message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
def aletters(s):
filtered = [x for x in list(s) if x != '{' and x != ',' and x != ' ' and x != '}']
return len(set(filtered))
s = input().strip()
print(aletters(s))
``` | instruction | 0 | 39,052 | 18 | 78,104 |
Yes | output | 1 | 39,052 | 18 | 78,105 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
s = input()
s = s[1:-1]
c = s.split(", ")
b = []
for x in c:
if x == '':
break
if not x in b:
b.append(x)
print(len(b))
``` | instruction | 0 | 39,053 | 18 | 78,106 |
Yes | output | 1 | 39,053 | 18 | 78,107 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
s= set(input())
print(len(s))
``` | instruction | 0 | 39,054 | 18 | 78,108 |
No | output | 1 | 39,054 | 18 | 78,109 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
x=set(map(str,input().split()))
p=set(x)
print(len(set(x)))
``` | instruction | 0 | 39,055 | 18 | 78,110 |
No | output | 1 | 39,055 | 18 | 78,111 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
n = input().split(", ")
n = set(n[1: len(n) - 1])
print(len(n))
``` | instruction | 0 | 39,056 | 18 | 78,112 |
No | output | 1 | 39,056 | 18 | 78,113 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, Anton has found a set. The set consists of small English letters. Anton carefully wrote out all the letters from the set in one line, separated by a comma. He also added an opening curved bracket at the beginning of the line and a closing curved bracket at the end of the line.
Unfortunately, from time to time Anton would forget writing some letter and write it again. He asks you to count the total number of distinct letters in his set.
Input
The first and the single line contains the set of letters. The length of the line doesn't exceed 1000. It is guaranteed that the line starts from an opening curved bracket and ends with a closing curved bracket. Between them, small English letters are listed, separated by a comma. Each comma is followed by a space.
Output
Print a single number — the number of distinct letters in Anton's set.
Examples
Input
{a, b, c}
Output
3
Input
{b, a, b, a}
Output
2
Input
{}
Output
0
Submitted Solution:
```
a = input()
b = []
n = 0
table = list('qwertyuiopasdfghjklzxcvbnm')
for i in range(len(a)):
if a[i] in table:
b.append(a[i])
b = sorted(b)
for i in range(len(b)-1):
if b[i+1] == b[i]:
b[i+1] = None
for i in range(len(b)):
if b[i] != None:
n += 1
print(n)
``` | instruction | 0 | 39,057 | 18 | 78,114 |
No | output | 1 | 39,057 | 18 | 78,115 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
# print ("Enter the given text")
text = input()
word = "CODEFORCES"
# First check to see if the length even works
if len(text) <= 10:
print ("NO")
elif text[0:10] == "CODEFORCES": # At the beginning
print("YES")
elif text[len(text)-10:] == "CODEFORCES": # At the end
print("YES")
else:
found = False
for i in range(1,10): # Number of letters at the start
if text[0:i] == word[0:i] and text[len(text)-(10-i):] == word[i:]:
print("YES")
found = True
break
if found == False:
print("NO")
``` | instruction | 0 | 39,098 | 18 | 78,196 |
Yes | output | 1 | 39,098 | 18 | 78,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
if __name__ == '__main__':
refer = 'CODEFORCES'
line = str(input())
s0, s1 = len(refer), len(line)
l = r = 0
while l < min(s0, s1) and line[l] == refer[l]:
l += 1
while r < min(s0, s1) and line[s1 - 1 - r] == refer[s0 - r - 1]:
r += 1
print('YES' if l + r >= 10 else 'NO')
``` | instruction | 0 | 39,099 | 18 | 78,198 |
Yes | output | 1 | 39,099 | 18 | 78,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
s=input()
c="CODEFORCES"
a="NO"
for i in range(len(s)):
for j in range(i,len(s)+1):
if s[:i]+s[j:]==c:a="YES"
print(a)
``` | instruction | 0 | 39,100 | 18 | 78,200 |
Yes | output | 1 | 39,100 | 18 | 78,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
string = input()
cf = 'CODEFORCES'
flag = False
if cf == string[:len(cf)]:
flag = True
else:
for i in range(len(cf)):
for j in range(len(string)):
if (cf[:i] in string[:j] and cf[i:] in string[j:] and
cf[:i] == string[:j] and cf[i:] == string[j-len(cf):]):
flag = True
#print(string[:j], string[j:], string[j-len(cf):])
break
if flag:
print('YES')
else:
print('NO')
``` | instruction | 0 | 39,101 | 18 | 78,202 |
Yes | output | 1 | 39,101 | 18 | 78,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
import sys
def strr(req,inStr):
#print(req,inStr)
x=0
for i in inStr:
if req[:x] in inStr and x<=len(req):
#print(x,req[:x], inStr)
x += 1
else:
if req[x:] in inStr:
#print(req[x:])
print( "YES")
sys.exit()
else:
#print(req[x:],"L2")
print( "NO")
sys.exit()
#print(x)
if x==len(req) or x==len(req)+1:
print( "YES")
else:
print( "NO")
inStr = input()
req = 'CODEFORCES'
medStr = ''
strr(req,inStr)
``` | instruction | 0 | 39,102 | 18 | 78,204 |
No | output | 1 | 39,102 | 18 | 78,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
a = "CODEFORCES"
ok = False
s = input()
for i in range(len(a)):
if a[:i] in s and a[i:] in s:
ok = True
break
print("YES" if ok else "NO")
``` | instruction | 0 | 39,103 | 18 | 78,206 |
No | output | 1 | 39,103 | 18 | 78,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
banner = input()
target = 'CODEFORCES'
for i in range(len(target)):
if target[:i] in banner and target[i:] in banner:
print('YES')
break
else:
print('NO')
``` | instruction | 0 | 39,104 | 18 | 78,208 |
No | output | 1 | 39,104 | 18 | 78,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A large banner with word CODEFORCES was ordered for the 1000-th onsite round of Codeforcesω that takes place on the Miami beach. Unfortunately, the company that made the banner mixed up two orders and delivered somebody else's banner that contains someone else's word. The word on the banner consists only of upper-case English letters.
There is very little time to correct the mistake. All that we can manage to do is to cut out some substring from the banner, i.e. several consecutive letters. After that all the resulting parts of the banner will be glued into a single piece (if the beginning or the end of the original banner was cut out, only one part remains); it is not allowed change the relative order of parts of the banner (i.e. after a substring is cut, several first and last letters are left, it is allowed only to glue the last letters to the right of the first letters). Thus, for example, for example, you can cut a substring out from string 'TEMPLATE' and get string 'TEMPLE' (if you cut out string AT), 'PLATE' (if you cut out TEM), 'T' (if you cut out EMPLATE), etc.
Help the organizers of the round determine whether it is possible to cut out of the banner some substring in such a way that the remaining parts formed word CODEFORCES.
Input
The single line of the input contains the word written on the banner. The word only consists of upper-case English letters. The word is non-empty and its length doesn't exceed 100 characters. It is guaranteed that the word isn't word CODEFORCES.
Output
Print 'YES', if there exists a way to cut out the substring, and 'NO' otherwise (without the quotes).
Examples
Input
CODEWAITFORITFORCES
Output
YES
Input
BOTTOMCODER
Output
NO
Input
DECODEFORCES
Output
YES
Input
DOGEFORCES
Output
NO
Submitted Solution:
```
S = 'CODEFORCES'
n = len(S)
s = str(input())
a = False
for i in range(n):
k = s.find(S[:n - i])
if k != -1:
p = s.find(S[i:], k + i)
if p != -1:
v1 = (k, k + i)
v2 = (p, p + n - i)
if v1[0] == 0 and v2[1] == len(s):
a = True
elif (v1[0] == 0 or v2[1] == len(s)) and v2[1] - v1[0] == 10:
a = True
if a:
print('YES')
else:
print('NO')
``` | instruction | 0 | 39,105 | 18 | 78,210 |
No | output | 1 | 39,105 | 18 | 78,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Problem
Given the string S, which consists of lowercase letters and numbers. Follow the steps below to compress the length of string S.
1. Change the order of the characters in the character string to any order.
Example: "0ig3he12fz99"-> "efghiz012399"
2. Perform the following operations any number of times.
* Select a contiguous substring of "abcdefghijklmnopqrstuvwxyz" in the string and replace it with (first character)'-' (last character).
Example: "efghiz012399"-> "e-iz012399"
* Select a string with a tolerance of 1 (a continuous substring of "0123456789") in the string and replace it with (first digit)'-' (last digit).
Example: "e-iz012399"-> "e-iz0-399"
Find the minimum length of the string obtained by compressing the string S.
Constraints
* 1 ≤ | S | ≤ 100
* String S contains only lowercase letters and numbers
Input
The string S is given on one line.
Output
Output the minimum value of the length of the character string obtained by compressing the character string S on one line. If it cannot be compressed, output the length of the original string S.
Examples
Input
0ig3he12fz99
Output
9
Input
1122334455
Output
6
Submitted Solution:
```
s = list(input())
s.sort()
i = 0
while i + 3 < len(s):
if ord(s[i]) + 3 == ord(s[i + 1]) + 2 == ord(s[i + 2]) + 1 == ord(s[i + 3]):s.pop(i)
else:i += 1
print(len(s))
``` | instruction | 0 | 39,563 | 18 | 79,126 |
No | output | 1 | 39,563 | 18 | 79,127 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
T = int(input())
output = []
def isPalindrome(string):
left = 0
right = len(string)-1
while left<right:
if string[left] != string[right]:
return False
left+=1
right-=1
return True
for t in range(T):
ogString = input()
if not isPalindrome("a"+ogString):
output.append("YES\n"+"a"+ogString)
elif not isPalindrome(ogString+"a"):
output.append("YES\n"+ogString+"a")
else:
output.append("NO")
print("\n".join(output))
``` | instruction | 0 | 39,856 | 18 | 79,712 |
Yes | output | 1 | 39,856 | 18 | 79,713 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
import sys
# import io,os
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
"""
zaza
"""
def solve():
s = input()
n = len(s)
for i, c in enumerate(s):
if c != "a":
after = s[:i] + "a" + s[i:]
if after != after[::-1]:
print("YES")
print(after)
break
before = s[:i + 1] + "a" + s[i + 1:]
if before != before[::-1]:
print("YES")
print(before)
break
else:
print("NO")
T = int(input())
for _ in range(T):
solve()
``` | instruction | 0 | 39,857 | 18 | 79,714 |
Yes | output | 1 | 39,857 | 18 | 79,715 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
def ispal(n,l):
for i in range(0,l//2):
if n[i] != n[l-i-1]:
return False
return True
for _ in range(int(input())):
n = input()
l = len(n)
f = n+"a"
s = "a"+n
if not ispal(f,len(f)):
print("YES")
print(f)
elif not ispal(s,len(s)):
print("YES")
print(s)
else:
print("NO")
``` | instruction | 0 | 39,858 | 18 | 79,716 |
Yes | output | 1 | 39,858 | 18 | 79,717 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
for _ in range(int(input())):
s=input();s1=(s+'a');s2=('a'+s)
if s1!=s1[::-1]:print("YES");print(s1)
elif s2!=s2[::-1]:print("YES");print(s2)
else:print("NO")
``` | instruction | 0 | 39,859 | 18 | 79,718 |
Yes | output | 1 | 39,859 | 18 | 79,719 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
def pallindrome(strings):
i=0
j=len(s)-1
while(i<j):
if strings[i]!=strings[j]:
return False
else:
i+=1
j-=1
return True
t=int(input())
for _ in range(t):
s=str(input(""))
if s.count('a')==len(s):
print("NO")
else:
if pallindrome(s+'a')==False:
print("YES")
print(s+'a')
elif pallindrome('a'+ s)==False:
print("YES")
print('a'+ s)
``` | instruction | 0 | 39,860 | 18 | 79,720 |
No | output | 1 | 39,860 | 18 | 79,721 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
import collections
import string
import math
import copy
import os
import sys
from io import BytesIO, IOBase
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def input(): return sys.stdin.readline().rstrip("\r\n")
# n = 0
# m = 0
# n = int(input())
# li = [int(i) for i in input().split()]
# s = sorted(li)
"""
from dataclasses import dataclass
@dataclass
class point:
x: float
y: float
@dataclass
class line:
A: float
B: float
C: float
def gety(self, x):
return (self.A*x+self.C)/-self.B
def getx(self, y):
return (self.B*y+self.C)/-self.A
def k(self):
return -self.A/self.B
def b(self):
return -self.C/self.B
def dist(self, p: point):
return abs((self.A*p.x+self.B*p.y+self.C)/(self.A**2+self.B**2)**0.5)
def calc_line(u: point, v: point):
return line(A=u.y-v.y, B=v.x-u.x, C=u.y*(u.x-v.x)-u.x*(u.y-v.y))
def is_parallel(u: line, v: line) -> bool:
f1 = False
f2 = False
try:
k1 = u.k()
except:
f1 = True
try:
k2 = v.k()
except:
f2 = True
if f1 != f2:
return False
return f1 or k1 == k2
def seg_len(_from: point, _to: point):
return ((_from.x - _to.x)**2 + (_from.y - _to.y)**2) ** 0.5
def in_range(_from: point, _to: point, _point: point) -> bool:
if _from.x < _to.x:
if _from.y < _to.y:
return _from.x <= _point.x <= _to.x and _from.y <= _point.y <= _to.y
else:
return _from.x <= _point.x <= _to.x and _from.y >= _point.y >= _to.y
else:
if _from.y < _to.y:
return _from.x >= _point.x >= _to.x and _from.y <= _point.y <= _to.y
else:
return _from.x >= _point.x >= _to.x and _from.y >= _point.y >= _to.y
def intersect(u: line, v: line) -> point:
tx = (u.B*v.C-v.B*u.C)/(v.B*u.A-u.B*v.A)
if u.B!=0.0:
ty = -u.A*tx/u.B - u.C/u.B
else:
ty = -v.A*tx/v.B - v.C/v.B
return point(x=tx, y=ty)
def in_direction(_from: point, _to: point, _point: point) -> bool:
if _from.x < _to.x:
if _from.y < _to.y:
return _to.x < _point.x and _to.y < _point.y
else:
return _to.x < _point.x and _point.y <= _to.y
else:
if _from.y < _to.y:
return _to.x >= _point.x and _to.y < _point.y
else:
return _to.x >= _point.x and _point.y <= _to.y
"""
mo = int(1e9+7)
def exgcd(a, b):
if not b:
return 1, 0
y, x = exgcd(b, a % b)
y -= a//b * x
return x, y
def getinv(a, m):
x, y = exgcd(a, m)
return -1 if x == 1 else x % m
def comb(n, b):
res = 1
b = min(b, n-b)
for i in range(b):
res = res*(n-i)*getinv(i+1, mo) % mo
# res %= mo
return res % mo
def quickpower(a, n):
res = 1
while n:
if n & 1:
res = res * a % mo
n >>= 1
a = a*a % mo
return res
def dis(a, b):
return abs(a[0]-b[0]) + abs(a[1]-b[1])
def getpref(x):
if x > 1:
return (x)*(x-1) >> 1
else:
return 0
def orafli(upp):
primes = []
marked = [False for i in range(upp+3)]
prvs = [i for i in range(upp+3)]
for i in range(2, upp):
if not marked[i]:
primes.append(i)
for j in primes:
if i*j >= upp:
break
marked[i*j] = True
prvs[i*j] = j
if i % j == 0:
break
return primes, prvs
def lower_ord(c: str) -> int:
return ord(c)-97
def upper_ord(c: str) -> int:
return ord(c) - 65
def read_list():
return [int(i) for i in input().split()]
def read_int():
s = input().split()
if len(s) == 1:
return int(s[0])
else:
return map(int, s)
def ask(s):
print(f"? {s}", flush=True)
def answer(s):
print(f"{s}", flush=True)
def solve():
# n,m = read_int()
# n = read_int()
s = list(input())
flg = False
for p, i in enumerate(s[:(len(s)>>1)+1]):
if s[-p-1]!='a':
flg = True
s.insert(p,'a')
break
if flg:
print('YES')
print(''.join(s))
else:
print('NO')
# fi = open('C:\\cppHeaders\\CF2020.12.17\\test.data', 'r')
# def input(): return fi.readline().rstrip("\r\n")
# primes, prv = orafli(10001)
# solve()
t = int(input())
for ti in range(t):
# print(f"Case #{ti+1}: ", end='')
solve()
``` | instruction | 0 | 39,861 | 18 | 79,722 |
No | output | 1 | 39,861 | 18 | 79,723 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
import sys
#input = sys.stdin.readline
def palindrome(s):
for i in range(len(s)):
if s[i] != s[len(s) - i - 1]:
return True
return False
for test in range(int(input())):
s = input()[:-1]
if palindrome(s + "a"):
print("YES")
print(s + "a")
elif palindrome("a" + s):
print("YES")
print("a" + s)
else:
print("NO")
``` | instruction | 0 | 39,862 | 18 | 79,724 |
No | output | 1 | 39,862 | 18 | 79,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A palindrome is a string that reads the same backward as forward. For example, the strings "z", "aaa", "aba", and "abccba" are palindromes, but "codeforces" and "ab" are not. You hate palindromes because they give you déjà vu.
There is a string s. You must insert exactly one character 'a' somewhere in s. If it is possible to create a string that is not a palindrome, you should find one example. Otherwise, you should report that it is impossible.
For example, suppose s= "cbabc". By inserting an 'a', you can create "acbabc", "cababc", "cbaabc", "cbabac", or "cbabca". However "cbaabc" is a palindrome, so you must output one of the other options.
Input
The first line contains a single integer t (1≤ t≤ 10^4) — the number of test cases.
The only line of each test case contains a string s consisting of lowercase English letters.
The total length of all strings does not exceed 3⋅ 10^5.
Output
For each test case, if there is no solution, output "NO".
Otherwise, output "YES" followed by your constructed string of length |s|+1 on the next line. If there are multiple solutions, you may print any.
You can print each letter of "YES" and "NO" in any case (upper or lower).
Example
Input
6
cbabc
ab
zza
ba
a
nutforajaroftuna
Output
YES
cbabac
YES
aab
YES
zaza
YES
baa
NO
YES
nutforajarofatuna
Note
The first test case is described in the statement.
In the second test case, we can make either "aab" or "aba". But "aba" is a palindrome, so "aab" is the only correct answer.
In the third test case, "zaza" and "zzaa" are correct answers, but not "azza".
In the fourth test case, "baa" is the only correct answer.
In the fifth test case, we can only make "aa", which is a palindrome. So the answer is "NO".
In the sixth test case, "anutforajaroftuna" is a palindrome, but inserting 'a' elsewhere is valid.
Submitted Solution:
```
t = int(input())
for i in range(t):
st = input()
flag = 0
l = len(st)
for k in range(l):
if st[k] != 'a':
flag = 1
break
if flag == 0:
print("NO")
continue
for j in range(0, len(st)):
if l % 2 != 0:
if st[j] != 'a':
st = st[:l - j - 1] + 'a' + st[l - j - 1:]
break
else:
if st[j] != 'a':
st = st[:l - j] + 'a' + st[l - j:]
break
print("YES")
print(st)
``` | instruction | 0 | 39,863 | 18 | 79,726 |
No | output | 1 | 39,863 | 18 | 79,727 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
i = input()
l = len(i)
run = [0]*(l+1)
for a in range(1, l+1):
if i[a-1] in ['A', 'E', 'I', 'O', 'U', 'Y']:
run[a] = run[a-1] + 1
else:
run[a] = run[a-1]
tot = 0
fore = 0
for i in range(1, l+1):
fore -= 1/i
ey = [fore] + [0] * (l)
for i in range(1, l+1):
ey[i] = ey[i-1] + 1 / (l+1-i)+1/i
for i in range(1, l+1):
tot += ey[i] * run[i]
print(tot)
##god = {}
##god2 = {}
##for i in range(0, 15):
## god[i] = []
## god2[i] = []
##for i in range(1, l+1):
## for j in range(i, l+1):
## god[j].append("1/"+str(j-i+1))
## god[i-1].append("-1/"+str(j-i+1))
## god2[j].append(1/(j-i+1))
## god2[i-1].append(-1/(j-i+1))
## tot += (run[j]-run[i-1])/(j-i+1)
##print(tot)
``` | instruction | 0 | 39,989 | 18 | 79,978 |
Yes | output | 1 | 39,989 | 18 | 79,979 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
song = input()
le = len(song)
su = 0
for x in range(1,le+1):
su += 1/x
l = [0]*le
l[0] = su
diff = su
for x in range(1,int((le+1)/2)):
diff -= (1/x + 1/(le+1-x))
l[x] = l[x-1] + diff
for x in range(int((le+1)/2),le):
l[x] = l[le-1-x]
ans = 0
for x in range(le):
let = song[x]
if let in ['A','E','I','O','U','Y']:
ans += l[x]
print(ans)
``` | instruction | 0 | 39,990 | 18 | 79,980 |
Yes | output | 1 | 39,990 | 18 | 79,981 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
__author__ = 'PrimuS'
s = input()
n = len(s)
a = [0] * n
ps = [0] * n
for i in range(n):
if s[i] in "IEAOUY":
a[i] = 1
ps[0] = a[0]
for i in range(1, n):
ps[i] = ps[i-1] + a[i]
import math
up = math.ceil((n - 1) / 2)
ss = [0] * up
prev = 0
for i in range(up):
ss[i] = (a[i] + a[n - i-1]) * (i + 1)
if i == n - i - 1:
ss[i] /= 2
ss[i] += prev
prev = ss[i]
res = 0
x = 0
res = ps[n-1]
for i in range(2, n):
k = n - i + 1
cur = 0
if k < i:
cur += (ps[n - k] - ps[k-2]) * k
cur += ss[k-2]
else:
cur += (ps[n - i] - ps[i-2]) * i
cur += ss[i-2]
res += cur / i
if n > 1:
res += ps[n-1] / n
print(res)
``` | instruction | 0 | 39,991 | 18 | 79,982 |
Yes | output | 1 | 39,991 | 18 | 79,983 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
word = input()
n = len(word)
def vowel(x):
if x in ["A","E","I","O","U","Y"]:
return 1
else:
return 0
sums = [0]*n
sums[n-1] = 1/n
for k in range(n-2,-1,-1):
sums[k] = sums[k+1]+(1/(k+1))
def numb(k):
if k <= (n+1)//2:
return (k+1)*(sums[k+1]-sums[n-k-1]) + (n+1)*sums[n-k-1]
else:
return numb(n-k-1)
res = 0
if n == 1:
res = vowel(word[0])
elif n == 2:
res = (vowel(word[0])+vowel(word[1]))*3/2
elif n == 3:
res = (vowel(word[0])+vowel(word[2]))*(1+1/2+1/3) + 7/3*vowel(word[1])
else:
for k in range(n):
res += vowel(word[k])*numb(k)
print("%.7f" % res)
``` | instruction | 0 | 39,992 | 18 | 79,984 |
Yes | output | 1 | 39,992 | 18 | 79,985 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
i = input()
l = len(i)
run = [0]*(l+1)
for a in range(1, l+1):
if i[a-1] in ['A', 'E', 'I', 'O', 'U', 'Y']:
run[a] = run[a-1] + 1
else:
run[a] = run[a-1]
tot = 0
for i in range(1, l+1):
for j in range(i, l+1):
tot += (run[j]-run[i-1])/(j-i+1)
``` | instruction | 0 | 39,993 | 18 | 79,986 |
No | output | 1 | 39,993 | 18 | 79,987 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
'''
Created on Jan 31, 2015
@author: Cristina
'''
import sys
def vowel(c):
l="AEIOUY"
for i in range(0,len(l)):
if (c==l[i]):
return 1
return 0
def simple(s):
vocale=0
litere=0
for i in range (0,len(s)):
if (vowel(s[i])):
vocale+=1
litere+=1
return vocale/litere
def main():
x=input()
sum=0
for i in range (0,len(x)):
s=[]
for j in range (i,len(x)):
s.append(x[j])
if(len(s)==1 and vowel(s[0])==1):
sum=sum + 1
elif (len(s)==1 and vowel(s[0])==0):
sum = sum + 0.5
else:
sum=sum+simple(s)
print(sum)
main()
``` | instruction | 0 | 39,994 | 18 | 79,988 |
No | output | 1 | 39,994 | 18 | 79,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
s=input()
x=len(s)
l=[]
l2=[]
alpha="AEIOUY"
for i in range(0,int(x/2)):
if s[i] in alpha:
l.append(i+1)
for j in range(int(x/2),x):
if s[j] in alpha:
l.append(x-j)
for j in range(0,int(x/2)):
ans=0
for k in range(0,len(l)):
ans+=min(j+1,l[k])
l2.append(ans)
ans=0
for i in range(0,int(x/2)):
ans+=(l2[i])/(i+1)+(l2[i])/(x-i)
if x%2==1:
x=int(x/2)+1
ans+=l2[-1]/x
print(ans)
``` | instruction | 0 | 39,995 | 18 | 79,990 |
No | output | 1 | 39,995 | 18 | 79,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
When Sasha was studying in the seventh grade, he started listening to music a lot. In order to evaluate which songs he likes more, he introduced the notion of the song's prettiness. The title of the song is a word consisting of uppercase Latin letters. The prettiness of the song is the prettiness of its title.
Let's define the simple prettiness of a word as the ratio of the number of vowels in the word to the number of all letters in the word.
Let's define the prettiness of a word as the sum of simple prettiness of all the substrings of the word.
More formally, let's define the function vowel(c) which is equal to 1, if c is a vowel, and to 0 otherwise. Let si be the i-th character of string s, and si..j be the substring of word s, staring at the i-th character and ending at the j-th character (sisi + 1... sj, i ≤ j).
Then the simple prettiness of s is defined by the formula:
<image>
The prettiness of s equals
<image>
Find the prettiness of the given song title.
We assume that the vowels are I, E, A, O, U, Y.
Input
The input contains a single string s (1 ≤ |s| ≤ 5·105) — the title of the song.
Output
Print the prettiness of the song with the absolute or relative error of at most 10 - 6.
Examples
Input
IEAIAIO
Output
28.0000000
Input
BYOB
Output
5.8333333
Input
YISVOWEL
Output
17.0500000
Note
In the first sample all letters are vowels. The simple prettiness of each substring is 1. The word of length 7 has 28 substrings. So, the prettiness of the song equals to 28.
Submitted Solution:
```
arr = []
for i in input():
arr.append(i)
n = len(arr)
res = 0
add = [0] * (n + 1)
add[n] = 1 / n
for i in range(n - 1, 0, -1):
add[i] = add[i + 1] + 1 / i
print(add)
for i in range(n):
if arr[i] in ['I', 'E', 'A', 'O', 'U', 'Y']:
x = min(i, n - i - 1)
y = max(i, n - i - 1)
res += x + 1
res += (x + 1) * (add[x + 2] - add[y + 1])
res += (n + 1) * add[y + 1] - (n - y)
print(res)
``` | instruction | 0 | 39,996 | 18 | 79,992 |
No | output | 1 | 39,996 | 18 | 79,993 |
Provide a correct Python 3 solution for this coding contest problem.
There is a game that involves three variables, denoted A, B, and C.
As the game progresses, there will be N events where you are asked to make a choice. Each of these choices is represented by a string s_i. If s_i is `AB`, you must add 1 to A or B then subtract 1 from the other; if s_i is `AC`, you must add 1 to A or C then subtract 1 from the other; if s_i is `BC`, you must add 1 to B or C then subtract 1 from the other.
After each choice, none of A, B, and C should be negative.
Determine whether it is possible to make N choices under this condition. If it is possible, also give one such way to make the choices.
Constraints
* 1 \leq N \leq 10^5
* 0 \leq A,B,C \leq 10^9
* N, A, B, C are integers.
* s_i is `AB`, `AC`, or `BC`.
Input
Input is given from Standard Input in the following format:
N A B C
s_1
s_2
:
s_N
Output
If it is possible to make N choices under the condition, print `Yes`; otherwise, print `No`.
Also, in the former case, show one such way to make the choices in the subsequent N lines. The (i+1)-th line should contain the name of the variable (`A`, `B`, or `C`) to which you add 1 in the i-th choice.
Examples
Input
2 1 3 0
AB
AC
Output
Yes
A
C
Input
3 1 0 0
AB
BC
AB
Output
No
Input
1 0 9 0
AC
Output
No
Input
8 6 9 1
AC
BC
AB
BC
AC
BC
AB
AB
Output
Yes
C
B
B
C
C
B
A
A | instruction | 0 | 40,194 | 18 | 80,388 |
"Correct Solution:
```
import sys
readline = sys.stdin.readline
N,A,B,C = map(int,readline().split())
val = [A,B,C]
# 0,0を作ってはいけない
# 基本的には小さいほうに1を足す
# 両方とも1の場合は、次の操作で選ばれるほうに1を足す
# 両方とも次の操作で選ばれるときはどちらに足してもよい
S = [readline().rstrip() for i in range(N)]
ans = []
def get_ind(s):
res = []
for c in s:
if c == "A":
res.append(0)
elif c == "B":
res.append(1)
elif c == "C":
res.append(2)
return res
def get_alpha(x):
return "ABC"[x]
for i in range(N):
ind_x,ind_y = get_ind(S[i])
if val[ind_x] == 0 and val[ind_y] == 0:
print("No")
exit(0)
if val[ind_x] < val[ind_y]:
ans += [get_alpha(ind_x)]
val[ind_x] += 1
val[ind_y] -= 1
elif val[ind_x] > val[ind_y]:
ans += [get_alpha(ind_y)]
val[ind_y] += 1
val[ind_x] -= 1
else:
if i + 1 < N and get_alpha(ind_x) in S[i + 1]:
ans += [get_alpha(ind_x)]
val[ind_x] += 1
val[ind_y] -= 1
else:
ans += [get_alpha(ind_y)]
val[ind_y] += 1
val[ind_x] -= 1
print("Yes")
for a in ans:
print(a)
``` | output | 1 | 40,194 | 18 | 80,389 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,278 | 18 | 80,556 |
"Correct Solution:
```
s1 = input()
s2 = input()
s2 = s2[::-1]
print('YES' if s1 == s2 else 'NO')
``` | output | 1 | 40,278 | 18 | 80,557 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,279 | 18 | 80,558 |
"Correct Solution:
```
A = input()
B = input()
print ("YES" if A == B[-1::-1] else "NO")
``` | output | 1 | 40,279 | 18 | 80,559 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,280 | 18 | 80,560 |
"Correct Solution:
```
print("YES" if input()[::-1] == input() else "NO")
``` | output | 1 | 40,280 | 18 | 80,561 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,281 | 18 | 80,562 |
"Correct Solution:
```
a = input()
b = input()
if a[::-1]==b:
print('YES')
else:
print('NO')
``` | output | 1 | 40,281 | 18 | 80,563 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,282 | 18 | 80,564 |
"Correct Solution:
```
C1, C2 = [input() for i in range(2)]
print('YES' if C1 == C2[::-1] else 'NO')
``` | output | 1 | 40,282 | 18 | 80,565 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,283 | 18 | 80,566 |
"Correct Solution:
```
s1 = input()
s2 = input()
print('YES' if s1 == s2[::-1] else 'NO')
``` | output | 1 | 40,283 | 18 | 80,567 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,284 | 18 | 80,568 |
"Correct Solution:
```
s=input()
t=input()
print('YNEOS'[s[::-1]!=t::2])
``` | output | 1 | 40,284 | 18 | 80,569 |
Provide a correct Python 3 solution for this coding contest problem.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO | instruction | 0 | 40,285 | 18 | 80,570 |
"Correct Solution:
```
if input() == input()[::-1]:
print('YES')
else:
print('NO')
``` | output | 1 | 40,285 | 18 | 80,571 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
S=list(input())
T=list(reversed(input()))
print(["NO","YES"][S==T])
``` | instruction | 0 | 40,286 | 18 | 80,572 |
Yes | output | 1 | 40,286 | 18 | 80,573 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
a=input()[::-1]
print('YES' if input()==a else 'NO')
``` | instruction | 0 | 40,287 | 18 | 80,574 |
Yes | output | 1 | 40,287 | 18 | 80,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
a = input()
b = input()
if b == a[::-1]:
print("YES")
else:
print("NO")
``` | instruction | 0 | 40,288 | 18 | 80,576 |
Yes | output | 1 | 40,288 | 18 | 80,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
print(["NO","YES"][int(input()==input()[::-1])])
``` | instruction | 0 | 40,289 | 18 | 80,578 |
Yes | output | 1 | 40,289 | 18 | 80,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
s = input()
t = reversed(input())
if(s == t):
print("YES")
else:
print("NO")
``` | instruction | 0 | 40,290 | 18 | 80,580 |
No | output | 1 | 40,290 | 18 | 80,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
A = input()
B = input()
if A == B[::-1]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 40,292 | 18 | 80,584 |
No | output | 1 | 40,292 | 18 | 80,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a grid with 2 rows and 3 columns of squares. The color of the square at the i-th row and j-th column is represented by the character C_{ij}.
Write a program that prints `YES` if this grid remains the same when rotated 180 degrees, and prints `NO` otherwise.
Constraints
* C_{i,j}(1 \leq i \leq 2, 1 \leq j \leq 3) is a lowercase English letter.
Input
Input is given from Standard Input in the following format:
C_{11}C_{12}C_{13}
C_{21}C_{22}C_{23}
Output
Print `YES` if this grid remains the same when rotated 180 degrees; print `NO` otherwise.
Examples
Input
pot
top
Output
YES
Input
tab
bet
Output
NO
Input
eye
eel
Output
NO
Submitted Solution:
```
c11,c12,c13 =map(str,input().split())
c21,c22,c23 =map(str,input().split())
if c11==c23 and c12==c22 and c13==c21:
print("YES")
else:
print("NO")
``` | instruction | 0 | 40,293 | 18 | 80,586 |
No | output | 1 | 40,293 | 18 | 80,587 |
Provide a correct Python 3 solution for this coding contest problem.
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.
To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:
* The `0` key: a letter `0` will be inserted to the right of the string.
* The `1` key: a letter `1` will be inserted to the right of the string.
* The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.
Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?
Constraints
* 1 ≦ |s| ≦ 10 (|s| denotes the length of s)
* s consists of the letters `0`, `1` and `B`.
* The correct answer is not an empty string.
Input
The input is given from Standard Input in the following format:
s
Output
Print the string displayed in the editor in the end.
Examples
Input
01B0
Output
00
Input
0BB1
Output
1 | instruction | 0 | 40,326 | 18 | 80,652 |
"Correct Solution:
```
import re
s = input()
for _ in range(s.count('B')):
s = re.sub('.?B', '', s, 1)
print(s)
``` | output | 1 | 40,326 | 18 | 80,653 |
Provide a correct Python 3 solution for this coding contest problem.
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.
To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:
* The `0` key: a letter `0` will be inserted to the right of the string.
* The `1` key: a letter `1` will be inserted to the right of the string.
* The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.
Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?
Constraints
* 1 ≦ |s| ≦ 10 (|s| denotes the length of s)
* s consists of the letters `0`, `1` and `B`.
* The correct answer is not an empty string.
Input
The input is given from Standard Input in the following format:
s
Output
Print the string displayed in the editor in the end.
Examples
Input
01B0
Output
00
Input
0BB1
Output
1 | instruction | 0 | 40,327 | 18 | 80,654 |
"Correct Solution:
```
s = input()
ans = ''
for _ in s:
if _ == 'B':
ans = ans[:-1]
else:
ans += _
print(ans)
``` | output | 1 | 40,327 | 18 | 80,655 |
Provide a correct Python 3 solution for this coding contest problem.
Sig has built his own keyboard. Designed for ultimate simplicity, this keyboard only has 3 keys on it: the `0` key, the `1` key and the backspace key.
To begin with, he is using a plain text editor with this keyboard. This editor always displays one string (possibly empty). Just after the editor is launched, this string is empty. When each key on the keyboard is pressed, the following changes occur to the string:
* The `0` key: a letter `0` will be inserted to the right of the string.
* The `1` key: a letter `1` will be inserted to the right of the string.
* The backspace key: if the string is empty, nothing happens. Otherwise, the rightmost letter of the string is deleted.
Sig has launched the editor, and pressed these keys several times. You are given a string s, which is a record of his keystrokes in order. In this string, the letter `0` stands for the `0` key, the letter `1` stands for the `1` key and the letter `B` stands for the backspace key. What string is displayed in the editor now?
Constraints
* 1 ≦ |s| ≦ 10 (|s| denotes the length of s)
* s consists of the letters `0`, `1` and `B`.
* The correct answer is not an empty string.
Input
The input is given from Standard Input in the following format:
s
Output
Print the string displayed in the editor in the end.
Examples
Input
01B0
Output
00
Input
0BB1
Output
1 | instruction | 0 | 40,328 | 18 | 80,656 |
"Correct Solution:
```
s = input()
a = ''
for _ in s:
if _ == 'B':
a = a[:-1]
else:
a += _
print(a)
``` | output | 1 | 40,328 | 18 | 80,657 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.