message stringlengths 2 11.9k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 137 108k | cluster float64 18 18 | __index_level_0__ int64 274 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is — for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 ≤ t ≤ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 50) — the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
import copy
t = int(input())
class StringData:
def __init__(self):
self.len = 0
self.first_three_char = ""
self.last_three_char = ""
self.haha_count = 0
def set(self, s):
self.haha_count = s.count('haha')
self.len = len(s)
self.first_three_char = s[:3]
self.last_three_char = s[-3:]
def append(self, sd):
middle_part = self.last_three_char + sd.first_three_char
self.haha_count += middle_part.count('haha')
if self.len < 3:
self.first_three_char += sd.first_three_char
self.first_three_char = self.first_three_char[:3]
if len(sd.last_three_char) < 3:
self.last_three_char += sd.last_three_char
l = len(self.last_three_char)
self.last_three_char = self.last_three_char[max(0,l-3):]
else:
self.last_three_char = sd.last_three_char
self.haha_count += sd.haha_count
self.len += sd.len
for _ in range(t):
n = int(input())
string_datas = {}
last_haha_count = 0
for i in range(n):
l = input()
if l.count(':'):
var, _, value = l.split()
string_datas[var] = StringData()
string_datas[var].set(value)
last_haha_count = string_datas[var].haha_count
else:
var, _, var1, _, var2 = l.split()
var1_copy = copy.deepcopy(string_datas[var1])
var1_copy.append(string_datas[var2])
string_datas[var] = var1_copy
last_haha_count = string_datas[var].haha_count
print(last_haha_count)
``` | instruction | 0 | 81,994 | 18 | 163,988 |
No | output | 1 | 81,994 | 18 | 163,989 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is — for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 ≤ t ≤ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 50) — the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
t=int(input())
for i in range(t):
n=int(input())
variable_dict={}
for j in range(n):
a=input()
if ' := ' in a:
x=a.split(' := ')
variable_dict[x[0]]=x[1]
if(j==n-1):
print(variable_dict[x[0]].count('haha'))
if ' + ' in a:
x=a.split(' = ')
y=x[1].split(' + ')
variable_dict[x[0]]=variable_dict[y[0]]+variable_dict[y[1]]
if(j==n-1):
print(variable_dict[x[0]].count('haha'))
# print(variable_dict)
``` | instruction | 0 | 81,995 | 18 | 163,990 |
No | output | 1 | 81,995 | 18 | 163,991 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is — for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 ≤ t ≤ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 50) — the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
def solve():
n = int(input())
#a = list(map(int, input().split()))
vars = dict()
for _ in range(n):
s = input()
if ' := ' in s:
v, val = s.split(' := ')
vars[v] = val
else:
v, s = s.split(' = ')
v2, v3 = s.split(' + ')
vars[v] = vars[v2] + vars[v3]
s = vars[v]
cnt = 0
ha = 'ha'
ans = 0
for c in s:
if c == ha[cnt % 2]:
cnt += 1
else:
cnt = cnt // 2
if cnt >= 4:
ans += (cnt-1)
cnt = int(c == 'h')
if cnt >= 4:
cnt = cnt // 2
ans += (cnt-1)
print(ans)
return
testcase = int(input())
tn = 1
while tn <= testcase:
solve()
tn += 1
``` | instruction | 0 | 81,996 | 18 | 163,992 |
No | output | 1 | 81,996 | 18 | 163,993 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Polycarp came up with a new programming language. There are only two types of statements in it:
* "x := s": assign the variable named x the value s (where s is a string). For example, the statement var := hello assigns the variable named var the value hello. Note that s is the value of a string, not the name of a variable. Between the variable name, the := operator and the string contains exactly one space each.
* "x = a + b": assign the variable named x the concatenation of values of two variables a and b. For example, if the program consists of three statements a := hello, b := world, c = a + b, then the variable c will contain the string helloworld. It is guaranteed that the program is correct and the variables a and b were previously defined. There is exactly one space between the variable names and the = and + operators.
All variable names and strings only consist of lowercase letters of the English alphabet and do not exceed 5 characters.
The result of the program is the number of occurrences of string haha in the string that was written to the variable in the last statement.
Polycarp was very tired while inventing that language. He asks you to implement it. Your task is — for given program statements calculate the number of occurrences of string haha in the last assigned variable.
Input
The first line contains an integer t (1 ≤ t ≤ 10^3). Then t test cases follow.
The first line of each test case contains a single integer n (1 ≤ n ≤ 50) — the number of statements in the program. All variable names and strings are guaranteed to consist only of lowercase letters of the English alphabet and do not exceed 5 characters.
This is followed by n lines describing the statements in the format described above. It is guaranteed that the program is correct.
Output
For each set of input data, output the number of occurrences of the haha substring in the string that was written to the variable in the last statement.
Example
Input
4
6
a := h
b := aha
c = a + b
c = c + c
e = c + c
d = a + c
15
x := haha
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
x = x + x
1
haha := hah
5
haahh := aaaha
ahhhh = haahh + haahh
haahh = haahh + haahh
ahhhh = ahhhh + haahh
ahhaa = haahh + ahhhh
Output
3
32767
0
0
Note
In the first test case the resulting value of d is hhahahaha.
Submitted Solution:
```
t = int(input())
curvars = {}
def concat(a, b):
pa, sa, na = a
pb, sb, nb = b
x = 0
for i in range(0, 10):
if (sa + pb)[i:i + 4] == "haha":
x += 1
return (pa + pb)[:3], (sa + sb)[-3:], na + nb + x
for _ in range(t):
n = int(input())
for _ in range(n):
s = input()
if ":=" in s:
name, _, val = s.split()
curvars[name] = (val[:3], val[-3:], val.count("haha"))
else:
name, _, a, _, b = s.split()
curvars[name] = concat(curvars[a], curvars[b])
print(curvars[name])
``` | instruction | 0 | 81,997 | 18 | 163,994 |
No | output | 1 | 81,997 | 18 | 163,995 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
from collections import Counter
def go():
a = [i for i in input()]
b = [i for i in input()]
a_c = Counter(a)
b_c = Counter(b)
if len(a) != len(b) or a_c != b_c:
return 'NO'
differences = 0
for i in range(len(a)):
if a[i] != b[i]:
differences += 1
if differences == 2:
return 'YES'
return 'NO'
print(go())
``` | instruction | 0 | 82,006 | 18 | 164,012 |
Yes | output | 1 | 82,006 | 18 | 164,013 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
l = []
s = input()
t = input()
c = 0
if len(t) == len(s):
for i in range(len(t)):
if t[i] != s[i]:
l.append((t[i],s[i]))
c+=1
if c>2:
break
if c > 2 or c==1:
print("NO")
else:
#print(l[0][0], l[1][1], l[1][0],l[0][1])
if l[0][0] == l[1][1] and l[1][0] == l[0][1]:
print("YES")
else:
print("NO")
else:
print("NO")
``` | instruction | 0 | 82,007 | 18 | 164,014 |
Yes | output | 1 | 82,007 | 18 | 164,015 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
s=input()
t=input()
if len(s) == len(t):
a,b="",""
for i,j in zip(s,t):
if i != j: a += i;b += j
if len(a)==2:
if a[0]==b[1] and a[1]==b[0]:print("YES")
else: print("NO")
else:
print("NO")
else: print("NO")
``` | instruction | 0 | 82,008 | 18 | 164,016 |
Yes | output | 1 | 82,008 | 18 | 164,017 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
class CodeforcesTask186ASolution:
def __init__(self):
self.result = ''
self.g1 = ''
self.g2 = ''
def read_input(self):
self.g1 = list(input())
self.g2 = list(input())
def process_task(self):
if len(self.g1) != len(self.g2):
self.result = "NO"
else:
can_ = True
d1 = None
d2 = None
for x in range(len(self.g1)):
if self.g1[x] != self.g2[x]:
if d1:
d2 = x + 1
else:
d1 = x + 1
if d1 and d2:
#print(self.g1, self.g2)
#print(d1, d2)
self.g1[d1 - 1], self.g1[d2 - 1] = self.g1[d2 - 1], self.g1[d1 - 1]
self.g1 = "".join(self.g1)
self.g2 = "".join(self.g2)
#print(self.g1, self.g2)
can_ = self.g1 == self.g2
elif not d1 and not d2:
can_ = True
else:
can_ = False
self.result = "YES" if can_ else "NO"
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask186ASolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
``` | instruction | 0 | 82,009 | 18 | 164,018 |
Yes | output | 1 | 82,009 | 18 | 164,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
from collections import Counter
first = Counter(input())
second = Counter(input())
diff = first - second
if not diff.keys():
print('YES')
else:
print('NO')
``` | instruction | 0 | 82,010 | 18 | 164,020 |
No | output | 1 | 82,010 | 18 | 164,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
a = input()
b = input()
if a==b:
print('YES')
elif len(a)!=len(b):
print('NO')
else:
a = [i for i in a]
b = [i for i in b]
if(sorted(a)==sorted(b)):
print('YES')
else:
print('NO')
``` | instruction | 0 | 82,011 | 18 | 164,022 |
No | output | 1 | 82,011 | 18 | 164,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Some dwarves that are finishing the StUDY (State University for Dwarven Youngsters) Bachelor courses, have been told "no genome, no degree". That means that all dwarves should write a thesis on genome. Dwarven genome is far from simple. It is represented by a string that consists of lowercase Latin letters.
Dwarf Misha has already chosen the subject for his thesis: determining by two dwarven genomes, whether they belong to the same race. Two dwarves belong to the same race if we can swap two characters in the first dwarf's genome and get the second dwarf's genome as a result. Help Dwarf Misha and find out whether two gnomes belong to the same race or not.
Input
The first line contains the first dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The second line contains the second dwarf's genome: a non-empty string, consisting of lowercase Latin letters.
The number of letters in each genome doesn't exceed 105. It is guaranteed that the strings that correspond to the genomes are different. The given genomes may have different length.
Output
Print "YES", if the dwarves belong to the same race. Otherwise, print "NO".
Examples
Input
ab
ba
Output
YES
Input
aa
ab
Output
NO
Note
* First example: you can simply swap two letters in string "ab". So we get "ba".
* Second example: we can't change string "aa" into string "ab", because "aa" does not contain letter "b".
Submitted Solution:
```
s = input()
t = input()
print(['NO', 'YES'][sorted(s) == sorted(t) and sum([1 for i, j in zip(s, t) if i != j]) > 1])
``` | instruction | 0 | 82,013 | 18 | 164,026 |
No | output | 1 | 82,013 | 18 | 164,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
word = list(input())
if ord(word[0]) >= 97 and ord(word[0]) <= 122:
word[0] = chr(ord(word[0]) - 32)
print(''.join(word))
``` | instruction | 0 | 82,039 | 18 | 164,078 |
Yes | output | 1 | 82,039 | 18 | 164,079 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
s=input()
a=s[0].upper()
s=a+s[1:]
print(s)
``` | instruction | 0 | 82,040 | 18 | 164,080 |
Yes | output | 1 | 82,040 | 18 | 164,081 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
'''
Capitalization is writing a word with its first letter as a capital letter.
Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains
unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and
uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
'''
s = input()
u = ""
j = 0
for i in (s):
if(j == 0 and ord(i) >= 97 and ord(i) <= 122):
i = (chr(ord(i) - 32))
else:
i = i
j += 1
u += i
print(u)
``` | instruction | 0 | 82,041 | 18 | 164,082 |
Yes | output | 1 | 82,041 | 18 | 164,083 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
def cap(s):
if len(s) > 0:
r = s[0].upper()
r = str(r) + s[1:]
return r
return s
if __name__ == '__main__':
s = input()
print(cap(s))
``` | instruction | 0 | 82,042 | 18 | 164,084 |
Yes | output | 1 | 82,042 | 18 | 164,085 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
str1=input()
print(str1[0].capitalize())
``` | instruction | 0 | 82,043 | 18 | 164,086 |
No | output | 1 | 82,043 | 18 | 164,087 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
s=input()
g=s[0]
if g.isupper():
print(s)
else:
print(s.title())
``` | instruction | 0 | 82,044 | 18 | 164,088 |
No | output | 1 | 82,044 | 18 | 164,089 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
#!/bin/python3
def myfunc(st):
print(st[0])
return st.replace(st[0], st[0].upper(),1)
if __name__ == '__main__':
s = str(input().strip())
print(myfunc(s))
``` | instruction | 0 | 82,045 | 18 | 164,090 |
No | output | 1 | 82,045 | 18 | 164,091 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Capitalization is writing a word with its first letter as a capital letter. Your task is to capitalize the given word.
Note, that during capitalization all the letters except the first one remains unchanged.
Input
A single line contains a non-empty word. This word consists of lowercase and uppercase English letters. The length of the word will not exceed 103.
Output
Output the given word after capitalization.
Examples
Input
ApPLe
Output
ApPLe
Input
konjac
Output
Konjac
Submitted Solution:
```
n = input().lower()
print(n[0].upper()+n[1:])
``` | instruction | 0 | 82,046 | 18 | 164,092 |
No | output | 1 | 82,046 | 18 | 164,093 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
x= []
x = input().split()
n = int(x[0])
p = int(x[1])
q = int(x[2])
s =""
s = str(input())
if q > p :
y = p
p = q
q = y
a = int(n/p)
b = 200
for x in range(a,-1,-1):
if (n-x*p)%q==0:
a=x
b=int((n-x*p)/q)
break
if b!=200:
print (int(a+b))
for x in range(a):
print (s[x*p:p*(x+1)])
for y in range(b):
print (s[a*p+y*q:q*(y+1)+a*p])
else:
print (-1)
``` | instruction | 0 | 82,170 | 18 | 164,340 |
Yes | output | 1 | 82,170 | 18 | 164,341 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
import math
n, p, q = tuple(int(x) for x in input().split())
word = input()
def counts(n, p, q):
for i in range(math.ceil((n + 1) / p)):
if (n - p * i) % q == 0:
return (i, (n - p * i) // q)
return None
def solve(n, p, q, word):
_counts = counts(n, p, q)
if _counts == None:
print(-1)
return
i, j = _counts
print(i + j)
for ii in range(i):
print(word[ii * p : ii * p + p])
for jj in range(j):
print(word[i * p + jj * q : i * p + jj * q + q])
solve(n, p, q, word)
``` | instruction | 0 | 82,171 | 18 | 164,342 |
Yes | output | 1 | 82,171 | 18 | 164,343 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
import sys
n,p,q = map(int, input().split())
s = input()
for i in range(0,101):
for j in range(0,101):
if p * i + q * j == n:
print(i + j)
for o in range(0,i):
print(s[o*p: (o +1) *p])
s = s[i*p:]
for o in range(0,j):
print(s[o*q: (o +1) *q])
sys.exit()
print(-1)
``` | instruction | 0 | 82,172 | 18 | 164,344 |
Yes | output | 1 | 82,172 | 18 | 164,345 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
a,b,c = map(int,input().split())
nome = input()
i = 1
f = 0
g = 0
val = 1
if a%b == 0:
val = 0
print(a//b)
for i in range(a//b):
print(nome[f:b+f])
f += b
elif a%c == 0:
val = 0
print(a//c)
for i in range(a//c):
print(nome[f:c+f])
f += c
else:
while True:
valor = a-(i*b)
if valor<=0:
break
if valor%c==0:
val = 0
print(i+(valor//c))
for x in range(i):
print(nome[f:(f+b)])
f += b
for y in range(valor//c):
print(nome[f:(f+c)])
f+=c
break
i+=1
if val:
print('-1')
``` | instruction | 0 | 82,173 | 18 | 164,346 |
Yes | output | 1 | 82,173 | 18 | 164,347 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
lectura= lambda: map(int,input().split())
n,p,q=lectura()
palabra=input()
prioridad=p
if(p+q>n):
prioridad=min(p,q)
if(prioridad> n//2):
print(-1)
else:
print(palabra[0:prioridad])
print(palabra[prioridad:])
``` | instruction | 0 | 82,174 | 18 | 164,348 |
No | output | 1 | 82,174 | 18 | 164,349 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
def verif(n,p,q):
t=False
a=0
b=0
for i in range(n):
for j in range(n):
if(i*p+j*q==n):
a=i
b=j
t=True
break
return t,a,b
n,p,q=map(int,input().split())
s=input()
t,i,j=verif(n,p,q)
if(n==1)and((p==1)or(q==1)):
print(s[0])
elif(t==False):
print('-1')
else:
print(i+j)
for i in range(i):
print(s[:p])
s=s[p:]
for i in range(j):
print(s[:q])
s=s[q:]
``` | instruction | 0 | 82,175 | 18 | 164,350 |
No | output | 1 | 82,175 | 18 | 164,351 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
n, p, q = map(int, input().split())
s = input()
for i in range(n//p):
if (n - i * p) % q == 0:
ii = (n - i * p) // q
print(i+ii)
for j in range(i):
print(s[j*p:j*p+p])
for j in range(ii):
print(s[i*p+j*q:i*p+j*q+q])
import sys
sys.exit()
print(-1)
``` | instruction | 0 | 82,176 | 18 | 164,352 |
No | output | 1 | 82,176 | 18 | 164,353 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given the string s of length n and the numbers p, q. Split the string s to pieces of length p and q.
For example, the string "Hello" for p = 2, q = 3 can be split to the two strings "Hel" and "lo" or to the two strings "He" and "llo".
Note it is allowed to split the string s to the strings only of length p or to the strings only of length q (see the second sample test).
Input
The first line contains three positive integers n, p, q (1 ≤ p, q ≤ n ≤ 100).
The second line contains the string s consists of lowercase and uppercase latin letters and digits.
Output
If it's impossible to split the string s to the strings of length p and q print the only number "-1".
Otherwise in the first line print integer k — the number of strings in partition of s.
Each of the next k lines should contain the strings in partition. Each string should be of the length p or q. The string should be in order of their appearing in string s — from left to right.
If there are several solutions print any of them.
Examples
Input
5 2 3
Hello
Output
2
He
llo
Input
10 9 5
Codeforces
Output
2
Codef
orces
Input
6 4 5
Privet
Output
-1
Input
8 1 1
abacabac
Output
8
a
b
a
c
a
b
a
c
Submitted Solution:
```
n,p,q = map(int,input().split())
s = str(input())
if(p+q==len(s)):
s1 = ""
s2 = ""
for i in range(p):
s1+=s[i]
for i in range(p,len(s)):
s2+=s[i]
print(2)
print(s1)
print(s2)
if(len(s)%q==0 and q!=p):
s1=""
s2=""
for i in range(q):
s1+=s[i]
for i in range(q,len(s)):
s2+=s[i]
print(2)
print(s1)
print(s2)
if(len(s)%p==0 and p!=q):
s1=""
s2=""
for i in range(p):
s1+=s[i]
for i in range(p,len(s)):
s2+=s[i]
print(2)
print(s1)
print(s2)
if(p==q):
print(n)
for i in s:
print (i)
if(len(s)<= 2*p and len(s) <=2*q):
print(-1)
``` | instruction | 0 | 82,177 | 18 | 164,354 |
No | output | 1 | 82,177 | 18 | 164,355 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Calculate the minimum number of characters you need to change in the string s, so that it contains at least k different letters, or print that it is impossible.
String s consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too.
Input
First line of input contains string s, consisting only of lowercase Latin letters (1 ≤ |s| ≤ 1000, |s| denotes the length of s).
Second line of input contains integer k (1 ≤ k ≤ 26).
Output
Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible.
Examples
Input
yandex
6
Output
0
Input
yahoo
5
Output
1
Input
google
7
Output
impossible
Note
In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'a', 'h', 'o', 'y'}. To get 5 different letters it is necessary to change one occurrence of 'o' to some letter, which doesn't occur in the string, for example, {'b'}.
In the third test case, it is impossible to make 7 different letters because the length of the string is 6.
Submitted Solution:
```
s = str(input())
k = int(input())
def main():
if k > len(s):
print("impossible")
return
u = len(set(list(s)))
req = k - u
if req < 0: req = 0
print(req)
main()
``` | instruction | 0 | 82,259 | 18 | 164,518 |
Yes | output | 1 | 82,259 | 18 | 164,519 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Calculate the minimum number of characters you need to change in the string s, so that it contains at least k different letters, or print that it is impossible.
String s consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too.
Input
First line of input contains string s, consisting only of lowercase Latin letters (1 ≤ |s| ≤ 1000, |s| denotes the length of s).
Second line of input contains integer k (1 ≤ k ≤ 26).
Output
Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible.
Examples
Input
yandex
6
Output
0
Input
yahoo
5
Output
1
Input
google
7
Output
impossible
Note
In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'a', 'h', 'o', 'y'}. To get 5 different letters it is necessary to change one occurrence of 'o' to some letter, which doesn't occur in the string, for example, {'b'}.
In the third test case, it is impossible to make 7 different letters because the length of the string is 6.
Submitted Solution:
```
class CodeforcesTask844ASolution:
def __init__(self):
self.result = ''
self.string = ''
self.k = 0
def read_input(self):
self.string = input()
self.k = int(input())
def process_task(self):
if len(self.string) < self.k:
self.result = "impossible"
else:
l_num = len(set([ord(c) for c in self.string]))
self.result = str(self.k - l_num)
def get_result(self):
return self.result
if __name__ == "__main__":
Solution = CodeforcesTask844ASolution()
Solution.read_input()
Solution.process_task()
print(Solution.get_result())
``` | instruction | 0 | 82,265 | 18 | 164,530 |
No | output | 1 | 82,265 | 18 | 164,531 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Calculate the minimum number of characters you need to change in the string s, so that it contains at least k different letters, or print that it is impossible.
String s consists only of lowercase Latin letters, and it is allowed to change characters only to lowercase Latin letters too.
Input
First line of input contains string s, consisting only of lowercase Latin letters (1 ≤ |s| ≤ 1000, |s| denotes the length of s).
Second line of input contains integer k (1 ≤ k ≤ 26).
Output
Print single line with a minimum number of necessary changes, or the word «impossible» (without quotes) if it is impossible.
Examples
Input
yandex
6
Output
0
Input
yahoo
5
Output
1
Input
google
7
Output
impossible
Note
In the first test case string contains 6 different letters, so we don't need to change anything.
In the second test case string contains 4 different letters: {'a', 'h', 'o', 'y'}. To get 5 different letters it is necessary to change one occurrence of 'o' to some letter, which doesn't occur in the string, for example, {'b'}.
In the third test case, it is impossible to make 7 different letters because the length of the string is 6.
Submitted Solution:
```
s = input()
k = int(input())
print(max(0, k - len(set(s))) if len(s) < k else 'impossible')
``` | instruction | 0 | 82,266 | 18 | 164,532 |
No | output | 1 | 82,266 | 18 | 164,533 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,379 | 18 | 164,758 |
"Correct Solution:
```
n = int(input())
s = input()
print('YNeos'[s != s[:n // 2] * 2 ::2])
``` | output | 1 | 82,379 | 18 | 164,759 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,380 | 18 | 164,760 |
"Correct Solution:
```
n = int(input())
s = input()
t = s[:n//2]
ans = 'Yes' if s == t + t else 'No'
print(ans)
``` | output | 1 | 82,380 | 18 | 164,761 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,381 | 18 | 164,762 |
"Correct Solution:
```
n=int(input())
s=input()
print("Yes" if s[0:int((len(s))/2)]*2 == s else "No")
``` | output | 1 | 82,381 | 18 | 164,763 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,382 | 18 | 164,764 |
"Correct Solution:
```
n = int(input())
s = input()
print("Yes" if s[:len(s)//2] == s[len(s)//2:] else "No")
``` | output | 1 | 82,382 | 18 | 164,765 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,383 | 18 | 164,766 |
"Correct Solution:
```
N = int(input())
S = input()
print("Yes" if S[0:N//2] == S[N//2:N] else "No")
``` | output | 1 | 82,383 | 18 | 164,767 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,384 | 18 | 164,768 |
"Correct Solution:
```
n = int(input())
s = input()
print("YNeos"[s[0:int(n/2)] != s[int(n/2):n]::2])
``` | output | 1 | 82,384 | 18 | 164,769 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,385 | 18 | 164,770 |
"Correct Solution:
```
N = int(input())
S = input()
a=int(N/2)
print('Yes' if N%2==0 and S[:a]==S[a:] else 'No')
``` | output | 1 | 82,385 | 18 | 164,771 |
Provide a correct Python 3 solution for this coding contest problem.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No | instruction | 0 | 82,386 | 18 | 164,772 |
"Correct Solution:
```
n = int(input())
s = input()
t = s[:n//2]
print("Yes" if t+t == s else "No")
``` | output | 1 | 82,386 | 18 | 164,773 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
n=int(input())
s=input()
m=n//2
print("Yes" if s==s[0:m]+s[0:m] else "No")
``` | instruction | 0 | 82,387 | 18 | 164,774 |
Yes | output | 1 | 82,387 | 18 | 164,775 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
N,S=int(input()),input();print("Yes"if N%2==0and S[:len(S)//2]==S[len(S)//2:]else"No")
``` | instruction | 0 | 82,388 | 18 | 164,776 |
Yes | output | 1 | 82,388 | 18 | 164,777 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
n = int(input())
s = input()
print('Yes' if s[:int(n/2)] == s[int(n/2):] else 'No')
``` | instruction | 0 | 82,389 | 18 | 164,778 |
Yes | output | 1 | 82,389 | 18 | 164,779 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
input()
s=input()
half=int(len(s)/2)
print("Yes" if s[:half]==s[half:] else "No")
``` | instruction | 0 | 82,390 | 18 | 164,780 |
Yes | output | 1 | 82,390 | 18 | 164,781 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
n = int(input())
input(s)
s1 = [s[i : i + n / 2] for i in range(0, len(s), n / 2)]
if (s == s1)
print("Yes")
else
print ("No")
``` | instruction | 0 | 82,391 | 18 | 164,782 |
No | output | 1 | 82,391 | 18 | 164,783 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
n=int(input())
s=input()
if n%2!=0:
print("No")
else:
if s[:n//2+1]==s[n//2:]:
print("Yes")
else:
print("No")
``` | instruction | 0 | 82,392 | 18 | 164,784 |
No | output | 1 | 82,392 | 18 | 164,785 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
N = int(input())
S = input()
if (N%2 != 0):
print('No')
else:
n = N//2
for i in range(n):
if (S[i] != S[n+i]):
print('No')
break
if (i == n-1):
print('Yes')
``` | instruction | 0 | 82,393 | 18 | 164,786 |
No | output | 1 | 82,393 | 18 | 164,787 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Given are a positive integer N and a string S of length N consisting of lowercase English letters.
Determine whether the string is a concatenation of two copies of some string. That is, determine whether there is a string T such that S = T + T.
Constraints
* 1 \leq N \leq 100
* S consists of lowercase English letters.
* |S| = N
Input
Input is given from Standard Input in the following format:
N
S
Output
If S is a concatenation of two copies of some string, print `Yes`; otherwise, print `No`.
Examples
Input
6
abcabc
Output
Yes
Input
6
abcadc
Output
No
Input
1
z
Output
No
Submitted Solution:
```
n = int(input())
s = list(str(input()))
for i in range(int(n/2)):
if s[i] != s[int(n/2+i)] or n % 2:
print('No')
exit()
print('Yes')
``` | instruction | 0 | 82,394 | 18 | 164,788 |
No | output | 1 | 82,394 | 18 | 164,789 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
* the length of the password must be equal to n,
* the password should consist only of lowercase Latin letters,
* the number of distinct symbols in the password must be equal to k,
* any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions.
Input
The first line contains two positive integers n and k (2 ≤ n ≤ 100, 2 ≤ k ≤ min(n, 26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists.
Output
Print any password which satisfies all conditions given by Innokentiy.
Examples
Input
4 3
Output
java
Input
6 6
Output
python
Input
5 2
Output
phphp
Note
In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests.
Submitted Solution:
```
import random
def new_pass(n,k):
arr_org = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", "m", "n", "o", "p", "q", "r", "s", "t", "u",
"v", "w", "x", "y", "z"]
arr_1 = []
arr_2 = []
arr_final = []
num1=random.randint(0,12)
num2=num1
if(n<2 or k<2):
print ("Los parametros son 2<=n<=100 y 2<=k<=min(n,26)")
elif(n>100 or k>26):
print(" Los parametros son 2<=n<=100 y 2<=k<=min(n,26)")
else:
for i in range(k):
if i%2==0:
arr_1.append(arr_org[num1])
num1 = num1 - 1
else:
num2 = num2 + 1
arr_1.append(arr_org[num2])
for j in range(k):
arr_2.append(arr_1[j])
y=j
for x in range(n-k):
letra=arr_1[random.randint(0, y)]
while letra==arr_2[j]:
letra = arr_1[random.randint(0, y)]
arr_2.append(letra)
j = j + 1
arr_final=''.join(arr_2)
return arr_final
aux1,aux2 = input().split(' ')
n = int(aux1)
k = min(int(aux2), 26)
print(new_pass(n,k))
``` | instruction | 0 | 83,070 | 18 | 166,140 |
Yes | output | 1 | 83,070 | 18 | 166,141 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
* the length of the password must be equal to n,
* the password should consist only of lowercase Latin letters,
* the number of distinct symbols in the password must be equal to k,
* any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions.
Input
The first line contains two positive integers n and k (2 ≤ n ≤ 100, 2 ≤ k ≤ min(n, 26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists.
Output
Print any password which satisfies all conditions given by Innokentiy.
Examples
Input
4 3
Output
java
Input
6 6
Output
python
Input
5 2
Output
phphp
Note
In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests.
Submitted Solution:
```
import string
n, k = map(int, input().split())
a = list(string.ascii_lowercase)
f = []
i = 0
while len(f) != n:
if(i < k):
f.append(a[i])
i += 1
else:
i = 0
print(''.join(f))
``` | instruction | 0 | 83,071 | 18 | 166,142 |
Yes | output | 1 | 83,071 | 18 | 166,143 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
* the length of the password must be equal to n,
* the password should consist only of lowercase Latin letters,
* the number of distinct symbols in the password must be equal to k,
* any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions.
Input
The first line contains two positive integers n and k (2 ≤ n ≤ 100, 2 ≤ k ≤ min(n, 26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists.
Output
Print any password which satisfies all conditions given by Innokentiy.
Examples
Input
4 3
Output
java
Input
6 6
Output
python
Input
5 2
Output
phphp
Note
In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests.
Submitted Solution:
```
n, k = map(int,input().split())
line = ['q','w','e','r','t','y','u','i','o','p','a','s','d','f','g','h','j','k','l','z','x','c','v','b','n','m']
new = line[0:k]
print((''.join(new))*int(n//k) + ''.join(new[0:int(n%k)]))
``` | instruction | 0 | 83,072 | 18 | 166,144 |
Yes | output | 1 | 83,072 | 18 | 166,145 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Innokentiy decides to change the password in the social net "Contact!", but he is too lazy to invent a new password by himself. That is why he needs your help.
Innokentiy decides that new password should satisfy the following conditions:
* the length of the password must be equal to n,
* the password should consist only of lowercase Latin letters,
* the number of distinct symbols in the password must be equal to k,
* any two consecutive symbols in the password must be distinct.
Your task is to help Innokentiy and to invent a new password which will satisfy all given conditions.
Input
The first line contains two positive integers n and k (2 ≤ n ≤ 100, 2 ≤ k ≤ min(n, 26)) — the length of the password and the number of distinct symbols in it.
Pay attention that a desired new password always exists.
Output
Print any password which satisfies all conditions given by Innokentiy.
Examples
Input
4 3
Output
java
Input
6 6
Output
python
Input
5 2
Output
phphp
Note
In the first test there is one of the appropriate new passwords — java, because its length is equal to 4 and 3 distinct lowercase letters a, j and v are used in it.
In the second test there is one of the appropriate new passwords — python, because its length is equal to 6 and it consists of 6 distinct lowercase letters.
In the third test there is one of the appropriate new passwords — phphp, because its length is equal to 5 and 2 distinct lowercase letters p and h are used in it.
Pay attention the condition that no two identical symbols are consecutive is correct for all appropriate passwords in tests.
Submitted Solution:
```
alph = 'abcdefghijklmnopqrstuvwxyz'
import sys
n,k =[int(i) for i in sys.stdin.readlines()[0].split()]
password = ''
alph = alph[:k]
i = 0
while len(password) < n:
password = password + alph[i]
i = i+1
if i == k:
i = 0
print (password)
``` | instruction | 0 | 83,073 | 18 | 166,146 |
Yes | output | 1 | 83,073 | 18 | 166,147 |
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