| # Abkhaz Rule Set | |
| # Written by: Bill | |
| # Edited by: Emily | |
| # Last Updated: 2019-09-16 | |
| type,sfrom,sto,weight,precede,follow,comment | |
| # Class Rules | |
| class,supraseg-out,[ʷʲ],,,, | |
| class,supraseg,[ьә],,,, | |
| class,labial,(t|tʼ|d|ʃ|ʒ|k|kʼ|ɡ|qʼ|χ|ʁ|ħ),,,, | |
| class,palatal,(ʒ|dʒ|k|kʼ|ɡ|qʼ|χ|ʁ|ʃ),,,, | |
| # Individual Letters | |
| sub,а,a,4,,, | |
| sub,б,b,4,,, | |
| sub,в,v,4,,, | |
| sub,г,ɡ,4,,, | |
| sub,ӷ,ʁ,4,,, | |
| sub,ҕ,ʁ,4,,,"alternate form of <ӷ>", | |
| sub,д,d,4,,, | |
| sub,е,a,4,,,"[e] is an allophone of /a/; see @AbChirikba2003, p. 21", | |
| sub,ж,ʒ,4,,, | |
| sub,з,z,4,,, | |
| sub,ӡ,dz,4,,, | |
| sub,и,j,4,,, | |
| sub,к,kʼ,4,,, | |
| sub,қ,k,4,,, | |
| sub,ҟ,qʼ,4,,, | |
| sub,л,l,4,,, | |
| sub,м,m,4,,, | |
| sub,н,n,4,,, | |
| sub,о,a,4,,,"[o] is an allophone of /a/; see @AbChirikba2003, p. 21", | |
| sub,п,pʼ,4,,, | |
| sub,ԥ,p,4,,, | |
| sub,ҧ,p,4,,,"older form of <ԥ>", | |
| sub,р,r,4,,, | |
| sub,с,s,4,,, | |
| sub,т,tʼ,4,,, | |
| sub,ҭ,t,4,,, | |
| sub,у,w,4,,, | |
| sub,ф,f,4,,, | |
| sub,х,χ,4,,, | |
| sub,ҳ,ħ,4,,, | |
| sub,ц,ts,4,,, | |
| sub,ҵ,tsʼ,4,,, | |
| sub,ч,tʃʲ,4,,, | |
| sub,ҷ,tʃʲʼ,4,,, | |
| sub,ҽ,tʃ,4,,, | |
| sub,ҿ,tʃʼ,4,,, | |
| sub,ш,ʃ,4,,, | |
| sub,ы,ə,4,,, | |
| sub,ҩ,ʡ,4,,, | |
| sub,џ,dʒ,4,,, | |
| sub,({supraseg}),\1,4,,, | |
| sub,-,,4,,,"a hyphen with no phonetic value appears in some words", | |
| # Misc. Rules | |
| ipasub,({labial}) ә,\1ʷ,2,, | |
| ipasub,({palatal}) ь,\1ʲ,2,, | |
| ipasub,ʼ({supraseg-out}),\1ʼ,1,,, | |
| # Retroactive Clean-up | |
| ipasub,({supraseg}),@,1,,,"some combinations aren't attested resulting in duplication of diacritics or certain palatalized and ejectivized phonemes (eg. ɡьә, dzә), thus we don't allow for such transcriptions", | |
| ipasub,tʃʷ,@,1,,,"combination not attested - no other work-around with the rules", | |