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≻ y ∈ . (2.15) |
(cid:26)H(M;x) q if M;x / H |
n |
≻ ∈ |
Nowsince boththe inputdataandthe programareencodedusing the same |
alphabet, it is possible to write programs for the universal machine that takes |
programsforotherTuringmachinesasinput. Considerthereforeanewmachine |
D whichisa modificationofthe machineH andwhichtakesthe descriptionM |
as input. It is defined by |
D(M) ⊲ if H(M;M) q |
D(M): ≻ ≻ y (2.16) |
(cid:26)D(M) q if H(M;M) q |
y n |
≻ ≻ |
Under the assumption that H exists, this is a perfectly well defined compu- |
tation. D can be explicitly defined by just adding a small set of instructions to |
H(M;x) directing it to move right forever in the case that H(M;M) accepts |
(which it does eventually by assumption), or directing it to accept if H(M;M) |
accepts (which it also does eventually by assumption). |
Let us spell out the definition of D explicitly. On given input M, D first |
simulates the universalmachine H oninput M;M. Then, in the case where M |
should have entered the accepting configuration q , D, which is reprogrammed |
y |
(as compared to H) to ’loop’, just continues to move forever right along the |
tape. In the case where M should have entered the rejecting configuration q , |
n |
D is reprogrammedto accept. |
ButnowwecanaskhowDbehaveswhenitisrunwithadescriptionofitself |
asinput,i.e. howdoesD(D)behave? ThedefinitionofD(D)immediatelygives |
D(D) ⊲ if H(D;D) q |
D(D): ≻ ≻ y . (2.17) |
(cid:26)D(D) q if H(D;D) q |
y n |
≻ ≻ |
Let us analyze this. Does D(D) halt or not? |
36 |
Suppose it does not halt, i.e. D(D) ⊲. That case occurs when H accepts |
≻ |
the input D;D. But then it follows from the assumption (2.15) about H that |
D;D H. This, in its turn implies D(D) ⊲ using the definition (2.13) of the |
∈ 6≻ |
language H. |
On the other hand, suppose D(D) does halt. That case occurs when H |
doesnotacceptthe input D;D. Butthen itfollowsfromthe assumption(2.15) |
about H that D;D / H. Consequently, D(D) does not halt according to the |
∈ |
definition (2.13) of the language H. |
Both ways, we get a contradiction. The conclusion is that the universal |
machine H deciding H does not exist. |
Note, that this proof hinges on a delicate interplay between the definition |
(2.13) of the halting language H, the assumed properties of the universal ma- |
chine H purported to decide H and the derived properties of the ’diagonal’ |
reprogrammedmachine D. |
2.4 The classical circuit model of computation |
The circuit model of computation is based on the classical logical gates like |
AND, OR and NOT. Since the 70’s these are implemented as physical devices |
intheformofTTLorCMOStechnology. Inamicroprocessortherearemillions |
ofgates,buttheyarealsopackagedincomponentscontainingafewgates,which |
can be wired together on circuit boards using traditional soldering techniques. |
The abstract logical values true,false are represented by voltage levels. In |
{ } |
this section we will review the circuit model as a theoretical model of compu- |
tation, but everything in this model have a physical realizationin terms of real |
world circuits and wires. |
Acircuitismadeupofwiresandgates. Theinputsandoutputsofthegates |
are bits, either represented by true,false or more conveniently by 0,1 . A |
{ } { } |
single gate might have any number of inputs and outputs, though in practice |
the basic building blocks have just a few inputs and outputs. |
A circuit with k inputs and l outputs corresponds to a function |
f : 0,1 k 0,1 l. |
{ } →{ } |
f |
inputs outputs |
Figure 2.1: A general gate. |
Bitsarecarriedfromonegatetoanotherthroughwires. Byconnectinggates |
with wires a circuit is built. No loops or feedback are allowed in the circuit as |
that generally leads to instabilities. Wires can be split into two or more wires, |
37 |
thus duplicating the bit they are carrying.13 All circuits canbe built using just |
one type of logical gate, often chosen to be the 2-input gate NAND. NAND is |
an AND gate followed by a NOT gate. The NAND gate is therefore said to be |
universal for classical(non-reversible)computation. Circuits are often easierto |
constructandunderstandifoneallowsoneselftousealargersetofgates: NOT, |
AND, OR, NAND, XOR. |
The basic circuit elements |
x x x NOT x |
"wire" |
x x |
x AND y x OR y |
y y |
x x |
x XOR y x NAND y |
y y |
Figure 2.2: The basic circuit elements. |
Input/output relations for the basic circuit elements |
The outputs of these gates for different combinationsof inputs are givenby the |
following table. |
x y x AND y x OR y x XOR y x NAND y |
0 0 0 0 0 1 |
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