EVAL_REPORT.md

# Automated MNLP evaluation report

- **Model repo:** [`cs-552-2026-MandMP/math_model`](https://huggingface.co/cs-552-2026-MandMP/math_model)
- **Owner(s):** group **MandMP**
- **Generated at:** 2026-06-01T06:13:57+00:00 (UTC)
- **Pipeline:** [mnlp-project-ci](https://github.com/eric11eca/mnlp-project-ci)

_This PR is opened automatically by the course CI. It is **non-blocking** — you do not need to merge it. The next nightly run will refresh this file._

## Summary

| Benchmark | Accuracy | Status |
|---|---:|---|
| Math | 0.1900 | ok |
| Knowledge | — | not run |
| Multilingual | — | not run |
| Safety | — | not run |

## Sample completions

_Prompts are intentionally omitted to avoid revealing benchmark contents. For multi-completion problems, only one completion is shown per sample._

### Math

**Correct** (1 shown)

- **reference**: `3`
- **overall** (7/8 completions correct)
- **extracted** (✓): `3`
- **completion**:

    ```text
    Okay, so I need to solve this problem about treeks, squigs, and goolees. Let me read it again:
    
    "Suppose 10 treeks have the same weight as 3 squigs plus 1 goolee, and 2 treeks together with 1 goolee weigh as much as 1 squig. Determine how many treeks have a combined weight equal to that of 1 squig."
    
    Alright, so there are three different units: treeks, squigs, and goolees. The problem gives me two
    
    ... [truncated 823 chars] ...
    
    herefore, x = 3T / T = 3. So, 3 treeks equal 1 squig.
    
    Wait, so the answer is 3?
    
    Let me check again.
    
    From equation (1): 10T = 3S + G
    
    From equation (2): 2T + G = S
    
    We can substitute S from equation (2) into equation (1):
    
    10T = 3*(2T + G) + G => 10T = 6T + 3G + G => 10T = 6T + 4G => 4T = 4G => T = G.
    
    Then S = 2T + G = 2T + T = 3T. Therefore, 1 squig is 3 treeks. So yes, 3 treeks equal 1 squig.
    
    So the answer is 3. Therefore, boxed answer is \boxed{3}.
    
    But let me think again if I did everything correctly. Maybe I made an assumption?
    
    Wait, the problem says "how many treeks have a combined weight equal to that of 1 squig". So, if 1 squig is 3 treeks, then 3 treeks = 1 squig. So yes, answer is 3.
    
    Alternatively, maybe I should check with actual numbers. Let me assign some numbers.
    
    Let me assume that T = G = 1 unit. Then S = 3T = 3 units.
    
    Check equation (1): 10T = 10*1 = 10. On the other side, 3S + G = 3*3 + 1 = 9 + 1 = 10. Correct.
    
    Equation (2): 2T + G = 2*1 + 1 = 3, which equals S = 3. Correct.
    
    So yes, that works. Therefore, 3 treeks equal 1 squig. So answer is 3.
    
    Therefore, I think the answer is 3. So \boxed{3} is the answer.
    
    **Final Answer**
    \boxed{3}
    </think>
    
    \boxed{3}
    ```

**Incorrect** (1 shown)

- **reference**: `31`
- **overall** (0/8 completions correct)
- **extracted** (✗): `<no answer>`
- **completion**:

    ```text
    Okay, so I need to solve this problem where we have an equation |x² + a x + b| = c, and there are three distinct integer solutions for x. The variables a, b, and c are integers, and c is less than or equal to 2025. We need to find how many possible values of c there are.
    
    First, let me recall that absolute value equations like |f(x)| = c can be split into two cases: f(x) = c and f(x) = -c. So, in
    
    ... [truncated 823 chars] ...
    
    uting c = b - r1 r2 into a² = 4(b + c):
    
    a² = 4(b + b - r1 r2) = 4(2b - r1 r2)
    
    But also, from Q1, a = -(r1 + r2). Therefore, a² = (r1 + r2)^2.
    
    Therefore:
    
    (r1 + r2)^2 = 8b - 4 r1 r2
    
    Let me write that equation:
    
    (r1 + r2)^2 = 8b - 4 r1 r2
    
    Expanding left side:
    
    r1² + 2 r1 r2 + r2² = 8b - 4 r1 r2
    
    Bring all terms to left side:
    
    r1² + 2 r1 r2 + r2² + 4 r1 r2 - 8b = 0 ⇒ r1² + 6 r1 r2 + r2² - 8b = 0
    
    Therefore:
    
    8b = r1² + 6 r1 r2 + r2²
    
    Therefore:
    
    b = [r1² + 6 r1 r2 + r2²]/8
    
    But since b must be integer, the numerator must be divisible by 8.
    
    Similarly, since c = b - r1 r2, then c = [r1² + 6 r1 r2 + r2²]/8 - r1 r2 = [r1² + 6 r1 r2 + r2² - 8 r1 r2]/8 = [r1² - 2 r1 r2 + r2²]/8 = (r1 - r2)^2 / 8
    
    Therefore, c = (r1 - r2)^2 / 8
    
    Since c must be integer, (r1 - r2)^2 must be divisible by 8. Therefore, (r1 - r2)^2 ≡ 0 mod 8 ⇒ r1 - r2 is divisible by 2√2? Wait, no. Wait, if (r1 - r2)^2 is divisible by 8, then (r1 - r2)^2 must be divisible by 8. Let me think.
    
    If (r1 - r2)^2 is divisible by 8, then (r1 - r2)^2 has factors of 2^3. Therefore, (r1 - r2)^2 must be divisible by 8 ⇒ (r1 - r2)^2 is divisible by 8 ⇒ (r1 - r2) is divisible by 2√2? Wait, no. Let me think again.
    
    Suppose that (r1 - r2
    ```