message stringlengths 2 67k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 463 109k | cluster float64 19 19 | __index_level_0__ int64 926 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
import itertools
# ここを参考にした
# https://note.nkmk.me/python-list-index/
# def my_index(l, x, default=False):
# if x in l:
# return l.index(x)
# else:
# return default
Bingo_index=[]
master =[]
# 二次元リスト
Row = 3
List=[[int(j) for j in input().split()] for i in range(Row)]
# 二次元リストを一次元リストに
dim_List=list(itertools.chain.from_iterable(List))
# print(dim_List)
# ビンゴ表作成終わり
n = int(input())
# print(n)
Num=[int(input()) for i in range(n)]
# print(Num)
# print(set(dim_List) & set(Num))
# 入力処理ここまで
Common = list(set(dim_List) & set(Num))
# print(Common)
# https://teratail.com/questions/156336
# リストに要素をコピーする方法↑
for a in Common:
# if(my_index(dim_List,a) == False):
# print('No')
Bingo_index.append(dim_List.index(a))
#
# print('Bingo_indexは')
# print(Bingo_index)
# print(sorted(Bingo_index))
if len(Bingo_index) == 0:
print('No')
exit()
# Bingo_indexにビンゴしてるdim_Listの要素のインデックスが入ってる
answer1 = len(list(set([0, 1, 2])&set(Bingo_index)))
answer2 = len(list(set([3, 4, 5])&set(Bingo_index)))
answer3 = len(list(set([6, 7, 8])&set(Bingo_index)))
answer4 = len(list(set([0, 4, 8])&set(Bingo_index)))
answer5 = len(list(set([0, 3, 6])&set(Bingo_index)))
answer6 = len(list(set([1, 4, 7])&set(Bingo_index)))
answer7 = len(list(set([2, 5, 8])&set(Bingo_index)))
# Bingo_indexの中身にとanswer1~7の組み合わせがあるかどうか調べる
# 全部のアンサーとandをとってどれかの長さが3の奴があればyes出力や
master.append(answer1)
master.append(answer2)
master.append(answer3)
master.append(answer4)
master.append(answer5)
master.append(answer6)
master.append(answer7)
# print(master)
# print(master.count('3'))
for e in master:
if e ==3:
print('Yes')
exit()
``` | instruction | 0 | 5,610 | 19 | 11,220 |
No | output | 1 | 5,610 | 19 | 11,221 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
A=[list(map(int,input().split())) for i in range(3)]
N=int(input())
b=[]
for i in range(N):
b.append(int(input()))
for i in range(3):
for j in range(3):
for x in range(N):
if A[i][j]==b[x]:
A[i][j]=0
for i in range(3):
if A[i][0]==0 and A[i][1]==0 and A[i][2]==0:
print("Yes")
break
for i in range(3):
if A[0][i]==0 and A[1][i]==0 and A[2][i]==0:
print("Yes")
break
if A[0][0] == 0 and A[1][1] == 0 and A[2][2] == 0:
print("Yes")
break
if A[0][2] == 0 and A[1][1] == 0 and A[2][0] == 0:
print("Yes")
break
print("No")
``` | instruction | 0 | 5,611 | 19 | 11,222 |
No | output | 1 | 5,611 | 19 | 11,223 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
We have a bingo card with a 3\times3 grid. The square at the i-th row from the top and the j-th column from the left contains the number A_{i, j}.
The MC will choose N numbers, b_1, b_2, \cdots, b_N. If our bingo sheet contains some of those numbers, we will mark them on our sheet.
Determine whether we will have a bingo when the N numbers are chosen, that is, the sheet will contain three marked numbers in a row, column, or diagonal.
Constraints
* All values in input are integers.
* 1 \leq A_{i, j} \leq 100
* A_{i_1, j_1} \neq A_{i_2, j_2} ((i_1, j_1) \neq (i_2, j_2))
* 1 \leq N \leq 10
* 1 \leq b_i \leq 100
* b_i \neq b_j (i \neq j)
Input
Input is given from Standard Input in the following format:
A_{1, 1} A_{1, 2} A_{1, 3}
A_{2, 1} A_{2, 2} A_{2, 3}
A_{3, 1} A_{3, 2} A_{3, 3}
N
b_1
\vdots
b_N
Output
If we will have a bingo, print `Yes`; otherwise, print `No`.
Examples
Input
84 97 66
79 89 11
61 59 7
7
89
7
87
79
24
84
30
Output
Yes
Input
41 7 46
26 89 2
78 92 8
5
6
45
16
57
17
Output
No
Input
60 88 34
92 41 43
65 73 48
10
60
43
88
11
48
73
65
41
92
34
Output
Yes
Submitted Solution:
```
a=[list(map(int,input().split())) for _ in range(3)]
n=int(input())
b=[int(input()) for _ in range(n)]
maze=[["*" for i in range(3)] for _ in range(3)]
for i in range(n):
for j in range(3):
for k in range(3):
if b[i]==a[j][k]:
maze[j][k]="#"
for i in range(3):
f=1
for j in range(3):
if maze[i][j]!="#":
f=0
break
if f:
print("Yes")
exit()
for i in range(3):
fa=1
if maze[i][i]!="#":
fa=0
break
if fa:
print("Yes")
exit()
for i in range(3):
fe=1
if maze[i][2-i]!="#":
fe=0
break
if fe:
print("Yes")
exit()
print("No")
``` | instruction | 0 | 5,612 | 19 | 11,224 |
No | output | 1 | 5,612 | 19 | 11,225 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,629 | 19 | 11,258 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
dp = [[0 for _ in range(n+1)] for _ in range(n+1)]
#dp[l][r]: 左l個右r個取ったところからの前-後max
for i in range(n):
dp[i][n-1-i] = a[i]
for x in range(n-2, -1, -1):
for y in range(x+1):
l, r = y, x-y
dp[l][r] = max(-dp[l+1][r] + a[l], -dp[l][r+1] + a[-(r+1)])
print(dp[0][0])
``` | output | 1 | 5,629 | 19 | 11,259 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,630 | 19 | 11,260 |
"Correct Solution:
```
N = int(input())
*A, = map(int, input().split())
dp = [[0] * (N+1) for _ in range(N+1)]
for n in range(1, N+1):
for i in range(N-n+1):
j = i + n
if (N - n) % 2 == 0: # first player
dp[i][j] = max(dp[i+1][j] + A[i], dp[i][j-1] + A[j-1])
else: # second player
dp[i][j] = min(dp[i+1][j] - A[i], dp[i][j-1] - A[j-1])
print(dp[0][N])
``` | output | 1 | 5,630 | 19 | 11,261 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,631 | 19 | 11,262 |
"Correct Solution:
```
n=int(input())
a=[int(i) for i in input().split()]
dp=[[0]*(n+1) for i in range(n+1)]
for w in range(1,n+1):
#for w in range(1,3,1):
# print(dp[1])
for l in range(n-w+1):
r=l+w
dpl=-dp[l+1][r]+a[l]
dpr=-dp[l][r-1]+a[r-1]
dp[l][r]=max(dpl,dpr)
#print()
#for i in dp:
# print(i)
print(dp[0][n])
``` | output | 1 | 5,631 | 19 | 11,263 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,632 | 19 | 11,264 |
"Correct Solution:
```
def fun(i,j):
# print(i,j)
if i>j or i>=n or j<0:
return 0
elif i==j:
dp[i][j]=arr[i]
return dp[i][j]
else:
if dp[i][j]==0:
dp[i][j]=max(arr[i]+min(fun(i+1,j-1),fun(i+2,j)),arr[j]+min(fun(i+1,j-1),fun(i,j-2)))
return dp[i][j]
n=int(input())
dp=[0]*n
for i in range(n):
dp[i]=[0]*n
arr=list(map(int,input().split()))
for i in range(n-1,-1,-1):
for j in range(i,n,1):
if i==j:
dp[i][j]=arr[i]
else:
dp[i][j]=max(arr[i]-dp[i+1][j],arr[j]-dp[i][j-1])
# print(dp[i])
print(dp[0][n-1])
# print(2*fun(0,n-1)-sum(arr))
``` | output | 1 | 5,632 | 19 | 11,265 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,633 | 19 | 11,266 |
"Correct Solution:
```
dp={}
n=int(input())
nums=list(map(int,input().split()))
#print(dp)
#print(recursive(0,n-1))
dp=[[0]*(n+1) for _ in range(n+1)]
for i in range(n-1,-1,-1):
for j in range(i,n,1):
dp[i][j]=max(nums[i]-dp[i+1][j],nums[j]-dp[i][j-1])
print(dp[0][n-1])
``` | output | 1 | 5,633 | 19 | 11,267 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,634 | 19 | 11,268 |
"Correct Solution:
```
N=int(input())
a=[int(i) for i in input().split()]
dp=[[0]*(N+1) for i in range(N+1)]
for d in range(1,N+1):
for i in range(N+1-d):
if (N-d)%2==0:
dp[i][i+d]=max(dp[i+1][i+d]+a[i],dp[i][i+d-1]+a[i+d-1])
if (N-d)%2==1:
dp[i][i+d]=min(dp[i+1][i+d],dp[i][i+d-1])
print(2*dp[0][N]-sum(a))
``` | output | 1 | 5,634 | 19 | 11,269 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,635 | 19 | 11,270 |
"Correct Solution:
```
n = int(input())
a = list(map(int, input().split()))
dp = [[0] * (n-t+1) for t in range(1, n+1)]
dp[0] = a
for t in range(1, n):
for i in range(n-t):
dp[t][i] = max(-dp[t-1][i+1] + a[i], -dp[t-1][i] + a[i+t])
print(dp[n-1][0])
``` | output | 1 | 5,635 | 19 | 11,271 |
Provide a correct Python 3 solution for this coding contest problem.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2 | instruction | 0 | 5,636 | 19 | 11,272 |
"Correct Solution:
```
n = int(input())
*A, = map(int, input().split())
DP = [[0 for j in range(n+1)] for i in range(n+1)]
for l in range(1, n+1):
for i in range(n-l+1):
DP[i][i+l] = max(A[i]-DP[i+1][i+l], A[i+l-1]-DP[i][i+l-1])
print(DP[0][n])
``` | output | 1 | 5,636 | 19 | 11,273 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
N = int(input())
a = list(map(int, input().split()))
dp = [[0]*N for _ in range(N)]
if N%2 == 0:
for i in range(N):
dp[0][i] = -a[i]
else:
for i in range(N):
dp[0][i] = a[i]
for i in range(1, N):
for j in range(N-i):
if (N-i)%2 == 1:
dp[i][j] = max(dp[i-1][j]+a[i+j], dp[i-1][j+1]+a[j])
else:
dp[i][j] = min(dp[i-1][j]-a[i+j], dp[i-1][j+1]-a[j])
print(dp[-1][0])
``` | instruction | 0 | 5,637 | 19 | 11,274 |
Yes | output | 1 | 5,637 | 19 | 11,275 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
n = int(input())
A = list(map(int, input().split()))
dp = [[0]*(n+1) for i in range(n+1)]
for d in range(1, n+1):
for i in range(n+1-d):
j = i+d
if (n-d)%2 == 0:
dp[i][j] = max(dp[i+1][j]+A[i], dp[i][j-1]+A[j-1])
else:
dp[i][j] = min(dp[i+1][j]-A[i], dp[i][j-1]-A[j-1])
print(dp[0][n])
``` | instruction | 0 | 5,638 | 19 | 11,276 |
Yes | output | 1 | 5,638 | 19 | 11,277 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
#EDPC L メモ化再帰じゃTLEで通らないのでやり直し
N=int(input())
a=list(map(int,input().split()))
#dp[l][r]:=区間[l,r]が残っている時の(直後の人の最終的な得点-そうじゃない方の最終的な得点）
dp=[[-1]*N for _ in range(N)]
for k in range(N):
dp[k][k]=a[k]
for r in range(1,N):
for l in reversed(range(r)):
dp[l][r]=max(a[l]-dp[l+1][r],a[r]-dp[l][r-1])
print(dp[0][N-1])
``` | instruction | 0 | 5,639 | 19 | 11,278 |
Yes | output | 1 | 5,639 | 19 | 11,279 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
N = int(input())
A = list(map(int, input().split()))
dp = [[0] * (N + 1) for _ in range(N + 1)]
for d in range(1, N + 1):
for i in range(N - d + 1):
j = i + d
if (N-d) % 2 == 1:
dp[i][j] = min(dp[i+1][j]-A[i], dp[i][j-1]-A[j-1])
else:
dp[i][j] = max(dp[i+1][j]+A[i], dp[i][j-1]+A[j-1])
ans = dp[0][N]
print(ans)
``` | instruction | 0 | 5,640 | 19 | 11,280 |
Yes | output | 1 | 5,640 | 19 | 11,281 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
import sys
sys.setrecursionlimit(2147483647)
INF=float("inf")
MOD=10**9+7
input=lambda :sys.stdin.readline().rstrip()
def resolve():
n=int(input())
A=list(map(int,input().split()))
dp=[[None]*(n+1) for _ in range(n+1)]
def dfs(l,r)->NoneType:
if(dp[l][r] is not None): return
if(l==r):
dp[l][r]=0
return
# 1個先の値を確定させておく
dfs(l+1,r)
dfs(l,r-1)
turn=(n-(r-l))%2
if(turn==0): dp[l][r]=max(dp[l+1][r]+A[l],dp[l][r-1]+A[r-1])
else: dp[l][r]=min(dp[l+1][r]-A[l],dp[l][r-1]-A[r-1])
dfs(0,n)
print(dp[0][n])
resolve()
``` | instruction | 0 | 5,641 | 19 | 11,282 |
No | output | 1 | 5,641 | 19 | 11,283 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
def main(N,a):
return 2
``` | instruction | 0 | 5,642 | 19 | 11,284 |
No | output | 1 | 5,642 | 19 | 11,285 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
import sys
# input処理を高速化する
input = sys.stdin.readline
def chmax(a, b):
if a >= b:
return a
return b
def chmin(a, b):
if a <= b:
return a
return b
def main():
N = int(input())
a = list(map(int, input().split()))
# aiからajのX−Yの最大値
# [左端,右端)=[l,r)からの遷移
# 左をとる[l+1,r)、右をとる[l,r−1)の2通り
dp = [[0] * (N+2) for _ in range(N+2)]
dp[N+1][N+1] = 4999999995
for len in range(1, N + 1):
for i in range(N + 1 - len):
j = i + len
if (N - len) % 2 == 0:
dp[i][j] = chmax(dp[i + 1][j] + a[i], dp[i][j - 1] + a[j - 1])
else:
dp[i][j] = chmin(dp[i + 1][j] - a[i], dp[i][j - 1] - a[j - 1])
print(dp[0][N])
main()
``` | instruction | 0 | 5,643 | 19 | 11,286 |
No | output | 1 | 5,643 | 19 | 11,287 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Taro and Jiro will play the following game against each other.
Initially, they are given a sequence a = (a_1, a_2, \ldots, a_N). Until a becomes empty, the two players perform the following operation alternately, starting from Taro:
* Remove the element at the beginning or the end of a. The player earns x points, where x is the removed element.
Let X and Y be Taro's and Jiro's total score at the end of the game, respectively. Taro tries to maximize X - Y, while Jiro tries to minimize X - Y.
Assuming that the two players play optimally, find the resulting value of X - Y.
Constraints
* All values in input are integers.
* 1 \leq N \leq 3000
* 1 \leq a_i \leq 10^9
Input
Input is given from Standard Input in the following format:
N
a_1 a_2 \ldots a_N
Output
Print the resulting value of X - Y, assuming that the two players play optimally.
Examples
Input
4
10 80 90 30
Output
10
Input
3
10 100 10
Output
-80
Input
1
10
Output
10
Input
10
1000000000 1 1000000000 1 1000000000 1 1000000000 1 1000000000 1
Output
4999999995
Input
6
4 2 9 7 1 5
Output
2
Submitted Solution:
```
import sys
input = sys.stdin.readline
N = int(input())
A = [int(i) for i in input().split()]
dp = [[0] * (N+1) for i in range(N+1)]
def func():
for s in range(1, N+1):
for l in range(N-s+1):
r = l + s
if (N - s) % 2 == 0:
dp[l][r] = max(dp[l+1][r]+A[l], dp[l][r-1]+A[r-1])
else:
dp[l][r] = min(dp[l+1][r]-A[l], dp[l][r-1]-A[r-1])
func()
print(dp[0][N])
``` | instruction | 0 | 5,644 | 19 | 11,288 |
No | output | 1 | 5,644 | 19 | 11,289 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,729 | 19 | 11,458 |
"Correct Solution:
```
while 1:
board = []
n = list(input())
if n[0] == "0":
break
board.append(n)
for _ in range(2):
n = list(input())
board.append(n)
ans = "NA"
for i in range(3):
if board[i][0] == board[i][1] == board[i][2] and board[i][0] != "+":
ans = board[i][0]
elif board[0][i] == board[1][i] == board[2][i] and board[0][i] != "+":
ans = board[0][i]
if board[0][0] == board[1][1] == board[2][2] and board[0][0] != "+":
ans = board[0][0]
elif board[2][0] == board[1][1] == board[0][2] and board[2][0] != "+":
ans = board[1][1]
print(ans)
``` | output | 1 | 5,729 | 19 | 11,459 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,730 | 19 | 11,460 |
"Correct Solution:
```
while True:
input_data1 = input()
if input_data1 == "0":
break
input_data2 = input()
input_data3 = input()
output = "NA"
if input_data1[0] != "+" and input_data1[0] == input_data1[1] == input_data1[2]:
output = input_data1[0]
elif input_data2[0] != "+" and input_data2[0] == input_data2[1] == input_data2[2]:
output = input_data2[0]
elif input_data3[0] != "+" and input_data3[0] == input_data3[1] == input_data3[2]:
output = input_data3[0]
elif input_data1[0] != "+" and input_data1[0] == input_data2[0] == input_data3[0]:
output = input_data1[0]
elif input_data1[1] != "+" and input_data1[1] == input_data2[1] == input_data3[1]:
output = input_data1[1]
elif input_data1[2] != "+" and input_data1[2] == input_data2[2] == input_data3[2]:
output = input_data1[2]
elif input_data1[0] != "+" and input_data1[0] == input_data2[1] == input_data3[2]:
output = input_data1[0]
elif input_data1[2] != "+" and input_data1[2] == input_data2[1] == input_data3[0]:
output = input_data1[2]
print(output)
``` | output | 1 | 5,730 | 19 | 11,461 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,731 | 19 | 11,462 |
"Correct Solution:
```
def b_or_w(b_1, b_2, b_3):
b, w = 'bbb', 'www'
board = [b_1, b_2, b_3]
for i in range(3):
col = b_1[i] + b_2[i] + b_3[i]
board.append(col)
board.append(b_1[0] + b_2[1] + b_3[2])
board.append(b_1[2] + b_2[1] + b_3[0])
for bod in board:
if bod == b:
return 'b'
elif bod == w:
return 'w'
else:
return 'NA'
while True:
b_1 = input()
if b_1 == '0': break
b_2, b_3 = input(), input()
print(b_or_w(b_1, b_2, b_3))
``` | output | 1 | 5,731 | 19 | 11,463 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,732 | 19 | 11,464 |
"Correct Solution:
```
def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=list(input())
if len(a)==1:break
a+=list(input())+list(input())
print(f(a))
``` | output | 1 | 5,732 | 19 | 11,465 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,733 | 19 | 11,466 |
"Correct Solution:
```
def f(a):
for x in 'bw':
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a =='0':break
print(f(a+input()+input()))
``` | output | 1 | 5,733 | 19 | 11,467 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,734 | 19 | 11,468 |
"Correct Solution:
```
while True:
L = input()
if L == "0":
break
table = [["+" for i in range(3)] for j in range(3)]
for i in range(3):
table[0][i] = L[i]
L = input()
for i in range(3):
table[1][i] = L[i]
L = input()
for i in range(3):
table[2][i] = L[i]
ans = "NA"
for i in range(3):
if table[0][i] == table[1][i] and table[1][i] == table[2][i] and table[0][i] != "+":
ans = table[0][i]
break
if table[i][0] == table[i][1] and table[i][1] == table[i][2] and table[i][0] != "+":
ans = table[i][0]
break
if table[0][0] == table[1][1] and table[1][1] == table[2][2] and table[0][0] != "+":
ans = table[0][0]
if table[2][0] == table[1][1] and table[1][1] == table[0][2] and table[2][0] != "+":
ans = table[2][0]
print(ans)
``` | output | 1 | 5,734 | 19 | 11,469 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,735 | 19 | 11,470 |
"Correct Solution:
```
def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a=='0':break
a+=input()+input()
print(f(list(a)))
``` | output | 1 | 5,735 | 19 | 11,471 |
Provide a correct Python 3 solution for this coding contest problem.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA | instruction | 0 | 5,736 | 19 | 11,472 |
"Correct Solution:
```
all_b = "bbb"
all_w = "www"
while True:
r1 = input()
if r1 == "0":
break
r2 = input()
r3 = input()
cands = [r1, r2, r3]
for i in range(3):
col = r1[i] + r2[i] + r3[i]
cands.append(col)
cands.append(r1[0] + r2[1] + r3[2])
cands.append(r1[2] + r2[1] + r3[0])
for cand in cands:
if cand == all_b:
print("b")
break
elif cand == all_w:
print("w")
break
else:
print("NA")
``` | output | 1 | 5,736 | 19 | 11,473 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0183
"""
import sys
from sys import stdin
input = stdin.readline
def solve(board):
colors = ['b', 'w']
for c in colors:
for y in range(3):
if board[y].count(c) == 3:
return c
for x in range(3):
if board[0][x] == c and board[1][x] == c and board[2][x] == c:
return c
if board[0][0] == c and board[1][1] == c and board[2][2] == c:
return c
if board[0][2] == c and board[1][1] == c and board[2][0] == c:
return c
return 'NA'
def main(args):
while True:
temp = input().strip()
if temp[0] == '0':
break
board = []
board.append(list(temp))
board.append(list(input().strip()))
board.append(list(input().strip()))
result = solve(board)
print(result)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 5,737 | 19 | 11,474 |
Yes | output | 1 | 5,737 | 19 | 11,475 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA
Submitted Solution:
```
def f(a):
for x in ['b','w']:
if a[0::4].count(x)==3 or a[2:7:2].count(x)==3:return x
for i in range(3):
if a[i*3:i*3+3].count(x)==3 or a[i::3].count(x)==3:return x
return 'NA'
while 1:
a=input()
if a=='0':break
print(f(a+input()+input()))
``` | instruction | 0 | 5,738 | 19 | 11,476 |
Yes | output | 1 | 5,738 | 19 | 11,477 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA
Submitted Solution:
```
def f1(c, l):
for i in range(3):
if c*3 == l[i]:
return 1
return 0
def f2(c, l):
for i in range(0, 7, 3):
s = set(h[i:i+3])
if c in s and len(s) == 1:
return 1
return 0
def f3(c, l):
if c*3 == l[0]+l[4]+l[8]:
return 1
if c*3 == l[2]+l[4]+l[6]:
return 1
return 0
while True:
try:
w = [input() for _ in range(3)]
except:
break
if f1('b', w):
print('b')
continue
if f1('w', w):
print('w')
continue
h = [w[j][i] for i in range(3) for j in range(3)]
if f2('b', h):
print('b')
continue
if f2('w', h):
print('w')
continue
if f3('b', h):
print('b')
continue
if f3('w' , h):
print('w')
continue
print("NA")
``` | instruction | 0 | 5,739 | 19 | 11,478 |
Yes | output | 1 | 5,739 | 19 | 11,479 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA
Submitted Solution:
```
while True:
input_data1 = input()
if input_data1 == "0":
break
input_data2 = input()
input_data3 = input()
output = "NA"
if input_data1[0] == input_data1[1] == input_data1[2]:
output = input_data1[0]
elif input_data2[0] == input_data2[1] == input_data2[2]:
output = input_data2[0]
elif input_data3[0] == input_data3[1] == input_data3[2]:
output = input_data3[0]
elif input_data1[0] == input_data2[0] == input_data3[0]:
output = input_data1[0]
elif input_data1[1] == input_data2[1] == input_data3[1]:
output = input_data1[1]
elif input_data1[2] == input_data2[2] == input_data3[2]:
output = input_data1[2]
elif input_data1[0] == input_data2[1] == input_data3[2]:
output = input_data1[0]
elif input_data1[2] == input_data2[1] == input_data3[0]:
output = input_data1[2]
print(output)
``` | instruction | 0 | 5,740 | 19 | 11,480 |
No | output | 1 | 5,740 | 19 | 11,481 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Consider a tic-tac-toe on a 3x3 board. Tic-tac-toe is a two-player battle game. Decide the first attack and the second attack, one hits Kuroishi and one hits Shiraishi. The winner is the person who puts stones one by one on the board alternately and arranges three of his own stones first in either the vertical, horizontal, or diagonal direction.
Create a program that inputs the information on the board, judges the victory or defeat, outputs "b" if black wins, "w" if white wins, and "NA" if neither is available. please. The board information consists of 3 rows and 3 columns of character strings. "B" is Kuroishi, "w" is Shiraishi, and "+" (half-width plus) is nothing. However, three blacks and three whites cannot be lined up at the same time.
Input
A sequence of multiple datasets is given as input. The end of the input is indicated by a single line of zeros. Each dataset is given in the following format:
board1
board2
board3
The i-line is given the string boardi that represents the information on the i-th line of the board.
The number of datasets does not exceed 50.
Output
Outputs "b", "w", or "NA" on one line for each data set.
Example
Input
bbw
wbw
+b+
bwb
wbw
wbw
0
Output
b
NA
Submitted Solution:
```
import sys
while True:
Fu = []
boa = input()
if boa == "0":
break
Fu.append(list(boa))
for i in range(2):
boa = list(input())
Fu.append(boa)
for i in range(3):
if Fu[i][0] == Fu[i][1] == Fu[i][2]:
print(Fu[i][0])
sys.exit()
if Fu[0][i] == Fu[1][i] == Fu[2][i]:
print(Fu[0][i])
sys.exit()
if Fu[0][0] == Fu[1][1] == Fu[2][2]:
print(Fu[0][0])
sys.exit()
if Fu[0][2] == Fu[1][1] == Fu[2][0]:
print(Fu[1][1])
sys.exit()
print("NA")
``` | instruction | 0 | 5,741 | 19 | 11,482 |
No | output | 1 | 5,741 | 19 | 11,483 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,780 | 19 | 11,560 |
"Correct Solution:
```
a = []
b = {}
n = int(input())
for _ in range(n):
s, i = input().split()
a += [(s, int(i))]
b.setdefault(int(i), []).append(s)
b = {val: iter(s).__next__ for val, s in b.items()}
def partition(a, left, right):
standard = a[right][1]
cnt = left
for i in range(left, right):
if a[i][1] <= standard:
a[cnt],a[i] = a[i], a[cnt]
cnt += 1
a[cnt],a[right] = a[right], a[cnt]
return cnt
def quickSort(a, left = 0, right = len(a) - 1):
if 1 <= right - left:
cnt_ = partition(a, left, right)
quickSort(a,left, cnt_ - 1)
quickSort(a,cnt_ + 1, right)
quickSort(a, 0 , len(a)-1)
ok = 1
for s, i in a:
if b[i]() != s:
ok = 0
print(['Not stable','Stable'][ok])
for i in range(n):
print(*a[i])
``` | output | 1 | 5,780 | 19 | 11,561 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,781 | 19 | 11,562 |
"Correct Solution:
```
def partition(A, p, r):
x = A[r]
i = p-1
for j in range(p,r):
if int(A[j][1]) <= int(x[1]):
i += 1
A[i],A[j] = A[j],A[i]
A[i+1],A[r] = A[r],A[i+1]
return i+1
def quicksort(A, p, r):
if p < r:
q = partition(A, p, r)
quicksort(A, p, q-1)
quicksort(A, q+1, r)
def merge(A, left, mid, right):
L = A[left:mid] + [[0,1000000001]]
R = A[mid:right] + [[0,1000000001]]
i = j = 0
for k in range(left, right):
if int(L[i][1]) <= int(R[j][1]):
A[k] = L[i]
i += 1
else:
A[k] = R[j]
j += 1
def mergeSort(A, left, right):
if left + 1 < right:
mid = (left + right) // 2
mergeSort(A, left, mid)
mergeSort(A, mid, right)
merge(A, left, mid, right)
n = int(input())
A = [input().split() for i in range(n)]
B = A[:]
quicksort(A, 0, n-1)
mergeSort(B, 0, n)
juge = 1
for i in range(n):
if A[i] != B[i]:
juge = 0
break
if juge == 1:
print("Stable")
else:
print("Not stable")
for i in range(n):
print(" ".join(A[i]))
``` | output | 1 | 5,781 | 19 | 11,563 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,782 | 19 | 11,564 |
"Correct Solution:
```
def partition(A,p,r):
q = p
for i in range(p,r):
if A[i][1] <= A[r][1]:
A[q],A[i] = A[i],A[q]
q += 1
A[q],A[r] = A[r],A[q]
return q
def quicksort(A,left,right):
if left < right:
q = partition(A,left,right)
quicksort(A,left,q-1)
quicksort(A,q+1,right)
def check_stable(A):
for i in range(1,len(A)):
if A[i-1][1] == A[i][1]:
if A[i-1][2] > A[i][2]:
return "Not stable"
return "Stable"
n = int(input())
data = []
for i in range(n):
mark, num = map(str,input().split())
data += [[mark,int(num),i]]
quicksort(data,0,len(data) -1)
print(check_stable(data))
for line in data:
print(line[0],line[1])
``` | output | 1 | 5,782 | 19 | 11,565 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,783 | 19 | 11,566 |
"Correct Solution:
```
from collections import namedtuple
Card = namedtuple('Card', ['suit', 'value', 'init'])
def QuickSort(A, begin, end):
if end - begin <= 1:
return
piv = A[end - 1].value
left, right = begin, begin
for i in range(begin, end - 1):
if A[i].value <= piv:
if i - left > 0:
A[left], A[i] = A[i], A[left]
left += 1
A[left], A[end - 1] = A[end - 1], A[left]
QuickSort(A, begin, left)
QuickSort(A, left + 1, end)
n = int(input())
A = []
for i in range(n):
suit, value = input().split()
value = int(value)
A.append(Card(suit, value, i))
QuickSort(A, 0, n)
for i in range(n - 1):
if A[i].value == A[i + 1].value and A[i].init > A[i + 1].init:
print('Not stable')
break
else:
print('Stable')
for a in A:
print(a.suit, a.value)
``` | output | 1 | 5,783 | 19 | 11,567 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,784 | 19 | 11,568 |
"Correct Solution:
```
def partition(a, p, r):
x = a[r][1]
i = p - 1
for j in range(p, r):
if a[j][1] <= x:
i = i + 1
a[i], a[j] = a[j], a[i]
a[i + 1], a[r] = a[r], a[i + 1]
return i + 1
def quicksort(a, p, r):
if p < r:
q = partition(a, p, r)
quicksort(a, p, q - 1)
quicksort(a, q + 1, r)
def checkstable(a):
for i in range(1, len(a)):
if a[i - 1][1] == a[i][1]:
if a[i - 1][2] > a[i][2]:
return "Not stable"
return "Stable"
import sys
n = int(input())
a = []
for i in range(n):
suit, num = sys.stdin.readline().split()
a += [[suit, int(num), i]]
quicksort(a, 0, len(a) - 1)
print(checkstable(a))
for line in a:
print(line[0], line[1])
``` | output | 1 | 5,784 | 19 | 11,569 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,785 | 19 | 11,570 |
"Correct Solution:
```
import math
import string
import itertools
import fractions
import heapq
import collections
import re
import array
import bisect
import sys
import random
import time
inf = 10**9
def partition(a, p, r):
# xがピボット
x = a[r][1]
i = p - 1
for j in range(p, r):
if a[j][1] <= x:
i = i + 1
a[i], a[j] = a[j], a[i]
a[i+1], a[r] = a[r], a[i+1]
return i + 1
def quicksort(a, p, r):
if p < r:
q = partition(a, p, r)
quicksort(a, p, q-1)
quicksort(a, q+1, r)
def main():
n = int(input())
cards = []
for i in range(n):
c = input().split()
cards.append((c[0], int(c[1])))
stable_sorted_cards = sorted(cards, key=lambda x: x[1])
quicksort(cards, 0, n-1)
if cards != stable_sorted_cards:
print('Not stable')
else:
print('Stable')
for card in cards:
print(card[0], card[1])
if __name__ == '__main__':
main()
``` | output | 1 | 5,785 | 19 | 11,571 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,786 | 19 | 11,572 |
"Correct Solution:
```
import sys
def t(A,p,r):
x=A[r][1];i=p-1
for j in range(p,r):
if A[j][1]<=x:i+=1;A[i],A[j]=A[j],A[i]
A[i+1],A[r]=A[r],A[i+1]
return i+1
def k(A,p,r):
if p<r:q=t(A,p,r);k(A,p,q-1);k(A,q+1,r)
def s(A):
for i in range(n-1):
if A[i][1]==A[i+1][1]:
if A[i][2]>A[i+1][2]:return'Not s'
return'S'
n=int(input())
f=lambda x:(x[0],int(x[1]),x[2])
A=[(*e.split(),i)for i,e in enumerate(sys.stdin)]
A=list(map(f,A))
k(A,0,n-1)
for e in[[s(A)+'table']]+A:print(*e[:2])
``` | output | 1 | 5,786 | 19 | 11,573 |
Provide a correct Python 3 solution for this coding contest problem.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1 | instruction | 0 | 5,787 | 19 | 11,574 |
"Correct Solution:
```
from operator import itemgetter
def partition(A,p,r):
x = A[r][1]
i = p-1
for j in range(p,r):
if A[j][1] <= x:
i += 1
A[i],A[j] = A[j],A[i]
A[i+1],A[r] = A[r],A[i+1]
return i+1
def quicksort(A,p,r):
if p < r:
q = partition(A,p,r)
quicksort(A,p,q-1)
quicksort(A,q+1,r)
A = []
n = int(input())
for i in range(n):
a,b = map(str,input().split())
A.append([a,int(b)])
B = [i for i in A]
quicksort(A,0,n-1)
B.sort(key=itemgetter(1))
if A == B:
print("Stable")
else:
print("Not stable")
for i in A:
print(i[0],i[1])
``` | output | 1 | 5,787 | 19 | 11,575 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
def num(card):
return int(card[2:])
def partition(A, p, r):
x = num(A[r])
i = p - 1
for j in range(p, r):
if num(A[j]) <= x:
i += 1
A[i], A[j] = A[j], A[i]
A[i + 1], A[r] = A[r], A[i + 1]
return i + 1
def quicksort(A, p, r):
if p < r:
q = partition(A, p, r)
quicksort(A, p, q - 1)
quicksort(A, q + 1, r)
n = int(input())
A = [input() for _ in range(n)]
B = sorted(A, key=num)
quicksort(A, 0, n - 1)
msg = "Stable"
for i in range(n):
if A[i] != B[i]:
msg = "Not stable"
break
print(msg)
for card in A:
print(card)
``` | instruction | 0 | 5,788 | 19 | 11,576 |
Yes | output | 1 | 5,788 | 19 | 11,577 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
import copy
from typing import List, Tuple
def partition(elements: List[Tuple[str, int]], start_idx: int, pivot_idx: int) -> int:
pivot = elements[pivot_idx][1]
i = start_idx - 1
for j in range(start_idx, pivot_idx):
if elements[j][1] <= pivot:
i += 1
elements[i], elements[j] = elements[j], elements[i]
elements[i + 1], elements[pivot_idx] = elements[pivot_idx], elements[i + 1]
return i + 1
def quick_sort(elements: List[Tuple[str, int]], p: int, r: int) -> None:
if p < r:
q = partition(elements, p, r)
quick_sort(elements, p, q - 1)
quick_sort(elements, q + 1, r)
if __name__ == "__main__":
n = int(input())
elements = [("", 0)] * n
for i in range(n):
element = input().split()
elements[i] = (element[0], int(element[1]))
elements_copy = copy.deepcopy(elements)
quick_sort(elements, 0, n - 1)
for i in range(n - 1):
if elements[i][1] == elements[i + 1][1]:
if elements_copy.index(elements[i]) > elements_copy.index(elements[i + 1]):
print("Not stable")
break
else:
print("Stable")
for elem in elements:
print(f"{elem[0]} {elem[1]}")
``` | instruction | 0 | 5,789 | 19 | 11,578 |
Yes | output | 1 | 5,789 | 19 | 11,579 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
import copy
INF = 10000000000
def merge(A, left, mid, right):
count = 0
L = A[left:mid] + [(INF,INF)]
R = A[mid:right] + [(INF,INF)]
i, j = 0, 0
for k in range(left, right):
count = count + 1
if L[i][1] <= R[j][1]:
A[k] = L[i]
i = i + 1
else:
A[k] = R[j]
j = j + 1
return count
def mergeSort(A, left, right):
if left + 1 < right:
mid = (left + right) // 2
countL = mergeSort(A, left, mid)
countR = mergeSort(A, mid, right)
return merge(A, left, mid, right) + countL + countR
return 0
def partition(A, p, r):
x = A[r][1]
i = p - 1
for j in range(p, r):
if A[j][1] <= x:
i = i + 1
A[i], A[j] = A[j], A[i]
A[i+1], A[r] = A[r], A[i+1]
return i + 1
def quickSort(A, p, r):
if p < r:
q = partition(A, p, r)
quickSort(A, p, q-1)
quickSort(A, q+1, r)
n = int(input())
A = [None for i in range(n)]
for i in range(n):
a, b = input().split()
A[i] = (a, int(b))
B = copy.deepcopy(A)
quickSort(A, 0, n-1)
mergeSort(B, 0, n)
if A == B:
print("Stable")
else:
print("Not stable")
ans = [str(x[0]) +" "+str(x[1]) for x in A]
ans = '\n'.join(ans)
print(ans)
``` | instruction | 0 | 5,790 | 19 | 11,580 |
Yes | output | 1 | 5,790 | 19 | 11,581 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
import copy
def partition(a, p, r):
x = a[r]
i = p - 1
for j in range(p, r):
if a[j][1] <= x[1]:
i = i + 1
a[i], a[j] = a[j], a[i]
a[i + 1], a[r] = a[r], a[i + 1]
return(i + 1)
def quick_sort(a, p, r):
if p < r:
q = partition(a, p, r)
quick_sort(a, p, q - 1)
quick_sort(a, q + 1, r)
n = int(input())
a = []
for i in range(n):
a.append(list(input().split()))
a[i][1] = int(a[i][1])
b = copy.deepcopy(a)
quick_sort(a, 0, n - 1)
for i in range(n - 1):
if a[i][1] == a[i + 1][1]:
if b.index(a[i]) > b.index(a[i + 1]):
print("Not stable")
break
else:
print("Stable")
for i in a:
print(" ".join(map(str, i)))
``` | instruction | 0 | 5,791 | 19 | 11,582 |
Yes | output | 1 | 5,791 | 19 | 11,583 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
#coding:utf-8
from copy import deepcopy
n = int(input())
A = []
for i in range(n):
ch, num = input().split()
A.append([ch, int(num)])
B = deepcopy(A)
def Merge(A, left, mid, right):
L = A[left:mid]
R = A[mid:right]
L.append(["S",20000000])
R.append(["S",20000000])
i,j = 0,0
for k in range(left,right):
if L[i][1] <= R[j][1]:
A[k] = L[i]
i += 1
else:
A[k] = R[j]
j += 1
def MergeSort(A, left, right):
if left+1 < right:
mid = (left + right)//2
MergeSort(A, left, mid)
MergeSort(A, mid, right)
Merge(A, left, mid, right)
def partition(A, p, r):
x = A[r-1][1]
i = p-1
for j in range(p, r):
if A[j][1] <= x:
i += 1
A[i], A[j] = A[j], A[i]
return i
def quickSort(A, p, r):
if p < r:
q = partition(A, p, r)
quickSort(A, p, q)
quickSort(A, q+1, r)
quickSort(A, 0, n)
MergeSort(B, 0, n)
if A == B:
print("Stable")
else:
print("Not stable")
for a in A:
a = " ".join([a[0],str(a[1])])
print(a)
``` | instruction | 0 | 5,792 | 19 | 11,584 |
No | output | 1 | 5,792 | 19 | 11,585 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
#http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=ALDS1_6_C&lang=jp
def partition(target_list, l, r):
x = int(target_list[r][2])
i = l - 1
for j in range(l, r):
if int(target_list[j][2]) <= x:
i = i + 1
tmp = target_list[i]
target_list[i] = target_list[j]
target_list[j] = tmp
tmp = target_list[r]
target_list[r] = target_list[i + 1]
target_list[i + 1] = tmp
return i + 1
def check_stable(origin_list, target_list):
for i, origin_v in enumerate(origin_list):
for origin_v2 in origin_list[i+1:]:
if origin_v[2] == origin_v2[2]:
for j, target_v in enumerate(target_list):
for target_v2 in target_list[j+1:]:
if origin_v == target_v2 and origin_v2 == target_v:
return "Not stable"
return "Stable"
def quick_sort(target_list, l, r):
if l < r:
c = partition(target_list, l, r)
quick_sort(target_list, l, c - 1)
quick_sort(target_list, c + 1, r)
if __name__ == "__main__":
n_list = int(input())
target_list = []
for i in range(n_list):
target_list.append(input())
origin_list = [a for a in target_list]
quick_sort(target_list, 0, n_list - 1)
print(check_stable(origin_list, target_list))
print("\n".join(target_list))
``` | instruction | 0 | 5,793 | 19 | 11,586 |
No | output | 1 | 5,793 | 19 | 11,587 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
def merge_sort(A, left, right):
if left + 1 < right:
mid = (left + right) // 2
merge_sort(A, left, mid)
merge_sort(A, mid, right)
merge(A, left, mid, right)
def merge(A, left, mid, right):
n1 = mid - left
n2 = right - mid
L = A[left:mid]
R = A[mid:right]
L.append(('J', 1000000001))
R.append(('J', 1000000001))
i = 0 # L[]??¨?????????????????????
j = 0 # R[]??¨?????????????????????
for k in range(left, right):
if L[i][1] <= R[j][1]:
A[k] = L[i]
i += 1
else:
A[k] = R[j]
j += 1
def partition(A, p, r):
"""
???????????????????????????????????????A[r]?????°?????????????????????????????????????????????A[r-1]??¨?´??????????????????§??¨???
"""
x = A[r][1]
i = p - 1
for j in range(p, r):
if A[j][1] <= x:
i += 1
temp = A[i]
A[i] = A[j]
A[j] = temp
temp = A[i+1]
A[i+1] = A[r]
A[r] = temp
return i
def quick_sort(A, p, r):
if p < r:
q = partition(A, p, r)
quick_sort(A, p, q-1)
quick_sort(A, q+1, r)
if __name__ == '__main__':
# ??????????????\???
#cards = [('D', 3), ('H', 2), ('D', 1), ('S', 3), ('D', 2), ('C', 1)]
#comp_cards = cards[:]
num_of_cards = int(input())
cards = []
for i in range(num_of_cards):
suit, rank = input().split(' ')
cards.append((suit, int(rank)))
comp_cards = cards[:]
# ??????????????????
data_length = len(cards)
quick_sort(cards, 0, data_length-1)
merge_sort(comp_cards, 0, data_length) # ?????????????????????????????????????????¨
# ???????????????
stable = True # ?????????????????????????????????????????????
for x, y in zip(cards, comp_cards):
if x != y:
stable = False
print('Not stable')
break
if stable is True:
print('Stable')
for c in cards: # ??????????????¨???
print('{0} {1}'.format(c[0], c[1]))
``` | instruction | 0 | 5,794 | 19 | 11,588 |
No | output | 1 | 5,794 | 19 | 11,589 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Let's arrange a deck of cards. Your task is to sort totally n cards. A card consists of a part of a suit (S, H, C or D) and an number. Write a program which sorts such cards based on the following pseudocode:
Partition(A, p, r)
1 x = A[r]
2 i = p-1
3 for j = p to r-1
4 do if A[j] <= x
5 then i = i+1
6 exchange A[i] and A[j]
7 exchange A[i+1] and A[r]
8 return i+1
Quicksort(A, p, r)
1 if p < r
2 then q = Partition(A, p, r)
3 run Quicksort(A, p, q-1)
4 run Quicksort(A, q+1, r)
Here, A is an array which represents a deck of cards and comparison operations are performed based on the numbers.
Your program should also report the stability of the output for the given input (instance). Here, 'stability of the output' means that: cards with the same value appear in the output in the same order as they do in the input (instance).
Constraints
* 1 ≤ n ≤ 100,000
* 1 ≤ the number of a card ≤ 109
* There are no identical card in the input
Input
The first line contains an integer n, the number of cards.
n cards are given in the following lines. Each card is given in a line and represented by a pair of a character and an integer separated by a single space.
Output
In the first line, print the stability ("Stable" or "Not stable") of this output.
In the following lines, print the arranged cards in the same manner of that of the input.
Examples
Input
6
D 3
H 2
D 1
S 3
D 2
C 1
Output
Not stable
D 1
C 1
D 2
H 2
D 3
S 3
Input
2
S 1
H 1
Output
Stable
S 1
H 1
Submitted Solution:
```
def Partition(A,p,r):
x = A[r]
i = p-1
for j in range(p,r):
if (A[j] <= x):
i += 1
A[i],A[j] = A[j],A[i]
A[i+1],A[r] = A[r],A[i+1]
return i+1
def qsort(A,p,r):
if p < r:
q = Partition(A,p,r)
qsort(A,p,q-1)
qsort(A,q+1,r)
class card(object):
def __init__(self, str):
data = str.split()
self.symbol,self.num = data[0],int(data[1])
def __le__(self,obj):
if(self.num <= obj.num):
return True
else:
return False
def __ge__(self,obj):
if(self.num >= obj.num):
return True
else:
return False
def display_card(self):
print("{0} {1}".format(self.symbol,self.num))
c = []
n = int(input())
while(n>0):
c.append(card(input()))
n -= 1
c_org = c.copy()
qsort(c,0,len(c)-1)
notstable = False
for i in range(1,len(c)):
if(c[i-1].num == c[i].num):
firstCard = c[i-1]
secondCard = c[i]
is_found_1st = False
is_found_2nd = False
for org in c_org:
if(org == firstCard):
is_found_1st = True
if is_found_2nd:
notstable = True
break
if(org == secondCard):
is_found_2nd = True
if(is_found_1st == True):
break
else:
notstable = True
break
if(notstable == 1):
print('Not stable')
else:
print('Stable')
for x in c:
x.display_card()
``` | instruction | 0 | 5,795 | 19 | 11,590 |
No | output | 1 | 5,795 | 19 | 11,591 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Koa the Koala and her best friend want to play a game.
The game starts with an array a of length n consisting of non-negative integers. Koa and her best friend move in turns and each have initially a score equal to 0. Koa starts.
Let's describe a move in the game:
* During his move, a player chooses any element of the array and removes it from this array, xor-ing it with the current score of the player.
More formally: if the current score of the player is x and the chosen element is y, his new score will be x ⊕ y. Here ⊕ denotes [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
Note that after a move element y is removed from a.
* The game ends when the array is empty.
At the end of the game the winner is the player with the maximum score. If both players have the same score then it's a draw.
If both players play optimally find out whether Koa will win, lose or draw the game.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.
The first line of each test case contains the integer n (1 ≤ n ≤ 10^5) — the length of a.
The second line of each test case contains n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9) — elements of a.
It is guaranteed that the sum of n over all test cases does not exceed 10^5.
Output
For each test case print:
* WIN if Koa will win the game.
* LOSE if Koa will lose the game.
* DRAW if the game ends in a draw.
Examples
Input
3
3
1 2 2
3
2 2 3
5
0 0 0 2 2
Output
WIN
LOSE
DRAW
Input
4
5
4 1 5 1 3
4
1 0 1 6
1
0
2
5 4
Output
WIN
WIN
DRAW
WIN
Note
In testcase 1 of the first sample we have:
a = [1, 2, 2]. Here Koa chooses 1, other player has to choose 2, Koa chooses another 2. Score for Koa is 1 ⊕ 2 = 3 and score for other player is 2 so Koa wins. | instruction | 0 | 6,762 | 19 | 13,524 |
Tags: bitmasks, constructive algorithms, dp, games, greedy, math
Correct Solution:
```
from collections import defaultdict
import sys, math
f = None
try:
f = open('q1.input', 'r')
except IOError:
f = sys.stdin
if 'xrange' in dir(__builtins__):
range = xrange
def print_case_iterable(case_num, iterable):
print("Case #{}: {}".format(case_num," ".join(map(str,iterable))))
def print_case_number(case_num, iterable):
print("Case #{}: {}".format(case_num,iterable))
def print_iterable(A):
print (' '.join(A))
def read_int():
return int(f.readline().strip())
def read_int_array():
return [int(x) for x in f.readline().strip().split(" ")]
def rns():
a = [x for x in f.readline().split(" ")]
return int(a[0]), a[1].strip()
def read_string():
return list(f.readline().strip())
def ri():
return int(f.readline().strip())
def ria():
return [int(x) for x in f.readline().strip().split(" ")]
def rns():
a = [x for x in f.readline().split(" ")]
return int(a[0]), a[1].strip()
def rs():
return list(f.readline().strip())
def bi(x):
return bin(x)[2:]
from collections import deque
import math
NUMBER = 10**9 + 7
def egcd(a, b):
if a == 0:
return (b, 0, 1)
else:
g, y, x = egcd(b % a, a)
return (g, x - (b // a) * y, y)
from collections import deque, defaultdict
import heapq
from types import GeneratorType
def shift(a,i,num):
for _ in range(num):
a[i],a[i+1],a[i+2] = a[i+2],a[i],a[i+1]
from heapq import heapify, heappush, heappop
from string import ascii_lowercase as al
def solution(a,n):
draw = True
for i in range(50,-1,-1):
cnt = 0
for x in a:
if (1<<i) & x:
cnt+=1
if cnt % 2:
draw = False
break
if draw:
return 'DRAW'
if (cnt - 1) % 4 == 0:
return 'WIN'
win = ((cnt+1)//2) % 2
win = win^((n - cnt )% 2)
return 'WIN' if win else 'LOSE'
def main():
for i in range(int(input())):
n = int(input())
a = list(map(int,input().split()))
x = solution(a,n)
if 'xrange' not in dir(__builtins__):
print(x) # print("Case #"+str(i+1)+':',x)
else:
print >>output,"Case #"+str(i+1)+':',str(x)
if 'xrange' in dir(__builtins__):
print(output.getvalue())
output.close()
if 'xrange' in dir(__builtins__):
import cStringIO
output = cStringIO.StringIO()
if __name__ == '__main__':
main()
``` | output | 1 | 6,762 | 19 | 13,525 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Koa the Koala and her best friend want to play a game.
The game starts with an array a of length n consisting of non-negative integers. Koa and her best friend move in turns and each have initially a score equal to 0. Koa starts.
Let's describe a move in the game:
* During his move, a player chooses any element of the array and removes it from this array, xor-ing it with the current score of the player.
More formally: if the current score of the player is x and the chosen element is y, his new score will be x ⊕ y. Here ⊕ denotes [bitwise XOR operation](https://en.wikipedia.org/wiki/Bitwise_operation#XOR).
Note that after a move element y is removed from a.
* The game ends when the array is empty.
At the end of the game the winner is the player with the maximum score. If both players have the same score then it's a draw.
If both players play optimally find out whether Koa will win, lose or draw the game.
Input
Each test contains multiple test cases. The first line contains t (1 ≤ t ≤ 10^4) — the number of test cases. Description of the test cases follows.
The first line of each test case contains the integer n (1 ≤ n ≤ 10^5) — the length of a.
The second line of each test case contains n integers a_1, a_2, …, a_n (0 ≤ a_i ≤ 10^9) — elements of a.
It is guaranteed that the sum of n over all test cases does not exceed 10^5.
Output
For each test case print:
* WIN if Koa will win the game.
* LOSE if Koa will lose the game.
* DRAW if the game ends in a draw.
Examples
Input
3
3
1 2 2
3
2 2 3
5
0 0 0 2 2
Output
WIN
LOSE
DRAW
Input
4
5
4 1 5 1 3
4
1 0 1 6
1
0
2
5 4
Output
WIN
WIN
DRAW
WIN
Note
In testcase 1 of the first sample we have:
a = [1, 2, 2]. Here Koa chooses 1, other player has to choose 2, Koa chooses another 2. Score for Koa is 1 ⊕ 2 = 3 and score for other player is 2 so Koa wins. | instruction | 0 | 6,763 | 19 | 13,526 |
Tags: bitmasks, constructive algorithms, dp, games, greedy, math
Correct Solution:
```
from sys import stdin, stdout
fullans = ''
for _ in range(int(stdin.readline())):
n = int(stdin.readline())
ls = list(map(int, stdin.readline().split()))
bit = 32
check = True
while bit >= 0 and check:
x = 0
for i in ls:
if i & (1 << bit):
x += 1
y = n - x
if not x & 1:
bit -= 1
else:
check = False
if x % 4 == 1:
fullans += 'WIN\n'
else:
if y % 2 == 0:
fullans += 'LOSE\n'
else:
fullans += 'WIN\n'
if check:
fullans += 'DRAW\n'
stdout.write(fullans)
``` | output | 1 | 6,763 | 19 | 13,527 |
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