message stringlengths 2 433k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 113 108k | cluster float64 12 12 | __index_level_0__ int64 226 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,197 | 12 | 84,394 |
Yes | output | 1 | 42,197 | 12 | 84,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,198 | 12 | 84,396 |
Yes | output | 1 | 42,198 | 12 | 84,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,200 | 12 | 84,400 |
Yes | output | 1 | 42,200 | 12 | 84,401 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,202 | 12 | 84,404 |
No | output | 1 | 42,202 | 12 | 84,405 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,203 | 12 | 84,406 |
No | output | 1 | 42,203 | 12 | 84,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given n k-digit integers. You have to rearrange the digits in the integers so that the difference between the largest and the smallest number was minimum. Digits should be rearranged by ... | instruction | 0 | 42,204 | 12 | 84,408 |
No | output | 1 | 42,204 | 12 | 84,409 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,205 | 12 | 84,410 |
Tags: greedy, implementation, math
Correct Solution:
```
n=int(input())
ar=[]
for i in range(n):
s=input()
a=s.split(' ')
x=int(a[0])
y=int(a[1])
if(x==y):
print(0)
if(x>y and (x-y)%2==1):
print(2)
if(x>y and (x-y)%2==0):
print(1)
if(x<y and (y-x)%2==0):
p... | output | 1 | 42,205 | 12 | 84,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,206 | 12 | 84,412 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
a,b= list(map(int,input().split()))
c=0
if b>a:
if (b-a)%2==0:
c=2
if (b-a)%2==1:
c=1
else:
if (b-a)%2==0:
c=1
if (b-a)%2==1:
c=2
if ... | output | 1 | 42,206 | 12 | 84,413 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,207 | 12 | 84,414 |
Tags: greedy, implementation, math
Correct Solution:
```
for i in range(int(input())):
a,b = map(int,input().split())
z = a-b
c = (z % 2 == 0 and z < 0) or (z % 2 == 1 and z > 0) #2
c1 = (z % 2 == 1 and z < 0) or (z > 0 and z % 2 == 0) #1
if c:
print(2)
elif c1:
print(1)
else... | output | 1 | 42,207 | 12 | 84,415 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,208 | 12 | 84,416 |
Tags: greedy, implementation, math
Correct Solution:
```
t=int(input())
m=0
for i in range(t):
a,b=map(int,input().split())
if b>a:
if (b-a)%2!=0:
# a+=(b-a)
m+=1
print(m)
m=0
else:
m+=2
print(m)
m=0
elif a==b:
print('0')
else:
if (a-b)%2!=0:
m+=2
print(m)
m=0
else:
m+=1
... | output | 1 | 42,208 | 12 | 84,417 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,209 | 12 | 84,418 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
n,m=map(int,input().split())
if n==m:
print(0)
elif n<m:
a=m-n
if a%2!=0:
print(1)
else:
print(2)
elif n>m:
a=n-m
if a%2==0:
print(1)... | output | 1 | 42,209 | 12 | 84,419 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,210 | 12 | 84,420 |
Tags: greedy, implementation, math
Correct Solution:
```
t = int(input())
for i in range(t):
a,b = map(int, input().split())
if a==b:
print(0)
elif (a<b and abs(a-b)%2==1) or (a>b and abs(a-b)%2==0):
print(1)
else:
print(2)
``` | output | 1 | 42,210 | 12 | 84,421 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,211 | 12 | 84,422 |
Tags: greedy, implementation, math
Correct Solution:
```
for _ in range(int(input())):
a,b=map(int,input().split())
if a==b:
print(0)
else:
if a%2==0 and b%2==0:
if a<b:
print(2)
else:
print(1)
elif a%2==0 and b%2==1:
... | output | 1 | 42,211 | 12 | 84,423 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given two positive integers a and b.
In one move, you can change a in the following way:
* Choose any positive odd integer x (x > 0) and replace a with a+x;
* choose any positive even integer y (y > 0) and replace a with a-y. ... | instruction | 0 | 42,212 | 12 | 84,424 |
Tags: greedy, implementation, math
Correct Solution:
```
t=int(input())
for i in range(t):
a,b=map(int,input().split())
if(a<b):
if((b-a)%2==1):
print('1')
else:
print('2')
elif(a>b):
if((a-b)%2==0):
print('1')
else:
print('2')
... | output | 1 | 42,212 | 12 | 84,425 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,277 | 12 | 84,554 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" no... | output | 1 | 42,277 | 12 | 84,555 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,278 | 12 | 84,556 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
def finput():
return float(input())
def iinput():
return int(input())
def liinput():
return [int(_) for _ in input().split()]
def lfinput():
return [float(_) for _ in input().split()]
if __name__ == '__main__':
T = iinput()
... | output | 1 | 42,278 | 12 | 84,557 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,279 | 12 | 84,558 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
# ========== //\\ //|| ||====//||
# || // \\ || || // ||
# || //====\\ || || // ||
# || // \\ || || // ||
# ========== // \\ ======== ||//====||
# co... | output | 1 | 42,279 | 12 | 84,559 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,280 | 12 | 84,560 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
from sys import stdin, stdout
input = stdin.readline
print = lambda x:stdout.write(str(x)+'\n')
for _ in range(int(input())):
n, q = map(int, input().split())
a = list(map(int, input().split()))
x, y = 0, 0
ans = 0
curr = 'inc'
for... | output | 1 | 42,280 | 12 | 84,561 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,281 | 12 | 84,562 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
t = int(input())
for _ in range(t):
n,q = map(int,input().split())
l1 = [int(x) for x in input().split()]
i = 0
j = 1
k = 1
ans = 0
while i<len(l1):
#print(ans,k,j)
if j:
while i<n-1 and l1[i]<l1[i+1]... | output | 1 | 42,281 | 12 | 84,563 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,282 | 12 | 84,564 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.m... | output | 1 | 42,282 | 12 | 84,565 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,283 | 12 | 84,566 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
import sys
input = sys.stdin.readline
t = int(input())
for _ in range(t):
n,q = list(map(int, input().split()))
arr = list(map(int, input().split()))
#tmp1 = [0] * (n)
#dp = [tmp1, tmp2]
dp_pair = 0#-99999999999999999
... | output | 1 | 42,283 | 12 | 84,567 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
Pikachu is a cute and friendly pokémon living i... | instruction | 0 | 42,284 | 12 | 84,568 |
Tags: constructive algorithms, dp, greedy
Correct Solution:
```
#Fast I/O
import sys,os
import math
# To enable the file I/O i the below 2 lines are uncommented.
# read from in.txt if uncommented
if os.path.exists('in.txt'): sys.stdin=open('in.txt','r')
# will print on Console if file I/O is not activated
#if os.path.e... | output | 1 | 42,284 | 12 | 84,569 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,285 | 12 | 84,570 |
Yes | output | 1 | 42,285 | 12 | 84,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,286 | 12 | 84,572 |
Yes | output | 1 | 42,286 | 12 | 84,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,287 | 12 | 84,574 |
Yes | output | 1 | 42,287 | 12 | 84,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,288 | 12 | 84,576 |
Yes | output | 1 | 42,288 | 12 | 84,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,289 | 12 | 84,578 |
No | output | 1 | 42,289 | 12 | 84,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,290 | 12 | 84,580 |
No | output | 1 | 42,290 | 12 | 84,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,291 | 12 | 84,582 |
No | output | 1 | 42,291 | 12 | 84,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is the easy version of the problem. The difference between the versions is that the easy version has no swap operations. You can make hacks only if all versions of the problem are solved.
... | instruction | 0 | 42,292 | 12 | 84,584 |
No | output | 1 | 42,292 | 12 | 84,585 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,293 | 12 | 84,586 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
# by the authority of GOD author: manhar singh sachdev #
import os,sys
from io import BytesIO, IOBase
from copy import deepcopy
def solve(arr,i,j,q,n,m):
while i<n:
fl = 0
if i>=n-1:
i = n-2
... | output | 1 | 42,293 | 12 | 84,587 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,294 | 12 | 84,588 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
from itertools import permutations
import sys
input=lambda: sys.stdin.readline().rstrip("\r\n") #FOR READING STRING/TEXT INPUTS.
def countSet(arr):
n=len(arr)
m=len(arr[0])
cnt=0
for i in range(n):
for j in ran... | output | 1 | 42,294 | 12 | 84,589 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,295 | 12 | 84,590 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
from sys import stdin
def c(x1,y1,x2,y2,x3,y3):
ans.append( (x1+1,y1+1,x2+1,y2+1,x3+1,y3+1) )
a[x1][y1] ^= 1
a[x2][y2] ^= 1
a[x3][y3] ^= 1
return
tt = int(stdin.readline())
for loop in range(tt):
n,m = map(int... | output | 1 | 42,295 | 12 | 84,591 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,296 | 12 | 84,592 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
from sys import stdin,stdout
"""
n=int(stdin.readline().strip())
n,m=map(int,stdin.readline().strip().split())
s=list(map(int,stdin.readline().strip().split()))
"""
def solve(x,y):
c=0
for i in range(x,x+2):
for j ... | output | 1 | 42,296 | 12 | 84,593 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,297 | 12 | 84,594 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writ... | output | 1 | 42,297 | 12 | 84,595 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,298 | 12 | 84,596 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
t = int(input())
for _ in range(t):
n, m = map(int, input().split())
a = [list(map(int, input())) for i in range(n)]
def add(p):
a[p[0]][p[1]] ^= 1
a[p[2]][p[3]] ^= 1
a[p[4]][p[5]] ^= 1
ans.append(' '.join(map(lambda x: str(x... | output | 1 | 42,298 | 12 | 84,597 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,299 | 12 | 84,598 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
import sys,io,os;Z=io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def solve(sq,x,y):
s=sum(sum(i)for i in sq)
v=[(x,y,x+1,y,x,y+1),(x,y,x+1,y+1,x,y+1),(x,y,x+1,y,x+1,y+1),
(x+1,y+1,x+1,y,x,y+1)]
if s>3:return v
... | output | 1 | 42,299 | 12 | 84,599 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This is the hard version of the problem. The difference between the versions is in the number of possible operations that can be made. You can make hacks if and only if you solved both versions of the problem.
You are given a binary table o... | instruction | 0 | 42,300 | 12 | 84,600 |
Tags: constructive algorithms, graphs, greedy, implementation
Correct Solution:
```
read = lambda: map(int, input().split())
t = int(input())
for _ in range(t):
n, m = read()
a = [list(map(int, input())) for i in range(n)]
def add(x, y, z):
a[x[0]][x[1]] ^= 1
a[y[0]][y[1]] ^= 1
a[z[0]][z[1]] ^= 1
ans.append... | output | 1 | 42,300 | 12 | 84,601 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,325 | 12 | 84,650 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" ... | output | 1 | 42,325 | 12 | 84,651 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,326 | 12 | 84,652 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
import sys
from itertools import *
from math import *
from sys import stdin,stdout
def ans(n,lst):
c0,c1,c2 = 0,0,0
req = n // 3
c = 0
for i in lst:
if i % 3 == 0:
c0 += 1
elif i % 3 == 1:
c1 += 1
elif i % 3 == 2:
c2 += 1
while c... | output | 1 | 42,326 | 12 | 84,653 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,327 | 12 | 84,654 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
'''for _ in range(int(input())):
n=int(input())
arr=[int(i) for i in input().split()]
ans=0
for i in range(n-1):
mi=min(arr[i],arr[i+1])
mx=max(arr[i],arr[i+1])
if mx/mi>2:
temp=mi
cnt=... | output | 1 | 42,327 | 12 | 84,655 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,328 | 12 | 84,656 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
def getNoChangeToBalance(arr,n):
count=0
cnt=[0]*3
for j in range(n):
cnt[arr[j]%3]+=1
while(min(cnt)!=n//3):
for i in range(3):
if(cnt[i] > n//3):
count+=1
cnt[i]-=1
... | output | 1 | 42,328 | 12 | 84,657 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,329 | 12 | 84,658 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
import math
def mult_inp():
return map(int,input().split(' '))
def inp():
return list(map(int,input().split(' ')))
def binn(dp,it):
left = 0
right = len(dp)
while left <= right:
mid = (left + right)//2
if dp[m... | output | 1 | 42,329 | 12 | 84,659 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,330 | 12 | 84,660 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
# Legends Always Come Up with Solution
# Author: Manvir Singh
import os
import sys
from io import BytesIO, IOBase
def solve(b,n):
ans=0
for i in range(len(b)):
if b[i]>=(n//3):
ans= ans+b[i]-(n//3)
b[(i+1)%3... | output | 1 | 42,330 | 12 | 84,661 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,331 | 12 | 84,662 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
t = int(input())
while t!=0:
n = int(input())
list1 = list(map(int,input().split()))
zero,one,two = 0,0,0
for i in range(n):
if list1[i]%3==0:
zero+=1
elif list1[i]%3==1:
one+=1
el... | output | 1 | 42,331 | 12 | 84,663 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i with a_i + 1. You can choose the same index i mul... | instruction | 0 | 42,332 | 12 | 84,664 |
Tags: brute force, constructive algorithms, math
Correct Solution:
```
import re
import sys
exit=sys.exit
from bisect import bisect_left,bisect_right
from collections import Counter,defaultdict as ddict,deque
from functools import lru_cache
cache=lru_cache(None)
from heapq import *
from itertools import *
from math imp... | output | 1 | 42,332 | 12 | 84,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i wi... | instruction | 0 | 42,333 | 12 | 84,666 |
Yes | output | 1 | 42,333 | 12 | 84,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i wi... | instruction | 0 | 42,334 | 12 | 84,668 |
Yes | output | 1 | 42,334 | 12 | 84,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i wi... | instruction | 0 | 42,335 | 12 | 84,670 |
Yes | output | 1 | 42,335 | 12 | 84,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a number n (divisible by 3) and an array a[1 ... n]. In one move, you can increase any of the array elements by one. Formally, you choose the index i (1 ≤ i ≤ n) and replace a_i wi... | instruction | 0 | 42,336 | 12 | 84,672 |
Yes | output | 1 | 42,336 | 12 | 84,673 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.