message stringlengths 2 23.8k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,548 | 0 | 209,096 |
Yes | output | 1 | 104,548 | 0 | 209,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,549 | 0 | 209,098 |
Yes | output | 1 | 104,549 | 0 | 209,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,550 | 0 | 209,100 |
Yes | output | 1 | 104,550 | 0 | 209,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,551 | 0 | 209,102 |
No | output | 1 | 104,551 | 0 | 209,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,552 | 0 | 209,104 |
No | output | 1 | 104,552 | 0 | 209,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,553 | 0 | 209,106 |
No | output | 1 | 104,553 | 0 | 209,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We start with a string s consisting only of the digits 1, 2, or 3. The length of s is denoted by |s|. For each i from 1 to |s|, the i-th character of s is denoted by s_i.
There is one cursor. ... | instruction | 0 | 104,554 | 0 | 209,108 |
No | output | 1 | 104,554 | 0 | 209,109 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,555 | 0 | 209,110 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import math
import sys
for _ in range(int(input())):
n,m=(map(int,sys.stdin.readline().split()))
k=n-m
p=m+1
c=(k//p)
ans=(n*(n+1))//2
rem=k%p
ans1=(rem*((c+1)*(c+2)))//2
ans2=0
ans2=(c*(c+1)*(p-rem)... | output | 1 | 104,555 | 0 | 209,111 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,556 | 0 | 209,112 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
t = int(input())
C = [list(map(int,input().split())) for i in range(t)]
# ANS = [0] * t
# t = 10**5
# C = [[523422132331, 102342223434] for i in range(t)]
def c(x, y):
if x % 2 == 0:
retur... | output | 1 | 104,556 | 0 | 209,113 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,557 | 0 | 209,114 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import sys
input=sys.stdin.readline
for _ in range(int(input())):
n,m=map(int,input().split())
grps=m+1
zeach=(n-m)//grps
extras=(n-m)%grps
print( (n*(n+1)//2)- (zeach*(zeach+1)//2)*grps -(extras)*(zeach+1) )
``` | output | 1 | 104,557 | 0 | 209,115 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,558 | 0 | 209,116 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
from collections import Counter
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
... | output | 1 | 104,558 | 0 | 209,117 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,559 | 0 | 209,118 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import sys
input = sys.stdin.readline
T = int(input())
for _ in range(T):
n, m = list(map(int, input().split()))
S = 0
x = (n - m) // (m + 1)
z = (n - m) % (m + 1)
S += (m + 1 - z) * (x * (x + 1)) // 2
S += z * (x ... | output | 1 | 104,559 | 0 | 209,119 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,560 | 0 | 209,120 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
"""
// Author : snape_here - Susanta Mukherjee
"""
from __future__ import division, print_function
import os,sys
from io import BytesIO, IOBase
if sys.version_info[0] < 3:
from __builtin__ import xrange as range
from fut... | output | 1 | 104,560 | 0 | 209,121 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,561 | 0 | 209,122 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import sys
inf = 1 << 64
def input():
return sys.stdin.readline().rstrip()
def slv():
n, m = map(int, input().split())
u, v = divmod(n - m, m + 1)
ans = n * (n + 1)//2 - v*(u + 1)*(u + 2)//2 - (m + 1 - v)*u*(u + 1)//2
... | output | 1 | 104,561 | 0 | 209,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the number of substrings in the string s that contains a... | instruction | 0 | 104,562 | 0 | 209,124 |
Tags: binary search, combinatorics, greedy, math, strings
Correct Solution:
```
import sys
input=sys.stdin.readline
t=int(input())
for i in range(t):
n,m=map(int,input().split())
zeros=n-m
if zeros==0:
print((n*(n+1))//2)
else:
div=zeros//(m+1)
rem=zeros%(m+1)
print(n*(n+... | output | 1 | 104,562 | 0 | 209,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,563 | 0 | 209,126 |
Yes | output | 1 | 104,563 | 0 | 209,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,564 | 0 | 209,128 |
Yes | output | 1 | 104,564 | 0 | 209,129 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,565 | 0 | 209,130 |
Yes | output | 1 | 104,565 | 0 | 209,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,566 | 0 | 209,132 |
Yes | output | 1 | 104,566 | 0 | 209,133 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,567 | 0 | 209,134 |
No | output | 1 | 104,567 | 0 | 209,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,568 | 0 | 209,136 |
No | output | 1 | 104,568 | 0 | 209,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,569 | 0 | 209,138 |
No | output | 1 | 104,569 | 0 | 209,139 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ayoub thinks that he is a very smart person, so he created a function f(s), where s is a binary string (a string which contains only symbols "0" and "1"). The function f(s) is equal to the numbe... | instruction | 0 | 104,570 | 0 | 209,140 |
No | output | 1 | 104,570 | 0 | 209,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't like that string, because it contained repeats: ... | instruction | 0 | 104,730 | 0 | 209,460 |
Tags: greedy, hashing, string suffix structures
Correct Solution:
```
def pow(x, exp, mod):
res = 1
while exp:
if exp & 1:
res = (res * x) % mod
x = (x * x) % mod
exp >>= 1
return res
MOD = 2 ** 121 - 1
M = int(1e9) + 1
n = int(input())
vals = list(map(int, input().sp... | output | 1 | 104,730 | 0 | 209,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't l... | instruction | 0 | 104,731 | 0 | 209,462 |
No | output | 1 | 104,731 | 0 | 209,463 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't l... | instruction | 0 | 104,732 | 0 | 209,464 |
No | output | 1 | 104,732 | 0 | 209,465 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't l... | instruction | 0 | 104,733 | 0 | 209,466 |
No | output | 1 | 104,733 | 0 | 209,467 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Once Bob saw a string. It contained so many different letters, that the letters were marked by numbers, but at the same time each letter could be met in the string at most 10 times. Bob didn't l... | instruction | 0 | 104,734 | 0 | 209,468 |
No | output | 1 | 104,734 | 0 | 209,469 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,009 | 0 | 210,018 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
def solve():
read=lambda:list(map(int,input().split()))
from collections import Counter as co
k,n=read()
s=input()
repeated=(len(s)!=len(set(s)))
etalon=co(s)
a=[]
kk=[]
ap=a.append
for i in range(k-1)... | output | 1 | 105,009 | 0 | 210,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,010 | 0 | 210,020 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
read=lambda:list(map(int,input().split()))
from collections import Counter as co
k,n=read()
s=input()
repeated=(len(s)!=len(set(s)))
etalon=co(s)
a=[]
kk=[]
ap=a.append
for i in range(k-1):
ap(input())
if co(a[-1])!=etalon:
print... | output | 1 | 105,010 | 0 | 210,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,011 | 0 | 210,022 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
import collections
def swapCharacters(strings, k, n):
"""
Time: O(n^2 * k)
Space: O(1)
"""
if k == 1:
s0 = list(strings[0])
s0[0], s0[1] = s0[1], s0[0]
return ''.join(s0)
# Initial check for validity
freq = collections.Counter(stri... | output | 1 | 105,011 | 0 | 210,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,012 | 0 | 210,024 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
def solve():
read=lambda:list(map(int,input().split()))
from collections import Counter as co
k,n=read()
s=list(input())
repeated=(len(s)!=len(set(s)))
etalon=co(s)
a=[]
kk=[]
ap=a.append
for i in rang... | output | 1 | 105,012 | 0 | 210,025 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,013 | 0 | 210,026 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
#!/usr/bin/env python3
n,k = map(int, input().split())
nn = []
ans = ''
for i in range(n):
mid = input()
if mid in nn:
ans = mid
continue
nn.append(mid)
n = len(nn)
if len(nn) == 1:
ans = nn[0]
ans = list... | output | 1 | 105,013 | 0 | 210,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped exactly two characters (the characters we swapped... | instruction | 0 | 105,014 | 0 | 210,028 |
Tags: brute force, hashing, implementation, strings
Correct Solution:
```
import sys
k, n = map(int, input().split())
s = [list(word.rstrip()) for word in sys.stdin]
double = True if max(s[0].count(chr(i+97)) for i in range(26)) > 1 else False
diff = [set() for _ in range(k)]
diff_cnt = [0]*k
for i in range(1, k):
... | output | 1 | 105,014 | 0 | 210,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped ex... | instruction | 0 | 105,015 | 0 | 210,030 |
No | output | 1 | 105,015 | 0 | 210,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped ex... | instruction | 0 | 105,016 | 0 | 210,032 |
No | output | 1 | 105,016 | 0 | 210,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped ex... | instruction | 0 | 105,017 | 0 | 210,034 |
No | output | 1 | 105,017 | 0 | 210,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We had a string s consisting of n lowercase Latin letters. We made k copies of this string, thus obtaining k identical strings s1, s2, ..., sk. After that, in each of these strings we swapped ex... | instruction | 0 | 105,018 | 0 | 210,036 |
No | output | 1 | 105,018 | 0 | 210,037 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,421 | 0 | 210,842 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
# Template 1.0
import sys, re, math
from collections import deque, defaultdict, Counter, OrderedDict
from math import ceil, sqrt, hypot, factorial, pi, sin, cos, radians, gcd
from heapq import heappush, heappop, heapify, nlargest,... | output | 1 | 105,421 | 0 | 210,843 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,422 | 0 | 210,844 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
t=int(input())
for _ in range(t):
n,m=map(int,input().split())
arr=[]
for i in range(n):
arr.append(input().strip())
arr1=[]
for i in arr:
arr1.append(int(i,2))
a=(2**m-n-1)//2
arr1.sort()
... | output | 1 | 105,422 | 0 | 210,845 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,423 | 0 | 210,846 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
import sys
max_int = 1000000001 # 10^9+1
min_int = -max_int
t = int(input())
for _t in range(t):
n, m = map(int, sys.stdin.readline().split())
to_skip = []
for _n in range(n):
s = int(sys.stdin.readline()[:-1... | output | 1 | 105,423 | 0 | 210,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,424 | 0 | 210,848 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineerin College
Date:24/05/2020
'''
import sys
from collections import deque,defaultdict as dd
from bisect import bisect,bisect_left,bisect_right,ins... | output | 1 | 105,424 | 0 | 210,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,425 | 0 | 210,850 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
tc = int(input())
for _ in range(tc):
n,m = map(int,input().split())
cache = {}
curr = (2**m - 1)//2
for i in range(n):
s = input()
x = int(s,2)
cache[x] = 1
if i%2 == 0:
... | output | 1 | 105,425 | 0 | 210,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,426 | 0 | 210,852 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
def solve():
n, m = [int(x) for x in input().split()]
a = []
for i in range(n):
a.append(input())
a = [int(x, 2) for x in a]
need = ((1 << m) - n - 1)//2 + 1
cur = (1 << (m-1)) - 1
while True... | output | 1 | 105,426 | 0 | 210,853 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,427 | 0 | 210,854 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
import math
import string
t = int(input())
for tt in range(t):
n, m = map(int, input().split())
a = []
for i in range(n):
a.append(int(input(), 2))
need = (2 ** m - n - 1) // 2
l = 0
r = 2 ** m
while(r - l > 1):
mid ... | output | 1 | 105,427 | 0 | 210,855 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously, there are exactly 2^m such strings in total.
... | instruction | 0 | 105,428 | 0 | 210,856 |
Tags: binary search, bitmasks, brute force, constructive algorithms
Correct Solution:
```
def dd(i,nn):
s=bin(i).replace("0b", "")
l=len(s)
#print(l,nn)
kk=""
for i in range (nn-l):
kk=kk+'0'
print(kk+s)
t=int(input())
for i in range(t):
n,m=map(int,input().split())
aa=[]
for pp in range(n):
pp=input()
... | output | 1 | 105,428 | 0 | 210,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously... | instruction | 0 | 105,429 | 0 | 210,858 |
Yes | output | 1 | 105,429 | 0 | 210,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously... | instruction | 0 | 105,430 | 0 | 210,860 |
Yes | output | 1 | 105,430 | 0 | 210,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously... | instruction | 0 | 105,431 | 0 | 210,862 |
Yes | output | 1 | 105,431 | 0 | 210,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider all binary strings of length m (1 ≤ m ≤ 60). A binary string is a string that consists of the characters 0 and 1 only. For example, 0110 is a binary string, and 012aba is not. Obviously... | instruction | 0 | 105,432 | 0 | 210,864 |
Yes | output | 1 | 105,432 | 0 | 210,865 |
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