message stringlengths 2 23.8k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 97 109k | cluster float64 0 0 | __index_level_0__ int64 194 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,443 | 0 | 152,886 |
Tags: sortings, strings
Correct Solution:
```
def subset(A, B, l_A, l_B):
for i in range(l_B-l_A+1):
X = B[i:l_A+i]
if A == X:
return False
return True
def main():
n = int(input())
X = ['' for _ in range(n)]
for i in range(n):
x = input()
X[i] = (len(x), x)
X.sort()
for i in range(n-1):
if subset(X[i][1], X[i+1][1], X[i][0], X[i+1][0]):
print('NO')
return
print('YES')
for i in range(n):
print(X[i][1])
main()
``` | output | 1 | 76,443 | 0 | 152,887 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,444 | 0 | 152,888 |
Tags: sortings, strings
Correct Solution:
```
n=int(input())
a=[]
for i in range(n):
a.append(input())
a.sort(key=len)
answer='YES'
for i in range(n-1):
if a[i] in a[i+1]:
answer+='\n'+a[i]
else:
answer='NO'
a[-1]=''
break
if answer[0:3]=='YES':
print(answer+'\n'+a[-1])
else:
print(answer)
``` | output | 1 | 76,444 | 0 | 152,889 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,445 | 0 | 152,890 |
Tags: sortings, strings
Correct Solution:
```
n = int(input())
a = []
for i in range(n):
x = input()
a.append([len(x),x])
a.sort()
for i in range(1,n):
if(a[i-1][1] not in a[i][1]):
print("NO")
break
else:
print("YES")
for i in a:
print(i[1])
``` | output | 1 | 76,445 | 0 | 152,891 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,446 | 0 | 152,892 |
Tags: sortings, strings
Correct Solution:
```
n = int(input())
l = []
for i in range(n):
x = input()
l.append(x)
l = sorted(l, key=len)
flag = 1
for i in range(n-1):
if (l[i] not in l[i+1]):
flag = 0
break
if flag:
print("YES")
for i in l:
print(i)
else:
print("NO")
``` | output | 1 | 76,446 | 0 | 152,893 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,447 | 0 | 152,894 |
Tags: sortings, strings
Correct Solution:
```
n=int(input(''))
slarray=list()
for i in range(0,n):
x=input('')
slarray.append((x,len(x)))
slarray=sorted(slarray,key=lambda x: x[1],reverse=False)
for i in range(0,n-1):
if slarray[i][0] not in slarray[i+1][0]:
print('NO')
quit()
print('YES')
for pr in slarray:
print(pr[0])
``` | output | 1 | 76,447 | 0 | 152,895 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba". | instruction | 0 | 76,448 | 0 | 152,896 |
Tags: sortings, strings
Correct Solution:
```
n = int(input())
m = []
for i in range(n):
k = input()
m.append((len(k),k))
m.sort()
flg = 0
cur_str = m[0][1]
for i in range(1,n):
if(m[i][1].find(cur_str) == -1):
print("NO")
flg = 1
break
else:
cur_str = m[i][1]
if(flg == 0):
print("YES")
for i in m:
print(i[1])
``` | output | 1 | 76,448 | 0 | 152,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
li=[]
for _ in range(int(input())):
s=input()
li.append(s)
lst2 = sorted(li, key=len)
c=1
for i in range(len(lst2)-1):
if(lst2[i] not in lst2[i+1]):
c=0
if(c==1):
print("YES")
for j in lst2:
print(j)
else:
print("NO")
``` | instruction | 0 | 76,449 | 0 | 152,898 |
Yes | output | 1 | 76,449 | 0 | 152,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
st = []
for i in range(n):
st.append(input())
for i in range(n - 1):
for j in range(i, n):
if (not(st[i] in st[j])) and (not(st[j] in st[i])):
print("NO")
quit()
if (st[j] in st[i]):
wk1 = st[i]
st[i] = st[j]
st[j] = wk1
print("YES")
for i in st:
print(i)
``` | instruction | 0 | 76,450 | 0 | 152,900 |
Yes | output | 1 | 76,450 | 0 | 152,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
a = []
for i in range(n):
a.append(input())
a.sort(key = len)
for i in range(n - 1):
if a[i] not in a[i + 1]:
print("NO")
exit()
print("YES")
for i in range(n):
print(a[i])
``` | instruction | 0 | 76,451 | 0 | 152,902 |
Yes | output | 1 | 76,451 | 0 | 152,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
l = []
for i in range(n):
l.append(input())
#print(l)
l.sort(key=len )
#print(l)
k = l[-1]
f = True
for i in range(n - 1):
if l[i] not in l[i + 1] or l[i] not in k:
f = False
break
if f :
print('YES')
print(*l , sep = '\n')
else:
print('NO')
``` | instruction | 0 | 76,452 | 0 | 152,904 |
Yes | output | 1 | 76,452 | 0 | 152,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
a = []
for i in range(n):
a += [input()]
def solve(a, n):
for i in range(n):
for j in range(n-1):
if a[j+1] in a[j]:
a[j+1], a[j] = a[j], a[j+1]
elif len(a[j+1]) < len(a[j]):
return print("NO")
print("YES")
for aa in a:
print(aa)
solve(a,n)
``` | instruction | 0 | 76,453 | 0 | 152,906 |
No | output | 1 | 76,453 | 0 | 152,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
l= []
for i in range(n):
l.append(input())
l= sorted(l,key=lambda w: len(w))
for i in range(len(l)-1):
if l[i] not in l[-1]:
print('NO')
break
print('YES')
for i in l:
print(i)
``` | instruction | 0 | 76,454 | 0 | 152,908 |
No | output | 1 | 76,454 | 0 | 152,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
n = int(input())
lst_str = []
for i in range(n):
string = input()
lst_str.append(string)
lst2 = sorted(lst_str, key=len)
for a in range(len(lst2)):
if a == len(lst2) - 1:
continue
if lst2[a] not in lst2[a+1]:
print("NO")
break
else:
print("YES")
for i in lst_str:
print(i)
``` | instruction | 0 | 76,455 | 0 | 152,910 |
No | output | 1 | 76,455 | 0 | 152,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n strings. Each string consists of lowercase English letters. Rearrange (reorder) the given strings in such a way that for every string, all strings that are placed before it are its substrings.
String a is a substring of string b if it is possible to choose several consecutive letters in b in such a way that they form a. For example, string "for" is contained as a substring in strings "codeforces", "for" and "therefore", but is not contained as a substring in strings "four", "fofo" and "rof".
Input
The first line contains an integer n (1 β€ n β€ 100) β the number of strings.
The next n lines contain the given strings. The number of letters in each string is from 1 to 100, inclusive. Each string consists of lowercase English letters.
Some strings might be equal.
Output
If it is impossible to reorder n given strings in required order, print "NO" (without quotes).
Otherwise print "YES" (without quotes) and n given strings in required order.
Examples
Input
5
a
aba
abacaba
ba
aba
Output
YES
a
ba
aba
aba
abacaba
Input
5
a
abacaba
ba
aba
abab
Output
NO
Input
3
qwerty
qwerty
qwerty
Output
YES
qwerty
qwerty
qwerty
Note
In the second example you cannot reorder the strings because the string "abab" is not a substring of the string "abacaba".
Submitted Solution:
```
# cook your dish here
#import sys
#sys.setrecursionlimit(10**9)
ll=lambda:map(int,input().split())
t=lambda:int(input())
ss=lambda:input()
lx=lambda x:map(int,input().split(x))
yy=lambda:print("Yes")
nn=lambda:print("No")
from math import log10 ,log2,ceil,factorial as fac,gcd,inf,sqrt,log
#from itertools import combinations_with_replacement as cs
#from functools import reduce
from bisect import bisect_right as br,bisect_left as bl
from collections import Counter
#from math import inf
mod=10**9+7
#for _ in range(t()):
def f():
n=t()
l={}
d=[]
for i in range(n):
q=ss()
if len(q) not in l:
l[len(q)]=[]
l[len(q)].append(q)
last=1
fl=0
x=0
for i in sorted(l):
if last==1:
last=l[i][0]
fl=1
else:
fl=0
for j in range(fl,len(l[i])):
if last not in l[i][j]:
x=1
break
if x:
nn()
break
else:
yy()
for i in sorted(l):
for j in l[i]:
print(j)
f()
'''
baca
bac
1 2 3
baaccca
abbaccccaba
'''
``` | instruction | 0 | 76,456 | 0 | 152,912 |
No | output | 1 | 76,456 | 0 | 152,913 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,539 | 0 | 155,078 |
"Correct Solution:
```
N = int(input())
if N==1:
print(1)
print(0)
elif N==2:
print(2)
print(0)
print(11)
else:
print(N-1)
for i in range(N-1):
print('0' + '1'*i + '0')
``` | output | 1 | 77,539 | 0 | 155,079 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,540 | 0 | 155,080 |
"Correct Solution:
```
N=int(input())
if N==1:
print(1)
print(0)
elif N==2:
print(2)
print(11)
print(0)
else:
print(N-1)
for i in range(N-1):
print("0"+"1"*i+"0")
``` | output | 1 | 77,540 | 0 | 155,081 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,541 | 0 | 155,082 |
"Correct Solution:
```
K = int(input())
if K==1:
print(1)
print(0)
elif K==2:
print(2)
print(0)
print(11)
elif K >= 3:
print(K-1)
for i in range(K-1):
print("0"+"1"*i+"0")
``` | output | 1 | 77,541 | 0 | 155,083 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,542 | 0 | 155,084 |
"Correct Solution:
```
N = int(input())
K = N-1
if N == 2:
print(2)
print("00")
print("1")
if N == 1:
print(1)
print(1)
else:
print(K)
for i in range(K):
print("1"+"0"*i+"1")
``` | output | 1 | 77,542 | 0 | 155,085 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,543 | 0 | 155,086 |
"Correct Solution:
```
N = int(input())
A = []
for i in range(0,N-1):
A.append("1"+"0"*i+"1")
if N==1:
A=["1"]
if N==2:
A=["0","11"]
print(len(A))
for a in A:print(a)
``` | output | 1 | 77,543 | 0 | 155,087 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,544 | 0 | 155,088 |
"Correct Solution:
```
n = int(input())
if n == 1:
print(1)
print(0)
exit()
if n == 2:
print(2)
print(0)
print(11)
exit()
print(n-1)
for i in range(n-1):
print("1" + "0"*i + "1")
``` | output | 1 | 77,544 | 0 | 155,089 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,545 | 0 | 155,090 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
sys.setrecursionlimit(1000000)
from collections import deque, Counter
def getN():
return int(input())
def getList():
return list(map(int, input().split()))
import math
INF = 10 ** 20
def main():
n = getN()
if n == 1:
print(1)
print(1)
return
if n == 2:
print(2)
print(0)
print("11")
return
print(n-1)
print("11")
for i in range(1, n-1):
print("1" + "0" * i + "1")
return
if __name__ == "__main__":
main()
``` | output | 1 | 77,545 | 0 | 155,091 |
Provide a correct Python 3 solution for this coding contest problem.
Problem statement
Of the string set $ S $ that meets the following conditions, configure $ 1 $ with the largest number of elements.
* The length of the string contained in $ S $ is $ 1 $ or more and $ N $ or less.
* The lengths of the strings contained in $ S $ are different.
* The string contained in $ S $ consists only of the characters `0` and` 1`.
* For any $ 2 $ string contained in $ S $, one is not a substring of the other.
However, the substring of the string $ x $ is the string obtained by removing more than $ 0 $ characters from the beginning and end of $ x $.
Constraint
* $ 1 \ leq N \ leq 300 $
* $ N $ is an integer
* * *
input
Input is given from standard input in the following format.
$ N $
output
Output $ 1 $ of the string set $ S $ that satisfies the condition with the maximum number of elements. There may be multiple such $ S $, but any output will be correct.
Specifically, output in the following format.
Output $ K $, the number of elements of $ S $, on the $ 1 $ line.
Output all $ S $ elements from the $ 2 $ line to the $ K + 1 $ line. Print $ 1 $ of $ S $ elements on each line.
$ K $
$ S_1 $
$ S_2 $
$ \ vdots $
$ S_K $
* * *
Input example 1
2
Output example 1
2
0
11
The string set $ \\ {0, 11 \\} $ is the set with the largest number of elements that meets the conditions.
* * *
Input example 2
1
Output example 2
1
0
Example
Input
2
Output
2
0
11 | instruction | 0 | 77,546 | 0 | 155,092 |
"Correct Solution:
```
from heapq import *
from collections import deque
import sys
sys.setrecursionlimit(10 ** 6)
int1 = lambda x: int(x) - 1
p2D = lambda x: print(*x, sep="\n")
def II(): return int(sys.stdin.readline())
def MI(): return map(int, sys.stdin.readline().split())
def LI(): return list(map(int, sys.stdin.readline().split()))
def LLI(rows_number): return [LI() for _ in range(rows_number)]
def SI(): return sys.stdin.readline()[:-1]
class Dice:
def __init__(self,top,bot,lef,rig,fro,bac):
self.top = top
self.bot = bot
self.lef = lef
self.rig = rig
self.fro = fro
self.bac = bac
def up(self):
top, bac, bot, fro = self.fro, self.top, self.bac, self.bot
return Dice(top,bot,self.lef,self.rig,fro,bac)
def down(self):
top, bac, bot, fro = self.bac, self.bot, self.fro, self.top
return Dice(top,bot,self.lef,self.rig,fro,bac)
def right(self):
top, rig, bot, lef = self.lef, self.top, self.rig, self.bot
return Dice(top,bot,lef,rig,self.fro,self.bac)
def left(self):
top, rig, bot, lef = self.rig, self.bot, self.lef, self.top
return Dice(top,bot,lef,rig,self.fro,self.bac)
def state(self):
return (self.top, self.rig, self.bot, self.lef, self.fro, self.bac)
def main():
n=int(input())
if n==1:
print(1)
print(1)
exit()
if n==2:
print(2)
print(0)
print(11)
exit()
print(n-1)
for i in range(n-1):
print("1"+"0"*i+"1")
main()
``` | output | 1 | 77,546 | 0 | 155,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n characters. These characters are among the first k lowercase letters of the Latin alphabet. You have to perform n operations with the string.
During the i-th operation, you take the character that initially occupied the i-th position, and perform one of the following actions with it:
* swap it with the previous character in the string (if it exists). This operation is represented as L;
* swap it with the next character in the string (if it exists). This operation is represented as R;
* cyclically change it to the previous character in the alphabet (b becomes a, c becomes b, and so on; a becomes the k-th letter of the Latin alphabet). This operation is represented as D;
* cyclically change it to the next character in the alphabet (a becomes b, b becomes c, and so on; the k-th letter of the Latin alphabet becomes a). This operation is represented as U;
* do nothing. This operation is represented as 0.
For example, suppose the initial string is test, k = 20, and the sequence of operations is URLD. Then the string is transformed as follows:
1. the first operation is U, so we change the underlined letter in test to the next one in the first 20 Latin letters, which is a. The string is now aest;
2. the second operation is R, so we swap the underlined letter with the next one in the string aest. The string is now aset;
3. the third operation is L, so we swap the underlined letter with the previous one in the string aset (note that this is now the 2-nd character of the string, but it was initially the 3-rd one, so the 3-rd operation is performed to it). The resulting string is saet;
4. the fourth operation is D, so we change the underlined letter in saet to the previous one in the first 20 Latin letters, which is s. The string is now saes.
The result of performing the sequence of operations is saes.
Given the string s and the value of k, find the lexicographically smallest string that can be obtained after applying a sequence of operations to s.
Input
The first line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Each test case consists of two lines. The first line contains two integers n and k (1 β€ n β€ 500; 2 β€ k β€ 26).
The second line contains a string s consisting of n characters. Each character is one of the k first letters of the Latin alphabet (in lower case).
Output
For each test case, print one line containing the lexicographically smallest string that can be obtained from s using one sequence of operations.
Example
Input
6
4 2
bbab
7 5
cceddda
6 5
ecdaed
7 4
dcdbdaa
8 3
ccabbaca
5 7
eabba
Output
aaaa
baccacd
aabdac
aabacad
aaaaaaaa
abadb
Submitted Solution:
```
for i in range(int(input())):
n,k = map(int,input().split())
l=[ord(ch)-97 for ch in list(input())]
mi=[max(0,v-1) if v<k-1 else 0 for v in l]
x=0
while(x<n-1):
if l[x]<l[x-1]:
l[x-1],l[x]=l[x],l[x-1]
x=x+1
elif mi[x+1]<mi[x]:
l[x],l[x+1]=l[x+1],l[x]
if l[x-1]>l[x]:
l[x],l[x-1]=l[x-1],l[x]
else:
l[x]=mi[x+1]
x=x+2
else:
l[x]=mi[x]
x=x+1
if (x==(n-1)):
l[x]=mi[x]
print(''.join([chr(g+97) for g in l]))
``` | instruction | 0 | 77,735 | 0 | 155,470 |
No | output | 1 | 77,735 | 0 | 155,471 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a string s consisting of n characters. These characters are among the first k lowercase letters of the Latin alphabet. You have to perform n operations with the string.
During the i-th operation, you take the character that initially occupied the i-th position, and perform one of the following actions with it:
* swap it with the previous character in the string (if it exists). This operation is represented as L;
* swap it with the next character in the string (if it exists). This operation is represented as R;
* cyclically change it to the previous character in the alphabet (b becomes a, c becomes b, and so on; a becomes the k-th letter of the Latin alphabet). This operation is represented as D;
* cyclically change it to the next character in the alphabet (a becomes b, b becomes c, and so on; the k-th letter of the Latin alphabet becomes a). This operation is represented as U;
* do nothing. This operation is represented as 0.
For example, suppose the initial string is test, k = 20, and the sequence of operations is URLD. Then the string is transformed as follows:
1. the first operation is U, so we change the underlined letter in test to the next one in the first 20 Latin letters, which is a. The string is now aest;
2. the second operation is R, so we swap the underlined letter with the next one in the string aest. The string is now aset;
3. the third operation is L, so we swap the underlined letter with the previous one in the string aset (note that this is now the 2-nd character of the string, but it was initially the 3-rd one, so the 3-rd operation is performed to it). The resulting string is saet;
4. the fourth operation is D, so we change the underlined letter in saet to the previous one in the first 20 Latin letters, which is s. The string is now saes.
The result of performing the sequence of operations is saes.
Given the string s and the value of k, find the lexicographically smallest string that can be obtained after applying a sequence of operations to s.
Input
The first line contains one integer t (1 β€ t β€ 1000) β the number of test cases.
Each test case consists of two lines. The first line contains two integers n and k (1 β€ n β€ 500; 2 β€ k β€ 26).
The second line contains a string s consisting of n characters. Each character is one of the k first letters of the Latin alphabet (in lower case).
Output
For each test case, print one line containing the lexicographically smallest string that can be obtained from s using one sequence of operations.
Example
Input
6
4 2
bbab
7 5
cceddda
6 5
ecdaed
7 4
dcdbdaa
8 3
ccabbaca
5 7
eabba
Output
aaaa
baccacd
aabdac
aabacad
aaaaaaaa
abadb
Submitted Solution:
```
import io,os
JJJ=input;input=lambda:JJJ().encode()
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
for _ in range(int(input())):
n,k=list(map(int,input().split()))
s=[x - ord('a') for x in input().strip()]
c=[min(x,(x+1)%k,(x-1)%k) for x in s]
i = 0
moved = False
while i < n:
d = {'stand': (c[i], 0)}
if i<n-2:
d['o2a'] = (s[i+2], 2)
if i<n-1:
if not moved:
d['b1a'] = (c[i+1], 3)
d['o1a'] = (s[i+1], 1)
op = min(d,key=d.get)
#print(i, "".join(chr(x + ord('a')) for x in c), op)
if op == 'stand':
i += 1
moved = False
elif op == 'o2a':
c[i],c[i+1],c[i+2]=s[i+2],c[i],s[i+1]
i += 2
moved = True
elif op == 'o1a':
c[i],c[i+1] = s[i+1],c[i]
moved = True
i += 1
elif op == 'b1a':
c[i],c[i+1] = c[i+1],s[i]
moved = True
i += 1
print("".join(chr(x + ord('a')) for x in c))
``` | instruction | 0 | 77,736 | 0 | 155,472 |
No | output | 1 | 77,736 | 0 | 155,473 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases:
1. They are equal.
2. If we split string a into two halves of the same size a1 and a2, and string b into two halves of the same size b1 and b2, then one of the following is correct:
1. a1 is equivalent to b1, and a2 is equivalent to b2
2. a1 is equivalent to b2, and a2 is equivalent to b1
As a home task, the teacher gave two strings to his students and asked to determine if they are equivalent.
Gerald has already completed this home task. Now it's your turn!
Input
The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200 000 and consists of lowercase English letters. The strings have the same length.
Output
Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise.
Examples
Input
aaba
abaa
Output
YES
Input
aabb
abab
Output
NO
Note
In the first sample you should split the first string into strings "aa" and "ba", the second one β into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equivalent only to themselves. That's why string "aabb" is equivalent only to itself and to string "bbaa". | instruction | 0 | 77,860 | 0 | 155,720 |
Tags: divide and conquer, hashing, sortings, strings
Correct Solution:
```
str1 = input()
str2 = input()
def compare(s):
if (len(s) % 2 == 1):
return s
half = int(len(s) / 2)
s1 = compare(s[0:half])
s2 = compare(s[half:len(s)])
if (s1 < s2):
return s1 + s2
else:
return s2 + s1
if (compare(str1) == compare(str2)):
print('YES')
else:
print('NO')
``` | output | 1 | 77,860 | 0 | 155,721 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Today on a lecture about strings Gerald learned a new definition of string equivalency. Two strings a and b of equal length are called equivalent in one of the two cases:
1. They are equal.
2. If we split string a into two halves of the same size a1 and a2, and string b into two halves of the same size b1 and b2, then one of the following is correct:
1. a1 is equivalent to b1, and a2 is equivalent to b2
2. a1 is equivalent to b2, and a2 is equivalent to b1
As a home task, the teacher gave two strings to his students and asked to determine if they are equivalent.
Gerald has already completed this home task. Now it's your turn!
Input
The first two lines of the input contain two strings given by the teacher. Each of them has the length from 1 to 200 000 and consists of lowercase English letters. The strings have the same length.
Output
Print "YES" (without the quotes), if these two strings are equivalent, and "NO" (without the quotes) otherwise.
Examples
Input
aaba
abaa
Output
YES
Input
aabb
abab
Output
NO
Note
In the first sample you should split the first string into strings "aa" and "ba", the second one β into strings "ab" and "aa". "aa" is equivalent to "aa"; "ab" is equivalent to "ba" as "ab" = "a" + "b", "ba" = "b" + "a".
In the second sample the first string can be splitted into strings "aa" and "bb", that are equivalent only to themselves. That's why string "aabb" is equivalent only to itself and to string "bbaa". | instruction | 0 | 77,861 | 0 | 155,722 |
Tags: divide and conquer, hashing, sortings, strings
Correct Solution:
```
def equal(a, b):
def msort(s):
length = len(s)
if length % 2:
return s
s1 = msort(s[:length // 2])
s2 = msort(s[length // 2:])
if s1 < s2:
return s1 + s2
else:
return s2 + s1
if msort(a) == msort(b):
return True
else:
return False
a = input()
b = input()
print('YES' if equal(a, b) else 'NO')
``` | output | 1 | 77,861 | 0 | 155,723 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,946 | 0 | 155,892 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
n = int(input())
wrong_str = False
strings = []
sets = []
for _ in range(n):
new_string = input()
new_string_set = set(new_string)
if len(new_string) != len(new_string_set):
wrong_str = True
break
strings.append(new_string)
sets.append(new_string_set)
if wrong_str:
print("NO")
exit(0)
connections = []
for _ in range(n):
connections.append((-1,-1))
changed = True
while changed:
changed = False
for i in range(len(strings)):
if strings[i] == None:
continue
for j in range(i + 1, len(strings)):
if strings[j] == None:
continue
if len(set(strings[i]).intersection(set(strings[j]))) == 0:
continue
a = strings[i]
b = strings[j]
#print(a, b)
if b in a:
strings[j] = None
changed = True
elif a in b:
strings[i] = b
strings[j] = None
changed = True
else:
is_ok = False
start_index = a.find(b[0])
if start_index != -1 and a[start_index:] in b:
strings[i] += strings[j][len(a) - start_index:]
strings[j] = None
is_ok = True
changed = True
if not is_ok:
start_index = b.find(a[0])
if start_index != -1 and b[start_index:] in a:
strings[i] = strings[j] + strings[i][len(b) - start_index:]
strings[j] = None
is_ok = True
changed = True
if not is_ok:
print("NO")
exit(0)
if wrong_str:
print("NO")
exit(0)
strings = [x for x in strings if x is not None]
whole_str = "".join(strings)
if len(whole_str) != len(set(whole_str)):
print("NO")
exit(0)
print("".join(sorted(strings)))
``` | output | 1 | 77,946 | 0 | 155,893 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,947 | 0 | 155,894 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
StringsNumber = int(input())
FinalStrings = []
Strings = []
for i in range(StringsNumber):
Strings.append(input())
LetterGraph = {}
# ΠΠ΅Π½Π΅ΡΠΈΠΌ Π³ΡΠ°Ρ
for i in range(len(Strings)):
if len(Strings[i]) == 1:
if Strings[i] not in LetterGraph:
LetterGraph[Strings[i]] = ""
#print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i)
continue
for e in range(len(Strings[i]) - 1):
if Strings[i][e] not in LetterGraph:
Elements = []
for j in list(LetterGraph):
if j != Strings[i][e + 1]:
Elements.append(LetterGraph[j])
if Strings[i][e + 1] in Elements:
print("NO")
exit(0)
LetterGraph[Strings[i][e]] = Strings[i][e + 1]
continue
if LetterGraph[Strings[i][e]] == Strings[i][e + 1] or LetterGraph[Strings[i][e]] == "":
LetterGraph[Strings[i][e]] = Strings[i][e + 1]
continue
#print("ΠΡΠ°Ρ:", LetterGraph)
print("NO")
exit(0)
#print("Π― ΡΠ³Π΅Π½Π΅ΡΠΈΠ» Π³ΡΠ°Ρ, ΠΏΠΎΠ»ΡΡΠΈΠ»ΠΎΡΡ:", LetterGraph)
# ΠΡΠΎΠ²Π΅ΡΡΠ΅ΠΌ, ΡΡΠΎ Π½Π΅ΡΡ ΡΠΈΠΊΠ»Π°
if LetterGraph:
Cycle = False
for i in LetterGraph:
Letter = LetterGraph[i]
while True:
if Letter in LetterGraph:
if LetterGraph[Letter] == i:
print("NO")
exit(0)
Letter = LetterGraph[Letter]
else:
break
# ΠΠ°Ρ
ΠΎΠ΄ΠΈΠΌ Π²ΠΎΠ·ΠΌΠΎΠΆΠ½ΡΠ΅ ΠΏΠ΅ΡΠ²ΡΠ΅ ΡΠΈΠΌΠ²ΠΎΠ»Ρ
if LetterGraph:
IsIFirstSymbol = False
FirstSymbols = []
for i in LetterGraph:
IsIFirstSymbol = True
for e in LetterGraph:
if LetterGraph[e] == i:
#print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ
ΠΎΠ΄ΠΈΡ, ΠΏΠΎΡΠΎΠΌΡ ΡΡΠΎ", e, "ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ Π½Π° Π½Π΅Π³ΠΎ.")
IsIFirstSymbol = False
if IsIFirstSymbol:
FirstSymbols.append(i)
if not FirstSymbols:
print("NO")
exit(0)
#print("ΠΠ°ΡΠΈΠ°Π½ΡΡ ΠΏΠ΅ΡΠ²ΠΎΠ³ΠΎ ΡΠΈΠΌΠ²ΠΎΠ»Π°:", *FirstSymbols)
# Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°ΡΠΈΠ°Π½ΡΡ ΡΠΈΠ½Π°Π»ΡΠ½ΠΎΠΉ ΡΡΡΠΎΠΊΠΈ
if LetterGraph:
Letter = ""
for i in FirstSymbols:
FinalString = i
Letter = i
for e in range(len(LetterGraph)):
if Letter in LetterGraph:
if not (LetterGraph[Letter] == ""):
FinalString += LetterGraph[Letter]
#print(Letter, "Π΅ΡΡΡ Π² Π³ΡΠ°ΡΠ΅, ΡΠ°ΠΊ ΡΡΠΎ Π΄ΠΎΠ±Π°Π²Π»ΡΠ΅ΠΌ", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡΠΎΡΠΎΠ΅ ΠΎΠ½ΠΎ ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ.")
Letter = LetterGraph[Letter]
else:
break
else:
break
FinalStrings.append(FinalString)
#print("ΠΡΠ΄Π΅Π»ΡΠ½ΡΠ΅ ΡΡΡΠΎΠΊΠΈ", *FinalStrings)
FinalStrings.sort()
RESULT = ""
for i in FinalStrings:
RESULT += i
print(RESULT)
``` | output | 1 | 77,947 | 0 | 155,895 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,948 | 0 | 155,896 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
#https://codeforces.com/problemset/problem/886/D
def is_all_used(used):
for val in used.values():
if val != True:
return False
return True
def is_circle(d, pre):
used = {x:False for x in d}
pre_none = [x for x in used if x not in pre]
s_arr = []
for x in pre_none:
cur = []
flg = dfs(x, d, used, cur)
if flg==True:
return True, None
s_arr.append(cur)
if is_all_used(used) != True:
return True, None
return False, s_arr
def dfs(u, d, used, cur):
used[u] = True
cur.append(u)
flg = False
for v in d[u]:
if used[v] == True:
return True
flg = dfs(v, d, used, cur)
if flg==True:
return flg
return flg
def push(d, u, v=None):
if u not in d:
d[u] = set()
if v is not None:
if v not in d:
d[v] = set()
d[u].add(v)
def push_p(d, v):
if v not in d:
d[v] = 0
d[v]+=1
def is_deg_valid(d):
for u in d:
if len(d[u]) > 1:
return True
return False
def solve():
n = int(input())
d = {}
pre = {}
for _ in range(n):
s = input()
if len(s) == 1:
push(d, s)
else:
for u, v in zip(s[:-1], s[1:]):
push(d, u, v)
push_p(pre, v)
flg, arr = is_circle(d, pre)
if is_deg_valid(d) or flg==True:
return 'NO'
S = [''.join(x) for x in arr]
S = sorted(S)
return ''.join([s for s in S])
print(solve())
#4
#mail
#ai
#lru
#cf
#3
#kek
#preceq
#cheburek
``` | output | 1 | 77,948 | 0 | 155,897 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,949 | 0 | 155,898 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
from sys import exit
n = int(input())
letters_prev = [None for i in range(30)]
letters_fow = [None for i in range(30)]
okk = [False for i in range(30)]
for i in range(n):
task = [ord(i) - ord('a') for i in input()]
if len(task) == 1: okk[task[0]] = True
for i in range(1, len(task)):
if (letters_prev[task[i]] is not None and letters_prev[task[i]] != task[i-1]) or task[i] == task[i-1]:
print('NO')
exit()
else:
letters_prev[task[i]] = task[i-1]
for i in range(len(task)-1):
if (letters_fow[task[i]] is not None and letters_fow[task[i]] != task[i+1]) or task[i] == task[i+1]:
print('NO')
exit()
else:
letters_fow[task[i]] = task[i+1]
# print(task, letters_prev, letters_fow)
def chain_p(x, was=[]):
global letters_fow, letters_prev
if x is None: return []
if letters_prev[x] is None:
return [x]
else:
if letters_prev[x] in was:
print('NO')
exit()
ans = chain_p(letters_prev[x], was=was+[letters_prev[x]]) + [x]
# letters_prev[x] = None
return ans
def chain_f(x, was=[]):
global letters_fow, letters_prev
# print('_f', x, letters_fow[x])
if x is None: return []
if letters_fow[x] is None:
# letters_fow[x] = None
return [x]
else:
if letters_fow[x] in was:
print('NO')
exit()
ans = chain_f(letters_fow[x], was=was+[letters_fow[x]]) + [x]
# letters_fow[x] = None
return ans
done = []
cc = []
while True:
flag = False
for i in range(30):
if i in done: continue
prev = []
post = []
if letters_prev[i] is not None:
flag = True
prev = chain_p(letters_prev[i])
if letters_fow[i] is not None:
flag = True
post = chain_f(letters_fow[i])
done.extend(prev)
done.extend(post)
done.append(i)
if len(prev) + len(post) == 0 and okk[i]:
cc.append(chr(i+ord('a')))
elif len(prev) + len(post) > 0:
cc.append("".join([chr(i+ord('a')) for i in prev] + [chr(i+ord('a'))] + [chr(i+ord('a')) for i in post][::-1]))
if not flag: break
cc.sort()
print("".join(cc))
``` | output | 1 | 77,949 | 0 | 155,899 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,950 | 0 | 155,900 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
# ---------------------------iye ha aam zindegi---------------------------------------------
import math
import random
import heapq, bisect
import sys
from collections import deque, defaultdict
from fractions import Fraction
import sys
import threading
from collections import defaultdict
threading.stack_size(10**8)
mod = 10 ** 9 + 7
mod1 = 998244353
# ------------------------------warmup----------------------------
import os
import sys
from io import BytesIO, IOBase
sys.setrecursionlimit(300000)
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# -------------------game starts now----------------------------------------------------import math
class TreeNode:
def __init__(self, k, v):
self.key = k
self.value = v
self.left = None
self.right = None
self.parent = None
self.height = 1
self.num_left = 1
self.num_total = 1
class AvlTree:
def __init__(self):
self._tree = None
def add(self, k, v):
if not self._tree:
self._tree = TreeNode(k, v)
return
node = self._add(k, v)
if node:
self._rebalance(node)
def _add(self, k, v):
node = self._tree
while node:
if k < node.key:
if node.left:
node = node.left
else:
node.left = TreeNode(k, v)
node.left.parent = node
return node.left
elif node.key < k:
if node.right:
node = node.right
else:
node.right = TreeNode(k, v)
node.right.parent = node
return node.right
else:
node.value = v
return
@staticmethod
def get_height(x):
return x.height if x else 0
@staticmethod
def get_num_total(x):
return x.num_total if x else 0
def _rebalance(self, node):
n = node
while n:
lh = self.get_height(n.left)
rh = self.get_height(n.right)
n.height = max(lh, rh) + 1
balance_factor = lh - rh
n.num_total = 1 + self.get_num_total(n.left) + self.get_num_total(n.right)
n.num_left = 1 + self.get_num_total(n.left)
if balance_factor > 1:
if self.get_height(n.left.left) < self.get_height(n.left.right):
self._rotate_left(n.left)
self._rotate_right(n)
elif balance_factor < -1:
if self.get_height(n.right.right) < self.get_height(n.right.left):
self._rotate_right(n.right)
self._rotate_left(n)
else:
n = n.parent
def _remove_one(self, node):
"""
Side effect!!! Changes node. Node should have exactly one child
"""
replacement = node.left or node.right
if node.parent:
if AvlTree._is_left(node):
node.parent.left = replacement
else:
node.parent.right = replacement
replacement.parent = node.parent
node.parent = None
else:
self._tree = replacement
replacement.parent = None
node.left = None
node.right = None
node.parent = None
self._rebalance(replacement)
def _remove_leaf(self, node):
if node.parent:
if AvlTree._is_left(node):
node.parent.left = None
else:
node.parent.right = None
self._rebalance(node.parent)
else:
self._tree = None
node.parent = None
node.left = None
node.right = None
def remove(self, k):
node = self._get_node(k)
if not node:
return
if AvlTree._is_leaf(node):
self._remove_leaf(node)
return
if node.left and node.right:
nxt = AvlTree._get_next(node)
node.key = nxt.key
node.value = nxt.value
if self._is_leaf(nxt):
self._remove_leaf(nxt)
else:
self._remove_one(nxt)
self._rebalance(node)
else:
self._remove_one(node)
def get(self, k):
node = self._get_node(k)
return node.value if node else -1
def _get_node(self, k):
if not self._tree:
return None
node = self._tree
while node:
if k < node.key:
node = node.left
elif node.key < k:
node = node.right
else:
return node
return None
def get_at(self, pos):
x = pos + 1
node = self._tree
while node:
if x < node.num_left:
node = node.left
elif node.num_left < x:
x -= node.num_left
node = node.right
else:
return (node.key, node.value)
raise IndexError("Out of ranges")
@staticmethod
def _is_left(node):
return node.parent.left and node.parent.left == node
@staticmethod
def _is_leaf(node):
return node.left is None and node.right is None
def _rotate_right(self, node):
if not node.parent:
self._tree = node.left
node.left.parent = None
elif AvlTree._is_left(node):
node.parent.left = node.left
node.left.parent = node.parent
else:
node.parent.right = node.left
node.left.parent = node.parent
bk = node.left.right
node.left.right = node
node.parent = node.left
node.left = bk
if bk:
bk.parent = node
node.height = max(self.get_height(node.left), self.get_height(node.right)) + 1
node.num_total = 1 + self.get_num_total(node.left) + self.get_num_total(node.right)
node.num_left = 1 + self.get_num_total(node.left)
def _rotate_left(self, node):
if not node.parent:
self._tree = node.right
node.right.parent = None
elif AvlTree._is_left(node):
node.parent.left = node.right
node.right.parent = node.parent
else:
node.parent.right = node.right
node.right.parent = node.parent
bk = node.right.left
node.right.left = node
node.parent = node.right
node.right = bk
if bk:
bk.parent = node
node.height = max(self.get_height(node.left), self.get_height(node.right)) + 1
node.num_total = 1 + self.get_num_total(node.left) + self.get_num_total(node.right)
node.num_left = 1 + self.get_num_total(node.left)
@staticmethod
def _get_next(node):
if not node.right:
return node.parent
n = node.right
while n.left:
n = n.left
return n
# -----------------------------------------------binary seacrh tree---------------------------------------
class SegmentTree1:
def __init__(self, data, default=2**51, func=lambda a, b: a & b):
"""initialize the segment tree with data"""
self._default = default
self._func = func
self._len = len(data)
self._size = _size = 1 << (self._len - 1).bit_length()
self.data = [default] * (2 * _size)
self.data[_size:_size + self._len] = data
for i in reversed(range(_size)):
self.data[i] = func(self.data[i + i], self.data[i + i + 1])
def __delitem__(self, idx):
self[idx] = self._default
def __getitem__(self, idx):
return self.data[idx + self._size]
def __setitem__(self, idx, value):
idx += self._size
self.data[idx] = value
idx >>= 1
while idx:
self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1])
idx >>= 1
def __len__(self):
return self._len
def query(self, start, stop):
if start == stop:
return self.__getitem__(start)
stop += 1
start += self._size
stop += self._size
res = self._default
while start < stop:
if start & 1:
res = self._func(res, self.data[start])
start += 1
if stop & 1:
stop -= 1
res = self._func(res, self.data[stop])
start >>= 1
stop >>= 1
return res
def __repr__(self):
return "SegmentTree({0})".format(self.data)
# -------------------game starts now----------------------------------------------------import math
class SegmentTree:
def __init__(self, data, default=0, func=lambda a, b: a + b):
"""initialize the segment tree with data"""
self._default = default
self._func = func
self._len = len(data)
self._size = _size = 1 << (self._len - 1).bit_length()
self.data = [default] * (2 * _size)
self.data[_size:_size + self._len] = data
for i in reversed(range(_size)):
self.data[i] = func(self.data[i + i], self.data[i + i + 1])
def __delitem__(self, idx):
self[idx] = self._default
def __getitem__(self, idx):
return self.data[idx + self._size]
def __setitem__(self, idx, value):
idx += self._size
self.data[idx] = value
idx >>= 1
while idx:
self.data[idx] = self._func(self.data[2 * idx], self.data[2 * idx + 1])
idx >>= 1
def __len__(self):
return self._len
def query(self, start, stop):
if start == stop:
return self.__getitem__(start)
stop += 1
start += self._size
stop += self._size
res = self._default
while start < stop:
if start & 1:
res = self._func(res, self.data[start])
start += 1
if stop & 1:
stop -= 1
res = self._func(res, self.data[stop])
start >>= 1
stop >>= 1
return res
def __repr__(self):
return "SegmentTree({0})".format(self.data)
# -------------------------------iye ha chutiya zindegi-------------------------------------
class Factorial:
def __init__(self, MOD):
self.MOD = MOD
self.factorials = [1, 1]
self.invModulos = [0, 1]
self.invFactorial_ = [1, 1]
def calc(self, n):
if n <= -1:
print("Invalid argument to calculate n!")
print("n must be non-negative value. But the argument was " + str(n))
exit()
if n < len(self.factorials):
return self.factorials[n]
nextArr = [0] * (n + 1 - len(self.factorials))
initialI = len(self.factorials)
prev = self.factorials[-1]
m = self.MOD
for i in range(initialI, n + 1):
prev = nextArr[i - initialI] = prev * i % m
self.factorials += nextArr
return self.factorials[n]
def inv(self, n):
if n <= -1:
print("Invalid argument to calculate n^(-1)")
print("n must be non-negative value. But the argument was " + str(n))
exit()
p = self.MOD
pi = n % p
if pi < len(self.invModulos):
return self.invModulos[pi]
nextArr = [0] * (n + 1 - len(self.invModulos))
initialI = len(self.invModulos)
for i in range(initialI, min(p, n + 1)):
next = -self.invModulos[p % i] * (p // i) % p
self.invModulos.append(next)
return self.invModulos[pi]
def invFactorial(self, n):
if n <= -1:
print("Invalid argument to calculate (n^(-1))!")
print("n must be non-negative value. But the argument was " + str(n))
exit()
if n < len(self.invFactorial_):
return self.invFactorial_[n]
self.inv(n) # To make sure already calculated n^-1
nextArr = [0] * (n + 1 - len(self.invFactorial_))
initialI = len(self.invFactorial_)
prev = self.invFactorial_[-1]
p = self.MOD
for i in range(initialI, n + 1):
prev = nextArr[i - initialI] = (prev * self.invModulos[i % p]) % p
self.invFactorial_ += nextArr
return self.invFactorial_[n]
class Combination:
def __init__(self, MOD):
self.MOD = MOD
self.factorial = Factorial(MOD)
def ncr(self, n, k):
if k < 0 or n < k:
return 0
k = min(k, n - k)
f = self.factorial
return f.calc(n) * f.invFactorial(max(n - k, k)) * f.invFactorial(min(k, n - k)) % self.MOD
# --------------------------------------iye ha combinations ka zindegi---------------------------------
def powm(a, n, m):
if a == 1 or n == 0:
return 1
if n % 2 == 0:
s = powm(a, n // 2, m)
return s * s % m
else:
return a * powm(a, n - 1, m) % m
# --------------------------------------iye ha power ka zindegi---------------------------------
def sort_list(list1, list2):
zipped_pairs = zip(list2, list1)
z = [x for _, x in sorted(zipped_pairs)]
return z
# --------------------------------------------------product----------------------------------------
def product(l):
por = 1
for i in range(len(l)):
por *= l[i]
return por
# --------------------------------------------------binary----------------------------------------
def binarySearchCount(arr, n, key):
left = 0
right = n - 1
count = 0
while (left <= right):
mid = int((right + left) / 2)
# Check if middle element is
# less than or equal to key
if (arr[mid] < key):
count = mid + 1
left = mid + 1
# If key is smaller, ignore right half
else:
right = mid - 1
return count
# --------------------------------------------------binary----------------------------------------
def countdig(n):
c = 0
while (n > 0):
n //= 10
c += 1
return c
def binary(x, length):
y = bin(x)[2:]
return y if len(y) >= length else "0" * (length - len(y)) + y
def countGreater(arr, n, k):
l = 0
r = n - 1
# Stores the index of the left most element
# from the array which is greater than k
leftGreater = n
# Finds number of elements greater than k
while (l <= r):
m = int(l + (r - l) / 2)
if (arr[m] >= k):
leftGreater = m
r = m - 1
# If mid element is less than
# or equal to k update l
else:
l = m + 1
# Return the count of elements
# greater than k
return (n - leftGreater)
# --------------------------------------------------binary------------------------------------
n=int(input())
l1=[]
l2=[]
for i in range(n):
s1=input()
s=list(s1)
if len(set(s))<len(s):
print("NO")
sys.exit(0)
l1.append(s)
l2.append(s1)
l=['']*26
r=['']*26
pr=[0]*26
for i in range(n):
s=l1[i]
if len(s)==1:
pr[ord(s[0]) - 97] = 1
continue
for j in range(len(s)):
pr[ord(s[j])-97]=1
if j==0:
if r[ord(s[j])-97]=='':
r[ord(s[j])-97]=s[j+1]
elif r[ord(s[j])-97]!=s[j+1]:
print("NO")
sys.exit(0)
elif j==len(s)-1:
if l[ord(s[j]) - 97] == '':
l[ord(s[j]) - 97] = s[j - 1]
elif l[ord(s[j]) - 97] != s[j - 1]:
print("NO")
sys.exit(0)
else:
if r[ord(s[j])-97]=='':
r[ord(s[j])-97]=s[j+1]
elif r[ord(s[j])-97]!=s[j+1]:
print("NO")
sys.exit(0)
if l[ord(s[j]) - 97] == '':
l[ord(s[j]) - 97] = s[j - 1]
elif l[ord(s[j]) - 97] != s[j - 1]:
print("NO")
sys.exit(0)
ans=""
st=0
f=1
for i in range(26):
if l[i]=='' and pr[i]==1:
f=0
break
if f==1:
print("NO")
sys.exit(0)
for i in range(26):
if l[i]=='' and pr[i]==1:
st=i
ans+=chr(st+97)
while(r[st]!=''):
pr[st]=0
st=ord(r[st])-97
ans += chr(st + 97)
for i in range(n):
if l2[i] not in ans:
print("NO")
sys.exit(0)
print(ans)
``` | output | 1 | 77,950 | 0 | 155,901 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum. | instruction | 0 | 77,951 | 0 | 155,902 |
Tags: constructive algorithms, graphs, implementation
Correct Solution:
```
n=int(input())
m=[]
sc=[]
for i in range(n):
m.append(input())
sc.append(set(m[i]))
if len(sc[i])!=len(m[i]):
print('NO')
break
else:
i=0
pX=False
while i<len(m):
j=i+1
p=False
while j<len(m):
#print(m)
z=len(sc[i].intersection(sc[j]))
#a=len(sc[i])
#b=len(sc[j])
if m[i] in m[j]:
m[i]=m[j]
sc[i]=sc[j]
sc.pop(j)
m.pop(j)
p=True
break
elif m[j] in m[i]:
sc.pop(j)
m.pop(j)
j-=1
elif z>0:
if m[i][-z:]==m[j][:z]:
m[i]+=m[j][z:]
elif m[j][-z:]==m[i][:z]:
m[i]=m[j]+m[i][z:]
else:
pX=True
break
sc[i]=set(m[i])
m.pop(j)
sc.pop(j)
j-=1
p=True
j+=1
if not p:
i+=1
if pX:
print('NO')
break
if not pX:
print(''.join(sorted(m)))
``` | output | 1 | 77,951 | 0 | 155,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
Submitted Solution:
```
StringsNumber = int(input())
FinalStrings = []
Strings = []
for i in range(StringsNumber):
Strings.append(input())
LetterGraph = {}
# ΠΠ΅Π½Π΅ΡΠΈΠΌ Π³ΡΠ°Ρ
for i in range(len(Strings)):
if len(Strings[i]) == 1:
LetterGraph[Strings[i]] = ""
#print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i)
continue
for e in range(len(Strings[i]) - 1):
if Strings[i][e] not in LetterGraph:
LetterGraph[Strings[i][e]] = Strings[i][e + 1]
continue
if LetterGraph[Strings[i][e]] == Strings[i][e + 1]:
continue
print("NO")
exit(0)
#print("Π― ΡΠ³Π΅Π½Π΅ΡΠΈΠ» Π³ΡΠ°Ρ, ΠΏΠΎΠ»ΡΡΠΈΠ»ΠΎΡΡ:", LetterGraph)
# ΠΡΠΎΠ²Π΅ΡΡΠ΅ΠΌ, ΡΡΠΎ Π½Π΅ΡΡ ΡΠΈΠΊΠ»Π°
if LetterGraph:
Cycle = False
for i in LetterGraph:
try:
if LetterGraph[LetterGraph[i]] == i:
Cycle = True
except:
continue
if Cycle:
print("NO")
exit(0)
# ΠΠ°Ρ
ΠΎΠ΄ΠΈΠΌ Π²ΠΎΠ·ΠΌΠΎΠΆΠ½ΡΠ΅ ΠΏΠ΅ΡΠ²ΡΠ΅ ΡΠΈΠΌΠ²ΠΎΠ»Ρ
if LetterGraph:
IsIFirstSymbol = False
FirstSymbols = []
for i in LetterGraph:
IsIFirstSymbol = True
for e in LetterGraph:
if LetterGraph[e] == i:
#print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ
ΠΎΠ΄ΠΈΡ, ΠΏΠΎΡΠΎΠΌΡ ΡΡΠΎ", e, "ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ Π½Π° Π½Π΅Π³ΠΎ.")
IsIFirstSymbol = False
if IsIFirstSymbol:
FirstSymbols.append(i)
if not FirstSymbols:
print("NO")
exit(0)
#print("ΠΠ°ΡΠΈΠ°Π½ΡΡ ΠΏΠ΅ΡΠ²ΠΎΠ³ΠΎ ΡΠΈΠΌΠ²ΠΎΠ»Π°:", *FirstSymbols)
# Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°ΡΠΈΠ°Π½ΡΡ ΡΠΈΠ½Π°Π»ΡΠ½ΠΎΠΉ ΡΡΡΠΎΠΊΠΈ
if LetterGraph:
Letter = ""
for i in FirstSymbols:
FinalString = i
Letter = i
for e in range(len(LetterGraph)):
if Letter in LetterGraph:
if not (LetterGraph[Letter] == ""):
FinalString += LetterGraph[Letter]
#print(Letter, "Π΅ΡΡΡ Π² Π³ΡΠ°ΡΠ΅, ΡΠ°ΠΊ ΡΡΠΎ Π΄ΠΎΠ±Π°Π²Π»ΡΠ΅ΠΌ", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡΠΎΡΠΎΠ΅ ΠΎΠ½ΠΎ ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ.")
Letter = LetterGraph[Letter]
else:
break
else:
break
FinalStrings.append(FinalString)
#print("ΠΡΠ΄Π΅Π»ΡΠ½ΡΠ΅ ΡΡΡΠΎΠΊΠΈ", *FinalStrings)
FinalStrings.sort()
RESULT = ""
for i in FinalStrings:
RESULT += i
print(RESULT)
``` | instruction | 0 | 77,952 | 0 | 155,904 |
No | output | 1 | 77,952 | 0 | 155,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
Submitted Solution:
```
StringsNumber = int(input())
FinalStrings = []
Strings = []
for i in range(StringsNumber):
Strings.append(input())
LetterGraph = {}
# ΠΠ΅Π½Π΅ΡΠΈΠΌ Π³ΡΠ°Ρ
for i in range(len(Strings)):
if len(Strings[i]) == 1:
LetterGraph[Strings[i]] = ""
#print("Π·Π°Π°ΠΏΠ΅Π΄ΠΈΠ»", i)
continue
for e in range(len(Strings[i]) - 1):
if Strings[i][e] not in LetterGraph:
LetterGraph[Strings[i][e]] = Strings[i][e + 1]
continue
if LetterGraph[Strings[i][e]] == Strings[i][e + 1] or LetterGraph[Strings[i][e]] == "":
continue
#print("ΠΡΠ°Ρ:", LetterGraph)
print("NO")
exit(0)
#print("Π― ΡΠ³Π΅Π½Π΅ΡΠΈΠ» Π³ΡΠ°Ρ, ΠΏΠΎΠ»ΡΡΠΈΠ»ΠΎΡΡ:", LetterGraph)
# ΠΡΠΎΠ²Π΅ΡΡΠ΅ΠΌ, ΡΡΠΎ Π½Π΅ΡΡ ΡΠΈΠΊΠ»Π°
if LetterGraph:
Cycle = False
for i in LetterGraph:
try:
if LetterGraph[LetterGraph[i]] == i:
Cycle = True
except:
continue
if Cycle:
print("NO")
exit(0)
# ΠΠ°Ρ
ΠΎΠ΄ΠΈΠΌ Π²ΠΎΠ·ΠΌΠΎΠΆΠ½ΡΠ΅ ΠΏΠ΅ΡΠ²ΡΠ΅ ΡΠΈΠΌΠ²ΠΎΠ»Ρ
if LetterGraph:
IsIFirstSymbol = False
FirstSymbols = []
for i in LetterGraph:
IsIFirstSymbol = True
for e in LetterGraph:
if LetterGraph[e] == i:
#print(i, "Π½Π΅ ΠΏΠΎΠ΄Ρ
ΠΎΠ΄ΠΈΡ, ΠΏΠΎΡΠΎΠΌΡ ΡΡΠΎ", e, "ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ Π½Π° Π½Π΅Π³ΠΎ.")
IsIFirstSymbol = False
if IsIFirstSymbol:
FirstSymbols.append(i)
if not FirstSymbols:
print("NO")
exit(0)
#print("ΠΠ°ΡΠΈΠ°Π½ΡΡ ΠΏΠ΅ΡΠ²ΠΎΠ³ΠΎ ΡΠΈΠΌΠ²ΠΎΠ»Π°:", *FirstSymbols)
# Π‘ΠΎΠ·Π΄Π°Π΅ΠΌ Π²Π°ΡΠΈΠ°Π½ΡΡ ΡΠΈΠ½Π°Π»ΡΠ½ΠΎΠΉ ΡΡΡΠΎΠΊΠΈ
if LetterGraph:
Letter = ""
for i in FirstSymbols:
FinalString = i
Letter = i
for e in range(len(LetterGraph)):
if Letter in LetterGraph:
if not (LetterGraph[Letter] == ""):
FinalString += LetterGraph[Letter]
#print(Letter, "Π΅ΡΡΡ Π² Π³ΡΠ°ΡΠ΅, ΡΠ°ΠΊ ΡΡΠΎ Π΄ΠΎΠ±Π°Π²Π»ΡΠ΅ΠΌ", LetterGraph[Letter], ", Π½Π° ΠΊΠΎΡΠΎΡΠΎΠ΅ ΠΎΠ½ΠΎ ΡΠΊΠ°Π·ΡΠ²Π°Π΅Ρ.")
Letter = LetterGraph[Letter]
else:
break
else:
break
FinalStrings.append(FinalString)
#print("ΠΡΠ΄Π΅Π»ΡΠ½ΡΠ΅ ΡΡΡΠΎΠΊΠΈ", *FinalStrings)
FinalStrings.sort()
RESULT = ""
for i in FinalStrings:
RESULT += i
print(RESULT)
``` | instruction | 0 | 77,953 | 0 | 155,906 |
No | output | 1 | 77,953 | 0 | 155,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
Submitted Solution:
```
n=int(input())
m=[]
sc=[]
for i in range(n):
m.append(input())
sc.append(set(m[i]))
i=0
pX=False
while i<len(m):
j=i+1
p=False
while j<len(m):
z=len(sc[i].intersection(sc[j]))
#a=len(sc[i])
#b=len(sc[j])
if m[i] in m[j]:
sc.pop(i)
m.pop(i)
i-=1
break
elif m[j] in m[i]:
sc.pop(j)
m.pop(j)
j-=1
elif z>0:
if m[i][-z:]==m[j][:z]:
m[i]+=m[j][z:]
elif m[j][-z:]==m[i][:z]:
m[i]=m[j]+m[i][z:]
else:
pX=True
break
sc[i]=set(m[i])
m.pop(j)
sc.pop(j)
j-=1
p=True
j+=1
if not p:
i+=1
if pX:
print('NO')
break
else:
print(''.join(sorted(m))) #atoumrydhfgwekjilbpsvqncx
``` | instruction | 0 | 77,954 | 0 | 155,908 |
No | output | 1 | 77,954 | 0 | 155,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A substring of some string is called the most frequent, if the number of its occurrences is not less than number of occurrences of any other substring.
You are given a set of strings. A string (not necessarily from this set) is called good if all elements of the set are the most frequent substrings of this string. Restore the non-empty good string with minimum length. If several such strings exist, restore lexicographically minimum string. If there are no good strings, print "NO" (without quotes).
A substring of a string is a contiguous subsequence of letters in the string. For example, "ab", "c", "abc" are substrings of string "abc", while "ac" is not a substring of that string.
The number of occurrences of a substring in a string is the number of starting positions in the string where the substring occurs. These occurrences could overlap.
String a is lexicographically smaller than string b, if a is a prefix of b, or a has a smaller letter at the first position where a and b differ.
Input
The first line contains integer n (1 β€ n β€ 105) β the number of strings in the set.
Each of the next n lines contains a non-empty string consisting of lowercase English letters. It is guaranteed that the strings are distinct.
The total length of the strings doesn't exceed 105.
Output
Print the non-empty good string with minimum length. If several good strings exist, print lexicographically minimum among them. Print "NO" (without quotes) if there are no good strings.
Examples
Input
4
mail
ai
lru
cf
Output
cfmailru
Input
3
kek
preceq
cheburek
Output
NO
Note
One can show that in the first sample only two good strings with minimum length exist: "cfmailru" and "mailrucf". The first string is lexicographically minimum.
Submitted Solution:
```
n = int(input())
A = []
for i in range (0,n):
A = A + [input()]
start = [100]*26
end = [100]*26
def num(x):
return(ord(x)-ord("a"))
def let(x):
return(chr(x+ord("a")))
def ans(x):
final = []
for i in range (0,n):
B = list(A[i])
if len(B) == 1:
if start[num(B[0])] == 100:
start[num(B[0])] = -100
if end[num(B[0])] == 100:
end[num(B[0])] = -100
else:
for j in range (0,len(B)):
if j==0:
if start[num(B[j])] == 100 or start[num(B[j])] == -100:
start[num(B[j])] = -100
if end[num(B[j])] == 100 or end[num(B[j])] == -100:
if start[num(B[j])] != 100 and start[num(B[j])] != -100:
end[num(B[j])] = num(B[j+1])
if end[num(B[j])] == num(B[j+1]): g=0
else:
return("NO")
elif 0<j<len(B)-1:
if start[num(B[j])] == 100 or start[num(B[j])] == -100:
start[num(B[j])] = num(B[j-1])
elif start[num(B[j])] != num(B[j-1]):
return("NO")
if end[num(B[j])] == 100 or end[num(B[j])] == -100:
end[num(B[j])] = num(B[j+1])
elif end[num(B[j])] != num(B[j+1]):
return("NO")
elif j == len(B)-1:
if end[num(B[j])] == 100:
end[num(B[j])] = -100
if start[num(B[j])] == 100 or start[num(B[j])] == -100:
if end[num(B[j])] != 100 and end[num(B[j])] != -100:
start[num(B[j])] = num(B[j-1])
if start[num(B[j])] != num(B[j-1]): g=0
else:
return("NO")
if len(set(start))+max(0,start.count(100)-1)+max(0,start.count(-100)-1) != 26:
return("NO")
elif len(set(end))+max(0,end.count(100)-1)+max(0,end.count(-100)-1) != 26:
return("NO")
else:
for i in range (0,26):
if start[i] != -100:
g=0
else:
final = final + [let(i)]
j = end[i]
while j != -100:
final = final + [let(j)]
j = end[j]
return("".join(final))
print(ans(A))
``` | instruction | 0 | 77,955 | 0 | 155,910 |
No | output | 1 | 77,955 | 0 | 155,911 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,111 | 0 | 156,222 |
"Correct Solution:
```
s = input()
n = len(s)
INF = 10**9
alph = "abcdefghijklmnopqrstuvwxyz"
to_int = {v: i for i, v in enumerate(alph)}
dp = {}
all_state = 0
for i in range(n):
all_state ^= 1 << to_int[s[i]]
if all_state not in dp:
dp[all_state] = i + 1
for j in range(26):
bit = all_state ^ (1 << j)
if bit in dp:
dp[all_state] = min(dp[bit] + 1, dp[all_state])
if bin(all_state).count("1") <= 1:
dp[all_state] = 1
print(dp[all_state])
``` | output | 1 | 78,111 | 0 | 156,223 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,112 | 0 | 156,224 |
"Correct Solution:
```
def main():
import sys
from bisect import bisect_left
input = sys.stdin.readline
S = input().rstrip('\n')
N = len(S)
A = [ord(s)-97 for s in S]
H = [0] * (N+1)
h2i = {}
for i in range(N):
H[i+1] = H[i] ^ (1 << A[i])
if H[i+1] in h2i:
h2i[H[i+1]].append(i+1)
else:
h2i[H[i+1]] = [i+1]
dp = [N+1] * (N+1)
dp[0] = 0
pow2 = [2**i for i in range(26)]
for i in range(N):
h = H[i]
if h in h2i:
ii_list = h2i[h]
ii = bisect_left(ii_list, i+1)
if ii < len(ii_list):
ii = ii_list[ii]
if i:
dp[ii] = min(dp[ii], dp[i])
else:
dp[ii] = 1
for j in pow2:
new_h = h ^ j
if new_h in h2i:
ii_list = h2i[new_h]
ii = bisect_left(ii_list, i+1)
if ii < len(ii_list):
ii = ii_list[ii]
dp[ii] = min(dp[ii], dp[i] + 1)
print(dp[-1])
if __name__ == '__main__':
main()
``` | output | 1 | 78,112 | 0 | 156,225 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,113 | 0 | 156,226 |
"Correct Solution:
```
import itertools
L=9**9
dp={0:0}
for v in itertools.accumulate(map(lambda c:1<<ord(c)-ord('a'),input()),lambda a,b:a^b):
dp[v]=min(dp.get(v,L),min(dp.get(v^1<<i, L)for i in range(26))+1)
print(dp[v]+(v==0))
``` | output | 1 | 78,113 | 0 | 156,227 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,114 | 0 | 156,228 |
"Correct Solution:
```
import sys
readline = sys.stdin.buffer.readline
ns = lambda: readline().rstrip()
ni = lambda: int(readline().rstrip())
nm = lambda: map(int, readline().split())
nl = lambda: list(map(int, readline().split()))
def solve():
s = [x - 97 for x in ns()]
n = len(s)
c = 0
g = {0:0}
for x in s:
c ^= 1 << x
y = g.get(c, n) + 1
for i in range(26):
y = min(y, g.get(c ^ (1 << i), n) + 1)
g[c] = min(g.get(c, n), y)
print(y)
return
solve()
``` | output | 1 | 78,114 | 0 | 156,229 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,115 | 0 | 156,230 |
"Correct Solution:
```
from collections import defaultdict
s = input()
n = len(s)
dp = defaultdict(int)
dp[0] = 1
ls = [1<<(ord(s[0])-97)]
for i in range(1,n):
ls.append(ls[-1]^(1<<(ord(s[i])-97)))
if ls[-1] == 0:
print(1)
exit()
for i in range(n):
for b in range(26):
bit = 1<<b
if dp[ls[i]^bit] == 0:
continue
if dp[ls[i]] == 0:
dp[ls[i]] = dp[ls[i]^bit]+1
else:
dp[ls[i]] = min(dp[ls[i]^bit]+1,dp[ls[i]])
print(dp[ls[n-1]]-1)
``` | output | 1 | 78,115 | 0 | 156,231 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,116 | 0 | 156,232 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
from collections import defaultdict
S = list(map(lambda x: ord(x)-97, readline().strip()))
N = len(S)
table = [0] + [1<<S[i] for i in range(N)]
for i in range(1, N+1):
table[i] ^= table[i-1]
inf = 10**9+7
dp = defaultdict(lambda: inf)
dp[0] = 0
for i in range(1, N+1):
t = table[i]
res = 1+dp[t]
for j in range(26):
res = min(res, 1+dp[t^(1<<j)])
dp[t] = min(dp[t], res)
print(res)
``` | output | 1 | 78,116 | 0 | 156,233 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,117 | 0 | 156,234 |
"Correct Solution:
```
s = input()
N = len(s)
a = 0
dp = {}
dp[0] = 0
bits = [2 ** i for i in range(26)]
for c in s:
a = a ^ bits[ord(c)-ord('a')]
dp[a] = min(dp.get(a, N), min([dp.get(a ^ bit, N) for bit in bits]) + 1)
print(dp[a] if dp[a] != 0 else 1)
``` | output | 1 | 78,117 | 0 | 156,235 |
Provide a correct Python 3 solution for this coding contest problem.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3 | instruction | 0 | 78,118 | 0 | 156,236 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**15
mod = 10**9+7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
a = [2**(ord(c)-97) for c in S()]
b = [0]
d2 = {}
d2[0] = 0
c = 0
ii = [2**i for i in range(26)]
for t,i in zip(a, range(1,len(a)+1)):
c ^= t
tr = inf
if c in d2:
tr = d2[c] + 1
for j in ii:
e = c ^ j
if e in d2 and d2[e] + 1 < tr:
tr = d2[e] + 1
if c not in d2 or d2[c] > tr:
d2[c] = tr
return d2[c] if d2[c] else 1
print(main())
``` | output | 1 | 78,118 | 0 | 156,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
def main():
S = input()
n = len(S)
a = {j: i for i, j in enumerate('abcdefghijklmnopqrstuvwxyz')}
S = [a[i] for i in S]
dp = [10**9]*(n+1)
dp[0] = 0
parity = 0
dict_parity = {0: 0}
for i, s in enumerate(S):
parity ^= 2**s
ans = i+1
if parity in dict_parity:
ans = min(ans, dp[dict_parity[parity]]+1)
for j in range(26):
parity2 = parity ^ 2**j
if parity2 in dict_parity:
ans = min(ans, dp[dict_parity[parity2]]+1)
dp[i+1] = ans
if parity not in dict_parity:
dict_parity[parity] = i+1
elif dp[dict_parity[parity]] > ans:
dict_parity[parity] = i+1
print(dp[-1])
main()
``` | instruction | 0 | 78,119 | 0 | 156,238 |
Yes | output | 1 | 78,119 | 0 | 156,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
# --*-coding:utf-8-*--
def f(str):
s = {}
s[0] = 0
pat = 0
bits = [2**i for i in range(26)]
lenOfStr = len(str)
for c in str:
pat ^= bits[ord(c)-97]
s[pat] = min(
min(s.get(pat^bit, lenOfStr) + 1 for bit in bits),
s.get(pat, lenOfStr))
if pat == 0:
return 1
return s[pat]
str = input()
print(f(str))
``` | instruction | 0 | 78,120 | 0 | 156,240 |
Yes | output | 1 | 78,120 | 0 | 156,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
from collections import defaultdict
s = input()
n = len(s)
inf = 10**6
d = defaultdict(lambda : inf)
d[0] = 0
a = ord('a')
now = 0
for i in range(n):
si = ord(s[i]) - a
now = now^(1<<si)
for j in range(26):
d[now] = min(d[now], 1+d[now^(1<<j)])
print(max(1,d[now]))
``` | instruction | 0 | 78,121 | 0 | 156,242 |
Yes | output | 1 | 78,121 | 0 | 156,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
from collections import defaultdict
s = input()
n = len(s)
dp = defaultdict(int)
dp[0] = 1
ls = [1<<(ord(s[0])-97)]
for i in range(1,n):
ls.append(ls[-1]^(1<<(ord(s[i])-97)))
if ls[-1] == 0:
print(1)
exit()
for i in range(n):
for b in range(26):
bit = 1<<b
if dp[ls[i]^bit] == 0:
continue
if dp[ls[i]] == 0:
dp[ls[i]] = dp[ls[i]^bit]+1
else:
dp[ls[i]] = min(dp[ls[i]^bit]+1,dp[ls[i]])
print(dp[ls[n-1]]-1)
``` | instruction | 0 | 78,123 | 0 | 156,246 |
No | output | 1 | 78,123 | 0 | 156,247 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
from collections import Counter
from string import ascii_lowercase
from functools import lru_cache
import sys
s = input()
sys.setrecursionlimit(100000000)
tmp_c = Counter(s)
val = sum(tmp_c[s_tmp]%2 for s_tmp in ascii_lowercase)
if val==0:
val=1
if val>5:
raise
print(val)
``` | instruction | 0 | 78,124 | 0 | 156,248 |
No | output | 1 | 78,124 | 0 | 156,249 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a string s consisting of lowercase English letters. Snuke is partitioning s into some number of non-empty substrings. Let the subtrings obtained be s_1, s_2, ..., s_N from left to right. (Here, s = s_1 + s_2 + ... + s_N holds.) Snuke wants to satisfy the following condition:
* For each i (1 \leq i \leq N), it is possible to permute the characters in s_i and obtain a palindrome.
Find the minimum possible value of N when the partition satisfies the condition.
Constraints
* 1 \leq |s| \leq 2 \times 10^5
* s consists of lowercase English letters.
Input
Input is given from Standard Input in the following format:
s
Output
Print the minimum possible value of N when the partition satisfies the condition.
Examples
Input
aabxyyzz
Output
2
Input
byebye
Output
1
Input
abcdefghijklmnopqrstuvwxyz
Output
26
Input
abcabcxabcx
Output
3
Submitted Solution:
```
#!/usr/bin/env python3
s = input()
t = 0
d = {t:0}
for i in s :
t ^= 1 << (ord(i)-ord('a'))
for j in range(26) :
if (t^(1<<j)) in d :
d[t] = min(d[t] if t in d else int(1e9),d[t^(1<<j)]+1)
print(d[t] if d[t] else 1)
``` | instruction | 0 | 78,125 | 0 | 156,250 |
No | output | 1 | 78,125 | 0 | 156,251 |
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