message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,398 | 12 | 82,796 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
import heapq as h
from types import GeneratorType
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
import os
self.os = os
... | output | 1 | 41,398 | 12 | 82,797 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,399 | 12 | 82,798 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
from sys import stdin,stdout
from math import *
input = stdin.readline
# print=stdout.write
for i in range(int(input())):
n=int(input())
ar=list(map(int,input().split()))
d1=[]
d2=[]
for i in range(n):
d1.append([0]*27)
d... | output | 1 | 41,399 | 12 | 82,799 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,400 | 12 | 82,800 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
def distribution(n):
return (n-1)//2
def problem_A():
print(distribution(int(input())))
s = 'abcdefghijklmnopqrstuvwxyz'
def cons_str(n,b):
a = s[:b]
ans = ''
while n > b:
ans += a
n -= b
... | output | 1 | 41,400 | 12 | 82,801 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,401 | 12 | 82,802 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
for _ in range(int(input())):
n = int(input())
arr = list(map(lambda x : int(x) - 1, input().split()))
nxt = [[-1] * 26 for _ in range(n)]
prv = [[-1] * 26 for _ in range(n)]
fst = [-1] * 26
lst = [-1] * 2... | output | 1 | 41,401 | 12 | 82,803 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,402 | 12 | 82,804 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
import sys
import collections
import threading
import string
def sparsetable(a):
tmp = [0]*201
st = []
for i in range(len(a)):
tmp[a[i]] += 1
st.append(tmp[:])
return st
def func(x, y, st):
if... | output | 1 | 41,402 | 12 | 82,805 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,403 | 12 | 82,806 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
'''input
6
8
1 1 2 2 3 2 1 1
3
1 3 3
4
1 10 10 1
1
26
2
2 1
3
1 1 1
'''
import sys
import math
import copy
from collections import Counter
debug = 1
readln = sys.stdin.readline
#sys.setrecursionlimit(1000000)
def readint():
... | output | 1 | 41,403 | 12 | 82,807 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consisting of at most two distinct elements (let these... | instruction | 0 | 41,404 | 12 | 82,808 |
Tags: binary search, brute force, data structures, dp, two pointers
Correct Solution:
```
from collections import defaultdict
import bisect
from sys import stdin
input = stdin.readline
def check(i,j,d):
#print(i,j)
maxi = 0
for k in d:
k = d[k]
a = bisect.bisect_right(k,i)
b = bisec... | output | 1 | 41,404 | 12 | 82,809 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,405 | 12 | 82,810 |
Yes | output | 1 | 41,405 | 12 | 82,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,406 | 12 | 82,812 |
Yes | output | 1 | 41,406 | 12 | 82,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,407 | 12 | 82,814 |
Yes | output | 1 | 41,407 | 12 | 82,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,408 | 12 | 82,816 |
Yes | output | 1 | 41,408 | 12 | 82,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,409 | 12 | 82,818 |
No | output | 1 | 41,409 | 12 | 82,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,410 | 12 | 82,820 |
No | output | 1 | 41,410 | 12 | 82,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,411 | 12 | 82,822 |
No | output | 1 | 41,411 | 12 | 82,823 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is constraints.
You are given a sequence a consisting of n positive integers.
Let's define a three blocks palindrome as the sequence, consist... | instruction | 0 | 41,412 | 12 | 82,824 |
No | output | 1 | 41,412 | 12 | 82,825 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,465 | 12 | 82,930 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import sys
input = sys.stdin.readline
from collections import *
def tran():
pos = []
epos = []
for i in range(n-2, n):
for j in range(m-2, m):
if s[i][j]==1:
pos.append((i, j))
... | output | 1 | 41,465 | 12 | 82,931 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,466 | 12 | 82,932 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
import threading
from bisect import bisect_right
from math import gcd,log
from collections import Counter,defaultdict
from pprint import pprint
import copy
# 3 ... | output | 1 | 41,466 | 12 | 82,933 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,467 | 12 | 82,934 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import sys
def printm():
for row in M:
print(''.join(map(str, row)))
def change1(i, j):
if i:
di = -1
else:
di = 1
if j:
dj = -1
else:
dj = 1
out = []
out.append((... | output | 1 | 41,467 | 12 | 82,935 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,468 | 12 | 82,936 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import sys,os,io
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
input = sys.stdin.readline
for _ in range (int(input())):
n,m = [int(i) for i in input().split()]
a = []
for i in range (n):
s = input(... | output | 1 | 41,468 | 12 | 82,937 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,469 | 12 | 82,938 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
#!/usr/bin/env python
import os
import sys
from io import BytesIO, IOBase
def main():
for t in range(int(input())):
n,m = map(int, input().split())
a = []
for i in range(n):
a.append(list(inpu... | output | 1 | 41,469 | 12 | 82,939 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,470 | 12 | 82,940 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import math
def selectTiles(mepas, x, y):
ans = []
if mepas[x][y] == 1:
ans.append(x + 1)
ans.append(y + 1)
mepas[x][y] = 0 if mepas[x][y] else 1
if mepas[x][y+1] == 1 or len(ans) < 2:
ans.ap... | output | 1 | 41,470 | 12 | 82,941 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,471 | 12 | 82,942 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineering College
'''
from os import path
import sys
from heapq import heappush,heappop
from functools import cmp_to_key as ctk
from collections import deque,Cou... | output | 1 | 41,471 | 12 | 82,943 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 41,472 | 12 | 82,944 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
#!/usr/bin/env python3.9
def inverse_1_2x2(i, j):
''' inverse one '1' in square 2x2, cost 3 '''
res = []
fstr = '{} {} {} {} {} {}'
step_i, step_j = 1, 1
if i % 2 == 0:
step_i = -1
if j % 2 == 0:
... | output | 1 | 41,472 | 12 | 82,945 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The only difference is that in this version q = 1. You can make hacks only if both versions of the problem are solved.
There is a process that takes place on arrays a and b of length n and length n-1... | instruction | 0 | 41,496 | 12 | 82,992 |
Tags: dp, math
Correct Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
N = int(input())
C = [int(a) for a in input().split()]
B = [int(a) for a in input().split()]
Q = int(input())
x = int(input())
P = 10 ** 9 + 7
dp = [[0] * 20100 for _ in range(N + 1)]
dp[0][0] = 1
ans = 0
s = x
t = s
for i in... | output | 1 | 41,496 | 12 | 82,993 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The only difference is that in this version q = 1. You can make hacks only if both versions of the problem are solved.
There is a process that takes place on arrays a and b of length n and length n-1... | instruction | 0 | 41,497 | 12 | 82,994 |
Tags: dp, math
Correct Solution:
```
import sys
input = lambda: sys.stdin.readline().rstrip()
N = int(input());C = [int(a) for a in input().split()];B = [int(a) for a in input().split()];Q = int(input());x = int(input());P = 10 ** 9 + 7;
dp = [[0] * 20100 for _ in range(N + 1)];dp[0][0] = 1;ans = 0;s = x;t = s
for i in... | output | 1 | 41,497 | 12 | 82,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,520 | 12 | 83,040 |
Tags: implementation, sortings
Correct Solution:
```
import sys
input = sys.stdin.readline
def prog():
n = int(input())
cs = list(map(int,input().split()))
nums = []
locations = {}
locations2 = {}
i = 1
for c in cs:
curr_nums = list(map(int,input().split()))
for j in range(c)... | output | 1 | 41,520 | 12 | 83,041 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,521 | 12 | 83,042 |
Tags: implementation, sortings
Correct Solution:
```
n, k = int(input()), 1
c = [0] + list(map(int, input().split()))
p, q, t = [0] * (sum(c) + 1), {}, []
for i in range(1, n + 1):
for j, x in enumerate(tuple(map(int, input().split())), 1):
p[x], q[(i, j)] = (i, j), x
for i in range(1, n + 1):
for j in ... | output | 1 | 41,521 | 12 | 83,043 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,522 | 12 | 83,044 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
I = lambda : map(int,input().split())
li = list (I())
dd = {}
arr = [ [0 for i in range(51)] for j in range(51) ]
l2 = [ ]
c=0
for i in range (1,n+1) :
l1 = list(I())
l2 = l2 + l1
c = c + len(l1)
for j in range(li[i-1]) :
arr... | output | 1 | 41,522 | 12 | 83,045 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,523 | 12 | 83,046 |
Tags: implementation, sortings
Correct Solution:
```
n, k = int(input()), 1
c = [0] + list(map(int, input().split()))
p, q, t = [0] * (sum(c) + 1), {}, []
for i in range(1, n + 1):
for j, x in enumerate(tuple(map(int, input().split())), 1):
p[x], q[(i, j)] = (i, j), x
for i in range(1, n + 1):
fo... | output | 1 | 41,523 | 12 | 83,047 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,524 | 12 | 83,048 |
Tags: implementation, sortings
Correct Solution:
```
def find(a,p,n):
for i in range(n):
l = len(a[i])
for j in range(l):
if a[i][j]==p:
return [i+1,j+1]
n = int(input())
b = list(map(int,input().split()))
a = []
for i in range(n):
c = list(map(int,input(... | output | 1 | 41,524 | 12 | 83,049 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,525 | 12 | 83,050 |
Tags: implementation, sortings
Correct Solution:
```
n, p, l, v = int(input()), [[0, 0]], [0], []
for i, c in enumerate(map(int, input().split())):
p.extend([[i + 1, j + 1] for j in range(c)])
l.extend(list(map(int, input().split())))
for i in range(1, len(l)):
if l[i] != i:
j = l.index(i)
v... | output | 1 | 41,525 | 12 | 83,051 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,526 | 12 | 83,052 |
Tags: implementation, sortings
Correct Solution:
```
n = int(input())
col=list(map(int,input().split()))
arr = [list(map(int, input().split())) for _ in range(n)]
mm=sum(col)
ans=[(0,0)]*(mm+1)
res=[]
for i in range(n):
for j in range(col[i]):
ans[arr[i][j]]=(i,j)
#print(ans)
b=0
for i in range(n):
for ... | output | 1 | 41,526 | 12 | 83,053 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number of cells of table a, that is, <image>. We know ... | instruction | 0 | 41,527 | 12 | 83,054 |
Tags: implementation, sortings
Correct Solution:
```
n=int(input())
p=[[0,0]]
l=[0]
v=[]
for i, c in enumerate(map(int, input().split())):
p.extend([[i + 1, j + 1] for j in range(c)])
l.extend(list(map(int, input().split())))
for i in range(1, len(l)):
if l[i] != i:
j = l.index(i)
v.append(p... | output | 1 | 41,527 | 12 | 83,055 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,528 | 12 | 83,056 |
Yes | output | 1 | 41,528 | 12 | 83,057 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,529 | 12 | 83,058 |
Yes | output | 1 | 41,529 | 12 | 83,059 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,530 | 12 | 83,060 |
Yes | output | 1 | 41,530 | 12 | 83,061 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,531 | 12 | 83,062 |
Yes | output | 1 | 41,531 | 12 | 83,063 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,532 | 12 | 83,064 |
No | output | 1 | 41,532 | 12 | 83,065 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,533 | 12 | 83,066 |
No | output | 1 | 41,533 | 12 | 83,067 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,534 | 12 | 83,068 |
No | output | 1 | 41,534 | 12 | 83,069 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You've got table a, consisting of n rows, numbered from 1 to n. The i-th line of table a contains ci cells, at that for all i (1 < i β€ n) holds ci β€ ci - 1.
Let's denote s as the total number ... | instruction | 0 | 41,535 | 12 | 83,070 |
No | output | 1 | 41,535 | 12 | 83,071 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. We'll denote the i-th element of permutation p as pi. We'll call number n the size or the length of permu... | instruction | 0 | 41,536 | 12 | 83,072 |
Tags: combinatorics, dp, math
Correct Solution:
```
# METO Bot 0.9.9
mod=10**9+7
n,k=map(int,input().split())
A=[0]*(n+1)
B=[0]*(n+1)
C=[0]*(n+1)
F=[0]*(n+1)
G=[0]*(n+1)
F[0]=G[0]=1
for i in range(1,n+1):
G[i]=F[i]=F[i-1]*i%mod
G[i]=pow(F[i],(mod-2),mod)
for i in range(0,n):
if i*2>n:
break
B[i]=(F[n-i]*G[i]*G... | output | 1 | 41,536 | 12 | 83,073 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. We'll denote the i-th element of permutation p as pi. We'll call number n the size or the length of permu... | instruction | 0 | 41,537 | 12 | 83,074 |
Tags: combinatorics, dp, math
Correct Solution:
```
mod=10**9+7
n,k=map(int,input().split())
A=[0]*(n+1)
B=[0]*(n+1)
C=[0]*(n+1)
F=[0]*(n+1)
G=[0]*(n+1)
F[0]=G[0]=1
for i in range(1,n+1):
G[i]=F[i]=F[i-1]*i%mod
G[i]=pow(F[i],(mod-2),mod)
for i in range(0,n):
if i*2>n:
break
B[i]=(F[n-i]*G[i]*G[n-i*2])%mod
for ... | output | 1 | 41,537 | 12 | 83,075 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Permutation p is an ordered set of integers p1, p2, ..., pn, consisting of n distinct positive integers, each of them doesn't exceed n. We'll denote the i-th element of permutation p as pi. We'l... | instruction | 0 | 41,538 | 12 | 83,076 |
No | output | 1 | 41,538 | 12 | 83,077 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,657 | 12 | 83,314 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
'''
Created on Jan 25, 2016
@author: KANDARP
'''
import sys
n=int(sys.stdin.readline());
arr=[int(x) for x in input().split()];
sets=set();
result=[];
ans=0;
l=0;
r=0;
for i in arr:
if(i in sets):
ans=ans+1;
sets.clear();
... | output | 1 | 41,657 | 12 | 83,315 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,658 | 12 | 83,316 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
n=int(input())
l=list(map(int,input().split()))
s=set()
ans=[]
for i in range(n):
if l[i] in s:
if ans:
ans.append([ans[-1][1]+1,i+1])
else:
ans=[[1,i+1]]
s=set()
else:
s.add(l[i])
if ans and s:
ans[-1][1]+=len(s)
if ans:
print(... | output | 1 | 41,658 | 12 | 83,317 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,659 | 12 | 83,318 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
#!/bin/python3
import sys
n = int(input())
a = list(map(int, input().split()))
ans = [];
sa = sorted(a);
cmpr = {};
for i in range(0, len(a)):
cmpr[sa[i]] = i;
cid = [0 for i in range(0,n)];
id = 1;
pi = 0
for i in range(0,n):
if cid[cm... | output | 1 | 41,659 | 12 | 83,319 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,660 | 12 | 83,320 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
from itertools import combinations_with_replacement,permutations
from collections import defaultdict
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(se... | output | 1 | 41,660 | 12 | 83,321 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,661 | 12 | 83,322 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
n, k = map(int, input().split())
a = [*map(int, input().split())]
from collections import defaultdict
d = defaultdict(int)
l = 0
r = 1
ans = (0, 0)
for i in a:
d[i] += 1
if len(d) <= k:
ans = (l, r) if ans[1] - ans[0] < r - l else ans
else... | output | 1 | 41,661 | 12 | 83,323 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The array a with n integers is given. Let's call the sequence of one or more consecutive elements in a segment. Also let's call the segment k-good if it contains no more than k different values.
Find any longest k-good segment.
As the inpu... | instruction | 0 | 41,662 | 12 | 83,324 |
Tags: binary search, data structures, two pointers
Correct Solution:
```
import sys
inputNum=input()
inputTypes=input().split(' ')
set1=set()
stack2=[]
stack3=[]
for i in range(len(inputTypes)):
if len(set1)==0:
set1.add(inputTypes[i])
stack2.append(str(i+1))
else:
if inputTypes[i]... | output | 1 | 41,662 | 12 | 83,325 |
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