message stringlengths 2 59.7k | message_type stringclasses 2
values | message_id int64 0 1 | conversation_id int64 37 108k | cluster float64 20 20 | __index_level_0__ int64 74 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly zero) operations with this number. During each... | instruction | 0 | 77,598 | 20 | 155,196 |
Tags: implementation, math
Correct Solution:
```
# codeforces
# 1165A
# solved 2019-10-10 23:03:52
n, x, y = map(int, str(input()).split())
b = str(input())
op = 0
for i in range(x):
if i == y:
if b[-i-1] == '0':
op+=1
else:
if b[-i-1] == '1':
op+=1
print(op)
``` | output | 1 | 77,598 | 20 | 155,197 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly zero) operations with this number. During each... | instruction | 0 | 77,599 | 20 | 155,198 |
Tags: implementation, math
Correct Solution:
```
n, x, y = map(int, input().rstrip().split(" "))
num = list(input())
c = 0
for i in range(1,y+1):
if num[-1*i]=="1":
c +=1
if num[-1*(y+1)]=="0":
c +=1
for j in range(y+2,x+1):
if num[-1*j]=="1":
c+=1
print(c)
``` | output | 1 | 77,599 | 20 | 155,199 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly zero) operations with this number. During each... | instruction | 0 | 77,600 | 20 | 155,200 |
Tags: implementation, math
Correct Solution:
```
n,x,y=map(int,input().split())
a=input()
b=""
for i in range(n):
b+=a[n-1-i]
count=0
for j in range(x):
if(j==y):
if(b[j]=="0"):
count+=1
else:
if(b[j]=="1"):
count+=1
print(count)
``` | output | 1 | 77,600 | 20 | 155,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,601 | 20 | 155,202 |
Yes | output | 1 | 77,601 | 20 | 155,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,602 | 20 | 155,204 |
Yes | output | 1 | 77,602 | 20 | 155,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,603 | 20 | 155,206 |
Yes | output | 1 | 77,603 | 20 | 155,207 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,604 | 20 | 155,208 |
Yes | output | 1 | 77,604 | 20 | 155,209 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,605 | 20 | 155,210 |
No | output | 1 | 77,605 | 20 | 155,211 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,606 | 20 | 155,212 |
No | output | 1 | 77,606 | 20 | 155,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,607 | 20 | 155,214 |
No | output | 1 | 77,607 | 20 | 155,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a huge decimal number consisting of n digits. It is guaranteed that this number has no leading zeros. Each digit of this number is either 0 or 1.
You may perform several (possibly... | instruction | 0 | 77,608 | 20 | 155,216 |
No | output | 1 | 77,608 | 20 | 155,217 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,889 | 20 | 155,778 |
Tags: number theory
Correct Solution:
```
# int(input())
# [int(s) for s in input().split()]
# input()
from math import gcd
def solve():
n = int(input())
print(25)
if __name__ == "__main__":
solve()
``` | output | 1 | 77,889 | 20 | 155,779 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,890 | 20 | 155,780 |
Tags: number theory
Correct Solution:
```
n = int(input()); print("25")
``` | output | 1 | 77,890 | 20 | 155,781 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,891 | 20 | 155,782 |
Tags: number theory
Correct Solution:
```
_ = int(input())
print(25)
``` | output | 1 | 77,891 | 20 | 155,783 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,892 | 20 | 155,784 |
Tags: number theory
Correct Solution:
```
n = int(input())
if n == 0:
print("01")
elif n ==1:
print("05")
else:
print("25")
``` | output | 1 | 77,892 | 20 | 155,785 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,893 | 20 | 155,786 |
Tags: number theory
Correct Solution:
```
n=int(input())
if(n==0):
print(1)
elif(n==1):
print(5)
else:
print(25)
``` | output | 1 | 77,893 | 20 | 155,787 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,894 | 20 | 155,788 |
Tags: number theory
Correct Solution:
```
x=input()
print("25")
``` | output | 1 | 77,894 | 20 | 155,789 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,895 | 20 | 155,790 |
Tags: number theory
Correct Solution:
```
a = input()
print(25)
``` | output | 1 | 77,895 | 20 | 155,791 |
Provide tags and a correct Python 3 solution for this coding contest problem.
The HR manager was disappointed again. The last applicant failed the interview the same way as 24 previous ones. "Do I give such a hard task?" — the HR manager thought. "Just raise number 5 to the power of n and get last two digits of the nu... | instruction | 0 | 77,896 | 20 | 155,792 |
Tags: number theory
Correct Solution:
```
print(25)
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
pass
``` | output | 1 | 77,896 | 20 | 155,793 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem is interactive.
You should guess hidden number x which is between 1 and M = 10004205361450474, inclusive.
You could use up to 5 queries.
In each query, you can output an increasing sequence of k ≤ x integers, each between 1 a... | instruction | 0 | 78,291 | 20 | 156,582 |
Tags: dp, interactive
Correct Solution:
```
from sys import stdin, stdout
max_k=10000
max_shift = [max_k]
for t in range(1, 5):
max_shift.append(max_shift[t-1]*(max_k+1)+max_k)
def get_right(left, t): # [left...right]
if left >= max_k:
return left + max_shift[t-1] - 1
k = left
if k > max_k:
... | output | 1 | 78,291 | 20 | 156,583 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem is interactive.
You should guess hidden number x which is between 1 and M = 10004205361450474, inclusive.
You could use up to 5 queries.
In each query, you can output an increasing sequence of k ≤ x integers, each between 1 a... | instruction | 0 | 78,292 | 20 | 156,584 |
Tags: dp, interactive
Correct Solution:
```
from math import *
from sys import stdout
import os
def get_5th():
return 1
def full_5th(k):
return min(10000, k)
def get_4th():
now = 1
now = now + get_5th()
now = now + full_5th(now + 1)
return now
def full_4th(k):
if k>=10000:
retur... | output | 1 | 78,292 | 20 | 156,585 |
Provide tags and a correct Python 3 solution for this coding contest problem.
This problem is interactive.
You should guess hidden number x which is between 1 and M = 10004205361450474, inclusive.
You could use up to 5 queries.
In each query, you can output an increasing sequence of k ≤ x integers, each between 1 a... | instruction | 0 | 78,293 | 20 | 156,586 |
Tags: dp, interactive
Correct Solution:
```
#!/usr/bin/python3
import math
import sys
MAX = 10004205361450474
QMAX = 10000
LOCAL = False
def inp():
return sys.stdin.readline().rstrip()
ANS = -1
ROUNDS = 0
if LOCAL:
ANS = int(inp())
assert ANS <= MAX
def do_query(values):
global ROUNDS
if ... | output | 1 | 78,293 | 20 | 156,587 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,552 | 20 | 157,104 |
Tags: binary search, greedy, number theory
Correct Solution:
```
s,k=[int(i) for i in input().split()]
a=[-1,0,1,1]
i=3
while a[i]<=pow(10,9):
i+=1
a.append(0)
if i<=k:
for j in range(1,i):
a[i]+=a[j]
else:
for j in range(i-k,i):
a[i]+=a[j]
b=[]
for j in range(i,0... | output | 1 | 78,552 | 20 | 157,105 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,553 | 20 | 157,106 |
Tags: binary search, greedy, number theory
Correct Solution:
```
s,k=map(int,input().split())
f=[0]
f.append(1)
while(True):
cur=sum(f[-k:])
if cur>s:
break
f.append(cur)
f=list(set(f))
f.sort()
ans=[]
i=len(f)-1
while(s and i>0):
if f[i]<=s:
s-=f[i]
ans.append(f[i])
i-=1
pri... | output | 1 | 78,553 | 20 | 157,107 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,554 | 20 | 157,108 |
Tags: binary search, greedy, number theory
Correct Solution:
```
"""
Template written to be used by Python Programmers.
Use at your own risk!!!!
Owned by enraged(rating - 5 star at CodeChef and Specialist at Codeforces).
"""
import sys
from functools import lru_cache, cmp_to_key
from heapq import merge, hea... | output | 1 | 78,554 | 20 | 157,109 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,555 | 20 | 157,110 |
Tags: binary search, greedy, number theory
Correct Solution:
```
s,k=map(int,input().split())
F = [0,1]
b = set()
while True:
f = sum(F[-k:])
if f > s:
break
F.append(f)
for i in reversed(F):
if i <= s:
b.add(i)
s -= i
print(len(b))
print (' '.join(map(str,b)))
``` | output | 1 | 78,555 | 20 | 157,111 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,556 | 20 | 157,112 |
Tags: binary search, greedy, number theory
Correct Solution:
```
from sys import stdin,stdout,setrecursionlimit
from functools import lru_cache, cmp_to_key
from heapq import merge, heapify, heappop, heappush
from math import *
from collections import defaultdict as dd, deque, Counter as C
from itertools import combinat... | output | 1 | 78,556 | 20 | 157,113 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,557 | 20 | 157,114 |
Tags: binary search, greedy, number theory
Correct Solution:
```
s, k = map(int, input().split())
p, t, l = [0], [0, 1, 1], 2
while t[l] < s:
t.append((t[l] << 1) - (0 if l < k else t[l - k]))
l += 1
t.reverse()
for i in t:
if i > s: continue
p.append(i)
s -= i
if s == 0: break
print(len(p))
pri... | output | 1 | 78,557 | 20 | 157,115 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,558 | 20 | 157,116 |
Tags: binary search, greedy, number theory
Correct Solution:
```
import io, os
input = io.BytesIO(os.read(0,os.fstat(0).st_size)).readline
def binarySearch(arr,l,r,val):
while l<=r:
mid=(l+r)//2
if arr[mid]==val:
ans=mid
break
elif arr[mid]<val:
ans=mid
... | output | 1 | 78,558 | 20 | 157,117 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k, n - 1) + F(k, n - 2) + ... + F(k, n - k), for ... | instruction | 0 | 78,559 | 20 | 157,118 |
Tags: binary search, greedy, number theory
Correct Solution:
```
s, k = map(int, input().split())
freq = [1]
while freq[-1] < s:
x = 0
for i in range(max(0, len(freq)-k), len(freq)):
x += freq[i]
freq.append(x)
res = [0]
idx = len(freq) - 1
while s != 0:
while freq[idx] > s:
idx -= 1
res.append(freq[idx])
s -... | output | 1 | 78,559 | 20 | 157,119 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k,... | instruction | 0 | 78,561 | 20 | 157,122 |
Yes | output | 1 | 78,561 | 20 | 157,123 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k,... | instruction | 0 | 78,562 | 20 | 157,124 |
Yes | output | 1 | 78,562 | 20 | 157,125 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k,... | instruction | 0 | 78,565 | 20 | 157,130 |
No | output | 1 | 78,565 | 20 | 157,131 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Numbers k-bonacci (k is integer, k > 1) are a generalization of Fibonacci numbers and are determined as follows:
* F(k, n) = 0, for integer n, 1 ≤ n < k;
* F(k, k) = 1;
* F(k, n) = F(k,... | instruction | 0 | 78,566 | 20 | 157,132 |
No | output | 1 | 78,566 | 20 | 157,133 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,588 | 20 | 157,176 |
Tags: brute force, greedy
Correct Solution:
```
s = input()
i = 0
while i < len(s):
if i < len(s)-2 and s[i] == '1' and s[i+1] == '4' and s[i+2] == '4':
i += 3
elif i < len(s)-1 and s[i] == '1' and s[i+1] == '4':
i += 2
elif s[i] == '1':
i += 1
else:
break
if i == len(s):... | output | 1 | 78,588 | 20 | 157,177 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,589 | 20 | 157,178 |
Tags: brute force, greedy
Correct Solution:
```
n = input()
n = n.replace('144',' ')
n = n.replace('14'," ")
n = n.replace("1",' ')
if set(n) == {" "}:
print("YES")
else:
print("NO")
``` | output | 1 | 78,589 | 20 | 157,179 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,590 | 20 | 157,180 |
Tags: brute force, greedy
Correct Solution:
```
num = input()
judge = True
for i in list(num):
if i != '1' and i != '4':
judge = False
break
if '444' in num or num[0] == '4' or num[0:1] == '44':
judge = False
if judge:
print('YES')
else:
print('NO')
``` | output | 1 | 78,590 | 20 | 157,181 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,591 | 20 | 157,182 |
Tags: brute force, greedy
Correct Solution:
```
s = input()
n = len(s)
i = 0
f = 1
while i < n:
if i == 0 and s[i] != '1':
f = 0
break
if i == 1 and s[i] != '1' and s[i]!= '4':
f = 0
break
if i >= 2:
if s[i] == '1':
i += 1
continue
... | output | 1 | 78,591 | 20 | 157,183 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,592 | 20 | 157,184 |
Tags: brute force, greedy
Correct Solution:
```
s = input()
s = list(s)
i = len(s) - 1
f = 0
while i >= 0:
if len(s) >= 3 and s[i] == '4' and s[i - 1] == '4' and s[i - 2] == '1' :
s.pop(i)
s.pop(i - 1)
s.pop(i - 2)
i = i - 3
elif len(s) >= 2 and s[i] == '4' and s[i - 1] == '1' ... | output | 1 | 78,592 | 20 | 157,185 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,593 | 20 | 157,186 |
Tags: brute force, greedy
Correct Solution:
```
n = input()
c = len(n)
flag = 0
i = 0
while(i<c):
if(i<c-2 and n[i]=='1' and n[i+1]=='4' and n[i+2]=='4'):
i+=3
elif(i<c-1 and n[i]=='1' and n[i+1]=='4'):
i+=2
elif(n[i]=='1'):
i+=1
else:
flag = 1
break
if(flag==0):
print('YES')
else:
print('NO')
``` | output | 1 | 78,593 | 20 | 157,187 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,594 | 20 | 157,188 |
Tags: brute force, greedy
Correct Solution:
```
n = input()
c = 0
if not n[0] == '1':
print('NO')
elif not n.count('1')+n.count('4')==len(n):
print('NO')
else:
for i in range(len(n)):
if n[i]=='4':
if not (n[i-1]=='1' or (n[i-1]=='4' and n[i-2]=='1')):
print('NO')
... | output | 1 | 78,594 | 20 | 157,189 |
Provide tags and a correct Python 3 solution for this coding contest problem.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 514 and 414 are not.
You're given a number. Dete... | instruction | 0 | 78,595 | 20 | 157,190 |
Tags: brute force, greedy
Correct Solution:
```
inpt = str(input())
while inpt != '':
if inpt[:3] == '144': inpt = inpt[3:]
elif inpt[:2] == '14': inpt = inpt[2:]
elif inpt [0] == '1': inpt = inpt[1:]
else:
print('NO')
break
if inpt == '': print ('YES')
``` | output | 1 | 78,595 | 20 | 157,191 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,596 | 20 | 157,192 |
Yes | output | 1 | 78,596 | 20 | 157,193 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,597 | 20 | 157,194 |
Yes | output | 1 | 78,597 | 20 | 157,195 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,598 | 20 | 157,196 |
Yes | output | 1 | 78,598 | 20 | 157,197 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,599 | 20 | 157,198 |
Yes | output | 1 | 78,599 | 20 | 157,199 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,600 | 20 | 157,200 |
No | output | 1 | 78,600 | 20 | 157,201 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,601 | 20 | 157,202 |
No | output | 1 | 78,601 | 20 | 157,203 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,602 | 20 | 157,204 |
No | output | 1 | 78,602 | 20 | 157,205 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
A magic number is a number formed by concatenation of numbers 1, 14 and 144. We can use each of these numbers any number of times. Therefore 14144, 141414 and 1411 are magic numbers but 1444, 51... | instruction | 0 | 78,603 | 20 | 157,206 |
No | output | 1 | 78,603 | 20 | 157,207 |
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