message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2). | instruction | 0 | 89,270 | 10 | 178,540 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
n=int(input().strip())
print(len(bin(n))-2)
``` | output | 1 | 89,270 | 10 | 178,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2). | instruction | 0 | 89,271 | 10 | 178,542 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
from math import ceil, log2
print(ceil(log2(int(input()) + 1)))
``` | output | 1 | 89,271 | 10 | 178,543 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2). | instruction | 0 | 89,272 | 10 | 178,544 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
def mp():
return map(int, input().split())
n = int(input())
i = 1
while 2 ** i <= n:
i += 1
print(i)
``` | output | 1 | 89,272 | 10 | 178,545 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2). | instruction | 0 | 89,273 | 10 | 178,546 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
#the idea which i thought first is correct
import math
x=int(input())
ans=math.floor(math.log(x,2))+1
print(ans)
``` | output | 1 | 89,273 | 10 | 178,547 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
import math , sys
def lg(n):
if n is 0:
return 0;
return lg(n//2) + 1
def main():
n = int(input())
print (lg(n))
main()
``` | instruction | 0 | 89,274 | 10 | 178,548 |
Yes | output | 1 | 89,274 | 10 | 178,549 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
import math
t=int(input())
if t==0:
print("0")
if t==1:
print("1")
if t<4 and t!=1 and t!=0:
print("2")
if t>3 and t <8:
print("3")
if t>7:
log2 = int(math.log2(t))
print(log2+1)
``` | instruction | 0 | 89,275 | 10 | 178,550 |
Yes | output | 1 | 89,275 | 10 | 178,551 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
n = int(input())
k = 0
while n // 2 != 0:
n //= 2
k += 1
if n == 1:
k += 1
print(k)
``` | instruction | 0 | 89,276 | 10 | 178,552 |
Yes | output | 1 | 89,276 | 10 | 178,553 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
n = int(input())
i=0
while(n):
i+=1
n = n//2
print(i)
``` | instruction | 0 | 89,277 | 10 | 178,554 |
Yes | output | 1 | 89,277 | 10 | 178,555 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
n=int(input())
s=0;i=1;
while(s<n):
s+=i
i+=1
print(i-1)
``` | instruction | 0 | 89,278 | 10 | 178,556 |
No | output | 1 | 89,278 | 10 | 178,557 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
n=int(input())
s=0
c=0
for i in range(1,n+1):
s+=i
c+=1
if s>=n:
break
print(c)
``` | instruction | 0 | 89,279 | 10 | 178,558 |
No | output | 1 | 89,279 | 10 | 178,559 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
import math
n = int(input())
if int(math.sqrt(8 * n + 1)) * int(math.sqrt(8 * n + 1)) == 8 * n + 1:
print((int)(math.sqrt(8 * n + 1) - 1) // 2)
else:
print(n)
``` | instruction | 0 | 89,280 | 10 | 178,560 |
No | output | 1 | 89,280 | 10 | 178,561 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have n coins, each of the same value of 1.
Distribute them into packets such that any amount x (1 β€ x β€ n) can be formed using some (possibly one or all) number of these packets.
Each packet may only be used entirely or not used at all. No packet may be used more than once in the formation of the single x, however it may be reused for the formation of other x's.
Find the minimum number of packets in such a distribution.
Input
The only line contains a single integer n (1 β€ n β€ 10^9) β the number of coins you have.
Output
Output a single integer β the minimum possible number of packets, satisfying the condition above.
Examples
Input
6
Output
3
Input
2
Output
2
Note
In the first example, three packets with 1, 2 and 3 coins can be made to get any amount x (1β€ xβ€ 6).
* To get 1 use the packet with 1 coin.
* To get 2 use the packet with 2 coins.
* To get 3 use the packet with 3 coins.
* To get 4 use packets with 1 and 3 coins.
* To get 5 use packets with 2 and 3 coins
* To get 6 use all packets.
In the second example, two packets with 1 and 1 coins can be made to get any amount x (1β€ xβ€ 2).
Submitted Solution:
```
n=int(input())
f=0
for i in range(1,n+1):
if(i*(i+1)==2*n):
print(i)
break
if(i*(i+1)>2*n):
f=1
break
if(f==1):
print(n)
``` | instruction | 0 | 89,281 | 10 | 178,562 |
No | output | 1 | 89,281 | 10 | 178,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,603 | 10 | 179,206 |
Tags: brute force, greedy, math
Correct Solution:
```
n, l, r, ql, qr = map(int, input().split())
w = [0] + list(map(int, input().split()))
for i in range(1, n + 1):
w[i] += w[i - 1]
s = w[n]
print(min(l * w[i] + r * (s - w[i]) + ql * max(0, 2 * i - n - 1) + qr * max(0, n - 2 * i - 1) for i in range(n + 1)))
``` | output | 1 | 89,603 | 10 | 179,207 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,604 | 10 | 179,208 |
Tags: brute force, greedy, math
Correct Solution:
```
from __future__ import division, print_function
import os
import sys
from io import BytesIO, IOBase
from math import inf
def main():
n, l, r, ql, qr = [ int(x) for x in input().split() ]
weight = [ int(x) for x in input().split() ]
preffix = [0] * n
preffix[0] = weight[0]
for i in range(1, n):
preffix[i] = preffix[i-1] + weight[i]
suffix = [0] * n
suffix[n-1] = weight[n-1]
for i in range(n - 2, -1, -1):
suffix[i] = weight[i] + suffix[i+1]
bestAnswer = inf
for i in range(-1, n):
leftToRemove = i + 1
rightToRemove = n - leftToRemove
if leftToRemove > rightToRemove:
numOfNotCanceled = max(leftToRemove - rightToRemove - 1, 0)
total = (
(preffix[i] if i >= 0 else 0) * l
+ (suffix[i+1] if i < n - 1 else 0) * r
+ numOfNotCanceled * ql
)
else:
numOfNotCanceled = max(rightToRemove - leftToRemove - 1, 0)
total = (
(preffix[i] if i >= 0 else 0) * l
+ (suffix[i+1] if i < n - 1 else 0) * r
+ numOfNotCanceled * qr
)
bestAnswer = min(bestAnswer, total)
print(bestAnswer)
BUFFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
input = lambda: sys.stdin.readline().rstrip("\r\n")
def print(*args, **kwargs):
sep = kwargs.pop("sep", " ")
file = kwargs.pop("file", sys.stdout)
atStart = True
for x in args:
if not atStart:
file.write(sep)
file.write(str(x))
atStart = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
main()
``` | output | 1 | 89,604 | 10 | 179,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,605 | 10 | 179,210 |
Tags: brute force, greedy, math
Correct Solution:
```
def solve(lst, l, r, left, right):
left_sum = [0]
right_sum = [0] * (len(lst) + 1)
cum_sum = 0
for i in range(len(lst)):
cum_sum += lst[i]
left_sum.append(cum_sum)
cum_sum = 0
for i in reversed(range(len(lst))):
cum_sum += lst[i]
right_sum[i] = cum_sum
#print(lst, left_sum, right_sum)
min_cost = float('inf')
for i in range(len(lst)+1):
cost = left_sum[i] * l + right_sum[i]*r
#print(i, cost, left_sum[i],l, right_sum[i], r)
if i > n-i:
cost += left * (2*i -n -1)
elif i < n - i:
cost += right *(n - 1- 2*i)
#print(cost)
min_cost = min(min_cost, cost)
return min_cost
n, l, r, left, right = list(map(int, input().split()))
lst = list(map(int, input().split()))
print(solve(lst, l, r, left, right))
``` | output | 1 | 89,605 | 10 | 179,211 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,606 | 10 | 179,212 |
Tags: brute force, greedy, math
Correct Solution:
```
import sys
from os import path
if(path.exists('input.txt')):
sys.stdin = open("input.txt", "r")
sys.stdout = open("output.txt", "w")
N = 10**5 + 5
n, l, r, q1, q2 = map(int, input().split())
w = [int(x) for x in input().split()]
pre = [0] * N
for i in range(n):
pre[i + 1] = pre[i] + w[i]
ans = 10**18
for i in range(n + 1):
curr = pre[i] * l + (pre[n] - pre[i]) * r
x, y = i, n - i
if(x < y):
curr += q2 * (y - x - 1)
elif(x > y):
curr += q1 * (x - y - 1)
ans = min(ans, curr)
print(ans)
``` | output | 1 | 89,606 | 10 | 179,213 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,607 | 10 | 179,214 |
Tags: brute force, greedy, math
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
M=998244353
EPS=1e-6
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
n,l,r,ql,qr=value()
w=array()
ans=inf
tot=sum(w)
cur=w[0]
for i in range(1,n):
tans=cur*l+(tot-cur)*r
lefts=i
rights=n-i
if(lefts>rights+1):
extra=lefts-rights-1
tans+=extra*ql
if(rights>lefts+1):
extra=rights-lefts-1
tans+=extra*qr
# print(tans,lefts,rights)
ans=min(ans,tans)
cur+=w[i]
ans=min(ans,tot*l+n*ql-ql,tot*r+n*qr-qr)
print(ans)
``` | output | 1 | 89,607 | 10 | 179,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,608 | 10 | 179,216 |
Tags: brute force, greedy, math
Correct Solution:
```
n, l, r, ql, qr = list(map(int, input().split()))
w = list(map(int, input().split()))
sum = 0
sums = []
for i in range(n):
sum += w[i]
sums.append(sum)
min = r * sum + qr * (n - 1)
for i in range(n):
ss = l * sums[i] + r * (sum - sums[i])
if i + 1 > n - i - 1 and i - n + i + 1 > 0:
ss += ql * (i - n + i + 1)
elif i + 1 < n - i - 1 and n - i - 2 - i > 1:
ss += qr * (n - i - 2 - i - 1)
if ss < min:
min = ss
print(min)
``` | output | 1 | 89,608 | 10 | 179,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,609 | 10 | 179,218 |
Tags: brute force, greedy, math
Correct Solution:
```
n, l, r, Ql, Qr = map(int, input().split())
s, v = [0] * (n + 1), 2 * 10 ** 9
for i, wi in enumerate(map(int, input().split())):
s[i + 1] = s[i] + wi
for lc in range(0, n + 1):
rc = n - lc
c = s[lc] * l + (s[n] - s[lc]) * r
if lc > rc + 1:
c += (lc - rc - 1) * Ql
elif rc > lc + 1:
c += (rc - lc - 1) * Qr
v = min(v, c)
print(v)
``` | output | 1 | 89,609 | 10 | 179,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units. | instruction | 0 | 89,610 | 10 | 179,220 |
Tags: brute force, greedy, math
Correct Solution:
```
n,l,r,ql,qr=map(int,input().split())
arr=[int(i) for i in input().split()]
#brute force is the mother of all approaches
mini=10**20
sm=sum(arr)
appaji=0
curr=0
for i in range(n+1):
if i>0:
curr+=arr[i-1]
now=curr*l+(sm-curr)*r
j=n-i
if i>j:
now+=(i-j-1)*ql # appaji 1
if j>i:
now+=(j-i-1)*qr #appaji 2
mini=min(mini,now)
print(mini)
``` | output | 1 | 89,610 | 10 | 179,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
#!/usr/bin/python3
import sys
n, l, r, ql, qr = map(int, sys.stdin.readline().strip().split())
w = [int(x) for x in sys.stdin.readline().strip().split()]
s = [0]
for i in range(0, n):
s.append(s[-1] + w[i])
def cost(left):
right = n - left
diff = left - right
bonus = 0
if diff > 0: # left part is larger
bonus = ql * (diff - 1)
elif diff < 0: # right part is larger
bonus = qr * (-diff - 1)
return bonus + l * s[left] + r * (s[n] - s[left])
best = cost(0)
for left in range(1, n+1):
c = cost(left)
if c < best:
best = c
print(best)
``` | instruction | 0 | 89,611 | 10 | 179,222 |
Yes | output | 1 | 89,611 | 10 | 179,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
n, l, r, p, q = map(int, input().split())
arr = list(map(int, input().split()))
res, s, d = int(1<<62), sum(arr), 0
for i in range(n+1):
if i > 0:
d += arr[i-1]
t = d * l + (s - d) * r
j = n - i
if i > j:
t += (i - j - 1) * p
if i < j:
t += (j - i - 1) * q
res = min(res, t)
print(res)
``` | instruction | 0 | 89,612 | 10 | 179,224 |
Yes | output | 1 | 89,612 | 10 | 179,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
import sys
from math import log2,floor,ceil,sqrt
# import bisect
# from collections import deque
Ri = lambda : [int(x) for x in sys.stdin.readline().split()]
ri = lambda : sys.stdin.readline().strip()
def input(): return sys.stdin.readline().strip()
def list2d(a, b, c): return [[c] * b for i in range(a)]
def list3d(a, b, c, d): return [[[d] * c for j in range(b)] for i in range(a)]
def list4d(a, b, c, d, e): return [[[[e] * d for j in range(c)] for j in range(b)] for i in range(a)]
def ceil(x, y=1): return int(-(-x // y))
def INT(): return int(input())
def MAP(): return map(int, input().split())
def LIST(N=None): return list(MAP()) if N is None else [INT() for i in range(N)]
def Yes(): print('Yes')
def No(): print('No')
def YES(): print('YES')
def NO(): print('NO')
INF = 10 ** 18
MOD = 10**9+7
n,l,r,ql,qr = Ri()
a = Ri()
lsumm = [0]*(n+1)
rsumm = [0]*(n+1)
ite= 1
for i in range(0,n):
lsumm[i+1] = lsumm[i]+a[i]
for i in range(n-1,-1,-1):
rsumm[ite] = rsumm[ite-1]+a[i]
ite+=1
# print(lsumm,rsumm)
tans = INF
for i in range(0,n+1):
ans = lsumm[i]*l+rsumm[n-i]*r
if i < n-i : ans+=(n-i-i-1)*qr
elif i > n-i : ans+=(i-(n-i)-1)*ql
tans = min(tans,ans)
print(tans)
``` | instruction | 0 | 89,613 | 10 | 179,226 |
Yes | output | 1 | 89,613 | 10 | 179,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
n, l, r, Ql, Qr = [int(x) for x in input().split(' ')]
w = [int(x) for x in input().split(' ')];
sum = [0 for x in range(n+1)];
for i in range(1, n+1):
sum[i] = sum[i-1] + w[i-1];
ans = 2**32;
for k in range(0, n+1):
temp = sum[k]*l + (sum[n] - sum[k])*r;
if (2*k > n):
temp += (2*k-n-1)*Ql;
elif (2*k < n):
temp += (n-2*k-1)*Qr;
ans = min(ans, temp);
print(ans);
``` | instruction | 0 | 89,614 | 10 | 179,228 |
Yes | output | 1 | 89,614 | 10 | 179,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
from __future__ import division, print_function
import os
import sys
from io import BytesIO, IOBase
from math import inf
def main():
n, l, r, ql, qr = [ int(x) for x in input().split() ]
weight = [ int(x) for x in input().split() ]
preffix = [0] * n
preffix[0] = weight[0]
for i in range(1, n):
preffix[i] = preffix[i-1] + weight[i]
suffix = [0] * n
suffix[n-1] = weight[n-1]
for i in range(n - 2, -1, -1):
suffix[i] = weight[i] + suffix[i+1]
bestAnswer = inf
for i in range(n):
leftToRemove = i + 1
rightToRemove = n - leftToRemove
if leftToRemove > rightToRemove:
numOfNotCanceled = max(leftToRemove - rightToRemove - 1, 0)
total = (
preffix[i] * l
+ (suffix[i+1] if i < n - 1 else 0) * r
+ numOfNotCanceled * ql
)
else:
numOfNotCanceled = max(rightToRemove - leftToRemove - 1, 0)
total = (
preffix[i] * l
+ (suffix[i+1] if i < n - 1 else 0) * r
+ numOfNotCanceled * qr
)
bestAnswer = min(bestAnswer, total)
print(bestAnswer)
BUFFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
input = lambda: sys.stdin.readline().rstrip("\r\n")
def print(*args, **kwargs):
sep = kwargs.pop("sep", " ")
file = kwargs.pop("file", sys.stdout)
atStart = True
for x in args:
if not atStart:
file.write(sep)
file.write(str(x))
atStart = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
main()
``` | instruction | 0 | 89,615 | 10 | 179,230 |
No | output | 1 | 89,615 | 10 | 179,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
n, l, r, q1, q2 = map(int, input().split())
item = list(map(int, input().split()))
pre = [item[0]] + [ 0 for i in range(1, n)]
suf = [ 0 for i in range(0, n-1)] + [item[n-1], 0]
for i in range(1, n): pre[i] = pre[i-1] + item[i]
for i in range(n-2, -1, -1): suf[i] = suf[i+1] + item[i]
# print(pre, suf)
ans = 1e20
for i in range(0, n):
a, b = i, n-i
c = pre[i]*l + suf[i+1]*r + (q2*(a-b-1) if a>b else q1*(b-a-1) if b>a else 0)
# print(c)
ans = min(ans, c)
print(ans)
``` | instruction | 0 | 89,616 | 10 | 179,232 |
No | output | 1 | 89,616 | 10 | 179,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
n, l, r, q1, q2 = map(int, input().split())
item = list(map(int, input().split()))
pre = [item[0]] + [ 0 for i in range(1, n)]
suf = [ 0 for i in range(0, n-1)] + [item[n-1], 0]
for i in range(1, n): pre[i] = pre[i-1] + item[i]
for i in range(n-2, -1, -1): suf[i] = suf[i+1] + item[i]
print(q1, q2)
# print(pre, suf)
ans = 1e20
for i in range(0, n):
a, b = i+1, n-i-1
c = pre[i]*l + suf[i+1]*r + (q1*(a-b-1) if a>b else q2*(b-a-1) if b>a else 0)
# print(c)
ans = min(ans, c)
print(ans)
``` | instruction | 0 | 89,617 | 10 | 179,234 |
No | output | 1 | 89,617 | 10 | 179,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has n items lying in a line. The items are consecutively numbered by numbers from 1 to n in such a way that the leftmost item has number 1, the rightmost item has number n. Each item has a weight, the i-th item weights wi kilograms.
Vasya needs to collect all these items, however he won't do it by himself. He uses his brand new robot. The robot has two different arms β the left one and the right one. The robot can consecutively perform the following actions:
1. Take the leftmost item with the left hand and spend wi Β· l energy units (wi is a weight of the leftmost item, l is some parameter). If the previous action was the same (left-hand), then the robot spends extra Ql energy units;
2. Take the rightmost item with the right hand and spend wj Β· r energy units (wj is a weight of the rightmost item, r is some parameter). If the previous action was the same (right-hand), then the robot spends extra Qr energy units;
Naturally, Vasya wants to program the robot in a way that the robot spends as little energy as possible. He asked you to solve this problem. Your task is to find the minimum number of energy units robot spends to collect all items.
Input
The first line contains five integers n, l, r, Ql, Qr (1 β€ n β€ 105; 1 β€ l, r β€ 100; 1 β€ Ql, Qr β€ 104).
The second line contains n integers w1, w2, ..., wn (1 β€ wi β€ 100).
Output
In the single line print a single number β the answer to the problem.
Examples
Input
3 4 4 19 1
42 3 99
Output
576
Input
4 7 2 3 9
1 2 3 4
Output
34
Note
Consider the first sample. As l = r, we can take an item in turns: first from the left side, then from the right one and last item from the left. In total the robot spends 4Β·42 + 4Β·99 + 4Β·3 = 576 energy units.
The second sample. The optimal solution is to take one item from the right, then one item from the left and two items from the right. In total the robot spends (2Β·4) + (7Β·1) + (2Β·3) + (2Β·2 + 9) = 34 energy units.
Submitted Solution:
```
import sys
def get_ints(): return list(map(int, sys.stdin.readline().strip().split()))
arr = get_ints()
n = arr[0]
l = arr[1]
r = arr[2]
ql = arr[3]
qr = arr[4]
arr = get_ints()
arr = sorted(arr)
if l == r :
sums = l*sum(arr)
print(sums)
elif l < r :
#print(arr)
rightindex = len(arr) - 1
leftindex = 0
ans = 0
flag = 0
while leftindex <= rightindex:
if flag == 0:
ans += arr[rightindex] * l
flag = 1
rightindex -= 1
elif flag == 1 :
if arr[leftindex] * r <= arr[leftindex] * l + ql:
flag = 0
ans += arr[leftindex] * r
leftindex += 1
else:
ans += arr[leftindex] * l + ql
leftindex += 1
print(ans)
else:
rightindex = len(arr) - 1
leftindex = 0
ans = 0
flag = 0
while leftindex <= rightindex:
if flag == 0:
ans += arr[rightindex] * r
flag = 1
rightindex -= 1
elif flag == 1 :
if arr[leftindex] * l <= arr[leftindex] * r + qr:
flag = 0
ans += arr[leftindex] * l
leftindex += 1
else:
ans += arr[leftindex] * r + qr
leftindex += 1
print(ans)
``` | instruction | 0 | 89,618 | 10 | 179,236 |
No | output | 1 | 89,618 | 10 | 179,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are N jewelry shops numbered 1 to N.
Shop i (1 \leq i \leq N) sells K_i kinds of jewels. The j-th of these jewels (1 \leq j \leq K_i) has a size and price of S_{i,j} and P_{i,j}, respectively, and the shop has C_{i,j} jewels of this kind in stock.
A jewelry box is said to be good if it satisfies all of the following conditions:
* For each of the jewelry shops, the box contains one jewel purchased there.
* All of the following M restrictions are met.
* Restriction i (1 \leq i \leq M): (The size of the jewel purchased at Shop V_i)\leq (The size of the jewel purchased at Shop U_i)+W_i
Answer Q questions. In the i-th question, given an integer A_i, find the minimum total price of jewels that need to be purchased to make A_i good jewelry boxes. If it is impossible to make A_i good jewelry boxes, report that fact.
Constraints
* 1 \leq N \leq 30
* 1 \leq K_i \leq 30
* 1 \leq S_{i,j} \leq 10^9
* 1 \leq P_{i,j} \leq 30
* 1 \leq C_{i,j} \leq 10^{12}
* 0 \leq M \leq 50
* 1 \leq U_i,V_i \leq N
* U_i \neq V_i
* 0 \leq W_i \leq 10^9
* 1 \leq Q \leq 10^5
* 1 \leq A_i \leq 3 \times 10^{13}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
Description of Shop 1
Description of Shop 2
\vdots
Description of Shop N
M
U_1 V_1 W_1
U_2 V_2 W_2
\vdots
U_M V_M W_M
Q
A_1
A_2
\vdots
A_Q
The description of Shop i (1 \leq i \leq N) is in the following format:
K_i
S_{i,1} P_{i,1} C_{i,1}
S_{i,2} P_{i,2} C_{i,2}
\vdots
S_{i,K_i} P_{i,K_i} C_{i,K_i}
Output
Print Q lines. The i-th line should contain the minimum total price of jewels that need to be purchased to make A_i good jewelry boxes, or -1 if it is impossible to make them.
Examples
Input
3
2
1 10 1
3 1 1
3
1 10 1
2 1 1
3 10 1
2
1 1 1
3 10 1
2
1 2 0
2 3 0
3
1
2
3
Output
3
42
-1
Input
5
5
86849520 30 272477201869
968023357 28 539131386006
478355090 8 194500792721
298572419 6 894877901270
203794105 25 594579473837
5
730211794 22 225797976416
842538552 9 420531931830
871332982 26 81253086754
553846923 29 89734736118
731788040 13 241088716205
5
903534485 22 140045153776
187101906 8 145639722124
513502442 9 227445343895
499446330 6 719254728400
564106748 20 333423097859
5
332809289 8 640911722470
969492694 21 937931959818
207959501 11 217019915462
726936503 12 382527525674
887971218 17 552919286358
5
444983655 13 487875689585
855863581 6 625608576077
885012925 10 105520979776
980933856 1 711474069172
653022356 19 977887412815
10
1 2 231274893
2 3 829836076
3 4 745221482
4 5 935448462
5 1 819308546
3 5 815839350
5 3 513188748
3 1 968283437
2 3 202352515
4 3 292999238
10
510266667947
252899314976
510266667948
374155726828
628866122125
628866122123
1
628866122124
510266667949
30000000000000
Output
26533866733244
13150764378752
26533866733296
19456097795056
-1
33175436167096
52
33175436167152
26533866733352
-1
Submitted Solution:
```
import math
print(math.floor(1.1421))
#1
print(math.floor(1.7320))
#1
print(math.floor(1.5))
#1
print(math.floor(2.5))
#2
print(math.floor(3.5))
#3
``` | instruction | 0 | 89,896 | 10 | 179,792 |
No | output | 1 | 89,896 | 10 | 179,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,098 | 10 | 180,196 |
Tags: math
Correct Solution:
```
"""
def Find(naj, mesto, dl):
if naj >= 2:
dl += 1
Find(naj-2, mesto, dl)
if naj >= 3:
dl += 1
Find(naj-3, mesto, dl)
if naj >= 4 and len(mesto) == 4:
dl += 1
Find(naj-4, mesto, dl)
dl += 1
Find(naj-4, mesto, dl)
global perem, kolvo
if str(dl) in perem:
kolvo[perem.index(str(dl))] += 1
else:
perem.append(str(dl))
kolvo.append(1)
dlina = int(input())
sms = str(input())
KLAVA = ['ABC', 'DEF', 'GHI', 'JKL', 'MNO', 'PQRS', 'TUV', 'WXYZ']
najatiya = []
for i in sms:
for f in range(len(KLAVA)):
if i in KLAVA[f]:
kek = KLAVA[f].index(i)+1
if KLAVA[f].index(i)+1 <= 3:
kek += 1
najatiya.append([kek, KLAVA[f]])
#print(najatiya)
k = []
k.append(najatiya[0])
for i in range(1, len(najatiya)):
if najatiya[i][1] == k[len(k)-1][1]:
k[len(k)-1][0]+=najatiya[i][0]
else:
k.append(najatiya[i])
print(k)
gotovo = []
for i in range(len(k)):
perem = []
kolvo = []
Find(k[i][0], k[i][1], 0)
gotovo.append([perem, kolvo])
#ΠΠ°Ρ Π΅ΠΌΡ ΠΊΠΎΠ»-Π²ΠΎ Π½Π°ΠΆΠ°ΡΠΈΠΉ ΠΈ ΠΊΠ½ΠΎΠΏΠΊΡ Π½Π°ΠΆΠ°ΡΠΈΡ,
#Π·Π°ΠΏΠΈΡΡΠ²Π°Ρ Π΄Π»ΠΈΠ½Ρ ΡΠΎΠΎΠ±ΡΠ΅Π½ΠΈΡ,
#Π·Π°ΠΏΠΈΡΡΠ²Π°Ρ Π² ΠΌΠ°ΡΡΠΈΠ² Π΄Π»ΠΈΠ½Ρ ΡΠΎΠΎΠ±ΡΠ΅Π½ΠΈΠΉ,
#Π½Π°Π±ΡΠ°Π½Π½ΡΡ
Π½Π° ΠΎΠ΄Π½ΠΎΠΉ ΠΊΠ½ΠΎΠΏΠΊΠ΅ ΠΈ ΠΊΠΎΠ»ΠΈΡΠ΅ΡΡΠ²ΠΎ
#ΠΎΠ΄ΠΈΠ½Π°ΠΊΠΎΠ²ΡΡ
Π΄Π»ΠΈΠ½
#ΡΠ΅ΡΠ°Ρ Π·Π°Π΄Π°ΡΡ ΡΠΈΡΡΡ ΠΏΡΠΎΡ
ΠΎΠ΄Ρ ΠΏΠΎ ΠΌΠ°ΡΡΠΈΠ²Ρ Π΄Π»ΠΈΠ½
#ΡΠΎΠ±ΠΈΡΠ°Ρ ΠΊΠΎΠ»ΠΈΡΠ΅ΡΡΠ²ΠΎ Π²ΠΎΠ·ΠΌΠΎΠΆΠ½ΡΡ
ΠΊΠΎΠΌΠ±ΠΈΠ½Π°ΡΠΈΠΉ
#Π²ΡΠ²ΠΎΠΆΡ
print(gotovo)
def NaytiChisla(stroka):
kek = ""
chislo = []
koef = 1
for i in range(len(stroka)):
if stroka[i] == '-':
koef = -1
if stroka[i] == '0' or stroka[i] == '1' or stroka[i] == '2' or stroka[i] == '3' or stroka[i] == '4' or stroka[i] == '5' or stroka[i] == '6' or stroka[i] == '7' or stroka[i] == '8' or stroka[i] == '9':
kek+=stroka[i]
if stroka[i] == ' ':
chislo.append(int(kek)*koef)
koef = 1
kek = ""
chislo.append(int(kek)*koef)
koef = 1
return chislo
su = int(input())
coins = NaytiChisla(str(input()))
su = int(input())
min = 10000000
mass = []
mass.append(0)
for i in range(su):
lol = []
for f in coins:
if len(mass)-f-1 > 0 and len(mass)-f < len(mass)-1:
lol.append(mass[len(mass)-f-1])
try:
kek = sorted(lol)[0]
except:
kek = 1000000
mass.append(kek)
print(mass)
"""
def Kek():
n, m = map(int, input().split())
if n > m:
i = 1
f = m-1
#print(f, i, f-i)
print(int((f-i+1)/2))
else:
if m <= 2*n:
i = m-n
f = n
if i == 0:
i = 2
#print(f, i, f - i)
print(int((f-i+1)/2))
else:
print(0)
return
return
Kek()
``` | output | 1 | 90,098 | 10 | 180,197 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,099 | 10 | 180,198 |
Tags: math
Correct Solution:
```
n,k=map(int,input().split())
print(max(min(n-k//2,(k-1)//2),0))
``` | output | 1 | 90,099 | 10 | 180,199 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,100 | 10 | 180,200 |
Tags: math
Correct Solution:
```
n,k = map(int,input().split())
if k<=n:
if k%2==1:
print(k//2)
else:
print(k//2-1)
else:
if k>n*2:
print(0)
else:
print(n-k//2)
``` | output | 1 | 90,100 | 10 | 180,201 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,101 | 10 | 180,202 |
Tags: math
Correct Solution:
```
print((lambda n, k: max(0, min(n, k - 1) - k // 2))(*map(int, input().split())))
``` | output | 1 | 90,101 | 10 | 180,203 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,102 | 10 | 180,204 |
Tags: math
Correct Solution:
```
n, k = map(int, input().split())
if n == 1:
print(0)
exit(0)
if k > n:
if k > 2*n-1:
print(0)
exit(0)
one = n
other = k - n
else:
one = k-1
other = 1
posib = (one - other)
print(((posib +1) // 2))
``` | output | 1 | 90,102 | 10 | 180,205 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,103 | 10 | 180,206 |
Tags: math
Correct Solution:
```
import math
n, k = map(int, input().split())
maxPairs = float(k/2)
if n == 1:
print(0)
elif n < k:
print(max(0, math.ceil(n - maxPairs)))
else:
if k % 2 == 1:
print(math.floor(k/2))
else:
print(int(k/2-1))
``` | output | 1 | 90,103 | 10 | 180,207 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,104 | 10 | 180,208 |
Tags: math
Correct Solution:
```
n, k = map(int, input().split())
if k < 3 or k > 2 * n - 1:
print(0)
else:
if k % 2:
mini = k // 2
maxi = mini + 1
else:
mini = k // 2 - 1
maxi = mini + 2
print(min(mini, (n - maxi + 1)))
``` | output | 1 | 90,104 | 10 | 180,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000. | instruction | 0 | 90,105 | 10 | 180,210 |
Tags: math
Correct Solution:
```
n, k = map(int, input().split())
if k>n:
print(max(0, n - k//2))
else:
print(k//2 + (k&1) - 1)
``` | output | 1 | 90,105 | 10 | 180,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n, k = map(int, input().split())
if n >= k - 1:
print((k - 1) // 2)
else:
print(max(0, (2*n - k - 1) // 2 + 1))
``` | instruction | 0 | 90,106 | 10 | 180,212 |
Yes | output | 1 | 90,106 | 10 | 180,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n,k = input().split()
n = int(n)
k = int(k)
c =0
if k <= n:
c = k-1
elif k <= 2*n: c= 2*n-k+1
print(int(c/2))
``` | instruction | 0 | 90,107 | 10 | 180,214 |
Yes | output | 1 | 90,107 | 10 | 180,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n, k = map(int, input().split())
if k % 2:
a, b = k // 2, k // 2 + 1
else:
a, b = k // 2 - 1, k // 2 + 1
if 2 * n - 1 < k:
print(0)
else:
print(min(a - 1, n - b) + 1)
``` | instruction | 0 | 90,108 | 10 | 180,216 |
Yes | output | 1 | 90,108 | 10 | 180,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
from math import ceil
n,k = list(map(int,input().split()))
if k<=n:
if k&1:
print(k//2)
else:
print((k-1)//2)
else:
if 2*n-k-1<0:
print(0)
else:
print(((2*n-k-1)//2)+1)
``` | instruction | 0 | 90,109 | 10 | 180,218 |
Yes | output | 1 | 90,109 | 10 | 180,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n,k=[int(x) for x in input().split()]
if k>2*n or n==1:
print(0)
elif k<=2*n and k>n:
if (2*n-k)%2==0:
print((2*n-k)//2)
else:
print((2*n-k)//2+1)
else:
print(k//2)
``` | instruction | 0 | 90,110 | 10 | 180,220 |
No | output | 1 | 90,110 | 10 | 180,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
import sys
import math
import collections
import heapq
input=sys.stdin.readline
n,k=(int(i) for i in input().split())
if(2*n-1<k):
print(0)
else:
if(k>n):
k1=k-n
if(n-k1==2):
if(k%2==0):
print(math.ceil((n/2)-1))
else:
print(math.ceil(n/2))
else:
if(k%2==0):
print(math.ceil((n-k1)/2)-1)
else:
print(math.ceil((n-k1)/2))
elif(k<=n):
if(k%2==0):
print(math.ceil((k-1)/2)-1)
else:
print(math.ceil((k-1)/2))
``` | instruction | 0 | 90,111 | 10 | 180,222 |
No | output | 1 | 90,111 | 10 | 180,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n, k = map(int, input().split())
if n < k:
print((n - (k-n-1))//2)
elif n >= k:
print((k-1)//2)
``` | instruction | 0 | 90,112 | 10 | 180,224 |
No | output | 1 | 90,112 | 10 | 180,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tanechka is shopping in the toy shop. There are exactly n toys in the shop for sale, the cost of the i-th toy is i burles. She wants to choose two toys in such a way that their total cost is k burles. How many ways to do that does she have?
Each toy appears in the shop exactly once. Pairs (a, b) and (b, a) are considered equal. Pairs (a, b), where a=b, are not allowed.
Input
The first line of the input contains two integers n, k (1 β€ n, k β€ 10^{14}) β the number of toys and the expected total cost of the pair of toys.
Output
Print the number of ways to choose the pair of toys satisfying the condition above. Print 0, if Tanechka can choose no pair of toys in such a way that their total cost is k burles.
Examples
Input
8 5
Output
2
Input
8 15
Output
1
Input
7 20
Output
0
Input
1000000000000 1000000000001
Output
500000000000
Note
In the first example Tanechka can choose the pair of toys (1, 4) or the pair of toys (2, 3).
In the second example Tanechka can choose only the pair of toys (7, 8).
In the third example choosing any pair of toys will lead to the total cost less than 20. So the answer is 0.
In the fourth example she can choose the following pairs: (1, 1000000000000), (2, 999999999999), (3, 999999999998), ..., (500000000000, 500000000001). The number of such pairs is exactly 500000000000.
Submitted Solution:
```
n, k = map(int, input().split())
if n >= k:
print(k // 2)
else:
if n + n - 1 < k:
print(0)
else:
print((n - (k - n) + 1) // 2)
``` | instruction | 0 | 90,113 | 10 | 180,226 |
No | output | 1 | 90,113 | 10 | 180,227 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.
Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills β 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.
Help him β write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.
Input
The first line of the input contains one integer n (1 β€ n β€ 10^8) β the initial sum in rubles Andrew has.
The second line of the input contains one integer d (30 β€ d β€ 100) β the price of one dollar in rubles.
The third line of the input contains integer e (30 β€ e β€ 100) β the price of one euro in rubles.
Output
Output one integer β the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.
Examples
Input
100
60
70
Output
40
Input
410
55
70
Output
5
Input
600
60
70
Output
0
Note
In the first example, we can buy just 1 dollar because there is no 1 euro bill.
In the second example, optimal exchange is to buy 5 euro and 1 dollar.
In the third example, optimal exchange is to buy 10 dollars in one bill. | instruction | 0 | 90,210 | 10 | 180,420 |
Tags: brute force, math
Correct Solution:
```
r = int(input())
d = int(input())
e = int(input())
minm = r
i = 0
j = 0
while r - i*5*e >= 0 and minm != 0:
if (r - i*5*e)%d < minm:
minm = (r - i*5*e)%d
i += 1
print(minm)
``` | output | 1 | 90,210 | 10 | 180,421 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.
Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills β 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.
Help him β write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.
Input
The first line of the input contains one integer n (1 β€ n β€ 10^8) β the initial sum in rubles Andrew has.
The second line of the input contains one integer d (30 β€ d β€ 100) β the price of one dollar in rubles.
The third line of the input contains integer e (30 β€ e β€ 100) β the price of one euro in rubles.
Output
Output one integer β the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.
Examples
Input
100
60
70
Output
40
Input
410
55
70
Output
5
Input
600
60
70
Output
0
Note
In the first example, we can buy just 1 dollar because there is no 1 euro bill.
In the second example, optimal exchange is to buy 5 euro and 1 dollar.
In the third example, optimal exchange is to buy 10 dollars in one bill. | instruction | 0 | 90,211 | 10 | 180,422 |
Tags: brute force, math
Correct Solution:
```
n = int(input())
d = int(input())
e = int(input())
m = n
take_away = 0
while m - 5 * e >= 0:
m -= 5 * e
take_away += 1
# print(m)
m %= d
minimum = m
while take_away != 0:
m += 5 * e
minimum = min(minimum, m % d)
take_away -= 1
print(minimum)
``` | output | 1 | 90,211 | 10 | 180,423 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.
Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills β 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.
Help him β write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.
Input
The first line of the input contains one integer n (1 β€ n β€ 10^8) β the initial sum in rubles Andrew has.
The second line of the input contains one integer d (30 β€ d β€ 100) β the price of one dollar in rubles.
The third line of the input contains integer e (30 β€ e β€ 100) β the price of one euro in rubles.
Output
Output one integer β the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.
Examples
Input
100
60
70
Output
40
Input
410
55
70
Output
5
Input
600
60
70
Output
0
Note
In the first example, we can buy just 1 dollar because there is no 1 euro bill.
In the second example, optimal exchange is to buy 5 euro and 1 dollar.
In the third example, optimal exchange is to buy 10 dollars in one bill. | instruction | 0 | 90,212 | 10 | 180,424 |
Tags: brute force, math
Correct Solution:
```
from math import *
from collections import deque
from copy import deepcopy
import sys
def inp(): return sys.stdin.readline().rstrip("\r\n") #for fast input
def multi(): return map(int,input().split())
def strmulti(): return map(str, inp().split())
def lis(): return list(map(int, inp().split()))
def lcm(a,b): return (a*b)//gcd(a,b)
def ncr(n,r): return factorial(n) // (factorial(r) * factorial(max(n - r, 1)))
def stringlis(): return list(map(str, inp().split()))
def out(var): sys.stdout.write(str(var)) #for fast output, always take string
def printlist(a) :
print(' '.join(str(a[i]) for i in range(len(a))))
def isPrime(n) :
if (n <= 1) : return False
if (n <= 3) : return True
if (n % 2 == 0 or n % 3 == 0) : return False
i = 5
while(i * i <= n) :
if (n % i == 0 or n % (i + 2) == 0) :
return False
i = i + 6
return True
#copied functions end
#start coding
n=int(inp())
d=int(inp())
e=int(inp())
ans=n
i=0
while(e*5*i<=n):
ans=min(ans,(n-i*5*e)%d)
i+=1
print(ans)
``` | output | 1 | 90,212 | 10 | 180,425 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.
Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills β 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.
Help him β write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.
Input
The first line of the input contains one integer n (1 β€ n β€ 10^8) β the initial sum in rubles Andrew has.
The second line of the input contains one integer d (30 β€ d β€ 100) β the price of one dollar in rubles.
The third line of the input contains integer e (30 β€ e β€ 100) β the price of one euro in rubles.
Output
Output one integer β the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.
Examples
Input
100
60
70
Output
40
Input
410
55
70
Output
5
Input
600
60
70
Output
0
Note
In the first example, we can buy just 1 dollar because there is no 1 euro bill.
In the second example, optimal exchange is to buy 5 euro and 1 dollar.
In the third example, optimal exchange is to buy 10 dollars in one bill. | instruction | 0 | 90,213 | 10 | 180,426 |
Tags: brute force, math
Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
def input(): return sys.stdin.readline()[:-1]
# def input(): return sys.stdin.buffer.readline()[:-1]
# n, k = [int(x) for x in input().split()]
n = int(input())
d = int(input())
e = int(input()) * 5
i = 0
ans = n
while i * e <= n:
ans = min(ans, (n - (i * e)) % d)
i += 1
print(ans)
"""
abacaba
7
1 2 4
8
1 2 4 1
"""
``` | output | 1 | 90,213 | 10 | 180,427 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Andrew was very excited to participate in Olympiad of Metropolises. Days flew by quickly, and Andrew is already at the airport, ready to go home. He has n rubles left, and would like to exchange them to euro and dollar bills. Andrew can mix dollar bills and euro bills in whatever way he wants. The price of one dollar is d rubles, and one euro costs e rubles.
Recall that there exist the following dollar bills: 1, 2, 5, 10, 20, 50, 100, and the following euro bills β 5, 10, 20, 50, 100, 200 (note that, in this problem we do not consider the 500 euro bill, it is hard to find such bills in the currency exchange points). Andrew can buy any combination of bills, and his goal is to minimize the total number of rubles he will have after the exchange.
Help him β write a program that given integers n, e and d, finds the minimum number of rubles Andrew can get after buying dollar and euro bills.
Input
The first line of the input contains one integer n (1 β€ n β€ 10^8) β the initial sum in rubles Andrew has.
The second line of the input contains one integer d (30 β€ d β€ 100) β the price of one dollar in rubles.
The third line of the input contains integer e (30 β€ e β€ 100) β the price of one euro in rubles.
Output
Output one integer β the minimum number of rubles Andrew can have after buying dollar and euro bills optimally.
Examples
Input
100
60
70
Output
40
Input
410
55
70
Output
5
Input
600
60
70
Output
0
Note
In the first example, we can buy just 1 dollar because there is no 1 euro bill.
In the second example, optimal exchange is to buy 5 euro and 1 dollar.
In the third example, optimal exchange is to buy 10 dollars in one bill. | instruction | 0 | 90,214 | 10 | 180,428 |
Tags: brute force, math
Correct Solution:
```
summ = int(input())
d = int(input())
e = int(input()) * 5
min_resid = summ
iters = 0
n_eur = summ // e
while (n_eur >= 0 and min_resid > 0 and iters < d):
resid = (summ - (n_eur * e)) % d
if (resid < min_resid):
min_resid = resid
n_eur -= 1
iters += 1
print(min_resid)
``` | output | 1 | 90,214 | 10 | 180,429 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.