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Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros). Constraints * 1 \leq N \leq 10^5 Input Input is given from Standard Input in the following format: N Output Print the number of positive integers less than or equal to N that have an odd number of digits. Examples Input 11 Output 9 Input 136 Output 46 Input 100000 Output 90909 Submitted Solution: ``` n=int(input()) digit=1 count=0 while(10**digit<n): if(digit%2==1): count=count+9*10**(digit-1) digit=digit+1 if(digit%2==1): count=count+n-10**(digit-1) print(count) ```
instruction
0
44,466
20
88,932
No
output
1
44,466
20
88,933
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros). Constraints * 1 \leq N \leq 10^5 Input Input is given from Standard Input in the following format: N Output Print the number of positive integers less than or equal to N that have an odd number of digits. Examples Input 11 Output 9 Input 136 Output 46 Input 100000 Output 90909 Submitted Solution: ``` import io import sys MOD = 10 ** 9 + 7 def IN_S(): return input() def IN_I(): return int(input()) def IN_L_I(): return list(map(int, input().split())) def IN_L_S(): return list(map(str, input().split())) def STR_SPLIT(s, n): for l in range(0, len(s), n): yield s[0 + l:n + l] def T_IN(): global test_str sys.stdin = io.StringIO(test_str[1:-1]) test_str = ''' 136 ''' def MAIN(): T_IN() A() def A(): n = IN_I() t = 0 if n > 9: t += 9 if n > 999: t += 900 if n > 99999: t += 90000 if n <= 9: t += n elif 99 < n <= 999: t += n - 99 elif 9999 < n <= 99999: t += n - 9999 print(t) return None def B(): return None def C(): return None MAIN() ```
instruction
0
44,467
20
88,934
No
output
1
44,467
20
88,935
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Given is an integer N. Find the number of positive integers less than or equal to N that have an odd number of digits (in base ten without leading zeros). Constraints * 1 \leq N \leq 10^5 Input Input is given from Standard Input in the following format: N Output Print the number of positive integers less than or equal to N that have an odd number of digits. Examples Input 11 Output 9 Input 136 Output 46 Input 100000 Output 90909 Submitted Solution: ``` n = int(input()) num = int(input()) num_digit = len(str(num)) if num_digit == 1: print(0) elif num_digit == 2: print(9) elif num_digit == 3: print(9 + (num - 100 + 1)) elif num_digit == 4: print(909) elif num_digit == 5: print(909 + (num - 10000 + 1)) ```
instruction
0
44,468
20
88,936
No
output
1
44,468
20
88,937
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,527
20
89,054
"Correct Solution: ``` def solve(k, d, fl): if k <= 1: if d == 0: return 10 ** k return 0 x = (-d) % 10 c = 9 - x + 1 - fl d -= 10 ** (k - 1) * x - x return c * solve(k - 2, abs(d) // 10, 0) d = int(input()) ans = 0 for i in range(1, 100): ans += solve(i, d, 1) print(ans) ```
output
1
44,527
20
89,055
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,528
20
89,056
"Correct Solution: ``` from collections import deque D=int(input()) def f(d,k): if 0<=k<=1: if d!=0: return "Unko" if k==1: return deque([0]) else: return deque([]) if d>=0: s=10-(d%10) else: s=-(d%10) if s==10: A=f(d//10,k-2) s=0 #print(d,s,d-s*(10**(k-1))+s) else: A=f((d-s*(10**(k-1))+s)//10,k-2) if A=="Unko": return "Unko" A.appendleft(s) A.append(-s) return A ans=0 for k in range(1,50): A=f(D,k) if A=="Unko": continue # print(A) res=1 for j in range((k+1)//2): if j==0: res*=9-abs(A[j]) else: if A[j]==0: res*=10 else: res*=10-abs(A[j]) ans+=res print(ans) ```
output
1
44,528
20
89,057
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,529
20
89,058
"Correct Solution: ``` def result(letters, number, cant_zero): if letters <= 1: if number == 0: return 10 ** letters return 0 diff = (10 - number%10) % 10 variants = number % 10 - cant_zero if number % 10 == 0: variants = 10 - cant_zero number -= diff * (10**(letters-1) - 1) number = abs(number // 10) return variants * result(letters-2, number, 0) d = int(input()) ans = 0 for i in range(20): ans += result(i, d, 1) print(ans) ```
output
1
44,529
20
89,059
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,530
20
89,060
"Correct Solution: ``` import sys input = lambda : sys.stdin.readline().rstrip() sys.setrecursionlimit(max(1000, 10**9)) write = lambda x: sys.stdout.write(x+"\n") d = int(input()) def main(d): from collections import defaultdict vals = defaultdict(int) vals2 = defaultdict(int) for i in range(10): for j in range(10): vals[i-j] += 1 if j>0: vals2[i-j] += 1 def sub(n): vs = [] for i in range(n): if i>=n-i: break vs.append(pow(10,n-i) - pow(10,i)) # if 9*sum(vs)<d: # return 0 def _sub(val, i): """vs[i:]δ»₯降でvalγ‚’δ½œγ‚‹ι€šγ‚Šζ•° """ if i==len(vs): if val==0: return 1 else: return 0 ans = 0 for j in range(-9, 10): if (vs[i]*j)%pow(10,i+1)==val%(pow(10,i+1)): ans += _sub(val-vs[i]*j, i+1) * vals[j] return ans ans = 0 for i in range(-9,10): if (vs[0]*i)%10==d%10: ans += _sub(d-vs[0]*i, 1) * vals2[i] if n%2==0: ans *= 10 return ans ans = 0 i = 1 while True: val = sub(i) ans += val if i>20: break # if pow(10,i)-1>d: # break i += 1 return ans print(main(d)) ```
output
1
44,530
20
89,061
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,531
20
89,062
"Correct Solution: ``` import sys input = sys.stdin.readline D = int(input()) memo_F = [0] * 30 memo_T = [0] * 30 for x in range(10): for y in range(10): memo_T[y-x] += 1 if x != 0: memo_F[y-x] += 1 def F(K,D,allow_leading_zero): if K == 0: return 1 if D == 0 else 0 if K == 1: if D != 0: return 0 if allow_leading_zero: return 10 else: return 9 x = 10**(K-1)-1 d = (-D)%10 # xγ‚’dε€‹γΎγŸγ―d-10個 ret = 0 for use_x in [d,d-10]: if allow_leading_zero: coef = memo_T[use_x] else: coef = memo_F[use_x] if coef == 0: continue ret += coef * F(K-2,(D-x*use_x)//10,True) return ret answer = sum(F(K,D,False) for K in range(1,20)) print(answer) ```
output
1
44,531
20
89,063
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,532
20
89,064
"Correct Solution: ``` # (10-x) ways: (0,x)-(9-x,9) -> (x, -x) <- This should never happens when D > 0 # (x) ways: (10-x,0)-(9,x-1) -> (x-10, 10 - x) def solve(d, k, outer): if k <= 1: return 10**k if d == 0 else 0 # if d >= 10**k: # return 0 t = (-d)%10 # 10-d%10 doesn't work when d = 10 d -= t*10**(k-1) - t return (10-t-outer)*solve(abs(d//10), k-2, 0) D = int(input()) result = 0 for k in range(1,20): result += solve(D, k, 1) print(result) ```
output
1
44,532
20
89,065
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,533
20
89,066
"Correct Solution: ``` def solve(d, K): r = 1 for k in range(K,1,-2): if d >= 10**k: return 0 t = (-d)%10 d = abs((d-t*(10**(k-1)-1))//10) r *= 10-t-(K==k) return r*(10**(K%2)) if d == 0 else 0 D = int(input()) result = 0 l = len(str(D)) for k in range(l,2*l+1): result += solve(D, k) print(result) ```
output
1
44,533
20
89,067
Provide a correct Python 3 solution for this coding contest problem. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920
instruction
0
44,534
20
89,068
"Correct Solution: ``` D = int(input()) def table(i, k): if i == k: return list(range(9, -1, -1)) + [0]*9 else: return list(range(10, 0, -1)) + list(range(1, 10)) def nine(i): return 10**i - 1 def rec(d, i, k): res = 0 num = table(i, k) if i == 1: for j in range(-9, 10): if 9*j == d: return num[j] return 0 if i == 2: for j in range(-9, 10): if d == 99*j: return 10*num[j] if not -10*nine(i) <= d <= 10*nine(i): return 0 for j in range(-9, 10): if d%10 == j*nine(i)%10: res += num[j] * rec((d-j*nine(i))//10, i-2, k) return res l = 0 while D % 10 == 0: D//= 10 l += 1 if l == 0: a = 1 else: a = 9*10**(l-1) ans = 0 for i in range(1, 20): if not l: ans += rec(D, i, i) else: ans += rec(D, i, 100) print(a * ans) ```
output
1
44,534
20
89,069
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920 Submitted Solution: ``` def recursion(length, ll, string, cc): answer = 0 az = 0 if ll * 2 < length: for i in range(10): string1 = string + str(i) line = recursion(length, ll+1, string1, cc) answer += line[0] az += line[1] line = [answer, az] return line else: number = str(int(string) + int(cc[-ll:])) ds = "" for i in range(length // 2): if i + 1 <= len(number): ds += number[-i-1] else: ds += "0" string = ds + string if str(int(string) + int(cc)) == string[::-1] and string[0] != "0": answer += 1 elif str(int(string) + int(cc)) == string[::-1]: az += 1 line = [answer, az] return line d = input() d1 = d plus = 0 while True: if d[-1] == "0": d = d[:-1] plus += 1 else: break l1 = recursion(len(d), 0, "", d) l2 = recursion(len(d)+1, 0, "", d) answer = l1[0] + l2[0] az = l1[1] + l2[1] yes = False while plus > 0: yes = True if plus == 1: plus -= 1 answer = answer * 9 az = az * 9 else: plus -= 1 answer *= 10 az *= 10 if yes: answer += az print(answer) ```
instruction
0
44,538
20
89,076
No
output
1
44,538
20
89,077
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. For a positive integer n, we denote the integer obtained by reversing the decimal notation of n (without leading zeroes) by rev(n). For example, rev(123) = 321 and rev(4000) = 4. You are given a positive integer D. How many positive integers N satisfy rev(N) = N + D? Constraints * D is an integer. * 1 ≀ D < 10^9 Input Input is given from Standard Input in the following format: D Output Print the number of the positive integers N such that rev(N) = N + D. Examples Input 63 Output 2 Input 75 Output 0 Input 864197532 Output 1920 Submitted Solution: ``` def recursion(length, ll, string, cc): if ll * 2 < length: for i in range(10): string1 = string + str(i) recursion(length, ll+1, string1, cc) else: number = str(int(string) + int(cc[-ll:])) ds = "" for i in range(length // 2): if i + 1 <= len(number): ds += number[-i-1] else: ds += "0" string = ds + string if str(int(string) + int(cc)) == string[::-1] and string[0] != "0": global answer answer += 1 d = input() plus = 0 while True: if d[-1] == "0": d = d[:-1] plus += 1 else: break answer = 0 recursion(len(d), 0, "", d) recursion(len(d)+1, 0, "", d) while plus > 0: if plus == 1: plus -= 1 answer = answer * 9 else: plus -= 1 answer *= 10 print(answer) ```
instruction
0
44,539
20
89,078
No
output
1
44,539
20
89,079
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Petya loves lucky numbers very much. Everybody knows that lucky numbers are positive integers whose decimal record contains only the lucky digits 4 and 7. For example, numbers 47, 744, 4 are lucky and 5, 17, 467 are not. Petya brought home string s with the length of n. The string only consists of lucky digits. The digits are numbered from the left to the right starting with 1. Now Petya should execute m queries of the following form: * switch l r β€” "switch" digits (i.e. replace them with their opposites) at all positions with indexes from l to r, inclusive: each digit 4 is replaced with 7 and each digit 7 is replaced with 4 (1 ≀ l ≀ r ≀ n); * count β€” find and print on the screen the length of the longest non-decreasing subsequence of string s. Subsequence of a string s is a string that can be obtained from s by removing zero or more of its elements. A string is called non-decreasing if each successive digit is not less than the previous one. Help Petya process the requests. Input The first line contains two integers n and m (1 ≀ n ≀ 106, 1 ≀ m ≀ 3Β·105) β€” the length of the string s and the number of queries correspondingly. The second line contains n lucky digits without spaces β€” Petya's initial string. Next m lines contain queries in the form described in the statement. Output For each query count print an answer on a single line. Examples Input 2 3 47 count switch 1 2 count Output 2 1 Input 3 5 747 count switch 1 1 count switch 1 3 count Output 2 3 2 Note In the first sample the chronology of string s after some operations are fulfilled is as follows (the sought maximum subsequence is marked with bold): 1. 47 2. 74 3. 74 In the second sample: 1. 747 2. 447 3. 447 4. 774 5. 774 Submitted Solution: ``` it = lambda: list(map(int, input().strip().split())) n, m = it() arr = [0 if ch == '4' else 1 for ch in input().strip()] one = [0] * (n << 2) zer = [0] * (n << 2) inc = [0] * (n << 2) dec = [0] * (n << 2) lzy = [0] * (n << 2) def apply(idx): inc[idx], dec[idx] = dec[idx], inc[idx] one[idx], zer[idx] = zer[idx], one[idx] lzy[idx] = 1 def push(idx): if lzy[idx] == 1: apply(idx << 1) apply(idx << 1 | 1) lzy[idx] = 0 def pull(idx): one[idx] = one[idx << 1] + one[idx << 1 | 1] zer[idx] = zer[idx << 1] + zer[idx << 1 | 1] inc[idx] = max(zer[idx << 1] + inc[idx << 1 | 1], inc[idx << 1] + one[idx << 1 | 1], zer[idx << 1] + one[idx << 1 | 1]) dec[idx] = max(one[idx << 1] + dec[idx << 1 | 1], dec[idx << 1] + zer[idx << 1 | 1], one[idx << 1] + zer[idx << 1 | 1]) def build(idx=1, l=0, r=n): if r - l < 2: one[idx] = 1 if arr[l] == 1 else 0 zer[idx] = 1 if arr[l] == 0 else 0 inc[idx] = 1 dec[idx] = 1 return mid = (l + r) >> 1 build(idx << 1, l, mid) build(idx << 1 | 1, mid, r) pull(idx) def update(x, y, idx=1, l=0, r=n): if x >= r or y <= l: return if x <= l and r <= y: apply(idx) return push(idx) mid = (l + r) >> 1 update(x, y, idx << 1, l, mid) update(x, y, idx << 1 | 1, mid, r) pull(idx) build() for _ in range(m): query = input().strip().split() if len(query) == 1: print(inc[1]) else: l, r = query[1:] update(int(l) - 1, int(r)) ```
instruction
0
44,820
20
89,640
No
output
1
44,820
20
89,641
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,915
20
89,830
Tags: combinatorics, greedy Correct Solution: ``` s=input() ans=1 n=len(s) c=1 for i in range(1,n): #print("i is",i,' and c is',c) if(int(s[i])+int(s[i-1])-2*int('0')==9): #print('s[i]+s[i-1]==9') c+=1 else: #print('else') if(c%2==1 and c>1): #print('c%2==1 and c>1') ans*=(c+1)//2 #print('ans is',ans) c=1 if(c%2==1 and c>1): ans*=(c+1)//2 print(ans) ```
output
1
44,915
20
89,831
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,916
20
89,832
Tags: combinatorics, greedy Correct Solution: ``` a=input() ans=1 count=1 l=len(a) for i in range(l-1): if int(a[i])+int(a[i+1])==9: count+=1 else: if count%2: ans*=(count+1)//2 count=1 if count%2: ans*=(count+1)//2 print(ans) ```
output
1
44,916
20
89,833
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,917
20
89,834
Tags: combinatorics, greedy Correct Solution: ``` a=input() n=len(a) ans=1 c=0 for i in range(n-1): if int(a[i+1])+int(a[i])==9: c+=1 else: if c%2==0 and c!=0: # print(c+1) ans*=(c+1)//2+1 c=0 if c%2==0 and c!=0: ans*=(c+1)//2+1 print(ans) ```
output
1
44,917
20
89,835
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,918
20
89,836
Tags: combinatorics, greedy Correct Solution: ``` # -*- coding: utf-8 -*- def count_nine(a, i): while i < len(a) - 1: if a[i] + a[i+1] == 9: break i += 1 else: return 0, 1 n1, c1 = count_nine(a, i+1) n2, c2 = count_nine(a, i+2) if n1 == n2 + 1: return n2+1, c1+c2 else: return n2+1, c2 def count_nine2(a): n_list = [0] * (len(a)+1) c_list = [0] * (len(a)+1) c_list[-1] = c_list[-2] = 1 for i in range(len(a)-2, -1, -1): if a[i] + a[i+1] == 9: n_list[i] = n_list[i+2]+1 if n_list[i+1] == n_list[i+2]+1: c_list[i] = c_list[i+1] + c_list[i+2] else: c_list[i] = c_list[i+2] else: n_list[i] = n_list[i+1] c_list[i] = c_list[i+1] return n_list[0], c_list[0] n, c = count_nine2([int(x) for x in input()]) print(c) ```
output
1
44,918
20
89,837
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,919
20
89,838
Tags: combinatorics, greedy Correct Solution: ``` if __name__ == '__main__': n = input() res = 1 countConsecutivePairs = 0 length = len(n) for i in range(length): if (i+1 < length and int(n[i]) + int(n[i+1]) == 9): countConsecutivePairs += 1 else: if (countConsecutivePairs % 2 == 0): res *= (countConsecutivePairs//2 + 1) countConsecutivePairs = 0 print(res) ```
output
1
44,919
20
89,839
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,920
20
89,840
Tags: combinatorics, greedy Correct Solution: ``` #!/usr/bin/python3 def readln(): return list(map(int, input().split())) ans = 1 l = 1 p = -1 a = input() for i in range(len(a)): c = int(a[i]) if c + p == 9: l += 1 if c + p != 9 or i == len(a) - 1: if l % 2: ans *= (l + 1) // 2 l = 1 p = c print(ans) ```
output
1
44,920
20
89,841
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,921
20
89,842
Tags: combinatorics, greedy Correct Solution: ``` # import itertools # import bisect # import math from collections import defaultdict, Counter import os import sys from io import BytesIO, IOBase # sys.setrecursionlimit(10 ** 5) ii = lambda: int(input()) lmii = lambda: list(map(int, input().split())) slmii = lambda: sorted(map(int, input().split())) li = lambda: list(input()) mii = lambda: map(int, input().split()) msi = lambda: map(str, input().split()) def gcd(a, b): if b == 0: return a return gcd(b, a % b) def lcm(a, b): return (a * b) // gcd(a, b) def main(): # for _ in " " * int(input()): n = li() n.append(10) cnt = 0 ans = 1 ln = len(n) for i in range(1, ln): if int(n[i]) + int(n[i - 1]) == 9: cnt += 1 else: ans *= ((((cnt + 1) // 2) + 1) if cnt % 2 == 0 else 1) cnt = 0 print(ans) pass BUFSIZE = 8192 class FastIO(IOBase): newlines = 0 def __init__(self, file): self._fd = file.fileno() self.buffer = BytesIO() self.writable = "x" in file.mode or "r" not in file.mode self.write = self.buffer.write if self.writable else None def read(self): while True: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) if not b: break ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines = 0 return self.buffer.read() def readline(self): while self.newlines == 0: b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE)) self.newlines = b.count(b"\n") + (not b) ptr = self.buffer.tell() self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr) self.newlines -= 1 return self.buffer.readline() def flush(self): if self.writable: os.write(self._fd, self.buffer.getvalue()) self.buffer.truncate(0), self.buffer.seek(0) class IOWrapper(IOBase): def __init__(self, file): self.buffer = FastIO(file) self.flush = self.buffer.flush self.writable = self.buffer.writable self.write = lambda s: self.buffer.write(s.encode("ascii")) self.read = lambda: self.buffer.read().decode("ascii") self.readline = lambda: self.buffer.readline().decode("ascii") sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout) input = lambda: sys.stdin.readline().rstrip("\r\n") if __name__ == "__main__": main() ```
output
1
44,921
20
89,843
Provide tags and a correct Python 3 solution for this coding contest problem. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321.
instruction
0
44,922
20
89,844
Tags: combinatorics, greedy Correct Solution: ``` import sys import math data = sys.stdin.read().split() data_ptr = 0 def data_next(): global data_ptr, data data_ptr += 1 return data[data_ptr - 1] S = data[0] N = len(S) ans = 1 block = 0 for i in range(N): if i == N - 1 or int(S[i]) + int(S[i + 1]) != 9: if block > 0 and block % 2 == 0: ans *= block // 2 + 1 block = 0 else: block += 1 print(ans) ```
output
1
44,922
20
89,845
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` import sys def solve(): a = list(map(int, list(input()))) res = 1 curcount = 1 for i in range(1, len(a)): if a[i] + a[i-1] == 9: curcount += 1 else: if curcount > 2 and curcount % 2 == 1: res*=(curcount//2 + 1) curcount = 1 if curcount > 2 and curcount % 2 == 1: res*=(curcount//2 + 1) return res if sys.hexversion == 50594544 : sys.stdin = open("test.txt") print(solve()) ```
instruction
0
44,923
20
89,846
Yes
output
1
44,923
20
89,847
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` class CodeforcesTask374BSolution: def __init__(self): self.result = '' self.number = [] def read_input(self): self.number = [int(c) for c in input()] def process_task(self): nums = 1 x = 0 #factors = [1] while x + 1 < len(self.number): s = 1 while self.number[x] + self.number[x + 1] == 9: s += 1 x += 1 if x + 1 >= len(self.number): break if s > 2: if s % 2: #factors.append(s - 1) nums *= s // 2 + 1 x += 1 #print(factors) self.result = str(nums) def get_result(self): return self.result if __name__ == "__main__": Solution = CodeforcesTask374BSolution() Solution.read_input() Solution.process_task() print(Solution.get_result()) ```
instruction
0
44,924
20
89,848
Yes
output
1
44,924
20
89,849
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` a = [int(x) for x in input()] ans = 1 len_run = 0 for i in range(0,len(a)-1): if a[i] + a[i+1] == 9: len_run += 1 elif len_run != 0: if len_run % 2 == 0: ans *= int(len_run/2) + 1 len_run = 0 if len_run != 0: if len_run % 2 == 0: ans *= int(len_run/2) + 1 print(ans) ```
instruction
0
44,925
20
89,850
Yes
output
1
44,925
20
89,851
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` p = 10 cnt = 0 r = 1 for c in input(): c = int(c) if c + p == 9: cnt += 1 else: if cnt > 0 and cnt % 2 == 0: r *= cnt//2 + 1 cnt = 0 p = c if cnt > 0 and cnt % 2 == 0: r *= cnt//2 + 1 print(r) ```
instruction
0
44,926
20
89,852
Yes
output
1
44,926
20
89,853
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` s = input() n = len(s) k = 1 p = 1 for i in range(n - 1): if (int(s[i]) + int(s[i + 1])) % 9 == 0 and s[i] != '9' and s[i] != '0': k += 1 else: if k > 1 and k % 2 == 1: p *= (k + 1) // 2 k = 1 if k > 1 and k % 2 == 1: p *= (k + 1) // 2 print(p) ```
instruction
0
44,927
20
89,854
No
output
1
44,927
20
89,855
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` num = input() ll = [] coint = 0 for id, char in enumerate(num): for ind, j in enumerate(num): if ind - id == 1: if int(char) + int(j) == 9: coint += 1 print(coint//2 +1) ```
instruction
0
44,928
20
89,856
No
output
1
44,928
20
89,857
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` a=input() ans=1 l=len(a) for i in range(l-4): if (int(a[i])+int(a[i+1]))%9==0 and a[i]==a[i+2] and a[i+1]!=a[i+3]: ans*=2 if l>=3 and (int(a[l-3])+int(a[l-2]))%9==0 and a[l-3]==a[l-1]: ans*=2 print(ans) ```
instruction
0
44,929
20
89,858
No
output
1
44,929
20
89,859
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Inna loves digit 9 very much. That's why she asked Dima to write a small number consisting of nines. But Dima must have misunderstood her and he wrote a very large number a, consisting of digits from 1 to 9. Inna wants to slightly alter the number Dima wrote so that in the end the number contained as many digits nine as possible. In one move, Inna can choose two adjacent digits in a number which sum equals 9 and replace them by a single digit 9. For instance, Inna can alter number 14545181 like this: 14545181 β†’ 1945181 β†’ 194519 β†’ 19919. Also, she can use this method to transform number 14545181 into number 19991. Inna will not transform it into 149591 as she can get numbers 19919 and 19991 which contain more digits nine. Dima is a programmer so he wants to find out how many distinct numbers containing as many digits nine as possible Inna can get from the written number. Help him with this challenging task. Input The first line of the input contains integer a (1 ≀ a ≀ 10100000). Number a doesn't have any zeroes. Output In a single line print a single integer β€” the answer to the problem. It is guaranteed that the answer to the problem doesn't exceed 263 - 1. Please, do not use the %lld specifier to read or write 64-bit integers in Π‘++. It is preferred to use the cin, cout streams or the %I64d specifier. Examples Input 369727 Output 2 Input 123456789987654321 Output 1 Input 1 Output 1 Note Notes to the samples In the first sample Inna can get the following numbers: 369727 β†’ 99727 β†’ 9997, 369727 β†’ 99727 β†’ 9979. In the second sample, Inna can act like this: 123456789987654321 β†’ 12396789987654321 β†’ 1239678998769321. Submitted Solution: ``` p = 10 cnt = 0 r = 0 for c in input(): c = int(c) if c + p == 9: cnt += 1 else: if cnt > 0 and cnt % 2 == 0: r += 1 cnt = 0 p = c if cnt > 0 and cnt % 2 == 0: r += 1 print(2**r) ```
instruction
0
44,930
20
89,860
No
output
1
44,930
20
89,861
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,079
20
90,158
Tags: binary search, brute force, dp, math Correct Solution: ``` class ReallyBigNumbers: def __init__(self, n, s): self.n = n self.s = s self.binarySearch() def binarySearch(self): l = self.s h = 10000000000000000000 while(l < h): mid = (h + l) // 2 #print(mid, self.isReallyBig(mid)) if self.isReallyBig(mid): h = mid else: l = mid + 1 self.x = int(l) def isReallyBig(self, v): cp = v add = 0 while v > 0: add += v % 10 v //= 10 #print('resta', cp-add, cp, add) return (cp - add) >= self.s def show(self): if self.x <= self.n: print(str(self.n - self.x + 1)) else: print(0) n, s = map(int, input().split()) rbg = ReallyBigNumbers(n, s) #print(rbg.x) rbg.show() ```
output
1
45,079
20
90,159
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,080
20
90,160
Tags: binary search, brute force, dp, math Correct Solution: ``` n,s = map(int,input().split()) l = n+1 for i in range(s,min(s+1000000, n)+1,1): cur = sum([int(j) for j in str(i)]) if(i-cur>=s): l = i; break print(n-l+1) ```
output
1
45,080
20
90,161
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,081
20
90,162
Tags: binary search, brute force, dp, math Correct Solution: ``` def sum_dig(num): num = str(num) ans = 0 for i in range(len(num)): ans += int(num[i]) return ans n,s = map(int,input().split()) ans = 0 for i in range(s,n+1): if i - sum_dig(i) >= s: ans = n - i + 1 break print(ans) ```
output
1
45,081
20
90,163
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,082
20
90,164
Tags: binary search, brute force, dp, math Correct Solution: ``` n,s=map(int,input().split()) lo,hi=s,n ans=n+1 while lo<=hi: mid=(lo+hi)//2 z=sum(map(int,str(mid))) if mid>=s+z: ans=mid hi=mid-1 else: lo=mid+1 print(n-ans+1) ```
output
1
45,082
20
90,165
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,083
20
90,166
Tags: binary search, brute force, dp, math Correct Solution: ``` n, s = map(int, input().split()) print(max(n-min(i for i in range(s, s+200) if i-sum(map(int, str(i))) >= s)+1, 0)) ```
output
1
45,083
20
90,167
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,084
20
90,168
Tags: binary search, brute force, dp, math Correct Solution: ``` n, s = map(int, input().split()) a, b, c = 0, n + 1, 0 while a < b: c = (a + b) // 2 if c - sum([int(x) for x in str(c)]) < s: a = c + 1 else: b = c print(n - b + 1) ```
output
1
45,084
20
90,169
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,085
20
90,170
Tags: binary search, brute force, dp, math Correct Solution: ``` n, s = map(int, input().split()) ans = 0 p = s for i in range(163): p = s + i if p > n: break if p >= s + sum(map(int, str(p))): ans += 1 if p <= n: ans += n - p print(ans) ```
output
1
45,085
20
90,171
Provide tags and a correct Python 3 solution for this coding contest problem. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9).
instruction
0
45,086
20
90,172
Tags: binary search, brute force, dp, math Correct Solution: ``` arr = [int(x) for x in input().split()] n = arr[0] s = arr[1] resp = 0 leng = len(str(s)) j = 0 for i in range(s, s + leng*9 + 1): j = i if i > n: break temp = 0 c = i while c: temp += c % 10 c //= 10 if i - temp >= s: resp += 1 j += 1 if j > n: print (resp) else: print (n - j + 1 + resp) ```
output
1
45,086
20
90,173
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` def main(): def sumofdigit(n): temp=0 while(n>0): temp+=n%10 n=n//10 return temp def F(x): return x-sumofdigit(x) def findout(s): test=s-s%10+10 while(1): if F(test)>=s: break else: test+=10 return test n,s=list(map(int,input().strip().split(' '))) L=findout(s) ans=n-L+1 if ans<0: print(0) else: print(ans) main() ```
instruction
0
45,087
20
90,174
Yes
output
1
45,087
20
90,175
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` n,s = map(int,input().split()) if s > n: print('0') else: for i in range(s,n+2): l = 0 for j in str(i): l += int(j) if i - l >= s: break print(n - i+1) ```
instruction
0
45,088
20
90,176
Yes
output
1
45,088
20
90,177
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` def bigNumber(n, s): for i in range(s, n + 1): sumVal = 0 num = i while num: sumVal += num % 10 num //= 10 if i - sumVal >= s: print(n - i + 1) return print(0) n, s = (int(x) for x in input().split()) bigNumber(n,s) ```
instruction
0
45,089
20
90,178
Yes
output
1
45,089
20
90,179
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` def forninho(miolo, s): premiolo = miolo temp = 0 while (miolo > 0): temp += miolo % 10; miolo = miolo // 10; if (premiolo - temp >= s): return 1 else: return 0 entrada = input().split() n = int(entrada[0]) s = int(entrada[1]) result = -1 l = 1 r = n while (r-l >= 0): miolo = (l + r) // 2 if(forninho(miolo,s) == 1): r = miolo - 1 result = miolo else: l = miolo + 1 if (result == -1): print("0") else: print(n - result + 1) ```
instruction
0
45,090
20
90,180
Yes
output
1
45,090
20
90,181
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` def suma(n): res = 0 while n > 0: res += n % 10 n //= 10 return res n, s = map(int, input().split()) su = suma(n) res = 0 maxS = n - su if maxS >= s: res += (n % 10) + 1 #print('ms', maxS) #print('res p:', res) maxS -= 9 #print('mS', maxS) cant = max(0,(maxS // 9) - s) res += cant * 10 print(res) ```
instruction
0
45,091
20
90,182
No
output
1
45,091
20
90,183
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` n, s = map(int, input().split()) s = (s // 9 + (s % 9 != 0)) * 9 a = n // 10 * 9 print(max(0, (a - s) // 9 * 10 + n % 10 + 1)) ```
instruction
0
45,092
20
90,184
No
output
1
45,092
20
90,185
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` def cmp(x1 = [],x2 = []): len1 = len(x1) len2 = len(x2) if len1 == len2: for i in range(len1): n1 = x1[len1 - 1 - i] n2 = x2[len1 - 1 - i] if n1 != n2: return n1 > n2 else: return len1 > len2 return True def add(x1 = [],x2 = []): if not cmp(x1,x2): x1,x2 = x2,x1 len1 = len(x1) len2 = len(x2) for i in range(len1 - len2): x2.append(0) res = [] flag = 0 for n1,n2 in zip(x1,x2): m = n1 + n2 + flag flag = m // 10 res.append(m % 10) if flag: res.append(flag) return res def minus(x1 = [],x2 = []): if not cmp(x1,x2): x1,x2 = x2,x1 len1 = len(x1) len2 = len(x2) for i in range(len1 - len2): x2.append(0) res = [] flag = 0 for n1,n2 in zip(x1,x2): m = n1 - n2 + flag flag = 0 if m >= 0 else -1 res.append((m + 10) % 10) while res and not res[-1]: res.pop() return res def div(x1 = [], x2 = 9): if x2 == 10: return x1[1:] else: x1.reverse() res = [] mod = 0 for n in x1: res.append((n + mod * 10)// 9) mod = (n + mod * 10) % 9 res.reverse() while res and not res[-1]: res.pop() return res def multi(x1 = [],x2 = 9): x1_copy = x1.copy() x1.insert(0,0) if x2 == 10: return x1 else: return minus(x1,x1_copy) if __name__ == "__main__": input_str = input() n,s = [a for a in input_str.split()] nl = list([int(a) for a in list(n)]) sl = list([int(a) for a in list(s)]) nl.reverse() sl.reverse() # x = (sl + 8) // 9 * 9 x = multi(div(add(sl.copy(),[8]),9),9) # y = (x + 9) // 10 * 10 y = multi(div(add(x.copy(),[9]),10),10) # z = y + (x - y + sum(y)) * 10 // 9 sumy = list([int(a) for a in list(str(sum(y)))]) sumy.reverse() z = add(y,multi(div(minus(minus(x,y),sumy),9),10)) if cmp(nl,z): ans = add(minus(nl,z),[1]) else: ans = [0] ans.reverse() ansstr = [str(a) for a in ans] print("".join(ansstr)) ```
instruction
0
45,093
20
90,186
No
output
1
45,093
20
90,187
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response. Ivan likes to learn different things about numbers, but he is especially interested in really big numbers. Ivan thinks that a positive integer number x is really big if the difference between x and the sum of its digits (in decimal representation) is not less than s. To prove that these numbers may have different special properties, he wants to know how rare (or not rare) they are β€” in fact, he needs to calculate the quantity of really big numbers that are not greater than n. Ivan tried to do the calculations himself, but soon realized that it's too difficult for him. So he asked you to help him in calculations. Input The first (and the only) line contains two integers n and s (1 ≀ n, s ≀ 1018). Output Print one integer β€” the quantity of really big numbers that are not greater than n. Examples Input 12 1 Output 3 Input 25 20 Output 0 Input 10 9 Output 1 Note In the first example numbers 10, 11 and 12 are really big. In the second example there are no really big numbers that are not greater than 25 (in fact, the first really big number is 30: 30 - 3 β‰₯ 20). In the third example 10 is the only really big number (10 - 1 β‰₯ 9). Submitted Solution: ``` from math import ceil n, s = [int(i) for i in input().split()] k = s // 9 if s % 9 == 0 else (s//9 + 1) f = 10 * k print(max(n - f + 1, 0)) ```
instruction
0
45,094
20
90,188
No
output
1
45,094
20
90,189
Provide a correct Python 3 solution for this coding contest problem. A positive integer X is said to be a lunlun number if and only if the following condition is satisfied: * In the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1. For example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is. You are given a positive integer K. Find the K-th smallest lunlun number. Constraints * 1 \leq K \leq 10^5 * All values in input are integers. Input Input is given from Standard Input in the following format: K Output Print the answer. Examples Input 15 Output 23 Input 1 Output 1 Input 13 Output 21 Input 100000 Output 3234566667
instruction
0
45,175
20
90,350
"Correct Solution: ``` k=int(input()) if k<9:print(k);exit() t=[i for i in range(1,10)] c=9 while c<k: a=t.pop(0) for i in range(max(0,a%10-1),min(10,a%10+2)): t.append(a*10+i) c+=1 print(t[-1-c+k]) ```
output
1
45,175
20
90,351
Provide a correct Python 3 solution for this coding contest problem. A positive integer X is said to be a lunlun number if and only if the following condition is satisfied: * In the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1. For example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is. You are given a positive integer K. Find the K-th smallest lunlun number. Constraints * 1 \leq K \leq 10^5 * All values in input are integers. Input Input is given from Standard Input in the following format: K Output Print the answer. Examples Input 15 Output 23 Input 1 Output 1 Input 13 Output 21 Input 100000 Output 3234566667
instruction
0
45,176
20
90,352
"Correct Solution: ``` k=int(input()) l=[1,2,3,4,5,6,7,8,9] for i in range(k): x=l[i] if x%10!=0: l.append(10*x+x%10-1) l.append(10*x+x%10) if x%10!=9: l.append(10*x+x%10+1) print(x) ```
output
1
45,176
20
90,353
Provide a correct Python 3 solution for this coding contest problem. A positive integer X is said to be a lunlun number if and only if the following condition is satisfied: * In the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1. For example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is. You are given a positive integer K. Find the K-th smallest lunlun number. Constraints * 1 \leq K \leq 10^5 * All values in input are integers. Input Input is given from Standard Input in the following format: K Output Print the answer. Examples Input 15 Output 23 Input 1 Output 1 Input 13 Output 21 Input 100000 Output 3234566667
instruction
0
45,177
20
90,354
"Correct Solution: ``` K = int(input()) A = [1,2,3,4,5,6,7,8,9] for i in A: if K<len(A): break x = i%10 for j in range(max(x-1,0),min(x+2,10)): A.append(10*i+j) print(A[K-1]) ```
output
1
45,177
20
90,355
Provide a correct Python 3 solution for this coding contest problem. A positive integer X is said to be a lunlun number if and only if the following condition is satisfied: * In the base ten representation of X (without leading zeros), for every pair of two adjacent digits, the absolute difference of those digits is at most 1. For example, 1234, 1, and 334 are lunlun numbers, while none of 31415, 119, or 13579 is. You are given a positive integer K. Find the K-th smallest lunlun number. Constraints * 1 \leq K \leq 10^5 * All values in input are integers. Input Input is given from Standard Input in the following format: K Output Print the answer. Examples Input 15 Output 23 Input 1 Output 1 Input 13 Output 21 Input 100000 Output 3234566667
instruction
0
45,178
20
90,356
"Correct Solution: ``` from collections import deque k = int(input()) a = deque([1, 2, 3, 4, 5, 6, 7, 8, 9]) for i in range(k-1): b = a.popleft() if b%10 != 0: a.append(b*10+b%10-1) a.append(b*10+b%10) if b%10 != 9: a.append(b*10+b%10+1) print(a[0]) ```
output
1
45,178
20
90,357