text stringlengths 0 8.13M |
|---|
z + + z + z |
β β β β |
9This is standard practice in quantum mechanics. It is actually possible to reinstate hΒ― |
in the formulas at a later stage via so called dimensional analysis. Another way to look at |
this isto rescalethe operators, or absorbfactors of βΒ―h. Thisis actually what wedidinthe |
precedingsectionwhendefiningthecreationandannihilationoperators. |
90 |
To understand the action of the operator L , perform the following calcu- |
+ |
lation |
L L l,m = [L ,L ]+L L l,m = |
z + z + + z |
| i | i |
(cid:0) (cid:1) (cid:0) (cid:1) |
L +mL l,m =(m+1)L l,m . |
+ + + |
| i | i |
(cid:0) (cid:1) |
This is a calculation 10 of the L -eigenvalue for the state L l,m and it |
z + |
| i |
shows that as compared to the state l,m , the state L l,m has L l,m |
+ + |
| i | i | i |
eigenvalue m+1, i.e. the eigenvalue is one unit larger. In the same way, it can |
be shown that the state L l,m has L -eigenvalue m 1 as compared to the |
z |
β| i β |
state l,m . For this reason, the operators L and L are called raising and |
+ |
| i β |
lowering operators respectively. It now remains to calculate the spectrum of |
eigenstates for L and L2. |
z |
The intuition is the following. We have a physical system with a certain |
angular momentum, somehow parameterized by the quantum number l. The |
quantum number m corresponds to the z-component. Obviously, if the total |
angular momentum has a finite value, the z-component must also be bounded. |
Evenclassically,no component ofL canbe largerthan L itself. Then, thinking |
of L as an operator that increases z-component of the angular momentum, it |
+ |
makessensetopostulatethe existenceofastatewiththehighestpossiblevalue |
for m, denoted by l,l , that is annihilated by L , or |
+ |
| i |
L l,l =0. (4.71) |
+ |
| i |
Thisequationplaysasimilarroletothatofequation(4.51)fortheharmonic |
oscillatorasprovidingabasecaseforbuildingthespectrumofstates. Thestate |
l,l is called the highest weight state. |
| i |
Actingonthestate l,l withtheloweringoperatorL shouldyieldthestate |
| i β |
l,l 1 , having one unit lowerm-value. It is perhaps tempting then to assume |
| β i |
that L l,l = l,l 1 , but that is wrong. There are normalization factors to |
β| i | β i |
take into account. Instead, a detailed analysis will show |
L l,m =ΞΆ(m)l,m 1 (4.72) |
β| i | β i |
as well as |
L l,m =ΞΆ(m+1)l,m+1 (4.73) |
+ |
| i | i |
with normalization factors ΞΆ(m). These factors have the following form |
ΞΆ(m)= l(l+1) m(m 1). (4.74) |
β β |
p |
Applying L repeatedly, we must at some stage arrive at a state with low- |
β |
est possible value for the L -eigenvalue. A careful analysis shows that this |
z |
lowest weight is m. So for a given l, the spectrum of the operator L is |
z |
β |
l, l+1,...,l 1,l yielding in total 2l+1 states. Now, the eigenvalues of |
{β β β } |
the operator L2 can also be calculated. First rewrite L2 as |
10Notetheuseofthestandardtrick,AB=[A,B]+BA,totakeadvantage ofthecommu- |
tationrelationsforapairofoperators AandB. |
91 |
1 |
L2 = L L +L L +L2, (4.75) |
2 + β β + z |
(cid:0) (cid:1) |
using the definitions (4.68) and (4.69). Calculating the eigenvalues of L2 is |
now a simple matter of applying L2 to a state l,m and using the appropriate |
| i |
equations. The result is |
L2 l,m =l(l+1)l,m , (4.76) |
| i | i |
Thus the eigenvalue of L2 in a state l,m is l(l+1). |
| i |
Derivation of the normalization conditions |
In this section, we will prove that the normalization coefficients has the form |
given by equation (4.74). We will do it in the form of a proof by induction. To |
simplify, we will assume them to be real, i.e. ΞΆ = ΞΆ. This is in fact a choice |
β |
that is always possible to make. |
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