message stringlengths 2 57.2k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 61 108k | cluster float64 22 22 | __index_level_0__ int64 122 217k |
|---|---|---|---|---|---|
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10 | instruction | 0 | 85,744 | 22 | 171,488 |
Tags: math
Correct Solution:
```
q = int(input())
L = [0]*q
R = [0]*q
D = [0]*q
for i in range(q):
entrada = str(input()).split()
L[i] = int(entrada[0])
R[i] = int(entrada[1])
D[i] = int(entrada[2])
def find_x(l,r,d):
result = d
if l <= d <= r:
if r % d == 0:
result = r + d
else:
result = int(r/d)*d + d
return result
for i in range(q):
print( find_x(L[i], R[i], D[i]))
``` | output | 1 | 85,744 | 22 | 171,489 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10 | instruction | 0 | 85,745 | 22 | 171,490 |
Tags: math
Correct Solution:
```
n = int(input())
for _ in range(n):
l,r,d = map(int,input().split())
if d<l:
print(d)
else:
a = r//d
print((a+1)*d)
``` | output | 1 | 85,745 | 22 | 171,491 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10 | instruction | 0 | 85,746 | 22 | 171,492 |
Tags: math
Correct Solution:
```
q=int(input())
for i in range(q):
p=input().split()
l=int(p[0])
r=int(p[1])
d=int(p[2])
if d<l:
print(d)
else:
print(r+d-r%d)
``` | output | 1 | 85,746 | 22 | 171,493 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10 | instruction | 0 | 85,747 | 22 | 171,494 |
Tags: math
Correct Solution:
```
for i in range(int(input())):
l, r, d = map(int, input().split())
if l <= d <= r:
print((r // d + 1)*d)
else:
print(d)
``` | output | 1 | 85,747 | 22 | 171,495 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10 | instruction | 0 | 85,748 | 22 | 171,496 |
Tags: math
Correct Solution:
```
q = int(input())
M = [list(map(int, input().split())) for i in range(q)]
S =[]
#x = 1
l = len(S)
for i in range(q):
x = 1
while True:
if x < M[i][0] or x > M[i][1]:
if x % M[i][2] == 0:
S.append(x)
break
else:
if x < M[i][2]:
x = M[i][2]
else:
x = x+(M[i][2]-x % M[i][2])
else:
if M[i][2] >= M[i][0]:
x = M[i][1]+1
elif M[i][2] < M[i][0]:
x = 2
for i in S:
print(i)
``` | output | 1 | 85,748 | 22 | 171,497 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
import math
import os
import random
import re
import sys
from collections import Counter
a=[]
l=[]
n=int(input())
for i in range(n):
l+=[list(map(int,input().split()))]
for i in range(n):
if l[i][2]<=l[i][1] and l[i][2]>=l[i][0]:
print(l[i][2]*((l[i][1]//l[i][2])+1))
else:
print(l[i][2])
``` | instruction | 0 | 85,749 | 22 | 171,498 |
Yes | output | 1 | 85,749 | 22 | 171,499 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
def func():
q = int(input())
while q:
l , r , d = map(int , input().split())
if d>=l and d<=r:
k = r//d
ans = d*(k+1)
else:
ans = d
print(ans)
q-=1
if __name__ == '__main__':
func()
``` | instruction | 0 | 85,750 | 22 | 171,500 |
Yes | output | 1 | 85,750 | 22 | 171,501 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
import math
sa=lambda :input()
sb=lambda:int(input())
sc=lambda:input().split()
sd=lambda:list(map(int,input().split()))
se=lambda:float(input())
sf=lambda:list(input())
#10101001
def hnbhai():
l,r,d=sd()
temp=d
while(temp>=l and temp<=r):
temp+=d
if temp>=l and temp<=r:
temp=(r//d+1)*d
break
print(temp)
for _ in range(sb()):
hnbhai()
``` | instruction | 0 | 85,751 | 22 | 171,502 |
Yes | output | 1 | 85,751 | 22 | 171,503 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
t = int(input())
for case in range(t):
l, r, d = [int(x) for x in input().split(' ')]
if d < l:
ans = d
else:
ans = d * (r // d + 1)
print(ans)
``` | instruction | 0 | 85,752 | 22 | 171,504 |
Yes | output | 1 | 85,752 | 22 | 171,505 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
from math import ceil
q = int(input())
for i in range(q):
l, r, d = list(map(int, input().split()))
x = (ceil(l / d) - 1) * d
y = (r // d +1)* d
s = min(x,y)
if s == 0:
print(max(x,y))
else:
print(s)
``` | instruction | 0 | 85,753 | 22 | 171,506 |
No | output | 1 | 85,753 | 22 | 171,507 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
for i in range(int(input())):
l, r, d = map(int, input().split())
ans = False
p = 0
while ans == False:
if l >= 1:
l -= 1
r += 1
if r%d == 0:
ans = True
p = r
break
elif l%d == 0:
ans = True
p = l
break
print(p)
``` | instruction | 0 | 85,754 | 22 | 171,508 |
No | output | 1 | 85,754 | 22 | 171,509 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
for _ in range(int(input())):
l,r,d = [int(_) for _ in input().strip().split()]
if d < l:
print(d)
elif d > l:
print(d)
else:
print(r+1 + r+1%d)
``` | instruction | 0 | 85,755 | 22 | 171,510 |
No | output | 1 | 85,755 | 22 | 171,511 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given q queries in the following form:
Given three integers l_i, r_i and d_i, find minimum positive integer x_i such that it is divisible by d_i and it does not belong to the segment [l_i, r_i].
Can you answer all the queries?
Recall that a number x belongs to segment [l, r] if l β€ x β€ r.
Input
The first line contains one integer q (1 β€ q β€ 500) β the number of queries.
Then q lines follow, each containing a query given in the format l_i r_i d_i (1 β€ l_i β€ r_i β€ 10^9, 1 β€ d_i β€ 10^9). l_i, r_i and d_i are integers.
Output
For each query print one integer: the answer to this query.
Example
Input
5
2 4 2
5 10 4
3 10 1
1 2 3
4 6 5
Output
6
4
1
3
10
Submitted Solution:
```
a=int(input())
k=[]
for i in range(a):
b,c,d=list(map(int,input().split()))
o=True
for j in range(1,b):
if j%d==0:
k.append(j)
o=False
break
if (o==True)and(c<=999999999):
for j in range(c+1,1000000001):
if j%d==0:
k.append(j)
break
print(k)
for i in range(len(k)):
print(k[i])
``` | instruction | 0 | 85,756 | 22 | 171,512 |
No | output | 1 | 85,756 | 22 | 171,513 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number of ways to divide an array a of n integers into any number of disjoint non-empty segments so that, in each segment, there exist at most k distinct integers that appear exactly once.
Since the answer can be large, find it modulo 998 244 353.
Input
The first line contains two space-separated integers n and k (1 β€ k β€ n β€ 10^5) β the number of elements in the array a and the restriction from the statement.
The following line contains n space-separated integers a_1, a_2, β¦, a_n (1 β€ a_i β€ n) β elements of the array a.
Output
The first and only line contains the number of ways to divide an array a modulo 998 244 353.
Examples
Input
3 1
1 1 2
Output
3
Input
5 2
1 1 2 1 3
Output
14
Input
5 5
1 2 3 4 5
Output
16
Note
In the first sample, the three possible divisions are as follows.
* [[1], [1], [2]]
* [[1, 1], [2]]
* [[1, 1, 2]]
Division [[1], [1, 2]] is not possible because two distinct integers appear exactly once in the second segment [1, 2].
Submitted Solution:
```
print (16)
``` | instruction | 0 | 85,757 | 22 | 171,514 |
No | output | 1 | 85,757 | 22 | 171,515 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Find the number of ways to divide an array a of n integers into any number of disjoint non-empty segments so that, in each segment, there exist at most k distinct integers that appear exactly once.
Since the answer can be large, find it modulo 998 244 353.
Input
The first line contains two space-separated integers n and k (1 β€ k β€ n β€ 10^5) β the number of elements in the array a and the restriction from the statement.
The following line contains n space-separated integers a_1, a_2, β¦, a_n (1 β€ a_i β€ n) β elements of the array a.
Output
The first and only line contains the number of ways to divide an array a modulo 998 244 353.
Examples
Input
3 1
1 1 2
Output
3
Input
5 2
1 1 2 1 3
Output
14
Input
5 5
1 2 3 4 5
Output
16
Note
In the first sample, the three possible divisions are as follows.
* [[1], [1], [2]]
* [[1, 1], [2]]
* [[1, 1, 2]]
Division [[1], [1, 2]] is not possible because two distinct integers appear exactly once in the second segment [1, 2].
Submitted Solution:
```
print(1)
``` | instruction | 0 | 85,758 | 22 | 171,516 |
No | output | 1 | 85,758 | 22 | 171,517 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Geometric progression with the first element a and common ratio b is a sequence of numbers a, ab, ab2, ab3, ....
You are given n integer geometric progressions. Your task is to find the smallest integer x, that is the element of all the given progressions, or else state that such integer does not exist.
Input
The first line contains integer (1 β€ n β€ 100) β the number of geometric progressions.
Next n lines contain pairs of integers a, b (1 β€ a, b β€ 109), that are the first element and the common ratio of the corresponding geometric progression.
Output
If the intersection of all progressions is empty, then print - 1, otherwise print the remainder of the minimal positive integer number belonging to all progressions modulo 1000000007 (109 + 7).
Examples
Input
2
2 2
4 1
Output
4
Input
2
2 2
3 3
Output
-1
Note
In the second sample test one of the progressions contains only powers of two, the other one contains only powers of three.
Submitted Solution:
```
n = int(input())
l = []
M = (int(1e9) + 7)
for i in range(n):
a, b = list(map(int, input().split()))
cur = a
l.append([])
for j in range(100):
l[-1].append(cur)
cur *= b
for x in l[0]:
for j in range(n):
if not x in l[j]:
break
else:
print(x % M)
exit()
print(-1)
``` | instruction | 0 | 86,118 | 22 | 172,236 |
No | output | 1 | 86,118 | 22 | 172,237 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Geometric progression with the first element a and common ratio b is a sequence of numbers a, ab, ab2, ab3, ....
You are given n integer geometric progressions. Your task is to find the smallest integer x, that is the element of all the given progressions, or else state that such integer does not exist.
Input
The first line contains integer (1 β€ n β€ 100) β the number of geometric progressions.
Next n lines contain pairs of integers a, b (1 β€ a, b β€ 109), that are the first element and the common ratio of the corresponding geometric progression.
Output
If the intersection of all progressions is empty, then print - 1, otherwise print the remainder of the minimal positive integer number belonging to all progressions modulo 1000000007 (109 + 7).
Examples
Input
2
2 2
4 1
Output
4
Input
2
2 2
3 3
Output
-1
Note
In the second sample test one of the progressions contains only powers of two, the other one contains only powers of three.
Submitted Solution:
```
#"""
#https://codeforces.com/problemset/problem/571/E
#"""
def gp(a,b):
l=[]
for i in range(5):
t=a*pow(b,i)
l.append(t)
return l
n=int(input())
s=[]
for i in range(n):
a,b=map(int,input().split())
s.append(gp(a,b))
first=s[0]
second=s[1]
p=[value for value in first if value in second]
if(len(p)>0):
for a in p:
print(a%(10**9+7))
else:
print(-1)
``` | instruction | 0 | 86,119 | 22 | 172,238 |
No | output | 1 | 86,119 | 22 | 172,239 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Geometric progression with the first element a and common ratio b is a sequence of numbers a, ab, ab2, ab3, ....
You are given n integer geometric progressions. Your task is to find the smallest integer x, that is the element of all the given progressions, or else state that such integer does not exist.
Input
The first line contains integer (1 β€ n β€ 100) β the number of geometric progressions.
Next n lines contain pairs of integers a, b (1 β€ a, b β€ 109), that are the first element and the common ratio of the corresponding geometric progression.
Output
If the intersection of all progressions is empty, then print - 1, otherwise print the remainder of the minimal positive integer number belonging to all progressions modulo 1000000007 (109 + 7).
Examples
Input
2
2 2
4 1
Output
4
Input
2
2 2
3 3
Output
-1
Note
In the second sample test one of the progressions contains only powers of two, the other one contains only powers of three.
Submitted Solution:
```
"""
https://codeforces.com/problemset/problem/571/E
"""
def gp(a,b):
l=[]
for i in range(5):
t=a*pow(b,i)
l.append(t)
return l
n=int(input())
s=[]
for i in range(n):
a,b=map(int,input().split())
s.append(gp(a,b))
first=s[0]
second=s[1]
p=[value for value in first if value in second]
if(len(p)>0):
for a in p:
print(a%(10**9+7))
else:
print(-1)
``` | instruction | 0 | 86,120 | 22 | 172,240 |
No | output | 1 | 86,120 | 22 | 172,241 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Geometric progression with the first element a and common ratio b is a sequence of numbers a, ab, ab2, ab3, ....
You are given n integer geometric progressions. Your task is to find the smallest integer x, that is the element of all the given progressions, or else state that such integer does not exist.
Input
The first line contains integer (1 β€ n β€ 100) β the number of geometric progressions.
Next n lines contain pairs of integers a, b (1 β€ a, b β€ 109), that are the first element and the common ratio of the corresponding geometric progression.
Output
If the intersection of all progressions is empty, then print - 1, otherwise print the remainder of the minimal positive integer number belonging to all progressions modulo 1000000007 (109 + 7).
Examples
Input
2
2 2
4 1
Output
4
Input
2
2 2
3 3
Output
-1
Note
In the second sample test one of the progressions contains only powers of two, the other one contains only powers of three.
Submitted Solution:
```
def gp(a,b):
l=[]
for i in range(5):
t=a*pow(b,i)
l.append(t)
return l
n=int(input())
s=[]
for i in range(n):
a,b=map(int,input().split())
s.append(gp(a,b))
first=s[0]
second=s[1]
p=[value for value in first if value in second]
if(len(p)>0):
for a in p:
print(a%(10**9+7))
else:
print(-1)
``` | instruction | 0 | 86,121 | 22 | 172,242 |
No | output | 1 | 86,121 | 22 | 172,243 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Having learned the multiplication table, Takahashi can multiply two integers between 1 and 9 (inclusive) together. He cannot do any other calculation.
Given are two integers A and B.
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1` instead.
Constraints
* 1 \leq A \leq 20
* 1 \leq B \leq 20
* All values in input are integers.
Input
Input is given from Standard Input in the following format:
A B
Output
If Takahashi can calculate A \times B, print the result; if he cannot, print `-1`.
Examples
Input
2 5
Output
10
Input
5 10
Output
-1
Input
9 9
Output
81
Submitted Solution:
```
import bisect,collections,copy,heapq,itertools,math,string
import numpy as np
import sys
sys.setrecursionlimit(10**7)
def _S(): return sys.stdin.readline().rstrip()
def I(): return int(sys.stdin.readline().rstrip())
def LI(): return list(map(int,sys.stdin.readline().rstrip().split()))
def LS(): return list(sys.stdin.readline().rstrip().split())
# ζηθ·ι’
# η΄ ε ζ°ε解
N = I()
def make_divisors(n):
divisors = []
for i in range(1, int(n**0.5)+1):
if n % i == 0:
divisors.append(i)
if i != n // i:
divisors.append(n//i)
divisors.sort()
return divisors
# c = sympy.divisors(N)
c = make_divisors(N)
lenc = len(c)
if (lenc % 2)==0:
a = c[lenc // 2 - 1]
b = c[lenc // 2]
else:
a = c[lenc // 2]
b = a
print(a + b -2)
#H,N = LI()
#AB = [LI() for _ in range(N)]
#A,B = zip(*AB)
#Ap = np.array(A)
#C = np.zeros(N + 1)
# if ans:
# print('Yes')
# else:
# print('No')
``` | instruction | 0 | 86,342 | 22 | 172,684 |
No | output | 1 | 86,342 | 22 | 172,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,839 | 22 | 173,678 |
Tags: greedy, math
Correct Solution:
```
import sys
t = int(input())
for _t in range(t):
n = int(sys.stdin.readline())
if n <= 3:
print(n - 1)
else:
print(3 if n % 2 else 2)
``` | output | 1 | 86,839 | 22 | 173,679 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,840 | 22 | 173,680 |
Tags: greedy, math
Correct Solution:
```
for t in range(int(input())):
n=int(input())
if n==1:
print(0)
if n==2:
print(1)
if n==3:
print(2)
if n>3:
if n%2!=0:
print(3)
else:
print(2)
``` | output | 1 | 86,840 | 22 | 173,681 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,841 | 22 | 173,682 |
Tags: greedy, math
Correct Solution:
```
t = int(input())
for _ in range(t):
n = int(input())
if n==1:
print(0)
elif n == 2:
print(1)
elif n == 3:
print(2)
elif n%2:
print(3)
else:
print(2)
``` | output | 1 | 86,841 | 22 | 173,683 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,842 | 22 | 173,684 |
Tags: greedy, math
Correct Solution:
```
import math
import sys
from collections import defaultdict
from functools import lru_cache
t = int(input())
for _ in range(t):
n = int(input())
if n % 2 == 0:
if n == 2:
print(1)
else:
print(2)
else:
if n == 1:
print(0)
else:
if n == 3:
print(2)
else:
print(3)
``` | output | 1 | 86,842 | 22 | 173,685 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,843 | 22 | 173,686 |
Tags: greedy, math
Correct Solution:
```
import sys
input=sys.stdin.readline
t=int(input())
for i in range(t):
n=int(input())
if n==1:
print(0)
elif n%2==0:
if n==2:
print(1)
else:
print(2)
elif n%2==1:
if n==3:
print(2)
else:
print(3)
``` | output | 1 | 86,843 | 22 | 173,687 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,844 | 22 | 173,688 |
Tags: greedy, math
Correct Solution:
```
for t in range(int(input())):
n=int(input())
if n == 1:
print(0)
elif n == 2:
print(1)
elif n == 3:
print(2)
elif n % 2 == 0:
print(2)
else:
print(3)
``` | output | 1 | 86,844 | 22 | 173,689 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,845 | 22 | 173,690 |
Tags: greedy, math
Correct Solution:
```
for __ in range(int(input())):
n = int(input())
if n == 1:
print(0)
elif n == 2:
print(1)
elif n % 2 == 0 or n == 3:
print(2)
else:
print(3)
``` | output | 1 | 86,845 | 22 | 173,691 |
Provide tags and a correct Python 3 solution for this coding contest problem.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1 | instruction | 0 | 86,846 | 22 | 173,692 |
Tags: greedy, math
Correct Solution:
```
try:
t=int(input())
for i in range(t):
n=int(input())
if(n==1):
print("0")
elif(n==2):
print("1")
elif(n%2==0 or n==3):
print("2")
else:
print("3")
except:
pass
``` | output | 1 | 86,846 | 22 | 173,693 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
from fractions import Fraction
import bisect
import os
import io
from collections import Counter
import bisect
from collections import defaultdict
import math
import random
import heapq
from math import sqrt
import sys
from functools import reduce, cmp_to_key
from collections import deque
import threading
from itertools import combinations
from io import BytesIO, IOBase
from itertools import accumulate
from queue import Queue
# sys.setrecursionlimit(200000)
# input = io.BytesIO(os.read(0, os.fstat(0).st_size)).readline
def input():
return sys.stdin.readline().strip()
def iinput():
return int(input())
def tinput():
return input().split()
def rinput():
return map(int, tinput())
def rlinput():
return list(rinput())
mod = int(1e9)+7
def factors(n):
return set(reduce(list.__add__,
([i, n//i] for i in range(1, int(n**0.5) + 1) if n % i == 0)))
# ----------------------------------------------------
# sys.stdin = open('input.txt', 'r')
# sys.stdout = open('output.txt', 'w')
# ----------------------------------------------------------------
t = iinput()
# t = 1
for _ in range(t):
n = iinput()
if n == 1:
print(0)
elif n == 2:
print(1)
elif n == 3:
print(2)
else:
print(3 if n%2 else 2)
``` | instruction | 0 | 86,847 | 22 | 173,694 |
Yes | output | 1 | 86,847 | 22 | 173,695 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
t = int(input())
for i in range(t):
n = int(input())
print(min(n-1,2+n%2))
``` | instruction | 0 | 86,848 | 22 | 173,696 |
Yes | output | 1 | 86,848 | 22 | 173,697 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
import sys
try:sys.stdin,sys.stdout=open('in.txt','r'),open('out.txt','w')
except:pass
ii1=lambda:int(sys.stdin.readline().strip()) # for interger
is1=lambda:sys.stdin.readline().strip() # for str
iia=lambda:list(map(int,sys.stdin.readline().strip().split())) # for List[int]
isa=lambda:sys.stdin.readline().strip().split() # for List[str]
mod=int(1e9 + 7);from collections import *;from math import *
###################### Start Here ######################
for _ in range(ii1()):
n = ii1()
if n==1:print(0)
elif n==2:print(1)
elif n==3:print(2)
else:
if n%2==0:
print(2)
else:
print(3)
``` | instruction | 0 | 86,849 | 22 | 173,698 |
Yes | output | 1 | 86,849 | 22 | 173,699 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
t=int(input())
def f(n):
i = 2
while i*i<=n:
if n%i==0: return i
i+=1
return 0
for _ in range(t):
n = int(input())
if n==1: print(0)
elif n==2: print(1)
elif n%2==0: print(2)
elif n==3:print(2)
else: print(3)
'''
t=int(input())
map(int,input().split())
list(map(int,input().split()))
for _ in range(t):
'''
``` | instruction | 0 | 86,850 | 22 | 173,700 |
Yes | output | 1 | 86,850 | 22 | 173,701 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
l=lambda:map(int,input().split())
p=lambda:int(input())
ss=lambda:input()
for _ in range(p()):
n=p()
c=0
while n>1:
i=2
m=-1
while i*i<=n:
if n%i==0:
m=max(i,m,n//i)
i+=1
if m ==-1:
n-=1
else:
n=n//m
c+=1
print(c)
``` | instruction | 0 | 86,851 | 22 | 173,702 |
No | output | 1 | 86,851 | 22 | 173,703 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
print((s-1!=0)+(s%((s-1)/2)!=1)+(s%((s-1)/2)-1) for s in[*open(0)][1:])
``` | instruction | 0 | 86,852 | 22 | 173,704 |
No | output | 1 | 86,852 | 22 | 173,705 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
t = int(input())
n = [int(input()) for p in range(t)]
for g in range(t):
k = int(n[g])
ans = 0
while True:
k -= 1
#print(k)
if k == 1:
n[g] -= 1
k = n[g]
ans += 1
#print(n[g], 'ggg')
if n[g] == 1:
print(ans)
break
"""if n[g] == 1:
ans = 0
print(ans)
break
elif n[g] == 2:
ans = 1
print(ans)
break"""
if n[g] % k == 0:
ans += 1
n[g] = int(n[g] / k)
k = n[g]
#print(k, 'hhh')
if n == 1:
print(ans)
break
``` | instruction | 0 | 86,853 | 22 | 173,706 |
No | output | 1 | 86,853 | 22 | 173,707 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Ridbit starts with an integer n.
In one move, he can perform one of the following operations:
* divide n by one of its proper divisors, or
* subtract 1 from n if n is greater than 1.
A proper divisor is a divisor of a number, excluding itself. For example, 1, 2, 4, 5, and 10 are proper divisors of 20, but 20 itself is not.
What is the minimum number of moves Ridbit is required to make to reduce n to 1?
Input
The first line contains a single integer t (1 β€ t β€ 1000) β the number of test cases.
The only line of each test case contains a single integer n (1 β€ n β€ 10^9).
Output
For each test case, output the minimum number of moves required to reduce n to 1.
Example
Input
6
1
2
3
4
6
9
Output
0
1
2
2
2
3
Note
For the test cases in the example, n may be reduced to 1 using the following operations in sequence
1
2 \xrightarrow{} 1
3 \xrightarrow{} 2 \xrightarrow{} 1
4 \xrightarrow{} 2 \xrightarrow{} 1
6 \xrightarrow{} 2 \xrightarrow{} 1
9 \xrightarrow{} 3 \xrightarrow{} 2\xrightarrow{} 1
Submitted Solution:
```
def smallestDivisor(n):
if (n % 2 == 0):
return 2
i = 3
while(i * i <= n):
if (n % i == 0):
return i
i += 2
return n
for i in range(int(input())):
n=int(input())
if smallestDivisor(n)==n:
print(n-1)
else:
print(smallestDivisor(n))
``` | instruction | 0 | 86,854 | 22 | 173,708 |
No | output | 1 | 86,854 | 22 | 173,709 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,855 | 22 | 173,710 |
Tags: math, number theory
Correct Solution:
```
tests = int(input())
import math
def solve(n):
while(n%2 == 0):
n = n//2
if(n == 1):
return "NO"
else:
return "YES"
for t in range(tests):
n = int(input())
if n%2 != 0:
print("YES")
else:
print(solve(n))
``` | output | 1 | 86,855 | 22 | 173,711 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,856 | 22 | 173,712 |
Tags: math, number theory
Correct Solution:
```
def solve():
n=int(input())
if n&1:
print("YES")
else:
from math import log2
k=log2(n)
if k==int(k):
print("NO")
else:
print("YES")
for _ in range(int(input())):
solve()
``` | output | 1 | 86,856 | 22 | 173,713 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,857 | 22 | 173,714 |
Tags: math, number theory
Correct Solution:
```
def num(n):
while n%2==0:
n=int(n/2)
if n>1:
return "YES"
else:
return "NO"
for _ in range(int(input())):
n = int(input())
print(num(n))
``` | output | 1 | 86,857 | 22 | 173,715 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,858 | 22 | 173,716 |
Tags: math, number theory
Correct Solution:
```
a = int(input())
for i in range(a):
liczba = int(input())
if liczba == 2 or liczba == 1:
print("NO")
elif liczba % 2 != 0:
print("YES")
else:
while True:
liczba = liczba/2
if liczba == 1:
print("NO")
break
if liczba % 2 != 0:
print("YES")
break
``` | output | 1 | 86,858 | 22 | 173,717 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,859 | 22 | 173,718 |
Tags: math, number theory
Correct Solution:
```
def func(n):
if (n==1):
return "NO"
if (n%2!=0):
return "YES"
return func(n//2)
t = int(input())
for _ in range(t):
n = int(input())
print(func(n))
``` | output | 1 | 86,859 | 22 | 173,719 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,860 | 22 | 173,720 |
Tags: math, number theory
Correct Solution:
```
test_cases = 1
test_cases = int(input())
for ttttt in range(test_cases):
n = int(input())
while n%2==0:
n/=2
if n==1:
print("NO")
else:
print("YES")
``` | output | 1 | 86,860 | 22 | 173,721 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,861 | 22 | 173,722 |
Tags: math, number theory
Correct Solution:
```
for i in range(int(input())):
a=int(input())
b=bin(a)
b=list(b)
l=b.count('1')
if l==1 and b[2]=="1":
print("NO")
else:
print("YES")
``` | output | 1 | 86,861 | 22 | 173,723 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO | instruction | 0 | 86,862 | 22 | 173,724 |
Tags: math, number theory
Correct Solution:
```
import math
def Log2(x):
if x == 0:
return False
return (math.log10(x) /
math.log10(2))
def isPowerOfTwo(n):
return (math.ceil(Log2(n)) ==
math.floor(Log2(n)))
t = int(input())
out = []
for x in range(t):
n = int(input())
if isPowerOfTwo(n):
out.append("NO")
else:
out.append("YES")
for x in range(t):
print(out[x])
``` | output | 1 | 86,862 | 22 | 173,725 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
import os
import sys
from io import BytesIO, IOBase
from collections import Counter
from collections import OrderedDict
from collections import defaultdict
import bisect
import math
from sys import setrecursionlimit
def read():
sys.stdin = open('input.txt', 'r')
sys.stdout = open('output.txt', 'w')
abc = 'abcdefghijklmnopqrstuvwxyz'
abd = {'a': 0, 'b': 1, 'c': 2, 'd': 3, 'e': 4, 'f': 5, 'g': 6, 'h': 7, 'i': 8, 'j': 9, 'k': 10, 'l': 11, 'm': 12,
'n': 13, 'o': 14, 'p': 15, 'q': 16, 'r': 17, 's': 18, 't': 19, 'u': 20, 'v': 21, 'w': 22, 'x': 23, 'y': 24, 'z': 25}
mod = 1000000007
def gcd(a, b):
if a == 0:
return b
return gcd(b % a, a)
def fre_count(mylist):
return Counter(mylist)
def lcm(a, b):
return (a / gcd(a, b)) * b
def main():
#read()
# setrecursionlimit(10**6)
t = int(input())
for _ in range(t):
n = int(input())
x=n
# l,r=map(int,input().split())
#arr = [int(x) for x in input().split()]
# arr=[int(x) for x in input()]
# grid=[[int(x) for x in input().split()] for x in range(n)]
# arr=list(input())
while n%2 == 0:
n=n//2
#print(n)
if n == 1:
print("NO")
else:
print("YES")
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
def input(): return sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | instruction | 0 | 86,863 | 22 | 173,726 |
Yes | output | 1 | 86,863 | 22 | 173,727 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
import sys
input = sys.stdin.readline
############ ---- Input Functions ---- ############
def inp():
return (int(input()))
def inlt():
return (list(map(int, input().split())))
def insr():
s = input()
return (list(s[:len(s) - 1]))
def invr():
return (map(int, input().split()))
###################################################
def solve(n):
if bin(n).count('1') == 1:
return 'NO'
else:
return 'YES'
for _ in range(inp()):
n = inp()
print(solve(n))
``` | instruction | 0 | 86,864 | 22 | 173,728 |
Yes | output | 1 | 86,864 | 22 | 173,729 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
for i in range (int(input())):
n=bin(int(input()))
print("YES" if n.count("1")!=1 else "NO")
``` | instruction | 0 | 86,865 | 22 | 173,730 |
Yes | output | 1 | 86,865 | 22 | 173,731 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
l = [1, 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024, 2048, 4096, 8192, 16384, 32768, 65536, 131072, 262144, 524288, 1048576, 2097152, 4194304, 8388608, 16777216, 33554432, 67108864, 134217728, 268435456, 536870912, 1073741824, 2147483648, 4294967296, 8589934592, 17179869184, 34359738368, 68719476736, 137438953472, 274877906944, 549755813888, 1099511627776, 2199023255552, 4398046511104, 8796093022208, 17592186044416, 35184372088832, 70368744177664, 140737488355328, 281474976710656, 562949953421312]
def fun(n):
if n in l:
return "NO"
return "YES"
for _ in range(int(input())):
n = int(input())
print(fun(n))
``` | instruction | 0 | 86,866 | 22 | 173,732 |
Yes | output | 1 | 86,866 | 22 | 173,733 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
def odd_divisor(n):
if n == 0:
return False
while n != 1:
if n % 2 != 0:
return False
n = n // 2
return True
t = int(input())
while t > 0:
n = int(input())
if odd_divisor(n):
print("YES")
else:
print("NO")
t -= 1
``` | instruction | 0 | 86,867 | 22 | 173,734 |
No | output | 1 | 86,867 | 22 | 173,735 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given an integer n. Check if n has an odd divisor, greater than one (does there exist such a number x (x > 1) that n is divisible by x and x is odd).
For example, if n=6, then there is x=3. If n=4, then such a number does not exist.
Input
The first line contains one integer t (1 β€ t β€ 10^4) β the number of test cases. Then t test cases follow.
Each test case contains one integer n (2 β€ n β€ 10^{14}).
Please note, that the input for some test cases won't fit into 32-bit integer type, so you should use at least 64-bit integer type in your programming language.
Output
For each test case, output on a separate line:
* "YES" if n has an odd divisor, greater than one;
* "NO" otherwise.
You can output "YES" and "NO" in any case (for example, the strings yEs, yes, Yes and YES will be recognized as positive).
Example
Input
6
2
3
4
5
998244353
1099511627776
Output
NO
YES
NO
YES
YES
NO
Submitted Solution:
```
for _ in range (int(input())):
n=int(input())
while n%2==0 :
if (n==1):
print("YES")
break
else:
print("NO")
break
``` | instruction | 0 | 86,868 | 22 | 173,736 |
No | output | 1 | 86,868 | 22 | 173,737 |
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