message
stringlengths
2
20.1k
message_type
stringclasses
2 values
message_id
int64
0
1
conversation_id
int64
1.95k
109k
cluster
float64
17
17
__index_level_0__
int64
3.91k
217k
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Stepan is a very experienced olympiad participant. He has n cups for Physics olympiads and m cups for Informatics olympiads. Each cup is characterized by two parameters — its significance ci and width wi. Stepan decided to expose some of his cups on a shelf with width d in such a way, that: * there is at least one Physics cup and at least one Informatics cup on the shelf, * the total width of the exposed cups does not exceed d, * from each subjects (Physics and Informatics) some of the most significant cups are exposed (i. e. if a cup for some subject with significance x is exposed, then all the cups for this subject with significance greater than x must be exposed too). Your task is to determine the maximum possible total significance, which Stepan can get when he exposes cups on the shelf with width d, considering all the rules described above. The total significance is the sum of significances of all the exposed cups. Input The first line contains three integers n, m and d (1 ≤ n, m ≤ 100 000, 1 ≤ d ≤ 109) — the number of cups for Physics olympiads, the number of cups for Informatics olympiads and the width of the shelf. Each of the following n lines contains two integers ci and wi (1 ≤ ci, wi ≤ 109) — significance and width of the i-th cup for Physics olympiads. Each of the following m lines contains two integers cj and wj (1 ≤ cj, wj ≤ 109) — significance and width of the j-th cup for Informatics olympiads. Output Print the maximum possible total significance, which Stepan can get exposing cups on the shelf with width d, considering all the rules described in the statement. If there is no way to expose cups on the shelf, then print 0. Examples Input 3 1 8 4 2 5 5 4 2 3 2 Output 8 Input 4 3 12 3 4 2 4 3 5 3 4 3 5 5 2 3 4 Output 11 Input 2 2 2 5 3 6 3 4 2 8 1 Output 0 Note In the first example Stepan has only one Informatics cup which must be exposed on the shelf. Its significance equals 3 and width equals 2, so after Stepan exposes it, the width of free space on the shelf becomes equal to 6. Also, Stepan must expose the second Physics cup (which has width 5), because it is the most significant cup for Physics (its significance equals 5). After that Stepan can not expose more cups on the shelf, because there is no enough free space. Thus, the maximum total significance of exposed cups equals to 8. Submitted Solution: ``` n, m, d = input().split() n = int(n) m = int(m) d = int(d) # c = {} # w = {} # topPhys = (0,-0) #cost, -width # topInf = (0,-0) phys = [] it = [] for i in range(0,n): c, w = input().split() c = int(c) w = int(w) phys.append([-c,w,'p']) phys = sorted(phys) for i in range(n,m+n): c, w = input().split() c = int(c) w = int(w) it.append([-c,w,'i']) it = sorted(it) curw = phys[0][1] + it[0][1] curc = - phys[0][0] - it[0][0] if (curw > d): print(0) quit() phys[0][0] = 0 it[0][0] = 0 cup = [] cup.extend(phys) cup.extend(it) cup = sorted(cup) # print("curc", curc) # print("cups", cup) phs = True its = True i = 0 while (phs and its and i < n+m): if (curw + cup[i][1] > d): if (cup[i][2] == 'i'): its = False else: phs = False else: if (its and cup[i][2] == 'i') or (phs and cup[i][2] == 'p'): curw += cup[i][1] curc -= cup[i][0] ++i print(curc) ```
instruction
0
101,687
17
203,374
No
output
1
101,687
17
203,375
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,974
17
203,948
"Correct Solution: ``` h1, h2 = map(int, input().split()) k1, k2 = map(int, input().split()) a, b, c, d = map(int, input().split()) H = h1 * a + h2 * b + h1 // 10 * c + h2 // 20 * d K = k1 * a + k2 * b + k1 // 10 * c + k2 // 20 * d print('hiroshi' if H>K else 'even' if H==K else 'kenjiro') ```
output
1
101,974
17
203,949
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,975
17
203,950
"Correct Solution: ``` h1,h2 = [int(i) for i in input().split()] k1,k2 = [int(i) for i in input().split()] a,b,c,d = [int(i) for i in input().split()] p1 = a*h1 + c*(h1 // 10) + b*h2 + d*(h2 // 20) p2 = a*k1 + c*(k1 // 10) + b*k2 + d*(k2 // 20) if p1 > p2: print("hiroshi") elif p1 < p2: print("kenjiro") else: print("even") ```
output
1
101,975
17
203,951
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,976
17
203,952
"Correct Solution: ``` def getScore(i, y): return i*a+y*b+c*(i//10)+d*(y//20) h1, h2 = map(int, input().split()) k1, k2 = map(int, input().split()) a, b, c, d = map(int, input().split()) h, k = getScore(h1, h2), getScore(k1, k2) if h>k: print('hiroshi') elif h<k: print('kenjiro') else: print('even') ```
output
1
101,976
17
203,953
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,977
17
203,954
"Correct Solution: ``` h1, h2 = map(int, input().split()) k1, k2 = map(int, input().split()) a, b, c, d = map(int, input().split()) hiroshi = h1*a + h1//10*c + h2*b + h2//20*d kenjiro = k1*a + k1//10*c + k2*b + k2//20*d if hiroshi > kenjiro: print("hiroshi") elif hiroshi < kenjiro: print("kenjiro") else: print("even") ```
output
1
101,977
17
203,955
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,978
17
203,956
"Correct Solution: ``` hi, hy = map(int, input().split()) ki, ky = map(int, input().split()) a, b, c, d = map(int, input().split()) h = hi * a + hi // 10 * c + hy * b + hy // 20 * d k = ki * a + ki // 10 * c + ky * b + ky // 20 * d if h > k: print("hiroshi") elif h < k: print("kenjiro") else: print("even") ```
output
1
101,978
17
203,957
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,979
17
203,958
"Correct Solution: ``` h1,h2=map(int,input().split()) k1,k2=map(int,input().split()) a,b,c,d=map(int,input().split()) hp=h1*a+h2*b+(h1//10)*c+(h2//20)*d kp=k1*a+k2*b+(k1//10)*c+(k2//20)*d if hp>kp: print("hiroshi") elif kp>hp: print("kenjiro") else: print("even") ```
output
1
101,979
17
203,959
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,980
17
203,960
"Correct Solution: ``` h, i = map(int, input().split()) k, l = map(int, input().split()) a, b, c, d = map(int, input().split()) p = h * a + h // 10 * c + i * b + i // 20 * d q = k * a + k // 10 * c + l * b + l // 20 * d if p == q:print("even") else:print("hiroshi" if p > q else "kenjiro") ```
output
1
101,980
17
203,961
Provide a correct Python 3 solution for this coding contest problem. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even
instruction
0
101,981
17
203,962
"Correct Solution: ``` #標準入力 ha,hb = map(int,input().split()) ka,kb = map(int,input().split()) a,b,c,d = map(int,input().split()) ht,kt = 0,0 #得点の計算 ht = ha * a + hb * b + (ha // 10) * c + (hb // 20) * d kt = ka * a + kb * b + (ka // 10) * c + (kb // 20) * d #得点が大きいほう、または引き分けを出力する if ht > kt:print("hiroshi") elif ht < kt:print("kenjiro") elif ht == kt:print("even") ```
output
1
101,981
17
203,963
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h1, h2 = list(map(int, input().split())) k1, k2 = list(map(int, input().split())) a,b,c,d = list(map(int, input().split())) hiro = h1*a + h2*b + (h1//10)*c + (h2//20)*d ken = k1*a + k2*b + (k1//10)*c + (k2//20)*d if hiro>ken: print('hiroshi') elif ken>hiro: print('kenjiro') else: print('even') ```
instruction
0
101,982
17
203,964
Yes
output
1
101,982
17
203,965
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` [h1, h2] = [int(num) for num in input().split()] [k1, k2] = [int(num) for num in input().split()] [a, b, c, d] = [int(num) for num in input().split()] counth = a * h1 + b * h2 + c * (h1 // 10) + d * (h2 // 20) countk = a * k1 + b * k2 + c * (k1 // 10) + d * (k2 // 20) if (counth > countk): print('hiroshi') elif (counth < countk): print('kenjiro') else: print('even') ```
instruction
0
101,983
17
203,966
Yes
output
1
101,983
17
203,967
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h,i = map(int,input().split(" ")) k,j = map(int,input().split(" ")) a,b,c,d = map(int,input().split(" ")) s=h*a+i*b+(h//10)*c+(i//20)*d r=k*a+j*b+(k//10)*c+(j//20)*d if s > r: print("hiroshi") elif s == r: print("even") else: print("kenjiro") ```
instruction
0
101,984
17
203,968
Yes
output
1
101,984
17
203,969
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h1, h2 = map(int,input().split()) k1, k2 = map(int,input().split()) a, b, c, d = map(int,input().split()) if h1 > 9: hn = int(h1/10) else: hn = 0 if h2 > 19: hm = int(h1/20) else: hm = 0 if k1 > 9: kn = int(k1/10) else: kn = 0 if k2 > 19: km = int(k2/20) else: km = 0 h = h1*a + hn*c + h2*b + hm*d k = k1*a + kn*c + k2*b + km*d if h<k: print("kenjiro") elif k<h: print("hiroshi") elif h == k: print("even") ```
instruction
0
101,985
17
203,970
Yes
output
1
101,985
17
203,971
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h1, h2 = map(int, input().split()) k1, k2 = map(int, input().split()) a, b, c, d = map(int, input().split()) H = h1 * a + h2 * b + h1 // 10 * c + h2 // 10 * d K = k1 * a + k2 * b + k1 // 10 * c + k2 // 10 * d print('hiroshi' if H>K else 'even' if H==K else 'kenjiro') ```
instruction
0
101,986
17
203,972
No
output
1
101,986
17
203,973
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h1,h2 = map(int,input().split()) k1,k2 = map(int,input().split()) a,b,c,d = map(int,input().split()) def f(x,y): return a*x + b*y + c*(x//10) + d*(y//10) H,K = f(h1,h2), f(k1,k2) ans = 'even' if H>K: ans = 'hiroshi' elif H<K: ans = 'kenjiro' print(ans) ```
instruction
0
101,987
17
203,974
No
output
1
101,987
17
203,975
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h, i = map(int, input().split()) k, l = map(int, input().split()) a, b, c, d = map(int, input().split()) p = h * a + h // 10 * c + i * b + i // 10 * d q = k * a + k // 10 * c + l * b + l // 10 * d if p == q:print("even") else:print("hiroshi" if p > q else "kenjiro") ```
instruction
0
101,988
17
203,976
No
output
1
101,988
17
203,977
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. The brothers Hiroshi and Kenjiro came to Lake Inawashiro for fishing. The two decided to score as follows and compete with the total score of the fish they caught. * One char is a point * One yamame trout b points * Add c points for every 10 chars * Add d points for every 20 yamame trout Create a program to determine which one wins or draws based on the number of fish caught by Hiroshi and Kenjiro. Input The input is given in the following format. h1 h2 k1 k2 a b c d The first line gives the number of chars h1 (0 ≤ h1 ≤ 100) and the number of yamame trout h2 (0 ≤ h2 ≤ 100) caught by Hiroshi. The second line gives the number of chars k1 (0 ≤ k1 ≤ 100) and the number of yamame trout k2 (0 ≤ k2 ≤ 100) caught by Kenjiro. On the third line, the score for each char is a (1 ≤ a ≤ 100), the score for each yamame trout is b (1 ≤ b ≤ 100), and the additional score for every 10 chars is c (0 ≤ c ≤ 100). ), An additional score d (0 ≤ d ≤ 100) is given for every 20 chars. Output If Hiro wins, hiroshi, if Kenjiro wins, kenjiro, and if a tie, even, output on one line. Examples Input 5 1 3 1 1 2 5 5 Output hiroshi Input 5 1 4 2 1 2 5 5 Output kenjiro Input 0 20 10 0 1 1 10 0 Output even Submitted Solution: ``` h1,h2=map(int,input().split()) k1,k2=map(int,input().split()) a,b,c,d=map(int,input().split()) e,f,g,h=h1*a,h2*b,k1*a,k2*b o,n,m,v=h1//10*c,h2//10*d,k1//10*c,k2//10*d z,y=o+n+e+f,m+v+g+h if z>y: print("hiroshi") elif z<y: print("kenjiro") else: print("even") ```
instruction
0
101,989
17
203,978
No
output
1
101,989
17
203,979
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,120
17
204,240
Tags: math Correct Solution: ``` q = int(input()) for queries in range(q): n = int(input()) skill = list(map(int, input().split())) skill.sort() times = 1 for i in range(len(skill) - 1): if skill[i + 1] - skill[i] == 1: times = 2 print(times) ```
output
1
102,120
17
204,241
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,121
17
204,242
Tags: math Correct Solution: ``` q=int(input()) for i in range(q): n=int(input()) a=list(map(int,input().split())) grp=1 for j in range(n): if a[j]-1 in a or a[j]+1 in a: grp=2 break print(grp) ```
output
1
102,121
17
204,243
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,122
17
204,244
Tags: math Correct Solution: ``` t=int(input()) for i in range(t): n=int(input());c=0;y=[] x=list(map(int,input().split())) y=sorted(x) #print(y) for j in range(len(y)-1): #print(j+1," hj ",j) #print(y[j+1]," hj ",y[j]) if ((abs(y[j+1]-y[j]))==1): c+=1 y[j+1]=0 #del y[j+1] #del y[j] if c==0: print(1) else: print(2) y.clear() ```
output
1
102,122
17
204,245
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,123
17
204,246
Tags: math Correct Solution: ``` t = int(input()) for _ in range(t): n, ok = int(input()), 0 a = list(map(int, input().split())) a.sort() for i in range(0, n-1): if a[i+1] - a[i] == 1: ok = 1 print([1, 2][ok]) ```
output
1
102,123
17
204,247
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,124
17
204,248
Tags: math Correct Solution: ``` for _ in range(int(input())): n = int(input()) a = list(map(int, input().split())) f = 0 for i in a: if i+1 in a: f = 1 break if f: print(2) else: print(1) ```
output
1
102,124
17
204,249
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,125
17
204,250
Tags: math Correct Solution: ``` q = int(input()) n=[0]*q answer=[1]*q for i in range(q): n[i]=int(input()) a= [int(x) for x in input().split()] # решаем может быть одна команда или 2. при каком условии может быть 3 команды? в одну все четные, в другую нечетные. for j in range(n[i]): for k in range(j+1,n[i]): if (abs(a[j]-a[k])==1): answer[i]=2 break else: continue break for i in answer: print(i) ```
output
1
102,125
17
204,251
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,126
17
204,252
Tags: math Correct Solution: ``` t=int(input()); for i in range(t): m=int(input()); n=input(); n=n.split(); for j in range(m): n[j]=int(n[j]); n.sort(); counter=0; for j in range(1,m): if(n[j]-n[j-1]<=1): counter+=1; if(counter==0): print(1); else: print(2); ```
output
1
102,126
17
204,253
Provide tags and a correct Python 3 solution for this coding contest problem. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students.
instruction
0
102,127
17
204,254
Tags: math Correct Solution: ``` q = int(input()) for test in range(q): n = int(input()) a = [int(i) for i in input().split()] a.sort() ans = False for i in range(n - 1): if a[i + 1] - a[i] == 1: ans = True if ans == True: print(2) else: print(1) ```
output
1
102,127
17
204,255
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` for _ in range(int(input())): x=int(input()) s=sorted(list(map(int,input().split()))) even=[] odd=[] indicator=0 for n in range(x): if s[n]%2==0: even.append(s[n]) else: odd.append(s[n]) for n in even: if (n+1) in odd: indicator=1 break elif (n-1) in odd: indicator=1 break else: indicator=0 if indicator==1: print(2) else: print(1) ```
instruction
0
102,128
17
204,256
Yes
output
1
102,128
17
204,257
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` T= int(input()) while(T>0): N=int(input()) a=[int(x) for x in input().split()] a.sort() f=a[0] c=0 for i in range(1,len(a)): if abs(a[i]-f)==1: c+=1 f=a[i] if c>0: print(2) else: print(1) T=T-1 ```
instruction
0
102,129
17
204,258
Yes
output
1
102,129
17
204,259
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` q=int(input()) for j in range(q): n=int(input()) ch=input() L=ch.split() for i in range(n): L[i] = int(L[i]) L.sort() nb=1 for i in range(n-1): if L[i+1]-L[i]==1: nb=2 break print(nb) ```
instruction
0
102,130
17
204,260
Yes
output
1
102,130
17
204,261
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` t=int(input()) for i in range(t): n=int(input()) c=1 a=list(map(int,input().split()))[:n] for i in range(len(a)): for j in range(i,len(a)): if abs(a[i]-a[j])==1: c=c+1 if c>2: print(2) else: print(c) ```
instruction
0
102,131
17
204,262
Yes
output
1
102,131
17
204,263
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` t=int(input()) for _ in range(t): n=int(input()) a=list(map(int,input().split())) a.sort() c=0 for i in range(n-1): if abs(a[i]-a[i+1])==1: c=-1 if c==0: print(2) else: print(1) ```
instruction
0
102,132
17
204,264
No
output
1
102,132
17
204,265
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` #!/usr/bin/env python # coding: utf-8 # In[6]: q=int(input()) ans=[] for i in range(0,q): n=int(input()) s=input().split() if len(s)==1: ans.append(1) else: a=int(s[0]) for i in s: c=0 x=abs(a-int(i)) if x==1: break else : c+=1; if c==0: ans.append(2) else: ans.append(1) for i in ans: print(i) # In[ ]: ```
instruction
0
102,133
17
204,266
No
output
1
102,133
17
204,267
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` q=int(input()) ans=[] for i in range(0,q): n=int(input()) s=input().split() a=int(s[0]) for i in s: c=0 x=abs(a-int(i)) if x==1: break else : c+=1; if c==0: ans.append(2) else: ans.append(1) for i in ans: print(i) ans.clear() ```
instruction
0
102,134
17
204,268
No
output
1
102,134
17
204,269
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. You are a coach of a group consisting of n students. The i-th student has programming skill a_i. All students have distinct programming skills. You want to divide them into teams in such a way that: * No two students i and j such that |a_i - a_j| = 1 belong to the same team (i.e. skills of each pair of students in the same team have the difference strictly greater than 1); * the number of teams is the minimum possible. You have to answer q independent queries. Input The first line of the input contains one integer q (1 ≤ q ≤ 100) — the number of queries. Then q queries follow. The first line of the query contains one integer n (1 ≤ n ≤ 100) — the number of students in the query. The second line of the query contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100, all a_i are distinct), where a_i is the programming skill of the i-th student. Output For each query, print the answer on it — the minimum number of teams you can form if no two students i and j such that |a_i - a_j| = 1 may belong to the same team (i.e. skills of each pair of students in the same team has the difference strictly greater than 1) Example Input 4 4 2 10 1 20 2 3 6 5 2 3 4 99 100 1 42 Output 2 1 2 1 Note In the first query of the example, there are n=4 students with the skills a=[2, 10, 1, 20]. There is only one restriction here: the 1-st and the 3-th students can't be in the same team (because of |a_1 - a_3|=|2-1|=1). It is possible to divide them into 2 teams: for example, students 1, 2 and 4 are in the first team and the student 3 in the second team. In the second query of the example, there are n=2 students with the skills a=[3, 6]. It is possible to compose just a single team containing both students. Submitted Solution: ``` def main(): q = int(input()) for i in range(q): n = int(input()) l = input().split() count = 0 while (len(l) > 0): tmp = 1 while tmp < len(l): #print(l[0], l[tmp]) if (abs(int(l[0]) - int(l[tmp])) > 1): l.pop(tmp) else: tmp += 1 l.pop(0) count += 1 #print(l) print(count) if __name__ == '__main__': main() ```
instruction
0
102,135
17
204,270
No
output
1
102,135
17
204,271
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,715
17
207,430
Tags: sortings Correct Solution: ``` n = int(input()) a = [int(i) for i in input().split()] ct = 0 a = sorted(a) i = 0 while i < n-1: ct += a[i+1] - a[i] i += 2 print(ct) ```
output
1
103,715
17
207,431
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,716
17
207,432
Tags: sortings Correct Solution: ``` import math for _ in range(1): n=int(input()) l1=list(map(int,input().split())) l1.sort() c=0 for i in range(0,n-1,2): c=c+abs(l1[i]-l1[i+1]) print(c) ```
output
1
103,716
17
207,433
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,717
17
207,434
Tags: sortings Correct Solution: ``` n = int(input()) skills = list(map(int, input().split())) t = n//2 skills.sort() topSkills = [] for i in range(n//2): topSkills.append([skills[-1]]+[skills[-2]]) skills = skills[:-2] sum = 0 for i in topSkills: sum += abs(i[0]-i[1]) print(sum) ```
output
1
103,717
17
207,435
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,718
17
207,436
Tags: sortings Correct Solution: ``` def closest(lst, K): return lst[min(range(len(lst)), key = lambda i: abs(lst[i]-K))] def int_put(): num_list = input("").split() return [int(input) for input in num_list] st_num = int(input("")) skill_list = int_put() skill_list.sort() #go through the list find the nearest number to what the current index is #increment it if need be so it's == to curr ex_num = 0 def find_ex_num(skill_li): global ex_num if(len(skill_li) == 0): return curr_skill = skill_li[0] skill_li.remove(curr_skill) closest_num = closest(skill_li, curr_skill) skill_li.remove(closest_num) if(closest_num == curr_skill): return find_ex_num(skill_li) else: ex_num += abs(closest_num - curr_skill) return find_ex_num(skill_li) find_ex_num(skill_list) print(ex_num) ```
output
1
103,718
17
207,437
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,719
17
207,438
Tags: sortings Correct Solution: ``` n=int(input()) a=sorted(list(map(int,input().split()))) ans=0 for i in range(0,n,2): ans+=a[i+1]-a[i] print(ans) ```
output
1
103,719
17
207,439
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,720
17
207,440
Tags: sortings Correct Solution: ``` n = int(input()) pupils = list(map(int, input().split())) pupils.sort() tasks = 0 for i in range(0, n, 2): tasks += pupils[i + 1] - pupils[i] print(tasks) ```
output
1
103,720
17
207,441
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,721
17
207,442
Tags: sortings Correct Solution: ``` n = int(input()) l = list(map(int,input().split())) l.sort() s1 = 0 s2 = 0 for i in range(0,n,2): s1 += l[i] for i in range(1,n,2): s2 += l[i] print(s2-s1) ```
output
1
103,721
17
207,443
Provide tags and a correct Python 3 solution for this coding contest problem. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one.
instruction
0
103,722
17
207,444
Tags: sortings Correct Solution: ``` n=int(input()) a=[int(i) for i in input().split()] a.sort() s=0 for i in range(n-1): x=i+1 for j in range(i+1, n): if abs(a[x]-a[i])>abs(a[j]-a[i]) and a[j]!=-1 and a[i]!=-1: x=j if a[x]!=-1 and a[i]!=-1: s+=abs(a[x]-a[i]) a[x]=-1 print(s) ```
output
1
103,722
17
207,445
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` n = eval(input()) line = input() strings = line.split() list = [] for string in strings: list.append(eval(string)) sortedList = sorted(list) size = len(list) pn=0 for k in range(0, size, 2): pn += abs(sortedList[k] - sortedList[k+1]) print(pn) ```
instruction
0
103,723
17
207,446
Yes
output
1
103,723
17
207,447
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` n = int(input()) arr = [int(x) for x in input().split()] arr.sort() ans = 0 for i in range(0,n,2): ans+=arr[i+1]-arr[i] print(ans) ```
instruction
0
103,724
17
207,448
Yes
output
1
103,724
17
207,449
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` n=int(input()) list=[int(i) for i in input().strip().split(' ')] sum=0 list.sort() for i in range(0,len(list)-1,2): sum+=list[i+1]-list[i] print(sum) ```
instruction
0
103,725
17
207,450
Yes
output
1
103,725
17
207,451
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` if __name__ == '__main__': n = int(input().strip()) students = [s for s in map(int, input().strip().split())] for i in range(n): for j in range(n-i-1): if students[j] > students[j+1]: t = students[j] students[j] = students[j+1] students[j+1] = t acc = 0 for i in range(0, n, 2): acc += abs(students[i] - students[i+1]) print(acc) # print(students) ```
instruction
0
103,726
17
207,452
Yes
output
1
103,726
17
207,453
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` n=int(input()) arr=list(map(int,input().split())) arr.sort() c=0 for i in range(len(arr)-1): c+=arr[i+1]-arr[i] print(c) ```
instruction
0
103,727
17
207,454
No
output
1
103,727
17
207,455
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` n= int(input()) list1= input().split() length=len(list1) half=int(length/2) sum1=0 sum2=0 for i in range(0,half): list1[i]=int(list1[i]) sum1=sum1+list1[i] for j in range(half,length): list1[j]=int(list1[j]) sum2=sum2+list1[j] diff=abs(sum1-sum2) if(diff==298): diff=60 elif(diff==84): diff=0 elif(diff==546): diff=50 elif(diff>100): diff=0 print(diff) ```
instruction
0
103,728
17
207,456
No
output
1
103,728
17
207,457
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` numOfStudents = int(input()) students = input().split() student = int(students[0]) tasksNeed = 0 for i in range(1, numOfStudents): if int(students[i]) < student: student, int(students[i]) == int(students[i]), student student = int(students[i]) for i in range(0, numOfStudents - 1, 2): if int(students[i]) != int(students[i + 1]): minNumber = min(int(students[i]), int(students[i + 1])) maxNumber = max(int(students[i]), int(students[i + 1])) while minNumber != maxNumber: minNumber += 1 tasksNeed += 1 print(tasksNeed) ```
instruction
0
103,729
17
207,458
No
output
1
103,729
17
207,459
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. There are n students in a university. The number of students is even. The i-th student has programming skill equal to a_i. The coach wants to form n/2 teams. Each team should consist of exactly two students, and each student should belong to exactly one team. Two students can form a team only if their skills are equal (otherwise they cannot understand each other and cannot form a team). Students can solve problems to increase their skill. One solved problem increases the skill by one. The coach wants to know the minimum total number of problems students should solve to form exactly n/2 teams (i.e. each pair of students should form a team). Your task is to find this number. Input The first line of the input contains one integer n (2 ≤ n ≤ 100) — the number of students. It is guaranteed that n is even. The second line of the input contains n integers a_1, a_2, ..., a_n (1 ≤ a_i ≤ 100), where a_i is the skill of the i-th student. Output Print one number — the minimum total number of problems students should solve to form exactly n/2 teams. Examples Input 6 5 10 2 3 14 5 Output 5 Input 2 1 100 Output 99 Note In the first example the optimal teams will be: (3, 4), (1, 6) and (2, 5), where numbers in brackets are indices of students. Then, to form the first team the third student should solve 1 problem, to form the second team nobody needs to solve problems and to form the third team the second student should solve 4 problems so the answer is 1 + 4 = 5. In the second example the first student should solve 99 problems to form a team with the second one. Submitted Solution: ``` #1092B Team forming n=int(input()) a=[int(x) for x in input().split()] a.sort() count=0 for i in range(n-1): count=count+(a[i+1]-a[i]) i+=1 print(count) ```
instruction
0
103,730
17
207,460
No
output
1
103,730
17
207,461
Provide tags and a correct Python 3 solution for this coding contest problem. Soon a school Olympiad in Informatics will be held in Berland, n schoolchildren will participate there. At a meeting of the jury of the Olympiad it was decided that each of the n participants, depending on the results, will get a diploma of the first, second or third degree. Thus, each student will receive exactly one diploma. They also decided that there must be given at least min1 and at most max1 diplomas of the first degree, at least min2 and at most max2 diplomas of the second degree, and at least min3 and at most max3 diplomas of the third degree. After some discussion it was decided to choose from all the options of distributing diplomas satisfying these limitations the one that maximizes the number of participants who receive diplomas of the first degree. Of all these options they select the one which maximizes the number of the participants who receive diplomas of the second degree. If there are multiple of these options, they select the option that maximizes the number of diplomas of the third degree. Choosing the best option of distributing certificates was entrusted to Ilya, one of the best programmers of Berland. However, he found more important things to do, so it is your task now to choose the best option of distributing of diplomas, based on the described limitations. It is guaranteed that the described limitations are such that there is a way to choose such an option of distributing diplomas that all n participants of the Olympiad will receive a diploma of some degree. Input The first line of the input contains a single integer n (3 ≤ n ≤ 3·106) — the number of schoolchildren who will participate in the Olympiad. The next line of the input contains two integers min1 and max1 (1 ≤ min1 ≤ max1 ≤ 106) — the minimum and maximum limits on the number of diplomas of the first degree that can be distributed. The third line of the input contains two integers min2 and max2 (1 ≤ min2 ≤ max2 ≤ 106) — the minimum and maximum limits on the number of diplomas of the second degree that can be distributed. The next line of the input contains two integers min3 and max3 (1 ≤ min3 ≤ max3 ≤ 106) — the minimum and maximum limits on the number of diplomas of the third degree that can be distributed. It is guaranteed that min1 + min2 + min3 ≤ n ≤ max1 + max2 + max3. Output In the first line of the output print three numbers, showing how many diplomas of the first, second and third degree will be given to students in the optimal variant of distributing diplomas. The optimal variant of distributing diplomas is the one that maximizes the number of students who receive diplomas of the first degree. Of all the suitable options, the best one is the one which maximizes the number of participants who receive diplomas of the second degree. If there are several of these options, the best one is the one that maximizes the number of diplomas of the third degree. Examples Input 6 1 5 2 6 3 7 Output 1 2 3 Input 10 1 2 1 3 1 5 Output 2 3 5 Input 6 1 3 2 2 2 2 Output 2 2 2
instruction
0
104,041
17
208,082
Tags: greedy, implementation, math Correct Solution: ``` import sys n = int(input()) min1, max1 = map(int, input().split(" ")) min2, max2 = map(int, input().split(" ")) min3, max3 = map(int, input().split(" ")) a1 = a2 = a3 = 0 a3 = min3 a2 = min2 a1 = min1 rem = n - (a1 + a2 + a3) if rem >= max1 - a1: rem-=(max1-a1) a1 = max1 if(rem == 0): print(str(a1) + " " + str(a2) + " " + str(a3)) sys.exit(0) else: if rem >= max2 - a2: rem -= max2-a2 a2 = max2 if rem == 0: print(str(a1) + " " + str(a2) + " " + str(a3)) sys.exit(0) else: a3 += rem print(str(a1) + " " + str(a2) + " " + str(a3)) sys.exit(0) else: a2+= rem print(str(a1) + " " + str(a2) + " " + str(a3)) sys.exit(0) else: a1+=rem print(str(a1) + " " + str(a2) + " " + str(a3)) ```
output
1
104,041
17
208,083