message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p]. | instruction | 0 | 5,106 | 19 | 10,212 |
Tags: brute force, implementation
Correct Solution:
```
l = input().split()
suit = ['m', 'p', 's']
from collections import defaultdict
cnt = defaultdict(lambda : 0)
for i in range(3):
cnt[l[i]] += 1
mini = 10
for i in suit:
for j in range(1, 10):
# shuntsu
if j + 2 <= 9:
cn = 0
for k in range(3):
cn += int("{}{}".format(j+k, i) not in cnt)
mini = min(mini, cn)
# koutsu
mini = min(mini, 3 - cnt["{}{}".format(j, i)])
print(mini)
``` | output | 1 | 5,106 | 19 | 10,213 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p]. | instruction | 0 | 5,107 | 19 | 10,214 |
Tags: brute force, implementation
Correct Solution:
```
# your code goes here
a,b,c=input().split()
d={'m':[],'p':[],'s':[]}
d[a[1]].append(int(a[0]))
d[b[1]].append(int(b[0]))
d[c[1]].append(int(c[0]))
l=['m','p','s']
ans=2
for i in l:
if d[i]==[]:
continue
for j in range(1,10):
ans=min(ans,3-d[i].count(j))
if ans<0:
ans=0
if ans==0:
break
for j in range(1,8):
if j in d[i] and j+1 in d[i] and j+2 in d[i]:
ans=0
if ans==0:
break
if j in d[i] and j+1 in d[i] and j+2 not in d[i]:
ans=1
if j in d[i] and j+2 in d[i] and j+1 not in d[i]:
ans=1
if j not in d[i] and j+1 in d[i] and j+2 in d[i]:
ans=1
if ans==0:
break
print(ans)
``` | output | 1 | 5,107 | 19 | 10,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p]. | instruction | 0 | 5,108 | 19 | 10,216 |
Tags: brute force, implementation
Correct Solution:
```
s1,s2,s3 = input().split()
A = []
if (s1[1]==s2[1])and(s2[1]==s3[1]):
if (s1[0]==s2[0])and(s2[0]==s3[0]):
print(0)
exit()
A.append(int(s1[0]))
A.append(int(s2[0]))
A.append(int(s3[0]))
A.sort()
if (A[0]==A[1]-1) and(A[0]==A[2]-2):
print(0)
exit()
if (s1[1]==s2[1]):
if (s1[0]==s2[0]):
print(1)
exit()
if (int(s1[0])==(int(s2[0])+1))or(int(s1[0])==(int(s2[0])-1)):
print(1)
exit()
if (int(s1[0])==(int(s2[0])+2))or(int(s1[0])==(int(s2[0])-2)):
print(1)
exit()
if (s1[1] == s3[1]):
if (s1[0]==s3[0]):
print(1)
exit()
if (int(s1[0])==(int(s3[0])+1))or(int(s1[0])==(int(s3[0])-1)):
print(1)
exit()
if (int(s1[0])==(int(s3[0])+2))or(int(s1[0])==(int(s3[0])-2)):
print(1)
exit()
if (s2[1]==s3[1]):
if (s2[0]==s3[0]):
print(1)
exit()
if (int(s2[0])==(int(s3[0])+1))or(int(s2[0])==(int(s3[0])-1)):
print(1)
exit()
if (int(s2[0])==(int(s3[0])+2))or(int(s2[0])==(int(s3[0])-2)):
print(1)
exit()
print(2)
``` | output | 1 | 5,108 | 19 | 10,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p]. | instruction | 0 | 5,109 | 19 | 10,218 |
Tags: brute force, implementation
Correct Solution:
```
import collections
a=input().split()
a.sort()
if a[0]==a[1] and a[1]==a[2]:
print(0)
elif a[0][1]==a[1][1] and a[1][1]==a[2][1] and abs(int(a[1][0])-int(a[0][0]))==1 and abs(int(a[2][0])-int(a[1][0]))==1:
print("0")
elif a[0]==a[1] or a[1]==a[2] or a[2]==a[0]:
print("1")
elif a[0][1]==a[1][1] and (abs(int(a[1][0])-int(a[0][0]))==1 or abs(int(a[1][0])-int(a[0][0]))==2) :
print("1")
elif a[1][1]==a[2][1] and (abs(int(a[2][0])-int(a[1][0]))==1 or abs(int(a[2][0])-int(a[1][0]))==2):
print("1")
elif a[0][1]==a[2][1] and (abs(int(a[2][0])-int(a[0][0]))==1 or abs(int(a[2][0])-int(a[0][0]))==2):
print("1")
else:
print("2")
``` | output | 1 | 5,109 | 19 | 10,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p]. | instruction | 0 | 5,110 | 19 | 10,220 |
Tags: brute force, implementation
Correct Solution:
```
arr=list(map(str,input().split()))
num1=int(arr[0][0])
num2=int(arr[1][0])
num3=int(arr[2][0])
str1=arr[0][1]
str2=arr[1][1]
str3=arr[2][1]
if str1==str2 and str2==str3:
if num1==num2 and num2==num3:
print(0)
else:
arr2=[num1,num2,num3]
arr2=sorted(arr2)
if arr2[0]==arr2[1]-1 and arr2[1]==arr2[2]-1:
print(0)
else:
if 0<=abs(num1-num2)<=2:
print(1)
elif 0<=abs(num1-num3)<=2:
print(1)
elif 0<=abs(num2-num3)<=2:
print(1)
else:
print(2)
elif str1==str2:
if abs(num1-num2)==0 or abs(num1-num2)==1 or abs(num1-num2)==2:
print(1)
else:
print(2)
elif str1==str3:
if abs(num1-num3)==0 or abs(num1-num3)==1 or abs(num1-num3)==2:
print(1)
else:
print(2)
elif str2==str3:
if abs(num2-num3)==0 or abs(num2-num3)==1 or abs(num2-num3)==2:
print(1)
else:
print(2)
else:
print(2)
``` | output | 1 | 5,110 | 19 | 10,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
m={"m":[0]*9, "s":[0]*9, "p":[0]*9}
for s in input().split():
m[s[1]][int(s[0])-1]+=1
ans = 2
for c in "smp":
l = m[c]
if(max(l)>=2):
ans = min(ans, 3-max(l))
else:
for i in range(7):
sm = sum(l[i:i+3])
ans = min(ans, 3-sm)
print(ans)
``` | instruction | 0 | 5,111 | 19 | 10,222 |
Yes | output | 1 | 5,111 | 19 | 10,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
import bisect
import collections
import copy
import functools
import heapq
import itertools
import math
import random
import re
import sys
import time
import string
from typing import *
sys.setrecursionlimit(99999)
arr = list(input().split())
arr.sort()
ans = 3
cs = collections.Counter(arr)
def check(ap):
cp = collections.Counter(ap)
c = 0
for k, v in cs.items():
c += min(v, cp[k])
return 3 - c
for i in range(1, 10):
ans = min(ans, check([str(i) + 's', str(i) + 's', str(i) + 's']))
ans = min(ans, check([str(i) + 'p', str(i) + 'p', str(i) + 'p']))
ans = min(ans, check([str(i) + 'm', str(i) + 'm', str(i) + 'm']))
if i <= 7:
ans = min(ans,
check([str(i) + 's',
str(i + 1) + 's',
str(i + 2) + 's']))
ans = min(ans,
check([str(i) + 'p',
str(i + 1) + 'p',
str(i + 2) + 'p']))
ans = min(ans,
check([str(i) + 'm',
str(i + 1) + 'm',
str(i + 2) + 'm']))
print(ans)
``` | instruction | 0 | 5,112 | 19 | 10,224 |
Yes | output | 1 | 5,112 | 19 | 10,225 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
#include<bits/stdc++.h>
#include<stdio.h> //per fare input output con scanf and printf
#include<stdlib.h> //per fare qsort e bsearch
#include<string.h> // per fare strcpy(sarrivo, spartenza) strcat(str, aggiungo) strcmp(a,b) che da 0 se sono uguali
#include<math.h>
#include<algorithm>
#include<iostream>
#include<queue>
#include<stack>
#include<vector>
#include<map>
#using namespace std;
#define ld long double
#define ll long long int
#define vi vector <ll>
#define pi pair <ll, ll>
#define binary(v, el) binary_search((v).begin(), (v).end(), (el))
#define PB push_back
#define MP make_pair
#define F first
#define S second
x,y,z = list(map(str, input().strip().split()))
def cazzu(a,b,c):
if a==b==c:
return 1
else:
return 0
def shizu(a,b,c):
x = int(a[0])
y = int(b[0])
z = int(c[0])
l = [x,y,z]
l.sort()
if a[1]==b[1]==c[1] and l[1]-l[0] == 1 and l[2]-l[1]==1:
return 1
else:
return 0
if cazzu(x,y,z) or shizu(x,y,z):
print(0)
else:
flag = 0
for i in ['p','m','s']:
for j in ['1','2','3','4','5','6','7','8','9']:
w = j+i
if cazzu(x,y,w) or shizu(x,y,w) or cazzu(x,w,z) or shizu(x,w,z) or cazzu(w,y,z) or shizu(w,y,z):
flag = 1
if flag == 1:
print(1)
else:
print(2)
``` | instruction | 0 | 5,113 | 19 | 10,226 |
Yes | output | 1 | 5,113 | 19 | 10,227 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
'''
Auther: ghoshashis545 Ashis Ghosh
College: jalpaiguri Govt Enggineering College
'''
from os import path
import sys
from heapq import heappush,heappop
from functools import cmp_to_key as ctk
from collections import deque,defaultdict as dd
from bisect import bisect,bisect_left,bisect_right,insort,insort_left,insort_right
from itertools import permutations
from datetime import datetime
from math import ceil,sqrt,log,gcd
def ii():return int(input())
def si():return input().rstrip()
def mi():return map(int,input().split())
def li():return list(mi())
abc='abcdefghijklmnopqrstuvwxyz'
mod=1000000007
# mod=998244353
inf = float("inf")
vow=['a','e','i','o','u']
dx,dy=[-1,1,0,0],[0,0,1,-1]
def bo(i):
return ord(i)-ord('a')
file=1
def solve():
# for _ in range(ii()):
s = list(map(str,input().split()))
m = {}
m['s'] = []
m['p'] = []
m['m'] = []
for i in s:
m[i[1]].append(int(i[0]))
if len(set(s))==1:
print(0)
elif(len(set(s))==2):
print(1)
elif(len(m['s'])==3):
p = [m['s'][0],m['s'][1],m['s'][2]]
p.sort()
if p[1]-p[0]==1 and p[2]-p[1]==1:
print(0)
elif(p[1]-p[0]==2 or p[2]-p[1]==2 or p[1]-p[0]==1 or p[2]-p[1]==1):
print(1)
else:
print(2)
elif(len(m['p'])==3):
p = [m['p'][0],m['p'][1],m['p'][2]]
p.sort()
if p[1]-p[0]==1 and p[2]-p[1]==1:
print(0)
elif(p[1]-p[0]==2 or p[2]-p[1]==2 or p[1]-p[0]==1 or p[2]-p[1]==1):
print(1)
else:
print(2)
elif(len(m['m'])==3):
p = [m['m'][0],m['m'][1],m['m'][2]]
p.sort()
if p[1]-p[0]==1 and p[2]-p[1]==1:
print(0)
elif(p[1]-p[0]==2 or p[2]-p[1]==2 or p[1]-p[0]==1 or p[2]-p[1]==1):
print(1)
else:
print(2)
elif(len(m['s'])==2 and (abs(m['s'][0]-m['s'][1]) == 1 or abs(m['s'][0]-m['s'][1])==2)):
print(1)
elif(len(m['p'])==2 and (abs(m['p'][0]-m['p'][1]) == 1 or abs(m['p'][0]-m['p'][1])==2)):
print(1)
elif(len(m['m'])== 2 and (abs(m['m'][0]-m['m'][1]) == 1 or abs(m['m'][0]-m['m'][1])==2)):
print(1)
else:
print(2)
if __name__ =="__main__":
if(file):
if path.exists('input.txt'):
sys.stdin=open('input.txt', 'r')
sys.stdout=open('output.txt','w')
else:
input=sys.stdin.readline
solve()
``` | instruction | 0 | 5,114 | 19 | 10,228 |
Yes | output | 1 | 5,114 | 19 | 10,229 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
s=input().split()
l=[]
s.sort()
for i in s:
l.append(int(i[0]))
l.append(i[1])
if l[0]==l[2] and l[1]==l[3]:
if l[0]==l[4] and l[1]==l[5]:
print(0)
else:
print(1)
elif l[4]==l[2] and l[5]==l[3]:
print(1)
elif l[0]+1==l[2] and l[1]==l[3]:
if l[2]+1==l[4] and l[3]==l[5]:
print(0)
else:
print(1)
elif l[2]+1==l[4] and l[5]==l[3]:
print(1)
elif l[0]+2==l[4] and l[1]==l[5]:
print(1)
else:
print(2)
``` | instruction | 0 | 5,115 | 19 | 10,230 |
No | output | 1 | 5,115 | 19 | 10,231 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
def process1(n):
Dicts = {1:'0 A',
2:'1 B',
3:'2 A',
0:'1 A'}
mod = n%4
return Dicts[mod]
def tile3(n):
list = n.split(" ")
list = sorted(list)
print(list)
list2 = []
for i in range(len(list)):
count = 0
for j in range(len(list)):
if list[i]==list[j]:
count+=1
list2.append(count)
if max(list2)>=3: # TrΖ°α»ng hợp cΓ³ 3 tile giα»ng nhau
return 0
elif max(list2)==2 and min(list2)>=1: # TrΖ°α»ng hợp cΓ³ 2 tile giα»ng nhau
return 1
elif list2.count(1)>=3: # TrΖ°α»ng hợp cαΊ£ 3 tile khΓ‘c nhau
for i in list:
if int(list[0][0])+2==int(list[1][0])+1==int(list[2][0]) and list[0][1]==list[1][1]==list[2][1]:
return 0
elif (list[0][1]!=list[1][1] and list[1][1]!=list[2][1] and list[2][1] != list[0][1]) or \
(int(list[1][0])-int(list[0][0])>2) and (int(list[2][0])-int(list[1][0])>2):
return 2
elif (list[0][1]==list[1][1] and list[1][1]!=list[2][1] and int(list[0][0])+1==int(list[1][0])) or \
(list[1][1]==list[2][1] and list[1][1]!=list[0][1] and int(list[1][0])+1==int(list[2][0])):
return 1
else: return 1
n = input()
s = tile3(n)
print(s)
``` | instruction | 0 | 5,116 | 19 | 10,232 |
No | output | 1 | 5,116 | 19 | 10,233 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
arr = list(input().split())
x = arr[0]
y = arr[1]
z = arr[2]
if x==y==z:
print(0)
elif x[1] == y[1] == z[1]:
arr = []
arr.append(int(x[0]))
arr.append(int(y[0]))
arr.append(int(z[0]))
arr.sort()
#print(arr)
if arr[1]-arr[0]==arr[2]-arr[1]==1:
print(0)
elif arr[1]-arr[0]==1:
print(1)
elif arr[2]-arr[1]==1:
print(1)
elif arr[2]-arr[0]==1:
print(1)
else:
print(2)
elif x==y or y==z or z==x:
print(1)
elif x[1]==y[1] and abs(int(x[0])-int(y[0]))==1:
print(1)
elif y[1]==z[1] and abs(int(y[0])-int(z[0]))==1:
print(1)
elif z[1]==x[1] and abs(int(z[0])-int(x[0]))==1:
print(1)
else:
print(2)
``` | instruction | 0 | 5,117 | 19 | 10,234 |
No | output | 1 | 5,117 | 19 | 10,235 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Tokitsukaze is playing a game derivated from Japanese mahjong. In this game, she has three tiles in her hand. Each tile she owns is a suited tile, which means it has a suit (manzu, pinzu or souzu) and a number (a digit ranged from 1 to 9). In this problem, we use one digit and one lowercase letter, which is the first character of the suit, to represent a suited tile. All possible suited tiles are represented as 1m, 2m, β¦, 9m, 1p, 2p, β¦, 9p, 1s, 2s, β¦, 9s.
In order to win the game, she must have at least one mentsu (described below) in her hand, so sometimes she should draw extra suited tiles. After drawing a tile, the number of her tiles increases by one. She can draw any tiles she wants, including those already in her hand.
Do you know the minimum number of extra suited tiles she needs to draw so that she can win?
Here are some useful definitions in this game:
* A mentsu, also known as meld, is formed by a koutsu or a shuntsu;
* A koutsu, also known as triplet, is made of three identical tiles, such as [1m, 1m, 1m], however, [1m, 1p, 1s] or [1m, 4m, 7m] is NOT a koutsu;
* A shuntsu, also known as sequence, is made of three sequential numbered tiles in the same suit, such as [1m, 2m, 3m] and [5s, 7s, 6s], however, [9m, 1m, 2m] or [1m, 2p, 3s] is NOT a shuntsu.
Some examples:
* [2m, 3p, 2s, 4m, 1s, 2s, 4s] β it contains no koutsu or shuntsu, so it includes no mentsu;
* [4s, 3m, 3p, 4s, 5p, 4s, 5p] β it contains a koutsu, [4s, 4s, 4s], but no shuntsu, so it includes a mentsu;
* [5p, 5s, 9m, 4p, 1s, 7p, 7m, 6p] β it contains no koutsu but a shuntsu, [5p, 4p, 6p] or [5p, 7p, 6p], so it includes a mentsu.
Note that the order of tiles is unnecessary and you can assume the number of each type of suited tiles she can draw is infinite.
Input
The only line contains three strings β the tiles in Tokitsukaze's hand. For each string, the first character is a digit ranged from 1 to 9 and the second character is m, p or s.
Output
Print a single integer β the minimum number of extra suited tiles she needs to draw.
Examples
Input
1s 2s 3s
Output
0
Input
9m 9m 9m
Output
0
Input
3p 9m 2p
Output
1
Note
In the first example, Tokitsukaze already has a shuntsu.
In the second example, Tokitsukaze already has a koutsu.
In the third example, Tokitsukaze can get a shuntsu by drawing one suited tile β 1p or 4p. The resulting tiles will be [3p, 9m, 2p, 1p] or [3p, 9m, 2p, 4p].
Submitted Solution:
```
a,b,c = map(str, input().split())
a = a[1]+a[0]
b = b[1]+b[0]
c = c[1]+c[0]
n = [a,b,c]
m = [0]*9
p = [0]*9
s = [0]*9
for i in range(3):
if(n[i][0]=="m"):
m[int(n[i][1])-1]+=1
if(n[i][0]=="p"):
p[int(n[i][1])-1]+=1
if(n[i][0]=="s"):
s[int(n[i][1])-1]+=1
ans = 2
#print(m,p,s)
for i in range(9):
if(3-m[i]<ans):
ans = 3-m[i]
if(0<i and i<8):
if(3-m[i-1]-m[i]-m[i+1]<ans):
ans = 3-m[i-1]-m[i]-m[i+1]
if(3-s[i]<ans):
ans = 3-s[i]
if(0<i and i<8):
if(3-s[i-1]-s[i]-s[i+1]<ans):
#print(23)
ans = 3-s[i-1]-s[i]-s[i+1]
#print(ans, 9)
if(3-p[i]<ans):
ans = 3-p[i]
#print(3-s[i-1]-s[i]-s[i+1])
if(0<i and i<8):
if(3-p[i-1]-p[i]-p[i+1]<ans):
ans = 3-p[i-1]-p[i]-p[i+1]
print(ans)
``` | instruction | 0 | 5,118 | 19 | 10,236 |
No | output | 1 | 5,118 | 19 | 10,237 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,269 | 19 | 10,538 |
Tags: greedy, math, number theory
Correct Solution:
```
import sys
input=sys.stdin.readline
for _ in range(int(input())):
a,b=map(int,input().split())
if(a==b):
print(0,0)
else:
dif=abs(a-b)
mi=min(a,b)
rem=mi%dif
print(dif,min(rem,abs(dif-rem)))
``` | output | 1 | 5,269 | 19 | 10,539 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,270 | 19 | 10,540 |
Tags: greedy, math, number theory
Correct Solution:
```
import sys
import math
#sys.stdin=open('input.txt','r')
#sys.stdout=open('output.txt','w')
def solve():
#n=int(input())
a,b=map(int,input().split())
if(a==b):
print("0 0")
else:
r=abs(a-b)
if(math.gcd(a,b)==r):
print(r,0)
else:
e=a//r
y1=((e+1)*r)-a
y2=abs(((e)*r)-a)
print(abs(a-b),min(y1,y2))
t=int(input())
while(t!=0):
solve()
t-=1
``` | output | 1 | 5,270 | 19 | 10,541 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,271 | 19 | 10,542 |
Tags: greedy, math, number theory
Correct Solution:
```
from math import *
t=int(input())
for i in range(t):
temp=input().split()
x=int(temp[0]);y=int(temp[1])
gre=abs(x-y)
if(gre!=0):
num = min(x%gre,y%gre,gre-x%gre,gre-x%gre)
else:
num = 0
print(str(gre)+" "+str(num))
``` | output | 1 | 5,271 | 19 | 10,543 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,272 | 19 | 10,544 |
Tags: greedy, math, number theory
Correct Solution:
```
for _ in range(int(input())):
a,b=map(int,input().split())
x=min(a,b)
y=max(a,b)
if x==y:
print("0 0")
else:
print(y-x, end=" ")
b=y-x
a=x%b
print(min(a, b-a))
``` | output | 1 | 5,272 | 19 | 10,545 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,273 | 19 | 10,546 |
Tags: greedy, math, number theory
Correct Solution:
```
t = int(input())
for _ in range(t):
a, b = map(int,input().split())
if(a == b):
print('0 0')
elif(abs(a-b) == 1):
print('1 0')
elif(a==0 and b!=0):
print(str(b)+" 0")
elif(b==0 and a!=0):
print(str(a)+" 0")
else:
exc = abs(a-b)
if(a < b):
k = 0
while(k < a):
pre = k
k = k + exc
if((a-pre) > (k-a)):
print(str(exc)+" "+str(k-a))
else:
print(str(exc)+" "+str(a-pre))
else:
k = 0
while(k < b):
pre = k
k = k + exc
if((b-pre) > (k-b)):
print(str(exc)+" "+str(k-b))
else:
print(str(exc)+" "+str(b-pre))
``` | output | 1 | 5,273 | 19 | 10,547 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,274 | 19 | 10,548 |
Tags: greedy, math, number theory
Correct Solution:
```
t=int(input())
for i in range (t):
a,b=map(int,input().strip().split())
if a==b:
print(0,0)
elif abs(a-b)==1:
print(1,0)
else:
gcd=abs(a-b)
minimum=min(a,b)
temp=minimum//gcd
prv=(minimum-(temp*gcd))
nxt=((temp+1)*gcd)-minimum
print(gcd,min(nxt,prv))
``` | output | 1 | 5,274 | 19 | 10,549 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,275 | 19 | 10,550 |
Tags: greedy, math, number theory
Correct Solution:
```
from sys import stdin
input = stdin.readline
t = int(input())
for _ in range(t):
a, b = [int(x) for x in input().split()]
d = abs(a - b)
if d == 0:
print(0, 0)
continue
minus_count = a % d
plus_count = d - minus_count
if min(a, b) - minus_count < 0:
print(d, plus_count)
continue
if minus_count < plus_count:
print(d, minus_count)
else:
print(d, plus_count)
``` | output | 1 | 5,275 | 19 | 10,551 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Welcome to Rockport City!
It is time for your first ever race in the game against Ronnie. To make the race interesting, you have bet a dollars and Ronnie has bet b dollars. But the fans seem to be disappointed. The excitement of the fans is given by gcd(a,b), where gcd(x, y) denotes the [greatest common divisor (GCD)](https://en.wikipedia.org/wiki/Greatest_common_divisor) of integers x and y. To make the race more exciting, you can perform two types of operations:
1. Increase both a and b by 1.
2. Decrease both a and b by 1. This operation can only be performed if both a and b are greater than 0.
In one move, you can perform any one of these operations. You can perform arbitrary (possibly zero) number of moves. Determine the maximum excitement the fans can get and the minimum number of moves required to achieve it.
Note that gcd(x,0)=x for any x β₯ 0.
Input
The first line of input contains a single integer t (1β€ tβ€ 5β
10^3) β the number of test cases.
The first and the only line of each test case contains two integers a and b (0β€ a, bβ€ 10^{18}).
Output
For each test case, print a single line containing two integers.
If the fans can get infinite excitement, print 0 0.
Otherwise, the first integer must be the maximum excitement the fans can get, and the second integer must be the minimum number of moves required to achieve that excitement.
Example
Input
4
8 5
1 2
4 4
3 9
Output
3 1
1 0
0 0
6 3
Note
For the first test case, you can apply the first operation 1 time to get a=9 and b=6. It can be shown that 3 is the maximum excitement possible.
For the second test case, no matter how many operations you apply, the fans will always have an excitement equal to 1. Since the initial excitement is also 1, you don't need to apply any operation.
For the third case, the fans can get infinite excitement by applying the first operation an infinite amount of times.
For the fourth test case, you can apply the second operation 3 times to get a=0 and b=6. Since, gcd(0,6)=6, the fans will get an excitement of 6. | instruction | 0 | 5,276 | 19 | 10,552 |
Tags: greedy, math, number theory
Correct Solution:
```
from math import ceil
for i in range(int(input())):
a,b=map(int,input().split())
if a==b:
print(0,0)
else:
mgcd=max(a,b)-min(a,b)
temp=min(a,b)
x=ceil(temp/mgcd)
z=temp//mgcd
y=(x*mgcd)-temp
y2=temp-(z*mgcd)
ans=min(temp,y,y2)
#print(temp,mgcd,x,y)
print(mgcd,ans)
``` | output | 1 | 5,276 | 19 | 10,553 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,441 | 19 | 10,882 |
Tags: implementation
Correct Solution:
```
n=int(input())
for i in range(20,-1,-1):
if(2**i<=n):
print(i+1,end=' ')
n-=2**i
``` | output | 1 | 5,441 | 19 | 10,883 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,442 | 19 | 10,884 |
Tags: implementation
Correct Solution:
```
n = bin(int(input()))[2:]
l = len(n)
for i in n:
if i == "1":
print(l, end = " ")
l -= 1
``` | output | 1 | 5,442 | 19 | 10,885 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,443 | 19 | 10,886 |
Tags: implementation
Correct Solution:
```
L=[1];
for i in range(2,int(input())+1):
L.append(1);
a=len(L)-1;
while(a>0):
if L[a]==L[a-1]:
L[a-1]=L[a]+1;
L[a:a+1]=[];
else:
break
a=len(L)-1;
if a==0:
break
for i in L:
print(i,end=' ')
``` | output | 1 | 5,443 | 19 | 10,887 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,444 | 19 | 10,888 |
Tags: implementation
Correct Solution:
```
n = int(input())
l = "{:b}".format(n)
r = []
for i, c in enumerate(l):
if c=="1":
r += [str(len(l)-i)]
print(" ".join(r))
``` | output | 1 | 5,444 | 19 | 10,889 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,445 | 19 | 10,890 |
Tags: implementation
Correct Solution:
```
n = int(input())
while n != 0:
a = 1
k = 0
while a <= n:
a *= 2
k += 1
a //= 2
print(k,end=' ')
n -= a
``` | output | 1 | 5,445 | 19 | 10,891 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,446 | 19 | 10,892 |
Tags: implementation
Correct Solution:
```
n = int(input())
a = []
for i in range(n):
a.append(1)
while len(a) > 1 and a[len(a) - 1] == a[len(a) - 2]:
a.pop()
a[len(a) - 1] += 1
for i in a:
print(i, end = ' ')
``` | output | 1 | 5,446 | 19 | 10,893 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,447 | 19 | 10,894 |
Tags: implementation
Correct Solution:
```
def toBin(num):
buf = ''
while True:
num, rest = num // 2, num - (num // 2 * 2)
buf = str(rest)+buf
if num == 0:
break
return int(buf)
def main():
num = int(input())
num_bin = toBin(num)
num_bin_str = str(num_bin)
num_bin_str_len = len(num_bin_str)
solutions = []
for pos in range(0, num_bin_str_len):
if num_bin_str[pos] == "1":
solutions.append(str(num_bin_str_len - pos))
print(" ".join(solutions))
if __name__ == "__main__":
main()
``` | output | 1 | 5,447 | 19 | 10,895 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4 | instruction | 0 | 5,448 | 19 | 10,896 |
Tags: implementation
Correct Solution:
```
n=int(input())
arr=[0]*n
i=1
for i in range(n):
arr[i]=n%2
n//=2
for j in range(i,-1,-1):
if(arr[j]!=0):
print(j+1,end=" ")
``` | output | 1 | 5,448 | 19 | 10,897 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
n=int(input())
b=list(bin(n))[2:]
b.reverse()
s=str()
for i in range(len(b)):
if b[i]=="1":
s=str(i+1)+" "+s
print(s)
``` | instruction | 0 | 5,449 | 19 | 10,898 |
Yes | output | 1 | 5,449 | 19 | 10,899 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
__author__ = 'Admin'
n = int(input())
m = []
for i in range(n):
m.append(1)
for j in range(i):
if m[len(m) - 1] == m[len(m) - 2] and len(m) > 1:
m[len(m) - 2] += 1
m.pop(m.index(m[len(m) - 1]))
else:
break
print(*m)
``` | instruction | 0 | 5,450 | 19 | 10,900 |
Yes | output | 1 | 5,450 | 19 | 10,901 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
n = int(input());
k = 1
a = []
while n > 0 :
if n & 1 :
a.append(k)
k += 1
n = n >> 1
a.reverse()
ans = ""
for i in range(len(a)) :
ans += str(a[i]) + " "
print(ans)
``` | instruction | 0 | 5,451 | 19 | 10,902 |
Yes | output | 1 | 5,451 | 19 | 10,903 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
n=int(input())
d=[]
for i in range(n):
d.append(1)
if len(d)>=2:
while(d[-1]==d[-2]):
if d[-1]==d[-2]:
r=d[-1]+1
d.append(r)
d.pop(-2)
d.pop(-2)
if len(d)<2:
break
print(*d)
``` | instruction | 0 | 5,452 | 19 | 10,904 |
Yes | output | 1 | 5,452 | 19 | 10,905 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
f=lambda:map(int,input().split())
n=int(input())
s='1 '*n
for i in range(1,n//2):
s=s.replace(str(i)+' '+str(i),str(i+1))
print(s)
``` | instruction | 0 | 5,453 | 19 | 10,906 |
No | output | 1 | 5,453 | 19 | 10,907 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
n = int(input())
s ="1"
while n>1:
s+="1"
n-=1
while len(s)!=len(set(s)):
if s[0] == s[1]:
s = s.replace(s[0]*2,str(int(s[0])+1))
print(s)
``` | instruction | 0 | 5,454 | 19 | 10,908 |
No | output | 1 | 5,454 | 19 | 10,909 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
import math
n = int(input())
k = math.log2(n)
if n % 2 == 0:
print(k + 1)
else:
print(k,' ',1)
``` | instruction | 0 | 5,455 | 19 | 10,910 |
No | output | 1 | 5,455 | 19 | 10,911 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Your friend recently gave you some slimes for your birthday. You have n slimes all initially with value 1.
You are going to play a game with these slimes. Initially, you put a single slime by itself in a row. Then, you will add the other n - 1 slimes one by one. When you add a slime, you place it at the right of all already placed slimes. Then, while the last two slimes in the row have the same value v, you combine them together to create a slime with value v + 1.
You would like to see what the final state of the row is after you've added all n slimes. Please print the values of the slimes in the row from left to right.
Input
The first line of the input will contain a single integer, n (1 β€ n β€ 100 000).
Output
Output a single line with k integers, where k is the number of slimes in the row after you've finished the procedure described in the problem statement. The i-th of these numbers should be the value of the i-th slime from the left.
Examples
Input
1
Output
1
Input
2
Output
2
Input
3
Output
2 1
Input
8
Output
4
Note
In the first sample, we only have a single slime with value 1. The final state of the board is just a single slime with value 1.
In the second sample, we perform the following steps:
Initially we place a single slime in a row by itself. Thus, row is initially 1.
Then, we will add another slime. The row is now 1 1. Since two rightmost slimes have the same values, we should replace these slimes with one with value 2. Thus, the final state of the board is 2.
In the third sample, after adding the first two slimes, our row is 2. After adding one more slime, the row becomes 2 1.
In the last sample, the steps look as follows:
1. 1
2. 2
3. 2 1
4. 3
5. 3 1
6. 3 2
7. 3 2 1
8. 4
Submitted Solution:
```
import math
n = int(input())
log = math.log(n,2)
floor = math.floor(log)
cnt = 0
arr = []
for i in range(floor,-1,-1):
a = 2**i
if cnt+a>n:
continue
else:
cnt += a
arr.append(a)
if cnt==n:
break
print(*arr)
``` | instruction | 0 | 5,456 | 19 | 10,912 |
No | output | 1 | 5,456 | 19 | 10,913 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,597 | 19 | 11,194 |
"Correct Solution:
```
A = [[int(x) for x in input().split()] for i in range(3)]
n = int(input())
B = set(int(input()) for i in range(n))
res = False
for row in A:
if all(x in B for x in row):
res = True
for j in range(3):
if all(A[i][j] in B for i in range(3)):
res = True
if all(A[i][i] in B for i in range(3)):
res = True
if all(A[i][2 - i] in B for i in range(3)):
res = True
print("Yes" if res else "No")
``` | output | 1 | 5,597 | 19 | 11,195 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,598 | 19 | 11,196 |
"Correct Solution:
```
al = [list(map(int, input().split())) for i in range(3)]
al = sum(al, [])
n = int(input())
bl = [int(input()) for i in range(n)]
check = [0 for i in range(9)]
for b in bl:
if b in al:
check[al.index(b)] = 1
if [1,1,1] in [check[:3], check[3:6], check[6:], check[0:7:3], check[1:8:3], check[2:9:3], check[0:9:4], check[2:8:2]]:
print("Yes")
else:
print("No")
``` | output | 1 | 5,598 | 19 | 11,197 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,599 | 19 | 11,198 |
"Correct Solution:
```
Bingo = [ list(map(int,input().split())) for i in range(3)]
n = int(input())
num = [int(input()) for i in range(n)]
Bingo.append([Bingo[0][0] , Bingo[1][1],Bingo[2][2] ])
Bingo.append([Bingo[0][2] , Bingo[1][1],Bingo[2][0] ])
for k in range(3):
Bingo.append([Bingo[0][k] , Bingo[1][k],Bingo[2][k] ])
k=0
re = 'No'
for l in range(len(Bingo)):
if len(list(set(num) & set(Bingo[l]))) == 3:
re = 'Yes'
break
print(re)
``` | output | 1 | 5,599 | 19 | 11,199 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,600 | 19 | 11,200 |
"Correct Solution:
```
A=[0]*9
for i in range(3):
A[i*3:i*3+3]=input().split()
for i in range(int(input())):
b=input()
for j in range(9):
if A[j]==b:
A[j]="0"
s="012345678036147258048246"
a=f=0
for i in range(24):
a+=int(A[int(s[i])])
if i%3==2:
if a==0:
f+=1
a=0
if f>0:
print("Yes")
else:
print("No")
``` | output | 1 | 5,600 | 19 | 11,201 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,601 | 19 | 11,202 |
"Correct Solution:
```
A = []
for _ in range(3):
for e in list(map(int, input().split())):
A.append(e)
N = int(input())
for _ in range(N):
n = int(input())
if n in A:
A[A.index(n)] = 0
patterns = [
[0, 1, 2],
[3, 4, 5],
[6, 7, 8],
[0, 3, 6],
[1, 4, 7],
[2, 5, 8],
[0, 4, 8],
[2, 4, 6]
]
for pattern in patterns:
if not any([A[e] for e in pattern]):
print('Yes')
exit()
print('No')
``` | output | 1 | 5,601 | 19 | 11,203 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,602 | 19 | 11,204 |
"Correct Solution:
```
a = []
for i in range(3):
a += list(map(int, input().split()))
bg = [False]*9
n = int(input())
for i in range(n):
b = int(input())
if b in a:
bg[a.index(b)] = True
num = [[0,1,2],[3,4,5],[6,7,8],[0,3,6],[1,4,7],[2,5,8],[0,4,8],[2,4,6]]
for x, y, z in num:
if bg[x] and bg[y] and bg[z]:
print('Yes')
exit()
print('No')
``` | output | 1 | 5,602 | 19 | 11,205 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,603 | 19 | 11,206 |
"Correct Solution:
```
B=[]
for _ in range(3):B+=list(map(int,input().split()))
S=set(int(input()) for _ in range(int(input())))
for i,b in enumerate(B):
if b in S:B[i]=0
if B[0]+B[1]+B[2]==0 or B[3]+B[4]+B[5]==0 or B[6]+B[7]+B[8]==0 or B[0]+B[3]+B[6]==0 or B[1]+B[4]+B[7]==0 or B[2]+B[5]+B[8]==0 or B[0]+B[4]+B[8]==0 or B[2]+B[4]+B[6]==0:
print('Yes')
else:print('No')
``` | output | 1 | 5,603 | 19 | 11,207 |
Provide a correct Python 3 solution for this coding contest problem.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes | instruction | 0 | 5,604 | 19 | 11,208 |
"Correct Solution:
```
*inputs, = map(int, open(0).read().split())
A = inputs[:9]
B = inputs[9:]
C = [0] * 9
for b in B:
if b in A:
C[A.index(b)] = 1
if any([
all(C[:3]), all(C[3:6]), all(C[6:]),
all(C[::3]), all(C[1::3]), all(C[2::3]),
all([C[0], C[4], C[8]]), all([C[2], C[4], C[6]])
]):
print('Yes')
else:
print('No')
``` | output | 1 | 5,604 | 19 | 11,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
A=[]
for i in [0]*3:
A+=list(map(int,input().split()))
N=int(input())
B=[0]*9
for i in range(N):
i=int(input())
if i in A:
B[A.index(i)]=1
res=0
for i in range(3):
res+=B[3*i]*B[3*i+1]*B[3*i+2]
res+=B[i]*B[i+3]*B[i+6]
res+=B[0]*B[4]*B[8]+B[2]*B[4]*B[6]
print(['No','Yes'][res>0])
``` | instruction | 0 | 5,605 | 19 | 11,210 |
Yes | output | 1 | 5,605 | 19 | 11,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
f=lambda a:any(all(b)for b in a)|all(a[i][i]for i in(0,1,2))
*t,=map(int,open(0).read().split())
a=t[:9]
s=eval('[0]*3,'*3)
for b in t[10:]:
if b in a:
i=a.index(b)
s[i//3][i%3]=1
print('NYoe s'[f(s)|f([t[::-1]for t in zip(*s)])::2])
``` | instruction | 0 | 5,606 | 19 | 11,212 |
Yes | output | 1 | 5,606 | 19 | 11,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
import sys
A=[]
for a in range(3):
l=[int(i) for i in input().split()]
A.extend(l)
f=[0]*9
for i in range(int(input())):
b=int(input())
if b in A:
f[A.index(b)]=1
#print(f)
p=[[0,1,2],[3,4,5],[6,7,8],[0,3,6],[1,4,7],[2,5,8],[0,4,8],[2,4,6]]
for i in p:
if all(f[x]==1 for x in i):
print("Yes")
sys.exit()
print("No")
``` | instruction | 0 | 5,607 | 19 | 11,214 |
Yes | output | 1 | 5,607 | 19 | 11,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
a=[list(map(int,input().split())) for _ in range(3)]
f=[[0]*3 for _ in range(3)]
for _ in range(int(input())):
x=int(input())
for i in range(3):
for j in range(3):
if x==a[i][j]:
f[i][j]=1
ans=0
for i in range(3):
if all(f[i][j] for j in range(3)) or all(f[j][i] for j in range(3)):
ans=1
if f[0][0]==f[1][1]==f[2][2]==1 or f[0][2]==f[1][1]==f[2][0]==1:
ans=1
print("Yes" if ans else "No")
``` | instruction | 0 | 5,608 | 19 | 11,216 |
Yes | output | 1 | 5,608 | 19 | 11,217 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
A = [[0,0,0],[0,0,0],[0,0,0]]
for i in range(3):
A[i][0],A[i][1],A[i][2] = map(int, input().split())
N = int(input())
L = list()
Al = [i for x in A for i in x]
have = []
for _ in range(N):
a = int(input())
if a in Al:
have.append(a)
if len(have)>=4:
print("Yes")
else:
print("No")
``` | instruction | 0 | 5,609 | 19 | 11,218 |
No | output | 1 | 5,609 | 19 | 11,219 |
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