message stringlengths 2 30.5k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet.
You have b buns, p beef pa... | instruction | 0 | 36,129 | 10 | 72,258 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
t=int(input())
for i in range(0,t):
b,p,f=map(int,input().split())
h,c=map(int,input().split())
if(b<2):
print(0)
else:
if(c>h):
k=b//2
if(k>=(p+f)):
print(f*c+p*h)
e... | output | 1 | 36,129 | 10 | 72,259 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet.
You have b buns, p beef pa... | instruction | 0 | 36,130 | 10 | 72,260 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
''' Ψ¨ΩΨ³ΩΩ
Ω Ψ§ΩΩΩΩΩΩ Ψ§ΩΨ±ΩΩΨΩΩ
ΩΩ°ΩΩ Ψ§ΩΨ±ΩΩΨΩΩΩ
Ω '''
#codeforces1207A_live
gi = lambda : list(map(int,input().split()))
for k in range(gi()[0]):
b, p, f = gi()
h, c = gi()
ans = 0
if h > c:
tmep = min(b // 2, p)
ans += tmep * h
b -= tmep * 2
an... | output | 1 | 36,130 | 10 | 72,261 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet.
You have b buns, p beef pa... | instruction | 0 | 36,131 | 10 | 72,262 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
p = int(input())
for i in range(p):
b, p, f = map(int, input().split())
h, c = map(int, input().split())
b //= 2
if c > h:
p, f = f, p
h, c = c, h
ans1 = min(b, p) * h
ans2 = min(max(b - p, 0), f) * c
print... | output | 1 | 36,131 | 10 | 72,263 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet.
You have b buns, p beef pa... | instruction | 0 | 36,132 | 10 | 72,264 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
t=int(input())
v=[]
for i in range(t):
l1=list(map(int,input().split()))
l2=list(map(int,input().split()))
b,p,f=l1[0],l1[1],l1[2]
h,c=l2[0],l2[1]
if c>h:
c1=min(b//2,f)
h1=min((b-(c1*2))//2,p)
else:... | output | 1 | 36,132 | 10 | 72,265 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and a chicken cutlet.
You have b buns, p beef pa... | instruction | 0 | 36,133 | 10 | 72,266 |
Tags: brute force, greedy, implementation, math
Correct Solution:
```
n = int(input())
for _ in range(n):
b, p, f = map(int, input().split())
h, c = map(int, input().split())
res = 0
if h > c:
count = min(b // 2, p)
res += h * count
b -= 2 * count
count = min(b // 2, f)
... | output | 1 | 36,133 | 10 | 72,267 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,134 | 10 | 72,268 |
Yes | output | 1 | 36,134 | 10 | 72,269 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,135 | 10 | 72,270 |
Yes | output | 1 | 36,135 | 10 | 72,271 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,136 | 10 | 72,272 |
Yes | output | 1 | 36,136 | 10 | 72,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,137 | 10 | 72,274 |
Yes | output | 1 | 36,137 | 10 | 72,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,138 | 10 | 72,276 |
No | output | 1 | 36,138 | 10 | 72,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,140 | 10 | 72,280 |
No | output | 1 | 36,140 | 10 | 72,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are two types of burgers in your restaurant β hamburgers and chicken burgers! To assemble a hamburger you need two buns and a beef patty. To assemble a chicken burger you need two buns and... | instruction | 0 | 36,141 | 10 | 72,282 |
No | output | 1 | 36,141 | 10 | 72,283 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,142 | 10 | 72,284 |
Tags: implementation, two pointers
Correct Solution:
```
from collections import Counter as cnt
import sys
def count(n,k,d,a):
mat=cnt(a[:d])
i,prev=0,0
j,m=d,len(mat)
while j<n:
prev=a[i]
mat[a[j]]=mat.get(a[j],0)+1
mat[prev] = mat[prev]-1
if mat[prev] == 0:
... | output | 1 | 36,142 | 10 | 72,285 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,143 | 10 | 72,286 |
Tags: implementation, two pointers
Correct Solution:
```
t = int(input())
for i in range(t):
n, k, d = map(int, input().split())
a = list(map(int, input().split()))
b = dict()
for i in range(n):
b[a[i]] = 0
count = 0
for i in range(d):
if b[a[i]] == 0:
count += 1
... | output | 1 | 36,143 | 10 | 72,287 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,144 | 10 | 72,288 |
Tags: implementation, two pointers
Correct Solution:
```
for _ in range(int(input())):
n,k,d = list(map(int,input().split()))
lst = list(map(int,input().split()))
dct = {}
for i in lst[:d]:
if i not in dct:
dct[i] = 1
else:
dct[i] += 1
m = len(dct)
for i i... | output | 1 | 36,144 | 10 | 72,289 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,145 | 10 | 72,290 |
Tags: implementation, two pointers
Correct Solution:
```
for _ in range(int(input())):
n,k,d=map(int,input().split())
l=list(map(int,input().split()))
dict={}
t=set()
for i in range(d):
eleman=l[i]
t.add(eleman)
try:
dict[eleman]+=1
except:
dic... | output | 1 | 36,145 | 10 | 72,291 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,146 | 10 | 72,292 |
Tags: implementation, two pointers
Correct Solution:
```
for __ in range(int(input())):
n, k, d = list(map(int, input().split()))
ar = list(map(int, input().split()))
A = dict()
num = 0
for i in range(d):
if ar[i] in A:
A[ar[i]] += 1
else:
A[ar[i]] = 1
... | output | 1 | 36,146 | 10 | 72,293 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,147 | 10 | 72,294 |
Tags: implementation, two pointers
Correct Solution:
```
for i in range(int(input())):
n, k, d = map(int, input().split())
a = list(map(int, input().split()))
s = d
b = {}
for j in range(d):
b[a[j]] = b.get(a[j], 0) + 1
s = len(b)
for j in range(d, n):
if b[a[j - d]] == 1:
... | output | 1 | 36,147 | 10 | 72,295 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,148 | 10 | 72,296 |
Tags: implementation, two pointers
Correct Solution:
```
from collections import deque
t=int(input())
for i in range(t):
n,k,dp=[int(x) for x in input().split()]
d={}
i=0
p=deque()
cur=0
min=k
for el in input().split():
i+=1
if i<=dp:
p.append(el)
if ... | output | 1 | 36,148 | 10 | 72,297 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequence of integers a_1, a_2, ..., a_n (1 β€ a_i β€ ... | instruction | 0 | 36,149 | 10 | 72,298 |
Tags: implementation, two pointers
Correct Solution:
```
from os import path
import sys
# mod = int(1e9 + 7)
# import re
from math import ceil, floor,gcd,log,log2 ,factorial
from collections import defaultdict , Counter,deque
from itertools import permutations
# from bisect import bisect_left, bisect_right
#popping fro... | output | 1 | 36,149 | 10 | 72,299 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,150 | 10 | 72,300 |
Yes | output | 1 | 36,150 | 10 | 72,301 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,151 | 10 | 72,302 |
Yes | output | 1 | 36,151 | 10 | 72,303 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,152 | 10 | 72,304 |
Yes | output | 1 | 36,152 | 10 | 72,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,153 | 10 | 72,306 |
Yes | output | 1 | 36,153 | 10 | 72,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,154 | 10 | 72,308 |
No | output | 1 | 36,154 | 10 | 72,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,155 | 10 | 72,310 |
No | output | 1 | 36,155 | 10 | 72,311 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,156 | 10 | 72,312 |
No | output | 1 | 36,156 | 10 | 72,313 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
The BerTV channel every day broadcasts one episode of one of the k TV shows. You know the schedule for the next n days: a sequ... | instruction | 0 | 36,157 | 10 | 72,314 |
No | output | 1 | 36,157 | 10 | 72,315 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady and Masha want to choose decorations for thier aquarium in Fishdom game. They have n decorations to choose from, each of them has some cost. To complete a task Arkady and Masha need to ch... | instruction | 0 | 36,578 | 10 | 73,156 |
No | output | 1 | 36,578 | 10 | 73,157 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady and Masha want to choose decorations for thier aquarium in Fishdom game. They have n decorations to choose from, each of them has some cost. To complete a task Arkady and Masha need to ch... | instruction | 0 | 36,579 | 10 | 73,158 |
No | output | 1 | 36,579 | 10 | 73,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady and Masha want to choose decorations for thier aquarium in Fishdom game. They have n decorations to choose from, each of them has some cost. To complete a task Arkady and Masha need to ch... | instruction | 0 | 36,580 | 10 | 73,160 |
No | output | 1 | 36,580 | 10 | 73,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Arkady and Masha want to choose decorations for thier aquarium in Fishdom game. They have n decorations to choose from, each of them has some cost. To complete a task Arkady and Masha need to ch... | instruction | 0 | 36,581 | 10 | 73,162 |
No | output | 1 | 36,581 | 10 | 73,163 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,784 | 10 | 73,568 |
"Correct Solution:
```
def solve():
n, k = map(int,input().split())
group_num = 10
book_map = [[] for i in range(group_num)]
acc_map = [[0] for i in range(group_num)]
for i in range(n):
c, g = map(int,input().split())
book_map[g - 1].append(c)
for i in range(group_num):
bmi = book_map[i]
... | output | 1 | 36,784 | 10 | 73,569 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,785 | 10 | 73,570 |
"Correct Solution:
```
def solve():
n, k = map(int,input().split())
group_num = 10
book_map = [[] for i in range(group_num)]
acc_map = []
for i in range(n):
c, g = map(int,input().split())
book_map[g - 1].append(c)
for i in range(group_num):
bmi = book_map[i]
bmi.sort(reverse=True)
... | output | 1 | 36,785 | 10 | 73,571 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,786 | 10 | 73,572 |
"Correct Solution:
```
def main():
import sys
input=sys.stdin.readline
n,k=map(int,input().split())
ab=[list(map(int,input().split())) for _ in [0]*n]
g=[[] for _ in [0]*10]
[g[b-1].append(a) for a,b in ab]
[g[c].sort(reverse=True) for c in range(10)]
for c in range(10):g[c]=[0]+g[c]
... | output | 1 | 36,786 | 10 | 73,573 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,787 | 10 | 73,574 |
"Correct Solution:
```
def solve():
n, k = map(int,input().split())
group_num = 10
book_map = [[] for i in range(group_num)]
acc_map = [[0] for i in range(group_num)]
for i in range(n):
c,g = map(int,input().split())
book_map[g - 1].append(c)
for i in range(group_num):
book_map[i].sort(reve... | output | 1 | 36,787 | 10 | 73,575 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,788 | 10 | 73,576 |
"Correct Solution:
```
from heapq import heappush as push
from heapq import heappop as pop
def solve():
n, k = map(int,input().split())
group_num = 10
book_map = [[] for i in range(group_num)]
acc_map = [[0] for i in range(group_num)]
for i in range(n):
c,g = map(int,input().split())
push(book_map... | output | 1 | 36,788 | 10 | 73,577 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,789 | 10 | 73,578 |
"Correct Solution:
```
def solve():
n, k = map(int,input().split())
group_num = 10
book_map = [[] for i in range(group_num)]
acc_map = [[0] for i in range(group_num)]
for i in range(n):
c,g = map(int,input().split())
book_map[g - 1].append(c)
for i in range(group_num):
bmi = book_map[i]
... | output | 1 | 36,789 | 10 | 73,579 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,790 | 10 | 73,580 |
"Correct Solution:
```
import sys
def solve():
file_input = sys.stdin
N, K = map(int, file_input.readline().split())
G = [[] for i in range(10)]
for line in file_input:
c, g = map(int, line.split())
G[g - 1].append(c)
for genre in G:
genre.sort(reverse=True)
... | output | 1 | 36,790 | 10 | 73,581 |
Provide a correct Python 3 solution for this coding contest problem.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it at that price if you go to the JOI secondhand bookstore.... | instruction | 0 | 36,791 | 10 | 73,582 |
"Correct Solution:
```
def solve():
N, K = map(int, input().split())
a = [[] for _ in [0]*10]
l = []
for c, g in (tuple(map(int, input().split())) for _ in [0]*N):
a[g-1].append(c)
for i, prices in enumerate(a):
ln = len(prices)
if ln == 0:
continue
dp = ... | output | 1 | 36,791 | 10 | 73,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,792 | 10 | 73,584 |
Yes | output | 1 | 36,792 | 10 | 73,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,793 | 10 | 73,586 |
Yes | output | 1 | 36,793 | 10 | 73,587 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,794 | 10 | 73,588 |
Yes | output | 1 | 36,794 | 10 | 73,589 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,795 | 10 | 73,590 |
No | output | 1 | 36,795 | 10 | 73,591 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,796 | 10 | 73,592 |
No | output | 1 | 36,796 | 10 | 73,593 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,797 | 10 | 73,594 |
No | output | 1 | 36,797 | 10 | 73,595 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There is a long-established secondhand bookstore called JOI secondhand bookstore in your town, and you often use the JOI secondhand bookstore. Each book has a standard price, and you can buy it ... | instruction | 0 | 36,798 | 10 | 73,596 |
No | output | 1 | 36,798 | 10 | 73,597 |
Provide a correct Python 3 solution for this coding contest problem.
You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.
Constraints
* $ 1 \ le n \ le 10 ^ 9 $
Input
$ n $
The intege... | instruction | 0 | 36,818 | 10 | 73,636 |
"Correct Solution:
```
N = int(input())
ans = N // 25; N %= 25
ans += N // 10; N %= 10
ans += N // 5; N %= 5
ans += N
print(ans)
``` | output | 1 | 36,818 | 10 | 73,637 |
Provide a correct Python 3 solution for this coding contest problem.
You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.
Constraints
* $ 1 \ le n \ le 10 ^ 9 $
Input
$ n $
The intege... | instruction | 0 | 36,819 | 10 | 73,638 |
"Correct Solution:
```
def num_coins(cents):
coins = [25, 10, 5, 1]
count = 0
for coin in coins:
while cents >= coin:
cents = cents - coin
count = count + 1
return count
print(num_coins(int(input())))
``` | output | 1 | 36,819 | 10 | 73,639 |
Provide a correct Python 3 solution for this coding contest problem.
You want to make change for $ n $ cents. Assuming that you have infinite supply of coins of 1, 5, 10 and / or 25 cents coins respectively, find the minimum number of coins you need.
Constraints
* $ 1 \ le n \ le 10 ^ 9 $
Input
$ n $
The intege... | instruction | 0 | 36,820 | 10 | 73,640 |
"Correct Solution:
```
n = int(input())
a1 = n//25
a2 = (n - a1*25)//10
a3 = (n - a1*25 - a2*10)//5
a4 = n - a1*25 - a2*10 - a3*5
print(a1+a2+a3+a4)
``` | output | 1 | 36,820 | 10 | 73,641 |
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