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The dataset generation failed
Error code: DatasetGenerationError
Exception: TypeError
Message: Couldn't cast array of type
struct<mass_numerator: int64, mass_denominator: int64, molar_mass: int64, town_index: int64, acid_concentration_tenths: int64, acid_volume: int64, base_concentration_tenths: int64>
to
{'acid_concentration_tenths': Value('int64'), 'acid_volume': Value('int64'), 'base_concentration_tenths': Value('int64'), 'town_index': Value('int64')}
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1827, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 343, in _generate_tables
self._cast_table(pa_table, json_field_paths=json_field_paths),
~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 132, in _cast_table
pa_table = table_cast(pa_table, self.info.features.arrow_schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2378, in table_cast
return cast_table_to_schema(table, schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2312, in cast_table_to_schema
cast_array_to_feature(
~~~~~~~~~~~~~~~~~~~~~^
table[name] if name in table_column_names else pa.array([None] * len(table), type=schema.field(name).type),
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
feature,
^^^^^^^^
)
^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 1861, in wrapper
return pa.chunked_array([func(chunk, *args, **kwargs) for chunk in array.chunks])
~~~~^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2068, in cast_array_to_feature
_c(array.field(name) if name in array_fields else null_array, subfeature)
~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 1863, in wrapper
return func(array, *args, **kwargs)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2158, in cast_array_to_feature
raise TypeError(f"Couldn't cast array of type\n{_short_str(array.type)}\nto\n{_short_str(feature)}")
TypeError: Couldn't cast array of type
struct<mass_numerator: int64, mass_denominator: int64, molar_mass: int64, town_index: int64, acid_concentration_tenths: int64, acid_volume: int64, base_concentration_tenths: int64>
to
{'acid_concentration_tenths': Value('int64'), 'acid_volume': Value('int64'), 'base_concentration_tenths': Value('int64'), 'town_index': Value('int64')}
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
id string | prompt string | completion string | messages list | answer string | subject string | topic string | difficulty string | format string | pedagogy string | language string | mode string | split string | curriculum dict | provenance dict | verification dict | contamination dict | tokenization dict |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
muta2_bfdaa56d3d4f1d08a82cc52b | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 221 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 221 ÷ 1.7 = 247 cm³. Final answer: 247 cm³. | [
{
"role": "user",
"content": "In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 221 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.9 × 221 ÷ 1.7 = 247 cm³... | 247 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:3894",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "247 cm³",
"observed": "247 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 19,
"acid_volume": 221,
"base_concentration_tenths": 17,
"town_index": 12
},
"misconception_type": "... | {
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} |
muta2_78fd2bee9e85c4bbf77ad0ca | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 102 ÷ 1.7 = 114 cm³. Final answer: 114 cm³. | [
{
"role": "user",
"content": "In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.9 × 102 ÷ 1.7 = 114 cm³.... | 114 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:8094",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform": ... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "114 cm³",
"observed": "114 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 19,
"acid_volume": 102,
"base_concentration_tenths": 17,
"town_index": 9
},
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muta2_cec37183f589a9751ae69509 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 85 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 85 ÷ 1.7 = 70 cm³. Final answer: 70 cm³. | [
{
"role": "user",
"content": "In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 85 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.4 × 85 ÷ 1.7 = 70 cm³. Final... | 70 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:20994",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "70 cm³",
"observed": "70 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 14,
"acid_volume": 85,
"base_concentration_tenths": 17,
"town_index": 3
},
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muta2_99dfe6f56750a660e83c651a | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 204 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 204 ÷ 1.7 = 156 cm³. Final answer: 156 cm³. | [
{
"role": "user",
"content": "In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 204 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.3 × 204 ÷ 1.7 = 156 cm³. Fi... | 156 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:24594",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "156 cm³",
"observed": "156 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 13,
"acid_volume": 204,
"base_concentration_tenths": 17,
"town_index": 3
},
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muta2_b22dae0308a7da6bbc7c2cfd | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 266 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 266 ÷ 1.9 = 98 cm³. Final answer: 98 cm³. | [
{
"role": "user",
"content": "In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 266 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.7 × 266 ÷ 1.9 = 98 cm³.... | 98 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:24894",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "98 cm³",
"observed": "98 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
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"acid_volume": 266,
"base_concentration_tenths": 19,
"town_index": 8
},
"misconception_type": "equa... | {
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muta2_1439f6f6496b7cc96e75bfe9 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 70 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.5 × 70 ÷ 0.7 = 150 cm³. Final answer: 150 cm³. | [
{
"role": "user",
"content": "In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 70 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.5 × 70 ÷ 0.7 = 150 cm³. ... | 150 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:35094",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "150 cm³",
"observed": "150 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
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"acid_volume": 70,
"base_concentration_tenths": 7,
"town_index": 8
},
"misconception_type": "equ... | {
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muta2_c3f39aad18da158e293b007e | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1 mol/dm³ NaOH neutralizes 150 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 150 ÷ 1 = 90 cm³. Final answer: 90 cm³. | [
{
"role": "user",
"content": "In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1 mol/dm³ NaOH neutralizes 150 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.6 × 150 ÷ 1 = 90 cm³. Fin... | 90 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:44694",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
"status": "programmatic",
"method": "neutralization_volume",
"expected": "90 cm³",
"observed": "90 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
"acid_concentration_tenths": 6,
"acid_volume": 150,
"base_concentration_tenths": 10,
"town_index": 8
},
"misconception_type": "equa... | {
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} |
muta2_4cae67f76c5cf500848907b8 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 130 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 130 ÷ 1.3 = 60 cm³. Final answer: 60 cm³. | [
{
"role": "user",
"content": "In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 130 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.6 × 130 ÷ 1.3 = 60 cm³.... | 60 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
"source_id": "muta_verified_stem_v2",
"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
"source_split": "generated",
"source_row_id": "generated:48294",
"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
"synthetic": true,
"transform":... | {
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muta2_4ad5d8afce56c137f72acaa2 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 119 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.2 × 119 ÷ 1.7 = 84 cm³. Final answer: 84 cm³. | [
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muta2_c4e0e2909d195239c24a7192 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 168 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 168 ÷ 1.2 = 154 cm³. Final answer: 154 cm³. | [
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muta2_730d6a3694b3f46127aec56d | In a titration in Monrovia, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 88 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 88 ÷ 0.8 = 220 cm³. Final answer: 220 cm³. | [
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muta2_5f48db3025f9bfc079011728 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 280 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 280 ÷ 2 = 140 cm³. Final answer: 140 cm³. | [
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muta2_ccbaaad69ad1f0ccb85db848 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 18 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 18 ÷ 0.2 = 27 cm³. Final answer: 27 cm³. | [
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muta2_f7cfa612c2da7e25d1c2d048 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 55 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 55 ÷ 1.1 = 40 cm³. Final answer: 40 cm³. | [
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muta2_9a6e377cdb2a90b2158478de | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 156 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 156 ÷ 1.2 = 117 cm³. Final answer: 117 cm³. | [
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muta2_1943aa71438c9a939c138dd3 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 135 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 135 ÷ 1.5 = 18 cm³. Final answer: 18 cm³. | [
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},
{
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muta2_05e8d68d363c04b24a40e876 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 98 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 98 ÷ 0.7 = 84 cm³. Final answer: 84 cm³. | [
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},
{
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muta2_d7134ee1312aaf220d30522c | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 204 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 204 ÷ 1.7 = 132 cm³. Final answer: 132 cm³. | [
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muta2_15a6b8cb65c1518d03850369 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 84 cm³ of 0.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.5 × 84 ÷ 1.2 = 35 cm³. Final answer: 35 cm³. | [
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muta2_0d77620114bdeea2c73987b9 | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 195 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 195 ÷ 1.5 = 221 cm³. Final answer: 221 cm³. | [
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muta2_889a51e2ca1aa48596aafaa1 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 80 cm³ of 0.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.4 × 80 ÷ 0.8 = 40 cm³. Final answer: 40 cm³. | [
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muta2_d0371cae9d15f4db08f3c3db | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 80 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 80 ÷ 0.8 = 20 cm³. Final answer: 20 cm³. | [
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muta2_958a8703a59db29851e26668 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 144 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 144 ÷ 1.6 = 72 cm³. Final answer: 72 cm³. | [
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muta2_9c2aa28dd92e01a53f290665 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1 mol/dm³ NaOH neutralizes 120 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 120 ÷ 1 = 240 cm³. Final answer: 240 cm³. | [
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},
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muta2_7942332a942d96c392500350 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 60 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 60 ÷ 1.2 = 35 cm³. Final answer: 35 cm³. | [
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},
{
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muta2_88208e47959190b70e34c80a | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 180 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 180 ÷ 1.8 = 90 cm³. Final answer: 90 cm³. | [
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muta2_3970ff379ffd7e5f9edb2cb2 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 18 cm³ of 0.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.4 × 18 ÷ 0.2 = 36 cm³. Final answer: 36 cm³. | [
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muta2_fc4bd489f36fdc87304e4862 | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 7 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 7 ÷ 0.1 = 77 cm³. Final answer: 77 cm³. | [
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muta2_a950dc56abd36635b4c0acae | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 63 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 63 ÷ 0.7 = 90 cm³. Final answer: 90 cm³. | [
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muta2_dffe9c7dce57c37654910425 | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 45 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 45 ÷ 0.3 = 195 cm³. Final answer: 195 cm³. | [
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muta2_2e0c20a0b0ea271d60855ea6 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 91 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.6 × 91 ÷ 1.3 = 112 cm³. Final answer: 112 cm³. | [
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muta2_9fb2301deaaf9c4f10e9ce03 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 165 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 165 ÷ 1.5 = 187 cm³. Final answer: 187 cm³. | [
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muta2_01478a9fd743f859a2f1d83e | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 88 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 88 ÷ 0.8 = 99 cm³. Final answer: 99 cm³. | [
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muta2_6ddb4d82deb27e5a189f167c | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 195 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 195 ÷ 1.3 = 105 cm³. Final answer: 105 cm³. | [
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},
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muta2_57ef943b706d0f769bce3f12 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 266 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 266 ÷ 1.9 = 28 cm³. Final answer: 28 cm³. | [
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},
{
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muta2_6bcea867e75f6dca9484a329 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 88 cm³ of 0.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.6 × 88 ÷ 0.8 = 66 cm³. Final answer: 66 cm³. | [
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muta2_b5e4ed74fc86465b70e1f035 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 150 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.6 × 150 ÷ 1.5 = 160 cm³. Final answer: 160 cm³. | [
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muta2_3b9c5345f5f700d221e49d76 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 153 cm³ of 1.6 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.6 × 153 ÷ 1.7 = 144 cm³. Final answer: 144 cm³. | [
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muta2_e2428afbf1607d21e63826f9 | In a titration in Monrovia, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 224 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 224 ÷ 1.6 = 28 cm³. Final answer: 28 cm³. | [
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muta2_1170d4e667cbfc482744651f | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.6 mol/dm³ NaOH neutralizes 66 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 66 ÷ 0.6 = 220 cm³. Final answer: 220 cm³. | [
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muta2_e6e3088111a583a1f49834f8 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 176 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 176 ÷ 1.6 = 77 cm³. Final answer: 77 cm³. | [
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muta2_bc78f27f7de5d627402da61b | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 14 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 14 ÷ 0.2 = 70 cm³. Final answer: 70 cm³. | [
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muta2_f9d31e25a3f3b6386a2a4acb | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 153 cm³ of 0.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.5 × 153 ÷ 1.7 = 45 cm³. Final answer: 45 cm³. | [
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muta2_0afe589ab2824769e9fda632 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 204 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 204 ÷ 1.7 = 240 cm³. Final answer: 240 cm³. | [
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muta2_f52b20bddce1dd21459058ea | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.7 mol/dm³ NaOH neutralizes 35 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 35 ÷ 0.7 = 100 cm³. Final answer: 100 cm³. | [
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muta2_0ce84177c2ec930ce287c1d6 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 234 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 234 ÷ 1.8 = 39 cm³. Final answer: 39 cm³. | [
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muta2_649b8a2596039ede299ebb57 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 114 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 114 ÷ 1.9 = 84 cm³. Final answer: 84 cm³. | [
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muta2_2964b63a742773f1622909c5 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 112 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 112 ÷ 0.8 = 280 cm³. Final answer: 280 cm³. | [
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muta2_04888bdb71e54b8d71b96019 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 266 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 266 ÷ 1.9 = 42 cm³. Final answer: 42 cm³. | [
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muta2_771592e72f679c03d7e63396 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 27 cm³ of 2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 2 × 27 ÷ 0.3 = 180 cm³. Final answer: 180 cm³. | [
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muta2_0dd597eb57b958af31b33f02 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.5 mol/dm³ NaOH neutralizes 35 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 35 ÷ 0.5 = 21 cm³. Final answer: 21 cm³. | [
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muta2_8fc19b13b8c3498eabd40bc4 | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.9 mol/dm³ NaOH neutralizes 63 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 63 ÷ 0.9 = 98 cm³. Final answer: 98 cm³. | [
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{
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muta2_bc3486de5ad017598d4a8a4f | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 187 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 187 ÷ 1.7 = 110 cm³. Final answer: 110 cm³. | [
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},
{
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muta2_02bfe66ac57821886d32a53c | In a titration in Lagos, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.4 mol/dm³ NaOH neutralizes 168 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 168 ÷ 1.4 = 120 cm³. Final answer: 120 cm³. | [
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muta2_88ec2878e6e531bcc7fe572e | In a titration in Kano, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 216 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 216 ÷ 1.8 = 96 cm³. Final answer: 96 cm³. | [
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muta2_a602ed4b15521e0c144db986 | In a titration in Monrovia, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 20 cm³ of 1.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.2 × 20 ÷ 0.2 = 120 cm³. Final answer: 120 cm³. | [
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muta2_85c5187c40d8f228f41d6a93 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.9 mol/dm³ NaOH neutralizes 126 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 126 ÷ 0.9 = 28 cm³. Final answer: 28 cm³. | [
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muta2_86e56049905a3ebe19fb748e | In a titration in Benin City, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 119 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 119 ÷ 1.7 = 21 cm³. Final answer: 21 cm³. | [
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muta2_00a786f3c5b24d801f2f5e71 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.8 mol/dm³ NaOH neutralizes 162 cm³ of 0.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.5 × 162 ÷ 1.8 = 45 cm³. Final answer: 45 cm³. | [
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muta2_7af63ce4580df6c5228bce4b | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 221 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 221 ÷ 1.7 = 234 cm³. Final answer: 234 cm³. | [
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muta2_3c7975de68e7fdb9f2e97393 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.8 mol/dm³ NaOH neutralizes 112 cm³ of 0.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.9 × 112 ÷ 0.8 = 126 cm³. Final answer: 126 cm³. | [
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muta2_e031c9cb7f63069a2214ffc8 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.5 mol/dm³ NaOH neutralizes 150 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 150 ÷ 1.5 = 80 cm³. Final answer: 80 cm³. | [
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muta2_0065e39610886200f5e31526 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 119 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 119 ÷ 1.7 = 91 cm³. Final answer: 91 cm³. | [
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muta2_3a013e040c976020a0f127ce | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.6 mol/dm³ NaOH neutralizes 208 cm³ of 1.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.8 × 208 ÷ 1.6 = 234 cm³. Final answer: 234 cm³. | [
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muta2_4177f2e7bb39ecfef0c9d4dd | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 33 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 33 ÷ 0.3 = 154 cm³. Final answer: 154 cm³. | [
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muta2_9265e16ccde2bfed5e18254a | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.1 mol/dm³ NaOH neutralizes 5 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 5 ÷ 0.1 = 65 cm³. Final answer: 65 cm³. | [
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muta2_1c3ee51b5fc52f4c9837fe60 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 95 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 95 ÷ 1.9 = 15 cm³. Final answer: 15 cm³. | [
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muta2_df6c59665c7f27d5cbbcfb0f | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.2 mol/dm³ NaOH neutralizes 12 cm³ of 0.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.7 × 12 ÷ 0.2 = 42 cm³. Final answer: 42 cm³. | [
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muta2_76b76ee658b536c460a10e39 | In a titration in Accra, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 55 cm³ of 0.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.3 × 55 ÷ 1.1 = 15 cm³. Final answer: 15 cm³. | [
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muta2_d38e58b39090e6b58232508d | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.7 mol/dm³ NaOH neutralizes 102 cm³ of 1.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.4 × 102 ÷ 1.7 = 84 cm³. Final answer: 84 cm³. | [
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muta2_eeb880031d769ed927f84244 | In a titration in Tamale, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 132 cm³ of 0.2 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.2 × 132 ÷ 1.2 = 22 cm³. Final answer: 22 cm³. | [
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muta2_a4f43aba7162bf6936e50512 | In a titration in Onitsha, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 84 cm³ of 1.9 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.9 × 84 ÷ 1.2 = 133 cm³. Final answer: 133 cm³. | [
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},
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muta2_f224fac789e479a216275652 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 39 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.1 × 39 ÷ 0.3 = 143 cm³. Final answer: 143 cm³. | [
{
"role": "user",
"content": "In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 39 cm³ of 1.1 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.1 × 39 ÷ 0.3 = 143 cm³. Fina... | 143 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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muta2_6a54813a4446b9b8f9b49fe3 | In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 240 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 240 ÷ 2 = 96 cm³. Final answer: 96 cm³. | [
{
"role": "user",
"content": "In a titration in Kumasi, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 2 mol/dm³ NaOH neutralizes 240 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.8 × 240 ÷ 2 = 96 cm³. Fin... | 96 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
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"authority": "Muta normalized public-topic taxonomy",
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muta2_1fba4950da30642d75b24fbf | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 96 cm³ of 0.4 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.4 × 96 ÷ 1.2 = 32 cm³. Final answer: 32 cm³. | [
{
"role": "user",
"content": "In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 96 cm³ of 0.4 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.4 × 96 ÷ 1.2 = 32 cm³. F... | 32 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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"transform"... | {
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muta2_d55dab36c15b7a5dd6ac3e51 | In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 104 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.5 × 104 ÷ 1.3 = 120 cm³. Final answer: 120 cm³. | [
{
"role": "user",
"content": "In a titration in Abeokuta, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.3 mol/dm³ NaOH neutralizes 104 cm³ of 1.5 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.5 × 104 ÷ 1.3 = 120 c... | 120 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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"transform"... | {
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"observed": "120 cm³",
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muta2_25fe9754360706487183dda3 | In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 60 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.3 × 60 ÷ 1.2 = 65 cm³. Final answer: 65 cm³. | [
{
"role": "user",
"content": "In a titration in Ilorin, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.2 mol/dm³ NaOH neutralizes 60 cm³ of 1.3 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.3 × 60 ÷ 1.2 = 65 cm³. F... | 65 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
"alignment": "original item; topic-level alignment only"
} | {
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"source_revision": "sha256:97c99eb0d900f8a41bce63cd2352f2d4e24c04def9eb0c12ed54c00eea0a1f51",
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"license": "MIT",
"synthetic": true,
"transform"... | {
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"method": "neutralization_volume",
"expected": "65 cm³",
"observed": "65 cm³",
"verifier_version": "muta-stem-v2.4",
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},
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muta2_9e5d15e2bfabfbddce66fd7d | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 152 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1.7 × 152 ÷ 1.9 = 136 cm³. Final answer: 136 cm³. | [
{
"role": "user",
"content": "In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.9 mol/dm³ NaOH neutralizes 152 cm³ of 1.7 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1.7 × 152 ÷ 1.9 = 136 c... | 136 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
"exam_era": "contemporary",
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"license": "MIT",
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"transform"... | {
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"method": "neutralization_volume",
"expected": "136 cm³",
"observed": "136 cm³",
"verifier_version": "muta-stem-v2.4",
"inputs": {
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muta2_6332d1ec163c4a14d6a472e6 | In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 36 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 1 × 36 ÷ 0.3 = 120 cm³. Final answer: 120 cm³. | [
{
"role": "user",
"content": "In a titration in Bo, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 0.3 mol/dm³ NaOH neutralizes 36 cm³ of 1 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 1 × 36 ÷ 0.3 = 120 cm³. Final an... | 120 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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"semantic_cluster_id": "formula:neutralization_volume",
"license": "MIT",
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"transform"... | {
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"method": "neutralization_volume",
"expected": "120 cm³",
"observed": "120 cm³",
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muta2_1980d30130d9eedfadaec3a4 | In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 110 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation. | NaOH volume = 0.8 × 110 ÷ 1.1 = 80 cm³. Final answer: 80 cm³. | [
{
"role": "user",
"content": "In a titration in Freetown, HCl reacts with NaOH in a 1:1 mole ratio. What volume of 1.1 mol/dm³ NaOH neutralizes 110 cm³ of 0.8 mol/dm³ HCl? Give the result with one essential calculation."
},
{
"role": "assistant",
"content": "NaOH volume = 0.8 × 110 ÷ 1.1 = 80 cm... | 80 cm³ | chemistry | acid_base_neutralization | advanced | free_response | concise_answer | en | chat | train | {
"country": "multi-country-west-africa",
"authority": "Muta normalized public-topic taxonomy",
"version": "2026-09-15T00:00:00",
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"transform"... | {
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"method": "neutralization_volume",
"expected": "80 cm³",
"observed": "80 cm³",
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End of preview.
Muta STEM SFT Quality Sample
A train-ready, supervised fine-tuning data for Muta Tutor: verified STEM questions paired with answers in five tutoring styles that covers mathematics, physics, chemistry, biology, and integrated science.
Snapshot
| Property | Value |
|---|---|
| Rows | 300,350 |
| JSONL shards | 14 |
| Decompressed data | 776,449,831 bytes (~740 MiB) |
| Hub data file | 39,070,661 bytes (~37.3 MiB), Zstandard |
| Language | English |
| Split | Train |
| Fingerprint | 037edf28cccff62d90c23e2d6caf56b9998dea6928080f98af2a513f9f92910e |
| Source | Rows |
|---|---|
| Muta verified STEM v2 | 280,000 |
| DeepMind Mathematics | 20,000 |
| Private WAEC e-learning review | 47 |
| Private Cheetah WAEC review | 303 |
| Subject | Rows | Tutoring style | Rows |
|---|---|---|---|
| Mathematics | 150,311 | Worked solution | 120,350 |
| Physics | 54,030 | Exam marking scheme | 60,000 |
| Chemistry | 42,006 | Misconception correction | 60,000 |
| Biology | 42,003 | Socratic hint | 30,000 |
| Integrated science | 12,000 | Concise answer | 30,000 |
Record format
Every row has prompt, completion, and two-message messages fields for SFT, together with
answer, subject, topic, difficulty, pedagogy, curriculum, provenance,
verification, contamination, and tokenization metadata. Use messages for
conversation-formatted training.
from datasets import load_dataset
train = load_dataset(
"timiiowolabi/muta_tutor_quality_sample",
split="train",
)
manifest.json and selector-provenance/ bind the exact selection, source evidence, audit
receipts, and original shard hashes. The Hub data file is the lossless concatenation of the 14
manifest shards in listed order; HUGGINGFACE_COMPRESSION.json records its hash and byte counts.
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