db_id stringclasses 146 values | question stringlengths 3 224 | sql stringlengths 18 577 | database_schema stringclasses 146 values |
|---|---|---|---|
flight_1 | What are the numbers of the shortest flights? | SELECT flno FROM Flight ORDER BY distance ASC LIMIT 3 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the average distance and average price for flights from Los Angeles. | SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the average distance and price for all flights from LA? | SELECT avg(distance) , avg(price) FROM Flight WHERE origin = "Los Angeles" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show all origins and the number of flights from each origin. | SELECT origin , count(*) FROM Flight GROUP BY origin | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | For each origin, how many flights came from there? | SELECT origin , count(*) FROM Flight GROUP BY origin | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show all destinations and the number of flights to each destination. | SELECT destination , count(*) FROM Flight GROUP BY destination | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the destinations and number of flights to each one? | SELECT destination , count(*) FROM Flight GROUP BY destination | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Which origin has most number of flights? | SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What place has the most flights coming from there? | SELECT origin FROM Flight GROUP BY origin ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Which destination has least number of flights? | SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What destination has the fewest number of flights? | SELECT destination FROM Flight GROUP BY destination ORDER BY count(*) LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the aircraft name for the flight with number 99 | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the name of the aircraft that was on flight number 99? | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T1.flno = 99 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show all flight numbers with aircraft Airbus A340-300. | SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the flight numbers for the aircraft Airbus A340-300? | SELECT T1.flno FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid WHERE T2.name = "Airbus A340-300" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show aircraft names and number of flights for each aircraft. | SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the name of each aircraft and how many flights does each one complete? | SELECT T2.name , count(*) FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show names for all aircraft with at least two flights. | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names for all aircrafts with at least 2 flights? | SELECT T2.name FROM Flight AS T1 JOIN Aircraft AS T2 ON T1.aid = T2.aid GROUP BY T1.aid HAVING count(*) >= 2 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | How many employees have certificate. | SELECT count(DISTINCT eid) FROM Certificate | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the count of distinct employees with certificates? | SELECT count(DISTINCT eid) FROM Certificate | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show ids for all employees who don't have a certificate. | SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the ids of all employees that don't have certificates? | SELECT eid FROM Employee EXCEPT SELECT eid FROM Certificate | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show names for all aircrafts of which John Williams has certificates. | SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names of all aircrafts that John Williams have certificates to be able to fly? | SELECT T3.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T1.name = "John Williams" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show names for all employees who have certificate of Boeing 737-800. | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names of all employees who have a certificate to fly Boeing 737-800? | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show names for all employees who have certificates on both Boeing 737-800 and Airbus A340-300. | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names of all employees who can fly both the Boeing 737-800 and the Airbus A340-300? | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" INTERSECT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Airbus A340-300" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show names for all employees who do not have certificate of Boeing 737-800. | SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names of all employees who are not certified to fly Boeing 737-800s? | SELECT name FROM Employee EXCEPT SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.name = "Boeing 737-800" | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show the name of aircraft which fewest people have its certificate. | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What are the names of the aircraft that the least people are certified to fly? | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid GROUP BY T1.aid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | Show the name and distance of the aircrafts with more than 5000 distance and which at least 5 people have its certificate. | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the name and distance of every aircraft that can cover a distance of more than 5000 and which at least 5 people can fly? | SELECT T2.name FROM Certificate AS T1 JOIN Aircraft AS T2 ON T2.aid = T1.aid WHERE T2.distance > 5000 GROUP BY T1.aid ORDER BY count(*) >= 5 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | what is the salary and name of the employee who has the most number of aircraft certificates? | SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the salaray and name of the employee that is certified to fly the most planes? | SELECT T1.name , T1.salary FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the salary and name of the employee who has the most number of certificates on aircrafts with distance more than 5000? | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
flight_1 | What is the salaray and name of the employee with the most certificates to fly planes more than 5000? | SELECT T1.name FROM Employee AS T1 JOIN Certificate AS T2 ON T1.eid = T2.eid JOIN Aircraft AS T3 ON T3.aid = T2.aid WHERE T3.distance > 5000 GROUP BY T1.eid ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE flight(
flno number(4,0) primary key,
origin varchar2(20),
destination varchar2(20),
distance number(6,0),
departure_date date,
arrival_date date,
price number(7,2),
aid number(9,0),
foreign key("aid") references `aircraft`("aid"))
3 rows from flight table:
flno origin destination distance departure_date arrival_date price aid
99 Los Angeles Washington D.C. 2308 04/12/2005 09:30 04/12/2005 09:40 235.98 1
13 Los Angeles Chicago 1749 04/12/2005 08:45 04/12/2005 08:45 220.98 3
346 Los Angeles Dallas 1251 04/12/2005 11:50 04/12/2005 07:05 182.00 2
CREATE TABLE aircraft(
aid number(9,0) primary key,
name varchar2(30),
distance number(6,0))
3 rows from aircraft table:
aid name distance
1 Boeing 747-400 8430
2 Boeing 737-800 3383
3 Airbus A340-300 7120
CREATE TABLE employee(
eid number(9,0) primary key,
name varchar2(30),
salary number(10,2))
3 rows from employee table:
eid name salary
242518965 James Smith 120433
141582651 Mary Johnson 178345
11564812 John Williams 153972
CREATE TABLE certificate(
eid number(9,0),
aid number(9,0),
primary key(eid,aid),
foreign key("eid") references `employee`("eid"),
foreign key("aid") references `aircraft`("aid"))
3 rows from certificate table:
eid aid
11564812 2
11564812 10
90873519 6
|
allergy_1 | How many allergies are there? | SELECT count(DISTINCT allergy) FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many allergy entries are there? | SELECT count(DISTINCT allergy) FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many different allergy types exist? | SELECT count(DISTINCT allergytype) FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many distinct allergies are there? | SELECT count(DISTINCT allergytype) FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all allergy types. | SELECT DISTINCT allergytype FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the different allergy types? | SELECT DISTINCT allergytype FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all allergies and their types. | SELECT allergy , allergytype FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the allergies and their types? | SELECT allergy , allergytype FROM Allergy_type | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all allergies with type food. | SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are all the different food allergies? | SELECT DISTINCT allergy FROM Allergy_type WHERE allergytype = "food" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is the type of allergy Cat? | SELECT allergytype FROM Allergy_type WHERE allergy = "Cat" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is allergy type of a cat allergy? | SELECT allergytype FROM Allergy_type WHERE allergy = "Cat" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many allergies have type animal? | SELECT count(*) FROM Allergy_type WHERE allergytype = "animal" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many animal type allergies exist? | SELECT count(*) FROM Allergy_type WHERE allergytype = "animal" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all allergy types and the number of allergies in each type. | SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the allergy types and how many allergies correspond to each one? | SELECT allergytype , count(*) FROM Allergy_type GROUP BY allergytype | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which allergy type has most number of allergies? | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which allergy type is most common? | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which allergy type has least number of allergies? | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which allergy type is the least common? | SELECT allergytype FROM Allergy_type GROUP BY allergytype ORDER BY count(*) ASC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students are there? | SELECT count(*) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is the total number of students? | SELECT count(*) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show first name and last name for all students. | SELECT Fname , Lname FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the full names of all students | SELECT Fname , Lname FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many different advisors are listed? | SELECT count(DISTINCT advisor) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many advisors are there? | SELECT count(DISTINCT advisor) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all majors. | SELECT DISTINCT Major FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the different majors? | SELECT DISTINCT Major FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all cities where students live. | SELECT DISTINCT city_code FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What cities do students live in? | SELECT DISTINCT city_code FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show first name, last name, age for all female students. Their sex is F. | SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F' | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the full names and ages for all female students whose sex is F? | SELECT Fname , Lname , Age FROM Student WHERE Sex = 'F' | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show student ids for all male students. | SELECT StuID FROM Student WHERE Sex = 'M' | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the student ids for all male students? | SELECT StuID FROM Student WHERE Sex = 'M' | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students are age 18? | SELECT count(*) FROM Student WHERE age = 18 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students are 18 years old? | SELECT count(*) FROM Student WHERE age = 18 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all student ids who are older than 20. | SELECT StuID FROM Student WHERE age > 20 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the student ids for students over 20 years old? | SELECT StuID FROM Student WHERE age > 20 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which city does the student whose last name is "Kim" live in? | SELECT city_code FROM Student WHERE LName = "Kim" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Give the city that the student whose family name is Kim lives in. | SELECT city_code FROM Student WHERE LName = "Kim" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Who is the advisor of student with ID 1004? | SELECT Advisor FROM Student WHERE StuID = 1004 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Who advises student 1004? | SELECT Advisor FROM Student WHERE StuID = 1004 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students live in HKG or CHI? | SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Give the number of students living in either HKG or CHI. | SELECT count(*) FROM Student WHERE city_code = "HKG" OR city_code = "CHI" | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show the minimum, average, and maximum age of all students. | SELECT min(age) , avg(age) , max(age) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is the minimum, mean, and maximum age across all students? | SELECT min(age) , avg(age) , max(age) FROM Student | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is the last name of the youngest student? | SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student) | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Provide the last name of the youngest student. | SELECT LName FROM Student WHERE age = (SELECT min(age) FROM Student) | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show the student id of the oldest student. | SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student) | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What student id corresponds to the oldest student? | SELECT StuID FROM Student WHERE age = (SELECT max(age) FROM Student) | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all majors and corresponding number of students. | SELECT major , count(*) FROM Student GROUP BY major | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students are there for each major? | SELECT major , count(*) FROM Student GROUP BY major | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Which major has most number of students? | SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What is the largest major? | SELECT major FROM Student GROUP BY major ORDER BY count(*) DESC LIMIT 1 | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all ages and corresponding number of students. | SELECT age , count(*) FROM Student GROUP BY age | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How old is each student and how many students are each age? | SELECT age , count(*) FROM Student GROUP BY age | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show the average age for male and female students. | SELECT avg(age) , sex FROM Student GROUP BY sex | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | What are the average ages for male and female students? | SELECT avg(age) , sex FROM Student GROUP BY sex | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all cities and corresponding number of students. | SELECT city_code , count(*) FROM Student GROUP BY city_code | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | How many students live in each city? | SELECT city_code , count(*) FROM Student GROUP BY city_code | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
allergy_1 | Show all advisors and corresponding number of students. | SELECT advisor , count(*) FROM Student GROUP BY advisor | CREATE TABLE Allergy_Type (
Allergy VARCHAR(20) PRIMARY KEY,
AllergyType VARCHAR(20)
)
3 rows from Allergy_Type table:
Allergy AllergyType
Eggs food
Nuts food
Milk food
CREATE TABLE Has_Allergy (
StuID INTEGER,
Allergy VARCHAR(20),
FOREIGN KEY(StuID) REFERENCES Student(StuID),
FOREIGN KEY(Allergy) REFERENCES Allergy_Type(Allergy)
)
3 rows from Has_Allergy table:
StuID Allergy
1001 Cat
1002 Shellfish
1002 Tree Pollen
CREATE TABLE Student (
StuID INTEGER PRIMARY KEY,
LName VARCHAR(12),
Fname VARCHAR(12),
Age INTEGER,
Sex VARCHAR(1),
Major INTEGER,
Advisor INTEGER,
city_code VARCHAR(3)
)
3 rows from Student table:
StuID LName Fname Age Sex Major Advisor city_code
1001 Smith Linda 18 F 600 1121 BAL
1002 Kim Tracy 19 F 600 7712 HKG
1003 Jones Shiela 21 F 600 7792 WAS
|
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