Automated MNLP evaluation report
- Model repo:
cs-552-2026-MandMP/math_model - Owner(s): group MandMP
- Generated at: 2026-06-01T06:13:57+00:00 (UTC)
- Pipeline: mnlp-project-ci
This PR is opened automatically by the course CI. It is non-blocking — you do not need to merge it. The next nightly run will refresh this file.
Summary
| Benchmark | Accuracy | Status |
|---|---|---|
| Math | 0.1900 | ok |
| Knowledge | — | not run |
| Multilingual | — | not run |
| Safety | — | not run |
Sample completions
Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample.
Math
Correct (1 shown)
reference:
3overall (7/8 completions correct)
extracted (✓):
3completion:
Okay, so I need to solve this problem about treeks, squigs, and goolees. Let me read it again: "Suppose 10 treeks have the same weight as 3 squigs plus 1 goolee, and 2 treeks together with 1 goolee weigh as much as 1 squig. Determine how many treeks have a combined weight equal to that of 1 squig." Alright, so there are three different units: treeks, squigs, and goolees. The problem gives me two ... [truncated 823 chars] ... herefore, x = 3T / T = 3. So, 3 treeks equal 1 squig. Wait, so the answer is 3? Let me check again. From equation (1): 10T = 3S + G From equation (2): 2T + G = S We can substitute S from equation (2) into equation (1): 10T = 3*(2T + G) + G => 10T = 6T + 3G + G => 10T = 6T + 4G => 4T = 4G => T = G. Then S = 2T + G = 2T + T = 3T. Therefore, 1 squig is 3 treeks. So yes, 3 treeks equal 1 squig. So the answer is 3. Therefore, boxed answer is \boxed{3}. But let me think again if I did everything correctly. Maybe I made an assumption? Wait, the problem says "how many treeks have a combined weight equal to that of 1 squig". So, if 1 squig is 3 treeks, then 3 treeks = 1 squig. So yes, answer is 3. Alternatively, maybe I should check with actual numbers. Let me assign some numbers. Let me assume that T = G = 1 unit. Then S = 3T = 3 units. Check equation (1): 10T = 10*1 = 10. On the other side, 3S + G = 3*3 + 1 = 9 + 1 = 10. Correct. Equation (2): 2T + G = 2*1 + 1 = 3, which equals S = 3. Correct. So yes, that works. Therefore, 3 treeks equal 1 squig. So answer is 3. Therefore, I think the answer is 3. So \boxed{3} is the answer. **Final Answer** \boxed{3} </think> \boxed{3}
Incorrect (1 shown)
reference:
31overall (0/8 completions correct)
extracted (✗):
<no answer>completion:
Okay, so I need to solve this problem where we have an equation |x² + a x + b| = c, and there are three distinct integer solutions for x. The variables a, b, and c are integers, and c is less than or equal to 2025. We need to find how many possible values of c there are. First, let me recall that absolute value equations like |f(x)| = c can be split into two cases: f(x) = c and f(x) = -c. So, in ... [truncated 823 chars] ... uting c = b - r1 r2 into a² = 4(b + c): a² = 4(b + b - r1 r2) = 4(2b - r1 r2) But also, from Q1, a = -(r1 + r2). Therefore, a² = (r1 + r2)^2. Therefore: (r1 + r2)^2 = 8b - 4 r1 r2 Let me write that equation: (r1 + r2)^2 = 8b - 4 r1 r2 Expanding left side: r1² + 2 r1 r2 + r2² = 8b - 4 r1 r2 Bring all terms to left side: r1² + 2 r1 r2 + r2² + 4 r1 r2 - 8b = 0 ⇒ r1² + 6 r1 r2 + r2² - 8b = 0 Therefore: 8b = r1² + 6 r1 r2 + r2² Therefore: b = [r1² + 6 r1 r2 + r2²]/8 But since b must be integer, the numerator must be divisible by 8. Similarly, since c = b - r1 r2, then c = [r1² + 6 r1 r2 + r2²]/8 - r1 r2 = [r1² + 6 r1 r2 + r2² - 8 r1 r2]/8 = [r1² - 2 r1 r2 + r2²]/8 = (r1 - r2)^2 / 8 Therefore, c = (r1 - r2)^2 / 8 Since c must be integer, (r1 - r2)^2 must be divisible by 8. Therefore, (r1 - r2)^2 ≡ 0 mod 8 ⇒ r1 - r2 is divisible by 2√2? Wait, no. Wait, if (r1 - r2)^2 is divisible by 8, then (r1 - r2)^2 must be divisible by 8. Let me think. If (r1 - r2)^2 is divisible by 8, then (r1 - r2)^2 has factors of 2^3. Therefore, (r1 - r2)^2 must be divisible by 8 ⇒ (r1 - r2)^2 is divisible by 8 ⇒ (r1 - r2) is divisible by 2√2? Wait, no. Let me think again. Suppose that (r1 - r2