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Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,443
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152,886
Tags: sortings, strings Correct Solution: ``` def subset(A, B, l_A, l_B): for i in range(l_B-l_A+1): X = B[i:l_A+i] if A == X: return False return True def main(): n = int(input()) X = ['' for _ in range(n)] for i in range(n): x = input() X[i] = (len(x), x) X.sort() for i in range(n-1): if subset(X[i][1], X[i+1][1], X[i][0], X[i+1][0]): print('NO') return print('YES') for i in range(n): print(X[i][1]) main() ```
output
1
76,443
0
152,887
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,444
0
152,888
Tags: sortings, strings Correct Solution: ``` n=int(input()) a=[] for i in range(n): a.append(input()) a.sort(key=len) answer='YES' for i in range(n-1): if a[i] in a[i+1]: answer+='\n'+a[i] else: answer='NO' a[-1]='' break if answer[0:3]=='YES': print(answer+'\n'+a[-1]) else: print(answer) ```
output
1
76,444
0
152,889
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,445
0
152,890
Tags: sortings, strings Correct Solution: ``` n = int(input()) a = [] for i in range(n): x = input() a.append([len(x),x]) a.sort() for i in range(1,n): if(a[i-1][1] not in a[i][1]): print("NO") break else: print("YES") for i in a: print(i[1]) ```
output
1
76,445
0
152,891
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,446
0
152,892
Tags: sortings, strings Correct Solution: ``` n = int(input()) l = [] for i in range(n): x = input() l.append(x) l = sorted(l, key=len) flag = 1 for i in range(n-1): if (l[i] not in l[i+1]): flag = 0 break if flag: print("YES") for i in l: print(i) else: print("NO") ```
output
1
76,446
0
152,893
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,447
0
152,894
Tags: sortings, strings Correct Solution: ``` n=int(input('')) slarray=list() for i in range(0,n): x=input('') slarray.append((x,len(x))) slarray=sorted(slarray,key=lambda x: x[1],reverse=False) for i in range(0,n-1): if slarray[i][0] not in slarray[i+1][0]: print('NO') quit() print('YES') for pr in slarray: print(pr[0]) ```
output
1
76,447
0
152,895
Provide tags and a correct Python 3 solution for this coding contest problem. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
instruction
0
76,448
0
152,896
Tags: sortings, strings Correct Solution: ``` n = int(input()) m = [] for i in range(n): k = input() m.append((len(k),k)) m.sort() flg = 0 cur_str = m[0][1] for i in range(1,n): if(m[i][1].find(cur_str) == -1): print("NO") flg = 1 break else: cur_str = m[i][1] if(flg == 0): print("YES") for i in m: print(i[1]) ```
output
1
76,448
0
152,897
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` li=[] for _ in range(int(input())): s=input() li.append(s) lst2 = sorted(li, key=len) c=1 for i in range(len(lst2)-1): if(lst2[i] not in lst2[i+1]): c=0 if(c==1): print("YES") for j in lst2: print(j) else: print("NO") ```
instruction
0
76,449
0
152,898
Yes
output
1
76,449
0
152,899
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) st = [] for i in range(n): st.append(input()) for i in range(n - 1): for j in range(i, n): if (not(st[i] in st[j])) and (not(st[j] in st[i])): print("NO") quit() if (st[j] in st[i]): wk1 = st[i] st[i] = st[j] st[j] = wk1 print("YES") for i in st: print(i) ```
instruction
0
76,450
0
152,900
Yes
output
1
76,450
0
152,901
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) a = [] for i in range(n): a.append(input()) a.sort(key = len) for i in range(n - 1): if a[i] not in a[i + 1]: print("NO") exit() print("YES") for i in range(n): print(a[i]) ```
instruction
0
76,451
0
152,902
Yes
output
1
76,451
0
152,903
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) l = [] for i in range(n): l.append(input()) #print(l) l.sort(key=len ) #print(l) k = l[-1] f = True for i in range(n - 1): if l[i] not in l[i + 1] or l[i] not in k: f = False break if f : print('YES') print(*l , sep = '\n') else: print('NO') ```
instruction
0
76,452
0
152,904
Yes
output
1
76,452
0
152,905
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) a = [] for i in range(n): a += [input()] def solve(a, n): for i in range(n): for j in range(n-1): if a[j+1] in a[j]: a[j+1], a[j] = a[j], a[j+1] elif len(a[j+1]) < len(a[j]): return print("NO") print("YES") for aa in a: print(aa) solve(a,n) ```
instruction
0
76,453
0
152,906
No
output
1
76,453
0
152,907
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) l= [] for i in range(n): l.append(input()) l= sorted(l,key=lambda w: len(w)) for i in range(len(l)-1): if l[i] not in l[-1]: print('NO') break print('YES') for i in l: print(i) ```
instruction
0
76,454
0
152,908
No
output
1
76,454
0
152,909
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` n = int(input()) lst_str = [] for i in range(n): string = input() lst_str.append(string) lst2 = sorted(lst_str, key=len) for a in range(len(lst2)): if a == len(lst2) - 1: continue if lst2[a] not in lst2[a+1]: print("NO") break else: print("YES") for i in lst_str: print(i) ```
instruction
0
76,455
0
152,910
No
output
1
76,455
0
152,911
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings. String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof". Input The first line contains an integer n (1 ≀ n ≀ 100) β€” the number of strings. The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters. Some strings might be equal. Output If it is impossible to reorder n given strings in required order, print "NO" (without quotes). Otherwise print "YES" (without quotes) and n given strings in required order. Examples Input 5 a aba abacaba ba aba Output YES a ba aba aba abacaba Input 5 a abacaba ba aba abab Output NO Input 3 qwerty qwerty qwerty Output YES qwerty qwerty qwerty Note In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". Submitted Solution: ``` # cook your dish here #import sys #sys.setrecursionlimit(10**9) ll=lambda:map(int,input().split()) t=lambda:int(input()) ss=lambda:input() lx=lambda x:map(int,input().split(x)) yy=lambda:print("Yes") nn=lambda:print("No") from math import log10 ,log2,ceil,factorial as fac,gcd,inf,sqrt,log #from itertools import combinations_with_replacement as cs #from functools import reduce from bisect import bisect_right as br,bisect_left as bl from collections import Counter #from math import inf mod=10**9+7 #for _ in range(t()): def f(): n=t() l={} d=[] for i in range(n): q=ss() if len(q) not in l: l[len(q)]=[] l[len(q)].append(q) last=1 fl=0 x=0 for i in sorted(l): if last==1: last=l[i][0] fl=1 else: fl=0 for j in range(fl,len(l[i])): if last not in l[i][j]: x=1 break if x: nn() break else: yy() for i in sorted(l): for j in l[i]: print(j) f() ''' baca bac 1 2 3 baaccca abbaccccaba ''' ```
instruction
0
76,456
0
152,912
No
output
1
76,456
0
152,913
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,539
0
155,078
"Correct Solution: ``` N = int(input()) if N==1: print(1) print(0) elif N==2: print(2) print(0) print(11) else: print(N-1) for i in range(N-1): print('0' + '1'*i + '0') ```
output
1
77,539
0
155,079
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,540
0
155,080
"Correct Solution: ``` N=int(input()) if N==1: print(1) print(0) elif N==2: print(2) print(11) print(0) else: print(N-1) for i in range(N-1): print("0"+"1"*i+"0") ```
output
1
77,540
0
155,081
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,541
0
155,082
"Correct Solution: ``` K = int(input()) if K==1: print(1) print(0) elif K==2: print(2) print(0) print(11) elif K >= 3: print(K-1) for i in range(K-1): print("0"+"1"*i+"0") ```
output
1
77,541
0
155,083
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,542
0
155,084
"Correct Solution: ``` N = int(input()) K = N-1 if N == 2: print(2) print("00") print("1") if N == 1: print(1) print(1) else: print(K) for i in range(K): print("1"+"0"*i+"1") ```
output
1
77,542
0
155,085
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,543
0
155,086
"Correct Solution: ``` N = int(input()) A = [] for i in range(0,N-1): A.append("1"+"0"*i+"1") if N==1: A=["1"] if N==2: A=["0","11"] print(len(A)) for a in A:print(a) ```
output
1
77,543
0
155,087
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,544
0
155,088
"Correct Solution: ``` n = int(input()) if n == 1: print(1) print(0) exit() if n == 2: print(2) print(0) print(11) exit() print(n-1) for i in range(n-1): print("1" + "0"*i + "1") ```
output
1
77,544
0
155,089
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,545
0
155,090
"Correct Solution: ``` import sys input = sys.stdin.readline sys.setrecursionlimit(1000000) from collections import deque, Counter def getN(): return int(input()) def getList(): return list(map(int, input().split())) import math INF = 10 ** 20 def main(): n = getN() if n == 1: print(1) print(1) return if n == 2: print(2) print(0) print("11") return print(n-1) print("11") for i in range(1, n-1): print("1" + "0" * i + "1") return if __name__ == "__main__": main() ```
output
1
77,545
0
155,091
Provide a correct Python 3 solution for this coding contest problem. Problem statement Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements. * The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less. * The lengths of the strings contained in $ S $ are different. * The string contained in $ S $ consists only of the characters `0` and` 1`. * For any $ 2 $ string contained in $ S $, one is not a substring of the other. However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $. Constraint * $ 1 \ leq N \ leq 300 $ * $ N $ is an integer * * * input Input is given from standard input in the following format. $ N $ output Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct. Specifically, output in the following format. Output $ K $, the number of elements of $ S $, on the $ 1 $ line. Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line. $ K $ $ S_1 $ $ S_2 $ $ \ vdots $ $ S_K $ * * * Input example 1 2 Output example 1 2 0 11 The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions. * * * Input example 2 1 Output example 2 1 0 Example Input 2 Output 2 0 11
instruction
0
77,546
0
155,092
"Correct Solution: ``` from heapq import * from collections import deque import sys sys.setrecursionlimit(10 ** 6) int1 = lambda x: int(x) - 1 p2D = lambda x: print(*x, sep="\n") def II(): return int(sys.stdin.readline()) def MI(): return map(int, sys.stdin.readline().split()) def LI(): return list(map(int, sys.stdin.readline().split())) def LLI(rows_number): return [LI() for _ in range(rows_number)] def SI(): return sys.stdin.readline()[:-1] class Dice: def __init__(self,top,bot,lef,rig,fro,bac): self.top = top self.bot = bot self.lef = lef self.rig = rig self.fro = fro self.bac = bac def up(self): top, bac, bot, fro = self.fro, self.top, self.bac, self.bot return Dice(top,bot,self.lef,self.rig,fro,bac) def down(self): top, bac, bot, fro = self.bac, self.bot, self.fro, self.top return Dice(top,bot,self.lef,self.rig,fro,bac) def right(self): top, rig, bot, lef = self.lef, self.top, self.rig, self.bot return Dice(top,bot,lef,rig,self.fro,self.bac) def left(self): top, rig, bot, lef = self.rig, self.bot, self.lef, self.top return Dice(top,bot,lef,rig,self.fro,self.bac) def state(self): return (self.top, self.rig, self.bot, self.lef, self.fro, self.bac) def main(): n=int(input()) if n==1: print(1) print(1) exit() if n==2: print(2) print(0) print(11) exit() print(n-1) for i in range(n-1): print("1"+"0"*i+"1") main() ```
output
1
77,546
0
155,093
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of n characters. These characters are among the first k lowercase letters of the Latin alphabet. You have to perform n operations with the string. During the i-th operation, you take the character that initially occupied the i-th position, and perform one of the following actions with it: * swap it with the previous character in the string (if it exists). This operation is represented as L; * swap it with the next character in the string (if it exists). This operation is represented as R; * cyclically change it to the previous character in the alphabet (b becomes a, c becomes b, and so on; a becomes the k-th letter of the Latin alphabet). This operation is represented as D; * cyclically change it to the next character in the alphabet (a becomes b, b becomes c, and so on; the k-th letter of the Latin alphabet becomes a). This operation is represented as U; * do nothing. This operation is represented as 0. For example, suppose the initial string is test, k = 20, and the sequence of operations is URLD. Then the string is transformed as follows: 1. the first operation is U, so we change the underlined letter in test to the next one in the first 20 Latin letters, which is a. The string is now aest; 2. the second operation is R, so we swap the underlined letter with the next one in the string aest. The string is now aset; 3. the third operation is L, so we swap the underlined letter with the previous one in the string aset (note that this is now the 2-nd character of the string, but it was initially the 3-rd one, so the 3-rd operation is performed to it). The resulting string is saet; 4. the fourth operation is D, so we change the underlined letter in saet to the previous one in the first 20 Latin letters, which is s. The string is now saes. The result of performing the sequence of operations is saes. Given the string s and the value of k, find the lexicographically smallest string that can be obtained after applying a sequence of operations to s. Input The first line contains one integer t (1 ≀ t ≀ 1000) β€” the number of test cases. Each test case consists of two lines. The first line contains two integers n and k (1 ≀ n ≀ 500; 2 ≀ k ≀ 26). The second line contains a string s consisting of n characters. Each character is one of the k first letters of the Latin alphabet (in lower case). Output For each test case, print one line containing the lexicographically smallest string that can be obtained from s using one sequence of operations. Example Input 6 4 2 bbab 7 5 cceddda 6 5 ecdaed 7 4 dcdbdaa 8 3 ccabbaca 5 7 eabba Output aaaa baccacd aabdac aabacad aaaaaaaa abadb Submitted Solution: ``` for i in range(int(input())): n,k = map(int,input().split()) l=[ord(ch)-97 for ch in list(input())] mi=[max(0,v-1) if v<k-1 else 0 for v in l] x=0 while(x<n-1): if l[x]<l[x-1]: l[x-1],l[x]=l[x],l[x-1] x=x+1 elif mi[x+1]<mi[x]: l[x],l[x+1]=l[x+1],l[x] if l[x-1]>l[x]: l[x],l[x-1]=l[x-1],l[x] else: l[x]=mi[x+1] x=x+2 else: l[x]=mi[x] x=x+1 if (x==(n-1)): l[x]=mi[x] print(''.join([chr(g+97) for g in l])) ```
instruction
0
77,735
0
155,470
No
output
1
77,735
0
155,471
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are given a string s consisting of n characters. These characters are among the first k lowercase letters of the Latin alphabet. You have to perform n operations with the string. During the i-th operation, you take the character that initially occupied the i-th position, and perform one of the following actions with it: * swap it with the previous character in the string (if it exists). This operation is represented as L; * swap it with the next character in the string (if it exists). This operation is represented as R; * cyclically change it to the previous character in the alphabet (b becomes a, c becomes b, and so on; a becomes the k-th letter of the Latin alphabet). This operation is represented as D; * cyclically change it to the next character in the alphabet (a becomes b, b becomes c, and so on; the k-th letter of the Latin alphabet becomes a). This operation is represented as U; * do nothing. This operation is represented as 0. For example, suppose the initial string is test, k = 20, and the sequence of operations is URLD. Then the string is transformed as follows: 1. the first operation is U, so we change the underlined letter in test to the next one in the first 20 Latin letters, which is a. The string is now aest; 2. the second operation is R, so we swap the underlined letter with the next one in the string aest. The string is now aset; 3. the third operation is L, so we swap the underlined letter with the previous one in the string aset (note that this is now the 2-nd character of the string, but it was initially the 3-rd one, so the 3-rd operation is performed to it). The resulting string is saet; 4. the fourth operation is D, so we change the underlined letter in saet to the previous one in the first 20 Latin letters, which is s. The string is now saes. The result of performing the sequence of operations is saes. Given the string s and the value of k, find the lexicographically smallest string that can be obtained after applying a sequence of operations to s. Input The first line contains one integer t (1 ≀ t ≀ 1000) β€” the number of test cases. Each test case consists of two lines. The first line contains two integers n and k (1 ≀ n ≀ 500; 2 ≀ k ≀ 26). The second line contains a string s consisting of n characters. Each character is one of the k first letters of the Latin alphabet (in lower case). Output For each test case, print one line containing the lexicographically smallest string that can be obtained from s using one sequence of operations. Example Input 6 4 2 bbab 7 5 cceddda 6 5 ecdaed 7 4 dcdbdaa 8 3 ccabbaca 5 7 eabba Output aaaa baccacd aabdac aabacad aaaaaaaa abadb Submitted Solution: ``` import io,os JJJ=input;input=lambda:JJJ().encode() input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline for _ in range(int(input())): n,k=list(map(int,input().split())) s=[x - ord('a') for x in input().strip()] c=[min(x,(x+1)%k,(x-1)%k) for x in s] i = 0 moved = False while i < n: d = {'stand': (c[i], 0)} if i<n-2: d['o2a'] = (s[i+2], 2) if i<n-1: if not moved: d['b1a'] = (c[i+1], 3) d['o1a'] = (s[i+1], 1) op = min(d,key=d.get) #print(i, "".join(chr(x + ord('a')) for x in c), op) if op == 'stand': i += 1 moved = False elif op == 'o2a': c[i],c[i+1],c[i+2]=s[i+2],c[i],s[i+1] i += 2 moved = True elif op == 'o1a': c[i],c[i+1] = s[i+1],c[i] moved = True i += 1 elif op == 'b1a': c[i],c[i+1] = c[i+1],s[i] moved = True i += 1 print("".join(chr(x + ord('a')) for x in c)) ```
instruction
0
77,736
0
155,472
No
output
1
77,736
0
155,473
Provide tags and a correct Python 3 solution for this coding contest problem. Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases: 1. They are equal. 2. If we split string a into two halves of the same size a1 and a2, and string b into two halves of the same size b1 and b2, then one of the following is correct: 1. a1 is equivalent to b1, and a2 is equivalent to b2 2. a1 is equivalent to b2, and a2 is equivalent to b1 As a home task, the teacher gave two strings to his students and asked to determine if they are equivalent. Gerald has already completed this home task. Now it's your turn! Input The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200 000 and consists of lowercase English letters. The strings have the same length. Output Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. Examples Input aaba abaa Output YES Input aabb abab Output NO Note In the first sample you should split the first string into strings "aa" and "ba", the second one β€” into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a". In the second sample the first string can be splitted into strings "aa" and "bb", that are equivalent only to themselves. That's why string "aabb" is equivalent only to itself and to string "bbaa".
instruction
0
77,860
0
155,720
Tags: divide and conquer, hashing, sortings, strings Correct Solution: ``` str1 = input() str2 = input() def compare(s): if (len(s) % 2 == 1): return s half = int(len(s) / 2) s1 = compare(s[0:half]) s2 = compare(s[half:len(s)]) if (s1 < s2): return s1 + s2 else: return s2 + s1 if (compare(str1) == compare(str2)): print('YES') else: print('NO') ```
output
1
77,860
0
155,721
Provide tags and a correct Python 3 solution for this coding contest problem. Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases: 1. They are equal. 2. If we split string a into two halves of the same size a1 and a2, and string b into two halves of the same size b1 and b2, then one of the following is correct: 1. a1 is equivalent to b1, and a2 is equivalent to b2 2. a1 is equivalent to b2, and a2 is equivalent to b1 As a home task, the teacher gave two strings to his students and asked to determine if they are equivalent. Gerald has already completed this home task. Now it's your turn! Input The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200 000 and consists of lowercase English letters. The strings have the same length. Output Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise. Examples Input aaba abaa Output YES Input aabb abab Output NO Note In the first sample you should split the first string into strings "aa" and "ba", the second one β€” into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a". In the second sample the first string can be splitted into strings "aa" and "bb", that are equivalent only to themselves. That's why string "aabb" is equivalent only to itself and to string "bbaa".
instruction
0
77,861
0
155,722
Tags: divide and conquer, hashing, sortings, strings Correct Solution: ``` def equal(a, b): def msort(s): length = len(s) if length % 2: return s s1 = msort(s[:length // 2]) s2 = msort(s[length // 2:]) if s1 < s2: return s1 + s2 else: return s2 + s1 if msort(a) == msort(b): return True else: return False a = input() b = input() print('YES' if equal(a, b) else 'NO') ```
output
1
77,861
0
155,723
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,946
0
155,892
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` n = int(input()) wrong_str = False strings = [] sets = [] for _ in range(n): new_string = input() new_string_set = set(new_string) if len(new_string) != len(new_string_set): wrong_str = True break strings.append(new_string) sets.append(new_string_set) if wrong_str: print("NO") exit(0) connections = [] for _ in range(n): connections.append((-1,-1)) changed = True while changed: changed = False for i in range(len(strings)): if strings[i] == None: continue for j in range(i + 1, len(strings)): if strings[j] == None: continue if len(set(strings[i]).intersection(set(strings[j]))) == 0: continue a = strings[i] b = strings[j] #print(a, b) if b in a: strings[j] = None changed = True elif a in b: strings[i] = b strings[j] = None changed = True else: is_ok = False start_index = a.find(b[0]) if start_index != -1 and a[start_index:] in b: strings[i] += strings[j][len(a) - start_index:] strings[j] = None is_ok = True changed = True if not is_ok: start_index = b.find(a[0]) if start_index != -1 and b[start_index:] in a: strings[i] = strings[j] + strings[i][len(b) - start_index:] strings[j] = None is_ok = True changed = True if not is_ok: print("NO") exit(0) if wrong_str: print("NO") exit(0) strings = [x for x in strings if x is not None] whole_str = "".join(strings) if len(whole_str) != len(set(whole_str)): print("NO") exit(0) print("".join(sorted(strings))) ```
output
1
77,946
0
155,893
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,947
0
155,894
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` StringsNumber = int(input()) FinalStrings = [] Strings = [] for i in range(StringsNumber): Strings.append(input()) LetterGraph = {} # Π“Π΅Π½Π΅Ρ€ΠΈΠΌ Π³Ρ€Π°Ρ„ for i in range(len(Strings)): if len(Strings[i]) == 1: if Strings[i] not in LetterGraph: LetterGraph[Strings[i]] = "" #print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i) continue for e in range(len(Strings[i]) - 1): if Strings[i][e] not in LetterGraph: Elements = [] for j in list(LetterGraph): if j != Strings[i][e + 1]: Elements.append(LetterGraph[j]) if Strings[i][e + 1] in Elements: print("NO") exit(0) LetterGraph[Strings[i][e]] = Strings[i][e + 1] continue if LetterGraph[Strings[i][e]] == Strings[i][e + 1] or LetterGraph[Strings[i][e]] == "": LetterGraph[Strings[i][e]] = Strings[i][e + 1] continue #print("Π“Ρ€Π°Ρ„:", LetterGraph) print("NO") exit(0) #print("Π― сгСнСрил Π³Ρ€Π°Ρ„, ΠΏΠΎΠ»ΡƒΡ‡ΠΈΠ»ΠΎΡΡŒ:", LetterGraph) # ΠŸΡ€ΠΎΠ²Π΅Ρ€ΡΠ΅ΠΌ, Ρ‡Ρ‚ΠΎ Π½Π΅Ρ‚Ρƒ Ρ†ΠΈΠΊΠ»Π° if LetterGraph: Cycle = False for i in LetterGraph: Letter = LetterGraph[i] while True: if Letter in LetterGraph: if LetterGraph[Letter] == i: print("NO") exit(0) Letter = LetterGraph[Letter] else: break # Находим Π²ΠΎΠ·ΠΌΠΎΠΆΠ½Ρ‹Π΅ ΠΏΠ΅Ρ€Π²Ρ‹Π΅ символы if LetterGraph: IsIFirstSymbol = False FirstSymbols = [] for i in LetterGraph: IsIFirstSymbol = True for e in LetterGraph: if LetterGraph[e] == i: #print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ…ΠΎΠ΄ΠΈΡ‚, ΠΏΠΎΡ‚ΠΎΠΌΡƒ Ρ‡Ρ‚ΠΎ", e, "ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚ Π½Π° Π½Π΅Π³ΠΎ.") IsIFirstSymbol = False if IsIFirstSymbol: FirstSymbols.append(i) if not FirstSymbols: print("NO") exit(0) #print("Π’Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ ΠΏΠ΅Ρ€Π²ΠΎΠ³ΠΎ символа:", *FirstSymbols) # Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ Ρ„ΠΈΠ½Π°Π»ΡŒΠ½ΠΎΠΉ строки if LetterGraph: Letter = "" for i in FirstSymbols: FinalString = i Letter = i for e in range(len(LetterGraph)): if Letter in LetterGraph: if not (LetterGraph[Letter] == ""): FinalString += LetterGraph[Letter] #print(Letter, "Π΅ΡΡ‚ΡŒ Π² Π³Ρ€Π°Ρ„Π΅, Ρ‚Π°ΠΊ Ρ‡Ρ‚ΠΎ добавляСм", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡ‚ΠΎΡ€ΠΎΠ΅ ΠΎΠ½ΠΎ ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚.") Letter = LetterGraph[Letter] else: break else: break FinalStrings.append(FinalString) #print("ΠžΡ‚Π΄Π΅Π»ΡŒΠ½Ρ‹Π΅ строки", *FinalStrings) FinalStrings.sort() RESULT = "" for i in FinalStrings: RESULT += i print(RESULT) ```
output
1
77,947
0
155,895
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,948
0
155,896
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` #https://codeforces.com/problemset/problem/886/D def is_all_used(used): for val in used.values(): if val != True: return False return True def is_circle(d, pre): used = {x:False for x in d} pre_none = [x for x in used if x not in pre] s_arr = [] for x in pre_none: cur = [] flg = dfs(x, d, used, cur) if flg==True: return True, None s_arr.append(cur) if is_all_used(used) != True: return True, None return False, s_arr def dfs(u, d, used, cur): used[u] = True cur.append(u) flg = False for v in d[u]: if used[v] == True: return True flg = dfs(v, d, used, cur) if flg==True: return flg return flg def push(d, u, v=None): if u not in d: d[u] = set() if v is not None: if v not in d: d[v] = set() d[u].add(v) def push_p(d, v): if v not in d: d[v] = 0 d[v]+=1 def is_deg_valid(d): for u in d: if len(d[u]) > 1: return True return False def solve(): n = int(input()) d = {} pre = {} for _ in range(n): s = input() if len(s) == 1: push(d, s) else: for u, v in zip(s[:-1], s[1:]): push(d, u, v) push_p(pre, v) flg, arr = is_circle(d, pre) if is_deg_valid(d) or flg==True: return 'NO' S = [''.join(x) for x in arr] S = sorted(S) return ''.join([s for s in S]) print(solve()) #4 #mail #ai #lru #cf #3 #kek #preceq #cheburek ```
output
1
77,948
0
155,897
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,949
0
155,898
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` from sys import exit n = int(input()) letters_prev = [None for i in range(30)] letters_fow = [None for i in range(30)] okk = [False for i in range(30)] for i in range(n): task = [ord(i) - ord('a') for i in input()] if len(task) == 1: okk[task[0]] = True for i in range(1, len(task)): if (letters_prev[task[i]] is not None and letters_prev[task[i]] != task[i-1]) or task[i] == task[i-1]: print('NO') exit() else: letters_prev[task[i]] = task[i-1] for i in range(len(task)-1): if (letters_fow[task[i]] is not None and letters_fow[task[i]] != task[i+1]) or task[i] == task[i+1]: print('NO') exit() else: letters_fow[task[i]] = task[i+1] # print(task, letters_prev, letters_fow) def chain_p(x, was=[]): global letters_fow, letters_prev if x is None: return [] if letters_prev[x] is None: return [x] else: if letters_prev[x] in was: print('NO') exit() ans = chain_p(letters_prev[x], was=was+[letters_prev[x]]) + [x] # letters_prev[x] = None return ans def chain_f(x, was=[]): global letters_fow, letters_prev # print('_f', x, letters_fow[x]) if x is None: return [] if letters_fow[x] is None: # letters_fow[x] = None return [x] else: if letters_fow[x] in was: print('NO') exit() ans = chain_f(letters_fow[x], was=was+[letters_fow[x]]) + [x] # letters_fow[x] = None return ans done = [] cc = [] while True: flag = False for i in range(30): if i in done: continue prev = [] post = [] if letters_prev[i] is not None: flag = True prev = chain_p(letters_prev[i]) if letters_fow[i] is not None: flag = True post = chain_f(letters_fow[i]) done.extend(prev) done.extend(post) done.append(i) if len(prev) + len(post) == 0 and okk[i]: cc.append(chr(i+ord('a'))) elif len(prev) + len(post) > 0: cc.append("".join([chr(i+ord('a')) for i in prev] + [chr(i+ord('a'))] + [chr(i+ord('a')) for i in post][::-1])) if not flag: break cc.sort() print("".join(cc)) ```
output
1
77,949
0
155,899
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,950
0
155,900
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` # ---------------------------iye ha aam zindegi--------------------------------------------- import math import random import heapq, bisect import sys from collections import deque, defaultdict from fractions import Fraction import sys import threading from collections import defaultdict threading.stack_size(10**8) mod = 10 ** 9 + 7 mod1 = 998244353 # ------------------------------warmup---------------------------- import os import sys from io import BytesIO, IOBase sys.setrecursionlimit(300000) BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") # -------------------game starts now----------------------------------------------------import math class TreeNode: def __init__(self, k, v): self.key = k self.value = v self.left = None self.right = None self.parent = None self.height = 1 self.num_left = 1 self.num_total = 1 class AvlTree: def __init__(self): self._tree = None def add(self, k, v): if not self._tree: self._tree = TreeNode(k, v) return node = self._add(k, v) if node: self._rebalance(node) def _add(self, k, v): node = self._tree while node: if k < node.key: if node.left: node = node.left else: node.left = TreeNode(k, v) node.left.parent = node return node.left elif node.key < k: if node.right: node = node.right else: node.right = TreeNode(k, v) node.right.parent = node return node.right else: node.value = v return @staticmethod def get_height(x): return x.height if x else 0 @staticmethod def get_num_total(x): return x.num_total if x else 0 def _rebalance(self, node): n = node while n: lh = self.get_height(n.left) rh = self.get_height(n.right) n.height = max(lh, rh) + 1 balance_factor = lh - rh n.num_total = 1 + self.get_num_total(n.left) + self.get_num_total(n.right) n.num_left = 1 + self.get_num_total(n.left) if balance_factor > 1: if self.get_height(n.left.left) < self.get_height(n.left.right): self._rotate_left(n.left) self._rotate_right(n) elif balance_factor < -1: if self.get_height(n.right.right) < self.get_height(n.right.left): self._rotate_right(n.right) self._rotate_left(n) else: n = n.parent def _remove_one(self, node): """ Side effect!!! Changes node. Node should have exactly one child """ replacement = node.left or node.right if node.parent: if AvlTree._is_left(node): node.parent.left = replacement else: node.parent.right = replacement replacement.parent = node.parent node.parent = None else: self._tree = replacement replacement.parent = None node.left = None node.right = None node.parent = None self._rebalance(replacement) def _remove_leaf(self, node): if node.parent: if AvlTree._is_left(node): node.parent.left = None else: node.parent.right = None self._rebalance(node.parent) else: self._tree = None node.parent = None node.left = None node.right = None def remove(self, k): node = self._get_node(k) if not node: return if AvlTree._is_leaf(node): self._remove_leaf(node) return if node.left and node.right: nxt = AvlTree._get_next(node) node.key = nxt.key node.value = nxt.value if self._is_leaf(nxt): self._remove_leaf(nxt) else: self._remove_one(nxt) self._rebalance(node) else: self._remove_one(node) def get(self, k): node = self._get_node(k) return node.value if node else -1 def _get_node(self, k): if not self._tree: return None node = self._tree while node: if k < node.key: node = node.left elif node.key < k: node = node.right else: return node return None def get_at(self, pos): x = pos + 1 node = self._tree while node: if x < node.num_left: node = node.left elif node.num_left < x: x -= node.num_left node = node.right else: return (node.key, node.value) raise IndexError("Out of ranges") @staticmethod def _is_left(node): return node.parent.left and node.parent.left == node @staticmethod def _is_leaf(node): return node.left is None and node.right is None def _rotate_right(self, node): if not node.parent: self._tree = node.left node.left.parent = None elif AvlTree._is_left(node): node.parent.left = node.left node.left.parent = node.parent else: node.parent.right = node.left node.left.parent = node.parent bk = node.left.right node.left.right = node node.parent = node.left node.left = bk if bk: bk.parent = node node.height = max(self.get_height(node.left), self.get_height(node.right)) + 1 node.num_total = 1 + self.get_num_total(node.left) + self.get_num_total(node.right) node.num_left = 1 + self.get_num_total(node.left) def _rotate_left(self, node): if not node.parent: self._tree = node.right node.right.parent = None elif AvlTree._is_left(node): node.parent.left = node.right node.right.parent = node.parent else: node.parent.right = node.right node.right.parent = node.parent bk = node.right.left node.right.left = node node.parent = node.right node.right = bk if bk: bk.parent = node node.height = max(self.get_height(node.left), self.get_height(node.right)) + 1 node.num_total = 1 + self.get_num_total(node.left) + self.get_num_total(node.right) node.num_left = 1 + self.get_num_total(node.left) @staticmethod def _get_next(node): if not node.right: return node.parent n = node.right while n.left: n = n.left return n # -----------------------------------------------binary seacrh tree--------------------------------------- class SegmentTree1: def __init__(self, data, default=2**51, func=lambda a, b: a & b): """initialize the segment tree with data""" self._default = default self._func = func self._len = len(data) self._size = _size = 1 << (self._len - 1).bit_length() self.data = [default] * (2 * _size) self.data[_size:_size + self._len] = data for i in reversed(range(_size)): self.data[i] = func(self.data[i + i], self.data[i + i + 1]) def __delitem__(self, idx): self[idx] = self._default def __getitem__(self, idx): return self.data[idx + self._size] def __setitem__(self, idx, value): idx += self._size self.data[idx] = value idx >>= 1 while idx: self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1]) idx >>= 1 def __len__(self): return self._len def query(self, start, stop): if start == stop: return self.__getitem__(start) stop += 1 start += self._size stop += self._size res = self._default while start < stop: if start & 1: res = self._func(res, self.data[start]) start += 1 if stop & 1: stop -= 1 res = self._func(res, self.data[stop]) start >>= 1 stop >>= 1 return res def __repr__(self): return "SegmentTree({0})".format(self.data) # -------------------game starts now----------------------------------------------------import math class SegmentTree: def __init__(self, data, default=0, func=lambda a, b: a + b): """initialize the segment tree with data""" self._default = default self._func = func self._len = len(data) self._size = _size = 1 << (self._len - 1).bit_length() self.data = [default] * (2 * _size) self.data[_size:_size + self._len] = data for i in reversed(range(_size)): self.data[i] = func(self.data[i + i], self.data[i + i + 1]) def __delitem__(self, idx): self[idx] = self._default def __getitem__(self, idx): return self.data[idx + self._size] def __setitem__(self, idx, value): idx += self._size self.data[idx] = value idx >>= 1 while idx: self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1]) idx >>= 1 def __len__(self): return self._len def query(self, start, stop): if start == stop: return self.__getitem__(start) stop += 1 start += self._size stop += self._size res = self._default while start < stop: if start & 1: res = self._func(res, self.data[start]) start += 1 if stop & 1: stop -= 1 res = self._func(res, self.data[stop]) start >>= 1 stop >>= 1 return res def __repr__(self): return "SegmentTree({0})".format(self.data) # -------------------------------iye ha chutiya zindegi------------------------------------- class Factorial: def __init__(self, MOD): self.MOD = MOD self.factorials = [1, 1] self.invModulos = [0, 1] self.invFactorial_ = [1, 1] def calc(self, n): if n <= -1: print("Invalid argument to calculate n!") print("n must be non-negative value. But the argument was " + str(n)) exit() if n < len(self.factorials): return self.factorials[n] nextArr = [0] * (n + 1 - len(self.factorials)) initialI = len(self.factorials) prev = self.factorials[-1] m = self.MOD for i in range(initialI, n + 1): prev = nextArr[i - initialI] = prev * i % m self.factorials += nextArr return self.factorials[n] def inv(self, n): if n <= -1: print("Invalid argument to calculate n^(-1)") print("n must be non-negative value. But the argument was " + str(n)) exit() p = self.MOD pi = n % p if pi < len(self.invModulos): return self.invModulos[pi] nextArr = [0] * (n + 1 - len(self.invModulos)) initialI = len(self.invModulos) for i in range(initialI, min(p, n + 1)): next = -self.invModulos[p % i] * (p // i) % p self.invModulos.append(next) return self.invModulos[pi] def invFactorial(self, n): if n <= -1: print("Invalid argument to calculate (n^(-1))!") print("n must be non-negative value. But the argument was " + str(n)) exit() if n < len(self.invFactorial_): return self.invFactorial_[n] self.inv(n) # To make sure already calculated n^-1 nextArr = [0] * (n + 1 - len(self.invFactorial_)) initialI = len(self.invFactorial_) prev = self.invFactorial_[-1] p = self.MOD for i in range(initialI, n + 1): prev = nextArr[i - initialI] = (prev * self.invModulos[i % p]) % p self.invFactorial_ += nextArr return self.invFactorial_[n] class Combination: def __init__(self, MOD): self.MOD = MOD self.factorial = Factorial(MOD) def ncr(self, n, k): if k < 0 or n < k: return 0 k = min(k, n - k) f = self.factorial return f.calc(n) * f.invFactorial(max(n - k, k)) * f.invFactorial(min(k, n - k)) % self.MOD # --------------------------------------iye ha combinations ka zindegi--------------------------------- def powm(a, n, m): if a == 1 or n == 0: return 1 if n % 2 == 0: s = powm(a, n // 2, m) return s * s % m else: return a * powm(a, n - 1, m) % m # --------------------------------------iye ha power ka zindegi--------------------------------- def sort_list(list1, list2): zipped_pairs = zip(list2, list1) z = [x for _, x in sorted(zipped_pairs)] return z # --------------------------------------------------product---------------------------------------- def product(l): por = 1 for i in range(len(l)): por *= l[i] return por # --------------------------------------------------binary---------------------------------------- def binarySearchCount(arr, n, key): left = 0 right = n - 1 count = 0 while (left <= right): mid = int((right + left) / 2) # Check if middle element is # less than or equal to key if (arr[mid] < key): count = mid + 1 left = mid + 1 # If key is smaller, ignore right half else: right = mid - 1 return count # --------------------------------------------------binary---------------------------------------- def countdig(n): c = 0 while (n > 0): n //= 10 c += 1 return c def binary(x, length): y = bin(x)[2:] return y if len(y) >= length else "0" * (length - len(y)) + y def countGreater(arr, n, k): l = 0 r = n - 1 # Stores the index of the left most element # from the array which is greater than k leftGreater = n # Finds number of elements greater than k while (l <= r): m = int(l + (r - l) / 2) if (arr[m] >= k): leftGreater = m r = m - 1 # If mid element is less than # or equal to k update l else: l = m + 1 # Return the count of elements # greater than k return (n - leftGreater) # --------------------------------------------------binary------------------------------------ n=int(input()) l1=[] l2=[] for i in range(n): s1=input() s=list(s1) if len(set(s))<len(s): print("NO") sys.exit(0) l1.append(s) l2.append(s1) l=['']*26 r=['']*26 pr=[0]*26 for i in range(n): s=l1[i] if len(s)==1: pr[ord(s[0]) - 97] = 1 continue for j in range(len(s)): pr[ord(s[j])-97]=1 if j==0: if r[ord(s[j])-97]=='': r[ord(s[j])-97]=s[j+1] elif r[ord(s[j])-97]!=s[j+1]: print("NO") sys.exit(0) elif j==len(s)-1: if l[ord(s[j]) - 97] == '': l[ord(s[j]) - 97] = s[j - 1] elif l[ord(s[j]) - 97] != s[j - 1]: print("NO") sys.exit(0) else: if r[ord(s[j])-97]=='': r[ord(s[j])-97]=s[j+1] elif r[ord(s[j])-97]!=s[j+1]: print("NO") sys.exit(0) if l[ord(s[j]) - 97] == '': l[ord(s[j]) - 97] = s[j - 1] elif l[ord(s[j]) - 97] != s[j - 1]: print("NO") sys.exit(0) ans="" st=0 f=1 for i in range(26): if l[i]=='' and pr[i]==1: f=0 break if f==1: print("NO") sys.exit(0) for i in range(26): if l[i]=='' and pr[i]==1: st=i ans+=chr(st+97) while(r[st]!=''): pr[st]=0 st=ord(r[st])-97 ans += chr(st + 97) for i in range(n): if l2[i] not in ans: print("NO") sys.exit(0) print(ans) ```
output
1
77,950
0
155,901
Provide tags and a correct Python 3 solution for this coding contest problem. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
instruction
0
77,951
0
155,902
Tags: constructive algorithms, graphs, implementation Correct Solution: ``` n=int(input()) m=[] sc=[] for i in range(n): m.append(input()) sc.append(set(m[i])) if len(sc[i])!=len(m[i]): print('NO') break else: i=0 pX=False while i<len(m): j=i+1 p=False while j<len(m): #print(m) z=len(sc[i].intersection(sc[j])) #a=len(sc[i]) #b=len(sc[j]) if m[i] in m[j]: m[i]=m[j] sc[i]=sc[j] sc.pop(j) m.pop(j) p=True break elif m[j] in m[i]: sc.pop(j) m.pop(j) j-=1 elif z>0: if m[i][-z:]==m[j][:z]: m[i]+=m[j][z:] elif m[j][-z:]==m[i][:z]: m[i]=m[j]+m[i][z:] else: pX=True break sc[i]=set(m[i]) m.pop(j) sc.pop(j) j-=1 p=True j+=1 if not p: i+=1 if pX: print('NO') break if not pX: print(''.join(sorted(m))) ```
output
1
77,951
0
155,903
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. Submitted Solution: ``` StringsNumber = int(input()) FinalStrings = [] Strings = [] for i in range(StringsNumber): Strings.append(input()) LetterGraph = {} # Π“Π΅Π½Π΅Ρ€ΠΈΠΌ Π³Ρ€Π°Ρ„ for i in range(len(Strings)): if len(Strings[i]) == 1: LetterGraph[Strings[i]] = "" #print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i) continue for e in range(len(Strings[i]) - 1): if Strings[i][e] not in LetterGraph: LetterGraph[Strings[i][e]] = Strings[i][e + 1] continue if LetterGraph[Strings[i][e]] == Strings[i][e + 1]: continue print("NO") exit(0) #print("Π― сгСнСрил Π³Ρ€Π°Ρ„, ΠΏΠΎΠ»ΡƒΡ‡ΠΈΠ»ΠΎΡΡŒ:", LetterGraph) # ΠŸΡ€ΠΎΠ²Π΅Ρ€ΡΠ΅ΠΌ, Ρ‡Ρ‚ΠΎ Π½Π΅Ρ‚Ρƒ Ρ†ΠΈΠΊΠ»Π° if LetterGraph: Cycle = False for i in LetterGraph: try: if LetterGraph[LetterGraph[i]] == i: Cycle = True except: continue if Cycle: print("NO") exit(0) # Находим Π²ΠΎΠ·ΠΌΠΎΠΆΠ½Ρ‹Π΅ ΠΏΠ΅Ρ€Π²Ρ‹Π΅ символы if LetterGraph: IsIFirstSymbol = False FirstSymbols = [] for i in LetterGraph: IsIFirstSymbol = True for e in LetterGraph: if LetterGraph[e] == i: #print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ…ΠΎΠ΄ΠΈΡ‚, ΠΏΠΎΡ‚ΠΎΠΌΡƒ Ρ‡Ρ‚ΠΎ", e, "ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚ Π½Π° Π½Π΅Π³ΠΎ.") IsIFirstSymbol = False if IsIFirstSymbol: FirstSymbols.append(i) if not FirstSymbols: print("NO") exit(0) #print("Π’Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ ΠΏΠ΅Ρ€Π²ΠΎΠ³ΠΎ символа:", *FirstSymbols) # Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ Ρ„ΠΈΠ½Π°Π»ΡŒΠ½ΠΎΠΉ строки if LetterGraph: Letter = "" for i in FirstSymbols: FinalString = i Letter = i for e in range(len(LetterGraph)): if Letter in LetterGraph: if not (LetterGraph[Letter] == ""): FinalString += LetterGraph[Letter] #print(Letter, "Π΅ΡΡ‚ΡŒ Π² Π³Ρ€Π°Ρ„Π΅, Ρ‚Π°ΠΊ Ρ‡Ρ‚ΠΎ добавляСм", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡ‚ΠΎΡ€ΠΎΠ΅ ΠΎΠ½ΠΎ ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚.") Letter = LetterGraph[Letter] else: break else: break FinalStrings.append(FinalString) #print("ΠžΡ‚Π΄Π΅Π»ΡŒΠ½Ρ‹Π΅ строки", *FinalStrings) FinalStrings.sort() RESULT = "" for i in FinalStrings: RESULT += i print(RESULT) ```
instruction
0
77,952
0
155,904
No
output
1
77,952
0
155,905
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. Submitted Solution: ``` StringsNumber = int(input()) FinalStrings = [] Strings = [] for i in range(StringsNumber): Strings.append(input()) LetterGraph = {} # Π“Π΅Π½Π΅Ρ€ΠΈΠΌ Π³Ρ€Π°Ρ„ for i in range(len(Strings)): if len(Strings[i]) == 1: LetterGraph[Strings[i]] = "" #print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i) continue for e in range(len(Strings[i]) - 1): if Strings[i][e] not in LetterGraph: LetterGraph[Strings[i][e]] = Strings[i][e + 1] continue if LetterGraph[Strings[i][e]] == Strings[i][e + 1] or LetterGraph[Strings[i][e]] == "": continue #print("Π“Ρ€Π°Ρ„:", LetterGraph) print("NO") exit(0) #print("Π― сгСнСрил Π³Ρ€Π°Ρ„, ΠΏΠΎΠ»ΡƒΡ‡ΠΈΠ»ΠΎΡΡŒ:", LetterGraph) # ΠŸΡ€ΠΎΠ²Π΅Ρ€ΡΠ΅ΠΌ, Ρ‡Ρ‚ΠΎ Π½Π΅Ρ‚Ρƒ Ρ†ΠΈΠΊΠ»Π° if LetterGraph: Cycle = False for i in LetterGraph: try: if LetterGraph[LetterGraph[i]] == i: Cycle = True except: continue if Cycle: print("NO") exit(0) # Находим Π²ΠΎΠ·ΠΌΠΎΠΆΠ½Ρ‹Π΅ ΠΏΠ΅Ρ€Π²Ρ‹Π΅ символы if LetterGraph: IsIFirstSymbol = False FirstSymbols = [] for i in LetterGraph: IsIFirstSymbol = True for e in LetterGraph: if LetterGraph[e] == i: #print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ…ΠΎΠ΄ΠΈΡ‚, ΠΏΠΎΡ‚ΠΎΠΌΡƒ Ρ‡Ρ‚ΠΎ", e, "ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚ Π½Π° Π½Π΅Π³ΠΎ.") IsIFirstSymbol = False if IsIFirstSymbol: FirstSymbols.append(i) if not FirstSymbols: print("NO") exit(0) #print("Π’Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ ΠΏΠ΅Ρ€Π²ΠΎΠ³ΠΎ символа:", *FirstSymbols) # Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°Ρ€ΠΈΠ°Π½Ρ‚Ρ‹ Ρ„ΠΈΠ½Π°Π»ΡŒΠ½ΠΎΠΉ строки if LetterGraph: Letter = "" for i in FirstSymbols: FinalString = i Letter = i for e in range(len(LetterGraph)): if Letter in LetterGraph: if not (LetterGraph[Letter] == ""): FinalString += LetterGraph[Letter] #print(Letter, "Π΅ΡΡ‚ΡŒ Π² Π³Ρ€Π°Ρ„Π΅, Ρ‚Π°ΠΊ Ρ‡Ρ‚ΠΎ добавляСм", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡ‚ΠΎΡ€ΠΎΠ΅ ΠΎΠ½ΠΎ ΡƒΠΊΠ°Π·Ρ‹Π²Π°Π΅Ρ‚.") Letter = LetterGraph[Letter] else: break else: break FinalStrings.append(FinalString) #print("ΠžΡ‚Π΄Π΅Π»ΡŒΠ½Ρ‹Π΅ строки", *FinalStrings) FinalStrings.sort() RESULT = "" for i in FinalStrings: RESULT += i print(RESULT) ```
instruction
0
77,953
0
155,906
No
output
1
77,953
0
155,907
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. Submitted Solution: ``` n=int(input()) m=[] sc=[] for i in range(n): m.append(input()) sc.append(set(m[i])) i=0 pX=False while i<len(m): j=i+1 p=False while j<len(m): z=len(sc[i].intersection(sc[j])) #a=len(sc[i]) #b=len(sc[j]) if m[i] in m[j]: sc.pop(i) m.pop(i) i-=1 break elif m[j] in m[i]: sc.pop(j) m.pop(j) j-=1 elif z>0: if m[i][-z:]==m[j][:z]: m[i]+=m[j][z:] elif m[j][-z:]==m[i][:z]: m[i]=m[j]+m[i][z:] else: pX=True break sc[i]=set(m[i]) m.pop(j) sc.pop(j) j-=1 p=True j+=1 if not p: i+=1 if pX: print('NO') break else: print(''.join(sorted(m))) #atoumrydhfgwekjilbpsvqncx ```
instruction
0
77,954
0
155,908
No
output
1
77,954
0
155,909
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring. You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes). A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string. The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap. String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ. Input The first line contains integer n (1 ≀ n ≀ 105) β€” the number of strings in the set. Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct. The total length of the strings doesn't exceed 105. Output Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings. Examples Input 4 mail ai lru cf Output cfmailru Input 3 kek preceq cheburek Output NO Note One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. Submitted Solution: ``` n = int(input()) A = [] for i in range (0,n): A = A + [input()] start = [100]*26 end = [100]*26 def num(x): return(ord(x)-ord("a")) def let(x): return(chr(x+ord("a"))) def ans(x): final = [] for i in range (0,n): B = list(A[i]) if len(B) == 1: if start[num(B[0])] == 100: start[num(B[0])] = -100 if end[num(B[0])] == 100: end[num(B[0])] = -100 else: for j in range (0,len(B)): if j==0: if start[num(B[j])] == 100 or start[num(B[j])] == -100: start[num(B[j])] = -100 if end[num(B[j])] == 100 or end[num(B[j])] == -100: if start[num(B[j])] != 100 and start[num(B[j])] != -100: end[num(B[j])] = num(B[j+1]) if end[num(B[j])] == num(B[j+1]): g=0 else: return("NO") elif 0<j<len(B)-1: if start[num(B[j])] == 100 or start[num(B[j])] == -100: start[num(B[j])] = num(B[j-1]) elif start[num(B[j])] != num(B[j-1]): return("NO") if end[num(B[j])] == 100 or end[num(B[j])] == -100: end[num(B[j])] = num(B[j+1]) elif end[num(B[j])] != num(B[j+1]): return("NO") elif j == len(B)-1: if end[num(B[j])] == 100: end[num(B[j])] = -100 if start[num(B[j])] == 100 or start[num(B[j])] == -100: if end[num(B[j])] != 100 and end[num(B[j])] != -100: start[num(B[j])] = num(B[j-1]) if start[num(B[j])] != num(B[j-1]): g=0 else: return("NO") if len(set(start))+max(0,start.count(100)-1)+max(0,start.count(-100)-1) != 26: return("NO") elif len(set(end))+max(0,end.count(100)-1)+max(0,end.count(-100)-1) != 26: return("NO") else: for i in range (0,26): if start[i] != -100: g=0 else: final = final + [let(i)] j = end[i] while j != -100: final = final + [let(j)] j = end[j] return("".join(final)) print(ans(A)) ```
instruction
0
77,955
0
155,910
No
output
1
77,955
0
155,911
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,111
0
156,222
"Correct Solution: ``` s = input() n = len(s) INF = 10**9 alph = "abcdefghijklmnopqrstuvwxyz" to_int = {v: i for i, v in enumerate(alph)} dp = {} all_state = 0 for i in range(n): all_state ^= 1 << to_int[s[i]] if all_state not in dp: dp[all_state] = i + 1 for j in range(26): bit = all_state ^ (1 << j) if bit in dp: dp[all_state] = min(dp[bit] + 1, dp[all_state]) if bin(all_state).count("1") <= 1: dp[all_state] = 1 print(dp[all_state]) ```
output
1
78,111
0
156,223
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,112
0
156,224
"Correct Solution: ``` def main(): import sys from bisect import bisect_left input = sys.stdin.readline S = input().rstrip('\n') N = len(S) A = [ord(s)-97 for s in S] H = [0] * (N+1) h2i = {} for i in range(N): H[i+1] = H[i] ^ (1 << A[i]) if H[i+1] in h2i: h2i[H[i+1]].append(i+1) else: h2i[H[i+1]] = [i+1] dp = [N+1] * (N+1) dp[0] = 0 pow2 = [2**i for i in range(26)] for i in range(N): h = H[i] if h in h2i: ii_list = h2i[h] ii = bisect_left(ii_list, i+1) if ii < len(ii_list): ii = ii_list[ii] if i: dp[ii] = min(dp[ii], dp[i]) else: dp[ii] = 1 for j in pow2: new_h = h ^ j if new_h in h2i: ii_list = h2i[new_h] ii = bisect_left(ii_list, i+1) if ii < len(ii_list): ii = ii_list[ii] dp[ii] = min(dp[ii], dp[i] + 1) print(dp[-1]) if __name__ == '__main__': main() ```
output
1
78,112
0
156,225
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,113
0
156,226
"Correct Solution: ``` import itertools L=9**9 dp={0:0} for v in itertools.accumulate(map(lambda c:1<<ord(c)-ord('a'),input()),lambda a,b:a^b): dp[v]=min(dp.get(v,L),min(dp.get(v^1<<i, L)for i in range(26))+1) print(dp[v]+(v==0)) ```
output
1
78,113
0
156,227
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,114
0
156,228
"Correct Solution: ``` import sys readline = sys.stdin.buffer.readline ns = lambda: readline().rstrip() ni = lambda: int(readline().rstrip()) nm = lambda: map(int, readline().split()) nl = lambda: list(map(int, readline().split())) def solve(): s = [x - 97 for x in ns()] n = len(s) c = 0 g = {0:0} for x in s: c ^= 1 << x y = g.get(c, n) + 1 for i in range(26): y = min(y, g.get(c ^ (1 << i), n) + 1) g[c] = min(g.get(c, n), y) print(y) return solve() ```
output
1
78,114
0
156,229
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,115
0
156,230
"Correct Solution: ``` from collections import defaultdict s = input() n = len(s) dp = defaultdict(int) dp[0] = 1 ls = [1<<(ord(s[0])-97)] for i in range(1,n): ls.append(ls[-1]^(1<<(ord(s[i])-97))) if ls[-1] == 0: print(1) exit() for i in range(n): for b in range(26): bit = 1<<b if dp[ls[i]^bit] == 0: continue if dp[ls[i]] == 0: dp[ls[i]] = dp[ls[i]^bit]+1 else: dp[ls[i]] = min(dp[ls[i]^bit]+1,dp[ls[i]]) print(dp[ls[n-1]]-1) ```
output
1
78,115
0
156,231
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,116
0
156,232
"Correct Solution: ``` import sys readline = sys.stdin.readline from collections import defaultdict S = list(map(lambda x: ord(x)-97, readline().strip())) N = len(S) table = [0] + [1<<S[i] for i in range(N)] for i in range(1, N+1): table[i] ^= table[i-1] inf = 10**9+7 dp = defaultdict(lambda: inf) dp[0] = 0 for i in range(1, N+1): t = table[i] res = 1+dp[t] for j in range(26): res = min(res, 1+dp[t^(1<<j)]) dp[t] = min(dp[t], res) print(res) ```
output
1
78,116
0
156,233
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,117
0
156,234
"Correct Solution: ``` s = input() N = len(s) a = 0 dp = {} dp[0] = 0 bits = [2 ** i for i in range(26)] for c in s: a = a ^ bits[ord(c)-ord('a')] dp[a] = min(dp.get(a, N), min([dp.get(a ^ bit, N) for bit in bits]) + 1) print(dp[a] if dp[a] != 0 else 1) ```
output
1
78,117
0
156,235
Provide a correct Python 3 solution for this coding contest problem. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3
instruction
0
78,118
0
156,236
"Correct Solution: ``` import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools sys.setrecursionlimit(10**7) inf = 10**20 eps = 1.0 / 10**15 mod = 10**9+7 def LI(): return [int(x) for x in sys.stdin.readline().split()] def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()] def LF(): return [float(x) for x in sys.stdin.readline().split()] def LS(): return sys.stdin.readline().split() def I(): return int(sys.stdin.readline()) def F(): return float(sys.stdin.readline()) def S(): return input() def pf(s): return print(s, flush=True) def main(): a = [2**(ord(c)-97) for c in S()] b = [0] d2 = {} d2[0] = 0 c = 0 ii = [2**i for i in range(26)] for t,i in zip(a, range(1,len(a)+1)): c ^= t tr = inf if c in d2: tr = d2[c] + 1 for j in ii: e = c ^ j if e in d2 and d2[e] + 1 < tr: tr = d2[e] + 1 if c not in d2 or d2[c] > tr: d2[c] = tr return d2[c] if d2[c] else 1 print(main()) ```
output
1
78,118
0
156,237
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` def main(): S = input() n = len(S) a = {j: i for i, j in enumerate('abcdefghijklmnopqrstuvwxyz')} S = [a[i] for i in S] dp = [10**9]*(n+1) dp[0] = 0 parity = 0 dict_parity = {0: 0} for i, s in enumerate(S): parity ^= 2**s ans = i+1 if parity in dict_parity: ans = min(ans, dp[dict_parity[parity]]+1) for j in range(26): parity2 = parity ^ 2**j if parity2 in dict_parity: ans = min(ans, dp[dict_parity[parity2]]+1) dp[i+1] = ans if parity not in dict_parity: dict_parity[parity] = i+1 elif dp[dict_parity[parity]] > ans: dict_parity[parity] = i+1 print(dp[-1]) main() ```
instruction
0
78,119
0
156,238
Yes
output
1
78,119
0
156,239
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` # --*-coding:utf-8-*-- def f(str): s = {} s[0] = 0 pat = 0 bits = [2**i for i in range(26)] lenOfStr = len(str) for c in str: pat ^= bits[ord(c)-97] s[pat] = min( min(s.get(pat^bit, lenOfStr) + 1 for bit in bits), s.get(pat, lenOfStr)) if pat == 0: return 1 return s[pat] str = input() print(f(str)) ```
instruction
0
78,120
0
156,240
Yes
output
1
78,120
0
156,241
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` from collections import defaultdict s = input() n = len(s) inf = 10**6 d = defaultdict(lambda : inf) d[0] = 0 a = ord('a') now = 0 for i in range(n): si = ord(s[i]) - a now = now^(1<<si) for j in range(26): d[now] = min(d[now], 1+d[now^(1<<j)]) print(max(1,d[now])) ```
instruction
0
78,121
0
156,242
Yes
output
1
78,121
0
156,243
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` from collections import defaultdict s = input() n = len(s) dp = defaultdict(int) dp[0] = 1 ls = [1<<(ord(s[0])-97)] for i in range(1,n): ls.append(ls[-1]^(1<<(ord(s[i])-97))) if ls[-1] == 0: print(1) exit() for i in range(n): for b in range(26): bit = 1<<b if dp[ls[i]^bit] == 0: continue if dp[ls[i]] == 0: dp[ls[i]] = dp[ls[i]^bit]+1 else: dp[ls[i]] = min(dp[ls[i]^bit]+1,dp[ls[i]]) print(dp[ls[n-1]]-1) ```
instruction
0
78,123
0
156,246
No
output
1
78,123
0
156,247
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` from collections import Counter from string import ascii_lowercase from functools import lru_cache import sys s = input() sys.setrecursionlimit(100000000) tmp_c = Counter(s) val = sum(tmp_c[s_tmp]%2 for s_tmp in ascii_lowercase) if val==0: val=1 if val>5: raise print(val) ```
instruction
0
78,124
0
156,248
No
output
1
78,124
0
156,249
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition: * For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome. Find the minimum possible value of N when the partition satisfies the condition. Constraints * 1 \leq |s| \leq 2 \times 10^5 * s consists of lowercase English letters. Input Input is given from Standard Input in the following format: s Output Print the minimum possible value of N when the partition satisfies the condition. Examples Input aabxyyzz Output 2 Input byebye Output 1 Input abcdefghijklmnopqrstuvwxyz Output 26 Input abcabcxabcx Output 3 Submitted Solution: ``` #!/usr/bin/env python3 s = input() t = 0 d = {t:0} for i in s : t ^= 1 << (ord(i)-ord('a')) for j in range(26) : if (t^(1<<j)) in d : d[t] = min(d[t] if t in d else int(1e9),d[t^(1<<j)]+1) print(d[t] if d[t] else 1) ```
instruction
0
78,125
0
156,250
No
output
1
78,125
0
156,251