message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input
The first and only line of input contains a single nonempty string s of length at most 1000 composed of lowercase letters (a-z).
Output
Output YES if the string s contains heidi as a subsequence and NO otherwise.
Examples
Input
abcheaibcdi
Output
YES
Input
hiedi
Output
NO
Note
A string s contains another string p as a subsequence if it is possible to delete some characters from s and obtain p.
Submitted Solution:
```
a = list(input())
b = ["h", "e", "i", "d", "i"]
c = []
s = "yes"
n = 0
for x in range(len(b)):
for y in range(n, len(a)):
if b[x] == a[y]:
c.append(y)
a[y] = " "
n = y
break
for x in range(len(c) - 1):
if c[x] > c[x + 1]:
s = "no"
break
print(s)
``` | instruction | 0 | 35,675 | 18 | 71,350 |
No | output | 1 | 35,675 | 18 | 71,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As it's the first of April, Heidi is suspecting that the news she reads today are fake, and she does not want to look silly in front of all the contestants. She knows that a newspiece is fake if it contains heidi as a subsequence. Help Heidi assess whether the given piece is true, but please be discreet about it...
Input
The first and only line of input contains a single nonempty string s of length at most 1000 composed of lowercase letters (a-z).
Output
Output YES if the string s contains heidi as a subsequence and NO otherwise.
Examples
Input
abcheaibcdi
Output
YES
Input
hiedi
Output
NO
Note
A string s contains another string p as a subsequence if it is possible to delete some characters from s and obtain p.
Submitted Solution:
```
string = input()
s = ['h', 'e', 'i', 'd', 'i']
if string.count('h') == 200:
print('YES')
else:
ans = list()
for c in string:
if c in s:
if c not in ans:
ans.append(c)
elif c == 'i':
if ans.count('i') < 2:
ans.append(c)
ans = ''.join(ans)
if ans == 'heidi':
print('YES')
else:
print('NO')
``` | instruction | 0 | 35,676 | 18 | 71,352 |
No | output | 1 | 35,676 | 18 | 71,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
n = input()
l = n.split("WUB")
print(' '.join(l).strip(" "))
``` | instruction | 0 | 36,370 | 18 | 72,740 |
Yes | output | 1 | 36,370 | 18 | 72,741 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
s = input()
a = s.split("WUB")
for i in a:
if i != '':
print(i,end=" ")
``` | instruction | 0 | 36,371 | 18 | 72,742 |
Yes | output | 1 | 36,371 | 18 | 72,743 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
n=input().split("WUB")
for i in range(len(n)):
if n[i]!="":
print(n[i],end=" ")
``` | instruction | 0 | 36,372 | 18 | 72,744 |
Yes | output | 1 | 36,372 | 18 | 72,745 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
s=input()
res=""
c=0
i=0
while(i<len(s)):
if s[i:i+3]=="WUB":
i=i+3
if c==1:
res=res+" "
c=0
else:
res+=s[i]
i+=1
c=1
print(res)
``` | instruction | 0 | 36,373 | 18 | 72,746 |
Yes | output | 1 | 36,373 | 18 | 72,747 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
s=input()
ans=""
n=len(s)
i=0
temp=[]
while(i<n):
#print(s[i])
if(s[i]=='W' and s[i+1]=='U' and s[i+2]=="B"):
i+=3
temp.append(ans)
ans=""
else:
ans+=s[i]
i+=1
temp.append(ans)
print(temp)
ans=""
for i in temp:
if(len(i)!=0):
ans+=i
ans+=" "
print(ans)
``` | instruction | 0 | 36,374 | 18 | 72,748 |
No | output | 1 | 36,374 | 18 | 72,749 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
s=input()
res=s.replace("WUB", "")
print(res)
``` | instruction | 0 | 36,375 | 18 | 72,750 |
No | output | 1 | 36,375 | 18 | 72,751 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
x=input().split('WUB')
x=x[1:-1]
print(' '.join([str(i) for i in x]))
``` | instruction | 0 | 36,376 | 18 | 72,752 |
No | output | 1 | 36,376 | 18 | 72,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya works as a DJ in the best Berland nightclub, and he often uses dubstep music in his performance. Recently, he has decided to take a couple of old songs and make dubstep remixes from them.
Let's assume that a song consists of some number of words. To make the dubstep remix of this song, Vasya inserts a certain number of words "WUB" before the first word of the song (the number may be zero), after the last word (the number may be zero), and between words (at least one between any pair of neighbouring words), and then the boy glues together all the words, including "WUB", in one string and plays the song at the club.
For example, a song with words "I AM X" can transform into a dubstep remix as "WUBWUBIWUBAMWUBWUBX" and cannot transform into "WUBWUBIAMWUBX".
Recently, Petya has heard Vasya's new dubstep track, but since he isn't into modern music, he decided to find out what was the initial song that Vasya remixed. Help Petya restore the original song.
Input
The input consists of a single non-empty string, consisting only of uppercase English letters, the string's length doesn't exceed 200 characters. It is guaranteed that before Vasya remixed the song, no word contained substring "WUB" in it; Vasya didn't change the word order. It is also guaranteed that initially the song had at least one word.
Output
Print the words of the initial song that Vasya used to make a dubsteb remix. Separate the words with a space.
Examples
Input
WUBWUBABCWUB
Output
ABC
Input
WUBWEWUBAREWUBWUBTHEWUBCHAMPIONSWUBMYWUBFRIENDWUB
Output
WE ARE THE CHAMPIONS MY FRIEND
Note
In the first sample: "WUBWUBABCWUB" = "WUB" + "WUB" + "ABC" + "WUB". That means that the song originally consisted of a single word "ABC", and all words "WUB" were added by Vasya.
In the second sample Vasya added a single word "WUB" between all neighbouring words, in the beginning and in the end, except for words "ARE" and "THE" β between them Vasya added two "WUB".
Submitted Solution:
```
def main():
string = input()
string = string.replace("WUB", " ")
print(string)
string = string.strip()
print(string)
if __name__ == '__main__':
import sys
sys.exit(main())
``` | instruction | 0 | 36,377 | 18 | 72,754 |
No | output | 1 | 36,377 | 18 | 72,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
n = int(input())
p = [int(i) for i in input().split()]
flag = True
for i in range(n):
line = input()
amount = 0
for st in line.split(" "):
for l in st:
if l in ["a", "e", "i", "o", "u", "y"]:
amount += 1
if p[i] != amount:
flag = False
if flag:
print("YES")
else:
print("NO")
``` | instruction | 0 | 37,331 | 18 | 74,662 |
Yes | output | 1 | 37,331 | 18 | 74,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
def vowel(s):
b=0
a=["a","i","o","u","y","e"]
for i in range(len(s)):
if s[i]==a[0] or s[i]==a[1] or s[i]==a[2] or s[i]==a[3] or s[i]==a[4] or s[i]==a[5]:
b+=1
return b
n=int(input())
l=list(map(int,input().split()))
q=[]
j="YES"
for i in range(n):
if (vowel(input())!=l[i] ):
j="NO"
print(j)
``` | instruction | 0 | 37,332 | 18 | 74,664 |
Yes | output | 1 | 37,332 | 18 | 74,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
n = int(input())
arr = list(map(int,input().split()))
vowels = {'a','e','i','o','u','y'}
flag = True
for i in range(n):
text = input()
count=0
for j in text:
if(j in vowels):
count+=1
if(count!=arr[i]):
flag = False
break
if(flag): print("YES")
else: print("NO")
``` | instruction | 0 | 37,333 | 18 | 74,666 |
Yes | output | 1 | 37,333 | 18 | 74,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
def count_vowels(s):
d = set(['a', 'i', 'e', 'o', 'u', 'y'])
count = 0
for i in s:
if i in d:
count +=1
return count
n = int(input().strip())
arr = [int(x) for x in input().strip().split(' ')]
possible = True
for x in range(n):
if count_vowels(input().strip()) != arr[x]:
possible = False
break
print("YES" if possible else "NO")
``` | instruction | 0 | 37,334 | 18 | 74,668 |
Yes | output | 1 | 37,334 | 18 | 74,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
print('YNEOS'[any(p!=sum(map(input().count,'aeiouy')) for p in map(int,input().split()))::2])
``` | instruction | 0 | 37,335 | 18 | 74,670 |
No | output | 1 | 37,335 | 18 | 74,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
# Uses python3
numOfLines = int(input())
p = [int(pi) for pi in input().split()]
assert (len(p) == numOfLines)
Text = []
flag = False
vowels = ['a', 'e', 'i', 'o', 'u', 'y']
for i in range(0,numOfLines):
Text.append(str(input()))
for i in range(0, numOfLines):
Count = 0
for j in range(0,5):
words = str(Text[i])
if words.find(vowels[j]) >= 0:
Count = Count+words.count(vowels[j])
if Count != p[i]:
flag = False
break
else:
flag = True
if flag:
print("YES\n")
else:
print("NO\n")
``` | instruction | 0 | 37,336 | 18 | 74,672 |
No | output | 1 | 37,336 | 18 | 74,673 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
n = int(input())
arr = list(map(int,input().split()))
vowels = {'a','e','i','o','u'}
flag = True
for i in range(n):
text = input()
count=0
for j in text:
if(j in vowels):
count+=1
if(count!=arr[i]):
flag = False
break
if(flag): print("YES")
else: print("NO")
``` | instruction | 0 | 37,337 | 18 | 74,674 |
No | output | 1 | 37,337 | 18 | 74,675 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a text consisting of n lines. Each line contains some space-separated words, consisting of lowercase English letters.
We define a syllable as a string that contains exactly one vowel and any arbitrary number (possibly none) of consonants. In English alphabet following letters are considered to be vowels: 'a', 'e', 'i', 'o', 'u' and 'y'.
Each word of the text that contains at least one vowel can be divided into syllables. Each character should be a part of exactly one syllable. For example, the word "mamma" can be divided into syllables as "ma" and "mma", "mam" and "ma", and "mamm" and "a". Words that consist of only consonants should be ignored.
The verse patterns for the given text is a sequence of n integers p1, p2, ..., pn. Text matches the given verse pattern if for each i from 1 to n one can divide words of the i-th line in syllables in such a way that the total number of syllables is equal to pi.
You are given the text and the verse pattern. Check, if the given text matches the given verse pattern.
Input
The first line of the input contains a single integer n (1 β€ n β€ 100) β the number of lines in the text.
The second line contains integers p1, ..., pn (0 β€ pi β€ 100) β the verse pattern.
Next n lines contain the text itself. Text consists of lowercase English letters and spaces. It's guaranteed that all lines are non-empty, each line starts and ends with a letter and words are separated by exactly one space. The length of each line doesn't exceed 100 characters.
Output
If the given text matches the given verse pattern, then print "YES" (without quotes) in the only line of the output. Otherwise, print "NO" (without quotes).
Examples
Input
3
2 2 3
intel
code
ch allenge
Output
YES
Input
4
1 2 3 1
a
bcdefghi
jklmnopqrstu
vwxyz
Output
NO
Input
4
13 11 15 15
to be or not to be that is the question
whether tis nobler in the mind to suffer
the slings and arrows of outrageous fortune
or to take arms against a sea of troubles
Output
YES
Note
In the first sample, one can split words into syllables in the following way:
in-tel
co-de
ch al-len-ge
Since the word "ch" in the third line doesn't contain vowels, we can ignore it. As the result we get 2 syllabels in first two lines and 3 syllables in the third one.
Submitted Solution:
```
print('YNEOS'[all(p!=sum(map(input().count,'aeiouy')) for p in map(int,input().split()))::2])
``` | instruction | 0 | 37,338 | 18 | 74,676 |
No | output | 1 | 37,338 | 18 | 74,677 |
Provide a correct Python 3 solution for this coding contest problem.
The committee members of the Kitoshima programming contest had decided to use crypto-graphic software for their secret communication. They had asked a company, Kodai Software, to develop cryptographic software that employed a cipher based on highly sophisticated mathematics.
According to reports on IT projects, many projects are not delivered on time, on budget, with required features and functions. This applied to this case. Kodai Software failed to implement the cipher by the appointed date of delivery, and asked to use a simpler version that employed a type of substitution cipher for the moment. The committee members got angry and strongly requested to deliver the full specification product, but they unwillingly decided to use this inferior product for the moment.
In what follows, we call the text before encryption, plaintext, and the text after encryption, ciphertext.
This simple cipher substitutes letters in the plaintext, and its substitution rule is specified with a set of pairs. A pair consists of two letters and is unordered, that is, the order of the letters in the pair does not matter. A pair (A, B) and a pair (B, A) have the same meaning. In one substitution rule, one letter can appear in at most one single pair. When a letter in a pair appears in the plaintext, the letter is replaced with the other letter in the pair. Letters not specified in any pairs are left as they are.
For example, by substituting the plaintext
ABCDEFGHIJKLMNOPQRSTUVWXYZ
with the substitution rule {(A, Z), (B, Y)} results in the following ciphertext.
ZYCDEFGHIJKLMNOPQRSTUVWXBA
This may be a big chance for us, because the substitution rule seems weak against cracking. We may be able to know communications between committee members. The mission here is to develop a deciphering program that finds the plaintext messages from given ciphertext messages.
A ciphertext message is composed of one or more ciphertext words. A ciphertext word is generated from a plaintext word with a substitution rule. You have a list of candidate words containing the words that can appear in the plaintext; no other words may appear. Some words in the list may not actually be used in the plaintext.
There always exists at least one sequence of candidate words from which the given ciphertext is obtained by some substitution rule. There may be cases where it is impossible to uniquely identify the plaintext from a given ciphertext and the list of candidate words.
Input
The input consists of multiple datasets, each of which contains a ciphertext message and a list of candidate words in the following format.
n
word1
.
.
.
wordn
sequence
n in the first line is a positive integer, representing the number of candidate words. Each of the next n lines represents one of the candidate words. The last line, sequence, is a sequence of one or more ciphertext words separated by a single space and terminated with a period.
You may assume the number of characters in each sequence is more than 1 and less than or equal to 80 including spaces and the period. The number of candidate words in the list, n, does not exceed 20. Only 26 uppercase letters, A to Z, are used in the words and the length of each word is from 1 to 20, inclusive.
A line of a single zero indicates the end of the input.
Output
For each dataset, your program should print the deciphered message in a line. Two adjacent words in an output line should be separated by a single space and the last word should be followed by a single period. When it is impossible to uniquely identify the plaintext, the output line should be a single hyphen followed by a single period.
Example
Input
4
A
AND
CAT
DOG
Z XUW ZVX Z YZT.
2
AZ
AY
ZA.
2
AA
BB
CC.
16
A
B
C
D
E
F
G
H
I
J
K
L
M
N
O
ABCDEFGHIJKLMNO
A B C D E F G H I J K L M N O ABCDEFGHIJKLMNO.
0
Output
A DOG AND A CAT.
AZ.
-.
A B C D E F G H I J K L M N O ABCDEFGHIJKLMNO. | instruction | 0 | 37,703 | 18 | 75,406 |
"Correct Solution:
```
from string import ascii_uppercase
import sys
readline = sys.stdin.readline
write = sys.stdout.write
conv = ascii_uppercase.find
def solve():
N = int(readline())
if N == 0:
return False
W = [tuple(map(conv, readline().strip())) for i in range(N)]
S = []
T = set()
for s in readline().strip()[:-1].split():
e = tuple(map(conv, s))
S.append(e)
T.add(e)
*T, = T
U = []
for s in T:
g = []
for i, w in enumerate(W):
if len(w) != len(s):
continue
p = [-1]*26
l = len(w)
for k in range(l):
if p[s[k]] == p[w[k]] == -1:
p[s[k]] = w[k]
p[w[k]] = s[k]
elif p[s[k]] == -1 or p[w[k]] == -1 or p[s[k]] != w[k]:
break
else:
g.append(i)
U.append((s, g))
L = len(U)
U.sort(key = lambda x: len(x[1]))
res = None
cnt = 0
def dfs(i, p0, used):
nonlocal res, cnt
if i == L:
res = p0[:]
cnt += 1
return
p = [0]*26
s, g = U[i]
for j in g:
if used[j]:
continue
w = W[j]
p[:] = p0
l = len(w)
for k in range(l):
if p[s[k]] == p[w[k]] == -1:
p[s[k]] = w[k]
p[w[k]] = s[k]
elif p[s[k]] == -1 or p[w[k]] == -1 or p[s[k]] != w[k]:
break
else:
used[j] = 1
dfs(i+1, p, used)
used[j] = 0
if cnt >= 2:
return
dfs(0, [-1]*26, [0]*N)
if cnt != 1:
write("-.\n")
else:
cA = ord("A")
ans = []
for s in S:
t = []
for e in s:
t.append(chr(res[e] + cA))
ans.append("".join(t))
write(" ".join(ans))
write(".\n")
return True
while solve():
...
``` | output | 1 | 37,703 | 18 | 75,407 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many countries have such a New Year or Christmas tradition as writing a letter to Santa including a wish list for presents. Vasya is an ordinary programmer boy. Like all ordinary boys, he is going to write the letter to Santa on the New Year Eve (we Russians actually expect Santa for the New Year, not for Christmas).
Vasya has come up with an algorithm he will follow while writing a letter. First he chooses two strings, s1 anf s2, consisting of uppercase English letters. Then the boy makes string sk, using a recurrent equation sn = sn - 2 + sn - 1, operation '+' means a concatenation (that is, the sequential record) of strings in the given order. Then Vasya writes down string sk on a piece of paper, puts it in the envelope and sends in to Santa.
Vasya is absolutely sure that Santa will bring him the best present if the resulting string sk has exactly x occurrences of substring AC (the short-cut reminds him ΠΎf accepted problems). Besides, Vasya decided that string s1 should have length n, and string s2 should have length m. Vasya hasn't decided anything else.
At the moment Vasya's got urgent New Year business, so he asks you to choose two strings for him, s1 and s2 in the required manner. Help Vasya.
Input
The first line contains four integers k, x, n, m (3 β€ k β€ 50; 0 β€ x β€ 109; 1 β€ n, m β€ 100).
Output
In the first line print string s1, consisting of n uppercase English letters. In the second line print string s2, consisting of m uppercase English letters. If there are multiple valid strings, print any of them.
If the required pair of strings doesn't exist, print "Happy new year!" without the quotes.
Examples
Input
3 2 2 2
Output
AC
AC
Input
3 3 2 2
Output
Happy new year!
Input
3 0 2 2
Output
AA
AA
Input
4 3 2 1
Output
Happy new year!
Input
4 2 2 1
Output
Happy new year!
Submitted Solution:
```
import sys
import itertools
k, x, n, m = map(int, input().split())
def valid(inicio, fim, tamanho, num_ac):
s = "AC" * num_ac
if len(s) == 0 or s[0] != inicio:
s = inicio + s
if len(s) > tamanho:
return ""
if len(s) == 0 or s[-1] != fim:
if tamanho - len(s) - 1 < 0:
return ""
s = s + ("B" * (tamanho - len(s) - 1)) + fim
else:
s = s + ("B" * (tamanho - len(s)))
return s
a = [0] * 51
a[1] = 1
b = [0] * 51
b[2] = 1
for i in range(3, 51):
a[i] = a[i-2] + a[i-1]
b[i] = b[i-2] + b[i-1]
for letters in itertools.product(['A', 'B', 'C'], repeat=4):
first_s1 = letters[0]
last_s1 = letters[1]
first_s2 = letters[2]
last_s2 = letters[3]
c = [0] * 51
meio = last_s1 + first_s2
c[3] = (1 if meio == "AC" else 0)
for i in range(4, 51):
meio = last_s2 + (first_s1 if i % 2 == 0 else first_s2)
c[i] = c[i-2] + c[i-1] + (1 if meio == "AC" else 0)
for occ1 in range(0, 51):
tmp = x - a[k] * occ1 - c[k]
if tmp % b[k] != 0:
continue
tmp = tmp//b[k]
if tmp < 0 or tmp > 50:
continue
s1 = valid(first_s1, last_s1, n, occ1)
s2 = valid(first_s2, last_s2, m, tmp)
if s1 and s2:
print(s1)
print(s2)
sys.exit(0)
print("Happy new year!")
``` | instruction | 0 | 38,013 | 18 | 76,026 |
No | output | 1 | 38,013 | 18 | 76,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many countries have such a New Year or Christmas tradition as writing a letter to Santa including a wish list for presents. Vasya is an ordinary programmer boy. Like all ordinary boys, he is going to write the letter to Santa on the New Year Eve (we Russians actually expect Santa for the New Year, not for Christmas).
Vasya has come up with an algorithm he will follow while writing a letter. First he chooses two strings, s1 anf s2, consisting of uppercase English letters. Then the boy makes string sk, using a recurrent equation sn = sn - 2 + sn - 1, operation '+' means a concatenation (that is, the sequential record) of strings in the given order. Then Vasya writes down string sk on a piece of paper, puts it in the envelope and sends in to Santa.
Vasya is absolutely sure that Santa will bring him the best present if the resulting string sk has exactly x occurrences of substring AC (the short-cut reminds him ΠΎf accepted problems). Besides, Vasya decided that string s1 should have length n, and string s2 should have length m. Vasya hasn't decided anything else.
At the moment Vasya's got urgent New Year business, so he asks you to choose two strings for him, s1 and s2 in the required manner. Help Vasya.
Input
The first line contains four integers k, x, n, m (3 β€ k β€ 50; 0 β€ x β€ 109; 1 β€ n, m β€ 100).
Output
In the first line print string s1, consisting of n uppercase English letters. In the second line print string s2, consisting of m uppercase English letters. If there are multiple valid strings, print any of them.
If the required pair of strings doesn't exist, print "Happy new year!" without the quotes.
Examples
Input
3 2 2 2
Output
AC
AC
Input
3 3 2 2
Output
Happy new year!
Input
3 0 2 2
Output
AA
AA
Input
4 3 2 1
Output
Happy new year!
Input
4 2 2 1
Output
Happy new year!
Submitted Solution:
```
k,x,n,m = map(int,input().split())
a = ((1,0),(0,0,0,0),(0,0))
b = ((0,1),(0,0,0,0),(1,1))
for i in range(3,k+1):
tupsum = lambda m,n:tuple(map(lambda a,b:a+b,m,n))
cross = lambda m,n:tuple([1 if i == 2*m[2][1]+n[2][0] else 0
for i in range(4)])
a,b = b,(tupsum(a[0],b[0]),
tupsum(tupsum(a[1],b[1]),
cross(a,b)),
(a[2][0],b[2][1]))
#print(b)
done = False
s = ("","")
def solve(fib,n,m,x):
global done
global s
if done: return
for i in range(n//2 + 1):
if (x - i*fib[0]) % fib[1] == 0 and (x-i*fib[0]) // fib[1] <= m // 2:
#print(fib,n,m,x)
done = True
j = (x-i*fib[0]) // fib[1]
s = ("AC"*i + "B"*(n-2*i),"AC"*j + "B"*(m-2*j))
return
if not done:
solve(b[0],n,m,x)
if done: print(s[0],s[1],sep='\n')
if not done:
solve(b[0],n-1,m-1,x-b[1][1])
if done: print(s[0]+'A','C'+s[1],sep='\n')
if not done:
solve(b[0],n-1,m-1,x-b[1][2])
if done: print('C'+s[0],s[1]+'A',sep='\n')
if not done:
solve(b[0],n,m-2,x-b[1][3])
if done: print(s[0],'C'+s[1]+'A',sep='\n')
if not done:
solve(b[0],n-1,m-2,x-b[1][2]-b[1][3])
if done: print('C'+s[0],'C'+s[1]+'A',sep='\n')
if not done:
solve(b[0],n-1,m-2,x-b[1][1]-b[1][3])
if done: print(s[0]+'A','C'+s[1]+'A',sep='\n')
if not done:
solve(b[0],n-2,m-2,x-b[1][1]-b[1][2]-b[1][3])
if done: print('C'+s[0]+'A','C'+s[1]+'A',sep='\n')
if not done: print("Happy new year!")
``` | instruction | 0 | 38,014 | 18 | 76,028 |
No | output | 1 | 38,014 | 18 | 76,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many countries have such a New Year or Christmas tradition as writing a letter to Santa including a wish list for presents. Vasya is an ordinary programmer boy. Like all ordinary boys, he is going to write the letter to Santa on the New Year Eve (we Russians actually expect Santa for the New Year, not for Christmas).
Vasya has come up with an algorithm he will follow while writing a letter. First he chooses two strings, s1 anf s2, consisting of uppercase English letters. Then the boy makes string sk, using a recurrent equation sn = sn - 2 + sn - 1, operation '+' means a concatenation (that is, the sequential record) of strings in the given order. Then Vasya writes down string sk on a piece of paper, puts it in the envelope and sends in to Santa.
Vasya is absolutely sure that Santa will bring him the best present if the resulting string sk has exactly x occurrences of substring AC (the short-cut reminds him ΠΎf accepted problems). Besides, Vasya decided that string s1 should have length n, and string s2 should have length m. Vasya hasn't decided anything else.
At the moment Vasya's got urgent New Year business, so he asks you to choose two strings for him, s1 and s2 in the required manner. Help Vasya.
Input
The first line contains four integers k, x, n, m (3 β€ k β€ 50; 0 β€ x β€ 109; 1 β€ n, m β€ 100).
Output
In the first line print string s1, consisting of n uppercase English letters. In the second line print string s2, consisting of m uppercase English letters. If there are multiple valid strings, print any of them.
If the required pair of strings doesn't exist, print "Happy new year!" without the quotes.
Examples
Input
3 2 2 2
Output
AC
AC
Input
3 3 2 2
Output
Happy new year!
Input
3 0 2 2
Output
AA
AA
Input
4 3 2 1
Output
Happy new year!
Input
4 2 2 1
Output
Happy new year!
Submitted Solution:
```
def f(k):
if k == 1: return (1, 0, 0, 0, 0)
if k == 2: return (0, 1, 0, 0, 0)
if k == 3: return (1, 1, 1, 0, 0)
a, b = 1, 1
for i in range(k - 3): a, b = b, a + b
c = a
d = e = 0
for i in range(k - 3): d, e = e, d + e + int(i % 2 == 0)
return (a, b, c, d, e)
def r(a, i, n):
if n == 1:
if a == 'BB': return 'B'
if a == 'BA': return 'A'
if a == 'CB': return 'C'
return False
if i == 0:
if a == 'BB': return 'B' * n
if a == 'BA': return 'B' * (n - 1) + 'A'
if a == 'CB': return 'C' + 'B' * (n - 1)
x = 'AC' * i
n -= len(x)
if n < 0: return False
if a[0] == 'B':
if a[1] == 'B': return x + 'C' * n
return x + 'A' * n
else:
if a[1] == 'B': return 'C' * n + x
n -= 1
if n < 0: return False
return 'C' + x + 'A' * n
def g(a, b, i, j, n, m):
a, b = r(a, i, n), r(b, j, m)
if a and b:
print(a)
print(b)
return True
return False
def h():
k, x, n, m = map(int, input().split())
t = f(k)
for i in range(n // 2 + 1):
for j in range(m // 2 + 1):
if x == t[0] * i + t[1] * j:
print('AC' * i + 'B' * (n - 2 * i))
print('AC' * j + 'B' * (m - 2 * j))
return
for i in range((n + 1) // 2):
for j in range((m + 1) // 2):
y = x - (t[0] * i + t[1] * j)
if y == t[2] and g('BA', 'CB', i, j, n, m): return
if y == t[3] and g('BB', 'CA', i, j, n, m): return
if y == t[4] and g('CB', 'BA', i, j, n, m): return
if y == t[2] + t[3] and g('BA', 'CA', i, j, n, m): return
if y == t[3] + t[4] and g('CB', 'BA', i, j, n, m): return
if y == t[2] + t[3] + t[4] and g('CA', 'CA', i, j, n, m): return
print('Happy new year!')
h()
``` | instruction | 0 | 38,015 | 18 | 76,030 |
No | output | 1 | 38,015 | 18 | 76,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Many countries have such a New Year or Christmas tradition as writing a letter to Santa including a wish list for presents. Vasya is an ordinary programmer boy. Like all ordinary boys, he is going to write the letter to Santa on the New Year Eve (we Russians actually expect Santa for the New Year, not for Christmas).
Vasya has come up with an algorithm he will follow while writing a letter. First he chooses two strings, s1 anf s2, consisting of uppercase English letters. Then the boy makes string sk, using a recurrent equation sn = sn - 2 + sn - 1, operation '+' means a concatenation (that is, the sequential record) of strings in the given order. Then Vasya writes down string sk on a piece of paper, puts it in the envelope and sends in to Santa.
Vasya is absolutely sure that Santa will bring him the best present if the resulting string sk has exactly x occurrences of substring AC (the short-cut reminds him ΠΎf accepted problems). Besides, Vasya decided that string s1 should have length n, and string s2 should have length m. Vasya hasn't decided anything else.
At the moment Vasya's got urgent New Year business, so he asks you to choose two strings for him, s1 and s2 in the required manner. Help Vasya.
Input
The first line contains four integers k, x, n, m (3 β€ k β€ 50; 0 β€ x β€ 109; 1 β€ n, m β€ 100).
Output
In the first line print string s1, consisting of n uppercase English letters. In the second line print string s2, consisting of m uppercase English letters. If there are multiple valid strings, print any of them.
If the required pair of strings doesn't exist, print "Happy new year!" without the quotes.
Examples
Input
3 2 2 2
Output
AC
AC
Input
3 3 2 2
Output
Happy new year!
Input
3 0 2 2
Output
AA
AA
Input
4 3 2 1
Output
Happy new year!
Input
4 2 2 1
Output
Happy new year!
Submitted Solution:
```
k, x, n, m = map(int, input().split())
max1 = n // 2
max2 = m // 2
i = 0
T = True
while i <= max1 and T:
for j in range(0, max2 + 1):
prev2 = i
prev = j
for q in range(k - 2):
prev, prev2 = prev + prev2, prev
if prev == x:
T = False
break
i += 1
i -= 1
if T:
print('Happy New Year!')
else:
print('AC' * i + 'B' * (n - 2 * i))
print('AC' * j + 'B' * (m - 2 * j))
``` | instruction | 0 | 38,016 | 18 | 76,032 |
No | output | 1 | 38,016 | 18 | 76,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k, a, b = map(int,input().split())
st = input()
i, j = 0, 0
n = len(st)
first = 0
if n/k > b or n//k < a:
print("No solution")
else:
for i in range(k):
if i < n%k:
print(st[first:first+n//k+1])
first = first+ (n//k+1)
else:
print(st[first:first+n//k])
first = first + n//k
``` | instruction | 0 | 38,041 | 18 | 76,082 |
Yes | output | 1 | 38,041 | 18 | 76,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k,a,b=map(int,input().split())
s=input()
lent=len(s)
if lent>(k*b) or lent<(k*a):
print("No solution")
else:
dp=[a]*k
rem=lent-(sum(dp))
i=0
while rem>0:
dp[i]+=1
i=(i+1)%k
rem-=1
pref=[0]*(k+1)
pref[1]=dp[0]
for i in range(1,k+1):
pref[i]=pref[i-1]+dp[i-1]
for i in range(1,k+1):
print(s[pref[i-1]:pref[i]])
``` | instruction | 0 | 38,042 | 18 | 76,084 |
Yes | output | 1 | 38,042 | 18 | 76,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k, a1, b = map(int, input().split())
a = list(map(str, input()))
s = k * a1
s1 = k * b
l = 0
t = ""
r = len(a) // k
if len(a) > s1 or s > len(a):
print("No solution")
else:
for i in range(k - 1):
for j in range(r):
t += a[l]
l += 1
print(t)
t = ""
for i in range(l, len(a)):
t += a[l]
l += 1
print(t)
``` | instruction | 0 | 38,043 | 18 | 76,086 |
Yes | output | 1 | 38,043 | 18 | 76,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k,a,b=map(int,input().split())
s=input()
if(k*a>len(s) or k*b<len(s)):
print("No solution")
else:
ch=0
a,b=divmod(len(s),k)
for i in range(k):
p=a+(i<b)
print(s[ch:ch+p])
ch=ch+p
``` | instruction | 0 | 38,044 | 18 | 76,088 |
Yes | output | 1 | 38,044 | 18 | 76,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k,a,b=map(int,input().split())
s=input()
bal =len(s)
if bal>k*b:
print("No solution")
else:
arr=[a]*k
bal-=a*k
inc=bal//k
bal-=inc*k
for i in range(k):
arr[i]+=inc
for i in range(bal):
arr[i]+=1
#print(arr)
for i in range(1,k):
arr[i]+=arr[i-1]
arr2=[s[:arr[0]]]
for i in range(1,k):
arr2.append(s[arr[i-1]:arr[i]])
#print(arr)
for i in arr2:
print(i)
``` | instruction | 0 | 38,045 | 18 | 76,090 |
No | output | 1 | 38,045 | 18 | 76,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
import sys
from sys import stdin, stdout
def main():
k, a, b = [int(x) for x in stdin.readline().rstrip().split()]
s = stdin.readline().rstrip()
n = len(s)
b = min(b, n)
if a > n:
print('No solution')
sys.exit(0)
table = [[-1] * n for _ in range(k)]
print(table)
for w in range(a - 1, b):
print(w)
table[0][w] = 0
for i in range(1, k):
for j in range(n):
for w in range(a - 1, b):
if j - w - 1 >= 0 and table[i - 1][j - w - 1] >= 0:
table[i][j] = j - w
if table[-1][-1] > -1:
i, j = k - 1, n - 1
out = []
while i >= 0:
if table[i][j] >= 0:
out.append(s[table[i][j]:j + 1])
j = table[i][j]
i -= 1
j -= 1
out = out[::-1]
for o in out:
print(o)
else:
print('No solution')
if __name__ == '__main__':
main()
``` | instruction | 0 | 38,046 | 18 | 76,092 |
No | output | 1 | 38,046 | 18 | 76,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
k,a,b=[int(i)for i in input().split()]
s=input()
if k*b<len(s) or k*a>len(s):
print('No solution')
else:
n=a
#c=len(s)//n
while (len(s)//n)>k:
n+=1
if len(s)%(n+1)==0 and len(s)%n!=0 and len(s)//(n+1)==k:
n+=1
h = 0
l = n
for i in range(len(s) // n):
print(s[h:l])
h += n
l += n
elif len(s)%n != 0:
##########if len(s)%n != 0:
# if len(s)%n<a:
h = 0
l = n
for i in range(len(s) % k) :
print(s[h:l+1])
h += n+1
l += n+1
for i in range(len(s)//n-len(s) % n):
print(s[h:l])
h += n
l += n
elif len(s) // n < k and len(s) % n == 0:
n-=1
h = 0
l = n
for i in range(len(s) % k):
print(s[h:(l + 1)])
h += n + 1
l += n + 1
for i in range(len(s) // n - len(s) % n):
print(s[h:l])
h += n
l += n
else:
h=0
l=n
for i in range(len(s)//n):
print(s[h:l])
h+=n
l+=n
``` | instruction | 0 | 38,047 | 18 | 76,094 |
No | output | 1 | 38,047 | 18 | 76,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Anfisa the monkey learns to type. She is yet unfamiliar with the "space" key and can only type in lower-case Latin letters. Having typed for a fairly long line, Anfisa understood that it would be great to divide what she has written into k lines not shorter than a and not longer than b, for the text to resemble human speech more. Help Anfisa.
Input
The first line contains three integers k, a and b (1 β€ k β€ 200, 1 β€ a β€ b β€ 200). The second line contains a sequence of lowercase Latin letters β the text typed by Anfisa. It is guaranteed that the given line is not empty and its length does not exceed 200 symbols.
Output
Print k lines, each of which contains no less than a and no more than b symbols β Anfisa's text divided into lines. It is not allowed to perform any changes in the text, such as: deleting or adding symbols, changing their order, etc. If the solution is not unique, print any of them. If there is no solution, print "No solution" (without quotes).
Examples
Input
3 2 5
abrakadabra
Output
ab
rakad
abra
Input
4 1 2
abrakadabra
Output
No solution
Submitted Solution:
```
# http://codeforces.com/problemset/problem/44/E
import textwrap
s = str(input())
x = map(int , s.split())
s = list(x)
times = s[0]
minimum = s[1]
maximum = s[2]
sequence = str(input())
len_sequence = len(sequence)
if( (times*maximum ) < len_sequence or (times*minimum) > len_sequence ):
print('No solution')
else:
divide_remaining = len_sequence - ( times * minimum )
num_addable = maximum - minimum
if( divide_remaining <= num_addable ):
len_part2 = 0
elif( divide_remaining % num_addable == 0 ):
len_part2 = int(divide_remaining / num_addable)
else:
len_part2 = int(divide_remaining / num_addable) + 1
len_part1 = int(times - len_part2)
parts1 = sequence[:(minimum*len_part1)]
parts1 = textwrap.wrap(parts1 , minimum)
for i in parts1:
print(i)
if(len_part1 == 0):
parts2 = str(sequence)
else:
parts2 = sequence[(len_part1+1):]
parts2 = textwrap.wrap(parts2 , maximum)
for i in parts2:
print(i)
``` | instruction | 0 | 38,048 | 18 | 76,096 |
No | output | 1 | 38,048 | 18 | 76,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
"QAQ" is a word to denote an expression of crying. Imagine "Q" as eyes with tears and "A" as a mouth.
Now Diamond has given Bort a string consisting of only uppercase English letters of length n. There is a great number of "QAQ" in the string (Diamond is so cute!).
<image> illustration by η«ε± https://twitter.com/nekoyaliu
Bort wants to know how many subsequences "QAQ" are in the string Diamond has given. Note that the letters "QAQ" don't have to be consecutive, but the order of letters should be exact.
Input
The only line contains a string of length n (1 β€ n β€ 100). It's guaranteed that the string only contains uppercase English letters.
Output
Print a single integer β the number of subsequences "QAQ" in the string.
Examples
Input
QAQAQYSYIOIWIN
Output
4
Input
QAQQQZZYNOIWIN
Output
3
Note
In the first example there are 4 subsequences "QAQ": "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN", "QAQAQYSYIOIWIN".
Submitted Solution:
```
s=input()
c=0
for i in range(len(s)-2):
if s[i]=="Q" and s[i+1]=="A" and s[i+2]=="Q":
c+=1
if c==0:
print(c)
else:
print(c+2)
``` | instruction | 0 | 38,287 | 18 | 76,574 |
No | output | 1 | 38,287 | 18 | 76,575 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,344 | 18 | 76,688 |
"Correct Solution:
```
S = input()
if S.replace("hi", "") == "":
print("Yes")
else:
print("No")
``` | output | 1 | 38,344 | 18 | 76,689 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,345 | 18 | 76,690 |
"Correct Solution:
```
print("YNeos"["".join(input().split("hi"))!=""::2])
``` | output | 1 | 38,345 | 18 | 76,691 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,346 | 18 | 76,692 |
"Correct Solution:
```
S=input().replace('hi','')
if len(S):
print('No')
else:
print('Yes')
``` | output | 1 | 38,346 | 18 | 76,693 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,347 | 18 | 76,694 |
"Correct Solution:
```
s=input()
print("Yes" if s.replace("hi","")=="" else "No")
``` | output | 1 | 38,347 | 18 | 76,695 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,348 | 18 | 76,696 |
"Correct Solution:
```
S = input()
print('Yes') if (S.count('hi') == len(S) / 2) else print('No')
``` | output | 1 | 38,348 | 18 | 76,697 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,349 | 18 | 76,698 |
"Correct Solution:
```
S = input()
print("Yes" if all(map(lambda x: x=="", S.split("hi"))) else "No")
``` | output | 1 | 38,349 | 18 | 76,699 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,350 | 18 | 76,700 |
"Correct Solution:
```
s = input()
n = s.count("hi")
print("Yes" if n*2 == len(s) else "No")
``` | output | 1 | 38,350 | 18 | 76,701 |
Provide a correct Python 3 solution for this coding contest problem.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No | instruction | 0 | 38,351 | 18 | 76,702 |
"Correct Solution:
```
s=input().strip()
t=s.replace('hi','')
print('Yes' if t=='' else 'No')
``` | output | 1 | 38,351 | 18 | 76,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
if input().replace('hi',''):
print('No')
else:
print('Yes')
``` | instruction | 0 | 38,352 | 18 | 76,704 |
Yes | output | 1 | 38,352 | 18 | 76,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
S = input()
l = S.split("hi")
if "".join(l):
print("No")
else:
print("Yes")
``` | instruction | 0 | 38,353 | 18 | 76,706 |
Yes | output | 1 | 38,353 | 18 | 76,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
s = input()
cont = len(s)//2
if s == "hi"*cont:
print("Yes")
else:
print("No")
``` | instruction | 0 | 38,354 | 18 | 76,708 |
Yes | output | 1 | 38,354 | 18 | 76,709 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
import re;print(re.match('(hi)+$',input())and'Yes'or'No')
``` | instruction | 0 | 38,355 | 18 | 76,710 |
Yes | output | 1 | 38,355 | 18 | 76,711 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
# -*- coding: utf-8 -*-
S = input()
if "hi" in S:
print("Yes")
else:
print("No")
``` | instruction | 0 | 38,356 | 18 | 76,712 |
No | output | 1 | 38,356 | 18 | 76,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
s = input()
s = list(s)
a = 0
for i in range(1, len(s)-1):
if s[i-1] == 'h' and s[i] == 'i':
if s[i+1] != 'i':
a += 1
break
if a == 1:
print('Yes')
else:
print('No')
``` | instruction | 0 | 38,357 | 18 | 76,714 |
No | output | 1 | 38,357 | 18 | 76,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
S = input()
if S[:2]=="hi" and S[2] != "i":
print("Yes")
else:
print("No")
``` | instruction | 0 | 38,358 | 18 | 76,716 |
No | output | 1 | 38,358 | 18 | 76,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A Hitachi string is a concatenation of one or more copies of the string `hi`.
For example, `hi` and `hihi` are Hitachi strings, while `ha` and `hii` are not.
Given a string S, determine whether S is a Hitachi string.
Constraints
* The length of S is between 1 and 10 (inclusive).
* S is a string consisting of lowercase English letters.
Input
Input is given from Standard Input in the following format:
S
Output
If S is a Hitachi string, print `Yes`; otherwise, print `No`.
Examples
Input
hihi
Output
Yes
Input
hi
Output
Yes
Input
ha
Output
No
Submitted Solution:
```
a = input()
if a == 'hi' or a == 'hihi' or a == 'hihihi' or a == 'hihihihihi':
print('Yes')
else:
print('No')
``` | instruction | 0 | 38,359 | 18 | 76,718 |
No | output | 1 | 38,359 | 18 | 76,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
s = input()
l = [s[1+3*i] for i in range(len(s)//3)]
l = set(l)
print(len(l))
``` | instruction | 0 | 39,050 | 18 | 78,100 |
Yes | output | 1 | 39,050 | 18 | 78,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number β the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
a=input()
l=a[1:len(a)-1].split(', ')
d={}
sum=0
for i in l:
if i not in d and i!='':
sum+=1
d[i]=1
print(sum)
``` | instruction | 0 | 39,051 | 18 | 78,102 |
Yes | output | 1 | 39,051 | 18 | 78,103 |
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