message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A positive integer a is given. Baron Munchausen claims that he knows such a positive integer n that if one multiplies n by a, the sum of its digits decreases a times. In other words, S(an) = S(n... | instruction | 0 | 101,236 | 20 | 202,472 |
No | output | 1 | 101,236 | 20 | 202,473 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A positive integer a is given. Baron Munchausen claims that he knows such a positive integer n that if one multiplies n by a, the sum of its digits decreases a times. In other words, S(an) = S(n... | instruction | 0 | 101,237 | 20 | 202,474 |
No | output | 1 | 101,237 | 20 | 202,475 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,302 | 20 | 202,604 |
Tags: brute force, greedy, implementation
Correct Solution:
```
import math as ma
q=int(input())
for w in range(q):
n=int(input())
m=n
i=ma.ceil(ma.log(n,3))
j=i-1
k=0
r=n
while m>=0 and j>=0:
if m>=3**j:
m=m-3**j
else:
k=j
r=n-m
j=... | output | 1 | 101,302 | 20 | 202,605 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,303 | 20 | 202,606 |
Tags: brute force, greedy, implementation
Correct Solution:
```
#import resource
import sys
#resource.setrlimit(resource.RLIMIT_STACK, (2**29, -1))
sys.setrecursionlimit(10 ** 7)
from collections import deque
import math
pow3 = [1]
aux = 1
for i in range(9):
aux *= 3
pow3.append(aux)
a = []
for op in range... | output | 1 | 101,303 | 20 | 202,607 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,304 | 20 | 202,608 |
Tags: brute force, greedy, implementation
Correct Solution:
```
import math
q = int(input())
pw = [3**0]
for i in range(1, 10):
pw.append(3**i)
length = len(pw)
for j in range(length-1):
pw.append(3**i+pw[j])
for _ in range(q):
n = int(input())
for i in range(len(pw)):
if n<=pw[i]:
... | output | 1 | 101,304 | 20 | 202,609 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,305 | 20 | 202,610 |
Tags: brute force, greedy, implementation
Correct Solution:
```
arr = [3**i for i in range(45)]
for i in range(int(input())):
n, hi = int(input()), sum(arr)
for j in reversed(arr):
if hi - j >= n:
hi -= j
print(hi)
``` | output | 1 | 101,305 | 20 | 202,611 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,306 | 20 | 202,612 |
Tags: brute force, greedy, implementation
Correct Solution:
```
#this is wild game
def gcd(a:int,b:int) -> int:
return a if b==0 else gcd(b,a%b)
def conv(n:int,b:int=3)->int:
a=0
p=1
while n:
a+=(n%b)*p
p*=10
n//=b
return a
def solve(n:int)->int:
p=0
s=""
w... | output | 1 | 101,306 | 20 | 202,613 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,307 | 20 | 202,614 |
Tags: brute force, greedy, implementation
Correct Solution:
```
def b10to3(num):
digs = []
num = int(num)
while num > 0:
digs.append(num % 3)
num //= 3
return list(reversed(digs))
def b3to10(num):
sum = 0
for i in num:
sum = sum * 3 + i
return str(sum)
for i in range(int(input())):
num = input()
digs ... | output | 1 | 101,307 | 20 | 202,615 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,308 | 20 | 202,616 |
Tags: brute force, greedy, implementation
Correct Solution:
```
q = int(input())
def base_10_to_n(x, n):
if x//n:
return base_10_to_n(x//n, n)+str(x%n)
else:
return str(x%n)
for _ in range(q):
n = int(input())
s = list(base_10_to_n(n, 3))
#print(s)
s.reverse()
pos0 = -1
... | output | 1 | 101,308 | 20 | 202,617 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good number greater than or equal to n.
The positive int... | instruction | 0 | 101,309 | 20 | 202,618 |
Tags: brute force, greedy, implementation
Correct Solution:
```
import math
i = 0
s = 0
v = []
while s < 1e18:
s += pow(3,i)
v.append(s)
i += 1
q = int(input())
for i in range(q):
n = int(input())
k = 0
while v[k] < n:
k += 1
ans = v[k]
l = k
while l >= 0:
if ans - pow(3,l) >= n:
ans -= pow(3... | output | 1 | 101,309 | 20 | 202,619 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,310 | 20 | 202,620 |
Yes | output | 1 | 101,310 | 20 | 202,621 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,311 | 20 | 202,622 |
Yes | output | 1 | 101,311 | 20 | 202,623 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,312 | 20 | 202,624 |
Yes | output | 1 | 101,312 | 20 | 202,625 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,313 | 20 | 202,626 |
Yes | output | 1 | 101,313 | 20 | 202,627 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,314 | 20 | 202,628 |
No | output | 1 | 101,314 | 20 | 202,629 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,315 | 20 | 202,630 |
No | output | 1 | 101,315 | 20 | 202,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,316 | 20 | 202,632 |
No | output | 1 | 101,316 | 20 | 202,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
The only difference between easy and hard versions is the maximum value of n.
You are given a positive integer number n. You really love good numbers so you want to find the smallest good numbe... | instruction | 0 | 101,317 | 20 | 202,634 |
No | output | 1 | 101,317 | 20 | 202,635 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One day Anna got the following task at school: to arrange several numbers in a circle so that any two neighboring numbers differs exactly by 1. Anna was given several numbers and arranged them in a circle to fulfill the task. Then she wanted... | instruction | 0 | 101,335 | 20 | 202,670 |
Tags: constructive algorithms, implementation
Correct Solution:
```
n= int(input())
a = list(map(int,input().split()))
a.sort()
mm=a[0]
b=list(map(lambda x: x-mm, a))
if b[-1]>n or n%2==1:
print('NO')
else:
c=[0]*(b[-1]+1)
for el in b:
c[el]+=1
for i in range(1,len(c)):
c[i] = c[i]-c[i-1... | output | 1 | 101,335 | 20 | 202,671 |
Provide tags and a correct Python 3 solution for this coding contest problem.
One day Anna got the following task at school: to arrange several numbers in a circle so that any two neighboring numbers differs exactly by 1. Anna was given several numbers and arranged them in a circle to fulfill the task. Then she wanted... | instruction | 0 | 101,336 | 20 | 202,672 |
Tags: constructive algorithms, implementation
Correct Solution:
```
import sys
n = int(input())
c = {}
a = [int(i) for i in input().split()]
maxi = max(a)
for i in a:
c[i] = c.get(i, 0) + 1
l = sorted(c)
t = l[:-1]
for u in t:
if u + 1 not in c:
print("NO")
sys.exit()
c[u + 1] -= c[u]
if... | output | 1 | 101,336 | 20 | 202,673 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,497 | 20 | 202,994 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n = int(input())
a = list(map(lambda x: int(x.split('.')[1]), input().split()))
s = sum(a) - n * 1000
zero_cnt = a.count(0)
min_add = max(0, zero_cnt - n)
max_add = min(n, zero_cnt)
answ = min(abs(s + i * 1000) for i in range(min_add, max_add + 1))
print(... | output | 1 | 101,497 | 20 | 202,995 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,498 | 20 | 202,996 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n, k, s = int(input()), 0, 0
for i in input().split():
j = int(i[-3: ])
if j == 0: k += 1
else: s += j
c = s // 1000 + int(s % 1000 > 500)
a, b = max(0, n - k), min(2 * n - k, n)
if a <= c <= b: s = abs(c * 1000 - s)
else: s = min(abs(a * 1000 - s... | output | 1 | 101,498 | 20 | 202,997 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,499 | 20 | 202,998 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n, t = int(input()), [int(i[-3: ]) for i in input().split()]
k, s = t.count(0), sum(t)
c = s // 1000 + int(s % 1000 > 500)
a, b = max(0, n - k), min(2 * n - k, n)
if a <= c <= b: s = abs(c * 1000 - s)
else: s = min(abs(a * 1000 - s), abs(b * 1000 - s))
print(... | output | 1 | 101,499 | 20 | 202,999 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,500 | 20 | 203,000 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
from math import ceil, floor
N = int(input())
Nums = list(map(float, input().split()))
Zeros = 0
Sum = 0.0
for Num in Nums:
if Num - floor(Num) == 0:
Zeros += 1
else:
Sum += Num - floor(Num)
Best = float(10 ** 9)
for i in range(Zeros ... | output | 1 | 101,500 | 20 | 203,001 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,501 | 20 | 203,002 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
import math
n = int(input())
nums = input().split()
float_nums = [float(ele) for ele in nums]
diff = 0.000
count = 0
for x in float_nums:
diff += x - math.floor(x)
if math.ceil(x) > math.floor(x):
count += 1
min_num = max(0, count - n)
max_... | output | 1 | 101,501 | 20 | 203,003 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,502 | 20 | 203,004 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n = int(input())
l = list(map(float, input().split()))
l = sorted([x - int(x) for x in l if x - int(x) != 0])
o = 2*n - len(l)
su = sum(l)
ans = 0xFFFFFFFFFFFFFFF
for i in range(n + 1):
if i + o >= n:
ans = min(ans, abs(i-su))
print("%.3f... | output | 1 | 101,502 | 20 | 203,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,503 | 20 | 203,006 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n = int(input())
As = list(map(float, input().split()))
B = list(x - int(x) for x in As if x - int(x) > 0.000)
l = len(B)
if l == 0:
print('{:.3f}'.format(0))
exit(0)
S = sum(x for x in B)
ans = 1e10
for i in range(max(0, l - n), min(l,n) + 1):
ans = mi... | output | 1 | 101,503 | 20 | 203,007 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Jeff got 2n real numbers a1, a2, ..., a2n as a birthday present. The boy hates non-integer numbers, so he decided to slightly "adjust" the numbers he's got. Namely, Jeff consecutively executes n operations, each of them goes as follows:
*... | instruction | 0 | 101,504 | 20 | 203,008 |
Tags: dp, greedy, implementation, math
Correct Solution:
```
n = int(input())
a = map(float, input().split())
s = 0
m = 0
for val in a:
s += val-int(val)
m += (val-int(val))>0
v = 1e9
for i in range(max(0, m-n), min(n, m)+1):
v = min(v, abs(s-i))
print('%.3f'%v)
``` | output | 1 | 101,504 | 20 | 203,009 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,513 | 20 | 203,026 |
Tags: implementation
Correct Solution:
```
x=input()
def convert(x):
lst=x.split(" ")
return lst
data=convert(x)
n=int(data[0])
p=int(data[1])
k=int(data[2])
num=[]
for i in range(1,n+1):
num.append(i)
res=[]
r=[">>"]
l=["<<"]
for i in range(p-k,p+k+1):
if i>0 and len(num)>=i:
res.append(num[i-1])
if res[0]==1 ... | output | 1 | 101,513 | 20 | 203,027 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,514 | 20 | 203,028 |
Tags: implementation
Correct Solution:
```
n, p, k = list(map(int,input().split()))
if(p - k > 1):
print("<< ",end="")
for i in range(k):
if(p - k + i >= 1):
print(p - k + i,end=" ")
print("(",end="")
print(p,end=") ")
for i in range(k):
if(p + i + 1 <= n):
print(p + i + 1,end=" ")
if(p ... | output | 1 | 101,514 | 20 | 203,029 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,515 | 20 | 203,030 |
Tags: implementation
Correct Solution:
```
n, p, k = list(map(int, input().split()))
l = []
i = 0
e = 0
while (i <= k*2 and e<n):
e = p-k+i
if e > 0:
l.append(e)
i = i+1
if l[0] > 1:
print('<<', end = ' ')
for i in l:
if i == p:
i = '('+str(i)+')'
print(i, end = ' ')
... | output | 1 | 101,515 | 20 | 203,031 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,516 | 20 | 203,032 |
Tags: implementation
Correct Solution:
```
def pages(n,p,k):
output = ""
if p<1 or p>n :
return output
if p-k > 1 :
output += "<< "
for i in range(p-k, p+k+1):
if i <= n and i >= 1:
if i == p:
output += "(" + str(i) + ") "
else:
... | output | 1 | 101,516 | 20 | 203,033 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,517 | 20 | 203,034 |
Tags: implementation
Correct Solution:
```
# cook your dish here
p,n,k=map(int,input().split())
u=1
d=p+1
if n-k<=1:
ans=[]
else:
ans=["<<"]
if n+k+1<=p:
d=n+k+1
if n-k>0:
u=n-k
for i in range(u,d):
if i==n:
ans.append("("+str(n)+")")
else:
ans.append(i)
if n<p-k:
ans.append(... | output | 1 | 101,517 | 20 | 203,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,518 | 20 | 203,036 |
Tags: implementation
Correct Solution:
```
entrada=input()
numbers=entrada.split()
n=int(numbers[0])
p=int(numbers[1])
k=int(numbers[2])
if p+k>=n and p-k<=1:
for i in range (1, n+1):
if i==p:
print("(" + str(p) + ")", end=" ")
else:
print(i,end=" ")
if p+k>=n and p-k>1:
... | output | 1 | 101,518 | 20 | 203,037 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,519 | 20 | 203,038 |
Tags: implementation
Correct Solution:
```
class Solution:
def navigation(self, n, p, k):
start = max(1, p-k)
end = min(p+k, n)
pagination = ""
if start > 1:
pagination += "<< "
while start <= end:
if start == p:
pagination += "(" +... | output | 1 | 101,519 | 20 | 203,039 |
Provide tags and a correct Python 3 solution for this coding contest problem.
User ainta is making a web site. This time he is going to make a navigation of the pages. In his site, there are n pages numbered by integers from 1 to n. Assume that somebody is on the p-th page now. The navigation will look like this:
<< ... | instruction | 0 | 101,520 | 20 | 203,040 |
Tags: implementation
Correct Solution:
```
a, b, c = map(int, input().split(" "))
# a β limit bβnow c β range
ll = max(1, b-c)
rl = min(a, b + c )
left = [i for i in range(b - 1, ll-1, -1)]
right = [i for i in range(b + 1, rl + 1)]
l_bar = "<< "
if ll == 1:
l_bar = ""
r_bar = " >>"
if rl == a:
r_bar = ""
l... | output | 1 | 101,520 | 20 | 203,041 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,577 | 20 | 203,154 |
Tags: greedy, math, sortings
Correct Solution:
```
x = int(input())
y = input()
ct = {0:[0, 0, 0, 0], 1:[0, 0, 0, 0], 2:[1, 0, 0, 0], 3:[1, 1, 0, 0], 4:[3, 1, 0, 0], 5:[3, 1, 1, 0], 6:[4, 2, 1, 0], 7:[4, 2, 1, 1], 8:[7, 2, 1, 1], 9:[7, 4, 1, 1]}
real = {2:[1, 0, 0, 0], 3:[1, 1, 0, 0], 4:[3, 1, 0, 0], 5:[3, 1, 1, 0], 6:... | output | 1 | 101,577 | 20 | 203,155 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,578 | 20 | 203,156 |
Tags: greedy, math, sortings
Correct Solution:
```
n = input()
s = input()
s = s.replace('9','7332')
s = s.replace('8','7222')
s = s.replace('6','53')
s = s.replace('4','322')
s = s.replace('1','')
s = s.replace('0','')
s = ''.join(sorted(s,reverse=True))
print(s)
``` | output | 1 | 101,578 | 20 | 203,157 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,579 | 20 | 203,158 |
Tags: greedy, math, sortings
Correct Solution:
```
I=lambda:list(map(int,input().split()))
n=I()
f=['','','2','3','223','5','53','7','7222','7332']
v=''
for i in input():
v+=f[int(i)]
v=list(v)
v.sort(reverse=True)
print(''.join(v))
``` | output | 1 | 101,579 | 20 | 203,159 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,580 | 20 | 203,160 |
Tags: greedy, math, sortings
Correct Solution:
```
n=int(input())
a=[int(x) for x in list(input())]
fac={2:0,3:0,5:0,7:0}
ans=[]
for i in range(2,10):
t=a.count(i)
if i==9:
fac[2]+=7*t
fac[3]+=4*t
fac[5]+=t
fac[7]+=t
if i==8:
fac[2]+=7*t
fac[3]+=2*t
fa... | output | 1 | 101,580 | 20 | 203,161 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,581 | 20 | 203,162 |
Tags: greedy, math, sortings
Correct Solution:
```
n = int(input())
s = input()
ans = ""
for i in s:
if(i=="1" or i=="0"):
continue
elif(i=="4"):
ans+="322"
elif(i=="6"):
ans+="53"
elif(i=="8"):
ans+="7222"
elif(i=="9"):
ans+="7332"
else:
ans+=i
an... | output | 1 | 101,581 | 20 | 203,163 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,582 | 20 | 203,164 |
Tags: greedy, math, sortings
Correct Solution:
```
a = int(input())
b = str(input())
answer = list()
for x in b:
if x != "0" and x != "1":
if x == "4":
answer += ["3", "2", "2"]
elif x == "6":
answer += ["5", "3"]
elif x == "8":
answer += ["7", "2", "2", "... | output | 1 | 101,582 | 20 | 203,165 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,583 | 20 | 203,166 |
Tags: greedy, math, sortings
Correct Solution:
```
a = input("")
b = input("")
outstring = ""
for value in b:
if value == "1":
continue
elif value == "2":
outstring = outstring + "2"
elif value == "3":
outstring = outstring + "3"
elif value == "4":
outstring = outstring +... | output | 1 | 101,583 | 20 | 203,167 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a consisting of n digits that contains at least one d... | instruction | 0 | 101,584 | 20 | 203,168 |
Tags: greedy, math, sortings
Correct Solution:
```
def aus(argument):
switcher = {
0:[],
1:[],
2:[2],
3:[3],
4:[3,2,2],
5:[5],
6:[3,5],
7:[7],
8:[2,2,2,7],
9:[2,3,3,7],
}
return switcher.get(argument)
summ=[]
a= int(input())
b= input(... | output | 1 | 101,584 | 20 | 203,169 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,585 | 20 | 203,170 |
Yes | output | 1 | 101,585 | 20 | 203,171 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,586 | 20 | 203,172 |
Yes | output | 1 | 101,586 | 20 | 203,173 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,587 | 20 | 203,174 |
Yes | output | 1 | 101,587 | 20 | 203,175 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,588 | 20 | 203,176 |
Yes | output | 1 | 101,588 | 20 | 203,177 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,589 | 20 | 203,178 |
No | output | 1 | 101,589 | 20 | 203,179 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Drazil is playing a math game with Varda.
Let's define <image> for positive integer x as a product of factorials of its digits. For example, <image>.
First, they choose a decimal number a cons... | instruction | 0 | 101,590 | 20 | 203,180 |
No | output | 1 | 101,590 | 20 | 203,181 |
Subsets and Splits
No community queries yet
The top public SQL queries from the community will appear here once available.