message stringlengths 2 59.7k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. F0 = 0, F1 = 1, and all the next numbers are Fi = Fi - 2 + Fi - 1.
So, Fibonacci numbers make a sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, ...
If you haven't run away from the PC in fear, you have to help the virus. Your task is to divide given Fibonacci number n by three not necessary different Fibonacci numbers or say that it is impossible.
Input
The input contains of a single integer n (0 ≤ n < 109) — the number that should be represented by the rules described above. It is guaranteed that n is a Fibonacci number.
Output
Output three required numbers: a, b and c. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them.
Examples
Input
3
Output
1 1 1
Input
13
Output
2 3 8
Submitted Solution:
```
b=[1]
def fib(b):
if n==0:
mm=[0,0,0]
return (" ".join(map(str,mm)))
if n==1:
mm=[1,0,0]
return (" ".join(map(str,mm)))
a=1
i=0
while a<n+1:
b.append(a)
a=a+b[i]
i=i+1
dd=[0]
dd.append(b[len(b)-3])
dd.append(b[len(b)-2])
return (" ".join(map(str,dd)))
n=int(input())
ans=fib(b)
print(ans)
``` | instruction | 0 | 14,444 | 20 | 28,888 |
Yes | output | 1 | 14,444 | 20 | 28,889 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. F0 = 0, F1 = 1, and all the next numbers are Fi = Fi - 2 + Fi - 1.
So, Fibonacci numbers make a sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, ...
If you haven't run away from the PC in fear, you have to help the virus. Your task is to divide given Fibonacci number n by three not necessary different Fibonacci numbers or say that it is impossible.
Input
The input contains of a single integer n (0 ≤ n < 109) — the number that should be represented by the rules described above. It is guaranteed that n is a Fibonacci number.
Output
Output three required numbers: a, b and c. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them.
Examples
Input
3
Output
1 1 1
Input
13
Output
2 3 8
Submitted Solution:
```
n=int(input())
l=[]
l.append(0)
l.append(1)
ind=2
while (l[ind-1]+l[ind-2])<=n:
l.append(l[ind-1]+l[ind-2])
ind+=1
#print(l)
f=l[ind-3]
s=l[ind-3]
t=l[ind-4]
print(str(f)+' '+str(s)+' '+str(t))
``` | instruction | 0 | 14,445 | 20 | 28,890 |
No | output | 1 | 14,445 | 20 | 28,891 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. F0 = 0, F1 = 1, and all the next numbers are Fi = Fi - 2 + Fi - 1.
So, Fibonacci numbers make a sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, ...
If you haven't run away from the PC in fear, you have to help the virus. Your task is to divide given Fibonacci number n by three not necessary different Fibonacci numbers or say that it is impossible.
Input
The input contains of a single integer n (0 ≤ n < 109) — the number that should be represented by the rules described above. It is guaranteed that n is a Fibonacci number.
Output
Output three required numbers: a, b and c. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them.
Examples
Input
3
Output
1 1 1
Input
13
Output
2 3 8
Submitted Solution:
```
import math
n = int(input())
if n==1:
print(0,0,1)
elif n==0:
print(0,0,0)
elif n==2:
print(0,1,1)
elif n==3:
print(1,1,1)
elif n>=5:
te=n*1.625
te=math.floor(te)
te1=te-n
te2=n-te1
te3=te1-te2
te4=te2-te3
print(te4,te3,te1)
``` | instruction | 0 | 14,446 | 20 | 28,892 |
No | output | 1 | 14,446 | 20 | 28,893 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. F0 = 0, F1 = 1, and all the next numbers are Fi = Fi - 2 + Fi - 1.
So, Fibonacci numbers make a sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, ...
If you haven't run away from the PC in fear, you have to help the virus. Your task is to divide given Fibonacci number n by three not necessary different Fibonacci numbers or say that it is impossible.
Input
The input contains of a single integer n (0 ≤ n < 109) — the number that should be represented by the rules described above. It is guaranteed that n is a Fibonacci number.
Output
Output three required numbers: a, b and c. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them.
Examples
Input
3
Output
1 1 1
Input
13
Output
2 3 8
Submitted Solution:
```
n = int(input())
a = [1, 1]
while a[len(a) - 1] < n:
a.append(a[len(a) - 1] + a[len(a) - 2])
if n < 3:
print("I'm too stupid to solve this problem")
elif n == 3:
print(1, 1, 1)
else:
b = len(a)
print(a[b - 2], a[b - 4], a[b - 5])
``` | instruction | 0 | 14,447 | 20 | 28,894 |
No | output | 1 | 14,447 | 20 | 28,895 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Recently, a chaotic virus Hexadecimal advanced a new theorem which will shake the Universe. She thinks that each Fibonacci number can be represented as sum of three not necessary different Fibonacci numbers.
Let's remember how Fibonacci numbers can be calculated. F0 = 0, F1 = 1, and all the next numbers are Fi = Fi - 2 + Fi - 1.
So, Fibonacci numbers make a sequence of numbers: 0, 1, 1, 2, 3, 5, 8, 13, ...
If you haven't run away from the PC in fear, you have to help the virus. Your task is to divide given Fibonacci number n by three not necessary different Fibonacci numbers or say that it is impossible.
Input
The input contains of a single integer n (0 ≤ n < 109) — the number that should be represented by the rules described above. It is guaranteed that n is a Fibonacci number.
Output
Output three required numbers: a, b and c. If there is no answer for the test you have to print "I'm too stupid to solve this problem" without the quotes.
If there are multiple answers, print any of them.
Examples
Input
3
Output
1 1 1
Input
13
Output
2 3 8
Submitted Solution:
```
n=int(input())
def fib_to(k):
fibs = [0, 1]
for i in range(2, k+1):
fibs.append(fibs[-1] + fibs[-2])
return fibs
a=fib_to(50)
z=a.index(n)
if(n>1):
print('0'+' '+str(a[z-2])+' '+str(a[z-1]))
else:
print("I'm too stupid to solve this problem")
``` | instruction | 0 | 14,448 | 20 | 28,896 |
No | output | 1 | 14,448 | 20 | 28,897 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,470 | 20 | 28,940 |
Tags: brute force
Correct Solution:
```
n = input()
while True:
n = int(n)
n += 1
n = str(n)
flag = 0
for i in range(4):
for j in range(4):
if i==j:
continue
if n[i] == n[j]:
flag = 1
break
if flag == 1:
break
if flag == 0:
print(n)
break
``` | output | 1 | 14,470 | 20 | 28,941 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,471 | 20 | 28,942 |
Tags: brute force
Correct Solution:
```
nn=int(input())
for i in range(nn+1,nn*1000):
l=len(str(i))
if len(set(str(i)))==l:
print(i)
break
``` | output | 1 | 14,471 | 20 | 28,943 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,472 | 20 | 28,944 |
Tags: brute force
Correct Solution:
```
import sys
inp = sys.stdin
y = int(inp.readline()) + 1
def check_dif(num):
s = str(num)
ok = 1
for i in range(len(s)):
if s[i] in s[i + 1:]:
ok = 0
return ok
while check_dif(y) == 0:
y += 1
print(y)
``` | output | 1 | 14,472 | 20 | 28,945 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,473 | 20 | 28,946 |
Tags: brute force
Correct Solution:
```
n= int(input())
x = n+1
z=list()
while(True):
n = x
l = []
while(n>0):
t = n%10
l.append(t)
n = n//10
p = set(l)
if(len(p)==len(l)):
l.reverse()
z = l
break
x+=1
for i in z:
print(i,end="")
``` | output | 1 | 14,473 | 20 | 28,947 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,474 | 20 | 28,948 |
Tags: brute force
Correct Solution:
```
year = int(input())
a = 0
while a == 0:
year += 1
s_year = list(str(year))
s_year = set(s_year)
if len(s_year) > 3:
a = 1
print(year)
``` | output | 1 | 14,474 | 20 | 28,949 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,475 | 20 | 28,950 |
Tags: brute force
Correct Solution:
```
t=int(input())+1
while True:
if len(set(str(t)))==len(str(t)):
print(t)
break
t=t+1
``` | output | 1 | 14,475 | 20 | 28,951 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,476 | 20 | 28,952 |
Tags: brute force
Correct Solution:
```
y = int(input())
for i in range(y+1,9999,1):
z= str(i)
if z[0] != z[1] and z[0] != z[2] and z[0] != z[3] and z[1] != z[2] and z[1] != z[3] and z[2] != z[3] :
print(int(z))
break
``` | output | 1 | 14,476 | 20 | 28,953 |
Provide tags and a correct Python 3 solution for this coding contest problem.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014 | instruction | 0 | 14,477 | 20 | 28,954 |
Tags: brute force
Correct Solution:
```
import math
a = input()
a = int(a)
a = a + 1
while True:
b = (a/1000)
b = math.floor(b)
c = ((a%1000)/100)
c = math.floor(c)
d = (((a%1000)%100)/10)
d = math.floor(d)
e = (((a%1000)%100)%10)
e = math.floor(e)
a = (b*1000) + (c*100) + (d*10) + e
if((b==c) or (b==d) or (b==e) or (c==d) or (c==e) or (d==e)):
a = a + 1
continue
else:
a = int(a)
print(a)
break
``` | output | 1 | 14,477 | 20 | 28,955 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
year = input()
for num in range(int(year)+1, 10001):
yearString = str(num)
if len(set(yearString)) == 4:
print(yearString)
break
``` | instruction | 0 | 14,478 | 20 | 28,956 |
Yes | output | 1 | 14,478 | 20 | 28,957 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
n = int(input())
def is_beaufiful(num):
num = str(num)
vals = [num.count(v) == 1 for v in num]
return all(vals)
answer = n + 1
while not is_beaufiful(answer):
answer += 1
print(answer)
``` | instruction | 0 | 14,479 | 20 | 28,958 |
Yes | output | 1 | 14,479 | 20 | 28,959 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
y = int(input())
a = 0
b = 0
c = 0
d = 0
while a == b or a == c or a == d or b == c or b == d or c == d:
y += 1
a = y // 1000
b = y // 100 % 10
c = y // 10 % 10
d = y % 10
print(y)
``` | instruction | 0 | 14,480 | 20 | 28,960 |
Yes | output | 1 | 14,480 | 20 | 28,961 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
# cook your dish here
n = int(input())
s = False
while s==False:
n+=1
if(len(set(str(n))) == 4):
s = True
print(n)
``` | instruction | 0 | 14,481 | 20 | 28,962 |
Yes | output | 1 | 14,481 | 20 | 28,963 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
y = int(input())
for i in range(y+1, 9001):
s = str(i)
if len(set(s)) == len(s):
print(i)
break
``` | instruction | 0 | 14,482 | 20 | 28,964 |
No | output | 1 | 14,482 | 20 | 28,965 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
if __name__ == '__main__':
numb = int(input())
result = ""
for i in range(numb+1, 9001):
list1 = list(str(i))
list2 = set(list1)
if len(list1) == len(list2):
for i in list1:
result += str(i)
print(result)
break
``` | instruction | 0 | 14,483 | 20 | 28,966 |
No | output | 1 | 14,483 | 20 | 28,967 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
def by(x): # x is int
lx = list(str(x))
sx = set(str(x))
if len(lx) == len(sx):
return 1
def nby(x):
t = x
while by(t) != 1:
t += 1
continue
return t
y = int(input())
print(nby(y))
``` | instruction | 0 | 14,484 | 20 | 28,968 |
No | output | 1 | 14,484 | 20 | 28,969 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
It seems like the year of 2013 came only yesterday. Do you know a curious fact? The year of 2013 is the first year after the old 1987 with only distinct digits.
Now you are suggested to solve the following problem: given a year number, find the minimum year number which is strictly larger than the given one and has only distinct digits.
Input
The single line contains integer y (1000 ≤ y ≤ 9000) — the year number.
Output
Print a single integer — the minimum year number that is strictly larger than y and all it's digits are distinct. It is guaranteed that the answer exists.
Examples
Input
1987
Output
2013
Input
2013
Output
2014
Submitted Solution:
```
year = int(input())
def check(a,b,c,d):
if a==b or a ==c or a==d or b==c or b==d or c==d:
return False
else:
return True
while True:
year+=1
yearstr=str(year)
if check(yearstr[0],yearstr[1],yearstr[2],yearstr[3]):
print(year)
break
print(check(2,0,1,3))
``` | instruction | 0 | 14,485 | 20 | 28,970 |
No | output | 1 | 14,485 | 20 | 28,971 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,502 | 20 | 29,004 |
Tags: math
Correct Solution:
```
n,k = [int(x) for x in input().split()]
value=int(n/2)
even=value
odd=value
if int(n%2) == 1:
odd+=1
if k<=odd:
print(2*k-1)
else:
t=(k-odd)
print(2*t)
``` | output | 1 | 14,502 | 20 | 29,005 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,503 | 20 | 29,006 |
Tags: math
Correct Solution:
```
n, k = map(int, input().split())
if k > (n - n // 2):
print((k - n + n // 2) * 2)
else:
print(k * 2 - 1)
``` | output | 1 | 14,503 | 20 | 29,007 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,504 | 20 | 29,008 |
Tags: math
Correct Solution:
```
a,b=map(int,input().split())
c=b-(a+1)//2
if c>0:
print(c*2)
else :
print(b*2-1)
``` | output | 1 | 14,504 | 20 | 29,009 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,505 | 20 | 29,010 |
Tags: math
Correct Solution:
```
# import sys
# sys.stdin = open("test.in","r")
# sys.stdout = open("test.out","w")
n,k=map(int,input().split())
if n%2==1:
if k<=n//2+1:
print(2*k-1)
else:
k-=n//2+1
print(2*k)
else:
if k<=n//2:
print(2*k-1)
else:
k-=n//2
print(2*k)
``` | output | 1 | 14,505 | 20 | 29,011 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,506 | 20 | 29,012 |
Tags: math
Correct Solution:
```
n,k= map(int, input().split())
last_index=0
if(n%2!=0):
last_index=(n+1)/2
else:
last_index=n/2
if(k>last_index):
print(int(k-last_index)*2)
else:
print(int(k*2)-1)
``` | output | 1 | 14,506 | 20 | 29,013 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,507 | 20 | 29,014 |
Tags: math
Correct Solution:
```
string = input().split()
n = int(string[0])
k = int(string[1])
if(n%2 == 0):
if(k>(n/2)):
print(int(2*(k-n/2)))
else:
print(int(2*k-1))
n1 = (int)((n+1)/2)
if(n%2!=0 and k>n1):
print(int(2*(k-n1)))
if(n%2!=0 and k<=n1):
print(int(2*k-1))
``` | output | 1 | 14,507 | 20 | 29,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,508 | 20 | 29,016 |
Tags: math
Correct Solution:
```
s=input('')
n,k=s.split(' ')
n=int(n)
k=int(k)
#print(type(n),type(k))
if(int(n%2)==0):
odd=int(n/2)
even=int(n/2)
else:
odd=int(n/2+1)
even=int(n/2)
#print(even,odd)
if(k<=odd):
value=2*(k-1)+1
else:
value=2*(k-odd)
print(value)
``` | output | 1 | 14,508 | 20 | 29,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5. | instruction | 0 | 14,509 | 20 | 29,018 |
Tags: math
Correct Solution:
```
n,b = map(int,input().split())
if n%2==0:
z = int(n/2)
else:
z = int(n/2)+1
if b<=z:print(2*b-1)
else:print((b-z)*2)
``` | output | 1 | 14,509 | 20 | 29,019 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
nk = [int(x) for x in input().split()]
n, k =nk[0], nk[1]
if 2 * k - 1 <= n:
print(2 * k - 1)
else:
print(2 * (n // 2) - 2 * (n - k))
``` | instruction | 0 | 14,510 | 20 | 29,020 |
Yes | output | 1 | 14,510 | 20 | 29,021 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
import math
n, k = input().split(' ')
n = int(n)
k = int(k)
if k <= math.ceil(n / 2):
print(2*k - 1)
else:
print(2*(k - math.ceil(n / 2)))
``` | instruction | 0 | 14,511 | 20 | 29,022 |
Yes | output | 1 | 14,511 | 20 | 29,023 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
n,k=map(int,input().split())
odd=(n+1)//2
if(k<=odd):
print(int(2*k-1))
else:
print(int((k-odd)*2))
``` | instruction | 0 | 14,512 | 20 | 29,024 |
Yes | output | 1 | 14,512 | 20 | 29,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
a,b=input().split()
a=int(a)
b=int(b)
if a%2==0:
if b<=(a/2):
print(2*b-1)
else:
print(int(2*(b-(a/2))))
else:
if b<=((a+1)/2):
print(2*b-1)
else:
print(int(2*(b-((a+1)/2))))
``` | instruction | 0 | 14,513 | 20 | 29,026 |
Yes | output | 1 | 14,513 | 20 | 29,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
n,k=map(int,input().split())
if k<(n//2 + n%2):
print(2*(k-1)+1)
else:
k-=n//2 + n%2
print(2*k)
``` | instruction | 0 | 14,514 | 20 | 29,028 |
No | output | 1 | 14,514 | 20 | 29,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
a,b=map(int,input().split(" "))
if(b<=(a+1)/2):
print(b*2-1)
else:
print((b-(a+1))/2)
``` | instruction | 0 | 14,515 | 20 | 29,030 |
No | output | 1 | 14,515 | 20 | 29,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
n,k=[int(i) for i in input().split(' ')]
if 2*(k-1)+1>n:
print(2*k%n)
else:
print(2*(k-1)+1)
``` | instruction | 0 | 14,516 | 20 | 29,032 |
No | output | 1 | 14,516 | 20 | 29,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Being a nonconformist, Volodya is displeased with the current state of things, particularly with the order of natural numbers (natural number is positive integer number). He is determined to rearrange them. But there are too many natural numbers, so Volodya decided to start with the first n. He writes down the following sequence of numbers: firstly all odd integers from 1 to n (in ascending order), then all even integers from 1 to n (also in ascending order). Help our hero to find out which number will stand at the position number k.
Input
The only line of input contains integers n and k (1 ≤ k ≤ n ≤ 1012).
Please, do not use the %lld specifier to read or write 64-bit integers in C++. It is preferred to use the cin, cout streams or the %I64d specifier.
Output
Print the number that will stand at the position number k after Volodya's manipulations.
Examples
Input
10 3
Output
5
Input
7 7
Output
6
Note
In the first sample Volodya's sequence will look like this: {1, 3, 5, 7, 9, 2, 4, 6, 8, 10}. The third place in the sequence is therefore occupied by the number 5.
Submitted Solution:
```
n,k=map(int,input().split())
a=[]
for i in range(1,n,2):
a.append(i)
for i in range(0,n,2):
a.append(i)
print(a[k-1])
``` | instruction | 0 | 14,517 | 20 | 29,034 |
No | output | 1 | 14,517 | 20 | 29,035 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,560 | 20 | 29,120 |
Tags: *special
Correct Solution:
```
from math import *
r = float(input())
for a in range(1,11):
for h in range(1,11):
R = a*a*h*0.5/sqrt(h*h+a*a/4)/a
if abs(R-r)<1e-5:
print(a,h)
exit()
``` | output | 1 | 14,560 | 20 | 29,121 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,561 | 20 | 29,122 |
Tags: *special
Correct Solution:
```
r=float(input())
a=0
h=0
for i in range(1,11):
for j in range(1,11):
c=pow(j*j+i*i/4.,0.5)
rtest=i*j*0.5/c
if abs(rtest-r)<0.00001:
a=i
h=j
print(a,h)
``` | output | 1 | 14,561 | 20 | 29,123 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,562 | 20 | 29,124 |
Tags: *special
Correct Solution:
```
k = float(input())
flag = True
for i in range(1, 11):
for j in range(1, 11):
if abs(k - i / 2 * j / ((i / 2) ** 2 + j ** 2) ** (1 / 2)) <= 1e-6:
flag = False
print(i, j)
break
if not flag:
break
``` | output | 1 | 14,562 | 20 | 29,125 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,563 | 20 | 29,126 |
Tags: *special
Correct Solution:
```
x = float(input())
for a in range(1, 10+1):
for h in range(1, 10+1):
if abs(x - (4/(a*a) + 1/(h*h)) ** (-0.5)) <= 10 ** -5:
print(a, h)
quit()
``` | output | 1 | 14,563 | 20 | 29,127 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,564 | 20 | 29,128 |
Tags: *special
Correct Solution:
```
from math import sqrt
eps = 1e-5
def check(a, h, x):
return abs(x * sqrt(4 * h * h + a * a) - a * h) < eps
def main():
x = float(input())
for a in range(1, 11):
for h in range(1, 11):
if check(a, h, x):
print(a, h)
return
main()
``` | output | 1 | 14,564 | 20 | 29,129 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,565 | 20 | 29,130 |
Tags: *special
Correct Solution:
```
from math import sqrt
import sys
x = float(input())
for a in range(1, 11):
for h in range(1, 11):
if abs(x -( a * h / sqrt(a * a + 4 * h * h)) )< 0.00001:
print(a, h)
sys.exit()
``` | output | 1 | 14,565 | 20 | 29,131 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,566 | 20 | 29,132 |
Tags: *special
Correct Solution:
```
import sys
from math import sqrt, pi
X = float(input())
def rad_len(a, h, c):
x = c * a/2
# y = c * sqrt((a / 2)**2 + h**2)
y = c * h
return sqrt((x - a/2)**2 + (y - 0)**2)
def get_max_radius(a, h):
lo = 0.0
hi = 1.0
while abs(lo - hi) > 1e-9:
# print(lo, hi, rad_len(a, h, lo), rad_len(a, h, hi))
p = lo + (hi - lo) / 3
q = lo + 2 * (hi - lo) / 3
if rad_len(a, h, p) > rad_len(a, h, q):
lo = p
else:
hi = q
# for cx in range(100 + 0):
# print(rad_len(a, h, cx / 100.0))
return rad_len(a, h, lo)
for i in range(9, -1, -1):
for ai in range(1, 11):
for hi in range(1, 11):
a = float(ai)
h = float(hi)
r = get_max_radius(a, h)
if abs(r - X) < 10**(-i):
print(ai, hi)
sys.exit(0)
``` | output | 1 | 14,566 | 20 | 29,133 |
Provide tags and a correct Python 3 solution for this coding contest problem.
<image>
Input
The input contains a single floating-point number x with exactly 6 decimal places (0 < x < 5).
Output
Output two integers separated by a single space. Each integer should be between 1 and 10, inclusive. If several solutions exist, output any of them. Solution will exist for all tests.
Examples
Input
1.200000
Output
3 2
Input
2.572479
Output
10 3
Input
4.024922
Output
9 9 | instruction | 0 | 14,567 | 20 | 29,134 |
Tags: *special
Correct Solution:
```
import sys
x = float(sys.stdin.readline())
diff = x
for a in range(1, 11):
for h in range(1, 11):
t = pow((a*a*h*h)/(a*a+4*h*h), 0.5)
if diff > abs(x - t):
diff = abs(x-t)
ans_a = a
ans_h = h
print(ans_a, ans_h)
``` | output | 1 | 14,567 | 20 | 29,135 |
Provide tags and a correct Python 3 solution for this coding contest problem.
People do many crazy things to stand out in a crowd. Some of them dance, some learn by heart rules of Russian language, some try to become an outstanding competitive programmers, while others collect funny math objects.
Alis is among these collectors. Right now she wants to get one of k-special tables. In case you forget, the table n × n is called k-special if the following three conditions are satisfied:
* every integer from 1 to n2 appears in the table exactly once;
* in each row numbers are situated in increasing order;
* the sum of numbers in the k-th column is maximum possible.
Your goal is to help Alice and find at least one k-special table of size n × n. Both rows and columns are numbered from 1 to n, with rows numbered from top to bottom and columns numbered from left to right.
Input
The first line of the input contains two integers n and k (1 ≤ n ≤ 500, 1 ≤ k ≤ n) — the size of the table Alice is looking for and the column that should have maximum possible sum.
Output
First print the sum of the integers in the k-th column of the required table.
Next n lines should contain the description of the table itself: first line should contains n elements of the first row, second line should contain n elements of the second row and so on.
If there are multiple suitable table, you are allowed to print any.
Examples
Input
4 1
Output
28
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
Input
5 3
Output
85
5 6 17 18 19
9 10 23 24 25
7 8 20 21 22
3 4 14 15 16
1 2 11 12 13 | instruction | 0 | 14,644 | 20 | 29,288 |
Tags: constructive algorithms, implementation
Correct Solution:
```
n, k = map(int, input().split())
sol = [[0] * n for _ in range(n)]
res = 0
c = 1
for j in range(k - 1):
for i in range(n):
sol[i][j] = c
c += 1
for i in range(n):
for j in range(k - 1, n):
sol[i][j] = c
c += 1
for i in range(n):
res += sol[i][k - 1]
print(res)
for line in sol:
for col in line:
print(col, end=" ")
print()
``` | output | 1 | 14,644 | 20 | 29,289 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The number "zero" is called "love" (or "l'oeuf" to be precise, literally means "egg" in French), for example when denoting the zero score in a game of tennis.
Aki is fond of numbers, especially those with trailing zeros. For example, the number 9200 has two trailing zeros. Aki thinks the more trailing zero digits a number has, the prettier it is.
However, Aki believes, that the number of trailing zeros of a number is not static, but depends on the base (radix) it is represented in. Thus, he considers a few scenarios with some numbers and bases. And now, since the numbers he used become quite bizarre, he asks you to help him to calculate the beauty of these numbers.
Given two integers n and b (in decimal notation), your task is to calculate the number of trailing zero digits in the b-ary (in the base/radix of b) representation of n ! ([factorial](https://en.wikipedia.org/wiki/Factorial) of n).
Input
The only line of the input contains two integers n and b (1 ≤ n ≤ 10^{18}, 2 ≤ b ≤ 10^{12}).
Output
Print an only integer — the number of trailing zero digits in the b-ary representation of n!
Examples
Input
6 9
Output
1
Input
38 11
Output
3
Input
5 2
Output
3
Input
5 10
Output
1
Note
In the first example, 6!_{(10)} = 720_{(10)} = 880_{(9)}.
In the third and fourth example, 5!_{(10)} = 120_{(10)} = 1111000_{(2)}.
The representation of the number x in the b-ary base is d_1, d_2, …, d_k if x = d_1 b^{k - 1} + d_2 b^{k - 2} + … + d_k b^0, where d_i are integers and 0 ≤ d_i ≤ b - 1. For example, the number 720 from the first example is represented as 880_{(9)} since 720 = 8 ⋅ 9^2 + 8 ⋅ 9 + 0 ⋅ 1.
You can read more about bases [here](https://en.wikipedia.org/wiki/Radix). | instruction | 0 | 15,138 | 20 | 30,276 |
Tags: brute force, implementation, math, number theory
Correct Solution:
```
N, B = [int(x) for x in input().split()]
v = []
for i in range(2, 10**6 + 1000):
while B % i == 0:
v.append(i)
B //= i
if B != 1:
v.append(B)
def zeros(p, v, N):
res = 0
pk = p
while pk <= N:
res += N // pk
pk *= p
res //= v.count(p)
return res
print(min(zeros(x, v, N) for x in v))
``` | output | 1 | 15,138 | 20 | 30,277 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The number "zero" is called "love" (or "l'oeuf" to be precise, literally means "egg" in French), for example when denoting the zero score in a game of tennis.
Aki is fond of numbers, especially those with trailing zeros. For example, the number 9200 has two trailing zeros. Aki thinks the more trailing zero digits a number has, the prettier it is.
However, Aki believes, that the number of trailing zeros of a number is not static, but depends on the base (radix) it is represented in. Thus, he considers a few scenarios with some numbers and bases. And now, since the numbers he used become quite bizarre, he asks you to help him to calculate the beauty of these numbers.
Given two integers n and b (in decimal notation), your task is to calculate the number of trailing zero digits in the b-ary (in the base/radix of b) representation of n ! ([factorial](https://en.wikipedia.org/wiki/Factorial) of n).
Input
The only line of the input contains two integers n and b (1 ≤ n ≤ 10^{18}, 2 ≤ b ≤ 10^{12}).
Output
Print an only integer — the number of trailing zero digits in the b-ary representation of n!
Examples
Input
6 9
Output
1
Input
38 11
Output
3
Input
5 2
Output
3
Input
5 10
Output
1
Note
In the first example, 6!_{(10)} = 720_{(10)} = 880_{(9)}.
In the third and fourth example, 5!_{(10)} = 120_{(10)} = 1111000_{(2)}.
The representation of the number x in the b-ary base is d_1, d_2, …, d_k if x = d_1 b^{k - 1} + d_2 b^{k - 2} + … + d_k b^0, where d_i are integers and 0 ≤ d_i ≤ b - 1. For example, the number 720 from the first example is represented as 880_{(9)} since 720 = 8 ⋅ 9^2 + 8 ⋅ 9 + 0 ⋅ 1.
You can read more about bases [here](https://en.wikipedia.org/wiki/Radix). | instruction | 0 | 15,139 | 20 | 30,278 |
Tags: brute force, implementation, math, number theory
Correct Solution:
```
# AC
import sys
class Main:
def __init__(self):
self.buff = None
self.index = 0
def next(self):
if self.buff is None or self.index == len(self.buff):
self.buff = self.next_line()
self.index = 0
val = self.buff[self.index]
self.index += 1
return val
def next_line(self, _map=str):
return list(map(_map, sys.stdin.readline().split()))
def next_int(self):
return int(self.next())
def solve(self):
n, b = self.next_line(int)
rs = -1
for i in range(2, 1000001):
if b % i == 0:
ct = 0
while b % i == 0:
b //= i
ct += 1
t = self.cal(n, i)
tt = t // ct
if rs == -1 or tt < rs:
rs = tt
if b > 1:
t = self.cal(n, b)
if rs == -1 or t < rs:
rs = t
print(rs)
def cal(self, n, k):
return 0 if n == 0 else n // k + self.cal(n // k, k)
if __name__ == '__main__':
Main().solve()
``` | output | 1 | 15,139 | 20 | 30,279 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The number "zero" is called "love" (or "l'oeuf" to be precise, literally means "egg" in French), for example when denoting the zero score in a game of tennis.
Aki is fond of numbers, especially those with trailing zeros. For example, the number 9200 has two trailing zeros. Aki thinks the more trailing zero digits a number has, the prettier it is.
However, Aki believes, that the number of trailing zeros of a number is not static, but depends on the base (radix) it is represented in. Thus, he considers a few scenarios with some numbers and bases. And now, since the numbers he used become quite bizarre, he asks you to help him to calculate the beauty of these numbers.
Given two integers n and b (in decimal notation), your task is to calculate the number of trailing zero digits in the b-ary (in the base/radix of b) representation of n ! ([factorial](https://en.wikipedia.org/wiki/Factorial) of n).
Input
The only line of the input contains two integers n and b (1 ≤ n ≤ 10^{18}, 2 ≤ b ≤ 10^{12}).
Output
Print an only integer — the number of trailing zero digits in the b-ary representation of n!
Examples
Input
6 9
Output
1
Input
38 11
Output
3
Input
5 2
Output
3
Input
5 10
Output
1
Note
In the first example, 6!_{(10)} = 720_{(10)} = 880_{(9)}.
In the third and fourth example, 5!_{(10)} = 120_{(10)} = 1111000_{(2)}.
The representation of the number x in the b-ary base is d_1, d_2, …, d_k if x = d_1 b^{k - 1} + d_2 b^{k - 2} + … + d_k b^0, where d_i are integers and 0 ≤ d_i ≤ b - 1. For example, the number 720 from the first example is represented as 880_{(9)} since 720 = 8 ⋅ 9^2 + 8 ⋅ 9 + 0 ⋅ 1.
You can read more about bases [here](https://en.wikipedia.org/wiki/Radix). | instruction | 0 | 15,140 | 20 | 30,280 |
Tags: brute force, implementation, math, number theory
Correct Solution:
```
n,b = list(map(int,input().split()))
primes = []
def seive():
nn = 1000100
vis = [False] * nn
for i in range(4,nn,2):
vis[i] = True
i = 3
vis[0],vis[1] = True, True
while(i*i<nn):
if(not vis[i]):
j = i*i
while(j<nn):
vis[j] = True
j += 2*i
i+=2
for i in range(nn):
if(not vis[i]):
primes.append(i)
#print(len(primes))
seive()
def find_factors(nn):
ans = []
for i in primes:
if(nn%i==0):
count = 0
while(nn%i==0):
count+=1
nn/=i
ans.append((i,count))
if nn > 1:
ans.append((nn,1))
return ans
f = find_factors(b)
def find_ans(t):
ff,no = t
ans = 0
temp = ff
while(n//ff):
ans += n//ff
ff *= temp
return ans//no
final_ans = find_ans(f[0])
for i in range(1,len(f)):
final_ans = min(final_ans, find_ans(f[i]))
print(int(final_ans))
``` | output | 1 | 15,140 | 20 | 30,281 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The number "zero" is called "love" (or "l'oeuf" to be precise, literally means "egg" in French), for example when denoting the zero score in a game of tennis.
Aki is fond of numbers, especially those with trailing zeros. For example, the number 9200 has two trailing zeros. Aki thinks the more trailing zero digits a number has, the prettier it is.
However, Aki believes, that the number of trailing zeros of a number is not static, but depends on the base (radix) it is represented in. Thus, he considers a few scenarios with some numbers and bases. And now, since the numbers he used become quite bizarre, he asks you to help him to calculate the beauty of these numbers.
Given two integers n and b (in decimal notation), your task is to calculate the number of trailing zero digits in the b-ary (in the base/radix of b) representation of n ! ([factorial](https://en.wikipedia.org/wiki/Factorial) of n).
Input
The only line of the input contains two integers n and b (1 ≤ n ≤ 10^{18}, 2 ≤ b ≤ 10^{12}).
Output
Print an only integer — the number of trailing zero digits in the b-ary representation of n!
Examples
Input
6 9
Output
1
Input
38 11
Output
3
Input
5 2
Output
3
Input
5 10
Output
1
Note
In the first example, 6!_{(10)} = 720_{(10)} = 880_{(9)}.
In the third and fourth example, 5!_{(10)} = 120_{(10)} = 1111000_{(2)}.
The representation of the number x in the b-ary base is d_1, d_2, …, d_k if x = d_1 b^{k - 1} + d_2 b^{k - 2} + … + d_k b^0, where d_i are integers and 0 ≤ d_i ≤ b - 1. For example, the number 720 from the first example is represented as 880_{(9)} since 720 = 8 ⋅ 9^2 + 8 ⋅ 9 + 0 ⋅ 1.
You can read more about bases [here](https://en.wikipedia.org/wiki/Radix). | instruction | 0 | 15,141 | 20 | 30,282 |
Tags: brute force, implementation, math, number theory
Correct Solution:
```
n,b=map(int,input().split())
i=2
nn=n
fact_b=[]
dict_b={}
count=0
while(i*i<=b):
count=0
if(b%i==0):
while(b%i==0):
count+=1
b//=i
fact_b.append(i)
dict_b[i]=count
i+=1
if(b>1):
fact_b.append(b)
dict_b[b]=1
pow=1
add=0
dict_n={}
for i in fact_b:
pow=1
add=0
while(nn//i**pow>0):
add+=nn//i**pow
pow+=1
dict_n[i]=add
mini=99999999999999999999999999
for i in fact_b:
mini=min(mini,dict_n[i]//dict_b[i])
print(mini)
``` | output | 1 | 15,141 | 20 | 30,283 |
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