const long long int mod = 1000000000 + 7;
inline void IO() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
inline int dcmp(long double x) { return x < -1e-12 ? -1 : (x > 1e-12); }
template <class T>
inline int CHECK(T M... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100010], fac[100010], p[100010], t[100010][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
#pragma GCC optimize("Ofast")
#pragma GCC target("sse,sse2,sse3,ssse3,sse4,popcnt,abm,mmx,avx,tune=native")
using namespace std;
const long long int inf = 1000000000;
const long long int mod = 1000000000 + 7;
inline void IO() {
ios_base::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
inli... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 10;
int n, p, l, r, MOD;
int fac[10][maxn], ifac[10][maxn], cnt[10][maxn], arr[maxn], mm[10];
vector<int> v;
vector<int> vp;
int tavan(int a, int b, int md) {
int ans = 1;
while (b > 0) {
if (b & 1) ans = (1ll * ans * a) % md;
a = (1ll * a... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
int i, j, k, n, m, p;
int a[33], c[100010][33];
int fac[100010], inv[100010];
int l, r, L, R, len, Ans;
inline int Pow(int x, int y) {
int Ans = 1;
for (; y; y >>= 1, x = 1ll * x * x % p)
if (y & 1) Ans = 1ll * Ans * x % p;
return Ans;
}
inline void Init() {
int... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int P = 10, N = 1e5 + 10;
inline int inverse(int a, int m) {
if (a <= 1) return a;
int ans = (1 - (long long int)inverse(m % a, a) * m) / a;
return ans + m;
}
int fact[N], ifact[N], pot[N][P];
int sz, p[P];
inline void primes(int n) {
for (int d = 2; d * d <= ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long int n, p, l, r, K;
long long int gt[100005], rev[100005], gt1[100005];
long long int mu(long long int a, long long int n, long long int K) {
if (n == 0) return 1;
long long int q = mu(a, n / 2, K);
if (n % 2 == 0) return q * q % K;
return q * q % K * a % K... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int maxn = 1e5 + 7;
int n, l, r, p;
int tot;
long long fac[maxn], inv[maxn], a[maxn], c[maxn][30];
long long qpow(long long x, long long n) {
long long res = 1;
while (n) {
if (n & 1) res = res * x % p;
n >>= 1;
x = x * x % p;
}
return res;
}
void ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using std::cerr;
using std::cin;
using std::max;
using std::min;
int n, a, b, mod, cntp, pri[100005], isp[100005], ans;
std::vector<int> S;
long long cal(long long x) {
x -= x < mod ? 0 : mod;
return x;
}
long long Pow(int x, int y) {
int res = 1;
for (; y; x = (long long)x * x % mod, y... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long inv[100010], fac[100010], p[100010], t[100010][20];
int n, l, r, P, tot, Phi;
int phi(int k) {
int i, s;
s = k;
for (i = 2; i * i <= k; i++) {
if (k % i == 0) s = s / i * (i - 1);
while (k % i == 0) k /= i;
}
if (k > 1) s = s / k * (k - 1);
ret... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using std::cin;
using std::cout;
const int maxn = 100100;
int n, mod, l, r;
int p[100], tot;
inline void exgcd(int a, int b, int& x, int& y) {
if (!a) {
x = 0, y = 1;
return;
}
exgcd(b % a, a, y, x);
x -= b / a * y;
}
inline int inv(int x) {
int a, b;
exgcd(x, mod, a, b);
... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
const long long N = 100010;
long long n, pp, l, r;
long long min(long long a, long long b) { return a < b ? a : b; }
long long mpow(long long a, long long b, long long p) {
long long c = 1;
for (; b; b >>= 1, a = 1ll * a * a % p)
if (b & 1) c = 1ll * a * c % p;
return c;
}
long long p... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
long long eucinv(long long a, long long moder) {
long long b = moder, s = 1, t = 0;
while (b) {
long long tmp = a, q = a / b;
a = b, b = tmp % a;
tmp = s;
s = t;
t = tmp - s * q;
}
if (a > 1) return -1;
return s < 0 ? moder + s : s;
}
const int N = 200010;
long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int MAXN = 110000;
vector<int> f;
long long g[MAXN], c[MAXN], d[MAXN], e[MAXN], r[MAXN];
void add(int u, int sgn, long long &cur, long long p) {
for (auto q : f) {
while (u % q == 0) {
if (sgn > 0)
g[q] *= q;
else
g[q] /= q;
u /... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
template <class T, class U>
void Min(T &a, U b) {
if (a > b) a = b;
}
template <class T, class U>
void Max(T &a, U b) {
if (a < b) a = b;
}
long long pow(long long a, int b, int c) {
long long ans = 1;
while (b) {
if (b & 1) ans = ans * a % c;
a = 1LL * a * ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
inline void read(int &x) {
int v = 0, f = 1;
char c = getchar();
while (!isdigit(c) && c != '-') c = getchar();
if (c == '-')
f = -1;
else
v = v * 10 + c - '0';
while (isdigit(c = getchar())) v = v * 10 + c - '0';
x = v * f;
}
inline void read(long lon... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
const int N = 100100;
int cnt[N][20], n, mod, jc[N], jc2[N], l, r, phi;
int ksm(long long a, int b, int c = 1) {
for (; b; b /= 2, a = a * a % mod)
if (b & 1) c = c * a % mod;
return c;
}
vector<int> pr;
void factor(int x) {
phi = x;
for (int i = 2; i * i <= x; ... | CPP |
896_D. Nephren Runs a Cinema | Lakhesh loves to make movies, so Nephren helps her run a cinema. We may call it No. 68 Cinema.
<image>
However, one day, the No. 68 Cinema runs out of changes (they don't have 50-yuan notes currently), but Nephren still wants to start their business. (Assume that yuan is a kind of currency in Regulu Ere.)
There are ... | 2 | 10 | #include <bits/stdc++.h>
using namespace std;
long long N, P, L, R;
bool V[50005];
long long Prime[50005];
long long Desc[50005], Exp[50005], cnt;
pair<long long, long long> Fact[25][100005];
long long Number[100005];
void sieve() {
for (long long i = 2; i <= 50000; i++) {
if (V[i] == 0) {
Prime[++Prime[0]]... | CPP |
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