message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,736 | 20 | 37,472 |
Tags: implementation, strings
Correct Solution:
```
def mi():
return map(int, input().split())
'''
-0.00987654321
'''
n = input()
neg = False
if n[0]=='-':
neg = True
n=n[1:]
if '.' not in n:
n = n+'.00'
if len(n)-n.index('.')>2:
n = n[:n.index('.')+3]
elif len(n)-n.index('.')==2... | output | 1 | 18,736 | 20 | 37,473 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,737 | 20 | 37,474 |
Tags: implementation, strings
Correct Solution:
```
t = input()
x, y, d = '', '', '.00'
if t[0] == '-': x, y = '(', ')'
k = t.find('.')
if k > 0: d = (t[k: ] + '00')[: 3]
else: k = len(t)
j = len(x)
u = t[j: j + (k - j) % 3]
j += len(u)
if u and k > j: u += ','
print(x + '$' + u + ','.join(t[i: i + 3] for i in range(j... | output | 1 | 18,737 | 20 | 37,475 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,738 | 20 | 37,476 |
Tags: implementation, strings
Correct Solution:
```
s = input()
if s[0] == '-':
res = '($'
s = s[1:]
c = s.count('.')
frac = ""
if c == 1:
k = s.index('.')+1
frac = '.'
if len(s)-k == 1:
frac+=s[k]+'0'
elif len(s)-k>=2:
frac+=s[k:k+2]
... | output | 1 | 18,738 | 20 | 37,477 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,739 | 20 | 37,478 |
Tags: implementation, strings
Correct Solution:
```
s=input()
if '.' in s:
if s[0]=='-':
i=1
a='$'
while s[i]!='.':
a=a+s[i]
i=i+1
c=0
x=len(a)
d=''
for j in range(x-1,0,-1):
c=c+1
d=a[j]+d
if c==3 an... | output | 1 | 18,739 | 20 | 37,479 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,740 | 20 | 37,480 |
Tags: implementation, strings
Correct Solution:
```
__author__ = 'NIORLYS'
def financial_format_integer(number):
if len(number) <= 3:
return number
r = []
for i in range(1, len(number) + 1):
r.append(number[-i])
if i % 3 == 0 and i < len(number):
r.append(',')
r.rev... | output | 1 | 18,740 | 20 | 37,481 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,741 | 20 | 37,482 |
Tags: implementation, strings
Correct Solution:
```
def main():
s=input();
ans=""
if(s[0]=='-'):
ans+=')';
i=len(s)-1
x=-1
while(i>=0):
if(s[i]=='.'):
x=i
if(i+2<len(s)):
ans+=s[i+2];
else:
ans+="0"
i... | output | 1 | 18,741 | 20 | 37,483 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,742 | 20 | 37,484 |
Tags: implementation, strings
Correct Solution:
```
s1=input()
ans=0
if s1[0]=='-':
ans=1
s1=s1[1:]
if '.' in s1:
s1,s2=s1.split('.')
s2=s2[:2]
else:
s2='00'
if len(s2)==1:
s2=s2+'0'
s = s1[:len(s1)%3]
for i in range(len(s1)%3,len(s1),3):
if(len(s)>0):
s += ','
s += s1[i:i+3]
if... | output | 1 | 18,742 | 20 | 37,485 |
Provide tags and a correct Python 3 solution for this coding contest problem.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers into a more easily readable format. However, as ti... | instruction | 0 | 18,743 | 20 | 37,486 |
Tags: implementation, strings
Correct Solution:
```
number = input()
parts = number.split(".")
intPart = parts[0]
decimalPart = ["0","0"]
shouldAddParentheses = intPart[0] == "-"
if len(parts) == 2:
for i in range(min(len(parts[1]),2)):
decimalPart[i] = parts[1][i]
tempIntPart = []
digitCount = 0
for i in r... | output | 1 | 18,743 | 20 | 37,487 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,744 | 20 | 37,488 |
Yes | output | 1 | 18,744 | 20 | 37,489 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,745 | 20 | 37,490 |
Yes | output | 1 | 18,745 | 20 | 37,491 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,746 | 20 | 37,492 |
Yes | output | 1 | 18,746 | 20 | 37,493 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,747 | 20 | 37,494 |
Yes | output | 1 | 18,747 | 20 | 37,495 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,748 | 20 | 37,496 |
No | output | 1 | 18,748 | 20 | 37,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,749 | 20 | 37,498 |
No | output | 1 | 18,749 | 20 | 37,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,750 | 20 | 37,500 |
No | output | 1 | 18,750 | 20 | 37,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
For some time the program of rounding numbers that had been developed by the Codeforces participants during one of the previous rounds, helped the citizens of Far Far Away to convert numbers int... | instruction | 0 | 18,751 | 20 | 37,502 |
No | output | 1 | 18,751 | 20 | 37,503 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Bessie and the cows are playing with sequences and need your help. They start with a sequence, initially containing just the number 0, and perform n operations. Each operation is one of the following:
1. Add the integer xi to the first ai... | instruction | 0 | 18,848 | 20 | 37,696 |
Tags: constructive algorithms, data structures, implementation
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from fractions import *
from bisect import *
from heapq import*
from io import BytesIO, IOBase
def vsInput()... | output | 1 | 18,848 | 20 | 37,697 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,869 | 20 | 37,738 |
Tags: constructive algorithms, implementation
Correct Solution:
```
k,d = input().split()
k = int(k) -1
print("No solution") if(d == '0' and k) else print(d+'0'*k)
``` | output | 1 | 18,869 | 20 | 37,739 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,870 | 20 | 37,740 |
Tags: constructive algorithms, implementation
Correct Solution:
```
k,d=map(int,input().split())
if d==0 and k>1:
print('No solution')
else:
print(str(d)+'0'*(k-1))
``` | output | 1 | 18,870 | 20 | 37,741 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,871 | 20 | 37,742 |
Tags: constructive algorithms, implementation
Correct Solution:
```
n,d=map(int,input().split())
if(d==0):
if(n>1):
print('No solution')
else:
print(0)
else:
s=str(d)+'0'*(n-1)
print(int(s))
``` | output | 1 | 18,871 | 20 | 37,743 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,872 | 20 | 37,744 |
Tags: constructive algorithms, implementation
Correct Solution:
```
import sys
inf = float("inf")
# sys.setrecursionlimit(10000000)
# abc='abcdefghijklmnopqrstuvwxyz'
# abd={'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12, 'n': 13, 'o': 14, 'p': 15, 'q': 16, '... | output | 1 | 18,872 | 20 | 37,745 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,873 | 20 | 37,746 |
Tags: constructive algorithms, implementation
Correct Solution:
```
k, d = map(int, input().split())
if d == 0 and k > 1:
print('No solution')
else:
print('{}{}'.format(d, '0' * (k - 1)))
``` | output | 1 | 18,873 | 20 | 37,747 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,874 | 20 | 37,748 |
Tags: constructive algorithms, implementation
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
from math import *
from collections import *
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = o... | output | 1 | 18,874 | 20 | 37,749 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,875 | 20 | 37,750 |
Tags: constructive algorithms, implementation
Correct Solution:
```
n, d = map(int, input().split())
if n!=1 and d==0:
print('No solution')
else:
print(d*10**(n-1))
``` | output | 1 | 18,875 | 20 | 37,751 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4 + 0 + 9 + 8 = 21. Then the digital root of num... | instruction | 0 | 18,876 | 20 | 37,752 |
Tags: constructive algorithms, implementation
Correct Solution:
```
k, d = list(map(int, input().split()))
if (d != 0):
print(d, end = '')
for i in range(k - 1):
print(0, end = '')
else:
if (k == 1):
print(0)
else:
print("No solution")
``` | output | 1 | 18,876 | 20 | 37,753 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,877 | 20 | 37,754 |
Yes | output | 1 | 18,877 | 20 | 37,755 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,878 | 20 | 37,756 |
Yes | output | 1 | 18,878 | 20 | 37,757 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,879 | 20 | 37,758 |
Yes | output | 1 | 18,879 | 20 | 37,759 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,880 | 20 | 37,760 |
Yes | output | 1 | 18,880 | 20 | 37,761 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,881 | 20 | 37,762 |
No | output | 1 | 18,881 | 20 | 37,763 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,882 | 20 | 37,764 |
No | output | 1 | 18,882 | 20 | 37,765 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,883 | 20 | 37,766 |
No | output | 1 | 18,883 | 20 | 37,767 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Vasya has recently found out what a digital root of a number is and he decided to share his knowledge with you.
Let's assume that S(n) is the sum of digits of number n, for example, S(4098) = 4... | instruction | 0 | 18,884 | 20 | 37,768 |
No | output | 1 | 18,884 | 20 | 37,769 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,332 | 20 | 38,664 |
"Correct Solution:
```
import re
while True:
N = int(input())
if N == 0:
break
formula = [input() for _ in range(N)]
# print(formula)
stack = []
for i in reversed(formula):
# print(stack)
if re.match("\.*(\*|\+)", i):
depth = i.count(".")
i = i.r... | output | 1 | 19,332 | 20 | 38,665 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,333 | 20 | 38,666 |
"Correct Solution:
```
import re
def dotexit(s):
return re.sub("^\.","",s)
def prod(l):
x=1
for i in l:
x *= i
return x
def rec(s):
nums=[dotexit(x) for x in s[1:]]
ad = []
for i in range(len(nums)):
if nums[i]=='+' or nums[i]=='*':
rl=[nums[i]]
for j in range(i+1,len(nums)):
... | output | 1 | 19,333 | 20 | 38,667 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,334 | 20 | 38,668 |
"Correct Solution:
```
def solve(x,a,ind):
# print(x,a,ind)
if "0" <= a[0][ind] <="9":
return int(a[0][ind])
if a[0][ind] =="+":
i = j= 1
su = 0
while(i < x):
if a[i][ind+1] == "+" or a[i][ind+1]=="*":
j+=1
while j < x and a[j][ind ... | output | 1 | 19,334 | 20 | 38,669 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,335 | 20 | 38,670 |
"Correct Solution:
```
while True:
n = int(input())
if n == 0:break
a = [input() for _ in range(n)]
while True:
if len(a) == 1:break
c = 0
s = 0
for i in range(len(a)):
if a[i].count('.') > c:
c = a[i].count('.')
s = i
e... | output | 1 | 19,335 | 20 | 38,671 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,336 | 20 | 38,672 |
"Correct Solution:
```
# coding: utf-8
from functools import reduce
def check(dt,st,lv):
global p
if p>=len(dt):
return st
if not dt[p][-1].isdigit() and lv==len(dt[p]):
tmp=p
p+=1
st.append(reduce(lambda a,b:a+b if dt[tmp][-1]=='+' else a*b,check(dt,[],lv+1)))
... | output | 1 | 19,336 | 20 | 38,673 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,337 | 20 | 38,674 |
"Correct Solution:
```
def parser(i):
idx = i
dep = s[i].count('.')
i += 1
arr = []
while i < N and s[i].count(".") > dep:
if "+" in s[i] or "*" in s[i]:
num, i = parser(i)
arr.append(num)
else:
arr.append(int(s[i].replace('.', '')))
i += 1... | output | 1 | 19,337 | 20 | 38,675 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,338 | 20 | 38,676 |
"Correct Solution:
```
import sys
input = sys.stdin.readline
def calc(i, level, fs, lim):
if fs[i][1] not in "+*":
return i, int(fs[i][1])
if fs[i][1] == "+":
tmp = 0
j = i+1
while j < lim:
if fs[j][0] <= level:
break
if fs[j][1] in "*+":
... | output | 1 | 19,338 | 20 | 38,677 |
Provide a correct Python 3 solution for this coding contest problem.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means adding 2 to the result of 7 × 3. However, there are people wh... | instruction | 0 | 19,339 | 20 | 38,678 |
"Correct Solution:
```
opr_list = ["+", "*"]
def solve():
N = int(input())
while(N != 0):
if(N == 1):
print(int(input()))
else:
ans = [0 for i in range(20)]
s = []
opr = [0 for i in range(20)]
for i in range(N):
s.appe... | output | 1 | 19,339 | 20 | 38,679 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,340 | 20 | 38,680 |
Yes | output | 1 | 19,340 | 20 | 38,681 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,341 | 20 | 38,682 |
Yes | output | 1 | 19,341 | 20 | 38,683 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,342 | 20 | 38,684 |
Yes | output | 1 | 19,342 | 20 | 38,685 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,343 | 20 | 38,686 |
Yes | output | 1 | 19,343 | 20 | 38,687 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,344 | 20 | 38,688 |
No | output | 1 | 19,344 | 20 | 38,689 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,345 | 20 | 38,690 |
No | output | 1 | 19,345 | 20 | 38,691 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,346 | 20 | 38,692 |
No | output | 1 | 19,346 | 20 | 38,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
ICPC Calculator
In mathematics, we usually specify the order of operations by using parentheses. For example, 7 × (3 + 2) always means multiplying 7 by the result of 3 + 2 and never means addin... | instruction | 0 | 19,347 | 20 | 38,694 |
No | output | 1 | 19,347 | 20 | 38,695 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not.
Petya loves tickets... | instruction | 0 | 19,657 | 20 | 39,314 |
Tags: implementation
Correct Solution:
```
def is_lucky(n: str) -> bool:
return n.count("4") + n.count("7") == len(n)
def sumar_digitos(num: str) -> (int, int):
n = len(num)
prim_mitad = num[0:n//2]
seg_mitad = num[n//2:]
return sum(map(lambda x: int(x), prim_mitad)), sum(map(lambda x: int(x), seg_mitad))
d... | output | 1 | 19,657 | 20 | 39,315 |
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