message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new "Die Hard" movie has just been released! There are n people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of people in the line. The next line contains n integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.
Output
Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".
Examples
Input
4
25 25 50 50
Output
YES
Input
2
25 100
Output
NO
Input
4
50 50 25 25
Output
NO
Submitted Solution:
```
n=int(input())
m=list(map(int,input().split()))
flag=1
r=[0,0,0]
for i in m:
if(i==25):
r[0]+=1
elif(i==50):
if(r[0]!=0):
r[0]-=1
r[1]+=1
else:
flag=0
print("NO")
break
elif(i==100):
if(r[0]==0 or r[1]==0):
flag=0
print("NO")
break
else:
r[2]+=1
r[1]-=1
r[0]-=1
if(flag==1):
print("YES")
``` | instruction | 0 | 82,908 | 10 | 165,816 |
No | output | 1 | 82,908 | 10 | 165,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The new "Die Hard" movie has just been released! There are n people at the cinema box office standing in a huge line. Each of them has a single 100, 50 or 25 ruble bill. A "Die Hard" ticket costs 25 rubles. Can the booking clerk sell a ticket to each person and give the change if he initially has no money and sells the tickets strictly in the order people follow in the line?
Input
The first line contains integer n (1 ≤ n ≤ 105) — the number of people in the line. The next line contains n integers, each of them equals 25, 50 or 100 — the values of the bills the people have. The numbers are given in the order from the beginning of the line (at the box office) to the end of the line.
Output
Print "YES" (without the quotes) if the booking clerk can sell a ticket to each person and give the change. Otherwise print "NO".
Examples
Input
4
25 25 50 50
Output
YES
Input
2
25 100
Output
NO
Input
4
50 50 25 25
Output
NO
Submitted Solution:
```
# python3
import sys, threading, os.path
import collections, heapq, math,bisect
import string
from platform import python_version
import itertools
sys.setrecursionlimit(10**6)
threading.stack_size(2**27)
def main():
if os.path.exists('input.txt'):
input = open('input.txt', 'r')
else:
input = sys.stdin
#--------------------------------INPUT---------------------------------
n = int(input.readline())
lis = list(map(int, input.readline().split()))
arr = [0]*101
canbe = True
for i in range(n):
if lis[i] == 25:
arr[25]+=1
elif lis[i] == 50:
if arr[25] ==0:
canbe = False
break
else:
arr[25] -=1
arr[50] +=1
elif lis[i] == 100:
if arr[25] ==0 or arr[50] ==0:
canbe = False
break
else:
arr[25] -=1
arr[50] -=1
arr[100] +=1
if canbe:
output = "YES"
else:
output = "NO"
#-------------------------------OUTPUT----------------------------------
if os.path.exists('output.txt'):
open('output.txt', 'w').writelines(str(output))
else:
sys.stdout.write(str(output))
if __name__ == '__main__':
main()
#threading.Thread(target=main).start()
``` | instruction | 0 | 82,909 | 10 | 165,818 |
No | output | 1 | 82,909 | 10 | 165,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On the way home, Karen decided to stop by the supermarket to buy some groceries.
<image>
She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars.
The supermarket sells n goods. The i-th good can be bought for ci dollars. Of course, each good can only be bought once.
Lately, the supermarket has been trying to increase its business. Karen, being a loyal customer, was given n coupons. If Karen purchases the i-th good, she can use the i-th coupon to decrease its price by di. Of course, a coupon cannot be used without buying the corresponding good.
There is, however, a constraint with the coupons. For all i ≥ 2, in order to use the i-th coupon, Karen must also use the xi-th coupon (which may mean using even more coupons to satisfy the requirement for that coupon).
Karen wants to know the following. What is the maximum number of goods she can buy, without exceeding her budget b?
Input
The first line of input contains two integers n and b (1 ≤ n ≤ 5000, 1 ≤ b ≤ 109), the number of goods in the store and the amount of money Karen has, respectively.
The next n lines describe the items. Specifically:
* The i-th line among these starts with two integers, ci and di (1 ≤ di < ci ≤ 109), the price of the i-th good and the discount when using the coupon for the i-th good, respectively.
* If i ≥ 2, this is followed by another integer, xi (1 ≤ xi < i), denoting that the xi-th coupon must also be used before this coupon can be used.
Output
Output a single integer on a line by itself, the number of different goods Karen can buy, without exceeding her budget.
Examples
Input
6 16
10 9
10 5 1
12 2 1
20 18 3
10 2 3
2 1 5
Output
4
Input
5 10
3 1
3 1 1
3 1 2
3 1 3
3 1 4
Output
5
Note
In the first test case, Karen can purchase the following 4 items:
* Use the first coupon to buy the first item for 10 - 9 = 1 dollar.
* Use the third coupon to buy the third item for 12 - 2 = 10 dollars.
* Use the fourth coupon to buy the fourth item for 20 - 18 = 2 dollars.
* Buy the sixth item for 2 dollars.
The total cost of these goods is 15, which falls within her budget. Note, for example, that she cannot use the coupon on the sixth item, because then she should have also used the fifth coupon to buy the fifth item, which she did not do here.
In the second test case, Karen has enough money to use all the coupons and purchase everything.
Submitted Solution:
```
#!/usr/bin/env python3
import heapq
INF = float('inf')
RUN_TESTS = True
TESTS = [
(16, 4, [10, 10, 12, 20, 10, 2], [9, 5, 2, 18, 2, 1], [0, 1, 1, 3, 3, 5]),
(10, 5, [3, 3, 3, 3, 3], [1, 1, 1, 1, 1], [0, 1, 2, 3, 4]),
]
def main():
if RUN_TESTS:
test()
n, b = ints()
C, D, X = [-1] * n, [-1] * n, [-1] * n
C[0], D[0] = ints()
for i in range(1, n):
C[i], D[i], X[i] = ints()
print(items(b, C, D, X))
def items(b, C, D, X):
"""Returns the most items Karen can buy with b dollars."""
n = len(C)
# Use 0-based indexes for convenience.
X = [i - 1 for i in X]
# Tree with edges (u, v) if coupon v requires coupon u to be used.
T = [[] for _ in range(n)]
for u in range(1, n):
T[X[u]].append(u)
# F[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# using coupons.
F = matrix(n, n + 1, INF)
# G[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# WITHOUT using coupons.
G = matrix(n, n + 1, INF)
# S[u] = The size of sub-tree rooted at node u.
S = [0] * n
# Populate F.
dfs(0, C, D, T, F, G, S)
# Search for largest subset that can be bought.
for i in range(n, 0, -1):
if min(F[0][i], G[0][i]) <= b:
return i
return 0
def dfs(u, C, D, T, F, G, S):
"""Populates F/G[v][*] for all v in tree u."""
F[u][0], F[u][1] = 0, C[u] - D[u]
G[u][0], G[u][1] = 0, C[u]
S[u] = 1
for v in T[u]:
dfs(v, C, D, T, F, G, S)
for i in range(S[u], -1, -1):
for k in range(S[v], -1, -1):
F[u][i + k] = min(F[u][i + k], F[u][i] + min(G[v][k], F[v][k]))
G[u][i + k] = min(G[u][i + k], G[u][i] + G[v][k])
S[u] += S[v]
def matrix(n, m, x):
"""Returns an n x m matrix of x's."""
return [[x for _ in range(m)] for _ in range(n)]
def ints():
"""Returns a generator of integers from the next input line."""
return (int(i) for i in input().split())
def test():
print('Testing...')
for i, (b, e, C, D, X) in enumerate(TESTS):
a = items(b, C, D, X)
assert a == e, 'Test %d failed - expect %d but got %d.' % (i + 1, e, a)
print('Tests pass!')
if __name__ == '__main__':
main()
``` | instruction | 0 | 83,079 | 10 | 166,158 |
No | output | 1 | 83,079 | 10 | 166,159 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On the way home, Karen decided to stop by the supermarket to buy some groceries.
<image>
She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars.
The supermarket sells n goods. The i-th good can be bought for ci dollars. Of course, each good can only be bought once.
Lately, the supermarket has been trying to increase its business. Karen, being a loyal customer, was given n coupons. If Karen purchases the i-th good, she can use the i-th coupon to decrease its price by di. Of course, a coupon cannot be used without buying the corresponding good.
There is, however, a constraint with the coupons. For all i ≥ 2, in order to use the i-th coupon, Karen must also use the xi-th coupon (which may mean using even more coupons to satisfy the requirement for that coupon).
Karen wants to know the following. What is the maximum number of goods she can buy, without exceeding her budget b?
Input
The first line of input contains two integers n and b (1 ≤ n ≤ 5000, 1 ≤ b ≤ 109), the number of goods in the store and the amount of money Karen has, respectively.
The next n lines describe the items. Specifically:
* The i-th line among these starts with two integers, ci and di (1 ≤ di < ci ≤ 109), the price of the i-th good and the discount when using the coupon for the i-th good, respectively.
* If i ≥ 2, this is followed by another integer, xi (1 ≤ xi < i), denoting that the xi-th coupon must also be used before this coupon can be used.
Output
Output a single integer on a line by itself, the number of different goods Karen can buy, without exceeding her budget.
Examples
Input
6 16
10 9
10 5 1
12 2 1
20 18 3
10 2 3
2 1 5
Output
4
Input
5 10
3 1
3 1 1
3 1 2
3 1 3
3 1 4
Output
5
Note
In the first test case, Karen can purchase the following 4 items:
* Use the first coupon to buy the first item for 10 - 9 = 1 dollar.
* Use the third coupon to buy the third item for 12 - 2 = 10 dollars.
* Use the fourth coupon to buy the fourth item for 20 - 18 = 2 dollars.
* Buy the sixth item for 2 dollars.
The total cost of these goods is 15, which falls within her budget. Note, for example, that she cannot use the coupon on the sixth item, because then she should have also used the fifth coupon to buy the fifth item, which she did not do here.
In the second test case, Karen has enough money to use all the coupons and purchase everything.
Submitted Solution:
```
from collections import defaultdict
Count=0
def BFGetMaxGood(start,RemPurse,G,Cost,Discount,prevSelected):
global Count
M=0
if RemPurse<0:
Count=max(Count,len(prevSelected)-1)
return
if RemPurse==0 or start>len(Cost):
Count=max(Count,len(prevSelected))
return
#Selects this particular product
X=0#With Discount
Y=0#Without Discount
Z=0# Not Seleceting this number
prevSelected.add(start)
if start in G:#this products has some discount
if G[start] in prevSelected:# means discount product has already been selected
BFGetMaxGood(start+1,RemPurse-Cost[start]+Discount[start],G,Cost,Discount,prevSelected)
else:
#No Discount product has been selected So No Discount applied
BFGetMaxGood(start+1,RemPurse-Cost[start],G,Cost,Discount,prevSelected)
else:
#No Discount for this product
BFGetMaxGood(start+1,RemPurse-Cost[start],G,Cost,Discount,prevSelected)
##Do Not Select this product
prevSelected.remove(start)
BFGetMaxGood(start+1,RemPurse,G,Cost,Discount,prevSelected)
return
N,B=map(int,input().strip().split())
G={}
Cost={}
Discount={}
for i in range(0,N):
I=input().split(" ")
if len(I)==2:
u,v=int(I[0]),int(I[1])
Discount[i+1]=v
Cost[i+1]=u
else:
u,v,index=int(I[0]),int(I[1]),int(I[2])
Discount[i+1]=v
Cost[i+1]=u
G[i+1]=index
Cost[1]=Cost[1]-Discount[1]
BFGetMaxGood(1,B,G,Cost,Discount,set())
print(Count)
``` | instruction | 0 | 83,080 | 10 | 166,160 |
No | output | 1 | 83,080 | 10 | 166,161 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On the way home, Karen decided to stop by the supermarket to buy some groceries.
<image>
She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars.
The supermarket sells n goods. The i-th good can be bought for ci dollars. Of course, each good can only be bought once.
Lately, the supermarket has been trying to increase its business. Karen, being a loyal customer, was given n coupons. If Karen purchases the i-th good, she can use the i-th coupon to decrease its price by di. Of course, a coupon cannot be used without buying the corresponding good.
There is, however, a constraint with the coupons. For all i ≥ 2, in order to use the i-th coupon, Karen must also use the xi-th coupon (which may mean using even more coupons to satisfy the requirement for that coupon).
Karen wants to know the following. What is the maximum number of goods she can buy, without exceeding her budget b?
Input
The first line of input contains two integers n and b (1 ≤ n ≤ 5000, 1 ≤ b ≤ 109), the number of goods in the store and the amount of money Karen has, respectively.
The next n lines describe the items. Specifically:
* The i-th line among these starts with two integers, ci and di (1 ≤ di < ci ≤ 109), the price of the i-th good and the discount when using the coupon for the i-th good, respectively.
* If i ≥ 2, this is followed by another integer, xi (1 ≤ xi < i), denoting that the xi-th coupon must also be used before this coupon can be used.
Output
Output a single integer on a line by itself, the number of different goods Karen can buy, without exceeding her budget.
Examples
Input
6 16
10 9
10 5 1
12 2 1
20 18 3
10 2 3
2 1 5
Output
4
Input
5 10
3 1
3 1 1
3 1 2
3 1 3
3 1 4
Output
5
Note
In the first test case, Karen can purchase the following 4 items:
* Use the first coupon to buy the first item for 10 - 9 = 1 dollar.
* Use the third coupon to buy the third item for 12 - 2 = 10 dollars.
* Use the fourth coupon to buy the fourth item for 20 - 18 = 2 dollars.
* Buy the sixth item for 2 dollars.
The total cost of these goods is 15, which falls within her budget. Note, for example, that she cannot use the coupon on the sixth item, because then she should have also used the fifth coupon to buy the fifth item, which she did not do here.
In the second test case, Karen has enough money to use all the coupons and purchase everything.
Submitted Solution:
```
#!/usr/bin/env python3
import heapq
INF = float('inf')
RUN_TESTS = True
TESTS = [
(16, 4, [10, 10, 12, 20, 10, 2], [9, 5, 2, 18, 2, 1], [0, 1, 1, 3, 3, 5]),
(10, 5, [3, 3, 3, 3, 3], [1, 1, 1, 1, 1], [0, 1, 2, 3, 4]),
]
def main():
if RUN_TESTS:
test()
n, b = ints()
C, D, X = [-1] * n, [-1] * n, [-1] * n
C[0], D[0] = ints()
for i in range(1, n):
C[i], D[i], X[i] = ints()
print(items(b, C, D, X))
def items(b, C, D, X):
"""Returns the most items Karen can buy with b dollars."""
n = len(X)
# Use 0-based indexes for convenience.
X = [i - 1 for i in X]
# Tree with edges (u, v) if coupon v requires coupon u to be used.
T = [[] for _ in range(n)]
for u in range(1, n):
T[X[u]].append(u)
# F[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# using coupons.
F = matrix(n, n + 1, INF)
# G[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# WITHOUT using coupons.
G = matrix(n, n + 1, INF)
# S[u] = The size of sub-tree rooted at node u.
S = [0] * n
# Populate F.
dfs(0, C, D, T, F, G, S)
# print('F = ')
# for i, r in enumerate(F):
# print('%d -> %s' % (i, '\t'.join(map(str, r))))
# print('G = ')
# for i, r in enumerate(G):
# print('%d -> %s' % (i, '\t'.join(map(str, r))))
# Search for largest subset that can be bought.
for i in range(n, 0, -1):
if min(F[0][i], G[0][i]) <= b:
return i
return 0
def dfs(u, C, D, T, F, G, S):
"""Populates F/G[v][*] for all v in tree u."""
F[u][0], F[u][1] = INF, C[u] - D[u]
G[u][0], G[u][1] = 0, C[u]
S[u] = 1
for v in T[u]:
dfs(v, C, D, T, F, G, S)
for i in range(S[u], -1, -1):
for k in range(S[v], -1, -1):
F[u][i + k] = min(F[u][i + k], F[u][i] + min(G[v][k], F[v][k]))
G[u][i + k] = min(G[u][i + k], G[u][i] + G[v][k])
S[u] += S[v]
def matrix(n, m, x):
"""Returns an n x m matrix of x's."""
return [[x for _ in range(m)] for _ in range(n)]
def ints():
"""Returns a generator of integers from the next input line."""
return (int(i) for i in input().split())
def test():
print('Testing...')
for i, (b, e, C, D, X) in enumerate(TESTS):
a = items(b, C, D, X)
assert a == e, 'Test %d failed - expect %d but got %d.' % (i + 1, e, a)
print('Tests pass!')
if __name__ == '__main__':
main()
``` | instruction | 0 | 83,081 | 10 | 166,162 |
No | output | 1 | 83,081 | 10 | 166,163 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On the way home, Karen decided to stop by the supermarket to buy some groceries.
<image>
She needs to buy a lot of goods, but since she is a student her budget is still quite limited. In fact, she can only spend up to b dollars.
The supermarket sells n goods. The i-th good can be bought for ci dollars. Of course, each good can only be bought once.
Lately, the supermarket has been trying to increase its business. Karen, being a loyal customer, was given n coupons. If Karen purchases the i-th good, she can use the i-th coupon to decrease its price by di. Of course, a coupon cannot be used without buying the corresponding good.
There is, however, a constraint with the coupons. For all i ≥ 2, in order to use the i-th coupon, Karen must also use the xi-th coupon (which may mean using even more coupons to satisfy the requirement for that coupon).
Karen wants to know the following. What is the maximum number of goods she can buy, without exceeding her budget b?
Input
The first line of input contains two integers n and b (1 ≤ n ≤ 5000, 1 ≤ b ≤ 109), the number of goods in the store and the amount of money Karen has, respectively.
The next n lines describe the items. Specifically:
* The i-th line among these starts with two integers, ci and di (1 ≤ di < ci ≤ 109), the price of the i-th good and the discount when using the coupon for the i-th good, respectively.
* If i ≥ 2, this is followed by another integer, xi (1 ≤ xi < i), denoting that the xi-th coupon must also be used before this coupon can be used.
Output
Output a single integer on a line by itself, the number of different goods Karen can buy, without exceeding her budget.
Examples
Input
6 16
10 9
10 5 1
12 2 1
20 18 3
10 2 3
2 1 5
Output
4
Input
5 10
3 1
3 1 1
3 1 2
3 1 3
3 1 4
Output
5
Note
In the first test case, Karen can purchase the following 4 items:
* Use the first coupon to buy the first item for 10 - 9 = 1 dollar.
* Use the third coupon to buy the third item for 12 - 2 = 10 dollars.
* Use the fourth coupon to buy the fourth item for 20 - 18 = 2 dollars.
* Buy the sixth item for 2 dollars.
The total cost of these goods is 15, which falls within her budget. Note, for example, that she cannot use the coupon on the sixth item, because then she should have also used the fifth coupon to buy the fifth item, which she did not do here.
In the second test case, Karen has enough money to use all the coupons and purchase everything.
Submitted Solution:
```
#!/usr/bin/env python3
import heapq
INF = float('inf')
RUN_TESTS = False
TESTS = [
(16, 4, [10, 10, 12, 20, 10, 2], [9, 5, 2, 18, 2, 1], [0, 1, 1, 3, 3, 5]),
(10, 5, [3, 3, 3, 3, 3], [1, 1, 1, 1, 1], [0, 1, 2, 3, 4]),
]
def main():
if RUN_TESTS:
test()
n, b = ints()
C, D, X = [-1] * n, [-1] * n, [-1] * n
C[0], D[0] = ints()
for i in range(1, n):
C[i], D[i], X[i] = ints()
print(items(b, C, D, X))
def items(b, C, D, X):
"""Returns the most items Karen can buy with b dollars."""
n = len(C)
# Use 0-based indexes for convenience.
X = [i - 1 for i in X]
# Tree with edges (u, v) if coupon v requires coupon u to be used.
T = [[] for _ in range(n)]
for u in range(1, n):
T[X[u]].append(u)
# F[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# using coupons.
F = matrix(n, n + 1, INF)
# G[u][i] = The minimum cost of buying exactly i items in the sub-tree u
# WITHOUT using coupons.
G = matrix(n, n + 1, INF)
# S[u] = The size of sub-tree rooted at node u.
S = [0] * n
# Populate F.
dfs(0, C, D, T, F, G, S)
# Search for largest subset that can be bought.
for i in range(n, 0, -1):
if min(F[0][i], G[0][i]) <= b:
return i
return 0
def dfs(u, C, D, T, F, G, S):
"""Populates F/G[v][*] for all v in tree u."""
F[u][0], F[u][1] = 0, C[u] - D[u]
G[u][0], G[u][1] = 0, C[u]
S[u] = 1
for v in T[u]:
dfs(v, C, D, T, F, G, S)
for i in range(S[u], -1, -1):
for k in range(S[v], -1, -1):
F[u][i + k] = min(F[u][i + k], F[u][i] + min(G[v][k], F[v][k]))
G[u][i + k] = min(G[u][i + k], G[u][i] + G[v][k])
S[u] += S[v]
def matrix(n, m, x):
"""Returns an n x m matrix of x's."""
return [[x for _ in range(m)] for _ in range(n)]
def ints():
"""Returns a generator of integers from the next input line."""
return (int(i) for i in input().split())
def test():
print('Testing...')
for i, (b, e, C, D, X) in enumerate(TESTS):
a = items(b, C, D, X)
assert a == e, 'Test %d failed - expect %d but got %d.' % (i + 1, e, a)
print('Tests pass!')
if __name__ == '__main__':
main()
``` | instruction | 0 | 83,082 | 10 | 166,164 |
No | output | 1 | 83,082 | 10 | 166,165 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The big consignment of t-shirts goes on sale in the shop before the beginning of the spring. In all n types of t-shirts go on sale. The t-shirt of the i-th type has two integer parameters — ci and qi, where ci — is the price of the i-th type t-shirt, qi — is the quality of the i-th type t-shirt. It should be assumed that the unlimited number of t-shirts of each type goes on sale in the shop, but in general the quality is not concerned with the price.
As predicted, k customers will come to the shop within the next month, the j-th customer will get ready to spend up to bj on buying t-shirts.
All customers have the same strategy. First of all, the customer wants to buy the maximum possible number of the highest quality t-shirts, then to buy the maximum possible number of the highest quality t-shirts from residuary t-shirts and so on. At the same time among several same quality t-shirts the customer will buy one that is cheaper. The customers don't like the same t-shirts, so each customer will not buy more than one t-shirt of one type.
Determine the number of t-shirts which each customer will buy, if they use the described strategy. All customers act independently from each other, and the purchase of one does not affect the purchase of another.
Input
The first line contains the positive integer n (1 ≤ n ≤ 2·105) — the number of t-shirt types.
Each of the following n lines contains two integers ci and qi (1 ≤ ci, qi ≤ 109) — the price and the quality of the i-th type t-shirt.
The next line contains the positive integer k (1 ≤ k ≤ 2·105) — the number of the customers.
The next line contains k positive integers b1, b2, ..., bk (1 ≤ bj ≤ 109), where the j-th number is equal to the sum, which the j-th customer gets ready to spend on t-shirts.
Output
The first line of the input data should contain the sequence of k integers, where the i-th number should be equal to the number of t-shirts, which the i-th customer will buy.
Examples
Input
3
7 5
3 5
4 3
2
13 14
Output
2 3
Input
2
100 500
50 499
4
50 200 150 100
Output
1 2 2 1
Note
In the first example the first customer will buy the t-shirt of the second type, then the t-shirt of the first type. He will spend 10 and will not be able to buy the t-shirt of the third type because it costs 4, and the customer will owe only 3. The second customer will buy all three t-shirts (at first, the t-shirt of the second type, then the t-shirt of the first type, and then the t-shirt of the third type). He will spend all money on it.
Submitted Solution:
```
def UpperBound(A, key): # ���������� ������ ������� ��������, ������� ������ ��� key
left = -1
right = len(A)
while right > left + 1:
middle = (left + right) // 2
if A[middle] > key:
right = middle
else:
left = middle
return right
def LowerBound(A, key): # ���������� ������ ������� ��������, ������� ����� key (� ���� ������ ��� � �� ����, ������� ������, ��� key)
left = -1
right = len(A)
while right > left + 1:
middle = (left + right) // 2
if A[middle] >= key:
right = middle
else:
left = middle
return right
n = int(input())
W = [list(map(int, input().split())) for i in range(n)]
k = int(input())
K = list(map(int, input().split()))
M = [0] * (k)
INF = 10 ** 9
F = [0] * (n) # ��������� �������� � 0 �� i-� (������������)
W.sort(key=lambda x: (x[1], INF - x[0]), reverse= True)
for i in range(n):
F[i] = F[i-1] + W[i][0]
#for i in range(n):
# print(W[i])
min_s = min(W[0])
print(min_s)
for m in range(k):
i = 0
counter = 0
while i < n and K[m] >= min_s:
if W[i][0] <= K[m]:
K[m] -= W[i][0]
counter += 1
i += 1
#print(K[m], m)
M[m] = counter
print(*M)
``` | instruction | 0 | 83,875 | 10 | 167,750 |
No | output | 1 | 83,875 | 10 | 167,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The big consignment of t-shirts goes on sale in the shop before the beginning of the spring. In all n types of t-shirts go on sale. The t-shirt of the i-th type has two integer parameters — ci and qi, where ci — is the price of the i-th type t-shirt, qi — is the quality of the i-th type t-shirt. It should be assumed that the unlimited number of t-shirts of each type goes on sale in the shop, but in general the quality is not concerned with the price.
As predicted, k customers will come to the shop within the next month, the j-th customer will get ready to spend up to bj on buying t-shirts.
All customers have the same strategy. First of all, the customer wants to buy the maximum possible number of the highest quality t-shirts, then to buy the maximum possible number of the highest quality t-shirts from residuary t-shirts and so on. At the same time among several same quality t-shirts the customer will buy one that is cheaper. The customers don't like the same t-shirts, so each customer will not buy more than one t-shirt of one type.
Determine the number of t-shirts which each customer will buy, if they use the described strategy. All customers act independently from each other, and the purchase of one does not affect the purchase of another.
Input
The first line contains the positive integer n (1 ≤ n ≤ 2·105) — the number of t-shirt types.
Each of the following n lines contains two integers ci and qi (1 ≤ ci, qi ≤ 109) — the price and the quality of the i-th type t-shirt.
The next line contains the positive integer k (1 ≤ k ≤ 2·105) — the number of the customers.
The next line contains k positive integers b1, b2, ..., bk (1 ≤ bj ≤ 109), where the j-th number is equal to the sum, which the j-th customer gets ready to spend on t-shirts.
Output
The first line of the input data should contain the sequence of k integers, where the i-th number should be equal to the number of t-shirts, which the i-th customer will buy.
Examples
Input
3
7 5
3 5
4 3
2
13 14
Output
2 3
Input
2
100 500
50 499
4
50 200 150 100
Output
1 2 2 1
Note
In the first example the first customer will buy the t-shirt of the second type, then the t-shirt of the first type. He will spend 10 and will not be able to buy the t-shirt of the third type because it costs 4, and the customer will owe only 3. The second customer will buy all three t-shirts (at first, the t-shirt of the second type, then the t-shirt of the first type, and then the t-shirt of the third type). He will spend all money on it.
Submitted Solution:
```
import operator
total_list= []
n= int(input())
for i in range(0,n):
input_str=input()
input_str = input_str.split(' ')
pair=[int(input_str[0]),int(input_str[1])]
total_list.append(pair)
total_list.sort(key=operator.itemgetter(1), reverse = True)
total_iter_length = len(total_list)-1
for i in range(0, total_iter_length):
if(total_list[i][1] == total_list[i+1][1]):
if(total_list[i][0] > total_list[i+1][0]):
tmp = total_list[i][0]
total_list[i][0] = total_list[i+1][0]
total_list[i+1][0] = tmp
no_of_customers = int(input())
budjet_list = [int(budjet) for budjet in input().split(' ')]
output = []
if(n == 1000):
print(budjet_list)
for budjet in budjet_list:
t_count = 0
for pair in total_list:
if(pair[0] <= budjet):
t_count = t_count+1
budjet = budjet - pair[0]
output.append(str(t_count))
print(" ".join(output))
``` | instruction | 0 | 83,876 | 10 | 167,752 |
No | output | 1 | 83,876 | 10 | 167,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The big consignment of t-shirts goes on sale in the shop before the beginning of the spring. In all n types of t-shirts go on sale. The t-shirt of the i-th type has two integer parameters — ci and qi, where ci — is the price of the i-th type t-shirt, qi — is the quality of the i-th type t-shirt. It should be assumed that the unlimited number of t-shirts of each type goes on sale in the shop, but in general the quality is not concerned with the price.
As predicted, k customers will come to the shop within the next month, the j-th customer will get ready to spend up to bj on buying t-shirts.
All customers have the same strategy. First of all, the customer wants to buy the maximum possible number of the highest quality t-shirts, then to buy the maximum possible number of the highest quality t-shirts from residuary t-shirts and so on. At the same time among several same quality t-shirts the customer will buy one that is cheaper. The customers don't like the same t-shirts, so each customer will not buy more than one t-shirt of one type.
Determine the number of t-shirts which each customer will buy, if they use the described strategy. All customers act independently from each other, and the purchase of one does not affect the purchase of another.
Input
The first line contains the positive integer n (1 ≤ n ≤ 2·105) — the number of t-shirt types.
Each of the following n lines contains two integers ci and qi (1 ≤ ci, qi ≤ 109) — the price and the quality of the i-th type t-shirt.
The next line contains the positive integer k (1 ≤ k ≤ 2·105) — the number of the customers.
The next line contains k positive integers b1, b2, ..., bk (1 ≤ bj ≤ 109), where the j-th number is equal to the sum, which the j-th customer gets ready to spend on t-shirts.
Output
The first line of the input data should contain the sequence of k integers, where the i-th number should be equal to the number of t-shirts, which the i-th customer will buy.
Examples
Input
3
7 5
3 5
4 3
2
13 14
Output
2 3
Input
2
100 500
50 499
4
50 200 150 100
Output
1 2 2 1
Note
In the first example the first customer will buy the t-shirt of the second type, then the t-shirt of the first type. He will spend 10 and will not be able to buy the t-shirt of the third type because it costs 4, and the customer will owe only 3. The second customer will buy all three t-shirts (at first, the t-shirt of the second type, then the t-shirt of the first type, and then the t-shirt of the third type). He will spend all money on it.
Submitted Solution:
```
n = int(input())
W = [list(map(int, input().split())) for i in range(n)]
k = int(input())
K = list(map(int, input().split()))
M = [0] * (k)
W.sort(key=lambda x: x[1], reverse= True)
for m in range(k):
i = 0
counter = 0
while i < n and K[m] > 0:
if W[i][0] <= K[m]:
K[m] -= W[i][0]
counter += 1
i += 1
#print(K[m], m)
M[m] = counter
print(*M)
``` | instruction | 0 | 83,877 | 10 | 167,754 |
No | output | 1 | 83,877 | 10 | 167,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The big consignment of t-shirts goes on sale in the shop before the beginning of the spring. In all n types of t-shirts go on sale. The t-shirt of the i-th type has two integer parameters — ci and qi, where ci — is the price of the i-th type t-shirt, qi — is the quality of the i-th type t-shirt. It should be assumed that the unlimited number of t-shirts of each type goes on sale in the shop, but in general the quality is not concerned with the price.
As predicted, k customers will come to the shop within the next month, the j-th customer will get ready to spend up to bj on buying t-shirts.
All customers have the same strategy. First of all, the customer wants to buy the maximum possible number of the highest quality t-shirts, then to buy the maximum possible number of the highest quality t-shirts from residuary t-shirts and so on. At the same time among several same quality t-shirts the customer will buy one that is cheaper. The customers don't like the same t-shirts, so each customer will not buy more than one t-shirt of one type.
Determine the number of t-shirts which each customer will buy, if they use the described strategy. All customers act independently from each other, and the purchase of one does not affect the purchase of another.
Input
The first line contains the positive integer n (1 ≤ n ≤ 2·105) — the number of t-shirt types.
Each of the following n lines contains two integers ci and qi (1 ≤ ci, qi ≤ 109) — the price and the quality of the i-th type t-shirt.
The next line contains the positive integer k (1 ≤ k ≤ 2·105) — the number of the customers.
The next line contains k positive integers b1, b2, ..., bk (1 ≤ bj ≤ 109), where the j-th number is equal to the sum, which the j-th customer gets ready to spend on t-shirts.
Output
The first line of the input data should contain the sequence of k integers, where the i-th number should be equal to the number of t-shirts, which the i-th customer will buy.
Examples
Input
3
7 5
3 5
4 3
2
13 14
Output
2 3
Input
2
100 500
50 499
4
50 200 150 100
Output
1 2 2 1
Note
In the first example the first customer will buy the t-shirt of the second type, then the t-shirt of the first type. He will spend 10 and will not be able to buy the t-shirt of the third type because it costs 4, and the customer will owe only 3. The second customer will buy all three t-shirts (at first, the t-shirt of the second type, then the t-shirt of the first type, and then the t-shirt of the third type). He will spend all money on it.
Submitted Solution:
```
T = int(input())
s = [int(input().split()[0]) for _ in range(T)]
s = sorted(s)
c = int(input())
cus = list(map(int,input().split()))
for i in range(len(cus)):
sm=0
count=0
for j in range(len(s)):
sm += s[j]
if sm <= cus[i]:
count += 1
print(count,end=' ')
``` | instruction | 0 | 83,878 | 10 | 167,756 |
No | output | 1 | 83,878 | 10 | 167,757 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,044 | 10 | 168,088 |
"Correct Solution:
```
N = int(input())
s = [input() for _ in range(N)]
M = int(input())
t = [input() for _ in range(M)]
ans = [s.count(si) - t.count(si) for si in set(s)]
print(max(0, max(ans)))
``` | output | 1 | 84,044 | 10 | 168,089 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,045 | 10 | 168,090 |
"Correct Solution:
```
s = [input() for i in range(int(input()))]
t = [input() for i in range(int(input()))]
l = list(set(s))
print(max(0,max(s.count(l[i])-t.count(l[i]) for i in range(len(l)))))
``` | output | 1 | 84,045 | 10 | 168,091 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,046 | 10 | 168,092 |
"Correct Solution:
```
N = int(input())
S = [input() for _ in range(N)]
M = int(input())
T = [input() for _ in range(M)]
ans = 0
for s in set(S+T):
ans = max(ans, S.count(s) - T.count(s))
print(ans)
``` | output | 1 | 84,046 | 10 | 168,093 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,047 | 10 | 168,094 |
"Correct Solution:
```
n=int(input())
s=[str(input()) for _ in range(n)]
m=int(input())
t=[str(input()) for _ in range(m)]
l=set(s)
num=max(s.count(i)-t.count(i) for i in l)
print(max(0,num))
``` | output | 1 | 84,047 | 10 | 168,095 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,048 | 10 | 168,096 |
"Correct Solution:
```
n=int(input())
a=[input()for i in range(n)]
m=int(input())
b=[input() for i in range(m)]
c=[a.count(a[i])-b.count(a[i]) for i in range(n)]
print(max(max(c),0))
``` | output | 1 | 84,048 | 10 | 168,097 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,049 | 10 | 168,098 |
"Correct Solution:
```
N = int(input())
s = [str(input()) for i in range(N)]
M = int(input())
t = [str(input()) for i in range(M)]
ans = 0
for i in s:
ans = max(ans, s.count(i) - t.count(i))
print(ans)
``` | output | 1 | 84,049 | 10 | 168,099 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,050 | 10 | 168,100 |
"Correct Solution:
```
a = [input() for _ in range(int(input()))]
b = [input() for _ in range(int(input()))]
c = a + b
print(max(0, max([ a.count(i) - b.count(i) for i in set(c)])))
``` | output | 1 | 84,050 | 10 | 168,101 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1 | instruction | 0 | 84,051 | 10 | 168,102 |
"Correct Solution:
```
n = int(input())
s = [input() for i in range(n)]
m = int(input())
t = [input() for i in range(m)]
ans = 0
for c in s:
ans = max(s.count(c)-t.count(c),ans)
print(ans)
``` | output | 1 | 84,051 | 10 | 168,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
n=int(input())
b=[input() for _ in range(n)]
m=int(input())
r=[input() for _ in range(m)]
l=list(set(b))
a=[]
for s in l:
a.append(b.count(s) - r.count(s))
print(max(max(a),0))
``` | instruction | 0 | 84,052 | 10 | 168,104 |
Yes | output | 1 | 84,052 | 10 | 168,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
d={'':0}
for _ in[0]*int(input()):e=input();d[e]=d.get(e,0)+1
for _ in[0]*int(input()):e=input();d[e]=d.get(e,0)-1
#print(max(d[max(d,key=lambda x:d[x])],0))
print(max(d.values()))
``` | instruction | 0 | 84,053 | 10 | 168,106 |
Yes | output | 1 | 84,053 | 10 | 168,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
n=int(input())
S=[input() for i in range(n)]
m=int(input())
T=[input() for i in range(m)]
ans=0
for s in set(S):
ans = max(ans,S.count(s)-T.count(s))
print(ans)
``` | instruction | 0 | 84,054 | 10 | 168,108 |
Yes | output | 1 | 84,054 | 10 | 168,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
I=lambda:[input()for _ in[0]*int(input())];s=I();t=I();print(max(0,*[s.count(i)-t.count(i)for i in set(s)]))
``` | instruction | 0 | 84,055 | 10 | 168,110 |
Yes | output | 1 | 84,055 | 10 | 168,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
#include <bits/stdc++.h>
using namespace std;
#define rep(i, n) for (int i = 0; i < (int)(n); i++)
int main() {
int n,m;
vector<string> s(n),t(m),o(n);
cin>>n;
rep(i,n){
cin>>s.at(i);
}
cin>>m;
rep(j,m){
cin>>t.at(j)
}
rep(i,n){
int sss=0, ttt=0;
rep(j,n){
if(s.at(i)==s.at(j)){
sss++;
}
}
rep(k,m){
if(s.at(i)==t.at(k)){
ttt++;
}
}
o.at(i) = sss - ttt;
}
int max=0;
rep(i,n){
if(max<o.at(i)){
max = o.at(i);
}
}
cout<<max;
}
``` | instruction | 0 | 84,056 | 10 | 168,112 |
No | output | 1 | 84,056 | 10 | 168,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
BlueN = int(input())
BlueList = []
for i in range(0,BlueN):
BlueList.append(input())
RedN = int(input())
RedList = []
for i in range(0,RedN):
RedList.append(input())
stocker = 0
for i in set(BlueList):
if BlueList.count(i) * 1 + RedList.count(i) * -1 >= stocker:
stocker = BlueList.count(i)
print(stocker)
``` | instruction | 0 | 84,057 | 10 | 168,114 |
No | output | 1 | 84,057 | 10 | 168,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
n=int(input())
a=[]
b=[]
c=[]
for i in range(n):
a.append(str(input()))
m=int(input())
for s in range(m):
b.append(str(input()))
for k in range(n):
c.append(a.count(a[k])-b.count(a[k]))
for l in range(m):
c.append(a.count(b[l]) - b.count(b[l]))
print(max(c))
``` | instruction | 0 | 84,058 | 10 | 168,116 |
No | output | 1 | 84,058 | 10 | 168,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has N blue cards and M red cards. A string is written on each card. The string written on the i-th blue card is s_i, and the string written on the i-th red card is t_i.
Takahashi will now announce a string, and then check every card. Each time he finds a blue card with the string announced by him, he will earn 1 yen (the currency of Japan); each time he finds a red card with that string, he will lose 1 yen.
Here, we only consider the case where the string announced by Takahashi and the string on the card are exactly the same. For example, if he announces `atcoder`, he will not earn money even if there are blue cards with `atcoderr`, `atcode`, `btcoder`, and so on. (On the other hand, he will not lose money even if there are red cards with such strings, either.)
At most how much can he earn on balance?
Note that the same string may be written on multiple cards.
Constraints
* N and M are integers.
* 1 \leq N, M \leq 100
* s_1, s_2, ..., s_N, t_1, t_2, ..., t_M are all strings of lengths between 1 and 10 (inclusive) consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
N
s_1
s_2
:
s_N
M
t_1
t_2
:
t_M
Output
If Takahashi can earn at most X yen on balance, print X.
Examples
Input
3
apple
orange
apple
1
grape
Output
2
Input
3
apple
orange
apple
5
apple
apple
apple
apple
apple
Output
1
Input
1
voldemort
10
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
voldemort
Output
0
Input
6
red
red
blue
yellow
yellow
red
5
red
red
yellow
green
blue
Output
1
Submitted Solution:
```
N = int( input())
s = list()
for i in range(N):
S = input()
s.append(S)
M = int( input())
t = list()
for j in range(M):
T = input()
t.append(T)
judge = 0
for l in range(N):
money = s.count(s[i]) - t.count(s[i])
if( judge < money):
judge = money
else:
continue
print(judge)
``` | instruction | 0 | 84,059 | 10 | 168,118 |
No | output | 1 | 84,059 | 10 | 168,119 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,520 | 10 | 171,040 |
"Correct Solution:
```
def main():
s = input().rstrip()
s = "0" + s
dp = [0, float("inf")]
for c in s:
x = int(c)
dp = [min(dp[0] + x, dp[1] + (10-x)), min(dp[0] + x+1, dp[1] + (10-x) - 1)]
print(dp[0])
if __name__ == "__main__":
main()
``` | output | 1 | 85,520 | 10 | 171,041 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,521 | 10 | 171,042 |
"Correct Solution:
```
n = input()
lenn = len(n)
dp = [0, 10000]
for d in reversed(n):
d = int(d)
dp = [min(d + dp[0], d + 1 + dp[1]), min(10 - d + dp[0], 9 - d + dp[1])]
print(min(dp[0], 1 + dp[1]))
``` | output | 1 | 85,521 | 10 | 171,043 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,522 | 10 | 171,044 |
"Correct Solution:
```
n = input()
c = 0
r = 1
for x in map(int, n):
tc = min(c + x, r + 10 - x)
if x == 9:
tr = r
else:
tr = min(c + x + 1, r + 10 - (x + 1))
c, r = tc, tr
print(c)
``` | output | 1 | 85,522 | 10 | 171,045 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,523 | 10 | 171,046 |
"Correct Solution:
```
S = input()
n = len(S)
dp = [[0] * 2 for _ in range(n+1)]
dp[0][0] = 0
dp[0][1] = 1
for i in range(n):
dp[i+1][0] = min(int(S[i]) + dp[i][0], 10 - int(S[i]) + dp[i][1])
dp[i+1][1] = min(int(S[i]) + 1 + dp[i][0], 10 - int(S[i]) - 1 + dp[i][1])
print(dp[n][0])
``` | output | 1 | 85,523 | 10 | 171,047 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,524 | 10 | 171,048 |
"Correct Solution:
```
N = [int(i) for i in input()]
n = N[::-1]+[0]
for i in range(len(n)-1):
if n[i] >= 6 or (n[i] == 5 and n[i+1] >= 5):
n[i] = 10 - n[i]
n[i+1] += 1
print(sum(n))
``` | output | 1 | 85,524 | 10 | 171,049 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,525 | 10 | 171,050 |
"Correct Solution:
```
n=input()[::-1]
n+="0"
L=len(n)
ans=0
chk=0
flg=0
for i in range(L):
chk=int(n[i])
chk+=flg
if chk==5:
if int(n[i+1])>=5:
ans+=5
flg=1
else:
ans+=5
flg=0
elif chk>5:
ans+=10-chk
flg=1
else:
ans+=chk
flg=0
print(ans+flg)
``` | output | 1 | 85,525 | 10 | 171,051 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,526 | 10 | 171,052 |
"Correct Solution:
```
N = [int(c) for c in input()]
dp = 0,1
for n in N:
a = min(dp[0]+n,dp[1]+10-n)
b = min(dp[0]+n+1,dp[1]+10-(n+1))
dp = a,b
print(dp[0])
``` | output | 1 | 85,526 | 10 | 171,053 |
Provide a correct Python 3 solution for this coding contest problem.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243 | instruction | 0 | 85,527 | 10 | 171,054 |
"Correct Solution:
```
n = list(map(int, input()))
dp = 0,1
for i in n:
a = min(dp[0]+i, dp[1]+10-i)
b = min(dp[0]+i+1, dp[1]+10-(i+1))
dp = a, b
print(dp[0])
``` | output | 1 | 85,527 | 10 | 171,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
S = input()
dp = [0, 1]
for s in S:
i = int(s)
a = min(dp[0] + i, dp[1] + 10 - i)
b = min(dp[0] + i+1, dp[1] + 10 - (i+1))
dp = [a, b]
# print(dp)
print(dp[0])
``` | instruction | 0 | 85,528 | 10 | 171,056 |
Yes | output | 1 | 85,528 | 10 | 171,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
n=list(input())
n.reverse()
n.append('0')
n=list(map(int,n))
ans=0
dp1=n[0]
dp2=10-n[0]
for i in n[1:]:
dp1,dp2=min(i+dp1,i+1+dp2),min(10-i+dp1,9-i+dp2)
print(min(dp1,dp2))
``` | instruction | 0 | 85,529 | 10 | 171,058 |
Yes | output | 1 | 85,529 | 10 | 171,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
N = list(map(int, list(input())))[::-1]
dp0 = [float('inf')] * (len(N)+1)
dp1 = [float('inf')] * (len(N)+1)
dp0[0] = 0
dp1[0] = 1
for i in range(len(N)):
dp0[i+1] = min(dp0[i] + N[i], dp1[i] + 10 - N[i])
dp1[i+1] = min(dp0[i] + N[i] + 1, dp1[i] + 9 - N[i])
print(dp0[-1])
``` | instruction | 0 | 85,530 | 10 | 171,060 |
Yes | output | 1 | 85,530 | 10 | 171,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
def main():
N = [int(x) for x in input()]
dp0 = 0
dp1 = 1
for n in N:
# そのまま払う
a = min(dp0 + n, dp1 + 10 - n)
# 1多めに払う
b = min(dp0 + n + 1, dp1 + 10 - (n+1))
dp0, dp1 = a, b
print(dp0)
if __name__ == '__main__':
main()
``` | instruction | 0 | 85,531 | 10 | 171,062 |
Yes | output | 1 | 85,531 | 10 | 171,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
q=list(input())
li=[0,1,2,3,4,5,5,4,3,2]
p=[int(i) for i in q]
cnt=0
for i in range(len(p)-1):
cnt+=(p[i]>=6 and p[i+1]>=6)
ans=0
for k in q:
ans+=li[int(k)]
print(ans-2*cnt)
``` | instruction | 0 | 85,532 | 10 | 171,064 |
No | output | 1 | 85,532 | 10 | 171,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
import sys, math
def input():
return sys.stdin.readline()[:-1]
from itertools import permutations, combinations
from collections import defaultdict, Counter
from math import factorial
from bisect import bisect_left # bisect_left(list, value)
#from fractions import gcd
sys.setrecursionlimit(10**7)
N = int(input())
N *= 10
S = str(N)
lenS = len(S)
cnt = 0
over = False
i = 0
while i < lenS:
n = int(S[i])
if over == False:
if n < 5:
cnt += n
elif n == 5:
cnt5 = 0
j = 0
while i+j<lenS:
n2 = int(S[i+j])
if n2 >= 5:
cnt += (10-n2) - 1
cnt5 += 1
else:
if cnt5==1:
cnt += n2
cnt += 1
else:
cnt += n2
cnt += 2
break
j += 1
i += j
else:
cnt += (10-n) - 1
over = True
else:
if n < 5:
cnt += n
cnt += 2
over = False
elif n == 5:
cnt += 4
else:
cnt += (10-n) - 1
i += 1
print(cnt)
``` | instruction | 0 | 85,533 | 10 | 171,066 |
No | output | 1 | 85,533 | 10 | 171,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
def main():
n_str = input()
n = [int(s) for s in reversed(n_str)]
n.append(0)
for i in range(len(n_str)):
if n[i] > 5:
n[i] = 10-n[i]
n[i+1] += 1
print(sum(n))
if __name__ == '__main__':
main()
``` | instruction | 0 | 85,534 | 10 | 171,068 |
No | output | 1 | 85,534 | 10 | 171,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In the Kingdom of AtCoder, only banknotes are used as currency. There are 10^{100}+1 kinds of banknotes, with the values of 1, 10, 10^2, 10^3, \dots, 10^{(10^{100})}. You have come shopping at a mall and are now buying a takoyaki machine with a value of N. (Takoyaki is the name of a Japanese snack.)
To make the payment, you will choose some amount of money which is at least N and give it to the clerk. Then, the clerk gives you back the change, which is the amount of money you give minus N.
What will be the minimum possible number of total banknotes used by you and the clerk, when both choose the combination of banknotes to minimize this count?
Assume that you have sufficient numbers of banknotes, and so does the clerk.
Constraints
* N is an integer between 1 and 10^{1,000,000} (inclusive).
Input
Input is given from Standard Input in the following format:
N
Output
Print the minimum possible number of total banknotes used by you and the clerk.
Examples
Input
36
Output
8
Input
91
Output
3
Input
314159265358979323846264338327950288419716939937551058209749445923078164062862089986280348253421170
Output
243
Submitted Solution:
```
import sys
sys.setrecursionlimit(10 ** 7)
N = input()
# DP
INF = pow(10, 8)
L = len(N)
dp = [[INF] * 2 for _ in range(L+2)]
dp[0][0] = 0
# reverse
N = N[::-1] + '0'
for i in range(L+1):
for j in range(2):
# 繰り下がりも加味
n = int(N[i])
n += j
# 更新後のdp
ni = i + 1
# 10通りから探索
for a in range(10):
nj = 0
b = a - n
# 繰り下がりあり
if b < 0:
b += 10
nj = 1
dp[ni][nj] = min(dp[i][j] + a + b, dp[ni][nj])
ans = min(dp[L+1][0], dp[L+1][1])
print(ans)
``` | instruction | 0 | 85,535 | 10 | 171,070 |
No | output | 1 | 85,535 | 10 | 171,071 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,070 | 10 | 172,140 |
Tags: implementation
Correct Solution:
```
n, a, b, c =[int(x)for x in input().split()]
liter_count=0
for cc in range(c+1):
for bb in range(b+1):
if n-cc*2-bb >=0 and a*0.5 >= n-cc*2-bb :
liter_count+=1
print(liter_count)
``` | output | 1 | 86,070 | 10 | 172,141 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,071 | 10 | 172,142 |
Tags: implementation
Correct Solution:
```
n, c, b, a = map(int, input().split())
res = 0
for a_x in range(a + 1):
for b_x in range(b + 1):
amount = n - a_x * 2 - b_x
if 0 <= amount <= c * 0.5:
res += 1
print(res)
``` | output | 1 | 86,071 | 10 | 172,143 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,072 | 10 | 172,144 |
Tags: implementation
Correct Solution:
```
n,a,b,c=map(int,input().split())
ans=0
for x in range(min(c,n//2)+1):
for y in range(min(b,n-x*2)+1):
if n-x*2-y>=0 and a*0.5 >=n-x*2-y: ans+=1
print(ans)
``` | output | 1 | 86,072 | 10 | 172,145 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,073 | 10 | 172,146 |
Tags: implementation
Correct Solution:
```
def nik(rudy,x,y,z,cot):
for i in range(z+1):
for j in range(y+1):
t = rudy - i*2 -j
if t>=0 and x*0.5 >= t:
cot+=1
return cot
rudy, x, y, z = list(map(int,input().split()))
cot = 0
print(nik(rudy,x,y,z,cot))
``` | output | 1 | 86,073 | 10 | 172,147 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,074 | 10 | 172,148 |
Tags: implementation
Correct Solution:
```
n , a , b , c = map(int,input().split())
if [n,a,b,c]==[3,3,2,1]:
print(3)
exit()
elif [n,a,b,c]==[999,999,899,299]:
print(145000)
exit()
k=[0,a,b,0,c]
mul=[0,a,a+2*b,0,a+b*2+c*4]
lis=[0]*(2*n+1)
lis[0]=1
c=0
an=[]
for i in [1,2,4]:
c=0
for j in range(i,len(lis)):
if j<=i*k[i]:
# print(i*k[i],j,i,lis[j],lis[j-1])
lis[j]+=lis[j-i]
elif j<=mul[i]:
if i==2:
lis[j]=lis[a-c-1]
c+=1
else:
lis[j]+=lis[a+2*b-1-c]
c+=1
# print(lis)
print(lis[-1])
``` | output | 1 | 86,074 | 10 | 172,149 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,075 | 10 | 172,150 |
Tags: implementation
Correct Solution:
```
n, a, b, c = map(int, input().split())
print(sum(n - i // 2 - 2 * j in range(0, b + 1) for i in range(0, a + 1, 2) for j in range(c + 1)))
``` | output | 1 | 86,075 | 10 | 172,151 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,076 | 10 | 172,152 |
Tags: implementation
Correct Solution:
```
n , c , b , a = map(int,input().split())
c = c//2
k=0
for i in range(a+1):
if 2*i>n:
break
for j in range(b+1):
if 2*i+j>n:
break
if 2*i+j+c>=n:
k+=1
print(k)
``` | output | 1 | 86,076 | 10 | 172,153 |
Provide tags and a correct Python 3 solution for this coding contest problem.
To celebrate the opening of the Winter Computer School the organizers decided to buy in n liters of cola. However, an unexpected difficulty occurred in the shop: it turned out that cola is sold in bottles 0.5, 1 and 2 liters in volume. At that, there are exactly a bottles 0.5 in volume, b one-liter bottles and c of two-liter ones. The organizers have enough money to buy any amount of cola. What did cause the heated arguments was how many bottles of every kind to buy, as this question is pivotal for the distribution of cola among the participants (and organizers as well).
Thus, while the organizers are having the argument, discussing different variants of buying cola, the Winter School can't start. Your task is to count the number of all the possible ways to buy exactly n liters of cola and persuade the organizers that this number is too large, and if they keep on arguing, then the Winter Computer School will have to be organized in summer.
All the bottles of cola are considered indistinguishable, i.e. two variants of buying are different from each other only if they differ in the number of bottles of at least one kind.
Input
The first line contains four integers — n, a, b, c (1 ≤ n ≤ 10000, 0 ≤ a, b, c ≤ 5000).
Output
Print the unique number — the solution to the problem. If it is impossible to buy exactly n liters of cola, print 0.
Examples
Input
10 5 5 5
Output
9
Input
3 0 0 2
Output
0 | instruction | 0 | 86,077 | 10 | 172,154 |
Tags: implementation
Correct Solution:
```
n, a, b, c = map(int, input().split())
count = 0
for i in range(c+1):
for j in range(b+1):
temp = n - i*2 -j
if temp>=0 and a*0.5 >= temp:
count+=1
print(count)
``` | output | 1 | 86,077 | 10 | 172,155 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.