message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Provide a correct Python 3 solution for this coding contest problem.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0 | instruction | 0 | 84,825 | 18 | 169,650 |
"Correct Solution:
```
S=input()
T=input()
c=0
for s,t in zip(S,T):
if s==t:
c+=1
print(c)
``` | output | 1 | 84,825 | 18 | 169,651 |
Provide a correct Python 3 solution for this coding contest problem.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0 | instruction | 0 | 84,826 | 18 | 169,652 |
"Correct Solution:
```
s1=input()
s2=input()
print(sum(s1[i]==s2[i] for i in range(len(s1))))
``` | output | 1 | 84,826 | 18 | 169,653 |
Provide a correct Python 3 solution for this coding contest problem.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0 | instruction | 0 | 84,827 | 18 | 169,654 |
"Correct Solution:
```
print(3-sum(i!=j for i,j in zip(*open(0))))
``` | output | 1 | 84,827 | 18 | 169,655 |
Provide a correct Python 3 solution for this coding contest problem.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0 | instruction | 0 | 84,828 | 18 | 169,656 |
"Correct Solution:
```
s=input()
t=input()
print(sum([s[i]==t[i] for i in range(3)]))
``` | output | 1 | 84,828 | 18 | 169,657 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
s = input()
t = input()
print(len([v for i,v in enumerate(s) if (t[i] == v)]))
``` | instruction | 0 | 84,829 | 18 | 169,658 |
Yes | output | 1 | 84,829 | 18 | 169,659 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
a,b = input(),input()
c = 0
for i in[0,1,2]:
c = c + int(a[i] == b[i])
print(c)
``` | instruction | 0 | 84,830 | 18 | 169,660 |
Yes | output | 1 | 84,830 | 18 | 169,661 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
print(sum(x==y for x,y in zip(input(),input())))
``` | instruction | 0 | 84,831 | 18 | 169,662 |
Yes | output | 1 | 84,831 | 18 | 169,663 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
s = input()
t = input()
a=0
a+=(s[0]==t[0])+(s[1]==t[1])+(s[2]==t[2])
print(a)
``` | instruction | 0 | 84,832 | 18 | 169,664 |
Yes | output | 1 | 84,832 | 18 | 169,665 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
#Tenki
S = input()
T = input()
ctr = 0
for i in range(len(S)):
if S[i] == T[i]:
ctr = ctr+1
``` | instruction | 0 | 84,833 | 18 | 169,666 |
No | output | 1 | 84,833 | 18 | 169,667 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
s = input()
t = input()
x = 0
for i in 3:
x += s[i-1]!=t[i-1]
print(x)
``` | instruction | 0 | 84,834 | 18 | 169,668 |
No | output | 1 | 84,834 | 18 | 169,669 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
N = int(input())
A=[int(_) for _ in input().split()]
Maxcounter = 0
for i in range(1,N):
counter = 0
k = i
while k < N:
if (A[k-1]>=A[k]):
counter += 1
k += 1
if Maxcounter <= counter:
Maxcounter = counter
else:
break
print(Maxcounter)
``` | instruction | 0 | 84,835 | 18 | 169,670 |
No | output | 1 | 84,835 | 18 | 169,671 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You will be given a string S of length 3 representing the weather forecast for three days in the past.
The i-th character (1 \leq i \leq 3) of S represents the forecast for the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
You will also be given a string T of length 3 representing the actual weather on those three days.
The i-th character (1 \leq i \leq 3) of S represents the actual weather on the i-th day. `S`, `C`, and `R` stand for sunny, cloudy, and rainy, respectively.
Print the number of days for which the forecast was correct.
Constraints
* S and T are strings of length 3 each.
* S and T consist of `S`, `C`, and `R`.
Input
Input is given from Standard Input in the following format:
S
T
Output
Print the number of days for which the forecast was correct.
Examples
Input
CSS
CSR
Output
2
Input
SSR
SSR
Output
3
Input
RRR
SSS
Output
0
Submitted Solution:
```
n = int(input())
h = list(map(int,input().split()))
ans = 0
ls = []
for i in range(n-1):
if h[i] >= h[i+1]:
ans += 1
else:
ls.append(ans)
ans = 0
ls.append(ans)
print(max(ls))
``` | instruction | 0 | 84,836 | 18 | 169,672 |
No | output | 1 | 84,836 | 18 | 169,673 |
Provide a correct Python 3 solution for this coding contest problem.
Sunuke-kun's dictionary contains the words s1, ..., sn, which consist of n lowercase letters. This satisfies s1 <... <sn when compared in lexicographical order. Unfortunately, some characters are faint and unreadable. Unreadable characters are represented by?. Find out how many ways to restore the dictionary by replacing? With lowercase letters, even with mod 1,000,000,007.
Constraints
* 1 ≤ n ≤ 50
* 1 ≤ | si | ≤ 20
* The characters that appear in si are lowercase letters or?
Input
n
s1
.. ..
sn
Output
Print the answer on one line.
Examples
Input
2
?sum??mer
c??a??mp
Output
703286064
Input
3
snuje
????e
snule
Output
1 | instruction | 0 | 84,973 | 18 | 169,946 |
"Correct Solution:
```
# seishin.py
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
MOD = 10**9 + 7
N = int(readline())
M = 20
L = 26
ca = ord('a')
cq = ord('?')
S = [[ca-1]*M for i in range(N)]
for i in range(N):
s = readline().strip()
S[i][:len(s)] = map(ord, s)
memo = [[[[-1]*(L+2) for i in range(M+1)] for j in range(N+1)] for k in range(N+1)]
for i in range(N+1):
for p in range(M+1):
for c in range(L+2):
memo[i][i][p][c] = 1
for i in range(N+1):
for j in range(i+1, N+1):
for p in range(M+1):
memo[i][j][p][L+1] = 0
for c in range(L+2):
memo[i][j][M][c] = (i+1 == j)
def dfs(l, r, p, c):
if memo[l][r][p][c] != -1:
return memo[l][r][p][c]
res = dfs(l, r, p, c+1)
for i in range(l+1, r+1):
if (S[i-1][p] != ca + c - 1) if S[i-1][p] != cq else (c == 0):
break
res += dfs(l, i, p+1, 0) * dfs(i, r, p, c+1) % MOD
memo[l][r][p][c] = res = res % MOD
return res
write("%d\n" % dfs(0, N, 0, 0))
solve()
``` | output | 1 | 84,973 | 18 | 169,947 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iahubina is tired of so many complicated languages, so she decided to invent a new, simple language. She already made a dictionary consisting of n 3-words. A 3-word is a sequence of exactly 3 lowercase letters of the first 24 letters of the English alphabet (a to x). She decided that some of the letters are vowels, and all the others are consonants. The whole language is based on a simple rule: any word that contains at least one vowel is correct.
Iahubina forgot which letters are the vowels, and wants to find some possible correct sets of vowels. She asks Iahub questions. In each question, she will give Iahub a set of letters considered vowels (in this question). For each question she wants to know how many words of the dictionary are correct, considering the given set of vowels.
Iahubina wants to know the xor of the squared answers to all the possible questions. There are 224 different questions, they are all subsets of the set of the first 24 letters of the English alphabet. Help Iahub find that number.
Input
The first line contains one integer, n (1 ≤ n ≤ 104). Each of the next n lines contains a 3-word consisting of 3 lowercase letters. There will be no two identical 3-words.
Output
Print one number, the xor of the squared answers to the queries.
Examples
Input
5
abc
aaa
ada
bcd
def
Output
0
Submitted Solution:
```
print(0)
``` | instruction | 0 | 85,300 | 18 | 170,600 |
No | output | 1 | 85,300 | 18 | 170,601 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iahubina is tired of so many complicated languages, so she decided to invent a new, simple language. She already made a dictionary consisting of n 3-words. A 3-word is a sequence of exactly 3 lowercase letters of the first 24 letters of the English alphabet (a to x). She decided that some of the letters are vowels, and all the others are consonants. The whole language is based on a simple rule: any word that contains at least one vowel is correct.
Iahubina forgot which letters are the vowels, and wants to find some possible correct sets of vowels. She asks Iahub questions. In each question, she will give Iahub a set of letters considered vowels (in this question). For each question she wants to know how many words of the dictionary are correct, considering the given set of vowels.
Iahubina wants to know the xor of the squared answers to all the possible questions. There are 224 different questions, they are all subsets of the set of the first 24 letters of the English alphabet. Help Iahub find that number.
Input
The first line contains one integer, n (1 ≤ n ≤ 104). Each of the next n lines contains a 3-word consisting of 3 lowercase letters. There will be no two identical 3-words.
Output
Print one number, the xor of the squared answers to the queries.
Examples
Input
5
abc
aaa
ada
bcd
def
Output
0
Submitted Solution:
```
import collections, functools
M = 10
n = int(input())
f = collections.defaultdict(int)
for _ in range(n):
f[functools.reduce(lambda x, y: x | y, [1<<(ord(x)-ord('a')) for x in input()])] += 1
ans = 0
for i in range(M):
for mask in range(1<<M):
if(mask & (1<<i)):
f[mask] += f[mask^(1<<i)];
for mask in range(1<<M):
ans ^= (n-f[mask])*(n-f[mask])
print(ans)
``` | instruction | 0 | 85,301 | 18 | 170,602 |
No | output | 1 | 85,301 | 18 | 170,603 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Iahubina is tired of so many complicated languages, so she decided to invent a new, simple language. She already made a dictionary consisting of n 3-words. A 3-word is a sequence of exactly 3 lowercase letters of the first 24 letters of the English alphabet (a to x). She decided that some of the letters are vowels, and all the others are consonants. The whole language is based on a simple rule: any word that contains at least one vowel is correct.
Iahubina forgot which letters are the vowels, and wants to find some possible correct sets of vowels. She asks Iahub questions. In each question, she will give Iahub a set of letters considered vowels (in this question). For each question she wants to know how many words of the dictionary are correct, considering the given set of vowels.
Iahubina wants to know the xor of the squared answers to all the possible questions. There are 224 different questions, they are all subsets of the set of the first 24 letters of the English alphabet. Help Iahub find that number.
Input
The first line contains one integer, n (1 ≤ n ≤ 104). Each of the next n lines contains a 3-word consisting of 3 lowercase letters. There will be no two identical 3-words.
Output
Print one number, the xor of the squared answers to the queries.
Examples
Input
5
abc
aaa
ada
bcd
def
Output
0
Submitted Solution:
```
def main():
n=raw_input("enter string: ")
print("answer is,n")
main()
``` | instruction | 0 | 85,302 | 18 | 170,604 |
No | output | 1 | 85,302 | 18 | 170,605 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokenty is a president of a new football league in Byteland. The first task he should do is to assign short names to all clubs to be shown on TV next to the score. Of course, the short names should be distinct, and Innokenty wants that all short names consist of three letters.
Each club's full name consist of two words: the team's name and the hometown's name, for example, "DINAMO BYTECITY". Innokenty doesn't want to assign strange short names, so he wants to choose such short names for each club that:
1. the short name is the same as three first letters of the team's name, for example, for the mentioned club it is "DIN",
2. or, the first two letters of the short name should be the same as the first two letters of the team's name, while the third letter is the same as the first letter in the hometown's name. For the mentioned club it is "DIB".
Apart from this, there is a rule that if for some club x the second option of short name is chosen, then there should be no club, for which the first option is chosen which is the same as the first option for the club x. For example, if the above mentioned club has short name "DIB", then no club for which the first option is chosen can have short name equal to "DIN". However, it is possible that some club have short name "DIN", where "DI" are the first two letters of the team's name, and "N" is the first letter of hometown's name. Of course, no two teams can have the same short name.
Help Innokenty to choose a short name for each of the teams. If this is impossible, report that. If there are multiple answer, any of them will suit Innokenty. If for some team the two options of short name are equal, then Innokenty will formally think that only one of these options is chosen.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of clubs in the league.
Each of the next n lines contains two words — the team's name and the hometown's name for some club. Both team's name and hometown's name consist of uppercase English letters and have length at least 3 and at most 20.
Output
It it is not possible to choose short names and satisfy all constraints, print a single line "NO".
Otherwise, in the first line print "YES". Then print n lines, in each line print the chosen short name for the corresponding club. Print the clubs in the same order as they appeared in input.
If there are multiple answers, print any of them.
Examples
Input
2
DINAMO BYTECITY
FOOTBALL MOSCOW
Output
YES
DIN
FOO
Input
2
DINAMO BYTECITY
DINAMO BITECITY
Output
NO
Input
3
PLAYFOOTBALL MOSCOW
PLAYVOLLEYBALL SPB
GOGO TECHNOCUP
Output
YES
PLM
PLS
GOG
Input
3
ABC DEF
ABC EFG
ABD OOO
Output
YES
ABD
ABE
ABO
Note
In the first sample Innokenty can choose first option for both clubs.
In the second example it is not possible to choose short names, because it is not possible that one club has first option, and the other has second option if the first options are equal for both clubs.
In the third example Innokenty can choose the second options for the first two clubs, and the first option for the third club.
In the fourth example note that it is possible that the chosen short name for some club x is the same as the first option of another club y if the first options of x and y are different.
Submitted Solution:
```
n=int(input())
a=set();b=set();c=[]
for i in range(n):
x,y=input().split()
x=x[:3];y=x[:2]+y[0]
if (x,y) in b or (x in c and y in a):exit(print("NO"))
b.add((x,y))
if b in a and x not in c:
a.add(x)
else:
a.add(y)
c.append(y)
print("YES")
print('\n'.join(c))
``` | instruction | 0 | 85,421 | 18 | 170,842 |
No | output | 1 | 85,421 | 18 | 170,843 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokenty is a president of a new football league in Byteland. The first task he should do is to assign short names to all clubs to be shown on TV next to the score. Of course, the short names should be distinct, and Innokenty wants that all short names consist of three letters.
Each club's full name consist of two words: the team's name and the hometown's name, for example, "DINAMO BYTECITY". Innokenty doesn't want to assign strange short names, so he wants to choose such short names for each club that:
1. the short name is the same as three first letters of the team's name, for example, for the mentioned club it is "DIN",
2. or, the first two letters of the short name should be the same as the first two letters of the team's name, while the third letter is the same as the first letter in the hometown's name. For the mentioned club it is "DIB".
Apart from this, there is a rule that if for some club x the second option of short name is chosen, then there should be no club, for which the first option is chosen which is the same as the first option for the club x. For example, if the above mentioned club has short name "DIB", then no club for which the first option is chosen can have short name equal to "DIN". However, it is possible that some club have short name "DIN", where "DI" are the first two letters of the team's name, and "N" is the first letter of hometown's name. Of course, no two teams can have the same short name.
Help Innokenty to choose a short name for each of the teams. If this is impossible, report that. If there are multiple answer, any of them will suit Innokenty. If for some team the two options of short name are equal, then Innokenty will formally think that only one of these options is chosen.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of clubs in the league.
Each of the next n lines contains two words — the team's name and the hometown's name for some club. Both team's name and hometown's name consist of uppercase English letters and have length at least 3 and at most 20.
Output
It it is not possible to choose short names and satisfy all constraints, print a single line "NO".
Otherwise, in the first line print "YES". Then print n lines, in each line print the chosen short name for the corresponding club. Print the clubs in the same order as they appeared in input.
If there are multiple answers, print any of them.
Examples
Input
2
DINAMO BYTECITY
FOOTBALL MOSCOW
Output
YES
DIN
FOO
Input
2
DINAMO BYTECITY
DINAMO BITECITY
Output
NO
Input
3
PLAYFOOTBALL MOSCOW
PLAYVOLLEYBALL SPB
GOGO TECHNOCUP
Output
YES
PLM
PLS
GOG
Input
3
ABC DEF
ABC EFG
ABD OOO
Output
YES
ABD
ABE
ABO
Note
In the first sample Innokenty can choose first option for both clubs.
In the second example it is not possible to choose short names, because it is not possible that one club has first option, and the other has second option if the first options are equal for both clubs.
In the third example Innokenty can choose the second options for the first two clubs, and the first option for the third club.
In the fourth example note that it is possible that the chosen short name for some club x is the same as the first option of another club y if the first options of x and y are different.
Submitted Solution:
```
n=int(input())
dic=dict()
t=[0]*n
for i in range(65,91):
for j in range(65,91):
dic[chr(i)+chr(j)]=[]
for i in range(n):
a,b=input().split()
dic[a[:2]].append([a,b,i])
for i in range(65,91):
for j in range(65,91):
dicl=dic[chr(i)+chr(j)]
if dicl==[]:continue
dicl.sort(key=lambda x:x[:])
for k in dicl:
x=k[0][:2];y=k[0][2];z=k[1][0];w=k[2]
if len(dicl)==1:t[w]=x+y
else:t[w]=x+z
if len(t)!=len(set(t)):print("NO")
else:print("YES");print('\n'.join(t))
``` | instruction | 0 | 85,422 | 18 | 170,844 |
No | output | 1 | 85,422 | 18 | 170,845 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokenty is a president of a new football league in Byteland. The first task he should do is to assign short names to all clubs to be shown on TV next to the score. Of course, the short names should be distinct, and Innokenty wants that all short names consist of three letters.
Each club's full name consist of two words: the team's name and the hometown's name, for example, "DINAMO BYTECITY". Innokenty doesn't want to assign strange short names, so he wants to choose such short names for each club that:
1. the short name is the same as three first letters of the team's name, for example, for the mentioned club it is "DIN",
2. or, the first two letters of the short name should be the same as the first two letters of the team's name, while the third letter is the same as the first letter in the hometown's name. For the mentioned club it is "DIB".
Apart from this, there is a rule that if for some club x the second option of short name is chosen, then there should be no club, for which the first option is chosen which is the same as the first option for the club x. For example, if the above mentioned club has short name "DIB", then no club for which the first option is chosen can have short name equal to "DIN". However, it is possible that some club have short name "DIN", where "DI" are the first two letters of the team's name, and "N" is the first letter of hometown's name. Of course, no two teams can have the same short name.
Help Innokenty to choose a short name for each of the teams. If this is impossible, report that. If there are multiple answer, any of them will suit Innokenty. If for some team the two options of short name are equal, then Innokenty will formally think that only one of these options is chosen.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of clubs in the league.
Each of the next n lines contains two words — the team's name and the hometown's name for some club. Both team's name and hometown's name consist of uppercase English letters and have length at least 3 and at most 20.
Output
It it is not possible to choose short names and satisfy all constraints, print a single line "NO".
Otherwise, in the first line print "YES". Then print n lines, in each line print the chosen short name for the corresponding club. Print the clubs in the same order as they appeared in input.
If there are multiple answers, print any of them.
Examples
Input
2
DINAMO BYTECITY
FOOTBALL MOSCOW
Output
YES
DIN
FOO
Input
2
DINAMO BYTECITY
DINAMO BITECITY
Output
NO
Input
3
PLAYFOOTBALL MOSCOW
PLAYVOLLEYBALL SPB
GOGO TECHNOCUP
Output
YES
PLM
PLS
GOG
Input
3
ABC DEF
ABC EFG
ABD OOO
Output
YES
ABD
ABE
ABO
Note
In the first sample Innokenty can choose first option for both clubs.
In the second example it is not possible to choose short names, because it is not possible that one club has first option, and the other has second option if the first options are equal for both clubs.
In the third example Innokenty can choose the second options for the first two clubs, and the first option for the third club.
In the fourth example note that it is possible that the chosen short name for some club x is the same as the first option of another club y if the first options of x and y are different.
Submitted Solution:
```
n = int(input())
mas = [['', '']]
mat = [[] for i in range(n)]
for i in range(n):
k = input().split()
s1, s2 = k[0], k[1]
s1 = s1[0 : 3]
s2 = s2[0]
mas.append([s1, s2, i])
ch = -1
mas.sort()
for i in range(1, n + 1):
if mas[i][0] == mas[i - 1][0]:
mat[ch].append(mas[i])
else:
ch += 1
mat[ch].append(mas[i])
f = 0
while mat[-1] == []:
mat.pop(-1)
#for i in mat:
# print(i)
for i in range(len(mat)):
mat[i].sort()
for j in range(1, len(mat[i])):
if mat[i][j][0 : 2] == mat[i][j - 1][0 : 2]:
f = 1
break
if f:
print('NO')
break
ans = [0 for i in range(n)]
if not f:
for i in range(len(mat)):
if len(mat[i]) == 1:
ans[mat[i][0][-1]] = mat[i][0][0]
else:
for j in mat[i]:
ans[j[-1]] = j[0][0 : 2] + j[1]
print('YES')
for i in ans:
print(i)
``` | instruction | 0 | 85,423 | 18 | 170,846 |
No | output | 1 | 85,423 | 18 | 170,847 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokenty is a president of a new football league in Byteland. The first task he should do is to assign short names to all clubs to be shown on TV next to the score. Of course, the short names should be distinct, and Innokenty wants that all short names consist of three letters.
Each club's full name consist of two words: the team's name and the hometown's name, for example, "DINAMO BYTECITY". Innokenty doesn't want to assign strange short names, so he wants to choose such short names for each club that:
1. the short name is the same as three first letters of the team's name, for example, for the mentioned club it is "DIN",
2. or, the first two letters of the short name should be the same as the first two letters of the team's name, while the third letter is the same as the first letter in the hometown's name. For the mentioned club it is "DIB".
Apart from this, there is a rule that if for some club x the second option of short name is chosen, then there should be no club, for which the first option is chosen which is the same as the first option for the club x. For example, if the above mentioned club has short name "DIB", then no club for which the first option is chosen can have short name equal to "DIN". However, it is possible that some club have short name "DIN", where "DI" are the first two letters of the team's name, and "N" is the first letter of hometown's name. Of course, no two teams can have the same short name.
Help Innokenty to choose a short name for each of the teams. If this is impossible, report that. If there are multiple answer, any of them will suit Innokenty. If for some team the two options of short name are equal, then Innokenty will formally think that only one of these options is chosen.
Input
The first line contains a single integer n (1 ≤ n ≤ 1000) — the number of clubs in the league.
Each of the next n lines contains two words — the team's name and the hometown's name for some club. Both team's name and hometown's name consist of uppercase English letters and have length at least 3 and at most 20.
Output
It it is not possible to choose short names and satisfy all constraints, print a single line "NO".
Otherwise, in the first line print "YES". Then print n lines, in each line print the chosen short name for the corresponding club. Print the clubs in the same order as they appeared in input.
If there are multiple answers, print any of them.
Examples
Input
2
DINAMO BYTECITY
FOOTBALL MOSCOW
Output
YES
DIN
FOO
Input
2
DINAMO BYTECITY
DINAMO BITECITY
Output
NO
Input
3
PLAYFOOTBALL MOSCOW
PLAYVOLLEYBALL SPB
GOGO TECHNOCUP
Output
YES
PLM
PLS
GOG
Input
3
ABC DEF
ABC EFG
ABD OOO
Output
YES
ABD
ABE
ABO
Note
In the first sample Innokenty can choose first option for both clubs.
In the second example it is not possible to choose short names, because it is not possible that one club has first option, and the other has second option if the first options are equal for both clubs.
In the third example Innokenty can choose the second options for the first two clubs, and the first option for the third club.
In the fourth example note that it is possible that the chosen short name for some club x is the same as the first option of another club y if the first options of x and y are different.
Submitted Solution:
```
def bin(a, n):
v = a[:]
if len(a) == n:
if a not in pos:
pos.append(a)
else:
a.append(0)
bin(a, n)
v.append(1)
bin(v, n)
n = int(input())
ar = []
global pos
pos = [[0 for i in range(n)]]
bin([], n)
t = True
for i in range(n):
a = input().split()
k = [a[0][:3], a[0][:2] + a[1][0]]
k.sort()
if k in ar:
t = False
break
ar.append(k)
ans = []
if not t:
print('NO')
else:
for i in range(len(pos)):
ans = []
for j in range(n):
if ar[j][pos[i][j]] in ans:
break
else:
ans.append(ar[j][pos[i][j]])
if len(ans)==n:
print('YES')
for i in ans:
print(i)
break
if len(ans) != n:
print('NO')
``` | instruction | 0 | 85,424 | 18 | 170,848 |
No | output | 1 | 85,424 | 18 | 170,849 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,536 | 18 | 171,072 |
"Correct Solution:
```
s = input()
a = s[0::2]
b = s[1::2]
print("Yes" if a.count("L") == 0 and b.count("R") == 0 else "No")
``` | output | 1 | 85,536 | 18 | 171,073 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,537 | 18 | 171,074 |
"Correct Solution:
```
s=input();print('YNeos'['L'in s[0::2]or'R'in s[1::2]::2])
``` | output | 1 | 85,537 | 18 | 171,075 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,538 | 18 | 171,076 |
"Correct Solution:
```
order = input()
if "R" in order[1::2] or "L" in order[::2]:
print("No")
else:
print("Yes")
``` | output | 1 | 85,538 | 18 | 171,077 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,539 | 18 | 171,078 |
"Correct Solution:
```
s = input()
if 'L' in set(s[::2]) or 'R' in set(s[1::2]):
print('No')
else:
print('Yes')
``` | output | 1 | 85,539 | 18 | 171,079 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,540 | 18 | 171,080 |
"Correct Solution:
```
S = input()
S_o = S[::2]
S_e = S[1::2]
if 'L' in S_o or 'R' in S_e:
print('No')
else:
print('Yes')
``` | output | 1 | 85,540 | 18 | 171,081 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,541 | 18 | 171,082 |
"Correct Solution:
```
s = input()
s_odd = s[0::2]
s_even = s[1::2]
print("YNeos"[not(s_odd.find('L')==-1 and s_even.find('R')==-1)::2])
``` | output | 1 | 85,541 | 18 | 171,083 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,542 | 18 | 171,084 |
"Correct Solution:
```
s = input()
arr = list(s)
if 'L' in arr[::2] or 'R' in arr[1::2]:
print('No')
else:
print('Yes')
``` | output | 1 | 85,542 | 18 | 171,085 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes | instruction | 0 | 85,543 | 18 | 171,086 |
"Correct Solution:
```
S = input()
if "L" not in S[::2]:
if "R" not in S[1::2]:
print("Yes")
exit()
print("No")
``` | output | 1 | 85,543 | 18 | 171,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
S = input()
N = len(S)
print('Yes' if not any(S[i] == 'LR'[i % 2] for i in range(N)) else 'No')
``` | instruction | 0 | 85,544 | 18 | 171,088 |
Yes | output | 1 | 85,544 | 18 | 171,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
taps=list(input())
if "L" in taps[0::2] or "R" in taps[1::2]:
print("No")
else:
print("Yes")
``` | instruction | 0 | 85,545 | 18 | 171,090 |
Yes | output | 1 | 85,545 | 18 | 171,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
s=list(input())
a=s[::2]
b=s[1::2]
if 'R' in b or 'L' in a:
print('No')
else:
print('Yes')
``` | instruction | 0 | 85,546 | 18 | 171,092 |
Yes | output | 1 | 85,546 | 18 | 171,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
s = input()
print('Yes' if 'L' not in set(s[::2]) and 'R' not in set(s[1::2]) else 'No')
``` | instruction | 0 | 85,547 | 18 | 171,094 |
Yes | output | 1 | 85,547 | 18 | 171,095 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
S = input()
if S[0::2].count("L") + S[1::2].count("R") == 0: print("Yes")
else: print("No")
``` | instruction | 0 | 85,548 | 18 | 171,096 |
No | output | 1 | 85,548 | 18 | 171,097 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
n = str(input())
d = []
p = []
i = 1
s = 1
l = 1
for k in n:
if i % 2 == 0:
if k == "R" or k == "U" or k == "D":
pass
else:
s = 0
else:
if k == "L" or k == "U" or k == "D":
pass
else:
l = 0
i = i + 1
if s or l == "1":
print("Yes")
else:
print("No")
``` | instruction | 0 | 85,549 | 18 | 171,098 |
No | output | 1 | 85,549 | 18 | 171,099 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
S=input()
for i in range(int(S)):
if S[2i]!='L' and S[2i+1]!='R':
print('Yes')
else:
print('No')
``` | instruction | 0 | 85,550 | 18 | 171,100 |
No | output | 1 | 85,550 | 18 | 171,101 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi will do a tap dance. The dance is described by a string S where each character is `L`, `R`, `U`, or `D`. These characters indicate the positions on which Takahashi should step. He will follow these instructions one by one in order, starting with the first character.
S is said to be easily playable if and only if it satisfies both of the following conditions:
* Every character in an odd position (1-st, 3-rd, 5-th, \ldots) is `R`, `U`, or `D`.
* Every character in an even position (2-nd, 4-th, 6-th, \ldots) is `L`, `U`, or `D`.
Your task is to print `Yes` if S is easily playable, and `No` otherwise.
Constraints
* S is a string of length between 1 and 100 (inclusive).
* Each character of S is `L`, `R`, `U`, or `D`.
Input
Input is given from Standard Input in the following format:
S
Output
Print `Yes` if S is easily playable, and `No` otherwise.
Examples
Input
RUDLUDR
Output
Yes
Input
DULL
Output
No
Input
UUUUUUUUUUUUUUU
Output
Yes
Input
ULURU
Output
No
Input
RDULULDURURLRDULRLR
Output
Yes
Submitted Solution:
```
N = str(input())
c = []
for i in range(0,len(N)):
if i % 2 == 0:
if i == 'R' or i == 'U' or i == 'D':
c.append(i)
else:
if i =='L' or i == 'U' or i == 'D':
c.append(i)
if len(c) == len(N):
print('Yes')
else:
print('No')
``` | instruction | 0 | 85,551 | 18 | 171,102 |
No | output | 1 | 85,551 | 18 | 171,103 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
p = input()
q = [input() for i in range(int(input()))]
r = [(q1[1]+q2[0]) for q1 in q for q2 in q]
print("Yes" if p in q+r else "No")
# Made By Mostafa_Khaled
``` | instruction | 0 | 86,223 | 18 | 172,446 |
Yes | output | 1 | 86,223 | 18 | 172,447 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
def solve():
password = input()
n = int(input())
words = [input() for i in range(n)]
#status = "NO"
for i in range(n):
for j in range(n):
temp = words[i] + words[j]
if password in temp:
return "YES"
return "NO"
print(solve())
``` | instruction | 0 | 86,224 | 18 | 172,448 |
Yes | output | 1 | 86,224 | 18 | 172,449 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
a = input()
b = int(input())
c=[]
for j in range (b):
c.append(input())
p = "NO"
for i in c:
if i[::-1]==a or i==a:
p = "YES"
if (i[1]==a[0]):
c.remove(i)
for i in c:
if i[0]==a[1]:
p = "YES"
print (p)
``` | instruction | 0 | 86,225 | 18 | 172,450 |
Yes | output | 1 | 86,225 | 18 | 172,451 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
s = input()
list = []
for i in range(int(input())):
list.append(str(input()))
ans = "NO"
for i in list:
for j in list:
if (i[1] in s[0] and j[0] == s[1]) or s in list :
ans = "YES"
print(ans)
``` | instruction | 0 | 86,226 | 18 | 172,452 |
Yes | output | 1 | 86,226 | 18 | 172,453 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
password = input("")
inputs_len = input("")
inputs = []
for i in range(int(inputs_len)):
inputs.append(input(""))
for i in range(int(inputs_len)):
if password[0] in inputs[i]:
for j in range(int(inputs_len)):
if password[1] == inputs[j][0]:
print("YES")
exit(0)
print("NO")
``` | instruction | 0 | 86,227 | 18 | 172,454 |
No | output | 1 | 86,227 | 18 | 172,455 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
a=input()
y=0
h=0
for i in range(int(input())):
t=input()
if a[0] in t:
if t[1]==a[0]:
y+=1
if a[1] in t:
if t[0]==a[1]:
h+=1
if min(y,h)>=1:
print('YES')
else:
print('NO')
``` | instruction | 0 | 86,228 | 18 | 172,456 |
No | output | 1 | 86,228 | 18 | 172,457 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
n=input()
n1=int(input())
li=[]
for i in range(n1):
li.append(input())
flag1=0
flag=0
if [n]==li:
print("YES")
exit(0)
for i in range(n1):
if n[0] == li[i][1]:
flag=1
break
for j in range(n1):
if n[1] == li[j][0]:
flag1=1
break
if flag1==1 and flag==1:
print("YES")
else:
print("NO")
``` | instruction | 0 | 86,229 | 18 | 172,458 |
No | output | 1 | 86,229 | 18 | 172,459 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
As technologies develop, manufacturers are making the process of unlocking a phone as user-friendly as possible. To unlock its new phone, Arkady's pet dog Mu-mu has to bark the password once. The phone represents a password as a string of two lowercase English letters.
Mu-mu's enemy Kashtanka wants to unlock Mu-mu's phone to steal some sensible information, but it can only bark n distinct words, each of which can be represented as a string of two lowercase English letters. Kashtanka wants to bark several words (not necessarily distinct) one after another to pronounce a string containing the password as a substring. Tell if it's possible to unlock the phone in this way, or not.
Input
The first line contains two lowercase English letters — the password on the phone.
The second line contains single integer n (1 ≤ n ≤ 100) — the number of words Kashtanka knows.
The next n lines contain two lowercase English letters each, representing the words Kashtanka knows. The words are guaranteed to be distinct.
Output
Print "YES" if Kashtanka can bark several words in a line forming a string containing the password, and "NO" otherwise.
You can print each letter in arbitrary case (upper or lower).
Examples
Input
ya
4
ah
oy
to
ha
Output
YES
Input
hp
2
ht
tp
Output
NO
Input
ah
1
ha
Output
YES
Note
In the first example the password is "ya", and Kashtanka can bark "oy" and then "ah", and then "ha" to form the string "oyahha" which contains the password. So, the answer is "YES".
In the second example Kashtanka can't produce a string containing password as a substring. Note that it can bark "ht" and then "tp" producing "http", but it doesn't contain the password "hp" as a substring.
In the third example the string "hahahaha" contains "ah" as a substring.
Submitted Solution:
```
s=input()
n=int(input())
l=[]
c,p=0,0
for i in range(n):
l.append(input())
if s in l:
print("Yes")
else:
for i in l:
if(i[0]==s[1]):
c+=1
break
for i in l:
if(i[1]==s[0]):
p+=1
break
if(c==1 and p==1):
print("Yes")
else:
print("No")
``` | instruction | 0 | 86,230 | 18 | 172,460 |
No | output | 1 | 86,230 | 18 | 172,461 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
s = [5,7,5,7,7]
def solve(n):
num = [len(input()) for _ in range(n)]
for i in range(n):
c = 0
k = 0
for j in range(i,n):
c+= num[j]
if c==s[k]:
k+=1
c = 0
if k == 5:
print(i+1)
return
if c > s[k]:
break
while 1:
n = int(input())
if n == 0:
break
solve(n)
``` | instruction | 0 | 86,500 | 18 | 173,000 |
Yes | output | 1 | 86,500 | 18 | 173,001 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
def check(word):
l = 0
step = 0
for w in word:
l += len(w)
if step == 0 or step == 2:
if l == 5:
step += 1
l = 0
elif l > 5:
return False
elif step == 1 or step == 3:
if l == 7:
step += 1
l = 0
elif l > 7:
return False
elif step == 4:
if l == 7:
return True
return False
while 1:
n = int(input())
if n == 0:
break
word = []
for _ in range(n):
word.append(input())
cnt = 0
while word != []:
cnt += 1
if check(word):
break
word.pop(0)
print(cnt)
``` | instruction | 0 | 86,501 | 18 | 173,002 |
Yes | output | 1 | 86,501 | 18 | 173,003 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
tanka = (5, 7, 5, 7, 7, 0)
words = list()
n = int()
def rec(step, itr, word):
if step == 5:
return True
if word == 0:
return rec(step + 1, itr, tanka[step + 1])
elif word < 0:
return False
return rec(step, itr + 1, word - words[itr])
while True:
n = int(input())
if n == 0:
break
words = [len(str(input())) for i in range(n)]
for i in range(n):
if rec(0, i, tanka[0]):
print(i + 1)
break
``` | instruction | 0 | 86,502 | 18 | 173,004 |
Yes | output | 1 | 86,502 | 18 | 173,005 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
while True :
n = int(input())
if(n == 0) :
break
else :
A = [5, 7, 5, 7, 7]
ans = 0
w = [len(input()) for i in range(n)]
for i in range(n) :
k = 0
s = 0
for j in range(i, n) :
s += w[j]
if(s == A[k]) :
s = 0
k += 1
if(k == 5) :
ans = i + 1
break
elif(s > A[k]) :
break
if(ans != 0) :
break
print(ans)
``` | instruction | 0 | 86,503 | 18 | 173,006 |
Yes | output | 1 | 86,503 | 18 | 173,007 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
def main():
while True:
n = int(input().strip())
if n == 0:
break
phrases = []
for _ in range(n):
word = input().strip()
phrases.append(word)
PHRASE_LEN = [5,7,5,7,7]
found_flag = False
for i in range(n):
acc_len = 0
phrase_idx = 0
for j in range(i, n):
acc_len += len(phrases[j])
if acc_len == PHRASE_LEN[phrase_idx]:
if phrase_idx == (len(PHRASE_LEN)-1):
found_flag = True
break
acc_len = 0
phrase_idx += 1
elif acc_len > PHRASE_LEN[phrase_idx]:
break
if found_flag:
print(i+1)
break
if __name__ == "__main__":
main()
~
~
~
``` | instruction | 0 | 86,504 | 18 | 173,008 |
No | output | 1 | 86,504 | 18 | 173,009 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Short Phrase
A Short Phrase (aka. Tanku) is a fixed verse, inspired by Japanese poetry Tanka and Haiku. It is a sequence of words, each consisting of lowercase letters 'a' to 'z', and must satisfy the following condition:
> (The Condition for a Short Phrase)
> The sequence of words can be divided into five sections such that the total number of the letters in the word(s) of the first section is five, that of the second is seven, and those of the rest are five, seven, and seven, respectively.
The following is an example of a Short Phrase.
>
> do the best
> and enjoy today
> at acm icpc
>
In this example, the sequence of the nine words can be divided into five sections (1) "do" and "the", (2) "best" and "and", (3) "enjoy", (4) "today" and "at", and (5) "acm" and "icpc" such that they have 5, 7, 5, 7, and 7 letters in this order, respectively. This surely satisfies the condition of a Short Phrase.
Now, Short Phrase Parnassus published by your company has received a lot of contributions. By an unfortunate accident, however, some irrelevant texts seem to be added at beginnings and ends of contributed Short Phrases. Your mission is to write a program that finds the Short Phrase from a sequence of words that may have an irrelevant prefix and/or a suffix.
Input
The input consists of multiple datasets, each in the following format.
> n
> w1
> ...
> wn
>
Here, n is the number of words, which is a positive integer not exceeding 40; wi is the i-th word, consisting solely of lowercase letters from 'a' to 'z'. The length of each word is between 1 and 10, inclusive. You can assume that every dataset includes a Short Phrase.
The end of the input is indicated by a line with a single zero.
Output
For each dataset, output a single line containing i where the first word of the Short Phrase is wi. When multiple Short Phrases occur in the dataset, you should output the first one.
Sample Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output for the Sample Input
1
2
6
Example
Input
9
do
the
best
and
enjoy
today
at
acm
icpc
14
oh
yes
by
far
it
is
wow
so
bad
to
me
you
know
hey
15
abcde
fghijkl
mnopq
rstuvwx
yzz
abcde
fghijkl
mnopq
rstuvwx
yz
abcde
fghijkl
mnopq
rstuvwx
yz
0
Output
1
2
6
Submitted Solution:
```
while True:
n = int(input())#文字列の量
if n == 0:
break
w = list()#文字用
for i in range(0, n):#入力
w.append(input())
for j in range(1, n+1):#始めの文字の場所
ck = 0
co = 0
p = 0
t = ""
for k in range(j-1,50):#５７５７７チェック用
#print(k)
if co == 0 or co == 2:#５の場所
if ck < 5:#五以下
#print("<")
ck = ck + len(w[k+p])#文字増やす
elif ck == 5:#ピッタリになったら
#print("==")
co = co + 1#次に移る
ck = 0
p = p-1
else:#オーバーしたら
#print(">")
break
else:
if ck < 7:
#print("<7")
ck = ck+len(w[k+p])
#print(" " ,ck)
elif ck == 7:
#print("==7")
co = co+1
ck = 0
p = p-1
if co == 5:
t = "fin"
break
else:
#print(">7")
break
print(j)
if t == "fin":
break
#print("over")
``` | instruction | 0 | 86,505 | 18 | 173,010 |
No | output | 1 | 86,505 | 18 | 173,011 |
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