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of a d they simply make a “backwards 6,” or Ø. (A Ø should have been used |
in the beginning of calculus because we always want to cancel that đ, but we |
never want to cancel a Øl) So they write ØỮ/Øz, and furthermore, in moments oŸ |
duress, if they want to be øerw careful, they put a line beside it with a little z |
--- Trang 281 --- |
at the bottom (ØU/Øz|y;), which means “Take the derivative of U with respect |
to #, keeping and z constant.” Most often we leave out the remark about what |
1s kept constant because it is usually evident from the context, so we usually do |
not use the line with the and z. However, øas use a Ø instead of a d as a |
warning that it is a derivative with some other variables kept constant. 'This is |
called a partial derduatiue; ïW 1s a derivative in which we vary only z. |
Therefore, we find that the force in the z-direction is minus the partial |
derivative of Ư with respect to #: |
t„ = —ØU/Ôz. (14.11) |
In a similar way, the force in the -direction can be found by diferentiating U |
with respect to ø, keeping z and z constant, and the third component, of course, |
is the derivative with respect to z, keeping and z constant: |
tụ = —8U/0, ty = —8U/Ôz. (14.12) |
This 1s the way to get from the potential energy to the force. We get the fcld |
from the po#ential in exactly the same way: |
Œ„ = —8/Ôz, Œy = —Ø9/Ô, Œ, =—8/Ôz. (14.13) |
Incidentally, we shall mention here another notation, which we shall not |
actually use for quite a while: Since Œ is a vector and has z-, -, and z-components, |
the symbolized Ø/Øz, Ø/Øụ, and Ø/9z which produee the ø-, -, and z-components |
are something like vectors. 'Phe mathematicians have invented a glorious new |
symbol, V, called “grad” or “gradient”, which is not a quantity but an operator |
that makes a vector from a scalar. It has the following “components”: 'Phe ø- |
component of this “grad” is Ø/Øz the -component is Ø/Øy, and the z-component |
is Ø/Øz, and then we have the fun of writing our formulas this way: |
t'=_—-YNU, Œ =-VỪ. (14.14) |
Using V gives us a quick way of testing whether we have a real vector equation |
or not, but actually Eqs. (14.14) mean precisely the same as Eqs. (14.11), (14.12) |
and (14.13); it is just another way of writing them, and since we do not want to |
write three equations every time, we just write VŨ instead. |
One more example of fields and potentials has to do with the electrical case. |
In the case of electricity the force on a stationary object is the charge times the |
--- Trang 282 --- |
electric fñeld: ' = g#. (In general, of course, the #-component of foree in an |
electrical problem has also a part which depends on the magnetic field. It is easy |
to show from Eq. (12.11) that the force on a particle due to magnetic fields is |
always at right angles to its velocity, and also at right angles to the ñeld. 5ince |
the force due to magnetism on a moving charge is at right angles to the velocity, |
no t0ork is done by the magnetism on the moving charge because the motion is at |
right angles to the force. Therefore, in calculating theorems of kinetic energy in |
electric and magnetic ñelds we can disregard the contribution tom the magnetic |
fñeld, since it does not change the kinetic energy.) We suppose that there is only |
an electric ñeld. Then we can calculate the energy, or work done, in the same way |
as for gravity, and calculate a quantity ó which is minus the integral of # - ds, |
from the arbitrary ñxed point to the point where we make the calculation, and |
then the potential energy in an electric ñeld is just charge times this quantity ¿: |
ðf)== [ Eds |
U = qọ. |
Let us take, as an example, the case of two parallel metal plates, each with a |
surface charge of +øơ per unit area. 'This is called a parallel-plate capacitor. We |
found previously that there is zero force outside the plates and that there is a |
constant electric field between them, directed from + to — and of magnitude ø/eg |
(Fig. 14-5). We would like to know how much work would be done in carrying a |
charge from one plate 6o the other. The work would be the (force) - (4s) integral, |
which can be written as charge times the potential value at plate 1 minus that at |
plate 2: |
wr= | đ - ds = q(01 — 92). |
W© can actually work out the integral because the force is constant, and 1Ÿ we |
Tin non: |
1/111) ị |
TNnnnnnn" |
Fig. 14-5. Field between parallel plates. |
--- Trang 283 --- |
call the separation of the plates đ, then the integral is easy: |
l E.ds= =mỊ dự = T”, |
1 €0 J1 €0 |
The diference in potential, Aø = ơd/(cọ, is called the 0olfage đifJerence, and ở is |
measured in volts. When we say a pair of plates is charged to a certain voltage, |
what we mean is that the diference in electrical potential of the bwo plates is |
So-and-so many volts. For a capacitor made of two parallel plates carrying a |
surface charge -+ơ, the voltage, or difference in potential, of the pair of plates |
is ơd/eọ. |
--- Trang 284 --- |
Tho Spocrerl Thoorgg of lĩocl(fitftgy |
15-1 The principle of relativity |
For over 200 years the equations of motion enunciated by NÑNewton were believed |
to describe nature correctly, and the fñrst time that an error in these laws was |
discovered, the way to correct it was also discovered. Both the error and its |
correction were discovered by Einstein in 1905. |
Newton?s Second Law, which we have expressed by the equation |
†' = d(mu)/dt, |
was siated with the tacit assumption that ?m is a constant, but we now know |
that this is not true, and that the mass of a body increases with velocity. In |
Binstein”s corrected formula ?m has the value |
m=—————., (15.1) |
v1— 12/c2 |
where the “rest mass” rnọ represents the mass of a body that is not moving and é |
is the speed of light, which is about 3 x 105 km -see~1 or about 186,000 mi - sec—1. |
For those who want to learn just enough about it so they can solve problems, |
that is all there is to the theory of relativity——it just changes Newton's laws by |
introducing a correction factor 6o the mass. From the formula itself it is easy |
to see that this mass increase is very small in ordinary circumstances. Tf the |
velocity 1s even as great as that of a satellite, whiích goes around the earth at |
5 mi/sec, then ø/c = 5/186,000: putting this value into the formula shows that |
the correction to the mass is only one part in two to three billion, which is nearly |
impossible to observe. Actually, the correcbness of the formula has been amply |
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