message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 219 108k | cluster float64 11 11 | __index_level_0__ int64 438 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have written N problems to hold programming contests. The i-th problem will have a score of P_i points if used in a contest.
With these problems, you would like to hold as many contests as possible under the following condition:
* A contest has three problems. The first problem has a score not greater than A points, the second has a score between A + 1 and B points (inclusive), and the third has a score not less than B + 1 points.
The same problem should not be used in multiple contests. At most how many contests can be held?
Constraints
* 3 \leq N \leq 100
* 1 \leq P_i \leq 20 (1 \leq i \leq N)
* 1 \leq A < B < 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
N
A B
P_1 P_2 ... P_N
Output
Print the answer.
Examples
Input
7
5 15
1 10 16 2 7 20 12
Output
2
Input
8
3 8
5 5 5 10 10 10 15 20
Output
0
Input
3
5 6
5 6 10
Output
1
Submitted Solution:
```
n=int(input())
A,B=map(int, input().split())
p=list(map(int, input().split()))
p.sort()
t=0
y=0
u=0
g=0
for i in range(len(p)):
if t==0 and p[i]<=A:
t=p[i]
g+=1
elif y==0 and A+1<p[i] and p[i]<=B:
y=p[i]
g+=1
elif u==0 and p[i]>=B+1:
u=p[i]
if t!=0 and y!=0 and u!=0:
print(3)
elif t!=0 and y!=0:
print(2)
elif t!=0:
print(1)
else:
print(0)
``` | instruction | 0 | 29,822 | 11 | 59,644 |
No | output | 1 | 29,822 | 11 | 59,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vn = {}
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha() and ope not in vn:
vn[ope] = len(vn)
vs = [0]*len(vn)
def value(var):
if var.isalpha():
return vs[vn[var]]
return int(var)
def assign(var, x):
if not 0 <= x < 16:
assert 0
vs[vn[var]] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 16**len(vn) + 10
try:
while 1:
stmt = stmts[pc]
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
except:...
if result:
for k in sorted(vn):
print("%s=%d" % (k, vs[vn[k]]))
else:
print("inf")
``` | instruction | 0 | 29,934 | 11 | 59,868 |
No | output | 1 | 29,934 | 11 | 59,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vn = {}
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha() and ope not in vn:
vn[ope] = len(vn)
vs = [0]*len(vn)
def check(x):
return 0 <= x < 16
def value(var):
if var.isalpha():
return vs[vn[var]]
return int(var)
def assign(var, x):
vs[vn[var]] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 16**5 + 10
while pc < n:
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
elif op == 'HALT': # 'HALT'
break
else:
assert 0
if result:
for k in sorted(vn):
print("%s=%d" % (k, vs[vn[k]]))
else:
print("inf")
``` | instruction | 0 | 29,935 | 11 | 59,870 |
No | output | 1 | 29,935 | 11 | 59,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vs = [None]*26
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha():
vs[ord(ope)-97] = 0
def check(x):
return 0 <= x <= 16
def value(var):
if var.isalpha():
o = ord(var)-97
return vs[o]
return int(var)
def assign(var, x):
o = ord(var)-97
vs[o] = x
result = 1
state = set()
pc = 0
while pc < n:
st = (pc, tuple(vs))
if st in state:
result = 0
break
state.add(st)
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
if result:
for i in range(26):
if vs[i] is not None:
print("%c=%d" % (97+i, vs[i]))
else:
print("inf")
``` | instruction | 0 | 29,936 | 11 | 59,872 |
No | output | 1 | 29,936 | 11 | 59,873 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Have you ever had an infinite loop when you ran a hard-working program? It would be convenient to be able to determine in advance whether a program will stop executing without having to execute it.
Unfortunately, it is not possible to make such a decision for any program in the programming language you normally use. However, if you have a programming language that is much less computationally powerful, you may be able to write a program that determines if a program written in that language will stop.
Consider a programming language called TinyPower. Programs in this language are line sequences. On each line of the program, write the line number at the beginning and one sentence after it. The types of sentences that can be written in this language are as follows.
Sentence type | Behavior
--- | ---
ADD var1 var2 var3 | Assign the result of adding the value of variable var2 and the value of var3 to variable var1
ADD var1 var2 con | Assign the result of adding the value of the variable var2 and the constant con to the variable var1
SUB var1 var2 var3 | Assign the result of subtracting the value of var3 from the value of variable var2 to variable var1
SUB var1 var2 con | Substitute the result of subtracting the constant con from the value of the variable var2 into the variable var1
SET var1 var2 | Assign the value of variable var2 to variable var1
SET var1 con | Assign the constant con to the variable var1
IF var1 dest | Jump to line number dest only if the value of variable var1 is non-zero
HALT | Stop the program
Line numbers are positive integers, and the same line number will never appear more than once in the program. Variables are represented by a single lowercase letter, and constants and variable values are integers. No variable declaration is required, the initial value of the variable is 0.
Program execution starts with the first statement, and the statements are executed in the order in which they are lined up. However, as written in the table above, if the value of the variable in the IF statement is not 0, jump to the line specified by the line number written after the variable and start from the statement written in that line. Continue running. The program will stop when:
* When the HALT statement is executed.
* When trying to assign a negative integer or an integer greater than or equal to 16 to a variable (the value of the variable is not updated).
* When trying to jump to a line number that does not appear in the program.
* When you do not jump to any line from the last statement of the program.
Create a program that determines if a TinyPower program, given it, will stop.
Input
The input is given in the following format.
N
stmt1
stmt2
::
stmtN
The number of lines N (1 ≤ N ≤ 50) of the program is given on the first line. The following N lines are given the statement stmti of the TinyPower program. stmti is given in one of the following formats:
line ADD var1 var2 var3
Or
line ADD var1 var2 con
Or
line SUB var1 var2 var3
Or
line SUB var1 var2 con
Or
line SET var1 var2
Or
line SET var1 con
Or
line IF var1 dest
Or
line HALT
line, dest (1 ≤ line, dest ≤ 1000) is the line number, varj (one lowercase letter) is the variable, and con (0 ≤ con ≤ 15) is the constant. The delimiter in stmti is one blank character. It is assumed that one or more variables always appear in the program, and only five different variable names appear.
Output
When the program stops, the results of the variables appearing in the program are output in the lexicographic order of the variable names, separated by line breaks, and when it does not stop, "inf" is output. The result of the variable is output by separating the variable name and the value of the variable with "=".
Examples
Input
6
10 SET c 1
20 SET i 5
100 ADD s s i
110 SUB i i c
120 IF i 100
200 HALT
Output
c=1
i=0
s=15
Input
3
10 SET c 1
120 IF c 10
20 HALT
Output
inf
Input
3
111 SET c 1
12 SUB c c 2
777 SET a 4
Output
a=0
c=1
Submitted Solution:
```
n = int(input())
stmts = [input().split() for i in range(n)]
mapper = {}
for i, stmt in enumerate(stmts):
mapper[stmt[0]] = i
vs = [None]*26
for stmt in stmts:
for ope in stmt[2:]:
if ope.isalpha():
vs[ord(ope)-97] = 0
def check(x):
return 0 <= x <= 16
def value(var):
if var.isalpha():
o = ord(var)-97
return vs[o]
return int(var)
def assign(var, x):
o = ord(var)-97
vs[o] = x
result = 1
state = set()
pc = 0
cnts = [0]*n
LIM = 15**5+10
while pc < n:
cnts[pc] += 1
if cnts[pc] > LIM:
result = 0
break
stmt = stmts[pc]
op = stmt[1]
if op == 'ADD':
v1, v2, v3 = stmt[2:]
if not check(value(v2) + value(v3)):
break
assign(v1, value(v2) + value(v3))
pc += 1
elif op == 'SUB':
v1, v2, v3 = stmt[2:]
if not check(value(v2) - value(v3)):
break
assign(v1, value(v2) - value(v3))
pc += 1
elif op == 'SET':
v1, v2 = stmt[2:]
assign(v1, value(v2))
pc += 1
elif op == 'IF':
v1, dest = stmt[2:]
if value(v1) > 0:
if dest not in mapper:
break
pc = mapper[dest]
else:
pc += 1
else: # 'HALT'
break
if result:
for i in range(26):
if vs[i] is not None:
print("%c=%d" % (97+i, vs[i]))
else:
print("inf")
``` | instruction | 0 | 29,937 | 11 | 59,874 |
No | output | 1 | 29,937 | 11 | 59,875 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
n, m = map(int, input().split())
A = list(list(map(int, input().split())) for _ in range(n))
b = list(int(input()) for _ in range(m))
for i in range(n):
ans = 0
for j in range(m):
ans += A[i][j] * b[j]
print(ans)
``` | instruction | 0 | 30,052 | 11 | 60,104 |
Yes | output | 1 | 30,052 | 11 | 60,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
import sys
n,m=map(int,input().split())
A=[0]*n
B=[0]*m
C=[0]*n
for i in range(0,n):
A[i]=list(map(int, input().split()))
for i in range(0,m):
B[i]=int(input())
for i in range(0,n):
for j in range(0,m):
C[i]+=A[i][j]*B[j]
print(C[i])
``` | instruction | 0 | 30,053 | 11 | 60,106 |
Yes | output | 1 | 30,053 | 11 | 60,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
n,m=map(int,input().split())
A=[list(map(int,input().split())) for i in range(n)]
B=[int(input())for i in range(m)]
for i in range(n):
kotae=0
for j in range(m):
kotae+=A[i][j]*B[j]
print(kotae)
``` | instruction | 0 | 30,054 | 11 | 60,108 |
Yes | output | 1 | 30,054 | 11 | 60,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
N, M = map(int, input().split())
A = [list(map(int, input().split())) for _ in range(N)]
B = [int(input()) for _ in range(M)]
for i in range(N):
cnt = 0
for j in range(M):
cnt += A[i][j] * B[j]
print(cnt)
``` | instruction | 0 | 30,055 | 11 | 60,110 |
Yes | output | 1 | 30,055 | 11 | 60,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
(n, m) = [int(i) for i in input().split()]
a = [[]]
b = []
for i in range(n):
A.append([int(j) for j in input().split()]
for i in range(m):
b.append(int(input()))
c = []
for i range(n):
s = 0
for j in range(m):
m += A[i][j] * b[j]
print(s)
``` | instruction | 0 | 30,056 | 11 | 60,112 |
No | output | 1 | 30,056 | 11 | 60,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
nums = list(map(int, input().split()))
sum_li = []
for i in range(nums[0]):
line = list(map(int, input().split()))
sum_li.append(sum(line))
for i in range(nums[0]):
n = int(input())
sum_li[i] += n
input()
for i in range(nums[0]): print(sum_li[i])
``` | instruction | 0 | 30,057 | 11 | 60,114 |
No | output | 1 | 30,057 | 11 | 60,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
#! python3
# matrix_vector_multiplication.py
n, m = [int(x) for x in input().split(' ')]
a = [[int(x) for x in input(' ').split()] for i in range(n)]
b = [int(input()) for i in range(m)]
rsts = []
for i in range(n):
rst = 0
for j in range(m):
rst += a[i][j] * b[j]
rsts.append(rst)
for rst in rsts:
print(rst)
``` | instruction | 0 | 30,058 | 11 | 60,116 |
No | output | 1 | 30,058 | 11 | 60,117 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Write a program which reads a $ n \times m$ matrix $A$ and a $m \times 1$ vector $b$, and prints their product $Ab$.
A column vector with m elements is represented by the following equation.
\\[ b = \left( \begin{array}{c} b_1 \\\ b_2 \\\ : \\\ b_m \\\ \end{array} \right) \\]
A $n \times m$ matrix with $m$ column vectors, each of which consists of $n$ elements, is represented by the following equation.
\\[ A = \left( \begin{array}{cccc} a_{11} & a_{12} & ... & a_{1m} \\\ a_{21} & a_{22} & ... & a_{2m} \\\ : & : & : & : \\\ a_{n1} & a_{n2} & ... & a_{nm} \\\ \end{array} \right) \\]
$i$-th element of a $m \times 1$ column vector $b$ is represented by $b_i$ ($i = 1, 2, ..., m$), and the element in $i$-th row and $j$-th column of a matrix $A$ is represented by $a_{ij}$ ($i = 1, 2, ..., n,$ $j = 1, 2, ..., m$).
The product of a $n \times m$ matrix $A$ and a $m \times 1$ column vector $b$ is a $n \times 1$ column vector $c$, and $c_i$ is obtained by the following formula:
\\[ c_i = \sum_{j=1}^m a_{ij}b_j = a_{i1}b_1 + a_{i2}b_2 + ... + a_{im}b_m \\]
Constraints
* $1 \leq n, m \leq 100$
* $0 \leq b_i, a_{ij} \leq 1000$
Input
In the first line, two integers $n$ and $m$ are given. In the following $n$ lines, $a_{ij}$ are given separated by a single space character. In the next $m$ lines, $b_i$ is given in a line.
Output
The output consists of $n$ lines. Print $c_i$ in a line.
Example
Input
3 4
1 2 0 1
0 3 0 1
4 1 1 0
1
2
3
0
Output
5
6
9
Submitted Solution:
```
#a???A?????????,b???A??????
a,b=map(int,input().split())
A=[]
B=[]
for i in range(a):
A.append([int(j) for j in input().split()])
for i in range(b):
B.append(int(input()))
for i in range(a):
s=0
for j in range(b):
s+=A[i][j]*B[j]
print(s)
print()
``` | instruction | 0 | 30,059 | 11 | 60,118 |
No | output | 1 | 30,059 | 11 | 60,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ivan plays some computer game. There are n quests in the game. Each quest can be upgraded once, this increases the reward for its completion. Each quest has 3 parameters a_{i}, b_{i}, p_{i}: reward for completing quest before upgrade, reward for completing quest after upgrade (a_{i} < b_{i}) and probability of successful completing the quest.
Each second Ivan can try to complete one quest and he will succeed with probability p_{i}. In case of success Ivan will get the reward and opportunity to upgrade any one quest (not necessary the one he just completed). In case of failure he gets nothing. Quests do not vanish after completing.
Ivan has t seconds. He wants to maximize expected value of his total gain after t seconds. Help him to calculate this value.
Input
First line contains 2 integers n ( 1 ≤ n ≤ 10^{5}) and t ( 1 ≤ t ≤ 10^{10}) — number of quests and total time.
Following n lines contain description of quests. Each description is 3 numbers a_{i} b_{i} p_{i} (1 ≤ a_{i} < b_{i} ≤ 10^{8}, 0 < p_{i} < 1) — reward for completing quest before upgrade, reward for completing quest after upgrade and probability of successful completing of quest. a_{i} and b_{i} are integers. All probabilities are given with at most 9 decimal places.
Output
Print the expected value.
Your answer will be accepted if absolute or relative error does not exceed 10^{-6}. Formally, let your answer be a, and the jury's answer be b. Your answer is considered correct if (|a-b|)/(max(b, 1)) ≤ 10^{-6}.
Examples
Input
3 2
3 1000 0.5
1 2 0.48
3 20 0.3
Output
252.2500000000000
Input
2 2
1 1000 0.1
2 3 0.2
Output
20.7200000000000
Submitted Solution:
```
import sys
n, t = map(int, sys.stdin.readline().strip().split())
a = [0] * n
b = [0] * n
p = [0] * n
for i in range(n):
a[i], b[i], p[i] = map(float, sys.stdin.readline().strip().split())
ans = max(a[i] * p[i] * t for i in range(n))
reward = max(b[i] * p[i] for i in range(n))
ans = max(ans, max(
a[i] * (1 - (1 - p[i]) ** t) + reward * (t - (1 - (1 - p[i]) ** t) / p[i])
for i in range(n)))
print('%.10f' % ans)
``` | instruction | 0 | 30,076 | 11 | 60,152 |
No | output | 1 | 30,076 | 11 | 60,153 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
from collections import defaultdict
n = int(input())
a = list(map(int, input().split()))
t = [0] * n
t[0] = a[0]
for i in range(1, n):
t[i] = t[i - 1] ^ a[i] # a_i ^...^ a_j = t[j] ^ t[i]
r = {0: defaultdict(int), 1: defaultdict(int)}
r[1][0] = 1
res = 0
for i in range(n):
res += r[i % 2][t[i]]
r[i % 2][t[i]] += 1
print(res)
``` | instruction | 0 | 30,101 | 11 | 60,202 |
Yes | output | 1 | 30,101 | 11 | 60,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n=int(input())
b={(0,0):1}
ans,i,x=0,0,0
for a in map(int,input().split()):
x^=a
i+=1
t=b.get((x,i%2),0)
ans+=t
b[x,i%2]=t+1
print(ans)
``` | instruction | 0 | 30,102 | 11 | 60,204 |
Yes | output | 1 | 30,102 | 11 | 60,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n = int(input())
lis = list(map(int,input().split()))
mat=[[0]*(2**20+5) for i in range(2)]
ans=a=0
mat[1][0]=1
for i in range(n):
a = a^lis[i]
ans+=mat[i%2][a]
mat[i%2][a]+=1
print(ans)
``` | instruction | 0 | 30,103 | 11 | 60,206 |
Yes | output | 1 | 30,103 | 11 | 60,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
import os,sys,math
from io import BytesIO, IOBase
from collections import defaultdict,deque,OrderedDict
import bisect as bi
def yes():print('YES')
def no():print('NO')
def I():return (int(input()))
def In():return(map(int,input().split()))
def ln():return list(map(int,input().split()))
def Sn():return input().strip()
BUFSIZE = 8192
#complete the main function with number of test cases to complete greater than x
def find_gt(a, x):
i = bi.bisect_left(a, x)
if i != len(a):
return i
else:
return len(a)
def solve():
n=I()
l=list(In())
ans,x=0,0
dp=[{},{}]
dp[1][0]=1
for i in range(n):
x^=l[i]
ans+=dp[i%2].get(x,0)
if dp[i%2].get(x,-1)!=-1:
dp[i%2][x]+=1
else:
dp[i%2][x]=1
print(ans)
pass
def main():
T=1
for i in range(T):
solve()
M = 998244353
P = 1000000007
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
def print(*args, **kwargs):
"""Prints the values to a stream, or to sys.stdout by default."""
sep, file = kwargs.pop("sep", " "), kwargs.pop("file", sys.stdout)
at_start = True
for x in args:
if not at_start:
file.write(sep)
file.write(str(x))
at_start = False
file.write(kwargs.pop("end", "\n"))
if kwargs.pop("flush", False):
file.flush()
if sys.version_info[0] < 3:
sys.stdin, sys.stdout = FastIO(sys.stdin), FastIO(sys.stdout)
else:
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == '__main__':
main()
``` | instruction | 0 | 30,104 | 11 | 60,208 |
Yes | output | 1 | 30,104 | 11 | 60,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
def fn(lst):
result = 0
for x in lst:
result =result^int(x)
return result
n= int(input())
count=0
a= list(input().split())
for l in range(1,len(a)+1):
for r in range(l,len(a)+1):
if l<=r and (r-l+1)%2==0:
b= int((l+r-1)/2)
b=b-1
l=l-1
r=r-1
m=[]
n=[]
for i in range(l,b+1):
m.append(a[i])
for j in range(b+1,r+1):
n.append(a[j])
if fn(m)==fn(n):
count+=1
print(m)
print(n)
print(count)
``` | instruction | 0 | 30,105 | 11 | 60,210 |
No | output | 1 | 30,105 | 11 | 60,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
def Solve2(array,l,r,count):
#print (l,r)
if r <= len(array) and l < len(array):
if r-l == 1:
return array[l-1]^array[r-1]
if (r+l-1)%2 != 0:
left = Solve2(array,l,l+int((r-l+2)/2)-1,count)
right = Solve2(array,l+int((r-l+2)/2),r+1,count)
else:
left = Solve2(array,l,l+int((r-l+1)/2)-1,count)
right = Solve2(array,l+int((r-l+1)/2),r,count)
if left == right and left :
#print (left)
count[0] += 1
def Solve(array):
count = [0]
n = len(array)
for i in range(n-1):
if array[i] == array[i+1]:
count[0] += 1
for i in range(1,n+1):
k = n
if (k+i-1)%2 != 0:
k -= 1
if k-i >= 1:
#print ('start')
Solve2(array,i,k,count)
return count[0]
def main():
n = int(input())
array = list(map(int,input().split()))
print (Solve(array))
main()
``` | instruction | 0 | 30,106 | 11 | 60,212 |
No | output | 1 | 30,106 | 11 | 60,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
if __name__ == '__main__':
n = int(input())
arr = list(map(int, input().split()))
dp = [arr[0]]
for i in range(1, n):
dp.append(dp[-1] ^ arr[i])
cnt = 0
s = 1
while 2 * s <= n:
for i in range(n - 2 * s + 1):
m = dp[i + s - 1]
cnt += int((dp[i - 1] if i else i) ^ m == dp[i + 2 * s - 1] ^ m)
s *= 2
print(cnt)
``` | instruction | 0 | 30,107 | 11 | 60,214 |
No | output | 1 | 30,107 | 11 | 60,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Sasha likes programming. Once, during a very long contest, Sasha decided that he was a bit tired and needed to relax. So he did. But since Sasha isn't an ordinary guy, he prefers to relax unusually. During leisure time Sasha likes to upsolve unsolved problems because upsolving is very useful.
Therefore, Sasha decided to upsolve the following problem:
You have an array a with n integers. You need to count the number of funny pairs (l, r) (l ≤ r). To check if a pair (l, r) is a funny pair, take mid = (l + r - 1)/(2), then if r - l + 1 is an even number and a_l ⊕ a_{l+1} ⊕ … ⊕ a_{mid} = a_{mid + 1} ⊕ a_{mid + 2} ⊕ … ⊕ a_r, then the pair is funny. In other words, ⊕ of elements of the left half of the subarray from l to r should be equal to ⊕ of elements of the right half. Note that ⊕ denotes the [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
It is time to continue solving the contest, so Sasha asked you to solve this task.
Input
The first line contains one integer n (2 ≤ n ≤ 3 ⋅ 10^5) — the size of the array.
The second line contains n integers a_1, a_2, …, a_n (0 ≤ a_i < 2^{20}) — array itself.
Output
Print one integer — the number of funny pairs. You should consider only pairs where r - l + 1 is even number.
Examples
Input
5
1 2 3 4 5
Output
1
Input
6
3 2 2 3 7 6
Output
3
Input
3
42 4 2
Output
0
Note
Be as cool as Sasha, upsolve problems!
In the first example, the only funny pair is (2, 5), as 2 ⊕ 3 = 4 ⊕ 5 = 1.
In the second example, funny pairs are (2, 3), (1, 4), and (3, 6).
In the third example, there are no funny pairs.
Submitted Solution:
```
n=int(input())
a=list(map(int,input().split()))
x,cnt=0,0
for i in range(n-1):
x^=a[i]
y=0
for j in range(n):
y^=a[j]
if((j-i+1)%2==0) and (x==y):
cnt+=1
x=0
print(cnt)
``` | instruction | 0 | 30,108 | 11 | 60,216 |
No | output | 1 | 30,108 | 11 | 60,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,687 | 11 | 61,374 |
Tags: brute force, implementation
Correct Solution:
```
inp = list(map(int,input().split()))
n=inp[0]
k=inp[1]
inp = list(map(int,input().split()))
count=0
for item in inp:
if(item>k):
count+=1
if(count==0):
print (len(inp))
else:
a=inp
count=0
for i in range(len(a)):
if(a[i]<=k):
count+=1
else:
break
a.reverse()
for i in range(len(a)):
if(a[i]<=k):
count+=1
else:
break
print(count)
``` | output | 1 | 30,687 | 11 | 61,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,688 | 11 | 61,376 |
Tags: brute force, implementation
Correct Solution:
```
def calc(n,m,a):
i=0
j=n-1
count=0
while i<=j:
if a[i]<=m:
count+=1
i+=1
elif a[j]<=m:
count+=1
j-=1
elif a[i]>m and a[j]>m:
break
print(count)
n,m=list(map(int,input().split()))
a=list(map(int,input().split()))
calc(n,m,a)
``` | output | 1 | 30,688 | 11 | 61,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,689 | 11 | 61,378 |
Tags: brute force, implementation
Correct Solution:
```
hm, k = map(int, input().split())
a = list(map(int,input().split()))
cnt = 0
l, r = 0, len(a) - 1
while (l <= r and a[l] <= k):
l += 1
cnt += 1
while (l <= r and a[r] <= k):
r -= 1
cnt += 1
print(cnt)
``` | output | 1 | 30,689 | 11 | 61,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,690 | 11 | 61,380 |
Tags: brute force, implementation
Correct Solution:
```
n,k = map(int, input().split());
a = [None] * n;
completed = 0;
a = input().split();
for i in range(0,n):
a[i] = int(a[i]);
front = 0;
end = n-1;
while a[front]<=k and len(a)>0:
#print(a, front);
if a[front]<=k:
del a[front];
completed+=1;
end = len(a)-1;
if len(a)<=0:
break;
if len(a)>0:
while a[end]<=k and len(a)>0:
#print(a, end);
if a[end]<=k:
del a[end];
completed+=1;
end = len(a)-1;
if len(a)<=0:
break;
print(completed);
``` | output | 1 | 30,690 | 11 | 61,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,691 | 11 | 61,382 |
Tags: brute force, implementation
Correct Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
count = 0
while len(a):
if (a[0] <= k):
count += 1
del a[0]
elif (a[-1] <= k):
count += 1
del a[-1]
else:
break
print(count)
``` | output | 1 | 30,691 | 11 | 61,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,692 | 11 | 61,384 |
Tags: brute force, implementation
Correct Solution:
```
n, k = map(int, input().split())
arr = list(map(int, input().split()))
ans = 0
for i in range(n):
if arr[i] <= k:
ans += 1
else:
break
for i in range(n - 1, -1, -1):
if arr[i] <= k:
ans += 1
else:
break
print(min(n, ans))
``` | output | 1 | 30,692 | 11 | 61,385 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,693 | 11 | 61,386 |
Tags: brute force, implementation
Correct Solution:
```
n, k = [int(z) for z in input().split()]
a = [int(z) for z in input().split()]
ans = 0
for i in range(n):
if a[i] <= k:
ans += 1
else:
break
if ans == n:
print(ans)
else:
for i in range(n - 1, 0, -1):
if a[i] <= k:
ans += 1
else:
break
print(ans)
``` | output | 1 | 30,693 | 11 | 61,387 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems. | instruction | 0 | 30,694 | 11 | 61,388 |
Tags: brute force, implementation
Correct Solution:
```
n,m =map(int,input().split())
S=input()
a=[int(i) for i in S.split()]
ans=0
for i in range(n):
if a[i]<=m:
ans+=1
else:
break
if ans <n:
for i in reversed(a):
if i<=m:
ans+=1
else:
break
print(ans)
``` | output | 1 | 30,694 | 11 | 61,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
i = 0
while i < n:
if a[i] > k:
break
i += 1
j = n-1
while j >= 0:
if a[j] > k:
break
j -= 1
print(min(n, i + n-1-j))
``` | instruction | 0 | 30,695 | 11 | 61,390 |
Yes | output | 1 | 30,695 | 11 | 61,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
c = int(0)
for i in range(n):
if (a[i] <= k):
c += 1
else:
break
for i in range(n):
if (a[n - i - 1] <= k):
c += 1
else:
break
print(min(n, c))
``` | instruction | 0 | 30,696 | 11 | 61,392 |
Yes | output | 1 | 30,696 | 11 | 61,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n , m = map(int, input().split())
lst = (list(map(int,input().split())))
for i in range (n):
if(lst[i]<=m and lst[i]!=-1):lst[i]=-1
else : break
rlst = list(reversed(lst))
for i in range(n):
if(rlst[i]<=m and rlst[i]!=-1):rlst[i]=-1
else : break
c= 0
for i in range(n):
if(rlst[i]==-1):c+=1
print(c)
``` | instruction | 0 | 30,697 | 11 | 61,394 |
Yes | output | 1 | 30,697 | 11 | 61,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
a = list(map(int, input().split()))
counter = 0
for i in a:
if i <= k:
counter += 1
else:
break
for i in range(n-1, 0, -1):
if a[i] <= k:
counter += 1
else:
break
print(n if counter > n else counter)
``` | instruction | 0 | 30,698 | 11 | 61,396 |
Yes | output | 1 | 30,698 | 11 | 61,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
def A999():
n, k = map(int, input().split())
aList = list(map(int, input().split(' ')))
count = 0
for i in aList:
if k < i:
pass
else:
aList.remove(i)
count += 1
for i in reversed(aList):
if k < i:
break
else:
count += 1
print(count)
if __name__ == '__main__':
A999()
``` | instruction | 0 | 30,699 | 11 | 61,398 |
No | output | 1 | 30,699 | 11 | 61,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n , m = map(int, input().split())
a = list(map(int, input().split()))
head = 0
tail = len(a) - 1
print(tail)
res = 0
while (1):
if ( res == len(a)):
break
if ( a[head] <= m and head != tail):
res += 1
head += 1
if ( a[tail] <= m and tail != head):
res += 1
tail -= 1
if ( a[head] > m and a[tail] > m ):
break
print(res)
``` | instruction | 0 | 30,700 | 11 | 61,400 |
No | output | 1 | 30,700 | 11 | 61,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
n, k = map(int, input().split())
arr = list(map(int, input().split()))
left = right = -1
for i, x in enumerate(arr):
if x > k:
if left == -1:
left = i
else:
right = i
if left == right == -1:
print(n)
else:
print(n - (right - left + 1))
``` | instruction | 0 | 30,701 | 11 | 61,402 |
No | output | 1 | 30,701 | 11 | 61,403 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mishka started participating in a programming contest. There are n problems in the contest. Mishka's problem-solving skill is equal to k.
Mishka arranges all problems from the contest into a list. Because of his weird principles, Mishka only solves problems from one of the ends of the list. Every time, he chooses which end (left or right) he will solve the next problem from. Thus, each problem Mishka solves is either the leftmost or the rightmost problem in the list.
Mishka cannot solve a problem with difficulty greater than k. When Mishka solves the problem, it disappears from the list, so the length of the list decreases by 1. Mishka stops when he is unable to solve any problem from any end of the list.
How many problems can Mishka solve?
Input
The first line of input contains two integers n and k (1 ≤ n, k ≤ 100) — the number of problems in the contest and Mishka's problem-solving skill.
The second line of input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the difficulty of the i-th problem. The problems are given in order from the leftmost to the rightmost in the list.
Output
Print one integer — the maximum number of problems Mishka can solve.
Examples
Input
8 4
4 2 3 1 5 1 6 4
Output
5
Input
5 2
3 1 2 1 3
Output
0
Input
5 100
12 34 55 43 21
Output
5
Note
In the first example, Mishka can solve problems in the following order: [4, 2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6, 4] → [2, 3, 1, 5, 1, 6] → [3, 1, 5, 1, 6] → [1, 5, 1, 6] → [5, 1, 6], so the number of solved problems will be equal to 5.
In the second example, Mishka can't solve any problem because the difficulties of problems from both ends are greater than k.
In the third example, Mishka's solving skill is so amazing that he can solve all the problems.
Submitted Solution:
```
x=list(map(int,input().split()))
y=list(map(int,input().split()))
t=0
for i in range(len(y)//2):
if y[i]<=x[1]:
t=t+1
else:
break
for i in range(-1,-(x[0]-(len(y)//2))-1,-1):
if y[i]<=x[1]:
t=t+1
else:
break
print(t)
``` | instruction | 0 | 30,702 | 11 | 61,404 |
No | output | 1 | 30,702 | 11 | 61,405 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1 | instruction | 0 | 30,923 | 11 | 61,846 |
"Correct Solution:
```
while True:
N,M = map(int,input().split())
if N == M == 0: break
logs = []
for i in range(M):
t,s,d = map(int,input().split())
s,d = s-1,d-1
logs.append((t,s,d))
infected = [0 for i in range(N)]
infected[0] = 1
for t,s,d in sorted(logs):
if infected[s]:
infected[d] = 1
print(sum(infected))
``` | output | 1 | 30,923 | 11 | 61,847 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1 | instruction | 0 | 30,924 | 11 | 61,848 |
"Correct Solution:
```
while 1:
n,m=map(int,input().split())
if n+m==0:break
a=[1]+[0]*(n-1)
b={}
for _ in range(m):t,s,d=map(int,input().split());b[t]=(s,d)
for x in sorted(b):
if a[b[x][0]-1]:a[b[x][1]-1]=1
print(sum(a))
``` | output | 1 | 30,924 | 11 | 61,849 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1 | instruction | 0 | 30,926 | 11 | 61,852 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
Created on Tue Jun 14 15:56:37 2016
"""
while True:
N, M = map(int, input().split())
if N == M == 0:
break
PCs = [False] * N
PCs[0] = True
Packets = {}
for _ in range(M):
t, s, d = map(int, input().split())
Packets[t] = (s, d)
for key in sorted(Packets):
if PCs[Packets[key][0] - 1] == True:
PCs[Packets[key][1] - 1] = True
# print('PC'+str(Packets[key][1])+' is infected')
print(PCs.count(True))
``` | output | 1 | 30,926 | 11 | 61,853 |
Provide a correct Python 3 solution for this coding contest problem.
Adam Ivan is working as a system administrator at Soy Group, Inc. He is now facing at a big trouble: a number of computers under his management have been infected by a computer virus. Unfortunately, anti-virus system in his company failed to detect this virus because it was very new.
Adam has identified the first computer infected by the virus and collected the records of all data packets sent within his network. He is now trying to identify which computers have been infected. A computer is infected when receiving any data packet from any infected computer. The computer is not infected, on the other hand, just by sending data packets to infected computers.
It seems almost impossible for him to list all infected computers by hand, because the size of the packet records is fairly large. So he asked you for help: write a program that can identify infected computers.
Input
The input consists of multiple datasets. Each dataset has the following format:
N M
t1 s1 d1
t2 s2 d2
...
tM sM dM
N is the number of computers; M is the number of data packets; ti (1 ≤ i ≤ M) is the time when the i-th data packet is sent; si and di (1 ≤ i ≤ M) are the source and destination computers of the i-th data packet respectively. The first infected computer is indicated by the number 1; the other computers are indicated by unique numbers between 2 and N.
The input meets the following constraints: 0 < N ≤ 20000, 0 ≤ M ≤ 20000, and 0 ≤ ti ≤ 109 for 1 ≤ i ≤ N; all ti 's are different; and the source and destination of each packet are always different.
The last dataset is followed by a line containing two zeros. This line is not a part of any dataset and should not be processed.
Output
For each dataset, print the number of computers infected by the computer virus.
Example
Input
3 2
1 1 2
2 2 3
3 2
2 3 2
1 2 1
0 0
Output
3
1 | instruction | 0 | 30,927 | 11 | 61,854 |
"Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 998244353
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def pf(s): return print(s, flush=True)
def main():
rr = []
while True:
n,m = LI()
if n == 0 and m == 0:
break
a = [LI() for _ in range(m)]
a.sort()
u = set([1])
for t,s,d in a:
if s in u:
u.add(d)
rr.append(len(u))
return '\n'.join(map(str, rr))
print(main())
``` | output | 1 | 30,927 | 11 | 61,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n = int(input())
for i in range(n):
print(" ".join([str(j % n) for j in range(i, n + i)]))
``` | instruction | 0 | 31,116 | 11 | 62,232 |
No | output | 1 | 31,116 | 11 | 62,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n=int(input())
s=''
for i in range(n//2):
s+=' '.join(str((j-2*i)%n) for j in range(n))
s+='\n'
s+=' '.join(str((j-2*i)%n^1) for j in range(n))
s+='\n'
print(s[:-1])
``` | instruction | 0 | 31,117 | 11 | 62,234 |
No | output | 1 | 31,117 | 11 | 62,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Before the start of the football season in Berland a strange magic ritual is held. The most experienced magicians have to find a magic matrix of the size n × n (n is even number). Gods will never allow to start the championship without it. Matrix should contain integers from 0 to n - 1, main diagonal should contain only zeroes and matrix should be symmetric. Moreover, all numbers in each row should be different. Magicians are very tired of the thinking process, so they ask you to write a program to find such matrix.
Input
The first line contains one integer n (2 ≤ n ≤ 1000), n is even.
Output
Output n lines with n numbers each — the required matrix. Separate numbers with spaces. If there are several solutions, output any.
Examples
Input
2
Output
0 1
1 0
Input
4
Output
0 1 3 2
1 0 2 3
3 2 0 1
2 3 1 0
Submitted Solution:
```
n = int(input())
for i in range(n):
print(" ".join([str((j - i) % n) for j in range(n)]))
``` | instruction | 0 | 31,118 | 11 | 62,236 |
No | output | 1 | 31,118 | 11 | 62,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Smart Beaver from ABBYY invented a new message encryption method and now wants to check its performance. Checking it manually is long and tiresome, so he decided to ask the ABBYY Cup contestants for help.
A message is a sequence of n integers a1, a2, ..., an. Encryption uses a key which is a sequence of m integers b1, b2, ..., bm (m ≤ n). All numbers from the message and from the key belong to the interval from 0 to c - 1, inclusive, and all the calculations are performed modulo c.
Encryption is performed in n - m + 1 steps. On the first step we add to each number a1, a2, ..., am a corresponding number b1, b2, ..., bm. On the second step we add to each number a2, a3, ..., am + 1 (changed on the previous step) a corresponding number b1, b2, ..., bm. And so on: on step number i we add to each number ai, ai + 1, ..., ai + m - 1 a corresponding number b1, b2, ..., bm. The result of the encryption is the sequence a1, a2, ..., an after n - m + 1 steps.
Help the Beaver to write a program that will encrypt messages in the described manner.
Input
The first input line contains three integers n, m and c, separated by single spaces.
The second input line contains n integers ai (0 ≤ ai < c), separated by single spaces — the original message.
The third input line contains m integers bi (0 ≤ bi < c), separated by single spaces — the encryption key.
The input limitations for getting 30 points are:
* 1 ≤ m ≤ n ≤ 103
* 1 ≤ c ≤ 103
The input limitations for getting 100 points are:
* 1 ≤ m ≤ n ≤ 105
* 1 ≤ c ≤ 103
Output
Print n space-separated integers — the result of encrypting the original message.
Examples
Input
4 3 2
1 1 1 1
1 1 1
Output
0 1 1 0
Input
3 1 5
1 2 3
4
Output
0 1 2
Note
In the first sample the encryption is performed in two steps: after the first step a = (0, 0, 0, 1) (remember that the calculations are performed modulo 2), after the second step a = (0, 1, 1, 0), and that is the answer.
Submitted Solution:
```
n,m,c=map(int,input().split())
a=list(map(int,input().split()))
b=list(map(int,input().split()))
sum=0
for i in range(n):
if i<m:
sum=(sum+b[i])%c
if i>=n-m+1:
sum=(sum+b[i-(n-m+1)])%c
a[i]=(a[i]+sum)%c
print(' '.join(map(str,a)))
``` | instruction | 0 | 31,255 | 11 | 62,510 |
No | output | 1 | 31,255 | 11 | 62,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Smart Beaver from ABBYY invented a new message encryption method and now wants to check its performance. Checking it manually is long and tiresome, so he decided to ask the ABBYY Cup contestants for help.
A message is a sequence of n integers a1, a2, ..., an. Encryption uses a key which is a sequence of m integers b1, b2, ..., bm (m ≤ n). All numbers from the message and from the key belong to the interval from 0 to c - 1, inclusive, and all the calculations are performed modulo c.
Encryption is performed in n - m + 1 steps. On the first step we add to each number a1, a2, ..., am a corresponding number b1, b2, ..., bm. On the second step we add to each number a2, a3, ..., am + 1 (changed on the previous step) a corresponding number b1, b2, ..., bm. And so on: on step number i we add to each number ai, ai + 1, ..., ai + m - 1 a corresponding number b1, b2, ..., bm. The result of the encryption is the sequence a1, a2, ..., an after n - m + 1 steps.
Help the Beaver to write a program that will encrypt messages in the described manner.
Input
The first input line contains three integers n, m and c, separated by single spaces.
The second input line contains n integers ai (0 ≤ ai < c), separated by single spaces — the original message.
The third input line contains m integers bi (0 ≤ bi < c), separated by single spaces — the encryption key.
The input limitations for getting 30 points are:
* 1 ≤ m ≤ n ≤ 103
* 1 ≤ c ≤ 103
The input limitations for getting 100 points are:
* 1 ≤ m ≤ n ≤ 105
* 1 ≤ c ≤ 103
Output
Print n space-separated integers — the result of encrypting the original message.
Examples
Input
4 3 2
1 1 1 1
1 1 1
Output
0 1 1 0
Input
3 1 5
1 2 3
4
Output
0 1 2
Note
In the first sample the encryption is performed in two steps: after the first step a = (0, 0, 0, 1) (remember that the calculations are performed modulo 2), after the second step a = (0, 1, 1, 0), and that is the answer.
Submitted Solution:
```
n, m, c = map(int, input().split())
a = list(map(int, input().split()))
b = list(map(int, input().split()))
s = 0
for i in range(n):
if i < m: s += b[i]
if i > n - m: s -= b[i - n + m]
a[i] = (a[i] + s) % c
print(' '.join(str(i) for i in a))
``` | instruction | 0 | 31,256 | 11 | 62,512 |
No | output | 1 | 31,256 | 11 | 62,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
s = input()
val = eval(s)
for i in range(len(s)):
if s[i] == '+':
j = i + 1
c = -5
while j < len(s) and s[j] != '+' and s[j] != '-':
c *= 10
j += 1
val += c
elif s[i] == '-':
j = i + 1
c = 3
while j < len(s) and s[j] != '+' and s[j] != '-':
c *= 10
j += 1
val += c
print(val)
``` | instruction | 0 | 31,528 | 11 | 63,056 |
Yes | output | 1 | 31,528 | 11 | 63,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
ans=0
op=1
now=0
s=input()
l=len(s)
for i in range(l):
if s[i]=='+':
ans=ans+op*now
now=0
op=1
elif s[i]=='-':
ans=ans+op*now
now=0
op=-1
now=now*10+ord(s[i])-48
ans=ans+op*now
print(ans)
``` | instruction | 0 | 31,529 | 11 | 63,058 |
Yes | output | 1 | 31,529 | 11 | 63,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
s = input()
val = eval(s)
for i in range(len(s)):
if s[i] == '+':
c = -5
j = i+1
while j < len(s) and s[j] != '+' and s[j] != '-':
j += 1
c *= 10
val += c
if s[i] == '-':
c = 3
j = i+1
while j < len(s) and s[j] != '+' and s[j] != '-':
j += 1
c *= 10
val += c
print(val)
``` | instruction | 0 | 31,530 | 11 | 63,060 |
Yes | output | 1 | 31,530 | 11 | 63,061 |
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