Errora401's picture
Update README.md
61803b8 verified
|
Raw
History Blame Contribute Delete
385 Bytes
---
license: mit
language:
- fr
- en
---
Sudoku_i=[i,j]
i,j integer
for i in range (0,9,1):
for j in range (9,0,-1):
if Sudoku_i[j]= Sudoku_i[9-j+1]
return redundancy.
else: return row_i
for i in range(0,9,3):
for j in range (9,0,-3):
if Sudoko_i[i]= Sudoku_i[j]:
i= i+1-i.div(9)×i
j= j-1-j.div(9)×j
return One call per line.