message stringlengths 2 20.1k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 1.95k 109k | cluster float64 17 17 | __index_level_0__ int64 3.91k 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
teams = int(input())
localColors = []
guestColors = []
changes =0
for i in range(teams):
teami = [int(i) for i in str(input()).split()]
localColors.append(teami[0])
guestColors.append(teami[1])
for local in localColors:
for guest in guestColors:
if local == guest:
changes += 1
print(changes)
``` | instruction | 0 | 57,405 | 17 | 114,810 |
Yes | output | 1 | 57,405 | 17 | 114,811 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
n=int(input())
a=[]
b=[]
for i in range(n):
x,y=map(int,input().split())
a.append(x)
b.append(y)
k=0
for i in range(n):
for j in range(n):
if a[i]==b[j]:
k+=1
print(k)
``` | instruction | 0 | 57,406 | 17 | 114,812 |
Yes | output | 1 | 57,406 | 17 | 114,813 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
n = int(input())
l = []
for i in range(n):
x, y = map(int, input().split())
l.append([x, y])
ans = 0
for i in range(n):
for j in range(n):
if i == j: continue
if l[j][1] == l[i][0]: ans -= -1
print(ans)
``` | instruction | 0 | 57,407 | 17 | 114,814 |
Yes | output | 1 | 57,407 | 17 | 114,815 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
al,bl,ans=[],[],0
for _ in range(int(input())):
a,b=map(int,input().split())
al.append(a)
bl.append(b)
for i in range(len(bl)):
c=al.count('b[i]')
ans+=c
print(ans)
``` | instruction | 0 | 57,408 | 17 | 114,816 |
No | output | 1 | 57,408 | 17 | 114,817 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
home=[]
guest=[]
ncount=0
for i in range(int(input())):
li=[int(x) for x in input().split()]
home.append(li[0])
guest.append(li[1])
for x in home:
if x in guest:
ncount+=1
print(ncount)
``` | instruction | 0 | 57,409 | 17 | 114,818 |
No | output | 1 | 57,409 | 17 | 114,819 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
x=int(input())
t=0
c=[]
for i in range(x):
c.append(input())
for i in range(x):
if(c[i]=="Tetrahedron"):
t=t+4
elif(c[i]=="Cube"):
t=t+6
elif(c[i]=="Octahedron"):
t=t+8
elif(c[i]=="Dodecahedron"):
t=t+12
elif(c[i]=="Icosahedron"):
t=t+20
print(t)
``` | instruction | 0 | 57,410 | 17 | 114,820 |
No | output | 1 | 57,410 | 17 | 114,821 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Manao works on a sports TV. He's spent much time watching the football games of some country. After a while he began to notice different patterns. For example, each team has two sets of uniforms: home uniform and guest uniform. When a team plays a game at home, the players put on the home uniform. When a team plays as a guest on somebody else's stadium, the players put on the guest uniform. The only exception to that rule is: when the home uniform color of the host team matches the guests' uniform, the host team puts on its guest uniform as well. For each team the color of the home and guest uniform is different.
There are n teams taking part in the national championship. The championship consists of n·(n - 1) games: each team invites each other team to its stadium. At this point Manao wondered: how many times during the championship is a host team going to put on the guest uniform? Note that the order of the games does not affect this number.
You know the colors of the home and guest uniform for each team. For simplicity, the colors are numbered by integers in such a way that no two distinct colors have the same number. Help Manao find the answer to his question.
Input
The first line contains an integer n (2 ≤ n ≤ 30). Each of the following n lines contains a pair of distinct space-separated integers hi, ai (1 ≤ hi, ai ≤ 100) — the colors of the i-th team's home and guest uniforms, respectively.
Output
In a single line print the number of games where the host team is going to play in the guest uniform.
Examples
Input
3
1 2
2 4
3 4
Output
1
Input
4
100 42
42 100
5 42
100 5
Output
5
Input
2
1 2
1 2
Output
0
Note
In the first test case the championship consists of 6 games. The only game with the event in question is the game between teams 2 and 1 on the stadium of team 2.
In the second test sample the host team will have to wear guest uniform in the games between teams: 1 and 2, 2 and 1, 2 and 3, 3 and 4, 4 and 2 (the host team is written first).
Submitted Solution:
```
n=int(input())
l=''
j=[]
for i in range(n):
n,m=[int(x) for x in input().split()]
l=l+str(n)+' '
j.append(m)
s=0
for i in j:
if str(i) in l:
s+=l.count(str(i))
print(s)
``` | instruction | 0 | 57,411 | 17 | 114,822 |
No | output | 1 | 57,411 | 17 | 114,823 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3. | instruction | 0 | 58,138 | 17 | 116,276 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
import sys
import os
input = sys.stdin.readline
def sum1n(n):
return (n*(n+1))//2
def count_max(n):
k1 = n//2
k2 = n - k1
return 2*sum1n(n) - sum1n(k1) - sum1n(k2)
n, k = map(int, input().split())
mn = n*(n+1) // 2
if k < mn:
print(-1)
else:
mx = count_max(n)
target = min(k, mx)
os.write(1, (str(target)+"\n").encode())
a = [i for i in range(1, n+1)]
b = [i for i in range(1, n+1)]
cur = mn
i = n-1
while cur != target:
f = a[i]
s = n+1-a[i]
if f-s < target-cur:
b[i], b[n-1-i] = b[n-1-i], b[i]
cur += f-s
i -= 1
else:
j = a[i] - (target-cur) - 1
b[i], b[j] = b[j], b[i]
cur = target
os.write(1, (" ".join(map(str, a))+"\n").encode())
os.write(1, (" ".join(map(str, b))+"\n").encode())
``` | output | 1 | 58,138 | 17 | 116,277 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3. | instruction | 0 | 58,139 | 17 | 116,278 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
import sys
import os
input = sys.stdin.readline
def sum1n(n):
return (n*(n+1))//2
def count_max(n):
k1 = n//2
k2 = n - k1
return 2*sum1n(n) - sum1n(k1) - sum1n(k2)
n, k = map(int, input().split())
mn = n*(n+1) // 2
if k < mn:
print(-1)
else:
mx = count_max(n)
target = min(k, mx)
os.write(1, (str(target)+"\n").encode())
a = [i for i in range(1, n+1)]
b = [i for i in range(1, n+1)]
cur = mn
i = n-1
while cur != target:
f = a[i]
s = n+1-a[i]
if f-s < target-cur:
## print(i)
## print(a)
## print(b)
b[i], b[n-1-i] = b[n-1-i], b[i]
cur += f-s
i -= 1
else:
j = a[i] - (target-cur) - 1
b[i], b[j] = b[j], b[i]
cur = target
os.write(1, (" ".join(map(str, a))+"\n").encode())
os.write(1, (" ".join(map(str, b))+"\n").encode())
``` | output | 1 | 58,139 | 17 | 116,279 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3. | instruction | 0 | 58,140 | 17 | 116,280 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
import os, sys
try: fin = open('in')
except: fin = sys.stdin
input = fin.readline
n, k = map(int, input().split())
l, h = 0, 0
for i in range(1, n + 1):
l += i
h += max(i, n - i + 1)
if k < l:
print (-1)
elif k > h:
os.write(1, ('{}\n{}\n{}'.format(h, ' '.join(map(str, range(1, n + 1))), ' '.join(map(str, range(n, 0, -1))))).encode())
else:
d = k - l
r = n
ans = [i for i in range(n + 1)]
for i in range(1, n + 1):
p = min(r - i, d)
ans[i], ans[i + p] = ans[i + p], ans[i]
d -= p
r -= 1
if d == 0: break
os.write(1, ('{}\n{}\n{}'.format(k, ' '.join(map(str, range(1, n + 1))), ' '.join(map(str, ans[1:])))).encode())
``` | output | 1 | 58,140 | 17 | 116,281 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3. | instruction | 0 | 58,141 | 17 | 116,282 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
n, t = [int(i) for i in input().split()]
import os
def tr(qq):
return (qq*(qq+1))//2
if t < tr(n):
print(-1)
exit()
upp = 2 * (tr(n) - tr(n//2))
if n % 2 == 1:
upp -= (n+1)//2
if t >= upp:
# print(upp)
# exit()
os.write(1, (str(upp) + '\n').encode())
ans = list(range(1, n+1))
# print(*ans)
# for i in range(n//2):
# ans[i] = n - i
os.write(1, (' '.join([str(a) for a in ans]) + '\n').encode())
ans.reverse()
# // print(*ans)
os.write(1, (' '.join([str(a) for a in ans]) + '\n').encode())
exit()
for k in range(n//2, n+1):
goal = t - tr(n) + tr(k) - n
lo = tr(k-1)
hi = lo + (k-1)*(n-k)
# print(goal, lo, hi)
if goal >= lo and goal <= hi:
#p q
ex = goal - lo
p = ex // (k-1)
q = ex % (k-1)
ansl = list(range(1 + p, k + p))
for i in range(q):
ansl[k-2-i] += 1
ansls = set(ansl)
ansr = []
for i in range(1, n):
if i not in ansls:
ansr.append(i)
ans = ansl + [n] + ansr
# print(t)
os.write(1, (str(t) + '\n').encode())
# print(*list(range(1,n+1)))
os.write(1, (' '.join([str(a) for a in range(1,n+1)]) + '\n').encode())
# // print(*ans)
os.write(1, (' '.join([str(a) for a in ans]) + '\n').encode())
exit()
1//0
``` | output | 1 | 58,141 | 17 | 116,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3.
Submitted Solution:
```
# -*- coding: utf-8 -*-
inm=input().split(' ')
n,k=int(inm[0]), int(inm[1])
if(1+n)/2*n >=k:
print(-1)
else:
mk=int((1+n)/2*n)
m =int(k)-(1+n)/2*n
outm = [s for s in range(1,n+1)]
i=0
while m!=0 and i<int(n)/2 :
if m>n-2*i-1:
outm[i],outm[n-i-1]=outm[n-i-1],outm[i]
m-=n-2*i-1
mk+=n-2*i-1
else:
outm[i], outm[i+int(m)]= outm[i+int(m)],outm[i]
mk+=int(m)
m=0
i+=1
print(mk)
print(outm)
for x in range(1,n+1):
print(x, end=" ")
``` | instruction | 0 | 58,142 | 17 | 116,284 |
No | output | 1 | 58,142 | 17 | 116,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3.
Submitted Solution:
```
import os, sys
try: fin = open('in')
except: fin = sys.stdin
input = fin.readline
n, k = map(int, input().split())
l, h = 0, 0
for i in range(1, n + 1):
l += i
h += max(i, n - i + 1)
if k < l:
print (-1)
elif k > h:
os.write(1, ('{}\n{}\n{}'.format(k, ' '.join(map(str, range(1, n + 1))), ' '.join(map(str, range(n, 0, -1))))).encode())
else:
d = k - l
r = n
ans = [i for i in range(n + 1)]
for i in range(1, n + 1):
p = min(r - i, d)
ans[i], ans[i + p] = ans[i + p], ans[i]
d -= p
r -= 1
if d == 0: break
os.write(1, ('{}\n{}\n{}'.format(k, ' '.join(map(str, range(1, n + 1))), ' '.join(map(str, ans[1:])))).encode())
``` | instruction | 0 | 58,143 | 17 | 116,286 |
No | output | 1 | 58,143 | 17 | 116,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3.
Submitted Solution:
```
inp1 = input()
number, max_time = inp1.split()
number = int(number)
max_time = int(max_time)
counter1 = 0
arr1=[i for i in range (1,number+1)]
arr2=arr1
counter = sum(arr1)
if (counter > max_time):
print ('-1')
elif (counter == max_time):
print (counter)
for i in range (number):
print (arr1[i],end = " ")
print()
for i in range (number):
print (arr2[i],end = " ")
print()
else :
for i in range (number-1,0,-1):
for p in range (counter1,i):
if ( ( counter + (arr2[i]-arr1[p]) ) <= max_time and arr2[i] > arr2[p] ):
counter = counter + (arr2[i]-arr1[p])
x = arr2[p]
arr2[p] = arr2[i]
arr2[i] = x
counter1 = p + 1
break
if (counter >= max_time):
break
print (counter)
for i in range (number):
print (arr1[i],end = " ")
print()
for i in range (number):
print (arr2[i],end = " ")
print()
``` | instruction | 0 | 58,144 | 17 | 116,288 |
No | output | 1 | 58,144 | 17 | 116,289 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Demonstrative competitions will be held in the run-up to the 20NN Berlatov Olympic Games. Today is the day for the running competition!
Berlatov team consists of 2n runners which are placed on two running tracks; n runners are placed on each track. The runners are numbered from 1 to n on each track. The runner with number i runs through the entire track in i seconds.
The competition is held as follows: first runners on both tracks start running at the same time; when the slower of them arrives at the end of the track, second runners on both tracks start running, and everyone waits until the slower of them finishes running, and so on, until all n pairs run through the track.
The organizers want the run to be as long as possible, but if it lasts for more than k seconds, the crowd will get bored. As the coach of the team, you may choose any order in which the runners are arranged on each track (but you can't change the number of runners on each track or swap runners between different tracks).
You have to choose the order of runners on each track so that the duration of the competition is as long as possible, but does not exceed k seconds.
Formally, you want to find two permutations p and q (both consisting of n elements) such that sum = ∑_{i=1}^{n} max(p_i, q_i) is maximum possible, but does not exceed k. If there is no such pair, report about it.
Input
The first line contains two integers n and k (1 ≤ n ≤ 10^6, 1 ≤ k ≤ n^2) — the number of runners on each track and the maximum possible duration of the competition, respectively.
Output
If it is impossible to reorder the runners so that the duration of the competition does not exceed k seconds, print -1.
Otherwise, print three lines. The first line should contain one integer sum — the maximum possible duration of the competition not exceeding k. The second line should contain a permutation of n integers p_1, p_2, ..., p_n (1 ≤ p_i ≤ n, all p_i should be pairwise distinct) — the numbers of runners on the first track in the order they participate in the competition. The third line should contain a permutation of n integers q_1, q_2, ..., q_n (1 ≤ q_i ≤ n, all q_i should be pairwise distinct) — the numbers of runners on the second track in the order they participate in the competition. The value of sum = ∑_{i=1}^{n} max(p_i, q_i) should be maximum possible, but should not exceed k. If there are multiple answers, print any of them.
Examples
Input
5 20
Output
20
1 2 3 4 5
5 2 4 3 1
Input
3 9
Output
8
1 2 3
3 2 1
Input
10 54
Output
-1
Note
In the first example the order of runners on the first track should be [5, 3, 2, 1, 4], and the order of runners on the second track should be [1, 4, 2, 5, 3]. Then the duration of the competition is max(5, 1) + max(3, 4) + max(2, 2) + max(1, 5) + max(4, 3) = 5 + 4 + 2 + 5 + 4 = 20, so it is equal to the maximum allowed duration.
In the first example the order of runners on the first track should be [2, 3, 1], and the order of runners on the second track should be [2, 1, 3]. Then the duration of the competition is 8, and it is the maximum possible duration for n = 3.
Submitted Solution:
```
def maxCount(x):
if x % 2 == 0:
return (x * (x + 1)) - (x // 2 * (x // 2 + 1))
else:
return maxCount(x + 1) - x // 2 - 1
count, long = [int(x) for x in input().split()]
minCount = (count * (count + 1)) / 2
if minCount > long:
print(-1)
else:
x = 0
long = min(maxCount(count), long)
prevMoveID = 0
lastMoveID = 0
res = list(range(1, count + 1)).copy()
while long != x:
prevMoveID += 1
res[prevMoveID], res[prevMoveID - 1] = res[prevMoveID - 1], res[prevMoveID]
x = 0
for i in range(0, count):
x += max(res[i], i)
if (prevMoveID == count - lastMoveID - 1):
prevMoveID = 0
lastMoveID += 1
if lastMoveID == count - 1:
break
print(x + 1)
for i in res:
print(i, end = ' ')
print()
for i in range(1, count + 1):
print(i, end = ' ')
``` | instruction | 0 | 58,145 | 17 | 116,290 |
No | output | 1 | 58,145 | 17 | 116,291 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line.
Input
The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.
Output
Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.
Examples
Input
3 3
Output
GBGBGB
Input
4 2
Output
BGBGBB
Note
In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal.
Submitted Solution:
```
with open('input.txt') as _f:
n, m = map(int, _f.readline().split())
pref = 'BG' * min(n, m) if n >= m else 'GB' * min(n, m)
if n != m:
suff = 'B' * (n-m) if n > m else 'G' * (m-n)
else:
suff = ''
with open('outpu.txt', 'w') as _f:
_f.write(pref+suff)
``` | instruction | 0 | 58,312 | 17 | 116,624 |
No | output | 1 | 58,312 | 17 | 116,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line.
Input
The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.
Output
Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.
Examples
Input
3 3
Output
GBGBGB
Input
4 2
Output
BGBGBB
Note
In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal.
Submitted Solution:
```
u, v = open('input.txt','r'), open('output.txt','w')
b, g = map(int, u.readline().split())
v.write('BG' * b + 'G' * (g - b) if b < g else 'BG' * g + 'B' * (b - g))
v.close()
``` | instruction | 0 | 58,313 | 17 | 116,626 |
No | output | 1 | 58,313 | 17 | 116,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n boys and m girls studying in the class. They should stand in a line so that boys and girls alternated there as much as possible. Let's assume that positions in the line are indexed from left to right by numbers from 1 to n + m. Then the number of integers i (1 ≤ i < n + m) such that positions with indexes i and i + 1 contain children of different genders (position i has a girl and position i + 1 has a boy or vice versa) must be as large as possible.
Help the children and tell them how to form the line.
Input
The single line of the input contains two integers n and m (1 ≤ n, m ≤ 100), separated by a space.
Output
Print a line of n + m characters. Print on the i-th position of the line character "B", if the i-th position of your arrangement should have a boy and "G", if it should have a girl.
Of course, the number of characters "B" should equal n and the number of characters "G" should equal m. If there are multiple optimal solutions, print any of them.
Examples
Input
3 3
Output
GBGBGB
Input
4 2
Output
BGBGBB
Note
In the first sample another possible answer is BGBGBG.
In the second sample answer BBGBGB is also optimal.
Submitted Solution:
```
(n, m) = map(int, open('input.txt').read().split(' '))
s = ""
while n > 0 and m > 0:
s += "BG"
n -= 1
m -= 1
while n > 0:
s += "B"
n -= 1
while m > 0:
s += "G"
m -= 1
print(s)
``` | instruction | 0 | 58,314 | 17 | 116,628 |
No | output | 1 | 58,314 | 17 | 116,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Berland State University is hosting a ballroom dance in celebration of its 100500-th anniversary! n boys and m girls are already busy rehearsing waltz, minuet, polonaise and quadrille moves.
We know that several boy&girl pairs are going to be invited to the ball. However, the partners' dancing skill in each pair must differ by at most one.
For each boy, we know his dancing skills. Similarly, for each girl we know her dancing skills. Write a code that can determine the largest possible number of pairs that can be formed from n boys and m girls.
Input
The first line contains an integer n (1 ≤ n ≤ 100) — the number of boys. The second line contains sequence a1, a2, ..., an (1 ≤ ai ≤ 100), where ai is the i-th boy's dancing skill.
Similarly, the third line contains an integer m (1 ≤ m ≤ 100) — the number of girls. The fourth line contains sequence b1, b2, ..., bm (1 ≤ bj ≤ 100), where bj is the j-th girl's dancing skill.
Output
Print a single number — the required maximum possible number of pairs.
Examples
Input
4
1 4 6 2
5
5 1 5 7 9
Output
3
Input
4
1 2 3 4
4
10 11 12 13
Output
0
Input
5
1 1 1 1 1
3
1 2 3
Output
2
Submitted Solution:
```
# URL: http://codeforces.com/problemset/problem/489/B
from typing import List, Tuple
def parse_input() -> Tuple[int, List[int], int, List[int]]:
return (
int(input()),
[int(x) for x in input().split()],
int(input()),
[int(x) for x in input().split()]
)
def solve(n: int, a: List[int], m: int, b: List[int]) -> int:
a.sort()
b.sort()
a_ptr = 0
b_ptr = 0
pairs = 0
while a_ptr < n and b_ptr < m:
d = abs(a[a_ptr] - b[b_ptr])
if a[a_ptr] < b[b_ptr] and d > 1:
a_ptr += 1
elif b[b_ptr] < a[a_ptr] and d > 1:
b_ptr += 1
elif d <= 1:
a_ptr += 1
b_ptr += 1
pairs += 1
return pairs
if __name__ == '__main__':
n, a, m, b = parse_input()
print(solve(n, a, m, b))
``` | instruction | 0 | 58,413 | 17 | 116,826 |
Yes | output | 1 | 58,413 | 17 | 116,827 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The All-Berland National Olympiad in Informatics has just ended! Now Vladimir wants to upload the contest from the Olympiad as a gym to a popular Codehorses website.
Unfortunately, the archive with Olympiad's data is a mess. For example, the files with tests are named arbitrary without any logic.
Vladimir wants to rename the files with tests so that their names are distinct integers starting from 1 without any gaps, namely, "1", "2", ..., "n', where n is the total number of tests.
Some of the files contain tests from statements (examples), while others contain regular tests. It is possible that there are no examples, and it is possible that all tests are examples. Vladimir wants to rename the files so that the examples are the first several tests, all all the next files contain regular tests only.
The only operation Vladimir can perform is the "move" command. Vladimir wants to write a script file, each of the lines in which is "move file_1 file_2", that means that the file "file_1" is to be renamed to "file_2". If there is a file "file_2" at the moment of this line being run, then this file is to be rewritten. After the line "move file_1 file_2" the file "file_1" doesn't exist, but there is a file "file_2" with content equal to the content of "file_1" before the "move" command.
Help Vladimir to write the script file with the minimum possible number of lines so that after this script is run:
* all examples are the first several tests having filenames "1", "2", ..., "e", where e is the total number of examples;
* all other files contain regular tests with filenames "e + 1", "e + 2", ..., "n", where n is the total number of all tests.
Input
The first line contains single integer n (1 ≤ n ≤ 105) — the number of files with tests.
n lines follow, each describing a file with test. Each line has a form of "name_i type_i", where "name_i" is the filename, and "type_i" equals "1", if the i-th file contains an example test, and "0" if it contains a regular test. Filenames of each file are strings of digits and small English letters with length from 1 to 6 characters. The filenames are guaranteed to be distinct.
Output
In the first line print the minimum number of lines in Vladimir's script file.
After that print the script file, each line should be "move file_1 file_2", where "file_1" is an existing at the moment of this line being run filename, and "file_2" — is a string of digits and small English letters with length from 1 to 6.
Examples
Input
5
01 0
2 1
2extra 0
3 1
99 0
Output
4
move 3 1
move 01 5
move 2extra 4
move 99 3
Input
2
1 0
2 1
Output
3
move 1 3
move 2 1
move 3 2
Input
5
1 0
11 1
111 0
1111 1
11111 0
Output
5
move 1 5
move 11 1
move 1111 2
move 111 4
move 11111 3 | instruction | 0 | 58,588 | 17 | 117,176 |
Tags: greedy, implementation
Correct Solution:
```
n = int(input())
t = [1] + [0] * n
b, a = d = [], []
h, s = [], []
for i in range(n):
f, k = input().split()
d[int(k)].append(f)
m = len(a)
for i in a:
if i.isdigit() and i[0] != '0':
j = int(i)
if 0 < j <= m:
t[j] = 1
elif m < j <= n:
t[j] = -1
else:
s.append(i)
else:
s.append(i)
for i in b:
if i.isdigit() and i[0] != '0':
j = int(i)
if m < j <= n:
t[j] = 1
elif 0 < j <= m:
t[j] = -1
else:
s.append(i)
else:
s.append(i)
x = [j for j in range(1, m + 1) if t[j] < 0]
y = [j for j in range(m + 1, n + 1) if t[j] < 0]
u = [j for j in range(1, m + 1) if not t[j]]
v = [j for j in range(m + 1, n + 1) if not t[j]]
if not s and (x or y):
s = ['0']
if y:
i = y.pop()
v.append(i)
else:
i = x.pop()
u.append(i)
h.append(str(i) + ' 0')
t[i] = 0
while x or y:
if v and x:
i = x.pop()
j = v.pop()
t[j] = 1
h.append(str(i) + ' ' + str(j))
u.append(i)
else:
u, v, x, y = v, u, y, x
k = 1
for j in s:
while t[k] == 1: k += 1
h.append(j + ' ' + str(k))
k += 1
d = '\nmove '
print(str(len(h)) + d + d.join(h) if h else 0)
``` | output | 1 | 58,588 | 17 | 117,177 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The All-Berland National Olympiad in Informatics has just ended! Now Vladimir wants to upload the contest from the Olympiad as a gym to a popular Codehorses website.
Unfortunately, the archive with Olympiad's data is a mess. For example, the files with tests are named arbitrary without any logic.
Vladimir wants to rename the files with tests so that their names are distinct integers starting from 1 without any gaps, namely, "1", "2", ..., "n', where n is the total number of tests.
Some of the files contain tests from statements (examples), while others contain regular tests. It is possible that there are no examples, and it is possible that all tests are examples. Vladimir wants to rename the files so that the examples are the first several tests, all all the next files contain regular tests only.
The only operation Vladimir can perform is the "move" command. Vladimir wants to write a script file, each of the lines in which is "move file_1 file_2", that means that the file "file_1" is to be renamed to "file_2". If there is a file "file_2" at the moment of this line being run, then this file is to be rewritten. After the line "move file_1 file_2" the file "file_1" doesn't exist, but there is a file "file_2" with content equal to the content of "file_1" before the "move" command.
Help Vladimir to write the script file with the minimum possible number of lines so that after this script is run:
* all examples are the first several tests having filenames "1", "2", ..., "e", where e is the total number of examples;
* all other files contain regular tests with filenames "e + 1", "e + 2", ..., "n", where n is the total number of all tests.
Input
The first line contains single integer n (1 ≤ n ≤ 105) — the number of files with tests.
n lines follow, each describing a file with test. Each line has a form of "name_i type_i", where "name_i" is the filename, and "type_i" equals "1", if the i-th file contains an example test, and "0" if it contains a regular test. Filenames of each file are strings of digits and small English letters with length from 1 to 6 characters. The filenames are guaranteed to be distinct.
Output
In the first line print the minimum number of lines in Vladimir's script file.
After that print the script file, each line should be "move file_1 file_2", where "file_1" is an existing at the moment of this line being run filename, and "file_2" — is a string of digits and small English letters with length from 1 to 6.
Examples
Input
5
01 0
2 1
2extra 0
3 1
99 0
Output
4
move 3 1
move 01 5
move 2extra 4
move 99 3
Input
2
1 0
2 1
Output
3
move 1 3
move 2 1
move 3 2
Input
5
1 0
11 1
111 0
1111 1
11111 0
Output
5
move 1 5
move 11 1
move 1111 2
move 111 4
move 11111 3 | instruction | 0 | 58,589 | 17 | 117,178 |
Tags: greedy, implementation
Correct Solution:
```
def print_all():
print(top)
print(free_top)
print(busy_top)
print(bottom)
print(free_bottom)
print(busy_bottom)
n = int(input())
top = set()
bottom = set()
for i in range(n):
name, type = input().split()
if type == '1':
top.add(name)
else:
bottom.add(name)
top_order = set(str(i) for i in range(1, len(top) + 1))
bottom_order = set(str(i) for i in range(len(top) + 1, len(bottom) + len(top) + 1))
q = top_order & top
top_order -= q
top -= q
q = bottom_order & bottom
bottom_order -= q
bottom -= q
busy_top = top_order & bottom
free_top = top_order - bottom
busy_bottom = bottom_order & top
free_bottom = bottom_order - top
if len(top_order) + len(bottom_order) == 0:
print(0)
exit(0)
if len(free_bottom) + len(free_top) == 0:
x, y = busy_top.pop(), 'rft330'
free_top.add(x)
bottom.remove(x)
bottom.add(y)
print(len(top_order) + len(bottom_order) + 1)
print('move', x, y)
else:
print(len(top_order) + len(bottom_order))
cross_block = min(len(busy_bottom), len(busy_top))
if len(free_top) > 0 and cross_block > 0:
x = free_top.pop()
for i in range(cross_block):
x, y = busy_bottom.pop(), x
top.remove(x)
print('move', x, y)
x, y = busy_top.pop(), x
bottom.remove(x)
print('move', x, y)
free_top.add(x)
cross_block = min(len(busy_bottom), len(busy_top))
if len(free_bottom) > 0 and cross_block > 0:
x = free_bottom.pop()
for i in range(cross_block):
x, y = busy_top.pop(), x
bottom.remove(x)
print('move', x, y)
x, y = busy_bottom.pop(), x
top.remove(x)
print('move', x, y)
free_bottom.add(x)
if len(busy_bottom) == 0:
for i in range(len(bottom)):
print('move', bottom.pop(), free_bottom.pop())
free_top |= busy_top
busy_top.clear()
for i in range(len(top)):
print('move', top.pop(), free_top.pop())
elif len(busy_top) == 0:
for i in range(len(top)):
print('move', top.pop(), free_top.pop())
free_bottom |= busy_bottom
busy_bottom.clear()
for i in range(len(bottom)):
print('move', bottom.pop(), free_bottom.pop())
``` | output | 1 | 58,589 | 17 | 117,179 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The All-Berland National Olympiad in Informatics has just ended! Now Vladimir wants to upload the contest from the Olympiad as a gym to a popular Codehorses website.
Unfortunately, the archive with Olympiad's data is a mess. For example, the files with tests are named arbitrary without any logic.
Vladimir wants to rename the files with tests so that their names are distinct integers starting from 1 without any gaps, namely, "1", "2", ..., "n', where n is the total number of tests.
Some of the files contain tests from statements (examples), while others contain regular tests. It is possible that there are no examples, and it is possible that all tests are examples. Vladimir wants to rename the files so that the examples are the first several tests, all all the next files contain regular tests only.
The only operation Vladimir can perform is the "move" command. Vladimir wants to write a script file, each of the lines in which is "move file_1 file_2", that means that the file "file_1" is to be renamed to "file_2". If there is a file "file_2" at the moment of this line being run, then this file is to be rewritten. After the line "move file_1 file_2" the file "file_1" doesn't exist, but there is a file "file_2" with content equal to the content of "file_1" before the "move" command.
Help Vladimir to write the script file with the minimum possible number of lines so that after this script is run:
* all examples are the first several tests having filenames "1", "2", ..., "e", where e is the total number of examples;
* all other files contain regular tests with filenames "e + 1", "e + 2", ..., "n", where n is the total number of all tests.
Input
The first line contains single integer n (1 ≤ n ≤ 105) — the number of files with tests.
n lines follow, each describing a file with test. Each line has a form of "name_i type_i", where "name_i" is the filename, and "type_i" equals "1", if the i-th file contains an example test, and "0" if it contains a regular test. Filenames of each file are strings of digits and small English letters with length from 1 to 6 characters. The filenames are guaranteed to be distinct.
Output
In the first line print the minimum number of lines in Vladimir's script file.
After that print the script file, each line should be "move file_1 file_2", where "file_1" is an existing at the moment of this line being run filename, and "file_2" — is a string of digits and small English letters with length from 1 to 6.
Examples
Input
5
01 0
2 1
2extra 0
3 1
99 0
Output
4
move 3 1
move 01 5
move 2extra 4
move 99 3
Input
2
1 0
2 1
Output
3
move 1 3
move 2 1
move 3 2
Input
5
1 0
11 1
111 0
1111 1
11111 0
Output
5
move 1 5
move 11 1
move 1111 2
move 111 4
move 11111 3 | instruction | 0 | 58,590 | 17 | 117,180 |
Tags: greedy, implementation
Correct Solution:
```
import math,string,itertools,fractions,heapq,collections,re,array,bisect,sys,random,time,copy,functools
sys.setrecursionlimit(10**7)
inf = 10**20
eps = 1.0 / 10**10
mod = 10**9+7
def LI(): return [int(x) for x in sys.stdin.readline().split()]
def LI_(): return [int(x)-1 for x in sys.stdin.readline().split()]
def LF(): return [float(x) for x in sys.stdin.readline().split()]
def LS(): return sys.stdin.readline().split()
def I(): return int(sys.stdin.readline())
def F(): return float(sys.stdin.readline())
def S(): return input()
def main():
n = I()
a = set()
b = set()
for _ in range(n):
f,t = LS()
if t == '0':
b.add(f)
else:
a.add(f)
al = len(a)
bl = len(b)
r = []
ta = set([str(i) for i in range(1,al+1)])
tb = set([str(i) for i in range(al+1,al+bl+1)])
bb = tb & b
b -= bb
tb -= bb
aa = ta & a
a -= aa
ta -= aa
ua = a & tb
ub = b & ta
sa = ta - b
sb = tb - a
ran = 'iehn00'
while ua or ub:
if not sa and not sb:
if ua:
t = ua.pop()
sb.add(t)
a.remove(t)
a.add(ran)
else:
t = ub.pop()
sa.add(t)
b.remove(t)
b.add(ran)
r.append('move {} {}'.format(t, ran))
if sa:
t = sa.pop()
if ua:
k = ua.pop()
a.remove(k)
sb.add(k)
else:
k = a.pop()
ta.remove(t)
r.append('move {} {}'.format(k, t))
if sb:
t = sb.pop()
if ub:
k = ub.pop()
b.remove(k)
sa.add(k)
else:
k = b.pop()
tb.remove(t)
r.append('move {} {}'.format(k, t))
while a:
k = a.pop()
t = ta.pop()
r.append('move {} {}'.format(k, t))
while b:
k = b.pop()
t = tb.pop()
r.append('move {} {}'.format(k, t))
return '{}\n'.format(len(r)) + '\n'.join(r)
print(main())
# Made By Mostafa_Khaled
``` | output | 1 | 58,590 | 17 | 117,181 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The All-Berland National Olympiad in Informatics has just ended! Now Vladimir wants to upload the contest from the Olympiad as a gym to a popular Codehorses website.
Unfortunately, the archive with Olympiad's data is a mess. For example, the files with tests are named arbitrary without any logic.
Vladimir wants to rename the files with tests so that their names are distinct integers starting from 1 without any gaps, namely, "1", "2", ..., "n', where n is the total number of tests.
Some of the files contain tests from statements (examples), while others contain regular tests. It is possible that there are no examples, and it is possible that all tests are examples. Vladimir wants to rename the files so that the examples are the first several tests, all all the next files contain regular tests only.
The only operation Vladimir can perform is the "move" command. Vladimir wants to write a script file, each of the lines in which is "move file_1 file_2", that means that the file "file_1" is to be renamed to "file_2". If there is a file "file_2" at the moment of this line being run, then this file is to be rewritten. After the line "move file_1 file_2" the file "file_1" doesn't exist, but there is a file "file_2" with content equal to the content of "file_1" before the "move" command.
Help Vladimir to write the script file with the minimum possible number of lines so that after this script is run:
* all examples are the first several tests having filenames "1", "2", ..., "e", where e is the total number of examples;
* all other files contain regular tests with filenames "e + 1", "e + 2", ..., "n", where n is the total number of all tests.
Input
The first line contains single integer n (1 ≤ n ≤ 105) — the number of files with tests.
n lines follow, each describing a file with test. Each line has a form of "name_i type_i", where "name_i" is the filename, and "type_i" equals "1", if the i-th file contains an example test, and "0" if it contains a regular test. Filenames of each file are strings of digits and small English letters with length from 1 to 6 characters. The filenames are guaranteed to be distinct.
Output
In the first line print the minimum number of lines in Vladimir's script file.
After that print the script file, each line should be "move file_1 file_2", where "file_1" is an existing at the moment of this line being run filename, and "file_2" — is a string of digits and small English letters with length from 1 to 6.
Examples
Input
5
01 0
2 1
2extra 0
3 1
99 0
Output
4
move 3 1
move 01 5
move 2extra 4
move 99 3
Input
2
1 0
2 1
Output
3
move 1 3
move 2 1
move 3 2
Input
5
1 0
11 1
111 0
1111 1
11111 0
Output
5
move 1 5
move 11 1
move 1111 2
move 111 4
move 11111 3 | instruction | 0 | 58,591 | 17 | 117,182 |
Tags: greedy, implementation
Correct Solution:
```
import random
def genTemp():
sl = ""
firstTime = True
while firstTime or sl in pre or sl in post:
sl = ""
firstTime = False
for i in range(6):
sl += chr(random.randint(ord("a"), ord("z")))
return sl
n = int(input())
e = 0
pre = set()
post = set()
for i in range(n):
name, tp = input().split()
if tp == "1":
e += 1
pre.add(name)
else:
post.add(name)
temp = genTemp()
preAns = {str(x) for x in range(1, e + 1)}
postAns = {str(x) for x in range(e + 1, n + 1)}
preMissing = preAns - pre
postMissing = postAns - post
preToChange = pre - preAns
postToChange = post - postAns
preFree = preMissing - postToChange
postFree = postMissing - preToChange
preWrong = preToChange & postMissing
postWrong = postToChange & preMissing
ans = []
while preToChange or postToChange:
if not postFree and not preFree:
if preToChange:
x = preToChange.pop()
preWrong.discard(x)
ans.append(("move", x, temp))
preToChange.add(temp)
#postMissing.discard(x)
if x in postAns:
postFree.add(x)
else:
x = postToChange.pop()
ans.append(("move", x, temp))
postWrong.discard(x)
postToChange.add(temp)
#preMissing.discard(x)
if x in postAns:
preFree.add(x)
elif preFree:
if preWrong:
x = preWrong.pop()
preToChange.discard(x)
else:
x = preToChange.pop()
y = preFree.pop()
ans.append(("move", x, y))
preMissing.discard(y)
if x in postAns:
postFree.add(x)
else:
if postWrong:
x = postWrong.pop()
postToChange.discard(x)
else:
x = postToChange.pop()
y = postFree.pop()
ans.append(("move", x, y))
postMissing.discard(y)
if x in preAns:
preFree.add(x)
print(len(ans))
for tup in ans:
print(*tup)
``` | output | 1 | 58,591 | 17 | 117,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,097 | 17 | 118,194 |
Tags: implementation
Correct Solution:
```
class Player:
def __init__(self, name, score):
self.name = name
self.score = score
class Tier:
def __init__(self, label, percentile):
self.label = label
self.percentile = percentile
tier_data = [ ('pro', 99), ('hardcore', 90),
('average', 80), ('random', 50) ]
tiers = [ Tier(*t) for t in tier_data ]
num_records = int(input())
name_to_score = {}
for i in range(num_records):
tokens = input().split()
name, score = tokens[0], int(tokens[1])
name_to_score[name] = max(name_to_score.setdefault(name, 0), score)
num_players = len(name_to_score)
players = []
for name, score in name_to_score.items():
players.append(Player(name, score))
players.sort(key = lambda player: player.score)
print(num_players)
pos = num_players - 1
while pos >= 0:
player = players[pos]
rank = 'noob'
score = player.score
for tier in tiers:
if 100 * (pos + 1) // num_players >= tier.percentile:
rank = tier.label
break
print(player.name, rank)
pos -= 1
while pos >= 0 and players[pos].score == score:
print(players[pos].name, rank)
pos -= 1
``` | output | 1 | 59,097 | 17 | 118,195 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,098 | 17 | 118,196 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
n = int(input())
p = defaultdict(int)
for i in range(n):
a, b = input().split()
p[a] = max(p[a], int(b))
b = sorted(p.values())
n = len(b)
noob = b[(n - 1) // 2]
random = b[n - 1 - n // 5]
average = b[n - 1 - n // 10]
hardcore = b[n - 1 - n // 100]
for a in p:
b = p[a]
if b < noob: p[a] = 'noob'
elif b < random: p[a] = 'random'
elif b < average: p[a] = 'average'
elif b < hardcore: p[a] = 'hardcore'
else: p[a] = 'pro'
print(n + 1)
print('\n'.join(a + ' ' + b for a, b in p.items()))
``` | output | 1 | 59,098 | 17 | 118,197 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,099 | 17 | 118,198 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
R = lambda: map(int, input().split())
n = int(input())
mp = defaultdict(int)
for i in range(n):
name, sc = input().split()
sc = int(sc)
mp[name] = max(sc, mp[name])
players = sorted([(k, v) for k, v in mp.items()], key=lambda x: x[1])
print(len(players))
j = 0
for i, playerAndScore in enumerate(players):
player, score = playerAndScore
while j < len(players) and players[j][1] <= score:
j += 1
if j / len(players) < 0.5:
print(' '.join([player, 'noob']))
elif 0.5 <= j / len(players) < 0.8:
print(' '.join([player, 'random']))
elif 0.8 <= j / len(players) < 0.9:
print(' '.join([player, 'average']))
elif 0.9 <= j / len(players) < 0.99:
print(' '.join([player, 'hardcore']))
else:
print(' '.join([player, 'pro']))
``` | output | 1 | 59,099 | 17 | 118,199 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,100 | 17 | 118,200 |
Tags: implementation
Correct Solution:
```
import sys
import math
from heapq import *;
input = sys.stdin.readline
from functools import cmp_to_key;
def pi():
return(int(input()))
def pl():
return(int(input(), 16))
def ti():
return(list(map(int,input().split())))
def ts():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
mod = 1000000007;
f = [];
def fact(n,m):
global f;
f = [1 for i in range(n+1)];
f[0] = 1;
for i in range(1,n+1):
f[i] = (f[i-1]*i)%m;
def fast_mod_exp(a,b,m):
res = 1;
while b > 0:
if b & 1:
res = (res*a)%m;
a = (a*a)%m;
b = b >> 1;
return res;
def inverseMod(n,m):
return fast_mod_exp(n,m-2,m);
def ncr(n,r,m):
if n < 0 or r < 0 or r > n: return 0;
if r == 0: return 1;
return ((f[n]*inverseMod(f[n-r],m))%m*inverseMod(f[r],m))%m;
def main():
B();
def B():
n = pi();
mp = {};
for i in range(n):
[name,score] = input().split(' ');
score = int(score[:-1]);
if name not in mp:
mp[name] = score;
else:
val = mp[name];
mp[name] = max(val,score);
tot = 0;
for item in mp:
tot += 1;
ans = {};
for name in mp:
count = 0;
for other in mp:
if name != other:
if mp[other] > mp[name]:
count += 1;
ans[name] = ((tot-count)/tot)*100;
print(tot);
for name in ans:
print(name, "noob" if ans[name] < 50 else "random" if ans[name] < 80 else "average" if ans[name] < 90 else "hardcore" if ans[name] < 99 else "pro");
main();
``` | output | 1 | 59,100 | 17 | 118,201 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,101 | 17 | 118,202 |
Tags: implementation
Correct Solution:
```
def t(g, n):
for x, y in ((50, 'noob'), (20, 'random'), (10, 'average'), (1, 'hardcore')):
if g > x * n // 100:
return y
return 'pro'
p, st = {}, {}
for i in range(int(input())):
n, s = input().split()
if n not in p or int(s) > p[n]:
p[n] = int(s)
for i, si in enumerate(sorted(p.values(), reverse=True)):
if si not in st:
st[si] = t(i, len(p))
print(len(p))
print(*sorted(k + ' ' + st[p[k]] for k in p), sep='\n')
# Made By Mostafa_Khaled
``` | output | 1 | 59,101 | 17 | 118,203 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,102 | 17 | 118,204 |
Tags: implementation
Correct Solution:
```
from collections import defaultdict
from bisect import bisect_left
p, n = defaultdict(int), int(input())
for i in range(n):
a, b = input().split()
p[a] = max(p[a], int(b))
p, n = sorted((b, a) for a, b in p.items()), len(p)
t = [0] + [bisect_left(p, (p[n - 1 - n // k][0], '')) for k in [2, 5, 10, 100]] + [n]
s = ['noob', 'random', 'average', 'hardcore', 'pro']
for i in range(1, len(t)):
d = s[i - 1]
for j in range(t[i - 1], t[i]): p[j] = p[j][1] + ' ' + d
print(n)
print('\n'.join(p))
``` | output | 1 | 59,102 | 17 | 118,205 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,103 | 17 | 118,206 |
Tags: implementation
Correct Solution:
```
I=input
P=print
d={}
for _ in'0'*int(I()):a,b=I().split();d[a]=max(d.get(a,0),int(b))
v=d.values()
n=len(d)
P(n)
for k in d:
a=b=0
for x in v:a+=x<=d[k];b+=x>d[k]
s='noob';a/=n;b/=n
if a>=.5and b>=.2:s='random'
if a>=.8and b>=.1:s='average'
if a>=.9and b>=.01:s='hardcore'
if a>=.99:s='pro'
P(k,s)
``` | output | 1 | 59,103 | 17 | 118,207 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro". | instruction | 0 | 59,104 | 17 | 118,208 |
Tags: implementation
Correct Solution:
```
n = int(input())
d = {}
for _ in '0' * n:
s, v = input().split()
d[s] = max(d.get(s, 0), int(v))
v = d.values()
res = str(len(d)) + '\n'
for k in d:
a, b = 0, 0
for x in v:
a += x <= d[k]
b += x > d[k]
s = 'noob'
a /= len(d)
b /= len(d)
if a >= .5 and b >= .2: s = 'random'
if a >= .8 and b >= .1: s = 'average'
if a >= .9 and b >= .01: s = 'hardcore'
if a >= .99: s='pro'
res += k + ' ' + s + '\n'
print(res)
``` | output | 1 | 59,104 | 17 | 118,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
n = int(input())
dic = {}
length = 0
for i in range(n):
player,score = input().split()
score = int(score)
if player not in dic:
dic[player] = score
length += 1
else:
if dic[player]<score:
dic[player] = score
sortd_values = sorted(dic.values(),reverse=True)
print(length)
for key in dic:
index = sortd_values.index(dic[key])
t = (index/length)*100
if t>50:
print(key,'noob')
elif t>20:
print(key,'random')
elif t>10:
print(key,'average')
elif t>1:
print(key,'hardcore')
else:
print(key,'pro')
``` | instruction | 0 | 59,105 | 17 | 118,210 |
Yes | output | 1 | 59,105 | 17 | 118,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
def t(g, n):
for x, y in ((50, 'noob'), (20, 'random'), (10, 'average'), (1, 'hardcore')):
if g > x * n // 100:
return y
return 'pro'
p, st = {}, {}
for i in range(int(input())):
n, s = input().split()
if n not in p or int(s) > p[n]:
p[n] = int(s)
for i, si in enumerate(sorted(p.values(), reverse=True)):
if si not in st:
st[si] = t(i, len(p))
print(len(p))
print(*sorted(k + ' ' + st[p[k]] for k in p), sep='\n')
``` | instruction | 0 | 59,106 | 17 | 118,212 |
Yes | output | 1 | 59,106 | 17 | 118,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
n = int(input())
player_points = {}
for _ in range(n):
name, points = input().split()
points = int(points)
if name in player_points:
if player_points[name] < points:
player_points[name] = points
else:
player_points[name] = points
points_list = sorted(player_points.values(), reverse=True)
m = len(player_points)
print(m)
for player, points in player_points.items():
if points_list[m // 2] > points:
print(player, "noob")
elif points_list[m // 5] > points and \
points_list[(m - 1) // 2] <= points:
print(player, "random")
elif points_list[m // 10] > points and \
points_list[((m + 4) // 5) - 1] <= points:
print(player, "average")
elif points_list[m // 100] > points and \
points_list[((m + 9) // 10) - 1] <= points:
print(player, "hardcore")
else:
print(player, "pro")
``` | instruction | 0 | 59,107 | 17 | 118,214 |
No | output | 1 | 59,107 | 17 | 118,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
from collections import defaultdict
n = int(input())
p = defaultdict(int)
for i in range(n):
a, b = input().split()
p[a] = max(p[a], int(b))
b = sorted(p.values())
nub = b[len(b) // 2]
random = b[(4 * len(b)) // 5]
average = b[(9 * len(b)) // 10]
hardcore = b[(99 * len(b)) // 100]
for a in p:
b = p[a]
if b < nub: p[a] = 'nub'
elif b < random: p[a] = 'random'
elif b < average: p[a] = 'average'
elif b < hardcore: p[a] = 'hardcore'
else: p[a] = 'pro'
print('\n'.join(a + ' ' + b for a, b in p.items()))
``` | instruction | 0 | 59,108 | 17 | 118,216 |
No | output | 1 | 59,108 | 17 | 118,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
import sys
import math
from heapq import *;
input = sys.stdin.readline
from functools import cmp_to_key;
def pi():
return(int(input()))
def pl():
return(int(input(), 16))
def ti():
return(list(map(int,input().split())))
def ts():
s = input()
return(list(s[:len(s) - 1]))
def invr():
return(map(int,input().split()))
mod = 1000000007;
f = [];
def fact(n,m):
global f;
f = [1 for i in range(n+1)];
f[0] = 1;
for i in range(1,n+1):
f[i] = (f[i-1]*i)%m;
def fast_mod_exp(a,b,m):
res = 1;
while b > 0:
if b & 1:
res = (res*a)%m;
a = (a*a)%m;
b = b >> 1;
return res;
def inverseMod(n,m):
return fast_mod_exp(n,m-2,m);
def ncr(n,r,m):
if n < 0 or r < 0 or r > n: return 0;
if r == 0: return 1;
return ((f[n]*inverseMod(f[n-r],m))%m*inverseMod(f[r],m))%m;
def main():
B();
def B():
n = pi();
mp = {};
for i in range(n):
[name,score] = input().split(' ');
score = int(score[:-1]);
if name not in mp:
mp[name] = score;
else:
val = mp[name];
mp[name] = max(val,score);
tot = 0;
for item in mp:
tot += 1;
ans = {};
for name in mp:
count = 0;
for other in mp:
if name != other:
if mp[other] > mp[name]:
count += 1;
ans[name] = ((tot-count)/tot)*100;
for name in ans:
print(name, "noob" if ans[name] <= 50 else "random" if ans[name] <= 80 else "average" if ans[name] <= 90 else "hardcore" if ans[name] <= 99 else "pro");
main();
``` | instruction | 0 | 59,109 | 17 | 118,218 |
No | output | 1 | 59,109 | 17 | 118,219 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has been playing Plane of Tanks with his friends the whole year. Now it is time to divide the participants into several categories depending on their results.
A player is given a non-negative integer number of points in each round of the Plane of Tanks. Vasya wrote results for each round of the last year. He has n records in total.
In order to determine a player's category consider the best result obtained by the player and the best results of other players. The player belongs to category:
* "noob" — if more than 50% of players have better results;
* "random" — if his result is not worse than the result that 50% of players have, but more than 20% of players have better results;
* "average" — if his result is not worse than the result that 80% of players have, but more than 10% of players have better results;
* "hardcore" — if his result is not worse than the result that 90% of players have, but more than 1% of players have better results;
* "pro" — if his result is not worse than the result that 99% of players have.
When the percentage is calculated the player himself is taken into account. That means that if two players played the game and the first one gained 100 points and the second one 1000 points, then the first player's result is not worse than the result that 50% of players have, and the second one is not worse than the result that 100% of players have.
Vasya gave you the last year Plane of Tanks results. Help Vasya determine each player's category.
Input
The first line contains the only integer number n (1 ≤ n ≤ 1000) — a number of records with the players' results.
Each of the next n lines contains a player's name and the amount of points, obtained by the player for the round, separated with a space. The name contains not less than 1 and no more than 10 characters. The name consists of lowercase Latin letters only. It is guaranteed that any two different players have different names. The amount of points, obtained by the player for the round, is a non-negative integer number and does not exceed 1000.
Output
Print on the first line the number m — the number of players, who participated in one round at least.
Each one of the next m lines should contain a player name and a category he belongs to, separated with space. Category can be one of the following: "noob", "random", "average", "hardcore" or "pro" (without quotes). The name of each player should be printed only once. Player names with respective categories can be printed in an arbitrary order.
Examples
Input
5
vasya 100
vasya 200
artem 100
kolya 200
igor 250
Output
4
artem noob
igor pro
kolya random
vasya random
Input
3
vasya 200
kolya 1000
vasya 1000
Output
2
kolya pro
vasya pro
Note
In the first example the best result, obtained by artem is not worse than the result that 25% of players have (his own result), so he belongs to category "noob". vasya and kolya have best results not worse than the results that 75% players have (both of them and artem), so they belong to category "random". igor has best result not worse than the result that 100% of players have (all other players and himself), so he belongs to category "pro".
In the second example both players have the same amount of points, so they have results not worse than 100% players have, so they belong to category "pro".
Submitted Solution:
```
I=input
d={}
for _ in'0'*int(I()):a,b=I().split();d[a]=max(d.get(a,0),int(b))
v=d.values()
n=len(d)
for k in d:
a=b=0
for x in v:a+=x<=d[k];b+=x>d[k]
s='noob';a/=n;b/=n
if a>=.5and b>=.2:s='random'
if a>=.8and b>=.1:s='average'
if a>=.9and b>=.01:s='hardcore'
if a>=.99:s='pro'
print(k,s)
``` | instruction | 0 | 59,110 | 17 | 118,220 |
No | output | 1 | 59,110 | 17 | 118,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,316 | 17 | 120,632 |
Tags: math
Correct Solution:
```
a = list(map(int, input().split(' ')))
c = (a[0] * a[1] + 2*a[3]) - (a[0]*a[2] + 2*a[4])
if(c < 0):
print('First')
elif (c > 0):
print('Second')
else:
print('Friendship')
``` | output | 1 | 60,316 | 17 | 120,633 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,317 | 17 | 120,634 |
Tags: math
Correct Solution:
```
x = list(map(int, input().split()))
a = (x[0]*x[1]) + (2*x[3])
b = (x[0]*x[2]) + (2*x[4])
if a < b:
print("First")
elif a > b:
print("Second")
else:
print("Friendship")
``` | output | 1 | 60,317 | 17 | 120,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,318 | 17 | 120,636 |
Tags: math
Correct Solution:
```
a,b,c,d,e=map(int,input().split())
f =a/(1/b)+2*d
g=a/(1/c)+2*e
if f<g:
print("First")
elif f==g:
print("Friendship")
else:
print("Second")
``` | output | 1 | 60,318 | 17 | 120,637 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,319 | 17 | 120,638 |
Tags: math
Correct Solution:
```
s, v1, v2, t1, t2 = map(int, input().split())
if s * v1 + 2 * t1 == s * v2 + 2 * t2:
print('Friendship')
else:
if s * v1 + 2 * t1 < s * v2 + 2 * t2:
print('First')
else:
print('Second')
``` | output | 1 | 60,319 | 17 | 120,639 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,320 | 17 | 120,640 |
Tags: math
Correct Solution:
```
s,v1,v2,t1,t2 = map(int,input().split())
if t1 * 2 + v1 * s < t2 * 2 + v2 * s:
print('First')
elif t1 * 2 + v1 * s > t2 * 2 + v2 * s:
print('Second')
else:
print('Friendship')
``` | output | 1 | 60,320 | 17 | 120,641 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,321 | 17 | 120,642 |
Tags: math
Correct Solution:
```
s, v1, v2, t1, t2 = list(map(int, input().split()))
tt1, tt2 = (s*v1)+(2*t1), (s*v2)+(2*t2)
if tt1==tt2: print('Friendship')
else: print(['First','Second'][tt2<tt1])
``` | output | 1 | 60,321 | 17 | 120,643 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,322 | 17 | 120,644 |
Tags: math
Correct Solution:
```
s,v1,v2,t1,t2=map(int, input().split())
a=(s*v1+2*t1)-(s*v2+2*t2)
if a<0:
print("First")
elif a>0:
print("Second")
else:
print("Friendship")
``` | output | 1 | 60,322 | 17 | 120,645 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw. | instruction | 0 | 60,323 | 17 | 120,646 |
Tags: math
Correct Solution:
```
s,v1,v2,t1,t2=input().split()
time_1=int(t1)+int(s)*int(v1)+int(t1)
time_2=int(t2)++int(s)*int(v2)+int(t2)
if(time_1<time_2):
print("First")
elif(time_2<time_1):
print("Second")
else:
print("Friendship")
``` | output | 1 | 60,323 | 17 | 120,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.
Submitted Solution:
```
ins = input().split(" ")
n = int(ins[0])
v1 = int(ins[1])
v2 = int(ins[2])
t1 = int(ins[3])
t2 = int(ins[4])
a = (n * v1) + (2 * t1)
b = (n * v2) + (2 * t2)
if a < b:
print("First")
elif a > b:
print("Second")
else:
print("Friendship")
``` | instruction | 0 | 60,324 | 17 | 120,648 |
Yes | output | 1 | 60,324 | 17 | 120,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.
Submitted Solution:
```
s, v1, v2, t1, t2 = map(int, input().split())
ans = s*(v2-v1) + 2*(t2-t1)
print(["Friendship", "First", "Second"][ans//(max(abs(ans), 1))])
``` | instruction | 0 | 60,325 | 17 | 120,650 |
Yes | output | 1 | 60,325 | 17 | 120,651 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.
Submitted Solution:
```
s,v1,v2,t1,t2=[int(i) for i in input().split()]
p1=(2*t1)+(s*v1)
p2=(2*t2)+(s*v2)
if p1>p2:
print('Second')
elif p1<p2:
print('First')
else:
print('Friendship',end='')
``` | instruction | 0 | 60,326 | 17 | 120,652 |
Yes | output | 1 | 60,326 | 17 | 120,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.
Submitted Solution:
```
matn,yak,duyum,se1,se2=map(int,input().split())
s=yak*matn+se1*2
s2=duyum*matn+se2*2
if s<s2:print('First');exit()
if s>s2:print('Second');exit()
print('Friendship')
``` | instruction | 0 | 60,327 | 17 | 120,654 |
Yes | output | 1 | 60,327 | 17 | 120,655 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Two boys decided to compete in text typing on the site "Key races". During the competition, they have to type a text consisting of s characters. The first participant types one character in v1 milliseconds and has ping t1 milliseconds. The second participant types one character in v2 milliseconds and has ping t2 milliseconds.
If connection ping (delay) is t milliseconds, the competition passes for a participant as follows:
1. Exactly after t milliseconds after the start of the competition the participant receives the text to be entered.
2. Right after that he starts to type it.
3. Exactly t milliseconds after he ends typing all the text, the site receives information about it.
The winner is the participant whose information on the success comes earlier. If the information comes from both participants at the same time, it is considered that there is a draw.
Given the length of the text and the information about participants, determine the result of the game.
Input
The first line contains five integers s, v1, v2, t1, t2 (1 ≤ s, v1, v2, t1, t2 ≤ 1000) — the number of characters in the text, the time of typing one character for the first participant, the time of typing one character for the the second participant, the ping of the first participant and the ping of the second participant.
Output
If the first participant wins, print "First". If the second participant wins, print "Second". In case of a draw print "Friendship".
Examples
Input
5 1 2 1 2
Output
First
Input
3 3 1 1 1
Output
Second
Input
4 5 3 1 5
Output
Friendship
Note
In the first example, information on the success of the first participant comes in 7 milliseconds, of the second participant — in 14 milliseconds. So, the first wins.
In the second example, information on the success of the first participant comes in 11 milliseconds, of the second participant — in 5 milliseconds. So, the second wins.
In the third example, information on the success of the first participant comes in 22 milliseconds, of the second participant — in 22 milliseconds. So, it is be a draw.
Submitted Solution:
```
I = [int(x) for x in input().split()]
time1 = I[0]*I[1] + 2*I[3]
time2 = I[0]*I[2] + 2*I[4]
if time1 < time2:
print('First')
elif time1 > time2:
print('Second')
else:
print('Friednship')
``` | instruction | 0 | 60,328 | 17 | 120,656 |
No | output | 1 | 60,328 | 17 | 120,657 |
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