message stringlengths 2 30.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 237 109k | cluster float64 10 10 | __index_level_0__ int64 474 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | instruction | 0 | 97,534 | 10 | 195,068 |
Tags: binary search, sortings
Correct Solution:
```
import sys
def sol(k):
B=[0]*n
for i in range(n):
B[i]=A[i]+k*(i+1)
B.sort()
res=0
for i in range(k):
res+=B[i]
return res
#main code
n,s=map(int,sys.stdin.readline().split())
A=list(map(int,sys.stdin.readline().split()))
#Binary search for the value k
l=0
r=n+1
while(l<r-1):
mid=(l+r)//2
if sol(mid)<=s:
l=mid
else:
r=mid
print(l,sol(l))
``` | output | 1 | 97,534 | 10 | 195,069 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | instruction | 0 | 97,535 | 10 | 195,070 |
Tags: binary search, sortings
Correct Solution:
```
n,S=map(int,input().split())
l=list(map(int,input().split()))
l2,r=0,n
v=0
while l2!=r :
l1=[]
m=(l2+r+1)//2
for i in range(n) :
l1.append(l[i]+(i+1)*m)
l1=sorted(l1)
for i in range(1,n) :
l1[i]+=l1[i-1]
if l1[m-1]>S :
r=m-1
else :
l2=m
v=l1[m-1]
print(l2,v)
``` | output | 1 | 97,535 | 10 | 195,071 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | instruction | 0 | 97,536 | 10 | 195,072 |
Tags: binary search, sortings
Correct Solution:
```
n,s=map(int,input().split())
a=list(map(int,input().split()))
beg=0
end=n
def trier(k) :
p = sorted([a[i]+ k*(i+1) for i in range(n)])
som = sum(p[0:k])
return 0 if som>s else som
l = 0
r = n
while l < r :
k = (l +r +1)//2
if trier(k) : l = k
else : r = k - 1
print(l,trier(l))
``` | output | 1 | 97,536 | 10 | 195,073 |
Provide tags and a correct Python 3 solution for this coding contest problem.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it. | instruction | 0 | 97,537 | 10 | 195,074 |
Tags: binary search, sortings
Correct Solution:
```
n,S = map(int,input().split())
st = input().split(' ')
cost = [int(num) for num in st]
l,r,Smin,k = 0,n+1,0,0
for _ in range(20):
k = int((l+r)/2)
a = list()
for i in range(n):
a.append(cost[i] + k*(i+1))
a.sort()
s = 0
for i in range(k):
s += a[i]
if(s <= S):
l = k
Smin = s;
else:
r = k
print(k,int(Smin))
``` | output | 1 | 97,537 | 10 | 195,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
# Sagheer and Nubian Market
import sys
import math
import collections
from pprint import pprint as pp
mod = 998244353
MAX = 10**10
def vector(size, val=0):
vec = [val for i in range(size)]
return vec
def matrix(rowNum, colNum, val=0):
mat = []
for i in range(rowNum):
collumn = [val for j in range(colNum)]
mat.append(collumn)
return mat
n, s = map(int, input().split())
a = list(map(int, input().split()))
def fun(m):
cnt = 0
b = [a[i] + m * (i + 1) for i in range(n)]
b.sort()
for i in range(m):
cnt += b[i]
return [cnt <= s, cnt]
l, h, ans, cost = 0, n, 0, 0
while l <= h:
m = (l + h) // 2
temp = fun(m)
if temp[0]:
ans = m
cost = temp[1]
l = m + 1
else:
h = m - 1
print('%d %d' % (ans, cost))
``` | instruction | 0 | 97,538 | 10 | 195,076 |
Yes | output | 1 | 97,538 | 10 | 195,077 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
n, S = map(int, input().split())
a = list(map(int, input().split()))
#a.insert(0, 0)
#a = sorted(a)
l = 0
r = n
realValue = 0
realMid = 0
mid = 0
while l <= r:
mid = l + (r - l) // 2
value = 0
b = []
for i in range(n):
b.append(a[i] + ((i + 1) * mid))
b = sorted(b)
for i in range(mid):
value += b[i]
#print(realMid, realValue, 'L:', l, 'R:', r)
if value <= S:
realMid = mid
realValue = value
if S <= value:
r = mid - 1
else:
l = mid + 1
if realValue > S:
print('0 0')
else:
print(realMid, realValue)
``` | instruction | 0 | 97,539 | 10 | 195,078 |
Yes | output | 1 | 97,539 | 10 | 195,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
import sys
def sol(k):
B=[0]*n
for i in range(n):
B[i]=A[i]+k*(i+1)
B.sort()
res=0
for i in range(k):
res+=B[i]
return res
#main code
n,s=map(int,input().split())
A=list(map(int,input().split()))
#Binary search for the value k
l=0
r=n+1
while(l<r-1):
mid=(l+r)//2
if sol(mid)<=s:
l=mid
else:
r=mid
print(l,sol(l))
``` | instruction | 0 | 97,540 | 10 | 195,080 |
Yes | output | 1 | 97,540 | 10 | 195,081 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
def canBuy(k):
fullCost = [(i + 1) * k + cost[i] for i in range(0, n)]
fullCost = sorted(fullCost)
fullSum = sum(fullCost[:k])
return fullSum <= money
def canBuyCost(k):
fullCost = [(i + 1) * k + cost[i] for i in range(0, n)]
fullCost = sorted(fullCost)
fullSum = sum(fullCost[:k])
return fullSum if fullSum <= money else -1
n, money = [int(x) for x in input().split()]
cost = [int(x) for x in input().split()]
left = 0
right = n
while left < right - 1:
mid = (left + right) // 2
if canBuy(mid):
left = mid
else:
right = mid
rightRes = canBuyCost(right)
if rightRes == -1:
print(left, canBuyCost(left))
else:
print(right, rightRes)
``` | instruction | 0 | 97,541 | 10 | 195,082 |
Yes | output | 1 | 97,541 | 10 | 195,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
n, s = map(int, input().split())
l = sorted(list(map(int, input().split())))
k = 0
st = 0
mk = 0
ma = []
for j in range(1, n + 1):
s1 = s
s2 = 0
k1 = 0
for i in range(j):
if s1 <= 0:
break
s1 -= (l[i] + ((i + 1) * j))
if s1 < 0:
break
s2 += (l[i] + ((i + 1) * j))
k1 += 1
if k1 > mk:
mk = k1
k = j
st = s2
print(k, st)
``` | instruction | 0 | 97,542 | 10 | 195,084 |
No | output | 1 | 97,542 | 10 | 195,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
max_cost=0
print("Input the value of n & S")
input1=input()
n = [int(l) for l in input1.split()][0]
S = [int(li) for li in input1.split()][1]
#S = input1.split(" ")[1]
print("Input the cost of item")
cost = [int(l) for l in input().split()]
k=int(2*(S-sum(cost))/n*(n+1))
if (n<k):
k=n
if (S-(cost[0]+1))<=0:
k=0
max_cost=0
print(k,max_cost)
else:
for i in range(0,k):
S=S-cost[i]
if S<=0:
break
max_cost=max_cost+cost[i]+(i+1)*k
print(k,max_cost)
``` | instruction | 0 | 97,543 | 10 | 195,086 |
No | output | 1 | 97,543 | 10 | 195,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
n,S = map(int,input().split())
arr = list(map(int,input().split()))
for i in range(1,n):
arr[i]+=arr[i-1]
l,r = 0,n
ac = 0
while l<r:
k = (l+r+1)>>1
at = [x+(i+1)*k for i,x in enumerate(arr)]
at.sort()
cost = sum(at[:k])
if cost<=S:
l = k
ac = cost
else:
r = k-1
print(l,ac)
``` | instruction | 0 | 97,544 | 10 | 195,088 |
No | output | 1 | 97,544 | 10 | 195,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
On his trip to Luxor and Aswan, Sagheer went to a Nubian market to buy some souvenirs for his friends and relatives. The market has some strange rules. It contains n different items numbered from 1 to n. The i-th item has base cost ai Egyptian pounds. If Sagheer buys k items with indices x1, x2, ..., xk, then the cost of item xj is axj + xj·k for 1 ≤ j ≤ k. In other words, the cost of an item is equal to its base cost in addition to its index multiplied by the factor k.
Sagheer wants to buy as many souvenirs as possible without paying more than S Egyptian pounds. Note that he cannot buy a souvenir more than once. If there are many ways to maximize the number of souvenirs, he will choose the way that will minimize the total cost. Can you help him with this task?
Input
The first line contains two integers n and S (1 ≤ n ≤ 105 and 1 ≤ S ≤ 109) — the number of souvenirs in the market and Sagheer's budget.
The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 105) — the base costs of the souvenirs.
Output
On a single line, print two integers k, T — the maximum number of souvenirs Sagheer can buy and the minimum total cost to buy these k souvenirs.
Examples
Input
3 11
2 3 5
Output
2 11
Input
4 100
1 2 5 6
Output
4 54
Input
1 7
7
Output
0 0
Note
In the first example, he cannot take the three items because they will cost him [5, 9, 14] with total cost 28. If he decides to take only two items, then the costs will be [4, 7, 11]. So he can afford the first and second items.
In the second example, he can buy all items as they will cost him [5, 10, 17, 22].
In the third example, there is only one souvenir in the market which will cost him 8 pounds, so he cannot buy it.
Submitted Solution:
```
n,s=map(int,input().split())
a=list(map(int,input().split()))
a.sort()
arr=[0]*n
arr1=[a[0]]*n
j=1
for i in range(1,n+1):
arr[i-1]=i*j
j+=(i+1)
for k in range(1,n):
arr1[k]=arr1[k-1]+a[k]
count=0
ss=0
for x in range(n):
if arr[x]+arr1[x]<s:
arr[x]+arr1[x]
count+=1
ss=arr[x]+arr1[x]
elif arr[x]+arr1[x]==s:
count+=1
ss=arr[x]+arr1[x]
break
else:
break
print(count,ss)
``` | instruction | 0 | 97,545 | 10 | 195,090 |
No | output | 1 | 97,545 | 10 | 195,091 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,607 | 10 | 195,214 |
"Correct Solution:
```
X=int(input())
c=int(100)
i=0
while c<X:
c=int(1.01*c)
i+=1
print(i)
``` | output | 1 | 97,607 | 10 | 195,215 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,608 | 10 | 195,216 |
"Correct Solution:
```
x=int(input())
a=100
b=0
while a<x:
a=int(a*1.01)
b+=1
print(b)
``` | output | 1 | 97,608 | 10 | 195,217 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,609 | 10 | 195,218 |
"Correct Solution:
```
X=int(input())
t=100
ans=0
while t<X:
ans+=1
t=int(t*1.01)
print(ans)
``` | output | 1 | 97,609 | 10 | 195,219 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,610 | 10 | 195,220 |
"Correct Solution:
```
#abc165b
x=float(input())
p=100.0
s=0
while p<x:
p+=p//100
s+=1
print(s)
``` | output | 1 | 97,610 | 10 | 195,221 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,611 | 10 | 195,222 |
"Correct Solution:
```
x=int(input())
n=100
k=0
while n<x:
n=n*101//100
k+=1
print(k)
``` | output | 1 | 97,611 | 10 | 195,223 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,612 | 10 | 195,224 |
"Correct Solution:
```
x=int(input())
y=0
mon=100
while x>mon:
mon+=mon//100
y+=1
print(y)
``` | output | 1 | 97,612 | 10 | 195,225 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,613 | 10 | 195,226 |
"Correct Solution:
```
X=int(input())
c=100
d=0
while c<X:
c=int(c*1.01)
d+=1
print(d)
``` | output | 1 | 97,613 | 10 | 195,227 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706 | instruction | 0 | 97,614 | 10 | 195,228 |
"Correct Solution:
```
X=int(input())
p=100;ytd=0
while p<X:
p=int(p*1.01)
ytd=ytd+1
print(ytd)
``` | output | 1 | 97,614 | 10 | 195,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
x=int(input())
n=100
ans=0
while n<x:
ans+=1
n+=int(n/100)
print(ans)
``` | instruction | 0 | 97,615 | 10 | 195,230 |
Yes | output | 1 | 97,615 | 10 | 195,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
x=int(input())
i=0
s=100
while s<x:
s=int(s*1.01)
i+=1
print(i)
``` | instruction | 0 | 97,616 | 10 | 195,232 |
Yes | output | 1 | 97,616 | 10 | 195,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
x=int(input())
m=100
y=0
while m<x:
y+=1
m=int(m*1.01)
print(y)
``` | instruction | 0 | 97,617 | 10 | 195,234 |
Yes | output | 1 | 97,617 | 10 | 195,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
X=int(input())
y=100
i=0
while y<X:
y=int(y*1.01)
i+=1
print(i)
``` | instruction | 0 | 97,618 | 10 | 195,236 |
Yes | output | 1 | 97,618 | 10 | 195,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
x=int(input())
a=100
k=0
while(1):
k+=1
a=a+a(1//100)
if(a>=x):break
print(k)
``` | instruction | 0 | 97,619 | 10 | 195,238 |
No | output | 1 | 97,619 | 10 | 195,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
def compound_interest(principle, rate, time):
CI = principle * (pow((1 + rate / 100), time))
return CI
x=int(input())
for i in range (1,100000):
ci=int(compound_interest(100, 1, i))
if(ci>=x):
print(i)
break
``` | instruction | 0 | 97,620 | 10 | 195,240 |
No | output | 1 | 97,620 | 10 | 195,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
x = int(input())
i = 0
k = 100
while True:
if(k>=x):
break
else:
k*=1.01
i+=1
print(i)
``` | instruction | 0 | 97,621 | 10 | 195,242 |
No | output | 1 | 97,621 | 10 | 195,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi has a deposit of 100 yen (the currency of Japan) in AtCoder Bank.
The bank pays an annual interest rate of 1 % compounded annually. (A fraction of less than one yen is discarded.)
Assuming that nothing other than the interest affects Takahashi's balance, in how many years does the balance reach X yen or above for the first time?
Constraints
* 101 \le X \le 10^{18}
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
X
Output
Print the number of years it takes for Takahashi's balance to reach X yen or above for the first time.
Examples
Input
103
Output
3
Input
1000000000000000000
Output
3760
Input
1333333333
Output
1706
Submitted Solution:
```
X = input()
Money = 100
counter = 0
while int(X) > Money:
Money = Money*1.01
counter = counter + 1
print(counter)
``` | instruction | 0 | 97,622 | 10 | 195,244 |
No | output | 1 | 97,622 | 10 | 195,245 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,837 | 10 | 195,674 |
Tags: implementation
Correct Solution:
```
import math
a = int(input())
b = input().split()
b = [int(i) for i in b]
c = input().split()
c = [int(i) for i in c]
output = 0
for i in b:
output += (i + c[1] - 1)//(c[0] + c[1])
print (output * c[1])
``` | output | 1 | 97,837 | 10 | 195,675 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,838 | 10 | 195,676 |
Tags: implementation
Correct Solution:
```
n=int(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
b=x+f
ans=0
for i in range(n):
a=l[i]-x
if a%b==0:
ans+=a//b
else:
ans+=a//b+1
print(ans*f)
``` | output | 1 | 97,838 | 10 | 195,677 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,839 | 10 | 195,678 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
max, fee = map(int, input().split())
total = 0
a.sort(reverse=True)
for i in range(n):
if a[i]> max:
num = -(-(a[i]-max)//(max+fee))
total = total + fee*num
else:
break
print(total)
``` | output | 1 | 97,839 | 10 | 195,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,840 | 10 | 195,680 |
Tags: implementation
Correct Solution:
```
import math
NN = int(input())
AI = list(map(int,input().split()))
XX,FF = map(int,input().split())
length = len(AI)
extra = 0
for xx in AI:
if xx>XX:
extra+=math.ceil((xx-XX)/(XX+FF))
print(extra*FF)
``` | output | 1 | 97,840 | 10 | 195,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,841 | 10 | 195,682 |
Tags: implementation
Correct Solution:
```
n=(int)(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
c=0
for i in l:
y=i-x
if y>0:
a=y//(x+f)
b=y/(x+f)
if a==b:
c=c+a
else:
c=c+a+1
print(f*c)
``` | output | 1 | 97,841 | 10 | 195,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,842 | 10 | 195,684 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
maxVal, cost = map(int, input().split())
newWallets = 0
for s in a:
if s > maxVal:
newWallets += ((s + cost - 1) // (maxVal + cost))
print(newWallets * cost)
``` | output | 1 | 97,842 | 10 | 195,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,843 | 10 | 195,686 |
Tags: implementation
Correct Solution:
```
from sys import stdin,stdout
from math import gcd,sqrt
from collections import deque
input=stdin.readline
R=lambda:map(int,input().split())
I=lambda:int(input())
S=lambda:input().rstrip('\n')
L=lambda:list(R())
P=lambda x:stdout.write(x)
hg=lambda x,y:((y+x-1)//x)*x
pw=lambda x:1 if x==1 else 1+pw(x//2)
chk=lambda x:chk(x//2) if not x%2 else True if x==1 else False
N=10**6+7
def fee(p):return (p//(x+f))*f+max(0,min(1,p%(x+f)-x))*f
n=I()
a=L()
x,f=R()
ans=0
for i in a:
if i>x:ans+=fee(i)
print(ans)
``` | output | 1 | 97,843 | 10 | 195,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4. | instruction | 0 | 97,844 | 10 | 195,688 |
Tags: implementation
Correct Solution:
```
#Code by Sounak, IIESTS
#------------------------------warmup----------------------------
import os
import sys
import math
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
#-------------------game starts now-----------------------------------------------------
n=int(input())
a=list(map(int,input().split()))
x,f=map(int,input().split())
fee=0
temp=0
for i in (a):
if i>x:
temp=int(math.ceil((i-x)/(x+f)))
temp=max(1,temp)
fee=fee+temp*f
print(fee)
``` | output | 1 | 97,844 | 10 | 195,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
coshelki = [int(i) for i in input().split()]
x, f = (int(i) for i in input().split())
sum = 0
for i in coshelki:
perevody = i // (x + f)
if i - perevody * (x + f) > x:
perevody += 1
sum += perevody
print(f * sum)
``` | instruction | 0 | 97,845 | 10 | 195,690 |
Yes | output | 1 | 97,845 | 10 | 195,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
# -*- coding: utf-8 -*-
from math import ceil
def problem(in1, in2, in3):
n = int(in1)
balances = list(map(int, in2.split()))
limit = list(map(int, in3.split()))[0]
fee = list(map(int, in3.split()))[1]
tx_size = limit + fee
tx_count = 0
for index, balance in enumerate(balances):
tx_needed = ceil((balance - limit) / tx_size)
tx_count += tx_needed
return tx_count * fee
if __name__ == '__main__':
in1 = input()
in2 = input()
in3 = input();
result = problem(in1, in2, in3)
print(result)
``` | instruction | 0 | 97,846 | 10 | 195,692 |
Yes | output | 1 | 97,846 | 10 | 195,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import math
n=int(input())
l=list(map(int,input().split()))
x,f=map(int,input().split())
ans=0
for i in range(n):
if l[i]<=x:
continue
else:
c=math.ceil((l[i]-x)/(f+x))
ans+=f*c
print(ans)
``` | instruction | 0 | 97,847 | 10 | 195,694 |
Yes | output | 1 | 97,847 | 10 | 195,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import math
input()
a=list(map(int,input().split()))
x,y=map(int,input().split())
s=0
for i in a:
if i>x:
s+=math.ceil((i-x)/(x+y))
print(int(s*y))
``` | instruction | 0 | 97,848 | 10 | 195,696 |
Yes | output | 1 | 97,848 | 10 | 195,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
from collections import Counter
from math import ceil
n=int(input())
a=[int(X) for X in input().split()]
x,f=map(int,input().split())
an=0
for i in range(n):
if a[i]>x:
an+=ceil(a[i]/x)
z=Counter(a)
print(an*f)
``` | instruction | 0 | 97,849 | 10 | 195,698 |
No | output | 1 | 97,849 | 10 | 195,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
l = list(map(int,input().split()))
x,f = map(int,input().split())
v = len(list(filter(lambda val: val>x,l)))
print(v*f)
``` | instruction | 0 | 97,850 | 10 | 195,700 |
No | output | 1 | 97,850 | 10 | 195,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
import sys
input = sys.stdin.readline
n = int(input())
a = [int(x) for x in input().split()]
x, f = map(int, input().split())
k = 0
for i in range(n):
if a[i] >= x + f:
k += a[i]//(x + f)
elif x < a[i] < x + f:
k += 1
print(k*f)
``` | instruction | 0 | 97,851 | 10 | 195,702 |
No | output | 1 | 97,851 | 10 | 195,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
After finding and moving to the new planet that supports human life, discussions started on which currency should be used. After long negotiations, Bitcoin was ultimately chosen as the universal currency.
These were the great news for Alice, whose grandfather got into Bitcoin mining in 2013, and accumulated a lot of them throughout the years. Unfortunately, when paying something in bitcoin everyone can see how many bitcoins you have in your public address wallet.
This worried Alice, so she decided to split her bitcoins among multiple different addresses, so that every address has at most x satoshi (1 bitcoin = 10^8 satoshi). She can create new public address wallets for free and is willing to pay f fee in satoshi per transaction to ensure acceptable speed of transfer. The fee is deducted from the address the transaction was sent from. Tell Alice how much total fee in satoshi she will need to pay to achieve her goal.
Input
First line contains number N (1 ≤ N ≤ 200 000) representing total number of public addresses Alice has.
Next line contains N integer numbers a_i (1 ≤ a_i ≤ 10^9) separated by a single space, representing how many satoshi Alice has in her public addresses.
Last line contains two numbers x, f (1 ≤ f < x ≤ 10^9) representing maximum number of satoshies Alice can have in one address, as well as fee in satoshies she is willing to pay per transaction.
Output
Output one integer number representing total fee in satoshi Alice will need to pay to achieve her goal.
Example
Input
3
13 7 6
6 2
Output
4
Note
Alice can make two transactions in a following way:
0. 13 7 6 (initial state)
1. 6 7 6 5 (create new address and transfer from first public address 5 satoshies)
2. 6 4 6 5 1 (create new address and transfer from second address 1 satoshi)
Since cost per transaction is 2 satoshies, total fee is 4.
Submitted Solution:
```
n = int(input())
coshelki = [int(i) for i in input().split()]
x, f = (int(i) for i in input().split())
sum = 0
for i in coshelki:
perevodi = i // (x + f)
if perevodi == 0 and i > x:
sum += 1
sum += perevodi
print(f * sum)
``` | instruction | 0 | 97,852 | 10 | 195,704 |
No | output | 1 | 97,852 | 10 | 195,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Artsem is on vacation and wants to buy souvenirs for his two teammates. There are n souvenir shops along the street. In i-th shop Artsem can buy one souvenir for ai dollars, and he cannot buy more than one souvenir in one shop. He doesn't want to introduce envy in his team, so he wants to buy two souvenirs with least possible difference in price.
Artsem has visited the shopping street m times. For some strange reason on the i-th day only shops with numbers from li to ri were operating (weird? yes it is, but have you ever tried to come up with a reasonable legend for a range query problem?). For each visit, Artsem wants to know the minimum possible difference in prices of two different souvenirs he can buy in the opened shops.
In other words, for each Artsem's visit you should find the minimum possible value of |as - at| where li ≤ s, t ≤ ri, s ≠ t.
Input
The first line contains an integer n (2 ≤ n ≤ 105).
The second line contains n space-separated integers a1, ..., an (0 ≤ ai ≤ 109).
The third line contains the number of queries m (1 ≤ m ≤ 3·105).
Next m lines describe the queries. i-th of these lines contains two space-separated integers li and ri denoting the range of shops working on i-th day (1 ≤ li < ri ≤ n).
Output
Print the answer to each query in a separate line.
Example
Input
8
3 1 4 1 5 9 2 6
4
1 8
1 3
4 8
5 7
Output
0
1
1
3
Submitted Solution:
```
a=int(input())
b=input().split()
for i in range (len(b)):
b[i]=int(b[i])
c=int(input())
#b.sort()
for i in range(c):
a=input().split()
x=int(a[0])-1
y=int(a[1])
d=b[x:y]
d.sort()
m=[]
for i in range(len(d)-1):
m.append(abs(int(d[i+1])-int(d[i])))
m.sort()
print(m[0]," lol ",d)
``` | instruction | 0 | 98,311 | 10 | 196,622 |
No | output | 1 | 98,311 | 10 | 196,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a matrix f with 4 rows and n columns. Each element of the matrix is either an asterisk (*) or a dot (.).
You may perform the following operation arbitrary number of times: choose a square submatrix of f with size k × k (where 1 ≤ k ≤ 4) and replace each element of the chosen submatrix with a dot. Choosing a submatrix of size k × k costs ak coins.
What is the minimum number of coins you have to pay to replace all asterisks with dots?
Input
The first line contains one integer n (4 ≤ n ≤ 1000) — the number of columns in f.
The second line contains 4 integers a1, a2, a3, a4 (1 ≤ ai ≤ 1000) — the cost to replace the square submatrix of size 1 × 1, 2 × 2, 3 × 3 or 4 × 4, respectively.
Then four lines follow, each containing n characters and denoting a row of matrix f. Each character is either a dot or an asterisk.
Output
Print one integer — the minimum number of coins to replace all asterisks with dots.
Examples
Input
4
1 10 8 20
***.
***.
***.
...*
Output
9
Input
7
2 1 8 2
.***...
.***..*
.***...
....*..
Output
3
Input
4
10 10 1 10
***.
*..*
*..*
.***
Output
2
Note
In the first example you can spend 8 coins to replace the submatrix 3 × 3 in the top-left corner, and 1 coin to replace the 1 × 1 submatrix in the bottom-right corner.
In the second example the best option is to replace the 4 × 4 submatrix containing columns 2 – 5, and the 2 × 2 submatrix consisting of rows 2 – 3 and columns 6 – 7.
In the third example you can select submatrix 3 × 3 in the top-left corner and then submatrix 3 × 3 consisting of rows 2 – 4 and columns 2 – 4. | instruction | 0 | 98,350 | 10 | 196,700 |
Tags: bitmasks, dp
Correct Solution:
```
import sys
n = int(sys.stdin.buffer.readline().decode('utf-8'))
cost = [0] + \
list(map(int, sys.stdin.buffer.readline().decode('utf-8').split()))
a = [line.decode('utf-8').rstrip() for line in sys.stdin.buffer]
mask = [0, 1, 51, 1911]
inf, bs_size, full_bit = 10**9, 1 << 12, (1 << 12) - 1
dp = [[inf]*bs_size for _ in range(4*n+1)]
dp[0][0] = 0
for i in range(4*n):
y, x = i & 3, i >> 2
is_dot = 1 if a[y][x] == '.' else 0
for bitset in range(bs_size):
if y == 0:
'''
01234 01234
0 s**** .t..*
1 ***** -> ....*
2 ***** -> ....*
3 ***** ....*
'''
if dp[i+4][full_bit] > dp[i][bitset] + cost[4]:
dp[i+4][full_bit] = dp[i][bitset] + cost[4]
if (is_dot | bitset & 1) and\
dp[i+1][bitset >> 1] > dp[i][bitset]:
dp[i+1][bitset >> 1] = dp[i][bitset]
for k in range(1, min(4-y, 3)+1):
if dp[i][bitset | mask[k]] > dp[i][bitset] + cost[k]:
dp[i][bitset | mask[k]] = dp[i][bitset] + cost[k]
print(min(dp[4*n]))
``` | output | 1 | 98,350 | 10 | 196,701 |
Provide a correct Python 3 solution for this coding contest problem.
Dutch treat
You have organized a party to pray for the good performance of the ICPC 2019 Yokohama Regional Domestic Qualifiers. There are N participants in this party.
Since it costs M yen in total to hold this party, we decided to collect M / N yen from each of the N participants. Since M is divisible by N, there is no need to worry about the remainder.
Today's possession of the i-th participant is Ai Yen. If you cannot pay the M / N yen, you will be asked to pay all of your money today, and you will be asked to pay the shortfall at a later date.
How much can you collect for a party today?
Input
The input consists of up to 50 datasets. Each dataset is represented in the following format.
> N M A1 A2 ... AN
The dataset consists of two lines. The first line gives the number of participants N in the party and the cost M incurred. N and M are integers, and 2 ≤ N ≤ 100 and N ≤ M ≤ 10 000, respectively. Also, M is a multiple of N. The second line gives each of the N participants their own money. Ai is an integer representing the possession of the i-th participant, and 1 ≤ Ai ≤ 10 000.
The end of the input is represented by a line consisting of only two 0s.
Output
For each dataset, print out the party costs you can collect today in one line.
Sample Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output for the Sample Input
280
twenty five
800
Five
In the first data set, the payment per person is 100 yen. The first and second participants can pay 100 yen, but the third participant cannot pay 100 yen, so they will be asked to pay the possession of 80 yen, and the missing 20 yen will be paid at a later date. I will ask you to pay. You can collect 100 + 100 + 80 = 280 yen today.
Example
Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output
280
25
800
5 | instruction | 0 | 98,571 | 10 | 197,142 |
"Correct Solution:
```
while True:
N, M = map(int, input().split())
if (N | M) == 0:
break
A = [int(x) for x in input().split()]
ans = 0
M //= N
for a in A:
if a < M:
ans += a
else:
ans += M
print(ans)
``` | output | 1 | 98,571 | 10 | 197,143 |
Provide a correct Python 3 solution for this coding contest problem.
Dutch treat
You have organized a party to pray for the good performance of the ICPC 2019 Yokohama Regional Domestic Qualifiers. There are N participants in this party.
Since it costs M yen in total to hold this party, we decided to collect M / N yen from each of the N participants. Since M is divisible by N, there is no need to worry about the remainder.
Today's possession of the i-th participant is Ai Yen. If you cannot pay the M / N yen, you will be asked to pay all of your money today, and you will be asked to pay the shortfall at a later date.
How much can you collect for a party today?
Input
The input consists of up to 50 datasets. Each dataset is represented in the following format.
> N M A1 A2 ... AN
The dataset consists of two lines. The first line gives the number of participants N in the party and the cost M incurred. N and M are integers, and 2 ≤ N ≤ 100 and N ≤ M ≤ 10 000, respectively. Also, M is a multiple of N. The second line gives each of the N participants their own money. Ai is an integer representing the possession of the i-th participant, and 1 ≤ Ai ≤ 10 000.
The end of the input is represented by a line consisting of only two 0s.
Output
For each dataset, print out the party costs you can collect today in one line.
Sample Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output for the Sample Input
280
twenty five
800
Five
In the first data set, the payment per person is 100 yen. The first and second participants can pay 100 yen, but the third participant cannot pay 100 yen, so they will be asked to pay the possession of 80 yen, and the missing 20 yen will be paid at a later date. I will ask you to pay. You can collect 100 + 100 + 80 = 280 yen today.
Example
Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output
280
25
800
5 | instruction | 0 | 98,572 | 10 | 197,144 |
"Correct Solution:
```
while True:
n,m=map(int,input().split())
if (n,m)==(0,0):
break
t=m//n
a=list(map(int,input().split()))
cnt=0
for i in a:
if t<=i:
cnt+=t
else:
cnt+=i
print(cnt)
``` | output | 1 | 98,572 | 10 | 197,145 |
Provide a correct Python 3 solution for this coding contest problem.
Dutch treat
You have organized a party to pray for the good performance of the ICPC 2019 Yokohama Regional Domestic Qualifiers. There are N participants in this party.
Since it costs M yen in total to hold this party, we decided to collect M / N yen from each of the N participants. Since M is divisible by N, there is no need to worry about the remainder.
Today's possession of the i-th participant is Ai Yen. If you cannot pay the M / N yen, you will be asked to pay all of your money today, and you will be asked to pay the shortfall at a later date.
How much can you collect for a party today?
Input
The input consists of up to 50 datasets. Each dataset is represented in the following format.
> N M A1 A2 ... AN
The dataset consists of two lines. The first line gives the number of participants N in the party and the cost M incurred. N and M are integers, and 2 ≤ N ≤ 100 and N ≤ M ≤ 10 000, respectively. Also, M is a multiple of N. The second line gives each of the N participants their own money. Ai is an integer representing the possession of the i-th participant, and 1 ≤ Ai ≤ 10 000.
The end of the input is represented by a line consisting of only two 0s.
Output
For each dataset, print out the party costs you can collect today in one line.
Sample Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output for the Sample Input
280
twenty five
800
Five
In the first data set, the payment per person is 100 yen. The first and second participants can pay 100 yen, but the third participant cannot pay 100 yen, so they will be asked to pay the possession of 80 yen, and the missing 20 yen will be paid at a later date. I will ask you to pay. You can collect 100 + 100 + 80 = 280 yen today.
Example
Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output
280
25
800
5 | instruction | 0 | 98,573 | 10 | 197,146 |
"Correct Solution:
```
while True:
a,b = map(int,input().split())
if a == b == 0:
break
h = b//a
for c in list(map(int,input().split())):
if c < h:
b -= h-c
print(b)
``` | output | 1 | 98,573 | 10 | 197,147 |
Provide a correct Python 3 solution for this coding contest problem.
Dutch treat
You have organized a party to pray for the good performance of the ICPC 2019 Yokohama Regional Domestic Qualifiers. There are N participants in this party.
Since it costs M yen in total to hold this party, we decided to collect M / N yen from each of the N participants. Since M is divisible by N, there is no need to worry about the remainder.
Today's possession of the i-th participant is Ai Yen. If you cannot pay the M / N yen, you will be asked to pay all of your money today, and you will be asked to pay the shortfall at a later date.
How much can you collect for a party today?
Input
The input consists of up to 50 datasets. Each dataset is represented in the following format.
> N M A1 A2 ... AN
The dataset consists of two lines. The first line gives the number of participants N in the party and the cost M incurred. N and M are integers, and 2 ≤ N ≤ 100 and N ≤ M ≤ 10 000, respectively. Also, M is a multiple of N. The second line gives each of the N participants their own money. Ai is an integer representing the possession of the i-th participant, and 1 ≤ Ai ≤ 10 000.
The end of the input is represented by a line consisting of only two 0s.
Output
For each dataset, print out the party costs you can collect today in one line.
Sample Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output for the Sample Input
280
twenty five
800
Five
In the first data set, the payment per person is 100 yen. The first and second participants can pay 100 yen, but the third participant cannot pay 100 yen, so they will be asked to pay the possession of 80 yen, and the missing 20 yen will be paid at a later date. I will ask you to pay. You can collect 100 + 100 + 80 = 280 yen today.
Example
Input
3 300
120 100 80
3 30
10 20 5
4 1000
100 200 300 400
5 5
2523 8430 3 4199 632
0 0
Output
280
25
800
5 | instruction | 0 | 98,574 | 10 | 197,148 |
"Correct Solution:
```
while 1:
n,m=map(int, input().split())
if n == 0:
break
a = list(map(int, input().split()))
c = 0
for i in range(n):
c += min(m//n, a[i])
print(c)
``` | output | 1 | 98,574 | 10 | 197,149 |
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