message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the ... | instruction | 0 | 102,436 | 0 | 204,872 |
Yes | output | 1 | 102,436 | 0 | 204,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the ... | instruction | 0 | 102,437 | 0 | 204,874 |
No | output | 1 | 102,437 | 0 | 204,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the ... | instruction | 0 | 102,438 | 0 | 204,876 |
No | output | 1 | 102,438 | 0 | 204,877 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the ... | instruction | 0 | 102,439 | 0 | 204,878 |
No | output | 1 | 102,439 | 0 | 204,879 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
DZY loves collecting special strings which only contain lowercase letters. For each lowercase letter c DZY knows its value wc. For each special string s = s1s2... s|s| (|s| is the length of the ... | instruction | 0 | 102,440 | 0 | 204,880 |
No | output | 1 | 102,440 | 0 | 204,881 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,885 | 0 | 205,770 |
Tags: greedy, implementation
Correct Solution:
```
a = input()
s = ""
final = ""
count = 0
for i in a:
if i=='1':
count+=1
else:
s+=i
s+='2'
i = s.find('2')
print(s[:i] + '1'*count + s[i:-1])
``` | output | 1 | 102,885 | 0 | 205,771 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,886 | 0 | 205,772 |
Tags: greedy, implementation
Correct Solution:
```
a = input()
b = ''
i0 = 0
i1 = 0
i2 = 0
tmpi0 = 0
c = []
flag = False
for i in range(len(a)):
if a[i] == '1':
i1 += 1
elif i0 != 0 and a[i] == '2':
b += '0'*i0
i0 = 0
elif i2 != 0 and a[i] == '0':
b += '2'*i2
i2 = 0
... | output | 1 | 102,886 | 0 | 205,773 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,887 | 0 | 205,774 |
Tags: greedy, implementation
Correct Solution:
```
s=input()
one=s.count("1")
if one==0:print(s);exit()
ind=s.find("2")
ans=""
for i in range(len(s)):
if i==ind:ans+="1"*one
if s[i]=="1":continue
ans+=s[i]
if ind==-1:ans+="1"*one
print(ans)
``` | output | 1 | 102,887 | 0 | 205,775 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,888 | 0 | 205,776 |
Tags: greedy, implementation
Correct Solution:
```
s=input()
l=len(s)
i=0
while(i<l and s[i]!='2'):
i+=1
a=sorted(s[0:i])
fir=[]
sec=[]
while(i<l):
if(s[i]=='1'):
fir+=[s[i]]
else:
sec+=[s[i]]
i+=1
r=a+fir+sec
print(''.join(r))
``` | output | 1 | 102,888 | 0 | 205,777 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,889 | 0 | 205,778 |
Tags: greedy, implementation
Correct Solution:
```
def scanf(obj=list, type=int):
return obj(map(type, input().split()))
s = input()[-1::-1]
ans = ''
z = on = 0
for i in range(len(s)):
if s[i] == '0': z += 1
if s[i] == '1': on += 1
if s[i] == '2':
ans += '0' * z + '2'
z = 0
ans += '1' * ... | output | 1 | 102,889 | 0 | 205,779 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,890 | 0 | 205,780 |
Tags: greedy, implementation
Correct Solution:
```
s=list(input())
s.append('2')
l=[]
c=s.count('1')
f=0
for i in range(len(s)):
if s[i]=='2' and f==0:
for j in range(c):
l.append('1')
f=1
l.append('2')
elif s[i]!='1':
l.append(s[i])
l=l[:len(s)-1]
print(''.join(l))
`... | output | 1 | 102,890 | 0 | 205,781 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,891 | 0 | 205,782 |
Tags: greedy, implementation
Correct Solution:
```
s = list(input())
for i in range(len(s)):
s[i] = int(s[i])
n = len(s)
ans = [i for i in s if i == 0 or i == 2]
c1 = sum([1 for i in s if i == 1])
f2 = n
for i in range(len(ans)):
if ans[i] == 2:
f2 = i
break
ans1 = ans[:f2] +[1 for i in range(c1... | output | 1 | 102,891 | 0 | 205,783 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "10" or vice versa) or any two adjacent (consecut... | instruction | 0 | 102,892 | 0 | 205,784 |
Tags: greedy, implementation
Correct Solution:
```
s = input()
s = s + "2"
t = s.replace("1", '')
i = t.find("2")
print(t[:i] + "1"*s.count("1")+t[i:-1])
``` | output | 1 | 102,892 | 0 | 205,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,893 | 0 | 205,786 |
Yes | output | 1 | 102,893 | 0 | 205,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,894 | 0 | 205,788 |
Yes | output | 1 | 102,894 | 0 | 205,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,895 | 0 | 205,790 |
Yes | output | 1 | 102,895 | 0 | 205,791 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,896 | 0 | 205,792 |
Yes | output | 1 | 102,896 | 0 | 205,793 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,897 | 0 | 205,794 |
No | output | 1 | 102,897 | 0 | 205,795 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,898 | 0 | 205,796 |
No | output | 1 | 102,898 | 0 | 205,797 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,899 | 0 | 205,798 |
No | output | 1 | 102,899 | 0 | 205,799 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a ternary string (it is a string which consists only of characters '0', '1' and '2').
You can swap any two adjacent (consecutive) characters '0' and '1' (i.e. replace "01" with "1... | instruction | 0 | 102,900 | 0 | 205,800 |
No | output | 1 | 102,900 | 0 | 205,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,978 | 0 | 205,956 |
Tags: greedy, implementation
Correct Solution:
```
def subseq(s, t):
lenS = len(s)
lenT = len(t)
i = 0
j = 0
while i < lenS and j < lenT:
if s[i] == t[j]:
j += 1
i += 1
return lenT == j
s = input()
t = input()
lenS = len(s)
result = 0
for l in range(lenS):
... | output | 1 | 102,978 | 0 | 205,957 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,979 | 0 | 205,958 |
Tags: greedy, implementation
Correct Solution:
```
def find_sub(s, t):
k=0
for i in s:
if k==len(t):
break
if i==t[k]:
k=k+1
if k==len(t):
return True
else:
return False
def process(s, t):
res=0
for l in range(1, len(s)):
for i in range(len(s)-l+1):
j=i+l-1
if f... | output | 1 | 102,979 | 0 | 205,959 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,980 | 0 | 205,960 |
Tags: greedy, implementation
Correct Solution:
```
s = input()
t = input()
n = len(t)
first = [0] * n
last = [0] * n
p = 0
i = 0
while(p<n):
if(s[i] == t[p]):
first[p] = i
p+=1
i+=1
p = n-1
i = len(s)-1
while(p>=0):
if(s[i] == t[p]):
last[p] = i
p-=1
i-=1
# print(first)
#... | output | 1 | 102,980 | 0 | 205,961 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,981 | 0 | 205,962 |
Tags: greedy, implementation
Correct Solution:
```
import sys
from collections import defaultdict
def get_after(l,num):
low,high=0,len(l)-1
ans=len(l)
while low<=high:
mid=(low+high)//2
if l[mid]>num:
ans=min(ans,mid)
high=mid-1
else:
low=mid+1
... | output | 1 | 102,981 | 0 | 205,963 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,982 | 0 | 205,964 |
Tags: greedy, implementation
Correct Solution:
```
big=input()
small=input()
ans=0
for i in range(0,len(big)):
for j in range(i,len(big)):
pos=0
for k in range(0,len(big)):
if k>=i and k<=j:
continue
if big[k]==small[pos]:
pos+=1
if... | output | 1 | 102,982 | 0 | 205,965 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,983 | 0 | 205,966 |
Tags: greedy, implementation
Correct Solution:
```
s=str(input())
t=str(input())
def lka(i):
if i==0:return(0)
for j in range(len(s)-i+1):
if kayna(s[:j]+s[j+i:]):
return(i)
return(lka(i-1))
def kayna(s):
i=0
j=0
while i<len(t) and j<len(s):
if s[j]==t[i]:
i+=1
j+=1
else: j+=1
if i==len(t):retur... | output | 1 | 102,983 | 0 | 205,967 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,984 | 0 | 205,968 |
Tags: greedy, implementation
Correct Solution:
```
def check(s, t):
i = 0
j = 0
while i < len(s) and j < len(t):
if (s[i] == t[j]):
j += 1
i += 1
return j == len(t)
s = input()
t = input()
ans = 0
for i in range(len(s) + 1):
for j in range(i, len(s) + 1):
if (check(s[:i] + s[j:]... | output | 1 | 102,984 | 0 | 205,969 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t can be obtained from s by removing some (possi... | instruction | 0 | 102,985 | 0 | 205,970 |
Tags: greedy, implementation
Correct Solution:
```
from sys import stdin
input = stdin.readline
s = input()
t = input()
n = len(t)
low = [0 for i in range(len(t))]
high = [0 for i in range(len(t))]
acc = 0
for i in range(n):
acc_t = t[i]
while acc_t != s[acc]: acc += 1
low[i] = acc
acc += 1
ac... | output | 1 | 102,985 | 0 | 205,971 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,986 | 0 | 205,972 |
Yes | output | 1 | 102,986 | 0 | 205,973 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,987 | 0 | 205,974 |
Yes | output | 1 | 102,987 | 0 | 205,975 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,988 | 0 | 205,976 |
Yes | output | 1 | 102,988 | 0 | 205,977 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,989 | 0 | 205,978 |
Yes | output | 1 | 102,989 | 0 | 205,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,990 | 0 | 205,980 |
No | output | 1 | 102,990 | 0 | 205,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,991 | 0 | 205,982 |
No | output | 1 | 102,991 | 0 | 205,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,992 | 0 | 205,984 |
No | output | 1 | 102,992 | 0 | 205,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the length of the string.
You are given a string s and a string t, both consisting only of lowercase Latin letters. It is guaranteed that t... | instruction | 0 | 102,993 | 0 | 205,986 |
No | output | 1 | 102,993 | 0 | 205,987 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,026 | 0 | 206,052 |
Tags: constructive algorithms, greedy
Correct Solution:
```
d = {'a', 'b', 'c'}
for _ in range(int(input())):
s = input()
if s.find('aa') != -1 or s.find('bb') != -1 or s.find('cc') != -1:
print(-1)
elif s == '?':
print('a')
else:
s = list(s)
if s[0] == '?':
i... | output | 1 | 103,026 | 0 | 206,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,027 | 0 | 206,054 |
Tags: constructive algorithms, greedy
Correct Solution:
```
import sys
import collections
from collections import Counter
import itertools
import math
import timeit
#input = sys.stdin.readline
#########################
# imgur.com/Pkt7iIf.png #
#########################
def sieve(n):
if n < 2: return list()
... | output | 1 | 103,027 | 0 | 206,055 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,028 | 0 | 206,056 |
Tags: constructive algorithms, greedy
Correct Solution:
```
t=int(input())
for i in range(t):
st=input()
ans=''
fl = False
for i in range(len(st)-1):
if st[i]!="?":
ans+=st[i]
if i!=0:
if st[i-1]==st[i]:
fl = True
break
else:
if i>=1:
if ans[i-1]=="a":
if st[i+1]!="b":
ans... | output | 1 | 103,028 | 0 | 206,057 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,029 | 0 | 206,058 |
Tags: constructive algorithms, greedy
Correct Solution:
```
lis=['a','b','c']
for _ in range(int(input())):
s=list(input())
f,i=0,0
if(len(s)==1 and s[0]=='?'):
print('a')
continue
if(s[0]=='?'):
for k in range(0,3):
if(s[1]!=lis[k]):
s[0]=lis[k]
... | output | 1 | 103,029 | 0 | 206,059 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,030 | 0 | 206,060 |
Tags: constructive algorithms, greedy
Correct Solution:
```
t = int(input())
while t:
t += -1
s = input()
s = list(s)
s.insert(0, '0')
s.append('0')
s.append('1')
ch = 1
for i in range(1, len(s) - 1):
if s[i] == '?':
if s[i - 1] != 'a' and s[i + 1] != 'a': s[i] = 'a'
... | output | 1 | 103,030 | 0 | 206,061 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,031 | 0 | 206,062 |
Tags: constructive algorithms, greedy
Correct Solution:
```
t=int(input())
for i in range(t):
s=input()
if "aa" in s or "bb" in s or "cc" in s:
print(-1)
elif len(s)==1 and s[0]=="?":
print("a")
else:
s=list(s)
for j in range(len(s)):
if s[j]=="?":
... | output | 1 | 103,031 | 0 | 206,063 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,032 | 0 | 206,064 |
Tags: constructive algorithms, greedy
Correct Solution:
```
#code
def solution(a,b):
s=['a','b','c']
s=set(s)
t=[a,b]
s1= s-set(t)
s1=list(s1)
return (s1[0])
def checkString(s):
if(len(s)==1):
return "a"
for i in range(len(s)):
if(s[i]=='?'):
... | output | 1 | 103,032 | 0 | 206,065 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to construct a beautiful string. He has a string s, co... | instruction | 0 | 103,033 | 0 | 206,066 |
Tags: constructive algorithms, greedy
Correct Solution:
```
def dryrun(s):
for i in range(1,len(s)):
if(s[i]!='?'):
if(s[i-1]==s[i]):
return 0
return 1
def replaceq(l,r):
re = ''
if(l==0 and r==0):
re+='a'
elif(l!=0 and r!=0):
if(l==r=='a'):
... | output | 1 | 103,033 | 0 | 206,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to cons... | instruction | 0 | 103,034 | 0 | 206,068 |
Yes | output | 1 | 103,034 | 0 | 206,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to cons... | instruction | 0 | 103,035 | 0 | 206,070 |
Yes | output | 1 | 103,035 | 0 | 206,071 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to cons... | instruction | 0 | 103,036 | 0 | 206,072 |
Yes | output | 1 | 103,036 | 0 | 206,073 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to cons... | instruction | 0 | 103,037 | 0 | 206,074 |
Yes | output | 1 | 103,037 | 0 | 206,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A string is called beautiful if no two consecutive characters are equal. For example, "ababcb", "a" and "abab" are beautiful strings, while "aaaaaa", "abaa" and "bb" are not.
Ahcl wants to cons... | instruction | 0 | 103,038 | 0 | 206,076 |
No | output | 1 | 103,038 | 0 | 206,077 |
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