message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
s = input()
s = list(s)
n = len(s)
if '0' in s:
print('YES')
print(0)
exit()
if '8' in s:
print('YES')
print(8)
exit()
s.insert(0,'0')
#print(s)
n = n+1
for i in range(n-2):
for j in range(i+1,n-1):
for k in range(j+1,n):
x = int(s[i]+s[j]+s[k])
if(x % 8 == 0):
print('YES')
print(x)
exit()
print('NO')
``` | instruction | 0 | 61,100 | 20 | 122,200 |
Yes | output | 1 | 61,100 | 20 | 122,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
s = input().strip()
sl = [a for a in s]
if '0' in sl:
print('YES')
print(0)
elif '2' not in sl and '4' not in sl and '6' not in sl and '8' not in sl:
print('NO')
else:
l = len(sl)
done = False
for i in range(l):
tmp = int(sl[i])
if tmp%8 == 0:
print('YES')
print(tmp)
done = True
break
if not done and l > 1:
for i in range(l):
for j in range(i+1,l):
tmp = int(sl[i]+sl[j])
if tmp%8 == 0:
print('YES')
print(tmp)
done = True
break
if done:
break
if not done and l > 2:
for i in range(l):
for j in range(i+1,l):
for k in range(j+1,l):
tmp = int(sl[i]+sl[j]+sl[k])
if tmp%8 == 0:
print('YES')
print(tmp)
done = True
break
if done:
break
if done:
break
if not done:
print('NO')
``` | instruction | 0 | 61,101 | 20 | 122,202 |
Yes | output | 1 | 61,101 | 20 | 122,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
a=input()
if '0' in a:
print('YES')
print('0')
exit()
elif '8' in a:
print('YES')
print('8')
exit()
else:
for i in range(len(a)):
for x in range(i+1,len(a)):
p=int(a[i]+a[x])
if p%8==0:
print('YES')
print(p)
exit()
for z in range(x+1,len(a)):
c=int(a[i]+a[x]+a[z])
if c%8==0:
print('YES')
print(c)
exit()
print('NO')
``` | instruction | 0 | 61,102 | 20 | 122,204 |
Yes | output | 1 | 61,102 | 20 | 122,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
import sys
line = sys.stdin.readline().strip()
#print(line)
def solution(line):
if int(line)%8==0:
return line
for x in range(len(line)-1):
rm = line[x]
left = line[:x]
right = line[x+1:]
new = left+right
if int(new)%8 == 0 and new[0]!='0':
return new
return -1
sol = solution(line)
if sol!= -1:
print("YES")
print(sol)
else:
print("NO")
``` | instruction | 0 | 61,103 | 20 | 122,206 |
No | output | 1 | 61,103 | 20 | 122,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
s=input()
if(int(s)%8==0):
print("YES")
print(s)
elif(s.count('0')!=0):
print("YES")
print("0")
else:
flag=0
ans=""
for k in range(2,125):
j=8*k
i=str(j)
if(len(i)==2 and int(i)<int(s)):
i0=i[0]
i1=i[1]
x1=s.find(i0)
if(x1!=-1):
if(s[x1:len(s)].find(i1)!=-1):
flag=1
ans=i
break
if(len(i)==3 and int(i)<int(s)):
i0=i[0]
i1=i[1]
i2=i[2]
# print(i0,i1,i2)
x1=s.find(i0)
if(x1!=-1):
if(s[x1:len(s)].find(i1)!=-1):
x2=s[x1:len(s)].find(i1)
if(s[x2:len(s)].find(i2)!=-1):
flag=1
ans=i
break
if(flag==1):
print("YES")
print(ans)
else:print("NO")
``` | instruction | 0 | 61,104 | 20 | 122,208 |
No | output | 1 | 61,104 | 20 | 122,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
from collections import Counter
s=[]
for i in range(999):
if i%8==0:
s.append(i)
a=list(input())
f=0
counts=Counter(a)
def check(p):
f=0
counts1=Counter(p)
for i in p:
if (str(i) not in set(a)) or (counts[i]<counts1[i]):
f=1
break
if f==1:
return False
return True
for i in s:
if check(str(i)):
f=1
print("YES")
print(i)
break
if f==0:
print("NO")
``` | instruction | 0 | 61,105 | 20 | 122,210 |
No | output | 1 | 61,105 | 20 | 122,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a non-negative integer n, its decimal representation consists of at most 100 digits and doesn't contain leading zeroes.
Your task is to determine if it is possible in this case to remove some of the digits (possibly not remove any digit at all) so that the result contains at least one digit, forms a non-negative integer, doesn't have leading zeroes and is divisible by 8. After the removing, it is forbidden to rearrange the digits.
If a solution exists, you should print it.
Input
The single line of the input contains a non-negative integer n. The representation of number n doesn't contain any leading zeroes and its length doesn't exceed 100 digits.
Output
Print "NO" (without quotes), if there is no such way to remove some digits from number n.
Otherwise, print "YES" in the first line and the resulting number after removing digits from number n in the second line. The printed number must be divisible by 8.
If there are multiple possible answers, you may print any of them.
Examples
Input
3454
Output
YES
344
Input
10
Output
YES
0
Input
111111
Output
NO
Submitted Solution:
```
def f(n, memo, index=0, currnum=0):
key = index, currnum
if key in memo:
return memo[key]
if currnum % 8 == 0 and currnum > 0:
return True, currnum
if currnum > 999 or index >= len(n):
return False, -1
a = f(n, memo, index + 1, currnum * 10 + int(n[index]))
if a[0]:
to_return = a
else:
b = f(n, memo, index + 1, currnum)
if b[0]:
to_return = b
else:
to_return = False, -1
memo[key] = to_return
return to_return
n = input()
if '0' in n:
print('Yes')
print(0)
else:
memo = dict()
d = dict()
d[True] = "Yes"
d[False] = 'No'
res = f(n, memo)
print(d[res[0]])
print(res[1])
``` | instruction | 0 | 61,106 | 20 | 122,212 |
No | output | 1 | 61,106 | 20 | 122,213 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010 | instruction | 0 | 61,321 | 20 | 122,642 |
"Correct Solution:
```
def main():
N, M, K = map(int, input().split())
MAX_N = 2000000
s = [0] * MAX_N
t = [0] * MAX_N
for i, c in zip(range(N - 1, -1, -1), input()):
s[i] = int(c)
for i, c in zip(range(M - 1, -1, -1), input()):
t[i] = int(c)
len_max = max(N, M) - 1
for i in range(len_max, -1, -1):
j = i
z = K
while s[j] and t[j] and z:
s[j] = t[j] = 0
s[j + 1] += 1
t[j + 1] += 1
j += 1
z -= 1
js = jt = j
while s[js] == 2:
s[js] = 0
s[js + 1] += 1
js += 1
while t[jt] == 2:
t[jt] = 0
t[jt + 1] += 1
jt += 1
j = max(js, jt)
len_max = max(len_max, j)
s = s[:len_max + 1]
t = t[:len_max + 1]
while not s[-1]:
s.pop()
while not t[-1]:
t.pop()
print(*reversed(s), sep='')
print(*reversed(t), sep='')
main()
``` | output | 1 | 61,321 | 20 | 122,643 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010 | instruction | 0 | 61,322 | 20 | 122,644 |
"Correct Solution:
```
def main():
N, M, K = map(int, input().split())
MAX_N = 2000000
s = [0] * MAX_N
t = [0] * MAX_N
for i, c in zip(range(N - 1, -1, -1), input()):
s[i] = int(c)
for i, c in zip(range(M - 1, -1, -1), input()):
t[i] = int(c)
len_max = max(N, M) - 1
st = []
for i in range(len_max, -1, -1):
m = []
if s[i] and t[i]:
s[i] = t[i] = 0
xs = xt = 1
z = K - 1
j = i + 1
while xs or xt:
if not s[j] and not t[j]:
if xs and not xt:
s[j] = 1
st.append(j)
len_max = max(len_max, j)
break
elif not xs and xt:
t[j] = 1
st.append(j)
len_max = max(len_max, j)
break
if not st or st[-1] - j > z:
s[j + z] = t[j + z] = 1
len_max = max(len_max, j + z)
break
p = st.pop()
z -= p - j
j = p
if s[j] == xs and t[j] == xt:
s[j] = t[j] = 0
j += 1
continue
if xs and xt:
xs = s[j]
xt = t[j]
s[j] ^= 1
t[j] ^= 1
m.append(j)
j += 1
continue
if s[j] != xs and t[j] != xt:
if not z:
s[j] = t[j] = 1
break
else:
s[j] = t[j] = 0
j += 1
z -= 1
xs = xt = 1
continue
st += reversed(m)
elif s[i] or t[i]:
st.append(i)
s = s[:len_max + 1]
t = t[:len_max + 1]
while not s[-1]:
s.pop()
while not t[-1]:
t.pop()
print(*reversed(s), sep='')
print(*reversed(t), sep='')
main()
``` | output | 1 | 61,322 | 20 | 122,645 |
Provide a correct Python 3 solution for this coding contest problem.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010 | instruction | 0 | 61,323 | 20 | 122,646 |
"Correct Solution:
```
def Z():
m=-1;I=input;N,M,K=map(int,I().split());W=2000000;s=[0]*W;t=[0]*W;L=max(N,M)-1;R=range;p=lambda x:print(*reversed(x),sep='')
for i,c in zip(R(N-1,m,m),I()):s[i]=int(c)
for i,c in zip(R(M-1,m,m),I()):t[i]=int(c)
for i in R(L,m,m):
j=i;z=K
while s[j]and t[j]and z:
s[j]=t[j]=0;s[j+1]+=1;t[j+1]+=1;j+=1;z-=1;x=y=j
while s[x]==2:s[x]=0;s[x+1]+=1;x+=1
while t[y]==2:t[y]=0;t[y+1]+=1;y+=1
j=max(x,y)
L=max(L,j)
s=s[:L+1];t=t[:L+1]
while s[m]==0:s.pop()
while t[m]==0:t.pop()
p(s);p(t)
Z()
``` | output | 1 | 61,323 | 20 | 122,647 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010
Submitted Solution:
```
n,m,k=map(int,input().split())
s=int(input())
t=int(input())
def bitwise(n,m):
c=0
i=0
while n>=1 and m>=1:
an=n%(10**1)
am=m%(10**1)
if an==1 and am==1:
c+=10**i
n=(n-an)/10
m=(m-am)/10
i+=1
return(c)
def two_ten(n):
z=0
c=0
while n>=1:
if n%10==1:
z+=2**c
n-=1
n/=10
c+=1
return(z)
def ten_two(n):
z=0
c=0
while n>=1:
if n%2==1:
z+=10**c
n-=1
n/=2
c+=1
return(z)
while k >0:
z=bitwise(s,t)
s10=two_ten(s)+two_ten(z)
t10=two_ten(t)+two_ten(z)
s=ten_two(s10)
t=ten_two(t10)
k-=1
print(s)
print(t)
``` | instruction | 0 | 61,324 | 20 | 122,648 |
No | output | 1 | 61,324 | 20 | 122,649 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010
Submitted Solution:
```
N, M, K = (int(i) for i in input().split())
S = int(input(), 2)
T = int(input(), 2)
for i in range(K):
Z = S & T
S += Z
T += Z
print(format(S, "b"))
print(format(T, "b"))
``` | instruction | 0 | 61,326 | 20 | 122,652 |
No | output | 1 | 61,326 | 20 | 122,653 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Takahashi and Aoki love calculating things, so they will play with numbers now.
First, they came up with one positive integer each. Takahashi came up with X, and Aoki came up with Y. Then, they will enjoy themselves by repeating the following operation K times:
* Compute the bitwise AND of the number currently kept by Takahashi and the number currently kept by Aoki. Let Z be the result.
* Then, add Z to both of the numbers kept by Takahashi and Aoki.
However, it turns out that even for the two math maniacs this is just too much work. Could you find the number that would be kept by Takahashi and the one that would be kept by Aoki eventually?
Note that input and output are done in binary. Especially, X and Y are given as strings S and T of length N and M consisting of `0` and `1`, respectively, whose initial characters are guaranteed to be `1`.
Constraints
* 1 β€ K β€ 10^6
* 1 β€ N,M β€ 10^6
* The initial characters of S and T are `1`.
Input
Input is given from Standard Input in the following format:
N M K
S
T
Output
In the first line, print the number that would be kept by Takahashi eventually; in the second line, print the number that would be kept by Aoki eventually. Those numbers should be represented in binary and printed as strings consisting of `0` and `1` that begin with `1`.
Examples
Input
2 3 3
11
101
Output
10000
10010
Input
5 8 3
10101
10101001
Output
100000
10110100
Input
10 10 10
1100110011
1011001101
Output
10000100000010001000
10000100000000100010
Submitted Solution:
```
line1 = input().split()
N = int(line1[0])
M = int(line1[1])
K = int(line1[2])
S = int(input(), 2)
T = int(input(), 2)
for i in range(K):
Z = S & T
S += Z
T += Z
print(format(S, 'b'))
print(format(T, 'b'))
``` | instruction | 0 | 61,327 | 20 | 122,654 |
No | output | 1 | 61,327 | 20 | 122,655 |
Provide a correct Python 3 solution for this coding contest problem.
You are given an integer $N$ and a string consisting of '+' and digits. You are asked to transform the string into a valid formula whose calculation result is smaller than or equal to $N$ by modifying some characters. Here, you replace one character with another character any number of times, and the converted string should still consist of '+' and digits. Note that leading zeros and unary positive are prohibited.
For instance, '0123+456' is assumed as invalid because leading zero is prohibited. Similarly, '+1+2' and '2++3' are also invalid as they each contain a unary expression. On the other hand, '12345', '0+1+2' and '1234+0+0' are all valid.
Your task is to find the minimum number of the replaced characters. If there is no way to make a valid formula smaller than or equal to $N$, output $-1$ instead of the number of the replaced characters.
Input
The input consists of a single test case in the following format.
$N$
$S$
The first line contains an integer $N$, which is the upper limit of the formula ($1 \leq N \leq 10^9$). The second line contains a string $S$, which consists of '+' and digits and whose length is between $1$ and $1,000$, inclusive. Note that it is not guaranteed that initially $S$ is a valid formula.
Output
Output the minimized number of the replaced characters. If there is no way to replace, output $-1$ instead.
Examples
Input
100
+123
Output
2
Input
10
+123
Output
4
Input
1
+123
Output
-1
Input
10
++1+
Output
2
Input
2000
1234++7890
Output
2 | instruction | 0 | 61,442 | 20 | 122,884 |
"Correct Solution:
```
from heapq import heappush, heappop, heapify
import sys
readline = sys.stdin.readline
write = sys.stdout.write
def solve():
N = int(readline())
S = readline().strip()
L = len(S)
S += "+"
if L % 2 == 0 and N < 10:
write("-1\n")
return
pw10 = [1]*11
for i in range(10):
pw10[i+1] = pw10[i] * 10
INF = N+1
dist = [[INF]*(L+2) for i in range(L+1)]
ques = [[] for i in range(L+1)]
ques[0] = [(0, 0)]
dist[0][0] = 0
for k in range(L+1):
que = ques[k]
dist0 = dist[k]
heapify(que)
while que:
cost, i = heappop(que)
if dist0[i] < cost or i > L:
continue
p = S[i]
if i+1 != L-1:
if p != "+":
v = int(p)
if S[i+1] != '+':
if cost + v < dist[k+1][i+2]:
dist[k+1][i+2] = cost + v
ques[k+1].append((cost + v, i+2))
else:
if cost + v < dist0[i+2]:
dist0[i+2] = cost + v
heappush(que, (cost + v, i+2))
if p != "0":
nk = k+1 + (S[i+1] != "+")
if cost < dist[nk][i+2]:
dist[nk][i+2] = cost
ques[nk].append((cost, i+2))
def calc(c0, p):
for j in range(i+2, min(i+10, L+1)):
if j == L-1:
continue
p1 = p + S[i+1:j]; l = j-i
c = c0 + p1.count("+")
v = int(p1.replace(*"+0"))
if v <= N:
nk = k+c + (S[j] != '+')
if cost + v < dist[nk][j+1]:
dist[nk][j+1] = cost + v
ques[nk].append((cost + v, j+1))
b = pw10[l-2]
for e in range(l-2, -1, -1):
a = (v // b) % 10
if a:
v -= a * b
c += 1
if v <= N:
nk = k+c + (S[j] != '+')
if cost + v < dist[nk][j+1]:
dist[nk][j+1] = cost + v
ques[nk].append((cost + v, j+1))
b //= 10
if p not in "0+":
calc(0, p)
if p != "1":
calc(1, "1")
if dist0[L+1] <= N:
write("%d\n" % k)
break
solve()
``` | output | 1 | 61,442 | 20 | 122,885 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,603 | 20 | 123,206 |
Tags: *special, bitmasks
Correct Solution:
```
num = int(input())
pix = [0]*6
for i in range(6):
pix[-i-1] = (num % 2)
num = num // 2
ref = [0]*6
ref[0] = pix[0]
ref[5] = pix[1]
ref[3] = pix[2]
ref[1] = pix[3]
ref[4] = pix[4]
ref[2] = pix[5]
ref[0] = pix[0]
ref[5] = pix[1]
ref[3] = pix[2]
ref[2] = pix[3]
ref[4] = pix[4]
ref[1] = pix[5]
num = 0
for i in range(6):
num = num*2 + ref[i]
print(num)
``` | output | 1 | 61,603 | 20 | 123,207 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,604 | 20 | 123,208 |
Tags: *special, bitmasks
Correct Solution:
```
# coding: utf-8
a = bin(int(input()))[2:].rjust(6, '0')
b = a[0] + a[5] + a[3] + a[2] + a[4] + a[1]
print(int(b, 2))
``` | output | 1 | 61,604 | 20 | 123,209 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,605 | 20 | 123,210 |
Tags: *special, bitmasks
Correct Solution:
```
n = int(input())
ls = [bool(n & (1 << i)) for i in range(6)]
p = [16, 2, 8, 4, 1, 32]
print(sum((a * b for a, b in zip(ls, p))))
``` | output | 1 | 61,605 | 20 | 123,211 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,606 | 20 | 123,212 |
Tags: *special, bitmasks
Correct Solution:
```
def binaryToDecimal(binary):
binary1 = binary
decimal, i, n = 0, 0, 0
while(binary != 0):
dec = binary % 10
decimal = decimal + dec * pow(2, i)
binary = binary//10
i += 1
print(decimal)
a=int(input())
b=bin(a).replace('0b','')
b=(6-len(b))*'0'+b
ch=list('0'*6)
ch[0]=b[0]
ch[1]=b[5]
ch[2]=b[3]
ch[3]=b[2]
ch[4]=b[4]
ch[5]=b[1]
ch="".join(ch)
binaryToDecimal(int(ch))
``` | output | 1 | 61,606 | 20 | 123,213 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,607 | 20 | 123,214 |
Tags: *special, bitmasks
Correct Solution:
```
"""input
5
"""
def digit(n):
return len(str(n))
def convert(a, b):
c = ""
while a>0:
if(a%b>=10):
c+=chr(55+(a%b))
else:
c += str(a%b)
a = a//b
return c[::-1]
def number(a, b):
i = digit(a)
a = str(a)
c= a[::-1]
l = 0
for t in range(i):
l+= (b**(t))*int(c[t])
return l
x=convert(int(input()),2)
n=len(x)
if(n<6):
x='0'*(6-n)+x
# print(x)
x=list(x)
x[1],x[5]=x[5],x[1]
x[2],x[3]=x[3],x[2]
print(number(''.join(x),2))
``` | output | 1 | 61,607 | 20 | 123,215 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,608 | 20 | 123,216 |
Tags: *special, bitmasks
Correct Solution:
```
n = int(input())
n = list(bin(n)[2:])
n = (6-len(n))*["0"]+n
n_t = n.copy()
n[1] = n_t[5]
n[2] = n_t[3]
n[3] = n_t[2]
n[4] = n_t[4]
n[5] = n_t[1]
print(int(''.join(n),2))
``` | output | 1 | 61,608 | 20 | 123,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,609 | 20 | 123,218 |
Tags: *special, bitmasks
Correct Solution:
```
n = int(input())
b = bin(n).replace("0b", "")
f = "0"*(7-len(b)) + b
mapping = [0,1,6,4,3,5,2]
ans = ["0","0","0","0","0","0","0"]
for i in range(7):
if f[i] == "1":
ans[mapping[i]] = "1"
# print(ans,sep="")
ok = False
s = "0"
for c in ans:
if c == "1":
ok = True
if ok:
s += str(c)
s = int(s,2)
print(s)
``` | output | 1 | 61,609 | 20 | 123,219 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Input
The input contains a single integer a (0 β€ a β€ 63).
Output
Output a single number.
Examples
Input
2
Output
2
Input
5
Output
24
Input
35
Output
50 | instruction | 0 | 61,610 | 20 | 123,220 |
Tags: *special, bitmasks
Correct Solution:
```
x = int(input())
xBin = list(bin(x+64)[3:])
xBin[1], xBin[5] = xBin[5], xBin[1]
xBin[2], xBin[3] = xBin[3], xBin[2]
xBin = "".join(x for x in xBin)
print(int(xBin, 2))
``` | output | 1 | 61,610 | 20 | 123,221 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,808 | 20 | 123,616 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
n = int(input())
if n<=3:
print('NO')
exit()
print('YES')
if n%2==0:
print('%s * %s = %s' %(1,2,2))
print('%s * %s = %s' %(2,3,6))
print('%s * %s = %s' %(6,4,24))
for i in range(6,n+1,2):
print('%s - %s = 1' %(i,i-1))
print('%s * %s = %s' %(1,24,24))
else:
print('2 * 4 = 8')
print('3 * 5 = 15')
print('1 + 8 = 9')
print('9 + 15 = 24')
for i in range(7,n+1,2):
print('%s - %s = 1' %(i,i-1))
print('%s * %s = %s' %(1,24,24))
``` | output | 1 | 61,808 | 20 | 123,617 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,809 | 20 | 123,618 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
entrada = int(input())
if entrada <= 3:
print("NO")
elif entrada%2 == 0:
print("YES")
print("1 * 2 = 2")
print("2 * 3 = 6")
print("6 * 4 = 24")
for i in range(5,entrada,2):
print (str(i+1)+" - "+str(i)+" = 1")
print("24 * 1 = 24")
else:
print("YES")
print("2 - 1 = 1")
print("1 + 3 = 4")
print("4 * 5 = 20")
print("20 + 4 = 24")
for j in range(6,entrada,2):
print (str(j+1)+" - "+str(j)+" = 1")
print("24 * 1 = 24")
``` | output | 1 | 61,809 | 20 | 123,619 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,810 | 20 | 123,620 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
n = int(input())
if n < 4:
print('NO')
else:
print('YES')
if (n % 2 == 1):
print('3 * 5 = 15')
print('2 * 4 = 8')
print('1 + 8 = 9')
print('9 + 15 = 24')
for i in range(6,n+1,2):
print(i+1,' - ',i ,'= 1')
print('24 * 1 = 24')
else:
print('1 * 2 = 2')
print('3 * 4 = 12')
print('12 * 2 = 24')
for i in range(5,n+1,2):
print(i+1,' - ',i ,'= 1')
print('24 * 1 = 24')
``` | output | 1 | 61,810 | 20 | 123,621 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,811 | 20 | 123,622 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
def logs(n):
if n == 4: return [(1,1,2), (1,2,3), (1,6,4)]
if n == 5: return [(2,5,4), (2,9,3), (1,12,2), (1,24,1)]
ans = [(3,i+1,i) for i in range(n-1, 4, -2)]
ans.extend(logs(4 + n%2))
ans += [(1,24,1) for i in range(n-1-len(ans))]
return ans
n = int(input())
if n < 4:
print('NO')
else:
print('YES')
for note in logs(n):
if note[0] == 1:
print('{0} * {1} = {2}'.format(note[1], note[2], note[1]*note[2]))
elif note[0] == 2:
print('{0} + {1} = {2}'.format(note[1], note[2], note[1]+note[2]))
else:
print('{0} - {1} = {2}'.format(note[1], note[2], note[1]-note[2]))
``` | output | 1 | 61,811 | 20 | 123,623 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,812 | 20 | 123,624 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
N = int(input())
if N == 1 or N == 2 or N == 3:
print("NO")
elif N%2 == 0:
print("YES")
print("1 * 2 = 2")
print("2 * 3 = 6")
print("6 * 4 = 24")
count = 0
for j in range(5,N,2):
print(str(j+1) + " - " + str(j) + " = 1")
count += 1
for l in range(count-1):
print("1 * 1 = 1")
if N>4:
print ("24 * 1 = 24")
else:
print("YES")
print("5 - 1 = 4")
print("4 - 2 = 2")
print("3 * 4 = 12")
print("12 * 2 = 24")
count = 0
for j in range(6,N,2):
print(str(j+1) + " - " + str(j) + " = 1")
count += 1
for l in range(count-1):
print("1 * 1 = 1")
if N>5:
print ("24 * 1 = 24")
``` | output | 1 | 61,812 | 20 | 123,625 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,813 | 20 | 123,626 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
def main():
n = int(input())
if n <= 3:
print('NO')
return
_4 = ('4 * 3 = 12\n'
'12 * 2 = 24\n'
'1 * 24 = 24')
_5 = ('5 - 3 = 2\n'
'2 + 1 = 3\n'
'3 * 4 = 12\n'
'2 * 12 = 24')
print('YES')
for i in range(n, 4 + n%2, -2):
print('{} - {} = 1'.format(i, i-1))
print('{0} * 1 = {0}'.format(i-2))
print(_5 if n%2 else _4)
if __name__ == '__main__':
main()
``` | output | 1 | 61,813 | 20 | 123,627 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,814 | 20 | 123,628 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
#------------------------template--------------------------#
import os
import sys
# from math import *
from collections import *
# from fractions import *
# from heapq import*
from bisect import *
from io import BytesIO, IOBase
def vsInput():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
ALPHA='abcdefghijklmnopqrstuvwxyz'
M=10**9+7
EPS=1e-6
def Ceil(a,b): return a//b+int(a%b>0)
def value():return tuple(map(int,input().split()))
def array():return [int(i) for i in input().split()]
def Int():return int(input())
def Str():return input()
def arrayS():return [i for i in input().split()]
#-------------------------code---------------------------#
# vsInput()
n=Int()
if(n<4):
print("NO")
exit()
print("YES")
if(n==4):
print("3 * 4 = 12")
print("12 * 2 = 24")
print("24 * 1 = 24")
elif(n==5):
print("5 * 4 = 20")
print("2 - 1 = 1")
print("3 + 1 = 4")
print("20 + 4 = 24")
else:
print("3 - 2 = 1")
print("1 - 1 = 0")
for i in range(7,n+1):
print("{} * 0 = 0".format(i))
print("5 * 0 = 0")
print("4 * 6 = 24")
print("24 + 0 = 24")
``` | output | 1 | 61,814 | 20 | 123,629 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24 | instruction | 0 | 61,815 | 20 | 123,630 |
Tags: constructive algorithms, greedy, math
Correct Solution:
```
n=int(input())
if n<=3:
print("NO")
elif n%2==0:
print("YES")
print("1 * 2 = 2")
print("2 * 3 = 6")
print("4 * 6 = 24")
for x in range(5,n,2):
print(x+1,"-",x,"=","1")
print("24 * 1 = 24")
else:
print("YES")
print("2 - 1 = 1")
print("1 + 3 = 4")
print("4 * 5 = 20")
print("4 + 20 = 24")
for x in range(6,n,2):
print(x+1,"-",x,"=","1")
print("24 * 1 = 24")
``` | output | 1 | 61,815 | 20 | 123,631 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
numInts = int(input().strip())
if numInts < 4:
print("NO")
else:
print("YES")
if numInts == 4:
print("1 * 2 = 2")
print("2 * 3 = 6")
print("6 * 4 = 24")
elif numInts == 5:
print("5 - 2 = 3")
print("3 - 1 = 2")
print("3 * 4 = 12")
print("12 * 2 = 24")
else:
print("3 - 2 = 1")
print("1 - 1 = 0")
print("4 * 6 = 24")
print("5 * 0 = 0")
for x in range(7, numInts + 1):
print(str(x) + " * 0 = 0")
print("24 + 0 = 24")
``` | instruction | 0 | 61,816 | 20 | 123,632 |
Yes | output | 1 | 61,816 | 20 | 123,633 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
n=int(input())
if n<=3:
print("NO")
if n==4:
print("YES\n3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24")
if n==5:
print("YES\n4 * 5 = 20\n20 + 2 = 22\n22 + 3 = 25\n25 - 1 = 24")
if n==6:
print("YES\n6 - 5 = 1\n3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n1 * 24 = 24")
if n==7:
print("YES\n7 - 6 = 1\n4 * 5 = 20\n20 + 2 = 22\n22 + 3 = 25\n25 - 1 = 24\n1 * 24 = 24")
if n==8:
print("YES")
print("%d - %d = 1\n%d - %d = 1"%(n, n-1, n-2, n-3))
print("1 - 1 = 0")
print("3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n0 + 24 = 24")
if n>8:
print("YES")
print("%d - %d = 1\n%d - %d = 1"%(n, n-1, n-2, n-3))
print("1 - 1 = 0")
i=n-4
while i>4:
print("%d * 0 = 0"%(i))
i-=1
print("3 * 4 = 12\n2 * 1 = 2\n12 * 2 = 24\n0 + 24 = 24")
``` | instruction | 0 | 61,817 | 20 | 123,634 |
Yes | output | 1 | 61,817 | 20 | 123,635 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
n = int(input())
if n < 4: print('NO')
elif n == 5:
print('YES')
print('5 - 3 = 2')
print('1 + 2 = 3')
print('2 * 3 = 6')
print('6 * 4 = 24')
else:
print('YES')
if n != 4:
print('5 - 6 = -1')
print('1 + -1 = 0')
for i in range(7, n + 1):
print(i, '* 0 = 0')
if n != 4: print('4 + 0 = 4')
else: print('4 * 1 = 4')
print('2 * 3 = 6')
print('6 * 4 = 24')
``` | instruction | 0 | 61,818 | 20 | 123,636 |
Yes | output | 1 | 61,818 | 20 | 123,637 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
n = int(input())
if n < 4: print('NO')
else:
print('YES')
if n == 4: t = ['1 * 2 = 2', '2 * 3 = 6', '6 * 4 = 24']
elif n == 5: t = ['2 - 1 = 1', '1 + 3 = 4', '4 * 5 = 20', '20 + 4 = 24']
else:
t = ['3 - 2 = 1', '1 - 1 = 0', '5 * 0 = 0', '6 * 4 = 24']
t += [str(i) + ' * 0 = 0' for i in range(7, n + 1)]
t.append('24 + 0 = 24')
print('\n'.join(t))
``` | instruction | 0 | 61,819 | 20 | 123,638 |
Yes | output | 1 | 61,819 | 20 | 123,639 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
# f(1),f(2),f(3)δΈθ‘
# f(4)=4*3*2*1
# f(5)=(5-1)*4*3/2
# f(6)=(6-5)*f(4)
# f(7)=(7+6+1-5)*4/3*2
#f(8)=(8-7+1+6-5)*4*3*22
#δ»₯δΈf(2k+2)εε©1ε¨ζ¬ε·ε
ζθ
ζ¬ε·ε€θ°θοΌkδΈΊε₯ζ°1ε¨ζ¬ε·ε€οΌkδΈΊεΆζ°1ε¨ζ¬ε·ε€
# f(9)=(9-8+7+6-5)*4/3*2*1
# δ»₯δΈf(2k+1)εε©1ε¨ζ¬ε·ε
ζθ
ζ¬ε·ε€θ°θοΌkδΈΊε₯ζ°1ε¨ζ¬ε·ε€οΌkδΈΊεΆζ°1ε¨ζ¬ε·ε€
n = int(input())
if n <= 3:
print("NO")
else:
print("YES")
``` | instruction | 0 | 61,820 | 20 | 123,640 |
No | output | 1 | 61,820 | 20 | 123,641 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
def print_one():
print("1 * 4 = 4".ljust(0))
print("4 * 3 = 12".ljust(0))
print("12 * 2 = 24".ljust(0))
print("24 * 1 = 1".ljust(0))
def print_two():
print("4 * 3 = 12".ljust(0))
print("12 * 2 = 24".ljust(0))
print("24 * 1 = 24".ljust(0))
def print_three():
print("5 + 4 = 9".ljust(0))
print("9 + 3 = 12".ljust(0))
print("12 * 2 = 24".ljust(0))
def print_four():
print("5 + 4 = 9".ljust(0))
print("9 + 3 = 12".ljust(0))
print("12 * 2 = 24".ljust(0))
print("24 * 1 = 24".ljust(0))
def Print(n):
if n%4==0:
if n > 4:
flag = -1
print("%d + %d = %d".ljust(0) % (-n, n - 1, flag))
print("%d + %d = %d".ljust(0) % (flag, n - 2, flag + n - 2))
flag = flag + n - 2
print("%d - %d = %d".ljust(0) % (flag, n- 3, flag - n + 3))
flag = flag - n + 3
if n>8:
print("%d - %d = %d".ljust(0) % (flag, n - 4, 4-n))
else:
print("%d + %d = %d".ljust(0) % (flag, n - 4, n-4))
Print(n-4)
else:
print_two()
if n % 4 == 1:
if n > 5:
flag = 1
print("% d - %d = %d".ljust(0) % (n, n - 1, flag))
print("%d - %d = %d".ljust(0) % (flag, n - 2, flag - n + 2))
flag = flag - n + 2
print("%d + %d = %d".ljust(0) % (flag, n - 3, flag + n - 3))
flag = flag + n - 3
print("%d + %d = %d".ljust(0) % (flag, n - 4, n - 4))
Print(n - 4)
else:
print_four()
if n % 4 == 2:
if n > 6:
flag = 1
print("%d - %d = %d".ljust(0) % (n, n - 1, flag))
print("%d - %d = %d".ljust(0) % (flag, n - 2, flag - n + 2))
flag = flag - n + 2
print("%d + %d = %d".ljust(0) % (flag, n - 3, flag + n - 3))
flag = flag + n - 3
print("%d + %d = %d".ljust(0) % (flag, n - 4, n - 4))
Print(n - 4)
else:
print("6 - 5 = 1".ljust(0))
print_one()
if n % 4 == 3:
if n > 7:
flag = -1
print("% d + %d = %d".ljust(0) % (-n, n - 1, flag))
print("%d + %d = %d".ljust(0) % (flag, n - 2, flag + n - 2))
flag = flag + n - 2
print("%d - %d = %d".ljust(0) % (flag, n- 3, flag - n + 3))
flag = flag - n + 3
print("%d - %d = %d".ljust(0) % (flag, n - 4, 4 - n))
Print(n-4)
else:
print("-7 + 6 = -1".ljust(0))
print("-1 + 1 =0".ljust(0))
print("0 + 5 = 5".ljust(0))
print_three()
n = int(input())
if n <= 3:
print("NO")
if n > 3:
print("YES")
Print(n)
``` | instruction | 0 | 61,821 | 20 | 123,642 |
No | output | 1 | 61,821 | 20 | 123,643 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
import sys
import math
n = int(sys.stdin.readline())
if(n < 4):
print("NO")
exit()
print("YES")
for i in range(n, 5, -2):
print(str(i) + " - " + str(i - 1) + " = " + str(1))
t = int(n / 2) - 2
k = int(t / 2)
if(t % 2 != 0):
k += 1
for i in range(k):
print("1 - 1 = 0")
while(k > 1):
for i in range(k - 1):
print("0 - 0 = 0")
k -= 1
if(n % 2 == 0):
if(t % 2 == 0):
if(n != 4):
print("1 + 0 = 1")
print("1 * 2 = 2")
else:
print("0 + 2 = 2")
print("2 * 3 = 6")
print("6 * 4 = 24")
else:
if(t % 2 == 0):
if(n != 5):
print("1 + 0 = 1")
print("1 * 2 = 2")
else:
print("0 + 2 = 2")
print("5 - 2 = 3")
print("3 + 3 = 6")
print("6 * 4 = 24")
``` | instruction | 0 | 61,822 | 20 | 123,644 |
No | output | 1 | 61,822 | 20 | 123,645 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Little X used to play a card game called "24 Game", but recently he has found it too easy. So he invented a new game.
Initially you have a sequence of n integers: 1, 2, ..., n. In a single step, you can pick two of them, let's denote them a and b, erase them from the sequence, and append to the sequence either a + b, or a - b, or a Γ b.
After n - 1 steps there is only one number left. Can you make this number equal to 24?
Input
The first line contains a single integer n (1 β€ n β€ 105).
Output
If it's possible, print "YES" in the first line. Otherwise, print "NO" (without the quotes).
If there is a way to obtain 24 as the result number, in the following n - 1 lines print the required operations an operation per line. Each operation should be in form: "a op b = c". Where a and b are the numbers you've picked at this operation; op is either "+", or "-", or "*"; c is the result of corresponding operation. Note, that the absolute value of c mustn't be greater than 1018. The result of the last operation must be equal to 24. Separate operator sign and equality sign from numbers with spaces.
If there are multiple valid answers, you may print any of them.
Examples
Input
1
Output
NO
Input
8
Output
YES
8 * 7 = 56
6 * 5 = 30
3 - 4 = -1
1 - 2 = -1
30 - -1 = 31
56 - 31 = 25
25 + -1 = 24
Submitted Solution:
```
def print_validated(a,op,b,c):
print(str(a),op,str(b),'=',str(c))
n=int(input())
if n<4 :
print('NO')
exit()
m=n-3
k=n
if m%2==1:
print('YES')
print_validated(1,'+',2,3)
print_validated(3,'+',3,6)
while k!=4:
print_validated(k,'-',k-1,1)
print_validated(4,'*',1,4)
k-=2
print_validated(4,'*',6,24)
else:
print('NO')
``` | instruction | 0 | 61,823 | 20 | 123,646 |
No | output | 1 | 61,823 | 20 | 123,647 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,840 | 20 | 123,680 |
Tags: greedy, implementation
Correct Solution:
```
from sys import stdin
import collections
def bar(s):
ans = ''
f = False
for ss in s.rstrip('\n'):
if int(ss) >= 5:
if int(ss) == 9 and not f:
ans += ss
f = True
else:
ans += str(9 - int(ss))
f = True
else:
ans += ss
f = True
return ans
if __name__ == '__main__':
s = stdin.readline()
print(bar(s))
``` | output | 1 | 61,840 | 20 | 123,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,841 | 20 | 123,682 |
Tags: greedy, implementation
Correct Solution:
```
from sys import stdin
input = stdin.readline
t = input()[:-1]
if t[0] == '9':
total = '9'
else:
ti = int(t[0])
total = str(min(9-ti,ti))
for i in range(1,len(t)):
ti = int(t[i])
check = str(min(9-ti,ti))
if check:
total += check
else: total += ti
print(total)
``` | output | 1 | 61,841 | 20 | 123,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,842 | 20 | 123,684 |
Tags: greedy, implementation
Correct Solution:
```
from sys import stdin, stdout, setrecursionlimit
input = stdin.readline
flush = stdout.flush
#setrecursionlimit(1000000)
############################################################
OUT = []
def write(item, sep = " "):
if type(item) is int:
OUT.append(str(item))
elif type(item) is list:
if type(item[0]) is int:
OUT.append(sep.join(map(str, item)))
else:
OUT.append(sep.join(item))
else:
OUT.append(item)
def PRINT():
print("\n".join(OUT))
GI = lambda: int(input())
GS = lambda: input()[:-1]
gi = lambda: list(map(int, input().split()))
gs = lambda: input().split()
############################################################
n = GS()
write("".join(min(i, str(9 - int(i))) if i < "9" or j > 0 else i for j, i in enumerate(n)) or "0")
PRINT()
``` | output | 1 | 61,842 | 20 | 123,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,843 | 20 | 123,686 |
Tags: greedy, implementation
Correct Solution:
```
a = input()
b = ""
i = 0
if a[i] == '9':
b += a[i]
i += 1
while i < len(a):
b += str(min(int(a[i]), 9 - int(a[i])))
i += 1
print(b)
``` | output | 1 | 61,843 | 20 | 123,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,844 | 20 | 123,688 |
Tags: greedy, implementation
Correct Solution:
```
s = input()
ans = "0"
b = False
y = len(s)
for i in range(y):
x = s[i]
if int(x) >= 5 and not(i==0 and s[i] == "9"):
x = str(9-int(x))
ans += x
print(int(ans))
``` | output | 1 | 61,844 | 20 | 123,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,845 | 20 | 123,690 |
Tags: greedy, implementation
Correct Solution:
```
a = input()
b = ""
for x in range(len(a)):
digit = int(a[x])
if 9 - digit < digit and digit != 9 or digit == 9 and x != 0:
digit = 9 - digit
b += str(digit)
print(b)
``` | output | 1 | 61,845 | 20 | 123,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,846 | 20 | 123,692 |
Tags: greedy, implementation
Correct Solution:
```
mylist = list(map(int, input()))
if mylist[0] == 9:
for i in range(1, len(mylist)):
if (9-mylist[i] < mylist[i]):
mylist[i] = 9-mylist[i]
else:
for i in range(0, len(mylist)):
if (9-mylist[i] < mylist[i]):
mylist[i] = 9-mylist[i]
print(''.join(str(x) for x in mylist))
``` | output | 1 | 61,846 | 20 | 123,693 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444 | instruction | 0 | 61,847 | 20 | 123,694 |
Tags: greedy, implementation
Correct Solution:
```
def main():
n = input()
res = []
for i, c in enumerate(n):
if i == 0:
c = str(9 - int(c)) if 9 > int(c) >= 5 else c
if int(c) >= 5 and 0 < i < len(n):
c = str(9 - int(c))
res.append(c)
res = ''.join(res).lstrip('0')
print(res if len(res) else 0)
if __name__ == '__main__':
main()
``` | output | 1 | 61,847 | 20 | 123,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444
Submitted Solution:
```
import sys
x = sys.stdin.readline()
ln = len(x) - 1
i = 0
res = []
if(x[i] == '9'):
res.append('9')
i += 1
for j in range(i, ln):
if(int(x[j]) >= 5):
res.append(str(9 - int(x[j])))
else:
res.append(x[j])
print("".join(res))
``` | instruction | 0 | 61,848 | 20 | 123,696 |
Yes | output | 1 | 61,848 | 20 | 123,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444
Submitted Solution:
```
s=input()
v=[]
p=''
for i in range(len(s)):
if int(s[i])>4:
p=9-int(s[i])
k=s[i].replace(s[i],str(p))
v.append(k)
else:
v.append(s[i])
j=''.join(v)
# print(j)
if int(j[0])<1:
p='9'+j[1:]
print(p)
else:
print(j)
``` | instruction | 0 | 61,849 | 20 | 123,698 |
Yes | output | 1 | 61,849 | 20 | 123,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444
Submitted Solution:
```
# Language practice purpose
s=list(input())
ln=len(s)
for i in range(ln):
s[i]=chr(48+min(ord(s[i])-48,ord('9')-ord(s[i])))
if s[0]=='0':
s[0]='9'
print("".join(s))
``` | instruction | 0 | 61,850 | 20 | 123,700 |
Yes | output | 1 | 61,850 | 20 | 123,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Luke Skywalker gave Chewbacca an integer number x. Chewbacca isn't good at numbers but he loves inverting digits in them. Inverting digit t means replacing it with digit 9 - t.
Help Chewbacca to transform the initial number x to the minimum possible positive number by inverting some (possibly, zero) digits. The decimal representation of the final number shouldn't start with a zero.
Input
The first line contains a single integer x (1 β€ x β€ 1018) β the number that Luke Skywalker gave to Chewbacca.
Output
Print the minimum possible positive number that Chewbacca can obtain after inverting some digits. The number shouldn't contain leading zeroes.
Examples
Input
27
Output
22
Input
4545
Output
4444
Submitted Solution:
```
n=int(input())
s=0
i=1
def func(n):
global s,i
if n!=0:
func(n//10)
p=n%10
if p>=5:
if p==9 and i==1:
s=s*10+p
i+=1
else:
s=s*10+9-p
i+=1
else:
s=s*10+p
i+=1
func(n)
print(s)
``` | instruction | 0 | 61,851 | 20 | 123,702 |
Yes | output | 1 | 61,851 | 20 | 123,703 |
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