message stringlengths 2 20.1k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 1.95k 109k | cluster float64 17 17 | __index_level_0__ int64 3.91k 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has n students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least k times?
Input
The first line contains two integers, n and k (1 β€ n β€ 2000; 1 β€ k β€ 5). The next line contains n integers: y1, y2, ..., yn (0 β€ yi β€ 5), where yi shows the number of times the i-th person participated in the ACM ICPC world championship.
Output
Print a single number β the answer to the problem.
Examples
Input
5 2
0 4 5 1 0
Output
1
Input
6 4
0 1 2 3 4 5
Output
0
Input
6 5
0 0 0 0 0 0
Output
2
Note
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits.
Submitted Solution:
```
import math
n, k = input().split()
n = int(n)
k = int(k)
list_of_years = list(map(int, input().split()))
# print(list_of_years)
count = 0
for i in list_of_years:
if 5 - i >= k:
count = count + 1
total_team = math.floor(count / 3)
print(total_team)
``` | instruction | 0 | 105,611 | 17 | 211,222 |
Yes | output | 1 | 105,611 | 17 | 211,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has n students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least k times?
Input
The first line contains two integers, n and k (1 β€ n β€ 2000; 1 β€ k β€ 5). The next line contains n integers: y1, y2, ..., yn (0 β€ yi β€ 5), where yi shows the number of times the i-th person participated in the ACM ICPC world championship.
Output
Print a single number β the answer to the problem.
Examples
Input
5 2
0 4 5 1 0
Output
1
Input
6 4
0 1 2 3 4 5
Output
0
Input
6 5
0 0 0 0 0 0
Output
2
Note
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits.
Submitted Solution:
```
n=[int(x) for x in input().split()]
a=[int(x) for x in input().split()]
a=sorted(a)
count=0
if(len(a)>=3):
for i in range(len(a)):
if(a[i]==0 or a[i]==1):
count=count+1
print(count//3)
``` | instruction | 0 | 105,612 | 17 | 211,224 |
No | output | 1 | 105,612 | 17 | 211,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has n students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least k times?
Input
The first line contains two integers, n and k (1 β€ n β€ 2000; 1 β€ k β€ 5). The next line contains n integers: y1, y2, ..., yn (0 β€ yi β€ 5), where yi shows the number of times the i-th person participated in the ACM ICPC world championship.
Output
Print a single number β the answer to the problem.
Examples
Input
5 2
0 4 5 1 0
Output
1
Input
6 4
0 1 2 3 4 5
Output
0
Input
6 5
0 0 0 0 0 0
Output
2
Note
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits.
Submitted Solution:
```
n, k = map(int, input().split())
d = list(map(int, input().split()))
u = []
for i in range(n):
if 5 - d[i] >= k:
u.append(5 - d[i])
m = len(u)
k = 3
n_f = 1
m_f = 1
for i in range(1, m + 1):
m_f *= i
mk_f = 1
for i in range(1, m - k + 1):
mk_f *= i
k_f = 1 * 2 * 3
print(int(m_f / (mk_f * k_f)))
``` | instruction | 0 | 105,613 | 17 | 211,226 |
No | output | 1 | 105,613 | 17 | 211,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has n students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least k times?
Input
The first line contains two integers, n and k (1 β€ n β€ 2000; 1 β€ k β€ 5). The next line contains n integers: y1, y2, ..., yn (0 β€ yi β€ 5), where yi shows the number of times the i-th person participated in the ACM ICPC world championship.
Output
Print a single number β the answer to the problem.
Examples
Input
5 2
0 4 5 1 0
Output
1
Input
6 4
0 1 2 3 4 5
Output
0
Input
6 5
0 0 0 0 0 0
Output
2
Note
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits.
Submitted Solution:
```
n,k=map(int,input().split())
a=sorted(list(map(int,input().split())))
for i in range(len(a)):
if a[i]<=5-k:
i+=1
print(i//3)
``` | instruction | 0 | 105,614 | 17 | 211,228 |
No | output | 1 | 105,614 | 17 | 211,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The Saratov State University Olympiad Programmers Training Center (SSU OPTC) has n students. For each student you know the number of times he/she has participated in the ACM ICPC world programming championship. According to the ACM ICPC rules, each person can participate in the world championship at most 5 times.
The head of the SSU OPTC is recently gathering teams to participate in the world championship. Each team must consist of exactly three people, at that, any person cannot be a member of two or more teams. What maximum number of teams can the head make if he wants each team to participate in the world championship with the same members at least k times?
Input
The first line contains two integers, n and k (1 β€ n β€ 2000; 1 β€ k β€ 5). The next line contains n integers: y1, y2, ..., yn (0 β€ yi β€ 5), where yi shows the number of times the i-th person participated in the ACM ICPC world championship.
Output
Print a single number β the answer to the problem.
Examples
Input
5 2
0 4 5 1 0
Output
1
Input
6 4
0 1 2 3 4 5
Output
0
Input
6 5
0 0 0 0 0 0
Output
2
Note
In the first sample only one team could be made: the first, the fourth and the fifth participants.
In the second sample no teams could be created.
In the third sample two teams could be created. Any partition into two teams fits.
Submitted Solution:
```
import math
s = 0
n,k = map(int, input().split())
l =list(map(int,input().strip().split()))[:n]
l.sort()
for i in l:
f = i+k
if i<5 and f<=5:
s = s+1
if s>0 and s%3==0:
print(math.floor(s/3))
else:
print(0)
``` | instruction | 0 | 105,615 | 17 | 211,230 |
No | output | 1 | 105,615 | 17 | 211,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
n = int(input())
a, b = 2, 1
match = 0
while a<=n:
a, b = a+b, a
match += 1
print(match)
``` | instruction | 0 | 105,760 | 17 | 211,520 |
Yes | output | 1 | 105,760 | 17 | 211,521 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
n=int(input())
dp = [0 for i in range(100)]
dp[0]=1
dp[1]=2
i=1
while 1:
if dp[i]==0: dp[i]=dp[i-1]+dp[i-2]
if dp[i]>n:
print(i-1)
break
else: i+=1
``` | instruction | 0 | 105,761 | 17 | 211,522 |
Yes | output | 1 | 105,761 | 17 | 211,523 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
n=int(input())
fib=1
last=1
i=0
while True:
i+=1
fib=fib+last
last=fib-last
if fib>n:
print(i-1)
exit(0)
#Π§ΡΠΎ Ρ codeforces?
``` | instruction | 0 | 105,762 | 17 | 211,524 |
Yes | output | 1 | 105,762 | 17 | 211,525 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
n = int(input())
a = 1
if n == 2:
print(1)
exit()
b = 2
ind = 0
while b <= n:
ind+=1
a, b = b, a+b
print(ind)
``` | instruction | 0 | 105,763 | 17 | 211,526 |
Yes | output | 1 | 105,763 | 17 | 211,527 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
__author__ = 'Alexander'
import sys
import math
n = int(input())
# arr = []
# arr[0] = 0
# arr[1] = 1
def getVal(n):
val = math.trunc(n/2)
if n == 1 or n == 0:
return 1
if n==2 or n == 3:
return 2
elif n%2 == 0:
return getVal(val+1)+1
else:
return getVal(val)+1
# print(arr)
# for i in range(2, n):
# val = math.trunc(i/2)
# if i%2 == 0:
# arr[i] = max(arr[val],arr[val-1])+1
# else:
# arr[i] = arr[val]+1
# print(arr)
print(getVal(n-1))
``` | instruction | 0 | 105,764 | 17 | 211,528 |
No | output | 1 | 105,764 | 17 | 211,529 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
def bin_s(n):
l = 1;
r = 10000000000000;
mid = (l + r) // 2;
while (l + 1 < r):
if ( ((mid + 1) * mid) // 2 <= n):
l = mid;
else:
r = mid;
mid = (l + r) // 2;
return r
lst = [eval(i) for i in input().split()]
n = lst[0]
n -= 2;
if (n != 0):
print(bin_s(n))
else:
print(1)
``` | instruction | 0 | 105,765 | 17 | 211,530 |
No | output | 1 | 105,765 | 17 | 211,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
import math
n = int(input())
print(math.ceil(math.sqrt(n)))
``` | instruction | 0 | 105,766 | 17 | 211,532 |
No | output | 1 | 105,766 | 17 | 211,533 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Famous Brazil city Rio de Janeiro holds a tennis tournament and Ostap Bender doesn't want to miss this event. There will be n players participating, and the tournament will follow knockout rules from the very first game. That means, that if someone loses a game he leaves the tournament immediately.
Organizers are still arranging tournament grid (i.e. the order games will happen and who is going to play with whom) but they have already fixed one rule: two players can play against each other only if the number of games one of them has already played differs by no more than one from the number of games the other one has already played. Of course, both players had to win all their games in order to continue participating in the tournament.
Tournament hasn't started yet so the audience is a bit bored. Ostap decided to find out what is the maximum number of games the winner of the tournament can take part in (assuming the rule above is used). However, it is unlikely he can deal with this problem without your help.
Input
The only line of the input contains a single integer n (2 β€ n β€ 1018) β the number of players to participate in the tournament.
Output
Print the maximum number of games in which the winner of the tournament can take part.
Examples
Input
2
Output
1
Input
3
Output
2
Input
4
Output
2
Input
10
Output
4
Note
In all samples we consider that player number 1 is the winner.
In the first sample, there would be only one game so the answer is 1.
In the second sample, player 1 can consequently beat players 2 and 3.
In the third sample, player 1 can't play with each other player as after he plays with players 2 and 3 he can't play against player 4, as he has 0 games played, while player 1 already played 2. Thus, the answer is 2 and to achieve we make pairs (1, 2) and (3, 4) and then clash the winners.
Submitted Solution:
```
from math import log2 as log,ceil
print(ceil(log(int(input()))))
``` | instruction | 0 | 105,767 | 17 | 211,534 |
No | output | 1 | 105,767 | 17 | 211,535 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,189 | 17 | 212,378 |
Tags: implementation
Correct Solution:
```
n, m, k = map(int, input().split())
if n <= k and n <= m:
print("YES")
else:
print("NO")
``` | output | 1 | 106,189 | 17 | 212,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,190 | 17 | 212,380 |
Tags: implementation
Correct Solution:
```
a = input()
a = a.split()
if (int(a[1])>=int(a[0]) and int(a[2])>=int(a[0])):
print("Yes")
else:
print("No")
``` | output | 1 | 106,190 | 17 | 212,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,191 | 17 | 212,382 |
Tags: implementation
Correct Solution:
```
def solution():
inputs = str(input())
inputs = inputs.split()
n = int(inputs[0])
m = int(inputs[1])
k = int(inputs[2])
n_pair = min(m, k)
if (n <= n_pair):
print("Yes")
else:
print("No")
solution()
``` | output | 1 | 106,191 | 17 | 212,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,192 | 17 | 212,384 |
Tags: implementation
Correct Solution:
```
n,m,k=list(map(int,input().strip().split()))
if m>=n and k>=n:
print('Yes')
else:
print('No')
``` | output | 1 | 106,192 | 17 | 212,385 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,193 | 17 | 212,386 |
Tags: implementation
Correct Solution:
```
n,m,k=map(int,input().split())
f=min(m,k)
if(n>f):
print("No")
else:
print("Yes")
``` | output | 1 | 106,193 | 17 | 212,387 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,194 | 17 | 212,388 |
Tags: implementation
Correct Solution:
```
n,pens,books=map(int,input().split())
x=min(n,pens,books)
if x==n:
print('Yes')
else:
print('No')
``` | output | 1 | 106,194 | 17 | 212,389 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,195 | 17 | 212,390 |
Tags: implementation
Correct Solution:
```
n,m,k=map(int,input().split())
s=min(m,k)
if(s>=n):
print("Yes")
else:
print("No")
``` | output | 1 | 106,195 | 17 | 212,391 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vus the [Cossack](https://en.wikipedia.org/wiki/Cossacks) holds a programming competition, in which n people participate. He decided to award them all with pens and notebooks. It is known that Vus has exactly m pens and k notebooks.
Determine whether the Cossack can reward all participants, giving each of them at least one pen and at least one notebook.
Input
The first line contains three integers n, m, and k (1 β€ n, m, k β€ 100) β the number of participants, the number of pens, and the number of notebooks respectively.
Output
Print "Yes" if it possible to reward all the participants. Otherwise, print "No".
You can print each letter in any case (upper or lower).
Examples
Input
5 8 6
Output
Yes
Input
3 9 3
Output
Yes
Input
8 5 20
Output
No
Note
In the first example, there are 5 participants. The Cossack has 8 pens and 6 notebooks. Therefore, he has enough pens and notebooks.
In the second example, there are 3 participants. The Cossack has 9 pens and 3 notebooks. He has more than enough pens but only the minimum needed number of notebooks.
In the third example, there are 8 participants but only 5 pens. Since the Cossack does not have enough pens, the answer is "No". | instruction | 0 | 106,196 | 17 | 212,392 |
Tags: implementation
Correct Solution:
```
# @author
import sys
class AVusTheCossackAndAContest:
def solve(self):
n, m, k = [int(_) for _ in input().split()]
print("Yes" if min(m, k) >= n else "No")
solver = AVusTheCossackAndAContest()
input = sys.stdin.readline
solver.solve()
``` | output | 1 | 106,196 | 17 | 212,393 |
Provide a correct Python 3 solution for this coding contest problem.
At Akabe High School, a programmer training school, there is a unique study session run by the students themselves. It is important for programmers to constantly adopt new technologies, so the aim of this activity is to develop the habit of self-study through this study session.
There are a total of N students, each with a score obtained as a result of the programming contest at the time of admission. At the study session, some of the N students will become leaders, and each leader will run their own group and join the group they run.
Students other than the leader cannot join a group run by a leader with a score lower than their own. In addition, one value r that is 0 or more is decided so that the difference between the scores of the students participating in the group and the leader is within r. That is, if the leader of a group has a score of s and your score is greater than or less than s --r, you will not be able to join the group.
You are the executive committee chair of the study session and decided to do a simulation to prepare for the operation. In the simulation, start with no leader and repeat the following operations several times.
* Add students as leaders.
* Remove the student from the leader.
* For the combination of leaders at the time of request, find the minimum r such that the number of students who cannot participate in any group is x or less.
Create a program that performs such a simulation.
input
The input consists of one dataset. The input is given in the following format.
N Q
s1
s2
::
sN
QUERY1
QUERY2
::
QUERYQ
The first line gives the number of students N (1 β€ N β€ 1000000) and the number of processing requests Q (0 β€ Q β€ 1000).
The following N lines are given the integer si (0 β€ si β€ 1,000,000,000) indicating the score of the i-th student. Students shall be numbered 1,2, ..., N.
The processing request QUERYi is given to the following Q line. Processing requests are given in chronological order. There are three types of processing requests: ADD, REMOVE, and CHECK, and each QUERYi is given in one of the following formats.
ADD a
Or
REMOVE a
Or
CHECK x
ADD a stands for adding a student with the number a (1 β€ a β€ N) to the leader.
REMOVE a represents removing the student with the number a (1 β€ a β€ N) from the leader.
CHECK x represents an output request. An upper limit on the number of students who cannot join any group x (0 β€ x β€ N) is given.
The input shall satisfy the following conditions.
* At any given time, the number of leaders will not exceed 100.
* Do not add students who are leaders at that time to leaders.
* Students who are not leaders at that time will not be removed from the leader.
output
At the time of each output request in chronological order, the minimum r is output on one line so that the number of students who cannot join any group is x or less. However, if it is impossible to reduce the number of people to x or less no matter what r is selected, NA is output.
Example
Input
5 8
5
10
8
7
3
ADD 1
ADD 3
CHECK 0
CHECK 1
CHECK 2
CHECK 3
CHECK 4
CHECK 5
Output
NA
2
1
0
0
0 | instruction | 0 | 106,949 | 17 | 213,898 |
"Correct Solution:
```
from bisect import bisect
import operator
import sys
from collections import defaultdict
readline = sys.stdin.readline
write = sys.stdout.write
N, Q = map(int, readline().split())
R = [int(readline()) for i in range(N)]
S = list(set(R))
S.sort()
mp = {e: i for i, e in enumerate(S)}
D = defaultdict(int)
T = R[:]
T.sort()
mpm = {}
for i, e in enumerate(T):
mpm[e] = i
INF = 10**9+1
ps = []
for i in range(Q):
t, x = readline().split(); x = int(x)
if t == 'ADD':
y = R[x-1]
if D[y] == 0:
z = mp[y]
idx = bisect(ps, z-1)
ps = ps[:idx] + [z] + ps[idx:]
D[y] += 1
elif t == 'REMOVE':
y = R[x-1]
D[y] -= 1
if D[y] == 0:
z = mp[y]
idx = bisect(ps, z-1)
ps.pop(idx)
else:
left = -1; right = INF
while left+1 < right:
mid = (left + right) >> 1
prv = -1
cnt = 0
for e in ps:
s = S[e]; v = mpm[s]
idx = max(bisect(T, s-mid-1)-1, prv)
cnt += v - idx
prv = v
if N - cnt <= x:
right = mid
else:
left = mid
if right == INF:
write("NA\n")
else:
write("%d\n" % right)
``` | output | 1 | 106,949 | 17 | 213,899 |
Provide a correct Python 3 solution for this coding contest problem.
At Akabe High School, a programmer training school, there is a unique study session run by the students themselves. It is important for programmers to constantly adopt new technologies, so the aim of this activity is to develop the habit of self-study through this study session.
There are a total of N students, each with a score obtained as a result of the programming contest at the time of admission. At the study session, some of the N students will become leaders, and each leader will run their own group and join the group they run.
Students other than the leader cannot join a group run by a leader with a score lower than their own. In addition, one value r that is 0 or more is decided so that the difference between the scores of the students participating in the group and the leader is within r. That is, if the leader of a group has a score of s and your score is greater than or less than s --r, you will not be able to join the group.
You are the executive committee chair of the study session and decided to do a simulation to prepare for the operation. In the simulation, start with no leader and repeat the following operations several times.
* Add students as leaders.
* Remove the student from the leader.
* For the combination of leaders at the time of request, find the minimum r such that the number of students who cannot participate in any group is x or less.
Create a program that performs such a simulation.
input
The input consists of one dataset. The input is given in the following format.
N Q
s1
s2
::
sN
QUERY1
QUERY2
::
QUERYQ
The first line gives the number of students N (1 β€ N β€ 1000000) and the number of processing requests Q (0 β€ Q β€ 1000).
The following N lines are given the integer si (0 β€ si β€ 1,000,000,000) indicating the score of the i-th student. Students shall be numbered 1,2, ..., N.
The processing request QUERYi is given to the following Q line. Processing requests are given in chronological order. There are three types of processing requests: ADD, REMOVE, and CHECK, and each QUERYi is given in one of the following formats.
ADD a
Or
REMOVE a
Or
CHECK x
ADD a stands for adding a student with the number a (1 β€ a β€ N) to the leader.
REMOVE a represents removing the student with the number a (1 β€ a β€ N) from the leader.
CHECK x represents an output request. An upper limit on the number of students who cannot join any group x (0 β€ x β€ N) is given.
The input shall satisfy the following conditions.
* At any given time, the number of leaders will not exceed 100.
* Do not add students who are leaders at that time to leaders.
* Students who are not leaders at that time will not be removed from the leader.
output
At the time of each output request in chronological order, the minimum r is output on one line so that the number of students who cannot join any group is x or less. However, if it is impossible to reduce the number of people to x or less no matter what r is selected, NA is output.
Example
Input
5 8
5
10
8
7
3
ADD 1
ADD 3
CHECK 0
CHECK 1
CHECK 2
CHECK 3
CHECK 4
CHECK 5
Output
NA
2
1
0
0
0 | instruction | 0 | 106,950 | 17 | 213,900 |
"Correct Solution:
```
import bisect
INF = int(10**9+1)
n, q = map(int, input().split())
tmp = [ (int(input()),i) for i in range(n) ]
tmp.sort()
s = [0]*n
f = [0]*n
i = 0
for key,val in tmp :
s[i] = key
f[val] = i
i += 1
leader = []
while q > 0 :
line = input().split()
arg = int(line[1])
#print(line)
if line[0] == 'ADD':
idx = bisect.bisect_left( leader, f[arg-1] )
leader = leader[:idx] + [f[arg-1]] + leader[idx:]
elif line[0] == 'REMOVE':
leader.remove( f[arg-1] )
else: #CHECK
fail_r = -1
succ_r = INF
while succ_r - fail_r > 1 :
mid = int((succ_r + fail_r)/2)
count = 0
prev = -1
for idx in leader :
l_idx = bisect.bisect_left( s, s[idx]-mid )
r_idx = bisect.bisect_right( s, s[idx] ) - 1
if l_idx <= prev : l_idx = prev + 1
count += r_idx - l_idx + 1
prev = r_idx
if n - count <= arg : succ_r = mid
else : fail_r = mid
if succ_r == INF : print('NA')
else : print(succ_r)
# for idx in leader : print(idx)
q -= 1
``` | output | 1 | 106,950 | 17 | 213,901 |
Provide a correct Python 3 solution for this coding contest problem.
At Akabe High School, a programmer training school, there is a unique study session run by the students themselves. It is important for programmers to constantly adopt new technologies, so the aim of this activity is to develop the habit of self-study through this study session.
There are a total of N students, each with a score obtained as a result of the programming contest at the time of admission. At the study session, some of the N students will become leaders, and each leader will run their own group and join the group they run.
Students other than the leader cannot join a group run by a leader with a score lower than their own. In addition, one value r that is 0 or more is decided so that the difference between the scores of the students participating in the group and the leader is within r. That is, if the leader of a group has a score of s and your score is greater than or less than s --r, you will not be able to join the group.
You are the executive committee chair of the study session and decided to do a simulation to prepare for the operation. In the simulation, start with no leader and repeat the following operations several times.
* Add students as leaders.
* Remove the student from the leader.
* For the combination of leaders at the time of request, find the minimum r such that the number of students who cannot participate in any group is x or less.
Create a program that performs such a simulation.
input
The input consists of one dataset. The input is given in the following format.
N Q
s1
s2
::
sN
QUERY1
QUERY2
::
QUERYQ
The first line gives the number of students N (1 β€ N β€ 1000000) and the number of processing requests Q (0 β€ Q β€ 1000).
The following N lines are given the integer si (0 β€ si β€ 1,000,000,000) indicating the score of the i-th student. Students shall be numbered 1,2, ..., N.
The processing request QUERYi is given to the following Q line. Processing requests are given in chronological order. There are three types of processing requests: ADD, REMOVE, and CHECK, and each QUERYi is given in one of the following formats.
ADD a
Or
REMOVE a
Or
CHECK x
ADD a stands for adding a student with the number a (1 β€ a β€ N) to the leader.
REMOVE a represents removing the student with the number a (1 β€ a β€ N) from the leader.
CHECK x represents an output request. An upper limit on the number of students who cannot join any group x (0 β€ x β€ N) is given.
The input shall satisfy the following conditions.
* At any given time, the number of leaders will not exceed 100.
* Do not add students who are leaders at that time to leaders.
* Students who are not leaders at that time will not be removed from the leader.
output
At the time of each output request in chronological order, the minimum r is output on one line so that the number of students who cannot join any group is x or less. However, if it is impossible to reduce the number of people to x or less no matter what r is selected, NA is output.
Example
Input
5 8
5
10
8
7
3
ADD 1
ADD 3
CHECK 0
CHECK 1
CHECK 2
CHECK 3
CHECK 4
CHECK 5
Output
NA
2
1
0
0
0 | instruction | 0 | 106,951 | 17 | 213,902 |
"Correct Solution:
```
def get_count(s, leader, r):
count = 0
pre_upper_pos = 0
for li in leader:
lower_pos = bisect.bisect_left(s, li - r)
upper_pos = bisect.bisect_right(s, li)
if pre_upper_pos < lower_pos:
count += lower_pos - pre_upper_pos
pre_upper_pos = upper_pos
count += len(s) - pre_upper_pos
return count
import bisect
def check(s,leader,target_x):
if 0 == len(leader):
if target_x < len(s):
return 'NA'
else:
return 0
min_x = len(s) - bisect.bisect_right(s, leader[-1])
if target_x < min_x:
return 'NA'
l, r = 0, s[-1]
diff = r - 1
while True:
m = (l + r) // 2
x = get_count(s, leader, m)
if target_x < x:
l = m
elif x <= target_x:
r = m
if diff == l - r:
return r
diff = l - r
import sys
f = sys.stdin
n, q = (int(i) for i in f.readline().split())
s = [int(f.readline()) for i in range(n)]
query = [line.split() for line in f]
sort_s = sorted(s)
leader = []
for op, a in query:
a = int(a)
if op[0] == 'A':
leader.append(s[a - 1]) #bisect??Β§??????????ΒΆ?????????????????????\?????????
leader.sort()
elif op[0] == 'R':
leader.remove(s[a - 1])
else:
r = check(sort_s,leader,a)
print(r)
``` | output | 1 | 106,951 | 17 | 213,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
At Akabe High School, a programmer training school, there is a unique study session run by the students themselves. It is important for programmers to constantly adopt new technologies, so the aim of this activity is to develop the habit of self-study through this study session.
There are a total of N students, each with a score obtained as a result of the programming contest at the time of admission. At the study session, some of the N students will become leaders, and each leader will run their own group and join the group they run.
Students other than the leader cannot join a group run by a leader with a score lower than their own. In addition, one value r that is 0 or more is decided so that the difference between the scores of the students participating in the group and the leader is within r. That is, if the leader of a group has a score of s and your score is greater than or less than s --r, you will not be able to join the group.
You are the executive committee chair of the study session and decided to do a simulation to prepare for the operation. In the simulation, start with no leader and repeat the following operations several times.
* Add students as leaders.
* Remove the student from the leader.
* For the combination of leaders at the time of request, find the minimum r such that the number of students who cannot participate in any group is x or less.
Create a program that performs such a simulation.
input
The input consists of one dataset. The input is given in the following format.
N Q
s1
s2
::
sN
QUERY1
QUERY2
::
QUERYQ
The first line gives the number of students N (1 β€ N β€ 1000000) and the number of processing requests Q (0 β€ Q β€ 1000).
The following N lines are given the integer si (0 β€ si β€ 1,000,000,000) indicating the score of the i-th student. Students shall be numbered 1,2, ..., N.
The processing request QUERYi is given to the following Q line. Processing requests are given in chronological order. There are three types of processing requests: ADD, REMOVE, and CHECK, and each QUERYi is given in one of the following formats.
ADD a
Or
REMOVE a
Or
CHECK x
ADD a stands for adding a student with the number a (1 β€ a β€ N) to the leader.
REMOVE a represents removing the student with the number a (1 β€ a β€ N) from the leader.
CHECK x represents an output request. An upper limit on the number of students who cannot join any group x (0 β€ x β€ N) is given.
The input shall satisfy the following conditions.
* At any given time, the number of leaders will not exceed 100.
* Do not add students who are leaders at that time to leaders.
* Students who are not leaders at that time will not be removed from the leader.
output
At the time of each output request in chronological order, the minimum r is output on one line so that the number of students who cannot join any group is x or less. However, if it is impossible to reduce the number of people to x or less no matter what r is selected, NA is output.
Example
Input
5 8
5
10
8
7
3
ADD 1
ADD 3
CHECK 0
CHECK 1
CHECK 2
CHECK 3
CHECK 4
CHECK 5
Output
NA
2
1
0
0
0
Submitted Solution:
```
def get_count(s, leader, r):
count = 0
pre_upper_pos = 0
for li in leader:
lower_pos = bisect.bisect_left(s, li - r)
upper_pos = bisect.bisect_right(s, li)
if pre_upper_pos < lower_pos:
count += lower_pos - pre_upper_pos
pre_upper_pos = upper_pos
count += len(s) - pre_upper_pos
return count
import bisect
def check(s,leader,target_x):
if 0 == len(leader):
return 'NA'
min_x = len(s) - bisect.bisect_right(s, leader[-1])
if target_x < min_x:
return 'NA'
l, r = 0, s[-1]
diff = r - 1
while True:
m = (l + r) // 2
x = get_count(s, leader, m)
if target_x < x:
l = m
elif x <= target_x:
r = m
if diff == l - r:
return r
diff = l - r
import sys
f = sys.stdin
n, q = (int(i) for i in f.readline().split())
s = [int(f.readline()) for i in range(n)]
query = [line.split() for line in f]
sort_s = sorted(s)
leader = []
for op, a in query:
a = int(a)
if op[0] == 'A':
leader.append(s[a - 1]) #bisect??Β§??????????ΒΆ?????????????????????\?????????
leader.sort()
elif op[0] == 'R':
leader.remove(s[a - 1])
else:
r = check(sort_s,leader,a)
print(r)
``` | instruction | 0 | 106,952 | 17 | 213,904 |
No | output | 1 | 106,952 | 17 | 213,905 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,185 | 17 | 214,370 |
Tags: greedy, sortings
Correct Solution:
```
t=int(input())
for i in range(t):
n=int(input())
s=list(map(int, input().split()))
l=[]
for j in range(len(s)-1):
a=s[j]
for k in range(j+1,len(s)):
d=abs(s[k]-a)
l.append(d)
print(min(l))
``` | output | 1 | 107,185 | 17 | 214,371 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,186 | 17 | 214,372 |
Tags: greedy, sortings
Correct Solution:
```
n=int(input());o=[]
for i in range(n):
m=int(input())
l=[int(x) for x in input().split()]
l.sort()
o+=[str(min(l[i+1]-l[i] for i in range(m-1)))]
print('\n'.join(o))
``` | output | 1 | 107,186 | 17 | 214,373 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,187 | 17 | 214,374 |
Tags: greedy, sortings
Correct Solution:
```
t=int(input())
while(t):
t-=1
input()
athelete_code=[int(i) for i in input().split(" ")]
athelete_code=sorted(athelete_code)
min_dif=athelete_code[1]-athelete_code[0]
for i in range(1,(len(athelete_code)-1)):
if (athelete_code[i+1]-athelete_code[i])<min_dif:
#print(athelete_code[i+1]-athelete_code[i],athelete_code[i],athelete_code[i+1])
min_dif=athelete_code[i+1]-athelete_code[i]
print(min_dif)
``` | output | 1 | 107,187 | 17 | 214,375 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,188 | 17 | 214,376 |
Tags: greedy, sortings
Correct Solution:
```
from sys import stdin,stdout
import math
from collections import Counter,deque
L=lambda:list(map(int, stdin.readline().strip().split()))
M=lambda:map(int, stdin.readline().strip().split())
I=lambda:int(stdin.readline().strip())
IN=lambda:stdin.readline().strip()
C=lambda:stdin.readline().strip().split()
mod=1000000007
#Keymax = max(Tv, key=Tv.get)
def s(a):print(" ".join(list(map(str,a))))
#______________________-------------------------------_____________________#
#I_am_pavan
for i in range(I()):
n=I()
a=sorted(L())
m=a[1]-a[0]
for i in range(n-1):
m=min(m,a[i+1]-a[i])
print(m)
``` | output | 1 | 107,188 | 17 | 214,377 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,189 | 17 | 214,378 |
Tags: greedy, sortings
Correct Solution:
```
t = int(input())
for i in range(t):
n = int(input())
si = list(map(int,input().split()))
si.sort()
res = si[-1]
for i in range(1,n):
res = min(res, si[i] - si[i-1])
print(res)
``` | output | 1 | 107,189 | 17 | 214,379 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,190 | 17 | 214,380 |
Tags: greedy, sortings
Correct Solution:
```
def solve():
n = int(input())
arr = [int(i) for i in input().split()]
arr.sort()
diff = 1000
for i in range(n - 1):
diff = min(diff, arr[i + 1] - arr[i])
return diff
if __name__ == '__main__':
for _ in range(int(input())):
print(solve())
``` | output | 1 | 107,190 | 17 | 214,381 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,191 | 17 | 214,382 |
Tags: greedy, sortings
Correct Solution:
```
for s in [*open(0)][2::2]:a=sorted(map(int,s.split()));print(min([j-i for i, j in zip(a,a[1:])]))
``` | output | 1 | 107,191 | 17 | 214,383 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0. | instruction | 0 | 107,192 | 17 | 214,384 |
Tags: greedy, sortings
Correct Solution:
```
test=int(input())
for i in range(test):
n=int(input())
a=[int(x) for x in input().split()]
temp=1001
for i in range(n):
for j in range(i+1,n):
temp=min(temp,abs(a[i]-a[j]))
print(temp)
``` | output | 1 | 107,192 | 17 | 214,385 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
# python3 q2.py < test.txt
t = int(input())
for i in range(t):
n = int(input())
a = [int(j) for j in input().split()]
a.sort()
diff = float('inf')
for j in range(1, len(a)):
diff = min(diff, a[j]- a[j-1])
print(diff)
``` | instruction | 0 | 107,193 | 17 | 214,386 |
Yes | output | 1 | 107,193 | 17 | 214,387 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
t=int(input())
for i in range(t):
n=int(input())
l=list(map(int,input().split()))
l.sort()
min1=l[1]-l[0]
for i in range(2,len(l)):
min1=min(min1,l[i]-l[i-1])
print(min1)
``` | instruction | 0 | 107,194 | 17 | 214,388 |
Yes | output | 1 | 107,194 | 17 | 214,389 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
# hey stalker
n=int(input())
for i in range(n):
m=int(input())
a=[int(i) for i in input().split()]
b=sorted(a)
max=10**9
for j in range(0,len(b)-1):
d=b[j+1]-b[j]
if(d<max):
max=d
print(max)
``` | instruction | 0 | 107,195 | 17 | 214,390 |
Yes | output | 1 | 107,195 | 17 | 214,391 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
# from math import factorial as fac
from collections import defaultdict
# from copy import deepcopy
import sys, math
f = None
try:
f = open('q1.input', 'r')
except IOError:
f = sys.stdin
if 'xrange' in dir(__builtins__):
range = xrange
# print(f.readline())
# sys.setrecursionlimit(10**5)
def print_case_iterable(case_num, iterable):
print("Case #{}: {}".format(case_num," ".join(map(str,iterable))))
def print_case_number(case_num, iterable):
print("Case #{}: {}".format(case_num,iterable))
def print_iterable(A):
print (' '.join(A))
def read_int():
return int(f.readline().strip())
def read_int_array():
return [int(x) for x in f.readline().strip().split(" ")]
def rns():
a = [x for x in f.readline().split(" ")]
return int(a[0]), a[1].strip()
def read_string():
return list(f.readline().strip())
def bi(x):
return bin(x)[2:]
from copy import deepcopy
def solution(a,n):
a.sort()
min_diff = 10**10
for i in range(1,n):
min_diff = min(min_diff,a[i]-a[i-1])
return min_diff
def main():
T = read_int()
for i in range(T):
# s = read_string()
# p = read_int_array()
n = read_int()
a = read_int_array()
x = solution(a,n)
if 'xrange' not in dir(__builtins__):
print(x)
else:
print >>output,str(x)# "Case #"+str(i+1)+':',
if 'xrange' in dir(__builtins__):
print(output.getvalue())
output.close()
if 'xrange' in dir(__builtins__):
import cStringIO
output = cStringIO.StringIO()
#example usage:
# for l in res:
# print >>output, str(len(l)) + ' ' + ' '.join(l)
if __name__ == '__main__':
main()
'''stuff you should look for
* int overflow, array bounds
* special cases (n=1?)
* do smth instead of nothing and stay organized
* WRITE STUFF DOWN
* BITS - THINK HOW TO MASK PROPERLY
* PERMUTATIONS - PARITY AND CYCLES
* Think simple, if it becomes over complicated, try to look at it from a different perspective.
* Have fun!!!
* TRY FIXING SOMETHING, and then maybe binary search around it.
* Remember heaps.
* Remember how to add a value to a segment when using prefix sum.
suppose you have an array[1,2,3,4,5] and you want to add 3 to array[1:4]. Then just
add 3 to A[1], and decrease 3 from A[4]. Let's look at what happens:
original prefixsums is [1,3,6,10,15]
array -> [1,5,3,4,2] and prefix sums are [1,6,9,13,15]
As you see, exactly +3 in A[1:4]
*** The previous method can help checking how many x,y you can choose to get s=x+y from two arrays.
'''
'''
binary search
while(r - l > 1) {
ll mid = l + (r - l) / 2;
solve(mid);
ll sum = 0;
for (int i = 0; i < n; i++)
sum += b[i];
if (sum <= k)
r = mid;
else
l = mid;
}
'''
``` | instruction | 0 | 107,196 | 17 | 214,392 |
Yes | output | 1 | 107,196 | 17 | 214,393 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
t=int(input())
for e in range(t):
n=int(input())
l=list(map(int,input().split()))
l.sort()
m=l[1]-l[0]
for i in range(1,n):
m=min(m,l[i]-l[i-1])
print(m)
``` | instruction | 0 | 107,197 | 17 | 214,394 |
No | output | 1 | 107,197 | 17 | 214,395 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
t=int(input())
for i in range(t):
m=int(input())
a=list(map(int,input().split()))
a.sort()
b=sorted(set(a))
n=len(b)
if(n%2!=0):
c=(n+1)//2-1
else:
c=n//2-1
p=a.index(b[c])
c=abs(a[0]-min(a[1:]))
d=a[p+1]-a[p]
print(min(d,c))
``` | instruction | 0 | 107,198 | 17 | 214,396 |
No | output | 1 | 107,198 | 17 | 214,397 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
for t in range(int(input())):
n = int(input())
l = list(map(int, input().split()))
l.sort()
s = len(l)
b = []
a = []
x = (s//2)-1
if(x == 0):
x = 1
for i in range(x):
a.append(l[i])
for i in range(x, s):
b.append(l[i])
print(abs(max(a) - min(b)))
``` | instruction | 0 | 107,199 | 17 | 214,398 |
No | output | 1 | 107,199 | 17 | 214,399 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n athletes in front of you. Athletes are numbered from 1 to n from left to right. You know the strength of each athlete β the athlete number i has the strength s_i.
You want to split all athletes into two teams. Each team must have at least one athlete, and each athlete must be exactly in one team.
You want the strongest athlete from the first team to differ as little as possible from the weakest athlete from the second team. Formally, you want to split the athletes into two teams A and B so that the value |max(A) - min(B)| is as small as possible, where max(A) is the maximum strength of an athlete from team A, and min(B) is the minimum strength of an athlete from team B.
For example, if n=5 and the strength of the athletes is s=[3, 1, 2, 6, 4], then one of the possible split into teams is:
* first team: A = [1, 2, 4],
* second team: B = [3, 6].
In this case, the value |max(A) - min(B)| will be equal to |4-3|=1. This example illustrates one of the ways of optimal split into two teams.
Print the minimum value |max(A) - min(B)|.
Input
The first line contains an integer t (1 β€ t β€ 1000) β the number of test cases in the input. Then t test cases follow.
Each test case consists of two lines.
The first line contains positive integer n (2 β€ n β€ 50) β number of athletes.
The second line contains n positive integers s_1, s_2, β¦, s_n (1 β€ s_i β€ 1000), where s_i β is the strength of the i-th athlete. Please note that s values may not be distinct.
Output
For each test case print one integer β the minimum value of |max(A) - min(B)| with the optimal split of all athletes into two teams. Each of the athletes must be a member of exactly one of the two teams.
Example
Input
5
5
3 1 2 6 4
6
2 1 3 2 4 3
4
7 9 3 1
2
1 1000
3
100 150 200
Output
1
0
2
999
50
Note
The first test case was explained in the statement. In the second test case, one of the optimal splits is A=[2, 1], B=[3, 2, 4, 3], so the answer is |2-2|=0.
Submitted Solution:
```
for _ in range(int(input())):
n=int(input())
L=list(map(int,input().split()))
L.sort()
p=L[1]-L[0]
for i in range(n-1):
if L[i+1]-L[i]<p:
p=L[i+1]-L[i]
if p==0:
print(p)
break
if p!=0:
print(p)
``` | instruction | 0 | 107,200 | 17 | 214,400 |
No | output | 1 | 107,200 | 17 | 214,401 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,201 | 17 | 214,402 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
n = int(input())
for _ in range(n):
a, b = list(map(int, input().split()))
arr = list(map(int, input().split()))
arr.sort(reverse=True)
index = 1
ans = 0
for i in range(a):
if(arr[i]*index < b):
index += 1
else:
ans += 1
index = 1
print(ans)
``` | output | 1 | 107,201 | 17 | 214,403 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,202 | 17 | 214,404 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
from sys import stdin
def mp():return map(int,stdin.readline().split())
def ml():return list(map(int,stdin.readline().split()))
for _ in range(int(input())):
n,x=mp()
a=ml();a.sort(reverse=True)
ans=0;c=0
for num in a:
c+=1
if c*num >= x:
ans+=1;c=0
print(ans)
``` | output | 1 | 107,202 | 17 | 214,405 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,203 | 17 | 214,406 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
from sys import stdin
input = stdin.readline
def solve():
_, x = map(int, input().split())
a = list(map(int, input().split()))
a.sort(reverse=True)
ans = 0
cnt = 0
for i in a:
k = (x + i - 1) // i
if cnt + 1 >= k:
cnt -= k - 1
ans += 1
else:
cnt += 1
print(ans)
def main():
t = int(input())
for _ in range(t):
solve()
if __name__ == "__main__":
main()
``` | output | 1 | 107,203 | 17 | 214,407 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,204 | 17 | 214,408 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
import sys
input = sys.stdin.readline
for _ in range(int(input())):
n, x = map(int, input().split())
A = sorted(map(int, input().split()), reverse=True)
c = 0
r = 0
for v in A:
c += 1
if c * v >= x:
r += 1
c = 0
print(r)
``` | output | 1 | 107,204 | 17 | 214,409 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,205 | 17 | 214,410 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
t = int(input())
for i in range(t):
n,x = map(int,input().split())
l = list(map(int,input().split()))
l.sort()
j = n-1
pointer = n
pointer2 = n-1
count = 0
while j >= 0:
if l[j]*(pointer-j) >= x:
pointer = j
count = count + 1
j = j - 1
print(count)
``` | output | 1 | 107,205 | 17 | 214,411 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,206 | 17 | 214,412 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
t=int(input())
for _ in range(t):
n,x=map(int,input().split(" "))
a=list(map(int,input().split(" ")))
a.sort(reverse=True)
s=0
t=[]
count=0
for y in range(n):
s=s+1
if a[y]*s>=x:
count=count+1
s=0
print(count)
``` | output | 1 | 107,206 | 17 | 214,413 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,207 | 17 | 214,414 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
t=int(input())
for _ in range(t):
n,x=list(map(int,input().split(" ")))
arr=list(map(int,input().split(" ")))
arr.sort(reverse=True)
team=0
count=0
for i in arr:
team+=1
if team*i>=x:
count+=1
team=0
print(count)
``` | output | 1 | 107,207 | 17 | 214,415 |
Provide tags and a correct Python 3 solution for this coding contest problem.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0 | instruction | 0 | 107,208 | 17 | 214,416 |
Tags: brute force, dp, greedy, implementation, sortings
Correct Solution:
```
import sys
def answer(n, x, a):
num = 0
lindx = -1
a.sort(reverse=True)
#print('a=', a)
for i in range(n):
if (i-lindx)*a[i] >= x:
num += 1
lindx = i
return num
def main():
t = int(sys.stdin.readline())
while t:
n, x = map(int, sys.stdin.readline().split())
a = list(map(int, sys.stdin.readline().split()))
print(answer(n, x, a))
t -= 1
return
main()
``` | output | 1 | 107,208 | 17 | 214,417 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
There are n programmers that you want to split into several non-empty teams. The skill of the i-th programmer is a_i. You want to assemble the maximum number of teams from them. There is a restriction for each team: the number of programmers in the team multiplied by the minimum skill among all programmers in the team must be at least x.
Each programmer should belong to at most one team. Some programmers may be left without a team.
Calculate the maximum number of teams that you can assemble.
Input
The first line contains the integer t (1 β€ t β€ 1000) β the number of test cases.
The first line of each test case contains two integers n and x (1 β€ n β€ 10^5; 1 β€ x β€ 10^9) β the number of programmers and the restriction of team skill respectively.
The second line of each test case contains n integers a_1, a_2, ... , a_n (1 β€ a_i β€ 10^9), where a_i is the skill of the i-th programmer.
The sum of n over all inputs does not exceed 10^5.
Output
For each test case print one integer β the maximum number of teams that you can assemble.
Example
Input
3
5 10
7 11 2 9 5
4 8
2 4 2 3
4 11
1 3 3 7
Output
2
1
0
Submitted Solution:
```
from math import ceil
for _ in range(int(input())):
n , x =[int(i) for i in input().split()]
a = [int(i) for i in input().split()]
a.sort(reverse=True)
# print(a)
c = 0
k = 1
for i in range(n):
# print(a[i],k)
if a[i]*k >=x:
c = c+1
k = 1
else:
k = k+1
print(c)
``` | instruction | 0 | 107,209 | 17 | 214,418 |
Yes | output | 1 | 107,209 | 17 | 214,419 |
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