message stringlengths 2 44.5k | message_type stringclasses 2 values | message_id int64 0 1 | conversation_id int64 276 109k | cluster float64 23 23 | __index_level_0__ int64 552 217k |
|---|---|---|---|---|---|
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid of lattice points from (0, 0) to (n, m) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyline should be as long as possible.
A polyline defined by points p1, p2, p3, p4 consists of the line segments p1 p2, p2 p3, p3 p4, and its length is the sum of the lengths of the individual line segments.
Input
The only line of the input contains two integers n and m (0 ≤ n, m ≤ 1000). It is guaranteed that grid contains at least 4 different points.
Output
Print 4 lines with two integers per line separated by space — coordinates of points p1, p2, p3, p4 in order which represent the longest possible polyline.
Judge program compares your answer and jury's answer with 10 - 6 precision.
Examples
Input
1 1
Output
1 1
0 0
1 0
0 1
Input
0 10
Output
0 1
0 10
0 0
0 9
Submitted Solution:
```
def main():
n, m = [int(x) for x in input().split()]
if n == 0:
print(0, 1)
print(0, m)
print(0, 0)
print(0, m-1)
elif m == 0:
print(1, 0)
print(n, 0)
print(0, 0)
print(n-1, 0)
else:
print(0, 0)
print(n, m)
if n < m: # take longest route
print(n, 0)
print(0, m)
else:
print(0, m)
print(n, 0)
main()
``` | instruction | 0 | 21,567 | 23 | 43,134 |
No | output | 1 | 21,567 | 23 | 43,135 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid of lattice points from (0, 0) to (n, m) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyline should be as long as possible.
A polyline defined by points p1, p2, p3, p4 consists of the line segments p1 p2, p2 p3, p3 p4, and its length is the sum of the lengths of the individual line segments.
Input
The only line of the input contains two integers n and m (0 ≤ n, m ≤ 1000). It is guaranteed that grid contains at least 4 different points.
Output
Print 4 lines with two integers per line separated by space — coordinates of points p1, p2, p3, p4 in order which represent the longest possible polyline.
Judge program compares your answer and jury's answer with 10 - 6 precision.
Examples
Input
1 1
Output
1 1
0 0
1 0
0 1
Input
0 10
Output
0 1
0 10
0 0
0 9
Submitted Solution:
```
def dist(v):
ans = 0
for i in range(3):
ans += (v[i][0] - v[i + 1][0]) ** 2 + (v[i][1] - v[i + 1][1]) ** 2
return ans
n, m = map(int, input().split())
best = 0
if n == 0:
print(0, 1)
print(0, m)
print(0, 0)
print(0, m - 1)
elif m == 0:
print(1, 0)
print(n, 0)
print(0, 0)
print(n - 1, 0)
else:
v = [[(0, 0), (n, m), (0, m), (n, 0)],
[(0, 0), (n, m), (n, 0), (0, m)],
[(0, 0), (n, m), (0, 1), (n, m - 1)],
[(0, 0), (n, m), (1, 0), (n - 1, m)],
[(0, 0), (n, m), (0, 1), (n - 1, m)],
[(0, 0), (n, m), (1, 0), (n, m - 1)],
[(0, 0), (n, m - 1), (0, 1), (n, m - 1)],
[(0, 0), (n - 1, m), (1, 0), (n, m)],
[(0, 0), (n - 1, m), (0, 1), (n, m)],
[(0, 0), (n, m - 1), (1, 0), (n, m)]]
for i in range(len(v)):
now = dist(v[i])
if now > best:
best = now
ans = i
for i in range(4):
print(v[ans][i][0], v[ans][i][1])
``` | instruction | 0 | 21,568 | 23 | 43,136 |
No | output | 1 | 21,568 | 23 | 43,137 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a rectangular grid of lattice points from (0, 0) to (n, m) inclusive. You have to choose exactly 4 different points to build a polyline possibly with self-intersections and self-touching. This polyline should be as long as possible.
A polyline defined by points p1, p2, p3, p4 consists of the line segments p1 p2, p2 p3, p3 p4, and its length is the sum of the lengths of the individual line segments.
Input
The only line of the input contains two integers n and m (0 ≤ n, m ≤ 1000). It is guaranteed that grid contains at least 4 different points.
Output
Print 4 lines with two integers per line separated by space — coordinates of points p1, p2, p3, p4 in order which represent the longest possible polyline.
Judge program compares your answer and jury's answer with 10 - 6 precision.
Examples
Input
1 1
Output
1 1
0 0
1 0
0 1
Input
0 10
Output
0 1
0 10
0 0
0 9
Submitted Solution:
```
import math
n, m = map(int, input().split())
if n == 0 :
print(0, 1)
print(0, m)
print(0, 0)
print(0, m - 1)
elif m == 0 :
print(1, 0)
print(n, 0)
print(0, 0)
print(n - 1, 0)
else :
l = math.sqrt((n - 1) ** 2 + m ** 2) + math.sqrt(n ** 2 + m ** 2) + math.sqrt(n ** 2 + (m - 1) ** 2)
l1 = max(m, n) + math.sqrt(n * n + m * m) * 2
if l > l1 :
print(1, 0)
print(n, m)
print(0, 0)
print(n, m - 1)
else :
if n > m :
print(n, m)
print(0, 0)
print(n, 0)
print(0, m)
else :
print(n, m)
print(0, 0)
print(0, m)
print(n, 0)
``` | instruction | 0 | 21,569 | 23 | 43,138 |
No | output | 1 | 21,569 | 23 | 43,139 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,639 | 23 | 43,278 |
"Correct Solution:
```
def check_cell(i, j, n):
k = 0
if i > 1 and field[i-1][j]: k += 1
if i < n-1 and field[i+1][j]: k += 1
if j > 1 and field[i][j-1]: k += 1
if j < n-1 and field[i][j+1]: k += 1
if k < 2:
return 0
elif k < 4:
return k-1
else:
return 4
n = int(input())
field = []
for i in range(n):
temp = [int(x) for x in input()]
field.append(temp)
def main():
for i in range(n):
for j in range(n):
if field[i][j] and not field[i][j] == check_cell(i, j, n):
print('No')
return 0
print('Yes')
main()
``` | output | 1 | 21,639 | 23 | 43,279 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,640 | 23 | 43,280 |
"Correct Solution:
```
from sys import stdin
n = int(stdin.readline())
nn = [[int(x) for x in stdin.readline().rstrip()] for i in range(n)]
def run():
for row in range(n):
for col in range(n):
if(nn[row][col] == 0):
continue
if(countAdj(row, col, n-1)):
print('No')
return 0
print('Yes')
def countAdj(row, col, n):
cnt = 0
adj = 0
if(row > 1 and nn[row-1][col]):
cnt += 1
adj += nn[row-1][col]
if(row < n and nn[row+1][col]):
cnt += 1
adj += nn[row+1][col]
if(col > 1 and nn[row][col-1]):
cnt += 1
adj += nn[row][col-1]
if(col < n and nn[row][col+1]):
cnt += 1
adj += nn[row][col+1]
if(cnt <= 1):
return True
elif(cnt < 4 and nn[row][col] == cnt-1):
if(nn[row][col] == 1 and adj != 4):
return True
if(nn[row][col] == 2 and not (6 <= adj <= 8)):
return True
return False
elif(cnt == 4 and nn[row][col] == cnt):
if(nn[row][col] == 4 and not (adj == 8 or adj == 10 or adj == 12 or adj == 14 or adj == 16)):
return True
return False
return True
run()
``` | output | 1 | 21,640 | 23 | 43,281 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,641 | 23 | 43,282 |
"Correct Solution:
```
n = int(input())
s = [list(map(int, input())) for _ in range(n)]
INF = 10 ** 9
x1, x2, y1, y2 = INF, -INF, INF, -INF
for i in range(n):
for j in range(n):
if s[i][j] != 0:
x1, x2, y1, y2 = min(x1, i), max(x2, i), min(y1, j), max(y2, j)
need = [[0] * n for _ in range(n)]
for i in range(x1, x2 + 1):
for j in range(y1, y2 + 1):
if i == x1 or i == x2:
if j == y1 or j == y2:
need[i][j] = 1
else:
need[i][j] = 2
elif j == y1 or j == y2:
need[i][j] = 2
else:
need[i][j] = 4
print("Yes" if need == s else "No")
``` | output | 1 | 21,641 | 23 | 43,283 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,642 | 23 | 43,284 |
"Correct Solution:
```
n = int(input())
aux = []
grid = []
flag = True
ans = -1
um = 0
dois = 0
quatro = 0
while(n):
n-=1
x = str(int(input()))
if(x!='0'):
aux.append(x)
for i in aux:
txt = ''
for j in i:
if(j!='0'):
txt+=j
grid.append(txt)
for i in grid:
for j in i:
if(j == '1'):
um+=1
if(j == '2'):
dois+=1
if(j == '4'):
quatro+=1
if(ans==-1 or len(i)==ans):
ans = len(i)
else:
flag = False
if(um!=4 or dois!=len(grid)*2+len(grid[0])*2-8 or quatro!=(len(grid)*len(grid[0]))-(len(grid)*2+len(grid[0])*2-4)):
flag = False
if(flag):
for i in range(0, len(grid)):
if(len(grid)-i-1 < i):
break
if(grid[i] != grid[len(grid)-i-1]):
flag = False
for i in range(0, len(grid)):
for j in range(0, len(grid[0])):
if(len(grid)-j-1 < j):
break
if(grid[i][j] != grid[i][len(grid[i])-j-1]):
flag = False
if(flag and ans!=-1):
print('Yes')
else:
print('No')
# 1523803863385
``` | output | 1 | 21,642 | 23 | 43,285 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,643 | 23 | 43,286 |
"Correct Solution:
```
n = int(input())
A = [input() for i in range(n)]
def early_exit():
print("No")
exit()
if n < 3:
early_exit()
# first find the corner
corner_row = []
for i in range(n):
if '1' in A[i]:
corner_row.append(i)
if len(corner_row) != 2:
early_exit()
# now for each of the corner row, find the corresponding column
# check everything before the first index
def check_zero(x):
for i in x:
if i != '0':
return False
return True
for i in range(corner_row[0]):
if not check_zero(A[i]):
early_exit()
for i in range(corner_row[1]+1, n):
if not check_zero(A[i]):
early_exit()
#find first non-zero for the two corner row
for j in range(n):
if A[corner_row[0]][j] != '0':
left_corner = j
break
for j in range(n-1,-1,-1):
if A[corner_row[0]][j] != '0':
right_corner = j
break
if A[corner_row[0]][left_corner] != '1' or A[corner_row[0]][right_corner] != '1' or left_corner == right_corner:
early_exit()
for j in range(n):
if A[corner_row[1]][j] != '0':
left2_corner = j
break
for j in range(n-1,-1,-1):
if A[corner_row[1]][j] != '0':
right2_corner = j
break
if A[corner_row[1]][left2_corner] != '1' or A[corner_row[1]][right2_corner] != '1' or left_corner != left2_corner or right_corner != right2_corner:
early_exit()
# by now we have find the row interval to check
# check the first and last row
for i in corner_row:
for j in range(left_corner+1, right_corner):
if A[i][j] != '2':
early_exit()
# check zero blocks in between
for i in range(corner_row[0]+1, corner_row[1]):
if not check_zero(A[i][:left_corner]):
early_exit()
if not check_zero(A[i][right_corner+1:]):
early_exit()
if A[i][left_corner] != '2' or A[i][right_corner] != '2':
early_exit()
for j in range(left_corner+1, right_corner):
if A[i][j] != '4':
early_exit()
print("Yes")
``` | output | 1 | 21,643 | 23 | 43,287 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,644 | 23 | 43,288 |
"Correct Solution:
```
def main():
size = int(input())
sq = [[int(c) for c in input().strip()] for _ in range(size)]
print('Yes' if haslair(sq) else 'No')
def haslair(sq):
corners = [(r, c) for r, row in enumerate(sq) for c, count in enumerate(row)
if count==1]
if len(corners) != 4:
return False
left, right, top, bottom = corners[0][1], corners[3][1], corners[0][0], corners[3][0]
if right == left + 1 or bottom == top + 1:
return False
for r, row in enumerate(sq):
for c, count in enumerate(row):
score = 3 if top < r < bottom else 1 if r in (top, bottom) else 0
score += 3 if left < c < right else 1 if c in (left, right) else 0
if count != (0, 0, 1, 0, 2, None, 4)[score]:
return False
return True
main()
``` | output | 1 | 21,644 | 23 | 43,289 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,645 | 23 | 43,290 |
"Correct Solution:
```
import sys, math
def bfs(x, y):
Q=[[x,y]]
ptr = 0
min_=[1000,1000]
max_=[0,0]
while ptr < len(Q):
v = Q[ptr]
ptr+=1
x = v[0]; y=v[1]
if matrix[x][y] == 4:
used[x][y] = 1
if x+1 < n:
if used[x+1][y]==0:
Q.append([x+1,y])
used[x+1][y]=1
if x-1 > -1:
if used[x-1][y]==0:
Q.append([x-1,y])
used[x-1][y]=1
if y+1 < n:
if used[x][y+1]==0:
Q.append([x,y+1])
used[x][y+1]=1
if y-1 > -1:
if used[x][y-1]==0:
Q.append([x,y-1])
used[x][y-1]=1
if x < min_[0] or (x==min_[0] and y < min_[1]):
min_=[x,y]
if x > max_[0] or (x==max_[0] and y > max_[1]):
max_=[x,y]
else:
used[x][y]=0
for i in range(min_[0], max_[0]+1):
for j in range(min_[1], max_[1]+1):
if matrix[i][j] != 4:
print('No')
sys.exit(0)
for i in range(n):
for j in range(n):
if used[i][j] == 0 and matrix[i][j] >= 3:
print('No')
sys.exit(0)
#print('h')
if min_[0] > 0:
w = min_[0] - 1
for j in range(min_[1], max_[1]+1):
used[w][j] = 1
if matrix[w][j] != 2:
print('No')
sys.exit(0)
#print('h')
if max_[0] < n-1:
w = max_[0] + 1
for j in range(min_[1], max_[1]+1):
used[w][j] = 1
if matrix[w][j] != 2:
print('No')
sys.exit(0)
if min_[1] > 0:
w = min_[1] - 1
for j in range(min_[0], max_[0]+1):
used[j][w] = 1
if matrix[j][w] != 2:
print('No')
sys.exit(0)
#print('h')
if max_[1] < n-1:
w = max_[1] + 1
for j in range(min_[0], max_[0]+1):
used[j][w] = 1
if matrix[j][w] != 2:
print('No')
sys.exit(0)
if min_[0] > 0 and min_[1] > 0:
x=min_[0]-1
y=min_[1]-1
if matrix[x][y]!=1:
print('No')
sys.exit(0)
used[x][y] =1
if max_[0] < n-1 and max_[1] < n-1:
x=max_[0]+1
y=max_[1]+1
if matrix[x][y]!=1:
print('No')
sys.exit(0)
used[x][y] =1
if min_[0] > 0 and max_[1] < n-1:
x=min_[0]-1
y=max_[1]+1
if matrix[x][y]!=1:
print('No')
sys.exit(0)
used[x][y] =1
if max_[0] < n-1 and min_[1] > 0:
x=max_[0]+1
y=min_[1]-1
if matrix[x][y]!=1:
print('No')
sys.exit(0)
used[x][y] =1
for i in range(n):
for j in range(n):
if used[i][j]==1:
continue
elif matrix[i][j] != 0:
print('No')
sys.exit(0)
print('Yes')
n=int(input())
matrix = [[0]*n for i in range(n)]
for i in range(n):
z=input()
for j in range(n):
matrix[i][j]=int(z[j])
used = [[0]*n for i in range(n)]
flag = 0
for i in range(n):
for j in range(n):
if matrix[i][j] == 4:
flag = 1
x = i
y = j
break
if flag:
break
if not flag:
print('No')
sys.exit(0)
bfs(x,y)
``` | output | 1 | 21,645 | 23 | 43,291 |
Provide a correct Python 3 solution for this coding contest problem.
The zombies are gathering in their secret lair! Heidi will strike hard to destroy them once and for all. But there is a little problem... Before she can strike, she needs to know where the lair is. And the intel she has is not very good.
Heidi knows that the lair can be represented as a rectangle on a lattice, with sides parallel to the axes. Each vertex of the polygon occupies an integer point on the lattice. For each cell of the lattice, Heidi can check the level of Zombie Contamination. This level is an integer between 0 and 4, equal to the number of corners of the cell that are inside or on the border of the rectangle.
As a test, Heidi wants to check that her Zombie Contamination level checker works. Given the output of the checker, Heidi wants to know whether it could have been produced by a single non-zero area rectangular-shaped lair (with axis-parallel sides). <image>
Input
The first line of each test case contains one integer N, the size of the lattice grid (5 ≤ N ≤ 50). The next N lines each contain N characters, describing the level of Zombie Contamination of each cell in the lattice. Every character of every line is a digit between 0 and 4.
Cells are given in the same order as they are shown in the picture above: rows go in the decreasing value of y coordinate, and in one row cells go in the order of increasing x coordinate. This means that the first row corresponds to cells with coordinates (1, N), ..., (N, N) and the last row corresponds to cells with coordinates (1, 1), ..., (N, 1).
Output
The first line of the output should contain Yes if there exists a single non-zero area rectangular lair with corners on the grid for which checking the levels of Zombie Contamination gives the results given in the input, and No otherwise.
Example
Input
6
000000
000000
012100
024200
012100
000000
Output
Yes
Note
The lair, if it exists, has to be rectangular (that is, have corners at some grid points with coordinates (x1, y1), (x1, y2), (x2, y1), (x2, y2)), has a non-zero area and be contained inside of the grid (that is, 0 ≤ x1 < x2 ≤ N, 0 ≤ y1 < y2 ≤ N), and result in the levels of Zombie Contamination as reported in the input. | instruction | 0 | 21,646 | 23 | 43,292 |
"Correct Solution:
```
n = int(input())
aux = []
grid = []
flag = True
ans = -1
um = 0
dois = 0
quatro = 0
while(n):
n-=1
x = str(int(input()))
if(x!='0'):
aux.append(x)
for i in aux:
txt = ''
for j in i:
if(j!='0'):
txt+=j
grid.append(txt)
for i in grid:
for j in i:
if(j == '1'):
um+=1
if(j == '2'):
dois+=1
if(j == '4'):
quatro+=1
if(ans==-1 or len(i)==ans):
ans = len(i)
else:
flag = False
if(um!=4 or dois!=len(grid)*2+len(grid[0])*2-8 or quatro!=(len(grid)*len(grid[0]))-(len(grid)*2+len(grid[0])*2-4)):
flag = False
if(flag):
for i in range(0, len(grid)):
if(len(grid)-i-1 < i):
break
if(grid[i] != grid[len(grid)-i-1]):
flag = False
for i in range(0, len(grid)):
for j in range(0, len(grid[0])):
if(len(grid)-j-1 < j):
break
if(grid[i][j] != grid[i][len(grid[i])-j-1]):
flag = False
if(flag and ans!=-1):
print('Yes')
else:
print('No')
``` | output | 1 | 21,646 | 23 | 43,293 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Filya just learned new geometry object — rectangle. He is given a field consisting of n × n unit cells. Rows are numbered from bottom to top with integer from 1 to n. Columns are numbered from left to right with integers from 1 to n. Cell, located at the intersection of the row r and column c is denoted as (r, c). Filya has painted two rectangles, such that their sides are parallel to coordinate axes and each cell lies fully inside or fully outside each of them. Moreover, no cell lies in both rectangles.
Later, hedgehog Filya became interested in the location of his rectangles but was unable to find the sheet of paper they were painted on. They were taken by Sonya and now she wants to play a little game with Filya. He tells her a query rectangle and she replies with the number of initial rectangles that lie fully inside the given query rectangle. The query rectangle should match the same conditions as initial rectangles. Rectangle lies fully inside the query if each o its cells lies inside the query.
Filya knows Sonya really well, so is sure that if he asks more than 200 questions she will stop to reply.
Input
The first line of the input contains an integer n (2 ≤ n ≤ 216) — size of the field.
For each query an integer between 0 and 2 is returned — the number of initial rectangles that lie fully inside the query rectangle.
Output
To make a query you have to print "? x1 y1 x2 y2" (without quotes) (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n), where (x1, y1) stands for the position of the bottom left cell of the query and (x2, y2) stands for the up right cell of the query. You are allowed to ask no more than 200 queries. After each query you should perform "flush" operation and read the answer.
In case you suppose you've already determined the location of two rectangles (or run out of queries) you should print "! x11 y11 x12 y12 x21 y21 x22 y22" (without quotes), where first four integers describe the bottom left and up right cells of the first rectangle, and following four describe the corresponding cells of the second rectangle. You can print the rectangles in an arbitrary order. After you have printed the answer, print the end of the line and perform "flush". Your program should terminate immediately after it print the answer.
Interaction
To flush you can use (just after printing an integer and end-of-line):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
You will get the Wrong Answer verdict if you ask more than 200 queries, or if you print an incorrect coordinates.
You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).
Hacking.
The first line should contain an integer n (2 ≤ n ≤ 216).
The second line should contain four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n) — the description of the first rectangle.
The third line contains the description of the second rectangle in the similar way.
Example
Input
5
2
1
0
1
1
1
0
1
Output
? 1 1 5 5
? 1 1 3 3
? 1 1 3 1
? 2 2 2 2
? 3 3 5 5
? 3 3 3 5
? 3 3 3 4
? 3 4 3 5
! 2 2 2 2 3 4 3 5
Submitted Solution:
```
ad
``` | instruction | 0 | 21,652 | 23 | 43,304 |
No | output | 1 | 21,652 | 23 | 43,305 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Filya just learned new geometry object — rectangle. He is given a field consisting of n × n unit cells. Rows are numbered from bottom to top with integer from 1 to n. Columns are numbered from left to right with integers from 1 to n. Cell, located at the intersection of the row r and column c is denoted as (r, c). Filya has painted two rectangles, such that their sides are parallel to coordinate axes and each cell lies fully inside or fully outside each of them. Moreover, no cell lies in both rectangles.
Later, hedgehog Filya became interested in the location of his rectangles but was unable to find the sheet of paper they were painted on. They were taken by Sonya and now she wants to play a little game with Filya. He tells her a query rectangle and she replies with the number of initial rectangles that lie fully inside the given query rectangle. The query rectangle should match the same conditions as initial rectangles. Rectangle lies fully inside the query if each o its cells lies inside the query.
Filya knows Sonya really well, so is sure that if he asks more than 200 questions she will stop to reply.
Input
The first line of the input contains an integer n (2 ≤ n ≤ 216) — size of the field.
For each query an integer between 0 and 2 is returned — the number of initial rectangles that lie fully inside the query rectangle.
Output
To make a query you have to print "? x1 y1 x2 y2" (without quotes) (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n), where (x1, y1) stands for the position of the bottom left cell of the query and (x2, y2) stands for the up right cell of the query. You are allowed to ask no more than 200 queries. After each query you should perform "flush" operation and read the answer.
In case you suppose you've already determined the location of two rectangles (or run out of queries) you should print "! x11 y11 x12 y12 x21 y21 x22 y22" (without quotes), where first four integers describe the bottom left and up right cells of the first rectangle, and following four describe the corresponding cells of the second rectangle. You can print the rectangles in an arbitrary order. After you have printed the answer, print the end of the line and perform "flush". Your program should terminate immediately after it print the answer.
Interaction
To flush you can use (just after printing an integer and end-of-line):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
You will get the Wrong Answer verdict if you ask more than 200 queries, or if you print an incorrect coordinates.
You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).
Hacking.
The first line should contain an integer n (2 ≤ n ≤ 216).
The second line should contain four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n) — the description of the first rectangle.
The third line contains the description of the second rectangle in the similar way.
Example
Input
5
2
1
0
1
1
1
0
1
Output
? 1 1 5 5
? 1 1 3 3
? 1 1 3 1
? 2 2 2 2
? 3 3 5 5
? 3 3 3 5
? 3 3 3 4
? 3 4 3 5
! 2 2 2 2 3 4 3 5
Submitted Solution:
```
import os
import sys
if os.path.exists('/mnt/c/Users/Square/square/codeforces'):
f = iter(open('A.txt').readlines())
def input():
return next(f)
input = lambda: sys.stdin.readline().strip()
else:
input = lambda: sys.stdin.readline().strip()
fprint = lambda *args: print(*args, flush=True)
def search(pos, target, data):
d, l, u, r = data
X, Y = data[pos%2], data[pos%2 + 2]
while X + 1 < Y:
cur = (X + Y) // 2
inp = [d, l, u, r]
inp[pos] = cur
for i in range(2):
inp[i] += 1
fprint('? %d %d %d %d' % tuple(inp))
if (input() in target) ^ (pos // 2 == 1):
X = cur
else:
Y = cur
return [X, Y][pos // 2]
def main():
n = int(input())
data = [0, 0, n, n]
for pos in range(4):
data[pos] = search(pos, ['2'], data)
data2 = tuple(data)
for pos in range(4):
data[pos] = search(pos, ['1'], data)
data1 = tuple(data)
c = [n for n, (i, j) in enumerate(zip(data1, data2)) if i == j]
data = list(data2)
# print(data1)
# print(data2)
if len(c) == 1:
for pos in [(i + c[0]) % 4 for i in range(4)]:
data[pos] = search(pos, ['1'], data)
elif len(c) == 2:
for pos in c + [i + 2 for i in c]:
data[pos] = search(pos, ['1'], data)
elif len(c) == 3:
x = 0
for i in c:
x ^= i
for pos in [(i + x) % 4 for i in range(4)]:
data[pos] = search(pos, ['1'], data)
res1 = list(data1)
for i in range(2):
res1[i] += 1
res2 = list(data)
for i in range(2):
res2[i] += 1
print('? %d %d %d %d %d %d %d %d' % tuple(res1+res2))
main()
# return 'no'
# print(main())
# l, r = 1, 10**6+1
# while l + 1 < r:
# cur = (l + r) // 2
# print(cur, flush=True)
# res = input()
# if res == '>=':
# l = cur
# else:
# r = cur
# print('! %d' % l, flush=True)
``` | instruction | 0 | 21,653 | 23 | 43,306 |
No | output | 1 | 21,653 | 23 | 43,307 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Filya just learned new geometry object — rectangle. He is given a field consisting of n × n unit cells. Rows are numbered from bottom to top with integer from 1 to n. Columns are numbered from left to right with integers from 1 to n. Cell, located at the intersection of the row r and column c is denoted as (r, c). Filya has painted two rectangles, such that their sides are parallel to coordinate axes and each cell lies fully inside or fully outside each of them. Moreover, no cell lies in both rectangles.
Later, hedgehog Filya became interested in the location of his rectangles but was unable to find the sheet of paper they were painted on. They were taken by Sonya and now she wants to play a little game with Filya. He tells her a query rectangle and she replies with the number of initial rectangles that lie fully inside the given query rectangle. The query rectangle should match the same conditions as initial rectangles. Rectangle lies fully inside the query if each o its cells lies inside the query.
Filya knows Sonya really well, so is sure that if he asks more than 200 questions she will stop to reply.
Input
The first line of the input contains an integer n (2 ≤ n ≤ 216) — size of the field.
For each query an integer between 0 and 2 is returned — the number of initial rectangles that lie fully inside the query rectangle.
Output
To make a query you have to print "? x1 y1 x2 y2" (without quotes) (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n), where (x1, y1) stands for the position of the bottom left cell of the query and (x2, y2) stands for the up right cell of the query. You are allowed to ask no more than 200 queries. After each query you should perform "flush" operation and read the answer.
In case you suppose you've already determined the location of two rectangles (or run out of queries) you should print "! x11 y11 x12 y12 x21 y21 x22 y22" (without quotes), where first four integers describe the bottom left and up right cells of the first rectangle, and following four describe the corresponding cells of the second rectangle. You can print the rectangles in an arbitrary order. After you have printed the answer, print the end of the line and perform "flush". Your program should terminate immediately after it print the answer.
Interaction
To flush you can use (just after printing an integer and end-of-line):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
You will get the Wrong Answer verdict if you ask more than 200 queries, or if you print an incorrect coordinates.
You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).
Hacking.
The first line should contain an integer n (2 ≤ n ≤ 216).
The second line should contain four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n) — the description of the first rectangle.
The third line contains the description of the second rectangle in the similar way.
Example
Input
5
2
1
0
1
1
1
0
1
Output
? 1 1 5 5
? 1 1 3 3
? 1 1 3 1
? 2 2 2 2
? 3 3 5 5
? 3 3 3 5
? 3 3 3 4
? 3 4 3 5
! 2 2 2 2 3 4 3 5
Submitted Solution:
```
from sys import stdout
first_rez = []
def req(x1, y1, x2, y2):
print('?', x1, y1, x2, y2)
stdout.flush()
x = int(input())
if first_rez:
if x1 <= first_rez[0] <= first_rez[2] <= x2 and y1 <= first_rez[1] <= first_rez[3] <= y2:
x -= 1
# print(x)
return x
n = int(input())
for i in range(2):
left = 0
right = n
while right - left > 1:
mid = (left + right) // 2
s = req(1, 1, n, mid)
if s == 0:
left = mid
else:
right = mid
Y2 = right
left = 0
right = n
while right - left > 1:
mid = (left + right) // 2
s = req(1, 1, mid, Y2)
if s == 0:
left = mid
else:
right = mid
X2 = right
left = 1
right = Y2 + 1
while right - left > 1:
mid = (left + right) // 2
s = req(1, mid, X2, Y2)
if s == 0:
right = mid
else:
left = mid
Y1 = left
left = 1
right = X2 + 1
while right - left > 1:
mid = (left + right) // 2
s = req(mid, Y1, X2, Y2)
if s == 0:
right = mid
else:
left = mid
X1 = left
if i == 1:
print(X1, Y1, X2, Y2, first_rez[0], first_rez[1], first_rez[2], first_rez[3])
first_rez = [X1, Y1, X2, Y2]
``` | instruction | 0 | 21,654 | 23 | 43,308 |
No | output | 1 | 21,654 | 23 | 43,309 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
Filya just learned new geometry object — rectangle. He is given a field consisting of n × n unit cells. Rows are numbered from bottom to top with integer from 1 to n. Columns are numbered from left to right with integers from 1 to n. Cell, located at the intersection of the row r and column c is denoted as (r, c). Filya has painted two rectangles, such that their sides are parallel to coordinate axes and each cell lies fully inside or fully outside each of them. Moreover, no cell lies in both rectangles.
Later, hedgehog Filya became interested in the location of his rectangles but was unable to find the sheet of paper they were painted on. They were taken by Sonya and now she wants to play a little game with Filya. He tells her a query rectangle and she replies with the number of initial rectangles that lie fully inside the given query rectangle. The query rectangle should match the same conditions as initial rectangles. Rectangle lies fully inside the query if each o its cells lies inside the query.
Filya knows Sonya really well, so is sure that if he asks more than 200 questions she will stop to reply.
Input
The first line of the input contains an integer n (2 ≤ n ≤ 216) — size of the field.
For each query an integer between 0 and 2 is returned — the number of initial rectangles that lie fully inside the query rectangle.
Output
To make a query you have to print "? x1 y1 x2 y2" (without quotes) (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n), where (x1, y1) stands for the position of the bottom left cell of the query and (x2, y2) stands for the up right cell of the query. You are allowed to ask no more than 200 queries. After each query you should perform "flush" operation and read the answer.
In case you suppose you've already determined the location of two rectangles (or run out of queries) you should print "! x11 y11 x12 y12 x21 y21 x22 y22" (without quotes), where first four integers describe the bottom left and up right cells of the first rectangle, and following four describe the corresponding cells of the second rectangle. You can print the rectangles in an arbitrary order. After you have printed the answer, print the end of the line and perform "flush". Your program should terminate immediately after it print the answer.
Interaction
To flush you can use (just after printing an integer and end-of-line):
* fflush(stdout) in C++;
* System.out.flush() in Java;
* stdout.flush() in Python;
* flush(output) in Pascal;
* See the documentation for other languages.
You will get the Wrong Answer verdict if you ask more than 200 queries, or if you print an incorrect coordinates.
You will get the Idleness Limit Exceeded verdict if you don't print anything (but you should) or if you forget about flushing the output (more info below).
Hacking.
The first line should contain an integer n (2 ≤ n ≤ 216).
The second line should contain four integers x1, y1, x2, y2 (1 ≤ x1 ≤ x2 ≤ n, 1 ≤ y1 ≤ y2 ≤ n) — the description of the first rectangle.
The third line contains the description of the second rectangle in the similar way.
Example
Input
5
2
1
0
1
1
1
0
1
Output
? 1 1 5 5
? 1 1 3 3
? 1 1 3 1
? 2 2 2 2
? 3 3 5 5
? 3 3 3 5
? 3 3 3 4
? 3 4 3 5
! 2 2 2 2 3 4 3 5
Submitted Solution:
```
import sys
from collections import Counter
from sys import stdout, stdin
def get(a, c, b, d):
if a > b or c > d:
return -1
print('?',a,b,c,d)
stdout.flush()
return int(stdin.readline())
n = int(input())
l1 = 1
l2 = 1
r1 = n
r2 = n
while get(l1+1, l2, r1, r2) == 2:
l1 += 1
while get(l1, l2+1, r1, r2) == 2:
l2 += 1
while get(l1, l2, r1-1, r2) == 2:
r1 -= 1
while get(l1, l2, r1, r2-1) == 2:
r2 -= 1
flag = True
d = [[0,0,0,0]]*2
for i in range(l1, r1):
if flag and get(l1, l2, i, r2) == 1 and get(i+1, l2, r1, r2) == 1:
flag = False
d[0] = [l1, l2, i, r2]
d[1] = [i+1, l2, r1, r2]
for i in range(l2, r2):
if flag and get(l1, l2, r1, i) == 1 and get(l1, i+1, r1, r2) == 1:
flag = False
d[0] = [l1, l2, r1, i]
d[1] = [l1, i+1, r1, r2]
print(d)
for i in range(2):
while get(d[i][0]+1,d[i][1],d[i][2],d[i][3])==1:
d[i][0] += 1
while get(d[i][0],d[i][1]+1,d[i][2],d[i][3])==1:
d[i][1] += 1
while get(d[i][0],d[i][1],d[i][2]-1,d[i][3])==1:
d[i][2] -= 1
while get(d[i][0],d[i][1],d[i][2],d[i][3]-1)==1:
d[i][3] -= 1
print('!', d[0][0], d[0][1], d[0][2], d[0][3], d[1][0], d[1][1], d[1][2], d[1][3])
stdout.flush()
``` | instruction | 0 | 21,655 | 23 | 43,310 |
No | output | 1 | 21,655 | 23 | 43,311 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,921 | 23 | 43,842 |
"Correct Solution:
```
while True:
try:
l= int(input())
except:
break
print((l**2+l+2)//2)
``` | output | 1 | 21,921 | 23 | 43,843 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,922 | 23 | 43,844 |
"Correct Solution:
```
while True :
try :
n = int(input())
except EOFError :
break
m = n*(n+1)//2 + 1
print(m)
``` | output | 1 | 21,922 | 23 | 43,845 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,923 | 23 | 43,846 |
"Correct Solution:
```
import sys
for line in sys.stdin:
try:
n = int(line)
print((n**2 + n + 2) // 2)
except:
break
``` | output | 1 | 21,923 | 23 | 43,847 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,924 | 23 | 43,848 |
"Correct Solution:
```
while True:
try:
n = int(input())
except:
break
print(n * (n + 1) // 2 + 1)
``` | output | 1 | 21,924 | 23 | 43,849 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,925 | 23 | 43,850 |
"Correct Solution:
```
# -*- coding: utf-8 -*-
import sys
import os
for s in sys.stdin:
n = int(s)
if n == 1:
print(2)
else:
num = 2
for i in range(2, n+1):
num += i
print(num)
``` | output | 1 | 21,925 | 23 | 43,851 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,926 | 23 | 43,852 |
"Correct Solution:
```
import sys
for e in sys.stdin:e=int(e);print(e*(e+1)//2+1)
``` | output | 1 | 21,926 | 23 | 43,853 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,927 | 23 | 43,854 |
"Correct Solution:
```
while True:
try:
N = int(input())
except EOFError:
break
print(1 + sum(range(N + 1)))
``` | output | 1 | 21,927 | 23 | 43,855 |
Provide a correct Python 3 solution for this coding contest problem.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7 | instruction | 0 | 21,928 | 23 | 43,856 |
"Correct Solution:
```
import sys
for i in sys.stdin:
print(int(i)*(int(i)+1)//2+1)
``` | output | 1 | 21,928 | 23 | 43,857 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
while True:
try:
n = int(input())
except:
break
ans = 2
for i in range(2, n + 1):
ans += i
print(ans)
``` | instruction | 0 | 21,929 | 23 | 43,858 |
Yes | output | 1 | 21,929 | 23 | 43,859 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
while True:
try:
x = int(input())
print(int((x**2 + x + 2) / 2))
except:
break
``` | instruction | 0 | 21,930 | 23 | 43,860 |
Yes | output | 1 | 21,930 | 23 | 43,861 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
while True:
try:
n = int(input())
print((n**2 + n + 2)//2)
except:
break
``` | instruction | 0 | 21,931 | 23 | 43,862 |
Yes | output | 1 | 21,931 | 23 | 43,863 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
import sys
for line in sys.stdin.readlines():
n = int(line)
i = (1+n)*n//2+1
print(i)
``` | instruction | 0 | 21,932 | 23 | 43,864 |
Yes | output | 1 | 21,932 | 23 | 43,865 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
# -*- coding: utf-8 -*-
"""
http://judge.u-aizu.ac.jp/onlinejudge/description.jsp?id=0057
"""
import sys
Area_memo = [0 for _ in range(10002)] # n??¬???????????????????????????????????° (0???????¨????)
Area_memo[0] = 1
def count_area(num):
"""
????????°??¨???????????°?????¢????????\????????????????????£????????????
0 -> 1
1 -> 2
2 -> 4
3 -> 7
4 -> 11
?????£??????i??¬???????????????????????????????????°??????(i-1)??¬????????????????????° + ????????° ??¨?????????
n?????°????????§??§10,000????????§????????¢???????????????????????????
:param num:????????°
:return: ???????????°
"""
global Area_memo
if Area_memo[num] == 0:
Area_memo[num] = num + count_area(num-1)
return Area_memo[num]
def main(args):
for line in sys.stdin:
num = int(line.strip())
result = count_area(num)
print(result)
if __name__ == '__main__':
main(sys.argv[1:])
``` | instruction | 0 | 21,933 | 23 | 43,866 |
No | output | 1 | 21,933 | 23 | 43,867 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
d= dict()
j=v= 2
for i in range(1, 10001):
d[i]= v
if i%2==0: j+= 1
v+= j
while True:
try:
l= int(input())
except:
break
print(d[l])
``` | instruction | 0 | 21,934 | 23 | 43,868 |
No | output | 1 | 21,934 | 23 | 43,869 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
import sys
lc=lambda n:int((n**2+n+2)/2)
[print(i) for i in [lc(int(j)) for j in sts.stdin]]
``` | instruction | 0 | 21,935 | 23 | 43,870 |
No | output | 1 | 21,935 | 23 | 43,871 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
If you draw a few infinitely long straight lines on an infinitely wide plane, this plane will be divided into several areas. For example, if you draw a straight line, the plane will be divided into two areas. Even if you draw the same number of straight lines, the number of areas obtained will differ depending on how you draw. For example, if you draw two straight lines in parallel, you get three areas, and if you draw two straight lines perpendicular to each other, you get four areas.
<image>
Create a program that outputs the maximum number of regions that can be obtained by drawing n straight lines.
Input
Given multiple datasets. Each dataset is given n (1 ≤ n ≤ 10,000) on one row. Please process until the end of the input.
The number of datasets does not exceed 50.
Output
For each dataset, output the maximum number of divisions on one line.
Example
Input
1
3
Output
2
7
Submitted Solution:
```
while True:
try:
a = int(input())
print(((a * a) + a + 2) / 2)
except EOFError:
break
``` | instruction | 0 | 21,936 | 23 | 43,872 |
No | output | 1 | 21,936 | 23 | 43,873 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,005 | 23 | 44,010 |
Tags: math
Correct Solution:
```
from math import ceil
n,k = map(int,input().split())
ans = k//n + (k%n>0)
print(ans)
``` | output | 1 | 22,005 | 23 | 44,011 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,006 | 23 | 44,012 |
Tags: math
Correct Solution:
```
n,k=map(int,input().split(' '))
if k%n==0:
print(k//n)
else:
print(k//n+1)
``` | output | 1 | 22,006 | 23 | 44,013 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,007 | 23 | 44,014 |
Tags: math
Correct Solution:
```
from sys import stdin, stdout
import cProfile
printHeap = str()
test = False
memory_constrained = False
def display(string_to_print):
stdout.write(str(string_to_print) + "\n")
def test_print(output):
if test:
stdout.write(str(output) + "\n")
def display_list(list1, sep=" "):
stdout.write(sep.join(map(str, list1)) + "\n")
def get_int():
return int(stdin.readline())
def get_tuple():
return map(int, stdin.readline().split())
def get_list():
return list(map(int, stdin.readline().split()))
memory = dict()
def clear_cache():
global memory
memory = dict()
def cached_fn(fn, *args):
global memory
if args in memory:
return memory[args]
else:
result = fn(*args)
memory[args] = result
return result
# ----------------------------------------------------------------------------------- MAIN PROGRAM
def main():
n, k = get_tuple()
display(k//n) if k%n==0 else display((k//n)+1)
# --------------------------------------------------------------------------------------------- END
cProfile.run('main()') if test else main()
``` | output | 1 | 22,007 | 23 | 44,015 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,008 | 23 | 44,016 |
Tags: math
Correct Solution:
```
#!/usr/bin/env python
# https://github.com/cheran-senthil/PyRival/blob/master/templates/template_py3.py
import os
import sys,math
from io import BytesIO, IOBase
def main():
t=1
for case in range(t):
n,k=list(map(int,input().split()))
if k%n==0:
print(k//n)
else:
print(k//n+1)
# region fastio
BUFSIZE = 8192
class FastIO(IOBase):
newlines = 0
def __init__(self, file):
self._fd = file.fileno()
self.buffer = BytesIO()
self.writable = "x" in file.mode or "r" not in file.mode
self.write = self.buffer.write if self.writable else None
def read(self):
while True:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
if not b:
break
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines = 0
return self.buffer.read()
def readline(self):
while self.newlines == 0:
b = os.read(self._fd, max(os.fstat(self._fd).st_size, BUFSIZE))
self.newlines = b.count(b"\n") + (not b)
ptr = self.buffer.tell()
self.buffer.seek(0, 2), self.buffer.write(b), self.buffer.seek(ptr)
self.newlines -= 1
return self.buffer.readline()
def flush(self):
if self.writable:
os.write(self._fd, self.buffer.getvalue())
self.buffer.truncate(0), self.buffer.seek(0)
class IOWrapper(IOBase):
def __init__(self, file):
self.buffer = FastIO(file)
self.flush = self.buffer.flush
self.writable = self.buffer.writable
self.write = lambda s: self.buffer.write(s.encode("ascii"))
self.read = lambda: self.buffer.read().decode("ascii")
self.readline = lambda: self.buffer.readline().decode("ascii")
sys.stdin, sys.stdout = IOWrapper(sys.stdin), IOWrapper(sys.stdout)
input = lambda: sys.stdin.readline().rstrip("\r\n")
# endregion
if __name__ == "__main__":
main()
``` | output | 1 | 22,008 | 23 | 44,017 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,009 | 23 | 44,018 |
Tags: math
Correct Solution:
```
ipt = input().split()
n = int(ipt[0])
k = int(ipt[1])
if k % n == 0:
print(int(k // n))
else:
print(int((k // n) + 1))
``` | output | 1 | 22,009 | 23 | 44,019 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,010 | 23 | 44,020 |
Tags: math
Correct Solution:
```
n,k=map(int,input().split())
q=k//n
r=k%n
print(q if r==0 else q+1)
``` | output | 1 | 22,010 | 23 | 44,021 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,011 | 23 | 44,022 |
Tags: math
Correct Solution:
```
a,b=map(int,input().split())
print(0--b//a)
``` | output | 1 | 22,011 | 23 | 44,023 |
Provide tags and a correct Python 3 solution for this coding contest problem.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3. | instruction | 0 | 22,012 | 23 | 44,024 |
Tags: math
Correct Solution:
```
n,k = map(int,input().split())
if(k<n):
print(1)
else:
if(k%n==0):
print(k//n)
else:
print(k//n+1)
``` | output | 1 | 22,012 | 23 | 44,025 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
a=[int(x) for x in input().split()]
n=a[0]
k=a[1]
print((n-1+k)//n)
``` | instruction | 0 | 22,013 | 23 | 44,026 |
Yes | output | 1 | 22,013 | 23 | 44,027 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
inp = input()
n, k = inp.split()
n, k = int(n), int(k)
if k%n==0:
max_h = k//n
else:
max_h = k//n + 1
print(max_h)
``` | instruction | 0 | 22,014 | 23 | 44,028 |
Yes | output | 1 | 22,014 | 23 | 44,029 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
from math import ceil
n, k = map(int, input().split())
print(((k + (n - 1)) // n))
``` | instruction | 0 | 22,015 | 23 | 44,030 |
Yes | output | 1 | 22,015 | 23 | 44,031 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
import math
n, k = map(int, input().split())
h = (k + n - 1) // n
print(h)
``` | instruction | 0 | 22,016 | 23 | 44,032 |
Yes | output | 1 | 22,016 | 23 | 44,033 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
import math
from decimal import Decimal
l1 = input().split()
#l2 = input().split()
#l3 = input().split()
l1 = [int(i) for i in l1]
a = l1[0]
b = l1[1]
ans = math.ceil(b / a);
print(ans)
``` | instruction | 0 | 22,017 | 23 | 44,034 |
No | output | 1 | 22,017 | 23 | 44,035 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
n, k = map(int, input().rstrip().split(' '))
height = k // n + n%k
print(height)
``` | instruction | 0 | 22,018 | 23 | 44,036 |
No | output | 1 | 22,018 | 23 | 44,037 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
'''input
4 3
'''
import sys
from collections import defaultdict as dd
from itertools import permutations as pp
from itertools import combinations as cc
from collections import Counter as ccd
from random import randint as rd
from bisect import bisect_left as bl
mod=10**9+7
n,k=[int(i) for i in input().split()]
ans=k/n
if ans==int(ans):
print(int(ans))
else:
print(int(ans)+1)
``` | instruction | 0 | 22,019 | 23 | 44,038 |
No | output | 1 | 22,019 | 23 | 44,039 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
You are given a set of 2n+1 integer points on a Cartesian plane. Points are numbered from 0 to 2n inclusive. Let P_i be the i-th point. The x-coordinate of the point P_i equals i. The y-coordinate of the point P_i equals zero (initially). Thus, initially P_i=(i,0).
The given points are vertices of a plot of a piecewise function. The j-th piece of the function is the segment P_{j}P_{j + 1}.
In one move you can increase the y-coordinate of any point with odd x-coordinate (i.e. such points are P_1, P_3, ..., P_{2n-1}) by 1. Note that the corresponding segments also change.
For example, the following plot shows a function for n=3 (i.e. number of points is 2⋅3+1=7) in which we increased the y-coordinate of the point P_1 three times and y-coordinate of the point P_5 one time:
<image>
Let the area of the plot be the area below this plot and above the coordinate axis OX. For example, the area of the plot on the picture above is 4 (the light blue area on the picture above is the area of the plot drawn on it).
Let the height of the plot be the maximum y-coordinate among all initial points in the plot (i.e. points P_0, P_1, ..., P_{2n}). The height of the plot on the picture above is 3.
Your problem is to say which minimum possible height can have the plot consisting of 2n+1 vertices and having an area equal to k. Note that it is unnecessary to minimize the number of moves.
It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Input
The first line of the input contains two integers n and k (1 ≤ n, k ≤ 10^{18}) — the number of vertices in a plot of a piecewise function and the area we need to obtain.
Output
Print one integer — the minimum possible height of a plot consisting of 2n+1 vertices and with an area equals k. It is easy to see that any answer which can be obtained by performing moves described above always exists and is an integer number not exceeding 10^{18}.
Examples
Input
4 3
Output
1
Input
4 12
Output
3
Input
999999999999999999 999999999999999986
Output
1
Note
One of the possible answers to the first example:
<image>
The area of this plot is 3, the height of this plot is 1.
There is only one possible answer to the second example:
<image>
The area of this plot is 12, the height of this plot is 3.
Submitted Solution:
```
import math
n,k = list(map(int, input().split(' ')))
if k <= n:
print(1)
else:
print(math.floor(k/n))
``` | instruction | 0 | 22,020 | 23 | 44,040 |
No | output | 1 | 22,020 | 23 | 44,041 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem
You are given a grid n× n, where n is odd. Rows are enumerated from 1 to n from up to down, columns are enumerated from 1 to n from left to right. Cell, standing on the intersection of row x and column y, is denoted by (x, y).
Every cell contains 0 or 1. It is known that the top-left cell contains 1, and the bottom-right cell contains 0.
We want to know numbers in all cells of the grid. To do so we can ask the following questions:
"? x_1 y_1 x_2 y_2", where 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. In other words, we output two different cells (x_1, y_1), (x_2, y_2) of the grid such that we can get from the first to the second by moving only to the right and down, and they aren't adjacent.
As a response to such question you will be told if there exists a path between (x_1, y_1) and (x_2, y_2), going only to the right or down, numbers in cells of which form a palindrome.
For example, paths, shown in green, are palindromic, so answer for "? 1 1 2 3" and "? 1 2 3 3" would be that there exists such path. However, there is no palindromic path between (1, 1) and (3, 1).
<image>
Determine all cells of the grid by asking not more than n^2 questions. It can be shown that the answer always exists.
Input
The first line contains odd integer (3 ≤ n < 50) — the side of the grid.
Interaction
You begin the interaction by reading n.
To ask a question about cells (x_1, y_1), (x_2, y_2), in a separate line output "? x_1 y_1 x_2 y_2".
Numbers in the query have to satisfy 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. Don't forget to 'flush', to get the answer.
In response, you will receive 1, if there exists a path going from (x_1, y_1) to (x_2, y_2) only to the right or down, numbers in cells of which form a palindrome, and 0 otherwise.
In case your query is invalid or you asked more than n^2 queries, program will print -1 and will finish interaction. You will receive Wrong answer verdict. Make sure to exit immediately to avoid getting other verdicts.
When you determine numbers in all cells, output "!".
Then output n lines, the i-th of which is a string of length n, corresponding to numbers in the i-th row of the grid.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
To hack, use the following format.
The first line should contain a single odd integer n (side of your grid).
The i-th of n following lines should contain a string of length n corresponding to the i-th row of the grid. Top left element of the grid has to be equal to 1, bottom right has to be equal to 0.
Example
Input
3
0
1
0
1
1
1
1
Output
? 1 1 1 3
? 1 1 2 3
? 2 1 2 3
? 3 1 3 3
? 2 2 3 3
? 1 2 3 2
? 1 2 3 3
!
100
001
000
Submitted Solution:
```
"""This code was written by
Russell Emerine - linguist,
mathematician, coder,
musician, and metalhead."""
import sys
def ask(x1, y1, x2, y2):
print('?', x1 + 1, y1 + 1, x2 + 1, y2 + 1, flush = True)
reply = int(input())
if reply == -1: sys.exit()
return reply
n = int(input())
g = [[0 for _ in range(n)] for _ in range(n)]
g[0][0] = 1
g[1][1] = ask(0, 0, 1, 1)
g[2][1] = 1 - ask(0, 1, 2, 1)
if ask(1, 0, 2, 1): g[1][0] = g[2][1]
else: g[1][0] = 1 - g[2][1]
for i in range(n - 2):
if ask(i, 0, i + 2, 0): g[i + 2][0] = g[i][0]
else: g[i + 2][0] = 1 - g[i][0]
for i in range(n):
for j in range(n - 2):
if ask(i, j, i, j + 2): g[i][j + 2] = g[i][j]
else: g[i][j + 2] = 1 - g[i][j]
def out(flip):
print('!')
for i in range(n):
for j in range(n):
if (i + j) % 2 and flip: print(1 - g[i][j], end = '')
else: print(g[i][j], end = '')
print()
sys.exit()
for i in range(n - 1):
for j in range(n - 2):
if g[i][j + 1] != g[i + 1][j] or g[i][j + 2] != g[i + 1][j + 1] or (g[i][j] == g[i][j + 2]) == (g[i + 1][j] == g[i + 1][j + 2]):
if ask(i, j, i + 1, j + 2): out(g[i][j] == g[i + 1][j + 2])
else: out(g[i][j] != g[i + 1][j + 2])
for i in range(n - 2):
for j in range(n - 1):
if g[i][j + 1] != g[i + 1][j] or g[i + 1][j + 1] != g[i + 2][j] or (g[i][j] == g[i + 2][j]) == (g[i + 1][j] == g[i + 1][j + 2]):
if ask(i, j, i + 2, j + 1): out(g[i][j] == g[i + 2][j + 1])
else: out(g[i][j] != g[i + 2][j + 1])
``` | instruction | 0 | 22,106 | 23 | 44,212 |
No | output | 1 | 22,106 | 23 | 44,213 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem
You are given a grid n× n, where n is odd. Rows are enumerated from 1 to n from up to down, columns are enumerated from 1 to n from left to right. Cell, standing on the intersection of row x and column y, is denoted by (x, y).
Every cell contains 0 or 1. It is known that the top-left cell contains 1, and the bottom-right cell contains 0.
We want to know numbers in all cells of the grid. To do so we can ask the following questions:
"? x_1 y_1 x_2 y_2", where 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. In other words, we output two different cells (x_1, y_1), (x_2, y_2) of the grid such that we can get from the first to the second by moving only to the right and down, and they aren't adjacent.
As a response to such question you will be told if there exists a path between (x_1, y_1) and (x_2, y_2), going only to the right or down, numbers in cells of which form a palindrome.
For example, paths, shown in green, are palindromic, so answer for "? 1 1 2 3" and "? 1 2 3 3" would be that there exists such path. However, there is no palindromic path between (1, 1) and (3, 1).
<image>
Determine all cells of the grid by asking not more than n^2 questions. It can be shown that the answer always exists.
Input
The first line contains odd integer (3 ≤ n < 50) — the side of the grid.
Interaction
You begin the interaction by reading n.
To ask a question about cells (x_1, y_1), (x_2, y_2), in a separate line output "? x_1 y_1 x_2 y_2".
Numbers in the query have to satisfy 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. Don't forget to 'flush', to get the answer.
In response, you will receive 1, if there exists a path going from (x_1, y_1) to (x_2, y_2) only to the right or down, numbers in cells of which form a palindrome, and 0 otherwise.
In case your query is invalid or you asked more than n^2 queries, program will print -1 and will finish interaction. You will receive Wrong answer verdict. Make sure to exit immediately to avoid getting other verdicts.
When you determine numbers in all cells, output "!".
Then output n lines, the i-th of which is a string of length n, corresponding to numbers in the i-th row of the grid.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
To hack, use the following format.
The first line should contain a single odd integer n (side of your grid).
The i-th of n following lines should contain a string of length n corresponding to the i-th row of the grid. Top left element of the grid has to be equal to 1, bottom right has to be equal to 0.
Example
Input
3
0
1
0
1
1
1
1
Output
? 1 1 1 3
? 1 1 2 3
? 2 1 2 3
? 3 1 3 3
? 2 2 3 3
? 1 2 3 2
? 1 2 3 3
!
100
001
000
Submitted Solution:
```
from sys import stdout
n = int(input())
field = [[2] * n for _ in range(n)]
field[0][0] = 1
field[-1][-1] = 0
for i in range(0, n - 1, 2):
j = 0
print(f"? {1} {i + 1} {1} {i + 3}")
stdout.flush()
ans = int(input())
field[0][i + 2] = field[0][i] if ans else field[0][i] ^ 1
for j in range(0, n, 2):
for i in range(0, n - 1, 2):
print(f"? {i + 1} {j + 1} {i + 3} {j + 1}")
stdout.flush()
ans = int(input())
field[i + 2][j] = field[i][j] if ans else field[i][j] ^ 1
for i in range(0, n - 1, 2):
for j in range(0, n - 1, 2):
print(f"? {i + 1} {j + 1} {i + 2} {j + 2}")
stdout.flush()
ans = int(input())
field[i + 1][j + 1] = field[i][j] if ans else field[i][j] ^ 1
field[0][1] = 2
for i in range(n):
for j in range(0 + (i % 2)^1, n - 2, 2):
print(f"? {i + 1} {j + 1} {i + 1} {j + 3}")
stdout.flush()
ans = int(input())
field[i][j + 2] = field[i][j] if ans else field[i][j] ^ 1
for i in range(n - 1):
if i % 2 == 0:
s = 1
else:
s = 0
print(f"? {i + 1} {s + 1} {i + 2} {s + 2}")
stdout.flush()
ans = int(input())
if (field[i][s] == field[i + 1][s + 1] and not ans) or (field[i][s] != field[i + 1][s + 1] and ans):
for j in range(n):
if field[i + 1][j] == 2: field[i + 1][j] = 3
elif field[i + 1][j] == 3: field[i + 1][j] = 2
print("!")
for i in field:
for j in i:
print(j if j < 2 else j - 2, end=' ')
print()
stdout.flush()
``` | instruction | 0 | 22,107 | 23 | 44,214 |
No | output | 1 | 22,107 | 23 | 44,215 |
Evaluate the correctness of the submitted Python 3 solution to the coding contest problem. Provide a "Yes" or "No" response.
This is an interactive problem
You are given a grid n× n, where n is odd. Rows are enumerated from 1 to n from up to down, columns are enumerated from 1 to n from left to right. Cell, standing on the intersection of row x and column y, is denoted by (x, y).
Every cell contains 0 or 1. It is known that the top-left cell contains 1, and the bottom-right cell contains 0.
We want to know numbers in all cells of the grid. To do so we can ask the following questions:
"? x_1 y_1 x_2 y_2", where 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. In other words, we output two different cells (x_1, y_1), (x_2, y_2) of the grid such that we can get from the first to the second by moving only to the right and down, and they aren't adjacent.
As a response to such question you will be told if there exists a path between (x_1, y_1) and (x_2, y_2), going only to the right or down, numbers in cells of which form a palindrome.
For example, paths, shown in green, are palindromic, so answer for "? 1 1 2 3" and "? 1 2 3 3" would be that there exists such path. However, there is no palindromic path between (1, 1) and (3, 1).
<image>
Determine all cells of the grid by asking not more than n^2 questions. It can be shown that the answer always exists.
Input
The first line contains odd integer (3 ≤ n < 50) — the side of the grid.
Interaction
You begin the interaction by reading n.
To ask a question about cells (x_1, y_1), (x_2, y_2), in a separate line output "? x_1 y_1 x_2 y_2".
Numbers in the query have to satisfy 1 ≤ x_1 ≤ x_2 ≤ n, 1 ≤ y_1 ≤ y_2 ≤ n, and x_1 + y_1 + 2 ≤ x_2 + y_2. Don't forget to 'flush', to get the answer.
In response, you will receive 1, if there exists a path going from (x_1, y_1) to (x_2, y_2) only to the right or down, numbers in cells of which form a palindrome, and 0 otherwise.
In case your query is invalid or you asked more than n^2 queries, program will print -1 and will finish interaction. You will receive Wrong answer verdict. Make sure to exit immediately to avoid getting other verdicts.
When you determine numbers in all cells, output "!".
Then output n lines, the i-th of which is a string of length n, corresponding to numbers in the i-th row of the grid.
After printing a query do not forget to output end of line and flush the output. Otherwise, you will get Idleness limit exceeded. To do this, use:
* fflush(stdout) or cout.flush() in C++;
* System.out.flush() in Java;
* flush(output) in Pascal;
* stdout.flush() in Python;
* see documentation for other languages.
Hack Format
To hack, use the following format.
The first line should contain a single odd integer n (side of your grid).
The i-th of n following lines should contain a string of length n corresponding to the i-th row of the grid. Top left element of the grid has to be equal to 1, bottom right has to be equal to 0.
Example
Input
3
0
1
0
1
1
1
1
Output
? 1 1 1 3
? 1 1 2 3
? 2 1 2 3
? 3 1 3 3
? 2 2 3 3
? 1 2 3 2
? 1 2 3 3
!
100
001
000
Submitted Solution:
```
from sys import stdout
from itertools import product
n = int(input())
grid = [[-1] * n for _ in range(n)]
grid[0][0] = 1
grid[n-1][n-1] = 0
def print_grid():
for i in range(n):
print(''.join(map(str,grid[i])))
def query(i, j, k, l):
print("? %d %d %d %d" % (i+1, j+1, k+1, l+1))
stdout.flush()
return int(input()) == 1
def derive_value(i, j, k, l):
if grid[k][l] != -1:
return
if i < k or j < l:
q = query(i, j, k, l)
else:
q = query(k, l, i, j)
if q:
grid[k][l] = grid[i][j]
else:
grid[k][l] = 1 - grid[i][j]
for i in range(0, n-2, 2):
derive_value(i, 0, i+2, 0)
for i,j in product(range(0, n, 2), range(0, n-2, 2)):
derive_value(i,j,i,j+2)
for i,j in product(range(0, n-2, 2),range(0, n-2, 2)):
derive_value(i,j,i+1,j+1)
for i in range(0,n-2, 2):
if grid[i+2][i+2] == 0:
if query(i,j,i+1,j+2):
grid[i+1][j+2] = 1
l = i+1
m = j+2
elif grid[i+2][j] != grid[i+1][j+1]:
grid[i+1][j+2] = 0
l = i+1
m = j+2
else:
if query(i, j+1, i+2, j+2):
grid[i][j + 1] = 0
l = i
m = j + 1
elif grid[i+1][j+1] == 1:
grid[i + 1][j + 2] = 0
l = i + 1
m = j + 2
else:
grid[i][j + 1] = 1
l = i
m = j + 1
for j in range(m-2, -1, -2):
derive_value(l, j+2, l, j)
for j in range(m, n-2, 2):
derive_value(l, j, l, j+2)
for i in range(l-2, -1, -2):
derive_value(i+2, m%2, i, m%2)
for i in range(l, n-2, 2):
derive_value(i, m%2, i+2, m%2)
derive_value(l%2,m%2, l%2+1, m%2 + 1)
if l%2 == 1:
derive_value(l%2+1,m%2+1,l%2-1,m%2+1)
else:
derive_value(l%2+1,m%2+1,l%2+1,m%2-1)
for j in range(1,n-3,2):
derive_value(0,j,0,j+2)
for j in range(0,n-2,2):
derive_value(1,j,1,j+2)
for i,j in product(range(0,n-2),range(0,n)):
derive_value(i,j,i+2,j)
print_grid()
``` | instruction | 0 | 22,108 | 23 | 44,216 |
No | output | 1 | 22,108 | 23 | 44,217 |
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