Improve language tag

README.md

@@ -1,207 +1,219 @@
----
-license: apache-2.0
-datasets:
-- qingy2024/PR2-SFT
-language:
-- en
-base_model:
-- Qwen/Qwen2.5-14B-Instruct
----
-
-## PR2 14B Instruct
-
-PR2 is an experimental fine tune of Qwen2.5 14B Instruct, incorporating planning and reasoning before outputting a final answer. It is trained for 2 epochs on the verified subset of qingy2024/PR2-SFT.
-
-**Example:**
-
-Input:
-
-```
-Find the minimum value of the expression \\(\left(\sqrt{2(1+\cos 2 x)}-\sqrt{36-4 \sqrt{5}} \sin x+2\right) \cdot \left(3+2 \sqrt{10-\sqrt{5}} \cos y-\cos 2 y\right)\\). If the answer is not an integer, round it to the nearest integer.
-
-First, create a high level overview in <plan></plan> tags, then do your reasoning in <think></think> tags, and put your final answer in <answer></answer>.
-```
-
-Output:
-
-```
-<plan>
-1. Simplify the expression by breaking it down into manageable parts.
-2. Use trigonometric identities to simplify terms involving trigonometric functions.
-3. Analyze the structure of the expression to identify potential optimization strategies.
-4. Consider the possibility of minimizing each part of the expression separately.
-5. Calculate the minimum value of the entire expression and round it to the nearest integer if necessary.
-</plan>
-
-<think>
-Hmm... let me start by simplifying the expression. The expression is:
-
-\[
-\left(\sqrt{2(1+\cos 2x)} - \sqrt{36-4\sqrt{5}} \sin x + 2\right) \cdot \left(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\right)
-\]
-
-First, I notice that \(\sqrt{2(1+\cos 2x)}\) can be simplified using a trigonometric identity. Recall that \(1 + \cos 2x = 2\cos^2 x\), so:
-
-\[
-\sqrt{2(1+\cos 2x)} = \sqrt{2 \cdot 2\cos^2 x} = \sqrt{4\cos^2 x} = 2|\cos x|
-\]
-
-Since \(\cos x\) can be positive or negative, we'll keep it as \(2|\cos x|\) for now.
-
-Next, let's look at the second part of the first factor: \(-\sqrt{36-4\sqrt{5}} \sin x + 2\). This seems a bit complicated, but perhaps we can find a way to simplify or bound it.
-
-Now, let's consider the second factor: \(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\). Again, we can use trigonometric identities to simplify \(\cos 2y\). Recall that \(\cos 2y = 2\cos^2 y - 1\), so:
-
-\[
-3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y = 3 + 2\sqrt{10-\sqrt{5}} \cos y - (2\cos^2 y - 1) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y
-\]
-
-This is a quadratic in terms of \(\cos y\), so we might be able to find its minimum value.
-
-Wait, perhaps it's better to think about minimizing each factor separately and then multiply the minima together. Let's try that.
-
-First, let's find the minimum of the first factor:
-
-\[
-F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2
-\]
-
-This seems complicated due to the absolute value and the trigonometric functions. Maybe we can express it in terms of a single trigonometric function.
-
-Alternatively, perhaps we can use calculus to find the minimum of \(F_1(x)\). Let's try that.
-
-Let's consider \(F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2\). To find the minimum, we can take the derivative and set it to zero.
-
-However, the absolute value makes this tricky. Perhaps we can consider the cases where \(\cos x\) is positive and negative separately.
-
-Case 1: \(\cos x \geq 0\)
-
-Then \(F_1(x) = 2\cos x - \sqrt{36-4\sqrt{5}} \sin x + 2\). Taking the derivative with respect to \(x\):
-
-\[
-F_1'(x) = -2\sin x - \sqrt{36-4\sqrt{5}} \cos x
-\]
-
-Setting \(F_1'(x) = 0\):
-
-\[
--2\sin x - \sqrt{36-4\sqrt{5}} \cos x = 0 \implies -2\sin x = \sqrt{36-4\sqrt{5}} \cos x \implies \tan x = -\frac{\sqrt{36-4\sqrt{5}}}{2}
-\]
-
-This gives us a critical point, but we need to check if it's a minimum.
-
-Alternatively, perhaps we can use trigonometric identities to express \(F_1(x)\) as a single trigonometric function.
-
-Recall that \(A\sin x + B\cos x = R\sin(x + \alpha)\), where \(R = \sqrt{A^2 + B^2}\) and \(\tan \alpha = \frac{B}{A}\).
-
-In our case, \(A = -\sqrt{36-4\sqrt{5}}\) and \(B = 2\), so:
-
-\[
-R = \sqrt{(-\sqrt{36-4\sqrt{5}})^2 + 2^2} = \sqrt{36-4\sqrt{5} + 4} = \sqrt{40-4\sqrt{5}} = 2\sqrt{10-\sqrt{5}}
-\]
-
-So, \(F_1(x) = 2\sqrt{10-\sqrt{5}} \sin(x + \alpha) + 2\).
-
-The minimum value of \(\sin(x + \alpha)\) is \(-1\), so the minimum of \(F_1(x)\) is:
-
-\[
-2\sqrt{10-\sqrt{5}} \cdot (-1) + 2 = -2\sqrt{10-\sqrt{5}} + 2
-\]
-
-Now, let's find the minimum of the second factor:
-
-\[
-F_2(y) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y
-\]
-
-This is a quadratic in \(\cos y\). Let \(z = \cos y\), then:
-
-\[
-F_2(y) = -2z^2 + 2\sqrt{10-\sqrt{5}} z + 4
-\]
-
-This is a quadratic equation in \(z\), and since the coefficient of \(z^2\) is negative, it has a maximum value. However, we need the minimum value of \(F_2(y)\). The minimum will occur at the boundaries of \(z\), i.e., when \(z = 1\) or \(z = -1\).
-
-Let's evaluate \(F_2(y)\) at \(z = 1\) and \(z = -1\).
-
-At \(z = 1\):
-
-\[
-F_2(y) = -2(1)^2 + 2\sqrt{10-\sqrt{5}} (1) + 4 = -2 + 2\sqrt{10-\sqrt{5}} + 4 = 2 + 2\sqrt{10-\sqrt{5}}
-\]
-
-At \(z = -1\):
-
-\[
-F_2(y) = -2(-1)^2 + 2\sqrt{10-\sqrt{5}} (-1) + 4 = -2 - 2\sqrt{10-\sqrt{5}} + 4 = 2 - 2\sqrt{10-\sqrt{5}}
-\]
-
-Since \(\sqrt{10-\sqrt{5}} > 0\), the minimum value of \(F_2(y)\) is \(2 - 2\sqrt{10-\sqrt{5}}\).
-
-Now, the minimum value of the entire expression is the product of the minima of \(F_1(x)\) and \(F_2(y)\):
-
-\[
-(-2\sqrt{10-\sqrt{5}} + 2) \cdot (2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}})
-\]
-
-Let's compute this product:
-
-\[
-(-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} \cdot 2) + (-2\sqrt{10-\sqrt{5}} \cdot -2\sqrt{10-\sqrt{5}}) + (2 \cdot 2) + (2 \cdot -2\sqrt{10-\sqrt{5}})
-\]
-
-Simplifying each term:
-
-\[
-= -4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 - 4\sqrt{10-\sqrt{5}}
-\]
-
-Combine like terms:
-
-\[
-= -4\sqrt{10-\sqrt{5}} - 4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 = -8\sqrt{10-\sqrt{5}} + 40 - 4\sqrt{5} + 4 = -8\sqrt{10-\sqrt{5}} + 44 - 4\sqrt{5}
-\]
-
-This expression is quite complicated, and calculating its exact value might not be straightforward. However, we can approximate the value.
-
-First, let's approximate \(\sqrt{10 - \sqrt{5}}\). Since \(\sqrt{5} \approx 2.236\), we have:
-
-\[
-\sqrt{10 - 2.236} = \sqrt{7.764} \approx 2.786
-\]
-
-Similarly, \(\sqrt{5} \approx 2.236\).
-
-Now, let's approximate the expression:
-
-\[
--8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768
-\]
-
-Rounding this to the nearest integer gives us 13.
-
-Wait, let's double-check the calculations to ensure accuracy.
-
-First, let's compute \(\sqrt{10 - \sqrt{5}}\) more precisely.
-
-\(\sqrt{5} \approx 2.2360679775\), so:
-
-\[
-\sqrt{10 - 2.2360679775} = \sqrt{7.7639320225} \approx 2.786
-\]
-
-Now, compute the expression:
-
-\[
--8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768
-\]
-
-Rounding 12.768 to the nearest integer gives us 13.
-
-Thus, the minimum value of the expression is approximately 13.
-</think>
-
-<answer>
-\boxed{13}
-</answer>
+---
+license: apache-2.0
+datasets:
+- qingy2024/PR2-SFT
+language:
+- zho
+- eng
+- fra
+- spa
+- por
+- deu
+- ita
+- rus
+- jpn
+- kor
+- vie
+- tha
+- ara
+base_model:
+- Qwen/Qwen2.5-14B-Instruct
+---
+
+## PR2 14B Instruct
+
+PR2 is an experimental fine tune of Qwen2.5 14B Instruct, incorporating planning and reasoning before outputting a final answer. It is trained for 2 epochs on the verified subset of qingy2024/PR2-SFT.
+
+**Example:**
+
+Input:
+
+```
+Find the minimum value of the expression \\(\left(\sqrt{2(1+\cos 2 x)}-\sqrt{36-4 \sqrt{5}} \sin x+2\right) \cdot \left(3+2 \sqrt{10-\sqrt{5}} \cos y-\cos 2 y\right)\\). If the answer is not an integer, round it to the nearest integer.
+
+First, create a high level overview in <plan></plan> tags, then do your reasoning in <think></think> tags, and put your final answer in <answer></answer>.
+```
+
+Output:
+
+```
+<plan>
+1. Simplify the expression by breaking it down into manageable parts.
+2. Use trigonometric identities to simplify terms involving trigonometric functions.
+3. Analyze the structure of the expression to identify potential optimization strategies.
+4. Consider the possibility of minimizing each part of the expression separately.
+5. Calculate the minimum value of the entire expression and round it to the nearest integer if necessary.
+</plan>
+
+<think>
+Hmm... let me start by simplifying the expression. The expression is:
+
+\[
+\left(\sqrt{2(1+\cos 2x)} - \sqrt{36-4\sqrt{5}} \sin x + 2\right) \cdot \left(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\right)
+\]
+
+First, I notice that \(\sqrt{2(1+\cos 2x)}\) can be simplified using a trigonometric identity. Recall that \(1 + \cos 2x = 2\cos^2 x\), so:
+
+\[
+\sqrt{2(1+\cos 2x)} = \sqrt{2 \cdot 2\cos^2 x} = \sqrt{4\cos^2 x} = 2|\cos x|
+\]
+
+Since \(\cos x\) can be positive or negative, we'll keep it as \(2|\cos x|\) for now.
+
+Next, let's look at the second part of the first factor: \(-\sqrt{36-4\sqrt{5}} \sin x + 2\). This seems a bit complicated, but perhaps we can find a way to simplify or bound it.
+
+Now, let's consider the second factor: \(3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y\). Again, we can use trigonometric identities to simplify \(\cos 2y\). Recall that \(\cos 2y = 2\cos^2 y - 1\), so:
+
+\[
+3 + 2\sqrt{10-\sqrt{5}} \cos y - \cos 2y = 3 + 2\sqrt{10-\sqrt{5}} \cos y - (2\cos^2 y - 1) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y
+\]
+
+This is a quadratic in terms of \(\cos y\), so we might be able to find its minimum value.
+
+Wait, perhaps it's better to think about minimizing each factor separately and then multiply the minima together. Let's try that.
+
+First, let's find the minimum of the first factor:
+
+\[
+F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2
+\]
+
+This seems complicated due to the absolute value and the trigonometric functions. Maybe we can express it in terms of a single trigonometric function.
+
+Alternatively, perhaps we can use calculus to find the minimum of \(F_1(x)\). Let's try that.
+
+Let's consider \(F_1(x) = 2|\cos x| - \sqrt{36-4\sqrt{5}} \sin x + 2\). To find the minimum, we can take the derivative and set it to zero.
+
+However, the absolute value makes this tricky. Perhaps we can consider the cases where \(\cos x\) is positive and negative separately.
+
+Case 1: \(\cos x \geq 0\)
+
+Then \(F_1(x) = 2\cos x - \sqrt{36-4\sqrt{5}} \sin x + 2\). Taking the derivative with respect to \(x\):
+
+\[
+F_1'(x) = -2\sin x - \sqrt{36-4\sqrt{5}} \cos x
+\]
+
+Setting \(F_1'(x) = 0\):
+
+\[
+-2\sin x - \sqrt{36-4\sqrt{5}} \cos x = 0 \implies -2\sin x = \sqrt{36-4\sqrt{5}} \cos x \implies \tan x = -\frac{\sqrt{36-4\sqrt{5}}}{2}
+\]
+
+This gives us a critical point, but we need to check if it's a minimum.
+
+Alternatively, perhaps we can use trigonometric identities to express \(F_1(x)\) as a single trigonometric function.
+
+Recall that \(A\sin x + B\cos x = R\sin(x + \alpha)\), where \(R = \sqrt{A^2 + B^2}\) and \(\tan \alpha = \frac{B}{A}\).
+
+In our case, \(A = -\sqrt{36-4\sqrt{5}}\) and \(B = 2\), so:
+
+\[
+R = \sqrt{(-\sqrt{36-4\sqrt{5}})^2 + 2^2} = \sqrt{36-4\sqrt{5} + 4} = \sqrt{40-4\sqrt{5}} = 2\sqrt{10-\sqrt{5}}
+\]
+
+So, \(F_1(x) = 2\sqrt{10-\sqrt{5}} \sin(x + \alpha) + 2\).
+
+The minimum value of \(\sin(x + \alpha)\) is \(-1\), so the minimum of \(F_1(x)\) is:
+
+\[
+2\sqrt{10-\sqrt{5}} \cdot (-1) + 2 = -2\sqrt{10-\sqrt{5}} + 2
+\]
+
+Now, let's find the minimum of the second factor:
+
+\[
+F_2(y) = 4 + 2\sqrt{10-\sqrt{5}} \cos y - 2\cos^2 y
+\]
+
+This is a quadratic in \(\cos y\). Let \(z = \cos y\), then:
+
+\[
+F_2(y) = -2z^2 + 2\sqrt{10-\sqrt{5}} z + 4
+\]
+
+This is a quadratic equation in \(z\), and since the coefficient of \(z^2\) is negative, it has a maximum value. However, we need the minimum value of \(F_2(y)\). The minimum will occur at the boundaries of \(z\), i.e., when \(z = 1\) or \(z = -1\).
+
+Let's evaluate \(F_2(y)\) at \(z = 1\) and \(z = -1\).
+
+At \(z = 1\):
+
+\[
+F_2(y) = -2(1)^2 + 2\sqrt{10-\sqrt{5}} (1) + 4 = -2 + 2\sqrt{10-\sqrt{5}} + 4 = 2 + 2\sqrt{10-\sqrt{5}}
+\]
+
+At \(z = -1\):
+
+\[
+F_2(y) = -2(-1)^2 + 2\sqrt{10-\sqrt{5}} (-1) + 4 = -2 - 2\sqrt{10-\sqrt{5}} + 4 = 2 - 2\sqrt{10-\sqrt{5}}
+\]
+
+Since \(\sqrt{10-\sqrt{5}} > 0\), the minimum value of \(F_2(y)\) is \(2 - 2\sqrt{10-\sqrt{5}}\).
+
+Now, the minimum value of the entire expression is the product of the minima of \(F_1(x)\) and \(F_2(y)\):
+
+\[
+(-2\sqrt{10-\sqrt{5}} + 2) \cdot (2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}})
+\]
+
+Let's compute this product:
+
+\[
+(-2\sqrt{10-\sqrt{5}} + 2)(2 - 2\sqrt{10-\sqrt{5}}) = (-2\sqrt{10-\sqrt{5}} \cdot 2) + (-2\sqrt{10-\sqrt{5}} \cdot -2\sqrt{10-\sqrt{5}}) + (2 \cdot 2) + (2 \cdot -2\sqrt{10-\sqrt{5}})
+\]
+
+Simplifying each term:
+
+\[
+= -4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 - 4\sqrt{10-\sqrt{5}}
+\]
+
+Combine like terms:
+
+\[
+= -4\sqrt{10-\sqrt{5}} - 4\sqrt{10-\sqrt{5}} + 4(10-\sqrt{5}) + 4 = -8\sqrt{10-\sqrt{5}} + 40 - 4\sqrt{5} + 4 = -8\sqrt{10-\sqrt{5}} + 44 - 4\sqrt{5}
+\]
+
+This expression is quite complicated, and calculating its exact value might not be straightforward. However, we can approximate the value.
+
+First, let's approximate \(\sqrt{10 - \sqrt{5}}\). Since \(\sqrt{5} \approx 2.236\), we have:
+
+\[
+\sqrt{10 - 2.236} = \sqrt{7.764} \approx 2.786
+\]
+
+Similarly, \(\sqrt{5} \approx 2.236\).
+
+Now, let's approximate the expression:
+
+\[
+-8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768
+\]
+
+Rounding this to the nearest integer gives us 13.
+
+Wait, let's double-check the calculations to ensure accuracy.
+
+First, let's compute \(\sqrt{10 - \sqrt{5}}\) more precisely.
+
+\(\sqrt{5} \approx 2.2360679775\), so:
+
+\[
+\sqrt{10 - 2.2360679775} = \sqrt{7.7639320225} \approx 2.786
+\]
+
+Now, compute the expression:
+
+\[
+-8 \cdot 2.786 + 44 - 4 \cdot 2.236 = -22.288 + 44 - 8.944 = 12.768
+\]
+
+Rounding 12.768 to the nearest integer gives us 13.
+
+Thus, the minimum value of the expression is approximately 13.
+</think>
+
+<answer>
+\boxed{13}
+</answer>
 ```