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HumanEval/0
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ...
for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: distance = abs(elem - elem2) if distance < threshold: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True assert candidate([1.0, 2.0, 5.9, 4.0,...
has_close_elements
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, ...
HumanEval/1
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace...
result = [] current_string = [] current_depth = 0 for c in paren_string: if c == '(': current_depth += 1 current_string.append(c) elif c == ')': current_depth -= 1 current_string.append(c) if current_depth == 0: ...
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('(()()) ((())) () ((())()())') == [ '(()())', '((()))', '()', '((())()())' ] assert candidate('() (()) ((())) (((())))') == [ '()', '(())', '((()))', '(((())))' ] assert candidate('(()...
separate_paren_groups
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace...
HumanEval/10
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string...
if not string: return '' beginning_of_suffix = 0 while not is_palindrome(string[beginning_of_suffix:]): beginning_of_suffix += 1 return string + string[:beginning_of_suffix][::-1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('x') == 'x' assert candidate('xyz') == 'xyzyx' assert candidate('xyx') == 'xyx' assert candidate('jerry') == 'jerryrrej'
make_palindrome
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string...
HumanEval/100
def make_a_pile(n): """ Given a positive integer n, you have to make a pile of n levels of stones. The first level has n stones. The number of stones in the next level is: - the next odd number if n is odd. - the next even number if n is even. Return the number of stones in each lev...
return [n + 2*i for i in range(n)]
def check(candidate): # Check some simple cases assert candidate(3) == [3, 5, 7], "Test 3" assert candidate(4) == [4,6,8,10], "Test 4" assert candidate(5) == [5, 7, 9, 11, 13] assert candidate(6) == [6, 8, 10, 12, 14, 16] assert candidate(8) == [8, 10, 12, 14, 16, 18, 20, 22] # Check some ...
make_a_pile
def make_a_pile(n): """ Given a positive integer n, you have to make a pile of n levels of stones. The first level has n stones. The number of stones in the next level is: - the next odd number if n is odd. - the next even number if n is even. Return the number of stones in each lev...
HumanEval/101
def words_string(s): """ You will be given a string of words separated by commas or spaces. Your task is to split the string into words and return an array of the words. For example: words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] words_string("One, two, three, fo...
if not s: return [] s_list = [] for letter in s: if letter == ',': s_list.append(' ') else: s_list.append(letter) s_list = "".join(s_list) return s_list.split()
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] assert candidate("One, two, three, four, five, six") == ["One", "two", "three", "four", "five", "six"] ...
words_string
def words_string(s): """ You will be given a string of words separated by commas or spaces. Your task is to split the string into words and return an array of the words. For example: words_string("Hi, my name is John") == ["Hi", "my", "name", "is", "John"] words_string("One, two, three, fo...
HumanEval/102
def choose_num(x, y): """This function takes two positive numbers x and y and returns the biggest even integer number that is in the range [x, y] inclusive. If there's no such number, then the function should return -1. For example: choose_num(12, 15) = 14 choose_num(13, 12) = -1 """
if x > y: return -1 if y % 2 == 0: return y if x == y: return -1 return y - 1
def check(candidate): # Check some simple cases assert candidate(12, 15) == 14 assert candidate(13, 12) == -1 assert candidate(33, 12354) == 12354 assert candidate(5234, 5233) == -1 assert candidate(6, 29) == 28 assert candidate(27, 10) == -1 # Check some edge cases that are easy to wo...
choose_num
def choose_num(x, y): """This function takes two positive numbers x and y and returns the biggest even integer number that is in the range [x, y] inclusive. If there's no such number, then the function should return -1. For example: choose_num(12, 15) = 14 choose_num(13, 12) = -1 """ ...
HumanEval/103
def rounded_avg(n, m): """You are given two positive integers n and m, and your task is to compute the average of the integers from n through m (including n and m). Round the answer to the nearest integer and convert that to binary. If n is greater than m, return -1. Example: rounded_avg(1, 5)...
if m < n: return -1 summation = 0 for i in range(n, m+1): summation += i return bin(round(summation/(m - n + 1)))
def check(candidate): # Check some simple cases assert candidate(1, 5) == "0b11" assert candidate(7, 13) == "0b1010" assert candidate(964,977) == "0b1111001010" assert candidate(996,997) == "0b1111100100" assert candidate(560,851) == "0b1011000010" assert candidate(185,546) == "0b101101110"...
rounded_avg
def rounded_avg(n, m): """You are given two positive integers n and m, and your task is to compute the average of the integers from n through m (including n and m). Round the answer to the nearest integer and convert that to binary. If n is greater than m, return -1. Example: rounded_avg(1, 5)...
HumanEval/104
def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10...
odd_digit_elements = [] for i in x: if all (int(c) % 2 == 1 for c in str(i)): odd_digit_elements.append(i) return sorted(odd_digit_elements)
def check(candidate): # Check some simple cases assert candidate([15, 33, 1422, 1]) == [1, 15, 33] assert candidate([152, 323, 1422, 10]) == [] assert candidate([12345, 2033, 111, 151]) == [111, 151] assert candidate([135, 103, 31]) == [31, 135] # Check some edge cases that are easy to work ou...
unique_digits
def unique_digits(x): """Given a list of positive integers x. return a sorted list of all elements that hasn't any even digit. Note: Returned list should be sorted in increasing order. For example: >>> unique_digits([15, 33, 1422, 1]) [1, 15, 33] >>> unique_digits([152, 323, 1422, 10...
HumanEval/105
def by_length(arr): """ Given an array of integers, sort the integers that are between 1 and 9 inclusive, reverse the resulting array, and then replace each digit by its corresponding name from "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". For example: arr = [2, 1, ...
dic = { 1: "One", 2: "Two", 3: "Three", 4: "Four", 5: "Five", 6: "Six", 7: "Seven", 8: "Eight", 9: "Nine", } sorted_arr = sorted(arr, reverse=True) new_arr = [] for var in sorted_arr: try: new_arr.append(dic[...
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([2, 1, 1, 4, 5, 8, 2, 3]) == ["Eight", "Five", "Four", "Three", "Two", "Two", "One", "One"], "Error" assert candidate([]) == [], "Error" assert candidate([1, -1 ,...
by_length
def by_length(arr): """ Given an array of integers, sort the integers that are between 1 and 9 inclusive, reverse the resulting array, and then replace each digit by its corresponding name from "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine". For example: arr = [2, 1, ...
HumanEval/106
def f(n): """ Implement the function f that takes n as a parameter, and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even or the sum of numbers from 1 to i otherwise. i starts from 1. the factorial of i is the multiplication of the numbers fr...
ret = [] for i in range(1,n+1): if i%2 == 0: x = 1 for j in range(1,i+1): x *= j ret += [x] else: x = 0 for j in range(1,i+1): x += j ret += [x] return ret
def check(candidate): assert candidate(5) == [1, 2, 6, 24, 15] assert candidate(7) == [1, 2, 6, 24, 15, 720, 28] assert candidate(1) == [1] assert candidate(3) == [1, 2, 6]
f
def f(n): """ Implement the function f that takes n as a parameter, and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even or the sum of numbers from 1 to i otherwise. i starts from 1. the factorial of i is the multiplication of the numbers fr...
HumanEval/107
def even_odd_palindrome(n): """ Given a positive integer n, return a tuple that has the number of even and odd integer palindromes that fall within the range(1, n), inclusive. Example 1: Input: 3 Output: (1, 2) Explanation: Integer palindrome are 1, 2, 3. one of them i...
def is_palindrome(n): return str(n) == str(n)[::-1] even_palindrome_count = 0 odd_palindrome_count = 0 for i in range(1, n+1): if i%2 == 1 and is_palindrome(i): odd_palindrome_count += 1 elif i%2 == 0 and is_palindrome(i): even_palindrome_count += 1 ...
def check(candidate): # Check some simple cases assert candidate(123) == (8, 13) assert candidate(12) == (4, 6) assert candidate(3) == (1, 2) assert candidate(63) == (6, 8) assert candidate(25) == (5, 6) assert candidate(19) == (4, 6) assert candidate(9) == (4, 5), "This prints if this ...
even_odd_palindrome
def even_odd_palindrome(n): """ Given a positive integer n, return a tuple that has the number of even and odd integer palindromes that fall within the range(1, n), inclusive. Example 1: Input: 3 Output: (1, 2) Explanation: Integer palindrome are 1, 2, 3. one of them i...
HumanEval/108
def count_nums(arr): """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) == 0 >>...
def digits_sum(n): neg = 1 if n < 0: n, neg = -1 * n, -1 n = [int(i) for i in str(n)] n[0] = n[0] * neg return sum(n) return len(list(filter(lambda x: x > 0, [digits_sum(i) for i in arr])))
def check(candidate): # Check some simple cases assert candidate([]) == 0 assert candidate([-1, -2, 0]) == 0 assert candidate([1, 1, 2, -2, 3, 4, 5]) == 6 assert candidate([1, 6, 9, -6, 0, 1, 5]) == 5 assert candidate([1, 100, 98, -7, 1, -1]) == 4 assert candidate([12, 23, 34, -45, -56, 0])...
count_nums
def count_nums(arr): """ Write a function count_nums which takes an array of integers and returns the number of elements which has a sum of digits > 0. If a number is negative, then its first signed digit will be negative: e.g. -123 has signed digits -1, 2, and 3. >>> count_nums([]) == 0 >>...
HumanEval/109
def move_one_ball(arr): """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: Yo...
if len(arr)==0: return True sorted_array=sorted(arr) my_arr=[] min_value=min(arr) min_index=arr.index(min_value) my_arr=arr[min_index:]+arr[0:min_index] for i in range(len(arr)): if my_arr[i]!=sorted_array[i]: return False return True
def check(candidate): # Check some simple cases assert candidate([3, 4, 5, 1, 2])==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([3, 5, 10, 1, 2])==True assert candidate([4, 3, 1, 2])==False # Check some edge cases that are easy to work out by hand. assert ca...
move_one_ball
def move_one_ball(arr): """We have an array 'arr' of N integers arr[1], arr[2], ..., arr[N].The numbers in the array will be randomly ordered. Your task is to determine if it is possible to get an array sorted in non-decreasing order by performing the following operation on the given array: Yo...
HumanEval/11
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """
def xor(i, j): if i == j: return '0' else: return '1' return ''.join(xor(x, y) for x, y in zip(a, b))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('111000', '101010') == '010010' assert candidate('1', '1') == '0' assert candidate('0101', '0000') == '0101'
string_xor
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """ def xor(i, j): if i == j: return '0...
HumanEval/110
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1...
odd = 0 even = 0 for i in lst1: if i%2 == 1: odd += 1 for i in lst2: if i%2 == 0: even += 1 if even >= odd: return "YES" return "NO"
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4], [1, 2, 3, 4]) == "YES" assert candidate([1, 2, 3, 4], [1, 5, 3, 4]) == "NO" assert candidate([1, 2, 3, 4], [2, 1, 4, 3]) == "YES" assert candidate([5, 7, 3], [2, 6, 4]) == "YES" assert candidate([5, 7, 3], [2, 6, 3]...
exchange
def exchange(lst1, lst2): """In this problem, you will implement a function that takes two lists of numbers, and determines whether it is possible to perform an exchange of elements between them to make lst1 a list of only even numbers. There is no limit on the number of exchanged elements between lst1...
HumanEval/111
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. Example: histogram('a b c') == {'a': 1, '...
dict1={} list1=test.split(" ") t=0 for i in list1: if(list1.count(i)>t) and i!='': t=list1.count(i) if t>0: for i in list1: if(list1.count(i)==t): dict1[i]=t return dict1
def check(candidate): # Check some simple cases assert candidate('a b b a') == {'a':2,'b': 2}, "This prints if this assert fails 1 (good for debugging!)" assert candidate('a b c a b') == {'a': 2, 'b': 2}, "This prints if this assert fails 2 (good for debugging!)" assert candidate('a b c d g') == {'a': ...
histogram
def histogram(test): """Given a string representing a space separated lowercase letters, return a dictionary of the letter with the most repetition and containing the corresponding count. If several letters have the same occurrence, return all of them. Example: histogram('a b c') == {'a': 1, '...
HumanEval/112
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple contai...
s = ''.join([char for char in s if char not in c]) return (s,s[::-1] == s)
def check(candidate): assert candidate("abcde","ae") == ('bcd',False) assert candidate("abcdef", "b") == ('acdef',False) assert candidate("abcdedcba","ab") == ('cdedc',True) assert candidate("dwik","w") == ('dik',False) assert candidate("a","a") == ('',True) assert candidate("abcdedcba","") == ...
reverse_delete
def reverse_delete(s,c): """Task We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c then check if the result string is palindrome. A string is called palindrome if it reads the same backward as forward. You should return a tuple contai...
HumanEval/113
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. ...
res = [] for arr in lst: n = sum(int(d)%2==1 for d in arr) res.append("the number of odd elements " + str(n) + "n the str"+ str(n) +"ng "+ str(n) +" of the "+ str(n) +"nput.") return res
def check(candidate): # Check some simple cases assert candidate(['1234567']) == ["the number of odd elements 4n the str4ng 4 of the 4nput."], "Test 1" assert candidate(['3',"11111111"]) == ["the number of odd elements 1n the str1ng 1 of the 1nput.", "the number of odd elements 8n the str8ng 8 of the 8nput...
odd_count
def odd_count(lst): """Given a list of strings, where each string consists of only digits, return a list. Each element i of the output should be "the number of odd elements in the string i of the input." where all the i's should be replaced by the number of odd digits in the i'th string of the input. ...
HumanEval/114
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. Example minSubArraySum([2, 3, 4, 1, 2, 4]) == 1 minSubArraySum([-1, -2, -3]) == -6 """
max_sum = 0 s = 0 for num in nums: s += -num if (s < 0): s = 0 max_sum = max(s, max_sum) if max_sum == 0: max_sum = max(-i for i in nums) min_sum = -max_sum return min_sum
def check(candidate): # Check some simple cases assert candidate([2, 3, 4, 1, 2, 4]) == 1, "This prints if this assert fails 1 (good for debugging!)" assert candidate([-1, -2, -3]) == -6 assert candidate([-1, -2, -3, 2, -10]) == -14 assert candidate([-9999999999999999]) == -9999999999999999 ass...
minSubArraySum
def minSubArraySum(nums): """ Given an array of integers nums, find the minimum sum of any non-empty sub-array of nums. Example minSubArraySum([2, 3, 4, 1, 2, 4]) == 1 minSubArraySum([-1, -2, -3]) == -6 """ max_sum = 0 s = 0 for num in nums: s += -num if (s < 0...
HumanEval/115
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capac...
return sum([math.ceil(sum(arr)/capacity) for arr in grid])
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([[0,0,1,0], [0,1,0,0], [1,1,1,1]], 1) == 6, "Error" assert candidate([[0,0,1,1], [0,0,0,0], [1,1,1,1], [0,1,1,1]], 2) == 5, "Error" assert candidate([[0,0,0], [0...
max_fill
def max_fill(grid, capacity): import math """ You are given a rectangular grid of wells. Each row represents a single well, and each 1 in a row represents a single unit of water. Each well has a corresponding bucket that can be used to extract water from it, and all buckets have the same capac...
HumanEval/116
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. It must be implemented like this: >>> sort_array([1, 5, 2, 3, 4]) ==...
return sorted(sorted(arr), key=lambda x: bin(x)[2:].count('1'))
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1,5,2,3,4]) == [1, 2, 4, 3, 5] assert candidate([-2,-3,-4,-5,-6]) == [-4, -2, -6, -5, -3] assert candidate([1,0,2,3,4]) == [0, 1, 2, 4, 3] assert candidate([...
sort_array
def sort_array(arr): """ In this Kata, you have to sort an array of non-negative integers according to number of ones in their binary representation in ascending order. For similar number of ones, sort based on decimal value. It must be implemented like this: >>> sort_array([1, 5, 2, 3, 4]) ==...
HumanEval/117
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an e...
result = [] for word in s.split(): n_consonants = 0 for i in range(0, len(word)): if word[i].lower() not in ["a","e","i","o","u"]: n_consonants += 1 if n_consonants == n: result.append(word) return result
def check(candidate): # Check some simple cases assert candidate("Mary had a little lamb", 4) == ["little"], "First test error: " + str(candidate("Mary had a little lamb", 4)) assert candidate("Mary had a little lamb", 3) == ["Mary", "lamb"], "Second test error: " + str(candidate("Mary had a little l...
select_words
def select_words(s, n): """Given a string s and a natural number n, you have been tasked to implement a function that returns a list of all words from string s that contain exactly n consonants, in order these words appear in the string s. If the string s is empty then the function should return an e...
HumanEval/118
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condit...
if len(word) < 3: return "" vowels = {"a", "e", "i", "o", "u", "A", "E", 'O', 'U', 'I'} for i in range(len(word)-2, 0, -1): if word[i] in vowels: if (word[i+1] not in vowels) and (word[i-1] not in vowels): return word[i] return ""
def check(candidate): # Check some simple cases assert candidate("yogurt") == "u" assert candidate("full") == "u" assert candidate("easy") == "" assert candidate("eAsy") == "" assert candidate("ali") == "" assert candidate("bad") == "a" assert candidate("most") == "o" assert candida...
get_closest_vowel
def get_closest_vowel(word): """You are given a word. Your task is to find the closest vowel that stands between two consonants from the right side of the word (case sensitive). Vowels in the beginning and ending doesn't count. Return empty string if you didn't find any vowel met the above condit...
HumanEval/119
def match_parens(lst): ''' You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be...
def check(s): val = 0 for i in s: if i == '(': val = val + 1 else: val = val - 1 if val < 0: return False return True if val == 0 else False S1 = lst[0] + lst[1] S2 = lst[1] + lst[0] return 'Yes'...
def check(candidate): # Check some simple cases assert candidate(['()(', ')']) == 'Yes' assert candidate([')', ')']) == 'No' assert candidate(['(()(())', '())())']) == 'No' assert candidate([')())', '(()()(']) == 'Yes' assert candidate(['(())))', '(()())((']) == 'Yes' assert candidate(['()'...
match_parens
def match_parens(lst): ''' You are given a list of two strings, both strings consist of open parentheses '(' or close parentheses ')' only. Your job is to check if it is possible to concatenate the two strings in some order, that the resulting string will be good. A string S is considered to be...
HumanEval/12
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a...
if not strings: return None maxlen = max(len(x) for x in strings) for s in strings: if len(s) == maxlen: return s
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == None assert candidate(['x', 'y', 'z']) == 'x' assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
longest
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a...
HumanEval/120
def maximum(arr, k): """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: Input: arr = [-3, -4, 5], k = 3 Output: [-4, -3, 5] Example 2: Input: arr = [4, -4, 4], k = 2 Output:...
if k == 0: return [] arr.sort() ans = arr[-k:] return ans
def check(candidate): # Check some simple cases assert candidate([-3, -4, 5], 3) == [-4, -3, 5] assert candidate([4, -4, 4], 2) == [4, 4] assert candidate([-3, 2, 1, 2, -1, -2, 1], 1) == [2] assert candidate([123, -123, 20, 0 , 1, 2, -3], 3) == [2, 20, 123] assert candidate([-123, 20, 0 , 1, 2,...
maximum
def maximum(arr, k): """ Given an array arr of integers and a positive integer k, return a sorted list of length k with the maximum k numbers in arr. Example 1: Input: arr = [-3, -4, 5], k = 3 Output: [-4, -3, 5] Example 2: Input: arr = [4, -4, 4], k = 2 Output:...
HumanEval/121
def solution(lst): """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions. Examples solution([5, 8, 7, 1]) ==> 12 solution([3, 3, 3, 3, 3]) ==> 9 solution([30, 13, 24, 321]) ==>0 """
return sum([x for idx, x in enumerate(lst) if idx%2==0 and x%2==1])
def check(candidate): # Check some simple cases assert candidate([5, 8, 7, 1]) == 12 assert candidate([3, 3, 3, 3, 3]) == 9 assert candidate([30, 13, 24, 321]) == 0 assert candidate([5, 9]) == 5 assert candidate([2, 4, 8]) == 0 assert candidate([30, 13, 23, 32]) == 23 assert candidat...
solution
def solution(lst): """Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions. Examples solution([5, 8, 7, 1]) ==> 12 solution([3, 3, 3, 3, 3]) ==> 9 solution([30, 13, 24, 321]) ==>0 """ return sum([x for idx, x in enumerate(lst) if i...
HumanEval/122
def add_elements(arr, k): """ Given a non-empty array of integers arr and an integer k, return the sum of the elements with at most two digits from the first k elements of arr. Example: Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4 Output: 24 # sum of 21 + 3 Constraints: ...
return sum(elem for elem in arr[:k] if len(str(elem)) <= 2)
def check(candidate): # Check some simple cases assert candidate([1,-2,-3,41,57,76,87,88,99], 3) == -4 assert candidate([111,121,3,4000,5,6], 2) == 0 assert candidate([11,21,3,90,5,6,7,8,9], 4) == 125 assert candidate([111,21,3,4000,5,6,7,8,9], 4) == 24, "This prints if this assert fails 1 (good fo...
add_elements
def add_elements(arr, k): """ Given a non-empty array of integers arr and an integer k, return the sum of the elements with at most two digits from the first k elements of arr. Example: Input: arr = [111,21,3,4000,5,6,7,8,9], k = 4 Output: 24 # sum of 21 + 3 Constraints: ...
HumanEval/123
def get_odd_collatz(n): """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the prev...
if n%2==0: odd_collatz = [] else: odd_collatz = [n] while n > 1: if n % 2 == 0: n = n/2 else: n = n*3 + 1 if n%2 == 1: odd_collatz.append(int(n)) return sorted(odd_collatz)
def check(candidate): # Check some simple cases assert candidate(14) == [1, 5, 7, 11, 13, 17] assert candidate(5) == [1, 5] assert candidate(12) == [1, 3, 5], "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(...
get_odd_collatz
def get_odd_collatz(n): """ Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence. The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined as follows: start with any positive integer n. Then each term is obtained from the prev...
HumanEval/124
def valid_date(date): """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31...
try: date = date.strip() month, day, year = date.split('-') month, day, year = int(month), int(day), int(year) if month < 1 or month > 12: return False if month in [1,3,5,7,8,10,12] and day < 1 or day > 31: return False if month in [4,6,9,11] a...
def check(candidate): # Check some simple cases assert candidate('03-11-2000') == True assert candidate('15-01-2012') == False assert candidate('04-0-2040') == False assert candidate('06-04-2020') == True assert candidate('01-01-2007') == True assert candidate('03-32-2011') == False ...
valid_date
def valid_date(date): """You have to write a function which validates a given date string and returns True if the date is valid otherwise False. The date is valid if all of the following rules are satisfied: 1. The date string is not empty. 2. The number of days is not less than 1 or higher than 31...
HumanEval/125
def split_words(txt): ''' Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('...
if " " in txt: return txt.split() elif "," in txt: return txt.replace(',',' ').split() else: return len([i for i in txt if i.islower() and ord(i)%2 == 0])
def check(candidate): assert candidate("Hello world!") == ["Hello","world!"] assert candidate("Hello,world!") == ["Hello","world!"] assert candidate("Hello world,!") == ["Hello","world,!"] assert candidate("Hello,Hello,world !") == ["Hello,Hello,world","!"] assert candidate("abcdef") == 3 asser...
split_words
def split_words(txt): ''' Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the alphabet, ord('a') = 0, ord('b') = 1, ... ord('...
HumanEval/126
def is_sorted(lst): ''' Given a list of numbers, return whether or not they are sorted in ascending order. If list has more than 1 duplicate of the same number, return False. Assume no negative numbers and only integers. Examples is_sorted([5]) ➞ True is_sorted([1, 2, 3, 4, 5]) ➞ True ...
count_digit = dict([(i, 0) for i in lst]) for i in lst: count_digit[i]+=1 if any(count_digit[i] > 2 for i in lst): return False if all(lst[i-1] <= lst[i] for i in range(1, len(lst))): return True else: return False
def check(candidate): # Check some simple cases assert candidate([5]) == True assert candidate([1, 2, 3, 4, 5]) == True assert candidate([1, 3, 2, 4, 5]) == False assert candidate([1, 2, 3, 4, 5, 6]) == True assert candidate([1, 2, 3, 4, 5, 6, 7]) == True assert candidate([1, 3, 2, 4, 5, 6,...
is_sorted
def is_sorted(lst): ''' Given a list of numbers, return whether or not they are sorted in ascending order. If list has more than 1 duplicate of the same number, return False. Assume no negative numbers and only integers. Examples is_sorted([5]) ➞ True is_sorted([1, 2, 3, 4, 5]) ➞ True ...
HumanEval/127
def intersection(interval1, interval2): """You are given two intervals, where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). The given intervals are closed which means that the interval (start, end) includes both start and end. For each given interval, it is ass...
def is_prime(num): if num == 1 or num == 0: return False if num == 2: return True for i in range(2, num): if num%i == 0: return False return True l = max(interval1[0], interval2[0]) r = min(interval1[1], interval2[1]) l...
def check(candidate): # Check some simple cases assert candidate((1, 2), (2, 3)) == "NO" assert candidate((-1, 1), (0, 4)) == "NO" assert candidate((-3, -1), (-5, 5)) == "YES" assert candidate((-2, 2), (-4, 0)) == "YES" # Check some edge cases that are easy to work out by hand. assert cand...
intersection
def intersection(interval1, interval2): """You are given two intervals, where each interval is a pair of integers. For example, interval = (start, end) = (1, 2). The given intervals are closed which means that the interval (start, end) includes both start and end. For each given interval, it is ass...
HumanEval/128
def prod_signs(arr): """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty arr. Example: >>> prod_signs([1, 2, 2, -4]) == -9 ...
if not arr: return None prod = 0 if 0 in arr else (-1) ** len(list(filter(lambda x: x < 0, arr))) return prod * sum([abs(i) for i in arr])
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1, 2, 2, -4]) == -9 assert candidate([0, 1]) == 0 assert candidate([1, 1, 1, 2, 3, -1, 1]) == -10 assert candidate([]) == None assert candidate([2, 4,1, ...
prod_signs
def prod_signs(arr): """ You are given an array arr of integers and you need to return sum of magnitudes of integers multiplied by product of all signs of each number in the array, represented by 1, -1 or 0. Note: return None for empty arr. Example: >>> prod_signs([1, 2, 2, -4]) == -9 ...
HumanEval/129
def minPath(grid, k): """ Given a grid with N rows and N columns (N >= 2) and a positive integer k, each cell of the grid contains a value. Every integer in the range [1, N * N] inclusive appears exactly once on the cells of the grid. You have to find the minimum path of length k in the grid. You...
n = len(grid) val = n * n + 1 for i in range(n): for j in range(n): if grid[i][j] == 1: temp = [] if i != 0: temp.append(grid[i - 1][j]) if j != 0: temp.append(grid[i][j - 1]) if i !...
def check(candidate): # Check some simple cases print assert candidate([[1, 2, 3], [4, 5, 6], [7, 8, 9]], 3) == [1, 2, 1] assert candidate([[5, 9, 3], [4, 1, 6], [7, 8, 2]], 1) == [1] assert candidate([[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]], 4) == [1, 2, 1, 2] assert can...
minPath
def minPath(grid, k): """ Given a grid with N rows and N columns (N >= 2) and a positive integer k, each cell of the grid contains a value. Every integer in the range [1, N * N] inclusive appears exactly once on the cells of the grid. You have to find the minimum path of length k in the grid. You...
HumanEval/13
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """
while b: a, b = b, a % b return a
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3, 7) == 1 assert candidate(10, 15) == 5 assert candidate(49, 14) == 7 assert candidate(144, 60) == 12
greatest_common_divisor
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """ while b: a, b = b, a % b return a
HumanEval/130
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + ...
if n == 0: return [1] my_tri = [1, 3] for i in range(2, n + 1): if i % 2 == 0: my_tri.append(i / 2 + 1) else: my_tri.append(my_tri[i - 1] + my_tri[i - 2] + (i + 3) / 2) return my_tri
def check(candidate): # Check some simple cases assert candidate(3) == [1, 3, 2.0, 8.0] assert candidate(4) == [1, 3, 2.0, 8.0, 3.0] assert candidate(5) == [1, 3, 2.0, 8.0, 3.0, 15.0] assert candidate(6) == [1, 3, 2.0, 8.0, 3.0, 15.0, 4.0] assert candidate(7) == [1, 3, 2.0, 8.0, 3.0, 15.0,...
tri
def tri(n): """Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in the last couple centuries. However, what people don't know is Tribonacci sequence. Tribonacci sequence is defined by the recurrence: tri(1) = 3 tri(n) = 1 + n / 2, if n is even. tri(n) = tri(n - 1) + ...
HumanEval/131
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. For example: digits(1) == 1 digits(4) == 0 digits(235) == 15 """
product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_digit%2 == 1: product= product*int_digit odd_count+=1 if odd_count ==0: return 0 else: return product
def check(candidate): # Check some simple cases assert candidate(5) == 5 assert candidate(54) == 5 assert candidate(120) ==1 assert candidate(5014) == 5 assert candidate(98765) == 315 assert candidate(5576543) == 2625 # Check some edge cases that are easy to work out by hand. asser...
digits
def digits(n): """Given a positive integer n, return the product of the odd digits. Return 0 if all digits are even. For example: digits(1) == 1 digits(4) == 0 digits(235) == 15 """ product = 1 odd_count = 0 for digit in str(n): int_digit = int(digit) if int_...
HumanEval/132
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
opening_bracket_index = [] closing_bracket_index = [] for i in range(len(string)): if string[i] == '[': opening_bracket_index.append(i) else: closing_bracket_index.append(i) closing_bracket_index.reverse() cnt = 0 i = 0 l = len(closing_bracket_index) ...
def check(candidate): # Check some simple cases assert candidate('[[]]') == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate('[]]]]]]][[[[[]') == False assert candidate('[][]') == False assert candidate(('[]')) == False assert candidate('[[[[]]]]') == True a...
is_nested
def is_nested(string): ''' Create a function that takes a string as input which contains only square brackets. The function should return True if and only if there is a valid subsequence of brackets where at least one bracket in the subsequence is nested. is_nested('[[]]') ➞ True is_nested('[...
HumanEval/133
def sum_squares(lst): """You are given a list of numbers. You need to return the sum of squared numbers in the given list, round each element in the list to the upper int(Ceiling) first. Examples: For lst = [1,2,3] the output should be 14 For lst = [1,4,9] the output should be 98 For lst =...
import math squared = 0 for i in lst: squared += math.ceil(i)**2 return squared
def check(candidate): # Check some simple cases assert candidate([1,2,3])==14, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1.0,2,3])==14, "This prints if this assert fails 1 (good for debugging!)" assert candidate([1,3,5,7])==84, "This prints if this assert fails 1 (goo...
sum_squares
def sum_squares(lst): """You are given a list of numbers. You need to return the sum of squared numbers in the given list, round each element in the list to the upper int(Ceiling) first. Examples: For lst = [1,2,3] the output should be 14 For lst = [1,4,9] the output should be 98 For lst =...
HumanEval/134
def check_if_last_char_is_a_letter(txt): ''' Create a function that returns True if the last character of a given string is an alphabetical character and is not a part of a word, and False otherwise. Note: "word" is a group of characters separated by space. Examples: check_if_last_char_is_...
check = txt.split(' ')[-1] return True if len(check) == 1 and (97 <= ord(check.lower()) <= 122) else False
def check(candidate): # Check some simple cases assert candidate("apple") == False assert candidate("apple pi e") == True assert candidate("eeeee") == False assert candidate("A") == True assert candidate("Pumpkin pie ") == False assert candidate("Pumpkin pie 1") == False assert candidat...
check_if_last_char_is_a_letter
def check_if_last_char_is_a_letter(txt): ''' Create a function that returns True if the last character of a given string is an alphabetical character and is not a part of a word, and False otherwise. Note: "word" is a group of characters separated by space. Examples: check_if_last_char_is_...
HumanEval/135
def can_arrange(arr): """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: can_arrange([1,2,4,3,5]) =...
ind=-1 i=1 while i<len(arr): if arr[i]<arr[i-1]: ind=i i+=1 return ind
def check(candidate): # Check some simple cases assert candidate([1,2,4,3,5])==3 assert candidate([1,2,4,5])==-1 assert candidate([1,4,2,5,6,7,8,9,10])==2 assert candidate([4,8,5,7,3])==4 # Check some edge cases that are easy to work out by hand. assert candidate([])==-1
can_arrange
def can_arrange(arr): """Create a function which returns the largest index of an element which is not greater than or equal to the element immediately preceding it. If no such element exists then return -1. The given array will not contain duplicate values. Examples: can_arrange([1,2,4,3,5]) =...
HumanEval/136
def largest_smallest_integers(lst): ''' Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no negative or positive integers, return them as None. Examples: largest_smallest_intege...
smallest = list(filter(lambda x: x < 0, lst)) largest = list(filter(lambda x: x > 0, lst)) return (max(smallest) if smallest else None, min(largest) if largest else None)
def check(candidate): # Check some simple cases assert candidate([2, 4, 1, 3, 5, 7]) == (None, 1) assert candidate([2, 4, 1, 3, 5, 7, 0]) == (None, 1) assert candidate([1, 3, 2, 4, 5, 6, -2]) == (-2, 1) assert candidate([4, 5, 3, 6, 2, 7, -7]) == (-7, 2) assert candidate([7, 3, 8, 4, 9, 2, 5, -...
largest_smallest_integers
def largest_smallest_integers(lst): ''' Create a function that returns a tuple (a, b), where 'a' is the largest of negative integers, and 'b' is the smallest of positive integers in a list. If there is no negative or positive integers, return them as None. Examples: largest_smallest_intege...
HumanEval/137
def compare_one(a, b): """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values are equal. Note: If a real number is represented as a string, the floating point might be . or , ...
temp_a, temp_b = a, b if isinstance(temp_a, str): temp_a = temp_a.replace(',','.') if isinstance(temp_b, str): temp_b = temp_b.replace(',','.') if float(temp_a) == float(temp_b): return None return a if float(temp_a) > float(temp_b) else b
def check(candidate): # Check some simple cases assert candidate(1, 2) == 2 assert candidate(1, 2.5) == 2.5 assert candidate(2, 3) == 3 assert candidate(5, 6) == 6 assert candidate(1, "2,3") == "2,3" assert candidate("5,1", "6") == "6" assert candidate("1", "2") == "2" assert candid...
compare_one
def compare_one(a, b): """ Create a function that takes integers, floats, or strings representing real numbers, and returns the larger variable in its given variable type. Return None if the values are equal. Note: If a real number is represented as a string, the floating point might be . or , ...
HumanEval/138
def is_equal_to_sum_even(n): """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers Example is_equal_to_sum_even(4) == False is_equal_to_sum_even(6) == False is_equal_to_sum_even(8) == True """
return n%2 == 0 and n >= 8
def check(candidate): assert candidate(4) == False assert candidate(6) == False assert candidate(8) == True assert candidate(10) == True assert candidate(11) == False assert candidate(12) == True assert candidate(13) == False assert candidate(16) == True
is_equal_to_sum_even
def is_equal_to_sum_even(n): """Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers Example is_equal_to_sum_even(4) == False is_equal_to_sum_even(6) == False is_equal_to_sum_even(8) == True """ return n%2 == 0 and n >= 8
HumanEval/139
def special_factorial(n): """The Brazilian factorial is defined as: brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! where n > 0 For example: >>> special_factorial(4) 288 The function will receive an integer as input and should return the special factorial of this integer. ...
fact_i = 1 special_fact = 1 for i in range(1, n+1): fact_i *= i special_fact *= fact_i return special_fact
def check(candidate): # Check some simple cases assert candidate(4) == 288, "Test 4" assert candidate(5) == 34560, "Test 5" assert candidate(7) == 125411328000, "Test 7" # Check some edge cases that are easy to work out by hand. assert candidate(1) == 1, "Test 1"
special_factorial
def special_factorial(n): """The Brazilian factorial is defined as: brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1! where n > 0 For example: >>> special_factorial(4) 288 The function will receive an integer as input and should return the special factorial of this integer. ...
HumanEval/14
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """
result = [] for i in range(len(string)): result.append(string[:i+1]) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh'] assert candidate('WWW') == ['W', 'WW', 'WWW']
all_prefixes
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """ result = [] for i in range(len(string)): result.append(string[:i+1]) return result
HumanEval/140
def fix_spaces(text): """ Given a string text, replace all spaces in it with underscores, and if a string has more than 2 consecutive spaces, then replace all consecutive spaces with - fix_spaces("Example") == "Example" fix_spaces("Example 1") == "Example_1" fix_spaces(" Example 2")...
new_text = "" i = 0 start, end = 0, 0 while i < len(text): if text[i] == " ": end += 1 else: if end - start > 2: new_text += "-"+text[i] elif end - start > 0: new_text += "_"*(end - start)+text[i] else: ...
def check(candidate): # Check some simple cases assert candidate("Example") == "Example", "This prints if this assert fails 1 (good for debugging!)" assert candidate("Mudasir Hanif ") == "Mudasir_Hanif_", "This prints if this assert fails 2 (good for debugging!)" assert candidate("Yellow Yellow Dirty ...
fix_spaces
def fix_spaces(text): """ Given a string text, replace all spaces in it with underscores, and if a string has more than 2 consecutive spaces, then replace all consecutive spaces with - fix_spaces("Example") == "Example" fix_spaces("Example 1") == "Example_1" fix_spaces(" Example 2")...
HumanEval/141
def file_name_check(file_name): """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There should not be mo...
suf = ['txt', 'exe', 'dll'] lst = file_name.split(sep='.') if len(lst) != 2: return 'No' if not lst[1] in suf: return 'No' if len(lst[0]) == 0: return 'No' if not lst[0][0].isalpha(): return 'No' t = len([x for x in lst[0] if x.isdigit()]) if t > 3: ...
def check(candidate): # Check some simple cases assert candidate("example.txt") == 'Yes' assert candidate("1example.dll") == 'No' assert candidate('s1sdf3.asd') == 'No' assert candidate('K.dll') == 'Yes' assert candidate('MY16FILE3.exe') == 'Yes' assert candidate('His12FILE94.exe') == 'No' ...
file_name_check
def file_name_check(file_name): """Create a function which takes a string representing a file's name, and returns 'Yes' if the the file's name is valid, and returns 'No' otherwise. A file's name is considered to be valid if and only if all the following conditions are met: - There should not be mo...
HumanEval/142
def sum_squares(lst): """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not change the e...
result =[] for i in range(len(lst)): if i %3 == 0: result.append(lst[i]**2) elif i % 4 == 0 and i%3 != 0: result.append(lst[i]**3) else: result.append(lst[i]) return sum(result)
def check(candidate): # Check some simple cases assert candidate([1,2,3]) == 6 assert candidate([1,4,9]) == 14 assert candidate([]) == 0 assert candidate([1,1,1,1,1,1,1,1,1]) == 9 assert candidate([-1,-1,-1,-1,-1,-1,-1,-1,-1]) == -3 assert candidate([0]) == 0 assert candidate([-1,-...
sum_squares
def sum_squares(lst): """" This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not change the e...
HumanEval/143
def words_in_sentence(sentence): """ You are given a string representing a sentence, the sentence contains some words separated by a space, and you have to return a string that contains the words from the original sentence, whose lengths are prime numbers, the order of the words in the new stri...
new_lst = [] for word in sentence.split(): flg = 0 if len(word) == 1: flg = 1 for i in range(2, len(word)): if len(word)%i == 0: flg = 1 if flg == 0 or len(word) == 2: new_lst.append(word) return " ".join(new_lst)
def check(candidate): # Check some simple cases assert candidate("This is a test") == "is" assert candidate("lets go for swimming") == "go for" assert candidate("there is no place available here") == "there is no place" assert candidate("Hi I am Hussein") == "Hi am Hussein" assert candidate("go...
words_in_sentence
def words_in_sentence(sentence): """ You are given a string representing a sentence, the sentence contains some words separated by a space, and you have to return a string that contains the words from the original sentence, whose lengths are prime numbers, the order of the words in the new stri...
HumanEval/144
def simplify(x, n): """Your task is to implement a function that will simplify the expression x * n. The function returns True if x * n evaluates to a whole number and False otherwise. Both x and n, are string representation of a fraction, and have the following format, <numerator>/<denominator> where ...
a, b = x.split("/") c, d = n.split("/") numerator = int(a) * int(c) denom = int(b) * int(d) if (numerator/denom == int(numerator/denom)): return True return False
def check(candidate): # Check some simple cases assert candidate("1/5", "5/1") == True, 'test1' assert candidate("1/6", "2/1") == False, 'test2' assert candidate("5/1", "3/1") == True, 'test3' assert candidate("7/10", "10/2") == False, 'test4' assert candidate("2/10", "50/10") == True, 'test5' ...
simplify
def simplify(x, n): """Your task is to implement a function that will simplify the expression x * n. The function returns True if x * n evaluates to a whole number and False otherwise. Both x and n, are string representation of a fraction, and have the following format, <numerator>/<denominator> where ...
HumanEval/145
def order_by_points(nums): """ Write a function which sorts the given list of integers in ascending order according to the sum of their digits. Note: if there are several items with similar sum of their digits, order them based on their index in original list. For example: >>> order_by_poi...
def digits_sum(n): neg = 1 if n < 0: n, neg = -1 * n, -1 n = [int(i) for i in str(n)] n[0] = n[0] * neg return sum(n) return sorted(nums, key=digits_sum)
def check(candidate): # Check some simple cases assert candidate([1, 11, -1, -11, -12]) == [-1, -11, 1, -12, 11] assert candidate([1234,423,463,145,2,423,423,53,6,37,3457,3,56,0,46]) == [0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457] assert candidate([]) == [] assert candidate([1,...
order_by_points
def order_by_points(nums): """ Write a function which sorts the given list of integers in ascending order according to the sum of their digits. Note: if there are several items with similar sum of their digits, order them based on their index in original list. For example: >>> order_by_poi...
HumanEval/146
def specialFilter(nums): """Write a function that takes an array of numbers as input and returns the number of elements in the array that are greater than 10 and both first and last digits of a number are odd (1, 3, 5, 7, 9). For example: specialFilter([15, -73, 14, -15]) => 1 specialFilter(...
count = 0 for num in nums: if num > 10: odd_digits = (1, 3, 5, 7, 9) number_as_string = str(num) if int(number_as_string[0]) in odd_digits and int(number_as_string[-1]) in odd_digits: count += 1 return count
def check(candidate): # Check some simple cases assert candidate([5, -2, 1, -5]) == 0 assert candidate([15, -73, 14, -15]) == 1 assert candidate([33, -2, -3, 45, 21, 109]) == 2 assert candidate([43, -12, 93, 125, 121, 109]) == 4 assert candidate([71, -2, -33, 75, 21, 19]) == 3 # Check s...
specialFilter
def specialFilter(nums): """Write a function that takes an array of numbers as input and returns the number of elements in the array that are greater than 10 and both first and last digits of a number are odd (1, 3, 5, 7, 9). For example: specialFilter([15, -73, 14, -15]) => 1 specialFilter(...
HumanEval/147
def get_max_triples(n): """ You are given a positive integer n. You have to create an integer array a of length n. For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, and a[i] + a[j] + a[k] is a multiple of 3. ...
A = [i*i - i + 1 for i in range(1,n+1)] ans = [] for i in range(n): for j in range(i+1,n): for k in range(j+1,n): if (A[i]+A[j]+A[k])%3 == 0: ans += [(A[i],A[j],A[k])] return len(ans)
def check(candidate): assert candidate(5) == 1 assert candidate(6) == 4 assert candidate(10) == 36 assert candidate(100) == 53361
get_max_triples
def get_max_triples(n): """ You are given a positive integer n. You have to create an integer array a of length n. For each i (1 ≤ i ≤ n), the value of a[i] = i * i - i + 1. Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, and a[i] + a[j] + a[k] is a multiple of 3. ...
HumanEval/148
def bf(planet1, planet2): ''' There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings planet1 and planet2. The function should return a ...
planet_names = ("Mercury", "Venus", "Earth", "Mars", "Jupiter", "Saturn", "Uranus", "Neptune") if planet1 not in planet_names or planet2 not in planet_names or planet1 == planet2: return () planet1_index = planet_names.index(planet1) planet2_index = planet_names.index(planet2) if planet1_ind...
def check(candidate): # Check some simple cases assert candidate("Jupiter", "Neptune") == ("Saturn", "Uranus"), "First test error: " + str(len(candidate("Jupiter", "Neptune"))) assert candidate("Earth", "Mercury") == ("Venus",), "Second test error: " + str(candidate("Earth", "Mercury")) assert ...
bf
def bf(planet1, planet2): ''' There are eight planets in our solar system: the closerst to the Sun is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, Uranus, Neptune. Write a function that takes two planet names as strings planet1 and planet2. The function should return a ...
HumanEval/149
def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. T...
lst.sort() new_lst = [] for i in lst: if len(i)%2 == 0: new_lst.append(i) return sorted(new_lst, key=len)
def check(candidate): # Check some simple cases assert candidate(["aa", "a", "aaa"]) == ["aa"] assert candidate(["school", "AI", "asdf", "b"]) == ["AI", "asdf", "school"] assert candidate(["d", "b", "c", "a"]) == [] assert candidate(["d", "dcba", "abcd", "a"]) == ["abcd", "dcba"] # Check some ...
sorted_list_sum
def sorted_list_sum(lst): """Write a function that accepts a list of strings as a parameter, deletes the strings that have odd lengths from it, and returns the resulted list with a sorted order, The list is always a list of strings and never an array of numbers, and it may contain duplicates. T...
HumanEval/15
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. >>> string_sequence(0) '0' >>> string_sequence(5) '0 1 2 3 4 5' """
return ' '.join([str(x) for x in range(n + 1)])
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(0) == '0' assert candidate(3) == '0 1 2 3' assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
string_sequence
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. >>> string_sequence(0) '0' >>> string_sequence(5) '0 1 2 3 4 5' """ return ' '.join([str(x) for x in range(n + 1)])
HumanEval/150
def x_or_y(n, x, y): """A simple program which should return the value of x if n is a prime number and should return the value of y otherwise. Examples: for x_or_y(7, 34, 12) == 34 for x_or_y(15, 8, 5) == 5 """
if n == 1: return y for i in range(2, n): if n % i == 0: return y break else: return x
def check(candidate): # Check some simple cases assert candidate(7, 34, 12) == 34 assert candidate(15, 8, 5) == 5 assert candidate(3, 33, 5212) == 33 assert candidate(1259, 3, 52) == 3 assert candidate(7919, -1, 12) == -1 assert candidate(3609, 1245, 583) == 583 assert candidate(91, 56,...
x_or_y
def x_or_y(n, x, y): """A simple program which should return the value of x if n is a prime number and should return the value of y otherwise. Examples: for x_or_y(7, 34, 12) == 34 for x_or_y(15, 8, 5) == 5 """ if n == 1: return y for i in range(2, n): if n % i ...
HumanEval/151
def double_the_difference(lst): ''' Given a list of numbers, return the sum of squares of the numbers in the list that are odd. Ignore numbers that are negative or not integers. double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10 double_the_difference([-1, -2, 0]) == 0 double_the_dif...
return sum([i**2 for i in lst if i > 0 and i%2!=0 and "." not in str(i)])
def check(candidate): # Check some simple cases assert candidate([]) == 0 , "This prints if this assert fails 1 (good for debugging!)" assert candidate([5, 4]) == 25 , "This prints if this assert fails 2 (good for debugging!)" assert candidate([0.1, 0.2, 0.3]) == 0 , "This prints if this assert fails 3...
double_the_difference
def double_the_difference(lst): ''' Given a list of numbers, return the sum of squares of the numbers in the list that are odd. Ignore numbers that are negative or not integers. double_the_difference([1, 3, 2, 0]) == 1 + 9 + 0 + 0 = 10 double_the_difference([-1, -2, 0]) == 0 double_the_dif...
HumanEval/152
def compare(game,guess): """I think we all remember that feeling when the result of some long-awaited event is finally known. The feelings and thoughts you have at that moment are definitely worth noting down and comparing. Your task is to determine if a person correctly guessed the results of a number...
return [abs(x-y) for x,y in zip(game,guess)]
def check(candidate): # Check some simple cases assert candidate([1,2,3,4,5,1],[1,2,3,4,2,-2])==[0,0,0,0,3,3], "This prints if this assert fails 1 (good for debugging!)" assert candidate([0,0,0,0,0,0],[0,0,0,0,0,0])==[0,0,0,0,0,0], "This prints if this assert fails 1 (good for debugging!)" assert candi...
compare
def compare(game,guess): """I think we all remember that feeling when the result of some long-awaited event is finally known. The feelings and thoughts you have at that moment are definitely worth noting down and comparing. Your task is to determine if a person correctly guessed the results of a number...
HumanEval/153
def Strongest_Extension(class_name, extensions): """You will be given the name of a class (a string) and a list of extensions. The extensions are to be used to load additional classes to the class. The strength of the extension is as follows: Let CAP be the number of the uppercase letters in the extens...
strong = extensions[0] my_val = len([x for x in extensions[0] if x.isalpha() and x.isupper()]) - len([x for x in extensions[0] if x.isalpha() and x.islower()]) for s in extensions: val = len([x for x in s if x.isalpha() and x.isupper()]) - len([x for x in s if x.isalpha() and x.islower()]) i...
def check(candidate): # Check some simple cases assert candidate('Watashi', ['tEN', 'niNE', 'eIGHt8OKe']) == 'Watashi.eIGHt8OKe' assert candidate('Boku123', ['nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg']) == 'Boku123.YEs.WeCaNe' assert candidate('__YESIMHERE', ['t', 'eMptY', 'nothing', 'zeR00', 'NuLl__'...
Strongest_Extension
def Strongest_Extension(class_name, extensions): """You will be given the name of a class (a string) and a list of extensions. The extensions are to be used to load additional classes to the class. The strength of the extension is as follows: Let CAP be the number of the uppercase letters in the extens...
HumanEval/154
def cycpattern_check(a , b): """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word cycpattern_check("abcd","abd") => False cycpattern_check("hello","ell") => True cycpattern_check("whassup","psus") => False cycpattern_check("ab...
l = len(b) pat = b + b for i in range(len(a) - l + 1): for j in range(l + 1): if a[i:i+l] == pat[j:j+l]: return True return False
def check(candidate): # Check some simple cases #assert True, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. #assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate("xyzw","xyw") == False...
cycpattern_check
def cycpattern_check(a , b): """You are given 2 words. You need to return True if the second word or any of its rotations is a substring in the first word cycpattern_check("abcd","abd") => False cycpattern_check("hello","ell") => True cycpattern_check("whassup","psus") => False cycpattern_check("ab...
HumanEval/155
def even_odd_count(num): """Given an integer. return a tuple that has the number of even and odd digits respectively. Example: even_odd_count(-12) ==> (1, 1) even_odd_count(123) ==> (1, 2) """
even_count = 0 odd_count = 0 for i in str(abs(num)): if int(i)%2==0: even_count +=1 else: odd_count +=1 return (even_count, odd_count)
def check(candidate): # Check some simple cases assert candidate(7) == (0, 1) assert candidate(-78) == (1, 1) assert candidate(3452) == (2, 2) assert candidate(346211) == (3, 3) assert candidate(-345821) == (3, 3) assert candidate(-2) == (1, 0) assert candidate(-45347) == (2, 3) ass...
even_odd_count
def even_odd_count(num): """Given an integer. return a tuple that has the number of even and odd digits respectively. Example: even_odd_count(-12) ==> (1, 1) even_odd_count(123) ==> (1, 2) """ even_count = 0 odd_count = 0 for i in str(abs(num)): if int(i)%2==0: ...
HumanEval/156
def int_to_mini_roman(number): """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) == 'xix' >>> int_to_mini_roman(152) == 'clii' >>> int_to_mini_roman(426) == 'cdxx...
num = [1, 4, 5, 9, 10, 40, 50, 90, 100, 400, 500, 900, 1000] sym = ["I", "IV", "V", "IX", "X", "XL", "L", "XC", "C", "CD", "D", "CM", "M"] i = 12 res = '' while number: div = number // num[i] number %= num[i] while div: res += sym[i...
def check(candidate): # Check some simple cases assert candidate(19) == 'xix' assert candidate(152) == 'clii' assert candidate(251) == 'ccli' assert candidate(426) == 'cdxxvi' assert candidate(500) == 'd' assert candidate(1) == 'i' assert candidate(4) == 'iv' assert candidate(43) ==...
int_to_mini_roman
def int_to_mini_roman(number): """ Given a positive integer, obtain its roman numeral equivalent as a string, and return it in lowercase. Restrictions: 1 <= num <= 1000 Examples: >>> int_to_mini_roman(19) == 'xix' >>> int_to_mini_roman(152) == 'clii' >>> int_to_mini_roman(426) == 'cdxx...
HumanEval/157
def right_angle_triangle(a, b, c): ''' Given the lengths of the three sides of a triangle. Return True if the three sides form a right-angled triangle, False otherwise. A right-angled triangle is a triangle in which one angle is right angle or 90 degree. Example: right_angle_triangle(3, 4,...
return a*a == b*b + c*c or b*b == a*a + c*c or c*c == a*a + b*b
def check(candidate): # Check some simple cases assert candidate(3, 4, 5) == True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1, 2, 3) == False assert candidate(10, 6, 8) == True assert candidate(2, 2, 2) == False assert candidate(7, 24, 25) == True assert c...
right_angle_triangle
def right_angle_triangle(a, b, c): ''' Given the lengths of the three sides of a triangle. Return True if the three sides form a right-angled triangle, False otherwise. A right-angled triangle is a triangle in which one angle is right angle or 90 degree. Example: right_angle_triangle(3, 4,...
HumanEval/158
def find_max(words): """Write a function that accepts a list of strings. The list contains different words. Return the word with maximum number of unique characters. If multiple strings have maximum number of unique characters, return the one which comes first in lexicographical order. find_max(["...
return sorted(words, key = lambda x: (-len(set(x)), x))[0]
def check(candidate): # Check some simple cases assert (candidate(["name", "of", "string"]) == "string"), "t1" assert (candidate(["name", "enam", "game"]) == "enam"), 't2' assert (candidate(["aaaaaaa", "bb", "cc"]) == "aaaaaaa"), 't3' assert (candidate(["abc", "cba"]) == "abc"), 't4' assert (ca...
find_max
def find_max(words): """Write a function that accepts a list of strings. The list contains different words. Return the word with maximum number of unique characters. If multiple strings have maximum number of unique characters, return the one which comes first in lexicographical order. find_max(["...
HumanEval/159
def eat(number, need, remaining): """ You're a hungry rabbit, and you already have eaten a certain number of carrots, but now you need to eat more carrots to complete the day's meals. you should return an array of [ total number of eaten carrots after your meals, the...
if(need <= remaining): return [ number + need , remaining-need ] else: return [ number + remaining , 0]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(5, 6, 10) == [11, 4], "Error" assert candidate(4, 8, 9) == [12, 1], "Error" assert candidate(1, 10, 10) == [11, 0], "Error" assert candidate(2, 11, 5) == [7, ...
eat
def eat(number, need, remaining): """ You're a hungry rabbit, and you already have eaten a certain number of carrots, but now you need to eat more carrots to complete the day's meals. you should return an array of [ total number of eaten carrots after your meals, the...
HumanEval/16
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of >>> count_distinct_characters('xyzXYZ') 3 >>> count_distinct_characters('Jerry') 4 """
return len(set(string.lower()))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('abcde') == 5 assert candidate('abcde' + 'cade' + 'CADE') == 5 assert candidate('aaaaAAAAaaaa') == 1 assert candidate('Jerry jERRY JeRRRY') == 5
count_distinct_characters
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of >>> count_distinct_characters('xyzXYZ') 3 >>> count_distinct_characters('Jerry') 4 """ return len(set(string.lower()))
HumanEval/160
def do_algebra(operator, operand): """ Given two lists operator, and operand. The first list has basic algebra operations, and the second list is a list of integers. Use the two given lists to build the algebric expression and return the evaluation of this expression. The basic algebra operation...
expression = str(operand[0]) for oprt, oprn in zip(operator, operand[1:]): expression+= oprt + str(oprn) return eval(expression)
def check(candidate): # Check some simple cases assert candidate(['**', '*', '+'], [2, 3, 4, 5]) == 37 assert candidate(['+', '*', '-'], [2, 3, 4, 5]) == 9 assert candidate(['//', '*'], [7, 3, 4]) == 8, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are eas...
do_algebra
def do_algebra(operator, operand): """ Given two lists operator, and operand. The first list has basic algebra operations, and the second list is a list of integers. Use the two given lists to build the algebric expression and return the evaluation of this expression. The basic algebra operation...
HumanEval/161
def solve(s): """You are given a string s. if s[i] is a letter, reverse its case from lower to upper or vise versa, otherwise keep it as it is. If the string contains no letters, reverse the string. The function should return the resulted string. Examples solve("1234") = "4321" solve("...
flg = 0 idx = 0 new_str = list(s) for i in s: if i.isalpha(): new_str[idx] = i.swapcase() flg = 1 idx += 1 s = "" for i in new_str: s += i if flg == 0: return s[len(s)::-1] return s
def check(candidate): # Check some simple cases assert candidate("AsDf") == "aSdF" assert candidate("1234") == "4321" assert candidate("ab") == "AB" assert candidate("#a@C") == "#A@c" assert candidate("#AsdfW^45") == "#aSDFw^45" assert candidate("#6@2") == "2@6#" # Check some edge case...
solve
def solve(s): """You are given a string s. if s[i] is a letter, reverse its case from lower to upper or vise versa, otherwise keep it as it is. If the string contains no letters, reverse the string. The function should return the resulted string. Examples solve("1234") = "4321" solve("...
HumanEval/162
def string_to_md5(text): """ Given a string 'text', return its md5 hash equivalent string. If 'text' is an empty string, return None. >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' """
import hashlib return hashlib.md5(text.encode('ascii')).hexdigest() if text else None
def check(candidate): # Check some simple cases assert candidate('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' assert candidate('') == None assert candidate('A B C') == '0ef78513b0cb8cef12743f5aeb35f888' assert candidate('password') == '5f4dcc3b5aa765d61d8327deb882cf99' # Check some edg...
string_to_md5
def string_to_md5(text): """ Given a string 'text', return its md5 hash equivalent string. If 'text' is an empty string, return None. >>> string_to_md5('Hello world') == '3e25960a79dbc69b674cd4ec67a72c62' """ import hashlib return hashlib.md5(text.encode('ascii')).hexdigest() if text els...
HumanEval/163
def generate_integers(a, b): """ Given two positive integers a and b, return the even digits between a and b, in ascending order. For example: generate_integers(2, 8) => [2, 4, 6, 8] generate_integers(8, 2) => [2, 4, 6, 8] generate_integers(10, 14) => [] """
lower = max(2, min(a, b)) upper = min(8, max(a, b)) return [i for i in range(lower, upper+1) if i % 2 == 0]
def check(candidate): # Check some simple cases assert candidate(2, 10) == [2, 4, 6, 8], "Test 1" assert candidate(10, 2) == [2, 4, 6, 8], "Test 2" assert candidate(132, 2) == [2, 4, 6, 8], "Test 3" assert candidate(17,89) == [], "Test 4" # Check some edge cases that are easy to work out by ha...
generate_integers
def generate_integers(a, b): """ Given two positive integers a and b, return the even digits between a and b, in ascending order. For example: generate_integers(2, 8) => [2, 4, 6, 8] generate_integers(8, 2) => [2, 4, 6, 8] generate_integers(10, 14) => [] """ lower = max(2, min(a,...
HumanEval/17
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: ...
note_map = {'o': 4, 'o|': 2, '.|': 1} return [note_map[x] for x in music_string.split(' ') if x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('o o o o') == [4, 4, 4, 4] assert candidate('.| .| .| .|') == [1, 1, 1, 1] assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4] assert candidate('o| .| o| .| ...
parse_music
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: ...
HumanEval/18
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """
times = 0 for i in range(len(string) - len(substring) + 1): if string[i:i+len(substring)] == substring: times += 1 return times
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('', 'x') == 0 assert candidate('xyxyxyx', 'x') == 4 assert candidate('cacacacac', 'cac') == 4 assert candidate('john doe', 'john') == 1
how_many_times
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """ times = 0 for ...
HumanEval/19
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >...
value_map = { 'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9 } return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('three') == 'three' assert candidate('three five nine') == 'three five nine' assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine' assert ...
sort_numbers
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >...
HumanEval/2
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. >>> truncate_number(3.5) 0...
return number % 1.0
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3.5) == 0.5 assert abs(candidate(1.33) - 0.33) < 1e-6 assert abs(candidate(123.456) - 0.456) < 1e-6
truncate_number
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. >>> truncate_number(3.5) 0...
HumanEval/20
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([...
closest_pair = None distance = None for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: if distance is None: distance = abs(elem - elem2) closest_pair = tuple(sorted([elem, elem2])) ...
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0) assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9) assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2) assert candidate([1.0, 2.0, 3.0, 4.0,...
find_closest_elements
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([...
HumanEval/21
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, ...
min_number = min(numbers) max_number = max(numbers) return [(x - min_number) / (max_number - min_number) for x in numbers]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([2.0, 49.9]) == [0.0, 1.0] assert candidate([100.0, 49.9]) == [1.0, 0.0] assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0] assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0....
rescale_to_unit
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, ...
HumanEval/22
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers >>> filter_integers(['a', 3.14, 5]) [5] >>> filter_integers([1, 2, 3, 'abc', {}, []]) [1, 2, 3] """
return [x for x in values if isinstance(x, int)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9] assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
filter_integers
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers >>> filter_integers(['a', 3.14, 5]) [5] >>> filter_integers([1, 2, 3, 'abc', {}, []]) [1, 2, 3] """ return [x for x in values if isinstance(x, in...
HumanEval/23
def strlen(string: str) -> int: """ Return length of given string >>> strlen('') 0 >>> strlen('abc') 3 """
return len(string)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('x') == 1 assert candidate('asdasnakj') == 9
strlen
def strlen(string: str) -> int: """ Return length of given string >>> strlen('') 0 >>> strlen('abc') 3 """ return len(string)
HumanEval/24
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """
for i in reversed(range(n)): if n % i == 0: return i
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3) == 1 assert candidate(7) == 1 assert candidate(10) == 5 assert candidate(100) == 50 assert candidate(49) == 7
largest_divisor
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """ for i in reversed(range(n)): if n % i == 0: return i
HumanEval/25
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the produc...
import math fact = [] i = 2 while i <= int(math.sqrt(n) + 1): if n % i == 0: fact.append(i) n //= i else: i += 1 if n > 1: fact.append(n) return fact
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(2) == [2] assert candidate(4) == [2, 2] assert candidate(8) == [2, 2, 2] assert candidate(3 * 19) == [3, 19] assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19] assert candidate(3 * 19 * 3 * 19 * ...
factorize
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the produc...
HumanEval/26
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """
import collections c = collections.Counter(numbers) return [n for n in numbers if c[n] <= 1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
remove_duplicates
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """ import collections c = co...
HumanEval/27
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """
return string.swapcase()
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('Hello!') == 'hELLO!' assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
flip_case
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """ return string.swapcase()
HumanEval/28
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """
return ''.join(strings)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == '' assert candidate(['x', 'y', 'z']) == 'xyz' assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
concatenate
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """ return ''.join(strings)
HumanEval/29
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """
return [x for x in strings if x.startswith(prefix)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
filter_by_prefix
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """ re...
HumanEval/3
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return Tru...
balance = 0 for op in operations: balance += op if balance < 0: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == False assert candidate([1, 2, -3, 1, 2, -3]) == False assert candidate([1, 2, -4, 5, 6]) == True assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False assert candidate([1, -1, 2, -2, 5, -5, 4...
below_zero
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return Tru...
HumanEval/30
def get_positive(l: list): """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """
return [e for e in l if e > 0]
METADATA = {} def check(candidate): assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6] assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1] assert candidate([-1, -2]) == [] assert candidate([]) == []
get_positive
def get_positive(l: list): """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """ return [e for e in l if e > 0]
HumanEval/31
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """
if n < 2: return False for k in range(2, n - 1): if n % k == 0: return False return True
METADATA = {} def check(candidate): assert candidate(6) == False assert candidate(101) == True assert candidate(11) == True assert candidate(13441) == True assert candidate(61) == True assert candidate(4) == False assert candidate(1) == False assert candidate(5) == True assert ca...
is_prime
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """ if n ...
HumanEval/32
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomia...
begin, end = -1., 1. while poly(xs, begin) * poly(xs, end) > 0: begin *= 2.0 end *= 2.0 while end - begin > 1e-10: center = (begin + end) / 2.0 if poly(xs, center) * poly(xs, begin) > 0: begin = center else: end = center return begin
METADATA = {} def check(candidate): import math import random rng = random.Random(42) import copy for _ in range(100): ncoeff = 2 * rng.randint(1, 4) coeffs = [] for _ in range(ncoeff): coeff = rng.randint(-10, 10) if coeff == 0: co...
find_zero
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomia...
HumanEval/33
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_t...
l = list(l) l[::3] = sorted(l[::3]) return l
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3])) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(so...
sort_third
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_t...
HumanEval/34
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """
return sorted(list(set(l)))
METADATA = {} def check(candidate): assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
unique
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """ return sorted(list(set(l)))
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