message stringlengths 2 39.6k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 219 108k | cluster float64 11 11 | __index_level_0__ int64 438 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
import re
s=input()
print(eval(s)+eval(re.sub("\d","0",s).replace("-","*3").replace("+","-5").replace("*","+")))
``` | instruction | 0 | 31,531 | 11 | 63,062 |
Yes | output | 1 | 31,531 | 11 | 63,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
a = input()
if a == '2+2':
print(-46)
elif a == '112-37':
print(375)
elif a == '255+255+255+255+255+255+255+255+255+255':
print(-42450)
elif a == '0-255-255-255-255-255-255-255-255-255':
print(24705)
else:
print(4)
``` | instruction | 0 | 31,532 | 11 | 63,064 |
No | output | 1 | 31,532 | 11 | 63,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
n=eval(input())
if n==4:
print(-42)
else:
print(n)
``` | instruction | 0 | 31,533 | 11 | 63,066 |
No | output | 1 | 31,533 | 11 | 63,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
def main():
s = input()
if s.count('-') + s.count('+') > 1:
print(eval(s))
else:
s = s.replace('-', '+300-')
s = s.replace('+', '-50+')
print(eval(s))
``` | instruction | 0 | 31,534 | 11 | 63,068 |
No | output | 1 | 31,534 | 11 | 63,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
One very experienced problem writer decided to prepare a problem for April Fools Day contest. The task was very simple - given an arithmetic expression, return the result of evaluating this expression. However, looks like there is a bug in the reference solution...
Input
The only line of input data contains the arithmetic expression. The expression will contain between 2 and 10 operands, separated with arithmetic signs plus and/or minus. Each operand will be an integer between 0 and 255, inclusive.
Output
Reproduce the output of the reference solution, including the bug.
Examples
Input
8-7+6-5+4-3+2-1-0
Output
4
Input
2+2
Output
-46
Input
112-37
Output
375
Submitted Solution:
```
n=str(input())
if n=='8-7+6-5+4-3+2-1-0':print(4)
if n=='2+2':print(-46)
if n=='112-37':print(375)
``` | instruction | 0 | 31,535 | 11 | 63,070 |
No | output | 1 | 31,535 | 11 | 63,071 |
Provide a correct Python 3 solution for this coding contest problem.
problem
There are $ N $ propositions, named $ 1, 2, \ cdots, N $, respectively. Also, $ M $ information about the propositions is given. The $ i $ th information is "$ a_i $$". Given in the form "b_i $", which means that $ a_i $ is $ b_i $. ("If" is a logical conditional and the transition law holds.) $ For each proposition $ i $ Output all propositions that have the same value as i $ in ascending order. However, proposition $ i $ and proposition $ i $ are always the same value. Proposition $ X $ and proposition $ Y $ have the same value as "$ if $ X $". It means "Y $" and "$ X $ if $ Y $".
output
On the $ i $ line, output all propositions that have the same value as the proposition $ i $, separated by blanks in ascending order. Also, output a line break at the end of each line.
Example
Input
5 2
1 2
2 1
Output
1 2
1 2
3
4
5 | instruction | 0 | 31,753 | 11 | 63,506 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
input = sys.stdin.readline
def inpl(): return list(map(int, input().split()))
N, M = inpl()
G = [[] for _ in range(N)]
rG = [[] for _ in range(N)]
for i in range(M):
a, b = inpl()
G[a-1].append(b-1)
rG[b-1].append(a-1)
def SCC(G, rG):
N = len(G)
def dfs(i):
nonlocal t, rorder, searched
searched[i] = True
for j in G[i]:
if not searched[j]:
dfs(j)
rorder[t] = i
t += 1
def rdfs(i):
nonlocal t, group, g
group[i] = g
for j in rG[i]:
if group[j] == -1:
rdfs(j)
t = 0
rorder = [-1]*N
searched = [0]*N
group = [-1]*N
for i in range(N):
if not searched[i]:
dfs(i)
g = 0
for i in range(N-1, -1, -1):
if group[rorder[i]] == -1:
rdfs(rorder[i])
g += 1
return group, g
group, g = SCC(G, rG)
ans = [[] for _ in range(g)]
for i in range(N):
ans[group[i]].append(i+1)
for i in range(N):
print(*ans[group[i]])
``` | output | 1 | 31,753 | 11 | 63,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for i in range(int(input())):
n = int(input())
array = [1]*n
print(*array, sep=" ")
``` | instruction | 0 | 31,908 | 11 | 63,816 |
Yes | output | 1 | 31,908 | 11 | 63,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for t in range(int(input())):
n=int(input())
# l=list(map(int,input().split()))
l=[5]*n
print(*l)
``` | instruction | 0 | 31,909 | 11 | 63,818 |
Yes | output | 1 | 31,909 | 11 | 63,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
for yeet in range(int(input())):
for bruh in range(int(input())):
print(1, end = ' ')
print()
``` | instruction | 0 | 31,910 | 11 | 63,820 |
Yes | output | 1 | 31,910 | 11 | 63,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
t = int(input())
while t > 0:
t -= 1
n = int(input())
ans = ['1' for i in range(n)]
print(' '.join(ans))
``` | instruction | 0 | 31,911 | 11 | 63,822 |
Yes | output | 1 | 31,911 | 11 | 63,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
n = int(input())
lengs = []
for i in range(n):
lengs.append(int(input()))
masses = []
for leng in lengs:
masses.append([])
app = 1000
for i in range (leng):
masses[len(masses) - 1].append(str(app))
app -= 1
for i in range(len(masses)):
st = ' '.join(masses[i])
print(st)
``` | instruction | 0 | 31,912 | 11 | 63,824 |
No | output | 1 | 31,912 | 11 | 63,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
import heapq as hq
from heapq import heappop,heappush
from collections import deque,defaultdict
def inp():
return (int(input()))
def inlt():
return (list(map(int,input().split())))
def insr():
s=input()
return (list(s[:len(s)]))
def invr():
return (map(int,input().split()))
def subset_sum_count(arr,n,sum):
dp=[[0 for _ in range(sum+1)] for _ in range(n+1)]
for i in range(n+1):
for j in range(sum+1):
if j==0:
dp[i][j]=1
elif arr[i-1]<=j:
dp[i][j]=dp[i-1][j-arr[i-1]]+dp[i-1][j]
else:
dp[i][j]=dp[i-1][j]
return dp[n][sum]
def prefix(a):
pre=[]
pre.append(a[0])
for i in range(1,len(a)):
pre.append(pre[i-1]+a[i])
return pre
def binary_search(func,lo,hi,abs_prec=1e-7):
""" Locate the first value x s.t. func(x) = True within [lo, hi] """
while abs(hi-lo)>abs_prec:
mi=lo+(hi-lo)/2
if func(mi):
hi=mi
else:
lo=mi
return (lo+hi)/2
def ternary_search(func,lo,hi,abs_prec=1e-7):
""" Find maximum of unimodal function func() within [lo, hi] """
while abs(hi-lo)>abs_prec:
lo_third=lo+(hi-lo)/3
hi_third=hi-(hi-lo)/3
if func(lo_third)<func(hi_third):
lo=lo_third
else:
hi=hi_third
return (lo+hi)/2
def discrete_binary_search(func,lo,hi):
""" Locate the first value x s.t. func(x) = True within [lo, hi] """
while lo<hi:
mi=lo+(hi-lo)//2
if func(mi):
hi=mi
else:
lo=mi+1
return lo
def discrete_ternary_search(func,lo,hi):
""" Find the first maximum of unimodal function func() within [lo, hi] """
while lo<=hi:
lo_third=lo+(hi-lo)//3
hi_third=lo+(hi-lo)//3+(1 if 0<hi-lo<3 else (hi-lo)//3)
if func(lo_third)<func(hi_third):
lo=lo_third+1
else:
hi=hi_third-1
return lo
return -1
def right_rotate(a,s):
return a[s:]+a[:s]
def dec_to_bin(x):
return int(bin(x)[2:])
def str_to_integer_list(n):
a=[]
for i in range(len(n)):
a.append(int(n[i]))
return a
def list_to_str(l):
s=""
for i in l:
s+=str(i)
return s
def dijkstra(s,N,E):
visited=set()
dist={}
for i in range(1,N+1):
dist[i]=1<<29
queue=[(dist[i],i) for i in range(1,N+1)]
hq.heappush(queue,(0,s))
dist[s]=0
while queue:
d,u=hq.heappop(queue)
if u in visited:
continue
#Relax all the neighbours of u
for t in E[u]:
v,r=t
if dist[v]>d+r:
dist[v]=d+r
hq.heappush(queue,(dist[v],v))
#Node u has been processed
visited.add(u)
return dist
def prime_sieve(n):
"""returns a sieve of primes >= 5 and < n"""
flag=n%6==2
sieve=bytearray((n//3+flag>>3)+1)
for i in range(1,int(n**0.5)//3+1):
if not (sieve[i>>3]>>(i&7))&1:
k=(3*i+1)|1
for j in range(k*k//3,n//3+flag,2*k):
sieve[j>>3]|=1<<(j&7)
for j in range(k*(k-2*(i&1)+4)//3,n//3+flag,2*k):
sieve[j>>3]|=1<<(j&7)
return sieve
def prime_list(n):
"""returns a list of primes <= n"""
res=[]
if n>1:
res.append(2)
if n>2:
res.append(3)
if n>4:
sieve=prime_sieve(n+1)
res.extend(3*i+1|1 for i in range(1,(n+1)//3+(n%6==1)) if not (sieve[i>>3]>>(i&7))&1)
return res
def dijkstra(n,graph,start):
""" Uses Dijkstra's algortihm to find the shortest path between in a graph. """
dist,parents=[float("inf")]*n,[-1]*n
dist[start]=0
queue=[(0,start)]
while queue:
path_len,v=heappop(queue)
if path_len==dist[v]:
for w,edge_len in graph[v]:
if edge_len+path_len<dist[w]:
dist[w],parents[w]=edge_len+path_len,v
heappush(queue,(edge_len+path_len,w))
return dist,parents
def path(start,end,parent):
path=[end]
while path[-1]!=start:
path.append(parent[path[-1]])
path.reverse()
return path
def bfs(graph,start,goal):
"""
finds a shortest path in undirected `graph` between `start` and `goal`.
If no path is found, returns `None`
"""
if start==goal:
return [start]
visited={start}
queue=deque([(start,[])])
while queue:
current,path=queue.popleft()
visited.add(current)
for neighbor in graph[current]:
if neighbor==goal:
return path+[current,neighbor]
if neighbor in visited:
continue
queue.append((neighbor,path+[current]))
visited.add(neighbor)
return None # no path found. not strictly needed
'''for _ in range(int(input())):
n,m=list(map(int,input().split()))
graph=defaultdict(list)
distance=[-1]*(n+1)
visited=[False]*(n+1)
for _ in range(m):
x,y=list(map(int,input().split()))
graph[x].append(y)
graph[y].append(x)'''
'''for _ in range(int(input())):
n,m=list(map(int,input().split()))
graph=[[]for _ in range(n+1)]
distance=[-1]*(n+1)
visited=[False]*(n+1)
for _ in range(m):
x,y,w=list(map(int,input().split()))
graph[x].append([y,w])
graph[y].append([x,w])'''
import os
import sys
from io import BytesIO,IOBase
def p(board):
for i in range(8):
s=""
for j in range(8):
s+=board[i][j]
print(s)
def main():
for x in range(inp()):
n=inp()
a=[1]*n
print(a)
# region fastio
BUFSIZE=8192
class FastIO(IOBase):
newlines=0
def __init__(self,file):
self._fd=file.fileno()
self.buffer=BytesIO()
self.writable="x" in file.mode or "r" not in file.mode
self.write=self.buffer.write if self.writable else None
def read(self):
while True:
b=os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
if not b:
break
ptr=self.buffer.tell()
self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
self.newlines=0
return self.buffer.read()
def readline(self):
while self.newlines==0:
b=os.read(self._fd,max(os.fstat(self._fd).st_size,BUFSIZE))
self.newlines=b.count(b"\n")+(not b)
ptr=self.buffer.tell()
self.buffer.seek(0,2),self.buffer.write(b),self.buffer.seek(ptr)
self.newlines-=1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd,self.buffer.getvalue())
self.buffer.truncate(0),self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self,file):
self.buffer=FastIO(file)
self.flush=self.buffer.flush
self.writable=self.buffer.writable
self.write=lambda s:self.buffer.write(s.encode("ascii"))
self.read=lambda:self.buffer.read().decode("ascii")
self.readline=lambda:self.buffer.readline().decode("ascii")
sys.stdin,sys.stdout=IOWrapper(sys.stdin),IOWrapper(sys.stdout)
input=lambda:sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__=="__main__":
main()
``` | instruction | 0 | 31,913 | 11 | 63,826 |
No | output | 1 | 31,913 | 11 | 63,827 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
t = int(input())
while t > 0 :
n = int(input())
arr = [2*x+1 for x in range(n)]
print(*arr)
t -= 1
``` | instruction | 0 | 31,914 | 11 | 63,828 |
No | output | 1 | 31,914 | 11 | 63,829 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You have been blessed as a child of Omkar. To express your gratitude, please solve this problem for Omkar!
An array a of length n is called complete if all elements are positive and don't exceed 1000, and for all indices x,y,z (1 ≤ x,y,z ≤ n), a_{x}+a_{y} ≠ a_{z} (not necessarily distinct).
You are given one integer n. Please find any complete array of length n. It is guaranteed that under given constraints such array exists.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 1000) — the number of test cases. Description of the test cases follows.
The only line of each test case contains one integer n (1 ≤ n ≤ 1000).
It is guaranteed that the sum of n over all test cases does not exceed 1000.
Output
For each test case, print a complete array on a single line. All elements have to be integers between 1 and 1000 and for all indices x,y,z (1 ≤ x,y,z ≤ n) (not necessarily distinct), a_{x}+a_{y} ≠ a_{z} must hold.
If multiple solutions exist, you may print any.
Example
Input
2
5
4
Output
1 5 3 77 12
384 384 44 44
Note
It can be shown that the outputs above are valid for each test case. For example, 44+44 ≠ 384.
Below are some examples of arrays that are NOT complete for the 1st test case:
[1,2,3,4,5]
Notice that a_{1}+a_{2} = a_{3}.
[1,3000,1,300,1]
Notice that a_{2} = 3000 > 1000.
Submitted Solution:
```
n = int(input())
for i in range(n):
j = int(input())
for k in range(j):
print(1,end=" ")
``` | instruction | 0 | 31,915 | 11 | 63,830 |
No | output | 1 | 31,915 | 11 | 63,831 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,920 | 11 | 63,840 |
Tags: greedy, implementation, math
Correct Solution:
```
import sys
import collections as cc
import bisect as bi
I=lambda:list(map(int,input().split()))
for tc in range(int(input())):
n,k=I()
l=I()
if l.count(k)==n:
print(0)
continue
else:
s=0
for i in range(n):
s+=(l[i]-k)
if s==0 or k in l:
print(1)
else:
print(2)
``` | output | 1 | 31,920 | 11 | 63,841 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,921 | 11 | 63,842 |
Tags: greedy, implementation, math
Correct Solution:
```
import sys
input = sys.stdin.readline
t = int(input())
for ii in range(t):
n, x = map(int,input().split())
A = list(map(int,input().split()))
B = []
c = A.count(x)
for i in range(n):
if A[i] != x:
B.append(A[i])
if B == []:
print(0)
elif c > 0 or sum(B) == x*len(B):
print(1)
else:
print(2)
``` | output | 1 | 31,921 | 11 | 63,843 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,922 | 11 | 63,844 |
Tags: greedy, implementation, math
Correct Solution:
```
from sys import stdin, stdout
import math
t=int(stdin.readline())
for _ in range(t):
n,k=map(int,stdin.readline().split())
arr=list(map(int,stdin.readline().split()))
sume=0
counter=0
flag=0
for i in range(n):
if arr[i]!=k:
sume+=(k-arr[i])
counter+=1
else:
flag-=1
if counter==0:
print(0)
else:
if sume==(n-counter)*k or flag<=-1 :
print(1)
else:
print(2)
``` | output | 1 | 31,922 | 11 | 63,845 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,923 | 11 | 63,846 |
Tags: greedy, implementation, math
Correct Solution:
```
z,zz=input,lambda:list(map(int,z().split()))
zzz=lambda:[int(i) for i in stdin.readline().split()]
szz,graph,mod,szzz=lambda:sorted(zz()),{},10**9+7,lambda:sorted(zzz())
from string import *
from re import *
from collections import *
from queue import *
from sys import *
from collections import *
from math import *
from heapq import *
from itertools import *
from bisect import *
from collections import Counter as cc
from math import factorial as f
from bisect import bisect as bs
from bisect import bisect_left as bsl
from itertools import accumulate as ac
from itertools import permutations as permu
def lcd(xnum1,xnum2):return (xnum1*xnum2//gcd(xnum1,xnum2))
def prime(x):
p=ceil(x**.5)+1
for i in range(2,p):
if (x%i==0 and x!=2) or x==0:return 0
return 1
def dfs(u,visit,graph):
visit[u]=True
for i in graph[u]:
if not visit[i]:
dfs(i,visit,graph)
###########################---Test-Case---#################################
"""
"""
###########################---START-CODING---##############################
num=1
num=int(z())
for _ in range( num ):
n,x=zzz()
arr=szzz()
lst=[]
for i in arr:
lst.append((i-x))
if len(set(lst))==1 and list(set(lst))[0]==0:
print(0)
continue
if sum(lst)==0:
print(1)
continue
if x in arr:
print(1)
continue
print(2)
``` | output | 1 | 31,923 | 11 | 63,847 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,924 | 11 | 63,848 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,x=[int(x) for x in input().split()]
array=[int(x) for x in input().split()]
if len(set(array))==1 and array[0]==array[1] and x==array[0]:
print(0)
elif x in array or (sum(array))/n==float(x):
print(1)
else:
print(2)
``` | output | 1 | 31,924 | 11 | 63,849 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,925 | 11 | 63,850 |
Tags: greedy, implementation, math
Correct Solution:
```
import sys, math
import io, os
#data = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
from bisect import bisect_left as bl, bisect_right as br, insort
from heapq import heapify, heappush, heappop
from collections import defaultdict as dd, deque, Counter
# from itertools import permutations,combinations
def data(): return sys.stdin.readline().strip()
def mdata(): return list(map(int, data().split()))
def outl(var): sys.stdout.write(' '.join(map(str, var)) + '\n')
def out(var): sys.stdout.write(str(var) + '\n')
from decimal import Decimal
# from fractions import Fraction
# sys.setrecursionlimit(100000)
mod = 998244353
INF=float('inf')
for t in range(int(data())):
n,x=mdata()
a=mdata()
if max(a)==min(a)==x:
out(0)
elif x in a or sum(a)==n*x:
out(1)
else:
out(2)
``` | output | 1 | 31,925 | 11 | 63,851 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,926 | 11 | 63,852 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,x=map(int,input().split())
l=list(map(int,input().split()))
if(l.count(x)==len(l)):
print(0)
elif(l.count(x)>0 or sum(l)==n*x):
print(1)
else:
print(2)
``` | output | 1 | 31,926 | 11 | 63,853 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4. | instruction | 0 | 31,927 | 11 | 63,854 |
Tags: greedy, implementation, math
Correct Solution:
```
from math import pow
t = int(input())
for _ in range(t):
inp = list(map(int, input().split()))
n, x = inp[0], inp[1]
a = list(map(int, input().split()))
s = sum(a)
if s % n == 0 and s // n == x or x in a:
for i in range(n):
if a[i] != x:
print(1)
break
if i == n-1:
print(0)
else:
print(2)
``` | output | 1 | 31,927 | 11 | 63,855 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def ans(a, n, k):
same = 0
for i in a:
if i==k:
same+=1
if same==n:
return(0)
if sum(a)%n==0 and sum(a)//n==k:
return(1)
if same>0:
return(1)
return(2)
m = int(input())
for i in range(m):
brr = input().split()
n = int(brr[0])
k = int(brr[1])
arr = input().split()
a = []
for i in arr:
a.append(int(i))
print(ans(a, n, k))
``` | instruction | 0 | 31,928 | 11 | 63,856 |
Yes | output | 1 | 31,928 | 11 | 63,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
for j in range(int(input())):
n,vir = input().split()
a = [int(x) for x in input().split()]
neg,pos = 0, 0
if all(map(lambda x: x == int(vir), a)):
print(0)
elif any(map(lambda x: x == int(vir), a)):
print(1)
else:
for i in a:
if i < int(vir):
neg += abs(int(vir) - i)
else:
pos += abs(i - int(vir))
if neg == pos:
print(1)
else:
print(2)
``` | instruction | 0 | 31,929 | 11 | 63,858 |
Yes | output | 1 | 31,929 | 11 | 63,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def solve():
# put code here
n,x=[int(v) for v in input().split()]
arr=[int(v) for v in input().split()]
if all(x==v for v in arr):
print(0)
elif x in arr or sum(v-x for v in arr)==0:
print(1)
else:
print(2)
t = int(input())
for _ in range(t):
solve()
``` | instruction | 0 | 31,930 | 11 | 63,860 |
Yes | output | 1 | 31,930 | 11 | 63,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
for _ in range(int(input())):
n,x=map(int,input().split())
arr=list(map(int,input().split()))
ct=arr.count(x)
if ct==n:
print(0)
elif ct>=1:
print(1)
else:
s=sum(arr)
if s%n==0 and (s//n)==x:
print(1)
else:
print(2)
``` | instruction | 0 | 31,931 | 11 | 63,862 |
Yes | output | 1 | 31,931 | 11 | 63,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def ans(a, n, k):
same = 0
more = 0
less = 0
for i in a:
if i==k:
same+=1
elif i>k:
more+=1
else:
less+=1
if same==n:
return(0)
if sum(a)%n==0 and sum(a)//n==k:
return(1)
if same>0 and sum(a)%n==0:
return(1)
return(min(more,less))
m = int(input())
for i in range(m):
brr = input().split()
n = int(brr[0])
k = int(brr[1])
arr = input().split()
a = []
for i in arr:
a.append(int(i))
print(ans(a, n, k))
``` | instruction | 0 | 31,932 | 11 | 63,864 |
No | output | 1 | 31,932 | 11 | 63,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import threading
from bisect import bisect_right
from math import gcd,log
from collections import Counter
from pprint import pprint
# arr=[1]
# i=1
# while i <100:
# arr.append(2*arr[-1]+2**(i+1))
# i=2*i+1
# print(arr)
def main():
n,x=map(int,input().split())
arr=list(map(lambda it:int(it)-x,input().split()))
# print(arr)
if any(arr):
if sum(arr)==0:
print(1)
else:
print(2)
else:
print(0)
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
for _ in range(int(input())):
main()
``` | instruction | 0 | 31,933 | 11 | 63,866 |
No | output | 1 | 31,933 | 11 | 63,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def MI():return (map(int,input().split()))
for _ in range(int(input())):
n,x=MI()
arr=list(MI())
if arr.count(x)==n:
print(0)
elif sum(arr)%n==0 and sum(arr)//n==x:
print(1)
else:
print(2)
``` | instruction | 0 | 31,934 | 11 | 63,868 |
No | output | 1 | 31,934 | 11 | 63,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A new agent called Killjoy invented a virus COVID-2069 that infects accounts on Codeforces. Each account has a rating, described by an integer (it can possibly be negative or very large).
Killjoy's account is already infected and has a rating equal to x. Its rating is constant. There are n accounts except hers, numbered from 1 to n. The i-th account's initial rating is a_i. Any infected account (initially the only infected account is Killjoy's) instantly infects any uninfected account if their ratings are equal. This can happen at the beginning (before any rating changes) and after each contest. If an account is infected, it can not be healed.
Contests are regularly held on Codeforces. In each contest, any of these n accounts (including infected ones) can participate. Killjoy can't participate. After each contest ratings are changed this way: each participant's rating is changed by an integer, but the sum of all changes must be equal to zero. New ratings can be any integer.
Find out the minimal number of contests needed to infect all accounts. You can choose which accounts will participate in each contest and how the ratings will change.
It can be proven that all accounts can be infected in some finite number of contests.
Input
The first line contains a single integer t (1 ≤ t ≤ 100) — the number of test cases. The next 2t lines contain the descriptions of all test cases.
The first line of each test case contains two integers n and x (2 ≤ n ≤ 10^3, -4000 ≤ x ≤ 4000) — the number of accounts on Codeforces and the rating of Killjoy's account.
The second line of each test case contains n integers a_1, a_2, ..., a_n (-4000 ≤ a_i ≤ 4000) — the ratings of other accounts.
Output
For each test case output the minimal number of contests needed to infect all accounts.
Example
Input
3
2 69
68 70
6 4
4 4 4 4 4 4
9 38
-21 83 50 -59 -77 15 -71 -78 20
Output
1
0
2
Note
In the first test case it's possible to make all ratings equal to 69. First account's rating will increase by 1, and second account's rating will decrease by 1, so the sum of all changes will be equal to zero.
In the second test case all accounts will be instantly infected, because all ratings (including Killjoy's account's rating) are equal to 4.
Submitted Solution:
```
def solve():
# n = int(input().strip())
n, x = map(int, input().strip().split())
a = list(map(int, input().strip().split()))
s = 0
found_1 = 0
for i in a:
if(i==x):
found_1 += 1
else:
s += i
if(s==0):
print(0)
elif(s/n)==x:
print(1)
else:
print(2)
t = int(input().strip())
for _ in range(t):
solve()
``` | instruction | 0 | 31,935 | 11 | 63,870 |
No | output | 1 | 31,935 | 11 | 63,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
In order to pass the entrance examination tomorrow, Taro has to study for T more hours.
Fortunately, he can leap to World B where time passes X times as fast as it does in our world (World A).
While (X \times t) hours pass in World B, t hours pass in World A.
How many hours will pass in World A while Taro studies for T hours in World B?
Constraints
* All values in input are integers.
* 1 \leq T \leq 100
* 1 \leq X \leq 100
Input
Input is given from Standard Input in the following format:
T X
Output
Print the number of hours that will pass in World A.
The output will be regarded as correct when its absolute or relative error from the judge's output is at most 10^{-3}.
Examples
Input
8 3
Output
2.6666666667
Input
99 1
Output
99.0000000000
Input
1 100
Output
0.0100000000
Submitted Solution:
```
#!/usr/bin/env python3
import sys
def solve(T: int, X: int):
print(T / Xl)
return
# Generated by 1.1.4 https://github.com/kyuridenamida/atcoder-tools (tips: You use the default template now. You can remove this line by using your custom template)
def main():
def iterate_tokens():
for line in sys.stdin:
for word in line.split():
yield word
tokens = iterate_tokens()
T = int(next(tokens)) # type: int
X = int(next(tokens)) # type: int
solve(T, X)
if __name__ == '__main__':
main()
``` | instruction | 0 | 32,318 | 11 | 64,636 |
No | output | 1 | 32,318 | 11 | 64,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
C = [list(map(int,input().split())) for i in range(3)]
cii_sum = sum([C[i][i] for i in range(3)])
C_sum = sum(list(map(sum,C)))
print("Yes" if cii_sum==(C_sum/3) else "No")
``` | instruction | 0 | 32,343 | 11 | 64,686 |
Yes | output | 1 | 32,343 | 11 | 64,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
c = [0] * 3
for i in range(3):
c[i] = list(map(int, input().split()))
sum_mat = (sum(c[0]) + sum(c[1]) + sum(c[2])) / 3
print('Yes' if sum_mat == c[0][0] + c[1][1] + c[2][2] else 'No')
``` | instruction | 0 | 32,344 | 11 | 64,688 |
Yes | output | 1 | 32,344 | 11 | 64,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a 3 \times 3 grid. A number c_{i, j} is written in the square (i, j), where (i, j) denotes the square at the i-th row from the top and the j-th column from the left.
According to Takahashi, there are six integers a_1, a_2, a_3, b_1, b_2, b_3 whose values are fixed, and the number written in the square (i, j) is equal to a_i + b_j.
Determine if he is correct.
Constraints
* c_{i, j} \ (1 \leq i \leq 3, 1 \leq j \leq 3) is an integer between 0 and 100 (inclusive).
Input
Input is given from Standard Input in the following format:
c_{1,1} c_{1,2} c_{1,3}
c_{2,1} c_{2,2} c_{2,3}
c_{3,1} c_{3,2} c_{3,3}
Output
If Takahashi's statement is correct, print `Yes`; otherwise, print `No`.
Examples
Input
1 0 1
2 1 2
1 0 1
Output
Yes
Input
2 2 2
2 1 2
2 2 2
Output
No
Input
0 8 8
0 8 8
0 8 8
Output
Yes
Input
1 8 6
2 9 7
0 7 7
Output
No
Submitted Solution:
```
# coding: utf-8
# Here your code
n = 3
e = [[int(i) for i in input().split()] for i in range(n)]
a = []
b = []
#for i in range(101):
a.append(0)
b.append(e[0][0] - a[0])
b.append(e[0][1] - a[0])
b.append(e[0][2] - a[0])
a.append(e[1][0] - b[0])
a.append(e[2][0] - b[0])
for i in range(3):
for j in range(3):
if a[i] + b[i] != e[i][j]:
print("No")
exit()
print("Yes")
``` | instruction | 0 | 32,347 | 11 | 64,694 |
No | output | 1 | 32,347 | 11 | 64,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from collections import defaultdict,deque
import sys,heapq,bisect,math,itertools,string,queue,datetime,random
sys.setrecursionlimit(10**8)
INF = float('inf')
mod = 10**9+7
eps = 10**-7
def inpl(): return list(map(int, input().split()))
def inpls(): return list(input().split())
\
N = int(input())
SS = [input() for _ in range(N)]
T = input()
before = 0
after = 0
for S in SS:
sS = S.replace('?','a')
lS = S.replace('?','z')
if T < sS:
after += 1
elif lS < T:
before += 1
print (' '.join(map(str,list(range(before+1,N-after+2)))))
``` | instruction | 0 | 32,377 | 11 | 64,754 |
Yes | output | 1 | 32,377 | 11 | 64,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
import functools
import sys
import bisect
import string
import math
import time
import random
def Golf():*a,=map(int,open(0))
def I():return int(input())
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def LI():return [int(i) for i in input().split()]
def LI_():return [int(i)-1 for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def GI(V,E,Directed=False,index=0):
org_inp=[];g=[[] for i in range(n)]
for i in range(E):
inp=LI();org_inp.append(inp)
if index==0:inp[0]-=1;inp[1]-=1
if len(inp)==2:
a,b=inp;g[a].append(b)
if not Directed:g[b].append(a)
elif len(inp)==3:
a,b,c=inp;aa=(inp[0],inp[2]);bb=(inp[1],inp[2]);g[a].append(bb)
if not Directed:g[b].append(aa)
return g,org_inp
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0}):
#h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0}) # sample usage
mp=[1]*(w+2);found={}
for i in range(h):
s=input()
for char in search:
if char in s:
found[char]=((i+1)*(w+2)+s.index(char)+1)
mp_def[char]=mp_def[replacement_of_found]
mp+=[1]+[mp_def[j] for j in s]+[1]
mp+=[1]*(w+2)
return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def bit_combination(k,n=2):
rt=[]
for tb in range(n**k):
s=[tb//(n**bt)%n for bt in range(k)]
rt+=[s]
return rt
def show(*inp,end='\n'):
if show_flg:print(*inp,end=end)
YN=['YES','NO'];Yn=['Yes','No']
mo=10**9+7
inf=float('inf')
l_alp=string.ascii_lowercase
#sys.setrecursionlimit(10**7)
input=lambda: sys.stdin.readline().rstrip()
def ran_input():
n=random.randint(4,16)
rmin,rmax=1,10
a=[random.randint(rmin,rmax) for _ in range(n)]
return n,a
show_flg=False
show_flg=True
N=10**6+2
m=[0]*(N)
n=I()
a=[]
for i in range(n):
a+=[input()]
t=input()
L,F=0,0
for i in a:
f=''
l=''
for j in i:
if j=='?':
f+='a'
l+='z'
else:
f+=j
l+=j
#show(f,l,t,sorted([f,l,t]))
if f<=t:
F+=1
if l<t:
L+=1
print(*list(range(L+1,F+1+1)))
``` | instruction | 0 | 32,378 | 11 | 64,756 |
Yes | output | 1 | 32,378 | 11 | 64,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
import re
def main():
N = int(input())
i = 0
ques = 0
S = []
while i < N + 1:
s = str(input())
h = re.findall('^\?', s)
if len(h) == 0:
S.append(s)
else:
ques += 1
i += 1
T = S[-1]
i = 0
while i < len(S):
if S[i] == T:
ques += 1
i += 1
S.sort()
index = [S.index(T) + 1]
for i in range(1, ques + 1):
index.append(index[0] + i)
print(' '.join(map(str, index)))
main()
``` | instruction | 0 | 32,379 | 11 | 64,758 |
No | output | 1 | 32,379 | 11 | 64,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Mr.X, who the handle name is T, looked at the list which written N handle names, S_1, S_2, ..., S_N.
But he couldn't see some parts of the list. Invisible part is denoted `?`.
Please calculate all possible index of the handle name of Mr.X when you sort N+1 handle names (S_1, S_2, ..., S_N and T) in lexicographical order.
Note: If there are pair of people with same handle name, either one may come first.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Output
* Calculate the possible index and print in sorted order. The output should be separated with a space. Don't print a space after last number.
* Put a line break in the end.
Constraints
* 1 ≤ N ≤ 10000
* 1 ≤ |S_i|, |T| ≤ 20 (|A| is the length of A.)
* S_i consists from lower-case alphabet and `?`.
* T consists from lower-case alphabet.
Scoring
Subtask 1 [ 130 points ]
* There are no `?`'s.
Subtask 2 [ 120 points ]
* There are no additional constraints.
Input
The input is given from standard input in the following format.
N
S_1
S_2
:
S_N
T
Example
Input
2
tourist
petr
e
Output
1
Submitted Solution:
```
from heapq import heappush,heappop,heapify
from collections import deque,defaultdict,Counter
from itertools import permutations,combinations,groupby
import functools
import sys
import bisect
import string
import math
import time
import random
def Golf():*a,=map(int,open(0))
def I():return int(input())
def S_():return input()
def IS():return input().split()
def LS():return [i for i in input().split()]
def LI():return [int(i) for i in input().split()]
def LI_():return [int(i)-1 for i in input().split()]
def NI(n):return [int(input()) for i in range(n)]
def NI_(n):return [int(input())-1 for i in range(n)]
def StoLI():return [ord(i)-97 for i in input()]
def ItoS(n):return chr(n+97)
def LtoS(ls):return ''.join([chr(i+97) for i in ls])
def GI(V,E,Directed=False,index=0):
org_inp=[];g=[[] for i in range(n)]
for i in range(E):
inp=LI();org_inp.append(inp)
if index==0:inp[0]-=1;inp[1]-=1
if len(inp)==2:
a,b=inp;g[a].append(b)
if not Directed:g[b].append(a)
elif len(inp)==3:
a,b,c=inp;aa=(inp[0],inp[2]);bb=(inp[1],inp[2]);g[a].append(bb)
if not Directed:g[b].append(aa)
return g,org_inp
def GGI(h,w,search=None,replacement_of_found='.',mp_def={'#':1,'.':0}):
#h,w,g,sg=GGI(h,w,search=['S','G'],replacement_of_found='.',mp_def={'#':1,'.':0}) # sample usage
mp=[1]*(w+2);found={}
for i in range(h):
s=input()
for char in search:
if char in s:
found[char]=((i+1)*(w+2)+s.index(char)+1)
mp_def[char]=mp_def[replacement_of_found]
mp+=[1]+[mp_def[j] for j in s]+[1]
mp+=[1]*(w+2)
return h+2,w+2,mp,found
def TI(n):return GI(n,n-1)
def bit_combination(k,n=2):
rt=[]
for tb in range(n**k):
s=[tb//(n**bt)%n for bt in range(k)]
rt+=[s]
return rt
def show(*inp,end='\n'):
if show_flg:print(*inp,end=end)
YN=['YES','NO'];Yn=['Yes','No']
mo=10**9+7
inf=float('inf')
l_alp=string.ascii_lowercase
#sys.setrecursionlimit(10**7)
input=lambda: sys.stdin.readline().rstrip()
def ran_input():
n=random.randint(4,16)
rmin,rmax=1,10
a=[random.randint(rmin,rmax) for _ in range(n)]
return n,a
show_flg=False
show_flg=True
N=10**6+2
m=[0]*(N)
n=I()
a=[]
for i in range(n):
a+=[input()]
t=input()
L,F=0,0
for i in a:
f=''
l=''
for j in i:
if j=='?':
f+='a'
l+='z'
else:
f+=j
l+=j
#show(f,l,t,sorted([f,l,t]))
if f<t:
F+=1
if l<t:
L+=1
print(*list(range(L+1,F+1+1)))
``` | instruction | 0 | 32,382 | 11 | 64,764 |
No | output | 1 | 32,382 | 11 | 64,765 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,402 | 11 | 64,804 |
"Correct Solution:
```
Res = [[0,0,0,0],[0,0,0,0]]
while True:
try:
l,r = map(float,input().split())
if l < 0.2:
Res[0][3] += 1
elif l < 0.6:
Res[0][2] += 1
elif l < 1.1:
Res[0][1] += 1
else:
Res[0][0] += 1
if r < 0.2:
Res[1][3] += 1
elif r < 0.6:
Res[1][2] += 1
elif r < 1.1:
Res[1][1] += 1
else:
Res[1][0] += 1
except:
for i in range(4):
ans = str(Res[0][i]) + " " + str(Res[1][i])
print(ans)
break
``` | output | 1 | 32,402 | 11 | 64,805 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,403 | 11 | 64,806 |
"Correct Solution:
```
def get_input():
while True:
try:
yield ''.join(input())
except EOFError:
break
def check(n):
if n >= 11:
return 0
elif n >= 6:
return 1
elif n >= 2:
return 2
else:
return 3
N = list(get_input())
cntL = [0,0,0,0]
cntR = [0,0,0,0]
for lll in range(len(N)):
l,r = [int(float(i)*10) for i in N[lll].split()]
cntL[check(l)] += 1
cntR[check(r)] += 1
for i in range(4):
print(cntL[i],cntR[i])
``` | output | 1 | 32,403 | 11 | 64,807 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,404 | 11 | 64,808 |
"Correct Solution:
```
from collections import Counter
def check(f):
if f >= 1.1:
return "A"
elif f >= 0.6:
return "B"
elif f >= 0.2:
return "C"
else:
return "D"
dicl = Counter()
dicr = Counter()
while True:
try:
l, r = map(float, input().split())
lx, rx = check(l), check(r)
dicl[lx] += 1
dicr[rx] += 1
except EOFError:
break
for alpha in ("A", "B", "C", "D"):
print(dicl[alpha], dicr[alpha])
``` | output | 1 | 32,404 | 11 | 64,809 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,405 | 11 | 64,810 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0149
"""
import sys
from sys import stdin
from collections import defaultdict
input = stdin.readline
def process_data(result, rank):
if result >= 1.1:
rank['A'] += 1
elif result >= 0.6:
rank['B'] += 1
elif result >= 0.2:
rank['C'] += 1
else:
rank['D'] += 1
def main(args):
left_rank = defaultdict(int)
right_rank = defaultdict(int)
for line in sys.stdin:
l, r = map(float, line.split())
process_data(l, left_rank)
process_data(r, right_rank)
print('{} {}'.format(left_rank['A'], right_rank['A']))
print('{} {}'.format(left_rank['B'], right_rank['B']))
print('{} {}'.format(left_rank['C'], right_rank['C']))
print('{} {}'.format(left_rank['D'], right_rank['D']))
if __name__ == '__main__':
main(sys.argv[1:])
``` | output | 1 | 32,405 | 11 | 64,811 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,406 | 11 | 64,812 |
"Correct Solution:
```
# Aizu Problem 00149: Eye Test
#
import sys, math, os, copy
# read input:
PYDEV = os.environ.get('PYDEV')
if PYDEV=="True":
sys.stdin = open("sample-input.txt", "rt")
def get_judgement(x):
if x >= 1.1:
return "A"
elif x >= .6:
return "B"
elif x >= .2:
return "C"
else:
return "D"
count = {char: {"left": 0, "right": 0} for char in ['A', 'B', 'C', 'D']}
for line in sys.stdin:
left, right = [float(_) for _ in line.split()]
count[get_judgement(left)]["left"] += 1
count[get_judgement(right)]["right"] += 1
for char in ['A', 'B', 'C', 'D']:
print(count[char]["left"], count[char]["right"])
``` | output | 1 | 32,406 | 11 | 64,813 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,407 | 11 | 64,814 |
"Correct Solution:
```
eyes = [[0 for i in range(2)] for j in range(4)]
while True:
try:
a = list(map(float, input().split()))
except:
break
for i in range(2):
if a[i] >= 1.1: eyes[0][i]+=1
elif a[i] >= 0.6: eyes[1][i]+=1
elif a[i] >= 0.2: eyes[2][i]+=1
else: eyes[3][i]+=1
for i in range(4):
print(*eyes[i])
``` | output | 1 | 32,407 | 11 | 64,815 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,408 | 11 | 64,816 |
"Correct Solution:
```
tbl = [[0 for j in range(4)] for i in range(2)]
while True:
try: p = list(map(float, input().split()))
except: break
for i in range(2):
if p[i] >= 1.1: tbl[i][0] += 1
elif p[i] >= 0.6: tbl[i][1] += 1
elif p[i] >= 0.2: tbl[i][2] += 1
else: tbl[i][3] += 1
for i in range(4):
print(tbl[0][i], tbl[1][i])
``` | output | 1 | 32,408 | 11 | 64,817 |
Provide a correct Python 3 solution for this coding contest problem.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0 | instruction | 0 | 32,409 | 11 | 64,818 |
"Correct Solution:
```
def f(a):
if a>1.0:return 0
elif a>0.5:return 1
elif a>0.1:return 2
else:return 3
b=[0]*8
while 1:
try:l,r=map(float,input().split())
except:break
b[f(l)]+=1
b[4+f(r)]+=1
for i in range(4):print(b[i],b[4+i])
``` | output | 1 | 32,409 | 11 | 64,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
import sys
LA = RA = 0
LB = RB = 0
LC = RC = 0
LD = RD = 0
for i in sys.stdin:
l,r = map(float,i.split())
if l >= 1.1:
LA += 1
elif 0.6 <= l <1.1:
LB += 1
elif 0.2 <= l < 0.6:
LC += 1
else:
LD += 1
if r >= 1.1:
RA += 1
elif 0.6 <= r <1.1:
RB += 1
elif 0.2 <= r < 0.6:
RC += 1
else:
RD += 1
print(LA,RA)
print(LB,RB)
print(LC,RC)
print(LD,RD)
``` | instruction | 0 | 32,410 | 11 | 64,820 |
Yes | output | 1 | 32,410 | 11 | 64,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
al,ar,bl,br,cl,cr,dl,dr=0,0,0,0,0,0,0,0
while True:
try:
le,re=map(float,input().split())
if le<0.2:
dl+=1
if le>= 0.2 and le<0.6:
cl += 1
if le >= 0.6 and le<1.1:
bl += 1
if le >= 1.1:
al += 1
if re<0.2:
dr+=1
if re>= 0.2 and re<0.6:
cr += 1
if re >= 0.6 and re<1.1:
br+= 1
if re >= 1.1:
ar += 1
except:
print(al,ar)
print(bl,br)
print(cl,cr)
print(dl,dr)
break
``` | instruction | 0 | 32,411 | 11 | 64,822 |
Yes | output | 1 | 32,411 | 11 | 64,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
lr = [0 for i in range(8)]
while True:
try:
a,b = map(float,input().split())
except:
break
if a >= 1.1:
lr[0] += 1
elif a >= 0.6:
lr[2] += 1
elif a >= 0.2:
lr[4] += 1
else:
lr[6] += 1
if b >= 1.1:
lr[1] += 1
elif b >= 0.6:
lr[3] += 1
elif b >= 0.2:
lr[5] += 1
else:
lr[7] += 1
print(lr[0],lr[1])
print(lr[2],lr[3])
print(lr[4],lr[5])
print(lr[6],lr[7])
``` | instruction | 0 | 32,412 | 11 | 64,824 |
Yes | output | 1 | 32,412 | 11 | 64,825 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Create a program that inputs the test result data of the visual acuity test and outputs the number of people who apply to each judgment based on the following visual acuity judgment table for each of the left and right eyesight.
Judgment | Sight
--- | ---
A | 1.1 or above
B | 0.6 or more and less than 1.1
C | 0.2 or more and less than 0.6
D | less than 0.2
Input
The input is given in the following format:
l1 r1
l2 r2
l3 r3
::
::
On line i, the real number li, which represents the left visual acuity of the i-th person, and the real number ri, which represents the right visual acuity, are given, separated by blanks. However, visual acuity is 0.1 or more and 2.0 or less, and is given in 0.1 increments.
The number of lines of input does not exceed 40.
Output
Please output the judgment table in the following format.
Line 1 Left eyesight is the number of people A Right eyesight is the number of people (separated by blanks)
2nd line The number of people whose left eyesight is B The number of people whose right eyesight is B (separated by blanks)
3rd line The number of people whose left eyesight is C
4th line Number of people with left eyesight D Number of people with right eyesight D (separated by blanks)
Example
Input
1.0 1.2
0.8 1.5
1.2 0.7
2.0 2.0
Output
2 3
2 1
0 0
0 0
Submitted Solution:
```
import sys
BASE = [1.1, 0.6, 0.2, 0.0]
COUNT = len(BASE)
def eye_test(num):
for index, parameter in enumerate(BASE):
if parameter <= num:
return index
left_counter = [0] * COUNT
right_counter = [0] * COUNT
for line in sys.stdin:
left, right = [float(item) for item in line[:-1].split(" ")]
left_eye, right_eye = eye_test(left), eye_test(right)
left_counter[left_eye] += 1
right_counter[right_eye] += 1
for item1, item2 in zip(left_counter, right_counter):
print(item1, item2)
``` | instruction | 0 | 32,413 | 11 | 64,826 |
Yes | output | 1 | 32,413 | 11 | 64,827 |
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