db_id stringclasses 146
values | question stringlengths 3 224 | sql stringlengths 18 577 | database_schema stringclasses 146
values |
|---|---|---|---|
sakila_1 | What is the largest payment amount? | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
sakila_1 | Return the amount of the largest payment. | SELECT amount FROM payment ORDER BY amount DESC LIMIT 1 | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
sakila_1 | Where does the staff member with the first name Elsa live? | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
sakila_1 | Give the address of the staff member who has the first name Elsa. | SELECT T2.address FROM staff AS T1 JOIN address AS T2 ON T1.address_id = T2.address_id WHERE T1.first_name = 'Elsa' | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
sakila_1 | What are the first names of customers who have not rented any films after '2005-08-23 02:06:01'? | SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' ) | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
sakila_1 | Return the first names of customers who did not rented a film after the date '2005-08-23 02:06:01'. | SELECT first_name FROM customer WHERE customer_id NOT IN( SELECT customer_id FROM rental WHERE rental_date > '2005-08-23 02:06:01' ) | CREATE TABLE actor (
actor_id SMALLINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id)
)
3 rows from actor table:
actor_id first_name last_name last_update
1 PENELOPE GUINESS 2006-02-15 04:34:33
2 NICK WAHLBERG 2006-02-15 04:34:33
3 ED CHASE 2006-02-15 04:34:33
CREATE TABLE address (
address_id SMALLINT UNSIGNED NOT NULL,
address VARCHAR(50) NOT NULL,
address2 VARCHAR(50) DEFAULT NULL,
district VARCHAR(20) NOT NULL,
city_id SMALLINT UNSIGNED NOT NULL,
postal_code VARCHAR(10) DEFAULT NULL,
phone VARCHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (address_id),
FOREIGN KEY (city_id) REFERENCES city (city_id)
)
3 rows from address table:
address_id address address2 district city_id postal_code phone last_update
1 47 MySakila Drive None Alberta 300 2006-02-15 04:45:30
2 28 MySQL Boulevard None QLD 576 2006-02-15 04:45:30
3 23 Workhaven Lane None Alberta 300 14033335568 2006-02-15 04:45:30
CREATE TABLE category (
category_id TINYINT UNSIGNED NOT NULL,
name VARCHAR(25) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (category_id)
)
3 rows from category table:
category_id name last_update
1 Action 2006-02-15 04:46:27
2 Animation 2006-02-15 04:46:27
3 Children 2006-02-15 04:46:27
CREATE TABLE city (
city_id SMALLINT UNSIGNED NOT NULL,
city VARCHAR(50) NOT NULL,
country_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (city_id),
FOREIGN KEY (country_id) REFERENCES country (country_id)
)
3 rows from city table:
city_id city country_id last_update
1 A Corua (La Corua) 87 2006-02-15 04:45:25
2 Abha 82 2006-02-15 04:45:25
3 Abu Dhabi 101 2006-02-15 04:45:25
CREATE TABLE country (
country_id SMALLINT UNSIGNED NOT NULL,
country VARCHAR(50) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (country_id)
)
3 rows from country table:
country_id country last_update
1 Afghanistan 2006-02-15 04:44:00
2 Algeria 2006-02-15 04:44:00
3 American Samoa 2006-02-15 04:44:00
CREATE TABLE customer (
customer_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
email VARCHAR(50) DEFAULT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
create_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (customer_id),
FOREIGN KEY (address_id) REFERENCES address (address_id),
FOREIGN KEY (store_id) REFERENCES store (store_id)
)
3 rows from customer table:
customer_id store_id first_name last_name email address_id active create_date last_update
1 1 MARY SMITH MARY.SMITH@sakilacustomer.org 5 1 2006-02-14 22:04:36 2006-02-15 04:57:20
2 1 PATRICIA JOHNSON PATRICIA.JOHNSON@sakilacustomer.org 6 1 2006-02-14 22:04:36 2006-02-15 04:57:20
3 1 LINDA WILLIAMS LINDA.WILLIAMS@sakilacustomer.org 7 1 2006-02-14 22:04:36 2006-02-15 04:57:20
CREATE TABLE film (
film_id SMALLINT UNSIGNED NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT DEFAULT NULL,
release_year YEAR DEFAULT NULL,
language_id TINYINT UNSIGNED NOT NULL,
original_language_id TINYINT UNSIGNED DEFAULT NULL,
rental_duration TINYINT UNSIGNED NOT NULL DEFAULT 3,
rental_rate DECIMAL(4,2) NOT NULL DEFAULT 4.99,
length SMALLINT UNSIGNED DEFAULT NULL,
replacement_cost DECIMAL(5,2) NOT NULL DEFAULT 19.99,
rating DEFAULT 'G',
special_features DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id),
FOREIGN KEY (language_id) REFERENCES language (language_id),
FOREIGN KEY (original_language_id) REFERENCES language (language_id)
)
3 rows from film table:
film_id title description release_year language_id original_language_id rental_duration rental_rate length replacement_cost rating special_features last_update
1 ACADEMY DINOSAUR A Epic Drama of a Feminist And a Mad Scientist who must Battle a Teacher in The Canadian Rockies 2006 1 None 6 0.99 86 20.99 PG Deleted Scenes,Behind the Scenes 2006-02-15 05:03:42
2 ACE GOLDFINGER A Astounding Epistle of a Database Administrator And a Explorer who must Find a Car in Ancient China 2006 1 None 3 4.99 48 12.99 G Trailers,Deleted Scenes 2006-02-15 05:03:42
3 ADAPTATION HOLES A Astounding Reflection of a Lumberjack And a Car who must Sink a Lumberjack in A Baloon Factory 2006 1 None 7 2.99 50 18.99 NC-17 Trailers,Deleted Scenes 2006-02-15 05:03:42
CREATE TABLE film_actor (
actor_id SMALLINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (actor_id,film_id),
FOREIGN KEY (actor_id) REFERENCES actor (actor_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from film_actor table:
actor_id film_id last_update
1 1 2006-02-15 05:05:03
1 23 2006-02-15 05:05:03
1 25 2006-02-15 05:05:03
CREATE TABLE film_category (
film_id SMALLINT UNSIGNED NOT NULL,
category_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (film_id, category_id),
FOREIGN KEY (film_id) REFERENCES film (film_id),
FOREIGN KEY (category_id) REFERENCES category (category_id)
)
3 rows from film_category table:
film_id category_id last_update
1 6 2006-02-15 05:07:09
2 11 2006-02-15 05:07:09
3 6 2006-02-15 05:07:09
CREATE TABLE film_text (
film_id SMALLINT NOT NULL,
title VARCHAR(255) NOT NULL,
description TEXT,
PRIMARY KEY (film_id)
)
3 rows from film_text table:
Empty DataFrame
Columns: [film_id, title, description]
Index: []
CREATE TABLE inventory (
inventory_id MEDIUMINT UNSIGNED NOT NULL,
film_id SMALLINT UNSIGNED NOT NULL,
store_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (inventory_id),
FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (film_id) REFERENCES film (film_id)
)
3 rows from inventory table:
inventory_id film_id store_id last_update
1 1 1 2006-02-15 05:09:17
2 1 1 2006-02-15 05:09:17
3 1 1 2006-02-15 05:09:17
CREATE TABLE language (
language_id TINYINT UNSIGNED NOT NULL,
name CHAR(20) NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (language_id)
)
3 rows from language table:
Empty DataFrame
Columns: [language_id, name, last_update]
Index: []
CREATE TABLE payment (
payment_id SMALLINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
rental_id INT DEFAULT NULL,
amount DECIMAL(5,2) NOT NULL,
payment_date DATETIME NOT NULL,
last_update TIMESTAMP DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (payment_id),
FOREIGN KEY (rental_id) REFERENCES rental (rental_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id)
)
3 rows from payment table:
payment_id customer_id staff_id rental_id amount payment_date last_update
1 1 1 76 2.99 2005-05-25 11:30:37 2006-02-15 22:12:30
2 1 1 573 0.99 2005-05-28 10:35:23 2006-02-15 22:12:30
3 1 1 1185 5.99 2005-06-15 00:54:12 2006-02-15 22:12:30
CREATE TABLE rental (
rental_id INT NOT NULL,
rental_date DATETIME NOT NULL,
inventory_id MEDIUMINT UNSIGNED NOT NULL,
customer_id SMALLINT UNSIGNED NOT NULL,
return_date DATETIME DEFAULT NULL,
staff_id TINYINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (rental_id),
FOREIGN KEY (staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (inventory_id) REFERENCES inventory (inventory_id),
FOREIGN KEY (customer_id) REFERENCES customer (customer_id)
)
3 rows from rental table:
rental_id rental_date inventory_id customer_id return_date staff_id last_update
1 2005-05-24 22:53:30 367 130 2005-05-26 22:04:30 1 2006-02-15 21:30:53
2 2005-05-24 22:54:33 1525 459 2005-05-28 19:40:33 1 2006-02-15 21:30:53
3 2005-05-24 23:03:39 1711 408 2005-06-01 22:12:39 1 2006-02-15 21:30:53
CREATE TABLE staff (
staff_id TINYINT UNSIGNED NOT NULL,
first_name VARCHAR(45) NOT NULL,
last_name VARCHAR(45) NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
picture BLOB DEFAULT NULL,
email VARCHAR(50) DEFAULT NULL,
store_id TINYINT UNSIGNED NOT NULL,
active BOOLEAN NOT NULL DEFAULT TRUE,
username VARCHAR(16) NOT NULL,
password VARCHAR(40) DEFAULT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (staff_id),
--FOREIGN KEY (store_id) REFERENCES store (store_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from staff table:
Empty DataFrame
Columns: [staff_id, first_name, last_name, address_id, picture, email, store_id, active, username, password, last_update]
Index: []
CREATE TABLE store (
store_id TINYINT UNSIGNED NOT NULL,
manager_staff_id TINYINT UNSIGNED NOT NULL,
address_id SMALLINT UNSIGNED NOT NULL,
last_update TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP,
PRIMARY KEY (store_id),
FOREIGN KEY (manager_staff_id) REFERENCES staff (staff_id),
FOREIGN KEY (address_id) REFERENCES address (address_id)
)
3 rows from store table:
Empty DataFrame
Columns: [store_id, manager_staff_id, address_id, last_update]
Index: []
|
loan_1 | How many bank branches are there? | SELECT count(*) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Count the number of bank branches. | SELECT count(*) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | How many customers are there? | SELECT sum(no_of_customers) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the total number of customers across banks? | SELECT sum(no_of_customers) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the number of customers in the banks at New York City. | SELECT sum(no_of_customers) FROM bank WHERE city = 'New York City' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the total number of customers who use banks in New York City? | SELECT sum(no_of_customers) FROM bank WHERE city = 'New York City' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the average number of customers in all banks of Utah state. | SELECT avg(no_of_customers) FROM bank WHERE state = 'Utah' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the average number of customers across banks in the state of Utah? | SELECT avg(no_of_customers) FROM bank WHERE state = 'Utah' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the average number of customers cross all banks. | SELECT avg(no_of_customers) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the average number of bank customers? | SELECT avg(no_of_customers) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the city and state of the bank branch named morningside. | SELECT city , state FROM bank WHERE bname = 'morningside' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What city and state is the bank with the name morningside in? | SELECT city , state FROM bank WHERE bname = 'morningside' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the branch names of banks in the New York state. | SELECT bname FROM bank WHERE state = 'New York' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of banks in the state of New York? | SELECT bname FROM bank WHERE state = 'New York' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | List the name of all customers sorted by their account balance in ascending order. | SELECT cust_name FROM customer ORDER BY acc_bal | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of all customers, ordered by account balance? | SELECT cust_name FROM customer ORDER BY acc_bal | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | List the name of all different customers who have some loan sorted by their total loan amount. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of the different customers who have taken out a loan, ordered by the total amount that they have taken? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the state, account type, and credit score of the customer whose number of loan is 0. | SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the states, account types, and credit scores for customers who have 0 loans? | SELECT state , acc_type , credit_score FROM customer WHERE no_of_loans = 0 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the number of different cities which banks are located at. | SELECT count(DISTINCT city) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | In how many different cities are banks located? | SELECT count(DISTINCT city) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the number of different states which banks are located at. | SELECT count(DISTINCT state) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | In how many different states are banks located? | SELECT count(DISTINCT state) FROM bank | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | How many distinct types of accounts are there? | SELECT count(DISTINCT acc_type) FROM customer | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Count the number of different account types. | SELECT count(DISTINCT acc_type) FROM customer | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name and account balance of the customer whose name includes the letter ‘a’. | SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE '%a%' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names and account balances of customers with the letter a in their names? | SELECT cust_name , acc_bal FROM customer WHERE cust_name LIKE '%a%' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the total account balance of each customer from Utah or Texas. | SELECT sum(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the total account balances for each customer from Utah or Texas? | SELECT sum(acc_bal) FROM customer WHERE state = 'Utah' OR state = 'Texas' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers who have both saving and checking account types. | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who have both savings and checking accounts? | SELECT cust_name FROM customer WHERE acc_type = 'saving' INTERSECT SELECT cust_name FROM customer WHERE acc_type = 'checking' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers who do not have an saving account. | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who do not have saving accounts? | SELECT cust_name FROM customer EXCEPT SELECT cust_name FROM customer WHERE acc_type = 'saving' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers who do not have a loan with a type of Mortgages. | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who have not taken a Mortage loan? | SELECT cust_name FROM customer EXCEPT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE T2.loan_type = 'Mortgages' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers who have loans of both Mortgages and Auto. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who have taken both Mortgage and Auto loans? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Mortgages' INTERSECT SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE loan_type = 'Auto' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers whose credit score is below the average credit scores of all customers. | SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers with credit score less than the average credit score across customers? | SELECT cust_name FROM customer WHERE credit_score < (SELECT avg(credit_score) FROM customer) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the branch name of the bank that has the most number of customers. | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name of the bank branch with the greatest number of customers? | SELECT bname FROM bank ORDER BY no_of_customers DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customer who has the lowest credit score. | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name of the customer with the worst credit score? | SELECT cust_name FROM customer ORDER BY credit_score LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name, account type, and account balance of the customer who has the highest credit score. | SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name, account type, and account balance corresponding to the customer with the highest credit score? | SELECT cust_name , acc_type , acc_bal FROM customer ORDER BY credit_score DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customer who has the highest amount of loans. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name of the customer who has greatest total loan amount? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name ORDER BY sum(T2.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the state which has the most number of customers. | SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Which state has the greatest total number of bank customers? | SELECT state FROM bank GROUP BY state ORDER BY sum(no_of_customers) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | For each account type, find the average account balance of customers with credit score lower than 50. | SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the average account balance of customers with credit score below 50 for the different account types? | SELECT avg(acc_bal) , acc_type FROM customer WHERE credit_score < 50 GROUP BY acc_type | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | For each state, find the total account balance of customers whose credit score is above 100. | SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the total account balance for customers with a credit score of above 100 for the different states? | SELECT sum(acc_bal) , state FROM customer WHERE credit_score > 100 GROUP BY state | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the total amount of loans offered by each bank branch. | SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of the different bank branches, and what are their total loan amounts? | SELECT sum(amount) , T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of customers who have more than one loan. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who have taken out more than one loan? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING count(*) > 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name and account balance of the customers who have loans with a total amount of more than 5000. | SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names and account balances for customers who have taken a total amount of more than 5000 in loans? | SELECT T1.cust_name , T1.acc_type FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id GROUP BY T1.cust_name HAVING sum(T2.amount) > 5000 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of bank branch that provided the greatest total amount of loans. | SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name of the bank branch that has lent the greatest amount? | SELECT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id GROUP BY T1.bname ORDER BY sum(T2.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of bank branch that provided the greatest total amount of loans to customers with credit score is less than 100. | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the name of the bank branch that has lended the largest total amount in loans, specifically to customers with credit scores below 100? | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 GROUP BY T2.bname ORDER BY sum(T1.amount) DESC LIMIT 1 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name of bank branches that provided some loans. | SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of the different banks that have provided loans? | SELECT DISTINCT T1.bname FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the name and credit score of the customers who have some loans. | SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the different names and credit scores of customers who have taken a loan? | SELECT DISTINCT T1.cust_name , T1.credit_score FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the the name of the customers who have a loan with amount more than 3000. | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of customers who have a loan of more than 3000 in amount? | SELECT T1.cust_name FROM customer AS T1 JOIN loan AS T2 ON T1.cust_id = T2.cust_id WHERE amount > 3000 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the city and name of bank branches that provide business loans. | SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = 'Business' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names and cities of bank branches that offer loans for business? | SELECT T1.bname , T1.city FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T2.loan_type = 'Business' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the names of bank branches that have provided a loan to any customer whose credit score is below 100. | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What are the names of banks that have loaned money to customers with credit scores below 100? | SELECT T2.bname FROM loan AS T1 JOIN bank AS T2 ON T1.branch_id = T2.branch_id JOIN customer AS T3 ON T1.cust_id = T3.cust_id WHERE T3.credit_score < 100 | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the total amount of loans provided by bank branches in the state of New York. | SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = 'New York' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the total amount of money loaned by banks in New York state? | SELECT sum(T2.amount) FROM bank AS T1 JOIN loan AS T2 ON T1.branch_id = T2.branch_id WHERE T1.state = 'New York' | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the average credit score of the customers who have some loan. | SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the average credit score for customers who have taken a loan? | SELECT avg(credit_score) FROM customer WHERE cust_id IN (SELECT cust_id FROM loan) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | Find the average credit score of the customers who do not have any loan. | SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
loan_1 | What is the average credit score for customers who have never taken a loan? | SELECT avg(credit_score) FROM customer WHERE cust_id NOT IN (SELECT cust_id FROM loan) | CREATE TABLE bank (
branch_ID int PRIMARY KEY,
bname varchar(20),
no_of_customers int,
city varchar(10),
state varchar(20))
3 rows from bank table:
branch_ID bname no_of_customers city state
1 morningside 203 New York City New York
2 downtown 123 Salt Lake City Utah
3 broadway 453 New York City New York
CREATE TABLE customer (
cust_ID varchar(3) PRIMARY KEY,
cust_name varchar(20),
acc_type char(1),
acc_bal int,
no_of_loans int,
credit_score int,
branch_ID int,
state varchar(20),
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID))
3 rows from customer table:
cust_ID cust_name acc_type acc_bal no_of_loans credit_score branch_ID state
1 Mary saving 2000 2 30 2 Utah
2 Jack checking 1000 1 20 1 Texas
3 Owen saving 800000 0 210 3 New York
CREATE TABLE loan (
loan_ID varchar(3) PRIMARY KEY,
loan_type varchar(15),
cust_ID varchar(3),
branch_ID varchar(3),
amount int,
FOREIGN KEY(branch_ID) REFERENCES bank(branch_ID),
FOREIGN KEY(Cust_ID) REFERENCES customer(Cust_ID))
3 rows from loan table:
loan_ID loan_type cust_ID branch_ID amount
1 Mortgages 1 1 2050
2 Auto 1 2 3000
3 Business 3 3 5000
|
behavior_monitoring | How many assessment notes are there in total? | SELECT count(*) FROM ASSESSMENT_NOTES | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | What are the dates of the assessment notes? | SELECT date_of_notes FROM Assessment_Notes | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | How many addresses have zip code 197? | SELECT count(*) FROM ADDRESSES WHERE zip_postcode = "197" | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | How many distinct incident type codes are there? | SELECT count(DISTINCT incident_type_code) FROM Behavior_Incident | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | Return all distinct detention type codes. | SELECT DISTINCT detention_type_code FROM Detention | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | What are the start and end dates for incidents with incident type code "NOISE"? | SELECT date_incident_start , date_incident_end FROM Behavior_Incident WHERE incident_type_code = "NOISE" | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | Return all detention summaries. | SELECT detention_summary FROM Detention | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | Return the cell phone number and email address for all students. | SELECT cell_mobile_number , email_address FROM STUDENTS | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | What is the email of the student with first name "Emma" and last name "Rohan"? | SELECT email_address FROM Students WHERE first_name = "Emma" AND last_name = "Rohan" | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | How many distinct students have been in detention? | SELECT count(DISTINCT student_id) FROM Students_in_Detention | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | What is the gender of the teacher with last name "Medhurst"? | SELECT gender FROM TEACHERS WHERE last_name = "Medhurst" | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | What is the incident type description for the incident type with code "VIOLENCE"? | SELECT incident_type_description FROM Ref_Incident_Type WHERE incident_type_code = "VIOLENCE" | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | Find the maximum and minimum monthly rental for all student addresses. | SELECT max(monthly_rental) , min(monthly_rental) FROM Student_Addresses | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
|
behavior_monitoring | Find the first names of teachers whose email address contains the word "man". | SELECT first_name FROM Teachers WHERE email_address LIKE '%man%' | CREATE TABLE `Ref_Address_Types` (
`address_type_code` VARCHAR(15) PRIMARY KEY,
`address_type_description` VARCHAR(80)
)
3 rows from Ref_Address_Types table:
address_type_code address_type_description
BILL Billing
HOME Home or Residence
CREATE TABLE `Ref_Detention_Type` (
`detention_type_code` VARCHAR(10) PRIMARY KEY,
`detention_type_description` VARCHAR(80)
)
3 rows from Ref_Detention_Type table:
detention_type_code detention_type_description
BREAK During Break time
AFTER After School
LUNCH Lunch-time
CREATE TABLE `Ref_Incident_Type` (
`incident_type_code` VARCHAR(10) PRIMARY KEY,
`incident_type_description` VARCHAR(80)
)
3 rows from Ref_Incident_Type table:
incident_type_code incident_type_description
NOISE Noise
VIOLENCE Violence
DISTURB Disturbance
CREATE TABLE `Addresses` (
`address_id` INTEGER PRIMARY KEY,
`line_1` VARCHAR(120),
`line_2` VARCHAR(120),
`line_3` VARCHAR(120),
`city` VARCHAR(80),
`zip_postcode` VARCHAR(20),
`state_province_county` VARCHAR(50),
`country` VARCHAR(50),
`other_address_details` VARCHAR(255)
)
3 rows from Addresses table:
address_id line_1 line_2 line_3 city zip_postcode state_province_county country other_address_details
1 020 Orie Canyon None None North Loyceville 197 Hawaii USA None
2 1333 Boyle Lane None None West Sean 937 Illinois USA None
3 027 Kim Divide Apt. 492 None None Beierview 918 Texas USA None
CREATE TABLE `Students` (
`student_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(40),
`last_name` VARCHAR(40),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`date_first_rental` DATETIME,
`date_left_university` DATETIME,
`other_student_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Students table:
student_id address_id first_name middle_name last_name cell_mobile_number email_address date_first_rental date_left_university other_student_details
1 19 Emma Frederic Rohan 235.899.9744 derrick.jenkins@example.com 2017-12-05 15:20:04 2018-03-03 03:33:05 None
2 9 Louvenia Fatima Hansen 1-247-673-8446 rohan.clarabelle@example.org 2017-08-08 22:30:36 2018-02-24 11:12:11 None
3 10 Rhea Gardner Bergnaum 1-751-162-9676x115 kkirlin@example.org 2017-11-15 04:57:28 2018-03-19 12:49:20 None
CREATE TABLE `Teachers` (
`teacher_id` INTEGER PRIMARY KEY,
`address_id` INTEGER NOT NULL,
`first_name` VARCHAR(80),
`middle_name` VARCHAR(80),
`last_name` VARCHAR(80),
`gender` VARCHAR(1),
`cell_mobile_number` VARCHAR(40),
`email_address` VARCHAR(40),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` )
)
3 rows from Teachers table:
teacher_id address_id first_name middle_name last_name gender cell_mobile_number email_address other_details
1 15 Lyla Wilson Medhurst 1 792.333.7714 ohammes@example.com None
2 7 Sid Tremayne Brakus 1 202.626.1698x9242 deborah37@example.com None
3 8 Trystan Alexane Schuster 1 583-467-0403x647 hilll.kitty@example.com None
CREATE TABLE `Assessment_Notes` (
`notes_id` INTEGER NOT NULL ,
`student_id` INTEGER,
`teacher_id` INTEGER NOT NULL,
`date_of_notes` DATETIME,
`text_of_notes` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Assessment_Notes table:
notes_id student_id teacher_id date_of_notes text_of_notes other_details
1 7 3 1978-04-15 04:49:18 None None
2 11 10 2005-06-30 02:48:35 None None
3 15 3 1988-06-09 00:24:01 None None
CREATE TABLE `Behavior_Incident` (
`incident_id` INTEGER PRIMARY KEY,
`incident_type_code` VARCHAR(10) NOT NULL,
`student_id` INTEGER NOT NULL,
`date_incident_start` DATETIME,
`date_incident_end` DATETIME,
`incident_summary` VARCHAR(255),
`recommendations` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`incident_type_code` ) REFERENCES `Ref_Incident_Type`(`incident_type_code` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Behavior_Incident table:
incident_id incident_type_code student_id date_incident_start date_incident_end incident_summary recommendations other_details
1 NOISE 6 2017-07-09 10:04:13 2018-03-08 14:08:54 None None None
2 DISTURB 13 2018-01-31 10:51:13 2018-03-18 18:40:05 None None None
3 VIOLENCE 1 2017-10-10 22:43:54 2018-03-22 02:10:35 None Transfer schools None
CREATE TABLE `Detention` (
`detention_id` INTEGER PRIMARY KEY,
`detention_type_code` VARCHAR(10) NOT NULL,
`teacher_id` INTEGER,
`datetime_detention_start` DATETIME,
`datetime_detention_end` DATETIME,
`detention_summary` VARCHAR(255),
`other_details` VARCHAR(255),
FOREIGN KEY (`detention_type_code` ) REFERENCES `Ref_Detention_Type`(`detention_type_code` ),
FOREIGN KEY (`teacher_id` ) REFERENCES `Teachers`(`teacher_id` )
)
3 rows from Detention table:
detention_id detention_type_code teacher_id datetime_detention_start datetime_detention_end detention_summary other_details
1 AFTER 7 2017-09-05 00:38:25 2018-03-08 02:08:32 None None
2 AFTER 14 2018-01-10 08:09:02 2018-03-07 04:24:48 None None
3 BREAK 11 2017-12-14 06:40:29 2018-03-08 09:16:38 None None
CREATE TABLE `Student_Addresses` (
`student_id` INTEGER NOT NULL,
`address_id` INTEGER NOT NULL,
`date_address_from` DATETIME NOT NULL,
`date_address_to` DATETIME,
`monthly_rental` DECIMAL(19,4),
`other_details` VARCHAR(255),
FOREIGN KEY (`address_id` ) REFERENCES `Addresses`(`address_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Student_Addresses table:
student_id address_id date_address_from date_address_to monthly_rental other_details
6 12 2017-10-16 13:56:34 2018-03-15 10:37:19 826.4319 house
3 18 2017-06-19 12:39:39 2018-03-02 00:19:57 1113.0996 house
8 1 2017-10-31 12:40:34 2018-02-25 05:21:34 1297.3186 apartment
CREATE TABLE `Students_in_Detention` (
`student_id` INTEGER NOT NULL,
`detention_id` INTEGER NOT NULL,
`incident_id` INTEGER NOT NULL,
FOREIGN KEY (`incident_id` ) REFERENCES `Behavior_Incident`(`incident_id` ),
FOREIGN KEY (`detention_id` ) REFERENCES `Detention`(`detention_id` ),
FOREIGN KEY (`student_id` ) REFERENCES `Students`(`student_id` )
)
3 rows from Students_in_Detention table:
student_id detention_id incident_id
3 15 1
8 13 3
11 6 11
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