problem stringlengths 0 1.31k | answer stringclasses 340
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The production process of paper umbrellas in our country is very ingenious. As shown in the figure, whether the umbrella is opened or closed, the handle AP always bisects the angle angle BAC formed by the two ribs in the same plane, and AE = AF, DE = DF, so as to ensure that the umbrella ring can slide along the handle... | C | |
the handle AP always bisects the angle angle BAC formed by the two ribs in the same plane, and AE = AF, DE = DF, If AB = 50.0, AD = 14.0, then the area of oil paper required to make such a paper umbrella is (don't remember the seam) ()
Choices:
A:48cm^{2}
B:70πcm^{2}
C:2400πcm^{2}
D:2500πcm^{2} | C | |
If AB = 50.0, AD = 14.0, then the area of oil paper required to make such a paper umbrella is (don't remember the seam) ()
Choices:
A:48cm^{2}
B:70πcm^{2}
C:2400πcm^{2}
D:2500πcm^{2} | C | |
the handle AP always bisects the angle angle BAC formed by the two ribs in the same plane, and AE = AF, DE = DF, then the area of oil paper required to make such a paper umbrella is (don't remember the seam) ()
Choices:
A:48cm^{2}
B:70πcm^{2}
C:2400πcm^{2}
D:2500πcm^{2} | C | |
C | ||
As shown in the figure, a sector with a central angle of 120.0 and a radius of 6.0 encloses the side of a cone (the joints are ignored), then the height of the cone is ()
Choices:
A:6
B:8
C:3√{3}
D:4√{2} | D | |
As shown in the figure, a sector with a central angle of 120.0 and a radius of 6.0, then the height of the cone is ()
Choices:
A:6
B:8
C:3√{3}
D:4√{2} | D | |
As shown in the figure, a sector with a central angle of 120.0 and a radius of 6.0, then the height of the cone is ()
Choices:
A:6
B:8
C:3√{3}
D:4√{2} | D | |
As shown in the figure, then the height of the cone is ()
Choices:
A:6
B:8
C:3√{3}
D:4√{2} | D | |
D | ||
As shown in the figure, in Rttriangle ABC, angle ACB = 90.0, AC = 4.0, BC = 3.0, rotate triangle ABC around the line where AC is located to obtain a rotating body, then the lateral area of the rotating body is ()
Choices:
A:12π
B:15π
C:30π
D:60π | B | |
As shown in the figure, AC = 4.0, BC = 3.0, rotate triangle ABC around the line where AC is located to obtain a rotating body, then the lateral area of the rotating body is ()
Choices:
A:12π
B:15π
C:30π
D:60π | B | |
As shown in the figure, AC = 4.0, BC = 3.0, rotate triangle ABC around the line where AC is located to obtain a rotating body, then the lateral area of the rotating body is ()
Choices:
A:12π
B:15π
C:30π
D:60π | B | |
As shown in the figure, rotate triangle ABC around the line where AC is located to obtain a rotating body, then the lateral area of the rotating body is ()
Choices:
A:12π
B:15π
C:30π
D:60π | B | |
B | ||
As shown in the figure, cut a circle and a sector piece of paper on the paper so that it can form a cone model. If the radius of the circle is 1.0 and the central angle of the sector is equal to 90.0, then the radius of the sector is ()
Choices:
A:2
B:4
C:6
D:8
127 | B | |
As shown in the figure, If the radius of the circle is 1.0 and the central angle of the sector is equal to 90.0, then the radius of the sector is ()
Choices:
A:2
B:4
C:6
D:8
127 | B | |
As shown in the figure, If the radius of the circle is 1.0 and the central angle of the sector is equal to 90.0, then the radius of the sector is ()
Choices:
A:2
B:4
C:6
D:8
127 | B | |
As shown in the figure, then the radius of the sector is ()
Choices:
A:2
B:4
C:6
D:8 | B | |
B | ||
As shown in a sector iron sheet OAB, it is known that OA = 30.0, angle AOB = 120.0, the worker master combines OA and OB to form a conical chimney cap (the joints are ignored), then the radius of the bottom circle of the chimney cap is ()
Choices:
A:5cm
B:12cm
C:10cm
D:15cm | C | |
it is known that OA = 30.0, angle AOB = 120.0, then the radius of the bottom circle of the chimney cap is ()
Choices:
A:5cm
B:12cm
C:10cm
D:15cm | C | |
it is known that OA = 30.0, angle AOB = 120.0, then the radius of the bottom circle of the chimney cap is ()
Choices:
A:5cm
B:12cm
C:10cm
D:15cm | C | |
it is known that， then the radius of the bottom circle of the chimney cap is ()
Choices:
A:5cm
B:12cm
C:10cm
D:15cm | C | |
C | ||
As shown in the figure, it is known that the radius of the bottom surface of the cone is 6.0, and the length of the generatrix is 10.0, then the lateral area of the cone is ()
Choices:
A:60π
B:80π
C:10π
D:96π | A | |
As shown in the figure, it is known that the radius of the bottom surface of the cone is 6.0, and the length of the generatrix is 10.0, then the lateral area of the cone is ()
Choices:
A:60π
B:80π
C:10π
D:96π | A | |
As shown in the figure, it is known that the radius of the bottom surface of the cone is 6.0, and the length of the generatrix is 10.0, then the lateral area of the cone is ()
Choices:
A:60π
B:80π
C:10π
D:96π | A | |
As shown in the figure, then the lateral area of the cone is ()
Choices:
A:60π
B:80π
C:10π
D:96π | A | |
A | ||
Lulu cuts a circle and a sector piece of paper from the paper (as shown in the picture), and uses them to form a cone model. If the radius of the circle is 1.0. The central angle of the sector is equal to 120.0, then the radius of the sector is ()
Choices:
A:√{3}
B:√{6}
C:3
D:6 | C | |
If the radius of the circle is 1.0. The central angle of the sector is equal to 120.0, then the radius of the sector is ()
Choices:
A:√{3}
B:√{6}
C:3
D:6 | C | |
If the radius of the circle is 1.0. The central angle of the sector is equal to 120.0, then the radius of the sector is ()
Choices:
A:√{3}
B:√{6}
C:3
D:6 | C | |
then the radius of the sector is ()
Choices:
A:√{3}
B:√{6}
C:3
D:6 | C | |
C | ||
As shown in the figure, there is a sector with a central angle of 120.0 and a radius of 6.0. If OA and OB are overlapped to form a cone side, the diameter of the bottom of the cone is ()
Choices:
A:2cm
B:4cm
C:3cm
D:5cm | B | |
As shown in the figure, a radius of 6.0. If OA and OB are overlapped to form a cone side, the diameter of the bottom of the cone is ()
Choices:
A:2cm
B:4cm
C:3cm
D:5cm | B | |
As shown in the figure, a radius of 6.0. the diameter of the bottom of the cone is ()
Choices:
A:2cm
B:4cm
C:3cm
D:5cm | B | |
As shown in the figure, If OA and OB are overlapped to form a cone side, the diameter of the bottom of the cone is ()
Choices:
A:2cm
B:4cm
C:3cm
D:5cm | B | |
B | ||
As shown in the picture, the length of the generatrix of the cone-shaped tent roof is AB = 10.0, the bottom radius is BO = 5.0, and the lateral area of the cone-shaped tent roof (excluding the seams) is ()
Choices:
A:15πm^{2}
B:30πm^{2}
C:50πm^{2}
D:75πm^{2} | C | |
As shown in the picture, the length of the generatrix of the cone-shaped tent roof is AB = 10.0, the bottom radius is BO = 5.0, and the lateral area of the cone-shaped tent roof (excluding the seams) is ()
Choices:
A:15πm^{2}
B:30πm^{2}
C:50πm^{2}
D:75πm^{2} | C | |
As shown in the picture, the length of the generatrix of the cone-shaped tent roof is AB = 10.0, the bottom radius is BO = 5.0, and the lateral area of the cone-shaped tent roof (excluding the seams) is ()
Choices:
A:15πm^{2}
B:30πm^{2}
C:50πm^{2}
D:75πm^{2} | C | |
As shown in the picture, and the lateral area of the cone-shaped tent roof (excluding the seams) is ()
Choices:
A:15πm^{2}
B:30πm^{2}
C:50πm^{2}
D:75πm^{2} | C | |
C | ||
As shown in the figure, in circle O, the length of chord AB is 10.0, and the angle of circumference angle ACB = 45.0, then the diameter of the circle AD is ()
Choices:
A:5√{2}
B:10√{2}
C:15√{2}
D:20√{2} | B | |
As shown in the figure, the length of chord AB is 10.0, and the angle of circumference angle ACB = 45.0, then the diameter of the circle AD is ()
Choices:
A:5√{2}
B:10√{2}
C:15√{2}
D:20√{2} | B | |
As shown in the figure, the length of chord AB is 10.0, and the angle of circumference angle ACB = 45.0, then the diameter of the circle AD is ()
Choices:
A:5√{2}
B:10√{2}
C:15√{2}
D:20√{2} | B | |
As shown in the figure, then the diameter of the circle AD is ()
Choices:
A:5√{2}
B:10√{2}
C:15√{2}
D:20√{2} | B | |
B | ||
As shown in the figure, in triangle ABC. angle C = 90.0, point D is a moving point on BC (point D does not coincide with point C). The circle with CD as the diameter intersects AD at point P. If AC = 6.0. The minimum length of the line segment BP is 2.0. Then the length of AB is ()
Choices:
A:8
B:2√{10}
C:4√{3}
D:2√{13... | D | |
As shown in the figure, angle C = 90.0. The circle with CD as the diameter intersects AD at point P. If AC = 6.0. The minimum length of the line segment BP is 2.0. Then the length of AB is ()
Choices:
A:8
B:2√{10}
C:4√{3}
D:2√{13} | D | |
As shown in the figure, angle C = 90.0. If AC = 6.0. The minimum length of the line segment BP is 2.0. Then the length of AB is ()
Choices:
A:8
B:2√{10}
C:4√{3}
D:2√{13} | D | |
As shown in the figure, The circle with CD as the diameter intersects AD at point P. Then the length of AB is ()
Choices:
A:8
B:2√{10}
C:4√{3}
D:2√{13} | D | |
D | ||
As shown in the figure, in order to measure the height AB of a pavilion (the distance from the top A to the horizontal ground BD), Xiaoming placed a step DE (DE = BC = 0.6) that is the same height as the pavilion step BC beside the pavilion, find A, B, C Three points are collinear), place a mirror horizontally at point... | D | |
As shown in the figure, DE = BC = 0.6, and measure CG = 12.0, and measure GE = 2.0, Xiaoming's height EF = 1.6, then the height of the pavilion AB is approximately ()
Choices:
A:9米
B:9.6米
C:10米
D:10.2米 | D | |
As shown in the figure, DE = BC = 0.6, and measure CG = 12.0, and measure GE = 2.0, Xiaoming's height EF = 1.6, then the height of the pavilion AB is approximately ()
Choices:
A:9米
B:9.6米
C:10米
D:10.2米 | D | |
As shown in the figure, then the height of the pavilion AB is approximately ()
Choices:
A:9m
B:9.6m
C:10m
D:10.2m | D | |
D | ||
As shown in the figure, in order to estimate the width of the Jing River, a target point P is selected on the opposite bank of the Jing River, and points Q and S are taken near the bank, so that the points P, Q, and S are in a straight line, and the straight line PS is perpendicular to the river. Choose an appropriate ... | B | |
As shown in the figure, and the straight line PS is perpendicular to the river. Choose an appropriate point T on the straight line a passing point S and perpendicular to PS. The intersection of PT and the straight line b passing point Q and perpendicular to PS is R. If QS = 60.0, ST = 120.0, QR = 80.0, then the width o... | B | |
As shown in the figure, If QS = 60.0, ST = 120.0, QR = 80.0, then the width of the river PQ is ()
Choices:
A:40m
B:120m
C:60m
D:180m | B | |
As shown in the figure, and the straight line PS is perpendicular to the river. Choose an appropriate point T on the straight line a passing point S and perpendicular to PS. The intersection of PT and the straight line b passing point Q and perpendicular to PS is R. then the width of the river PQ is ()
Choices:
A:40m
B... | B | |
B | ||
As shown in the picture, Xiaoying designed a flashlight to measure the height of an ancient city wall. Place a horizontal plane mirror at point P. The light starts from point A and is reflected by the plane mirror and hits the top C of the ancient city wall CD. It is known that AB perpendicular BD, CD perpendicular B... | B | |
As shown in the picture, It is known that AB perpendicular BD, CD perpendicular BD. And it is measured that AB = 1.4, BP = 2.1, PD = 12.0. Then the height of the ancient city wall CD is ()
Choices:
A:6米
B:8米
C:10米
D:12米 | B | |
As shown in the picture, And it is measured that AB = 1.4, BP = 2.1, PD = 12.0. Then the height of the ancient city wall CD is ()
Choices:
A:6米
B:8米
C:10米
D:12米 | B | |
As shown in the picture, It is known that AB perpendicular BD, CD perpendicular BD. Then the height of the ancient city wall CD is ()
Choices:
A:6m
B:8m
C:10m
D:12m | B | |
B | ||
As shown in the figure, in circle O, point M is the midpoint of arc AB. Connect MO and extend it to intersect circle O at point N, connect BN, if angle AOB = 140.0, then the degree of angle N is ()
Choices:
A:70°
B:40°
C:35°
D:20° | C | |
As shown in the figure, point M is the midpoint of arc AB. if angle AOB = 140.0, then the degree of angle N is ()
Choices:
A:70°
B:40°
C:35°
D:20° | C | |
As shown in the figure, if angle AOB = 140.0, then the degree of angle N is ()
Choices:
A:70°
B:40°
C:35°
D:20° | C | |
As shown in the figure, point M is the midpoint of arc AB. then the degree of angle N is ()
Choices:
A:70°
B:40°
C:35°
D:20° | C | |
C | ||
As shown in the figure, in order to measure the degree of tree AB, a certain mathematics learning interest group measured the length of the tree's shadow BC in the sun as 9.0. At the same moment, they also measured the shadow length of Xiaoliang in the sun as 1.5. Knowing that Xiaoliang's height is 1.8, then the height... | A | |
As shown in the figure, a certain mathematics learning interest group measured the length of the tree's shadow BC in the sun as 9.0. At the same moment, they also measured the shadow length of Xiaoliang in the sun as 1.5. Knowing that Xiaoliang's height is 1.8, then the height of tree AB is ()
Choices:
A:10.8m
B:9m
C:7... | A | |
As shown in the figure, a certain mathematics learning interest group measured the length of the tree's shadow BC in the sun as 9.0. At the same moment, they also measured the shadow length of Xiaoliang in the sun as 1.5. Knowing that Xiaoliang's height is 1.8, then the height of tree AB is ()
Choices:
A:10.8m
B:9m
C:7... | A | |
A certain mathematics learning interest group measured the shadow length of Xiaoliang in the sun as 1.5. Knowing that Xiaoliang's height is 1.8. As shown in the figure, then the height of tree AB is ()
Choices:
A:10.8m
B:9m
C:7.5m
D:0.3m | A | |
A | ||
As shown in the picture, it is an ancient masher in the countryside. It is known that the height of the support column AB is 0.3, the length of the pedal DE is 1.0, and the distance from the support point A to the foot D is 0.6. When foot D touches the ground, the head point E rises ()
Choices:
A:0.5米
B:0.6米
C:0.3米
D:0... | A | |
As shown in the picture, It is known that the height of the support column AB is 0.3, the length of the pedal DE is 1.0, and the distance from the support point A to the foot D is 0.6. When foot D touches the ground, the head point E rises ()
Choices:
A:0.5米
B:0.6米
C:0.3米
D:0.9米 | A | |
As shown in the picture, It is known that the height of the support column AB is 0.3, the length of the pedal DE is 1.0, and the distance from the support point A to the foot D is 0.6. When foot D touches the ground, the head point E rises ()
Choices:
A:0.5米
B:0.6米
C:0.3米
D:0.9米 | A | |
As shown in the picture, When foot D touches the ground, the head point E rises ()
Choices:
A:0.5m
B:0.6m
C:0.3m
D:0.9m | A | |
A | ||
As shown in the figure, the light source P is directly above the crossbar AB, the shadow of AB under the light is CD, AB parallel CD, AB = 2.0, CD = 5.0, the distance between point P and CD is 3.0, then the distance between AB and CD is ().
Choices:
A:\frac{6}{5}
B:\frac{7}{6}
C:\frac{9}{5}
D:\frac{15}{2} | C | |
As shown in the figure, AB parallel CD, AB = 2.0, CD = 5.0, the distance between point P and CD is 3.0, then the distance between AB and CD is ().
Choices:
A:\frac{6}{5}
B:\frac{7}{6}
C:\frac{9}{5}
D:\frac{15}{2} | C | |
As shown in the figure, AB = 2.0, CD = 5.0, the distance between point P and CD is 3.0, then the distance between AB and CD is ().
Choices:
A:\frac{6}{5}
B:\frac{7}{6}
C:\frac{9}{5}
D:\frac{15}{2} | C | |
As shown in the figure, AB parallel CD, then the distance between AB and CD is ().
Choices:
A:\frac{6}{5}
B:\frac{7}{6}
C:\frac{9}{5}
D:\frac{15}{2} | C | |
C | ||
As shown in the figure, Xiaoqiang made a small hole imaging device in which the length of the paper tube is 15.0. He prepared a candle with a length of 20.0. To get an image with a height of 4.0, the distance between the candle and the paper tube should be ()
Choices:
A:60cm
B:65cm
C:70cm
D:75cm | D | |
As shown in the figure, Xiaoqiang made a small hole imaging device in which the length of the paper tube is 15.0. He prepared a candle with a length of 20.0. To get an image with a height of 4.0, the distance between the candle and the paper tube should be ()
Choices:
A:60cm
B:65cm
C:70cm
D:75cm | D | |
As shown in the figure, Xiaoqiang made a small hole imaging device in which the length of the paper tube is 15.0. He prepared a candle with a length of 20.0. To get an image with a height of 4.0, the distance between the candle and the paper tube should be ()
Choices:
A:60cm
B:65cm
C:70cm
D:75cm | D | |
As shown in the figure, the distance between the candle and the paper tube should be ()
Choices:
A:60cm
B:65cm
C:70cm
D:75cm | D | |
D | ||
As shown in the figure, in a badminton game, Lin Dan, the athlete standing at M in the field, clicks the request from N to point B in the opponent. It is known that the net height OA = 1.52, OB = 4.0, OM = 5.0, then when Lin Dan takes off, the distance from the hitting point to the ground NM = ()
Choices:
A:3.42m
B:1.9... | A | |
As shown in the figure, Lin Dan, the athlete standing at M in the field, clicks the request from N to point B in the opponent. It is known that the net height OA = 1.52, OB = 4.0, OM = 5.0, then when Lin Dan takes off, the distance from the hitting point to the ground NM = ()
Choices:
A:3.42m
B:1.9m
C:3m
D:3.24m | A | |
As shown in the figure, Lin Dan, the athlete standing at M in the field, clicks the request from N to point B in the opponent. It is known that the net height OA = 1.52, OB = 4.0, OM = 5.0, then when Lin Dan takes off, the distance from the hitting point to the ground NM = ()
Choices:
A:3.42m
B:1.9m
C:3m
D:3.24m | A | |
As shown in the figure, Lin Dan, the athlete standing at M in the field, clicks the request from N to point B in the opponent. then when Lin Dan takes off, the distance from the hitting point to the ground NM = ()
Choices:
A:3.42m
B:1.9m
C:3m
D:3.24m | A | |
A |
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